row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
24,000 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you need to convert them both to 15ths and then add them together | True_Neither | null |
24,001 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you need to convert thme into fifteenths then add the top numbers to gether | True_Correct | null |
24,002 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you need to make the denominators equal before you add them | True_Neither | null |
24,003 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you need to make the denominators the same = 15 and 1x5=5 and 2x3=6 and 5+6=11 so it would be 11/15 | True_Correct | null |
24,004 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you need to make them the same denominator which is 5/15add 6/15 it equals 11/15 | True_Correct | null |
24,005 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you need to smiplify it | True_Neither | null |
24,006 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you time both the denominator and the numerator, so 5x3 2x3 and 3x5 and 1x5 | True_Correct | null |
24,007 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you time each number and then add the top two because the denominator is the same | True_Neither | null |
24,008 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you times 1/3 by 5 and then 2/5 times 3 so you then you get the same bottom number and then you just add the top numbers | True_Correct | null |
24,009 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you times 3 and 5 to get the same denominator | True_Neither | null |
24,010 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you times 3 by 5 to get 15 so you need to times 1 times 5 and 2 times three. | True_Correct | null |
24,011 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you times everything by three and then add the numerators | True_Neither | null |
24,012 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you turn them both into 15ths and that is your answer | True_Neither | null |
24,013 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you would convert the denominator into 15 | True_Neither | null |
24,014 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you would need to change each fractions denominator to 15 and change the numerator and add the 2 fractions to get the answer | True_Correct | null |
24,015 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because you x 1/3 by 5 and 2/5 by 3 | True_Neither | null |
24,016 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because, the denominator both equals to 15 and when 3 times 5 equals t 15 you have to time the numerator of the fraction with the same number do the same thing to the other one and you just plus them together. | True_Correct | null |
24,017 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | because,1/3 = 5/15 and 2/5 = 6/15 . you add them together which will equal 11/15 | True_Correct | null |
24,018 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | becausse 3 and 5 go in to 15 | True_Neither | null |
24,019 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | becquw 3 ion think it is | True_Neither | null |
24,020 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | becuase i made them into 15ths and then added them | True_Correct | null |
24,021 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | becuase times them both to make the denominators the same so you would make them 15 then add the top numbers together | True_Neither | null |
24,022 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | becuse you find the comen multiple of the denominater which is 15 | True_Neither | null |
24,023 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | both numbers go into 30 so you do 1/3 x 10 = 10/30 and 2/5 x 6 = 12/30 then you add 10/30 + 12/30 = 22/30 = 11/15 | True_Correct | null |
24,024 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | both numerators times the same amount as denominators | True_Neither | null |
24,025 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | both the denominators have to be the same. 3 & 5 are both factors of 15 so i times 1x3 and 3x5 and i times 2x3 and 5x3. which gives me 5 over 15 + 6 over 15 which gives me a final answer of 11 over 15 | True_Correct | null |
24,026 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | by finding the common denominator which is 15, we multiply 3 by 5 and 5 by 3, so 1 gets mutiplied by 5 and 2 by 3 which gives us 11 over 15 | True_Correct | null |
24,027 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | calculated mentally but im not quite sure im correct | True_Neither | null |
24,028 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | cause i made it so they had the same denominater | True_Neither | null |
24,029 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change 1/3 to 5/15 then change 2/5 to 6/15 then add them together to get 11/15 | True_Correct | null |
24,030 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change both the bottom number to 15. to get from 3 to 15 you times by 5 so you do the same with the top. same thing with 2/5
=11/15 | True_Correct | null |
24,031 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change demominator on both to 15. so times 1/3 by 5 and 2/5 by three so you have
5/15 and 6/15.
5+ 6 = 11 so 11/15 is the answer | True_Correct | null |
24,032 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change denominators to 15 then multiply the numerator by 5 then add them | True_Neither | null |
24,033 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change into 15ths and then add | True_Neither | null |
24,034 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change it to a common denominator then add the numerator | True_Neither | null |
24,035 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominaters to 15
1 x 5
2 x 3 | True_Correct | null |
24,036 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominator of each fraction to 15
so it would change to 5 over 15 and 6 over 15
when added together it makes 11 over 15 | True_Correct | null |
24,037 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominator then times the top like you did with the bottom and add them up | True_Correct | null |
24,038 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominator to 15ths. then you will get 5/15 + 6/15. | True_Correct | null |
24,039 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominators to 15 then change the denominator to what ever you have x it by then add the numonitors together | True_Correct | null |
24,040 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominators to 15 then do 1 x 5 and 2 x 3 add them together which equals 11 | True_Correct | null |
24,041 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominators to the nearest factor or multiple and then add them together... | True_Neither | null |
24,042 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the denominators to the same | True_Neither | null |
24,043 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change the fractions so they have the same denominater and add them together. 5/15+6/15=11/15 | True_Correct | null |
24,044 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change them both into fifteenth and then added them. | True_Neither | null |
24,045 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | change them to fifteenth them add them together. | True_Neither | null |
24,046 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | changed the denominator into 15'ths and then worked it out from there . | True_Neither | null |
24,047 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | changing both of the fractions to be over 15 gives us
5/15 + 6/15
5+6 is 11
11/15 | True_Correct | null |
24,048 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | cinvert them to the lcm and add them | True_Neither | null |
24,049 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denominator and multiply the numerators | True_Neither | null |
24,050 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denominator has to be 15 | True_Neither | null |
24,051 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denominator is 15 so that’s 5/15 plus 6/15 | True_Correct | null |
24,052 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denominator is 15. 1/3 in 15s is 5/15.
2/5 in 15s is 6/15. 5 + 6 = 11 | True_Correct | null |
24,053 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denominator is 15. 3 x 5 = 15, 2 x 6 = 15 | True_Neither | null |
24,054 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denominator is 15. making the sum 5 over 15 + 6 over 15 which is = 11 over 15 | True_Correct | null |
24,055 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common denomonator is 15.
1/3 turns into 5/15.
2/5 turns into 6/15.
5/15 + 6/15 = 11/15 | True_Correct | null |
24,056 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | common multiple of both 3 and 5 is 15 so the denominator becomes 15 the sum is now;
5/15+6/15= 11/15 | True_Correct | null |
24,057 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | con vert the denom then numer | True_Neither | null |
24,058 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert 1/3 to 5/15 and 2/5 into 6/15 then add it together and it makes 11/15 | True_Correct | null |
24,059 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert 1/3 to 5/15 and 2/5 to 6/15 then add them up | True_Correct | null |
24,060 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert 1/3 to 5/15 plus 2/5 witch converts to 6/15 and plus together is 11/15 | True_Correct | null |
24,061 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert 3 and 5 into 15 then 1/3 will become 5/15 then you covert 2/5 into 6/15 then add =11/15 | True_Correct | null |
24,062 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert each one so they are out of 15 so 1x5=5 (5/15) and 2x3=6 (6/15) so 5+6=11 so its 11/15 (d) | True_Correct | null |
24,063 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert into 15ths 1 3rd would = 5 15ths and 2 5ths would = 6 15ths | True_Correct | null |
24,064 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert it to 5 15ths and 6 15ths which would be 11 over 15 | True_Correct | null |
24,065 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert the dominator of both numbers and you can use the denominator of 15 and the numerators become 5 and 6 which add up to 11 | True_Correct | null |
24,066 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert them both to a common denomitor and then add the numerators | True_Neither | null |
24,067 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | convert them into 15ths and add them. | True_Correct | null |
24,068 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | converted them both to 15 and added the numerator | True_Neither | null |
24,069 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | converting the fractions to a common denominator gives 15 as the new denominator and 5 + 6 = 11 as the numerator | True_Correct | null |
24,070 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | cross method and find common denominator=15 | True_Neither | null |
24,071 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | cross multiplication gives you the fractions 5/15 and 6/15 and em up and you get 11/15 | True_Correct | null |
24,072 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d as i picked a number that goes into the 5 and 3 times table.the number is 15. then 1×3 and 2×3 and then carry on | True_Correct | null |
24,073 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d as you have to find the denominitor which is 15 then you can add it | True_Neither | null |
24,074 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d beacue 3x5 is 15 the times the numerator by 5 which is 5/5 | True_Neither | null |
24,075 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because you change both denominator and × the top by what you × the bottom and add themail you get 11/15 | True_Correct | null |
24,076 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because 1/3 into 15th is 5/15 and 2 into 15th is 6/15 add 6 and 5 is 11/15 | True_Correct | null |
24,077 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because 1/3 is 5/15 and 2/5 is 6/15 so 5/15 plus 6/15 is 11/15 | True_Correct | null |
24,078 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because 1/3=5/15 & 2/5=6/15 then 6/15+5/15=11/15 so the answer is d | True_Correct | null |
24,079 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because first i changed the denominator to 15 then i changed the numerator and i got 5/15 and 6/15 then added it together and i had 11/15 | True_Correct | null |
24,080 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because i made the denominators the same what was 15 | True_Neither | null |
24,081 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because if you convert both fractions into 15ths you get; 1/3=5/15 and 2/5=6/15 the add the numerators you get 11/15 and that can't be simplified. | True_Correct | null |
24,082 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because if you plus it it equals that | True_Neither | null |
24,083 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because if you turn them into 15ns you will get 5 over 15 add 6 over 15 and 5+6 is 11 | True_Correct | null |
24,084 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because that is the answer | True_Neither | null |
24,085 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because that is what you get if you actually add the two fractions together. | True_Neither | null |
24,086 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because the denominator is 15 and 5+6=11 | True_Correct | null |
24,087 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because the lowest common denominator is 15 , so that rules out a and c and 1/3 converted into /15 is 5/15 , so both of them added together isn't 3/15 , so it can only be d. | True_Neither | null |
24,088 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because the lowest common multiple of 3 and 5 is 15 so 1/3 is 5/15 2/5 is 6/15 so 5/15 + 6/15 = 11/15 and 11/15 cannot simplify so that is the answer | True_Correct | null |
24,089 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because when i worked it out, my answer was 11/15. | True_Neither | null |
24,090 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because you are using your times tables | True_Neither | null |
24,091 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because you can rule out the others. | True_Neither | null |
24,092 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because you have to change it to the same denominator | True_Neither | null |
24,093 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because you have to find a common denominator which is 15. 5/15+6/15=11/15. | True_Correct | null |
24,094 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d because you just have to convert them then add them. | True_Correct | null |
24,095 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d is the correct answer because 1/3 + 2/5 = 11/15 | True_Neither | null |
24,096 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d is the correct answer because we take 15 as a common denominator which is going to equal
11/15 | True_Neither | null |
24,097 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | d, if you make all of them into 15ths 5 add 6= 11 | True_Correct | null |
24,098 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | denominator has to be 15 to add both numerators together🌮 | True_Neither | null |
24,099 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | denominator is 15 1/3 is 5 and 2/5 is 6 plus then to get d | True_Neither | null |
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