row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
24,700 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i used the same denominator lcm | True_Neither | null |
24,701 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i used the whiteboard to help me | True_Neither | null |
24,702 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out and this is the answer i got. | True_Neither | null |
24,703 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out by converting 1/3 into 5/15 and i also converted 2/5 into 6/15 then i added thenm together to get 11/15 | True_Correct | null |
24,704 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out by making the denominator the same and then changing the numerator to fit the denominator and then i added them together. | True_Correct | null |
24,705 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out in my book | True_Neither | null |
24,706 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out in my head | True_Neither | null |
24,707 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on a piece of paper | True_Neither | null |
24,708 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on a post it note | True_Neither | null |
24,709 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on a whiteboard and got the answer 11/15. | True_Neither | null |
24,710 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on my whiteboard. | True_Neither | null |
24,711 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on paper | True_Neither | null |
24,712 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on paper | True_Neither | null |
24,713 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on paper. | True_Neither | null |
24,714 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on paper. | True_Neither | null |
24,715 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked it out on white bored | True_Neither | null |
24,716 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked out five times three and the rest came easily to me | True_Neither | null |
24,717 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked this out in my head | True_Neither | null |
24,718 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked this out in my revision book | True_Neither | null |
24,719 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i worked what timetable goes into 3 and 5 and that was 15 so i put that as the common denominator. then i timed it | True_Neither | null |
24,720 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i would not be able to | True_Neither | null |
24,721 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | i would not be able to | True_Neither | null |
24,722 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if something has 15 parts, one third would be 5 parts. two fifths would be 6 parts. 5 + 6 =11, so 11 over 15. | True_Correct | null |
24,723 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if u change the denominator into 15 and then times 1 x 5 is 5 then 2x3 is 6 then u do 5/15 + 6/15 then you’ll get 11/15 | True_Correct | null |
24,724 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if u convert both of them into 15 and do the same to to the top and add them which is 11 over 15 | True_Correct | null |
24,725 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if u times it across 3 times 2 equal 6 1 times 5 equal 5 add 5and 6 which is eleven then times the bottom numbers 5times 3 equals 15 so it equals 11-15 👍 | True_Correct | null |
24,726 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if we change the denomiantors so they are equal and then multiply the numerators by the number we multiplied the denominators by and we add the two fractions it will equal 11/15 | True_Correct | null |
24,727 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if we convert the denominators of the fractions to 15, we get 5/15 + 6/15. we add them together and get 11/15 | True_Correct | null |
24,728 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if we find the common denominator between both it would be 15, by making it 15 let's say 3x5 = 15 for the first fraction so multiply 1 by 5. then for the 2nd fraction, it's 5x3=15 so 2x3= 6.
so if we do it now it's 5/15+6/15 = 11/15 | True_Correct | null |
24,729 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you add them together you get11/15. | True_Neither | null |
24,730 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you add then it this awser | True_Neither | null |
24,731 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change 1/3 to 5/15 and you change 2/5 to 6/15 5/15+6/15=11/15 so 11/15 is the answer | True_Misconception | Denominator-only_change |
24,732 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change both denominators to 15, both change into 5 over 15 and 6 over 15, which added together equals 11 over 15. | True_Correct | null |
24,733 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the denominator then you will get 15 and then you will get eleven fifteenths | True_Neither | null |
24,734 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the denominator to 15 (because 3x5= 15) it would leave you with 5/15 and 6/15 then add the numerators together to get 11/15. | True_Correct | null |
24,735 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the denominator to 15 (because 5 and 5 both go into it)it would leave you with 5/15 and 6/15. add the numerators together to get 11/15 | True_Correct | null |
24,736 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the denominator to 15 because they both go into that then times the denominator by the numerator on the other side and do the same on the other then add them up it gives you 11/15 | True_Correct | null |
24,737 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the denominator to 15 then you change the tops too | True_Neither | null |
24,738 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the denominator to the lcm which is 15 you get 5/15 add 6/15 which i 11/15 and that cant be simplified | True_Correct | null |
24,739 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you change the dinominator show they are the same all you have to add the numerators. | True_Neither | null |
24,740 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert 1/3 and 2/5 into a common denominator of 3 and 5 you get 15 and 1/3 is 5/15 and 2/5 is 6/15.
5/15 add 6/15 is 11/15. | True_Correct | null |
24,741 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert both fractions to /15, this added together would be 11 | True_Correct | null |
24,742 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert it to 15ths you get 5/15 and 6/15 add them together to get 11/15. | True_Correct | null |
24,743 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert the sum you do 5/15 + 6/15 which equals 11/15 | True_Correct | null |
24,744 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert them both into the same denomintor, the question would be 5/15 + 6/15 which would equal 11/15 | True_Correct | null |
24,745 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert them into 15 they would be 5/15 and 6/15 =11/15 | True_Correct | null |
24,746 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert them into 15ths you get 5/15 and 6/15 add the numerator it is 11/15 | True_Correct | null |
24,747 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert them into over 15 then,it would be 5/15 +6/15 which then = 11/15 | True_Correct | null |
24,748 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert them to 15ths and then add them together you get 11/15. | True_Correct | null |
24,749 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you convert them to the same denominator, then correct the numerator, you can add them together to get the answer. | True_Correct | null |
24,750 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you covert them into common denominators, they would be:
5/15 and 6/15
if you add them together, you would get 11/15 | True_Correct | null |
24,751 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you find a common denominator it is easy.
5/15 + 6/15 =11/15 | True_Correct | null |
24,752 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you give both of the numbers a common denominator of 15, the sum end up being 5/15+ 6/15 which equals 11/15 | True_Correct | null |
24,753 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you make both have the same denominator, it would get you to 5/15 and 6/15
add them together and you would get 11/15 | True_Correct | null |
24,754 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you make both the numbers have the same denominator you get 5/15 + 6/15 = 11/15 | True_Correct | null |
24,755 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you make the denominators the same it would make 11 15ths | True_Neither | null |
24,756 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you make the denominators the same, you get 5/15+6/15 which makes 11/15 | True_Correct | null |
24,757 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you put 15 on the bottom of the fractions become 5/15 and 6/15 which adds up to 11/15 | True_Correct | null |
24,758 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you put them both over a denominator of 15, then you get 5/15 and 6/15 so you just add them together. | True_Correct | null |
24,759 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you put them under the same denominator the equation becomes 5/15+6/15 which is 11/15 | True_Correct | null |
24,760 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you turn the denominators to 15 then add the numerators the total is 11. | True_Correct | null |
24,761 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you turn them into 15th's and add them together you gets that number . | True_Correct | null |
24,762 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you turn them into 15ths 2/5 becomes 6/15 and 1/3 becomes 5/15 then if you add them together you get 11/15 | True_Correct | null |
24,763 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | if you work it out you will get
11/15 | True_Neither | null |
24,764 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | im pretty sure this is the one | True_Neither | null |
24,765 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | in order to add 1/3 to 2/5 you have to find a common denominator. the smallest one is 15. 3 x 5 = 15, so 1 x 5 = 5. 5 x 3 = 15 so 2 x 3 = 6.
5/15 + 6/15 = 11/15. this number cannot be simplified. | True_Correct | null |
24,766 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | in order to do addition we need to make the denominator the same number. so i found the lcm and times 1x5/3x5 + 2x3/5x3 = 11+15 | True_Correct | null |
24,767 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | is this because i first changed the fractions so that they had the same denominator and then i added those fractions together and got 11/15 | True_Correct | null |
24,768 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it has got to have a common denominator | True_Neither | null |
24,769 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is 11/15 because you conver both fractions in 15ths and then add 6/15 to 5/15 to get 11/15. | True_Correct | null |
24,770 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is 11/15 because you have to change the denominator to 15 and then 1/3 becomes 5/15 and 2/5 become 6/15 and then you add them together to get 11/15 | True_Correct | null |
24,771 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is b as 3 x5 = 15
1 x 5 = 5
3 x 2= 6 = 11/15 | True_Correct | null |
24,772 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is because you have to find a lowest common denominator which is 15 and then you have to times 3 by 2 then 1 by 5 and then your answer should be 11/15 | True_Correct | null |
24,773 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d 1/3 +2/5 = 11/15 because 1/3 times 5=5/15 and 2/5 times 3 = 6/15+ 5/15 = 11/15. | True_Correct | null |
24,774 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d as i tuned the bottom of both fractions into 15, as it is the lowest multiple point between the two fractions, and the answer i got happened to be answer d | True_Correct | null |
24,775 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because 1/3 + 2/5 is 11/15 | True_Neither | null |
24,776 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because 1/3 + 2/5= 11/15 because you have to x 1/3 by 5 and 2/5 by 3 to get your answer of 11/15 | True_Neither | null |
24,777 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because 1/3 you change it to 5/15 and you change 2/5 to 6/15 and then you add it up and you will get the answer. | True_Correct | null |
24,778 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because 1/3= 5/15 and 2/5 = 6/15 add them together= 11/15 | True_Correct | null |
24,779 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because 3 and 5 both go into 15 so both of the denominators = 15. then you do 1 x 5 = 5 and 2 x 3 = 6. finally 5/15 + 6/15 = 11/15. | True_Correct | null |
24,780 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because a common denominator is 15 so 3x5=15 and (1x5)+(2x3)=11. | True_Correct | null |
24,781 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because if you convert them into 15ths ( x3, x5) you would do the same to the numerators to make it 5/15 and 6/15 which is 11/15. | True_Correct | null |
24,782 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because if you get them in the same denominator then add it togereg | True_Neither | null |
24,783 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is d because you change 1/3 to 5/15 and 2/5 to 6/15 and you add it together and you will get the answer. | True_Correct | null |
24,784 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is the only one that makes sense | True_Neither | null |
24,785 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is the only one that works | True_Neither | null |
24,786 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it is this because you find a common denominator then times it by numerator then add | True_Neither | null |
24,787 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it would be 11/15 because to get the common denominator you multiply 3 by 5 and vice versa to get 5/15 + 6/15 is 11/15. | True_Correct | null |
24,788 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it would be 11/15 because you need to get a common denominator of 1/3 and 2/5 which is 15 so then it would be 5/15 and 6/15 which equals to 11/15 when you plus them | True_Correct | null |
24,789 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it would be 22/30 and if you divide it by 2 its 11/15 so its right | True_Neither | null |
24,790 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it would have to be fifteenths and three fifteenths means that you haven't multiplied the top number | True_Neither | null |
24,791 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it would turn into 6\15 and 5\15 | True_Neither | null |
24,792 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it wouldn't be b because whatever you do to the bottom you have to the top | True_Neither | null |
24,793 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it's d because you make them the same denominator and then you ad them together to make 11/15 | True_Correct | null |
24,794 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it's not a as it's literally adding 1 to 2 and 3 to 5. it's not b as you can't times 3 by 5 and add 1 to 2. it's either 11/30 or 11/15; a 50/50 chance. | True_Neither | null |
24,795 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | it's simplified because they go into 15 and add them together | True_Neither | null |
24,796 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | its 11/15 because i knew that 15 goes into 3 and 5 so then i did 5x3=15 3x5=15 then 1x5=5 and 2x3=6 add then together to get 11/15 and you cant simplifly | True_Correct | null |
24,797 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | its because we get the denominators the same first then we add them up | True_Neither | null |
24,798 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | its d because 1/3 + 2/5 would have to convert to 6/15 then 1/3 would convert to 5/15 then add them together and its 11/15 | True_Correct | null |
24,799 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | its hard to explain theese things | True_Neither | null |
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