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stringclasses
49 values
StudentExplanation
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Category
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Misconception
stringclasses
35 values
8,500
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because 72 is 3 fifths and the differance between 120 and 72 i 48
False_Misconception
Wrong_Fraction
8,501
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because 72 is 3 fifths and the differance between 120 and 72 is 48
False_Misconception
Wrong_Fraction
8,502
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because half is 60 and 3/5 is 72 so 120 - 72=48
False_Misconception
Wrong_Fraction
8,503
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because i if it 120 so i add it to gever and i got 40
False_Neither
null
8,504
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because i added them all up and divided by 5 an times that answer by three
False_Neither
null
8,505
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because i divided 120 by 5 then mulitiplied it by 3
False_Neither
null
8,506
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because i worked out what 1 / 5 was and then doubled it.
False_Misconception
Wrong_Fraction
8,507
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because if you look at the numbers you can tell that it can't be a or c so i picked d because it seems like the right one.
False_Neither
null
8,508
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because there are 2/5 left which = 48
False_Misconception
Wrong_Fraction
8,509
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because there are 72 blue counters so you need to minus tht from the totsl
False_Misconception
Wrong_Fraction
8,510
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because you find 3/5 of 120=72 then you do 120-72=48 so that is how I got 48
False_Misconception
Wrong_Fraction
8,511
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
because you have to find 2/5 of 120 which is 48 so the answer is 48
False_Misconception
Wrong_Fraction
8,512
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
brcause one of them is 24 and if you times that by two it gives you 48.
False_Misconception
Wrong_Fraction
8,513
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
d because 3 / 5 of 120 is 72 and 72 minus 120 equals 48.
False_Misconception
Wrong_Fraction
8,514
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
d because it must not be c and also b would not make sense and a is the same thing as both of those, so that's why i picked it.
False_Neither
null
8,515
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
d because when youu divide 120 by 5 you get an answer of 24 and therefore to find 2/5 you have to multiply 24 by 2
False_Misconception
Wrong_Fraction
8,516
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
d because you have to divide by 5 then x by 3 and that gets you to this answer
False_Neither
null
8,517
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
divide 120 by 5 then times it by 2 to get the answer
False_Misconception
Wrong_Fraction
8,518
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
divide 120 by 5, and then multiply by 3, to get the answer for the red counters. subtract 72 (blue counter) from 120, to find out how much to pay for each blue counter.
False_Misconception
Wrong_Fraction
8,519
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
divide by bottom times by the top and take away frim your starting number.
False_Misconception
Wrong_Fraction
8,520
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
divide by the bottom times by the top
False_Neither
null
8,521
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
do 120 divided by 3 which is 40 and 48 is closest to 40.
False_Neither
null
8,522
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
each part is 24 and if there is only 2 24s left you do 24x2=48. I needed help.
False_Misconception
Wrong_Fraction
8,523
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
first I divided 120 by 5(the denominator) which gave me 24 as 2 5ths were left I times 24 by 2 giving me 48(D)
False_Misconception
Wrong_Fraction
8,524
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
first i divided 120 by 5 (the denominator) which gave me 24 as 2 5ths were left i times 24 by 2 giving me 48 (d)
False_Misconception
Wrong_Fraction
8,525
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
for this question, i calculated what 2 / 5 of 120 was, because if 3 /5 are blue, then that means 2/5, which gave me an answer of 48.
False_Misconception
Wrong_Fraction
8,526
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
half is 60 andd 3/5 is 72 so 120 - 72 = 48.
False_Misconception
Wrong_Fraction
8,527
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
half is 60 so take away 12 to get your answer
False_Neither
null
8,528
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
half of 120 is 60 and take away 12=48 half =60+12=72+48=120=48red countiters
False_Neither
null
8,529
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
halff of 120 is 60 and take away 12 = 48 half =60+12=72+48=120=48red countiters
False_Misconception
Wrong_Fraction
8,530
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
how many 5's are in 120 which is 24 than x that by three which equals 72 than you do how much is between 72 and 120
False_Misconception
Wrong_Fraction
8,531
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
how much 5's are in 120 which is 24 than x that by three which equals 72 than you do how much is between 72 and 120
False_Misconception
Wrong_Fraction
8,532
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i added them alll up and then divided by 5 times that answer by three
False_Neither
null
8,533
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i am gesturing because i do not have a piece of paper.
False_Neither
null
8,534
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i chose d because i calculated how much was left to make a whole and it was 2/5 of 120. i then did 2 / 5 of that number and that gave me 48.
False_Misconception
Wrong_Fraction
8,535
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i chose this because it seemed like the most reasonable answer
False_Neither
null
8,536
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i did 120 divided by 5 and thenn times it by 3.
False_Neither
null
8,537
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i did 3 / 5 of 120, which is 72, and then took away the remaining from 120.
False_Misconception
Wrong_Fraction
8,538
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i divided 120 by 5 and then multiplied by 3, so it came out to be 3 times what it should have been.
False_Neither
null
8,539
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i divided and it was the closest to my answer
False_Neither
null
8,540
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i divided it and it was closestt to my answer.
False_Neither
null
8,541
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i divided it by 5 then X it by 2
False_Misconception
Wrong_Fraction
8,542
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i divided it by 5, then xed it.
False_Neither
null
8,543
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i don't know so i guessed
False_Neither
null
8,544
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i dont know how to explain
False_Neither
null
8,545
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i forgot how to figure out the bar method but when i tried this was the closest
False_Neither
null
8,546
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i found 1/5 by dividing 120 by 5= 24, and then multiplied that by 3 to get to 75 (3/5). then i knew that i had to find the 2/5 that are missing from the hole so i did 24+24=48
False_Misconception
Wrong_Fraction
8,547
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i got 24 and then doubled it.
False_Misconception
Wrong_Fraction
8,548
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i got 40 because i if it 120 so i add it to gever and i get 40.
False_Neither
null
8,549
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i got a bit stuck on this one but 3/5 is 75% so i took 75 away from 120.
False_Neither
null
8,550
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i knew it couldn’t be a or c so i started wuth forty eight and halfed it. then i multiplies it by five and got an answer of 120.
False_Neither
null
8,551
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i know because i used a bar model to find out that it is 24 per piece and 24+24 is 48
False_Misconception
Wrong_Fraction
8,552
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i know that 35 =90 so i guessed from there.
False_Neither
null
8,553
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i know the answer is d because if 1/5 of 120 is 24 then 2/5 must be double (48 )
False_Misconception
Wrong_Fraction
8,554
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i know this because we put 24 in a bar model and 3 parts equals 72 counters so i subtracted 72 from 120 to get 48.
False_Misconception
Wrong_Fraction
8,555
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i subtracted 72 from 120 so that i concluded with the answer 48
False_Misconception
Wrong_Fraction
8,556
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i thimk this because i believe it.
False_Neither
null
8,557
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think it because 2 fifths are left over so 24 multiplied by 2 =48
False_Misconception
Wrong_Fraction
8,558
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think it is 48 because you could timrs it by 3 to get 120 something.
False_Neither
null
8,559
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think it is d because there are 2/5 left of the counters, and 1/5 is 24, so 2/4 is double: 48.
False_Misconception
Wrong_Fraction
8,560
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think it would be d because the number is 27.
False_Neither
null
8,561
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think it's because i made a bar model out of some paper.
False_Neither
null
8,562
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think the answer is d because 120 divided by 5 = 24. 24 x the two extra fifths = 48
False_Misconception
Wrong_Fraction
8,563
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think the answer is d because i worked it out and i got this answer.
False_Neither
null
8,564
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because 1 / 5 is 24 and 3 /5 is 72 and 120 - 72 is 48 so it is d.
False_Misconception
Wrong_Fraction
8,565
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because 120 divided by 5 is 24 times 3 which is 7 and then taken away from 120 is 48.
False_Misconception
Wrong_Fraction
8,566
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because 3/5 is equivalent to 48
False_Neither
null
8,567
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because 60 is 1 / 2 and 24 is lower than 1 quarter so 48 - 24 = 48.
False_Neither
null
8,568
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because i first divided twenty by five and i got 24 and since i needed to find out 2/5 i doubled it and got 48.
False_Misconception
Wrong_Fraction
8,569
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because if you divide 120 by five and then times by two, you get 48.
False_Misconception
Wrong_Fraction
8,570
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because one - fifthh of 120 is 24. 24 x 3 = 72 and 120 minus 72 = 48.
False_Misconception
Wrong_Fraction
8,571
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because the counter of red is 72 so the blue must be 48.
False_Misconception
Wrong_Fraction
8,572
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this because you divide by bottom (denominator) and times by top (numerator).
False_Neither
null
8,573
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this is because 120 divided by 5 is 24 then 24 times by 2 is 48.
False_Misconception
Wrong_Fraction
8,574
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this is because 3 / 5 of 120 is 72 so yiu do 120 - 72 = 48.
False_Misconception
Wrong_Fraction
8,575
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this is because 3/5 is equivalent to 6/10 so i divided 120 by 10 to get 12. then to find 3/10 i multiplied 12 by 6 toget 72. the then i took that away from 120 leaving me with 48.
False_Misconception
Wrong_Fraction
8,576
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i think this is because when you divide 5 by 120 it is 24 then you multiply it by 2.
False_Misconception
Wrong_Fraction
8,577
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i worked out that 1 fifth is 24 and the blue counters were 2 fifths so i doubled 24 which was 48.
False_Misconception
Wrong_Fraction
8,578
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i worked out whst one fifth was and then worked back from there.
False_Neither
null
8,579
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i worked outt that 1 fifth is 24 and the blue counters were 2 fifths so i doubled 24 which was 48.
False_Misconception
Wrong_Fraction
8,580
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i'm nott sure, so i guessed.
False_Neither
null
8,581
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
i've worked this out on a bar model.
False_Neither
null
8,582
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if 120 divided by 5 is 24 timrs 3 is 72 then do 120 -62 is 48.
False_Misconception
Wrong_Fraction
8,583
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if 3/5 are blue 2/5 are red and 2/5 of 120 is 48
False_Misconception
Wrong_Fraction
8,584
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if 3/5 are red then 2/5 would be blue. 1 / 5 of 120 is 24. 24x2=48
False_Misconception
Wrong_Fraction
8,585
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if i do 5 divided by 120 which is 24 and times by 3 that is 72 and then take it away from 120 that equals 48.
False_Misconception
Wrong_Fraction
8,586
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you change 3 /5 into 6/10 then you divide 120 by 10 and times it by 6. then whatever that numberr is you take it away from 120.
False_Misconception
Wrong_Fraction
8,587
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you divide 120 by 3, which is 40, then 48 is closest to 40.
False_Neither
null
8,588
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you divide 120 by 5 and times your answer by three and subtract it from 120 it will equall 48
False_Misconception
Wrong_Fraction
8,589
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you divide 120 by 5 and times your answer by three and then subtract it from 120 it will equal 48.
False_Misconception
Wrong_Fraction
8,590
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you divide 120 by 5 it equals 24 and 24 times by 3 is 48
False_Neither
null
8,591
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you divide by the bottom and times by the top you get 72 then you take it away frome 120
False_Misconception
Wrong_Fraction
8,592
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you do 24X5 it is 120 so the
False_Neither
null
8,593
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you find 3/5 you can take that away from 120 so it would be 120-72=48
False_Misconception
Wrong_Fraction
8,594
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if you take the first and last terms by the srcond you get 72 then you subtract the 72 from the 120.
False_Misconception
Wrong_Fraction
8,595
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if youu do 24x5 it is 120 so the
False_Neither
null
8,596
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
if youu multiply 3/5 by 120, the answer will be 120 - 120.
False_Neither
null
8,597
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
it is d as i didd 2/5 of 120 and 120 / 5 = 24 and 24 x 2 = 48.
False_Misconception
Wrong_Fraction
8,598
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
it is d because if 3/5 arr blue, that leaves 2/5 as red, and 48 divided by 120 is 48.
False_Misconception
Wrong_Fraction
8,599
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 48 \)
multiply 3/5 by 120 and then minus the answer by 120
False_Misconception
Wrong_Fraction