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prime-number-of-set-bits-in-binary-representation | Brian Kernighan's Algorithm | Easiest | Simplest | No Where On Youtube | brian-kernighans-algorithm-easiest-simpl-tr36 | IntuitionWe need to iterate to each number, calculate the number of set bits and check whether they are prime or not.ApproachWe first iterate to each number usi | rohanmalhotracodes | NORMAL | 2025-01-30T20:43:15.408978+00:00 | 2025-01-30T20:43:15.408978+00:00 | 128 | false | # Intuition
We need to iterate to each number, calculate the number of set bits and check whether they are prime or not.
# Approach
We first iterate to each number using the loop
while(left<=right){
left++
}
to iterate to each value in the range [left,right]
Then, we count the number of primes in each value we iter... | 1 | 0 | ['Math', 'Bit Manipulation', 'C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | ☑️ Finding Prime Number of Set Bits in Binary Representation. ☑️ | finding-prime-number-of-set-bits-in-bina-ic8v | Code | Abdusalom_16 | NORMAL | 2025-01-26T17:29:50.741711+00:00 | 2025-01-26T17:29:50.741711+00:00 | 36 | false | # Code
```dart []
class Solution {
int countPrimeSetBits(int left, int right) {
int result = 0;
for(int i = left; i <= right; i++){
String conv = i.toRadixString(2);
int count = 0;
for(int j = 0; j < conv.length; j++){
if(conv[j] == "1"){
count++;
... | 1 | 0 | ['Math', 'Bit Manipulation', 'Dart'] | 0 |
prime-number-of-set-bits-in-binary-representation | Bit Manipulation | Easy | Beats 100% | ✅ | bit-manipulation-easy-beats-100-by-batma-sw05 | Intuition\n Describe your first thoughts on how to solve this problem. \nThe problem requires counting numbers within a given range [left, right] where the numb | batman505 | NORMAL | 2024-10-01T08:52:25.078647+00:00 | 2024-10-01T08:52:25.078711+00:00 | 75 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem requires counting numbers within a given range `[left, right]` where the number of set bits (1s in the binary representation) of each number is prime. The solution involves checking each number, counting its set bits, and then... | 1 | 0 | ['Bit Manipulation', 'C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | Finding Set bits and checking if its prime for all values btw left and right | finding-set-bits-and-checking-if-its-pri-4s1l | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | sdeepthi035 | NORMAL | 2024-09-11T13:43:54.485673+00:00 | 2024-09-11T13:43:54.485695+00:00 | 73 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 0 | ['Java'] | 0 |
prime-number-of-set-bits-in-binary-representation | C || C++ || JAVA || PYTHON || 762. Prime Number of Set Bits in Binary Representation | c-c-java-python-762-prime-number-of-set-sndhe | Complexity\n- Time complexity:O(n)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity:O(1)\n Add your space complexity here, e.g. O(n) \n\n# Code | harithvarakesan | NORMAL | 2024-09-03T16:29:08.520327+00:00 | 2024-09-03T16:29:08.520350+00:00 | 463 | false | # Complexity\n- Time complexity:$$O(n)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:$$O(1)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```java []\nclass Solution {\n public int countPrimeSetBits(int left, int right) {\n int total=0;\n for(int i... | 1 | 0 | ['Math', 'Bit Manipulation', 'C', 'Python', 'C++', 'Java', 'Python3'] | 1 |
prime-number-of-set-bits-in-binary-representation | without built in function brute approach beats 50% | without-built-in-function-brute-approach-ky7e | Intuition\nto understand solution go first study how to find number of setbits .\n\n# Approach\nby doing bitwise and of a number n and (n-1) you can find number | ashmit76 | NORMAL | 2024-06-15T18:40:33.052785+00:00 | 2024-06-15T18:40:33.052817+00:00 | 51 | false | # Intuition\nto understand solution go first study how to find number of setbits .\n\n# Approach\nby doing bitwise and of a number n and (n-1) you can find number of set bits . \n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complex... | 1 | 0 | ['C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | C++ easy Solution using Seive of Eratosthenes | c-easy-solution-using-seive-of-eratosthe-vfmb | Intuition\n Describe your first thoughts on how to solve this problem. \n1. Use the sieve of Eratosthenes to precompute whether each number from 0 to 100 is pri | skill_improve | NORMAL | 2024-05-01T10:10:20.607694+00:00 | 2024-05-01T10:10:20.607722+00:00 | 79 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n1. Use the sieve of Eratosthenes to precompute whether each number from 0 to 100 is prime or not.\n1. For each number in the range [left, right], count the number of set bits (1s) using __builtin_popcount.\n1. Check if the count of set bi... | 1 | 0 | ['Math', 'Bit Manipulation', 'C++'] | 1 |
prime-number-of-set-bits-in-binary-representation | Easy java solution | easy-java-solution-by-vidojevica-27z1 | Intuition\nTo solve this problem, we need to count the number of integers with a prime number of set bits in their binary representation within the given range. | vidojevica | NORMAL | 2024-04-15T15:07:40.582088+00:00 | 2024-04-15T15:07:40.582125+00:00 | 411 | false | # Intuition\nTo solve this problem, we need to count the number of integers with a prime number of set bits in their binary representation within the given range.\n\n# Approach\n1.Iterate through each integer in the given range.\n2.Count the number of set bits in the binary representation of each integer.\n3.Check if t... | 1 | 0 | ['Java'] | 0 |
prime-number-of-set-bits-in-binary-representation | Simple java code 2 ms beats 97 % | simple-java-code-2-ms-beats-97-by-arobh-kjxe | \n# Complexity\n- \n\n# Code\n\nclass Solution {\n public int countPrimeSetBits(int left, int right) {\n final int[] arr = new int[20]; \n arr[ | Arobh | NORMAL | 2024-01-16T03:20:44.290250+00:00 | 2024-01-16T03:20:44.290278+00:00 | 29 | false | \n# Complexity\n- \n\n# Code\n```\nclass Solution {\n public int countPrimeSetBits(int left, int right) {\n final int[] arr = new int[20]; \n arr[2] = 1; arr[3] = 1; arr[5] = 1; arr[7] = 1;... | 1 | 0 | ['Java'] | 0 |
prime-number-of-set-bits-in-binary-representation | prime-number-of-set-bits-in-binary-representation | prime-number-of-set-bits-in-binary-repre-c3im | Code\n\nclass Solution:\n def countPrimeSetBits(self, left: int, right: int) -> int:\n count = 0\n for i in range(left,right + 1):\n | _suraj__007 | NORMAL | 2023-11-29T14:44:16.761171+00:00 | 2023-11-29T14:44:16.761197+00:00 | 258 | false | # Code\n```\nclass Solution:\n def countPrimeSetBits(self, left: int, right: int) -> int:\n count = 0\n for i in range(left,right + 1):\n a = bin(i)[2:]\n t = a.count("1")\n l = []\n if t==1:\n pass\n else:\n for i in ... | 1 | 0 | ['Python3'] | 0 |
prime-number-of-set-bits-in-binary-representation | [C++] || Simple and Easy to Understand Solution || Clean Code | c-simple-and-easy-to-understand-solution-nnxb | \n\n# Code\n\nclass Solution {\npublic:\n\n bool isprime(int x){\n return (x == 2 || x == 3 || x == 5 || x == 7 ||\n x == 11 || x == 13 | C0derX | NORMAL | 2023-10-03T12:12:12.967471+00:00 | 2023-10-03T12:12:12.967499+00:00 | 6 | false | \n\n# Code\n```\nclass Solution {\npublic:\n\n bool isprime(int x){\n return (x == 2 || x == 3 || x == 5 || x == 7 ||\n x == 11 || x == 13 || x == 17 || x == 19);\n }\n int countSetBits(int n){\n int cnt=0;\n while(n){\n cnt++;\n n=n&(n-1);\n }\n... | 1 | 0 | ['Math', 'Bit Manipulation', 'C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | Solution with 3 for loop javascript | solution-with-3-for-loop-javascript-by-m-3cj0 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | MentalistTr | NORMAL | 2023-08-11T16:02:46.170691+00:00 | 2023-08-11T16:02:46.170716+00:00 | 12 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 0 | ['JavaScript'] | 0 |
prime-number-of-set-bits-in-binary-representation | C# solution | 70% time, 67.5% space | used set | c-solution-70-time-675-space-used-set-by-wv7y | Complexity\n- Time complexity: O(n)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity: O(log2(n))\n Add your space complexity here, e.g. O(n) \n | photon_einstein | NORMAL | 2023-05-27T02:06:53.545139+00:00 | 2023-05-27T02:06:53.545172+00:00 | 453 | false | # Complexity\n- Time complexity: O(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(log2(n))\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\npublic class Solution {\n public int CountPrimeSetBits(int left, int right) {\n int i, maxPrime = 32, step=1, n... | 1 | 0 | ['C#'] | 0 |
prime-number-of-set-bits-in-binary-representation | 762. Prime Number of Set Bits in Binary Representation | 762-prime-number-of-set-bits-in-binary-r-g7or | \nclass Solution {\npublic:\n bool isPrime(int n){\n bool flag=true;\n if(n==0 || n==1) return false;\n for(int i=2;i*i<=n;i++){\n | pspraneetsehra08 | NORMAL | 2023-05-23T14:10:24.883901+00:00 | 2023-05-23T14:10:24.883943+00:00 | 325 | false | ```\nclass Solution {\npublic:\n bool isPrime(int n){\n bool flag=true;\n if(n==0 || n==1) return false;\n for(int i=2;i*i<=n;i++){\n if(n%i==0){\n flag=false;\n break;\n }\n }\n return flag;\n }\n int countPrimeSetBits(i... | 1 | 0 | ['Bit Manipulation', 'C', 'C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | Prime Number of Set Bits in Binary Representation Solution in C++ | prime-number-of-set-bits-in-binary-repre-nh32 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | The_Kunal_Singh | NORMAL | 2023-02-18T05:31:21.428048+00:00 | 2023-02-18T05:31:21.428098+00:00 | 61 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nO(n^2)\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n... | 1 | 0 | ['C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | JavaScript | javascript-by-ruben_krbashyan-gfko | \n\nvar countPrimeSetBits = function (left, right) {\n // numbers not greater then 10^6 have max 20 set bits\n // primes to check 2, 3, 5, 7, 11, 13, 17, | ruben_krbashyan | NORMAL | 2023-01-28T23:50:56.551404+00:00 | 2023-01-28T23:50:56.551437+00:00 | 147 | false | \n```\nvar countPrimeSetBits = function (left, right) {\n // numbers not greater then 10^6 have max 20 set bits\n // primes to check 2, 3, 5, 7, 11, 13, 17, 19\n \n const primes = [2, 3, 5, 7, 11, 13, 17, 19];\n let count = 0;\n\n for (let i = left; i <= right; i++) {\n const setBitCount = [...... | 1 | 0 | ['JavaScript'] | 0 |
prime-number-of-set-bits-in-binary-representation | easy solution||c++ | easy-solutionc-by-himanshukla2003-jyk7 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- O(n^2 | himanshukla2003 | NORMAL | 2023-01-08T08:20:15.342482+00:00 | 2023-01-08T08:20:15.342522+00:00 | 473 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- O(n^2)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Cod... | 1 | 0 | ['C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | ✅ [Swift] Easy to understand | swift-easy-to-understand-by-lmvtsv-9e6d | \nclass Solution {\n func countPrimeSetBits(_ left: Int, _ right: Int) -> Int {\n\t var left = left\n\t var result = 0\n\t while left <= right {\n\t | lmvtsv | NORMAL | 2022-12-01T13:40:21.127972+00:00 | 2022-12-01T13:40:21.127994+00:00 | 66 | false | ```\nclass Solution {\n func countPrimeSetBits(_ left: Int, _ right: Int) -> Int {\n\t var left = left\n\t var result = 0\n\t while left <= right {\n\t\t result += isPrime(left.nonzeroBitCount) ? 1 : 0\n\t\t left += 1\n\t }\n\t return result\n }\n\n func isPrime(_ number: Int) -> Bool {\n\... | 1 | 0 | ['Swift'] | 0 |
prime-number-of-set-bits-in-binary-representation | Prime Number of Set Bits in Binary Representation || Solution | prime-number-of-set-bits-in-binary-repre-4w2z | \nclass Solution {\npublic:\n int countPrimeSetBits(int left, int right) {\n int count=0;\n for(int i=left;i<=right;++i)\n {\n | SAJAL_2526 | NORMAL | 2022-10-18T16:55:06.453170+00:00 | 2022-10-18T16:55:06.453274+00:00 | 151 | false | ```\nclass Solution {\npublic:\n int countPrimeSetBits(int left, int right) {\n int count=0;\n for(int i=left;i<=right;++i)\n {\n bitset<32> b(i);\n int x=b.count();\n int flag=0;\n if(x==1)\n continue;\n for(int j=2;j<=sqrt... | 1 | 0 | ['Bit Manipulation', 'C'] | 0 |
prime-number-of-set-bits-in-binary-representation | Prime Number of Set Bits in Binary Representation (Python) | prime-number-of-set-bits-in-binary-repre-fowy | I have this problem explained and solved on my channel , please check it out.\nhttps://youtube.com/playlist?list=PLxukZCav2iGzzFMWq-esWbEEZ0KJ17t9L\nalso please | abdullah956 | NORMAL | 2022-10-16T09:14:55.345364+00:00 | 2022-10-16T09:17:58.589545+00:00 | 1,131 | false | I have this problem explained and solved on my channel , please check it out.\nhttps://youtube.com/playlist?list=PLxukZCav2iGzzFMWq-esWbEEZ0KJ17t9L\nalso please, give your valueable feedback.\n```\nclass Solution:\n def countPrimeSetBits(self, left: int, right: int) -> int:\n def isPrime(n:int)->bool :\n ... | 1 | 0 | ['Python'] | 0 |
prime-number-of-set-bits-in-binary-representation | C++ | Setbit Count | Easy Code | c-setbit-count-easy-code-by-ankit4601-exur | Please Upvote :)\n\n\nclass Solution {\npublic:\n int countPrimeSetBits(int left, int right) {\n int res=0;\n for(int i=left;i<=right;i++)\n | ankit4601 | NORMAL | 2022-08-22T17:56:25.813261+00:00 | 2022-08-22T17:56:25.813295+00:00 | 485 | false | Please Upvote :)\n\n```\nclass Solution {\npublic:\n int countPrimeSetBits(int left, int right) {\n int res=0;\n for(int i=left;i<=right;i++)\n {\n if(check(bits(i)))\n res++;\n }\n return res;\n }\n int check(int n)\n {\n if(n<2)\n ... | 1 | 0 | ['Bit Manipulation', 'C', 'C++'] | 0 |
prime-number-of-set-bits-in-binary-representation | Almighty C++ | almighty-c-by-nitinkumar12577-fszm | \tint countSetBits(int n)\n\t\t{\n\t\t\tint count = 0;\n\t\t\twhile(n!=0)\n\t\t\t{\n\t\t\t\tn = n&(n-1);\n\t\t\t\tcount++;\n\t\t\t}\n\t\t\treturn count;\n\t\t}\ | nitinkumar12577 | NORMAL | 2022-08-06T09:50:53.022464+00:00 | 2022-08-06T09:51:19.564363+00:00 | 243 | false | \tint countSetBits(int n)\n\t\t{\n\t\t\tint count = 0;\n\t\t\twhile(n!=0)\n\t\t\t{\n\t\t\t\tn = n&(n-1);\n\t\t\t\tcount++;\n\t\t\t}\n\t\t\treturn count;\n\t\t}\n \n bool isPrime(int n)\n {\n if(n==2 || n==3 || n==5 || n==7 || n==11 || n==13 || n==17 || n==19 || n==23 || n==29)\n return true;\... | 1 | 0 | ['C'] | 0 |
prime-number-of-set-bits-in-binary-representation | C++ || 100% fast || 100% less memory usage | c-100-fast-100-less-memory-usage-by-van_-t1qq | \nclass Solution {\npublic:\n bool isPrimary(int n){\n if(n <= 1) return false;\n for(int i = 2; i<=n/2; i++){\n if(n%i == 0) return | van_astrea | NORMAL | 2022-07-31T11:18:19.873928+00:00 | 2022-07-31T11:18:19.873972+00:00 | 235 | false | ```\nclass Solution {\npublic:\n bool isPrimary(int n){\n if(n <= 1) return false;\n for(int i = 2; i<=n/2; i++){\n if(n%i == 0) return false;\n }\n return true;\n }\n \n int countBits(int n){\n int x = 0;\n while(n>0){\n n = n & (n-1);\n ... | 1 | 0 | ['C'] | 0 |
prime-number-of-set-bits-in-binary-representation | Python | Easy and Fast | python-easy-and-fast-by-aryonbe-k418 | ```\nimport math\nclass Solution:\n def countPrimeSetBits(self, left: int, right: int) -> int:\n primes = set()\n for i in range(2, 30):\n | aryonbe | NORMAL | 2022-07-11T05:53:08.205818+00:00 | 2022-07-11T05:53:08.205865+00:00 | 213 | false | ```\nimport math\nclass Solution:\n def countPrimeSetBits(self, left: int, right: int) -> int:\n primes = set()\n for i in range(2, 30):\n for p in primes:\n if i%p == 0: break\n else:\n primes.add(i)\n res = 0\n for i in range(left, rig... | 1 | 0 | ['Python'] | 0 |
prime-number-of-set-bits-in-binary-representation | A faster solution | O(4*log(r)*log(r)) | 0ms | Digit DP | C++ | a-faster-solution-o4logrlogr-0ms-digit-d-qktj | Wrote a digit dp solution out of boredom.\nPrecautionary advice for beginners : It is okay if you don\'t understand this solution right now. This code is optima | suraj__k | NORMAL | 2022-07-01T15:52:46.859957+00:00 | 2022-07-10T04:29:47.412334+00:00 | 185 | false | Wrote a digit dp solution out of boredom.\nPrecautionary advice for beginners : It is okay if you don\'t understand this solution right now. This code is optimal for higher constraints on R-L (like 1e18), where we can not traverse from L to R for optimal solution.\n\nConvert both left and right to their binary represen... | 1 | 0 | ['Dynamic Programming', 'Recursion', 'Memoization', 'C'] | 0 |
prime-number-of-set-bits-in-binary-representation | C++ solution with Brian Kernighan’s Algorithm | c-solution-with-brian-kernighans-algorit-gupy | \nclass Solution {\npublic:\n int countPrimeSetBits(int left, int right) \n {\n vector<bool> prime(20, false);\n prime[2] = prime[3] = prime | osmanay | NORMAL | 2022-06-19T16:47:58.715827+00:00 | 2022-06-19T16:47:58.715876+00:00 | 132 | false | ```\nclass Solution {\npublic:\n int countPrimeSetBits(int left, int right) \n {\n vector<bool> prime(20, false);\n prime[2] = prime[3] = prime[5] = prime[7] = prime[11] = prime[13] = prime[17] = prime[19] = true;\n \n int res = 0;\n \n for(int i=left; i<=right; i++)\n ... | 1 | 0 | [] | 1 |
prime-number-of-set-bits-in-binary-representation | java || simple solution || easy to understand | java-simple-solution-easy-to-understand-2vqhh | class Solution {\n boolean prime(int n)\n {\n int i,c=0;\n for(i=1;i<=n;i++)\n {\n if(n%i==0)c++;\n }\n if(c | solver-01 | NORMAL | 2022-05-22T10:50:43.263081+00:00 | 2022-05-22T10:50:43.263115+00:00 | 23 | false | class Solution {\n boolean prime(int n)\n {\n int i,c=0;\n for(i=1;i<=n;i++)\n {\n if(n%i==0)c++;\n }\n if(c==2){\n return true;\n }\n else{\n return false;\n }\n }\n public int countPrimeSetBits(int left, int right) {\... | 1 | 0 | [] | 0 |
prime-number-of-set-bits-in-binary-representation | C++ O((log N) ^ 2) Solution (0ms) | c-olog-n-2-solution-0ms-by-stingxp-n2bk | Main idea\n\nGiven a = 10101001, we can count the number of positive integers less than a with 5 bits set as follows:\n\n1. Count b\'s such that b = 0xxxxxxx an | stingxp | NORMAL | 2022-04-29T09:32:23.585149+00:00 | 2022-04-29T12:54:43.136427+00:00 | 70 | false | # Main idea\n\nGiven `a = 10101001`, we can count the number of positive integers less than `a` with 5 bits set as follows:\n\n1. Count `b`\'s such that `b = 0xxxxxxx` and there are 5 bits set in `x`\'s.\n\t- There are <img src="https://render.githubusercontent.com/render/math?math=7\\choose5"> such `b`\'s.\n1. Count `... | 1 | 0 | [] | 0 |
prime-number-of-set-bits-in-binary-representation | Easy || C++ || Kernighan's Algorithm || Explained | easy-c-kernighans-algorithm-explained-by-wfci | class Solution {\npublic:\n\t\n\t/\n\t\t=>Idea is to find the no of set bits of interget i which is in range [left,right] inclusive\n\t\t=>so to calculate no. o | its_Dark_ | NORMAL | 2022-04-15T09:34:11.476453+00:00 | 2022-04-15T09:52:07.332272+00:00 | 54 | false | class Solution {\npublic:\n\t\n\t*/\n\t\t=>Idea is to find the no of set bits of interget i which is in range [left,right] inclusive\n\t\t=>so to calculate no. of set bits \n\t\t\t\t=>we find the right most set bit everytime and subtrract that from the orgnal no. untill the orignal no. is greater than 0\n\t\t\t\t=>chec... | 1 | 0 | [] | 0 |
combinations | Short Iterative C++ Answer 8ms | short-iterative-c-answer-8ms-by-hengyi-xtma | class Solution {\n public:\n \tvector<vector<int>> combine(int n, int k) {\n \t\tvector<vector<int>> result;\n \t\tint i = 0;\n \t\tvector<int> p | hengyi | NORMAL | 2015-10-09T05:47:58+00:00 | 2018-10-26T05:21:48.708530+00:00 | 53,751 | false | class Solution {\n public:\n \tvector<vector<int>> combine(int n, int k) {\n \t\tvector<vector<int>> result;\n \t\tint i = 0;\n \t\tvector<int> p(k, 0);\n \t\twhile (i >= 0) {\n \t\t\tp[i]++;\n \t\t\tif (p[i] > n) --i;\n \t\t\telse if (i == k - 1) result.push_back(p);\n \t\t\telse {\n ... | 477 | 7 | [] | 52 |
combinations | Backtracking Solution Java | backtracking-solution-java-by-fabrizio3-8ntr | public static List<List<Integer>> combine(int n, int k) {\n \t\tList<List<Integer>> combs = new ArrayList<List<Integer>>();\n \t\tcombine(combs, new A | fabrizio3 | NORMAL | 2015-04-10T09:15:05+00:00 | 2018-10-26T09:09:57.632221+00:00 | 99,425 | false | public static List<List<Integer>> combine(int n, int k) {\n \t\tList<List<Integer>> combs = new ArrayList<List<Integer>>();\n \t\tcombine(combs, new ArrayList<Integer>(), 1, n, k);\n \t\treturn combs;\n \t}\n \tpublic static void combine(List<List<Integer>> combs, List<Integer> comb, int start, i... | 387 | 8 | ['Backtracking', 'Java'] | 71 |
combinations | 【Video】Simple Backtracking Solution | video-simple-backtracking-solution-by-ni-ug0h | Intuition\nUsing backtracking to create all possible combinations.\n\n---\n\n# Solution Video\n\nhttps://youtu.be/oDn_6n0ahkM\n\n## Subscribe to my channel from | niits | NORMAL | 2024-07-05T02:25:06.239282+00:00 | 2024-07-05T02:25:06.239315+00:00 | 17,047 | false | # Intuition\nUsing backtracking to create all possible combinations.\n\n---\n\n# Solution Video\n\nhttps://youtu.be/oDn_6n0ahkM\n\n## Subscribe to my channel from here\nhttp://www.youtube.com/channel/UC9RMNwYTL3SXCP6ShLWVFww?sub_confirmation=1\n\n---\n\n# Approach\nThis is based on Python. Other might be different a bi... | 318 | 0 | ['C++', 'Java', 'Python3', 'JavaScript'] | 1 |
combinations | Backtracking cheatsheet + simple solution | backtracking-cheatsheet-simple-solution-xa1a0 | Backtracking\nBacktracking is a general algorithm for finding all (or some) solutions to some computational problems which incrementally builds candidates to th | sahana__63 | NORMAL | 2020-09-13T04:34:27.664557+00:00 | 2020-09-13T08:09:12.922708+00:00 | 40,199 | false | ### Backtracking\nBacktracking is a general algorithm for finding all (or some) solutions to some computational problems which incrementally builds candidates to the solution and abandons a candidate ("backtracks") as soon as it determines that the candidate cannot lead to a valid solution. \n\nIt is due to this backtr... | 282 | 0 | ['Backtracking', 'Python', 'Python3'] | 14 |
combinations | 1-liner, 3-liner, 4-liner | 1-liner-3-liner-4-liner-by-stefanpochman-hp5q | Library - AC in 64 ms\n\nFirst the obvious solution - Python already provides this functionality and it's not forbidden, so let's take advantage of it.\n\n f | stefanpochmann | NORMAL | 2015-05-24T02:24:28+00:00 | 2018-09-08T13:29:54.894018+00:00 | 36,102 | false | **Library - AC in 64 ms**\n\nFirst the obvious solution - Python already provides this functionality and it's not forbidden, so let's take advantage of it.\n\n from itertools import combinations\n \n class Solution:\n def combine(self, n, k):\n return list(combinations(range(1, n+1), k))\n\n-... | 234 | 24 | ['Python'] | 43 |
combinations | Clear and simple explanation with intuition: 100% faster | clear-and-simple-explanation-with-intuit-fejs | Intuition: Since we are asked to calculate all the possible combinations , hence we have to use backtracking\n\nConcept: In every backtracking problem , there a | thisisakshat | NORMAL | 2021-04-04T08:12:20.505067+00:00 | 2021-04-04T10:10:25.809782+00:00 | 16,979 | false | **Intuition:** Since we are asked to calculate all the possible combinations , hence we have to use backtracking\n\n**Concept:** In every backtracking problem , there are two things to keep in mind , which we will explore here as well :\n* Base Case: Every problem of backtracking has some base case which tells us at w... | 186 | 0 | ['Backtracking', 'Recursion', 'C', 'C++'] | 14 |
combinations | A short recursive Java solution based on C(n,k)=C(n-1,k-1)+C(n-1,k) | a-short-recursive-java-solution-based-on-j0y8 | Basically, this solution follows the idea of the mathematical formula C(n,k)=C(n-1,k-1)+C(n-1,k).\n\nHere C(n,k) is divided into two situations. Situation one, | vision57 | NORMAL | 2015-04-22T14:30:33+00:00 | 2015-04-22T14:30:33+00:00 | 30,543 | false | Basically, this solution follows the idea of the mathematical formula C(n,k)=C(n-1,k-1)+C(n-1,k).\n\nHere C(n,k) is divided into two situations. Situation one, number n is selected, so we only need to select k-1 from n-1 next. Situation two, number n is not selected, and the rest job is selecting k from n-1.\n\n pub... | 136 | 5 | [] | 22 |
combinations | 3 ms Java Solution | 3-ms-java-solution-by-anshu2-a2fj | public class Solution {\n public List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> result = new ArrayList<List<Integer>>();\n | anshu2 | NORMAL | 2015-12-30T02:46:47+00:00 | 2018-10-24T10:53:05.383434+00:00 | 14,340 | false | public class Solution {\n public List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> result = new ArrayList<List<Integer>>();\n if (k > n || k < 0) {\n return result;\n }\n if (k == 0) {\n result.add(new ArrayList<Integer... | 135 | 2 | ['Java'] | 15 |
combinations | A template to those combination problems | a-template-to-those-combination-problems-4w10 | Template first.\nAll those combination problems share a common characteristic: either select the element at current position or not, and continue the same proce | zefengsong | NORMAL | 2017-07-29T09:27:46.846000+00:00 | 2017-07-29T09:27:46.846000+00:00 | 9,619 | false | **Template first.**\nAll those combination problems share a common characteristic: either select the element at current position or not, and continue the same process to the next position. Therefore, I summarized a simple template to those problems.\n```\nvector<vector<int>> main(...){\n vector<vector<int>>res; // ... | 127 | 1 | ['C++'] | 6 |
combinations | 🧩 Iterative & Backtracking [VIDEO] 100% Efficient Combinatorial Generation | iterative-backtracking-video-100-efficie-1n77 | Intuition\nGiven two integers n and k, the task is to generate all possible combinations of k numbers from the range [1, n]. The initial intuition to solve this | vanAmsen | NORMAL | 2023-08-01T00:29:29.083218+00:00 | 2023-08-01T03:00:46.966797+00:00 | 17,300 | false | # Intuition\nGiven two integers `n` and `k`, the task is to generate all possible combinations of `k` numbers from the range `[1, n]`. The initial intuition to solve this problem is to leverage the concept of combination generation, where we iteratively choose `k` numbers from `n` numbers without any repetition. Howeve... | 110 | 1 | ['C++', 'Java', 'Python3', 'JavaScript', 'C#'] | 8 |
combinations | Python easy to understand DFS solution | python-easy-to-understand-dfs-solution-b-8m90 | \nclass Solution(object):\n def combine(self, n, k):\n ret = []\n self.dfs(list(range(1, n+1)), k, [], ret)\n return ret\n \n def | oldcodingfarmer | NORMAL | 2015-07-18T13:37:37+00:00 | 2020-09-10T14:40:35.377731+00:00 | 20,492 | false | ```\nclass Solution(object):\n def combine(self, n, k):\n ret = []\n self.dfs(list(range(1, n+1)), k, [], ret)\n return ret\n \n def dfs(self, nums, k, path, ret):\n if len(path) == k:\n ret.append(path)\n return \n for i in range(len(nums)):\n ... | 107 | 3 | ['Backtracking', 'Python'] | 14 |
combinations | My shortest c++ solution,using dfs | my-shortest-c-solutionusing-dfs-by-nanga-7dud | my idea is using backtracking ,every time I push a number into vector,then I push a bigger one into it;\nthen i pop the latest one,and push a another bigger on | nangao | NORMAL | 2014-10-10T05:48:27+00:00 | 2018-10-08T20:47:58.421472+00:00 | 24,619 | false | my idea is using backtracking ,every time I push a number into vector,then I push a bigger one into it;\nthen i pop the latest one,and push a another bigger one...\nand if I has push k number into vector,I push this into result;\n\n**this solution take 24 ms.**\n\n\n\n class Solution {\n public:\n vector<... | 99 | 2 | ['Depth-First Search'] | 16 |
combinations | General Backtracking questions solutions in Python for reference : | general-backtracking-questions-solutions-0mur | I have taken solutions of @caikehe from frequently asked backtracking questions which I found really helpful and had copied for my reference. I thought this pos | coders-block | NORMAL | 2019-11-15T06:08:58.797774+00:00 | 2019-11-15T06:30:47.768802+00:00 | 6,863 | false | I have taken solutions of @caikehe from frequently asked backtracking questions which I found really helpful and had copied for my reference. I thought this post will be helpful for everybody as in an interview I think these basic solutions can come in handy. Please add any more questions in comments that you think mig... | 70 | 1 | ['Backtracking', 'Python', 'Python3'] | 4 |
combinations | ✅☑️ Best C++ Solution Ever || Easy Solution || Backtracking || One Stop Solution. | best-c-solution-ever-easy-solution-backt-yqfp | Intuition\n Describe your first thoughts on how to solve this problem. \nWe can solve this problem using Array + Backtracking.\n\n# Approach\n Describe your app | its_vishal_7575 | NORMAL | 2023-02-21T11:40:02.150041+00:00 | 2023-02-21T11:40:02.150090+00:00 | 7,298 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nWe can solve this problem using Array + Backtracking.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nWe can easily understand the approach by seeing the code which is easy to understand with comments.\n\n# Complex... | 61 | 1 | ['Array', 'Backtracking', 'C++'] | 3 |
combinations | AC Python backtracking iterative solution 60 ms | ac-python-backtracking-iterative-solutio-nedo | def combine(self, n, k):\n ans = []\n stack = []\n x = 1\n while True:\n l = len(stack)\n if l == k:\n | dietpepsi | NORMAL | 2015-10-01T22:04:08+00:00 | 2018-10-04T03:03:19.081884+00:00 | 19,310 | false | def combine(self, n, k):\n ans = []\n stack = []\n x = 1\n while True:\n l = len(stack)\n if l == k:\n ans.append(stack[:])\n if l == k or x > n - k + l + 1:\n if not stack:\n return ans\n x ... | 61 | 1 | [] | 27 |
combinations | 2 Methods || Backtracking && Recursion || Video || C++ || Java || Python | 2-methods-backtracking-recursion-video-c-vcr5 | Intuition\n Describe your first thoughts on how to solve this problem. \nfind recursively by take not take.\n\nFor detailed explanation you can refer to my yout | shivam-727 | NORMAL | 2023-08-01T00:21:01.544453+00:00 | 2023-08-16T11:14:22.620128+00:00 | 15,292 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nfind recursively by take not take.\n\nFor detailed explanation you can refer to my youtube channel (hindi Language)\nhttps://youtu.be/QHaj0oRoYCI\n or link in my profile.Here,you can find any solution in playlists monthwise from june 2023... | 52 | 3 | ['Backtracking', 'Recursion', 'Python', 'C++', 'Java'] | 6 |
combinations | [Python] 2 solutions - Bitmasking, Backtracking - Clean & Concise | python-2-solutions-bitmasking-backtracki-r5pf | \u2714\uFE0F Solution 1: Bitmasking\npython\nclass Solution:\n def combine(self, n: int, k: int) -> List[List[int]]:\n \n def countBit1s(num, n | hiepit | NORMAL | 2021-09-11T02:47:35.178671+00:00 | 2024-04-12T21:47:20.480032+00:00 | 2,105 | false | **\u2714\uFE0F Solution 1: Bitmasking**\n```python\nclass Solution:\n def combine(self, n: int, k: int) -> List[List[int]]:\n \n def countBit1s(num, n):\n bits = 0\n for i in range(n):\n if (num >> i) & 1:\n bits += 1\n return bits\n ... | 41 | 0 | ['Backtracking', 'Bitmask'] | 2 |
combinations | Fast & simple python code . recursive | fast-simple-python-code-recursive-by-bol-8nns | def combine(self, n, k):\n if k==1:\n return [[i] for i in range(1,n+1)]\n elif k==n:\n return [[i for i in range(1,n+1)]]\n | boler1132 | NORMAL | 2015-05-20T14:44:47+00:00 | 2015-05-20T14:44:47+00:00 | 6,116 | false | def combine(self, n, k):\n if k==1:\n return [[i] for i in range(1,n+1)]\n elif k==n:\n return [[i for i in range(1,n+1)]]\n else:\n rs=[]\n rs+=self.combine(n-1,k)\n part=self.combine(n-1,k-1)\n for ls in part:\n ... | 35 | 1 | [] | 1 |
combinations | Two Approach, Recursive & Iterative, [C++] | two-approach-recursive-iterative-c-by-ak-qwhq | Implementation\n\n\n1st Approach\nRecursive Solution, Backtracking\n\nclass Solution {\npublic:\n void findCombination(vector<vector<int>> &res, vector<int> | akashsahuji | NORMAL | 2021-11-19T07:13:45.334867+00:00 | 2021-11-19T07:13:45.334912+00:00 | 2,913 | false | Implementation\n\n\n**1st Approach\nRecursive Solution, Backtracking**\n```\nclass Solution {\npublic:\n void findCombination(vector<vector<int>> &res, vector<int> temp, int index, int n, int k){\n if(temp.size() == k){\n res.push_back(temp);\n return;\n }\n for(int itr = i... | 30 | 0 | ['Backtracking', 'Depth-First Search', 'Recursion', 'C', 'Combinatorics', 'Iterator'] | 6 |
combinations | DP for the problem | dp-for-the-problem-by-left_peter-1js1 | I didn't see any DP solution for this problem, so I share mine:\nThe idea is simple, if the combination k out of n (select k elements from [1,n]) is combine(k, | left_peter | NORMAL | 2014-10-10T02:45:44+00:00 | 2014-10-10T02:45:44+00:00 | 9,422 | false | I didn't see any DP solution for this problem, so I share mine:\nThe idea is simple, if the combination k out of n (select k elements from [1,n]) is combine(k, n).\n\nLet's consider how can we get combine(k, n) by adding the last element n to something we already have (combine(k - 1, n - 1) and combine(k, n - 1)). Actu... | 28 | 0 | [] | 4 |
combinations | Python/JS/Go by DFS + backtracking [w/ Hint] 有中文解說影片 | pythonjsgo-by-dfs-backtracking-w-hint-yo-i8fp | \u4E2D\u6587\u8A73\u89E3 \u89E3\u8AAA\u5F71\u7247\nTutorial video in Chinese\n\nHint & recall:\n\nDFS template with backtracking\n\n\ndef dfs( parameter ):\n\n\ | brianchiang_tw | NORMAL | 2020-08-16T03:26:17.783883+00:00 | 2024-02-15T15:26:53.323529+00:00 | 4,485 | false | [\u4E2D\u6587\u8A73\u89E3 \u89E3\u8AAA\u5F71\u7247\nTutorial video in Chinese](https://www.youtube.com/watch?v=ITwWVCfLgug&t=468s )\n\nHint & recall:\n\n**DFS template** with **backtracking**\n\n```\ndef dfs( parameter ):\n\n\tif stop condtion or base case:\n\t\t# base case:\n\t\tupdate result\n\t return\n\t\n\telse... | 25 | 0 | ['Math', 'Backtracking', 'Depth-First Search', 'Breadth-First Search', 'Queue', 'Python', 'Go', 'Python3', 'JavaScript'] | 2 |
combinations | Iterative Java solution | iterative-java-solution-by-shpolsky-f2tm | Hi guys!\n\nThe idea is to iteratively generate combinations for all lengths from 1 to k. We start with a list of all numbers <= n as combinations for k == 1. W | shpolsky | NORMAL | 2015-02-07T13:07:12+00:00 | 2018-09-13T17:54:37.745179+00:00 | 9,161 | false | Hi guys!\n\nThe idea is to iteratively generate combinations for all lengths from 1 to k. We start with a list of all numbers <= n as combinations for k == 1. When we have all combinations of length k-1, we can get the new ones for a length k with trying to add to each one all elements that are <= n and greater than th... | 25 | 0 | ['Java'] | 4 |
combinations | Straight - forward Approach || Easiest Explaination || Java Code | straight-forward-approach-easiest-explai-ulbw | Here we have used Backtracking (TAKE & DON\'T TAKE Concept) to achieve the Possible Combinations. \n\nLet us understand the Methdology -\n1. The recursive funct | itssme | NORMAL | 2022-07-27T08:29:02.330098+00:00 | 2022-07-27T08:29:02.330141+00:00 | 1,719 | false | Here we have used Backtracking ***(TAKE & DON\'T TAKE Concept)*** to achieve the Possible Combinations. \n\nLet us understand the Methdology -\n**1.** The recursive function must have a Base (End) condition, right? So in our case what will be the base condition?\n**2.** Inside the recursive function **(solveitforMe)**,... | 24 | 0 | ['Backtracking', 'Recursion', 'Java'] | 3 |
combinations | Python3 solution with detailed explanation | python3-solution-with-detailed-explanati-0zv6 | Combination questions can be solved with dfs most of the time. I\'m following caikehe\'s approach. Also, if you want to fully understand this concept and backtr | peyman_np | NORMAL | 2020-07-11T00:00:22.799896+00:00 | 2020-08-24T22:17:01.014863+00:00 | 4,047 | false | Combination questions can be solved with `dfs` most of the time. I\'m following [caikehe](https://leetcode.com/problems/combinations/discuss/26990/Easy-to-understand-Python-solution-with-comments.)\'s approach. Also, if you want to fully understand this concept and [backtracking](https://www.***.org/backtracking-introd... | 24 | 0 | ['Depth-First Search', 'Python', 'Python3'] | 2 |
combinations | Backtracking | Easy to Understand | Faster | Simple | JavaScript Submission | backtracking-easy-to-understand-faster-s-e5hh | Please do upvote, it motivates me to write more such post\uD83D\uDE03\n\n\nvar combine = function(n, k) {\n let out = comb(k, n);\n // console.log(out);\n | mrmagician | NORMAL | 2020-01-09T09:11:12.578891+00:00 | 2020-01-09T09:11:12.578939+00:00 | 2,787 | false | **Please do upvote, it motivates me to write more such post\uD83D\uDE03**\n\n```\nvar combine = function(n, k) {\n let out = comb(k, n);\n // console.log(out);\n return out;\n};\n\n\nfunction comb(max, n, out=[], curr = [], index = 1){\n if(curr.length===max){\n out.push(curr);\n return [];\n ... | 23 | 6 | ['Backtracking', 'JavaScript'] | 0 |
combinations | ✔️Python||C||C++🔥99%✅Backtrack with graph explained || Beginner-friendly ^_^ | pythoncc99backtrack-with-graph-explained-1is6 | Intuition\nThis is a backtracking problem.\nWe made a recursion function, and get all combinations by take or not take specific number.\n\n# Approach\n## variab | luluboy168 | NORMAL | 2023-08-01T07:58:35.182571+00:00 | 2023-08-01T08:00:55.874846+00:00 | 3,283 | false | # Intuition\nThis is a backtracking problem.\nWe made a recursion function, and get all combinations by take or not take specific number.\n\n# Approach\n## variables\n`nums` is the current combination.\n`pos` is the current position in `nums`\n`cur` is the current number\n\nIn the function `backtrack`:\nIf `pos == k`, ... | 19 | 2 | ['Backtracking', 'C', 'Python', 'C++', 'Python3'] | 4 |
combinations | C++ concise recursive solution C(n,k) ->C(n-1,k-1) / 8ms | c-concise-recursive-solution-cnk-cn-1k-1-lheb | class Solution {\n public:\n vector<vector<int>> combine(int n, int k) {\n vector<vector<int>> ans;\n vector<int> temp;\n | susandebug | NORMAL | 2015-08-26T13:30:23+00:00 | 2015-08-26T13:30:23+00:00 | 5,061 | false | class Solution {\n public:\n vector<vector<int>> combine(int n, int k) {\n vector<vector<int>> ans;\n vector<int> temp;\n combine(1,n,k,ans,temp); //call fuction to get combination of k numbers which range is 1-n\n return ans;\n }\n private:\n ... | 19 | 0 | ['Recursion'] | 5 |
combinations | C++ || Bits approach || Day 1 | c-bits-approach-day-1-by-chiikuu-sy2n | Code\n\nclass Solution {\npublic:\n vector<vector<int>> combine(int n, int k) {\n vector<vector<int>>ans;\n for(int i=0;i<(1<<n) ;i++){\n | CHIIKUU | NORMAL | 2023-08-01T05:57:57.406633+00:00 | 2023-08-01T09:00:02.991071+00:00 | 1,125 | false | # Code\n```\nclass Solution {\npublic:\n vector<vector<int>> combine(int n, int k) {\n vector<vector<int>>ans;\n for(int i=0;i<(1<<n) ;i++){\n vector<int>v;\n int f = __builtin_popcountll(i);\n if(f!=k)continue;\n for(int j=0;j<n;j++){\n if((1<... | 18 | 1 | ['Bit Manipulation', 'Bitmask', 'C++'] | 1 |
combinations | ✅Recursive and Iterative solution using C++ with explanations | recursive-and-iterative-solution-using-c-vzgc | If you\u2019re interested in coding you can join my Discord Server, link in the comment section. Also if you find any mistakes please let me know. Thank you!\u2 | dhruba-datta | NORMAL | 2022-04-11T13:18:40.443224+00:00 | 2022-04-11T13:18:40.443264+00:00 | 1,617 | false | > **If you\u2019re interested in coding you can join my Discord Server, link in the comment section. Also if you find any mistakes please let me know. Thank you!\u2764\uFE0F**\n> \n\n---\n\n\n## Explanation:\n\n### Solution 01\n\n- Using ***Recursive & Backtracking.***\n- As we have to take elements from 1 to n, first ... | 18 | 0 | ['Backtracking', 'Recursion', 'C', 'C++'] | 1 |
combinations | [Python] [4 Approaches] Explained + Visualized | python-4-approaches-explained-visualized-cc54 | -------------------------------------------------------\n[1] Sub-optimal Iterative: TLE : 23 / 27 test cases passed.\n------------------------------------------ | Hieroglyphs | NORMAL | 2021-08-17T13:39:54.454884+00:00 | 2021-08-17T21:15:55.052079+00:00 | 1,392 | false | -------------------------------------------------------\n[1] Sub-optimal Iterative: TLE : 23 / 27 test cases passed.\n-------------------------------------------------------\n-------------------------------------------------------\n- Generate all nodes/permutations (n!)\n- Check if the same combo seen before by sorting... | 17 | 0 | ['Depth-First Search', 'Recursion', 'Iterator', 'Python'] | 1 |
combinations | 🚀⚡WITHOUT BACKTRACKING✅ || [C++/Java/Py3/JS]🍨 || EASY n CLEAN Explanation 💖✅ || BEATS💯⚡ | without-backtracking-cjavapy3js-easy-n-c-nvw7 | ApproachFunction: combine(n, k)
Initialize result as an empty list to store all valid combinations.
Create a curr list of size k (preallocated) to store the cur | Fawz-Haaroon | NORMAL | 2025-02-08T18:17:01.953959+00:00 | 2025-02-10T12:48:55.292546+00:00 | 1,911 | false |
# Approach
### **Function: `combine(n, k)`**
1. Initialize `result` as an empty list to store all valid combinations.
2. Create a `curr` list of size `k` (preallocated) to store the current combination.
3. Call the recursive `dfs(start, depth, n, k, curr, result)` function with:
- `start = 1` (begin with the first ... | 16 | 2 | ['Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 0 |
combinations | 🔥 Easy Backtracking for Generating Combinations | easy-backtracking-for-generating-combina-ymoh | Intuition\nIn this problem, we\'re asked to generate all possible combinations of \nk numbers out of n. My initial instinct was to use a recursive strategy, par | phistellar | NORMAL | 2023-08-01T01:48:33.832492+00:00 | 2023-08-01T02:24:33.805419+00:00 | 2,372 | false | # Intuition\nIn this problem, we\'re asked to generate all possible combinations of \nk numbers out of n. My initial instinct was to use a recursive strategy, particularly the backtracking approach. Backtracking is a powerful method that systematically explores all potential combinations, distinguishing the ones that m... | 15 | 0 | ['C++', 'Java', 'Python3', 'JavaScript', 'C#'] | 1 |
combinations | Java | TC:O(K*C(N,K)) | SC:O(K) | Optimized Iterative & Backtracking solutions | java-tcokcnk-scok-optimized-iterative-ba-5dvo | Backtracking (Recursive Solution)\n\n\n/**\n * Backtracking (Recursive Solution)\n *\n * Time complexity = InternalNodes in the RecursionTree + K * LeafNode | NarutoBaryonMode | NORMAL | 2021-10-30T21:45:59.149100+00:00 | 2021-10-30T21:47:57.528894+00:00 | 931 | false | **Backtracking (Recursive Solution)**\n\n```\n/**\n * Backtracking (Recursive Solution)\n *\n * Time complexity = InternalNodes in the RecursionTree + K * LeafNodes in RecursionTree\n * = (C(N,0) + C(N,1) + ... + C(N,K-1)) + K * C(N,K)\n *\n * Space Complexity = O(K) -> Depth of Recursion tree +... | 15 | 0 | ['Backtracking', 'Iterator', 'Java'] | 2 |
combinations | Perhaps the simplest solution using recursion(backtracing). | perhaps-the-simplest-solution-using-recu-vz5h | The idea is that C(n,k) = C(n-1, k-1) U n + C(n-1,k), do you get this?\n\n class Solution {\n public:\n vector > combine(int n, int k) {\n | ever4kenny | NORMAL | 2014-11-12T07:36:47+00:00 | 2014-11-12T07:36:47+00:00 | 6,989 | false | The idea is that C(n,k) = C(n-1, k-1) U n + C(n-1,k), do you get this?\n\n class Solution {\n public:\n vector<vector<int> > combine(int n, int k) {\n \n vector<vector<int> > result;\n if (n < 1 || k <1 || k > n)\n {\n return result;\n }... | 14 | 0 | [] | 4 |
combinations | Simple Java Code with the best explanation | simple-java-code-with-the-best-explanati-yvgh | Java Solution with explanation\n\n\nclass Solution {\n public List<List<Integer>> combine(int n, int k) {\n\t//declaring new list of list for storing results | Anim3_sh | NORMAL | 2023-01-29T05:03:14.158341+00:00 | 2023-01-31T11:57:19.499720+00:00 | 2,036 | false | ***Java Solution with explanation***\n\n```\nclass Solution {\n public List<List<Integer>> combine(int n, int k) {\n\t//declaring new list of list for storing results\n List<List<Integer>> res = new ArrayList<>();\n\t\t//calling the helper function\n helper(n, k, 1, res, new ArrayList<>());\n r... | 13 | 0 | ['Backtracking', 'Java'] | 1 |
combinations | c++ simple solution || using dfs and backtracking | c-simple-solution-using-dfs-and-backtrac-g38u | \nclass Solution {\npublic:\n void solve(vector<vector<int>>& result,int n,int begin ,int k ,vector<int>& combination){\n if(combination.size()==k){\n | yash_pal2907 | NORMAL | 2021-01-31T16:43:19.241760+00:00 | 2021-01-31T16:43:19.241806+00:00 | 1,283 | false | ```\nclass Solution {\npublic:\n void solve(vector<vector<int>>& result,int n,int begin ,int k ,vector<int>& combination){\n if(combination.size()==k){\n result.push_back(combination);\n return;\n }\n for(int i=begin ; i<=n ;i++){\n combination.push_back(i);\n ... | 13 | 0 | ['Backtracking', 'Depth-First Search', 'C'] | 3 |
combinations | ✅ [C++ , Java , Python] Simple solution with explanation (Backtracking)✅ | c-java-python-simple-solution-with-expla-yacg | Intuition\nIt is pretty clear from the constraints that the solution of 2n could work. We could use a backtracking approch in which if we see that the going pat | upadhyayabhi0107 | NORMAL | 2023-08-01T03:11:41.659712+00:00 | 2023-08-01T03:13:37.821469+00:00 | 4,149 | false | # Intuition\nIt is pretty clear from the constraints that the solution of 2<sup>n</sup> could work. We could use a backtracking approch in which if we see that the going path doesn\'t leads towards answer we could backtrack.\n<table>\n<tr>\n<th>Input Parameters</th>\n<th>Required time Complexity</th>\n</tr>\n<tr>\n<td>... | 12 | 0 | ['Backtracking', 'C++', 'Java', 'Python3'] | 0 |
combinations | JAVA 0ms SOLUTION🔥🚀 || STEP BY STEP EXPLAINED😉😉 | java-0ms-solution-step-by-step-explained-68uz | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | abhiyadav05 | NORMAL | 2023-04-29T18:26:46.916577+00:00 | 2023-04-29T18:26:46.916619+00:00 | 1,757 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->O(n choose k)\n\n- Space complexity:\n<!-- Add your space complexity here, e.g... | 12 | 0 | ['Backtracking', 'Recursion', 'Java'] | 1 |
combinations | javascript(DFS) | javascriptdfs-by-yinchuhui88-m359 | \nvar combine = function(n, k) {\n let result = [];\n \n function dfs(current, start) {\n if(current.length == k) {\n result.push(cur | yinchuhui88 | NORMAL | 2018-10-10T06:06:05.315229+00:00 | 2018-10-10T06:06:05.315271+00:00 | 1,368 | false | ```\nvar combine = function(n, k) {\n let result = [];\n \n function dfs(current, start) {\n if(current.length == k) {\n result.push(current);\n return;\n }\n if(current.length > k) {\n return;\n }\n \n for(let i = start; i <= n; i++) {... | 12 | 0 | [] | 2 |
combinations | 2ms beats 90% Java solution, a small trick to end search early | 2ms-beats-90-java-solution-a-small-trick-l4hk | public List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> results = new ArrayList<>();\n dfs(1, n, k, new ArrayList<Integer>(), res | kkklll | NORMAL | 2016-06-07T17:22:00+00:00 | 2016-06-07T17:22:00+00:00 | 2,233 | false | public List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> results = new ArrayList<>();\n dfs(1, n, k, new ArrayList<Integer>(), results);\n return results;\n }\n \n private void dfs(int crt, int n, int level, List<Integer> comb, List<List<Integer>> results) {\n if... | 12 | 0 | [] | 5 |
combinations | ✅Simple C++ Backtracking Solution|90%✅ | simple-c-backtracking-solution90-by-xaho-7gf0 | Intuition\n Describe your first thoughts on how to solve this problem. \nSimply generate all the subsets but if size execeeds k then return . \n\n# Approach\n D | Xahoor72 | NORMAL | 2023-01-25T10:01:10.342081+00:00 | 2023-01-25T10:01:10.342127+00:00 | 2,660 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nSimply generate all the subsets but if size execeeds k then return . \n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nUse Backtracking like allother subset problems\n# Complexity\n- Time complexity:$$(2^n)$$\n<!-- ... | 11 | 0 | ['Backtracking', 'Depth-First Search', 'Recursion', 'C++'] | 2 |
combinations | ✔️ 100% Fastest Swift Solution | 100-fastest-swift-solution-by-sergeylesc-7tp3 | \nclass Solution {\n func combine(_ n: Int, _ k: Int) -> [[Int]] {\n var res: [[Int]] = []\n \n \n func backtrack(_ path: [Int], | sergeyleschev | NORMAL | 2022-04-06T05:46:41.373520+00:00 | 2022-04-06T05:46:41.373559+00:00 | 723 | false | ```\nclass Solution {\n func combine(_ n: Int, _ k: Int) -> [[Int]] {\n var res: [[Int]] = []\n \n \n func backtrack(_ path: [Int], _ max: Int) {\n if path.count == k {\n res.append(path)\n return\n \n }\n \n ... | 11 | 0 | ['Swift'] | 2 |
combinations | Python DFS: solution & visualization step by step | python-dfs-solution-visualization-step-b-py3w | Not the most optimal solution in terms of runtime, but for someone who is learning recursive solutions (such as myself) I hope the visualization is helpful!\n\n | sahn1998 | NORMAL | 2020-10-01T00:30:57.885927+00:00 | 2020-10-01T00:38:01.269723+00:00 | 727 | false | Not the most optimal solution in terms of runtime, but for someone who is learning recursive solutions (such as myself) I hope the visualization is helpful!\n```\nclass Solution(object):\n def combine(self, n, k):\n """\n :type n: int\n :type k: int\n :rtype: List[List[int]]\n """\... | 11 | 0 | ['Backtracking', 'Depth-First Search', 'Recursion', 'Python3'] | 0 |
combinations | ✅ 🔥 31 ms Runtime Beats 99.45% User🔥|| Code Idea ✅ || Algorithm & Solving Step ✅ || | 31-ms-runtime-beats-9945-user-code-idea-gw5yc | \n\n\u2705 IF YOU LIKE THIS SOLUTION, PLEASE UPVOTE AT THE END \u2705 :\n\n### Problem Intuition :\n\nGiven two integers n and k, we need to generate all combi | Letssoumen | NORMAL | 2024-12-02T03:34:34.391950+00:00 | 2024-12-02T03:34:34.391988+00:00 | 1,492 | false | \n\n\u2705 IF YOU LIKE THIS SOLUTION, PLEASE UPVOTE AT THE END \u2705 :\n\n### **Problem Intuition** :\n\nGiven two integers `n` and `k`, we need to generate all combinati... | 10 | 0 | ['Backtracking', 'C++', 'Java', 'Python3'] | 1 |
combinations | 2 Unique approaches (using String and without it) | 2-unique-approaches-using-string-and-wit-3484 | Note\n- The string method is very similar to the input-output recursion and backtracking method.\n- Comment down if you want an article on that; it is a useful | quagmire8 | NORMAL | 2024-03-23T07:31:03.349785+00:00 | 2024-03-23T09:41:41.225267+00:00 | 505 | false | # Note\n- The string method is very similar to the input-output recursion and backtracking method.\n- Comment down if you want an article on that; it is a useful method for these type of problems.\n- The non-string method follows a simple backtracking approach.\n\n# Intuition\nThe problem involves generating all combin... | 9 | 0 | ['C++'] | 2 |
combinations | C++ Math||DP||unordered_map, map, 4D array | c-mathdpunordered_map-map-4d-array-by-an-tim6 | Intuition\n Describe your first thoughts on how to solve this problem. \nHere I provide other idea from backtracking. I prefer to use DP. The backtracking solut | anwendeng | NORMAL | 2023-08-01T00:17:45.880748+00:00 | 2023-08-02T02:32:20.115402+00:00 | 982 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nHere I provide other idea from backtracking. I prefer to use DP. The backtracking solution can be used to solve the similar question.\n[46. Permutations\n](https://leetcode.com/problems/permutations/solutions/3850602/cpython-bitmask-backt... | 9 | 1 | ['Math', 'Dynamic Programming', 'C++'] | 0 |
combinations | Backtracking | Simple | Straightforward | backtracking-simple-straightforward-by-t-krjv | If you find this helpful, do upvote.\n\n\nvar combine = function(n, k) {\n let res = [];\n function backtrack(start = 1, path = []){\n if(path.leng | tusharsheth | NORMAL | 2021-12-10T05:01:05.238107+00:00 | 2021-12-10T05:01:05.238153+00:00 | 881 | false | If you find this helpful, do upvote.\n\n```\nvar combine = function(n, k) {\n let res = [];\n function backtrack(start = 1, path = []){\n if(path.length == k){\n res.push(Array.from(path));\n }else {\n for(let i=start; i<=n; i++){\n path.push(i);\n ... | 9 | 0 | ['Backtracking', 'JavaScript'] | 0 |
combinations | Javascript Straightforward Backtracking Solution | javascript-straightforward-backtracking-mrrt8 | \n/**\n * @param {number} n\n * @param {number} k\n * @return {number[][]}\n */\nvar combine = function (n, k) {\n if (n == 1 && k == 1) return [[1]];\n l | tokcao | NORMAL | 2020-06-24T20:43:08.169004+00:00 | 2020-06-24T20:43:08.169034+00:00 | 1,188 | false | ```\n/**\n * @param {number} n\n * @param {number} k\n * @return {number[][]}\n */\nvar combine = function (n, k) {\n if (n == 1 && k == 1) return [[1]];\n let out = [];\n const dfs = (currentSolution, startNumber, out) => {\n if (currentSolution.length == k) out.push(Array.from(currentSolution));\n ... | 9 | 0 | ['Backtracking', 'JavaScript'] | 2 |
combinations | Time complexity analysis of Backtracking Java | time-complexity-analysis-of-backtracking-ddul | Here is the code, classic dfs backtracing.\n\npublic List<List<Integer>> combine(int n, int k) {\n List<Integer> curr=new ArrayList<Integer>();\n | egg8egg | NORMAL | 2019-10-02T17:54:01.772139+00:00 | 2019-10-02T17:54:01.772195+00:00 | 1,340 | false | Here is the code, classic dfs backtracing.\n```\npublic List<List<Integer>> combine(int n, int k) {\n List<Integer> curr=new ArrayList<Integer>();\n List<List<Integer>> ans =new ArrayList<List<Integer>>();\n dfs(n,k,1,curr,ans);\n return ans;\n }\n \n private void dfs(int n, int k,i... | 9 | 0 | [] | 3 |
combinations | Recursive Javascript Solution | recursive-javascript-solution-by-gbaik-xkvp | \nfunction combinations(n, k) {\n let result = [];\n\n function traverse(arr, depth) {\n if (arr.length === k) {\n result.push(arr);\n return;\n | gbaik | NORMAL | 2017-12-06T23:44:38.242000+00:00 | 2017-12-06T23:44:38.242000+00:00 | 1,730 | false | ```\nfunction combinations(n, k) {\n let result = [];\n\n function traverse(arr, depth) {\n if (arr.length === k) {\n result.push(arr);\n return;\n }\n \n if (depth > n) { \n return;\n }\n\n traverse(arr, depth + 1); \n traverse(arr.concat(depth), depth + 1);\n }\n\n traver... | 9 | 0 | ['Recursion', 'JavaScript'] | 0 |
combinations | ONE LINER BY USING BUILTIN FUNCTIONS AND MANY BEATS THAN SIMPLE BACK TRACING SOLUTIONS | one-liner-by-using-builtin-functions-and-o5q1 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | ahsankhalid859 | NORMAL | 2023-08-07T01:43:26.457304+00:00 | 2023-08-07T01:43:26.457336+00:00 | 80 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 8 | 0 | ['Python3'] | 1 |
combinations | python dfs solution - TLE solved for the test case n=20, k=16 | python-dfs-solution-tle-solved-for-the-t-nws5 | \nclass Solution(object):\n def combine(self, n, k):\n """\n :type n: int\n :type k: int\n :rtype: List[List[int]]\n """\n | shuang10 | NORMAL | 2017-10-10T13:43:08.939000+00:00 | 2017-10-10T13:43:08.939000+00:00 | 976 | false | ```\nclass Solution(object):\n def combine(self, n, k):\n """\n :type n: int\n :type k: int\n :rtype: List[List[int]]\n """\n res = []\n if k==0 or n<1:\n return res\n \n self.dfs(n, k, [], res, 1)\n return res\n \n def dfs(se... | 8 | 0 | ['Depth-First Search', 'Python'] | 4 |
combinations | Easy to understand [C++/Java/python3] | easy-to-understand-cjavapython3-by-sriga-euye | Intuition\n Describe your first thoughts on how to solve this problem. \nThe problem requires finding all possible combinations of k numbers chosen from the ran | sriganesh777 | NORMAL | 2023-08-01T03:40:09.787453+00:00 | 2023-08-01T03:40:09.787477+00:00 | 180 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem requires finding all possible combinations of k numbers chosen from the range [1, n]. To solve this, we can use a backtracking approach. The idea is to start with an empty combination and keep adding numbers to it one by one u... | 7 | 0 | ['Backtracking', 'Recursion', 'C++', 'Java', 'Python3'] | 1 |
combinations | C++ || Recursion Backtracking | c-recursion-backtracking-by-abhay5349sin-ggj1 | Connect with me on LinkedIn: https://www.linkedin.com/in/abhay5349singh/\n\n\nclass Solution {\npublic:\n \n void solve(int n, int k, int num, vector<int> | abhay5349singh | NORMAL | 2023-08-01T01:49:06.656382+00:00 | 2023-08-01T01:49:06.656406+00:00 | 1,816 | false | **Connect with me on LinkedIn**: https://www.linkedin.com/in/abhay5349singh/\n\n```\nclass Solution {\npublic:\n \n void solve(int n, int k, int num, vector<int> &sub_ans, vector<vector<int>> &ans){\n if(k==0){\n ans.push_back(sub_ans);\n return;\n }\n if(num == n+1) ret... | 7 | 1 | ['Backtracking', 'Recursion', 'C++'] | 1 |
combinations | Python simple recursion - 76 ms, faster than 97.09% | python-simple-recursion-76-ms-faster-tha-vmj9 | nCk can be constructed through the result of two sub parts:\n1. (n-1)C(k)\n2. (n-1)C(k-1), with n appended to each result.\n\nThe base cases are when n==k and w | udhavsethi | NORMAL | 2021-11-15T22:09:05.467466+00:00 | 2021-11-15T22:09:05.467499+00:00 | 239 | false | *nCk* can be constructed through the result of two sub parts:\n1. *(n-1)C(k)*\n2. *(n-1)C(k-1)*, with *n* appended to each result.\n\nThe base cases are when *n==k* and when *k==1*\n\n```\nclass Solution:\n def combine(self, n: int, k: int) -> List[List[int]]:\n if n == k:\n return [[x for x in ran... | 7 | 0 | [] | 0 |
combinations | C++ | Backtracking recursion | c-backtracking-recursion-by-pratham7711-bgoa | \nclass Solution {\npublic:\n \n void helper(vector<vector<int>> &res , vector<int>& ans , int n , int left , int k)\n {\n if(k == 0)\n {\n | pratham7711 | NORMAL | 2021-11-03T22:10:17.641850+00:00 | 2021-11-03T22:10:17.641892+00:00 | 925 | false | ```\nclass Solution {\npublic:\n \n void helper(vector<vector<int>> &res , vector<int>& ans , int n , int left , int k)\n {\n if(k == 0)\n {\n res.push_back(ans);\n return ;\n }\n \n for(int i = left ; i <= n ; i++)\n {\n ans.push_back(i);\n ... | 7 | 0 | ['Recursion', 'C', 'C++'] | 1 |
combinations | [C++][Backtracking] - Simple and easy to understand solution | cbacktracking-simple-and-easy-to-underst-x1h2 | \nclass Solution {\npublic:\n void backtrack(int n,int k,vector<int> &curr,vector<vector<int> >&ans,int num){\n curr.push_back(num);\n if(curr. | morning_coder | NORMAL | 2020-12-05T13:34:56.053815+00:00 | 2020-12-05T13:34:56.053859+00:00 | 781 | false | ```\nclass Solution {\npublic:\n void backtrack(int n,int k,vector<int> &curr,vector<vector<int> >&ans,int num){\n curr.push_back(num);\n if(curr.size()==k){\n ans.push_back(curr);\n curr.pop_back();\n return;\n }\n for(int i=num+1;i<=n;i++){\n ... | 7 | 0 | ['Backtracking', 'C', 'C++'] | 1 |
combinations | .::Kotlin::. Backtracking | kotlin-backtracking-by-dzmtr-qce4 | \n\nclass Solution {\n fun combine(n: Int, k: Int): List<List<Int>> {\n val res = mutableSetOf<List<Int>>()\n \n fun backtrack(j: Int, c | dzmtr | NORMAL | 2023-08-01T07:28:36.712146+00:00 | 2023-08-01T07:28:36.712174+00:00 | 33 | false | \n```\nclass Solution {\n fun combine(n: Int, k: Int): List<List<Int>> {\n val res = mutableSetOf<List<Int>>()\n \n fun backtrack(j: Int, cur: List<Int>) {\n if (cur.size == k) { res += cur; return }\n for (num in j+1..n) backtrack(num, cur + num)\n }\n\n back... | 6 | 0 | ['Kotlin'] | 0 |
combinations | Python3 one-liner Solution | python3-one-liner-solution-by-motaharozz-xiol | \n\nclass Solution:\n def combine(self, n: int, k: int) -> List[List[int]]:\n return combinations(range(1,n+1),k)\n | Motaharozzaman1996 | NORMAL | 2023-08-01T03:12:51.694812+00:00 | 2023-08-01T03:12:51.694838+00:00 | 821 | false | \n```\nclass Solution:\n def combine(self, n: int, k: int) -> List[List[int]]:\n return combinations(range(1,n+1),k)\n``` | 6 | 0 | ['Python', 'Python3'] | 2 |
combinations | 2 approaches || easy || short | 2-approaches-easy-short-by-kdojha115-0n1t | \nApproach 1:\n\nSimple and fast\n\ncode:\n\nclass Solution\n{\npublic:\n\tvector<vector<int>> combine(int n, int k)\n\t{\n\t\tvector<vector<int>> result;\n\t\t | kdojha115 | NORMAL | 2022-10-31T18:47:39.034335+00:00 | 2022-10-31T18:47:39.034376+00:00 | 1,499 | false | \n```Approach 1:```\n\n**Simple and fast**\n\ncode:\n```\nclass Solution\n{\npublic:\n\tvector<vector<int>> combine(int n, int k)\n\t{\n\t\tvector<vector<int>> result;\n\t\tint i = 0;\n\t\tvector<int> p(k, 0);\n\t\twhile (i >= 0)\n\t\t{\n\t\t\tp[i]++;\n\t\t\tif (p[i] > n)\n\t\t\t\t--i;\n\t\t\telse if (i == k - 1)\n\t\t... | 6 | 0 | ['Recursion'] | 0 |
combinations | Java solution using backtracking | java-solution-using-backtracking-by-sava-k5n8 | \npublic List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> res = new ArrayList();\n combinations(res, new ArrayList<Integer>(), 1, | savan07 | NORMAL | 2022-06-25T08:17:29.106179+00:00 | 2022-06-25T08:17:29.106223+00:00 | 587 | false | ```\npublic List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> res = new ArrayList();\n combinations(res, new ArrayList<Integer>(), 1, n, k);\n return res;\n }\n private void combinations(List<List<Integer>> res, List<Integer> temp, int start, int end, int k){\n if(k == ... | 6 | 0 | ['Backtracking', 'Java'] | 1 |
combinations | [JS] Simple Backtracking Solution | js-simple-backtracking-solution-by-js11-xrqj | ```\nvar combine = function(n, k) {\n const backtrack = (first = 1, arr = []) => {\n if (arr.length == k) {\n output.push([...arr])\n | js11 | NORMAL | 2021-11-26T18:07:27.008187+00:00 | 2021-11-26T18:07:27.008219+00:00 | 723 | false | ```\nvar combine = function(n, k) {\n const backtrack = (first = 1, arr = []) => {\n if (arr.length == k) {\n output.push([...arr])\n }\n if (arr.length < k)\n for (let i = first; i <= n; i++) {\n arr.push(i);\n backtrack(i + 1, arr);\n ... | 6 | 0 | ['Backtracking', 'JavaScript'] | 0 |
combinations | c# solution | c-solution-by-csharp-gqon | ```\npublic class Solution {\n private IList> res = new List>();\n \n public IList> Combine(int n, int k) {\n Helper(n, k, 1, new List());\n | csharp | NORMAL | 2020-10-31T10:54:51.167626+00:00 | 2020-10-31T10:54:51.167655+00:00 | 632 | false | ```\npublic class Solution {\n private IList<IList<int>> res = new List<IList<int>>();\n \n public IList<IList<int>> Combine(int n, int k) {\n Helper(n, k, 1, new List<int>());\n \n return res;\n }\n \n private void Helper(int n, int k, int i, List<int> l)\n {\n if (l.Co... | 6 | 0 | [] | 1 |
combinations | JavaScript | javascript-by-doronin-e5ah | \nfunction findCombination(n, k, position, seq, mutRes) {\n if (k === 0) { mutRes.push([...seq]); return; } \n if (position > n) return;\n \n seq.pu | doronin | NORMAL | 2020-07-15T20:23:08.702577+00:00 | 2020-07-15T20:23:08.702605+00:00 | 733 | false | ```\nfunction findCombination(n, k, position, seq, mutRes) {\n if (k === 0) { mutRes.push([...seq]); return; } \n if (position > n) return;\n \n seq.push(position);\n findCombination(n, k - 1, position + 1, seq, mutRes);\n seq.pop();\n \n findCombination(n, k, position + 1, seq, mutRes);\n}\n\n\... | 6 | 1 | [] | 2 |
combinations | backtracking python | backtracking-python-by-guopeip0413-eq8p | Hope it helps:\n```\nclass Solution(object):\n def combine(self, n, k):\n """\n :type n: int\n :type k: int\n :rtype: List[List[i | guopeip0413 | NORMAL | 2018-05-15T04:05:29.816184+00:00 | 2018-05-15T04:05:29.816184+00:00 | 721 | false | Hope it helps:\n```\nclass Solution(object):\n def combine(self, n, k):\n """\n :type n: int\n :type k: int\n :rtype: List[List[int]]\n """\n if k>n:\n return []\n ans=[]\n self.helper(n,1,k,ans,[])\n return ans\n \n def helper(self,n,st... | 6 | 1 | [] | 3 |
combinations | DFS recursive Java Solution | dfs-recursive-java-solution-by-siyang3-hb41 | A DFS idea with back-trace. Very straightforward.\n\n public class Solution {\n public List> combine(int n, int k) {\n List> rslt = new Arr | siyang3 | NORMAL | 2015-04-01T16:54:46+00:00 | 2015-04-01T16:54:46+00:00 | 1,921 | false | A DFS idea with back-trace. Very straightforward.\n\n public class Solution {\n public List<List<Integer>> combine(int n, int k) {\n List<List<Integer>> rslt = new ArrayList<List<Integer>>();\n dfs(new Stack<Integer>(), 1, n, k, rslt);\n return rslt;\n }\n \n ... | 6 | 0 | ['Depth-First Search', 'Java'] | 0 |
combinations | Easy Python recursive solution 64ms | easy-python-recursive-solution-64ms-by-m-g6zm | def combinations(n, k, start=1):\n if k == 1:\n return [[x,] for x in xrange(start, n+1)]\n \n Result = []\n for FirstNum in | metrowind | NORMAL | 2015-12-09T22:36:27+00:00 | 2018-09-16T20:54:45.662124+00:00 | 1,686 | false | def combinations(n, k, start=1):\n if k == 1:\n return [[x,] for x in xrange(start, n+1)]\n \n Result = []\n for FirstNum in xrange(start, n - k + 2):\n for Comb in combinations(n, k-1, FirstNum + 1):\n Result.append([FirstNum,] + Comb)\n return R... | 6 | 0 | ['Python'] | 2 |
combinations | Combinations v.s Combination Sum III (Java) | combinations-vs-combination-sum-iii-java-jhxn | These two questions are very similar, so here I am going to put these two questions into comparisons.\n\nIn Combinations, given k is the length of the sub-list, | issac3 | NORMAL | 2016-05-23T17:19:11+00:00 | 2016-05-23T17:19:11+00:00 | 760 | false | These two questions are very similar, so here I am going to put these two questions into comparisons.\n\nIn ***Combinations***, given `k` is the length of the sub-list, `n` is the last number of combination, return all possible combinations of k numbers out of 1 ... n.\n\nIn ***Combination Sum III***, `k` is the lengt... | 6 | 0 | ['Backtracking', 'Java'] | 1 |
combinations | Efficient and Simple Solution for Combinations | efficient-and-simple-solution-for-combin-ry6d | Problem UnderstandingThe task is to generate all possible combinations of size k from the numbers 1 to n. Each combination should be unique, and the order of th | princesharma21102004 | NORMAL | 2025-02-01T21:40:24.022611+00:00 | 2025-02-03T17:46:25.086479+00:00 | 450 | false | # Problem Understanding
The task is to generate all possible combinations of size k from the numbers 1 to n. Each combination should be unique, and the order of the numbers in the combination doesn't matter.
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
To generate all possible combin... | 5 | 1 | ['Backtracking', 'C++'] | 0 |
combinations | Combinations [C++] | combinations-c-by-moveeeax-xfhn | IntuitionThe problem requires generating all combinations of k numbers from the range [1, n]. This is a classic combinatorial problem that can be efficiently so | moveeeax | NORMAL | 2025-01-21T08:23:18.097492+00:00 | 2025-01-21T08:23:18.097492+00:00 | 386 | false | # Intuition
The problem requires generating all combinations of `k` numbers from the range `[1, n]`. This is a classic combinatorial problem that can be efficiently solved using backtracking.
# Approach
1. Use a backtracking algorithm to explore all potential combinations:
- Start from the first number and attempt ... | 5 | 0 | ['C++'] | 0 |
combinations | ✅BEST SOLUTION | BACKTRACKING | JAVA | EXPLAINED🔥🔥🔥 | best-solution-backtracking-java-explaine-7wl2 | Approach:\nEmploys a backtracking approach to explore all possible combinations.\nThe backtrack function recursively constructs combinations:\nBase case: If the | AdnanNShaikh | NORMAL | 2024-09-09T16:06:26.062891+00:00 | 2024-09-09T16:06:26.062926+00:00 | 748 | false | **Approach:**\nEmploys a backtracking approach to explore all possible combinations.\nThe backtrack function recursively constructs combinations:\nBase case: If the current combination\'s size equals k, add it to the result list.\nFor each number from start to n:\nAdd the number to the current combination.\nRecursively... | 5 | 0 | ['Java'] | 1 |
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