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find-the-maximum-factor-score-of-array | Java Solution | java-solution-by-dheeraj_2602-cfad | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Dheeraj_2602 | NORMAL | 2024-10-27T17:18:41.901359+00:00 | 2024-10-27T17:18:41.901389+00:00 | 13 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\nO(n^2)\n- Space complexity:\nO(1)\n# Code\n```java []\nclass Solution {\n public long maxScore(int[] nums) {\n if (nums.l... | 0 | 0 | ['Java'] | 0 |
find-the-maximum-factor-score-of-array | 100x speed-up of prevailing "7ms" (fastest) solution | 100x-speed-up-of-prevailing-7ms-fastest-yf53e | Intuition\n\nReuse the prime_factors_t c++ class which I attempted (and developed) in another problem\n\nGCD and LCM calculations are as simple as bitwise AND a | jrmwng | NORMAL | 2024-10-27T16:43:09.521416+00:00 | 2024-10-27T16:43:09.521450+00:00 | 13 | false | # Intuition\n\nReuse the `prime_factors_t` c++ class which I attempted (and developed) in another problem\n\nGCD and LCM calculations are as simple as bitwise AND and bitwise OR respectively in the `prime_factors_t` representation.\n\n# Approach\n\nUse the Excel file which I used in the development of `prime_factors_t`... | 0 | 0 | ['Bit Manipulation', 'Bitmask', 'C++'] | 0 |
find-the-maximum-factor-score-of-array | Brute Force solution! | brute-force-solution-by-chiragbellara-mi2u | Intuition\nWe get the product of every possible removal, and compare them.\n\n# Approach\nInitialize the maximum value as the product of the lcm and gcd of the | ChiragBellara | NORMAL | 2024-10-27T15:40:21.597085+00:00 | 2024-10-27T15:40:21.597122+00:00 | 11 | false | # Intuition\nWe get the product of every possible removal, and compare them.\n\n# Approach\nInitialize the maximum value as the product of the lcm and gcd of the entire nums list, as that will be the possible value when no number is removed from the list.\nThen simply iterate over the list and remove every number and c... | 0 | 0 | ['Array', 'Python3'] | 0 |
find-the-maximum-factor-score-of-array | Simple Java Solution | Beats 100% | simple-java-solution-beats-100-by-nithin-i3gv | \n\n# Code\njava []\nclass Solution {\n long gcd(long a, long b) \n { \n return b == 0 ? a: gcd(b, a % b); \n }\n\n long lcm(int[] arr, | nithin_1217 | NORMAL | 2024-10-27T15:25:00.739425+00:00 | 2024-10-27T15:25:00.739457+00:00 | 15 | false | \n\n# Code\n```java []\nclass Solution {\n long gcd(long a, long b) \n { \n return b == 0 ? a: gcd(b, a % b); \n }\n\n long lcm(int[] arr, int idx, int r)\n {\n if (idx == arr.length - 1){\n if(idx == r) return 1;\n return arr[idx];\n }\n if(r == id... | 0 | 0 | ['Java'] | 0 |
find-the-maximum-factor-score-of-array | Python3 solution faster than 100% | python3-solution-faster-than-100-by-subh-g6qd | \nimport math\nclass Solution:\n def maxScore(self,nums: list[int]) -> int:\n def product(array):\n if len(array)!=0:\n lcm | elixlamp | NORMAL | 2024-10-27T15:20:20.069814+00:00 | 2024-10-27T15:21:35.645323+00:00 | 26 | false | ```\nimport math\nclass Solution:\n def maxScore(self,nums: list[int]) -> int:\n def product(array):\n if len(array)!=0:\n lcm = array[0]\n gcd = array[0]\n for x in range(len(array)):\n lcm = max(math.lcm(array[x],lcm),lcm)\n ... | 0 | 0 | ['Python', 'Python3'] | 0 |
find-the-maximum-factor-score-of-array | Simple Python solution || 100% faster | simple-python-solution-100-faster-by-chi-y5gg | Code\npython3 []\nimport math\n\nclass Solution:\n def maxScore(self, nums: List[int]) -> int:\n if len(nums) == 1:\n return nums[0]**2\n | chiragnayak10 | NORMAL | 2024-10-27T14:33:14.793566+00:00 | 2024-10-27T14:33:14.793590+00:00 | 2 | false | # Code\n```python3 []\nimport math\n\nclass Solution:\n def maxScore(self, nums: List[int]) -> int:\n if len(nums) == 1:\n return nums[0]**2\n max_score = 0\n\n for i in range(-1,len(nums)):\n if i == 0:\n start = 1\n gcd_value = nums[1]\n ... | 0 | 0 | ['Python3'] | 0 |
find-the-maximum-factor-score-of-array | Brute Force | brute-force-by-trifecta_of_reality-g7tu | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | trifecta_of_reality | NORMAL | 2024-10-27T14:27:05.339924+00:00 | 2024-10-27T14:27:05.339961+00:00 | 16 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
find-the-maximum-factor-score-of-array | c++ solution | c-solution-by-dilipsuthar60-3p9d | \nclass Solution {\npublic:\n long long gcd(long long a,long long b){\n return __gcd(a,b);\n }\n long long lcm(long long a,long long b){\n | dilipsuthar17 | NORMAL | 2024-10-27T13:50:38.202317+00:00 | 2024-10-27T13:50:38.202344+00:00 | 1 | false | ```\nclass Solution {\npublic:\n long long gcd(long long a,long long b){\n return __gcd(a,b);\n }\n long long lcm(long long a,long long b){\n return a*b/gcd(a,b);\n }\n long long maxScore(vector<int>& nums) {\n int n=nums.size();\n if(n==1) return nums[0]*nums[0];\n lon... | 0 | 0 | ['C', 'C++'] | 0 |
find-the-maximum-factor-score-of-array | Rust beginner solution | rust-beginner-solution-by-chenyo-17-ou0f | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | chenyo-17 | NORMAL | 2024-10-27T13:48:27.223287+00:00 | 2024-10-27T13:48:27.223317+00:00 | 5 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity: O(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(n)\n<!-- Add your space complexity here, e.g. $... | 0 | 0 | ['Rust'] | 0 |
smallest-number-with-all-set-bits | [Java/C++/Python] Different ideas | javacpython-different-ideas-by-lee215-6qce | Explanation\nSolution 1. while loop on res = res * 2 + 1\nSolution 2. Build-in count leading zeros\nSolution 3. Build-in count bit length\n\n# Complexity\nTime | lee215 | NORMAL | 2024-12-01T04:32:41.952130+00:00 | 2024-12-01T12:29:30.946106+00:00 | 1,927 | false | # **Explanation**\nSolution 1. while loop on `res = res * 2 + 1`\nSolution 2. Build-in count leading zeros\nSolution 3. Build-in count bit length\n\n# **Complexity**\nTime `O(logn)`\nSpace `O(1)`\n<br>\n\n**Java**\n```Java\n public int smallestNumber(int n) {\n int res = 1;\n while (res < n)\n ... | 19 | 3 | ['C', 'Python', 'Java'] | 2 |
smallest-number-with-all-set-bits | 🔥 Find the Smallest Number with Only Set Bits 🔢 | find-the-smallest-number-with-only-set-b-8jef | Intuition \uD83D\uDCA1 \n\nThe problem revolves around finding the smallest number greater than or equal to a given number n where the binary representation of | lasheenwael9 | NORMAL | 2024-12-02T04:56:32.750751+00:00 | 2024-12-02T04:56:32.750776+00:00 | 1,265 | false | # Intuition \uD83D\uDCA1 \n\nThe problem revolves around finding the smallest number greater than or equal to a given number `n` where the binary representation of the number contains only `1`s. \n\n1. **Key Insight**: \n - Numbers with only `1`s in their binary representation (e.g., 1, 3, 7, 15) follow the form $... | 14 | 0 | ['Bit Manipulation', 'C++', 'Java', 'Python3', 'JavaScript'] | 2 |
smallest-number-with-all-set-bits | 1 less than largest power of 2 greater than n | 1-less-than-largest-power-of-2-greater-t-4hha | Approach\n- - Find the next larget power of 2 i.e. ceil(log2(n+1))\n- Then reurn power of 2 to the number found above and then - 1 to have all bits set.\n\n# Co | kreakEmp | NORMAL | 2024-12-01T05:03:28.355327+00:00 | 2024-12-01T05:08:17.125979+00:00 | 1,327 | false | # Approach\n- - Find the next larget power of 2 i.e. ceil(log2(n+1))\n- Then reurn power of 2 to the number found above and then - 1 to have all bits set.\n\n# Code\n```cpp []\nint smallestNumber(int n) {\n return pow(2, ceil(log2(n+1))) - 1;\n}\n```\n\n\n\n---\n\n\n<b>Here is an article of my interview experience -... | 9 | 3 | ['C++'] | 2 |
smallest-number-with-all-set-bits | Python3 || 1 line, Count the bits || T/S: 99% / 59% | python3-1-line-count-the-bits-ts-99-59-b-8rgf | This problem is equivalent to: Given a number n, find the greatest integer with the same bit-length. Thus, we determine the bit-length of n and use mathematics | Spaulding_ | NORMAL | 2024-12-01T04:33:52.161899+00:00 | 2024-12-08T02:29:41.488118+00:00 | 363 | false | This problem is equivalent to: *Given a number *n*, find the greatest integer with the same bit-length.* Thus, we determine the bit-length of *n* and use mathematics to complete the task.\n\n```python3 []\nclass Solution:\n def smallestNumber(self, n: int) -> int:\n \n return pow(2, n.bit_length()) - 1... | 8 | 0 | ['C++', 'Java', 'Python3'] | 0 |
smallest-number-with-all-set-bits | One-Liners | one-liners-by-votrubac-bb78 | Two solutions in case you do not want bit manipulations...\n\nC++\ncpp\nint smallestNumber(int n) {\n return pow(2, floor(log2(n) + 1)) - 1;\n}\n\nC++\ncpp\n | votrubac | NORMAL | 2024-12-01T04:47:16.547971+00:00 | 2024-12-01T04:55:43.978155+00:00 | 440 | false | Two solutions in case you do not want bit manipulations...\n\n**C++**\n```cpp\nint smallestNumber(int n) {\n return pow(2, floor(log2(n) + 1)) - 1;\n}\n```\n**C++**\n```cpp\nint sb[10] = {1, 3, 7, 15, 31, 63, 127, 255, 511, 1023};\nint smallestNumber(int n) {\n return *lower_bound(begin(sb), end(sb), n);\n}\n``` | 7 | 2 | [] | 0 |
smallest-number-with-all-set-bits | Intuition + Approach | Power of 2 | T.C ~ O(logn) | intuition-approach-power-of-2-tc-ologn-b-i4y6 | Intuition\n\nIf we subtract 1 from any power of 2 we will get number having all set bits.\n\nExample:-\n\n 2^3 -1 = (8-1) =7 -> binary(111)\n\n## Approach\n | langesicht | NORMAL | 2024-12-01T04:58:38.616360+00:00 | 2024-12-01T10:58:19.250732+00:00 | 504 | false | # Intuition\n\nIf we subtract 1 from any power of 2 we will get number having all set bits.\n\nExample:-\n\n 2^3 -1 = (8-1) =7 -> binary(111)\n\n## Approach\n- Find 1st power of 2 which is greater than or equal to n+1\n- Ans is (Power of 2) -1\n\n For Example:- \n n = 5,\n power of 2 greater t... | 6 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | bit_ceil 1 line||beats 100% | bit_ceil-1-linebeats-100-by-anwendeng-osy5 | Intuition\n Describe your first thoughts on how to solve this problem. \nUse bit_ceil (C++20). That is the smallest 2 powers greater or equal to n\n# Approach\n | anwendeng | NORMAL | 2024-12-01T05:52:16.568432+00:00 | 2024-12-01T05:57:33.538119+00:00 | 202 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nUse bit_ceil (C++20). That is the smallest 2 powers greater or equal to n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n- If bit_ceil(n)=n, n is a 2 power, return 2*n-1\n- otherwise return bit_ceil(n)-1\n# Complexi... | 5 | 1 | ['Bit Manipulation', 'C++'] | 2 |
smallest-number-with-all-set-bits | [Python, Java, C++, Rust] Elegant & Short | O(1) | Power Of Two | python-java-c-rust-elegant-short-o1-powe-ki9y | Complexity\n- Time complexity: O(1)\n- Space complexity: O(1)\n\n# Code\npython3 []\nclass Solution:\n def smallestNumber(self, n: int) -> int:\n retu | Kyrylo-Ktl | NORMAL | 2024-12-01T10:03:30.276733+00:00 | 2024-12-01T10:13:13.750927+00:00 | 226 | false | # Complexity\n- Time complexity: $$O(1)$$\n- Space complexity: $$O(1)$$\n\n# Code\n```python3 []\nclass Solution:\n def smallestNumber(self, n: int) -> int:\n return (1 << n.bit_length()) - 1\n```\n```java []\nimport java.math.BigInteger;\n\nclass Solution {\n public int smallestNumber(int n) {\n re... | 4 | 0 | ['Python', 'C++', 'Java', 'Python3', 'Rust'] | 0 |
smallest-number-with-all-set-bits | 🔥Beats 100 % 🔥 | Easiest Solution ✔️ | O(1) and O(n) | Bit Manipulation | beats-100-easiest-solution-o1-and-on-bit-j5ty | Intuition\nThe goal is to find the smallest number >= n where all bits in its binary representation are set (e.g., 1, 3, 7, 15, etc.). Starting from n, we check | ntrcxst | NORMAL | 2024-12-01T05:16:25.863480+00:00 | 2024-12-01T05:16:25.863519+00:00 | 138 | false | # Intuition\nThe goal is to find the smallest number `>= n` where all **bits** in its binary representation are set (e.g., 1, 3, 7, 15, etc.). Starting from `n`, we check if the number satisfies the condition `x & (x + 1) == 0`, which is true only if `x` has all **bits set** , binary \n`0111 & 1000 = 0`. If `x` doesn\'... | 4 | 0 | ['Bit Manipulation', 'Bitmask', 'Java'] | 1 |
smallest-number-with-all-set-bits | 💯Very Easy Detailed Solution || 🎯 Beats 100% || 🎯 Two Approaches | very-easy-detailed-solution-beats-100-tw-svn4 | Approach 1: Brute Force\n Describe your approach to solving the problem. \n1. Helper Function check(String str):\n - This method checks if a given binary str | chaturvedialok44 | NORMAL | 2024-12-02T06:06:30.724977+00:00 | 2024-12-02T06:06:30.725006+00:00 | 187 | false | # Approach 1: Brute Force\n<!-- Describe your approach to solving the problem. -->\n1. **Helper Function check(String str):**\n - This method checks if a given binary string contains only the character \'1\'.\n - If it encounters a \'0\' in the string, it returns false; otherwise, it returns true.\n\n2. **Method ... | 3 | 0 | ['Math', 'String', 'Bit Manipulation', 'String Matching', 'Bitmask', 'Java'] | 2 |
smallest-number-with-all-set-bits | 💢☠💫Easiest👾Faster✅💯 Lesser🧠 🎯 C++✅Python3🐍✅Java✅C✅Python🐍✅C#✅💥🔥💫Explained☠💥🔥 Beats 100 | easiestfaster-lesser-cpython3javacpython-vrhi | \n\n# Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n\n Describe your first thoughts on how to solve this problem. \n- J | Edwards310 | NORMAL | 2024-12-01T09:56:04.251796+00:00 | 2024-12-01T09:56:04.251831+00:00 | 134 | false | \n\n# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n\n<!-- Describe your first thoughts on how to solve this problem. -->\n- ***JavaScript Code -->**... | 3 | 1 | ['C', 'PHP', 'Python', 'C++', 'Java', 'Go', 'Python3', 'JavaScript', 'C#', 'Dart'] | 0 |
smallest-number-with-all-set-bits | [Python3] Math | python3-math-by-ye15-yo9h | Intuition\nCount the number of bits of n and create an all 1 binary. \n\nAnalysis\nTime complexity O(1)\nSpace complexity O(1)\n\nImplemetation\n\nclass Solutio | ye15 | NORMAL | 2024-12-01T04:44:57.321582+00:00 | 2024-12-01T04:47:44.562088+00:00 | 158 | false | **Intuition**\nCount the number of bits of `n` and create an all `1` binary. \n\n**Analysis**\nTime complexity `O(1)`\nSpace complexity `O(1)`\n\n**Implemetation**\n```\nclass Solution:\n def smallestNumber(self, n: int) -> int:\n return (1<<n.bit_length()) - 1\n``` | 3 | 0 | ['Python3'] | 1 |
smallest-number-with-all-set-bits | Easiest Solution💯 || 100% beats | easiest-solution-100-beats-by-aryaman123-8nan | Code | aryaman123 | NORMAL | 2025-03-19T16:05:29.600995+00:00 | 2025-03-19T16:05:29.600995+00:00 | 93 | false |
# Code
```java []
class Solution {
public int smallestNumber(int n) {
int ans = poweroftwo(n+1);
return ans-1;
}
public int poweroftwo(int n){
int p = 1;
while(p<n){
p*=2;
}
return p;
}
}
``` | 2 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | 100% Best Solution | 100-best-solution-by-luffy240605-nckx | IntuitionAll set bits are present in numbers just before the powers of 2 for example 7 just before 8 , 15 just before 16 etc. So we will count the number of bit | luffy240605 | NORMAL | 2025-01-07T01:25:52.241169+00:00 | 2025-01-07T01:27:15.151351+00:00 | 86 | false | # Intuition
All set bits are present in numbers just before the powers of 2 for example 7 just before 8 , 15 just before 16 etc. So we will count the number of bits in the number n(given) and return 2 to the power the number of bits in that number - 1.
# Approach
Initialize count variable and count the number of bits... | 2 | 0 | ['C++'] | 1 |
smallest-number-with-all-set-bits | [Swift, C++, Python3] Simplest solution 0ms O(logN) | swift-c-python3-simplest-solution-0ms-ol-fnfn | Intuition\nThe first numbers which contain only set bits are 1, 3, 7, 15, 31.\nSo, each next only set bits number can be calculated as current * 2 + 1.\n\n\n\n\ | evkobak | NORMAL | 2024-12-02T05:13:20.488650+00:00 | 2024-12-02T07:01:06.156742+00:00 | 43 | false | # Intuition\nThe first numbers which contain only set bits are 1, 3, 7, 15, 31.\nSo, each next only set bits number can be calculated as `current * 2 + 1`.\n\n\n\n\n# Approach\nWe can... | 2 | 0 | ['Swift', 'C++', 'Python3'] | 0 |
smallest-number-with-all-set-bits | Simple and Easy Solution | ✅Beats 100% | C++| Java | Python | JavaScript | simple-and-easy-solution-beats-100-c-jav-e5td | \n\n# \u2B06\uFE0F Upvote if it helps! \u2B06\uFE0F \n## Connect with me on LinkedIn: Bijoy Sing \n\n---\n\n\n## Follow me also on Codeforces: Bijoy Sing\n\n\ | BijoySingh7 | NORMAL | 2024-12-01T05:45:28.738744+00:00 | 2024-12-01T05:47:40.106978+00:00 | 572 | false | \n\n# \u2B06\uFE0F Upvote if it helps! \u2B06\uFE0F \n## Connect with me on LinkedIn: [Bijoy Sing](https://www.linkedin.com/in/bijoy-sing-236a5a1b2/) \n\n---\n\n\n## Follow me also on Codeforces: [Bijoy Sing](https://codeforces.com/profile/BijoySingh7)\n\n\n---\n\n### **Solution in C++, Python, Java, and JavaScript**... | 2 | 0 | ['Bit Manipulation', 'Bitmask', 'Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 2 |
smallest-number-with-all-set-bits | ✅ Simple Java Solution | simple-java-solution-by-harsh__005-57wt | CODE\nJava []\npublic int smallestNumber(int n) {\n\tString str = Integer.toBinaryString(n);\n\tint i=str.length()-1, res = 0;\n\n\twhile(i >= 0) {\n\t\tres += | Harsh__005 | NORMAL | 2024-12-01T05:36:16.680373+00:00 | 2024-12-01T05:36:16.680400+00:00 | 55 | false | ## **CODE**\n```Java []\npublic int smallestNumber(int n) {\n\tString str = Integer.toBinaryString(n);\n\tint i=str.length()-1, res = 0;\n\n\twhile(i >= 0) {\n\t\tres += (1<<i);\n\t\ti--;\n\t}\n\treturn res;\n}\n``` | 2 | 0 | ['Java'] | 1 |
smallest-number-with-all-set-bits | 3370. Smallest Number With All Set Bits | 3370-smallest-number-with-all-set-bits-b-mxkg | Intuition\n\nGenerate string like below:\n0\n01\n011\n0111\n01111\n011111\n\nConvert to decimal\n0\n1\n3\n7\n15\n31\n\nif greater than n, return that converted | pgmreddy | NORMAL | 2024-12-01T05:15:48.081407+00:00 | 2024-12-01T05:24:48.730053+00:00 | 59 | false | # Intuition\n```\nGenerate string like below:\n0\n01\n011\n0111\n01111\n011111\n\nConvert to decimal\n0\n1\n3\n7\n15\n31\n\nif greater than n, return that converted decimal number\n```\n\nor\n```\nn and next to n bit and is 0\n```\n\n# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -... | 2 | 0 | ['JavaScript'] | 0 |
smallest-number-with-all-set-bits | Set all bits in n | C++, Python, Java | set-all-bits-in-n-c-python-java-by-not_y-eu9n | Approach\n Describe your approach to solving the problem. \nSet all the bits in n\'s binary representation to 1.\n\nFor the python version, 2^k-1 is a number wi | not_yl3 | NORMAL | 2024-12-01T05:02:18.821899+00:00 | 2024-12-01T20:59:54.003385+00:00 | 188 | false | # Approach\n<!-- Describe your approach to solving the problem. -->\nSet all the bits in n\'s binary representation to 1.\n\nFor the python version, $$2^k-1$$ is a number with all `k` set bits.\n# Complexity\n- Time complexity: $$O(log(n))$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```C++ []\nc... | 2 | 0 | ['Bit Manipulation', 'C', 'Python', 'C++', 'Java', 'Python3'] | 0 |
smallest-number-with-all-set-bits | simple and easy C++ solution | Bitmask | simple-and-easy-c-solution-bitmask-by-sh-5ivk | \n# if it\'s help, please up \u2B06 vote! \u2764\uFE0F\n###### Let\'s Connect on Linkedin: www.linkedin.com/in/shishirrsiam\n\n\n\n# Code\ncpp []\nclass Solutio | shishirRsiam | NORMAL | 2024-12-01T04:55:12.471249+00:00 | 2024-12-01T04:55:12.471278+00:00 | 102 | false | \n# if it\'s help, please up \u2B06 vote! \u2764\uFE0F\n###### Let\'s Connect on Linkedin: www.linkedin.com/in/shishirrsiam\n\n\n\n# Code\n```cpp []\nclass Solution {\npublic:\n int smallestNumber(int n) \n {\n bitset<24>bits(n);\n string num, s = bits.to_string();\n\n int idx = s.find(\'1\')... | 2 | 1 | ['Bit Manipulation', 'Bitmask', 'C++'] | 0 |
smallest-number-with-all-set-bits | C code No built-in functions, Only bit manipulation (explained) | c-code-no-built-in-functions-only-bit-ma-muo7 | Code | amiensa | NORMAL | 2025-04-05T22:00:00.105554+00:00 | 2025-04-05T22:00:00.105554+00:00 | 10 | false |
# Code
```c []
int smallestNumber(int n) {
int count = 0; // number of 1's in "n"
int lastone = 0; // refers to last bit with value 1
// in "n" starting from right
int m = n;
for(int i = 1 ; i < 11 ; i++){
if(m & 1){
lastone=i;
count++;
}
... | 1 | 0 | ['Bit Manipulation', 'C'] | 0 |
smallest-number-with-all-set-bits | 100 Beats Solution 🔥|| Java 🎯 | 100-beats-solution-java-by-user8688f-obzg | Approachres * 2 + 1 upto n gives the answerComplexity
Time complexity:O(Log(N))
Space complexity:O(1)
Code | user8688F | NORMAL | 2025-03-22T07:29:25.072332+00:00 | 2025-03-22T07:29:25.072332+00:00 | 29 | false | # Approach
res * 2 + 1 upto n gives the answer
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:O(Log(N))
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:O(1)
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
![7865b3eb-6d8d-42fe-9c51-188ad4821476_1... | 1 | 0 | ['Math', 'Java'] | 0 |
smallest-number-with-all-set-bits | 100% Acceptance!✅With Efficient Memory!✅ Very Easy To understand!✅ | 100-acceptancewith-efficient-memory-very-h3uj | IntuitionApproachComplexity
Time complexity:O(n)✅
Space complexity:O(1)✅
Code | velan_m_velan | NORMAL | 2025-03-19T07:55:47.450649+00:00 | 2025-03-19T07:55:47.450649+00:00 | 50 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:$$O(n)$$✅
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:$$O(1)$$✅
<!-- Add your space complexity here, e.g. $$O(... | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Simple Go, no bit manipulation | simple-go-no-bit-manipulation-by-user891-gjbp | ApproachWe need find power of 2 that is bigger than the given number and subtract 1.5 -> 101
next greater number that is a power of 2 is 8
8 -> 1000
subtract 1 | user8912Cp | NORMAL | 2025-03-17T04:06:28.214915+00:00 | 2025-03-17T04:06:28.214915+00:00 | 18 | false | # Approach
We need find power of 2 that is bigger than the given number and subtract 1.
5 -> 101
next greater number that is a power of 2 is 8
8 -> 1000
subtract 1
7 -> 111
Same length as 5 in binary representation, but all bits are ones
# Complexity
- Time complexity:
O(log(n))
- Space complexity:
O(n)
# Code
```g... | 1 | 0 | ['Go'] | 0 |
smallest-number-with-all-set-bits | ☑️ Finding Smallest Number With All Set Bits. ☑️ | finding-smallest-number-with-all-set-bit-w009 | Code | Abdusalom_16 | NORMAL | 2025-03-15T11:50:46.516379+00:00 | 2025-03-15T11:50:46.516379+00:00 | 19 | false | # Code
```dart []
class Solution {
int smallestNumber(int n) {
while(true){
List<String> conv = n.toRadixString(2).split("");
if(conv.toSet().length == 1 && conv.first == "1"){
return n;
}
n++;
}
return 999;
}
}
``` | 1 | 0 | ['Math', 'Bit Manipulation', 'Dart'] | 0 |
smallest-number-with-all-set-bits | // ONE LINER SOLUTION >- BEATS 100% | one-liner-solution-beats-100-by-fwupexeg-msec | 🧠 Intuition
The goal is to find a pattern related to the highest power of 2 in the given number n. Observing the binary representation of numbers, we notice tha | fWUpExEgyB | NORMAL | 2025-02-27T08:49:50.324449+00:00 | 2025-02-27T08:49:50.324449+00:00 | 53 | false | 🧠 Intuition
The goal is to find a pattern related to the highest power of 2 in the given number n. Observing the binary representation of numbers, we notice that:
The highest power of 2 in n is the most significant set bit.
If we take 2 * highestOneBit(n) - 1, we get a number consisting of all 1s in binary, covering ... | 1 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | EASIEST 2 LINE SOLUTION BEATING 100% IN 0ms | easiest-2-line-solution-beating-100-in-0-ov3w | ApproachTo find the smallest number x greater than or equal to n where x's binary representation consists of only set bits (i.e., all bits are 1), we can utiliz | arshi_bansal | NORMAL | 2025-02-09T07:34:47.579409+00:00 | 2025-02-09T07:34:47.579409+00:00 | 62 | false | # Approach
<!-- Describe your approach to solving the problem. -->
To find the smallest number x greater than or equal to n where x's binary representation consists of only set bits (i.e., all bits are 1), we can utilize the following method:
1. Start with a number of the form 2^k - 1, which in binary is k consecutive ... | 1 | 0 | ['Math', 'Bit Manipulation', 'Java'] | 0 |
smallest-number-with-all-set-bits | 0MS 🏆 || 🌟JAVA ☕ | 0ms-java-by-galani_jenis-1x3p | Code | Galani_jenis | NORMAL | 2025-01-29T05:39:29.541636+00:00 | 2025-01-29T05:39:29.541636+00:00 | 58 | false |
# Code
```java []
class Solution {
public int smallestNumber(int n) {
int ans = 1;
while (ans < n)
ans = ans * 2 + 1;
return ans;
}
}
``` | 1 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | "Simple & small" ahh solution | Beats 100%. | simple-small-ahh-solution-beats-100-by-a-6g9s | IntuitionApproach
Find the smallest power of 2 that is strictly greater than n.
Return that power of 2, subtracting 1 as the result.
Complexity
Time complexity: | AnaghaBharadwaj | NORMAL | 2025-01-20T06:04:48.605269+00:00 | 2025-01-20T06:04:48.605269+00:00 | 59 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
1. Find the smallest power of 2 that is strictly greater than n.
2. Return that power of 2, subtracting 1 as the result.
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:O(n)
<!-- Add your ... | 1 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | BEATS 100% WITH 3 LINES OF CODE | beats-100-with-3-lines-of-code-by-yashve-eapv | IntuitionApproachFirst find the number of bits in the number and then return the 2 raise to the power bits -1. If you find any difficulty please refer to my sol | Yashvendra | NORMAL | 2025-01-01T16:45:20.703110+00:00 | 2025-01-01T16:45:20.703110+00:00 | 12 | false | # Intuition
# Approach
First find the number of bits in the number and then return the 2 raise to the power bits -1. If you find any difficulty please refer to my solution.
# Complexity
- Time complexity: O(1).
- Space complexity: O(1).
# Code
```java []
class Solution {
public int smallestNumber(int n) {
... | 1 | 0 | ['Math', 'Bit Manipulation', 'Java'] | 0 |
smallest-number-with-all-set-bits | 🔥Beats 100 % 🔥 || Easiest Solution ✔️ || JAVA || | beats-100-easiest-solution-java-by-happy-f8bo | IntuitionThe problem revolves around finding the smallest number greater than or equal to a given number n where the binary representation of the number contain | Happy-Singh-Chauhan | NORMAL | 2024-12-24T18:02:26.617969+00:00 | 2024-12-24T18:02:26.617969+00:00 | 38 | false | # Intuition
*The problem revolves around finding the smallest number greater than or equal to a given number n where the binary representation of the number contains only 1s.*
# Approach
1. Determine the number of bits b needed to represent n.
2. Calculate the result as Math.pow(2,b)-1.
# Complexity
- Time complexity... | 1 | 0 | ['Math', 'Bit Manipulation', 'Java'] | 0 |
smallest-number-with-all-set-bits | optimal approach: o(logn) | optimal-approach-ologn-by-bhagavanreddy-9ntl | IntuitionApproach :Best approachBy using left shift operatorComplexity
Time complexity:O(LogN)
Space complexity:O(1)
Code | bhagavanreddy | NORMAL | 2024-12-24T15:15:46.384695+00:00 | 2024-12-24T15:15:46.384695+00:00 | 29 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach :Best approach
By using left shift operator
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:O(LogN)
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:O(1)
<!-- Add... | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Bit Updation 🔥✅ - Beats 100% | C++ Solution | bit-updation-beats-100-c-solution-by-saj-uoqu | IntuitionStart with the value 1. Now we will keep converting our number from 1 -> 11 -> 111 like this , until it become just greater than the n.Approachwhile th | Sajal0701 | NORMAL | 2024-12-21T13:22:05.892083+00:00 | 2024-12-21T13:22:05.892083+00:00 | 42 | false | # Intuition
Start with the value 1. Now we will keep converting our number from 1 -> 11 -> 111 like this , until it become just greater than the n.
# Approach
while the value of x is lesser than n we will convert right most unset bit to 1.
Simply run a while loop until the value of x is lesser than n. In each itera... | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | ✅ C++ Simple Code ✅ | c-simple-code-by-jagdish9903-liwp | \n\n# Code\ncpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n int ans = log2(n);\n return pow(2, (ans + 1)) - 1; \n }\n};\n | Jagdish9903 | NORMAL | 2024-12-05T07:30:46.303363+00:00 | 2024-12-05T07:30:46.303385+00:00 | 19 | false | \n\n# Code\n```cpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n int ans = log2(n);\n return pow(2, (ans + 1)) - 1; \n }\n};\n``` | 1 | 0 | ['Math', 'Bit Manipulation', 'C++'] | 0 |
smallest-number-with-all-set-bits | Used built in function kuch STL ka | used-built-in-function-kuch-stl-ka-by-ye-cz6x | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | yesyesem | NORMAL | 2024-12-04T18:54:48.812561+00:00 | 2024-12-04T18:54:48.812597+00:00 | 17 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Need to learn bitset conversion binary find_first_not_of() etc need to do STL properly | need-to-learn-bitset-conversion-binary-f-rsw7 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | yesyesem | NORMAL | 2024-12-04T16:58:18.405964+00:00 | 2024-12-04T16:58:18.405999+00:00 | 15 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | C# O(1) solution | c-o1-solution-by-idhammond-hpoe | Approach\nPropagating any set bit to the right by 8 bits then 4 bits, then 2 bits and finally 1 bit, using a shift and or operation, results in all bits to the | idhammond | NORMAL | 2024-12-04T08:08:49.489434+00:00 | 2024-12-04T08:08:49.489479+00:00 | 4 | false | # Approach\nPropagating any set bit to the right by 8 bits then 4 bits, then 2 bits and finally 1 bit, using a shift and or operation, results in all bits to the right of any set bit also getting set.\n\nFor example: `001000000000` -> `001000000010` -> `001000100010` -> `001010101010` -> `001111111111`\n\n# Complexity\... | 1 | 0 | ['C#'] | 0 |
smallest-number-with-all-set-bits | Unique Solution | unique-solution-by-himanshu_gahlot-7qaz | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Himanshu_Gahlot | NORMAL | 2024-12-04T04:19:57.723182+00:00 | 2024-12-04T04:19:57.723204+00:00 | 10 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 0 | ['Bit Manipulation', 'Java'] | 0 |
smallest-number-with-all-set-bits | Simple Solution C# | 0 MS | simple-solution-c-0-ms-by-nyester-iats | Approach\n Describe your approach to solving the problem. \n\n# Code\ncsharp []\npublic class Solution {\n public int SmallestNumber(int n) \n {\n | Nyester | NORMAL | 2024-12-03T11:45:19.966128+00:00 | 2024-12-03T11:45:19.966169+00:00 | 10 | false | # Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Code\n```csharp []\npublic class Solution {\n public int SmallestNumber(int n) \n {\n // Count the number of bits\n int bits = 0;\n while(n > 0)\n {\n n /= 2;\n bits++;\n } \n ... | 1 | 0 | ['C#'] | 0 |
smallest-number-with-all-set-bits | Binary Manipulation Approach || Python3 | binary-manipulation-approach-python3-by-eind3 | Binary Manipulation Approach:\n\n# Intuition\n- The idea is to find the smallest number that has the same number of bits set to 1 as the binary representation o | lavanyaimmaneni12 | NORMAL | 2024-12-01T18:05:06.418546+00:00 | 2024-12-01T18:05:06.418584+00:00 | 20 | false | # Binary Manipulation Approach:\n\n# Intuition\n- The idea is to find the smallest number that has the same number of bits set to 1 as the binary representation of the given number \\( n \\).\n\n# Approach\n- Convert \\( n \\) to its binary representation.\n- Count the number of bits set to 1.\n- Construct a binary num... | 1 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | C bit-shifting | c-bit-shifting-by-michelusa-f0o3 | Set bits, one at a time.\n\n# Code\nc []\nint smallestNumber(int n) {\n int res = 0;\n\n while (n > 0) {\n res = (res << 1) | 1;\n n >>= 1;\ | michelusa | NORMAL | 2024-12-01T11:53:35.169227+00:00 | 2024-12-01T11:53:35.169260+00:00 | 39 | false | Set bits, one at a time.\n\n# Code\n```c []\nint smallestNumber(int n) {\n int res = 0;\n\n while (n > 0) {\n res = (res << 1) | 1;\n n >>= 1;\n }\n\n return res;\n}\n``` | 1 | 0 | ['C'] | 0 |
smallest-number-with-all-set-bits | 🚀 LeetCode Solution: Finding the Greatest Square and the Smallest Number | leetcode-solution-finding-the-greatest-s-zboh | Here\u2019s how your LeetCode solution post could look:\n\n---\n\n### \uD83D\uDE80 LeetCode Solution: Finding the Greatest Square and the Smallest Number\n\n\uD | krishnakanthpathi | NORMAL | 2024-12-01T07:02:02.103897+00:00 | 2024-12-01T07:02:02.103934+00:00 | 20 | false | Here\u2019s how your LeetCode solution post could look:\n\n---\n\n### \uD83D\uDE80 LeetCode Solution: Finding the Greatest Square and the Smallest Number\n\n\uD83D\uDCA1 **Problem Statement**: \nGiven a number `n`, the task is to: \n1. Find the smallest number that is larger than `n` and is a power of 2. \n2. Return... | 1 | 0 | ['Python', 'Python3'] | 0 |
smallest-number-with-all-set-bits | Using Mersenne Numbers | using-mersenne-numbers-by-sapilol-hu4v | \n\n\n# Code\ncpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n int z = 1;\n for (int i = 0; i <= n; i++) {\n z = (1 | LeadingTheAbyss | NORMAL | 2024-12-01T04:36:26.755756+00:00 | 2024-12-01T04:36:26.755781+00:00 | 17 | false | \n\n\n# Code\n```cpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n int z = 1;\n for (int i = 0; i <= n; i++) {\n z = (1 << i);\n if (z > n)\n ... | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Easy to understand C++ Solution | easy-to-understand-c-solution-by-rajvir_-fqp4 | Complexity\n- Time complexity: O(1)\n\n- Space complexity: O(1)\n\n# Code\ncpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n for(int i | rajvir_singh | NORMAL | 2024-12-01T04:33:26.888809+00:00 | 2024-12-01T04:33:26.888828+00:00 | 109 | false | # Complexity\n- Time complexity: O(1)\n\n- Space complexity: O(1)\n\n# Code\n```cpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n for(int i = 1; i <= 10; i++){\n int x = pow(2, i) - 1;\n if(x >= n) return x;\n }\n return -1;\n }\n};\n``` | 1 | 0 | ['Bit Manipulation', 'C++'] | 0 |
smallest-number-with-all-set-bits | C++ O(1) Clean 1-Line bit_width | c-o1-clean-1-line-bit_width-by-bramar2-iey7 | Complexity\n- Time complexity: $O(1)$\n\n- Space complexity: $O(1)$\n\n# Code\ncpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n retur | bramar2 | NORMAL | 2024-12-01T04:14:43.991018+00:00 | 2024-12-01T05:56:16.150089+00:00 | 32 | false | # Complexity\n- Time complexity: $O(1)$\n\n- Space complexity: $O(1)$\n\n# Code\n```cpp []\nclass Solution {\npublic:\n int smallestNumber(int n) {\n return (1 << bit_width(unsigned(n))) - 1;\n }\n};\n``` | 1 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Easy C solution 100% 💡 | easy-c-solution-100-by-jossue-05aj | 💡 IntuitionWhen we look at a binary number like 5 = 101, its bitwise complement (within its significant bits) is 2 = 010.
If we perform a bitwise OR between the | Jossue | NORMAL | 2025-04-12T03:57:35.741571+00:00 | 2025-04-12T03:57:35.741571+00:00 | 1 | false | # 💡 Intuition
When we look at a binary number like `5 = 101`, its bitwise complement (within its significant bits) is `2 = 010`.
If we perform a bitwise OR between the number and its complement, we get a result with all bits set:
`5 | 2 = 101 | 010 = 111`.
This idea helps us construct the smallest number greater... | 0 | 0 | ['C'] | 0 |
smallest-number-with-all-set-bits | easiest o(1) java solution (one array and loop) | easiest-o1-java-solution-one-array-and-l-w6qn | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | dpasala | NORMAL | 2025-04-08T19:20:04.739908+00:00 | 2025-04-08T19:20:04.739908+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | One line solution in Kotlin | Math | Logarithm | one-line-solution-in-kotlin-math-logarit-o5me | Code | ahmadali_ok | NORMAL | 2025-04-01T18:18:08.954298+00:00 | 2025-04-01T18:18:08.954298+00:00 | 2 | false |
# Code
```kotlin []
class Solution {
fun smallestNumber(n: Int): Int {
return (2.00.pow(log2(n.toDouble()).toInt().toDouble() + 1.00) - 1.00).toInt()
}
}
``` | 0 | 0 | ['Kotlin'] | 0 |
smallest-number-with-all-set-bits | simple | simple-by-ryuji-zypg | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | ryuji | NORMAL | 2025-03-31T20:02:31.652095+00:00 | 2025-03-31T20:02:31.652095+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Rust'] | 0 |
smallest-number-with-all-set-bits | Simple Swift Solution | simple-swift-solution-by-felisviridis-1bgz | Code | Felisviridis | NORMAL | 2025-03-28T09:45:36.362757+00:00 | 2025-03-28T09:45:36.362757+00:00 | 1 | false |
# Code
```swift []
class Solution {
func smallestNumber(_ n: Int) -> Int {
var num = 0
while num < n {
num = num << 1 + 1
}
return num
}
}
``` | 0 | 0 | ['Swift'] | 0 |
smallest-number-with-all-set-bits | simplest solution using cpp. | simplest-solution-using-cpp-by-prachi_ja-dv1r | IntuitionApproachComplexity
Time complexity:
O(1)
Space complexity:
O(1)Code | prachi_jadon | NORMAL | 2025-03-25T03:19:42.157769+00:00 | 2025-03-25T03:19:42.157769+00:00 | 3 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
O(1)
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
O(1... | 0 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Something Interesting | something-interesting-by-shakhob-lsh7 | Code | Shakhob | NORMAL | 2025-03-23T01:13:32.592346+00:00 | 2025-03-23T01:13:32.592346+00:00 | 2 | false | # Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
current = n
while True:
if bin(current).count('0') == 1:
return current
current += 1
``` | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Beats 100% | beats-100-by-raji1804-3sc9 | Code | Raji1804 | NORMAL | 2025-03-22T06:10:19.450881+00:00 | 2025-03-22T06:10:19.450881+00:00 | 2 | false |
# Code
```java []
class Solution {
public int smallestNumber(int n) {
double p=0,ans=0;
if(n==1)
return 1;
for(int i=0;i<n;i++)
{
p=Math.pow(2,i);
if(p>n)
{
ans=p-1;
break;
}
... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | 0ms JAVA CODE........!!!!!!!!!!!!! | 0ms-java-code-by-devesh_agrawal-svu0 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | Devesh_Agrawal | NORMAL | 2025-03-19T14:33:25.881229+00:00 | 2025-03-19T14:33:25.881229+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | 0ms JAVA CODE........!!!!!!!!!!!!! | 0ms-java-code-by-devesh_agrawal-os5a | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | Devesh_Agrawal | NORMAL | 2025-03-19T14:33:24.040483+00:00 | 2025-03-19T14:33:24.040483+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | Simple Solution by Baby Beginner | simple-solution-by-baby-beginner-by-chan-1mzq | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | chandueddalausa | NORMAL | 2025-03-18T18:10:36.760850+00:00 | 2025-03-18T18:10:36.760850+00:00 | 3 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | 100% beats | 100-beats-by-kunal_1310-xq5n | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | kunal_1310 | NORMAL | 2025-03-17T17:49:01.668679+00:00 | 2025-03-17T17:49:01.668679+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | SIMPLE C PROGRAM | simple-c-program-by-mr_jaikumar-knby | IntuitionApproachComplexity
Time complexity:0 MS
Space complexity:
Code | Mr_JAIKUMAR | NORMAL | 2025-03-14T05:38:14.846770+00:00 | 2025-03-14T05:38:14.846770+00:00 | 6 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:0 MS
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Co... | 0 | 0 | ['C'] | 0 |
smallest-number-with-all-set-bits | easy solution | easy-solution-by-owenwu4-tqym | Intuitionuse a loop and play around with the upper bound - n cubed in this caseApproachComplexity
Time complexity:
Space complexity:
Code | owenwu4 | NORMAL | 2025-03-13T21:53:21.360981+00:00 | 2025-03-13T21:53:21.360981+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
use a loop and play around with the upper bound - n cubed in this case
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space compl... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | JAVA | Shift operators | Log N solutions | java-shift-operators-log-n-solutions-by-3nj2p | IntuitionFind the position of leftmost set bit. Leftmost set bit will tell us how many set bits we want.ApproachTo get left most set bit maintain a counter pos | pankajsbagal | NORMAL | 2025-03-12T17:17:11.966283+00:00 | 2025-03-12T17:17:11.966283+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Find the position of leftmost set bit. Leftmost set bit will tell us how many set bits we want.
# Approach
<!-- Describe your approach to solving the problem. -->
To get left most set bit maintain a counter `pos` to count the position of b... | 0 | 0 | ['Math', 'Bit Manipulation', 'Java'] | 0 |
smallest-number-with-all-set-bits | smallest number with all set bits | smallest-number-with-all-set-bits-by-anu-r8yq | Code | AnushaYelleti | NORMAL | 2025-03-12T14:22:09.538125+00:00 | 2025-03-12T14:22:09.538125+00:00 | 1 | false |
# Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
f=True
ans=0
temp=n
while(f):
b=bin(temp)[2:]
if b.count('1')==len(b):
ans=temp
f=False
temp+=1
return ans
``` | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Python | 1 line | Beats %100 | python-1-line-beats-100-by-isinsarici-dnr9 | Code | isinsarici | NORMAL | 2025-03-11T22:41:14.988261+00:00 | 2025-03-11T22:41:14.988261+00:00 | 2 | false |
# Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
return int(bin(n)[2:].replace('0', '1'), 2)
``` | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Beats 100% solution. Super easy cpp code. | beats-100-solution-super-easy-cpp-code-b-higl | IntuitionFind the nearest power (p) of 2 which surpasses n. Subtract 1 from the number (p-1);ApproachInitialize count=0;
Run a while loop and divide the number | codestguy | NORMAL | 2025-03-10T12:18:54.578103+00:00 | 2025-03-10T12:18:54.578103+00:00 | 2 | false | # Intuition
Find the nearest power (p) of 2 which surpasses n. Subtract 1 from the number (p-1);
# Approach
Initialize count=0;
Run a while loop and divide the number by 2 till n becomes 0 and count++;
# Complexity
- Time complexity:
O(n).
- Space complexity:
O(1)
# Code
```cpp []
class Solution {
public:
int sma... | 0 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Simple and Easy Solution with Intuition | ✅Beats 100% | Java | Python 🔥🔥 | simple-and-easy-solution-with-intuition-zdod3 | 🔹 Approach 1: Brute Force (O(logN))IntuitionIterate from num and increment until we find a number where all bits are set.Algorithm
Start with num.
Increment num | sohith_reddy01 | NORMAL | 2025-03-08T19:34:34.862636+00:00 | 2025-03-08T19:40:32.375397+00:00 | 4 | false | ## **🔹 Approach 1: Brute Force (O(logN))**
### **Intuition**
Iterate from `num` and increment until we find a number where **all bits are set**.
### **Algorithm**
1. Start with `num`.
2. Increment `num` until `num & (num + 1) == 0`.
3. Return the result.
### **Implementation**
#### **Java**
```java
cl... | 0 | 0 | ['Bit Manipulation', 'Bitmask', 'Java', 'Python3'] | 0 |
smallest-number-with-all-set-bits | Without using log | without-using-log-by-nishant15-8y3v | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | nishant15 | NORMAL | 2025-03-08T18:30:48.364081+00:00 | 2025-03-08T18:30:48.364081+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['C#'] | 0 |
smallest-number-with-all-set-bits | Optimized simple solution - beats 100%🔥 | optimized-simple-solution-beats-100-by-c-od14 | Complexity
Time complexity: O(1)
Space complexity: O(1)
Code | cyrusjetson | NORMAL | 2025-03-06T05:01:55.445702+00:00 | 2025-03-06T05:01:55.445702+00:00 | 3 | false | # Complexity
- Time complexity: O(1)
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity: O(1)
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
```java []
class Solution {
public int smallestNumber(int n) {
int powerr = (int) (Math.log(n) / Math.log(2));
return (i... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | C++ | c-by-nguyenvinhhung2705-fw4y | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | kazumin | NORMAL | 2025-03-03T15:32:04.083308+00:00 | 2025-03-03T15:32:04.083308+00:00 | 3 | false | # Intuition
# Approach
# Complexity
- Time complexity:
- Space complexity:
# Code
```cpp []
class Solution {
public:
int smallestNumber(int n) {
n+=1
while((n & n-1) != 0){
n++;
}
return n-1;
}
};
``` | 0 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | Elixir solution. | elixir-solution-by-spring555-7blo | IntuitionApproachComplexity
Time complexity: 0ms
Space complexity: 72.15MB
Code | spring555 | NORMAL | 2025-03-02T09:31:13.812577+00:00 | 2025-03-02T09:31:13.812577+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity: 0ms
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity: 72.15MB
<!-- Add your space complexity here, e.g. $$O(n)$$ -... | 0 | 0 | ['Elixir'] | 0 |
smallest-number-with-all-set-bits | simple log solution | simple-log-solution-by-ishanchauhan79-cnyt | Code | IshanChauhan79 | NORMAL | 2025-02-27T11:02:02.505890+00:00 | 2025-02-27T11:02:02.505890+00:00 | 1 | false |
# Code
```typescript []
function smallestNumber(n: number): number {
const log2 = Math.log2(n + 1);
const log2C = Math.ceil(log2)
return Math.pow(2, log2C) - 1
};
``` | 0 | 0 | ['TypeScript'] | 0 |
smallest-number-with-all-set-bits | Simple js solution | simple-js-solution-by-midhunambadan-jud6 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | midhunambadan | NORMAL | 2025-02-25T12:54:53.307876+00:00 | 2025-02-25T12:54:53.307876+00:00 | 7 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['JavaScript'] | 0 |
smallest-number-with-all-set-bits | Easy Solution | easy-solution-by-kallamswethanareddy-8ohc | Code | kallamswethanareddy | NORMAL | 2025-02-20T16:43:29.488091+00:00 | 2025-02-20T16:43:29.488091+00:00 | 5 | false |
# Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
x=n
while x>=n:
a=bin(x)[2:]
if '0' in a:
x+=1
if '0' not in a:
return x
break
``` | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Python one-line solution | python-one-line-solution-by-redberry33-bx32 | Code | redberry33 | NORMAL | 2025-02-19T12:52:04.314717+00:00 | 2025-02-19T12:52:04.314717+00:00 | 2 | false |
# Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
return 2**len(bin(n)[2:]) -1
``` | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | [C++] Simple Solution | c-simple-solution-by-samuel3shin-utqs | Code | Samuel3Shin | NORMAL | 2025-02-18T16:12:28.670617+00:00 | 2025-02-18T16:12:28.670617+00:00 | 3 | false | # Code
```cpp []
class Solution {
public:
int smallestNumber(int n) {
int cur = 1;
int mult = 2;
while(cur <= n) {
if(cur >= n) return cur;
cur += mult;
mult *= 2;
}
return cur;
}
};
``` | 0 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | 🚀 Smallest Number with Same Binary Length 🔢 | smallest-number-with-same-binary-length-mpxe8 | IntuitionThe goal is to find the smallest possible number that has the same number of binary digits as the given number n.Observations:
The smallest number with | fisherman611 | NORMAL | 2025-02-16T18:28:00.209370+00:00 | 2025-02-16T18:28:00.209370+00:00 | 3 | false | ## Intuition
The goal is to find the smallest possible number that has the same number of binary digits as the given number `n`.
Observations:
1. The smallest number with a given binary length consists of all `1`s in binary representation.
2. Converting `n` to binary helps determine its length.
3. Constructing a new ... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | EASY SOLUTION BEATS 100% | easy-solution-beats-100-by-lakshmisatvik-jq8s | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | lakshmisatvikasuggula2006 | NORMAL | 2025-02-16T14:29:39.034905+00:00 | 2025-02-16T14:29:39.034905+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Typescript ✅ | typescript-by-kay-79-taba | Code | Kay-79 | NORMAL | 2025-02-11T06:15:07.861455+00:00 | 2025-02-11T06:15:07.861455+00:00 | 1 | false | # Code
```typescript []
function smallestNumber(n: number): number {
let bin = n.toString(2).split("");
for (let i = 0; i < bin.length; i++) {
if (bin[i] === "0") bin[i] = "1";
}
return parseInt(bin.join(""), 2);
}
``` | 0 | 0 | ['TypeScript'] | 0 |
smallest-number-with-all-set-bits | C++ solution | c-solution-by-sy7794564-dsa4 | Code | sy7794564 | NORMAL | 2025-02-07T08:30:02.227831+00:00 | 2025-02-07T08:30:02.227831+00:00 | 3 | false |
# Code
```cpp []
class Solution {
public:
int smallestNumber(int n) {
int x = 1;
while (x <= n) {
x <<= 1 ;
}
return x-1;
}
};
``` | 0 | 0 | ['C++'] | 0 |
smallest-number-with-all-set-bits | simple C | simple-c-by-hadsid-3ql8 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | hadsid | NORMAL | 2025-02-07T06:46:57.573487+00:00 | 2025-02-07T06:46:57.573487+00:00 | 5 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['C'] | 0 |
smallest-number-with-all-set-bits | Swift, Beats 100.00%, bit << 1 + | 1 | swift-beats-10000-bit-1-1-by-victor-smk-qq1i | null | Victor-SMK | NORMAL | 2025-02-05T18:06:37.889774+00:00 | 2025-02-05T18:06:37.889774+00:00 | 3 | false |
```swift []
class Solution {
func smallestNumber(_ n: Int) -> Int {
var ans = 1
while ans < n {
ans = ans << 1 | 1
}
return ans
}
}
``` | 0 | 0 | ['Swift'] | 0 |
smallest-number-with-all-set-bits | Smallest Number with All set Bits - python3 | smallest-number-with-all-set-bits-python-gp4v | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | ChaithraDee | NORMAL | 2025-02-01T15:41:29.677792+00:00 | 2025-02-01T15:41:29.677792+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Smallest Number with All set Bits - python3 | smallest-number-with-all-set-bits-python-iw9i | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | ChaithraDee | NORMAL | 2025-02-01T15:41:22.606763+00:00 | 2025-02-01T15:41:22.606763+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Bit Manipulation | bit-manipulation-by-ivl7sth6io-i5t4 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | iVl7stH6Io | NORMAL | 2025-01-30T21:11:46.486191+00:00 | 2025-01-30T21:11:46.486191+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Java two rows solution beats 100% | java-two-rows-solution-beats-100-by-had0-nc96 | IntuitionThere are two ways to solve a problem:
1)Transform to String and search for '0' in a String.
2)Use operator & if all the bits are '1' in bin.ApproachTh | had0uken | NORMAL | 2025-01-27T14:50:27.596300+00:00 | 2025-01-27T14:50:27.596300+00:00 | 4 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
There are two ways to solve a problem:
1)Transform to String and search for '0' in a String.
2)Use operator & if all the bits are '1' in bin.
# Approach
<!-- Describe your approach to solving the problem. -->
The second way is much faster a... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | Smallest number with all set bits | smallest-number-with-all-set-bits-by-nib-lrte | Approach2^n-1 has all set bits
case 1:n=3
2^3-1=8-1=7
7 has all set bits "111"Complexity
Time complexity:
O(1)--->100%
Code | NIBISHA | NORMAL | 2025-01-27T13:24:54.724374+00:00 | 2025-01-27T13:24:54.724374+00:00 | 2 | false | # Approach
2^n-1 has all set bits
case 1:n=3
2^3-1=8-1=7
7 has all set bits "111"
# Complexity
- Time complexity:
O(1)--->100%
# Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
i=0
while(1):
if pow(2,i)-1<n:
i+=1
else:
... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | easy eye caching java code for beginners!!!!!!!!!!!!!!! | easy-eye-caching-java-code-for-beginners-fyr6 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | CHURCHILL04 | NORMAL | 2025-01-27T03:46:43.286215+00:00 | 2025-01-27T03:46:43.286215+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | 3370. Smallest Number With All Set Bits | 3370-smallest-number-with-all-set-bits-b-8xoh | IntuitionEasy one!Approachwhile loop to count number of bits and returning the result as "2 raised to the power of count"-1.Complexity
Time complexity: O(logN) | SPD-LEGEND | NORMAL | 2025-01-25T06:51:10.647837+00:00 | 2025-01-25T06:51:10.647837+00:00 | 1 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Easy one!
# Approach
<!-- Describe your approach to solving the problem. -->
while loop to count number of bits and returning the result as "2 raised to the power of count"-1.
# Complexity
- Time complexity: O(logN)
<!-- Add your time compl... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | 3370. Smallest Number With All Set Bits | 3370-smallest-number-with-all-set-bits-b-57mw | Complexity
Time complexity: O(n)
Space complexity: O(1)
Code | SiriusStella | NORMAL | 2025-01-22T03:21:38.586204+00:00 | 2025-01-22T03:21:38.586204+00:00 | 3 | false | # Complexity
- Time complexity: O(n)
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity: O(1)
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
```python []
class Solution(object):
def smallestNumber(self, n):
"""
:type n: int
:rtype: int
"""
... | 0 | 0 | ['Python'] | 0 |
smallest-number-with-all-set-bits | simple One-liner 100% java | simple-one-liner-100-java-by-prakharmish-a4ck | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | PrakharMishraEnginner | NORMAL | 2025-01-21T10:11:22.852964+00:00 | 2025-01-21T10:11:22.852964+00:00 | 3 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Java'] | 0 |
smallest-number-with-all-set-bits | The 2^m - 1 Binary Pattern Solution | the-2m-1-binary-pattern-solution-by-mpra-vkxl | IntuitionThe key insight comes from understanding how numbers with all 1's work in binary. When you have a number with m consecutive 1's in binary, it's equal t | mpractice | NORMAL | 2025-01-21T02:51:39.303831+00:00 | 2025-01-21T02:51:39.303831+00:00 | 1 | false | # Intuition
The key insight comes from understanding how numbers with all 1's work in binary. When you have a number with m consecutive 1's in binary, it's equal to 2^m - 1. This is because:
For example with m=4 bits:
1111₂ = 2⁴ - 1 = 16 - 1 = 15₁₀
Breaking this down: 1111₂ = 2³ + 2² + 2¹ + 2⁰ = 8 + 4 + 2 + 1 = 15
So... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | 0ms Python | 0ms-python-by-mubina1-blbr | Complexity
Time complexity: O(1)
Space complexity: O(1)
Code | mubina1 | NORMAL | 2025-01-19T14:52:55.232310+00:00 | 2025-01-19T14:52:55.232310+00:00 | 2 | false |
# Complexity
- Time complexity: O(1)
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity: O(1)
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
```python3 []
class Solution:
def smallestNumber(self, n: int) -> int:
a=bin(n).replace('0b', '')
return 2**len(a) - 1
... | 0 | 0 | ['Python3'] | 0 |
smallest-number-with-all-set-bits | Time Complexity : O( logn ) | Space Complexity : O( 1 ) | time-complexity-o-logn-space-complexity-e3kl5 | Code | Trigun_2005 | NORMAL | 2025-01-18T13:55:54.053781+00:00 | 2025-01-18T13:55:54.053781+00:00 | 3 | false | # Code
```cpp []
class Solution {
public:
int smallestNumber(int n) {
int result = 0;
while(n > result)
result = result*2 + 1;
return result;
}
};
``` | 0 | 0 | ['C++'] | 0 |
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