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department-highest-salary | SIMPLE LOGIC NO ADVANCE FUNCTION USED | simple-logic-no-advance-function-used-by-x3z7 | \nSELECT D.name AS DEPARTMENT , \n E.name AS EMPLOYEE , \n\t\t E.salary\n FROM EMPLOYEE AS E \n\t JOIN \n\t\t\t\t DEPARTMENT AS | recursive_coder | NORMAL | 2022-10-18T09:27:25.017522+00:00 | 2022-10-22T13:00:53.266168+00:00 | 1,921 | false | ```\nSELECT D.name AS DEPARTMENT , \n E.name AS EMPLOYEE , \n\t\t E.salary\n FROM EMPLOYEE AS E \n\t JOIN \n\t\t\t\t DEPARTMENT AS D \n\t\t\t\t ON E.departmentId = D.id\n WHERE E.salary = ( SELECT MAX(salary) # this subquery gives max salary of an department so that we can gene... | 7 | 0 | [] | 1 |
department-highest-salary | simplest solution | simplest-solution-by-invincible2511-qyab | \nselect d.name as Department ,e.name as Employee ,e.salary \nfrom Employee e, Department d \nwhere e.DepartmentId = d.id and (DepartmentId,Salary) in \n(select | Invincible2511 | NORMAL | 2022-09-03T17:55:49.653021+00:00 | 2022-09-03T17:55:49.653064+00:00 | 3,665 | false | ```\nselect d.name as Department ,e.name as Employee ,e.salary \nfrom Employee e, Department d \nwhere e.DepartmentId = d.id and (DepartmentId,Salary) in \n(select DepartmentId,max(Salary) as max from Employee group by DepartmentId)\n``` | 7 | 0 | ['MySQL'] | 3 |
department-highest-salary | clean code, I was upset about the discussion, none was clear. | clean-code-i-was-upset-about-the-discuss-8ktp | Upvote if you like the cleanliness!! \n\nwith cte as(\nselect d.Name as Department, \n e.Name as Employee, \n e.Salary as Salary,\n rank() over(partiti | shuvokamal | NORMAL | 2021-02-16T23:52:12.602151+00:00 | 2021-02-16T23:52:12.602193+00:00 | 403 | false | Upvote if you like the cleanliness!! \n\nwith cte as(\nselect d.Name as Department, \n e.Name as Employee, \n e.Salary as Salary,\n rank() over(partition by d.Name Order by Salary desc) as ranks\n from Employee e inner join Department d on d.Id = e.Departmentid)\n \nselect \nDepartment,\nEmployee, \nSala... | 7 | 0 | [] | 1 |
department-highest-salary | MYSQL- Easy Solution - Window Function and CTE | mysql-easy-solution-window-function-and-dpnx5 | \n# Code\n\nwith new as\n(select *, dense_rank() over(partition by departmentId order by salary desc) as rn from employee)\n\nselect d.name as department, new.n | KG-Profile | NORMAL | 2024-04-14T14:59:07.348241+00:00 | 2024-06-12T16:49:16.006078+00:00 | 746 | false | \n# Code\n```\nwith new as\n(select *, dense_rank() over(partition by departmentId order by salary desc) as rn from employee)\n\nselect d.name as department, new.name as employee , salary from new\njoin department d on d.id=new.departmentId\nwhere rn=1\n``` | 6 | 0 | ['MySQL'] | 0 |
department-highest-salary | ✅ Pandas Beginner Friendly Solution 🔥 | pandas-beginner-friendly-solution-by-pni-oo7p | \uD83D\uDD3C IF YOU FIND THIS POST HELPFUL PLEASE UPVOTE \uD83D\uDC4D\n\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department | pniraj657 | NORMAL | 2023-08-18T15:04:52.314472+00:00 | 2023-08-18T15:04:52.314503+00:00 | 508 | false | **\uD83D\uDD3C IF YOU FIND THIS POST HELPFUL PLEASE UPVOTE \uD83D\uDC4D**\n```\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n \n merged_df = employee.merge(department, left_on = \'departmentId\', right_on = \'id\')\n \n merged_df = ... | 6 | 0 | ['Python'] | 0 |
department-highest-salary | MS SQL| two approach | subquery| group by | join | ms-sql-two-approach-subquery-group-by-jo-u4jr | Approach 1\n\nselect d.name as Department, e.name as Employee, e.salary as Salary \nfrom Employee e join Department d on e.departmentId = d.id\nwhere 1 > (selec | kenechi03 | NORMAL | 2022-03-23T07:47:52.076726+00:00 | 2023-09-10T21:49:26.449904+00:00 | 1,077 | false | Approach 1\n```\nselect d.name as Department, e.name as Employee, e.salary as Salary \nfrom Employee e join Department d on e.departmentId = d.id\nwhere 1 > (select count(salary) \n from Employee e1 \n where e1.salary > e.salary and e1.departmentId = e.departmentId);\n\n```\n\nApproach 2\n\n```\ns... | 6 | 0 | ['MS SQL Server'] | 1 |
department-highest-salary | Simple Using RANK() function🌻 | simple-using-rank-function-by-ravithemor-jj7r | Intuition\nThe query selects the Department name, Employee name, and Salary from a derived table (t1) that includes the Department name, Employee name, Salary, | ravithemore | NORMAL | 2023-11-17T06:27:24.770799+00:00 | 2023-11-17T06:27:24.770829+00:00 | 849 | false | # Intuition\nThe query selects the Department name, Employee name, and Salary from a derived table (t1) that includes the Department name, Employee name, Salary, and the rank of each employee within their department based on salary in descending order. The outer query then filters the results to only include rows where... | 5 | 0 | ['MySQL'] | 1 |
department-highest-salary | Easy-Peasy Solution | easy-peasy-solution-by-priyanka8d19-sk45 | Code\n\n# Write your MySQL query statement below\n\nselect d.name as department,e.name as employee ,e.salary from employee as e \njoin \ndepartment as d on e.de | priyanka8d19 | NORMAL | 2023-05-07T10:07:03.377465+00:00 | 2023-05-07T10:07:03.377499+00:00 | 3,779 | false | # Code\n```\n# Write your MySQL query statement below\n\nselect d.name as department,e.name as employee ,e.salary from employee as e \njoin \ndepartment as d on e.departmentId=d.id \n where (e.departmentId,e.salary) in (\n select departmentId , max(salary) from employee\n group by departmentId\n);\n``` | 5 | 0 | ['MySQL'] | 1 |
department-highest-salary | EASY MySQL QUERY💯👌 | easy-mysql-query-by-dipesh_12-810u | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | dipesh_12 | NORMAL | 2023-03-21T06:34:23.120755+00:00 | 2023-03-21T06:34:23.120789+00:00 | 3,315 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 5 | 0 | ['MySQL'] | 0 |
department-highest-salary | Simple MySQL Querry | simple-mysql-querry-by-user6774u-w9ss | \nSELECT \n dep.Name as Department,\n emp.Name as Employee,\n emp.Salary \nfrom \n Department dep,\n Employee emp \nwhere \n emp.DepartmentId | user6774u | NORMAL | 2022-03-21T05:08:27.773532+00:00 | 2022-03-21T05:08:27.773570+00:00 | 311 | false | ```\nSELECT \n dep.Name as Department,\n emp.Name as Employee,\n emp.Salary \nfrom \n Department dep,\n Employee emp \nwhere \n emp.DepartmentId = dep.Id \nand \n emp.Salary=\n (Select \n max(Salary) \n from \n Employee emp2 \n where \n emp2.D... | 5 | 0 | ['MySQL'] | 0 |
department-highest-salary | group by and having || oracle | group-by-and-having-oracle-by-abhinavred-ppfa | \n/* Write your PL/SQL query statement below */\nselect d.name department,e.name employee ,e.salary salary from employee e,department d where e.departmentid=d.i | abhinavreddy19 | NORMAL | 2021-07-18T13:43:53.108969+00:00 | 2021-07-18T13:43:53.109012+00:00 | 935 | false | ```\n/* Write your PL/SQL query statement below */\nselect d.name department,e.name employee ,e.salary salary from employee e,department d where e.departmentid=d.id and\ne.salary=(select max(distinct salary) from employee group by departmentid having departmentid=e.departmentid);\n``` | 5 | 0 | ['Oracle'] | 0 |
department-highest-salary | simple MYSQL query | simple-mysql-query-by-samarthtandon97-sp3s | \nSELECT \n d.Name AS Department, e.Name AS Employee, e.Salary AS Salary\nFROM \n Employee AS e, Department AS d\nWHERE \n e.DepartmentID = d.Id\n A | samarthtandon97 | NORMAL | 2019-12-02T10:08:09.133171+00:00 | 2019-12-02T10:08:09.133208+00:00 | 465 | false | ```\nSELECT \n d.Name AS Department, e.Name AS Employee, e.Salary AS Salary\nFROM \n Employee AS e, Department AS d\nWHERE \n e.DepartmentID = d.Id\n AND\n e.Salary = (SELECT \n MAX(Salary) \n FROM \n Employee\n WHERE\n ... | 5 | 0 | [] | 0 |
department-highest-salary | MSSQL Window function | mssql-window-function-by-pogodin-032m | \nSELECT\n d.Name AS Department,\n Sel.Name AS Employee,\n Sel.Salary AS Salary\nFROM\n(\n SELECT\n Name,\n Salary,\n Departmen | pogodin | NORMAL | 2019-07-31T19:28:51.141055+00:00 | 2019-07-31T19:28:51.141125+00:00 | 845 | false | ```\nSELECT\n d.Name AS Department,\n Sel.Name AS Employee,\n Sel.Salary AS Salary\nFROM\n(\n SELECT\n Name,\n Salary,\n DepartmentId,\n DENSE_RANK() OVER (PARTITION BY DepartmentId ORDER BY Salary DESC) AS dr\n FROM Employee \n) AS Sel\nINNER JOIN Department d ON d.Id = Sel.D... | 5 | 0 | [] | 2 |
department-highest-salary | SIMPLEST PANDAS SOLUTION WITH EXPLANTION ❤ | simplest-pandas-solution-with-explantion-zosf | IntuitionApproach
Merge DataFrames: Combine the employee and department DataFrames using departmentId (from employee) and id (from department) to include depar | Y4heW1qDC3 | NORMAL | 2025-01-14T16:12:00.496599+00:00 | 2025-01-14T16:12:00.496599+00:00 | 908 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->Here’s a explanation of the code:
1. Merge DataFrames: Combine the employee and department DataFrames using departmentId (from employee) and id (from department) to include... | 4 | 0 | ['Pandas'] | 0 |
department-highest-salary | Department Highest Salary, simple pandas solution | department-highest-salary-simple-pandas-fgit3 | \n\n# Code\n\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n \n df = employee.m | Shariq20220 | NORMAL | 2024-07-23T10:50:39.831477+00:00 | 2024-07-23T10:50:39.831509+00:00 | 941 | false | \n\n# Code\n```\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n \n df = employee.merge(department, left_on =\'departmentId\', right_on = \'id\', how =\'inner\')\n\n df[\'max_salary\'] = df.groupby(\'name_y\') [\'salary\'].transform(max)... | 4 | 0 | ['Database', 'Python', 'Python3', 'Pandas'] | 0 |
department-highest-salary | BEST solutions || MySQL || Pandas || Beats 100% !! | best-solutions-mysql-pandas-beats-100-by-zxfm | Code\n\n# Write your MySQL query statement below\nSELECT D.Name AS Department, E.Name AS Employee, E.Salary \nFROM Employee E, Department D \nWHERE E.Department | prathams29 | NORMAL | 2023-08-02T01:56:27.129309+00:00 | 2023-08-02T01:56:27.129327+00:00 | 1,536 | false | # Code\n```\n# Write your MySQL query statement below\nSELECT D.Name AS Department, E.Name AS Employee, E.Salary \nFROM Employee E, Department D \nWHERE E.DepartmentId = D.id AND (DepartmentId,Salary) in \n (SELECT DepartmentId,max(Salary) as max FROM Employee GROUP BY DepartmentId)\n```\n```\nimport pandas as pd\n\nd... | 4 | 0 | ['MySQL', 'Pandas'] | 0 |
department-highest-salary | MySQL Solution for Department Highest Salary Problem | mysql-solution-for-department-highest-sa-jcat | Intuition\n Describe your first thoughts on how to solve this problem. \nThe goal is to find employees who have the highest salary in each department. To achiev | Aman_Raj_Sinha | NORMAL | 2023-07-03T03:49:22.586331+00:00 | 2023-07-03T03:49:22.586350+00:00 | 2,517 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe goal is to find employees who have the highest salary in each department. To achieve this, we need to compare the salary of each employee within their respective department and select the ones with the maximum salary.\n\n# Approach\n<... | 4 | 0 | ['MySQL'] | 0 |
department-highest-salary | SIMPLE and EASY TO UNDERSTAND SOLUTION || MySQL | simple-and-easy-to-understand-solution-m-0vtg | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Yashkumar_Sawarkar | NORMAL | 2023-03-09T11:33:59.267204+00:00 | 2023-03-09T11:33:59.267246+00:00 | 2,645 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 4 | 0 | ['MySQL'] | 0 |
department-highest-salary | Accepted simple oracle | accepted-simple-oracle-by-krystali-52h1 | oracle\n\nselect d.Name as Department, e.Name as Employee, e.Salary\nfrom Department d inner join Employee e on d.Id = e.DepartmentId\nwhere (e.Salary, e.Depart | krystali | NORMAL | 2020-12-19T16:15:32.927150+00:00 | 2020-12-19T16:15:32.927180+00:00 | 315 | false | oracle\n```\nselect d.Name as Department, e.Name as Employee, e.Salary\nfrom Department d inner join Employee e on d.Id = e.DepartmentId\nwhere (e.Salary, e.DepartmentId) in (select max(Salary), DepartmentId from Employee group by DepartmentId)\n``` | 4 | 0 | ['Oracle'] | 1 |
department-highest-salary | Accepted Solution without using Max() function | accepted-solution-without-using-max-func-4ecn | select b.Name Department, a.Name Employee, a.Salary from\n (\n select a.Name, a.Salary, a.DepartmentId \n from Employee a left outer join Emplo | baiji | NORMAL | 2015-02-07T19:57:14+00:00 | 2015-02-07T19:57:14+00:00 | 1,063 | false | select b.Name Department, a.Name Employee, a.Salary from\n (\n select a.Name, a.Salary, a.DepartmentId \n from Employee a left outer join Employee b\n on a.DepartmentId = b.DepartmentId \n and a.Salary < b.Salary\n where b.Id is null\n ) a join Department b\n on a.Departm... | 4 | 1 | [] | 1 |
department-highest-salary | 🏆🏆Beats 97%| 📈📈Easy Solution |Python Pandas | beats-97-easy-solution-python-pandas-by-waa3k | \n\n\n# Intuition\n Describe your first thoughts on how to solve this problem. \n\uD83E\uDD14When working with organizational data, it\'s common to analyze empl | u23cs159 | NORMAL | 2024-06-09T07:56:59.878554+00:00 | 2024-06-09T07:56:59.878573+00:00 | 1,219 | false | \n\n\n# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\uD83E\uDD14When working with organizational data, it\'s common to analyze employee salaries to... | 3 | 0 | ['Python3', 'Pandas'] | 0 |
department-highest-salary | MS SQL SERVER - Subqueries - CTE | ms-sql-server-subqueries-cte-by-lshigami-fdvu | \n\n# Subqueries \n\n/* Write your T-SQL query statement below */\nselect d.name Department , e.name Employee ,salary Salary \nfrom employee e\njoin department | lshigami | NORMAL | 2024-05-01T16:43:05.956626+00:00 | 2024-05-01T16:44:43.704779+00:00 | 1,687 | false | \n\n# Subqueries \n```\n/* Write your T-SQL query statement below */\nselect d.name Department , e.name Employee ,salary Salary \nfrom employee e\njoin department d\non e.departmentId =d.id\nwhere salary = \n(select max(salary) from employee t where t.departmentId =e.departmentId )\n\n```\n# CTE \n```\nWITH emp as (\n... | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | ✅ 100% EASY || FAST 🔥|| CLEAN SOLUTION 🌟 | 100-easy-fast-clean-solution-by-vinay_ra-xow1 | \n Add your space complexity here, e.g. O(n) \n\n# Code\n\n# Write your MySQL query statement below\nselect department, Employee, salary from(\nselect d.name as | Vinay_Raju | NORMAL | 2023-10-14T21:25:24.174785+00:00 | 2023-10-14T21:25:24.174804+00:00 | 234 | false | \n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\n# Write your MySQL query statement below\nselect department, Employee, salary from(\nselect d.name as department,e.name as Employee,e.salary, dense_rank() over(partition by d.name order by salary desc) as rank_\n from Employee e join department d ... | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | Pandas | SQL | Explained Step By Step | Department Highest Salary | pandas-sql-explained-step-by-step-depart-bs45 | \nsee the Successfully Accepted Submission\nPython\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd | Khosiyat | NORMAL | 2023-10-03T17:13:00.371193+00:00 | 2023-10-03T17:13:00.371221+00:00 | 946 | false | \n[see the Successfully Accepted Submission]( https://leetcode.com/submissions/detail/1056909975/)\n```Python\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n \n merged_employee = employee.merge(\n department, left_on=\'departmentId\... | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | Pandas Simple Solution | pandas-simple-solution-by-hayyan_hajwani-nt38 | Intuition\n Describe your first thoughts on how to solve this problem. \nEasy Solution you will understand once you see the code\n\n# Approach\n Describe your a | Hayyan_Hajwani | NORMAL | 2023-08-07T18:20:28.362257+00:00 | 2023-08-07T18:20:28.362280+00:00 | 427 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nEasy Solution you will understand once you see the code\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexit... | 3 | 0 | ['Pandas'] | 0 |
department-highest-salary | EASY MYSQL SOLUTION | easy-mysql-solution-by-2005115-60be | \n\n# Code\n\nSELECT D.Name AS Department ,E.Name AS Employee ,E.Salary \nfrom \n\tEmployee E,\n\tDepartment D \nWHERE E.DepartmentId = D.id \n AND (Department | 2005115 | NORMAL | 2023-07-13T14:25:31.236724+00:00 | 2023-07-13T14:25:31.236758+00:00 | 1,061 | false | \n\n# Code\n```\nSELECT D.Name AS Department ,E.Name AS Employee ,E.Salary \nfrom \n\tEmployee E,\n\tDepartment D \nWHERE E.DepartmentId = D.id \n AND (DepartmentId,Salary) in \n (SELECT DepartmentId,max(Salary) as max FROM Employee GROUP BY DepartmentId)\n``` | 3 | 0 | ['MySQL'] | 1 |
department-highest-salary | Solved via CTE | solved-via-cte-by-shnitsel666-fgqo | Code\n\n;WITH emp as (\n select Max(salary) as maxSalary, departmentId from Employee\n group by\n departmentId\n)\n\nselect e.name as Employee, e.salary as S | shnitsel666 | NORMAL | 2023-05-16T16:38:48.761242+00:00 | 2023-05-16T16:38:48.761280+00:00 | 1,987 | false | # Code\n```\n;WITH emp as (\n select Max(salary) as maxSalary, departmentId from Employee\n group by\n departmentId\n)\n\nselect e.name as Employee, e.salary as Salary, d.name as Department from Employee e \ninner join Department d\non d.id = e.departmentId\ninner join emp\non emp.maxSalary = e.salary and emp.depart... | 3 | 0 | ['MS SQL Server'] | 1 |
department-highest-salary | ✅ SQL || Multiple Approaches || Easy to understand | sql-multiple-approaches-easy-to-understa-wbe5 | I just found this Blog and Github repository with solutions to Leetcode problems.\nhttps://leet-codes.blogspot.com/2022/10/department-highest-salary.html\nIt ha | pmistry_ | NORMAL | 2022-11-15T02:39:05.277240+00:00 | 2022-11-15T02:39:05.277287+00:00 | 1,351 | false | I just found this Blog and Github repository with solutions to Leetcode problems.\nhttps://leet-codes.blogspot.com/2022/10/department-highest-salary.html\nIt has solutions to almost every problem on Leetcode, and I recommend checking it out.\nNote: You can bookmark it as a resource, and approach. Other approaches are i... | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | 93% FASTER | 93-faster-by-rikam-nvdr | \n\n\n\nSELECT Department, Employee, Salary \nFROM ( \n SELECT *, rank() over(PARTITION BY Department ORDER BY Salary DESC) AS Highest_Salaries \n | rikam | NORMAL | 2022-11-14T10:41:59.933335+00:00 | 2022-11-14T10:41:59.933375+00:00 | 857 | false | \n\n\n```\nSELECT Department, Employee, Salary \nFROM ( \n SELECT *, rank() over(PARTITION BY Department ORDER BY Salary DESC) AS Highest_Salaries \n FROM (\n SELECT d.name AS Depar... | 3 | 0 | [] | 0 |
department-highest-salary | MYSQL subquery, easy to understand | mysql-subquery-easy-to-understand-by-wil-rgmf | \nselect d.name as department,e.name as employee,salary\nfrom department d\njoin employee e\non d.id = e.departmentid\nwhere (departmentid,salary ) in\n(select | william_26 | NORMAL | 2022-10-15T05:58:08.652759+00:00 | 2022-10-15T05:58:08.652785+00:00 | 351 | false | ```\nselect d.name as department,e.name as employee,salary\nfrom department d\njoin employee e\non d.id = e.departmentid\nwhere (departmentid,salary ) in\n(select departmentid,max(salary) from employee group by departmentid);\n```\nBreaking the code\n\n1 inside the subquerry, we can get the max salary for each departme... | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | Easy solution by JOIN & GROUP BY in MySQL beats 72.88% runtimes & 100% memory | easy-solution-by-join-group-by-in-mysql-z21vj | ```\nSELECT \n\te2.departmentname AS Department,\n e1.name AS Employee,\n e1.salary AS Salary \nFROM employee e1 JOIN \n(\n\tSELECT \t\n\t\te.departmentid | pritom5928 | NORMAL | 2022-09-18T16:39:15.347378+00:00 | 2022-09-18T16:39:15.347413+00:00 | 110 | false | ```\nSELECT \n\te2.departmentname AS Department,\n e1.name AS Employee,\n e1.salary AS Salary \nFROM employee e1 JOIN \n(\n\tSELECT \t\n\t\te.departmentid, \n d.name AS departmentname, \n max(e.salary) AS maxsalary \n FROM employee e JOIN department d ON e.departmentid = d.id \n\tGROUP BY e.depar... | 3 | 0 | ['MySQL'] | 1 |
department-highest-salary | Inner Join - where - group by | 70.20% time | inner-join-where-group-by-7020-time-by-p-k73k | \n# Write your MySQL query statement below\nselect Department.name as Department, Employee.name as Employee, Employee.salary as salary\nfrom Employee\ninner joi | photon_einstein | NORMAL | 2022-04-23T22:54:14.673074+00:00 | 2022-04-23T22:54:14.673105+00:00 | 167 | false | ```\n# Write your MySQL query statement below\nselect Department.name as Department, Employee.name as Employee, Employee.salary as salary\nfrom Employee\ninner join Department on\nemployee.departmentId = department.id\nwhere \n(employee.departmentId, salary) IN (\n select DepartmentId, max(salary)\n from Employee... | 3 | 0 | [] | 0 |
department-highest-salary | Correlated subqueries | correlated-subqueries-by-calvinliang-mj61 | SELECT d.name AS Department, e.name AS Employee, Salary\nFROM Employee e\nJOIN department d ON e.departmentId = d.id\nWHERE salary = (SELECT MAX(salary) FROM em | calvinliang | NORMAL | 2022-03-05T20:22:35.933368+00:00 | 2022-03-05T20:22:35.933411+00:00 | 166 | false | SELECT d.name AS Department, e.name AS Employee, Salary\nFROM Employee e\nJOIN department d ON e.departmentId = d.id\nWHERE salary = (SELECT MAX(salary) FROM employee WHERE departmentId = e.departmentId )\n\nI learned that from Mosh | 3 | 0 | ['MySQL'] | 1 |
department-highest-salary | Solution with explanation using RANK() in MySQL | solution-with-explanation-using-rank-in-mnc4r | This query can be written using INNER JOIN and/or Sub-query. This solution shows a way of writing it using RANK() function.\n\nStep 1\nWe need to rank the empl | iamrafiul | NORMAL | 2021-10-15T12:58:54.098383+00:00 | 2021-10-15T13:00:59.360899+00:00 | 356 | false | This query can be written using INNER JOIN and/or Sub-query. This solution shows a way of writing it using `RANK()` function.\n\n**`Step 1`**\nWe need to rank the employees based on their salaries for each department\n\n```\nSELECT\n\td.Name AS Department,\n\te.Name as Employee,\n\te.Salary,\n\t/* Ranking employee bas... | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | Intuitive Solution | intuitive-solution-by-divyeshgarg-2lii | Approach/Steps:\n1. Calculate department wise highest salaries\n\t\n\tselect DepartmentId, max(Salary) from Employee group by DepartmentId\n\t\n2. Fetch all Emp | divyeshgarg | NORMAL | 2021-09-21T10:20:17.852527+00:00 | 2021-09-21T10:20:17.852558+00:00 | 205 | false | Approach/Steps:\n1. Calculate department wise highest salaries\n\t```\n\tselect DepartmentId, max(Salary) from Employee group by DepartmentId\n\t```\n2. Fetch all Employees which are getting highest salary in the department\n\t```\n\tselect * from Employee\n\twhere (DepartmentId, Salary) in \n\t(select DepartmentId, ma... | 3 | 0 | ['MySQL'] | 1 |
department-highest-salary | Using Subquery | using-subquery-by-sanjaychandak95-44uz | \nselect max(e2.salary) from employee e2 where e2.departmentid = e.departmentid\n\nthis query will give maximum salary for one departmentId\nand use this result | sanjaychandak95 | NORMAL | 2021-09-17T04:47:53.448615+00:00 | 2021-09-17T04:48:12.706476+00:00 | 250 | false | ```\nselect max(e2.salary) from employee e2 where e2.departmentid = e.departmentid\n```\nthis query will give maximum salary for one departmentId\nand use this result to our main query so the result will be like below:\n\n```\nselect d.name as Department, e.name as Employee, e.salary as Salary\nfrom department d , Empl... | 3 | 0 | [] | 0 |
department-highest-salary | Using inner join, easy to understand | using-inner-join-easy-to-understand-by-5-71l5 | \nSELECT Department.Name AS Department, Employee.Name AS Employee, Employee.Salary AS Salary\nFROM Employee INNER JOIN Department\nON Employee.DepartmentId =Dep | 5899biswas | NORMAL | 2021-07-23T18:06:20.171961+00:00 | 2021-07-23T18:06:20.172029+00:00 | 428 | false | ```\nSELECT Department.Name AS Department, Employee.Name AS Employee, Employee.Salary AS Salary\nFROM Employee INNER JOIN Department\nON Employee.DepartmentId =Department.Id\nWHERE Employee.Salary=\n (\n SELECT MAX(Salary) FROM Employee \n WHERE Employee.DepartmentId=Department.Id\n );\n\t``` | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | 【MySQL】simple window function | mysql-simple-window-function-by-qiaochow-sux9 | \nselect b.Name as Department, a.Name as Employee, Salary\nfrom \n# rank Salary in department\n(select *, dense_rank () over (partition by DepartmentId order by | qiaochow | NORMAL | 2021-06-22T20:13:50.667651+00:00 | 2021-06-22T20:15:07.941043+00:00 | 298 | false | ```\nselect b.Name as Department, a.Name as Employee, Salary\nfrom \n# rank Salary in department\n(select *, dense_rank () over (partition by DepartmentId order by Salary desc) as salaryRank\nfrom Employee) a \njoin Department b \non a.DepartmentId = b.Id and a.salaryRank = 1\n``` | 3 | 0 | ['MySQL'] | 0 |
department-highest-salary | Simple solution using WHERE and AND | simple-solution-using-where-and-and-by-e-80ku | \nSELECT D.NAME AS Department, E.NAME AS Employee, E.SALARY AS Salary\nFROM EMPLOYEE AS E, DEPARTMENT AS D\nWHERE D.ID = E.DEPARTMENTID\nAND E.SALARY = \n (S | emiliahep | NORMAL | 2021-06-09T17:52:24.219008+00:00 | 2021-06-09T17:52:24.219058+00:00 | 343 | false | ```\nSELECT D.NAME AS Department, E.NAME AS Employee, E.SALARY AS Salary\nFROM EMPLOYEE AS E, DEPARTMENT AS D\nWHERE D.ID = E.DEPARTMENTID\nAND E.SALARY = \n (SELECT MAX(SALARY) \n FROM EMPLOYEE AS E2 \n WHERE E2.DEPARTMENTID = D.ID)\n```\n\n\n | 3 | 0 | [] | 1 |
department-highest-salary | use dense_rank() and inner join | use-dense_rank-and-inner-join-by-xunjuey-9mr3 | \nSELECT Department, Employee, Salary\nFROM (SELECT D.Name AS Department, E.Name AS Employee, E.Salary AS Salary , DENSE_RANK() OVER(PARTITION BY E.DepartmentId | xunjueyulin | NORMAL | 2020-10-03T02:40:46.595174+00:00 | 2020-10-03T02:42:36.988316+00:00 | 258 | false | ```\nSELECT Department, Employee, Salary\nFROM (SELECT D.Name AS Department, E.Name AS Employee, E.Salary AS Salary , DENSE_RANK() OVER(PARTITION BY E.DepartmentId ORDER BY E.Salary DESC) RN\n FROM Employee E\n INNER JOIN Department D\n ON E.DepartmentId = D.Id)\nWHERE RN=1\n```\n\u4E00\u5F00\u59CB\u60F3\u7... | 3 | 0 | ['Oracle'] | 0 |
department-highest-salary | MySQL using inner join | mysql-using-inner-join-by-pallaviroy-16nn | \nselect d.Name as Department,\ne.Name as Employee,\ne.Salary\nfrom Employee e inner join Department d\non e.DepartmentId = d.Id\nwhere e.Salary = (select max(s | pallaviroy | NORMAL | 2020-05-21T01:55:08.679999+00:00 | 2020-05-21T01:55:08.680051+00:00 | 352 | false | ```\nselect d.Name as Department,\ne.Name as Employee,\ne.Salary\nfrom Employee e inner join Department d\non e.DepartmentId = d.Id\nwhere e.Salary = (select max(salary) from Employee where departmentId = d.Id);\n``` | 3 | 0 | [] | 0 |
department-highest-salary | 248ms Ans beats 99% and illustration | 248ms-ans-beats-99-and-illustration-by-y-k3yo | The most tricky part is to get the actual name of each department. Otherwise it is a simple question\nFirst we find the max price from the employee table of eac | ycchou | NORMAL | 2018-12-03T02:08:19.550259+00:00 | 2018-12-03T02:08:19.550305+00:00 | 513 | false | The most tricky part is to get the actual name of each department. Otherwise it is a simple question\nFirst we find the max price from the employee table of each departmentID\nSecond, join the filtered employee table and department table and get the name of department\n```\nselect Department.Name as Department, a.Name ... | 3 | 0 | [] | 2 |
department-highest-salary | What's wrong with my code? | whats-wrong-with-my-code-by-neverlate-le-6n36 | select Department.Name Department ,Employee.Name Employee, max(Salary) Salary\nfrom Employee join Department on Employee.DepartmentId = Department.ID \ngroup b | neverlate-leetcode | NORMAL | 2017-09-25T07:43:04.410000+00:00 | 2017-09-25T07:43:04.410000+00:00 | 558 | false | select Department.Name Department ,Employee.Name Employee, max(Salary) Salary\nfrom Employee join Department on Employee.DepartmentId = Department.ID \ngroup by Department.ID\norder by Department.ID\n\n{"headers": {"Employee": ["Id", "Name", "Salary", "DepartmentId"], "Department": ["Id", "Name"]}, "rows": {"Employee... | 3 | 0 | [] | 3 |
department-highest-salary | 📚 Easy and Simple Four Solutions With Explanation 🚀 | Beginner-Friendly 🎓 | Beats 98.88% ⚡ | easy-and-simple-four-solutions-with-expl-dwmm | 🎯 Approach 1: Using WITH Clause and DENSE_RANK📌🖥️Code🧠Complexity Analysis
CTE Execution (WITH Clause):
The MaxSalaryCTE computes a DENSE_RANK() for each empl | bulbul_rahman | NORMAL | 2025-03-28T12:11:30.341302+00:00 | 2025-03-28T12:11:30.341302+00:00 | 549 | false | # 🎯 Approach 1: Using WITH Clause and DENSE_RANK📌
# 🖥️Code
```mysql []
With MaxSalaryCTE AS
(
select *,
dense_rank() Over(Partition By DepartmentId order by Salary Desc) RN
from employee
)
Select
d.name Department,
m.name Employee,
m.salary Salary
From MaxSalaryC... | 2 | 0 | ['MySQL'] | 0 |
department-highest-salary | Easy Way To Resolve | easy-way-to-resolve-by-daniel_charle_j-9jqp | \n\n# Approach\n Describe your approach to solving the problem. \nCreated a temporary table first and got the Unique department_id and salaey, Then did a join w | Daniel_Charles_J | NORMAL | 2024-09-03T11:10:35.746985+00:00 | 2024-09-03T11:10:35.747016+00:00 | 649 | false | \n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nCreated a temporary table first and got the Unique department_id and salaey, Then did a join with two tables, used the temp table in the where condition.\n\n\n# Code\n```postgresql []\n-- Write your PostgreSQL query statement below\nWITH temp as (... | 2 | 0 | ['PostgreSQL'] | 0 |
department-highest-salary | Simple solution that beats 81% of Postgres users | simple-solution-that-beats-81-of-postgre-9lwp | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | pp0787 | NORMAL | 2024-04-08T22:30:46.817995+00:00 | 2024-04-08T22:30:46.818040+00:00 | 222 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['PostgreSQL'] | 1 |
department-highest-salary | PostGreSQL easy solution | postgresql-easy-solution-by-rdaaraujo-ymgu | Intuition\nThink on previous problems and used then to solve this one.\n\n# Approach\nEasy using the WHERE clause.\n\n# Complexity\n- Time complexity:\nNone\n\n | rdaaraujo | NORMAL | 2024-04-01T12:52:10.967003+00:00 | 2024-04-01T12:52:10.967029+00:00 | 403 | false | # Intuition\nThink on previous problems and used then to solve this one.\n\n# Approach\nEasy using the WHERE clause.\n\n# Complexity\n- Time complexity:\nNone\n\n- Space complexity:\nNone\n\n# Code\n```\n-- Write your PostgreSQL query statement below\nSELECT d.Name AS Department, e.Name As Employee, e.Salary AS Salary\... | 2 | 0 | ['PostgreSQL'] | 0 |
department-highest-salary | MySQL Clean Solution | mysql-clean-solution-by-shree_govind_jee-h15j | Code\n\n# Write your MySQL query statement below\nSELECT d.name AS Department, e.name AS Employee, e.salary AS Salary\nFROM Department d, Employee e\nWHERE e.de | Shree_Govind_Jee | NORMAL | 2024-03-08T04:55:43.990391+00:00 | 2024-03-08T04:55:43.990420+00:00 | 1,689 | false | # Code\n```\n# Write your MySQL query statement below\nSELECT d.name AS Department, e.name AS Employee, e.salary AS Salary\nFROM Department d, Employee e\nWHERE e.departmentId = d.id AND (e.departmentId, salary) IN (\n SELECT departmentId, MAX(salary)\n FROM Employee \n GROUP BY departmentId\n);\n``` | 2 | 0 | ['Database', 'MySQL'] | 0 |
department-highest-salary | Easy | Sub Query | easy-sub-query-by-cold_ice-g9yk | \n# Code\n\n# Write your MySQL query statement below\n\nwith cte as(\nselect e.name as Employee, e.salary, d.name as Department \nfrom Employee e join Departmen | Cold_Ice | NORMAL | 2024-02-13T14:08:52.126730+00:00 | 2024-02-13T14:08:52.126762+00:00 | 684 | false | \n# Code\n```\n# Write your MySQL query statement below\n\nwith cte as(\nselect e.name as Employee, e.salary, d.name as Department \nfrom Employee e join Department d\non e.departmentId = d.id \n)\nselect Employee, salary,Department from cte having (Department,salary) in \n(select Department,max(salary) as salary from ... | 2 | 0 | ['MySQL'] | 0 |
department-highest-salary | Fast and Simple Solution by using window func with description | fast-and-simple-solution-by-using-window-quj8 | Problem Statement\nGiven two tables Employee and Department with columns id, name, and salary in the Employee table, and id and name in the Department table, th | OnDecember | NORMAL | 2023-12-24T09:26:14.574227+00:00 | 2023-12-24T09:26:14.574259+00:00 | 2,112 | false | # Problem Statement\nGiven two tables `Employee` and `Department` with columns `id`, `name`, and `salary` in the `Employee` table, and `id` and `name` in the `Department` table, the task is to retrieve the top salaried employee from each department.\n\n## Intuition\nThe problem involves selecting the top salaried emplo... | 2 | 0 | ['MySQL'] | 0 |
department-highest-salary | Not fast, but simple | not-fast-but-simple-by-badsenseavail-7k8p | Code\n\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n#Find max salary in every depar | BadSenseAvail | NORMAL | 2023-12-04T14:09:10.519436+00:00 | 2023-12-04T14:12:38.135717+00:00 | 589 | false | # Code\n```\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n#Find max salary in every department\n high_dep = employee.groupby([\'departmentId\']).agg(max).reset_index()\n# Add employees who have these salaries in each department\n employee... | 2 | 0 | ['Pandas'] | 2 |
department-highest-salary | INNER JOIN Solurion of department highest salary problem | inner-join-solurion-of-department-highes-zkzn | Approach\n- The INNER JOIN keyword selects records that have matching values in both tables.\n- The WHERE clause is used to filter records. \n- The MAX() functi | tiwafuj | NORMAL | 2023-11-20T19:46:18.021144+00:00 | 2023-11-20T19:46:18.021233+00:00 | 129 | false | # Approach\n- The `INNER JOIN` keyword selects records that have matching values in both tables.\n- The `WHERE` clause is used to filter records. \n- The `MAX()` function returns the largest value of the selected column.\n- The `GROUP B`Y statement groups rows that have the same values into summary rows.\n# Code\n```\n... | 2 | 0 | ['Database', 'MySQL'] | 0 |
department-highest-salary | RANK || DENSE_RANK || MySQL | rank-dense_rank-mysql-by-akanksha_23x07-p7ex | Intuition\n\n\n# Approach\n\n\n# Complexity\n- Time complexity:\nBeats 93.18% of users with MySQL\n\n- Space complexity:\n\n\n# Code\n\n# Write your MySQL query | akanksha_23x07 | NORMAL | 2023-10-29T08:31:40.488590+00:00 | 2023-10-29T08:31:40.488607+00:00 | 11 | false | # Intuition\n\n\n# Approach\n\n\n# Complexity\n- Time complexity:\nBeats 93.18% of users with MySQL\n\n- Space complexity:\n\n\n# Code\n```\n# Write your MySQL query statement below\nSELECT Department, Employee, Salary \nFROM\n(SELECT e.name as Employee, d.name AS Department, e.salary AS Salary,\nDENSE_RANK() OVER(PART... | 2 | 0 | ['MySQL'] | 0 |
department-highest-salary | ,✅ 100% EASY || Only in 3 lines🔥|| keep it simple and clean🌟 | 100-easy-only-in-3-lines-keep-it-simple-pfe2y | Intuition\nThink about the top employees that have highiest salaries, not the max\n\n\n# Code\n\nimport pandas as pd\n\ndef department_highest_salary(employee: | MehdiChellak | NORMAL | 2023-10-08T20:06:35.081233+00:00 | 2023-10-08T20:06:35.081261+00:00 | 217 | false | # Intuition\nThink about the top employees that have highiest salaries, not the max\n\n\n# Code\n```\nimport pandas as pd\n\ndef department_highest_salary(employee: pd.DataFrame, department: pd.DataFrame) -> pd.DataFrame:\n\n # Find the top 1 highest salaries in each department using nlargest,\n # keeping employe... | 2 | 0 | ['Pandas'] | 1 |
department-highest-salary | 184. Department Highest Salary💰 | 184-department-highest-salary-by-axatsac-8h29 | \n# Code\n\n# Write your MySQL query statement below\nSELECT DEPT.name AS Department, EMP.name AS Employee, EMP.salary AS Salary \nFROM Department DEPT, Employe | AxatSachani | NORMAL | 2023-08-29T16:44:32.898822+00:00 | 2023-08-29T16:44:32.898842+00:00 | 1,915 | false | \n# Code\n```\n# Write your MySQL query statement below\nSELECT DEPT.name AS Department, EMP.name AS Employee, EMP.salary AS Salary \nFROM Department DEPT, Employee EMP WHERE\nEMP.departmentId = DEPT.id AND (EMP.departmentId, salary) IN \n(SELECT departmentId, MAX(salary) FROM Employee GROUP BY departmentId)\n``` | 2 | 0 | ['Database', 'MySQL'] | 0 |
department-highest-salary | SQL and Pandas solution with explanation (SQL solution with Window function and nested inner join) | sql-and-pandas-solution-with-explanation-9b80 | Reflection on Complexity\nI would like to highlight the intricate nature of the SQL query I have developed, which I consider to be among the most intricate in m | luizasantos | NORMAL | 2023-08-12T13:14:12.379078+00:00 | 2023-08-12T13:14:12.379110+00:00 | 192 | false | # Reflection on Complexity\nI would like to highlight the intricate nature of the SQL query I have developed, which I consider to be among the most intricate in my repertoire. While I am fully cognizant of the potential avenues for enhancement, I take a sense of accomplishment in my achievement.\n\nCommencing with a ne... | 2 | 0 | ['Python', 'Python3', 'MySQL', 'MS SQL Server', 'Pandas'] | 0 |
department-highest-salary | MySQL Eassy solution | mysql-eassy-solution-by-triyambkeshtiwar-eznf | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | triyambkeshtiwari | NORMAL | 2023-08-06T15:22:35.663797+00:00 | 2023-08-06T15:22:35.663819+00:00 | 1,638 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['MySQL'] | 2 |
department-highest-salary | CTE || FIRST_VAL | cte-first_val-by-amogh_n21-k21y | \nwith temporary_table(name,salary,departmentId,top_salary) as\n(select e.name,e.salary,e.departmentId,FIRST_VALUE(e.salary) over(partition by departmentId orde | Amogh_N21 | NORMAL | 2023-08-05T13:23:52.502919+00:00 | 2023-08-05T13:23:52.502943+00:00 | 1,464 | false | ```\nwith temporary_table(name,salary,departmentId,top_salary) as\n(select e.name,e.salary,e.departmentId,FIRST_VALUE(e.salary) over(partition by departmentId order by salary desc) as top_salary from Employee e)\n\n\nselect d.name as Department, t.name as Employee, t.salary as Salary \nfrom temporary_table t inner... | 2 | 0 | [] | 1 |
department-highest-salary | Clear Solution | clear-solution-by-mohit94596-jutv | -- We can write an inner query to get max salary department wise. \n-- After that we can use that result and join it with employee and department\n-- to get dep | mohit94596 | NORMAL | 2023-08-02T02:58:00.997730+00:00 | 2023-08-02T02:58:00.997752+00:00 | 34 | false | -- We can write an inner query to get max salary department wise. \n-- After that we can use that result and join it with employee and department\n-- to get department name, employee name and max salary. \n\n/* Write your T-SQL query statement below */\n```\nselect d.name Department, emp.name Employee, temp.salary Sala... | 2 | 0 | [] | 0 |
department-highest-salary | Easy to understand Solution for maximum Salary of each Department | easy-to-understand-solution-for-maximum-4fjb7 | Intuition\n Describe your first thoughts on how to solve this problem. \nFind MAX salary for each department\n# Approach\n Describe your approach to solving the | jitendervirmani | NORMAL | 2023-07-10T03:19:07.249503+00:00 | 2023-07-10T03:19:07.249531+00:00 | 265 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nFind MAX salary for each department\n# Approach\n<!-- Describe your approach to solving the problem. -->\nFirst find MAX salary for each department, that can be done only with employee table with departmentId & Salary. then filter that da... | 2 | 0 | ['MySQL', 'Oracle', 'MS SQL Server'] | 0 |
department-highest-salary | Easy solution SQL SERVER | easy-solution-sql-server-by-tmuhammadqod-gq36 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | TMuhammadqodir | NORMAL | 2023-06-20T17:18:28.331020+00:00 | 2023-06-20T17:18:28.331044+00:00 | 492 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['MS SQL Server'] | 1 |
department-highest-salary | SOLUTION WITH WINDOW FUNCTION ( SQL SERVER ) | solution-with-window-function-sql-server-w9bc | Intuition\r\n Describe your first thoughts on how to solve this problem. \r\n\r\n# Approach\r\n Describe your approach to solving the problem. \r\n\r\n# Complex | cooking_Guy_9ice | NORMAL | 2023-05-20T15:38:03.066515+00:00 | 2023-05-20T15:38:03.066538+00:00 | 4,791 | false | # Intuition\r\n<!-- Describe your first thoughts on how to solve this problem. -->\r\n\r\n# Approach\r\n<!-- Describe your approach to solving the problem. -->\r\n\r\n# Complexity\r\n- Time complexity:\r\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\r\n\r\n- Space complexity:\r\n<!-- Add your space complexity ... | 2 | 0 | ['MS SQL Server'] | 2 |
department-highest-salary | MSSQL solution with DENSE_RANK() | mssql-solution-with-dense_rank-by-yektao-f252 | \n# Code\n\n/* Write your T-SQL query statement below */\nSELECT\n Department, Employee, Salary\nFROM\n(SELECT\n D.NAME AS Department,\n E.NAME AS Empl | yektaozan | NORMAL | 2023-04-18T11:20:54.860055+00:00 | 2023-04-18T11:20:54.860100+00:00 | 775 | false | \n# Code\n```\n/* Write your T-SQL query statement below */\nSELECT\n Department, Employee, Salary\nFROM\n(SELECT\n D.NAME AS Department,\n E.NAME AS Employee,\n E.SALARY AS Salary,\n DENSE_RANK() OVER(PARTITION BY D.NAME ORDER BY E.SALARY DESC) AS rank\nFROM \n EMPLOYEE E\nJOIN \n DEPARTMENT D ON ... | 2 | 0 | ['MS SQL Server'] | 1 |
department-highest-salary | Easy to understand Step-by-step Explanation 😄 (Beats 80%) | easy-to-understand-step-by-step-explanat-yh67 | Intuition\n Describe your first thoughts on how to solve this problem. \n\nYou can solve this problem by using a combination of GROUP BY and MAX(salary). The tr | hankehly | NORMAL | 2023-04-18T03:48:31.242971+00:00 | 2023-04-18T03:51:47.174136+00:00 | 1,461 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\nYou can solve this problem by using a combination of `GROUP BY` and `MAX(salary)`. The tricky part is that more than one employee may have the maximum department salary. This means that we have to split the search process into several s... | 2 | 0 | ['MySQL'] | 0 |
split-the-array | 【Video】Simple Hash solution - Python, JavaScript, Java and C++ | video-simple-hash-solution-python-javasc-q2ys | Intuition\nWe don\'t have to care about length of 2 arrays.\n\n# Solution Video\n\nhttps://youtu.be/YLZVibZ5RW8\n\n### \u2B50\uFE0F\u2B50\uFE0F Don\'t forget to | niits | NORMAL | 2024-02-25T15:28:35.217490+00:00 | 2024-02-25T15:28:35.217520+00:00 | 2,473 | false | # Intuition\nWe don\'t have to care about length of 2 arrays.\n\n# Solution Video\n\nhttps://youtu.be/YLZVibZ5RW8\n\n### \u2B50\uFE0F\u2B50\uFE0F Don\'t forget to subscribe to my channel! \u2B50\uFE0F\u2B50\uFE0F\n\n**\u25A0 Subscribe URL**\nhttp://www.youtube.com/channel/UC9RMNwYTL3SXCP6ShLWVFww?sub_confirmation=1\n\n... | 25 | 2 | ['C++', 'Java', 'Python3', 'JavaScript'] | 4 |
split-the-array | [Python3] 1 line solution using Counter || 33ms | python3-1-line-solution-using-counter-33-vfx4 | python3 []\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n return all(val <= 2 for val in Counter(nums).values())\n | yourick | NORMAL | 2024-02-25T05:26:00.104546+00:00 | 2024-02-25T07:39:12.681054+00:00 | 1,464 | false | ```python3 []\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n return all(val <= 2 for val in Counter(nums).values())\n``` | 18 | 0 | ['Python', 'Python3'] | 2 |
split-the-array | Beats 100% | Detailed Solution | Java, C, C++, JavaScript, Python ✅✅ | beats-100-detailed-solution-java-c-c-jav-bw0d | Its Easy, Just read \n# You can do it\n# Approach\n Describe your approach to solving the problem. \n1. int[] data = new int[101]; creates an integer array name | Ikapoor123 | NORMAL | 2024-02-25T04:13:36.885917+00:00 | 2024-02-26T05:53:45.836142+00:00 | 1,759 | false | # Its Easy, Just read \n# You can do it\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. int[] data = new int[101]; creates an integer array named data with a size of 101. This array will be used to store the frequency of each number in the input array nums.\n2. for (int i : nums) iterates over ... | 9 | 2 | ['Hash Table', 'Stack', 'Ordered Map', 'C', 'Suffix Array', 'Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 3 |
split-the-array | Python 3 || 1 line, Counter || T/S: 84% / 72% | python-3-1-line-counter-ts-84-72-by-spau-easv | \nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n \n return max(set(Counter(nums).values())) <= 2\n\nhttps://leetcode.com/p | Spaulding_ | NORMAL | 2024-02-25T04:49:28.257374+00:00 | 2024-06-12T04:02:00.293745+00:00 | 421 | false | ```\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n \n return max(set(Counter(nums).values())) <= 2\n```\n[https://leetcode.com/problems/split-the-array/submissions/1185447945/](https://leetcode.com/problems/split-the-array/submissions/1185447945/)\n\n\nI could be wrong, but I thin... | 8 | 0 | ['Python3'] | 0 |
split-the-array | ✅☑ Easy Java Solution | HashMap | 1ms 🔥 | easy-java-solution-hashmap-1ms-by-yashma-0vye | \n\n# Code\n\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n HashMap<Integer,Integer> table = new HashMap<>();\n for(int i | yashmahajan270502 | NORMAL | 2024-03-02T17:43:13.179267+00:00 | 2024-03-02T17:55:32.328031+00:00 | 449 | false | \n\n# Code\n```\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n HashMap<Integer,Integer> table = new HashMap<>();\n for(int i=0; i<nums.length; i++)\n {\n if(table.containsKey(nums[i]))\n {\n table.put(nums[i],table.get(nums[i])+1);\n ... | 7 | 0 | ['Java'] | 0 |
split-the-array | 👏Beats 98.75% of users with Java || Simple & Easy Array Approach 🔥💥 | beats-9875-of-users-with-java-simple-eas-lvfe | Intuition\nmake a array variable cnt and count the frequency of every element if any element\'s frequency is go to more than 2 simply return false.\n\n\n# I thi | Rutvik_Jasani | NORMAL | 2024-03-01T07:39:30.552716+00:00 | 2024-03-01T07:40:29.695887+00:00 | 288 | false | # Intuition\nmake a array variable cnt and count the frequency of every element if any element\'s frequency is go to more than 2 simply return false.\n\n\n# **I think This can Help you**\n {\n HashMap<Integer, Integer> hm=new HashMap<>();\n for(int i=0;i | 1asthakhushi1 | NORMAL | 2024-02-25T04:01:55.575453+00:00 | 2024-02-25T04:29:36.285371+00:00 | 999 | false | \n\n# Code\n```\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n HashMap<Integer, Integer> hm=new HashMap<>();\n for(int i=0;i<nums.length;i++){\n hm.put(nums[i],hm.getOrDefault(nums[i],0)+1);\n if(hm.get(nums[i])>2)\n return false;\n }\n ... | 5 | 0 | ['Hash Table', 'Java'] | 1 |
split-the-array | split the array | split-the-array-by-jamiyat-wktd | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Jamiyat | NORMAL | 2024-03-17T15:18:17.029900+00:00 | 2024-03-17T15:18:17.029930+00:00 | 203 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 4 | 0 | ['Python3'] | 0 |
split-the-array | 3046. Split the Array | 3046-split-the-array-by-pgmreddy-bl8x | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | pgmreddy | NORMAL | 2024-02-25T04:56:19.439911+00:00 | 2024-02-25T04:56:19.439929+00:00 | 220 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 4 | 0 | ['JavaScript'] | 3 |
split-the-array | ✅ Java Solution | Easy | java-solution-easy-by-harsh__005-oi8w | Code\nJava []\npublic boolean isPossibleToSplit(int[] nums) {\n\tMap<Integer, Integer> map = new HashMap<>();\n\tfor(int num : nums) map.put(num, map.getOrDefau | Harsh__005 | NORMAL | 2024-02-25T04:08:09.268301+00:00 | 2024-02-25T04:08:09.268326+00:00 | 442 | false | # Code\n```Java []\npublic boolean isPossibleToSplit(int[] nums) {\n\tMap<Integer, Integer> map = new HashMap<>();\n\tfor(int num : nums) map.put(num, map.getOrDefault(num, 0)+1);\n\n\tfor(int val : map.values()){\n\t\tif(val>2) return false;\n\t}\n\n\treturn true;\n}\n``` | 4 | 0 | ['Java'] | 1 |
split-the-array | 0ms 100% beat in java very easiest code 😊. | 0ms-100-beat-in-java-very-easiest-code-b-f5ok | Code | Galani_jenis | NORMAL | 2025-01-02T05:45:05.248689+00:00 | 2025-01-02T05:45:05.248689+00:00 | 396 | false | 
# Code
```java []
class Solution {
public boolean isPossibleToSplit(int[] nums) {
int[] numbers = new int[101];
// for (int i: nums)... | 3 | 0 | ['Java'] | 0 |
split-the-array | Just Understandin seconds | just-understandin-seconds-by-vansh0123-74i5 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | vansh0123 | NORMAL | 2024-08-28T14:09:34.831342+00:00 | 2024-08-28T14:09:34.831379+00:00 | 372 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 3 | 0 | ['Java'] | 0 |
split-the-array | Don't Use Hashmap. Use Arrays Instead of Hashmaps for O(1) Space. Achieves 100% Efficiency. | dont-use-hashmap-use-arrays-instead-of-h-73z2 | Intuition\nOur approach will be to use an index array to keep track of the frequency of each element in the input array. If any element appears more than twice, | muhammadfarhankt | NORMAL | 2024-03-27T06:29:09.922254+00:00 | 2024-03-27T06:40:22.662594+00:00 | 415 | false | # Intuition\nOur approach will be to use an index array to keep track of the frequency of each element in the input array. If any element appears more than twice, it is not possible to split the array as required.\n\n# Approach\nWe initialize an index array of size 100, as the elements in the input array are within the... | 3 | 0 | ['Array', 'Hash Table', 'Math', 'Counting', 'Python', 'C++', 'Java', 'Go', 'Python3', 'JavaScript'] | 0 |
split-the-array | Easy one line Solution | easy-one-line-solution-by-demonsword09-oiu6 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | DemonSword09 | NORMAL | 2024-03-05T06:01:23.625279+00:00 | 2024-03-05T06:01:23.625315+00:00 | 410 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 3 | 0 | ['Python3'] | 0 |
split-the-array | Python3 ✅✅✅ || Tiub-Recommended | python3-tiub-recommended-by-blackhole_ti-c0f3 | \n\n# Code\n\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n turn = 1\n half1 = []\n half2 = []\n for | Little_Tiub | NORMAL | 2024-03-03T05:21:39.618353+00:00 | 2024-03-03T05:21:39.618388+00:00 | 67 | false | \n\n# Code\n```\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n turn = 1\n half1 = []\n half2 = []\n for n in nums:\n if turn == 1:\n ... | 3 | 0 | ['Python3'] | 0 |
split-the-array | Frequency of each item should be less than 2 | frequency-of-each-item-should-be-less-th-alxk | \n# Code\n\nbool isPossibleToSplit(vector<int>& nums) {\n vector<int> freq(101, 0);\n for(auto n: nums) freq[n]++;\n for(auto f: freq) if(f > 2) return | kreakEmp | NORMAL | 2024-02-25T08:13:05.834685+00:00 | 2024-02-25T08:14:23.386643+00:00 | 871 | false | \n# Code\n```\nbool isPossibleToSplit(vector<int>& nums) {\n vector<int> freq(101, 0);\n for(auto n: nums) freq[n]++;\n for(auto f: freq) if(f > 2) return false;\n return true;\n}\n\n```\n\n---\n\n<b>Here is an article of my interview experience at Amazon, taht may be helpful for you: https://leetcode.com/d... | 3 | 0 | ['C++'] | 4 |
split-the-array | JS Solution | js-solution-by-bola-nabil-hrty | \n# Code\n\nvar isPossibleToSplit = function(nums) {\n if (nums.length % 2 !== 0) {\n return false;\n }\n\n const nums1 = new Set();\n const nums2 = new | bola-nabil | NORMAL | 2024-02-25T08:08:07.834794+00:00 | 2024-02-25T08:08:07.834813+00:00 | 149 | false | \n# Code\n```\nvar isPossibleToSplit = function(nums) {\n if (nums.length % 2 !== 0) {\n return false;\n }\n\n const nums1 = new Set();\n const nums2 = new Set();\n\n for (const num of nums) {\n if (!nums1.has(num)) {\n nums1.add(num);\n } else if (!nums2.has(num)) {\n nums2.add(num);\n } els... | 3 | 0 | ['JavaScript'] | 0 |
split-the-array | ✅Beats 100% Frequency Array || Split the Array || Simple solution in Java, C++, Python & javascript | beats-100-frequency-array-split-the-arra-bwrc | Intuition\nThe goal of the isPossibleToSplit function is to determine whether it is possible to split the given array nums into two parts (nums1 and nums2), eac | Mohit-P | NORMAL | 2024-02-25T04:28:53.352531+00:00 | 2024-02-25T04:28:53.352551+00:00 | 967 | false | # Intuition\nThe goal of the `isPossibleToSplit` function is to determine whether it is possible to split the given array `nums` into two parts (`nums1` and `nums2`), each containing distinct elements.\n\n# Approach\n1. **Frequency Array:**\n The code utilizes an array (`elementFrequency`) to store the frequency of ... | 3 | 0 | ['Array', 'Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 0 |
split-the-array | Easy Python Solution | easy-python-solution-by-_suraj__007-4xmc | Code\n\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n for i in range(len(nums)):\n if nums.count(nums[i])>2:\n | _suraj__007 | NORMAL | 2024-02-25T04:10:29.211113+00:00 | 2024-02-25T04:10:29.211138+00:00 | 130 | false | # Code\n```\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n for i in range(len(nums)):\n if nums.count(nums[i])>2:\n return False\n return True\n \n``` | 3 | 0 | ['Python3'] | 0 |
split-the-array | ✅HashMap solution || Split the array|| Simple solution in Java, C++, Python & javascript | hashmap-solution-split-the-array-simple-1jfpn | Intuition\nThe goal of the isPossibleToSplit function is to determine whether it is possible to split the given array nums into two distinct parts (nums1 and nu | Mohit-P | NORMAL | 2024-02-25T04:07:41.476198+00:00 | 2024-02-25T04:07:41.476223+00:00 | 841 | false | # Intuition\nThe goal of the `isPossibleToSplit` function is to determine whether it is possible to split the given array `nums` into two distinct parts (`nums1` and `nums2`), each containing distinct elements.\n\n# Approach\n1. **Frequency Map:**\n The code uses a HashMap (`map`) to keep track of the frequency of e... | 3 | 0 | ['Array', 'Hash Table', 'Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 1 |
split-the-array | Easy JAVA Solution | easy-java-solution-by-mayur0106-pbyz | \n- Time complexity: O(n)\n- Space complexity: O(n)\n\n\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n \n int n=nums.leng | mayur0106 | NORMAL | 2024-02-25T04:03:43.641282+00:00 | 2024-02-25T04:03:43.641317+00:00 | 333 | false | \n- Time complexity: O(n)\n- Space complexity: O(n)\n\n```\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n \n int n=nums.length;\n Map<Integer,Integer> map=new HashMap<>();\n for(int i=0;i<n;i++)\n {\n map.put(nums[i],map.getOrDefault(nums[i],0)+1);\... | 3 | 0 | ['Java'] | 0 |
split-the-array | ✅Easy Java Solution✅ | easy-java-solution-by-anshchaudhary1-2m12 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | anshchaudhary1 | NORMAL | 2024-02-25T04:01:23.012601+00:00 | 2024-02-25T04:01:23.012624+00:00 | 230 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 3 | 0 | ['Java'] | 1 |
split-the-array | O(n) python solution with explanation | on-python-solution-with-explanation-by-9-tpl0 | IntuitionSo, in this problem, we have to split the array into TWO parts. The splitting should be done in such a way that both parts should have distinct element | 9chaitanya11 | NORMAL | 2025-02-20T22:57:55.275643+00:00 | 2025-02-20T23:02:37.855034+00:00 | 183 | false | # Intuition
So, in this problem, we have to split the array into TWO parts. The splitting should be done in such a way that both parts should have distinct elements. We can solve this problem using hashmap.
# Approach
So, we will create a hashmap named count which will count the number of elements in the array. If the... | 2 | 0 | ['Python3'] | 0 |
split-the-array | Simple...Think Opposite | simplethink-opposite-by-hk_international-ouz3 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | HK_INTERNATIONAL | NORMAL | 2024-10-22T00:29:23.289826+00:00 | 2024-10-22T00:29:23.289863+00:00 | 115 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['Array', 'Hash Table', 'Counting', 'JavaScript'] | 1 |
split-the-array | 👏Beats 98.75% of users with Java || Simple & Easy Array Approach 🔥💥 | beats-9875-of-users-with-java-simple-eas-xv4h | \n\n# Code\n\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n int[] cnt = new int[101]; \n for(int i=0;i<nums.length;i++){ | Ankit1317 | NORMAL | 2024-07-31T06:10:34.094900+00:00 | 2024-07-31T06:10:34.094919+00:00 | 211 | false | \n\n# Code\n```\nclass Solution {\n public boolean isPossibleToSplit(int[] nums) {\n int[] cnt = new int[101]; \n for(int i=0;i<nums.length;i++){ \n cnt[nums[i]-1]++;\n if(cnt[nums[i]-1]>2){\n return false;\n }\n }\n return true; \n }\n}... | 2 | 0 | ['Array', 'Hash Table', 'Counting', 'Java'] | 1 |
split-the-array | Efficient Solution: Beats 90% in Runtime | efficient-solution-beats-90-in-runtime-b-5a72 | Intuition\nThe first thought is to check if every integer in the array appears exactly twice. If any integer appears more than twice or if the total number of e | ShreekrushnaDongare | NORMAL | 2024-07-26T18:10:51.623758+00:00 | 2024-07-26T18:10:51.623787+00:00 | 32 | false | ## Intuition\nThe first thought is to check if every integer in the array appears exactly twice. If any integer appears more than twice or if the total number of elements is odd, it would be impossible to form pairs.\n\n## Approach\n1. **Check array length:** If the length of the array is odd, return `false` since an o... | 2 | 0 | ['C++'] | 0 |
split-the-array | using map, easy C++ code | using-map-easy-c-code-by-divyam45-e195 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\nAny element\'s count > 2 will cause repetition in the splitted array\n De | divyam72 | NORMAL | 2024-07-01T02:29:21.410551+00:00 | 2024-07-01T02:29:21.410582+00:00 | 164 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\nAny element\'s count > 2 will cause repetition in the splitted array\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Sp... | 2 | 0 | ['Array', 'Hash Table', 'Counting', 'C++'] | 0 |
split-the-array | Easy solution in cpp !! Beats 92% user runtime !!! | easy-solution-in-cpp-beats-92-user-runti-idjw | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | parijatb_03 | NORMAL | 2024-06-19T22:28:13.572416+00:00 | 2024-06-19T22:28:13.572442+00:00 | 47 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['C++'] | 0 |
split-the-array | Easy Hash Solution || Beats 100% | easy-hash-solution-beats-100-by-shivamkh-h0sj | \n\n# C++\n\nclass Solution {\npublic:\n bool isPossibleToSplit(vector<int>& nums) {\n ios_base::sync_with_stdio(0);\n\n int freq[101] = {}; // | ShivamKhator | NORMAL | 2024-05-23T04:48:59.263924+00:00 | 2024-05-23T04:48:59.263955+00:00 | 69 | false | \n\n# C++\n```\nclass Solution {\npublic:\n bool isPossibleToSplit(vector<int>& nums) {\n ios_base::sync_with_stdio(0);\n\n int freq[101] = {}; // Initialize an array to store frequency of each number\n\n // Iterate through each element in the vector\n for (int num : nums)\n if... | 2 | 0 | ['Array', 'Hash Table', 'C++'] | 0 |
split-the-array | SIMPLE JAVA and PYTHON Solution || Beginner friendly || Without HashMap | simple-java-and-python-solution-beginner-bsg0 | Intuition\n Describe your first thoughts on how to solve this problem. \nThis function aims to determine whether it\'s possible to split an array into two non-e | Pushkar91949 | NORMAL | 2024-03-18T16:49:55.461726+00:00 | 2024-03-18T16:49:55.461755+00:00 | 120 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThis function aims to determine whether it\'s possible to split an array into two non-empty subsets, each having the same sum. Instead of using a dictionary to store the frequency of each number, it uses a list x of size 101, assuming the... | 2 | 0 | ['Array', 'Java', 'Python3'] | 0 |
split-the-array | ✅ Beats 98% | Simple 5 lines of code | beats-98-simple-5-lines-of-code-by-escap-o2lc | \n\n# Code\n\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n counter = Counter(nums)\n for f in counter.values():\n | durvesh_danve | NORMAL | 2024-03-16T18:18:12.134057+00:00 | 2024-03-16T18:18:12.134087+00:00 | 92 | false | \n\n# Code\n```\nclass Solution:\n def isPossibleToSplit(self, nums: List[int]) -> bool:\n counter = Counter(nums)\n for f in counter.values():\n if f > 2:\n return False\n return True\n \n``` | 2 | 0 | ['Python3'] | 0 |
split-the-array | Easy JavaScript Solution Beginner Level. | easy-javascript-solution-beginner-level-onp75 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | abhinandkbabu | NORMAL | 2024-03-07T03:33:29.532359+00:00 | 2024-03-07T03:33:29.532417+00:00 | 152 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['JavaScript'] | 1 |
split-the-array | 👏Beats 73.67% of users with Java || Easy & Simple HashMap Approach 🔥💥 | beats-7367-of-users-with-java-easy-simpl-1wpw | Intuition\nMake a Hashmap as a hm and store the all element\'s frequency and check if any element\'s frequency is more than 2 then return false, else return tru | Rutvik_Jasani | NORMAL | 2024-03-01T07:51:28.827643+00:00 | 2024-03-01T07:51:28.827675+00:00 | 216 | false | # Intuition\nMake a Hashmap as a hm and store the all element\'s frequency and check if any element\'s frequency is more than 2 then return false, else return true.\n\n# **I Think This can Help You**\n$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['Java'] | 0 |
split-the-array | ✅ 5 Variations | 5-variations-by-eleev-70uh | Solutions\nSwift []\nfinal class Solution {\n @_optimize(speed)\n func isPossibleToSplit(_ nums: [Int]) -> Bool {\n nums.withUnsafeBufferPointer {\ | eleev | NORMAL | 2024-02-25T16:22:51.264934+00:00 | 2024-02-25T16:22:51.264972+00:00 | 14 | false | # Solutions\n```Swift []\nfinal class Solution {\n @_optimize(speed)\n func isPossibleToSplit(_ nums: [Int]) -> Bool {\n nums.withUnsafeBufferPointer {\n var freqs = ContiguousArray<UInt8>(repeating:0, count: 101)\n for num in $0 {\n freqs[num] += 1\n if ... | 2 | 0 | ['Array', 'Hash Table', 'Swift'] | 0 |
split-the-array | more than 2 times occurence | more-than-2-times-occurence-by-ssmbforev-g6y1 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | ssmbforever | NORMAL | 2024-02-25T10:31:53.343206+00:00 | 2024-02-25T10:31:53.343229+00:00 | 102 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['Java'] | 0 |
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