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smallest-string-with-a-given-numeric-value | Simple + Intuitive|| Beginner Friendly || | simple-intuitive-beginner-friendly-by-pr-dita | \n\t string ans="";\n while(k)\n {\n\t\t\t int t=n-1; //remaining letters\n\t\t\t int t2=k-t; //finding t | prajjwal333 | NORMAL | 2022-03-22T04:19:46.628825+00:00 | 2022-03-22T04:26:54.267133+00:00 | 47 | false | ```\n\t string ans="";\n while(k)\n {\n\t\t\t int t=n-1; //remaining letters\n\t\t\t int t2=k-t; //finding the max value after removing the remaining letter\n int rem=t2/26; // checking for the max value\n char add;\n\t\t\t ... | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | Smallest String easy to understand JAVA solution | smallest-string-easy-to-understand-java-wc8cy | class Solution {\n public String getSmallestString(int n, int k) {\n //initializing array with size n\n char arr[]=new char[n]; \n //f | Sanku2906X | NORMAL | 2022-03-22T03:38:48.342259+00:00 | 2022-03-22T03:38:48.342299+00:00 | 64 | false | class Solution {\n public String getSmallestString(int n, int k) {\n //initializing array with size n\n char arr[]=new char[n]; \n //filling whole array with a\n Arrays.fill(arr,\'a\'); \n //for the a in array\n k-=n; \n //turn the character into ... | 2 | 0 | ['Array', 'Java'] | 1 |
smallest-string-with-a-given-numeric-value | Explaination || Greedy with proof | explaination-greedy-with-proof-by-ishubh-64bf | Since the constraints on k are suitable, we need not worry about edge cases.\nIntuition:\nlets say we have n spaces and k sum\n____________\nlets fill i=0, for | iShubhamRana | NORMAL | 2022-03-22T02:15:13.884543+00:00 | 2022-03-22T03:51:49.043623+00:00 | 58 | false | Since the constraints on k are suitable, we need not worry about edge cases.\n**Intuition**:\nlets say we have **n spaces and k sum**\n____________________________________________________________\nlets **fill i=0**, for every position **we have to fill the smallest alphabet possible such that after filling that alphabe... | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | Greedy O(n) Solution with Image Explanation | greedy-on-solution-with-image-explanatio-edgx | Leetcode 1663. Smallest String With A Given Numeric Value\n\nBy Frank Luo\n\n# Greedy\n\nAs we want to minimize the lexicographical order of the constructed str | longluo | NORMAL | 2022-03-22T02:06:15.058968+00:00 | 2022-11-15T02:33:26.589417+00:00 | 259 | false | [Leetcode](https://leetcode.com/) [1663. Smallest String With A Given Numeric Value](https://leetcode.com/problems/smallest-string-with-a-given-numeric-value/)\n\n***By Frank Luo***\n\n# Greedy\n\nAs we want to minimize the **lexicographical** order of the constructed string, let\'s start from the **beginning** of the ... | 2 | 0 | ['Greedy', 'Java'] | 0 |
smallest-string-with-a-given-numeric-value | py: smallest string with a given numeric val, easy | py-smallest-string-with-a-given-numeric-hpfbx | \nclass Solution:\n def getSmallestString(self, n: int, k: int) -> str:\n ans = []\n for i in range(1, n+1):\n j = max(1, k-(26*(n-i | snalli | NORMAL | 2021-09-17T07:42:34.375583+00:00 | 2021-09-17T07:42:34.375617+00:00 | 107 | false | ```\nclass Solution:\n def getSmallestString(self, n: int, k: int) -> str:\n ans = []\n for i in range(1, n+1):\n j = max(1, k-(26*(n-i)))\n ans.append(chr(ord(\'a\')+j-1))\n k -= j\n \n return \'\'.join(ans)\n``` | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | PYTHON FOR BEGINNERS | python-for-beginners-by-msustar-oznv | \tclass Solution:\n def getSmallestString(self, n: int, k: int) -> str:\n cantZ,rest,cantA,ch,backZ,digits=0,0,0,0,0,n\n cantZ=k//26\n r | msustar | NORMAL | 2021-09-03T14:11:31.727564+00:00 | 2021-09-03T14:11:31.727591+00:00 | 73 | false | \tclass Solution:\n def getSmallestString(self, n: int, k: int) -> str:\n cantZ,rest,cantA,ch,backZ,digits=0,0,0,0,0,n\n cantZ=k//26\n rest=k%26\n if rest>digits-cantZ:\n cantA=digits - cantZ-1\n ch=rest-cantA\n return "a"*cantA +chr(ch+96)+"z"*(cantZ) \n... | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | JAVA | beats 96% | java-beats-96-by-shwetali_ps-s3a9 | \npublic String getSmallestString(int n, int k) {\n char[] alphabets = new char[]{\'a\',\'b\',\'c\',\'d\',\'e\',\'f\',\n | shwetali_ps | NORMAL | 2021-04-09T19:27:59.456679+00:00 | 2021-04-09T19:27:59.456712+00:00 | 74 | false | ```\npublic String getSmallestString(int n, int k) {\n char[] alphabets = new char[]{\'a\',\'b\',\'c\',\'d\',\'e\',\'f\',\n \'g\',\'h\',\'i\',\'j\',\'k\',\'l\',\n \'m\',\'n\',\'o\',\'p\',\'q\',\'r\',\n ... | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | Python O(logn) Binary Search solution, faster than 91%, explained. | python-ologn-binary-search-solution-fast-a3te | If you think it through or see enough cases, you\'ll find this important pattern: \nThe solution is always formed by a bunch of \'a\'s, a bunch of \'z\'s and AT | G5-Qin | NORMAL | 2021-01-28T14:18:04.277094+00:00 | 2021-01-28T14:18:04.277134+00:00 | 128 | false | If you think it through or see enough cases, you\'ll find this important pattern: \n**The solution is always formed by a bunch of \'a\'s, a bunch of \'z\'s and AT MOST ONE character that is neither \'a\' or \'z\'.**\nIf you could not think it through, just do it reversely, if you have a solution for some case which con... | 2 | 1 | [] | 1 |
smallest-string-with-a-given-numeric-value | [Java] Smallest String With A Given Numeric Value | easy explanation | java-smallest-string-with-a-given-numeri-vmjg | \n\nProblem disection and solution approach\nSince there is a total order on the set of strings (as defined in task), a greedy approach constructing the solutio | fdokic | NORMAL | 2021-01-28T09:00:05.602325+00:00 | 2021-01-28T10:43:31.422964+00:00 | 232 | false | \n\n**Problem disection and solution approach**\nSince there is a total order on the set of strings (as defined in task), a greedy approach constructing the solution is sufficient, as for each index i of a string of length n, choosing the optimal character according to the order is possible because of it (can compare l... | 2 | 0 | ['Array', 'Java'] | 1 |
smallest-string-with-a-given-numeric-value | 6 Line C++ & Python Solution O(1) Time (Better than 100%) | 6-line-c-python-solution-o1-time-better-gldi2 | We first take x as k - n as we need to have space for all the n characters in the string.\nSince we need to get the lexicographically smallest string we need t | sainikhilreddy | NORMAL | 2020-11-23T05:09:45.501817+00:00 | 2020-11-24T07:11:08.690674+00:00 | 197 | false | We first take **x** as **k - n** as we need to have space for all the **n** characters in the string.\nSince we need to get the lexicographically smallest string we need to get the value of **x** below 25 by inserting all **z**\'s at the end.\nOnce we get the **x** below 25 we insert the character corresponding to it ... | 2 | 0 | ['C', 'Python', 'Python3'] | 0 |
smallest-string-with-a-given-numeric-value | C# | c-by-pramodr-cmp6 | \npublic class Solution {\n public string GetSmallestString(int n, int k) {\n char[] ans = new char[n];\n Array.Fill(ans,\'a\');\n k = k | pramodr | NORMAL | 2020-11-22T05:29:49.529640+00:00 | 2020-11-22T05:29:49.529675+00:00 | 115 | false | ```\npublic class Solution {\n public string GetSmallestString(int n, int k) {\n char[] ans = new char[n];\n Array.Fill(ans,\'a\');\n k = k-n;\n \n for(int i=n-1;i>=0;i--){\n int diff = Math.Min(k,25);\n ans[i]=(char)(\'a\'+diff);\n k=k-diff;\n ... | 2 | 0 | [] | 1 |
smallest-string-with-a-given-numeric-value | Unexpected TLE !! Can Anyone Explain | unexpected-tle-can-anyone-explain-by-aas-9dqn | \n\nclass Solution {\npublic:\n string getSmallestString(int n, int k) {\n string s = "";\n for(int i=0; i=0){\n s[n-i-1] += 25; | aashraya18 | NORMAL | 2020-11-22T05:08:52.306132+00:00 | 2020-11-22T05:11:12.136637+00:00 | 109 | false | ```\n\n```class Solution {\npublic:\n string getSmallestString(int n, int k) {\n string s = "";\n for(int i=0; i<n; i++){\n s = s + \'a\'; \n }\n int i=0;\n int rem = k - n;\n while(rem!=0){\n if(rem -25 >=0){\n s[n-i-1] += 25;\n ... | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | Java, O(n) | java-on-by-knownothingg-xiqe | \n\nclass Solution {\n\tpublic String getSmallestString(int n, int k) {\n\t// create a char array with length of n\n\t\tchar[] arr = new char[n];\n\t\t// imagin | KnowNothingg | NORMAL | 2020-11-22T04:43:59.484954+00:00 | 2020-11-22T04:43:59.484983+00:00 | 62 | false | \n```\nclass Solution {\n\tpublic String getSmallestString(int n, int k) {\n\t// create a char array with length of n\n\t\tchar[] arr = new char[n];\n\t\t// imagine arr is filled with \'a\', \'a\' value is 1, so subtract n from k\n k -= n;\n\t\tfor(int i = n-1; i >= 0; i--) {\n\t\t\tint cur = Math.min(k, 25);\n\... | 2 | 1 | [] | 0 |
smallest-string-with-a-given-numeric-value | Python 1 liner | python-1-liner-by-user0571rf-asla | answer is in the form of aaaa?zzz. initially all chars are \'a\' and we need to add k-n more. the number of \'z\' is (k-n)//25 and the ? char is (k-n)%25 the r | user0571rf | NORMAL | 2020-11-22T04:11:50.372949+00:00 | 2021-01-29T21:59:42.902917+00:00 | 115 | false | answer is in the form of aaaa?zzz. initially all chars are \'a\' and we need to add k-n more. the number of \'z\' is (k-n)//25 and the ? char is (k-n)%25 the rest is \'a\'s\n\n```\n def getSmallestString(self, n: int, k: int) -> str:\n return \'a\'*(n-(k-n)//25-((k-n)%25>0))+chr((k-n)%25+ord(\'a\'))*((k-n)%2... | 2 | 1 | ['Python', 'Python3'] | 1 |
smallest-string-with-a-given-numeric-value | Java, O(n), Greedy try smallest character from left to right | java-on-greedy-try-smallest-character-fr-gc7h | \nclass Solution {\n public String getSmallestString(int n, int k) {\n StringBuilder res = new StringBuilder();\n for(int i = 0; i < n; i++){\n | toffeelu | NORMAL | 2020-11-22T04:00:36.014238+00:00 | 2020-11-22T04:00:36.014278+00:00 | 111 | false | ```\nclass Solution {\n public String getSmallestString(int n, int k) {\n StringBuilder res = new StringBuilder();\n for(int i = 0; i < n; i++){\n int left = n - i - 1;\n //check if we put a \'a\' here, it\'s still possible to satisfy the requirement\n if(k <= left * 26... | 2 | 0 | [] | 0 |
smallest-string-with-a-given-numeric-value | beats 85% || simple cpp || greedy | beats-85-simple-cpp-greedy-by-yaswanth09-45v4 | Code\n\nclass Solution {\npublic:\n string getSmallestString(int n, int k) {\n string res(n,\'a\');\n k-=n;\n for(int i = n-1 ; i >= 0 a | yaswanth0901 | NORMAL | 2024-05-24T09:06:16.614700+00:00 | 2024-05-24T09:06:16.614723+00:00 | 14 | false | # Code\n```\nclass Solution {\npublic:\n string getSmallestString(int n, int k) {\n string res(n,\'a\');\n k-=n;\n for(int i = n-1 ; i >= 0 and k ; i--) {\n int x = min(25,k);\n res[i]+=x;\n k-=x;\n }\n return res;\n }\n};\n``` | 1 | 0 | ['C++'] | 0 |
smallest-string-with-a-given-numeric-value | Easy and Straightforward Code | easy-and-straightforward-code-by-jeet_sa-ree3 | Intuition\n Describe your first thoughts on how to solve this problem. \nWe try to assign \'a\' to the starting characters of strings and \'z\' to the last part | jeet_sankala | NORMAL | 2024-01-06T21:14:19.194243+00:00 | 2024-01-06T21:14:19.194273+00:00 | 50 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nWe try to assign \'a\' to the starting characters of strings and \'z\' to the last part of string so that we could possibly get the lexicographical smallest string .\n# Approach\n<!-- Describe your approach to solving the problem. -->\nFi... | 1 | 0 | ['Greedy', 'C++'] | 1 |
smallest-string-with-a-given-numeric-value | Best Java Solution || Beats 100% | best-java-solution-beats-100-by-ravikuma-8ofn | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | ravikumar50 | NORMAL | 2023-10-07T06:20:46.574269+00:00 | 2023-10-07T06:20:46.574292+00:00 | 125 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 1 | ['Java'] | 0 |
smallest-string-with-a-given-numeric-value | very easy python solution | very-easy-python-solution-by-a-fr0stbite-fgi0 | Approach\ndon\'t care about n, get most optimal, and split up\n\n# Complexity\n- Time complexity: ay, space-man i bet u don\'t know ur complexity\n\n- Space com | a-fr0stbite | NORMAL | 2023-09-14T02:01:31.067332+00:00 | 2023-10-04T05:41:20.328595+00:00 | 3 | false | # Approach\ndon\'t care about `n`, get most optimal, and split up\n\n# Complexity\n- Time complexity: ay, space-man i bet u don\'t know ur complexity\n\n- Space complexity: OH YEAH I DO\n\n- Time complexity: Then what is it?\n\n- Space complexity: well... uh... i... i think its $$O(n+k)$$...\n\n- Time complexity: sus..... | 1 | 0 | ['Python3'] | 0 |
smallest-string-with-a-given-numeric-value | Java Backtracking O(n) Easy | java-backtracking-on-easy-by-peekaboo682-o4t0 | Intutition\n- Backtracking - Keep decreasing the value of start so that the sum always remains equal to target k and length always remains n.\n\n\n# Approach\n | peekaboo682 | NORMAL | 2023-09-04T16:49:48.304978+00:00 | 2023-09-04T17:36:37.616104+00:00 | 214 | false | # Intutition\n- Backtracking - Keep decreasing the value of start so that the sum always remains equal to target k and length always remains n.\n\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n- Set start value to z and buf value to n.\n- Start is used to store the character to be appended and ... | 1 | 0 | ['Java'] | 0 |
smallest-string-with-a-given-numeric-value | Briefly explained C++ Solution || Detailed | briefly-explained-c-solution-detailed-by-5d8o | Intuition\nDont get in n instead just declare the string of size n and reverse fill it .\n# Approach\nHelloo ! \nI will break this question in two simple parts | Sakettiwari | NORMAL | 2023-08-31T21:30:19.767395+00:00 | 2023-08-31T21:30:19.767421+00:00 | 196 | false | # Intuition\nDont get in n instead just declare the string of size n and reverse fill it .\n# Approach\nHelloo ! \nI will break this question in two simple parts and I hope it will make the question more easier.\n\nFirst **tackle n**\ndeclare a string of size n with all a\'s;\nDONE!\n\nNow **tackle k**\nWe know for any... | 1 | 0 | ['C++'] | 0 |
maximum-average-pass-ratio | C++ Greedy Max Heap O(m log n) | c-greedy-max-heap-om-log-n-by-votrubac-d0q9 | How much of profit in score can we get if we add one extra student to a particular class? Send an extra student to the class with the most profit; repeat till y | votrubac | NORMAL | 2021-03-14T04:01:37.755500+00:00 | 2021-03-14T06:24:37.121902+00:00 | 10,961 | false | How much of profit in score can we get if we add one extra student to a particular class? Send an extra student to the class with the most profit; repeat till you run out of students.\n\nLet\'s track profits for all classes in a max heap. While we still have extra students, we pick a class that gives us the maximum pro... | 121 | 2 | [] | 26 |
maximum-average-pass-ratio | [Python/Java] Max Heap - Clean & Concise | pythonjava-max-heap-clean-concise-by-hie-fnu1 | Idea\n- How much profit we can get if we add one extraStudents to a particular class (pass, total)? This profit can be defined as: (pass+1)/(total+1) - pass/tot | hiepit | NORMAL | 2021-03-14T04:00:37.367789+00:00 | 2021-03-14T05:01:44.000819+00:00 | 7,531 | false | **Idea**\n- How much profit we can get if we add one `extraStudents` to a particular class `(pass, total`)? This profit can be defined as: `(pass+1)/(total+1) - pass/total`.\n- For each student from `extraStudents`, we try to add to a class which will increase its profit maximum.\n- We can use `maxHeap` structure which... | 109 | 7 | [] | 12 |
maximum-average-pass-ratio | [C++] Explained Priority Queue | Greedy Solution | Find the Delta | c-explained-priority-queue-greedy-soluti-p0xj | There are few incorrect approaches:\n1. Choosing the smallest class size\n2. Choosing the smallest pass size\n3. Choosing the least pass ratio\n\nInstead, the c | vector_long_long | NORMAL | 2021-03-14T04:06:03.977339+00:00 | 2021-06-18T22:23:24.738221+00:00 | 4,824 | false | There are few incorrect approaches:\n1. Choosing the smallest class size\n2. Choosing the smallest pass size\n3. Choosing the least pass ratio\n\nInstead, the correct approach is:\n**Find the difference**, namely the delta. \n\nFor example, even though `1/2` and `10/20` has the same ratio. However, `1/2`\'s delta is eq... | 81 | 2 | ['C', 'Heap (Priority Queue)', 'C++'] | 6 |
maximum-average-pass-ratio | Greedy+make_heap vs 2nd largest||251ms beats 100% | greedymake_heap251ms-beats-100-by-anwend-cmr7 | IntuitionTo compute the increment for each pair (p,q)
q+1p+1−qp=q(q+1)q−p
Then use Greedy to deploy the extraStudents for the pair (p,q) with the most increm | anwendeng | NORMAL | 2024-12-15T01:36:31.702128+00:00 | 2024-12-15T11:56:44.427859+00:00 | 11,460 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nTo compute the increment for each pair $(p, q)$\n$$ \n\\frac{p+1}{q+1}-\\frac{p}{q}=\\frac{q-p}{q(q+1)}\n$$\nThen use Greedy to deploy the extraStudents for the pair $(p, q)$ with the most increment at each time; that is done by using `ma... | 48 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'C++', 'Python3'] | 11 |
maximum-average-pass-ratio | [Python] Greedy Solution using Priority Queue | python-greedy-solution-using-priority-qu-gwfq | Explanation\nGreedily take the best current choice using priority queue.\n\n\n# Prove\nFor each class, the delta is decreasing when we add extra students.\nThe | lee215 | NORMAL | 2021-03-14T04:08:03.710314+00:00 | 2021-03-14T08:57:29.034800+00:00 | 4,655 | false | # **Explanation**\nGreedily take the best current choice using priority queue.\n<br>\n\n# **Prove**\nFor each class, the delta is decreasing when we add extra students.\nThe best local option is always the best.\nIt\'s a loss if we don\'t take it.\n<br>\n\n# **Complexity**\nTime `O(n + klogn)`\nSpace `O(n)`\n<br>\n\n**... | 45 | 2 | [] | 8 |
maximum-average-pass-ratio | Java PriorityQueue | java-priorityqueue-by-vikrant_pc-lpwp | \nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n PriorityQueue<int[]> queue = new PriorityQueue<>(new Cmp()) | vikrant_pc | NORMAL | 2021-03-14T04:00:31.762661+00:00 | 2021-03-14T04:14:29.487547+00:00 | 2,221 | false | ```\nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n PriorityQueue<int[]> queue = new PriorityQueue<>(new Cmp());\n for(int[] c: classes) queue.offer(c); // add all to priority queue\n for(;extraStudents > 0;extraStudents--) { // add extra student to... | 28 | 0 | [] | 8 |
maximum-average-pass-ratio | Priority queue O((m+n)log n) Solution 100% Beats | simple-queue-omn-solution-100-beats-by-s-oshz | 🧠 Intuition 🤔The problem is about maximizing the overall average ratio by distributing extra students across the classes. The key idea is to identify which clas | Sumeet_Sharma-1 | NORMAL | 2024-12-15T01:50:05.778806+00:00 | 2024-12-15T04:15:18.316228+00:00 | 7,479 | false | # \uD83E\uDDE0 Intuition \uD83E\uDD14 \nThe problem is about maximizing the overall average ratio by distributing extra students across the classes. The key idea is to identify which class benefits the most from each extra student. This can be achieved by calculating the improvement, or "gain," for adding a student to... | 24 | 2 | ['Array', 'Heap (Priority Queue)', 'C++', 'Java', 'Python3', 'C#'] | 6 |
maximum-average-pass-ratio | Easy C++ solution || commented fully & explained | easy-c-solution-commented-fully-explaine-r9ul | \nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n \n //among all classes i choose the one | saiteja_balla0413 | NORMAL | 2021-06-18T06:49:37.856993+00:00 | 2021-06-18T06:49:37.857034+00:00 | 1,645 | false | ```\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n \n //among all classes i choose the one which will have a larger growth in the pass ratio if i add one student to the class\n \n //add one student to the each class and store the grow... | 23 | 0 | ['C', 'Heap (Priority Queue)'] | 3 |
maximum-average-pass-ratio | [Python] 100% Efficient solution, easy to understand with comments and explanation | python-100-efficient-solution-easy-to-un-nwpy | Key Idea: We need to keep assigning the remaining extra students to the class which can experience the greatest impact. \n\nLet see an example below, if we have | captainx | NORMAL | 2021-03-14T04:36:33.573517+00:00 | 2021-03-14T05:31:48.216744+00:00 | 2,333 | false | **Key Idea:** We need to keep assigning the remaining extra students to the class which can experience the greatest impact. \n\nLet see an example below, if we have following clasess - [[2,4], [3,9], [4,5], [2,10]], then the impact of assignment students to each class can be defined as,\n\n```\n# In simple terms it can... | 22 | 2 | ['Heap (Priority Queue)', 'Python', 'Python3'] | 2 |
maximum-average-pass-ratio | Python | Greedy Algorithm Pattern & Priority Queue (Heap) | python-greedy-algorithm-pattern-priority-tq0w | see the Successfully Accepted SubmissionCodeKey InsightsImpact of an Extra StudentAdding one extra student to a class will increase its pass ratio. The key is t | Khosiyat | NORMAL | 2024-12-15T00:27:24.657569+00:00 | 2024-12-15T00:27:24.657569+00:00 | 2,662 | false | [see the Successfully Accepted Submission](https://leetcode.com/problems/maximum-average-pass-ratio/submissions/1478957269/?envType=daily-question&envId=2024-12-15)\n\n# Code\n```python3 []\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n # Function to cal... | 17 | 1 | ['Python3'] | 2 |
maximum-average-pass-ratio | Faster Convergence | Heavy Math | C++ 64-91 ms 100% | faster-convergence-heavy-math-c-100-ms-1-w5xa | IntuitionWe have an array of up to 105 classes containing class population (105, which is quite a large class) and the number of studends who are going to pass | sergei99 | NORMAL | 2024-12-15T15:31:50.177122+00:00 | 2024-12-16T12:53:15.476655+00:00 | 720 | false | # Intuition\nWe have an array of up to $10^5$ classes containing class population ($10^5$, which is quite a large class) and the number of studends who are going to pass a forthcoming exam successfully. We need to distribute up to $10^5$ extra studends across classes so as to maximize the average pass ratio, which is c... | 12 | 0 | ['Array', 'Math', 'Greedy', 'Heap (Priority Queue)', 'C++'] | 8 |
maximum-average-pass-ratio | Solution for waifujahat | C# 119ms 100% / C++ 164ms 100% | Max Heap | solution-for-waifujahat-c-119ms-100-max-4nntc | C# SubmissionsC++ SubmissionsHow to SolvePersonally I think this task is hard, rather than medium. I need to maximizing the average pass ratio after distributin | waifujahat | NORMAL | 2024-12-15T05:49:05.520960+00:00 | 2024-12-15T08:07:32.817594+00:00 | 1,374 | false | # C# Submissions\n\n\n---\n\n# C++ Submissions\n', 'C++', 'C#'] | 0 |
maximum-average-pass-ratio | [C++] why using vector<int> in priority_queue got TLE? | c-why-using-vectorint-in-priority_queue-5vmd1 | I used vector in priority_queue then I got TLE. \nBut if I replace the vector with pair in priority_queue, it passes all test cases.\nJust wonder why it happens | dannini_ | NORMAL | 2021-03-14T04:13:29.586316+00:00 | 2021-03-14T04:16:51.320852+00:00 | 941 | false | I used vector<int> in priority_queue then I got TLE. \nBut if I replace the vector<int> with pair<int, int> in priority_queue, it passes all test cases.\nJust wonder why it happens?\n\nHere\'s my code:\n```\nclass Solution {\npublic:\n static double cal(vector<int>& v) {\n return (double) (v[1] - v[0]) / (dou... | 12 | 0 | [] | 5 |
maximum-average-pass-ratio | C++ using priority queue | c-using-priority-queue-by-code_time-wb29 | initial ratio for one class=x/y\nafter adding 1 child=(x+1)/(y+1)\nchange in ratio by adding one child=(y-x)/(y*(y+1))\nkeep removing and adding this ratio from | code_time | NORMAL | 2021-03-14T04:02:49.326967+00:00 | 2021-03-14T07:57:31.068895+00:00 | 870 | false | initial ratio for one class=x/y\nafter adding 1 child=(x+1)/(y+1)\nchange in ratio by adding one child=(y-x)/(y*(y+1))\nkeep removing and adding this ratio from priority queue for all the extra students\n```\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& c, int e) {\n priority_queue<... | 10 | 0 | [] | 1 |
maximum-average-pass-ratio | C++ MaxHeap | No Lambda Nonsense | Comparator Class / Functor | Explained with comments | c-maxheap-no-lambda-nonsense-comparator-od60d | I was more familiar with Comparator Classes / Functors and completely clueless about auto []()\nSo here\'s one without Lambda functions.\n\nExplaination:\nIt is | isthisdp | NORMAL | 2021-03-23T10:48:11.219447+00:00 | 2021-03-23T10:53:59.184310+00:00 | 856 | false | I was more familiar with Comparator Classes / Functors and completely clueless about `auto []()`\nSo here\'s one without Lambda functions.\n\n**Explaination:**\nIt is not sufficient to pick out the class with the least pass ratio, add a brilliant kid (extraStudent), and recalculate the average. Although that might seem... | 9 | 1 | ['Greedy', 'C', 'Heap (Priority Queue)'] | 2 |
maximum-average-pass-ratio | using heaps | c++ 🏆🔥 | using-heaps-c-by-shyyshawarma-2g6h | Intuitionin this problem in order to maximise the average pass ratio you need to maximise the pass ratio
the maximum change in the pass ration is checked acc to | Shyyshawarma | NORMAL | 2024-12-15T05:41:47.325801+00:00 | 2024-12-15T05:44:51.382949+00:00 | 1,056 | false | # Intuition\n\nin this problem in order to maximise the average pass ratio you need to maximise the pass ratio\nthe maximum change in the pass ration is c... | 8 | 0 | ['C++'] | 2 |
maximum-average-pass-ratio | Most Optimal Heap(Priority Queue) O(k + m logk) Approach 👀 | most-optimal-heappriority-queue-approach-g4ka | IntuitionTo maximize the average pass ratio, we should allocate extra students to classes where the gain (improvement in pass ratio) is largest. By focusing on | JK_01 | NORMAL | 2024-12-15T02:25:13.359156+00:00 | 2024-12-15T07:32:08.017585+00:00 | 2,462 | false | # Intuition\nTo maximize the average pass ratio, we should allocate extra students to classes where the gain (improvement in pass ratio) is largest. By focusing on the classes that benefit the most from an extra student, we maximize the overall pass ratio.\n\n# Approach\n1. **Gain Function:** Calculate the gain for add... | 7 | 0 | ['Heap (Priority Queue)', 'C++', 'Java', 'Python3'] | 4 |
maximum-average-pass-ratio | Clean Python 3, greedy with heap | clean-python-3-greedy-with-heap-by-lench-4jie | Greedy add genius students into most benefit class.\n\nTime: O(N + ElogN)\nSpace: O(N)\n\nimport heapq\nclass Solution:\n def maxAverageRatio(self, classes: | lenchen1112 | NORMAL | 2021-03-14T04:02:07.028096+00:00 | 2021-03-14T04:02:07.028122+00:00 | 364 | false | Greedy add genius students into most benefit class.\n\nTime: `O(N + ElogN)`\nSpace: `O(N)`\n```\nimport heapq\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n total = sum(p / t for p, t in classes)\n heap = [(p / t - (p + 1) / (t + 1), p, t) for p, ... | 7 | 0 | [] | 2 |
maximum-average-pass-ratio | PriorityQueue | Solution for LeetCode#1792 | priorityqueue-solution-for-leetcode1792-mrgti | IntuitionThe problem requires maximizing the average pass ratio across all classes by optimally allocating extra students. The key insight is that we should pri | samir023041 | NORMAL | 2024-12-15T07:15:42.278114+00:00 | 2024-12-15T19:11:37.036346+00:00 | 783 | false | \n\n# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem requires maximizing the average pass ratio across all classes by optimally allocating extra students. The ke... | 6 | 0 | ['Heap (Priority Queue)', 'Java'] | 1 |
maximum-average-pass-ratio | Beginner Friendly - Hinglish-Comments-Intuition- Approach -easy to understand | beginner-friendly-hinglish-comments-intu-vc9d | Intuition
Humare paas classes hain, jisme pass aur total students ka ratio diya hai.
Hume extraStudents dene hain taaki pass ratio ko maximize kiya ja sake.
Har | mr_unknown_19 | NORMAL | 2024-12-15T03:28:37.402218+00:00 | 2024-12-15T03:28:37.402218+00:00 | 748 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n1. Humare paas classes hain, jisme pass aur total students ka ratio diya hai.\n2. Hume extraStudents dene hain taaki pass ratio ko maximize kiya ja sake.\n3. Har class ke liye hum ek delta (improvement) calculate karte hain, jo batata hai... | 6 | 0 | ['Greedy', 'Heap (Priority Queue)', 'C++'] | 1 |
maximum-average-pass-ratio | JAVA || Easiest Code || Simple Approach || Beginner Friendly 🔥🚀 | java-easiest-code-simple-approach-beginn-n9a7 | IntuitionThe goal is to maximize the average pass ratio after assigning extraStudents to the classes. The pass ratio for each class is defined as the number of | user6791FW | NORMAL | 2024-12-15T12:38:04.709380+00:00 | 2024-12-15T12:38:04.709380+00:00 | 330 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\nThe goal is to maximize the average pass ratio after assigning `extraStudents` to the classes. The pass ratio for each class is defined as the number of passing students divided by the total number of students in that class. By assignin... | 5 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'Java'] | 1 |
maximum-average-pass-ratio | Simple Solution Using MinPriorityQueue | simple-solution-using-minpriorityqueue-b-ye32 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | tavvfikk | NORMAL | 2024-12-15T06:09:39.984038+00:00 | 2024-12-15T06:09:39.984038+00:00 | 441 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 5 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'JavaScript'] | 0 |
maximum-average-pass-ratio | Greedy Proof | greedy-proof-by-yingyangme-hwei | Hi Guys, this is kinda my first post on leetcode, applogies for bad grammer and formatting. Also it\'s been ages since I\'ve written a mathematical proof, so it | yingyangme | NORMAL | 2022-01-23T07:00:41.777274+00:00 | 2022-01-23T08:28:56.844755+00:00 | 242 | false | Hi Guys, this is kinda my first post on leetcode, applogies for bad grammer and formatting. Also it\'s been ages since I\'ve written a mathematical proof, so it might not be very accurate but hopefully it should be intutive. Hope this can help one of you. \n\n### Greedy Algorithm\nIteratively each brilient student is a... | 5 | 0 | ['Greedy'] | 0 |
maximum-average-pass-ratio | [Python] Greedy Heap | python-greedy-heap-by-rowe1227-g74a | \n\nhtml5\n<b>Time Complexity: O((m+n)·log(n))</b> where m = extraStudents and n = classes.length ∵ we perform m operations on a length n heap\n<b | rowe1227 | NORMAL | 2021-03-14T04:00:23.747233+00:00 | 2021-03-14T08:39:41.429257+00:00 | 406 | false | \n\n```html5\n<b>Time Complexity: O((m+n)·log(n))</b> where m = extraStudents and n = classes.length ∵ we perform m operations on a length n heap\n<b>Space Complexity: O(n)</b> ∵ every class must be stored in the heap.\n```\n\n**Approach:**\n\nGreedily select the most needy class to receive a brill... | 5 | 0 | [] | 1 |
maximum-average-pass-ratio | ✨Max Heap Explained Simply 🔑 |🔄 Beginner-Friendly 🔝 | Achieves 100% Success 🎯🔥 | max-heap-explained-simply-beginner-frien-7uub | Intuition 🤔✨We want to maximize the average pass ratio 🤓. To do this:
1️⃣ Focus on the class that benefits the most 📈 when we add a student.
2️⃣ Repeat this for | mansimittal935 | NORMAL | 2024-12-15T14:22:26.242733+00:00 | 2024-12-15T14:22:26.242733+00:00 | 194 | false | # Intuition \uD83E\uDD14\u2728\nWe want to maximize the average pass ratio \uD83E\uDD13. To do this:\n1\uFE0F\u20E3 Focus on the class that benefits the most \uD83D\uDCC8 when we add a student.\n2\uFE0F\u20E3 Repeat this for every extraStudent \uD83D\uDC69\u200D\uD83C\uDF93\uD83D\uDC68\u200D\uD83C\uDF93.\n3\uFE0F\u20E3... | 4 | 1 | ['Swift', 'Heap (Priority Queue)', 'Python', 'C++', 'Java', 'Go', 'Rust', 'Ruby', 'C#', 'Dart'] | 0 |
maximum-average-pass-ratio | 251 ms -> 100% | 97.74 MB -> 56.39% | Simple as it gets with explanation. | 251-ms-100-9774-mb-5639-simple-as-it-get-ycd2 | Code | Ununheks | NORMAL | 2024-12-15T13:38:16.015858+00:00 | 2024-12-15T13:38:16.015858+00:00 | 177 | false | \n\n# Code\n```cpp []\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n int classesLen = classes.size();\n \n // pq to know which... | 4 | 0 | ['C++'] | 1 |
maximum-average-pass-ratio | Simple py,JAVA code explaine din detail!! HEAP(Priority Queue) || Greedy | simple-pyjava-code-explaine-din-detail-h-mgjb | Problem understanding
They have given a list of list classes which contains pass and total of a class.idx[0] denotes the no of students who have passed the gina | arjunprabhakar1910 | NORMAL | 2024-12-15T04:13:35.521284+00:00 | 2024-12-15T04:13:35.521284+00:00 | 567 | false | # Problem understanding\n- They have given a list of list `classes` which contains `pass` and `total` of a class.`idx[0]` denotes the no of students who have passed the ginal exam and `idx[1]` total number of students in the the given ***class<sub>idx</sub>***.\n- They also given `extraStudents` which are *genius* stud... | 4 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'Python', 'Java'] | 1 |
maximum-average-pass-ratio | simple and intutive approach with comments | simple-and-intutive-approach-with-commen-j52f | Intuition\nadd a single student in class which enhance the average maximum among them.\nthen update its new enhancment after adding a passed student\n\n# Approa | Ghost1818 | NORMAL | 2024-01-13T10:22:36.002170+00:00 | 2024-01-13T10:26:08.310007+00:00 | 205 | false | # Intuition\nadd a single student in class which enhance the average maximum among them.\nthen update its new enhancment after adding a passed student\n\n# Approach\nstore the profit of every class in max heap with its index\nupdate the profit of particular class where a student is added and\nupdate classes vector as w... | 4 | 0 | ['Greedy', 'Heap (Priority Queue)', 'C++'] | 1 |
maximum-average-pass-ratio | Max Heap , C++ Easy Beats 90% ✅✅ | max-heap-c-easy-beats-90-by-deepak_5910-vfbk | Approach\n Describe your approach to solving the problem. \nWhat do you think about extra students, in which class do you add extra students.\nAfter adding a st | Deepak_5910 | NORMAL | 2023-06-27T09:43:12.866478+00:00 | 2023-10-12T19:37:02.662605+00:00 | 401 | false | # Approach\n<!-- Describe your approach to solving the problem. -->\nWhat do you think about **extra students**, in which class do you add extra students.\nAfter adding a student to all class keep **track of difference** but actually we will add that one student in class which has **maximum difference.**\n\n# Complexit... | 4 | 0 | ['Heap (Priority Queue)', 'C++'] | 1 |
maximum-average-pass-ratio | max heap | C++ | Commented code || Greedy | max-heap-c-commented-code-greedy-by-lazy-l7n5 | \n\ndouble maxAverageRatio(vector<vector<int>>& classes, int extra) {\n priority_queue<pair<double,pair<int,int>>>pq;\n int n=classes.size();\n | lazy_buddy | NORMAL | 2021-08-25T08:12:43.230484+00:00 | 2021-08-25T08:12:43.230514+00:00 | 329 | false | ```\n\ndouble maxAverageRatio(vector<vector<int>>& classes, int extra) {\n priority_queue<pair<double,pair<int,int>>>pq;\n int n=classes.size();\n //calculating the difference between the previous ration and new ratio\n //here I will increament student and pass student of each class by one an... | 4 | 0 | [] | 0 |
maximum-average-pass-ratio | C++ || Not Very Simple | c-not-very-simple-by-tagarwal_be18-13hs | \nclass node\n{\n public:\n int x, y;\n double z;\n \n node(int x, int y, double z)\n {\n this -> x = x;\n this -> y = y;\n | tagarwal_be18 | NORMAL | 2021-05-24T19:22:18.017575+00:00 | 2021-05-24T19:22:18.017620+00:00 | 548 | false | ```\nclass node\n{\n public:\n int x, y;\n double z;\n \n node(int x, int y, double z)\n {\n this -> x = x;\n this -> y = y;\n this -> z = z;\n }\n};\n\nclass cmp\n{\n public:\n bool operator()(node a, node b)\n {\n return a.z < b.z;\n }\n};\n\nclass ... | 4 | 0 | ['C', 'Heap (Priority Queue)', 'C++'] | 2 |
maximum-average-pass-ratio | [JavaScript] Max Heap Approach O(N logN) Time | javascript-max-heap-approach-on-logn-tim-eb0c | Time: O((N + M) * logN) where N is # of classes and M is # of extraStudents\nSpace: O(N)\njavascript\nvar maxAverageRatio = function(classes, extraStudents) {\ | control_the_narrative | NORMAL | 2021-04-19T10:51:34.796053+00:00 | 2021-04-19T10:51:34.796084+00:00 | 382 | false | Time: `O((N + M) * logN)` where `N` is # of `classes` and `M` is # of `extraStudents`\nSpace: `O(N)`\n```javascript\nvar maxAverageRatio = function(classes, extraStudents) {\n const heap = new MaxPriorityQueue({priority: x => x[2]});\n \n for(let [pass, total] of classes) {\n const before = pass/total;... | 4 | 0 | ['Heap (Priority Queue)', 'JavaScript'] | 0 |
maximum-average-pass-ratio | Python3 greedy algorithm | python3-greedy-algorithm-by-otoc-h0lj | Greedy algorithm: for each step of adding a student, maximize the increment of average score\n\n\n def maxAverageRatio(self, classes: List[List[int]], extraS | otoc | NORMAL | 2021-03-14T04:02:41.928471+00:00 | 2021-03-14T16:58:44.206034+00:00 | 253 | false | Greedy algorithm: for each step of adding a student, maximize the increment of average score\n\n```\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n heap = [[-(p + 1) / (t + 1) + p / t, p / t, p, t] for p, t in classes]\n heapq.heapify(heap)\n while extraStud... | 4 | 0 | [] | 0 |
maximum-average-pass-ratio | [Java] 🎄 Priority Queue ✨ Inline comments for clarity 😍 | java-priority-queue-inline-comments-for-7byf4 | IntuitionGreedily increase the pass rate for the classes where adding just 1 student increases the pass rate more than in others.Complexity
Time complexity:
O( | kesshb | NORMAL | 2024-12-15T11:22:31.239849+00:00 | 2024-12-15T11:22:31.239849+00:00 | 206 | false | # Intuition\nGreedily increase the pass rate for the classes where adding just 1 student increases the pass rate more than in others.\n\n# Complexity\n- Time complexity:\n$$O(n log n)$$\n\n- Space complexity:\n$$O(n)$$\n\n# Code\n```java []\nclass Solution {\n public double maxAverageRatio(int[][] classes, int extra... | 3 | 0 | ['Java'] | 0 |
maximum-average-pass-ratio | Best Solution You will ever see in Hinenglish | best-solution-you-will-ever-see-in-hinen-jhap | SochDekho Question keh rha hain ki har ek student kaisa add kara taka avergae max ho jai. Toh agr sum max kar denga toh avg bhi max ho jaiga
Aur sum max ke lia | jastegsingh007 | NORMAL | 2024-12-15T04:51:57.393613+00:00 | 2024-12-15T04:55:12.923957+00:00 | 330 | false | # Soch\nDekho Question keh rha hain ki har ek student kaisa add kara taka avergae max ho jai. Toh agr sum max kar denga toh avg bhi max ho jaiga \nAur sum max ke lia unn ratio mein students add karo jo sum ko maximize karai\nPehla thought aayga DP karloo jissa ya toh iss student pe dalo ya mat daloo\nBut constraints de... | 3 | 0 | ['Python3'] | 0 |
maximum-average-pass-ratio | C# - Fast - 962ms - PriorityQueue of improvement of pass ratio | c-fast-962ms-priorityqueue-of-improvemen-ws9w | Intuition / ApproachThe thing to figure out is which one class would be made better by the most by adding a brilliant student. That would be the one that would | hafthor | NORMAL | 2024-12-15T01:49:41.842734+00:00 | 2024-12-16T11:57:55.747695+00:00 | 119 | false | \n\n# Intuition / Approach\nThe thing to figure out is which one class would be made better by the most by adding a brilliant student. That would be the one that would make the biggest impact on the pass rat... | 3 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'C#'] | 2 |
maximum-average-pass-ratio | go heap | go-heap-by-dynasty919-10ja | \nfunc maxAverageRatio(classes [][]int, extraStudents int) float64 {\n h := &maxheap{}\n for _, c := range classes {\n heap.Push(h, [2]int{c[0], c[ | dynasty919 | NORMAL | 2021-12-21T12:07:09.912398+00:00 | 2021-12-21T12:07:42.360165+00:00 | 175 | false | ```\nfunc maxAverageRatio(classes [][]int, extraStudents int) float64 {\n h := &maxheap{}\n for _, c := range classes {\n heap.Push(h, [2]int{c[0], c[1]})\n }\n \n for extraStudents > 0 {\n c := heap.Pop(h).([2]int)\n extraStudents--\n c[0]++\n c[1]++\n heap.Push... | 3 | 0 | ['Go'] | 1 |
maximum-average-pass-ratio | C# SortedSet | c-sortedset-by-venki07-x6wv | \npublic class Solution {\n public double MaxAverageRatio(int[][] classes, int extraStudents) {\n \n var set = new SortedSet<(double delta, int | venki07 | NORMAL | 2021-08-04T14:45:29.014344+00:00 | 2021-08-04T14:45:29.014394+00:00 | 162 | false | ```\npublic class Solution {\n public double MaxAverageRatio(int[][] classes, int extraStudents) {\n \n var set = new SortedSet<(double delta, int index, double pass, double total)>();\n int index = 0;\n \n double avg = 0.0;\n foreach(var cl in classes)\n {\n ... | 3 | 1 | [] | 1 |
maximum-average-pass-ratio | Java | O(mlogn) | Heap, Greedy | Small code | java-omlogn-heap-greedy-small-code-by-av-xdsn | \nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n double sum=0;\n PriorityQueue<int[]> pq = new Priori | avishekde | NORMAL | 2021-07-23T11:17:59.001706+00:00 | 2021-07-23T11:17:59.001741+00:00 | 447 | false | ```\nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n double sum=0;\n PriorityQueue<int[]> pq = new PriorityQueue<>((a,b)->Double.compare((double)(b[0]+1)/(b[1]+1)-(double)b[0]/b[1],(double)(a[0]+1)/(a[1]+1)-(double)a[0]/a[1]));\n for(int[] c: classes){\n ... | 3 | 0 | ['Greedy', 'Heap (Priority Queue)'] | 0 |
maximum-average-pass-ratio | JavaScript and TypeScript Solution | javascript-and-typescript-solution-by-me-fxsf | JavaScript AC (932 ms, 69.7 MB)\njs\n/**\n * @param {number[][]} classes\n * @param {number} extraStudents\n * @return {number}\n */\nvar maxAverageRatio = func | menheracapoo | NORMAL | 2021-03-16T14:41:39.760711+00:00 | 2021-03-16T14:41:39.760751+00:00 | 163 | false | JavaScript AC (932 ms, 69.7 MB)\n```js\n/**\n * @param {number[][]} classes\n * @param {number} extraStudents\n * @return {number}\n */\nvar maxAverageRatio = function(classes, extraStudents) {\n const q = new MaxPriorityQueue({\n priority: i => (classes[i][0] + 1) / (classes[i][1] + 1) - \n classes[i][0] / cl... | 3 | 0 | [] | 0 |
maximum-average-pass-ratio | Java || PriorityQueue || O(mlogn+nlogn) | java-priorityqueue-omlognnlogn-by-legend-i23r | \n\t// O(mlogn+nlogn)\n\t// PriorityQueue\n\tpublic double maxAverageRatio(int[][] classes, int extraStudents) {\n\n\t\tPriorityQueue heap = new PriorityQueue(n | LegendaryCoder | NORMAL | 2021-03-15T12:32:32.466056+00:00 | 2021-03-15T12:32:32.466094+00:00 | 172 | false | \n\t// O(m*logn+n*logn)\n\t// PriorityQueue\n\tpublic double maxAverageRatio(int[][] classes, int extraStudents) {\n\n\t\tPriorityQueue<double[]> heap = new PriorityQueue<double[]>(new Comparator<double[]>() {\n\t\t\t@Override\n\t\t\tpublic int compare(double[] o1, double[] o2) {\n\t\t\t\treturn Double.compare(o2[0], o... | 3 | 0 | [] | 0 |
maximum-average-pass-ratio | [Python] Clear Greedy+Heap Solution with Video Explanation | python-clear-greedyheap-solution-with-vi-09uu | Video with clear visualization and explanation:\nhttps://youtu.be/TIn0wbbJDVs\n\n\n\nIntuition: Greedy+Heap\n \n\nCode\n\nfrom heapq import *\n\nclass Solution: | iverson52000 | NORMAL | 2021-03-14T20:36:43.965789+00:00 | 2021-03-14T20:36:43.965828+00:00 | 220 | false | Video with clear visualization and explanation:\nhttps://youtu.be/TIn0wbbJDVs\n\n\n\nIntuition: Greedy+Heap\n \n\n**Code**\n```\nfrom heapq import *\n\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n heap = []\n \n for p, t in classes:\n ... | 3 | 2 | ['Python'] | 0 |
maximum-average-pass-ratio | So beat 100% is meaningless (at least for C++) | so-beat-100-is-meaningless-at-least-for-htnk2 | Basically, I submitted twice using C++ in contest, one got TLE, and one got AC, but they both passed after contest, and beat 100%. Shown as below:\n\nTLE one:\n | acmer29 | NORMAL | 2021-03-14T08:35:56.896256+00:00 | 2021-03-14T08:39:49.865422+00:00 | 195 | false | Basically, I submitted twice using C++ in contest, one got TLE, and one got AC, but they both passed after contest, and beat 100%. Shown as below:\n\nTLE one:\n```\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<heapNode, vector<heapNode>... | 3 | 0 | ['C'] | 0 |
maximum-average-pass-ratio | [Python] Simple solution, explained, priority queue | python-simple-solution-explained-priorit-27gs | \nimport heapq\n\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n \n # Organize the heap | scornz | NORMAL | 2021-03-14T04:12:05.939282+00:00 | 2021-03-14T04:12:05.939329+00:00 | 336 | false | ```\nimport heapq\n\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n \n # Organize the heap based on the "ratio improvement factor"\n # i.e. The (new ratio) - (old ratio), the one that will improve the largest should be the one added to\n ... | 3 | 0 | ['Heap (Priority Queue)', 'Python3'] | 0 |
maximum-average-pass-ratio | C++ Use set to track the most effective at the end | c-use-set-to-track-the-most-effective-at-dsww | ~~~\nclass Solution {\npublic:\n double maxAverageRatio(vector>& c, int extraStudents) {\n set> s;\n int n = c.size();\n for (int i = 0; | xiaoping3418 | NORMAL | 2021-03-14T04:03:36.854141+00:00 | 2021-03-14T04:04:10.088563+00:00 | 181 | false | ~~~\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& c, int extraStudents) {\n set<pair<double, int>> s;\n int n = c.size();\n for (int i = 0; i < n; ++i) {\n double d = 1.0 * (c[i][0] + 1) / (c[i][1] + 1) - 1.0 * c[i][0] / c[i][1];\n s.insert({d, i}... | 3 | 0 | [] | 1 |
maximum-average-pass-ratio | [Java] Greedy solution using priority queue (with trick for early termination) | java-greedy-solution-using-priority-queu-0o01 | Use a max heap: the comparator compares the passing ratio with adding one more student.\nFor a class, if number of passing sutdents is equal to total number of | ninjavic | NORMAL | 2021-03-14T04:01:58.043054+00:00 | 2021-03-14T04:24:19.320656+00:00 | 168 | false | Use a max heap: the comparator compares the passing ratio with adding one more student.\nFor a class, if number of passing sutdents is equal to total number of students, it\'s passing ratio is already 1 and adding more passing students doesn\'t help further.\nThus, only add those with potential to increase the passing ... | 3 | 1 | [] | 0 |
maximum-average-pass-ratio | [Python3] Simple | Fastest | python3-simple-fastest-by-sushanthsamala-pa8k | Logic: We need to pick the class whose pass ratio will increase the most when we add 1 extraStudent. We need to repeat this for every extraStudent\n\nclass Solu | sushanthsamala | NORMAL | 2021-03-14T04:01:21.034047+00:00 | 2021-03-14T04:01:21.034076+00:00 | 252 | false | Logic: We need to pick the class whose pass ratio will increase the most when we add 1 extraStudent. We need to repeat this for every extraStudent\n```\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n h = []\n ones = 0\n for a,b in classes:\n... | 3 | 1 | [] | 0 |
maximum-average-pass-ratio | Greedy, use priority queue to get the maximum increasement. O(nLogn), binary serach doesn't work | greedy-use-priority-queue-to-get-the-max-vf2s | \n\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<double, pair<int, int> | chejianchao | NORMAL | 2021-03-14T04:00:43.582651+00:00 | 2021-03-14T04:00:43.582680+00:00 | 304 | false | \n```\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<double, pair<int, int> > > pq;\n for(auto &cls : classes) {\n int t = cls[1], p = cls[0];\n double add = (p + 1) * 1.0 / (t + 1) - (p * 1.0 / t);\n ... | 3 | 0 | [] | 1 |
maximum-average-pass-ratio | CPP || easy to understand || best in world | cpp-easy-to-understand-best-in-world-by-gcblf | IntuitionWe can use nested pair for it pair<increased_differnce,pair<value_at_subarray[0],value_at_subarray[1]>>Complexity
Time complexity:O(N)
Space complexit | apoorvjain7222 | NORMAL | 2024-12-15T18:05:18.306983+00:00 | 2024-12-15T18:05:18.306983+00:00 | 99 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nWe can use nested pair for it pair<increased_differnce,pair<value_at_subarray[0],value_at_subarray[1]>>\n# Complexity\n- Time complexity:O(N)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:O(N)\n<!-- Add your... | 2 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'C++'] | 0 |
maximum-average-pass-ratio | Priority Queue Approach ||O(NlogN) ||Beats 89% Users|| Brief Desciption of Time and Space Complexity | priority-queue-approach-onlogn-beats-89-54fee | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | Heisenberg_wc | NORMAL | 2024-12-15T13:38:25.470926+00:00 | 2024-12-15T13:38:25.470926+00:00 | 98 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['C++'] | 0 |
maximum-average-pass-ratio | Beats 100% Users With 160ms Runtime || MAX HEAP. | beats-100-users-with-160ms-runtime-max-h-3ex0 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | Yash-8055 | NORMAL | 2024-12-15T11:58:36.373688+00:00 | 2024-12-15T11:58:36.373688+00:00 | 83 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['C++'] | 0 |
maximum-average-pass-ratio | Beat 99%|C++ solution| easy to understand | beat-99c-solution-easy-to-understand-by-yemoy | Intuitionwe need to maximise average.so for this we have to find the maximum growth rate of each class.ApproachComplexity
Time complexity: O (N logN)
Space | anandupadhyay042 | NORMAL | 2024-12-15T11:30:11.041049+00:00 | 2024-12-15T11:30:11.041049+00:00 | 161 | false | # Intuition\nwe need to maximise average.so for this we have to find the maximum growth rate of each class.\n\n# Approach\n\n# Complexity\n- Time complexity: O (N logN)\n\n\n- Space c... | 2 | 0 | ['C++'] | 0 |
maximum-average-pass-ratio | ✅ Easy to Understand | Greedy | Priority Queue | Detailed Video Explanation🔥 | easy-to-understand-greedy-priority-queue-s0k6 | IntuitionTo maximize the average pass ratio across all classes, we need to distribute the extra students strategically. Intuitively, adding a student to a class | sahilpcs | NORMAL | 2024-12-15T09:29:52.934394+00:00 | 2024-12-15T09:29:52.934394+00:00 | 364 | false | # Intuition\nTo maximize the average pass ratio across all classes, we need to distribute the extra students strategically. Intuitively, adding a student to a class where it has the maximum impact on the pass ratio is the optimal approach. By focusing on the marginal gain in pass ratio for each class, we can prioritize... | 2 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'Python', 'C++', 'Java'] | 0 |
maximum-average-pass-ratio | Question is poorly asked | Key point here is marginal gain | Easy to read | question-is-poorly-asked-key-point-here-zn4bt | IntuitionApproachComplexity
Time complexity:
O(n * log(n))
logn (Enqueqe an element to pq)
Space complexity:
O(n)
Code | vivek781113 | NORMAL | 2024-12-15T06:43:07.297117+00:00 | 2024-12-15T06:43:07.297117+00:00 | 57 | false | # Intuition\n - the key here is, we want to maximize the avg.\n - what are the candiates which will give max avg, this will be calculated by marginal gain\n - Marginal Gain = (pass + 1) / (total + 1) - pass / total;\n# Approach\n - we will iterate through each class, find the candiated which will give max m... | 2 | 0 | ['Greedy', 'Heap (Priority Queue)', 'C#'] | 0 |
maximum-average-pass-ratio | Simple and Beginner friendly || Priority Queue || Clean code | simple-and-beginner-friendly-priority-qu-0uj3 | Intuition
To maximize the average ratio of passed to total students in multiple classes after applying a given number of operations, we use a greedy strategy w | hamza_18 | NORMAL | 2024-12-15T06:37:10.563336+00:00 | 2024-12-15T06:37:10.563336+00:00 | 181 | false | # Intuition\n1. To maximize the average ratio of passed to total students in multiple classes after applying a given number of operations, we use a greedy strategy with a priority queue (max-heap).\n\n2. Key Idea: Each operation adds 1 to both the passed and total students of a class. The impact of this operation is bi... | 2 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'C++'] | 0 |
maximum-average-pass-ratio | C++ | Greedy | Priority Queue | greedy-by-ahmedsayed1-8660 | Code | AhmedSayed1 | NORMAL | 2024-12-15T05:30:38.322902+00:00 | 2024-12-15T05:31:47.831146+00:00 | 53 | false | # Code\n```cpp []\ndouble calc(int a,int b){\n return (a+1) / double(b+1) - (a) / double(b);\n}\n\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<double, pair<int, int>>>pq;\n for(auto i : classes)pq.push({calc(i[0],i[1]), ... | 2 | 0 | ['Greedy', 'Heap (Priority Queue)', 'C++'] | 0 |
maximum-average-pass-ratio | c++ | c-by-shashwat1915-nx22 | Code | shashwat1915 | NORMAL | 2024-12-15T04:05:59.952385+00:00 | 2024-12-15T04:05:59.952385+00:00 | 242 | false | # Code\n```cpp []\nclass Solution {\npublic:\ndouble rate_checker(int student,int total){\nreturn (double) (student+1)/(total+1)- (double) student/total;\n}\n double maxAverageRatio(vector<vector<int>>& c, int e) {\n double ans=0.0;\n priority_queue<pair<double,pair<int,int>>>q;\n for(auto x:c) ... | 2 | 0 | ['Array', 'Greedy', 'Heap (Priority Queue)', 'C++'] | 0 |
maximum-average-pass-ratio | The CHEATCODE to solving this problem! | the-cheatcode-to-solving-this-problem-by-zfsr | IntuitionWe have an integer extraStudents to disperse among classes. Naturally, while we still have an extraStudent we want to assign them to the class that wil | zachross | NORMAL | 2024-12-15T03:45:46.697128+00:00 | 2024-12-15T03:45:46.697128+00:00 | 106 | false | # Intuition\nWe have an integer *extraStudents* to disperse among classes. Naturally, while we still have an *extraStudent* we want to assign them to the class that will benefit the most. \n\nBut how do we know which class will benefit most? There is no obvious greedy heuristic that works. Here is where the CHEAT comes... | 2 | 0 | ['Greedy', 'Heap (Priority Queue)', 'Python3'] | 0 |
maximum-average-pass-ratio | easy heap solution C | Runtime Beats 100.00% | Memory Beats 100.00% | easy-heap-solution-c-runtime-beats-10000-fj5r | Complexity
Time complexity: O(nlogn)
Space complexity: O(n)
Code | JoshDave | NORMAL | 2024-12-15T02:55:41.917663+00:00 | 2024-12-15T04:43:47.048847+00:00 | 184 | false | # Complexity\n- Time complexity: O(nlogn)\n- Space complexity: O(n)\n\n# Code\n```c []\nstruct node {\n double value;\n int index;\n};\n\n#define get_parent(index) ((index - 1)>>1)\n#define get_left_child(index) ((index<<1) + 1)\n#define get_right_child(index) ((index<<1) + 2)\n\nvoid swap(struct node* a, struct node... | 2 | 0 | ['C'] | 0 |
maximum-average-pass-ratio | beats 97% 🎯✅✅✅ easy to understand | beats-97-easy-to-understand-by-ritik6g-ops0 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | ritik6g | NORMAL | 2024-12-15T02:01:48.993044+00:00 | 2024-12-15T02:01:48.993044+00:00 | 641 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['C++'] | 2 |
maximum-average-pass-ratio | Java & Python3 Solution | java-python3-solution-by-bleu_2-z2mt | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | Bleu_2 | NORMAL | 2024-12-15T01:28:31.777530+00:00 | 2024-12-15T01:28:31.777530+00:00 | 482 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['Array', 'Java', 'Python3'] | 0 |
maximum-average-pass-ratio | [Kotlin] Heap / Priority Queue solution (with comments) | kotlin-heap-priority-queue-solution-with-bkjx | Intuition / ApproachThe key to this problem is to greedily add students to the class which would benefit the most (i.e. would see the highest increase in pass r | ZennY24 | NORMAL | 2024-12-15T01:15:47.633569+00:00 | 2024-12-15T01:16:52.194095+00:00 | 51 | false | # Intuition / Approach\n\nThe key to this problem is to greedily add students to the class which would benefit the most (i.e. would see the highest increase in pass ratio with this student) until no extra students remain. We can keep track of which class would see the highest increase by maintaining a heap / priority q... | 2 | 0 | ['Greedy', 'Heap (Priority Queue)', 'Kotlin'] | 0 |
maximum-average-pass-ratio | C++ || Priority Queue || Beats 95% | c-priority-queue-beats-95-by-vikalp_07-5lyl | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | vikalp_07 | NORMAL | 2023-08-15T06:58:07.627831+00:00 | 2023-08-15T06:58:07.627860+00:00 | 577 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 2 | 0 | ['C++'] | 0 |
maximum-average-pass-ratio | C++| Priority Queue | Greedy | c-priority-queue-greedy-by-ayushmanshivh-6uts | What the question ask? so we have to assign ExtraStudent in such class that we"ll get maximum possible ratio . so How we"ll do this . We have to send ExtraStude | AyushmanShivhare | NORMAL | 2022-07-08T12:49:54.285764+00:00 | 2022-07-08T12:49:54.285797+00:00 | 336 | false | What the question ask? so we have to assign ExtraStudent in such class that we"ll get maximum possible ratio . so How we"ll do this . We have to send ExtraStudents to classes 1 by 1 according to their ratio(calculate the difference of all classes for 1 student) where we get more difference we"ll send the student to th... | 2 | 0 | ['C', 'Heap (Priority Queue)'] | 0 |
maximum-average-pass-ratio | Java Priority Queue Clean Code Solution | java-priority-queue-clean-code-solution-h1h6h | \nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n PriorityQueue<double[]> pq = new PriorityQueue<>(new Compar | Superman-Qiang | NORMAL | 2022-05-05T03:28:10.185045+00:00 | 2022-05-05T03:28:10.185093+00:00 | 529 | false | ```\nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n PriorityQueue<double[]> pq = new PriorityQueue<>(new Comparator<double[]>(){\n public int compare(double[] a, double[] b){\n double adiff = (a[0]+1)/(a[1]+1) - (a[0]/a[1]); \n... | 2 | 0 | ['Heap (Priority Queue)', 'Java'] | 2 |
maximum-average-pass-ratio | C++ Solution Explanation | priority_queue | [1792] | c-solution-explanation-priority_queue-17-7dmo | How priority_queue (max heap) came into picture-->\nWe have to return maximum average pass ratio which is equal to sum of all pass ratios / number of classes. W | SameerNITW | NORMAL | 2022-03-02T17:50:13.786329+00:00 | 2022-03-03T11:13:45.924036+00:00 | 203 | false | **How priority_queue (max heap) came into picture-->**\nWe have to return maximum average pass ratio which is equal to sum of all pass ratios / number of classes. Where number of classes is constant so we need to increase the sum of all pass ratios.\nIn each class there is a pass ratio before adding extra students, as ... | 2 | 0 | ['C', 'Heap (Priority Queue)'] | 0 |
maximum-average-pass-ratio | C++ Solution | c-solution-by-mk_kr_24-tgtd | \ndouble precise(double a)\n{\n double intpart;\n double fractpart = modf (a, &intpart);\n fractpart = roundf(fractpart * 100000.0)/100000.0; // Round t | mk_kr_24 | NORMAL | 2021-09-22T04:54:36.925688+00:00 | 2021-09-22T04:54:36.925716+00:00 | 192 | false | ```\ndouble precise(double a)\n{\n double intpart;\n double fractpart = modf (a, &intpart);\n fractpart = roundf(fractpart * 100000.0)/100000.0; // Round to 5 decimal places\n double b = intpart + fractpart;\n return b;\n}\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes,... | 2 | 0 | [] | 0 |
maximum-average-pass-ratio | Python solution with Heap - With the idea | python-solution-with-heap-with-the-idea-abaj6 | The idea is add each student such that their addition increases the particular class average more.\n\nFor this, I maintained a heap in which i keep adding what | ravinamani15 | NORMAL | 2021-07-04T13:54:59.328253+00:00 | 2021-07-04T13:54:59.328299+00:00 | 142 | false | The idea is add each student such that their addition increases the particular class average more.\n\nFor this, I maintained a heap in which i keep adding what will be the change in average with addition of one student to that particular class. i.e., `x/y - (x+1)/(y+1)` will be the negative value of change in average w... | 2 | 0 | [] | 1 |
maximum-average-pass-ratio | python solution | heap | | python-solution-heap-by-abhishen99-dbkl | \nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n h = []\n n=len(classes)\n \n | Abhishen99 | NORMAL | 2021-06-28T19:32:03.068609+00:00 | 2021-06-28T19:32:03.068635+00:00 | 367 | false | ```\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], extraStudents: int) -> float:\n h = []\n n=len(classes)\n \n \n for i in classes:\n currpassration = i[0]/i[1]\n ifaddthan = (i[0]+1)/ (i[1]+1)\n \n increase = ifa... | 2 | 0 | ['Python', 'Python3'] | 0 |
maximum-average-pass-ratio | python heap solution | python-heap-solution-by-heisenbarg-gbmy | ```\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], e: int) -> float:\n heap=[]\n for i,j in classes:\n diff= | heisenbarg | NORMAL | 2021-06-18T08:25:25.788007+00:00 | 2021-06-18T08:25:25.788036+00:00 | 270 | false | ```\nclass Solution:\n def maxAverageRatio(self, classes: List[List[int]], e: int) -> float:\n heap=[]\n for i,j in classes:\n diff=(i+1)/(j+1)-(i/j)\n heapq.heappush(heap,(-diff,i,j))\n while(e>0):\n diff,i,j=heapq.heappop(heap)\n i+=1\n j+... | 2 | 0 | ['Heap (Priority Queue)', 'Python', 'Python3'] | 0 |
maximum-average-pass-ratio | C++ clean solution | c-clean-solution-by-nishchhal-f5dw | \nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<double,int>> q;\n | nishchhal | NORMAL | 2021-04-05T19:58:36.084894+00:00 | 2021-04-05T19:58:36.084939+00:00 | 311 | false | ```\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<double,int>> q;\n \n for(int i=0;i<classes.size();i++){\n double a=(float)(classes[i][0]+1)/(float)(classes[i][1]+1)-(float)classes[i][0]/(float)classes[i][... | 2 | 0 | ['Greedy', 'C', 'Heap (Priority Queue)'] | 0 |
maximum-average-pass-ratio | Java Simple and easy solution, using max heap and faster than 100%, clean code with comments. | java-simple-and-easy-solution-using-max-nkb5j | PLEASE UPVOTE IF YOU LIKE THIS SOLUTION\n\n\nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n //max heap\n | satyaDcoder | NORMAL | 2021-03-20T01:57:01.866337+00:00 | 2021-03-20T01:57:01.866365+00:00 | 211 | false | **PLEASE UPVOTE IF YOU LIKE THIS SOLUTION**\n\n```\nclass Solution {\n public double maxAverageRatio(int[][] classes, int extraStudents) {\n //max heap\n //here we are using Max Heap, whaich has maximum element in root\n PriorityQueue<Class> maxHeap = new PriorityQueue<Class>(Comparator.comparin... | 2 | 0 | ['Heap (Priority Queue)'] | 0 |
maximum-average-pass-ratio | Simple C++ Solution Priority Queue | simple-c-solution-priority-queue-by-arya-7dg5 | \nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<long double,pair<long lo | aryan29 | NORMAL | 2021-03-15T10:52:28.624706+00:00 | 2021-03-15T10:52:28.624731+00:00 | 117 | false | ```\nclass Solution {\npublic:\n double maxAverageRatio(vector<vector<int>>& classes, int extraStudents) {\n priority_queue<pair<long double,pair<long long int,long long int>>>pq;\n for(auto it:classes)\n {\n long long int z=(it[1]);\n z=z*(it[1]+1);\n long doubl... | 2 | 0 | [] | 0 |
maximum-average-pass-ratio | [Java] PriorityQueue Solution beats 100% | java-priorityqueue-solution-beats-100-by-e1ys | \npublic double maxAverageRatio(int[][] classes, int extraStudents) {\n\tQueue<double[]> pq = new PriorityQueue<>((a,b) -> {\n\t\tdouble ratioDiffA = (a[0] + 1) | jerrywusa | NORMAL | 2021-03-14T18:01:06.548487+00:00 | 2021-03-14T18:01:06.548529+00:00 | 123 | false | ```\npublic double maxAverageRatio(int[][] classes, int extraStudents) {\n\tQueue<double[]> pq = new PriorityQueue<>((a,b) -> {\n\t\tdouble ratioDiffA = (a[0] + 1) / (a[1] + 1) - a[0] / a[1];\n\t\tdouble ratioDiffB = (b[0] + 1) / (b[1] + 1) - b[0] / b[1];\n\t\treturn Double.compare(ratioDiffB, ratioDiffA);\n\t});\n\tfo... | 2 | 0 | [] | 1 |
maximum-average-pass-ratio | [C++] Simple Heap solution. [Detailed Explanation] | c-simple-heap-solution-detailed-explanat-oxrl | \n/*\n https://leetcode.com/problems/maximum-average-pass-ratio/\n \n At a glance the obvious choice seems like picking the class with least pass\n | cryptx_ | NORMAL | 2021-03-14T06:47:10.878453+00:00 | 2021-03-14T06:47:10.878501+00:00 | 254 | false | ```\n/*\n https://leetcode.com/problems/maximum-average-pass-ratio/\n \n At a glance the obvious choice seems like picking the class with least pass\n ratio each time and adding a genius student. But this only brings the lower \n ratio scores near the avg, doesn\'t try to increase the max observed score ... | 2 | 0 | ['C', 'Heap (Priority Queue)', 'C++'] | 0 |
maximum-average-pass-ratio | Ruby - Greedy, Priority Queue. | ruby-greedy-priority-queue-by-shhavel-w6pw | Observation\n\nIf there is a class with pass equeals p and total students equals t then pass ration equals p / t.\nAdding an extra student who passed exam incre | shhavel | NORMAL | 2021-03-14T05:17:41.964887+00:00 | 2021-03-15T13:44:15.309406+00:00 | 94 | false | ### Observation\n\nIf there is a class with pass equeals `p` and total students equals `t` then pass ration equals `p / t`.\nAdding an extra student who passed exam increases ration by:\n\n```\np + 1 p (p + 1) * t - p * (t + 1) t - p\n----- - - = -------------------------- = -----------\nt + 1 t ... | 2 | 0 | ['Ruby'] | 1 |
maximum-average-pass-ratio | C++ priority queue | c-priority-queue-by-lisongsun-wu2n | The minute the contest is over, I realized the solution was so simple. Wasted the whole time working on a totally wrong path. Sad.\nKey points:\n Calculate rati | lisongsun | NORMAL | 2021-03-14T05:04:51.875442+00:00 | 2021-03-14T05:22:53.402752+00:00 | 151 | false | The minute the contest is over, I realized the solution was so simple. Wasted the whole time working on a totally wrong path. Sad.\n**Key points:**\n* Calculate ratio gain for inserting a student to each class. Use that ratio gain as key in a priority queue. Bundle class id in the queue with ratio gain.\n* Each time, i... | 2 | 1 | ['C', 'Heap (Priority Queue)'] | 1 |
maximum-average-pass-ratio | C++ | using priority_queue | simple and sort | c-using-priority_queue-simple-and-sort-b-ytjf | \nclass Solution {\npublic:\n double mx(double a,double b)\n {\n return (a+1)/(b+1)-a/b;\n }\n \n double maxAverageRatio(vector<vector<int | sonusharmahbllhb | NORMAL | 2021-03-14T04:58:17.774879+00:00 | 2021-03-14T05:01:18.560033+00:00 | 163 | false | ```\nclass Solution {\npublic:\n double mx(double a,double b)\n {\n return (a+1)/(b+1)-a/b;\n }\n \n double maxAverageRatio(vector<vector<int>>& cls, int extra) {\n priority_queue<pair<double,pair<double,double>>> pq;\n \n for(auto v:cls)\n pq.push({mx(v[0],v[1]),{v... | 2 | 0 | ['C', 'C++'] | 0 |
maximum-average-pass-ratio | [C++]- Simple and easy to understand solution | c-simple-and-easy-to-understand-solution-3d46 | Ques : How we are arranging in priority queue ? Based on what factor comparator will arrange ?\n--> Based upon the gain of average after incrementing the existi | morning_coder | NORMAL | 2021-03-14T04:45:20.842172+00:00 | 2021-03-14T04:46:13.198885+00:00 | 353 | false | **Ques : How we are arranging in priority queue ? Based on what factor comparator will arrange ?**\n--> Based upon the gain of average after incrementing the existing values of {pass,total}. Gain should be maximum.\n\n```\nclass comparator{\n public : \n int operator()(pair<int,int> &v1,pair<int,int> &v2){\n ... | 2 | 0 | ['Greedy', 'C', 'Heap (Priority Queue)', 'C++'] | 1 |
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