question_slug stringlengths 3 77 | title stringlengths 1 183 | slug stringlengths 12 45 | summary stringlengths 1 160 ⌀ | author stringlengths 2 30 | certification stringclasses 2
values | created_at stringdate 2013-10-25 17:32:12 2025-04-12 09:38:24 | updated_at stringdate 2013-10-25 17:32:12 2025-04-12 09:38:24 | hit_count int64 0 10.6M | has_video bool 2
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determine-color-of-a-chessboard-square | JavaScript Simple Solution 99.1% faster | javascript-simple-solution-991-faster-by-t2z1 | \n/**\n * @param {string} coords\n * @return {boolean}\n */\nconst squareIsWhite = function (coords) {\n const letters = [\'a\', \'b\', \'c\', \'d\', \'e\', | js_pro | NORMAL | 2022-10-07T09:05:37.744952+00:00 | 2024-11-24T07:15:39.979684+00:00 | 595 | false | ```\n/**\n * @param {string} coords\n * @return {boolean}\n */\nconst squareIsWhite = function (coords) {\n const letters = [\'a\', \'b\', \'c\', \'d\', \'e\', \'f\', \'g\', \'h\'];\n const [l, n] = coords.split(\'\');\n\n return (letters.indexOf(l) % 2 == 0 && n % 2 == 0) \n || (letters.indexOf(l) % 2 ... | 2 | 0 | ['JavaScript'] | 1 |
determine-color-of-a-chessboard-square | Java | Math | Faster Than 100% Java Submissions | java-math-faster-than-100-java-submissio-givh | \nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n Character str = coordinates.charAt(0);\n int num = Character.getNumer | Divyansh__26 | NORMAL | 2022-09-14T15:30:29.822855+00:00 | 2022-09-14T15:30:29.822897+00:00 | 173 | false | ```\nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n Character str = coordinates.charAt(0);\n int num = Character.getNumericValue(coordinates.charAt(1));\n int flag=0;\n if(str==\'a\' || str==\'c\' || str==\'e\' || str==\'g\'){\n if(num%2==0)\n ... | 2 | 0 | ['Math', 'String', 'Java'] | 0 |
determine-color-of-a-chessboard-square | Simple if-else faster than 83% | simple-if-else-faster-than-83-by-aruj900-zl7k | \nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n black = "aceg"\n white = "bdfh"\n if coordinates[0] in black an | aruj900 | NORMAL | 2022-08-29T10:13:12.823343+00:00 | 2022-08-29T10:13:12.823390+00:00 | 373 | false | ```\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n black = "aceg"\n white = "bdfh"\n if coordinates[0] in black and int(coordinates[1]) % 2 == 1:\n return False\n elif coordinates[0] in white and int(coordinates[1]) % 2 == 0:\n return False\n... | 2 | 0 | ['Python', 'Python3'] | 0 |
determine-color-of-a-chessboard-square | [Python] One Line Solution || Faster than 94% | python-one-line-solution-faster-than-94-2tz5h | Python Code -\n\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n alphabets=\'abcdefgh\'\n return True if (alphabets.inde | rksreeraj | NORMAL | 2022-08-16T11:49:43.901082+00:00 | 2022-08-16T11:49:43.901128+00:00 | 104 | false | # Python Code -\n```\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n alphabets=\'abcdefgh\'\n return True if (alphabets.index(coordinates[0]) + int(coordinates[1])) % 2 == 0 else False\n``` | 2 | 0 | ['Python'] | 0 |
determine-color-of-a-chessboard-square | [PYTHON 3] EASY | SELF EXPLANITORY | python-3-easy-self-explanitory-by-omkarx-l53h | ```\nclass Solution:\n def squareIsWhite(self, c: str) -> bool:\n e,o = ["b","d","f","h"], ["a","c","e","g"]\n if int(c[-1]) % 2 == 0:\n | omkarxpatel | NORMAL | 2022-07-13T14:41:03.033188+00:00 | 2022-07-13T14:41:03.033225+00:00 | 610 | false | ```\nclass Solution:\n def squareIsWhite(self, c: str) -> bool:\n e,o = ["b","d","f","h"], ["a","c","e","g"]\n if int(c[-1]) % 2 == 0:\n if c[0] in e: return False\n else: return True\n else:\n if c[0] in e: return True\n else: return False\n | 2 | 0 | ['Python', 'Python3'] | 0 |
determine-color-of-a-chessboard-square | ✔ C++ || one-liner easy O(1) | c-one-liner-easy-o1-by-_aditya_hegde-snlw | Intuition:-\n\n-> You can easily get the pattern in the chessboard.\n-> sum( x, y ) of any co-ordinate is even -> Its black square (return 0)\n-> sum( x, y ) of | _Aditya_Hegde_ | NORMAL | 2022-06-18T09:38:36.421469+00:00 | 2022-06-18T09:38:36.421508+00:00 | 59 | false | **Intuition:-**\n\n-> You can easily get the **pattern** in the chessboard.\n-> sum( x, y ) of any co-ordinate is **even** -> Its **black square** (return 0)\n-> sum( x, y ) of any co-ordinate is **odd** -> its **while square** (return 1)\n-> also I have used **bitwise AND operator** to check odd or even. (&)\n-> I hav... | 2 | 0 | ['C'] | 0 |
determine-color-of-a-chessboard-square | Easy python solution | easy-python-solution-by-rupeshmohanty-eu8q | \nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n odds = [\'a\',\'c\',\'e\',\'g\']\n evens = [\'b\',\'d\',\'f\',\'h\']\n | rupeshmohanty | NORMAL | 2022-06-07T14:40:06.585294+00:00 | 2022-06-07T14:40:06.585343+00:00 | 99 | false | ```\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n odds = [\'a\',\'c\',\'e\',\'g\']\n evens = [\'b\',\'d\',\'f\',\'h\']\n \n if coordinates[0] in odds:\n if int(coordinates[1]) % 2 != 0:\n return False\n else:\n ... | 2 | 0 | ['Python'] | 0 |
determine-color-of-a-chessboard-square | Java One-liner with explanation | java-one-liner-with-explanation-by-alexg-e66r | \nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n return (coordinates.charAt(0) + coordinates.charAt(1)) % 2 != 0;\n }\n}\n | alexgornovoi | NORMAL | 2022-03-19T16:56:02.384628+00:00 | 2022-03-19T16:58:50.524049+00:00 | 102 | false | ```\nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n return (coordinates.charAt(0) + coordinates.charAt(1)) % 2 != 0;\n }\n}\n```\nThe ASCII decimal value for the letter "a" is odd and the ASCII decimal value for "b" is even and "c" is odd ... etc. As for the numbers the ASCII value... | 2 | 0 | ['Java'] | 2 |
determine-color-of-a-chessboard-square | Python C one line | python-c-one-line-by-mrchuck-a5fe | py\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n return sum(map(ord,coordinates)) % 2\n\nc\nbool squareIsWhite(char * coordi | mrchuck | NORMAL | 2022-02-26T13:25:30.600766+00:00 | 2022-02-26T13:26:54.491315+00:00 | 166 | false | ```py\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n return sum(map(ord,coordinates)) % 2\n```\n```c\nbool squareIsWhite(char * coordinates){\n return (*coordinates + *++coordinates) % 2;\n}\n``` | 2 | 0 | ['C', 'Python'] | 0 |
determine-color-of-a-chessboard-square | Easy Solution 100% fast | easy-solution-100-fast-by-deepank4-udiq | \nclass Solution {\npublic:\n bool squareIsWhite(string c) {\n\t//if sum of cordinates is even than color is black \n int x = c[0]-\'a\'+1;\n i | deepank4 | NORMAL | 2022-01-19T18:09:40.299367+00:00 | 2022-01-19T18:09:40.299411+00:00 | 177 | false | ```\nclass Solution {\npublic:\n bool squareIsWhite(string c) {\n\t//if sum of cordinates is even than color is black \n int x = c[0]-\'a\'+1;\n int y = c[1]-\'1\'+1;\n cout<<y << "\\n ";\n if((x+y)%2==0)\n return false;\n return true;\n }\n};\n``` | 2 | 0 | ['C', 'C++'] | 0 |
determine-color-of-a-chessboard-square | Beginner friendly JavaScript solution | beginner-friendly-javascript-solution-by-k7s1 | Time Complexity : O(n)\n\n/**\n * @param {string} coordinates\n * @return {boolean}\n */\nvar squareIsWhite = function(coordinates) {\n let oddchar = "aceg", | HimanshuBhoir | NORMAL | 2022-01-19T08:53:41.226948+00:00 | 2022-01-19T08:53:41.226981+00:00 | 127 | false | **Time Complexity : O(n)**\n```\n/**\n * @param {string} coordinates\n * @return {boolean}\n */\nvar squareIsWhite = function(coordinates) {\n let oddchar = "aceg", evenchar = "bdfh", ch = coordinates.charAt(0), n = parseInt(coordinates.charAt(1)+"");\n if((n % 2 != 0 && oddchar.includes(ch)) || (n % 2 == 0 && ev... | 2 | 0 | ['JavaScript'] | 0 |
determine-color-of-a-chessboard-square | Short || Clean || One Liner || Java | short-clean-one-liner-java-by-himanshubh-30ks | \njava []\nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n return (coordinates.charAt(0)-\'a\'+ coordinates.charAt(1)-\'0\') % | HimanshuBhoir | NORMAL | 2022-01-19T08:52:51.226840+00:00 | 2023-01-05T11:04:10.646269+00:00 | 74 | false | \n```java []\nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n return (coordinates.charAt(0)-\'a\'+ coordinates.charAt(1)-\'0\') % 2 == 0;\n }\n}\n``` | 2 | 0 | ['Java'] | 0 |
determine-color-of-a-chessboard-square | c++ 100 % faster | c-100-faster-by-mannu_story07-wixs | class Solution {\npublic:\n bool squareIsWhite(string coordinates) {\n int x = coordinates[0]-\'a\';\n int y = coordinates[1] - 1;\n if( | Mannu_story07 | NORMAL | 2021-10-02T05:49:31.265547+00:00 | 2021-10-02T05:49:31.265605+00:00 | 61 | false | class Solution {\npublic:\n bool squareIsWhite(string coordinates) {\n int x = coordinates[0]-\'a\';\n int y = coordinates[1] - 1;\n if((x % 2 == 0 && y % 2 ==0 || x % 2 != 0 && y % 2 != 0)){\n return false;\n }\n else {\n return true;\n }\n }\n* 1... | 2 | 0 | [] | 0 |
determine-color-of-a-chessboard-square | [Java] 3 line simple %100 solution | java-3-line-simple-100-solution-by-zeldo-4uw7 | if you like it pls upvote\n\n\n\nJava\n\nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n int left = coordinates.charAt(0)-\'a\ | zeldox | NORMAL | 2021-08-29T22:48:11.378555+00:00 | 2021-08-29T22:48:11.378585+00:00 | 157 | false | if you like it pls upvote\n\n\n\nJava\n```\nclass Solution {\n public boolean squareIsWhite(String coordinates) {\n int left = coordinates.charAt(0)-\'a\';\n int right = coordinates.charAt(1)-\'1\'; \n return (left %2 == 0 && right % 2 == 1) || (left %2 != 0 && right % 2 != 1);\n }\n}\n`... | 2 | 0 | ['Java'] | 0 |
determine-color-of-a-chessboard-square | C++ 100% fast | c-100-fast-by-harshattree-ep2o | \n bool squareIsWhite(string coordinates) {\n int a=coordinates[0]+coordinates[1];\n if(a%2==1)\n return true;\n return false;\n | HarshAttree | NORMAL | 2021-07-22T05:16:50.723722+00:00 | 2021-07-22T05:16:50.723766+00:00 | 51 | false | ```\n bool squareIsWhite(string coordinates) {\n int a=coordinates[0]+coordinates[1];\n if(a%2==1)\n return true;\n return false;\n }\n``` | 2 | 0 | [] | 0 |
determine-color-of-a-chessboard-square | 100% faster one line [Java] Solution with explanation | 100-faster-one-line-java-solution-with-e-wlld | Imagine the x cordinate are also 1,2,3...so on. \n\n\nIdea is : Now, when we see this board we can find the logic that.\n- If x and y both are even Or odd then | HemantPatel | NORMAL | 2021-07-02T04:31:36.505750+00:00 | 2021-07-02T04:31:36.505798+00:00 | 148 | false | Imagine the x cordinate are also 1,2,3...so on. <br>\n<img src="https://assets.leetcode.com/users/images/36b5a71a-2639-4344-9edc-f88982b9096a_1625199149.2753234.png" alt="chess board image" width="300" height="auto">\n\n**Idea is :** Now, when we see this board we can find the logic that.\n- If x and y both are even Or... | 2 | 0 | ['Java'] | 0 |
determine-color-of-a-chessboard-square | C++ || One Liner || Easy understanding || With Comments | c-one-liner-easy-understanding-with-comm-iwpi | //Idea behind this to find a unique square number.\n//If that square number is even it will be white , else black.\n\nclass Solution {\npublic:\n bool square | ajaayush | NORMAL | 2021-06-22T07:13:51.944594+00:00 | 2021-06-22T07:13:51.944637+00:00 | 152 | false | //Idea behind this to find a unique square number.\n//If that square number is even it will be white , else black.\n```\nclass Solution {\npublic:\n bool squareIsWhite(string coordinates) {\n int i= (int)(coordinates[0]-\'a\'+1) + (int)(coordinates[1]-\'0\');\n if(i%2==0)\n return false;\n ... | 2 | 0 | ['Math', 'C', 'C++'] | 0 |
determine-color-of-a-chessboard-square | PYTHON 1 LINER || WITH EXPLANATION | python-1-liner-with-explanation-by-mahad-wxm0 | \nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n \'\'\'\n check if file/x-coordinate and rank/y-coordinate are both eve | mahadrehan | NORMAL | 2021-06-22T05:33:13.010244+00:00 | 2021-06-22T05:43:05.748527+00:00 | 80 | false | ```\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n \'\'\'\n check if file/x-coordinate and rank/y-coordinate are both even or are both odd\n must be odd rank with even file, or odd file with even rank for it to be a white square\n \'\'\'\n return int(coordi... | 2 | 0 | [] | 0 |
determine-color-of-a-chessboard-square | JAVA ONE LINER | java-one-liner-by-tanmaymishrapersonal-xu6a | \nclass Solution {\n public boolean squareIsWhite(String coordinates) \n {\n return ((coordinates.charAt(0)-\'a\'+coordinates.charAt(1)-\'1\')%2!=0) | tanmaymishrapersonal | NORMAL | 2021-06-12T18:25:15.159085+00:00 | 2021-06-12T18:25:15.159117+00:00 | 66 | false | ```\nclass Solution {\n public boolean squareIsWhite(String coordinates) \n {\n return ((coordinates.charAt(0)-\'a\'+coordinates.charAt(1)-\'1\')%2!=0);\n }\n}\n\n \n``` | 2 | 0 | [] | 2 |
determine-color-of-a-chessboard-square | Java || 1 Liner || 0ms || beats 100% || T.C - O(1) S.C - O(1) | java-1-liner-0ms-beats-100-tc-o1-sc-o1-b-rm6v | \n\tpublic boolean squareIsWhite(String coordinates) {\n \n char ch = coordinates.charAt(0);\n int num = coordinates.charAt(1);\n \n | LegendaryCoder | NORMAL | 2021-05-18T17:08:00.715892+00:00 | 2021-05-18T17:08:00.715935+00:00 | 63 | false | \n\tpublic boolean squareIsWhite(String coordinates) {\n \n char ch = coordinates.charAt(0);\n int num = coordinates.charAt(1);\n \n int val = (ch - \'a\') + (num - \'0\');\n return (val % 2 == 0) ? true : false;\n } | 2 | 1 | [] | 0 |
determine-color-of-a-chessboard-square | Easy C# Solution | easy-c-solution-by-venendroid-x3vx | \n public bool SquareIsWhite(string coordinates)\n {\n //From the chess board we can see BLACK box are in ODD integer places for these columns \n | venendroid | NORMAL | 2021-04-22T06:15:24.130890+00:00 | 2021-04-22T06:15:24.130929+00:00 | 59 | false | ```\n public bool SquareIsWhite(string coordinates)\n {\n //From the chess board we can see BLACK box are in ODD integer places for these columns \n var oddBlackList = new HashSet<char>(){\'a\', \'c\', \'e\', \'g\'};\n \n //Whole idea is:\n //From the give coordinates, if first cha... | 2 | 0 | [] | 0 |
determine-color-of-a-chessboard-square | python one line sol (faster than 93%) (less mem than 100%) | python-one-line-sol-faster-than-93-less-6h4vm | \nclass Solution(object):\n def squareIsWhite(self, coordinates):\n return ((ord(coordinates[0])) + int(coordinates[1])) % 2\n | elayan | NORMAL | 2021-04-15T11:00:10.235463+00:00 | 2021-04-15T11:00:10.235505+00:00 | 48 | false | ```\nclass Solution(object):\n def squareIsWhite(self, coordinates):\n return ((ord(coordinates[0])) + int(coordinates[1])) % 2\n``` | 2 | 1 | [] | 2 |
determine-color-of-a-chessboard-square | [C++] [Time-O(1)] | c-time-o1-by-turbotorquetiger-qmjg | Time Complexity: O(1)\nSpace Complexity: O(1)\n\n\nclass Solution \n{\npublic:\n bool squareIsWhite(string cood)\n {\n int f = cood[0]-\'a\';\n | ihavehiddenmyid | NORMAL | 2021-04-10T15:23:10.874530+00:00 | 2021-04-10T15:23:10.874555+00:00 | 117 | false | **Time Complexity: O(1)\nSpace Complexity: O(1)**\n\n```\nclass Solution \n{\npublic:\n bool squareIsWhite(string cood)\n {\n int f = cood[0]-\'a\';\n int s = cood[1]-\'0\';\n \n // f = a, c, e, g\n if ( f % 2 == 0 ) {\n if ( s % 2 == 0 ) {\n return tru... | 2 | 0 | ['C'] | 0 |
determine-color-of-a-chessboard-square | Javascript, 100% faster, simple | javascript-100-faster-simple-by-mstaso1-vte3 | \nvar squareIsWhite = function(coordinates) {\n const columns = [\'a\', \'b\', \'c\', \'d\', \'e\', \'f\', \'g\', \'h\']\n \n let i = 0;\n \n whi | mstaso1 | NORMAL | 2021-04-07T18:44:29.238181+00:00 | 2021-04-07T18:44:29.238213+00:00 | 114 | false | ```\nvar squareIsWhite = function(coordinates) {\n const columns = [\'a\', \'b\', \'c\', \'d\', \'e\', \'f\', \'g\', \'h\']\n \n let i = 0;\n \n while(coordinates[0] !== columns[i]) {\n i++;\n }\n \n let num = i + parseInt(coordinates[1]);\n \n \n return num % 2 === 0 \n \n};\... | 2 | 0 | [] | 1 |
determine-color-of-a-chessboard-square | [Python] 1-lines | python-1-lines-by-maiyude-7ccm | \nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n return True if ((ord(coordinates[0]))+int(coordinates[1])) % 2 else False\n | maiyude | NORMAL | 2021-04-03T16:46:43.207322+00:00 | 2021-04-03T16:46:43.207365+00:00 | 208 | false | ```\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n return True if ((ord(coordinates[0]))+int(coordinates[1])) % 2 else False\n``` | 2 | 0 | ['Python', 'Python3'] | 1 |
determine-color-of-a-chessboard-square | Simple Python 3 solution | simple-python-3-solution-by-swap24-jnc9 | \nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n x, y = ord(coordinates[0]) - 65, int(coordinates[1])\n return y % 2 == | swap24 | NORMAL | 2021-04-03T16:28:22.022359+00:00 | 2021-04-03T16:28:22.022401+00:00 | 83 | false | ```\nclass Solution:\n def squareIsWhite(self, coordinates: str) -> bool:\n x, y = ord(coordinates[0]) - 65, int(coordinates[1])\n return y % 2 == 1 if x % 2 == 1 else y % 2 == 0\n``` | 2 | 0 | [] | 0 |
determine-color-of-a-chessboard-square | C# one liner | 0ms, beats 100% | c-one-liner-0ms-beats-100-by-bkga9sasfa-xoas | Complexity
Time complexity: O(1)
Space complexity: O(1)
Code | bKGa9sAsfA | NORMAL | 2025-03-07T10:03:28.191008+00:00 | 2025-03-07T10:03:28.191008+00:00 | 23 | false | # Complexity
- Time complexity: $$O(1)$$
- Space complexity: $$O(1)$$
# Code
```csharp []
public class Solution {
public bool SquareIsWhite(string coordinates) {
return ((coordinates[0] + coordinates[1]) & 1) == 1;
}
}
``` | 1 | 0 | ['C#'] | 0 |
determine-color-of-a-chessboard-square | Beats 100% , simple approach... | beats-100-simple-approach-by-arun_george-3hvo | IntuitionThe problem involves determining the color of a square on a chessboard given its coordinates. Chessboards have alternating colors, and the color of a s | Arun_George_ | NORMAL | 2025-03-05T16:55:30.003942+00:00 | 2025-03-06T16:12:03.709795+00:00 | 91 | false | # Intuition
The problem involves determining the color of a square on a chessboard given its coordinates. Chessboards have alternating colors, and the color of a square can be determined based on the combination of its letter (column) and number (row).
 | c-7-lines-dp-on-n-m-by-votrubac-pe0i | A twist of the 300. Longest Increasing Subsequence problem.\n\nFor each position i,we track the maximum increasing subsequence. To do that, we analyze all j < i | votrubac | NORMAL | 2018-12-19T04:54:05.665157+00:00 | 2018-12-19T04:54:05.665223+00:00 | 3,064 | false | A twist of the [300. Longest Increasing Subsequence](https://leetcode.com/problems/longest-increasing-subsequence/description/) problem.\n\nFor each position ```i```,we track the maximum increasing subsequence. To do that, we analyze all ```j < i```, and if ```A[j] < A[i]``` for *all strings* , then ```dp[i] = dp[j] + ... | 45 | 2 | [] | 7 |
delete-columns-to-make-sorted-iii | C++. Variation of LIS. Easy to understand. | c-variation-of-lis-easy-to-understand-by-yv99 | \nclass Solution {\npublic:\n int minDeletionSize(vector<string>& A) {\n int m = A.size();\n int n = A[0].size();\n vector<int> dp(A[0]. | user5787i | NORMAL | 2019-06-16T13:28:28.008161+00:00 | 2019-06-16T13:28:28.008199+00:00 | 1,367 | false | ```\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& A) {\n int m = A.size();\n int n = A[0].size();\n vector<int> dp(A[0].size(), 1);\n for(int i = 0; i < n; i++) {\n for(int j = 0; j < i; j++) {\n if(cmp(A, i, j)) {\n dp[i] = ... | 13 | 0 | [] | 2 |
delete-columns-to-make-sorted-iii | TypeScript | Memory beats 100% | typescript-memory-beats-100-by-r9n-2wg9 | Intuition\nKeep rows in order by deleting the minimum number of columns.\n\n# Approach\nDynamic Programming (DP): Track the longest sequence of valid columns.\n | r9n | NORMAL | 2024-09-10T21:47:13.610396+00:00 | 2024-09-10T21:47:13.610422+00:00 | 37 | false | # Intuition\nKeep rows in order by deleting the minimum number of columns.\n\n# Approach\nDynamic Programming (DP): Track the longest sequence of valid columns.\n\nCompare Columns: Check if one column can follow another in all rows.\n\nCompute Deletions: The result is the total columns minus the length of the longest v... | 9 | 0 | ['TypeScript'] | 0 |
delete-columns-to-make-sorted-iii | Python 3 || 6 lines, dp || T/S: 75% / 99% | python-3-6-lines-dp-ts-75-99-by-spauldin-v61m | \nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n\n n = len(strs[0])\n\n isValid = lambda x: all(s[x] <= s[j] for s in s | Spaulding_ | NORMAL | 2023-08-17T20:28:48.267668+00:00 | 2024-05-31T18:55:55.578372+00:00 | 257 | false | ```\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n\n n = len(strs[0])\n\n isValid = lambda x: all(s[x] <= s[j] for s in strs)\n\n dp = [1] * n\n\n for j in range(1, n):\n\n dp[j] = max((dp[x] for x in \n filter(isValid,range(j)))... | 8 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | Java simple LIS for all Strings. Faster than 98.76% | java-simple-lis-for-all-strings-faster-t-icp4 | ```\n\tpublic int minDeletionSize(String[] A) {\n int max= 1;\n int[] Lis= new int[A[0].length()];\n for(int i=0; i<A[0].length(); i++){\n | sunnydhotre | NORMAL | 2021-02-13T01:07:07.638573+00:00 | 2021-02-13T01:07:07.638617+00:00 | 605 | false | ```\n\tpublic int minDeletionSize(String[] A) {\n int max= 1;\n int[] Lis= new int[A[0].length()];\n for(int i=0; i<A[0].length(); i++){\n Lis[i]= 1;\n for(int j=0; j<i; j++){\n if(checkLexicographic(A,i,j)){\n Lis[i]= Math.max(Lis[i],Lis[j]+1... | 6 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | c++ solution based on graph theory and bfs | c-solution-based-on-graph-theory-and-bfs-52am | Regard this problem as the longest connection path problem for a graph, refer to the codes and comments below.\n\nclass Solution {\npublic:\n int minDeletion | jiayinggao | NORMAL | 2022-05-27T17:50:05.632910+00:00 | 2022-05-27T17:50:05.632957+00:00 | 547 | false | Regard this problem as the longest connection path problem for a graph, refer to the codes and comments below.\n``` \nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n int single_size = strs.front().size();\n // printf("step1: establish the edges of the graph.\\n");\n vec... | 5 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | C++ Solution | Longest Increasing Subsequence | c-solution-longest-increasing-subsequenc-17hf | Make a vector of strings (in this case, v) in same column, and find maximum increasing subsequence among those strings. \nCheck function checks whether a string | harshnadar23 | NORMAL | 2021-09-03T05:29:01.442756+00:00 | 2021-09-03T05:29:35.143252+00:00 | 472 | false | Make a vector of strings (in this case, v) in same column, and find maximum increasing subsequence among those strings. \nCheck function checks whether a string a is less than b according to the definition given. (every character should be lexographically less than or equal to corresponding one in b).\nI would suggest ... | 5 | 0 | ['Dynamic Programming'] | 0 |
delete-columns-to-make-sorted-iii | [Python3] top-down dp | python3-top-down-dp-by-ye15-qps3 | \n\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n m, n = len(strs), len(strs[0]) # dimensions\n \n @cache \n | ye15 | NORMAL | 2021-06-08T03:40:02.347707+00:00 | 2021-06-08T03:40:26.624368+00:00 | 333 | false | \n```\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n m, n = len(strs), len(strs[0]) # dimensions\n \n @cache \n def fn(k, prev):\n """Return min deleted columns to make sorted."""\n if k == n: return 0 \n ans = 1 + fn(k+1, prev) # ... | 5 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | Java Solution With Explanation | java-solution-with-explanation-by-naveen-1kfu | Idea\nPrereq https://leetcode.com/problems/longest-increasing-subsequence/discuss/342274/Intuitive-Java-Solution-With-Explanation\n\nNow, when filling the dp ar | naveen_kothamasu | NORMAL | 2019-07-24T04:00:22.142200+00:00 | 2019-07-24T04:00:22.142232+00:00 | 642 | false | **Idea**\n**Prereq** https://leetcode.com/problems/longest-increasing-subsequence/discuss/342274/Intuitive-Java-Solution-With-Explanation\n\nNow, when filling the `dp` array instead of looking at one string for comparing `i` and `j` indices, we need to look at all strings at those indices and confirm char at `i` can be... | 4 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Solution | solution-by-deleted_user-d7gn | C++ []\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n \n int n = strs.size();\n int m = strs[0].length();\n\ | deleted_user | NORMAL | 2023-05-16T12:39:56.258657+00:00 | 2023-05-16T13:34:13.691015+00:00 | 377 | false | ```C++ []\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n \n int n = strs.size();\n int m = strs[0].length();\n\n vector<int> dp(m, 1);\n int res = 1;\n for(int i = 0; i < m; i++) {\n for(int j = 0; j < i; j++) {\n for(int... | 3 | 0 | ['C++', 'Java', 'Python3'] | 0 |
delete-columns-to-make-sorted-iii | Beats 98% || C++ || DP || Memoization | beats-98-c-dp-memoization-by-akash92-o71h | Intuition\n Describe your first thoughts on how to solve this problem. \nIf we can find the longest non decreasing common subsequence in all the strings, then w | akash92 | NORMAL | 2024-09-07T04:35:42.866345+00:00 | 2024-09-07T04:35:42.866388+00:00 | 107 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nIf we can find the longest non decreasing common subsequence in all the strings, then we can subtract its length from the total length of the string to get the minimum deletions.\n\n# Approach\n<!-- Describe your approach to solving the p... | 2 | 0 | ['Array', 'String', 'Dynamic Programming', 'Recursion', 'Memoization', 'C++'] | 0 |
delete-columns-to-make-sorted-iii | [C++] Simple Dynamic Programming || Memoization | c-simple-dynamic-programming-memoization-oiqg | Approach: \n We need to ensure that after all the deletions, all the strings remain lexicographically sorted (increasing order i.e prev_char<=current_char). \n | yagni99 | NORMAL | 2024-05-02T06:21:47.720549+00:00 | 2024-05-02T06:32:09.298911+00:00 | 118 | false | **Approach**: \n* We need to ensure that after all the deletions, all the strings remain lexicographically sorted (increasing order i.e ```prev_char<=current_char```). \n* We maintain current index and a previous index as our dp states. At each current index we choose whether to delete that index or not (deleting will ... | 2 | 0 | ['Dynamic Programming', 'Recursion', 'Memoization'] | 0 |
delete-columns-to-make-sorted-iii | C++| Recursion + Memo | c-recursion-memo-by-kumarabhi98-ofen | In simple words, a String in lexicographically increasing if last character is smaller than or equal to the current character in a string.\n1. Using this idea, | kumarabhi98 | NORMAL | 2022-03-25T13:58:10.906498+00:00 | 2022-03-25T14:00:22.369931+00:00 | 342 | false | In simple words, a String in lexicographically increasing if last character is smaller than or equal to the current character in a string.\n1. Using this idea, try to delete every index keeping the record of `last` (closest previous index which is not deleted). \n1. There is also a possibility that we do not need to de... | 2 | 1 | ['Memoization', 'C'] | 0 |
delete-columns-to-make-sorted-iii | [C++] O(n^2) Alternate intuition (not LIS) Bottom-up DP. 16ms | c-on2-alternate-intuition-not-lis-bottom-sd2m | Define dp[i+1] as min deletions in strs[0...i] necessary to make every string in strs[0...i]\'s columns in lexicographical order where we are not deleting the | jossheim | NORMAL | 2021-07-16T03:55:13.084624+00:00 | 2021-07-16T04:33:22.233589+00:00 | 252 | false | Define `dp[i+1]` as min deletions in `strs[0...i]` necessary to make every string in `strs[0...i]`\'s columns in lexicographical order where we are **not deleting** the `i+1th` column (`strs[i]`).\n\n`m`: Number of strings in `strs`.\n\nRelation:\n```dp[i] = min {dp[k] + (i-k-1)} for all k in [0, i-1] such that strs[j... | 2 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Python3 - Longest Increasing Subsequence | python3-longest-increasing-subsequence-b-b1ar | For each column iterate all columns before it which forms a increasing sequence of characters which will give you the longest such subsequence. Then you can del | havingfun | NORMAL | 2020-06-15T11:25:19.884179+00:00 | 2020-06-15T11:25:19.884215+00:00 | 277 | false | For each column iterate all columns before it which forms a increasing sequence of characters which will give you the longest such subsequence. Then you can delete all other columns to get one of the longest subsequence.\n\nIntution -\nThink about how will you solve this problem if you have a single string ->\n1st Idea... | 2 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | easy python solution with memoization | easy-python-solution-with-memoization-by-uw69 | for A = ["babca","bbazb"]\nfirst we conver it to\nb,b line 1\na,b line 2\nb,a line 3\nc,z line 4\na,b line 5\n\nwhether we should left line 1 or not is determin | bupt_wc | NORMAL | 2018-12-16T04:11:44.940037+00:00 | 2018-12-16T04:11:44.940135+00:00 | 737 | false | for A = ["babca","bbazb"]\nfirst we conver it to\n`b,b` line 1\n`a,b` line 2\n`b,a` line 3\n`c,z` line 4\n`a,b` line 5\n\nwhether we should left `line 1` or not is determined by which will get smaller `D.length`.\nif we do not delete this line, then the next line\'s element should all be larger than this line, otherwis... | 2 | 0 | [] | 1 |
delete-columns-to-make-sorted-iii | DP | Memoization | Pick/Notpick approach | C++ | dp-memoization-picknotpick-approach-c-by-ezw9 | \nclass Solution {\npublic:\n int dp[105][105];\n int solve(int ind, int n, int prev, vector<string>& strs) {\n if(ind == n) return 0;\n if( | siddh5599 | NORMAL | 2023-09-08T10:07:40.977690+00:00 | 2023-09-08T10:07:40.977720+00:00 | 318 | false | ```\nclass Solution {\npublic:\n int dp[105][105];\n int solve(int ind, int n, int prev, vector<string>& strs) {\n if(ind == n) return 0;\n if(prev >= 0 && dp[ind][prev] != -1) return dp[ind][prev];\n int minval = 150;\n int flag = 0;\n for(int i = 0;i < strs.size();i++) {\n ... | 1 | 0 | ['Dynamic Programming', 'Memoization'] | 1 |
delete-columns-to-make-sorted-iii | java easiest solution | java-easiest-solution-by-codewithlegend-vr3k | Code\n\nclass Solution {\npublic int minDeletionSize(String[] strs) {\n int n = strs.length;\n int m = strs[0].length();\n int[] dp = new int[m];\n | CodeWithLegend | NORMAL | 2023-05-11T14:55:40.746191+00:00 | 2023-05-11T14:55:40.746276+00:00 | 105 | false | # Code\n```\nclass Solution {\npublic int minDeletionSize(String[] strs) {\n int n = strs.length;\n int m = strs[0].length();\n int[] dp = new int[m];\n \n int overallMax = 0;\n for(int i=0;i<m;i++){\n dp[i] = 1;\n for(int j=0;j<i;j++){\n \n if(isValid(strs,i,j)){\n... | 1 | 0 | ['Java'] | 0 |
delete-columns-to-make-sorted-iii | EASY UNDERSTAND 70% FASTER C++ SOLUTION | easy-understand-70-faster-c-solution-by-dwz0p | \nclass Solution {\npublic:\n int check(vector<string> &v,int i,int j){\n for(int k = 0; k < v.size(); k++){\n if(v[k][j]>v[k][i])\n | abhay_12345 | NORMAL | 2022-12-01T09:07:50.080864+00:00 | 2022-12-01T09:07:50.080905+00:00 | 427 | false | ```\nclass Solution {\npublic:\n int check(vector<string> &v,int i,int j){\n for(int k = 0; k < v.size(); k++){\n if(v[k][j]>v[k][i])\n return 0;\n }\n return 1;\n }\n int minDeletionSize(vector<string>& strs) {\n vector<int> dp(strs[0].length(),1);\n ... | 1 | 0 | ['Dynamic Programming', 'Depth-First Search', 'C', 'C++'] | 1 |
delete-columns-to-make-sorted-iii | [Python3] O(mn^2) DP | python3-omn2-dp-by-cava-uygs | Intuition\n Describe your first thoughts on how to solve this problem. \nThis problem is similar to longest non-decrease subseqence, except we need to consider | cava | NORMAL | 2022-11-30T09:34:39.962255+00:00 | 2022-11-30T09:34:39.962299+00:00 | 183 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThis problem is similar to longest non-decrease subseqence, except we need to consider all strings at the same time.\n\n\n# Code\n```\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n m, n = len(strs), len(... | 1 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | JavaScript Solution | javascript-solution-by-crisdev2705-4m8m | Complexity\n- Memory: 42.8 MB\n\n- Runtime: 103 ms\n\n- Beats: 100%\n\n# Code\n\n/**\n * @param {string[]} strs\n * @return {number}\n */\nvar minDeletionSize = | crisdev2705 | NORMAL | 2022-11-18T04:46:40.934270+00:00 | 2022-11-18T04:48:42.819892+00:00 | 167 | false | # Complexity\n- Memory: 42.8 MB\n\n- Runtime: 103 ms\n\n- Beats: 100%\n\n# Code\n```\n/**\n * @param {string[]} strs\n * @return {number}\n */\nvar minDeletionSize = function(strs) {\n if (strs.length === 0) return 0\n let dp = new Array(strs[0].length).fill(1)\n for (let i = 1; i < strs[0].length; i++) {\n ... | 1 | 0 | ['JavaScript'] | 0 |
delete-columns-to-make-sorted-iii | [C++] | MEMOIZATION | DYNAMIC PROGRAAMING | c-memoization-dynamic-prograaming-by-jat-q8bv | \nclass Solution {\npublic:\n int dp[101][101];\n int helper(vector<string>&strs, int i, int j){\n if(i==strs[0].length()){\n return 0;\ | jatinbansal1179 | NORMAL | 2022-10-01T08:18:23.304192+00:00 | 2022-10-01T08:18:23.304234+00:00 | 318 | false | ```\nclass Solution {\npublic:\n int dp[101][101];\n int helper(vector<string>&strs, int i, int j){\n if(i==strs[0].length()){\n return 0;\n }\n if(dp[i][j]!=-1){\n return dp[i][j];\n }\n int ans = INT_MIN;\n bool b = false;\n \n for(int k ... | 1 | 1 | ['Dynamic Programming', 'Recursion', 'Memoization', 'C', 'C++'] | 1 |
delete-columns-to-make-sorted-iii | Delete Columns to Make Sorted III Solution Java | delete-columns-to-make-sorted-iii-soluti-ef2v | class Solution {\n public int minDeletionSize(String[] A) {\n final int n = A[0].length();\n // dp[i] := LIS ending at A[*][i]\n int[] dp = new int[n] | bhupendra786 | NORMAL | 2022-09-26T08:20:20.889886+00:00 | 2022-09-26T08:20:20.889924+00:00 | 270 | false | class Solution {\n public int minDeletionSize(String[] A) {\n final int n = A[0].length();\n // dp[i] := LIS ending at A[*][i]\n int[] dp = new int[n];\n Arrays.fill(dp, 1);\n\n for (int i = 1; i < n; ++i)\n for (int j = 0; j < i; ++j)\n if (isSorted(A, j, i))\n dp[i] = Math.max(dp[... | 1 | 0 | ['Array', 'String', 'Dynamic Programming'] | 0 |
delete-columns-to-make-sorted-iii | Java Basic Dp | java-basic-dp-by-mi1-ap3k | \nclass Solution {\n public int minDeletionSize(String[] strs) {\n for(int i=0;i<strs.length;i++){\n strs[i] = "0"+strs[i];\n }\n | mi1 | NORMAL | 2021-11-06T05:38:28.000759+00:00 | 2021-11-06T05:38:28.000805+00:00 | 99 | false | ```\nclass Solution {\n public int minDeletionSize(String[] strs) {\n for(int i=0;i<strs.length;i++){\n strs[i] = "0"+strs[i];\n }\n int[][]dp= new int[105][105];\n for(int[]row:dp) Arrays.fill(row,-1);\n return solve(strs,0,1,dp);\n }\n \n private int solve(Str... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Java DP | java-dp-by-prathihaspodduturi-37q8 | \nclass Solution {\n public boolean check(String s[],int i,int j)\n {\n for(int p=0;p<s.length;p++)\n {\n if(s[p].charAt(i)>s[p]. | prathihaspodduturi | NORMAL | 2021-10-16T08:51:37.837432+00:00 | 2021-10-16T08:51:37.837462+00:00 | 83 | false | ```\nclass Solution {\n public boolean check(String s[],int i,int j)\n {\n for(int p=0;p<s.length;p++)\n {\n if(s[p].charAt(i)>s[p].charAt(j))\n return false;\n }\n return true;\n }\n public int minDeletionSize(String[] s) {\n int n=s.length,m=s[0... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Python3 maximum increasing sequence with explanation (Runtime: 96 ms, faster than 100.00%) | python3-maximum-increasing-sequence-with-kcnh | Explanation:\nSave to dp[i] max len of possible string can be made out of all strings of str[0:i] when all satisfy the requirement.\nSo, first dp[0] is 1, becau | MVR11 | NORMAL | 2021-10-06T21:47:34.077788+00:00 | 2021-10-06T21:47:34.079699+00:00 | 124 | false | **Explanation:**\nSave to dp[i] max len of possible string can be made out of all strings of str[0:i] when all satisfy the requirement.\nSo, first dp[0] is 1, because if all strs are 1 char, then all satisfy the requirements.\nFor dp[1]:\n- check if all str[0] and [1] satisfy requirements. If so, save to dp[1] max of (... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | C++ | Solution | Fast and short | c-solution-fast-and-short-by-paraslaul-gl9d | \n int minDeletionSize(vector<string>& strs) {\n// so what question demands is internal sorting of strings (not among each other)\n// so what | ParasLaul | NORMAL | 2021-06-12T22:48:47.307330+00:00 | 2021-06-12T22:48:47.307372+00:00 | 214 | false | ```\n int minDeletionSize(vector<string>& strs) {\n// so what question demands is internal sorting of strings (not among each other)\n// so what this is a good variation of LIS and truly a hard question\n// so let me draw what i want to explain\n// 1. k-> b a b c a\n// 2. k-> b b a z b\n// ... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Solution in Go + Explanation | solution-in-go-explanation-by-lutraman-0y53 | After a long time and some pain, I figured that this problem can be seen as a graph problem:\n\nlet\'s look at this example: ["aaaaabaa", "abcdefgb"]\nrearrange | lutraman | NORMAL | 2021-04-09T11:05:27.907263+00:00 | 2021-04-26T09:30:42.175793+00:00 | 107 | false | After a long time and some pain, I figured that this problem can be seen as a graph problem:\n\nlet\'s look at this example: ["aaaaabaa", "abcdefgb"]\nrearranged to a matrix shape:\n```\n\ta a a a a b a a\n\ta b c d e f g b\n```\nWe can think of each column in the matrix as a node in the graph\n\nFrom each node to anot... | 1 | 0 | ['Dynamic Programming', 'Depth-First Search', 'Graph', 'Go'] | 0 |
delete-columns-to-make-sorted-iii | [Rust] 100% | rust-100-by-nickx720-n651 | \nimpl Solution {\n pub fn min_deletion_size(a: Vec<String>) -> i32 {\n let len = a[0].len();\n let mut dp: Vec<i32> = vec![1; len];\n let mut r | nickx720 | NORMAL | 2020-12-01T11:03:05.113883+00:00 | 2020-12-01T11:03:05.115136+00:00 | 84 | false | ```\nimpl Solution {\n pub fn min_deletion_size(a: Vec<String>) -> i32 {\n let len = a[0].len();\n let mut dp: Vec<i32> = vec![1; len];\n let mut res = 1;\n for i in 0..len {\n for j in 0..i {\n let mut flag: bool = false;\n for item in a.iter() {\n let ite... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Longest Increasing Subsequence - 1D DP | longest-increasing-subsequence-1d-dp-by-vsq0f | For general LIS problem, there is a nice O(nlogn) solution https://www.cs.princeton.edu/courses/archive/spring13/cos423/lectures/LongestIncreasingSubsequence.pd | huangdachuan | NORMAL | 2020-10-15T22:58:42.201100+00:00 | 2020-10-15T22:58:42.201144+00:00 | 178 | false | For general LIS problem, there is a nice O(nlogn) solution https://www.cs.princeton.edu/courses/archive/spring13/cos423/lectures/LongestIncreasingSubsequence.pdf\n```\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& A) {\n int n = A[0].size();\n vector<int> dp(n, 1);\n int lis = ... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Simple Java sol | simple-java-sol-by-cuny-66brother-yx49 | \nclass Solution {\n public int minDeletionSize(String[] A) {\n int dp[]=new int[A[0].length()];\n int res=1;\n Arrays.fill(dp,1);\n | CUNY-66brother | NORMAL | 2020-05-01T22:48:26.404305+00:00 | 2020-05-01T22:48:26.404360+00:00 | 128 | false | ```\nclass Solution {\n public int minDeletionSize(String[] A) {\n int dp[]=new int[A[0].length()];\n int res=1;\n Arrays.fill(dp,1);\n for(int i=1;i<A[0].length();i++){\n int longest=1;\n for(int j=i-1;j>=0;j--){\n boolean all=true;\n f... | 1 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | Accepted C# DP Solution | accepted-c-dp-solution-by-maxpushkarev-hya0 | \n public class Solution\n {\n public int MinDeletionSize(string[] rows)\n {\n int length = rows[0].Length;\n int [] d | maxpushkarev | NORMAL | 2020-03-18T02:55:49.301123+00:00 | 2020-03-18T02:55:49.301177+00:00 | 90 | false | ```\n public class Solution\n {\n public int MinDeletionSize(string[] rows)\n {\n int length = rows[0].Length;\n int [] dp = new int[length];\n\n for (int i = length - 1; i >= 0; i--)\n {\n dp[i] = length - i - 1;\n\n for (int... | 1 | 1 | ['Dynamic Programming'] | 0 |
delete-columns-to-make-sorted-iii | [C++] DP with Memo | c-dp-with-memo-by-shaktirajpandey1996-4xcw | Assumptions:-\nDP[i][j] will give information about minimum number of deletion required to make array index upto i lexicographically sorted where j is the previ | shaktirajpandey1996 | NORMAL | 2019-08-28T18:09:36.432235+00:00 | 2019-08-28T18:09:36.432272+00:00 | 303 | false | Assumptions:-\n**DP[i][j]** will give information about ***minimum number of deletion*** required to make array index upto **i** lexicographically sorted where j is the previously used value.\n\n```\nconst int inf = 1e8;\nclass Solution {\npublic:\n int N, M;\n vector<string > P;\n vector<vector<int> > DP;\n ... | 1 | 0 | [] | 1 |
delete-columns-to-make-sorted-iii | Java 10ms DP solution | java-10ms-dp-solution-by-brianjr-8dg9 | \nclass Solution {\n public int minDeletionSize(String[] A) {\n int len = A[0].length();\n int min = len;\n int[] dp = new int[len];\n | brianjr | NORMAL | 2018-12-16T18:44:01.095058+00:00 | 2018-12-16T18:44:01.095146+00:00 | 180 | false | ```\nclass Solution {\n public int minDeletionSize(String[] A) {\n int len = A[0].length();\n int min = len;\n int[] dp = new int[len];\n for(int i=1; i<len; i++) {\n dp[i] = i;\n for(int j=i-1; j>=0; j--) {\n if(canCompare(A, i, j)) {\n ... | 1 | 1 | [] | 0 |
delete-columns-to-make-sorted-iii | [Java] DP | Longest Increasing Subsequence | java-dp-longest-increasing-subsequence-b-ihss | My solution is O(kn^2) \n\n\n public int minDeletionSize(String[] A) {\n int[] dp = new int[A[0].length()];\n int max = 1;\n dp[0] = 1;\ | gcarrillo | NORMAL | 2018-12-16T04:00:53.003447+00:00 | 2018-12-16T04:00:53.003519+00:00 | 346 | false | My solution is ```O(kn^2)``` \n\n```\n public int minDeletionSize(String[] A) {\n int[] dp = new int[A[0].length()];\n int max = 1;\n dp[0] = 1;\n for(int i = 1; i < dp.length; i++){\n dp[i] = 1;\n for(int j = 0; j < i; j++){\n boolean mark = true;\n\t... | 1 | 1 | [] | 1 |
delete-columns-to-make-sorted-iii | C++ DP Solution based on LIS | c-dp-solution-based-on-lis-by-gengar33-ic61 | IntuitionInstead of caring for what to delete, think of what to keep. Since the questions says lexicographic, we can think of LIS approach.ApproachComplexity
T | gengar33 | NORMAL | 2025-03-14T04:48:10.111023+00:00 | 2025-03-14T04:48:10.111023+00:00 | 5 | false | # Intuition
Instead of caring for what to delete, think of what to keep. Since the questions says lexicographic, we can think of LIS approach.
# Approach
Idea here is to use LIS.
If you see the first 2 loops they are pretty much standard LIS way.
Now for each string, we check that if t... | 0 | 0 | ['Dynamic Programming', 'C++'] | 0 |
delete-columns-to-make-sorted-iii | C++ DP Solution based on LIS | c-dp-solution-based-on-lis-by-gengar33-ug2j | IntuitionInstead of caring for what to delete, think of what to keep. Since the questions says lexicographic, we can think of LIS approach.ApproachComplexity
T | gengar33 | NORMAL | 2025-03-14T04:45:24.671422+00:00 | 2025-03-14T04:45:24.671422+00:00 | 7 | false | # Intuition
Instead of caring for what to delete, think of what to keep. Since the questions says lexicographic, we can think of LIS approach.
# Approach
Idea here is to use LIS.
If you see the first 2 loops they are pretty much standard LIS way.
Now for each string, we check that if t... | 0 | 0 | ['Dynamic Programming', 'C++'] | 0 |
delete-columns-to-make-sorted-iii | 960. Delete Columns to Make Sorted III | 960-delete-columns-to-make-sorted-iii-by-hl4u | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | G8xd0QPqTy | NORMAL | 2025-01-02T03:48:18.851028+00:00 | 2025-01-02T03:48:18.851028+00:00 | 6 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Python'] | 0 |
delete-columns-to-make-sorted-iii | EASY PICK NOT PICK SOLUTION | easy-pick-not-pick-solution-by-uppalaaka-dhuq | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | UppalaAkash | NORMAL | 2025-01-01T13:31:08.627559+00:00 | 2025-01-01T13:31:08.627559+00:00 | 14 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | 100% Memory || 100% Runtime || DP || Memoized || with witout approach | 100-memory-100-runtime-dp-memoized-with-cw2hy | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | twinwal | NORMAL | 2024-12-17T12:03:14.711414+00:00 | 2024-12-17T12:03:14.711414+00:00 | 4 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Kotlin'] | 0 |
delete-columns-to-make-sorted-iii | Python (Simple DP) | python-simple-dp-by-rnotappl-lkh2 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | rnotappl | NORMAL | 2024-11-28T06:28:46.681586+00:00 | 2024-11-28T06:28:46.681622+00:00 | 3 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | python3 recursive dp | python3-recursive-dp-by-0icy-n0vh | \n# Code\npython3 []\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n\n @cache\n def dp(prev,i):\n if i>=len( | 0icy | NORMAL | 2024-11-22T05:26:49.390307+00:00 | 2024-11-22T05:26:49.390357+00:00 | 3 | false | \n# Code\n```python3 []\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n\n @cache\n def dp(prev,i):\n if i>=len(strs[0]):\n return 0\n t1 = 1+dp(prev,i+1)\n t2 = inf\n if prev == -1:\n t2 = dp(i,i+1)\n ... | 0 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | DP | dp-by-linda2024-2vy0 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | linda2024 | NORMAL | 2024-10-19T22:33:48.700246+00:00 | 2024-10-19T22:33:48.700262+00:00 | 3 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C#'] | 0 |
delete-columns-to-make-sorted-iii | pyhthon | pyhthon-by-hassam_472-q4cb | \n# Code\npython3 []\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n if not strs:\n return 0\n \n n = | hassam_472 | NORMAL | 2024-10-19T13:15:46.149910+00:00 | 2024-10-19T13:15:46.149944+00:00 | 5 | false | \n# Code\n```python3 []\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n if not strs:\n return 0\n \n n = len(strs)\n m = len(strs[0])\n \n # dp[i] represents the maximum length of the sorted subsequence ending at index i\n dp = [1] *... | 0 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | Pick max indices | pick-max-indices-by-theabbie-9nn8 | \nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n m = len(strs[0])\n @lru_cache(maxsize = None)\n def dp(i, prev) | theabbie | NORMAL | 2024-10-17T11:48:04.191704+00:00 | 2024-10-17T11:48:04.191727+00:00 | 0 | false | ```\nclass Solution:\n def minDeletionSize(self, strs: List[str]) -> int:\n m = len(strs[0])\n @lru_cache(maxsize = None)\n def dp(i, prev):\n if i >= m:\n return 0\n take = True\n for s in strs:\n if prev != -1 and s[prev] > s[i]:\n... | 0 | 0 | ['Python'] | 0 |
delete-columns-to-make-sorted-iii | delete-columns-to-make-sorted-iii - TypeScript Solution | delete-columns-to-make-sorted-iii-typesc-uckr | \n\n# Code\ntypescript []\nfunction minDeletionSize(strs: string[]): number {\n const numRows = strs.length;\n const numCols = strs[0].length;\n const | himashusharma | NORMAL | 2024-10-10T04:59:28.876193+00:00 | 2024-10-10T04:59:28.876229+00:00 | 2 | false | \n\n# Code\n```typescript []\nfunction minDeletionSize(strs: string[]): number {\n const numRows = strs.length;\n const numCols = strs[0].length;\n const dp: number[] = new Array(numCols).fill(1);\n let minDeletions = numCols;\n\n for(let i = 0; i < numCols; ++i){\n for(let j = 0; j<i; ++j){\n ... | 0 | 0 | ['Array', 'String', 'Dynamic Programming', 'TypeScript', 'JavaScript'] | 0 |
delete-columns-to-make-sorted-iii | Delete Column With DP | delete-column-with-dp-by-ansh1707-jt1l | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Ansh1707 | NORMAL | 2024-10-04T01:09:28.093089+00:00 | 2024-10-04T01:09:28.093112+00:00 | 1 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Python'] | 0 |
delete-columns-to-make-sorted-iii | Delete Columns to Make Sorted III | delete-columns-to-make-sorted-iii-by-sha-zmkk | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Shaludroid | NORMAL | 2024-09-06T21:24:23.664368+00:00 | 2024-09-06T21:24:23.664399+00:00 | 19 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Java'] | 0 |
delete-columns-to-make-sorted-iii | 960. Delete Columns to Make Sorted III.cpp | 960-delete-columns-to-make-sorted-iiicpp-p6d9 | Code\n\nclass Solution {\npublic:\n vector<bitset<100>>t; \n void fill_table(vector<string>& strs){\n for(auto &w: strs){\n vector<vector<int>>v(26, | 202021ganesh | NORMAL | 2024-08-22T10:09:53.330250+00:00 | 2024-08-22T10:09:53.330281+00:00 | 1 | false | **Code**\n```\nclass Solution {\npublic:\n vector<bitset<100>>t; \n void fill_table(vector<string>& strs){\n for(auto &w: strs){\n vector<vector<int>>v(26, vector<int>());\n v[w.back() - \'a\'].push_back(w.size()-1);\n for(int j = w.size()-2; j >= 0; j--){\n bitset<100>b;\n int id = w... | 0 | 0 | ['C'] | 0 |
delete-columns-to-make-sorted-iii | In C++ | in-c-by-ranjithgopinath-0mfu | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | RanjithGopinath | NORMAL | 2024-08-10T13:56:29.960076+00:00 | 2024-08-10T13:56:29.960103+00:00 | 13 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | very easy | very-easy-by-omsonekar4-tuhv | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | omsonekar4 | NORMAL | 2024-08-06T20:51:54.270521+00:00 | 2024-08-06T20:51:54.270545+00:00 | 4 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | DP: Maximal increasing subsequence(all strings through) | dp-maximal-increasing-subsequenceall-str-fpkf | Approach\nSimilar to the search for the maximum length of an increasing subsequence.\n\u041Enly the comparison goes through all strings in a special function\n# | sav20011962 | NORMAL | 2024-08-01T09:25:14.834287+00:00 | 2024-08-01T11:57:56.844867+00:00 | 9 | false | # Approach\nSimilar to the search for the maximum length of an increasing subsequence.\n\u041Enly the comparison goes through all strings in a special function\n# Complexity\n\n# Code\n```\n// similar to th... | 0 | 0 | ['Dynamic Programming', 'Kotlin'] | 0 |
delete-columns-to-make-sorted-iii | simple lis | simple-lis-by-harsh99429-ucd4 | \n# Complexity\n- Time complexity:\nO(n^2*m)\nm is the size of each string \n\n- Space complexity:\nO(n)\n\n# Code\n\nclass Solution:\n def minDeletionSize(s | harsh99429 | NORMAL | 2024-07-25T19:45:48.394421+00:00 | 2024-07-25T19:45:48.394457+00:00 | 8 | false | \n# Complexity\n- Time complexity:\n$$O(n^2*m)$$\nm is the size of each string \n\n- Space complexity:\n$$O(n)$$\n\n# Code\n```\nclass Solution:\n def minDeletionSize(self, l: List[str]) -> int:\n n=len(l[0]) #len of each str\n m=len(l) #len of list\n dp=[1 for _ in range(n)]\n\n for i i... | 0 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | C++ || DP || Commented | c-dp-commented-by-saiteja_balla0413-mk3c | \nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n int n=strs[0].size();\n vector<vector<int>> dp(n+1,vector<int>(n+1, | saiteja_balla0413 | NORMAL | 2024-04-19T15:03:30.879577+00:00 | 2024-04-19T15:03:30.879614+00:00 | 19 | false | ```\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n int n=strs[0].size();\n vector<vector<int>> dp(n+1,vector<int>(n+1,-1));\n return dfs(0,1,strs,dp);\n }\n //returns true if every string\'s char at ind is >= char at last, since it should be in lexicographical ... | 0 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | JS/TS Solution, beats 100% | jsts-solution-beats-100-by-jamauss-pgts | Able to determine the deletion size by using .charAt to compare with what\'s still left.\n\n# Code\n\nconst minDeletionSize = (strs: string[]): number => {\n | jamauss | NORMAL | 2023-12-21T18:33:48.869478+00:00 | 2023-12-21T18:33:48.869516+00:00 | 19 | false | Able to determine the deletion size by using `.charAt` to compare with what\'s still left.\n\n# Code\n```\nconst minDeletionSize = (strs: string[]): number => {\n \n const totalStrs = strs.length;\n const strSize = strs[0].length;\n let result:number = strSize - 1;\n let k:number = 0;\n\n let dp:numbe... | 0 | 0 | ['TypeScript', 'JavaScript'] | 0 |
delete-columns-to-make-sorted-iii | Solution to 960. Delete Columns to Make Sorted III | solution-to-960-delete-columns-to-make-s-vh1e | Intuition\n Describe your first thoughts on how to solve this problem. \nThe intuition behind this problem is to find the longest increasing subsequence of colu | Askalany | NORMAL | 2023-12-15T09:14:11.070911+00:00 | 2023-12-15T09:14:11.070934+00:00 | 44 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe intuition behind this problem is to find the longest increasing subsequence of columns. This is because the columns in the longest increasing subsequence do not need to be deleted to make the rows sorted. The remaining columns, which ... | 0 | 0 | ['Array', 'String', 'Dynamic Programming', 'Python3'] | 0 |
delete-columns-to-make-sorted-iii | python super easy to understand (dp top down) | python-super-easy-to-understand-dp-top-d-ce41 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | harrychen1995 | NORMAL | 2023-11-06T15:04:41.802657+00:00 | 2023-11-06T15:04:41.802687+00:00 | 25 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Dynamic Programming', 'Python3'] | 0 |
delete-columns-to-make-sorted-iii | Solution | solution-by-user0352v-85l4 | \n\n# Code\n\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n \n int n = strs.size();\n int m = strs[0].length | user0352V | NORMAL | 2023-10-30T15:13:21.014742+00:00 | 2023-10-30T15:13:21.014762+00:00 | 18 | false | \n\n# Code\n```\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n \n int n = strs.size();\n int m = strs[0].length();\n\n vector<int> dp(m, 1);\n int res = 1;\n for(int i = 0; i < m; i++) {\n for(int j = 0; j < i; j++) {\n f... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | CPP || INCLUDE - EXCLUDE CALL ONLY || DP || memoization | cpp-include-exclude-call-only-dp-memoiza-ciks | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | abhi_bittu2525 | NORMAL | 2023-10-12T17:39:33.803279+00:00 | 2023-10-12T17:39:33.803312+00:00 | 36 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | Efficient JS Solution (Beat over 80% time and 100% memory) | efficient-js-solution-beat-over-80-time-q9wr2 | \n\n# Approach\nClassic LIS.\n\n# Complexity\n- let n = strs.length, m = max(strs[i].length)\n- Time complexity: O(nm^2)\n- Space complexity: O(m)\n\n# Code\njs | CuteTN | NORMAL | 2023-10-03T19:13:31.043576+00:00 | 2023-10-03T19:13:31.043606+00:00 | 15 | false | \n\n# Approach\nClassic LIS.\n\n# Complexity\n- let `n = strs.length`, `m = max(strs[i].length)`\n- Time complexity: $$O(nm^2)$$\n- Space complexity: $$O(m)$$\n\n# Code\n```js\nlet dp = new Uint8Array(100);... | 0 | 0 | ['Dynamic Programming', 'JavaScript'] | 0 |
delete-columns-to-make-sorted-iii | C++, JavaScript, Java Solution. | c-javascript-java-solution-by-samuel-akt-w12n | \n\n# C++\n\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n int n = strs.size();\n int m = strs[0].size();\n | Samuel-Aktar-Laskar | NORMAL | 2023-09-12T16:25:19.747819+00:00 | 2023-09-12T16:41:39.518380+00:00 | 13 | false | \n\n# C++\n```\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n int n = strs.size();\n int m = strs[0].size();\n vector<int> ways(m,0);\n for(int i=m-1;i>=0;i--){\n int ans = 0;\n for(int j=i+1;j<m;j++){\n int k;\n ... | 0 | 0 | ['C++', 'JavaScript'] | 0 |
delete-columns-to-make-sorted-iii | C++ Easy Solution | c-easy-solution-by-md_aziz_ali-mg71 | Code\n\nclass Solution {\npublic:\n vector<vector<int>>dp;\n int solve(vector<string>& strs,int i,int n,int prev){\n if(i == n)\n return | Md_Aziz_Ali | NORMAL | 2023-09-09T02:32:39.001297+00:00 | 2023-09-09T02:32:39.001318+00:00 | 23 | false | # Code\n```\nclass Solution {\npublic:\n vector<vector<int>>dp;\n int solve(vector<string>& strs,int i,int n,int prev){\n if(i == n)\n return 0;\n if(dp[i][prev+1] != -1)\n return dp[i][prev + 1];\n bool flag = true;\n for(int j = 0;j < strs.size();j++){\n ... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | Easy to Understand DP solution | easy-to-understand-dp-solution-by-raj_ti-yaco | Explanation\nHere dp[i] means the solution for 1...i and taking the ith index in our solution. Similarly dp1[i] means the solution for i...n taking in the ith | raj_tirtha | NORMAL | 2023-08-30T08:09:56.963591+00:00 | 2023-08-30T08:09:56.963621+00:00 | 19 | false | # Explanation\nHere dp[i] means the solution for 1...i and taking the ith index in our solution. Similarly dp1[i] means the solution for i...n taking in the ith index. But for dp11 we will maintain the reverse order as after i the string should be increasing. Hence our final answer will be dp[i]+dp1[i]. Time complexit... | 0 | 0 | ['C++'] | 0 |
delete-columns-to-make-sorted-iii | Python 3: LIS DP Solution with comments; TC - 99.37% | python-3-lis-dp-solution-with-comments-t-62l0 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | hootielander | NORMAL | 2023-08-28T14:50:07.200436+00:00 | 2023-08-28T14:50:07.200468+00:00 | 23 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Python3'] | 0 |
delete-columns-to-make-sorted-iii | Python: pick or skip DP: top-down to 1D bottom-up optimized | python-pick-or-skip-dp-top-down-to-1d-bo-8xnh | "Pick or Skip DP" (Knapsack)\n\nYou can pick a column or skip it. Then you need to figure out when you can pick a column.\nYou can pick it when it\'s either the | vokasik | NORMAL | 2023-08-24T02:26:31.750267+00:00 | 2023-08-24T02:44:18.415820+00:00 | 26 | false | **"Pick or Skip DP" (Knapsack)**\n\nYou can pick a column or skip it. Then you need to figure out when you can pick a column.\nYou can pick it when it\'s either the first time you pick any column or `all_rows[prev_picked_col] < all_rows[trying_to_pick_col]`\nReturn `COLS - max(picked_columns)`\n\nLooks like medium LIS ... | 0 | 0 | ['Dynamic Programming', 'Python'] | 0 |
delete-columns-to-make-sorted-iii | Easy C# 100% | easy-c-100-by-kuramshin34-y9b4 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | kuramshin34 | NORMAL | 2023-08-23T08:02:08.901371+00:00 | 2023-08-23T08:02:08.901393+00:00 | 9 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C#'] | 0 |
delete-columns-to-make-sorted-iii | Simple C++ solution Based on LIS | simple-c-solution-based-on-lis-by-tag_98-1j1d | Intuition\n Describe your first thoughts on how to solve this problem. \nSame intuition as LIS\n\nIn this Problem we find the maximum length so our answer is ( | Tag_989 | NORMAL | 2023-07-10T14:22:18.688158+00:00 | 2023-07-10T14:22:18.688177+00:00 | 57 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nSame intuition as LIS\n\nIn this Problem we find the maximum length so our answer is **( strs[0].size() - maxlength )**\n\n# Code\n```\nclass Solution {\npublic:\n int minDeletionSize(vector<string>& strs) {\n int n=strs.size();... | 0 | 0 | ['Dynamic Programming', 'C++'] | 0 |
delete-columns-to-make-sorted-iii | My Solution | my-solution-by-hope_ma-5ovj | \n/**\n * Time Complexity: O(rows * cols * cols)\n * Space Complexity: O(cols)\n * where `rows` is the length of the vector `strs`\n * `cols` is the lengt | hope_ma | NORMAL | 2023-07-06T07:57:58.876254+00:00 | 2023-07-06T07:57:58.876284+00:00 | 18 | false | ```\n/**\n * Time Complexity: O(rows * cols * cols)\n * Space Complexity: O(cols)\n * where `rows` is the length of the vector `strs`\n * `cols` is the length of the string `strs.front()`\n */\nclass Solution {\n public:\n int minDeletionSize(const vector<string> &strs) {\n const int cols = static_cast<int>(s... | 0 | 0 | [] | 0 |
delete-columns-to-make-sorted-iii | (Python) Delete Columns to Make Sorted III | python-delete-columns-to-make-sorted-iii-28ef | Intuition\nThe intuition behind the approach is to use dynamic programming to find the length of the longest increasing subsequence (LIS) for each position in t | codewithsom | NORMAL | 2023-07-01T17:45:47.832552+00:00 | 2023-07-01T17:45:47.832571+00:00 | 32 | false | # Intuition\nThe intuition behind the approach is to use dynamic programming to find the length of the longest increasing subsequence (LIS) for each position in the strings. By keeping track of this information, we can determine the minimum number of deletions required to make all the strings lexicographically sorted.\... | 0 | 0 | ['Array', 'String', 'Dynamic Programming', 'Sorting', 'Python3'] | 0 |
delete-columns-to-make-sorted-iii | Scala solution | scala-solution-by-malovig-uy1m | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | malovig | NORMAL | 2023-06-16T20:02:10.773556+00:00 | 2023-06-16T20:02:10.773576+00:00 | 24 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity: O(m^2 * n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(m)\n<!-- Add your space complexity here, ... | 0 | 0 | ['Scala'] | 0 |
delete-columns-to-make-sorted-iii | O(n*m*m) DP solution | onmm-dp-solution-by-xjpig-bjpf | Intuition\n Describe your first thoughts on how to solve this problem. \ndp[i] memorize the longest increasing subsequnce up to ith position in the string.\n\n- | XJPIG | NORMAL | 2023-05-01T12:14:22.632308+00:00 | 2023-05-01T12:14:36.792077+00:00 | 46 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\ndp[i] memorize the longest increasing subsequnce up to ith position in the string.\n\n- Time complexity: $$O(n*m*m)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(m)$$\n<!-- Add your space complexity h... | 0 | 0 | ['C++'] | 0 |
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