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construct-the-minimum-bitwise-array-ii | Python3. O( n ). Backtracking, Update SET bits | python3-o-n-backtracking-update-set-bits-hy2c | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n \nSwitch bits one | srptv | NORMAL | 2024-10-12T16:05:54.754059+00:00 | 2024-10-13T01:37:19.831418+00:00 | 67 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n \nSwitch **bits** one by one and **check** if it\'s valid \n \n Ex: 10111\n\n 10110 check ( 10110 | (10110 - 1) == 10111?) no? go next, else return\n ... | 1 | 0 | ['Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | bitmask solution explain | bitmask-solution-explain-by-_dharamvir-z7xo | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | _dharamvir__ | NORMAL | 2024-10-12T16:05:03.287342+00:00 | 2024-10-12T16:10:35.955887+00:00 | 249 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:O(n*32)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:O(n)\n<!-- Add your space complexity here, e.g. ... | 1 | 0 | ['Array', 'Bitmask', 'C++'] | 3 |
construct-the-minimum-bitwise-array-ii | [Java] O(n) Look at the last block of ones | java-on-look-at-the-last-block-of-ones-b-90ej | Intuition\nWe have prime numbers only. They all are odd except 2. For 2 we always return -1. For all the others answer exists.\nWhen we add 1 to the number what | whoawhoawhoa | NORMAL | 2024-10-12T16:01:26.233035+00:00 | 2024-10-12T16:15:36.581443+00:00 | 118 | false | # Intuition\nWe have prime numbers only. They all are odd except 2. For 2 we always return -1. For all the others answer exists.\nWhen we add 1 to the number what happens bitwise?\nThe last block of ones shifts by 1 position to the left.\nWe know that each number is odd - the last block always starts at the last positi... | 1 | 0 | ['Bit Manipulation', 'Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Java | Time 100% | Space 100% | java-time-100-space-100-by-viraj_modi-rtsx | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | viraj_modi | NORMAL | 2024-10-12T16:01:00.845944+00:00 | 2024-10-12T16:02:20.709860+00:00 | 120 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 1 | 0 | ['Math', 'Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy to understand solution in c++ | easy-to-understand-solution-in-c-by-code-idhl | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | coderkrishna07mishra | NORMAL | 2025-03-19T09:54:10.763434+00:00 | 2025-03-19T09:54:10.763434+00:00 | 2 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['Array', 'Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Bit operation | bit-operation-by-wondertx-tsq0 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | wondertx | NORMAL | 2025-01-31T03:15:59.001341+00:00 | 2025-01-31T03:15:59.001341+00:00 | 3 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | one pass bitwise-2. | one-pass-bitwise-2-by-rishiinsane-k8xn | IntuitionApproachComplexity
Time complexity:
O(n)
Space complexity:
O(n)
Code | RishiINSANE | NORMAL | 2025-01-26T09:45:06.737326+00:00 | 2025-01-26T09:45:06.737326+00:00 | 7 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
O(n)
- Space complexity:
O(n)
# Code
```cpp []
class Solution {
public:
vector<int> minBitwiseArray(vector<int>& nums) {
int ... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Simple Bitmask & Greedy | simple-bitmask-greedy-by-eskandar1-e8et | Complexity
Time complexity:
O(31*n) = O(n)
Space complexity:
cpp -> O(1)
java -> O(n)Code | Eskandar1 | NORMAL | 2025-01-26T00:05:48.288234+00:00 | 2025-01-26T00:10:59.525188+00:00 | 1 | false |
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
O(31*n) = O(n)
---
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
cpp -> O(1)
java -> O(n)
----
# Code
```cpp []
class Solution {
public:
vector<int> minBitwiseArray(vector<int>& nums) {
for(in... | 0 | 0 | ['Array', 'Greedy', 'Bit Manipulation', 'Bitmask', 'C++', 'Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Track lowest continuous 1s | track-lowest-continuous-1s-by-linda2024-vjc8 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | linda2024 | NORMAL | 2025-01-12T04:56:21.920909+00:00 | 2025-01-12T04:56:21.920909+00:00 | 5 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 0 | 0 | ['C#'] | 0 |
construct-the-minimum-bitwise-array-ii | BIT MANIPULATION | bit-manipulation-by-prachikumari-w5dw | Intuition2 Special Cases to Cater , while obseriving Binary Number behaviuorLSB:
nums.get(i)%2 == 1 (01) ending in binary so to make LSB(trainling zeroes) just | PrachiKumari | NORMAL | 2024-12-30T10:11:02.660525+00:00 | 2024-12-30T10:11:02.660525+00:00 | 4 | false | # Intuition
2 Special Cases to Cater , while obseriving Binary Number behaviuor
LSB:
nums.get(i)%2 == 1 (01) ending in binary so to make LSB(trainling zeroes) just subtract 1(power of 2 at LSB ie 1) ans[i] = nums.get(i)-1
nums.get(i)%2 == 3 (11) ending in binary so to make LSB
trailing zeroes just get to the rightMo... | 0 | 0 | ['Java'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ | Beats 100% | T.C. O (N * 32), S.C. O (1) | c-beats-100-tc-o-n-32-sc-o-1-by-aman786-bpty | \nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> ans;\n \n for(int i=0;i<nums.size(); i++){\ | Aman786 | NORMAL | 2024-12-20T16:32:25.400487+00:00 | 2024-12-20T16:32:25.400566+00:00 | 2 | false | ```\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> ans;\n \n for(int i=0;i<nums.size(); i++){\n \n if(nums[i]==2){\n ans.push_back(-1);\n continue;\n }\n \n int last_... | 0 | 0 | ['Bit Manipulation', 'C'] | 0 |
construct-the-minimum-bitwise-array-ii | converting the first '1' before the first '0' | converting-the-first-1-before-the-first-kzq2b | IntuitionBy analyzing the examples provided, you can notice a pattern: converting the first '1' before the first '0' gives you the answer.Code | J22qIDYZa7 | NORMAL | 2024-12-23T05:25:47.776358+00:00 | 2024-12-23T05:25:47.776358+00:00 | 1 | false | # Intuition
By analyzing the examples provided, you can notice a pattern: converting the first '1' before the first '0' gives you the answer.
# Code
```php []
class Solution
{
public function minBitwiseArray($nums)
{
$ans = [];
foreach ($nums as $num) {
if ($num == 2) {
... | 0 | 0 | ['PHP'] | 0 |
construct-the-minimum-bitwise-array-ii | From Brute Force to optimized | from-brute-force-to-optimized-by-rknice1-b268 | Brute Force Approach\nTime: O(NMax(nums))\nSpce: O(N)\n\n\nans=[-1]*len(nums)\nfor num in nums:\n for i in range(0,num):\n\t\t\t\t if (i) | (i+1)==nu | rknice16 | NORMAL | 2024-12-04T12:26:48.150582+00:00 | 2024-12-04T12:26:48.150619+00:00 | 2 | false | **Brute Force Approach**\nTime: O(N*Max(nums))\nSpce: O(N)\n\n```\nans=[-1]*len(nums)\nfor num in nums:\n for i in range(0,num):\n\t\t\t\t if (i) | (i+1)==nums:\n\t\t\t\t\t\t ans[i]=i\n\t\t\t\t\t\t\t\t\t\tbreak\nreturn ans\n```\n**Optimized Approach**\nfor every nums[i]:\n unset a bit and try\n\t\t... | 0 | 0 | ['Array', 'Bit Manipulation', 'Python'] | 0 |
construct-the-minimum-bitwise-array-ii | Rust/Python. Real linear solution with full explanation | rustpython-real-linear-solution-with-ful-kar4 | Intuition\n\nFirst we need to understand that the question asks to solve equation:\n\nx OR (x + 1) = y\n\nfor x. Here they have a strange requirement of y being | salvadordali | NORMAL | 2024-11-22T08:39:01.355465+00:00 | 2024-11-22T08:42:53.561872+00:00 | 3 | false | # Intuition\n\nFirst we need to understand that the question asks to solve equation:\n\n`x OR (x + 1) = y`\n\nfor `x`. Here they have a strange requirement of `y` being prime, but we later we will see that it is irrelevant. On top of this the `x` should be as small as possible.\n\n\nLets look at some number `1011100111... | 0 | 0 | ['Python3', 'Rust'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ 100% | c-100-by-soundsoflife-in8j | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | soundsoflife | NORMAL | 2024-11-13T16:57:39.068699+00:00 | 2024-11-13T16:57:39.068743+00:00 | 2 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy to UnderStand Beginner Friendly | easy-to-understand-beginner-friendly-by-mxp7b | To address this problem, here\u2019s the breakdown:\n\n# Intuition\nThe goal is to transform each element of the array v by minimizing its binary representation | tinku_tries | NORMAL | 2024-11-11T09:51:37.425549+00:00 | 2024-11-11T09:51:37.425589+00:00 | 4 | false | To address this problem, here\u2019s the breakdown:\n\n# Intuition\nThe goal is to transform each element of the array `v` by minimizing its binary representation. For each element `v[i]`, if it is odd, we attempt to adjust it such that the resulting value retains as few high-value bits as possible while being slightly... | 0 | 0 | ['Array', 'Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Simple C++ Solution Beats 100% , O(N) | simple-c-solution-beats-100-on-by-samart-a24m | Code\ncpp []\nvector<int> minBitwiseArray(vector<int>& nums) {\n int n=nums.size();\n vector<int> ans(n);\n for(int i=0;i<n;++i){\n | samarth_verma_007 | NORMAL | 2024-11-04T18:12:41.151895+00:00 | 2024-11-04T18:12:41.151925+00:00 | 5 | false | # Code\n```cpp []\nvector<int> minBitwiseArray(vector<int>& nums) {\n int n=nums.size();\n vector<int> ans(n);\n for(int i=0;i<n;++i){\n if(nums[i]&1){\n int j=0;\n while(nums[i] & (1<<j)){\n ++j;\n }\n\n --j... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Bit Manipulation | bit-manipulation-by-djverma5-32xg | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Djverma5 | NORMAL | 2024-10-29T08:03:34.865491+00:00 | 2024-10-29T08:03:34.865518+00:00 | 1 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n$$O(n Log(max(nums[i])))$$\n\n- Space complexity:\n$$O(1)$$\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBit... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | beating 100% c++ solution (no explanation) | beating-100-c-solution-no-explanation-by-0bpq | \n\n# Code\ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> res;\n for(int ele: nums) | lcq_dev | NORMAL | 2024-10-26T15:45:04.001871+00:00 | 2024-10-26T15:45:04.001895+00:00 | 1 | false | \n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> res;\n for(int ele: nums) {\n int a = 0;\n int temp = 0;\n\n int count = 0;\n while(ele!=0) {\n if(((ele>>count)&1) == 0) {\... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Simple Python3 Solution | simple-python3-solution-by-xxhrxx-5m9n | Basically what we need to do is to find the where the consecutive 1 ends from the end of the binary presentation of the target and then construct the number\n\n | xxhrxx | NORMAL | 2024-10-24T18:30:10.269513+00:00 | 2024-10-24T18:30:10.269544+00:00 | 2 | false | Basically what we need to do is to find the where the consecutive 1 ends from the end of the binary presentation of the target and then construct the number\n\nFor example:\ntarget = 11111000111111\nres ~~= 11111000011111\n\nas adding 1 in res yield to 11111000100000 which contributes to the only missing 1 in the t... | 0 | 0 | ['Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ Solution | c-solution-by-tlexceeded-o0to | Intuition\n Describe your first thoughts on how to solve this problem. \n\nLet num is any number in array.\n\n1) if num is in the form of x0 -> even -> -1(not p | TLExceeded | NORMAL | 2024-10-23T05:20:22.391761+00:00 | 2024-10-23T05:20:22.391814+00:00 | 10 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\nLet num is any number in array.\n\n1) if num is in the form of x0 -> even -> -1(not possible use pen and paper to check since adding 1 is always a odd number).\n2) only even prime number is 2 thus -1 for 2\n3) odd prime have 2 form\n4) ... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Python3 | 0ms | Beats 100% | python3-0ms-beats-100-by-padth-8xay | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | padth | NORMAL | 2024-10-23T04:13:33.664760+00:00 | 2024-10-23T04:13:33.664783+00:00 | 2 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | C Solution || Beats 100% || Bit Manipulation Approach || With Explanations | c-solution-beats-100-bit-manipulation-ap-unwt | Intuition\nThe goal is to modify each number in the array such that for odd numbers, we find the minimum bitwise transformation that satisfies a given condition | Heber_Alturria | NORMAL | 2024-10-22T21:57:43.455366+00:00 | 2024-10-22T21:57:43.455398+00:00 | 1 | false | # Intuition\nThe goal is to modify each number in the array such that for odd numbers, we find the minimum bitwise transformation that satisfies a given condition. For even numbers, a predetermined result is returned. The key observation is that for odd numbers, we can use bitwise operations to manipulate individual bi... | 0 | 0 | ['Array', 'Bit Manipulation', 'C'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ | Bit Manipulation | Beats 100% | c-bit-manipulation-beats-100-by-rajharsh-huqk | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | rajharsh_24 | NORMAL | 2024-10-22T18:32:04.181802+00:00 | 2024-10-22T18:32:04.181841+00:00 | 6 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | C & Python || 1ms || Beats 100% || Bit manipulation | c-python-1ms-beats-100-bit-manipulation-h0zve | Intuition\nIf the original is 1110010101001111\nThen best value is 1110010101000111\ni.e. make the leftmost 1 in the rightmost block of 1\'s a 0.\n\nThe C and P | i_have_no_biscuits | NORMAL | 2024-10-21T17:20:19.099319+00:00 | 2024-10-21T17:20:19.099351+00:00 | 2 | false | # Intuition\nIf the original is 1110010101001111\nThen best value is 1110010101000111\ni.e. make the leftmost 1 in the rightmost block of 1\'s a 0.\n\nThe C and Python code are basically identical (ignoring the messing around you have to do with dynamic memory in C)!\n\n# Code\n```c []\nint value(int n) {\n if (n % ... | 0 | 0 | ['C'] | 0 |
construct-the-minimum-bitwise-array-ii | Beats 100% solutions | beats-100-solutions-by-0056harshit_gupta-opgd | Complexity\n- Time complexity:O(N)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity:O(N)\n Add your space complexity here, e.g. O(n) \n\n# Code | 0056harshit_gupta | NORMAL | 2024-10-20T13:08:46.640860+00:00 | 2024-10-20T13:08:46.640902+00:00 | 3 | false | # Complexity\n- Time complexity:O(N)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:O(N)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> ans;\n for(int ... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Beats 95% solutions | beats-95-solutions-by-0056harshit_gupta-68qf | Complexity\n- Time complexity:O(N)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity:O(N)\n Add your space complexity here, e.g. O(n) \n\n# Code | 0056harshit_gupta | NORMAL | 2024-10-20T13:00:57.208928+00:00 | 2024-10-20T13:00:57.208957+00:00 | 3 | false | # Complexity\n- Time complexity:O(N)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:O(N)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> ans;\n for(int ... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Simple Java Solution | simple-java-solution-by-prince_kumar1-khda | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | prince_kumar1 | NORMAL | 2024-10-20T11:04:09.482988+00:00 | 2024-10-20T11:04:09.483013+00:00 | 2 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Java'] | 0 |
construct-the-minimum-bitwise-array-ii | scala solution. lowest unset bit | scala-solution-lowest-unset-bit-by-vitit-0e4o | scala []\nobject Solution {\n def minBitwiseArray(nums: List[Int]): Array[Int] = {\n nums.map(BigInt(_)).map(bigInt => (Option.when((bigInt&1) != 0) {\n | vititov | NORMAL | 2024-10-19T17:05:13.000528+00:00 | 2024-10-19T17:05:13.000551+00:00 | 0 | false | ```scala []\nobject Solution {\n def minBitwiseArray(nums: List[Int]): Array[Int] = {\n nums.map(BigInt(_)).map(bigInt => (Option.when((bigInt&1) != 0) {\n lazy val lowestUnSetBit = (~bigInt).lowestSetBit\n lazy val hiBits = bigInt & ~((1<<lowestUnSetBit)-1)\n lazy val loBits = (1<<(lowestUnSetBit-1)... | 0 | 0 | ['Scala'] | 0 |
construct-the-minimum-bitwise-array-ii | Beats 100% | Easy C++ Solution | beats-100-easy-c-solution-by-krishiiitp-5w76 | Code\ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n=nums.size();\n vector<int> ans(n),v;\n | krishiiitp | NORMAL | 2024-10-19T16:44:45.809006+00:00 | 2024-10-19T16:44:45.809030+00:00 | 3 | false | # Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n=nums.size();\n vector<int> ans(n),v;\n for(int i=0;i<n;i++){\n if(nums[i]==2){\n ans[i]=-1;\n }else{\n int some=nums[i];\n wh... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy Solution with Bit Manipulation | easy-solution-with-bit-manipulation-by-s-4nsp | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \nBit manipulation\n\n# C | Shayan704 | NORMAL | 2024-10-19T07:09:50.413162+00:00 | 2024-10-19T07:09:50.413207+00:00 | 5 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nBit manipulation\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nO(N*31)\n\n- Space complexity:\n<!-- Add your space comple... | 0 | 0 | ['Bit Manipulation', 'Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Beats 100% | beats-100-by-dhyey_24-812k | Complexity\n- Time complexity:O(n)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity: O(1)\n Add your space complexity here, e.g. O(n) \n\n# Cod | dhyey_24 | NORMAL | 2024-10-19T07:01:22.824432+00:00 | 2024-10-19T07:01:22.824469+00:00 | 4 | false | # Complexity\n- Time complexity:O(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(1)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& arr) {\n int n = arr.size() ;\n vect... | 0 | 0 | ['Array', 'Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | One line solution. Bit manipulation. O(n) | one-line-solution-bit-manipulation-on-by-0cin | \nclass Solution:\n def minBitwiseArray(self, nums: List[int]) -> List[int]:\n return [(n&(n+1)) | ((~n&(n+1))//2-1) for n in nums]\n | xxxxkav | NORMAL | 2024-10-18T22:14:25.402374+00:00 | 2024-10-18T22:14:33.674104+00:00 | 2 | false | ```\nclass Solution:\n def minBitwiseArray(self, nums: List[int]) -> List[int]:\n return [(n&(n+1)) | ((~n&(n+1))//2-1) for n in nums]\n``` | 0 | 0 | ['Bit Manipulation', 'Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | why leftmost works | what happens when we add 1 to a number | Proof | why-leftmost-works-what-happens-when-we-jxdnd | In binary addition, adding 1 to a number follows rules very similar to how addition works in decimal, but with only two digits (0 and 1). Let\'s take a deeper l | byp8as | NORMAL | 2024-10-18T19:26:01.879495+00:00 | 2024-10-18T19:26:01.879524+00:00 | 4 | false | In binary addition, adding `1` to a number follows rules very similar to how addition works in decimal, but with only two digits (`0` and `1`). Let\'s take a deeper look at what happens bit by bit when we add `1` to a binary number.\n\n#### Binary addition works with the following basic rules:\n\n- 0 + 0 = 0\n- 0 + 1 =... | 0 | 0 | ['Math', 'Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Java, Easy And Optimized Solution using bitwise Operator | java-easy-and-optimized-solution-using-b-ujrv | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | vipin_121 | NORMAL | 2024-10-18T09:45:16.052687+00:00 | 2024-10-18T09:45:16.052711+00:00 | 2 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Java'] | 0 |
construct-the-minimum-bitwise-array-ii | C++, Easy and Optimized Using Bitwise Operator | c-easy-and-optimized-using-bitwise-opera-hq5h | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Ashutosh_2002 | NORMAL | 2024-10-18T09:44:41.550820+00:00 | 2024-10-18T09:44:41.550855+00:00 | 2 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Beats 100% solutions | beats-100-solutions-by-rupesh5129-jxm2 | Intuition\n- Find the position of the first unset bit from LSB.\n- Now toggle the next bit to the right.\n\n# Complexity\n- Time complexity: O(n)\n\n- Space com | rupesh5129 | NORMAL | 2024-10-18T07:56:08.881231+00:00 | 2024-10-18T07:56:08.881254+00:00 | 1 | false | # Intuition\n- Find the position of the first unset bit from LSB.\n- Now toggle the next bit to the right.\n\n# Complexity\n- Time complexity: O(n)\n\n- Space complexity: O(1)\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n = nums.size();\n for... | 0 | 0 | ['Bitmask', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Flip farthest 1 in right to left continuous sequence | flip-farthest-1-in-right-to-left-continu-ery6 | \nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector <int> ans;\n for(auto & it : nums){\n if(it | xelladze | NORMAL | 2024-10-17T22:27:15.376044+00:00 | 2024-10-17T22:30:29.174215+00:00 | 2 | false | ```\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector <int> ans;\n for(auto & it : nums){\n if(it == 2)\n ans.push_back(-1);\n else{\n for(int i = 0; i < 32; i++){\n if((it & 1 << i) <= 0){\n ... | 0 | 0 | [] | 0 |
construct-the-minimum-bitwise-array-ii | C++ || O(n) || Easy & Simple | c-on-easy-simple-by-ajay_makvana-x28e | Complexity\n- Time complexity: O(n * K)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity: O(K)\n Add your space complexity here, e.g. O(n) \n\n | AJAY_MAKVANA | NORMAL | 2024-10-17T19:22:46.311713+00:00 | 2024-10-17T19:22:46.311737+00:00 | 8 | false | # Complexity\n- Time complexity: O(n * K)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(K)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n = nums.size();\n ... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Few lines of code | few-lines-of-code-by-leeetforce-8lk7 | \n# Complexity\n- Time complexity:O(n)\n\n- Space complexity:O(n)\n\n# Code\ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& num | Leeetforce | NORMAL | 2024-10-17T17:42:43.754093+00:00 | 2024-10-17T17:42:43.754134+00:00 | 1 | false | \n# Complexity\n- Time complexity:$$O(n)$$\n\n- Space complexity:$$O(n)$$\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> ans;\n for(int&num:nums){\n if(num==2) ans.push_back(-1);\n else{\n int i=0;\n ... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | [C] | c-by-zhang_jiabo-50av | C []\nint * minBitwiseArray(\n\tconst int * const nums,\n\tconst int numsLen,\n\n\tint * const pRetsLen //out\n){\n\t*pRetsLen = numsLen;\n\tint * const rets = | zhang_jiabo | NORMAL | 2024-10-17T07:50:31.294287+00:00 | 2024-10-17T07:50:31.294322+00:00 | 2 | false | ```C []\nint * minBitwiseArray(\n\tconst int * const nums,\n\tconst int numsLen,\n\n\tint * const pRetsLen //out\n){\n\t*pRetsLen = numsLen;\n\tint * const rets = (int *)malloc(sizeof (int) * *pRetsLen);\n\n\tfor (int i = 0; i < numsLen; i += 1){\n\t\tif (nums[i] % 2 == 0){\n\t\t\trets[i] = -1;\n\t\t\tcontinue;\n\t\t}\... | 0 | 0 | ['C'] | 0 |
construct-the-minimum-bitwise-array-ii | || BIT MANIPULATION, IN ONE PASS O(N)|| | bit-manipulation-in-one-pass-on-by-anmol-lsgo | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \nSo , for even numbers t | anmol_050 | NORMAL | 2024-10-16T12:11:07.054492+00:00 | 2024-10-16T12:11:07.054530+00:00 | 6 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nSo , for even numbers those num has 0th bit not set so cannot find any ans[i] for them always -1 for them , as only prime numbers here so for 2 ans[i] has to be -1\n\n... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Bitwise Greedy | bitwise-greedy-by-parteek_coder-kkol | Code\ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n = nums.size();\n vector<int>ans(n,-1);\n | parteek_coder | NORMAL | 2024-10-16T08:11:28.049264+00:00 | 2024-10-16T08:11:28.049299+00:00 | 6 | false | # Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n = nums.size();\n vector<int>ans(n,-1);\n for(int i=0;i<n;i++){\n if(nums[i]==2) ans[i]=-1;\n else {\n int j=1;\n while(j<32 && ((1<<j)&nums[... | 0 | 0 | ['Greedy', 'Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | BEAT 100% ULTRA SHORT, EASY BRUTE - FORCE APPROACH ✅✅ | beat-100-ultra-short-easy-brute-force-ap-w3ik | BEAT 100%\n\n\n# Code\ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n for (int i = 0; i < nums.size(); i++) {\ | Nitansh_Koshta | NORMAL | 2024-10-15T14:04:57.462604+00:00 | 2024-10-15T14:04:57.462638+00:00 | 0 | false | # BEAT 100%\n\n\n# Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n for (int i = 0; i < nums.size(); i++) {\n if (nums[i] % 2 ==... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Beats 100.00% on time & 100.00% on memory | 1-liner | beats-10000-on-time-10000-on-memory-1-li-49u9 | \n\ntypescript []\nfunction minBitwiseArray(nums: number[]): number[] {\n return nums.map((num) => (num === 2 ? -1 : (((-num - 2) ^ num) >> 2) + num))\n}\n | NicholasGreenwood | NORMAL | 2024-10-15T12:53:25.900768+00:00 | 2024-10-15T12:53:25.900791+00:00 | 1 | false | \n\n```typescript []\nfunction minBitwiseArray(nums: number[]): number[] {\n return nums.map((num) => (num === 2 ? -1 : (((-num - 2) ^ num) >> 2) + num))\n}\n``` | 0 | 0 | ['TypeScript'] | 0 |
construct-the-minimum-bitwise-array-ii | ✅FINDING RIGHTMOST UNSET BIT🔥🔥 | finding-rightmost-unset-bit-by-amarnatht-nbxk | Intuition\n Describe your first thoughts on how to solve this problem. \nThe goal of this function is to modify each element in the given array nums \nbased on | amarnathtripathy | NORMAL | 2024-10-15T11:50:27.581991+00:00 | 2024-10-15T11:50:27.582017+00:00 | 2 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe goal of this function is to modify each element in the given array `nums` \nbased on certain bitwise operations. The modification is aimed at finding a \nsmaller number by flipping the rightmost unset bit. The function handles a \nspe... | 0 | 0 | ['Array', 'Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | VERY EASY SOLUTION||C++||BIT_MANIPULATION | very-easy-solutioncbit_manipulation-by-s-z46q | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | spidee180 | NORMAL | 2024-10-15T10:55:28.405031+00:00 | 2024-10-15T10:55:28.405055+00:00 | 5 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Java - simple - unset each bit - approach | java-simple-unset-each-bit-approach-by-t-ulfk | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | tanmayrsm | NORMAL | 2024-10-15T10:48:44.762878+00:00 | 2024-10-15T10:48:44.762899+00:00 | 3 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity: $$O(nlogB)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(n)$$\n<!-- Add your space complexity ... | 0 | 0 | ['Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy solution but hard to come up with | easy-solution-but-hard-to-come-up-with-b-w8cn | Intuition\nThe goal of this solution is to unset (toggle) the last consecutive set bit (the rightmost sequence of 1s) in each number of the given array using XO | Aarav_vaish | NORMAL | 2024-10-15T06:47:05.083700+00:00 | 2024-10-15T06:47:05.083745+00:00 | 4 | false | # Intuition\nThe goal of this solution is to unset (toggle) the last consecutive set bit (the rightmost sequence of 1s) in each number of the given array using XOR. \n\nThe last consecutive 1 bit is the rightmost bit in a sequence of 1s. Unsetting this bit (changing it from 1 to 0) often results in the smallest possibl... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | [C++] Set the bit before the rightmost zero to zero with xor. | c-set-the-bit-before-the-rightmost-zero-cc72u | \ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n = nums.size();\n vector<int> ans;\n\n for | lovebaonvwu | NORMAL | 2024-10-15T01:11:54.012481+00:00 | 2024-10-15T01:11:54.012507+00:00 | 4 | false | \n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n = nums.size();\n vector<int> ans;\n\n for (auto p : nums) {\n if (p % 2 == 0) {\n ans.push_back(-1);\n } else {\n for (int i = 1; i < 31; ++i) {\n... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | JAVA 1ms(100%) with O(N*logV) | java-1ms100-with-onlogv-by-meringueee-0o17 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | meringueee | NORMAL | 2024-10-15T00:04:01.194975+00:00 | 2024-10-15T00:04:01.195003+00:00 | 4 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy C++ || Bitwise Operations || Beats 100% | easy-c-bitwise-operations-beats-100-by-y-ulm7 | Code\ncpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& a) {\n int n = a.size();\n vector<int> ans(n, -1);\n | yoyobuzz | NORMAL | 2024-10-14T20:20:17.489901+00:00 | 2024-10-14T20:20:17.489929+00:00 | 21 | false | # Code\n```cpp []\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& a) {\n int n = a.size();\n vector<int> ans(n, -1);\n for(int i=0; i<n; i++){\n if(a[i] == 2) continue;\n int last = -1;\n for(int j = 0; j <=30; j++){\n if( ((a... | 0 | 0 | ['C++'] | 1 |
construct-the-minimum-bitwise-array-ii | pro c++ code || time complexity O(N) || space complexity O(1)||simple bitmask observation | pro-c-code-time-complexity-on-space-comp-nnq5 | Intuition\njust observe and try to visualise every testcases given at start point\nby changing them into bits\n\n# Approach\n Describe your approach to solving | Md_Imtiyaz | NORMAL | 2024-10-14T16:28:56.344149+00:00 | 2024-10-14T16:28:56.344181+00:00 | 6 | false | # Intuition\njust observe and try to visualise every testcases given at start point\nby changing them into bits\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n- O(N)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n- O(1)\n<!-- A... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | [C++][Bit manipulation] | cbit-manipulation-by-mumrocks-u0q4 | \n\n# Code\ncpp []\nclass Solution {\n inline int minBitwise(const int n){\n if (n==2) return -1;\n\n int idx=0;\n while ((n & (1<<idx)) | MumRocks | NORMAL | 2024-10-14T15:49:51.749608+00:00 | 2024-10-14T15:49:51.749629+00:00 | 0 | false | \n\n# Code\n```cpp []\nclass Solution {\n inline int minBitwise(const int n){\n if (n==2) return -1;\n\n int idx=0;\n while ((n & (1<<idx))!=0) idx++;\n idx--;\n\n int mask = ~(1<<idx);\n return (n&mask);\n }\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | O(32N) PrefixBit | python-brute-force-o32n-prefixbit-beats-oge0x | IntuitionWant: ans[i] OR (ans[i] + 1) == nums[i]Prime means all odd, except 2
So at least (p-1)|p==p (trivial root)We brute force all possible prefix|prefix-1 a | justinleung0204 | NORMAL | 2024-10-14T14:40:10.525469+00:00 | 2025-02-15T18:15:22.831437+00:00 | 7 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Want: ans[i] OR (ans[i] + 1) == nums[i]
Prime means all odd, except 2
So at least (p-1)|p==p (trivial root)
We brute force all possible prefix|prefix-1 and return the smallest
101101
prefix|(prefix-1)
100000|01111... | 0 | 0 | ['Bit Manipulation', 'Prefix Sum', 'Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ Solution (Simple and easy to understand) | c-solution-simple-and-easy-to-understand-dak8 | Intuition\n Describe your first thoughts on how to solve this problem. \nThis problem follow a specific pattern.\n# Approach\n Describe your approach to solving | hazemkhairat4 | NORMAL | 2024-10-14T12:10:44.110925+00:00 | 2024-10-14T12:10:44.110948+00:00 | 8 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThis problem follow a specific pattern.\n# Approach\n<!-- Describe your approach to solving the problem. -->\nThe pattern is to continue shifting the number until you find 0 to the right, and you must have a counter to count how much you ... | 0 | 0 | ['Bit Manipulation', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Python 3 fast solution | python-3-fast-solution-by-fm2alexei-vunm | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | fm2alexei | NORMAL | 2024-10-14T10:24:03.422259+00:00 | 2024-10-14T10:24:03.422282+00:00 | 4 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['Bit Manipulation', 'Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | One of the Easiest solution With explanation | C++| Beats 100% | one-of-the-easiest-solution-with-explana-c01t | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | Rohit_Kumar_Srivastava | NORMAL | 2024-10-14T09:29:10.938921+00:00 | 2024-10-14T09:29:10.938989+00:00 | 8 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | easy c++ solution | easy-c-solution-by-zachisworking-802n | Intuition\neverything written in code\n\n# Code\ncpp []\n#include <vector>\nusing namespace std;\n\nclass Solution {\npublic:\n vector<int> minBitwiseArray(v | ZAChisworking | NORMAL | 2024-10-13T17:27:36.184943+00:00 | 2024-10-13T17:27:36.184976+00:00 | 11 | false | # Intuition\neverything written in code\n\n# Code\n```cpp []\n#include <vector>\nusing namespace std;\n\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> ans;\n int n = nums.size();\n\n for (int i = 0; i < n; i++) {\n if (nums[i] % 2 == 0) {\n... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ solution bit manipulation | c-solution-bit-manipulation-by-oleksam-e653 | \n// Please, upvote if you like it. Thanks :-)\nvector<int> minBitwiseArray(vector<int>& nums) {\n\tint n = nums.size();\n\tvector<int> res(n, 10e8);\n\tfor (in | oleksam | NORMAL | 2024-10-13T16:12:58.110768+00:00 | 2024-10-13T16:12:58.110803+00:00 | 0 | false | ```\n// Please, upvote if you like it. Thanks :-)\nvector<int> minBitwiseArray(vector<int>& nums) {\n\tint n = nums.size();\n\tvector<int> res(n, 10e8);\n\tfor (int i = 0; i < n; i++) {\n\t\tif (nums[i] & 1) {\n\t\t\tbitset<32> bs(nums[i]);\n\t\t\tfor (int j = 0; j < 31; j++) {\n\t\t\t\tauto copy = bs;\n\t\t\t\tcopy.se... | 0 | 0 | ['Array', 'Bit Manipulation', 'C', 'Bitmask', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | C++ bitwise solution | c-bitwise-solution-by-nguyenchiemminhvu-od3f | \nstatic bool fastIO = []()\n{\n std::cin.tie(0)->sync_with_stdio(false);\n return true;\n}();\n\nclass Solution\n{\npublic:\n vector<int> minBitwiseAr | nguyenchiemminhvu | NORMAL | 2024-10-13T15:02:40.017944+00:00 | 2024-10-13T15:02:40.017969+00:00 | 5 | false | ```\nstatic bool fastIO = []()\n{\n std::cin.tie(0)->sync_with_stdio(false);\n return true;\n}();\n\nclass Solution\n{\npublic:\n vector<int> minBitwiseArray(vector<int>& nums)\n {\n std::vector<int> res(nums.size(), -1);\n for (int i = 0; i < nums.size(); i++)\n {\n int coun... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Time complexity : 31 times O(N) | 2 ms Beats 100.00% | time-complexity-31-times-on-2-ms-beats-1-98sy | Intuition\n for value = 7 \n we can find a number such that : num | (num + 1) = value\nby setting any one bit of value\'s binary representation from 1 to 0.\nT | AddDeepanshuVerma | NORMAL | 2024-10-13T14:08:52.320654+00:00 | 2024-10-13T14:08:52.320713+00:00 | 8 | false | # Intuition\n for value = 7 \n we can find a number such that : num | (num + 1) = value\nby setting any one bit of value\'s binary representation from 1 to 0.\nTo find the minimum, start from 31st bit and which ever number we get after turning any one bit from 1 to 0, does prove our given condition is the answer\nHenc... | 0 | 0 | ['Math', 'Bit Manipulation', 'Java'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy Solution using Bit Manipulation | easy-solution-using-bit-manipulation-by-7u399 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | J_P_11 | NORMAL | 2024-10-13T13:49:10.982171+00:00 | 2024-10-13T13:50:04.802993+00:00 | 7 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | c++ solution | c-solution-by-dilipsuthar60-ez2n | \nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n=nums.size();\n vector<int>ans(n,0);\n for(int i=0 | dilipsuthar17 | NORMAL | 2024-10-13T12:46:20.940715+00:00 | 2024-10-13T12:58:34.660460+00:00 | 13 | false | ```\nclass Solution {\npublic:\n vector<int> minBitwiseArray(vector<int>& nums) {\n int n=nums.size();\n vector<int>ans(n,0);\n for(int i=0;i<n;i++){\n int result=1e9;\n for(int j=0;j<31;j++){\n if(nums[i]&(1<<j)){\n int k=nums[i]-(1<<j);\n... | 0 | 0 | ['C', 'C++'] | 0 |
construct-the-minimum-bitwise-array-ii | BEST PYTHON SOLUTION WITH 59MS OF RUNTIME ! | best-python-solution-with-59ms-of-runtim-fmi9 | \n# Code\npython3 []\nclass Solution:\n def minBitwiseArray(self, nums: List[int]) -> List[int]:\n ans = [0] * len(nums) # Initialize ans array\n | rishabnotfound | NORMAL | 2024-10-13T10:33:21.482275+00:00 | 2024-10-13T10:33:21.482310+00:00 | 7 | false | \n# Code\n```python3 []\nclass Solution:\n def minBitwiseArray(self, nums: List[int]) -> List[int]:\n ans = [0] * len(nums) # Initialize ans array\n for i, num in enumerate(nums):\n # Convert the number to binary (without the \'0b\' prefix)\n b = bin(num)[2:]\n \n ... | 0 | 0 | ['Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | 📌 C++ || 7 Lines || Faster 96% | c-7-lines-faster-96-by-t86-z771 | Intuition\n- Basically, the problem is broken down to for only even number\n\t- If we have the 01 pattern in binary, then convert it to 00\n\t- Example, 11111 - | t86 | NORMAL | 2024-10-13T10:12:48.137445+00:00 | 2024-10-13T10:12:48.137484+00:00 | 11 | false | **Intuition**\n- Basically, the problem is broken down to for only `even` number\n\t- If we have the `01` pattern in binary, then convert it to `00`\n\t- Example, `11111` -> `01111`, `1010101` -> `1010100`, `10111` -> `10011`\n\n**Code**\n```c++\nvector<int> minBitwiseArray(vector<int>& nums) {\n vector<int> res;\n ... | 0 | 0 | ['C'] | 0 |
construct-the-minimum-bitwise-array-ii | Fast and simple O(n) solution | fast-and-simple-on-solution-by-waxm-mx1z | Intuition\nThe key to understanding the solution is the realize that for a given number the answer will vary only by a single set bit if at all such a number ex | waxm | NORMAL | 2024-10-13T09:53:22.598366+00:00 | 2024-10-13T09:53:22.598390+00:00 | 4 | false | # Intuition\nThe key to understanding the solution is the realize that for a given number the answer will vary only by a single set bit if at all such a number exists. \n\n# Approach\nLet\'s consider the number 13 for which we want to find the answer.\n\nThe number 13 in binary is 1101.\n\nWe can find variations for th... | 0 | 0 | ['TypeScript'] | 0 |
construct-the-minimum-bitwise-array-ii | Simple bit manipulation | O(n) | simple-bit-manipulation-on-by-kavishgupt-xcbe | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | kavishgupta2011 | NORMAL | 2024-10-13T09:51:04.091435+00:00 | 2024-10-13T09:51:04.091467+00:00 | 14 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Simple Observation Using Bit Manipulation | simple-observation-using-bit-manipulatio-c2b1 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | catchme999 | NORMAL | 2024-10-13T09:14:20.191749+00:00 | 2024-10-13T09:14:20.191773+00:00 | 5 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
construct-the-minimum-bitwise-array-ii | Easy to understand code!!! | easy-to-understand-code-by-daminrido139-whsc | Intuition\n Describe your first thoughts on how to solve this problem. \nObserving pattern for various inputs is the key to solve this problem.\n# Approach\n De | chicken_strips | NORMAL | 2024-10-13T08:58:17.674351+00:00 | 2024-10-13T08:58:17.674370+00:00 | 0 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nObserving pattern for various inputs is the key to solve this problem.\n# Approach\n<!-- Describe your approach to solving the problem. -->\n.................Input............ Answer.............\n.................1111...............111..... | 0 | 0 | ['Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | bit manipulation | bit-manipulation-by-swatilohiya0343-cait | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | swatilohiya0343 | NORMAL | 2024-10-13T08:37:39.394397+00:00 | 2024-10-13T08:37:39.394424+00:00 | 5 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity: O(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(1)\n<!-- Add your space complexity here, e.g. $... | 0 | 0 | ['Bit Manipulation', 'Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | Python || Simple solution | python-simple-solution-by-vilaparthibhas-i2hh | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | vilaparthibhaskar | NORMAL | 2024-10-13T07:45:02.058738+00:00 | 2024-10-13T07:45:02.058786+00:00 | 6 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\no(n)\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n... | 0 | 0 | ['Bit Manipulation', 'Python3'] | 0 |
construct-the-minimum-bitwise-array-ii | c++(0ms) only bit manipulations | c0ms-only-bit-manipulations-by-zx007pi-26cg | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | zx007pi | NORMAL | 2024-10-13T07:36:52.530029+00:00 | 2024-10-13T07:36:52.530057+00:00 | 5 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
transform-to-chessboard | [C++/Java/Python] Solution with Explanation | cjavapython-solution-with-explanation-by-pp3w | Intuition:\nTwo conditions to help solve this problem:\n1. In a valid chess board, there are 2 and only 2 kinds of rows and one is inverse to the other.\nFor ex | lee215 | NORMAL | 2018-02-11T17:45:15.784000+00:00 | 2021-01-29T07:05:55.721440+00:00 | 18,742 | false | # **Intuition**:\nTwo conditions to help solve this problem:\n1. In a valid chess board, there are 2 and only 2 kinds of rows and one is inverse to the other.\nFor example if there is a row 01010011 in the board, any other row must be either 01010011 or 10101100.\nThe same for columns\nA corollary is that, any rectangl... | 191 | 6 | [] | 38 |
transform-to-chessboard | Python, detailed explanation | python-detailed-explanation-by-yuanzhi24-pa97 | How to check impossible board?\n1. Each row in the board must either equal to the first row or equal to the reverse of the first row. \nThe same apply to column | yuanzhi247012 | NORMAL | 2019-11-29T14:38:14.862074+00:00 | 2019-11-29T14:44:08.245552+00:00 | 2,984 | false | How to check impossible board?\n1. Each row in the board must either equal to the first row or equal to the reverse of the first row. \nThe same apply to column, but you don\'t need to check column, because if all rows complies with this rule, all columns automatically comply with this rule by themselves. Only need to ... | 72 | 1 | [] | 4 |
transform-to-chessboard | C++ solution with Image explanation | c-solution-with-image-explanation-by-luc-q8d2 | Logic of how check if it a valid board \nTo understand if a board can be a chess board (so if it is valid) we can think in opposite way (so from the chess board | lucayan0506 | NORMAL | 2021-09-26T13:30:06.050973+00:00 | 2021-09-26T13:33:38.085295+00:00 | 3,125 | false | ## Logic of how check if it a valid board \nTo understand if a board can be a chess board (so if it is valid) we can think in opposite way (so from the chess board and get the rules that a chess board **must have.**\n//2` and `(n-1)//2`.\n2. The same is for columns.\n3. Number of `1` in all board should be `n*n//2` if `n` is even and `(n*n +- 1)//2` if n i... | 28 | 4 | ['Math'] | 7 |
transform-to-chessboard | C++ solution with very detailed comments, especially the swap counting part | c-solution-with-very-detailed-comments-e-j9tb | Inspired by this and this posts, but use a different approach to count swap number, IMHO, which is more intuitive.\nC++\n int movesToChessboard(vector<vector | bwv988 | NORMAL | 2019-02-10T21:58:22.163132+00:00 | 2019-07-24T13:12:31.561408+00:00 | 1,725 | false | Inspired by [this](https://leetcode.com/problems/transform-to-chessboard/discuss/114847/Easy-and-Concise-Solution-with-Explanation-C%2B%2BJavaPython) and [this](https://leetcode.com/problems/transform-to-chessboard/discuss/132113/Java-Clear-Code-with-Detailed-Explanations) posts, but use a different approach to count s... | 17 | 0 | [] | 1 |
transform-to-chessboard | Short Python Solution; Beat 100%; with line-by-line explanation | short-python-solution-beat-100-with-line-4y5l | Beat 100%\n(Inspired by Maozi Chen\'s observations; he/she is a genius!)\nMy understanding:\nKey observation: A solvable board iff it satisfies the following re | yuxiong | NORMAL | 2018-09-12T05:38:04.096985+00:00 | 2018-09-12T05:38:04.097033+00:00 | 1,189 | false | Beat 100%\n(Inspired by Maozi Chen\'s observations; he/she is a genius!)\nMy understanding:\nKey observation: A solvable board iff it satisfies the following requirements:\n 1) Each row/column either the same as the first row/column or exactly cell-by-cell reversed color of the first row/column.\n Example1: I... | 14 | 1 | [] | 1 |
transform-to-chessboard | ⚡C# | Beats runtime AND memory 100% [EXPLAINED IN DETAILS] | c-beats-runtime-and-memory-100-explained-7knw | Intuition\nWhen I looked at this problem, it was clear that I needed to transform a grid of 0s and 1s into a chessboard pattern, where no two adjacent cells are | r9n | NORMAL | 2024-09-05T21:30:46.369438+00:00 | 2024-09-05T21:30:46.369462+00:00 | 118 | false | # Intuition\nWhen I looked at this problem, it was clear that I needed to transform a grid of 0s and 1s into a chessboard pattern, where no two adjacent cells are the same. Essentially, I want the board to look like a checkerboard, alternating between 0 and 1.\n\nTo solve this, I realized I could only swap rows and col... | 11 | 0 | ['C#'] | 0 |
transform-to-chessboard | Short C++ solution, no swaps, 9ms, O(n^2) time, O(1) space | short-c-solution-no-swaps-9ms-on2-time-o-9rqr | The algorithm is based on counting. A solvable board has each row/column either the same as the first row/column or exactly cell-by-cell reversed color of the f | mzchen | NORMAL | 2018-02-11T05:27:35.814000+00:00 | 2018-09-12T00:26:54.186892+00:00 | 2,417 | false | The algorithm is based on counting. A solvable board has each row/column either the same as the first row/column or exactly cell-by-cell reversed color of the first row/column.\n\nIn the loop we count for **rs** and **cs**, the number of rows/columns being the same as the first row/column, and **rm** and **cm**, the nu... | 11 | 1 | [] | 0 |
transform-to-chessboard | [Python3] alternating numbers | python3-alternating-numbers-by-ye15-uqsu | \n\nclass Solution:\n def movesToChessboard(self, board: List[List[int]]) -> int:\n n = len(board)\n \n def fn(vals): \n """R | ye15 | NORMAL | 2021-06-29T21:21:48.074875+00:00 | 2021-06-29T21:40:34.684378+00:00 | 944 | false | \n```\nclass Solution:\n def movesToChessboard(self, board: List[List[int]]) -> int:\n n = len(board)\n \n def fn(vals): \n """Return min moves to transform to chessboard."""\n total = odd = 0 \n for i, x in enumerate(vals): \n if vals[0] == x: \n ... | 8 | 0 | ['Python3'] | 1 |
transform-to-chessboard | JavaScript easy to read solution | javascript-easy-to-read-solution-by-elle-725o | \n/**\n * @param {number[][]} board\n * @return {number}\n */\nvar movesToChessboard = function(board) {\n const boardSize = board.length;\n const boardSi | elleuz | NORMAL | 2021-09-26T11:25:34.312618+00:00 | 2021-09-26T11:51:00.768728+00:00 | 519 | false | ```\n/**\n * @param {number[][]} board\n * @return {number}\n */\nvar movesToChessboard = function(board) {\n const boardSize = board.length;\n const boardSizeIsEven = boardSize % 2 === 0;\n \n if(!canBeTransformed(board)) return -1;\n \n // to convert to 010101\n let rowSwap = 0;\n let colSw... | 6 | 0 | ['JavaScript'] | 0 |
transform-to-chessboard | Transform to Chessboard || [C++/Java/Python] | transform-to-chessboard-cjavapython-by-r-6wy0 | Intuition:\nTwo conditions to help solve this problem:\n\n1. In a valid chess board, there are 2 and only 2 kinds of rows and one is inverse to the other.\nFor | rishabhsarang200 | NORMAL | 2021-09-26T08:45:14.361605+00:00 | 2021-09-27T07:52:38.893953+00:00 | 711 | false | **Intuition**:\nTwo conditions to help solve this problem:\n\n1. In a valid chess board, there are 2 and only 2 kinds of rows and one is inverse to the other.\nFor example if there is a row 01010011 in the board, any other row must be either 01010011 or 10101100.\nThe same for columns\nA corollary is that, any rectangl... | 6 | 4 | [] | 2 |
transform-to-chessboard | C++ little longer | c-little-longer-by-khacker-6vis | \nint movesToChessboard(vector<vector<int>>& b) {\n int N = b.size(), rowSum = 0, colSum = 0, rowSwap = 0, colSwap = 0;\n for (int i = 0; i < N; + | khacker | NORMAL | 2021-09-26T07:04:37.032510+00:00 | 2021-09-26T07:04:37.032556+00:00 | 162 | false | ```\nint movesToChessboard(vector<vector<int>>& b) {\n int N = b.size(), rowSum = 0, colSum = 0, rowSwap = 0, colSwap = 0;\n for (int i = 0; i < N; ++i) for (int j = 0; j < N; ++j)\n if (b[0][0]^b[i][0]^b[0][j]^b[i][j]) return -1;\n for (int i = 0; i < N; ++i) {\n rowSum +... | 6 | 5 | [] | 0 |
transform-to-chessboard | JavaScript solution | javascript-solution-by-yyoon-shev | My code is ugly but at least it passed all the test cases.\nThe main idea is the following:\n\n1. rows and columns can be fixed independantly, because they don\ | yyoon | NORMAL | 2021-04-21T22:13:07.187137+00:00 | 2021-04-21T22:22:07.954757+00:00 | 313 | false | My code is ugly but at least it passed all the test cases.\nThe main idea is the following:\n\n1. rows and columns can be fixed **independantly**, because they don\'t affect eachother.\n2. If the size is odd, first position and last position in the row and column is **decided**. If one has three, zero has two in the fi... | 5 | 0 | [] | 1 |
transform-to-chessboard | C++ Solution with proof | c-solution-with-proof-by-matecompufrj-0wbk | The key idea is:\nIf the grid has a solution, we can arrive at the solution by looking only at the first row and the first column. This happens because each sol | matecompufrj | NORMAL | 2021-10-15T20:16:22.214232+00:00 | 2021-10-15T20:16:22.214270+00:00 | 580 | false | **The key idea is:**\nIf the grid has a solution, we can arrive at the solution by looking only at the first row and the first column. This happens because each solution step moves the entire row or entire column.\n\n**How to know if the table has a solution?**\nThe dimensions are dependent, so we need to check that wh... | 4 | 0 | ['C'] | 0 |
transform-to-chessboard | c++ Solution | c-solution-by-saurabhvikastekam-jtiq | \nclass Solution \n{\npublic:\n int movesToChessboard(vector<vector<int>>& board) \n {\n int n = board.size();\n int cnt1 = 1, cnt2 = 0;\n | SaurabhVikasTekam | NORMAL | 2021-09-27T07:26:46.969248+00:00 | 2021-09-27T07:26:46.969317+00:00 | 663 | false | ```\nclass Solution \n{\npublic:\n int movesToChessboard(vector<vector<int>>& board) \n {\n int n = board.size();\n int cnt1 = 1, cnt2 = 0;\n for (int i = 1; i < n; ++i) \n {\n if (board[0][0] == board[i][0]) \n {\n ++cnt1;\n for (int... | 4 | 0 | ['C', 'C++'] | 0 |
transform-to-chessboard | [JavaScript] Check number of 1s and 0s | javascript-check-number-of-1s-and-0s-by-zr5wo | ```\nvar movesToChessboard = function(board) {\n const n = board.length;\n\n for (let i = 0; i < n; i++)\n for (let j = 0; j < n; j++)\n | tmohan | NORMAL | 2021-09-04T11:14:52.281157+00:00 | 2021-09-04T11:14:52.281185+00:00 | 222 | false | ```\nvar movesToChessboard = function(board) {\n const n = board.length;\n\n for (let i = 0; i < n; i++)\n for (let j = 0; j < n; j++)\n if (board[0][0] ^ board[i][0] ^ board[0][j] ^ board[i][j]) \n return -1;\n\n let rowSwaps = 0, colSwaps = 0, rowSum = 0, colSum = 0;\n\n f... | 4 | 0 | [] | 1 |
transform-to-chessboard | C++ solution with comments | c-solution-with-comments-by-sup6yj3a8-9mil | \nint isRawSame(const vector<vector<int>> &vec, const int &a, const int &b){\n for (int col=0; col<vec[a].size(); ++col) {\n if (vec[a][col] != vec[b] | sup6yj3a8 | NORMAL | 2021-07-27T11:09:28.100095+00:00 | 2021-07-27T11:10:22.830676+00:00 | 456 | false | ```\nint isRawSame(const vector<vector<int>> &vec, const int &a, const int &b){\n for (int col=0; col<vec[a].size(); ++col) {\n if (vec[a][col] != vec[b][col]) {return false;}\n }\n return true;\n}\n\n// Find the min number of swaping of vec to fit ans1 {0, 1, 0, 1, .....} or ans2 {1, 0, 1, 0, .....}.\n... | 4 | 2 | ['C'] | 1 |
transform-to-chessboard | Java beats 100% | java-beats-100-by-deleted_user-p31v | Java beats 100%\n\n\n\n# Code\n\nclass Solution {\n public int movesToChessboard(int[][] board) {\n int N = board.length, rowSum = 0, colSum = 0, rowS | deleted_user | NORMAL | 2024-05-25T04:46:24.324690+00:00 | 2024-05-25T04:46:24.324710+00:00 | 153 | false | Java beats 100%\n\n\n\n# Code\n```\nclass Solution {\n public int movesToChessboard(int[][] board) {\n int N = board.length, rowSum = 0, colSum = 0, rowSwap = 0, colSwap = 0;\n for (int r = ... | 3 | 0 | ['Java'] | 0 |
transform-to-chessboard | 782: Beats 98.8%, Solution with step by step explanation | 782-beats-988-solution-with-step-by-step-0qck | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n\n n = len(board)\n\n\nGet the size of the board.\n\n\n for | Marlen09 | NORMAL | 2023-10-28T07:03:19.602139+00:00 | 2023-10-28T07:03:19.602169+00:00 | 210 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n```\n n = len(board)\n```\n\nGet the size of the board.\n\n```\n for i in range(n):\n for j in range(n):\n if board[0][0] ^ board[i][0] ^ board[0][j] ^ board[i][j]:\n ... | 3 | 0 | ['Array', 'Math', 'Bit Manipulation', 'Matrix', 'Python', 'Python3'] | 0 |
transform-to-chessboard | Python (Bipartite graph) | python-bipartite-graph-by-404akhan-ehlh | Consider bipartite graph of rows and columns. If row and column intersection has 1, then connect with an edge corresponding vertices in the graph. Swaping rows | 404akhan | NORMAL | 2021-11-10T11:57:18.353424+00:00 | 2021-11-10T11:59:35.807275+00:00 | 456 | false | Consider bipartite graph of rows and columns. If row and column intersection has `1`, then connect with an edge corresponding vertices in the graph. Swaping rows or columns correspond to swapping vertices in the graph. At the end we want to have chessboard construction, which implies that we have connected component of... | 3 | 0 | [] | 1 |
transform-to-chessboard | using bit manipulation | using-bit-manipulation-by-mittal582-d5f1 | ```\nclass Solution {\npublic:\n int movesToChessboard(vector>& board) {\n set s;\n int n = board.size();\n \n for(auto& row : bo | mittal582 | NORMAL | 2021-09-26T10:32:14.744221+00:00 | 2021-09-27T13:14:38.486051+00:00 | 370 | false | ```\nclass Solution {\npublic:\n int movesToChessboard(vector<vector<int>>& board) {\n set<int> s;\n int n = board.size();\n \n for(auto& row : board) {\n int code = 0;\n for(int& num : row) {\n code = code*2 + num;\n }\n s.insert... | 3 | 0 | [] | 2 |
transform-to-chessboard | C++ (ADDED EXPLANATION IN COMMENTS) | c-added-explanation-in-comments-by-sum_i-odel | \nclass Solution {\npublic:\n enum{COL,ROW};\n int addedXOR(vector<vector<int>>& board,int orientation,int index)\n {\n int res=0;\n if(o | sum_it_zzz | NORMAL | 2021-09-26T10:06:17.872113+00:00 | 2021-09-26T16:26:14.289040+00:00 | 306 | false | ```\nclass Solution {\npublic:\n enum{COL,ROW};\n int addedXOR(vector<vector<int>>& board,int orientation,int index)\n {\n int res=0;\n if(orientation==COL)\n for(int i=0;i<board.size();i++)\n res+=board[i][index]^board[i][index+1];\n else if(orientation==ROW)\n ... | 3 | 0 | [] | 0 |
transform-to-chessboard | C++ O(N*N) solution | c-onn-solution-by-tt89-i8ab | \tclass Solution {\n\tpublic:\n\t\tint n;\n\t\tvector> arr;\n\n\t\tint getRow(vector &v,int x) {\n\t\t\tint ans=0;\n\t\t\tfor(int i=0;i<n;i++) {\n\t\t\t\tif(v[i | tt89 | NORMAL | 2021-09-26T10:02:08.394645+00:00 | 2021-09-26T10:02:08.394688+00:00 | 406 | false | \tclass Solution {\n\tpublic:\n\t\tint n;\n\t\tvector<vector<int>> arr;\n\n\t\tint getRow(vector<int> &v,int x) {\n\t\t\tint ans=0;\n\t\t\tfor(int i=0;i<n;i++) {\n\t\t\t\tif(v[i]!=x) ans++;\n\t\t\t\tx^=1;\n\t\t\t}\n\t\t\treturn ans;\n\t\t}\n\n\t\tint calc(vector<vector<int>> &v) {\n\t\t\tint ans1=0, x=0;\n\t\t\tfor(int... | 3 | 1 | ['C'] | 0 |
transform-to-chessboard | Java XOR check | java-xor-check-by-hobiter-wm9w | Ref:https://leetcode.com/problems/transform-to-chessboard/discuss/114847/C%2B%2BJavaPython-Solution-with-Explanation\n\npublic int movesToChessboard(int[][] bd) | hobiter | NORMAL | 2020-06-07T16:42:10.026989+00:00 | 2020-06-07T16:42:54.380007+00:00 | 912 | false | Ref:https://leetcode.com/problems/transform-to-chessboard/discuss/114847/C%2B%2BJavaPython-Solution-with-Explanation\n```\npublic int movesToChessboard(int[][] bd) {\n int n = bd.length, rs = 0, cs = 0, ro = 0, co = 0;;\n for (int i = 0; i < n; i++) {\n co += bd[0][i];\n ro += bd[i][... | 3 | 0 | [] | 1 |
transform-to-chessboard | C++ O(N^2) time solution with explantion | c-on2-time-solution-with-explantion-by-i-risb | Two rows are either the same or have opposite contents. This is equivalent to each 2x2 square has xor sum equal to zero. Then we need to move rows so that two r | imrusty | NORMAL | 2018-02-18T21:13:05.477693+00:00 | 2018-10-11T01:57:04.429779+00:00 | 1,086 | false | Two rows are either the same or have opposite contents. This is equivalent to each 2x2 square has xor sum equal to zero. Then we need to move rows so that two rows that are the same either occupie all even positions or all odd positions. Do the same for columns.
```
class Solution {
public:
int cal(vector<int> &v) ... | 3 | 1 | [] | 1 |
transform-to-chessboard | [Python3] Four rounds of check before counting min number of swaps | python3-four-rounds-of-check-before-coun-ws2u | \nclass Solution:\n def build_pat(self, lst: List[int]) -> int:\n """Build a pattern out of a given list of 1s and 0s"""\n n = len(lst)\n | fanchenbao | NORMAL | 2021-09-27T01:34:27.779311+00:00 | 2021-10-01T18:17:43.009868+00:00 | 212 | false | ```\nclass Solution:\n def build_pat(self, lst: List[int]) -> int:\n """Build a pattern out of a given list of 1s and 0s"""\n n = len(lst)\n pat = 0\n for i in range(n):\n pat |= (lst[i] << (n - i - 1))\n return pat\n\n def count_swap(self, pat: int, val1: int, val2: ... | 2 | 0 | [] | 1 |
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