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Q:
"Enable Wifi" not showing
I recently used sudo apt-get autoremove command and after that "Enable Wifi" option is not showing.
$ lspci -knn | grep Net -A3
02:00.0 Network controller [0280]: Realtek Semiconductor Co., Ltd. RTL8821AE 802.11ac PCIe Wireless Network Adapter [10ec:8821]
Subsystem: Lenovo RTL8821AE 802.11ac PCIe Wireless Network Adapter [17aa:a814]
Kernel modules: rtl8821ae, wl
$ iwconfig is
lo no wireless extensions.
enp1s0 no wireless extensions.
From /var/apt/history.log:
Start-Date: 2017-11-06 01:15:38
Commandline: apt-get autoremove
Requested-By: praveen (1000)
Remove: linux-headers-4.10.0-28-generic:amd64 (4.10.0-28.32~16.04.2), librpmsign3:amd64 (4.12.0.1+dfsg1-3build3), linux-image-extra-4.10.0-33-generic:amd64 (4.10.0-33.37~16.04.1),
librpmbuild3:amd64 (4.12.0.1+dfsg1-3build3),
linux-image-extra-4.10.0-35-generic:amd64 (4.10.0-35.39~16.04.1),
debugedit:amd64 (4.12.0.1+dfsg1-3build3),
linux-headers-4.10.0-33-generic:amd64 (4.10.0-33.37~16.04.1),
linux-image-4.10.0-28-generic:amd64 (4.10.0-28.32~16.04.2),
linux-headers-4.10.0-35-generic:amd64 (4.10.0-35.39~16.04.1),
rpm:amd64 (4.12.0.1+dfsg1-3build3),
linux-image-4.10.0-33-generic:amd64 (4.10.0-33.37~16.04.1),
linux-headers-4.10.0-28:amd64 (4.10.0-28.32~16.04.2),
linux-headers-4.10.0-33:amd64 (4.10.0-33.37~16.04.1),
linux-headers-4.10.0-35:amd64 (4.10.0-35.39~16.04.1),
linux-image-4.10.0-35-generic:amd64 (4.10.0-35.39~16.04.1),
linux-image-extra-4.10.0-28-generic:amd64 (4.10.0-28.32~16.04.2)
End-Date: 2017-11-06 01:17:19
Output of uname -a:
Linux praveen-Lenovo-ideapad-300-15ISK 4.10.0-38-generic #42~16.04.1-Ubuntu SMP Tue Oct 10 16:32:20 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux
$ dpkg-query -Wf '${db:Status-Abbrev} ${Package;-40} ${Version}\n' linux-{image,headers}-\* | grep '^i'
ii linux-headers-4.10.0-37 4.10.0-37.41~16.04.1
ii linux-headers-4.10.0-37-generic 4.10.0-37.41~16.04.1
ii linux-headers-4.10.0-38 4.10.0-38.42~16.04.1
ii linux-headers-4.10.0-38-generic 4.10.0-38.42~16.04.1
ii linux-headers-4.4.0-98 4.4.0-98.121
ii linux-headers-4.4.0-98-generic 4.4.0-98.121
ii linux-headers-generic 4.4.0.98.103
ii linux-headers-generic-hwe-16.04 4.10.0.38.40
ii linux-image-4.10.0-37-generic 4.10.0-37.41~16.04.1
ii linux-image-4.10.0-38-generic 4.10.0-38.42~16.04.1
ii linux-image-extra-4.10.0-37-generic 4.10.0-37.41~16.04.1
ii linux-image-extra-4.10.0-38-generic 4.10.0-38.42~16.04.1
ii linux-image-generic-hwe-16.04 4.10.0.38.40
A:
These commands will work for
rtl8192ce, rtl8192se, rtl8192de, rtl8188ee, rtl8192ee, rtl8723ae, rtl8723be, and rtl8821ae. If you have any other driver then please search and install.
sudo apt-get install linux-headers-generic build-essential git
git clone http://github.com/lwfinger/rtlwifi_new.git
cd rtlwifi_new
make
sudo make install
After that if your system does not load appropriate kernel module,you can run below command in same directory(make sure to run this for your specific driver in my case it is rtl8821ae):
sudo modprobe rtl8821ae
| 2024-05-01T23:14:03.371983 | https://example.com/article/8737 |
---
abstract: 'Considering a non-constant smooth solution $f$ of the Tanno equation on a closed, connected Kähler manifold $(M,g,J)$ with positively definite metric $g$, Tanno showed that the manifold can be finitely covered by $(\mathbb{C}P(n),\mbox{const}\cdot g_{FS})$, where $g_{FS}$ denotes the Fubini-Study metric of constant holomorphic sectional curvature equal to $1$. The goal of this paper is to give a proof of Tannos Theorem for Kähler metrics with arbitrary signature.'
author:
- 'A. Fedorova, S. Rosemann'
nocite: '[@*]'
title: 'The Tanno-Theorem for Kählerian metrics with arbitrary signature'
---
Introduction {#sec:hpr}
============
Tanno equation and Main result
------------------------------
Let $(M,g,J)$ be a pseudo-Riemannian Kähler manifold of real dimension $2n$. During the whole paper, we are using tensor notation, for example $T^{i_{1}...i_{p}}_{j_{1}...j_{q},k}$ means covariant differentiation of the tensor $T^{i_{1}...i_{p}}_{j_{1}...j_{q}}$ with respect to the Levi-Civita connection of $g$. If $\omega_{i}$ is a $1$-form on $M$, then $\bar{\omega}_{i}=J^{\alpha}_{i}\omega_{\alpha}$. Moreover, the Kählerian $2$-form is denoted by the symbol $J_{ij}=g_{i\alpha}J^{\alpha}_{j}$. We are interested in the question, if $(M,g,J)$ allows the existence of a non-constant solution $f$ of the equation $$\begin{aligned}
f_{,ijk}+c(2f_{,k}g_{ij}+f_{,i}g_{jk}+f_{,j}g_{ik}-\bar{f}_{,i}J_{jk}-\bar{f}_{,j}J_{ik})=0\label{eq:tanno}\end{aligned}$$ Originally this equation appeared first in spectral geometry, see [@Tanno1978]. Let $(\mathbb{C}P(n),g_{FS})$ be the complex projective space with Fubini-Study metric $g_{FS}$ of constant holomorphic sectional curvature equal to $1$. Then, the eigenfunctions of the Laplacian to the first eigenvalue $-(n+1)$ satisfy with $c=\frac{1}{4}$.
Conversely, contracting with $g^{ij}$ shows that $(\Delta f)_{,k}=-4c(n+1)f_{,k}$, hence $$\Delta(f+C)=-4c(n+1)(f+C)$$ for any solution $f$ of and some constant $C$.
The goal of this paper is to give a proof of the following Theorem:
\[thm:main\] Let $f$ be a non-constant smooth function on a closed, connected pseudo-Riemannian Kähler manifold $(M^{2n},g,J)$ such that the equation (\[eq:tanno\]) is fulfilled for some constant $c$. Then $c\neq 0$ and $(M^{2n}, 4cg, J)$ can be finitely covered by $(\mathbb{C}P(n), g_{FS}, J_{standard})$.
In particular we obtain that on a closed, connected Kähler manifold $(M,g,J)$ such that $Cg$ is not positively definite for any constant $C\neq 0$, any solution of is necessarily a constant. If we assume in addition lightlike completeness, there is a simple and short proof of this statement. Indeed, let $f$ be a solution of equation and let $\gamma:\mathbb{R}\rightarrow M$ be a lightlike geodesic. Restricting to $\gamma$ yields the ordinary differential equation $f'''(t)=0$, where $f(t)=f(\gamma(t))$. The general solution $f(t)=At^{2}+Bt+C$ must have vanishing constants $A$ and $B$ since $\gamma$ is complete and $f$ is bounded on the closed manifold $M$. We obtain that each solution $f$ of equation is constant along any lightlike geodesic. Since two arbitrary points can be connected by a broken lightlike geodesic, we obtain that all solutions of are constant. Theorem \[thm:main\] generalises this result to the case of a closed, connected lightlike incomplete manifold.
Theorem \[thm:main\] was proven in [@Tanno1978] for positively definite $g$ and $c>0$. In this case it is sufficient to require that the manifold is complete. In [@HiramatuK] it was proven that the equation with positively definite $g$ on a closed manifold can not have non-constant solutions for $c\leq 0$.
The Riemannian analogue: Gallot-Tanno equation
----------------------------------------------
Let us recall that the equation (\[eq:tanno\]) was introduced in [@Tanno1978] as “Kählerization” of $$\begin{aligned}
f_{,ijk}+c(2f_{,k} \cdot g_{ij}+ f_{,i} g_{j k} + f_{,j} g_{i k})=0\label{eq:GallotTanno}\end{aligned}$$ As its Kählerian analogue , this equation has its origin in spectral geometry: Consider the Laplacian on the sphere $S^{n}$ of constant sectional curvature equal to $1$. Then the eigenfunctions corresponding to the second eigenvalue $-2(n+1)$ satisfy with $c=1$, see [@Tanno1978; @Gallot1979]. Moreover, this equation appeared independently in many other parts of differential geometry. It is known that a non-constant solution of on a Riemannian manifold $(M,g)$ implies the decomposability of the cone $(M'=\mathbb{R}_{>0}\times M,g'=dr^{2}+r^{2}g)$ (decomposability means that $(M',g')$ locally looks like a product manifold), see [@Gallot1979]. In [@Mounoud2010; @Matveev2010] it was shown that this remains to be true in the pseudo-Riemannian situation for a cone over a closed manifold. Furthermore, equation is related to conformal and projective differential geometry (see [@Hiramatu; @Tanno1978] and [@Matveev2010; @Mounoud2010] for references). The classical result dealing with equation states that on a complete, connected Riemannian manifold, the existence of a non-constant solution of with $c>0$ implies that the manifold can be covered by the euclidean sphere $S^{n}$. This was proven by Gallot and Tanno independently, see [@Tanno1978; @Gallot1979]. Recently, this result was generalised to the pseudo-Riemannian situation under the additional assumption that the manifold is closed, see [@Mounoud2010; @Cortes2009]. For non-closed manifolds, generalisations of the classical result of Gallot and Tanno for metrics with arbitrary signature where discussed in more detail in [@Cortes2009].
Organisation of the paper
-------------------------
The goal of this paper is to give a proof of Theorem \[thm:main\]. In Section \[sec:c=0\] we consider the case when the constant $c$ in the equation (\[eq:tanno\]) is equal to zero. We show that there are no non-constant solutions of (\[eq:tanno\]) with $c=0$ on a closed, connected manifold. The relation between non-constant solutions of and holomorph-projective geometry (the Kählerian analogue of projective geometry) will be shown in Section \[sec:hpro\]. Given a solution of (\[eq:tanno\]), we can construct a solution of a linear PDE system which appears in the theory of holomorph-projectively equivalent Kähler metrics. Going a step further, in Section \[sec:proj\] we asign to each solution of a $(1,1)$-tensor on $\widehat{M}:=\mathbb{R}^{2}\times M$. The family of tensors constructed in this way is invariant with respect to the operation of real polynomials on endomorphisms of the tangent bundle $T\widehat{M}$. This fact allows us to find special solutions of such that the corresponding $(1,1)$-tensor acts as a non-trivial projector on $T\widehat{M}$. Using such a solution, the final goal of this Section is to show that the metric $g$ is Riemannian up to multiplication with a constant. The last step in the proof of Theorem \[thm:main\] is an application of the Theorem proven by Tanno for positive-definite $g$ and will be done in Section \[sec:proof\].
The case when $c=0$ {#sec:c=0}
===================
Let us now treat the case when the constant $c$ in the equation (\[eq:tanno\]) is equal to zero. We show
\[thm:c=0\] Let $(M,g,J)$ be a closed, connected pseudo-Riemannian Kähler manifold and $f$ a solution of $f_{,ijk}=0$. Then $f$ is a constant.
Let $p$ and $q$ be points of $M$ where $f$ takes its maximum and minimum value respectively. Then $f_{,i}(p)=f_{,i}(q)=0$ and the hessian satisfies $f_{,ij}(p)\leq 0$ and $f_{,ij}(q)\geq 0$. By assumption $f_{,ij}$ is parallel. It follows that $f_{,ij}=0$ implying that $f_{,i}$ is parallel. Since $f_{,i}(p)=$ we obtain that $f_{,i}=0$ on the whole of $M$, hence $f$ is a constant.
Solutions of (\[eq:tanno\]) correspond to solutions of Frobenius system {#sec:hpro}
=======================================================================
Let $f$ be a non-constant solution of equation on a closed, connected manifold $M$. By Theorem \[thm:c=0\] we obtain $c\ne 0$. The constant $c$ can therefore be included in the metric $g$ without changing the Levi-Civita connection. For simplicity, we denote the new metric again with the symbol $g$, hence $f$ satisfies equation (\[eq:tanno\]) with $c=1$. Consider the symmetric $(0,2)$-tensor $a_{ij}$ and the function $\mu$ defined by $$\begin{gathered}
a_{ij}:=-f_{,ij}-2fg_{ij}\mbox{ and }\mu:=-2f\label{eq:def}\end{gathered}$$ Then we obtain that the following linear system of PDE‘s is satisfied: $$\begin{gathered}
\label{eq:system}
\begin{array}{c}
a_{i j,k}=f_i g_{j k} + f_j g_{i k}-\bar{f}_i J_{jk}-\bar{f}_j J_{ik}\\
f_{i,j}=\mu g_{i j}-a_{i j},\\
\mu_{,i}=-2f_i
\end{array}
\end{gathered}$$ Indeed, covariantly differentiating $a_{ij}=-f_{,ij}-2 f g_{ij}$ and substituting yields $$\begin{aligned}
a_{ij,k}&=-f_{,ijk}-2 f_{,k} g_{ij}=2 f_{,k} \cdot g_{ij}+ f_{,i} g_{j k} +
f_{,j} g_{i k} - \bar{f}_{,i}J_{jk}-\bar{f}_{,j}J_{ik} -2 f_{,k}
g_{ij}\nonumber\\
&=f_{,i} g_{j k}+f_{,j} g_{i k}-\bar{f}_{,i}J_{jk}-\bar{f}_{,j}J_{ik},\nonumber\end{aligned}$$ which is the first equation in . The second and third equations of are equivalent to the definition .
\[rem:hpro\] The first equation $$\begin{aligned}
a_{i j,k}=f_i g_{j k} + f_j g_{i k}-\bar{f}_i J_{jk}-\bar{f}_j J_{ik}\label{eq:main}\end{aligned}$$ in is the main equation in holomorph-projective geometry, see for example [@Sin2; @DomMik1978] or [@Mikes] for a survey on this topic. Two Kähler metrics $g$ and $\bar{g}$ are said to be *holomorph-projectively equivalent* if their holomorphically-planar curves coincide. Recall that a curve $\gamma:I\rightarrow M$ is called *holomorphically-planar* with respect to the Kähler metric $g$ if there are functions $\alpha,\beta:I\rightarrow\mathbb{R}$ such that $\nabla_{\dot{\gamma}}\dot{\gamma}=\alpha \dot{\gamma}+\beta J\dot{\gamma}$ is satisfied, see [@Otsuki1954; @Tashiro1956]. The importance of equation is due to the fact, that the solutions $(a_{ij},f_{i})$ of , such that $a_{ij}$ is symmetric and hermitian, are in $1:1$ correspondence with metrics $\bar{g}$ beeing holomorph-projectively equivalent to $g$.
\[rem:hpro2\] We want to mention that the $1$-form $f_{i}$ corresponding to a solution $(a_{ij},f_{i})$ of always is the differential of a function. Indeed, contracting equation with $g^{ij}$ shows that $f_{i}=\frac{1}{4}a^{\alpha}_{\alpha,i}$, in particular $f_{i,j}=f_{j,i}$.
Let us note that the construction is invertible: If there is a solution $(a_{ij},f_{i},\mu)$ of (\[eq:system\]) we can use the equations in (\[eq:system\]) to show that $\mu$ always constitutes a solution of equation (\[eq:tanno\]) with $c=1$. Indeed, $$\begin{aligned}
\mu_{,ijk}&\overset{\mbox{\tiny\eqref{eq:system}}}{=}\nabla_{k}(-2f_{i,j})\overset{\mbox{\tiny\eqref{eq:system}}}{=}\nabla_{k}(-2\mu \tilde{g}_{ij}+2a_{ij})\nonumber\\
&=-2\mu_{,k} \tilde{g}_{ij}+2a_{ij,k}\overset{\mbox{\tiny\eqref{eq:system}}}{=}-2\mu_{,k} \tilde{g}_{ij}+2f_{i}\tilde{g}_{ik}+2f_{j}\tilde{g}_{jk}-2\bar{f}_{i}\tilde{J}_{jk}-2\bar{f}_{j}\tilde{J}_{ik}\nonumber\\
&\overset{\mbox{\tiny\eqref{eq:system}}}{=}-2\mu_{,k} \tilde{g}_{ij}-\mu_{,i}\tilde{g}_{ik}-\mu_{,j}\tilde{g}_{jk}+\bar{\mu}_{,i}\tilde{J}_{jk}+\bar{\mu}_{,j}\tilde{J}_{ik}\nonumber\end{aligned}$$ Hence, given a solution $(a_{ij},f_{i},\mu)$ of we can define $f:=-\frac{1}{2}\mu$ which gives a solution of . This definition is the inverse construction to and therefore, the solutions $f$ of and $(a_{ij},f_{i},\mu)$ of are in linear $1:1$ correspondence.\
Let us now show the main advantage of working with a system like (\[eq:system\]):
\[lem:frobenius\] Let $(a_{ij},f_i,\mu)$ be a solution of the system (\[eq:system\]) such that $a_{ij}=0$, $f_i=0$, $\mu=0$ at some point $p$ of the connected Kähler manifold $(M,g,J)$. Then $a_{ij}\equiv 0$, $f_i\equiv 0$, $\mu\equiv 0$ at all points of $M$.
The system is in Frobenius form, i.e., the derivatives of the unknowns $a_{ij}, f_i, \mu$ are expressed as (linear) functions of the unknowns: $$\left(\begin{array}{c}a_{ij,k}\\f_{i,j}\\\mu_{,i}\end{array}\right)
=F\left(\begin{array}{c}a_{ij}\\f_{i}\\\mu\end{array}\right)\nonumber,$$ and all linear systems in the Frobenius form have the property that the vanishing of the solution at one point implies the vanishing at all points.
If there is a non-constant solution of with $c=1$, then $g$ is positively definite {#sec:proj}
==================================================================================
The goal of this section is to prove the following
\[pos\] Let $(M, g, J)$ be a closed, connected Kähler manifold. Suppose $f$ is a non-constant solution of with $c=1$. Then, the metric $g$ is positively definite.
First we want to show that it is possible to choose one solution of equation (\[eq:tanno\]) such that the corresponding $(1,1)$-tensor $a^i_j=g^{i\alpha}a_{\alpha j}=-f^{i}_{,j}-2f\delta^{i}_{j}$ has a clear and simple structure of eigenspaces and eigenvectors. Evaluating $a_{ij},f_{,ij}$ and $g_{ij}$ on these eigenspaces will show that $g$ has to be positively definite.
Matrix of the extended system {#99}
-----------------------------
In order to find the special solution of (\[eq:tanno\]) mentioned above, we asign to each solution $f$ of (\[eq:tanno\]) a $(1,1)$-tensor on the $(2n+2)$-dimensional manifold $\widehat{M}={\mathbb R}^2\times M$ with coordinates $(\underbrace{x_+,x_-}_{{\mathbb R}^2},\underbrace{x_1,\dots,x_{2n}}_{M})$. For every solution $f$ of equation (\[eq:tanno\]), let us consider the $(2n+2)\times(2n+2)$-matrix $$\begin{gathered}
\label{eq:operator}
L(f)=\left(
\begin{array}{cc|ccc}
\mu&0&f_{1}&\dots&f_{2n}\\
0&\mu&\bar{f}_{1}&\dots&\bar{f}_{2n}\\
\hline
f^{1}&\bar{f}^{1}&&&\\
\vdots&\vdots&&a^i_j&\\
f^{2n}&\bar{f}^{2n}&&&
\end{array}\right)\end{gathered}$$ where $a_{ij}$ and $\mu$ are defined by the equations . The matrix $L(f)$ is a well-defined $(1,1)$-tensor field on $\widehat{M}$ (in the sense that after a change of coordinates on $M$ the components of the matrix $L$ transform according to tensor rules).
Using we see that the identity transformation of $T\widehat{M}$ corresponds to the function $f=-\frac{1}{2}$, i.e. $$\begin{gathered}
\nonumber
L\left(-\frac{1}{2}\right)=\left(
\begin{array}{cc|ccc}
1&0&0&\dots&0\\
0&1&0&\dots&0\\
\hline
0&0&&&\\
\vdots&\vdots&&\delta^i_j&\\
0&0&&&
\end{array}\right)={\bf 1}
\end{gathered}$$
The matrix $L$ contains the information on the function $f$ and its first and second derivatives. By equation and Lemma \[lem:frobenius\], if this matrix is vanishing at some point of $\widehat{M}$ then $f\equiv 0$ on the whole of $M$. In the next section, we will see that the matrix formalism does have advantages: we will show that the polynomials of the matrix $L$ also correspond to certain solutions of equation .
The constructions which where done here are visually similar to those which can be done for equation . However, in the non-Kählerian situation the corresponding $(1,1)$-tensor on the cone manifold is covariantly constant with respect to the connection induced by the cone metric, see [@Gallot1979; @Mounoud2010; @Matveev2010]. This is not the case for the extended operator which poses additional difficulties.
Algebraic properties of $L$
---------------------------
Obviously, the mapping $f\longmapsto L(f)$ applied to arbitrary smooth functions $f$ on $M$ is a linear injective mapping between the space of smooth functions on $M$ and the space of $(1,1)$-tensors on $\widehat{M}$. For two smooth functions $F$ and $H$ on $M$ let us define a new product $$\begin{aligned}
F*H:=-2FH-\frac{1}{2}F_{,\alpha}H^{\alpha}_{,}\mbox{ and the $k$-fold potency }F^{*k}:=\underbrace{F*...*F}_{k\mbox{ \tiny times}},\nonumber\end{aligned}$$ The product $*$ is bilinear and commuting but not associative. However, it turns out that the mapping $L$ now preserves the potencies $f^{*k}$ of solutions of :
\[lem:product\]
1. Let $f$ be a solution of equation with $c=1$. Then, for every $k\geq 0$ there exists a solution $\tilde{f}$ such that $$L^k(f)=L(\tilde {f}), \mbox{ where }L^k = \underbrace{L
\cdot ... \cdot L}_\text{$k$ times}.$$
2. If $f$ is a solution of with $c=1$, then $L^{k}(f)=L(f^{*k})$. In particular, $f^{*k}$ is a solution of .
$(1)$ Given two solutions $f$ and $F$ of equation , we denote by $(a_{ij},f_i,\mu)$ and $(A_{ij},F_i,{{\mathcal M}})$ the corresponding solutions of , constructed by . After direct calculation we obtain for the product of the corresponding matrices $L(f)$ and $L(F)$: $$\begin{gathered}
\label{eq:product}
L(f)\cdot L(F)=\left(
\begin{array}{cc|ccc}
\mu {{\mathcal M}}+f_k F^k&f_k \bar{F}^k&\mu
F_{1}+f_k A^k_1&\dots&\mu F_{2n}+f_k
A^k_{2n}\\
\bar{f}_k F^k&\mu {{\mathcal M}}+f_k F^k&\mu
\bar F_{1}+\bar f_k
A^k_1&\dots&\mu\bar{F}_{2n}+\bar{f}_k A^k_{2n}\\
\hline
\vphantom{\dfrac{1}{2}}{{\mathcal M}}f^{1}+a^1_kF^k&{{\mathcal M}}\bar{f}^{1}+a^1_k\bar{F}^k&&&\\
\vdots&\vdots&\multicolumn{3}{c}{a^i_k
A^k_j+f^i F_j+\bar{f}^i\bar{F}_j}\\
{{\mathcal M}}f^{2n}+a^{2n}_k F^k&
{{\mathcal M}}\bar{f}^{2n}+a^{2n}_k\bar{F}^k&&&
\end{array}\right)
\end{gathered}$$ Suppose that $$\begin{gathered}
\label{eq:op_eq}
\mu F_j+f_k A^k_j= {{\mathcal M}}f_j+a^k_j F_k\quad\mbox{and}\quad f^k \bar{F}_k=0
\end{gathered}$$ then $L(f)\cdot L(F)$ takes the form $$\begin{gathered}
\label{eq:product_sol}
L(f)\cdot L(F)=\left(
\begin{array}{cc|ccc}
\tilde{\mu}&0&\tilde{f}_{1}&\dots&\tilde{f}_{2n}\\
0&\tilde{\mu}&\bar{\tilde{f}}_{1}&\dots&\bar{\tilde{f}}_{2n}\\
\hline
\tilde{f}^{1}&\bar{\tilde{f}}^{1}&&&\\
\vdots&\vdots&&\tilde{a}^i_j&\\
\tilde{f}^{2n}&\bar{\tilde{f}}^{2n}&&&
\end{array}\right)\end{gathered}$$ where $\tilde a^{i}_{j}=a^i_k
A^k_j+f^i F_j+\bar{f}^i\bar{F}_j,\tilde {f}_i=\mu F_i+ A^k_i f_k$ and $\tilde\mu=\mu {{\mathcal M}}+f_k F^k$. Now we show that $\tilde {a}_{ij}$, $\tilde {f}_i$ and $\tilde \mu$ satisfy (\[eq:system\]). In addition, we show that $L(f)\cdot L(F)$ is self-adjoint. Let us check the first equation of : $$\begin{gathered}
\nonumber
\tilde a_{ij,k}=(a_{is}
A^s_j+f_i F_j+\bar{f}_i\bar{F}_j)_{,k}=
a_{is,k}A^s_j+a^s_i
A_{sj,k}+f_{i,k}F_j+f_i F_{j,k}+
\bar{f}_{i,k}\bar{F}_j+\bar{f}_i\bar{F}_{j,k}
\\
\stackrel{(\ref{eq:system})}{=}A^s_j f_i g_{sk}+A^s_j f_s g_{ik}+
A^s_j \bar {f}_i J^{s'}_{\ \ s}g_{s' k}+A^s_j \bar{f}_s
J^{{{i'}}}_{\ \ i}g_{{{i'}}k}+a^s_i F_j g_{sk}+a^s_i F_s g_{jk}+
a^s_i \bar{F}_j J^{s'}_{\ \ s}g_{s' k}+a^s_i \bar{f}_s
J^{{{j'}}}_{\ \ j}g_{{{j'}}k}\\
+\mu g_{ik} F_j-a_{ik}F_j+{{\mathcal M}}g_{jk}f_i-A_{jk}f_i+
\mu J^{{{i'}}}_{\ \ i} g_{{{i'}}k} \bar{F}_j-J^{{{i'}}}_{\ \ i}
a_{{{i'}}k}\bar{F}_j+{{\mathcal M}}J^{{{j'}}}_{\ \
j}g_{{{j'}}k}\bar{f}_i-J^{{{j'}}}_{\ \ j}A_{{{j'}}k}\bar{f}_i\\
=g_{ik}(f_s A^s_j+\mu F_j)+g_{jk}(F_s
a^s_i+{{\mathcal M}}f_i)+
J^{{{i'}}}_{\ \ i}g_{{{i'}}k}(\bar{f}_s A^s_j+\mu \bar{F}_j)+
J^{{{j'}}}_{\ \ j}g_{{{j'}}k}(\bar{F}_s a^s_i+{{\mathcal M}}\bar{f}_i)
\\
\stackrel{\eqref{eq:op_eq}}{=}\tilde{f}_i g_{j k} + \tilde{f}_j g_{i k}-J^{\alpha}_{i}\tilde{f}_\alpha J_{j k} - J^{\alpha}_{j}\tilde{f}_\alpha J_{i k}
\end{gathered}$$ For the second equation one can calculate: $$\begin{gathered}
\nonumber
\tilde {f}_{i,k}=(\mu{F}_i+f_j A^j_i)_{,
k}=\mu_{,k}F_i+\mu F_{i, k}+ f_{j,k}
A^j_i+f^j A_{ij,k}\\
\stackrel{(\ref{eq:system})}{=}-2f_k F_i+\mu{{\mathcal M}}g_{ik}-\mu A_{ik}+\mu A_{ik}
-a_{jk}A^j_i+ f^j F_i g_{j k} + f^j F_j
g_{i k}+f^j J^{{j'}}_{\ \ j}J^{{i'}}_{\ \ i}F_{{i'}}g_{{{j'}}k} +
f^j J^{{j'}}_{\ \ j}J^{{i'}}_{\ \ i}F_{{j'}}g_{{{i'}}k}\\
=(\mu {{\mathcal M}}+f^j F_j)g_{ik}-(f_k F_i
+\bar{f}_k \bar{F}_i+A_{ij}
a^j_k)+f^j\bar{F}_j J^{{i'}}_{\ \ i}g_{{{i'}}k}\stackrel{\eqref{eq:op_eq}}{=}
\tilde \mu g_{ki}-\tilde a_{ki}
\end{gathered}$$ As we already stated in Remark \[rem:hpro2\], since $(\tilde{a}_{ij},\tilde{f}_{i})$ satisfies , the $1$-form $\tilde{f}_{i}$ is the differential of a function. It follows that $\tilde{f}_{i,j}$ is symmetric and from the last calculation we obtain that $\tilde a_{ij}$ is symmetric since it is the linear combination of two symmetric tensors. Let us now check the third equation of : $$\begin{gathered}
\nonumber
\tilde \mu_{, i}=(\mu {{\mathcal M}}+f_k F^k)_{, i}=
\mu_{, i} {{\mathcal M}}+ \mu {{\mathcal M}}_{, i} +f_{k, i} F^k+f^k
F_{k, i}\\
\stackrel{(\ref{eq:system})}{=}-2f_i {{\mathcal M}}-2F_i \mu +F^k (\mu g_{ik}-a_{ik})+f^k ({{\mathcal M}}g_{ik}-A_{ik})=-(\mu F_i+f_k
A^k_i)-({{\mathcal M}}f_i+F_k
a^k_i)\stackrel{\eqref{eq:op_eq}}{=}-2\tilde f_i
\end{gathered}$$ Thus, $(\tilde{a}_{ij},\tilde{f}_{i},\tilde \mu)$ is a solution of .\
Now we show that the operator $L(F)=L^k(f)$ satisfies the conditions . Since $L^{k}\cdot L=L\cdot L^{k}$, using (\[eq:product\]) we obtain $$\mu F_j+f_k A^k_j= {{\mathcal M}}f_j+a^k_j F_k$$ The last condition will be checked by induction. Suppose $f^i \bar {F}_i=0$ then $$f^i J^{{i'}}_{\ \ i}\widetilde{F}_{{i'}}=f^i \cdot J^{{i'}}_{\
\ i}(\mu F_{{i'}}+f_k A^k_{{i'}})=\mu\cdot 0 + f^k
(J_{\ \ i}^{{i'}}A_{k {{i'}}})f^i=0.$$ From the constructions in , it is obvious that $L(\tilde{f})=L^{k+1}(f)$ where $\tilde{f}=-\frac{1}{2}\tilde{\mu}$. This completes the proof of the first part of Lemma \[lem:product\].\
Part $(2)$ follows immediately from the already proven part: Proceeding by induction, we assume $L(f^{*k})=L^{k}(f)$. We already know from the first part of Lemma \[lem:product\], that $L^{k+1}(f)=L(f)\cdot L^{k}(f)=L(\tilde{f})$. The solution $\tilde{f}$ of is given by the formula $\tilde{f}=-\frac{1}{2}\tilde{\mu}=-2fF -\frac{1}{2}f_k F^k$, see the equations following formula . By assumption $F=f^{*k}$ and therefore $\tilde{f}=f*f^{*k}=f^{*(k+1)}$.
Let us consider the natural operation of polynomials with real coefficients on elements of $T^{1}_{1}\widehat{M}$. From Lemma \[lem:product\], we immediately obtain that the family of $(1,1)$-tensors $L(f)$, constructed from solutions $f$ of is invariant with respect to this operation:
Let $f$ be a solution of with $c=1$ and $P(t)=c_k t^k+\dots+c_1 t+c_0$ an arbitrary polynomial with real coefficients. Then $P*(f):=c_k f^{*k}+c_{k-1} f^{*(k-1)}+\dots+c_1 f-\frac{1}{2}c_0$ is a solution of with $c=1$ and $L(P*(f))=P(L(f))$.
There exists a solution $f$ of such that $L(f)$ is a projector.
---------------------------------------------------------------
We assume that $(M, g, J)$ is a closed, connected Kähler manifold. Our goal is to show that the existence of a non-constant solution $f$ of (\[eq:tanno\]) with $c=1$ implies the existence of a solution $\check{f}$ of (\[eq:tanno\]) such that the matrix $L(\check{f})$ is a non-trivial (i.e. $\neq 0$ and $\neq {{\bf 1}}$) projector. (Recall that a matrix $L$ is a *projector*, if $L^2=L$.). We need
\[lem:minim\] Let $(M, g, J)$ be a connected Kähler manifold and $f$ a solution of with $c=1$.
Let $P(t)$ be the minimal polynomial of $L(f)$ at the point $\hat p \in\widehat M$. Then, $P(t)$ is the minimal polynomial of $L(f)$ at every point $\hat q\in \widehat M$.
We will always assume that the leading coefficient of a minimal polynomial is $1$.
As we have already proved, there exists a solution $\tilde{f}$ such that $$P(L(f))=L(\tilde{f}).$$ Since $P(L(f))$ vanishes at the point $\hat p=(x_+, x_-,p)$, we obtain that $\tilde {a}_{ij}=0$, $\tilde{f}_{i}=0$ and $\tilde \mu=0$ at $p$, where $(\tilde {a}_{ij},\tilde{f}_{i},\tilde \mu)$ denotes the solution of corresponding to $\tilde{f}$. Then, by Lemma \[lem:frobenius\], the solution $(\tilde a_{ij},\tilde{f}_{i},\tilde
\mu)$ of is identically zero on $M$. Thus, $P(L(f))$ vanishes at all points of $\widehat M$. It follows, that the polynomial $P(t)$ is divisible by the minimal polynomial of $L(f)$ at $\hat
q$. By the same reasoning (interchanging $p$ and $q$), we obtain that $Q(t)$ is divisible by $P(t)$. Consequently, $P(t)= Q(t)$.
The eigenvalues of $L(f)$ are constant functions on $\widehat M$.
By Lemma \[lem:minim\], the minimal polynomial does not depend on the points of $\widehat M$. Then, the roots of the minimal polynomial are also constant (i.e., do not depend on the points of $\widehat M$).
In order to find the desired special solution of equation (\[eq:tanno\]), we will use that $M$ is closed.
\[lem:two\_eigenvalues\] Suppose $(M,g,J)$ is a closed, connected Kähler manifold. Let $f$ be a non-constant solution of with $c=1$. Then at every point of $\widehat M$ the matrix $L(f)$ has at least two different real eigenvalues.
Let $(a_{ij},f_{i},\mu)$ denote the solution of corresponding to $f$. Since $M$ is closed, the function $\mu$ admits its maximal and minimal values $\mu_{\max}$ and $\mu_{\min}$. Let $p \in M$ be a point where $\mu=\mu_{\max}$. At this point, $\mu_{,i}=0$ implying $f_i=\bar {f}_i=0$. Then, the matrix of $L(f)$ at $p$ has the form
$$\begin{gathered}
L(f)=\left(
\begin{array}{cc|ccc}
\mu_{\max}&0&0&\dots&0\\
0&\mu_{\max}&0&\dots&0\\
\hline
0&0&&&\\
\vdots&\vdots&&a^i_j&\\
0&0&&&
\end{array}\right)
\end{gathered}$$
Thus, $\mu_{\max}$ is an eigenvalue of $L(f)$ at $p$ and, since the eigenvalues are constant, $\mu_{\mbox{\tiny max}}$ is an eigenvalue of $L(f)$ everywhere on $M$. The same holds for $\mu_{\min}$. Since $f_i\not\equiv 0$, $\mu$ is not constant implying $\mu_{\max}\ne \mu_{\min}$. Finally, $L(f)$ has two different real eigenvalues $\mu_{\max},
\mu_{\min}$ at every point.
\[-3\] For further use let us note that in the proof of Lemma \[lem:two\_eigenvalues\] we have proved that if $\mu_{,i}=0$ at a point $p$ then $\mu(p)$ is an eigenvalue of $L$.
Finally, let us show that there is always a solution of (\[eq:tanno\]) of the desired special kind:
Suppose $(M,g,J)$ is a closed and connected Kähler manifold. For every non-constant solution $f$ of with $c=1$, there exists a polynomial $P(t)$ such that $P(L(f))$ is a non-trivial (i.e. it is neither ${\bf 0}$ nor ${{\bf 1}}$) projector.
We take a point $\hat{p}\in \widehat{M}$. By Lemma \[lem:two\_eigenvalues\], $L(f)$ has at least two real eigenvalues at the point $\hat{p}$. Then, by linear algebra, there exists a polynomial $P$ such that $P( L(f))$ is a nontrivial projector at the point $\hat{p}$. Evidently, a matrix is a nontrivial projector, if and only if its minimal polynomial is $t(t-1)$ (multiplied by any nonzero constant). Since by Lemma \[lem:minim\] the minimal polynomial of $P( L(f))$ is the same at all points, the matrix $P( L(f))$ is a projector at every point of $\widehat{M}$.
Thus, given a non-constant solution of with $c=1$ on a closed and connected Kähler manifold $M$, without loss of generality we can think that a solution $f$ of (\[eq:tanno\]) with $c=1$ is chosen such that the corresponding $(1,1)$-tensor $L(f)$ is a non-trivial projector.
Structure of eigenspaces of $a_j^i$, if $L(f)$ is a nontrivial projector
------------------------------------------------------------------------
Assuming that $L(f)$ is a nontrivial projector, it has precisely two eigenvalues $1$ and $0$ and the $(2n+2)$-dimensional tangent space of $\widehat M$ at every point $\hat x=(x_+,x_-,p)$ can be decomposed into the sum of the corresponding eigenspaces $$T_{\hat x}\widehat M =
E_{L(f)}(1)\oplus E_{L(f)}(0).$$ The dimensions of $E_{L(f)}(1)$ and $E_{L(f)}(0)$ are even; we assume that the dimension of $E_{L(f)}(1)$ is $2k+2$ and the dimension of $E_{L(f)}(0)$ is $2n-2k$. If $(a_{ij},f_{i},\mu)$ is the solution of corresponding to $f$, $\mu_{\max}$ and $\mu_{\min}$ are eigenvalues of $L(f)$, see Lemma \[lem:two\_eigenvalues\]. Since $L(f)$ is a projector we obtain $\mu_{\min}=0\leq\mu(x)\leq 1=\mu_{\max}$ on $M$. In view of Remark \[-3\], the only critical values of $\mu$ are $1$ and $0$.
Let $f$ be a solution of (\[eq:tanno\]) with $c=1$ such that $L(f)$ is a non-trivial projector. Let $(a_{ij},f_{i},\mu)$ be the solution of corresponding to $f$. Then, the following statements hold: \[lem:eigen\]
1. At the point $p$ such that $0<\mu< 1$, $a^i_j$ has the following structure of eigenvalues and eigenspaces
1. eigenvalue $1$ with geometric multiplicity $2k$;
2. eigenvalue $0$ with geometric multiplicity $(2n-2k-2)$;
3. eigenvalue $(1-\mu)$ with multiplicity $2$.
2. At the point $p$ such that $\mu=1$, $a^i_j$ has the following structure of eigenvalues and eigenspaces:
1. eigenvalue $1$ with geometric multiplicity $2k$;
2. eigenvalue $0$ with geometric multiplicity $(2n-2k)$;
3. At the point $p$ such that $\mu=0$, $a^i_j$ has the following structure of eigenvalues and eigenspaces:
1. eigenvalue $1$ with geometric multiplicity $2k+2$;
2. eigenvalue $0$ with geometric multiplicity $(2n-2k-2)$.
We identify $M$ with the set $(0,0)\times M\subset \widehat M$. This identification allows us to consider $T_xM$ as a linear subspace of $T_{(0,0)\times x} \widehat M$: the vector $(v_1,...,v_n)\in T_xM$ is identified with $(0,0,v_1,...,v_n)\in T_{(0,0)\times x} \widehat M$.
Consider the point $p$ such that $0<\mu< 1$. For any vector $v\in E_{L(f)}(1)\cap T_{p}M$ we calculate $$\begin{gathered}
L(f) v=\left(
\begin{array}{cc|ccc}
\mu&0&f_{1}&\dots&f_{2n}\\
0&\mu&\bar{f}_{1}&\dots&\bar{f}_{2n}\\
\hline
f^{1}&\bar{f}^{1}&&&\\
\vdots&\vdots&&a^i_j&\\
f^{2n}&\bar{f}^{2n}&&&
\end{array}\right)
\left(
\begin{array}{c}
0\\
0\\
v^1\\
\vdots\\
v^{2n}
\end{array}
\right)=
\left(
\begin{array}{c}
f_j v^j\\
\bar {f}_j v^j\\
\\
a^i_j v^j\\
\\
\end{array}
\right)
= \left(
\begin{array}{c}
0\\
0\\
v^1\\
\vdots\\
v^{2n}
\end{array}
\right)
\end{gathered}$$
Thus, $v=(v^1,\dots v^{2n})$ is an eigenvector of $a^i_j$ with eigenvalue $1$, hence $E_{L(f)}(1)\cap T_{p}M$ is contained in the eigenspace $E_{1}$ of $a^{i}_{j}$ with eigenvalue $1$. Similarly, any $v \in E_{L(f)}(0)\cap T_{p}M$ is an eigenvector of $a^i_j$ with eigenvalue $0$ and $E_{L(f)}(0)\cap T_{p}M$ is contained in the eigenspace $E_{0}$ of $a^{i}_{j}$ with eigenvalue $0$. Note that the dimension of $E_{L(f)}(1)\cap T_{p}M$ is at least $2k$, and the dimension of $E_{L(f)}(0)\cap T_{p}M$ is at least $2n - 2k - 2$. Let us now show that $f^i$ and $\bar{f}^i$ are eigenvectors of $a^i_j$ with eigenvalue $(1-\mu)$. We multiply the first basis vector $(1,0,\dots,0)$ by the matrix $L(f)^2-L(f)$ (which is identically zero) and obtain $$\begin{gathered}
0 = (L(f)^2-L(f)) \left(
\begin{array}{c}
1\\
0\\
0\\
\vdots\\
0
\end{array}
\right)=
\left(
\begin{array}{c}
\mu^2 + f_j f^j - \mu\\
\bar{f}_i f^i\\
\\
\mu f^i + a^i_j f^j-f^i\\
\\
\end{array}
\right)
\end{gathered}$$ This gives us the necessary equation $a^i_j f^j= (1-\mu)f^i$. Considering the same procedure for the second basis vector $(0,1,\dots,0)$ we obtain that $\bar{f}^{i}$ is an eigenvector of $a^{i}_{j}$ to the eigenvalue $(1-\mu)$ and hence, the dimension of the eigenspace $E_{1-\mu}$ of $a^{i}_{j}$ corresponding to the eigenvalue $1-\mu$ is at least $2$. On the one hand, $dim E_{1}+dim E_{0}+dim E_{1-\mu}$ is at most $2n$ but on the other hand, $2k \leq dim(E_{L(f)}(1)\cap T_{p}M)\leq dim E_{1}$, $2n - 2k - 2\leq dim(E_{L(f)}(0)\cap T_{p}M)\leq dim E_{0}$ and $2 \leq dim E_{1-\mu}$ implying that $$\begin{aligned}
T_{p}M=E_{1}\oplus E_{0}\oplus E_{1-\mu}. \end{aligned}$$ Furthermore $E_{1}=E_{L(f)}(1)\cap T_{p}M$, $E_{0}=E_{L(f)}(0)\cap T_{p}M$ and $E_{1-\mu}={\mathrm{span}}\{f^{i},\bar{f}^{i}\}$ are of dimensions $2k$, $2n-2k-2$ and $2$ respectively. The proof at the points such that $\mu=0$ or $\mu=1$ is similar.
If there exists a solution $f$ of equation (\[eq:tanno\]) such that $L(f)$ is a non-trivial projector, the metric $g$ is positively definite on a closed $M$
-------------------------------------------------------------------------------------------------------------------------------------------------------------
Above we have proven that, given a non-constant solution of with $c=1$, there always exists a solution $f$ of (\[eq:tanno\]) such that the corresponding matrix $L(f)$ is a non-trivial projector. If $(a_{ij},f_{i},\mu)$ is the solution of corresponding to $f$, this implies that the eigenvalues and the dimension of the eigenspaces of $a^i_j$ are given by Lemma \[lem:eigen\]. Now we are ready to prove that $g$ is positively definite (as we claimed in Theorem \[pos\]).
Let us consider such a solution $f$ and the corresponding solution $(a_{ij},f_{i},\mu)$ of . We rewrite the second equation in (\[eq:system\]) in the form $$\begin{gathered}
\label{eq:mu}
\mu_{,i j} =2 a_{i j} -2 \mu\, g_{i j}\end{gathered}$$ Let $p$ be a point where $\mu$ takes its maximum value $1$. As we have already shown $f^i(p)=0$ and the tangent space $T_pM$ is equal to the direct sum of the eigenspaces: $$T_p M=E_1\oplus E_0$$ Consider the restriction of (\[eq:mu\]) to $E_0$. Since the restriction of the bilinear form $a_{i j}$ to $E_0$ is identically zero, the equation takes the form: $$\left.\mu_{,i j}\right|_{E_0}=-2 \left.g_{i j}\right|_{E_0}.$$ But $\mu_{,i j}$ is the Hessian of $\mu$ at the maximum point $p$. Then, it is non-positively definite. Hence, the non-degenerate metric tensor $g_{ij}$ is positively definite on $E_0$ at $p$. Let us now consider the distribution of the orthogonal complement $E_1^\bot$, which is well-defined, smooth and integrable in a neighborhood of $p$. The restriction of the metric $g$ onto $E_1^\bot$ is non-degenerate and is positively definite in one point. Hence, by continuity it is positively definite in a whole neighborhood. Similarly, at a minimum point $q$ one can consider the restriction of (\[eq:mu\]) to $E_1$: $$\left.\mu_{,i j}\right|_{E_1}=2 \left.a_{i j}\right|_{E_1}=2
\left.g_{i j}\right|_{E_1},$$ since $a^{i}_{j\,|E_{1}}=\delta^{i}_{j\,|E_{1}}$, which implies that $g$ is positively definite on $E_1$ at $q$. Considering the distribution $E_0^\bot$, we obtain that the restriction of $g$ to $E_0^\bot$ is positively definite in a neighborhood of $q$. Let us now consider the general point $x$, where $$T_xM=E_1\oplus E_0 \oplus {\mathrm{span}}\{f^i,\bar{f}^i\}.$$ We choose a piecewise smooth path $\gamma:[0,1]\rightarrow M$, connecting a point $p=\gamma(0)$ where $\mu(p)=1$ with the point $x=\gamma(1)$, such that there is no point along $\gamma$ where $\mu=0$. Since the distribution $E_{1}^{\perp}$ is differentiable on $M\setminus\{q\in M:\mu(q)=0\}$, there cannot be a change of signature of the restriction of the metric $g_{|E_{1}^{\perp}}$ along that path, unless the determinant of $g_{|E_{1}^{\perp}}$ vanishes at some point between $p$ and $x$. Since $g$ is nondegenerate, this never can happen and we obtain that $g_{|E_{1}^{\perp}}$ is positively definite at $x$. Exactly the same arguments can be used if one wants to show that $g_{|E_{0}^{\perp}}$ is positively definite at $x$. In the end, we obtain that $g$ is positively definite at each point of $M$ and hence, Theorem \[pos\] is proven.
Proof of Theorem \[thm:main\] {#sec:proof}
=============================
Let $(M,g,J)$ be a closed, connected pseudo-Riemannian Kähler manifold and $f$ a non-constant solution of equation . By Theorem \[thm:c=0\], $c\neq 0$ and the metric $g$ can be replaced by $\tilde{g}=c\cdot g$ without changing the Levi-Civita connection. The function $f$ is now a non-constant solution of with $c=1$ and using Theorem \[pos\] we obtain that $\tilde{g}$ has to be positive-definite. Applying the classical result of Tanno [@Tanno1978] for positive-definite metrics, we obtain that $(M,4cg,J)$ has constant holomorphic sectional curvature equal to $1$, hence Theorem \[thm:main\] is proven.
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| 2024-03-26T23:14:03.371983 | https://example.com/article/4794 |
For 8-bit music, this game has some that is both painful and awesome. For the purpose of this blog only the awesome music will be shared. Most of this is included with the songs that Link learns to play on his ocarina, a later staple of the series, which he learns from those about the island.
There are three, of these songs. One is taught by a girl who sings in the main village and is the person who found Link laying on the beach. Another is taught by a singing fish, which is my favorite of the three. The last is taught by some frogs and allows to resurrect things with the very tune.
I am going to post those songs, here, in order of least amusing first. That meaning they are not in order you obtain them in game and the one which is annoying, at least its "sung" counterpart.
1 comment
Disclaimer
Any audio, video or images on this site have no direct claim to them, unless stated otherwise, by the writer of this blog. The author or link to source object is always available if you need proof as such if it was not provided in the blog post that it was spoken about. | 2024-03-08T23:14:03.371983 | https://example.com/article/7698 |
Endothelial modulation of resting and stimulated vascular tone in the pig capsular testicular artery.
We have investigated the wall tension characteristics and the role of endothelium on vascular tone, at rest and under K+ depolarization, in isolated rings from the pig capsular testicular artery. The active tension reached a maximum that was significantly lower in vessels without endothelium, whereas the passive tension and the Ca2+-dependent myogenic tone were not significantly affected by endothelium removal. Both NG-nitro-l-arginine (L-NOARG, 10(-4) M) and methylene blue (10(-5) M), increased the basal resting tension (BRT) in vessels with endothelium, while indomethacin (10(-6) M) decreased BRT in vessels both with and without endothelium. Either removal of endothelium or treatment with indomethacin (10(-6) M), quinacrine (10(-5) M) or ibuprofen (10(-5) M), significantly depressed the K+ concentration response curve, while dazoxiben (10(-5) M) and SQ 30,741 (10(-5) M) had no effect. L-NOARG (10(-6) M) potentiated the contractile response to K+ in vessels with endothelium, whereas L-NOARG (10(-4) M) was ineffective in vessels devoid of endothelium. These results suggest that a predominating NO release from endothelium, together with a cyclooxygenase-derived vasoconstrictor, modulate vascular tone at rest. In contrast, predominant endothelial release of a cyclooxygenase-derived contractile factor, but different from TXA2, PGH2 or superoxide anions, is induced by K+ depolarization and leads to vasoconstriction. | 2024-01-16T23:14:03.371983 | https://example.com/article/1165 |
After a string of frustrating injuries, Indiana head coach Tom Allen had a plan for his starting quarterback going into the offseason.
And much like he did on the field when healthy in 2019, Michael Penix was executing on that plan at a very high level.
At its core, the idea was that Penix needed to get bigger and stronger to help him endure the physicality of Big Ten football.
“We set out a plan for him and his weight has increased quite a bit since the end of the season,” Allen said in February as the team was getting set to embark on spring practice.
After checking in on the 2019 roster at 202 pounds, Penix added more than 15 pounds while rehabbing from a shoulder injury that ended his 2019 season.
“He’s close to 220 — 217, 218 right now,” Allen said in February. “Really changing himself there which is really important.”
Penix officially weighed in at 218 on the 2020 spring roster, and he looked noticeably more muscular as IU took the field in March.
That was then.
Now?
The annual Cream and Crimson spring game should be in 10 days, but instead Penix, like just about everyone else around the country, is back home.
Tampa, Fla., to be precise.
Penix is long way from the IU weight room in the the north end zone of Memorial Stadium, and a long way from the training table meals that college athletes are accustomed to.
But while much has changed over the last month, Penix found a familiar face to help keep him on the plan.
“My mom’s been cooking a lot for me,” Penix said this week on a teleconference.
And so far mom’s home cooking has been on point.
“My weight’s definitely been staying the same, if not going up a little bit. I’m certainly not losing any weight,” Penix said.
While everything he knew a month ago has changed, Penix believes that maintaining his new physique is part of his commitment to his team.
And that is fueling him to find answers rather than excuses.
“I can’t just go out and come back not my weight. That would be letting my team down and that’s something I’m not going to do,” Penix said.
While mom is keeping Penix well fed in the kitchen, the challenges in the weight room and on the football field are far greater.
The biggest challenge of them all?
What weight room? What football field?
Penix’s experience over the last month has been like most everyone else throughout this evolving COVID-19 pandemic.
Just when you think you find an answer to get you through your new reality — things change.
“At the beginning of this, we were on the field. We were going basic quarterback drills, just continue to stay fresh on mechanics,” Penix said.
As a quarterback, Penix needs plenty of open space to refine his craft.
And day by day, that space is shrinking.
“As they’re closing the fields down here, it’s just been a lot of fractional work. Making sure that we’re studying film and helping me just continue to focus and stay sharp on my game,” Penix said.
Probably no one has had a greater challenge in the IU program in recent weeks than new strength coach Aaron Wellman.
All Wellman has had to do in his first days on the job is design customized training plans for every player on the team, that he has never met, based on the equipment that they have, or don’t have, available at home.
Allen remarked that Penix had been one of the top five performers in the workouts back at the cozy confines of Memorial Stadium over the winter.
Weight training is the key component to Penix’s additional pounds.
But now the redshirt sophomore has been reduced to what he has available, and Wellman’s plan.
“He (Wellman) gave us all workouts,” Penix said. “He made them specific for whatever we had. He sent out body workouts if we don’t have weights. He sent out dumbbell workouts. If you have a full gym, he sent us a full gym workout. He’s been talking to us and continuing to tell us that working out is going to keep us in shape. I’ve been training and running on my own for the most part.”
There is one more thing that Penix is missing throughout this strange new reality. Something every good quarterback needs.
Receivers.
Penix has been staying in touch with that group remotely, and he hopes to reunite with the guys that are uniquely capable of providing him with the repetitions he needs soon.
“I’m going to go back to Bloomington soon just to get with some receivers. We are always communicating. We always talk about how we want to run things,” Penix said.
But as for when that will be?
Penix is stuck under the same cloud of uncertainty as the rest of us.
“No specific plans yet. It is whenever the time comes,” Penix said.
You can follow us on Twitter: @daily_hoosier
Find us on Facebook: thedailyhoosier The Daily Hoosier –“Where Indiana fans assemble when they’re not at Assembly” Seven ways to support completely free IU coverage at no additional cost to you.
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| 2023-11-24T23:14:03.371983 | https://example.com/article/2539 |
Picking a favorite superhero is tough. But as of today thanks to good, not-so-old-fashioned Google Trends analytics, we know one thing for certain: Batman is the most popular superhero in the world – on YouTube at least.
Logging more than 3 billion views of more than 71,000 hours of video, the Dark Knight is almost a billion views ahead of the next most popular hero—Thor—based on data released today by YouTube. Coming up close behind Thor is Superman, with 1.7 billion views and counting, and close behind the Man of Steel is Iron Man, the Avengers, and Wolverine. (Google’s analysis only looked at the specific name of each character, so nicknames like Man of Steel and Dark Knight weren’t counted in the totals.)
“If YouTube popularity can determine who’ll win the upcoming Batman vs. Superman movie, your views and uploads put Batman as the clear winner,” the video-sharing site wrote on the YouTube Trends blog today. “Based on keyword searches, Batman is the most popular of all superheroes on YouTube.”
All told, the top 10 superheroes on YouTube have amassed more than 10 billion views and some 234,000 hours of video, and even though Batman may “the one man who beat” Superman in overall searches since YouTube launched in 2005, his status has fallen a bit since 2008—overcome by searches for Thor, Iron Man, and the rest of the Avengers.
Some of this data seems fairly obvious–most of the search spikes each hero’s timeline correlate to the release of films about that character or group of characters (in the case of the Avengers)—but there are a few interesting and unexpected tidbits. For example, Superman, despite being consistently popular (lots of Smallville fans out there?) and coming in third place, never really sees a huge bump in interest. There was a small jump in June when Man of Steel was released, but nothing like the leap Iron Man saw a month earlier around the release of Iron Man 3.
It’s also surprising that Spider-Man, who has had a string of successful films in the last few years—all with his name in the title—actually comes in at No. 7, with 340 million views, and Captain America, who had his own film and is an Avenger, is behind him. It’s also interesting that after those two not-so-super heroes and the Justice League, which is getting a film in 2017, sits Deadpool—the off-kilter anti-hero with no movie (yet) but a loyal following. The analytics don’t reveal why the searches were done (obviously) but it’s possible folks were looking for tidbits from the Marvel character’s videogame or simply trying figure out who this “Deadpool” is that everyone’s talking about. Either way, he’s got a lot of catching up to do before he ever reaches Batman status.
Check out videos for the most popular superheroes—and an interactive chart of their performance since 2008—below. | 2024-05-14T23:14:03.371983 | https://example.com/article/2508 |
/*-----------------------------------------------------------------
LOG
GEM - Graphics Environment for Multimedia
SURF point detection and tracking
Copyright (c) 1997-1999 Mark Danks. mark@danks.org
Copyright (c) Günther Geiger. geiger@epy.co.at
Copyright (c) 2001-2002 IOhannes m zmoelnig. forum::für::umläute. IEM. zmoelnig@iem.kug.ac.at
Copyright (c) 2002 James Tittle & Chris Clepper
For information on usage and redistribution, and for a DISCLAIMER OF ALL
WARRANTIES, see the file, "GEM.LICENSE.TERMS" in this distribution.
-----------------------------------------------------------------*/
#ifndef INCLUDE_PIX_OPENCV_SURF_H_
#define INCLUDE_PIX_OPENCV_SURF_H_
#ifndef _EiC
#include "cv.h"
#endif
#include "Base/GemPixObj.h"
#define MAX_MARKERS 500
#define DSCSIZE 128
/*-----------------------------------------------------------------
-------------------------------------------------------------------
CLASS
pix_opencv_surf
SURF point detection and tracking
KEYWORDS
pix
DESCRIPTION
-----------------------------------------------------------------*/
class GEM_EXTERN pix_opencv_surf : public GemPixObj
{
CPPEXTERN_HEADER(pix_opencv_surf, GemPixObj)
public:
//////////
// Constructor
pix_opencv_surf();
protected:
//////////
// Destructor
virtual ~pix_opencv_surf();
//////////
// Do the processing
virtual void processRGBAImage(imageStruct &image);
virtual void processRGBImage(imageStruct &image);
virtual void processYUVImage(imageStruct &image);
virtual void processGrayImage(imageStruct &image);
void nightModeMess(float nightmode);
void hessianMess(float hessian);
void markMess(int, t_atom*);
void deleteMess(float index);
void clearMess(void);
void maxMoveMess(float maxmove);
void ftoleranceMess(float ftolerance);
void delaunayMess(t_symbol *s);
void pdelaunayMess(float fpoint, float fthreshold);
int comp_xsize;
int comp_ysize;
t_outlet *m_dataout;
int x_hessian;
int x_criteria;
int night_mode;
int x_maxmove;
int x_markall;
int x_ftolerance;
int x_delaunay;
int x_threshold;
private:
//////////
// Static member functions
static void nightModeMessCallback(void *data, t_floatarg nightmode);
static void hessianMessCallback(void *data, t_floatarg hessian);
static void markMessCallback(void *data, t_symbol* name, int argc, t_atom* argv);
static void deleteMessCallback(void *data, t_floatarg index);
static void clearMessCallback(void *data);
static void maxMoveMessCallback(void *data, t_floatarg maxmove);
static void ftoleranceMessCallback(void *data, t_floatarg ftolerance);
static void delaunayMessCallback(void *data, t_symbol *s);
static void pdelaunayMessCallback(void *data, t_floatarg fpoint, t_floatarg fthreshold);
// Internal Open CV data
IplImage *orgb, *rgba, *rgb, *gray, *ogray;
t_atom x_list[3];
int x_xmark[MAX_MARKERS];
int x_ymark[MAX_MARKERS];
float x_rdesc[MAX_MARKERS][DSCSIZE];
int x_found[MAX_MARKERS];
// internal OpenCV structures
CvSeq *objectKeypoints, *objectDescriptors;
CvFont font;
// structures needed for the delaunay
CvRect x_fullrect;
CvMemStorage* x_storage;
CvSubdiv2D* x_subdiv;
};
#endif // for header file
| 2023-11-09T23:14:03.371983 | https://example.com/article/6386 |
A case of GM1-gangliosidosis type I: glycosphingolipid profiles of urine and transformed lymphocytes and beta-D-galactosidase activities in peripheral lymphocytes, cultured skin fibroblasts and transformed lymphocytes.
A female infant with early-onset GM1-gangliosidosis type I was investigated. The lymphocytes, transformed lymphocytes and cultured skin fibroblasts of the patient were demonstrated to have severe beta-D-galactosidase deficiency. The beta-D-galactosidase activities of these cells from the patient's father and mother were at the lower limit of the normal range. The oligosaccharide accumulation in urine of the patient showed the typical type I GM1-gangliosidosis pattern, but no GM1 ganglioside was detected in the patient's urine or transformed lymphocytes. The clinical features were compatible with infantile GM1-gangliosidosis. The mixture of homogenates from the cultured fibroblasts or transformed lymphocytes of the patient and controls showed no complementation of beta-D-galactosidase activity against the controls. | 2023-11-01T23:14:03.371983 | https://example.com/article/2752 |
I don’t want to masquerade as an all-wise mother and grandma. No mother of 4 daughters ever masters sibling rivalry. In the last 3 years, since 3 daughers became mothers, I feel like I am back in adolescence and all the rules have changed.
My daughters find my journals hysterically funny.
Fall 176–Emma is 3 1/2; Michelle is 17 months
When Emma came home from nursery school, she wanted me to read Green Eggs and Ham. She settled on my lap in the small black chair, and I began to read. Michelle immediately came over protesting, tried to climb into the chair. I assumed she wanted to listen to the story, so I asked Emma to move to the couch, so we all could fit. But then Michelle started grabbing the book, bringing me her books to read.
I discouraged her, feeling she had had my exclusive attention for 4 hours; now it was Emma’s turn. My friend Terry offered to read to Michelle, but she struggled down from her lap 2 or 3 times. I finished reading Green Eggs and Ham. Terry started to read to Emma and Erin, so I could read to Michelle. Michelle got down from my lap and tried to grab the book away from Terry. When that failed, she tried bribery–3 books, her blanket, a slip, her rabbit skin. Erin wanted the rabbit skin, but every time she took it away from Michelle, she protested and only stopped when Terry took it back from Erin.
Finally Michelle used one of the cardboard blocks to climb on the ottoman; from there she lunged for the big black chair where Terry was sitting with Emma and Erin. She didn’t quite make it and had to be rescued, but she had achieved her purpose–the reading stopped. I’ve noticed that she often starts fussing if someone picks up Emma, reads to her, pays her exclusive attention in any way, shape, or form
I’m glad to see such self-assertion on her part, even though I feel pulled in two directions now with both of them clamoring for exclusive attention. It frees me from being Michelle’s defender. More and more I can let them learn to handle their disputes by themselves. I know Emma’s worst won’t really hurt Michelle, and Michelle’s protests more than enough to warn me if any mayhem is actually occurring. Once or twice lately I’ve rushed in ready to scold Emma, when Michelle’s protests had absolutely nothing to do with her. Emma’s being away at school mornings seems to have encouraged Michelle to increase her demands. If she could get rid of Anne in the mornings, why not all day?
After describing this revealing incident, I earnestly tried to establish rules for myself . As the oldest of six, I probably overidentified with Emma. I read this to her recently, when her son was Michelle’s age, and we collapsed in helpless laughter. How earnest and intellectual I was trying to be, pretending I could objectively stay above the fray. Some of my advice is excellent; too bad I wasn’t able to follow it. I had obviously read too many parenting books and taken too many contradictory parenting classes.
When in doubt about what to do, don’t interfere.
If I am concerned that one of them could really get hurt, always intervene. In practical terms, that means always being within interfering distance when they are both playing on the slide, on the climbing structure, or on the terrace.
When other people are around who would tend to think very badly of Emma if she made Michelle cry, intervene.
Protect Emma from Michelle. She should have time alone in her room to paint, to build with blocks, when Michelle is not constantly at her back, intent to destroy what she has just made. When Emma complains that Michelle is bothering her, respond and help her out. It is completely unreasonable to expect Emma to handle Michelle’s interference by herself. I find it hard enough to distract single-minded Michelle.
Encourage Anne to find solutions to the problem herself. “I’m sorry Michelle keeps knocking down your blocks. Do you have any idea how we can stop her from doing it.” Poor Anne. No wonder, she told me, a few years later, “Don’t give me any of that active listening crap.”
Try to spend one hour special time with Anne after dinner. Now that she will be away from me three hours a day in nursery school, this is particularly important.
Make a firm rule about no hitting with things. The thing used as a weapon gets put in the closet until the next day. “Blocks are for building, not for hitting Michelle. You can have it back tomorrow.”
When I find it necessary to intervene, use actions not words. No screaming, no getting angry. Separate them physically. Then, and only then, try to help Anne. “I think you are trying to say something to Michelle. Talk it. You can talk; you don’t have to hit. I know how you feel, but I can’t let you hurt Michelle. It makes her feel like hitting you.”
When one of them is likely to continue hurting, use physical restraint. Take her to another room to calm down, telling her she can come back when she can play without hurting.
Don’t get angry. If I can’t intervene without getting angry, don’t bother. Michelle is not a helpless baby, and she is not always an innocent victim. Don’t always assume I saw the curtain-raiser to this particular squabble.
In my defense, my daughters are all very close to one another and form a wonderful support system.
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About maryjograves
Children are my passion. I have 4 daughters, 5 grandkids under 5 with another on the way, 5 younger brothers, 11 nieces and nephews, 8 great nieces and nephews. I advocate a revolution for a child friendly US. I have been an editor, public librarian, social worker, and internet educator. Tweet @RedstockingGran @ChildrensWings | 2024-05-08T23:14:03.371983 | https://example.com/article/6845 |
Barberini, the name of a powerful Italian family, originally of Tuscan extraction, who settled in Florence during the early part of the 11th century. They acquired great wealth and influence, and in 1623 Maffeo Barberini was raised to the papal throne as Urban VIII. He made his brother, Antonio, a distinguished soldier, and two nephews, cardinals, and gave to a third nephew, Taddeo, the principality of Palestrina. Great jealousy of their increasing power was excited amongst the neighbouring princes, and Odoardo Farnese, duke of Parma, made war upon Taddeo, and defeated the papal troops. After the death of Urban in 1644 his successor, Innocent X., showed hostility to the Barberini family. Taddeo fled to Paris, where he died in 1647, and with him the family became extinct in the male line. His daughter Cornelia married Prince Giulio Cesare Colonna di Sciarra in 1728, who added her name to his own. On the death of Prince Enrico Barberini-Colonna the name went to his daughter and heiress Donna Maria and her husband Marquis Luigi Sacchetti, who received the title of prince of Palestrina and permission to bear the name of Barberini. The fine Barberini palace and library in Rome give evidence of their wealth and magnificence. The ruthless way in which they plundered ancient buildings to adorn their own palaces is the origin of the saying, “Quod non fecerunt barbari, fecerunt Barberini.” | 2024-03-26T23:14:03.371983 | https://example.com/article/6957 |
Real Spanish Sangria madria sangria offers a flavorful blend of ruby-red wine and hints of orange, lemon, and lime. true to the traditional spanish style, this sangria has just the right amount of sweetness and refreshment it pairs perfectly with family & friends, laughter and delicious meal.
Kids
Cheese Quesadilla served with taco sauce and sour cream on side. the following meals include one of the following sides: white rice, yellow rice, black beans, refried beans, french fries, sliced tomato or plantains. | 2024-04-18T23:14:03.371983 | https://example.com/article/9806 |
LOS GATOS, Calif. (KGO) -- Caltrans hopes to open a 220-foot section of Highway 35 in the Santa Cruz Mountains above Los Gatos by mid-January after it was wiped out by a mudslide during last February's fierce storms.The project was "super fast tracked," meaning that Caltrans engineers were planning and designing repairs at the same time that crews from Disney Construction were already working on the project.The $10 million project was deemed an emergency repair, and by accelerating the project, the work will be completed about a year sooner than if work waited until competitive bids and all design work were done.The repair work was documented by time-lapse video over the past 10 months taken by two cameras mounted over the destroyed road, which shows the complexity and scale of the work undertaken by as many as 60 contractors and subcontractors at its peak.The contractor had special challenges it had to surmount. Among them, using lightweight cellular concrete instead of traditional compacted soil and rock to fill breaches behind massive retaining walls, caused by the massive mudslide. Support beams for the retaining walls were drilled on average about 30 feet into bedrock to prevent future failures.Close to 200 trees were lost as the slide took out the roadway. Replacement trees will be planted.Sky7 flew twice over the site last February and March, providing some perspective on how much damage was done and how much progress has been made. | 2023-11-11T23:14:03.371983 | https://example.com/article/4463 |
Q:
How to remove a remote using LibGit2Sharp?
I've checked libgit2sharp v0.15.0 and it seems like there is no method for removing a remote.
Is there any way to do it?
A:
I've checked libgit2sharp v0.15.0 and it seems like there is no method for removing a remote.
That's completely correct. Such a method doesn't exist yet as it's not supported by libgit2 yet.
There's a work in progress (see PR #1199) to implement this. Subscribing to this PR would let you know about it's future progress.
Is there any way to do it?
You can do it by hand this way:
Remove the whole config section that describes the remote to be deleted
Delete from the config every branch (remote, merge) tuple that depends on the remote to be deleted
Delete from .git/refs/remotes/ every remote tracking branch reference
For instance, if you're willing to drop the remote "useless"
Drop this whole section from the config
[remote "useless"]
url = https://github.com/useless/project.git
fetch = +refs/heads/*:refs/remotes/useless/*
Remove remote and merge entries from the two following branches
[branch "vNext"]
remote = useless
merge = refs/heads/vNext
[branch "topic/awesome_feature"]
remote = useless
merge = refs/heads/topic/awesome_feature
Delete the following references
- .git/refs/remotes/useless/vNext
- .git/refs/remotes/useless/topic/awesome_feature
Update
Pull Request #731 just made possible the removal of remotes through the API.
Syntax: repo.Network.Remotes.Remove(remoteName)
| 2024-05-25T23:14:03.371983 | https://example.com/article/4008 |
(TNS) — Bremen, Germany — Researchers will test new robot technology in the Mars-like deserts of Utah, the German Research Centre for Artificial Intelligence (DFKI) announced Wednesday.
"Many situations that could occur in space can be almost perfectly simulated here," Frank Kirchner, head of the Robotics Innovation Centre said.
The objective of the four-week-long field test is to observe how these new systems work in a natural, unstructured landscape that is similar to Mars, the press release said.
RELATED SpaceX Explosion Investigation Draws Political Support
The two robots, Coyote III and SherpaTT, are remote controlled via Bluetooth technology and semi-autonomous, meaning they can act independently to some extent.
Last week, DFKI presented a praying mantis-like robot, named Mantis, that can manoeuvre over rubble and steep craters, while using its forearms to collect samples.
Mantis could also be helpful on Earth during disaster situations, the researchers said.
©2016 Deutsche Presse-Agentur GmbH (Hamburg, Germany) Distributed by Tribune Content Agency, LLC.
Looking for the latest gov tech news as it happens? Subscribe to GT newsletters. | 2024-04-04T23:14:03.371983 | https://example.com/article/3501 |
General Data
Category
Geographical Area
Latitude
Longitude
Telephone
Useful Numbers
Harbour services 0187 960315. To have or book a mooring place please contact boatswain Riccardo at the following phone number: +39 327 3704050
Features
Minimum Draught
1 m
Maximum Draught
3 m
Sea Bottoms
sand an mud
Boat Posts
1300
Port Entrance Times
24 h/24
Max Boat Length
15 m
Near Anchorages
Porto Venere and La Spezia
Bans
Mooring is not allowed at the areas reserved for fishing boats and at the piers of
“Navigazione Golfo dei Poeti” and “Intur” societies. Moreover, boats can't stop and drop the anchor in the channels reserved for free transiting and near the fixed crane.
Dock Services
Fuel
Water
Energy
Slide
Slipway
Crane
Travel Lift
Toilets
Showers
Fire Services
Engine Reparations
Electric Reparations
Weather Forecast Service
Anchorage Staff
Security Staff
Scuba Divers
Description
Located in the easternmost shore in the Gulf of La Spezia, opposite Porto Venere, Tino and Plamaria islands and near the eastuary of river Magra, Lerici is one among the most beautiful towns of Liguria.
It has preserved its original medieval structure. Thanks to its bay, well-sheltered against libeccio and sirocco, and its proximity to Francigena road, it became a very important maritime and commercial junction over the centuries.
Lerici has always been a reference harbour for pilgrims travelling to Rome or even St. James of Compostela. The harbour has always hosted cargo, passenger and military ships.
What is striking in the landscape around Lerici and its harbour is certainly the castle which overlooks the harbour and the bay, once a point of contention between Genoa and Pisa.
The harbour itself extends from the castle through a 250-metre-long dock, two piers and a quay. Today, its hosts many fishing and recreational boats, most of which are stationary.
Moreover, there are some areas reserved for transiting boats, equipped with water and electricty and managed by Erix Sailing Club. These areas can receive both motor and sailing boats up to 12 m. Some mooring places are also available (only for sailing boats) at the piers owned by the Club and the buoys. The club provides guests with toilets, showers, Wi-Fi and even a terrace.
The dock is equipped with a coffee bar, a gas station and a scuba diving centre.
The town of Lerici, of course, offers all you need: having a walk along the dock at the sunset and tasting the typical Ligurian delicacies at one of the many restaurants existing here is with no doubt a unique and unforgettable experience.
Together with La Spezia and Porto Venere, Lerici faces the famous and wonderful Gulf of Poets. Together with the not far San Terenzo, these towns have hosted stars like Lord Byron and Mary Shelley over the years. Another interesting village in the surroundings is Tellaro, a typical coastal village, considered one among the most beautiful seaside villages of Italy. | 2023-10-20T23:14:03.371983 | https://example.com/article/2456 |
Q:
How to initialize Type of Record and overcome ORA-06530: Reference to uninitialized composite error
I want to initialize the values into the RECORD TYPE. Below is my code.
I am facing "ORA-06530: Reference to uninitialized composite error" at runtime. The code compiles fine.
CREATE OR REPLACE TYPE TY_PERSONAL_MASTER AS OBJECT
(
ID NUMBER(20),
FNAME VARCHAR2(30),
LNAME VARCHAR2(30)
);
CREATE OR REPLACE TYPE TY_PROF_MASTERS IS TABLE OF TY_PROF_MASTER;
CREATE OR REPLACE TYPE TY_PROF_MASTER AS OBJECT
(
ID NUMBER(20),
EMPLOYER VARCHAR2(20),
DOJ DATE
);
CREATE TABLE TABLE_HOBBIES
(
ID NUMBER(20),
HNAME VARCHAR2(20)
);
CREATE OR REPLACE PACKAGE INITIALIZE IS
TYPE PERSON IS RECORD(
PERSONAL TY_PERSONAL_MASTER,
PROFESSIONAL TY_PROF_MASTERS,
v_hobbies TABLE_HOBBIES%ROWTYE
)
END INITIALIZE;
CREATE OR REPLACE PACKAGE BODY INITIALIZE IS
FUNCTION FN_INITIALIZE(P_ACTION IN VARCHAR2) RETURN BOOLEAN IS
L_TO_INITIALIZE PERSON;
BEGIN
L_TO_INITIALIZE.PERSONAL.ID := 1;
-- The above line throws "ORA-06530: Reference to uninitialized composite error" at runtime.
-- I have just given example of assigning 1 value. However, I want to initialize all the values.
END FN_INITIALIZE;
END INITIALIZE;
A:
They are different types so you have to handle them differently:
CREATE OR REPLACE PACKAGE BODY INITIALIZE IS
FUNCTION FN_INITIALIZE(P_ACTION IN VARCHAR2) RETURN BOOLEAN IS
L_TO_INITIALIZE PERSON;
BEGIN
-- object so need to call constructor
L_TO_INITIALIZE.PERSONAL := TY_PERSONAL_MASTER(1, 'Bob', 'Hope');
-- can also assign values directly once created
L_TO_INITIALIZE.PERSONAL.ID := 1;
L_TO_INITIALIZE.PERSONAL.FNAME := 'Bob';
L_TO_INITIALIZE.PERSONAL.LNAME := 'Hope';
-- table type so need to call constructor
L_TO_INITIALIZE.PROFESSIONAL := new TY_PROF_MASTERS();
-- need to extend to make room for new entry
L_TO_INITIALIZE.PROFESSIONAL.extend(1);
-- object so need to call constructor
L_TO_INITIALIZE.PROFESSIONAL(1) := new TY_PROF_MASTER(2, 'USO', date '1941-05-06');
-- can also assign values directly once created
L_TO_INITIALIZE.PROFESSIONAL(1).DOJ := date '1941-03-01';
-- record so no constructor, just assign values
L_TO_INITIALIZE.v_hobbies.ID := 3;
L_TO_INITIALIZE.v_hobbies.HNAME := 'Fishing';
RETURN TRUE;
END FN_INITIALIZE;
END INITIALIZE;
/
| 2024-01-05T23:14:03.371983 | https://example.com/article/4877 |
Program Requirements
Each program requires official transcripts from each college and university attended. Transcripts from your undergraduate institution showing degree conferred are required. If you were an undergraduate student at Radford University, the Graduate Admissions Office will request your transcript. A minimum undergraduate grade point average of 2.75 is required; however some programs have more stringent requirements noted below. Official test scores are required for most programs (see specific program below).
In addition to a completed online Radford University Graduate application, $50 non-refundable application fee, and a transcript from all institutions attended, the following supplemental application materials are required for each program:
Application Deadline: Priority admission - materials due Feb. 15 for Summer and Fall admission. Space-available admission - materials due by April 15 for Summer and Fall admission. If there continues to be space available after the April 15 deadline, we will continue to accept applicants until the program is full.
A letter of interest/personal statement describing the applicant’s professional and/or research experience, outlining the person’s career goals, and reasons for pursuing doctoral study
Curriculum vita
An essay that addresses the applicant’s cultural background and experiences and the applicant’s thoughts regarding the etiology of client distress and the nature of the change process (limited to five pages)
Three reference forms AND the accompanying letters of recommendation, including at least one from a professor who can comment on the applicant’s academic skills and ability to pursue doctoral-level training and one from a supervisor who can speak to the applicant’s counseling skills and response to supervision.
Compensatory application materials or interview required to assess applicants who do not meet all entrance requirements
Applications are accepted on a rolling admission basis. For individuals who are seeking initial teacher licensure, admission to Teacher Education Program is required prior to field experiences, including passing scores on required teacher exams.
History and theory before the end of the first semester and prior to admission as regular status
Applications are accepted on a rolling admission basis. All students entering the M.A. (Music) program, which requires at least two hours of graduate level applied study, must also present an entrance audition in their applied performance area for placement purposes. Students entering the M.S. in Music Therapy without a bachelor's degree from an NASM member institution must also present an entrance audition in their undergraduate major and minor performing areas for diagnostic purposes.
Minimum undergraduate grade point average (GPA) of 3.25 on a 4.0 scale.
Official GRE score (please see the program website for preferred and minimum GRE scores – also, please use ETS code 0373 when submitting scores to RU).
Minimum cumulative GPA of 3.0 in prerequisite undergraduate Anatomy and Physiology, General Biology I and II with labs, Chemistry I and II with labs, Physics I and II with labs and Statistics/Biostatistics courses.
Other coursework in Abnormal Psychology, Biochemistry, Biomechanics, Kinesiology, Public Speaking and Technical Writing recommended but not required.
One academic/ educational reference, one professional reference from a licensed physical therapist, AND one from another source.
Minimum cumulative grade point average of 2.75 and minimum grade point average of 3.0 in all undergraduate social work courses (for Advanced Standing applicants), or in the last 60 hours of upper division coursework (for Standard applicants)
Three letters of recommendation (at least one from a professor who can speak to academic potential, and one from a supervisor in human services who can speak to practice skills, (applicants for Advanced Standing are encouraged to provide a reference from their senior field instructor)
Previous experience in the field of human services as an employee, student and/or volunteer
Personal essay
Case study
Legal/military history form
Resume
The deadline for submission of application materials for all Advanced Standing applicants is Jan. 31. For fullest consideration, applicants should submit Fall Standard applications for the MSW program by March 1. All materials must be submitted before an application can be reviewed. Additional application documentscan be found here.
Minimum undergraduate grade point average of 2.75 and 3.0 graduate grade point average if applicable
Three letters of professional recommendation, one letter must be from your current supervisor if you are teaching or in a field placement
Letter of application
Resume
Compensatory application materials and interview required to assess applicants who do not meet all entrance requirements
Applications are accepted on a rolling admission basis, but applications must be received Nov. 1, April 1 and July 1 for the following term. For those seeking initial teacher licensure, admission to Teacher Education Program is required prior to field experiences, including passing scores on VCLA and Praxis I (and RVE for certain programs).
B.F.A in studio art or a B.A. in art or graphic design or commensurate collegiate course work including at least 18 credit hours in upper level studios and 12 credit hours in art history
CD or electronic portfolio with 20 recent art works
Resume
Application deadline: Priority admission - materials due April 1 for Fall admission. Materials due Nov. 1 for Spring admission. If there continues to be space available after these deadlines, we will continue to review applications until the program is full. | 2024-03-17T23:14:03.371983 | https://example.com/article/1282 |
T=d li cd
V=a
R=-15,15,2
F=(-a)+5
C=(-a)+5
| 2024-07-08T23:14:03.371983 | https://example.com/article/5349 |
33 F.3d 1379
In re Stokes (Phillip)*
NO. 94-60361
United States Court of Appeals,Fifth Circuit.
Aug 15, 1994
1
Appeal From: S.D.Miss.
2
AFFIRMED.
*
Fed.R.App.P. 34(a); 5th Cir.R. 34.2
| 2023-09-30T23:14:03.371983 | https://example.com/article/6413 |
The invention relates to a self-tapping screw.
This type of self-tapping screw is screwed into a predrilled drill hole in the substrate using a suitable tool such as, for example, a screwdriver, drill hammer, screw-wench or the like, wherein the start of the thread of the screw grooves a mating thread into the substrate that corresponds to the thread. The subsequent thread of the screw engages in the mating thread, whereby when a load is applied to the screw, it transmits the load to the substrate. In a soft substrate such as, for example, porous concrete or plasterboard, self-tapping screws can also be screwed in directly without predrilling a drill hole in the soft substrate.
An essential advantage of self-tapping screws is the possibility of unscrewing them from the substrate without parts of the fastening that was created remaining in the substrate. Self-tapping concrete screws, which are driven into mineral substrates, are also used in practice by users for temporary fastenings, for example, in concrete form work, building scaffolding or when configuring drilling and cutting tools in diamond drilling and separating technology. As a result, the self-tapping screws are not only removable, but are also reusable in principle.
Known from European Patent Document No. EP 1 862 677 A1 is a self-tapping screw with a shaft, which has a first end and an opposing second end with a load-engaging means, and with a thread, which extends at least in sections over the length of the shaft, wherein at least one wear indicator means is provided on the thread.
The at least one wear indicator means of the known screw indicates the rate of wear of the thread and thereby allows a conclusion to be drawn about the load capacity or load bearing property of a removed self-tapping screw and about its ability to be reused.
When manufacturing the screw as well as during its use, parts of the thread can break out, which the user might inadvertently interpret as wear indicator means. This could lead to a misinterpretation with respect to the reusability of the screw.
The object of the invention is creating a self-tapping screw, in particular a concrete screw, which can be used several times and in which a simple assessment of usability is possible.
According to the invention, at least one identifier is provided on the screw for identifying the wear indicator.
The at least one identifier guarantees a clear identification of the at least one wear indicator. Because of the identifier provided on the screw, it is no longer possible for any undesired breakouts in the thread or damage to the thread to be inadvertently interpreted as a wear indicator. As a result, even with repeated use of a self-tapping screw that has wear indicators, a reliable assessment by the user with respect to its reusability is guaranteed.
The at least one identifier is preferably provided on a thread flank of the thread and preferably directly adjacent to the wear indicator to be identified by this identifier. The at least one identifier is advantageously configured directly during the forming of the thread on the thread.
The at least one identifier is preferably provided on an outer side of the shaft and advantageously directly adjacent to the wear indicator to be identified by this identifier. The at least one identifier is advantageously configured directly during the forming of the shaft on the shaft.
Several identifiers may be provided on a self-tapping screw, each of which is arranged on the thread flanks of the thread and/or on the outer side of the shaft.
The at least one identifier is preferably a depression provided on the screw, which can be configured in a simple manner during manufacturing of the self-tapping screw, e.g., in a rolling method, on the screw.
The at least one identifier is preferably an elevation provided on the screw, which can be configured in a simple manner during manufacturing of the self-tapping screw, e.g., in a rolling method, on the screw.
Several identifiers may be provided on a self-tapping screw, which are configured as depressions and/or as elevations. In addition, the at least one identifier may also be a profiling, which features only depressions, only elevations, or depressions and elevations.
At least two identifiers are preferably provided for identifying a wear indicator, which make a simple and precise identification of the wear indicator possible.
The at least one identifier preferably has a polygonal design in plan view, whereby the at least one identifier features an advantageous design for identifying the corresponding wear indicator. A corner of the at least one identifier advantageously points in the direction of the to-be-identified wear indicator, thereby further improving the identifiability of the to-be-identified wear indicator. The identifier has an especially advantageous triangular design in plan view.
In an alternative embodiment, the at least one identifier has a round design in plan view, thereby making it possible for the at least one identifier to be configured in a simple way. In addition to a circular design, the at least one identifier may also have an oval design or a design with more than two inflection points.
The invention is explained in greater detail in the following on the basis of exemplary embodiments. | 2023-12-30T23:14:03.371983 | https://example.com/article/3042 |
Child custody and support laws have become more onerous over the last 50 years due to fewer parents staying together and women becoming equally as capable as men at earning a living outside the home. Instead of reflecting these changes, the laws have lagged behind, continuing to favor mothers over fathers. The laws generally award primary custody to the parent who spent more time at home with the children and less time working, even if the difference was miniscule. The other parent is then ordered to pay a crushing amount of child support, sometimes on top of alimony. In a small percentage of situations, usually where the father was the primary caregiver, this situation is reversed and the laws punish the mother.
Fathers have reacted over the years in different ways. Some fathers' rights activists in Britain dress up as super heroes and scale public buildings to draw attention to the inequity. The founder of Fathers 4 Justice, Matt O'Connor, started a hunger strike for equal parenting earlier this month outside the home of British Prime Minister David Cameron. Some fathers tragically commit suicide. Last month, a distraught father immolated himself on the steps of a courthouse in New Hampshire, after mailing a 15-page "last statement" to the local newspaper detailing his final frustrations with the child custody legal system. The most high-profile victim of the child custody system, actor Alec Baldwin, helped bring exposure to the unfairness by writing a book about his experience.
Although a few small changes have been made to the laws within the last few years, due to exposure and the efforts of advocacy organizations, there has not been significant progress. According to the U.S. Census Bureau, 84 percent of custodial parents are mothers, a figure that has not changed since 1983. This is unfortunate, because Canadian economist Paul Miller analyzed data on families and found that "parental gender is not a…predictor at all of any of the child outcomes examined, that is behavioral, educational or health outcomes." The children often end up with "Parental Alienation Syndrome," developing a dislike for the noncustodial parent bought on by the custodial parent. Long term studies of children in the U.S. and New Zealand have found there is a direct correlation between a father's absence and teen pregnancy.
The latest effort to change the system calls for "shared parenting." Although advocacy groups differ on how shared parenting would be implemented, it generally consists of making the default custody arrangement 50/50 joint physical and legal custody when parents split up, absent egregious circumstances. This would replace the current system which leaves it up to a judge's whim to decide what constitutes "the best interests of the child." Shared parenting bills are being introduced in state legislatures around the country, and several states now have some version of shared parenting. In those states, studies are finding that divorce rates are lower and the children are better adjusted.
In addition to passing shared parenting laws, there must be tougher requirements for issuing restraining orders and reform of child support laws. 50/50 shared custody should not include child support unless there are egregious circumstances. Child support creates an incentive to continue fighting. Neither parent wants to get stuck paying it, and some parents greedily want it as a source of income to use as they please, since there is little monitoring of how it is spent. Eliminate child support in all but the most egregious situations, and most of the fighting clogging our family courts will cease.
The "deadbeat dad" roundups by law enforcement of fathers who are behind in child support needs to stop. Many of them are fathers who were not lucky enough to be awarded custody, and are now working two jobs just to try and keep up with expenses and child support. Figures from the Federal Office of Child Support Enforcement show that more than two-thirds of "deadbeat dads" earn poverty-level wages, and only four percent earn $40,000 or more per year. Less than one in 20 noncustodial parents who suffer a drop in income are able to get the court to reduce their child support payments. Grandparents often end up paying the child support.
Laws like the Violence Against Women Act need to be repealed or significantly revised. Every year $1 billion is given to domestic violence organizations, making it very easy for one spouse to complain about the other and have the complaint used against them in child custody disputes. These organizations, which tend to favor women, have now formed their own lobbying organizations that fight against meaningful changes in child custody laws.
David Usher of The Center for Marriage Policy believes the solution lies in renewing the importance of marriage. He proposes eliminating no-fault divorce laws and requiring couples where only one spouse wants a divorce to work out the divorce agreement themselves. This would disincentivize divorce, since couples could no longer simply run to court to end the marriage, but would be forced to work with each other to come up with a custody situation they both agree to. Currently, marriage is about the only kind of contract where one party can unilaterally end the contract. The Center for Marriage Policy recommends shared parenting that would place a child primarily with one parent for the first half of their childhood, then with the second parent for their later years.
The small changes that have been made in recent years are encouraging. Thanks to organizations like Fathers and Families, last year Massachusetts, which has some of the most punishing child support laws in the country, reduced the interest on overdue child support by 50%. Legislation has been passed in several states around the country within the past year protecting disabled and military parents from child custody abuses. As families continue to modernize, and more women also suffer the effects of outdated child custody laws, the laws will be finally forced to keep up. It may just not be in our lifetime. This is a new kind of civil rights struggle, and one day our great-grandchildren will look back and remember their forefathers who fought so hard for their right to have meaningful time with both parents.
Rachel Alexander and her brother Andrew are co-Editors of Intellectual Conservative. Rachel practices law and social media political consulting in Phoenix, Arizona. She has been published in the American Spectator, Townhall.com, Fox News, NewsMax, Accuracy in Media, The Americano, ParcBench, and other publications. | 2023-10-14T23:14:03.371983 | https://example.com/article/8145 |
Drill hole SC-82W intersected another higher grade massive sulphide zone approximately 45 metres updip from a similar intersection reported originally in hole SC-82 (October 29, 2015 press release). As was the case in SC-82, this shallower high grade massive sulphides intercept is located along the potential up-dip extension of the CFO Lens. Another mineralized interval was also obtained along the Gap Lens in hole SC-31W2. These mineralized intervals, as were all intercepts released by the Company since June, are located outside of the mineral resources as currently estimated (see attached Figure 1) at the Scott project.
Assay results are shown below:
DDH SC-82W Section 1900W(weighted averages)
From(m)
To(m)
Length(m)
Cu%
Zn%
Aug/t
Agg/t
Remarks
588.6
593.6
5.0
0.7
12.1
0.2
10.2
massive sulphides (CFO horizon)
including
588.6
589.3
0.7
3.6
22.2
0.6
26.3
massive and stringers sulphides
DDH SC-31W2 Section 1900W(weighted averages)
From(m)
To(m)
Length(m)
Cu%
Zn%
Aug/t
Agg/t
Remarks
853.0
884.0
31.0
1.0
1.4
0.2
28.2
stringers sulphides (Gap Lens)
including
853.0
859.4
6.4
1.8
0.9
0.1
48.7
stringer sulphides
and
876.0
884.0
8.0
1.0
1.7
0.2
32.3
stringer sulphides
As this is still preliminary drilling on the above mineralization, the exact shape and true width cannot be determined with certainty. The core lengths obtained may not reflect the true width of the mineralization.
The high grade massive sulphides (5.0 metres of 12.1% zinc and 0.7% copper) discovered at a depth of 588.6 metres are associated with a distinct mineralized horizon located about 100 metres to the north of the one hosting the newly discovered Gap Lens. These sulphides are associated with a rhyolite unit known as “Tony Rhyolite” and this interval is therefore interpreted as being located along the up-dip extension of the CFO Lens but at much shallower depth than indicated by previous work (see attached Figure 1).
Hole SC-82W did not intersect mineralization along the Gap Lens. Indeed, at the targeted depth volcanic host rocks are cut by barren intrusive rocks associated with the Chibougamau Pluton. This situation is analogous to what happened in hole SC-53W5 (see Figure 1 and press release of October 13, 2015) and reinforces the concept of a steep plunge to the west for the Gap Lens and possibly the West Lens. Hole SC-31W2 is a wedge cut drilled from hole SC-31W (press release of November 30, 2015). The stringer sulphides in SC-31W2 are all hosted by altered rhyolite, as is the case in the West Lens and in previous intersections from the Gap Lens.
Company president Gérald Riverin stated: “We are very encouraged with the high grade results of SC-82W along the CFO horizon. Now with a second cut on this target horizon, we are confident that this shallower high grade zone has some extent and may develop into a significant zone. We are looking forward to pursuing drilling in this sector.”
Drilling will resume shortly with one drill rig and in fact the hole that was in progress just before the winter holiday break had already reached a depth of 900 metres and was close to the target depth.
All drill core discussed in this press release was logged and marked up for assay at the Company’s secure facility in Chibougamau, Quebec. Drill core for assay was split in half. Half of the core was shipped in sample bags to Techni-Lab S.G.B. Abitibi Inc. (ACTLABS) of Ste-Germaine-Boulé, Quebec, with appropriate standards, duplicates and replicates used for quality control purposes. The other half of the core is retained for future reference.
Work is carried out by the personnel of Yorbeau, under the supervision of Gérald Riverin, PhD, P. Geo. He is a qualified person (as defined by National Instrument 43-101) and has reviewed and approved the content of this release.
About Yorbeau Resources Inc.
The Company’s 100% controlled Rouyn Property contains four known gold deposits in the 6-km-long Augmitto-Astoria corridor situated on the western half of the property. Two of the four deposits, Astoria and Augmitto, have substantial underground infrastructure and have been the focus of NI 43-101 technical reports that include resource estimates. The Company has recently expanded its exploration property portfolio by acquiring strategic base metal properties in prospective areas of the Abitibi Belt of Quebec and Ontario that also feature infrastructure favourable for mining development.
Forward-looking statements: Except for statement of historical fact, all statements in this news release, without limitation, regarding new projects, acquisitions, future plans and objectives are forward-looking statements which involve risks and uncertainties. There can be no assurance that such statements will prove to be accurate; actual results and future events could differ materially from those anticipated in such statements. | 2023-10-22T23:14:03.371983 | https://example.com/article/3314 |
Levels of plasma lipid peroxides before and after choledocholithotomy in patients with obstructive jaundice.
Plasma lipid peroxide levels were measured in a group of 40 healthy controls and 11 patients with jaundice. In the case of these 11 patients, we checked the plasma lipid peroxide concentrations prior to and after choledocholithotomy. Before choledocholithotomy, there were significantly higher mean concentrations of plasma lipid peroxides and bilirubin in patients with jaundice than in the control cases (11.8 +/- 2.3 vs. 2.0 +/- 0.1 nmol/ml and 10.3 +/- 1.82 vs. 0.7 +/- 0.03 mg/dl, respectively, P < 0.05). In addition, patients with jaundice had lower plasma vitamin E levels in comparison to the controls (8.2 +/- 0.6 vs. 12.2 +/- 0.5 micrograms/ml, P < 0.05). In patients with jaundice, the increased plasma lipid peroxides were clearly related to the serum levels of bilirubin (r = 0.87, P < 0.05). After surgery, the higher plasma levels of lipid peroxide and bilirubin were reduced markedly (11.8 +/- 2.3 vs. 3.7 +/- 0.4 nmol/ml and 10.3 +/- 1.82 vs. 3.1 +/- 0.47 mg/dl, respectively, P < 0.05) with the restoration of bile flow which was associated with improvement in liver function tests. Consequently, these results suggest that there is an involvement of lipid peroxidation in liver cells damaged by obstructive jaundice in patients with cholelithiasis, and that these high plasma lipid peroxide levels may correlate with the severity of the disease. | 2024-02-29T23:14:03.371983 | https://example.com/article/7944 |
Serotonergic mediation of tetrahydro-beta-carboline.
Rats were trained to discriminate between the stimulus properties of tetrahydro-beta-carboline (THBC) and its vehicle in a two-lever, food-motivated operant task. By steadily increasing the training dose, the discrimination was attained at 20.0 mg/kg THBC. Dose-response experiments subsequently indicated that decreasing doses of THBC produced decreased discrimination and generated an ED50 = 3.63 mg/kg. Administration of the serotonergically-active drug, fenfluramine, produced THBC-appropriate responding in a dose-responsive manner. In addition, LSD and yohimbine produced partial generalizations in the THBC-trained rats. These data suggest that the discriminative stimulus properties of THBC are mediated by serotonergic neurons in the central nervous system. | 2024-02-02T23:14:03.371983 | https://example.com/article/2273 |
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One of the much-loved classics of all-time and a masterpiece from award winning film maker Steven Spielberg, E.T. - The Extra Terrestrial is released for the first time ever in stunning high definition Blu-ray.
To celebrate the 30th Anniversary of this much loved classic, the picture and sound have been fully restored to give a stunning Blu-ray special edition. Loaded with all-new special features E.T. - The Extra Terrestrial is a must-own for all fans of high definition to give an out of this world experience.
A lost alien, three million light years away from home. A lonely ten-year old boy willing to take him home. Two lives changed by a timeless adventure and a friendship that knows no earthly bounds.
Winner of four Oscars and two Golden Globes, including Best Motion Picture, ET is funny, moving and unforgettable.
A captivating classic that will embrace everyone with its magic touch.
5'E.T. ''PHONE HOME''
one of the most delightful and charming family movies ever brought to screen, and surely one of the top movies on your wish-list transferred on to blu-ray.the story tells of the meeting up and subsequent friendship between 'elliot' a lonely 10 year old and lost alien E.T'elliot' trys to keep his new friend secret, however the authorities get wind of the find and seek to exploit the 'alien''E.T. is getting weaker by the day, ' elliot' with friends 'gertie' and 'micheal' aim to aim to rescue the little fellah and help him find a way home.a must own family movie..............enjoy.
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People don't want to open Portage and Main to pedestrians because they have no idea what it will look like, urban planners say after a new poll suggested declining support for yanking barriers from the iconic intersection.
Michelle Richard, a former planner with the City of Winnipeg, says no vision or drawings have been presented to show the benefits of a pedestrian-friendly intersection — so people have drawn their own conclusions ahead of next month's plebiscite.
"People will inevitably kind of fall to the perspective that they feel sort of speaks to their concerns — and for most Winnipeggers, it's a traffic concern."
The proportion of people who favour opening Portage and Main to pedestrians is at its lowest mark in the 20 years Probe Research has tracked this topic, suggests the poll, which was commissioned by CBC Manitoba.
The top concern driving opposition is the fear of traffic gridlock.
Support for opening the intersection rose slowly, peaking at 42 per cent in 2016, but it has since slipped precipitously, with only 33 per cent of Winnipeggers who responded to the late August poll saying they want to reopen the intersection. The poll of 600 Winnipeg adults was weighted to reflect the city's age and gender demographics and has a margin of error of plus or minus four per cent.
Even among young adults and people who live, work or play downtown, the majority of poll respondents don't want people walking across Portage and Main.
The poll suggests 42 per cent of Winnipeggers aged 18-34 and 48 per cent of those who frequently spend time downtown want the intersection reopened.
And they're unlikely to budge from their stance. Seventy-six per cent of respondents said either there's no chance or it's unlikely they will change their minds.
"There is a broad and deep intense dislike for this idea," said Mary Agnes Welch, a senior researcher at Probe Research.
She believes the abrupt drop is linked to the recent focus on opening Portage and Main. The concept has become real to Winnipeggers for perhaps the first time since it was closed to pedestrians in 1979 in order to shoehorn people toward the shops downstairs.
'Lost' in the conversation
Richard, now a planning consultant with Richard Wintrup and Associates, said the declining support conflicts with the walkable neighbourhoods where we crave to live and the areas we seek out as tourists.
Portage and Main should be a similar haven, she argued.
"Something's been lost here," she said.
"The focus of opening an intersection is, from my perspective, not the right focus. It's about how do we create the heart of Winnipeg in this place," she said. "Walking, and the opening of the intersection, is just one part of that whole vision that really should have been explored over the last four years."
In 2014, Brian Bowman was elected mayor after a campaign during which he promised to reopen the intersection. Negotiations with the property owners at the intersection's corners lasted until early 2017, traffic study findings were revealed later that year, and the cost was pegged at $6 million with $5.5 million more to bolster Winnipeg Transit's fleet to accommodate rush-hour delays.
A request for designs for the revitalized intersection, made earlier this year, has been shelved until after the plebiscite determines whether the majority of the public is even interested.
While all this was going on, no one explained to Winnipeggers how an opened intersection could influence the city's economic, social and environmental well-being for the better, Richard said.
Time-lapse video shot from the roof of the Fairmont Hotel shows late-afternoon traffic at Winnipeg's most famous intersection. 0:39
"Nobody's gone through a process to explore and let people kind of have the opportunity to be brought along with an alternative vision," said Richard, who questions why the city never introduced a public awareness campaign.
"Maybe moving forward, it has to be there. I don't know how you recover from the numbers [in this poll]."
She said the survey's findings do not go against the city's efforts to promote active transportation, such as more bike lanes. Protected routes for cyclists, for example, can be seen and understood by people, Richard said.
"With Portage and Main, it's something a little less tangible."
People have been barred from crossing Portage and Main on foot since 1979, when property owners agreed to shoehorn pedestrians into the underground concourse and toward its businesses. (Lyzaville Sale/CBC)
Richard Milgrom, head of the University of Manitoba's department of city planning, understands the resistance to a barrier-free intersection.
There has to be some kind of concept for voters to consider, he said.
"People don't know what they're voting to have."
Too many haven't considered that the intersection would have to be remodelled, he said. There would likely be barrier changes, a redeveloped median and a concerted effort to make Portage and Main a place where people want to linger, he said.
"What most people want is what they know, and what people know is 'I like to drive my car through Portage and Main.'"
The survey suggests 28 per cent of people consider traffic flow the top reason to keep the intersection closed to pedestrians. Other arguments, in order of preference, are the cost, safety of pedestrians and the view the investment will not improve the downtown.
This debate hangs on traffic, Welch said.
"That is sort of the litmus test on this question — do you think cars should be king or do you think pedestrians should be king? And we are profoundly divided on that issue."
Cars take precedence
Hazel Borys, a Winnipeg-based urban planner, believes Portage and Main will always be the realm of cars, but it can and should exist for more modes of transportation.
"We don't think of it as a people place, we think of it as a car place, but it can really be both, and it can be both really gracefully."
The survey suggests 66 per cent of people agree with the statement that "smooth traffic through the downtown is more important than pedestrian access."
Sixty per cent of respondents don't enjoy spending time downtown, while 33 per cent believe it's important for visitors and tourists to cross the intersection on foot.
Many other intersections in downtown Winnipeg have similar traffic counts, yet there are no complaints about permitting vehicle and pedestrians at those corners, Borys said.
"So much about this is just our perception. What does it mean to be a car city and what does it mean to also open ourselves to other ways of getting around?"
In line with the city's swelling population, increasingly more vehicles are on Winnipeg roads. As of Sept. 1, 381,279 passenger vehicles were registered in Winnipeg, a total that has increased annually for at least the last decade, Manitoba Public Insurance said.
Milgrom believes the city's car culture is firmly entrenched in part because some people have no choice but to drive.
"It doesn't work to say people shouldn't be driving cars everywhere. There has to be some good viable alternatives to it," he said.
"Right now we have an underfunded transit system. We have pedestrian environments that generally aren't very good."
People cross Main Street at Portage Avenue in February 1979, seven months before the underground pedestrian concourse opened. (Winnipeg Archives)
The 2016 census results say 69 per cent of the city's commuters (216,675 citizens) are driving their vehicles to work and nine per cent of people (28,065) are passengers, with the latter a rising figure.
Transit ridership fell 1.1 per cent from the 2011 census to 42,375 riders in 2016, and walking to work remained fairly steady at nearly 19,000 Winnipeggers, or six per cent of commuters.
Convincing more drivers to turn over their keys will take time, Milgrom said. City planning cannot be overhauled in a night, and urban sprawl nearly stipulates a driver's licence for many.
On an average weekday, 81,000 vehicles pass through Portage and Main, the City of Winnipeg says. (Gary Solilak/CBC)
"We need some people who will stand up and do the right thing. If we make every single decision based on some sort of referendum, it's going to be very hard."
Outside Winnipeg's downtown, nearly four in five denizens balk at opening the intersection.
Frank Capasso, president of the Sage Creek Residents Association, said he understands where his neighbours are coming from, even though he's in the minority who support opening the intersection.
"To get downtown, unless you have a car, it's difficult to get to from where I live," Capasso said.
Suburbs like his are growing, and his neighbours rarely feel compelled to go downtown. They pass through the centre of the city to go elsewhere.
Frank Sherlock, executive vice-president of property management at Artis REIT, wants a strategy for reopening the intersection to pedestrians that goes beyond a paint job and new lighting. (Marcy Makusa/CBC)
"We don't go enough downtown so people don't want it open."
Frank Sherlock has a big stake in the future of the intersection. He's executive vice-president of property management at Artis REIT, which owns 1.5 million square feet of property around the intersection, including the Shops at Winnipeg Square.
He supports making the corner pedestrian-friendly, but he wants meaningful development and investment along with it. Painting lines on pavement and installing street lighting is not enough.
"If it's just opening the intersection, making it look like any other intersection and doing nothing else, I think it will be a flop."
The referendum is non-binding, but Bowman and Jenny Motkaluk, the most high-profile candidates for mayor, have promised to do what the majority wants.
With files from Bartley Kives, Marcy Markusa | 2024-07-07T23:14:03.371983 | https://example.com/article/9478 |
208*v**2 + 12*v - 217*v**2. Let s(x) = x**2 - x - 3. Let w(z) = -2*l(z) - 14*s(z). Suppose w(c) = 0. Calculate c.
0, 5/2
Suppose -198*b + 1405 + 10*b**2 + 1230 - 2227 - 13*b**2 = 0. What is b?
-68, 2
Let x(h) be the second derivative of h**4/4 - 15*h**3 + 627*h**2/2 + 2492*h. Determine g, given that x(g) = 0.
11, 19
Let d be 1 + (-3)/3 + 6/3. Factor 321 + 1407 + 58*y**2 - 55*y**d + 144*y.
3*(y + 24)**2
Let y = -8261/145 + -1474/29. Let x = 108 + y. Factor -x*n**2 + 0*n + 0.
-n**2/5
Let u(f) be the second derivative of f**5/330 - 37*f**4/33 + 5476*f**3/33 + 59*f**2 + 241*f. Let w(p) be the first derivative of u(p). Factor w(h).
2*(h - 74)**2/11
Let d(r) be the first derivative of 0*r**2 + 2/3*r**4 - 14*r - 1/3*r**3 - 5/12*r**6 + 13 - 1/8*r**5. Let q(l) be the first derivative of d(l). Factor q(y).
-y*(y + 1)*(5*y - 2)**2/2
Let g(c) be the third derivative of c**7/70 + 311*c**6/40 + 6006*c**5/5 - 3042*c**4 - 12*c**2 + 5*c. Factor g(a).
3*a*(a - 1)*(a + 156)**2
Let u(a) be the first derivative of 3*a**4/2 + 13*a**3 + 12*a**2 - 144*a - 2098. Factor u(k).
3*(k + 4)**2*(2*k - 3)
Let d(f) be the third derivative of 3*f**7/280 - 133*f**6/480 - 29*f**5/40 - f**4/3 + 111*f**2 + 2. Factor d(v).
v*(v - 16)*(v + 1)*(9*v + 2)/4
Factor 468*m - 1952*m**2 + 1020 + 7*m**3 + 3862*m**2 - 10*m**3 - 1937*m**2.
-3*(m - 10)*(m + 2)*(m + 17)
Let f(k) be the first derivative of k**4/8 - 65*k**3/6 + 127*k**2/4 - 63*k/2 + 905. Factor f(l).
(l - 63)*(l - 1)**2/2
Let g(c) = 4*c**3 - 3132*c**2 + 3123*c - 20. Let d(t) = -2*t**3 + 1566*t**2 - 1562*t + 8. Let n(l) = 5*d(l) + 2*g(l). Factor n(s).
-2*s*(s - 782)*(s - 1)
Let i = -700 - -93. Let k = 610 + i. Suppose 2/3 + 3*s - 2/3*s**2 - k*s**3 = 0. Calculate s.
-1, -2/9, 1
Factor -112/3 - 1/3*y**2 - 58/3*y.
-(y + 2)*(y + 56)/3
Let h(y) be the first derivative of y**5/5 - 3*y**4/2 + 8*y**3/3 + 3*y**2 - 9*y + 4852. Determine j so that h(j) = 0.
-1, 1, 3
Let p(l) be the first derivative of -l**4/12 + 46*l**3/9 + 49*l**2/6 - 94*l/3 - 1009. Factor p(y).
-(y - 47)*(y - 1)*(y + 2)/3
Let n(u) be the first derivative of 7/15*u**3 + 1/4*u**4 + 0*u - 1 - 4/25*u**5 - 1/5*u**2. Find r such that n(r) = 0.
-1, 0, 1/4, 2
Suppose 3842/13 - 2/13*x**3 + 7682/13*x + 3838/13*x**2 = 0. What is x?
-1, 1921
Let b(f) be the third derivative of -f**8/392 + 13*f**7/49 + 207*f**6/70 + 422*f**5/35 + 142*f**4/7 - 4849*f**2. Factor b(o).
-6*o*(o - 71)*(o + 2)**3/7
Let u be 12 - (6 + (13 - 21))/((-36)/171). Let h = 8 + -6. Let 0 + h*q**3 + 1/2*q**4 + u*q**2 + q = 0. Calculate q.
-2, -1, 0
Solve 2/3*s**2 + 2468642/3 - 4444/3*s = 0 for s.
1111
Let m(g) be the first derivative of 2*g**3/33 - 1104*g**2/11 + 609408*g/11 - 2743. Factor m(o).
2*(o - 552)**2/11
Let m(o) be the second derivative of -o**4/72 + 23*o**3/12 - 3*o + 82. Determine b, given that m(b) = 0.
0, 69
Solve -1884/7 + 4/7*v**3 + 3772/7*v - 1892/7*v**2 = 0.
1, 471
Let p(d) = -2*d**2 + 83*d - 132. Let k be p(42). Let x = k - -176. Factor -2/13*f + 2/13*f**3 + 0 + 0*f**x.
2*f*(f - 1)*(f + 1)/13
Let q(o) be the third derivative of 0*o - 6/5*o**4 + 0 - 22*o**2 + 1/75*o**5 + 216/5*o**3. Determine d so that q(d) = 0.
18
Let c be 56/35 + (112/630 - (-4)/18). Let i(g) be the first derivative of 0*g + 0*g**c + 2/9*g**3 - 13. Find k, given that i(k) = 0.
0
Suppose 27/2*q**4 - 51/2 + 3/4*q**5 - 42*q**2 + 21/2*q**3 - 261/4*q = 0. Calculate q.
-17, -1, 2
Suppose 0 = 14*h - 34 - 92. Suppose -5*o = -4*v - 0*o + 11, 5 = 5*o. Determine t, given that -5*t**2 - h*t**4 + 9*t**4 + v*t**4 + t**4 = 0.
-1, 0, 1
Let v(l) be the first derivative of -2*l**2 - 6*l + 34 + 2/3*l**3. Determine n so that v(n) = 0.
-1, 3
Let l(i) be the first derivative of i**4/44 - 95*i**3/66 - 16*i**2/11 + 164*i - 53. Let f(p) be the first derivative of l(p). Factor f(g).
(g - 32)*(3*g + 1)/11
Let r be 180*2/(-16)*-4. Suppose -u - 4*u = -r. Factor -48*p**2 + 30*p**3 + 3*p - p - u*p**4 + 34*p**2.
-2*p*(p - 1)*(3*p - 1)**2
Let z(p) be the first derivative of -p**6/27 - 4*p**5/45 + 119*p**4/18 - 208*p**3/9 + 8145. Solve z(o) = 0 for o.
-13, 0, 3, 8
Let s be 38/(-285)*11*-5 - 7. Let -8/3 - s*h**2 + 3*h = 0. Calculate h.
1, 8
Let p(i) be the second derivative of 11*i**5/30 + 80*i**4/27 + 173*i**3/27 - 10*i**2/3 - 8174*i. Factor p(s).
2*(s + 2)*(s + 3)*(33*s - 5)/9
Suppose 2448 + 224 + 4*m**2 - 273*m - 373*m - 18*m + 548 = 0. Calculate m.
5, 161
What is t in 1/8*t**4 + 1/2*t**3 - 11/2*t**2 + 72 - 12*t = 0?
-6, 4
Let t(k) be the second derivative of 19/2*k**4 - 3*k - 1/14*k**7 - 15/4*k**5 + 4/5*k**6 - 14*k**3 + 4 + 12*k**2. Factor t(h).
-3*(h - 2)**3*(h - 1)**2
Let d(r) be the second derivative of -r**6/6 + 35*r**5/4 - 65*r**4 + 150*r**3 - 12196*r. Factor d(z).
-5*z*(z - 30)*(z - 3)*(z - 2)
Let n be (-10)/25 - (-6360)/25. Solve -328*y - 567*y**4 - 1017*y**2 + n*y**3 - 43*y**5 - 36 - 6*y**5 - 1497*y**3 = 0 for y.
-9, -1, -2/7
Let s(k) be the second derivative of -k**8/1344 + k**6/480 - 55*k**2/2 - k + 25. Let m(p) be the first derivative of s(p). Factor m(a).
-a**3*(a - 1)*(a + 1)/4
Find m, given that 232*m - m**3 + 21*m**2 + 35*m + 99*m**2 + 5*m**3 + 597*m = 0.
-18, -12, 0
Let p(d) be the second derivative of -d**9/3780 - d**8/240 + 4*d**7/315 - 2*d**4/3 + 8*d + 2. Let c(i) be the third derivative of p(i). Factor c(n).
-4*n**2*(n - 1)*(n + 8)
Let -80 + 92/5*v + 2/5*v**2 = 0. What is v?
-50, 4
Suppose 68*o - 75*o + 14 = 0. Let s be (26 + -22)/(o + (2 - -14)). Factor s*u**3 + 0*u**2 + 4/9 - 2/3*u.
2*(u - 1)**2*(u + 2)/9
Let j be (24/(-10))/(-4) + 0. Let k be 53/((-8109)/170)*144/(-80). Solve 9/5*d + j + 9/5*d**k + 3/5*d**3 = 0.
-1
Suppose -2*g + 34 = 13*l - 15*l, l - 58 = -4*g. Determine z, given that 34 - 36*z**3 + 79 + g - 4*z**4 - 88*z**2 = 0.
-4, -2, 1
Suppose -2*i + 3*i - 3 = 0. Let b(x) = -1300*x + 3900. Let c be b(3). Factor c*h**2 + 1/3*h**i - 2/3 - h.
(h - 2)*(h + 1)**2/3
Let -624 - 219/5*f**2 - 1608/5*f - 3/5*f**3 = 0. Calculate f.
-65, -4
Suppose 229*c + 51 - 967 = 0. Let h(u) be the second derivative of -1/84*u**7 + 1/2*u**2 + 2/3*u**c + 0 - 3/4*u**3 - 25*u - 7/20*u**5 + 1/10*u**6. Factor h(i).
-(i - 2)*(i - 1)**4/2
Let s be (((-39)/455)/1)/(11 + 960/(-84)). What is t in 9/5*t**3 + 0 - 2/5*t**2 + 2/5*t**4 - 8/5*t - s*t**5 = 0?
-2, -1, 0, 1, 4
Factor -g**5 - 4*g**5 - 3149*g**4 - 84872965*g - 994590*g**3 + 475*g**4 - 85863700*g**2 - 1186*g**4.
-5*g*(g + 1)*(g + 257)**3
Let u(a) = 14*a**2 - 20*a - 88. Let f(m) = 79*m**2 - 122*m - 528. Let c(q) = -6*f(q) + 34*u(q). Factor c(z).
2*(z + 4)*(z + 22)
Let u(k) = 241*k**3 + 777*k**2 - 25732*k - 135166. Let r(h) = -240*h**3 - 774*h**2 + 25734*h + 135165. Let n(b) = -2*r(b) - 3*u(b). Factor n(p).
-3*(p - 11)*(9*p + 64)**2
Let i(c) be the third derivative of -c**6/15 + 173*c**5/60 + 125*c**4/12 + 23*c**3/2 - 1205*c**2 + 2. Factor i(o).
-(o - 23)*(o + 1)*(8*o + 3)
Let p(w) be the third derivative of -5/108*w**4 + 2/9*w**3 + 1/540*w**6 - 2 + 0*w - 1/135*w**5 + 31*w**2. Factor p(m).
2*(m - 3)*(m - 1)*(m + 2)/9
Find k such that 8*k**2 - 3*k**4 + 3/2*k**3 + 0 - 1/2*k**5 - 6*k = 0.
-6, -2, 0, 1
Suppose q + 0*q - 4*f - 5 = 0, -3*f = 15. Let t be (-10)/(-8) + (945/(-36))/q. Factor 0 + 3/4*h**2 + 3/8*h**t + 3/8*h.
3*h*(h + 1)**2/8
Factor -659*w + w**2 + 1974*w - 681*w.
w*(w + 634)
Let w be ((-6)/10)/(2 - -5 - 869/110). Factor 0 + 26/3*y + w*y**2.
2*y*(y + 13)/3
Let y = 3846481/2051448 + -2/256431. Determine g, given that 129/8*g**3 + 21/2*g**4 + 0 + y*g**5 - 9/2*g + 3*g**2 = 0.
-3, -2, -1, 0, 2/5
Factor -7*r - 93*r + 11*r**3 + 24*r**3 + 4*r**4 + r**3 - 12*r**2 + 72.
4*(r - 1)**2*(r + 2)*(r + 9)
Let v(l) = 14*l + 102. Let u be v(-7). Factor -39*t**3 - 403*t**2 + t**5 - 7*t**5 + 439*t**2 + 3*t**5 + 18*t**u - 12*t.
-3*t*(t - 2)**2*(t - 1)**2
Factor 98816 + 28*q**3 + 970*q**2 - 33*q**3 - 48000*q - 6656.
-5*(q - 96)**2*(q - 2)
Let c(a) = 2*a**2 - 18*a + 23. Let o be c(15). Suppose 3*i = i + 3*n + 131, 2*n - o = -3*i. Let 0*x**3 - 75 + 2*x**2 + i - 4*x + x**3 = 0. What is x?
-2, 2
Let f(p) = p**3 + 11*p**2 + 6*p + 12. Let t be f(-10). Factor 11 - 37 - t*h - 10 - 1968*h**2 + 1952*h**2 - 8*h.
-4*(h + 3)*(4*h + 3)
Let i = -228569 + 228572. Determine f, given that 56/9 + 124/9*f**i + 32/9*f - 74/3*f**2 + 10/9*f**4 = 0.
-14, -2/5, 1
Suppose -10/3*k - 11/3 + 1/3*k**2 = 0. Calculate k.
-1, 11
Let g be (-21)/108 - (-11 - 164 | 2024-06-26T23:14:03.371983 | https://example.com/article/8881 |
Q:
How to write an update hook for git submodules?
I would like to copy some files in the submodules in my "vendor/assets" directory to another directory -- "public/assets." I heard about update hooks but I am not sure if they work for submodules. I wrote a simple hook and ran update from commandline, but it didn't work.
My update hook looks like this:
#.git/gooks/update.rb
#!/usr/bin/env ruby
puts "Copying files..."
So is this even possible?
btw, I'm using Braid to manage my submodules.
A:
The update hook is only run when someone has pushed into the current repository, which doesn't sound like what you want. You could use the post-commit hook, if you want to copy these files into place every time you create a commit in your repository. (That should be sufficient, because you'd need to commit the new version of any submodule in the main project when you change the commit that the submodule is meant to be at. This would be a natural point to update the files in public/assets.)
You say that your test hook isn't being run - that may be simply because you have the name wrong. The update hook must be an executable file called .git/hooks/update (n.b. without a .rb suffix). Similarly, a post-commit hook must be .git/hooks/post-commit.
You shouldn't create hooks in any particular submodule for this task, since the action the hook will be taking is specific to the main project. Because of that, it doesn't really matter whether the change you're worried about it due to committing a new version of the submodules or just updating any random file.
For writing hooks, you'll find the official githooks documentation useful, and possibly these additional tips.
| 2024-03-02T23:14:03.371983 | https://example.com/article/2031 |
Q:
Please explain this delete top 100 SQL syntax
Basically I want to do this:
delete top( 100 ) from table order by id asc
but MS SQL doesn't allow order in this position
The common solution seems to be this:
DELETE table WHERE id IN(SELECT TOP (100) id FROM table ORDER BY id asc)
But I also found this method here:
delete table from (select top (100) * from table order by id asc) table
which has a much better estimated execution plan (74:26). Unfortunately I don't really understand the syntax, please can some one explain it to me?
Always interested in any other methods to achieve the same result as well.
EDIT: I'm still not getting it I'm afraid, I want to be able to read the query as I read the first two which are practically English. The above queries to me are:
delete the top 100 records from table, with the records ordered by id ascending
delete the top 100 records from table where id is anyone of (this lot of ids)
delete table from (this lot of records) table
I can't change the third one into a logical English sentence... I guess what I'm trying to get at is how does this turn into "delete from table (this lot of records)". The 'from' seems to be in an illogical position and the second mention of 'table' is logically superfluous (to me).
A:
This is explained well here (The article talks about using a view but I presume the same logic must apply to your query if you are getting a better execution plan)
the first one reads the “deleted”
portion of the table twice. Once to identify
the rows to delete and then once more
to perform the delete.
The second one avoids this.
Edit This seems to be more a question about syntax. The syntax for delete is described here.
The relevant bit is
DELETE
[ FROM ]
{ <object> | rowset_function_limited
}
[ FROM <table_source> [ ,...n ] ]
Your query is
delete alias
from
(select top (100) *
from table
order by id asc) alias
You are using a derived table so need the FROM <table_source>. You are omitting the first optional FROM.
A:
What you are looking to do is a technique called a Fast Ordered Delete.
Take a look at the following Blog post: Performing Fast SQL Server Delete operations
A:
The delete command takes several similar forms, as the from keyword is optional, and the deletion table can be specified separate from the query selecting the records:
delete table where ...
delete from table where ...
delete table from <query...>
delete from table from <query...>
The idea with the last two ones is that you can first define which table to delete from, then you can specify a query that picks out the records to delete. The query can join in other tables, that's why you would need to separately define from which table to delete.
The query that you found just uses a subquery to pick out the records to delete.
| 2023-11-13T23:14:03.371983 | https://example.com/article/8670 |
// Copyright 2014 The Chromium Authors. All rights reserved.
// Use of this source code is governed by a BSD-style license that can be
// found in the LICENSE file.
#include "ios/chrome/browser/memory/memory_metrics.h"
#include <mach/mach.h>
#include <stddef.h>
#include <stdint.h>
#include <memory>
#include "base/logging.h"
#include "base/mac/scoped_mach_port.h"
#include "base/process/process_handle.h"
#include "base/process/process_metrics.h"
#include "build/build_config.h"
#ifdef ARCH_CPU_64_BITS
#define cr_vm_region vm_region_64
#else
#define cr_vm_region vm_region
#endif
namespace {
// The number of pages returned by host_statistics and vm_region are a count
// of pages of 4096 bytes even when running on arm64 but the constants that
// are exposed (vm_page_size, VM_PAGE_SIZE, host_page_size) are all equals to
// 16384 bytes. So we define our own constant here to convert from page count
// to bytes.
const uint64_t kVMPageSize = 4096;
}
namespace memory_util {
uint64_t GetFreePhysicalBytes() {
vm_statistics_data_t vmstat;
mach_msg_type_number_t count = HOST_VM_INFO_COUNT;
base::mac::ScopedMachSendRight host(mach_host_self());
kern_return_t result = host_statistics(
host.get(), HOST_VM_INFO, reinterpret_cast<host_info_t>(&vmstat), &count);
if (result != KERN_SUCCESS) {
LOG(ERROR) << "Calling host_statistics failed.";
return 0;
}
return vmstat.free_count * kVMPageSize;
}
uint64_t GetRealMemoryUsedInBytes() {
base::ProcessHandle process_handle = base::GetCurrentProcessHandle();
std::unique_ptr<base::ProcessMetrics> process_metrics(
base::ProcessMetrics::CreateProcessMetrics(process_handle));
return static_cast<uint64_t>(process_metrics->GetWorkingSetSize());
}
uint64_t GetDirtyVMBytes() {
// Iterate over all VM regions and sum their dirty pages.
unsigned int total_dirty_pages = 0;
vm_size_t vm_size = 0;
kern_return_t result;
for (vm_address_t address = MACH_VM_MIN_ADDRESS;; address += vm_size) {
vm_region_extended_info_data_t info;
mach_msg_type_number_t info_count = VM_REGION_EXTENDED_INFO_COUNT;
mach_port_t object_name;
result = cr_vm_region(
mach_task_self(), &address, &vm_size, VM_REGION_EXTENDED_INFO,
reinterpret_cast<vm_region_info_t>(&info), &info_count, &object_name);
if (result == KERN_INVALID_ADDRESS) {
// The end of the address space has been reached.
break;
} else if (result != KERN_SUCCESS) {
LOG(ERROR) << "Calling vm_region failed with code: " << result;
break;
} else {
total_dirty_pages += info.pages_dirtied;
}
}
return total_dirty_pages * kVMPageSize;
}
uint64_t GetInternalVMBytes() {
task_vm_info_data_t task_vm_info;
mach_msg_type_number_t count = TASK_VM_INFO_COUNT;
kern_return_t result =
task_info(mach_task_self(), TASK_VM_INFO,
reinterpret_cast<task_info_t>(&task_vm_info), &count);
if (result != KERN_SUCCESS) {
LOG(ERROR) << "Calling task_info failed.";
return 0;
}
return static_cast<uint64_t>(task_vm_info.internal);
}
} // namespace memory_util
| 2023-08-28T23:14:03.371983 | https://example.com/article/8368 |
TOKYO, March 24. /ITAR-TASS/. The majority of Japanese believe that Tokyo should pursue a more independent policy in connection with the crisis around Ukraine, and should not just tighten sanctions against Russia together with the West, according to a public opinion poll conducted by the Nikkei Research centre and TV Tokyo. The poll was conducted by telephone by a random sample method among 1,500 citizens of the country.
Only 31% of those polled supported the “tightening of sanctions against Russia in coordination with the United States and European Union. At the same time, 52% of respondents believe that Japan, in connection with the situation around Ukraine, should pursue “an independent diplomatic policy”, taking into account the importance of negotiations with Russia on the territorial issue and other factors.
The Japanese government’s attitude towards the situation over Crimea is more reserved than that of its Western partners. After the signing of the agreement on the peninsula’s accession to Russia, Tokyo, however, announced the suspension of the consultations with Moscow on easing visa restrictions and froze the beginning of talks on a number of documents. However, Japanese government representatives have said that these measures are limited and do not affect economic relations. | 2023-08-23T23:14:03.371983 | https://example.com/article/4810 |
This application claims the benefit of Korean Patent Application No. 2001-1129 filed on Jan. 9, 2001, in the Korean Industrial Property Office, the disclosure of which is incorporated herein by reference.
1. Field of the Invention
The present invention relates to a tilt compensation method and an apparatus therefor, and more particularly, to a method of compensating for the tilt of an optical recording medium in which the tilt margin is between 0 and 0.0052, that is, 0 less than tilt margin less than 0.0052, and an apparatus used therefor.
2. Description of the Related Art
When an optical disc such as a DVD or a CD-RW used for high density recording is tilted, an error is generated during recording or reproducing data according to a degree of tilt. When the disc is tilted severely, recording or reproducing of data itself is difficult.
Table 1 below shows how margin changes, with respect to the characteristic of light and the change in tilt and thickness of an optical disc at a data recording surface thereof, according to a change in numerical aperture (NA), may affect a process of recording data on the optical disc. As shown in the table, when the numeral aperture increases, a spot size decreases so that the data recording capacity is increased. However, it is also shown that the depth of focus and margin of disc tilt are reduced.
A new optical disc named as a DDCD (double density CD) has been suggested. The DDCD uses the same wavelength as the wavelength used for an existing CD while using an objective lens having a larger NA and having a small track pitch. Also, the NA of a DDCD is different from that of an existing DVD (digital versatile disc).
Thus, a tilt margin of the DDCD is clearly different from that of the existing CD or DVD. Table 2 shows the characteristics of a CD, a DDCD and a DVD. In Table 2, the NA of the DDCD is 0.50 for reading only, that is, for reproducing only and 0.55 when used for both reading and recording. The NA of the CD is 0.45 for reading only and 0.50 when used for both reading and recording. The NA of the DVD is 0.60 when used for both reading only and reading and recording together. It can be seen that the NA of the DDCD is greater than that of the existing CD and less than the existing DVD.
Table 3 below shows the result of calculation of tilt margin with respect to a CD, DDCD and DVD by using a mathematical formula (xcex/tNA3; where xe2x80x9ctxe2x80x9d denotes the thickness of a disc) indicating a tilt margin.
It can be seen from Table 3 that the tilt margin of a DDCD is less than that of a CD and 22% less than that of a DVD. Such a fact can also be seen from FIG. 1.
In detail, FIG. 1 is a graph showing the cases of different NAs which may have the same tilt margin as that of a DVD. In the graph, the horizontal axis denotes wavelength (nm) and the vertical axis denotes the thickness of an optical disc (mm). The first and second lines G1 and G2 indicate a change of the tilt margin of a CD-R/RW when the NA is 0.5 and a change of the tilt margin of a DVD when the NA is 0.6, respectively. In FIG. 1, all lines indicating different NAs show the same tilt margins. For example, the tilt margins indicated by the first and second lines G1 and G2 are the same.
The NA of a DDCD is 0.55 for recording and reproducing, and a graph corresponding to this condition is indicated by a projection line which is positioned between the first and second lines G1 and G2. Thus, if the tilt margin of a DDCD having a NA of 0.55 is the same as that of a DVD, since the wavelength of a DDCD is 780 nm, the thickness of the DDCD must be about 0.92 mm. However, since the thickness of a DDCD is actually 1.2 mm, the tilt margin of the DDCD naturally decreases, which can be seen from the above mathematical formula. Therefore, since the tilt margin of DDCD is different from that of CD or DVD, correction for this difference is needed.
Accordingly, it is an object of the present invention to provide a tilt compensation method by which recording is performed by controlling power and/or time needed for recording according to the tilt of an optical recording medium.
It is another object of the present invention to provide a method that adaptively compensates for a recording pulse according to the detected tilt of an optical recording medium.
It is yet another object of the present invention to provide a tilt compensating apparatus which performs recording by controlling power and/or time needed to record according to the tilt of an optical recording medium.
It is yet another object of the present invention to provide a tilt compensating apparatus to adaptively compensate for a recording pulse according to the detected tilt of an optical recording medium.
The foregoing and other objects of the present invention are achieved by providing a method that compensates for a tilt of a recordable and reproducible optical recording medium comprising detecting a tilt of the optical recording medium, and compensating for a recording signal having a predetermined recording pattern by using a predetermined system according to the detected tilt, wherein, when detecting the tilt, the tilt is detected with respect to an optical recording medium in which a tilt margin is greater than 0 and less than 0.0052 (0 less than tilt margin less than 0.0052).
The foregoing and other objects are also achieved by providing a method that compensates for a tilt of an optical recording medium when input data is recorded as a mark and a space by a recording pulse having a predetermined recording pattern. The method comprises detecting a tilt of the optical recording medium, and adaptively compensating for the recording pattern according to the detected tilt by using a memory, where a recording power and/or time compensating for the amount of shift of the recording pattern and the length and width of a mark according to the tilt and/or the length of the mark is stored, wherein, during detecting the tilt, the tilt is detected with respect to an optical recording medium in which a tilt margin is greater than 0 and less than 0.0052 (0 less than tilt margin less than 0.0052).
The foregoing and other objects may also be achieved by providing an apparatus that compensates for a tilt of a recordable and reproducible optical recording medium comprising a tilt detector detecting a tilt of the optical recording medium, and a recording compensator compensating for a recording signal having a predetermined recording pattern by using a predetermined system according to the tilt detected by the tilt detector, wherein the tilt detector detects the tilt with respect to an optical recording medium in which a tilt margin is greater than 0 and less than 0.0052 (0 less than tilt margin less than 0.0052) and the recording compensator compensates for the detected tilt.
The foregoing and other objects may also be achieved by providing an apparatus that compensates for a tilt of an optical recording medium when input data is recorded as a mark and a space by a recording pulse having a predetermined recording pattern, the apparatus comprising a tilt detector detecting a tilt of the optical recording medium, and a recording compensator adaptively compensating for the recording pattern according to the tilt detected by the tilt detector by using a memory where a recording power and/or time compensating for the amount of shift of the recording pattern and the length and width of a mark according to the tilt and/or the length of the mark is stored, wherein the tilt detector detects the tilt with respect to an optical recording medium in which a tilt margin is greater than 0 and less than 0.0052 (0 less than tilt margin less than 0.0052) and the recording compensator compensates for the detected tilt. | 2024-02-24T23:14:03.371983 | https://example.com/article/6708 |
U.S. authorities have identified a suspect in last year's "Vault 7" leaks of CIA hacking and electronic surveillance tools used in foreign espionage operations, reports the Washington Post.
The Vault 7 release - a series of 24 documents which began to publish on March 7, 2017 - reveal that the CIA had a wide variety of tools to use against adversaries, including the ability to "spoof" its malware to appear as though it was created by a foreign intelligence agency, as well as the ability to take control of Samsung Smart TV's and surveil a target using a "Fake Off" mode in which they appear to be powered down while eavesdropping.
The CIA's hand crafted hacking techniques pose a problem for the agency. Each technique it has created forms a "fingerprint" that can be used by forensic investigators to attribute multiple different attacks to the same entity. ... The CIA's Remote Devices Branch's UMBRAGE group collects and maintains a substantial library of attack techniques 'stolen' from malware produced in other states including the Russian Federation. With UMBRAGE and related projects the CIA cannot only increase its total number of attack types but also misdirect attribution by leaving behind the "fingerprints" of the groups that the attack techniques were stolen from. UMBRAGE components cover keyloggers, password collection, webcam capture, data destruction, persistence, privilege escalation, stealth, anti-virus (PSP) avoidance and survey techniques. -WikiLeaks
Joshua Adam Schulte, 29, a former employee in the CIA's Engineering Development Group, is believed to have provided the agency's top-secret cyber warfare tools to WikiLeaks - according to a disclosure by federal prosecutors at a January hearing in a Manhattan court on unrelated charges of possessing, receiving and transporting child pornography. Schulte, who has been in jail for months, has pleaded not guilty on the child porn charges.
Schulte previously worked for the NSA before joining the CIA, then "left the intelligence community in 2016 and took a job in the private sector," according to a statement reviewed by The Post.
Schulte also claimed that he reported “incompetent management and bureaucracy” at the CIA to that agency’s inspector general as well as a congressional oversight committee. That painted him as a disgruntled employee, he said, and when he left the CIA in 2016, suspicion fell upon him as “the only one to have recently departed [the CIA engineering group] on poor terms,” Schulte wrote. -WaPo
Prosecutors allege that they found a large collection of child pornography on a server maintained by Schulte, however his attorneys argue that anywhere from 50 to 100 people had access to it, which Schulte set up several years ago to share movies and other digital files.
Federal authorities searched Schulte’s apartment in New York last year and obtained personal computer equipment, notebooks and handwritten notes, according to a copy of the search warrant reviewed by The Washington Post. But that failed to provide the evidence that prosecutors needed to indict Schulte with illegally giving the information to WikiLeaks. -WaPo
And while Schulte "remains a target of that investigation," prosecutor Matthew Laroche, assistant US attorney in the Southern District of New York, said that the investigation is "ongoing." Part of that investigation, reports WaPo, is analyzing whether the Tor network - which allows internet users to hide their location (in theory) "was used in transmitting classified information."
In other hearings in Schulte’s case, prosecutors have alleged that he used Tor at his New York apartment, but they have provided no evidence that he did so to disclose classified information. Schulte’s attorneys have said that Tor is used for all kinds of communications and have maintained that he played no role in the Vault 7 leaks. -WaPo
“Due to these unfortunate coincidences the FBI ultimately made the snap judgment that I was guilty of the leaks and targeted me,” Schulte said. He has launched Facebook and GoFundMe pages to raise money for his defense, as well as post articles critical of the criminal justice system.
As The Post notes, the Vault 7 release was one of the most significant leaks in the CIA's history, "exposing secret cyberweapons and spying techniques that might be used against the United States, according to current and former intelligence officials."
The CIA's toy chest includes:
Tools code named "Marble" can misdirect forensic investigators from attributing viruses, trojans and hacking attacks to their agency by inserted code fragments in foreign languages. The tool was in use as recently as 2016. Per the WikiLeaks release:
"The source code shows that Marble has test examples not just in English but also in Chinese, Russian, Korean, Arabic and Farsi. This would permit a forensic attribution double game, for example by pretending that the spoken language of the malware creator was not American English, but Chinese, but then showing attempts to conceal the use of Chinese, drawing forensic investigators even more strongly to the wrong conclusion, --- but there are other possibilities, such as hiding fake error messages."
iPads / iPhones / Android devices and Smart TV’s are all susceptible to hacks and malware. The agency's "Dark Matter" project reveals that the CIA has been bugging “factory fresh” iPhones since at least 2008 through suppliers. Another, "Sonic Screwdriver" allows the CIA to execute code on a Mac laptop or desktop while it's booting up.
The increasing sophistication of surveillance techniques has drawn comparisons with George Orwell’s 1984, but “Weeping Angel”, developed by the CIA’s Embedded Devices Branch (EDB), which infests smart TVs, transforming them into covert microphones, is surely its most emblematic realization.
The Obama administration promised to disclose all serious vulnerabilities they found to Apple, Google, Microsoft, and other US-based manufacturers. The US Government broke that commitment.
"Year Zero" documents show that the CIA breached the Obama administration's commitments. Many of the vulnerabilities used in the CIA's cyber arsenal are pervasive and some may already have been found by rival intelligence agencies or cyber criminals.
The Frankfurt consulate is a major CIA hacking base of operations.
In addition to its operations in Langley, Virginia the CIA also uses the U.S. consulate in Frankfurt as a covert base for its hackers covering Europe, the Middle East and Africa. CIA hackers operating out of the Frankfurt consulate ( "Center for Cyber Intelligence Europe" or CCIE) are given diplomatic ("black") passports and State Department cover.
Instant messaging encryption is a joke.
These techniques permit the CIA to bypass the encryption of WhatsApp, Signal, Telegram, Wiebo, Confide and Cloackman by hacking the "smart" phones that they run on and collecting audio and message traffic before encryption is applied.
The CIA laughs at Anti-Virus / Anti-Malware programs.
You can see the Vault7 release here. | 2024-05-30T23:14:03.371983 | https://example.com/article/7476 |
+ 526 = 2*o - 267, 0 = -2*k + c*o + 322. Is k a composite number?
True
Let a = 134 + -128. Is ((-4)/a)/(38/(-22857)) prime?
True
Suppose -108818529 = -343*l + 85291609 + 34053805. Is l composite?
False
Suppose -2*l = 2*x - 346956, -2*l + 520394 = 3*x - 7*l. Is x a prime number?
True
Let n(a) = a**3 + 19*a**2 + a - 9. Let c be n(-8). Let o = 1006 + c. Is o prime?
True
Suppose 68*c - 73*c + 19260 = 0. Let n = -1909 + c. Is n prime?
False
Suppose 2*i + x = 15347, -3*x - 14520 = -5*i + 23853. Suppose 13*j - i = 13867. Is j prime?
True
Let w be 8*(-2)/(-4) - -1. Suppose -w*n = -13930 - 4245. Is n a prime number?
False
Let s be (14 - 12)*(-6)/4. Is (-369)/(-2)*(s + (-88)/(-24)) composite?
True
Let m be (-6573)/(-14)*4/3*116. Is (-1)/(-5) - m/(-20) prime?
True
Let u(d) = 34224*d - 1353. Is u(13) composite?
True
Suppose 0 = -0*x - x + 12. Suppose -4*g + 29864 = 4*q, -2*q - 2*g + 37342 = 3*q. Is q/x + (-1)/(-2) + 0 composite?
True
Let c(r) = r**3 - 5*r**2 + 70*r + 15. Let p(a) = a**2 - a - 1. Let b be p(4). Is c(b) a prime number?
True
Is (127097 - -2) + (2 - (-12 - -16)) prime?
False
Suppose 55*i - 5218301 - 11656584 - 11550710 = 0. Is i a composite number?
False
Let g = 60 + -56. Suppose q = -5*b + 12, 1 - 7 = -g*b + q. Suppose b*h = 2*v - 1264, 3*v - 5*h - 1225 - 673 = 0. Is v a composite number?
False
Let c be 4 - -2*(-1)/2. Suppose -y + 1050 = y - c*q, -3*y + 1576 = -4*q. Let o = y - 305. Is o a composite number?
False
Suppose 3*g = 0, 4*c + 2*g - 45 = 11. Let s(v) = 10*v**2 + 19*v + 11. Is s(c) prime?
True
Let n(s) = -80*s**3 + 13*s**2 - 20*s + 8. Let t be n(-10). Is (-21 - -13) + t/4 prime?
True
Suppose 5*v = 3*y + 28, 0*v + y + 36 = 5*v. Let b(g) be the second derivative of 1127*g**3/6 - 11*g**2/2 - 422*g. Is b(v) prime?
False
Let j(w) = 5*w**3 - 7*w**2 + 6*w - 3. Let z be 2*(18/9 - 5/2). Let c(n) = n**3 - 1. Let r(l) = z*c(l) - j(l). Is r(-5) a prime number?
False
Let x = -209 - -212. Suppose -4*y - r = -552, 0 = x*r + 12. Is y a composite number?
False
Let x(i) = -1 + i**2 - 22*i - 3 - 2*i**2. Suppose -11 = 3*z + 16. Is x(z) prime?
True
Is (-43)/86 + 861*957/6 prime?
False
Let j be ((-5931)/(-6))/(9/(-132)). Is (12/3)/4*j/(-2) composite?
True
Suppose 34*g = 21*g - 106*g + 42914613. Is g prime?
False
Suppose 0 = -2*l + 7*l + 2*s + 111, -3*s = 4*l + 93. Let c(w) = w**3 + 22*w**2 + 20*w - 21. Let z be c(l). Suppose z = t - 1862 + 741. Is t composite?
True
Let i = -102 - -86. Let d be (-1)/((-4)/i) + 3. Is (d + 212/(-8))*-2 a composite number?
True
Let v = -54 + 3698. Let u = v - 2075. Is u a prime number?
False
Suppose 690456 = 22*a + 222362. Is a prime?
True
Let w(r) = -r + 11. Let a be w(10). Suppose a = f - 1. Is f*(-5574)/(-12)*2/2 composite?
False
Is (12/((-1320)/7030078))/((-2)/10) composite?
True
Is 2 + -4 - 44994*-1 - (-12 + 15) composite?
True
Let a be (-1)/(-2)*4*(-82042)/(-76). Suppose 1102 = 3*y - a. Is y a prime number?
True
Is (4/48*-3)/(6 - (-4341725)/(-723620)) prime?
False
Suppose 2*y - 8914071 = p - 1799573, y + p = 3557243. Is y composite?
True
Let x(k) = 114*k**3 - 2*k**2 + 15. Let c(l) = -4*l**2 + 56*l + 4. Let o be c(14). Is x(o) composite?
True
Let i = 218219 + 534. Is i a prime number?
False
Suppose -2*o + 562470 + 154788 = 4*l, -5*o - 717209 = -4*l. Is l composite?
True
Suppose -58*j - 24 = -64*j. Suppose d = -j*l + 557, -2*d + 1094 = -2*l + 5*l. Is d a prime number?
True
Let j(h) = 10 - 15*h - 8*h + 381*h**2 + 37*h - 14*h. Is j(-7) a composite number?
False
Suppose -5*r + 55*p - 51*p + 241519 = 0, 2*p = -12. Is r composite?
False
Let m(h) = 15*h**3 - 18*h**2 - 13*h + 37. Is m(18) prime?
False
Let c be -3 + 2 - 14/1. Let d be ((-12)/(-15))/(((-18)/c)/3). Suppose -t + 5*r = t - 8329, 16718 = 4*t + d*r. Is t prime?
True
Let y = 2796 + 1077. Let r = y - 1502. Is r prime?
True
Let h(o) = 9267*o - 1033. Is h(21) a prime number?
False
Let n(g) = -9*g**3 + 52*g**2 - 41*g - 751. Is n(-42) prime?
True
Let x = -887 - -1455. Suppose 4*d + 2*h + x = 5*h, 4*d = 4*h - 564. Let f = d - -324. Is f a prime number?
True
Let v(k) = -13*k**3 - 30*k**2 + 13*k + 56. Is v(-13) prime?
False
Suppose -9*p + 1197 + 315 = 0. Let b = -129 + p. Is b prime?
False
Let h(b) = 2788*b**3 + 2*b**2 + 5*b - 6. Let d = -199 + 200. Is h(d) prime?
True
Let j be (7820/(-272))/((-5)/264). Suppose f + b - 365 = 2224, 5*f - 4*b - 12963 = 0. Let c = f - j. Is c a composite number?
True
Let y(n) = -742*n + 79. Let d(c) = -495*c + 52. Let q(k) = -7*d(k) + 5*y(k). Is q(-2) a composite number?
False
Let q(l) = 2*l**3 + 116*l**2 + 68*l - 73. Is q(-56) a prime number?
True
Suppose -7*c = -1056 + 17828. Let n = 3582 + c. Is n composite?
True
Let w(d) = -52*d**3 + 0*d + 3*d + 8*d**2 + 53*d**3 + 26. Let b be w(-8). Suppose b*h = 5*p - 3239, -h - 3*h + 661 = p. Is p composite?
True
Let g = -58 + 672. Let a = 14167 - g. Is a a composite number?
False
Let d be ((-6)/10)/(2/(-31870)). Suppose s + 19127 = 4*u + 6*s, 2*u - d = -5*s. Suppose r + 5*v = 6710 - 1927, 0 = -r - 4*v + u. Is r a prime number?
True
Let m = -225355 - -319182. Is m composite?
False
Suppose -2*b = q - 365847 + 27786, 0 = 4*q - 4*b - 1352196. Is q a prime number?
False
Suppose 2*j - j = -108. Let f be j/(-20) - (-9)/15. Suppose -4*r + f*r = 238. Is r composite?
True
Suppose 25*w - 46901285 - 9667040 = 0. Is w prime?
False
Let s(h) = h**3 - 16*h**2 - h + 38. Let t be s(16). Suppose -t = -x - 10*x. Suppose 7*z = x*z + 12295. Is z a prime number?
True
Let s = 6307 + -4282. Suppose r = d - 4*d + 421, 5*r - 5*d = s. Is r prime?
True
Suppose -2*w = 4*m - 616, -3*w + 852 = -m - 79. Suppose 19 - 2 = -p. Let n = w + p. Is n prime?
True
Let p(a) = -a**3 + 7*a**2 - 17*a + 33. Let h be p(5). Is ((-1)/h)/((-64)/(-86144)) a prime number?
True
Is ((-2)/12)/(-6 + (-704166678)/(-117361116)) composite?
False
Let h be 2*-1*(-7154)/28. Let i = h - -460. Is i a composite number?
False
Let a(m) = 373416*m - 445. Is a(1) composite?
False
Suppose 5*p - 282*q - 60494 = -285*q, 0 = -4*p + 2*q + 48382. Is p prime?
True
Let m(q) = q**3 + 2*q**2 + 3*q + 2. Let y(j) = -j**2 + 9*j - 10. Let b be y(8). Let t be m(b). Let d(c) = 98*c**2 + 8*c - 1. Is d(t) a composite number?
True
Let z be (-2)/4 - 839228/(-104). Suppose 176 = -9*x + z. Is x prime?
True
Suppose 353751 = 14*v - 31375. Is v prime?
True
Suppose -822 = -4*p + 4242. Suppose -43*c + 635 + 26670 = 0. Let t = p - c. Is t a composite number?
False
Let w(y) be the third derivative of 539*y**5/30 - y**4/3 - 49*y**3/6 + 2*y**2 + 9. Is w(-4) a composite number?
False
Is 7 + (-267)/39 - (-147882)/39 - 1 a prime number?
False
Let g(i) = 3*i**2 + 54*i + 17. Let o be g(-28). Let f = o + 1638. Is f a composite number?
True
Let n(z) = 355*z + 14. Suppose -2*v = -7 - 1. Let x be n(v). Let p = x - 893. Is p prime?
True
Let r(l) be the first derivative of l**2/2 - l - 7. Let s(v) = 114*v - 7. Let a(d) = 6*r(d) + s(d). Is a(4) composite?
False
Is (4/2 - 16/10) + (-1365327)/(-45) a prime number?
True
Suppose -43*a - 154*a = -77817758. Is a prime?
False
Is (6 + -23 - -11) + 164875 + -2 composite?
True
Let z = 58 + -53. Suppose -4*m + 233 = -n + 1372, z*n + 5*m = 5695. Is n prime?
False
Let y(q) = 374*q**3 - 6*q**2 - 51*q + 3. Is y(8) prime?
True
Suppose 8*d - 98276 = 4676. Is d a prime number?
False
Is (-163838)/(-3) - 7/(-21) prime?
False
Let x = -166880 - -80342. Is 34/51 - (x/9 + -1) prime?
False
Let b = -36 + 135. Let u = 199 + b. Let q = u - -207. Is q composite?
True
Let n(o) = -o**3 - 3*o**2 - 6*o + 4. Let y be n(0). Suppose 8*z + 16412 = 4*w + 3*z, 0 = -y*w - 4*z + 16412. Is w prime?
False
Let i(t) = -3. Let g(d) = -11*d - 220. Let b(p) = g(p) - 33*i(p). Is b(-34) a composite number?
True
Suppose 21*b = 11*b - 14*b + 763368. Is b composite?
True
Let u(p) = p**3 + 25*p**2 - 9*p - 37. Let d be u(-21). Suppose -d = -5*m - 2*h, -h - 1143 = -5*m + 2*m. Is m composite?
True
Let g(i) = 7*i**3 - 2*i**2 + 2*i + 2. Let t be g(-1). Is ((-2136)/18)/4*t a prime number?
False
Suppose 282*z = -93194987 + 608677733. Is z a prime number?
True
Let b be 3*-2*(-48)/(-32). Let h(q) = 4*q + 40. Let w be h(b). Suppose 5*f = -k + 1871, 2*k + 7436 = 6*k - w*f. Is k prime?
True
Is 3 + (-136160)/(-3) + -6 + 240/45 composite?
False
Let o = -2363 - -10170. Is o composite?
True
Let h(c) = 4030*c + 543. Let o(n) = 2016 | 2024-03-25T23:14:03.371983 | https://example.com/article/3215 |
Drugs produced by the pharmaceutical companies (although sometimes necessary) are frequently associated with significant adverse side effects and can increase the body’s toxicity.
IV Oasis was founded by a certified physician with the goal of foregoing traditional medicine in favor of a more natural and effective way to treat patients. | 2023-10-23T23:14:03.371983 | https://example.com/article/1154 |
Rockchip Electronics And Security Accelerator
Required properties:
- compatible: Should be "rockchip,rk3288-crypto"
- reg: Base physical address of the engine and length of memory mapped
region
- interrupts: Interrupt number
- clocks: Reference to the clocks about crypto
- clock-names: "aclk" used to clock data
"hclk" used to clock data
"sclk" used to clock crypto accelerator
"apb_pclk" used to clock dma
- resets: Must contain an entry for each entry in reset-names.
See ../reset/reset.txt for details.
- reset-names: Must include the name "crypto-rst".
Examples:
crypto: cypto-controller@ff8a0000 {
compatible = "rockchip,rk3288-crypto";
reg = <0xff8a0000 0x4000>;
interrupts = <GIC_SPI 48 IRQ_TYPE_LEVEL_HIGH>;
clocks = <&cru ACLK_CRYPTO>, <&cru HCLK_CRYPTO>,
<&cru SCLK_CRYPTO>, <&cru ACLK_DMAC1>;
clock-names = "aclk", "hclk", "sclk", "apb_pclk";
resets = <&cru SRST_CRYPTO>;
reset-names = "crypto-rst";
};
| 2023-11-20T23:14:03.371983 | https://example.com/article/2498 |
Yesterday, Kazakhstan was among the rapidly developing republics of former USSR. However, the world recession has given an estimate for the genuine price of the nation’s “success”, where the major vector of economic development was the export of mineral resources. | 2024-01-09T23:14:03.371983 | https://example.com/article/3090 |
Is Washington at the End of the Rope with Venezuela?
The silence is almost deafening. Is it the quiet before the storm? – Or is the US giving up on Venezuela? I don’t think so. It’s more like a regrouping after a first defeat, well, it’s a multiple defeat, if we start counting since the failed coup attempt against Hugo Chavez on 11 April 2002.
However, Washington is not giving up. The first blows come flying. Pompeo to Maduro – open your borders for humanitarian aid, or else…. which implies the usual, “all options are on the table – ’humanitarian’ military intervention is an option”.
Washington – April 10, 2019, high level US and South American (members of the infamous and nefarious Lima Group, naturally) politicians and military held a secret meeting about the strategic next steps to subdue Venezuela, how to “regime-change” the Maduro Government, by ‘military options’, as reported by investigative journalist Max Blumenthal.
The meeting was dubbed ‘Assessing the Use of Military Force in Venezuela.’ It was hosted by the DC-based neoliberal thinktank the Center for Strategic and International Studies.
Venezuela’s ambassador to the UN, Samuel Moncada, denounces Trump’s preparations for war to the entire UN community.
The UN Community is increasingly taking note of the atrocities and lawlessness of the one rogue UN member that has the arrogance of thinking and acting as if it were above the law, above every law, even the laws made by its own lawmakers, the United States of America.
In the context of the failed coup attempt on Venezuela, a group of about 60 UN members formed, including Russia, China, India, Pakistan, Iran and many more, representing about half of the world population, in support of Venezuela and especially in support of the UN Charter.
The group requests and will enhance actions for UN members to respect the UN principles, the laws and rules upon which the United Nations were created almost 75 years ago. This is a new twist within the UN body.
On 11 April, US Treasury Secretary, Steven Mnuchin, met in Washington with 16 ministers of finance and representatives of 20 countries (Argentina, Brazil, Canada, Chile, Colombia, Costa Rica, Ecuador, France, Germany, Guatemala, Guyana, Italy, Japan, Mexico, Panama, Portugal, Peru, Spain, and the UK) – to enhance the support of some 50 countries of the self-declared president Juan Guaidó, and how to support Venezuela, once the Maduro Government “is gone”. – Hilarious, if it wasn’t so serious.
It is as if these, otherwise smart people, were falling into the trap of Joseph Goebbels, Hitler’s Propaganda Minister – if a lie is repeated enough, it becomes the truth.
Indeed, there is no other country in recent history that emulates Hitler and his approaches to world dominance by manipulation as well as Washington. And indeed, it is not quite clear, who was teaching whom.
Venezuela’s Vice-president, Delcy Rodriguez, denounces the preparation of a military intervention in Venezuela by the US, Colombia and Brazil. She warns the world from a humanitarian disaster if the global community, allows the United States and its minions to interfere in Venezuela.
Mexico’s new President, Andrés Manuel López Obrador (AMLO), also vehemently rejects any interference in Venezuela – and offers his Government’s services to mediate a dialogue between the Maduro Government and the opposition, a dialogue to which President Maduro has invited the opposition already many times. To no avail.
Mostly because the orders from Washington are clear, no dialogue – no compromise, the Maduro Government must be go.
We will inject the necessary capital into the inefficient oil industry, and our petrol corporations are eager to revive Venezuela’s hydrocarbon industry and make it profitable again.
These are the bold and honest words of John Bolton, US National security Adviser. Let’s see where all this hoopla may lead. If it sounds like wishful thinking, it is wishful thinking.
—-
Even though the true media hero, Julian Assange is for totally illegal reasons behind bars in the UK.
And this because laws are made in Washington as Washington sees fit, as Trump signs papers, shows them on TV and they becomes law – and laws of the US are applied throughout the US vassalic world, and especially by its poodle puppets in London.
Never mind this minor detail of human derailment. More importantly, it seems that Mr. Assange’s spirit and that of his creation of truth telling, Wikileaks, is increasingly reflected by politicians and journalists – who, though somehow coopted into the ‘system’, feel discomfort with this very system and decide to leak so-called classified information into the non-mainstream truth-telling media.
A classical case may be the secret ‘RoundTable’ that took place in Washington on 10 April to discuss the fate of Venezuela. The news about it was first published by the Grayzone portal on 13 April.
Mr. Blumenthal has obtained the information along with a “check-in list” of the high-flying participants to this private ‘round-table’. When confronted and asked for interviews on the event, most members on the list were surprised, even stunned, and refused to talk.
Somebody from inside must have leaked the information about the clandestine meeting.
On a totally different issue, but equally important for the concept and philosophy of leaking information to the outside world, is the recent disclosure – “leak” – by someone in the French military that sophisticated French weaponry was used by Saudi Arabia to attack and kill defenseless Yemenis.
And this, although the French – and especially Roi Macron himself, has always denied that the French were participating offensively in this also illegal US-UK-NATO proxy war. The French narrative was and is that France’s weapons were only defensive. Sounds as stupid as calling the US War Ministry, the Ministry of Defense.
Are we entering a Leak-zone (no pun intended) – an epoch of leaking, of divulging ‘secret’ and classified information?
Have we had enough impunity?
It’s time to stop it.
What is this “classified” and secret information anyway?
In a so-called Democracy – why are the elected government officials privileged to hold on to secret information, unknown to the public who lives under the illusion that they elected them, and – more importantly, or even worse – the public, who pays for them.
Can’t you see, dear People, what aberration of “democracy” we have moved into? – Please, just open your eyes and see all these contradictions, contradictions for us, but they serve the chosen- and you believe elected-by-you – elite, lining their pockets and increasing their power.
Now the public must know the truth. This new Leak-Culture may take hold. – If so, its high time, but never too late.
It would be another sign towards the empire heaving on its last breath, or as Andrew Vltchek so adroitly puts it, when he describing the ultimate crime of the lawless London gang, the police manhandling a sick and defenseless Julian Assange, “By dragging him from the embassy into a police van, it [the empire] has admitted that it already has begun sewing its own funeral gown.”
—
Back to Venezuela. Has Washington given up? Most likely not. Although their first coup attempt has failed. The Venezuelan military did not defect.
Despite Trump’s warning, even threats, they stood and still stand behind Nicolás Maduro.
The humanitarian aid trucks at the border in Cúcuta did not cross into Venezuela.
In fact, they were burned by the very opposition, hoping to make believe that Maduro’s troops put them on fire.
No. They were indeed the opposition forces and their allies in Colombia.
Ironically, the mayor of Cúcuta, after the humanitarian aid stayed stuck at the border, asked Colombian President Duque, whether he, the mayor, might distribute the aid among the poor people of Cúcuta, because this aid was more needed in Cúcuta than in Venezuela.
Second, Juan Guaidó was never able to mobilize the crowds as Washington expected. Guaidó, a US lackey in the first place, lacks any charisma. He does not appeal even to the majority of Venezuela’s opposition.
So, he is a dead horse. Bad choice by Washington.
Third, a direct military intervention seems unlikely – at least at this point – as Russia quietly but with considerable force has made known her presence in the country.
And so does China. Though China may not have sent military personnel, China’s position was and is: Don’t mess with Venezuela. China and Russia have both huge investments in Venezuela’s hydrocarbon industry.
In the meantime, Bolton and Pompeo have already accused, in addition to Venezuela, Cuba and Nicaragua as spreading ‘socialism’ in the region.
That’s their crime. It’s now in the open – it’s not just the oil, it’s also ideology. They are going to be sanctioned.
In Cuba invoking again the 1996 Helms–Burton Act, under which foreign companies are prohibited from doing business in Cuba, lest they are prevented from doing business in the US.
In addition, the amount of money Cuban American’s may send home is again limited, after Obama lifted the restrictions. – And exile Cubans – mostly applying to those in Florida – may now sue Cuba in US courts for confiscated and nationalized land after the revolution.
And that after 60 years. I wonder, what US courts have to meddle in Cuba. This latest US arrogance stinks to heaven.
Will the world smell it? – Is Washington at the end of the rope with Venezuela? – Will see. Not voluntarily; that’s for sure. But if leakers keep leaking, it’s a sign that even insiders have had it.
Peter Koenig is an economist and geopolitical analyst. He is also a water resources and environmental specialist. He worked for over 30 years with the World Bank and the World Health Organization around the world in the fields of environment and water. He lectures at universities in the US, Europe and South America. He writes regularly for Global Research; ICH; RT; Sputnik; PressTV; The 21st Century; TeleSUR; The Saker Blog, the New Eastern Outlook (NEO); and other internet sites. He is the author of Implosion – An Economic Thriller about War, Environmental Destruction and Corporate Greed – fiction based on facts and on 30 years of World Bank experience around the globe. He is also a co-author of The World Order and Revolution! – Essays from the Resistance.
Peter Koenig is a Research Associate of the Centre for Research on Globalization. | 2024-04-01T23:14:03.371983 | https://example.com/article/4865 |
NHBC have refused to accept that our house falling apart is covered by the policy Crest Nicholson sold to us. Our house is falling apart as we speak and many of our neighbours with the same build are having the same problem. The major issue with houses is that you can’t do a product recall. […]
I am sure that we are one of many victims of the poor finishing and workmanship carried out by Crest Nicholson. In our area alone (all houses around five years old), there are a large number of houses similar to ours (Wentworth II) that have the outside paintwork peeling from the walls not in isolated places […] | 2024-04-08T23:14:03.371983 | https://example.com/article/7975 |
This process should take about a week and you should closely monitor your pet for any changes in appetite, attitude, or stools. 4healthâ„¢ for Dogs. No wheat, corn, or soy. Antioxidant Formulation. 4healthâ„¢ for Cats. No wheat, corn, or soy. Antioxidant Formulation. 4healthâ„¢ Grain Free. No Wheat, No Corn, No Soy, No Rice.TSC carries 4 Health, Daimond, Retriever, Taste of the Wild, DAD's, Beggin' Strips, Alpo, Gravy Train, Hill's, Iams, Kibbles 'n Bits and Greenies dog food and.Tractor Supply Co. 4health dog food Pet Food Product Database PetfoodIndustry.com.Tractor Supply Company has a Dog Food? Do You want to know More about their brand, 4health? Look No Further because we have ALL the information You .
NUTRO VENISON MEAL, BROWN RICE & OATMEAL ADULT DRY DOG FOOD 30LB. NUTRO VENISON MEAL, BROWN RICE & OATMEAL ADULT DRY .
The 4Health brand of dog food from Tractor Supply Company is actually. dog foods provide a balance of energy and nutrition for active dogs that are free from .
Just used my $10 off on a bag of Earthborn Meadow Feast. I hope my dogs do well on it. It was a good deal! Author. Posts. Viewing 2 posts – 1 .
The Tractor Supply Company was originally started in 1938 as a mail-order. Food; 4health Healthy Weight Dog Food; 4health Grain Free Turkey & Potato Dog Food. What was recalled: All brands of 4health dry pet foods with a “Best Before†.
If I had a dollar for every time someone said: “ The girl at tractor supply said, Or My. You need to consider the dogs' age and lifestyle, activity level and health.Feed your pet's primal hunger with 4health Untamed, a premium pet food specifically. Tractor Supply.
This process should take about a week and you should closely monitor your pet for any changes in appetite, attitude, or stools. 4healthâ„¢ for Dogs. No wheat, corn, or soy. Antioxidant Formulation. 4healthâ„¢ for Cats. No wheat, corn, or soy. Antioxidant Formulation. 4healthâ„¢ Grain Free. No Wheat, No Corn, No Soy, No Rice.TSC carries 4 Health, Daimond, Retriever, Taste of the Wild, DAD's, Beggin' Strips, Alpo, Gravy Train, Hill's, Iams, Kibbles 'n Bits and Greenies dog food and.Tractor Supply Co. 4health dog food Pet Food Product Database PetfoodIndustry.com.Tractor Supply Company has a Dog Food? Do You want to know More about their brand, 4health? Look No Further because we have ALL the information You .Tractor Supply has a $10 off if you spend $50 and sign up for their Loyalty. I mix 4Health stews and the salmon and potato recipes in my dogs' .
Find CountyLine 18 in. Wall Mount Fan in the Fans category at Tractor Supply Co.Moves Air Fast Few things cool a large area better.
Factory Ordered 324021. 18" 1/3HP 115V SINGLE SPEED BARN FAN · 18" 1/3HP 115V SINGLE SPEED BARN FAN · Write the first review .
Keep your greenhouse, barn, warehouse, livestock, home or business cool with the proper circulation or exhaust fans. Built to handle maximum floor area in .
We have a large selection of fans, ventilation units and replacement parts. Brands include DURAFAN, Multifan, Whirl-Wind, Port-A-Cool and more.
Shop for barn and livestock ventilation fans at Fleet Farm. We carry wall mount, exhaust, and shuttered fans for large barns and small horse stalls.
LED Antique Lantern – Tractor Supply Online Store. 6 stall barn with tack room, wash rack, grain room, and 2 bedroom apartment overhead! also from King .
With the predicted heat of 104 degrees today, I bought 2 fans at TSC.. I have purchased their sealed motor fans before for the barn and have .
I've been approved by the higher powers(the wife) to buy a snow blower, this being because I made her go shovel some of the driveway last .
Looking to buy a snowblower. I live in CO and you never know how much or when it is coming. At HD they have a what looks to be nice Cub .
For example, there are a dozen or so heavy-duty snow blowers that are never. .. If I were a company like Husqvarna (or Toro, Honda, Ariens, Cub Cadet) I .
(12). $2,099.99. Cub Cadet 2X (28") 277cc Two-Stage Snow Blower. Model: 28HP. (3). $1,049.99. Ariens Platinum 30 SHO (30") 414cc Two-Stage Snow Blower.
Buy online and pick up in store. Faster Checkout; Neighbor’s Club; Wishlist; Promotional Email; Registering your tax-exempt status. Create an Account. CURRENT SHOPPING SESSION. Click the. Financing Available with Tractor Supply Co. Applies for Business Card · Business Account Log In. Offers Available with the Tractor Supply Personal Credit Card. 5610 Tractor Supply Company jobs available on Indeed.com. Apply to Tractor Trailer Driver, Team Member, Help Desk Analyst and more! 234 Tractor Supply Company jobs available in Florida on Indeed.com.
Apply to Store Manager, Supply Chain Analyst, Material Specialist and more! See who you know at Tractor Supply Company, leverage your professional. See more information about Tractor Supply Company, find and apply to jobs that. To apply, fill out the information and mail or fax your application to the address. Tractor Supply Company® offers two different credit terms: revolving credit with. 1-Click Job Application allows you to apply to 380+ jobs at TRACTOR SUPPLY COMPANY! Find career vacancies near you that are hiring now on ZipRecruiter. | 2023-09-13T23:14:03.371983 | https://example.com/article/9305 |
<?php
declare(strict_types=1);
/*
* This file is part of the SolidWorx Lodash-PHP project.
*
* @author Pierre du Plessis <open-source@solidworx.co>
* @copyright Copyright (c) 2017
*/
use PHPUnit\Framework\TestCase;
use function _\partition;
class PartitionTest extends TestCase
{
public function testPartition()
{
$users = [
['user' => 'barney', 'age' => 36, 'active' => false],
['user' => 'fred', 'age' => 40, 'active' => true],
['user' => 'pebbles', 'age' => 1, 'active' => false],
];
$result = [
[
['user' => 'fred', 'age' => 40, 'active' => true],
],
[
['user' => 'barney', 'age' => 36, 'active' => false],
['user' => 'pebbles', 'age' => 1, 'active' => false],
],
];
$this->assertSame($result, partition($users, function ($user) {
return $user['active'];
}));
}
}
| 2024-02-05T23:14:03.371983 | https://example.com/article/8463 |
Blog
Why Site Hoardings Are An Important Part Of Community Engagement
by Shannell Davies
on 29th November 2018
Although construction site hoardings are sometimes treated as a temporary, disposable part of the construction process, they represent a tremendous opportunity to positively engage nearby residents and boost the contractor’s reputation.
It is an unavoidable fact that initiating any building project automatically enters the construction company into a dialogue with the local community, whether the contractor takes ownership of the situation or not. Plain, undecorated hoardings may be functionally acceptable – but with extra care, these could be used to improve public relations, engage local residents and improve brand equity.
Giving a voice to the local community
Often construction works are seen as an imposition by the local residents, who may feel as though an unsolicited outside force has arrived to fill their environment with machinery, scaffolding, noise, and disruption. They are also likely to feel that there is nothing they can do about it – a situation likely to breed resentment and complaints.
By involving the neighbours in decisions on the design of the site hoardings, a contractor can give them some input in the process; it may be that they would be prepared to tolerate or react positively to the presence of the works in their environment if the hoarding graphics displayed something appealing, an image of local importance, or any other subject of their choice.
By initiating talks or forums with the town hall, local council, or even by polling residents on social media, a construction company can make the locals feel as though they are being listened to and erect hoardings that everybody agrees are more appropriate for the area.
Reducing potential delays and expenses
The majority of contractors work in a manner that is considerate of residents’ needs, attempting to keep noise, dust, and disruption to a minimum. However, if complaints do arise, it’s important to make sure that they don’t delay the work or cause too much unnecessary expense – and hoarding graphics have a part to play in this, too.
Sometimes, badly-judged or entirely undecorated and ugly hoardings can cause neighbours to complain, forcing a time-consuming and potentially expensive process of redesigning and reprinting the graphics – a situation that could have been avoided by speaking to the locals beforehand and asking for their input.
Early discussions can negate these kinds of problems, but to be on the safe side, you could even adopt a policy of approachability into the designs themselves. By using site hoardings to display contact details, a construction company can invite potentially unhappy locals to speak with the site manager or head office to resolve the issue directly and discreetly – and not leave them to complain to the council or local press.
Conveying the nature of the project
Construction projects are sometimes undertaken without much communication to the neighbours as to what is actually being built; often, it’s not always easy for residents in proximity to the site to become aware of the planning stages of a project (aside from the standard planning applications and notices), and are thus expected to tolerate building works in their environment despite having no idea what is happening.
Hoardings, then, are a great opportunity to very clearly illustrate how the local community can expect the finished work to look – and sometimes ideas that may not sound too appealing on paper can be made more palatable by visualising the idea with some artwork to show that the proposed building could look very attractive when completed.
Hoardings can in some circumstances also be used to generate interest for the client’s business; in the case of a block of flats, appealing promotional artwork around the building site could prime the local community to be excited about the new residential opportunities and to make enquiries – improving the standing of the contractor in the eyes of both the local inhabitants and the client.
Mitigating controversy
Sometimes, regrettably, a construction contract may come with a pre-existing dispute – perhaps the local community is unhappy about their tax money being deployed on a project they don’t believe to be a priority, or there might be disagreement about the environmental impact of the building work in a particular location.
Even though these issues may have been under discussion long before the construction company arrives to begin their work, it may well be the contractor who bears the brunt of much of the local displeasure.
The site hoardings, however, are an opportunity to diminish potential ill-feeling and communicate with positive messaging. The printed designs on the hoardings could explain the beneficial impact of the work being undertaken for the local community, and emphasise the contractor’s dedication to cultural sensitivity and environmental protection. In other words, a construction company can show that they have been listening.
In a sense, the hoardings of a building site are the “face” of a contractor; where the plans, contracts, and the construction work itself are often obfuscated from public view, the site hoardings are the one thing prominently on show for all to see – so why present a blank board?
Overall, hoarding graphics represent a tremendous opportunity to increase brand awareness and equity. In time, a construction company can build an emotional association that their business cares about the communities in which it works, listens to the concerns of residents and is invested in the future of local people. | 2024-05-18T23:14:03.371983 | https://example.com/article/9922 |
Reducing Tensions in the Layers of Organizations
by Paul Hobcraft
The really hard part of managing in larger organizations is in managing the layers and competing forces. Often we forget to reinforce acceptable behaviours, we leave role structures lose and incomplete and we set deliverables in often ‘woolly’ ways. This just promotes uncertainly and it is not an adaptive organization in leaving this so open. These unnatural built-in tensions create this shearing effect. They grind against each other, like tectonic plates that force further disruption and upheaval.
These different layers actually require several levels of reconfiguration designed into the organization. One really critical one to address and to ‘kill off,’ is the pressure of time. Time horizons to achieve different tasks often cannot be ‘legislated’ or ‘dictated’ but sadly they are forced on reluctant innovators responsible for delivery of new concepts. We need to re-establish the difference between goals– within a certain period covered (one year), objectives– attained later but are progressed within the period and finally ideals– those unattainable but clearly possible concepts, that progress at slower rates and go well beyond normal goals. Innovation works within this environment, actually it will thrive.
Not just the incremental, but the radical, disruptive and breakthrough innovation craved for by the top management, can finally have a ‘decent’ time horizon to be managed through. Planning needs to account for all three horizons and publically discussed, irrespective of the industry you are in, it does not matter if you are building planes or developing food products.
We really should stop pretending that innovation is not so hard and actually state it is often incompatible to much of what we perform on a daily basis. The task of managing intangibles (unknowns) alongside tangibles (known’s) needs greater appreciation of their complexities, and the difficulties of balancing the two for achieving a ‘decent’ result. Leadership, I believe, would need to understand innovation far more in this demanding environment of enquiry. No wonder it is often ducked and just vaguely talked about as much of innovation understanding is still poorly understood in its impacts and effect.
The opportunity of the network economy
Again, the realization of the growing web of networks that we are constantly engaging with, is become a growing part of the new more adaptive innovating enterprise. We need to encourage more empowerment to engage with outside parties, to explore, to investigate, to bring in and then diffuse and disperse in new ways. For this we need to design around more absorptive capacity I’ve often written about.
Reducing activities and replacing these with outcome orientation
Innovation is no different from what we expect from efficiency or effectiveness; we want to see the outcomes. We have struggled on many parts of establishing the really good metrics for judging innovation. They seem to get lost within organizations. Part of the innovation activities has been assigned to some other cost centre, or the capacity was already established and we often don’t break these down and assign these clearly enough to the different activities, we should, but into outcome orientation ones. Were the activities contributing to efficiency or innovation? We judge these through effectiveness of the outcome.
We need to balance existing performance engines for repeatable everyday tasks with innovation delivery engines for new activities to make our organizations function more effectively. Vijay Govindarajan and Chris Trimble have offered some thoughts on this at the implementation stage, although they are still needs more examination. As Scott Anthony points out in his article “Negotiating Innovation and Control’ on the different ways to balance tension there is one, in my opinion, that needs deeper investigation and development and that is the ‘ambidextrous’ one. This makes distinctions but links the parts of the whole organization by developing competing frames, not competing forces. Roger Martin suggests in one of his books “The Opposable Mind” that we need to develop “integrative thinking” as part of this need to change.
Ecosystems often reflect the shearing effect.
In any environment the ‘rates of exchange’ of the different components or constituents operate at different speeds. Interactions occur more at your own level of contribution, the different layers sometimes you are simply oblivious too or ignore. The ‘in-spite of’ syndrome kicks in. Sometimes though, something catastrophic does occurs and you have to pay attention ( a merger, layoffs, threat of closure) but the real reality is, different layers within organizations tend to be often simply oblivious, even impervious, to necessary change and just ‘does its job’.
Maybe then, this is why so many organizations seem dysfunctional but do continue to survive, to limp along, until something really does disrupt their world as the existing ecosystem just seems to allow different interactions and speeds. Can we not alter this though in more thoughtful ways. than the ‘carrot and the stick’ approach or ‘fear and retribution’ methodologies often employed to achieve results?
The worrying thing is any dynamics within the system are dominated by the slow components, and the rapid components simply have to follow along. “Slow constrains quick, slow controls quick”. The only way to ensure a speeding up is to be coherent on the purpose, clarify the bounds and governing principles that need to be enacted.
Consciously working on our dysfunctional points would help innovation
Simply by consciously working on all the dysfunction points within an organization will certainly reduce the tensions, reduce the shearing and allow the organization in all its layers to ‘react’ and be allowed to come back into a balance, where innovation sits equally alongside efficiency, especially if both focus on outcome orientation and that certainly is not the current business as usual we see today.
Freeing up valuable time to innovate.
Perhaps working on these dysfunction spots it might free up some real, much needed space for innovation to take a deeper hold. It does seem with all the suggested emphasis on efficiency and effectiveness, if you accept this argument, it might be a good idea to have innovation alongside, as it does thrives more when there is creative tensions around!
This article is part two (of two blogs) on built-in tensions within organizations.
Paul Hobcraft runs Agility Innovation, an advisory business that stimulates sound innovation practice, researches topics that relate to innovation for the future, as well as aligning innovation to organizations core capabilities. | 2023-07-31T23:14:03.371983 | https://example.com/article/3869 |
Q:
Inserting data from *.txt file into assoc array
I have a text file 'test.txt' having fruitnames and their scientific names in separate lines.
I want to create an array as
$FRUIT_NAME ( fruit1=>"apple,
SNfruit1=>"Pyrus malus",
fruit2=>"mango",
SNfruit2=>"Mangifera indica" ... )
But, I am getting blank values in SNfruit1, SNfruit2..
Here is the 'test.txt'
SNapple="Pyrus malus"
SNmango="Mangifera indica"
SNbanana="Musa paradisicum"
SNorange="Citrus aurantium"
SNDefault="No SN"
fruit1="apple|$SNapple"
fruit2="mango|$SNmango"
fruit3="banana|$SNbanana"
fruit4="orange|$SNorange"
veg1="potato"
veg2="cauliflower"
Here is the code file 'test.php':
$lines=explode("\n", file_get_contents('test.txt'));
$FRUIT_NAME=[] ;
$result=[];
for($i=0; $i<count($lines); $i++)
{ if (strpos($lines[$i], '=') !== false)
{
$link = explode('=', $lines[$i], 2);
if (strpos(substr($lines[$i], 0, 2), 'SN') !== false)
$result[str_replace('"',"",$link[0])] = $link[1];
else
{ $FName=$link[1];
if (strpos($link[1], '|') !== false)
{
$LINK = explode('|$', $link[1]);
$FName=$LINK[0];
$SN=str_replace('"',"",$LINK[1]);
}
else $SN="SNDefault" ;
$FRUIT_NAME[$link[0]] = $FName ;
//$FRUIT_NAME["SN".$link[0]] = $SN ;
$FRUIT_NAME['SN'.$link[0]] = $result[$SN] ;
}
}
}
foreach ($result as $key => $value) echo "$key::$value".'<br>';
echo '============================================';
foreach ($FRUIT_NAME as $key => $value) echo "$key::$value".'<br>';
A:
Re-write your middle if-else statement:
if (strpos(substr($lines[$i], 0, 2), 'SN') !== false)
$result[str_replace('"',"",$link[0])] = $link[1];
else
with
if (strpos(substr($lines[$i], 0, 2), 'SN') !== false){
$result[$link[0]] = str_replace('"',"",$link[1]);
}
and
$FName=$link[1];
if (strpos($link[1], '|') !== false) {
$LINK = explode('|$', $link[1]);
$FName=$LINK[0];
$SN=str_replace('"',"",$LINK[1]);
} else $SN="SNDefault" ;
$FRUIT_NAME[$link[0]] = $FName ;
$FRUIT_NAME['SN'.$link[0]] = $result[$SN] ;
with
$link[1] = str_replace('"','',$link[1]);
if (strpos($link[1], '|$') !== false) {
$sublink = explode('|$', $link[1]);
$FRUIT_NAME[$link[0]] = $sublink[0];
$FRUIT_NAME["SN".$link[0]] = $result[trim($sublink[1])];
} else {
$FRUIT_NAME[$link[0]] = $link[1] ;
}
then outputs will be:
SNapple::Pyrus malus
SNmango::Mangifera indica
SNbanana::Musa paradisicum
SNorange::Citrus aurantium
SNDefault::No SN
============================================
fruit1::apple
SNfruit1::Pyrus malus
fruit2::mango
SNfruit2::Mangifera indica
fruit3::banana
SNfruit3::Musa paradisicum
fruit4::orange
SNfruit4::Citrus aurantium
veg1::potato
veg2::cauliflower
The problem was in true and false parts.
In true you did str_replace of wrong element, that's why you've received values like "apple instead of clean apple.
In false part you didn't trim, that's why indexes were incorrect and so your $FRUIT_NAME was built not so correctly.
Note: echo '============================================'.'<br>';
| 2023-09-16T23:14:03.371983 | https://example.com/article/8977 |
In a cloud computing scenario, magnetic disk data of a virtual machine (Virtual Machine, VM), including data of a system disk and of a data disk, is under a security risk. If full disk encryption is performed on VM data and a key is held by a user, unauthorized personnel are incapable of obtaining data of the user. In this way, sensitive data of the user in the cloud is protected to a great degree.
A conventional full disk encryption technology, as a solution to terminal security, is already mature. In the conventional technology, before booting an operation system, that is, in a pre-boot (Pre-boot) phase, a key may be generated by a boot loader (boot loader) program according to a password input by the user. Data on the magnetic disk is decrypted by use of the key. The decrypted data includes an operation system (Operation System, OS), and the operation system may be booted after being decrypted.
In the foregoing conventional full disk encryption technology, the user executes an operation on a single terminal, and the boot loader program may obtain the key. However, in a cloud application scenario, a key needed by the VM needs to be obtained from an external cloud platform. Before the operation system of the VM is booted, the VM does not have an IP address and is incapable of communicating with the outside, thereby being incapable of obtaining the key. Therefore, the operation system of the VM cannot be booted, which causes the VM to be halted in the pre-boot phase. | 2023-12-21T23:14:03.371983 | https://example.com/article/3774 |
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