Datasets:

inputs
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655k
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from collections import defaultdict def char_freq(message): frequency = defaultdict(lambda: 0) for letter in list(message): frequency[letter] += 1 return frequency
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): unique = set(message) freq = dict(list(zip(unique, [0]*len(unique)))) for s in message: freq[s] += 1 return freq
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from itertools import groupby def char_freq(message): return { x: len(list(gp)) for x, gp in groupby(sorted(message)) }
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dic = {} for each in message: try: if dic[each]: dic[each] += 1 except KeyError: dic[each] = 1 return(dic)
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): s = set(message) n = [message.count(i) for i in s] return dict(zip(s,n))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from collections import Counter as c def char_freq(m): return dict(c(m))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from collections import Counter def char_freq(message): return dict(Counter(list(message)))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
char_freq = lambda s: {e:s.count(e) for e in set(s)}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): return dict(zip(list(message), [message.count(c) for c in message]))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
import collections def char_freq(message): return collections.Counter(message) import collections def char_freq(message): letters = collections.defaultdict(int) for letter in message: letters[letter] += 1 return letters
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from collections import defaultdict def char_freq(message): char_dict = defaultdict(int) for c in message: char_dict[c] += 1 return char_dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from typing import Dict def char_freq(message: str) -> Dict[int, str]: """ Get the frequency of each and every character! """ return dict([(_, message.count(_)) for _ in sorted(set(message))])
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): count = {} for character in message: count.setdefault(character, 0) count[character] += 1 return count
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
char_freq = lambda m, counter = __import__('collections').Counter: counter(m)
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): return { m: message.count(m) for m in message }
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
char_freq=lambda m:{i:list(m).count(i) for i in set(m)}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
char_freq = lambda m: {c:m.count(c) for c in m}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
char_freq = lambda message:{x:message.count(x) for x in message}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(m): s = list(m) k = set(s) v = list(map(lambda x: s.count(x), k)) return dict(zip(k, v))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
lets = "().!?,-' 0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPRQSTUVWXYZ" def char_freq(message): retDict={} for l in lets: if message.count(l)>0: retDict[l]= message.count(l) return retDict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): ABC = "abcdefghijklmnopqrstuvwxyz ABCDEFGHIJKLMNOPQRSTUVWXYZ" count = [] letters = [] for l in message: c = message.count(l) if c>0: count.append(c) letters.append(l) return dict(zip(letters,count)) pass
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(m): o={} for i in range(0,len(m)): if not o.get(m[i]): o[m[i]]=1 else: o[m[i]]=o[m[i]]+1 return o
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
char_freq = __import__("collections").Counter
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(string): my_dict = {} for s in string: n = string.count(s) my_dict[s] = n return my_dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): char = {} for i in message: if i in char: char[i] += 1 else: char[i] = 1 return char
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): characters = {} for char in message: characters[char] = characters.get(char,0)+ 1 return(characters)
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): frequency_table = {} for char in message: frequency_table[char] = frequency_table.get(char, 0)+ 1 return(frequency_table)
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): str_ = {} for i in message: if i in str_: str_[i] += 1 else: str_[i] = 1 return str_
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): chars = list(message) counts = [message.count(char) for char in chars] return {chars[i]:counts[i] for i in range(len(chars))}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dct = {} for key in message: dct[key] = message.count(key) return dct
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dict = {} characters = [] for letter in message: if letter not in characters: characters.append(letter) dict[letter] = message.count(letter) return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): arr = [] dict = {} for i in message: arr.append(i) for i in arr: arr.count(i) dict[i] = arr.count(i) return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): freqs = {} index = 0 while index < len(message): if message[index] not in list(freqs.keys()): freqs[message[index]] = 1 else: freqs[message[index]] += 1 index += 1 return freqs
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): my_dict = {} for i in message: my_dict[i] = my_dict.get(i, 0) + 1 return my_dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dict = {} chars = set(message) for char in chars: dict[char] = message.count(char) return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): char_list = [str(a) for a in message] return {x: char_list.count(x) for x in (char_list)}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dict = {} for char in message: dict[char] = 0 for char in message: dict[char] = dict[char] + 1 return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): l = {} for n in message: l[n] = message.count(n) n.replace(n, '') return l
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): message = sorted(list(message)) d = {message[i]: message.count(message[i]) for i in range(len(message))} return d
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dict={} for i in message: if i in dict: dict[i] = dict[i] + 1 else: dict[i] = 1 return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): char_list = list(message) keys = set(char_list) map = {} for key in keys: map[key] = char_list.count(key) return map
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dictCh = {} for ch in message: if ch not in dictCh.keys(): dictCh[ch] = 1 else: dictCh[ch] += 1 return dictCh
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): arr = [*message] _dict={} for i in arr: _dict[i] = _dict.get(i, 0) + 1 return _dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): char = {} for c in message : if c in char : char[c] += 1 else : char[c] = 1 return char
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from collections import defaultdict, Counter def char_freq(message): my_dict = {} for letter in message: my_dict[letter] = my_dict.get(letter, 0) + 1 return my_dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): a = {} for i in message: if i not in a: a.setdefault(i,1) else: a[i]+=1 return a
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): r = {} for m in message: r[m] = r.get(m, 0)+1 return r
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): d=dict.fromkeys(message, 0) for string in message: d[string]+=1 return d
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): char_dict = {} for letter in message: if letter not in char_dict: char_dict[letter] = 1 else: char_dict[letter] = char_dict[letter] + 1 return char_dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(msg): res = {} for c in msg: try: res[c] += 1 except KeyError: res[c] = 1 return res
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): liste=[] dict={} liste_count=[message.count(letter) for letter in message] for letter in message: liste.append(letter) i=0 for i in range(0,len(liste)): dict[liste[i]]=liste_count[i] i+=1 return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): return dict(map(lambda letter: (letter, message.count(letter)), message))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): return {chr: message.count(chr) for chr in message}
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): chars = {} for char in message: try: chars[char] = 1 + chars[char] except: chars[char] = 1 return chars
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dict = {}; for x in message: if not(x in dict): dict[x] = 1 else: dict[x] += 1 return dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): print(message) d = dict() for c in message: d[c] = d.get(c,0) + 1 sorted_dict = dict(sorted(d.items(), key=lambda item: item[0])) return sorted_dict
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): a = {} for i in message: if i not in a: a[i] = 0 a[i] += 1 return a
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): r = {} for x in message: r[x] = r.get(x, 0) + 1 return r
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): result = {} for character in message: if character in result: result[character] += 1 else: result[character] = 1 return result
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): x = {} for i in range(len(message)): x[message[i]] = message.count(message[i]) return x
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): diccionario = {} for x in message: if x in diccionario: diccionario[x] += 1 else: diccionario[x] = 1 return diccionario
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): msgL = list(message) msgD = dict.fromkeys(msgL) for i in msgL: if msgD[i] is None: msgD[i] = 0 msgD[i] +=1 return msgD
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): d = dict() chars = list(message) for char in chars: d[char] = d.get(char,0) + 1 return d
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): set(message) character_counts = {} for i in set(message): count = message.count(i) character_counts[i] = count return character_counts pass
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): d = {}.fromkeys(set(list(message)), 0) for i in message: d[i] += 1 return d
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): solution = {} for c in message: if c in solution: solution[c] += 1 continue solution[c] = 1 return solution
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): freq = {} for c in message: if not c in freq: freq[c] = 0 freq[c] += 1 return freq
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): out = {} for el in message: if el not in out.keys(): out[el] = 1 else: out[el] += 1 return out
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(n): d = {} for i in n: d[i] = n.count(i) return d
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): count = {} for n in message: if (count.get(n)) != None: count[n] = count[n] + 1 else: count[n] = 1 return count
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
from collections import Counter def char_freq(message: str) -> dict: return dict(Counter(c for c in message))
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
import collections def char_freq(message): hashing = collections.defaultdict(int) for i in message: hashing[i]+=1 return hashing
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): a = {} for i in message: if i not in a: a[i] = 1 else: a[i] +=1 return a
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): a = list(dict.fromkeys(message)) dicts ={} for x in a: dicts[x] = message.count(x) return dicts
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dict = {} for x in message: if x not in list(dict.keys()): dict[x] = 1 else: dict[x] += 1 return(dict)
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): arr=list(message) arr=list(dict.fromkeys(arr)) res={} for i in arr: res[i]=message.count(i) return res
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): res = {} for v in message: if v not in res: res[v] = message.count(v) return res
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): d = {} for s in message: if s not in d: d[s] = 1 else: d[s] = d[s] + 1 return d
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): print(message) chars = {} for char in range(len(message)) : if message[char] not in chars : chars[message[char]] = 1 else : chars[message[char]] = chars[message[char]] + 1 return chars
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): cnt = dict() for ch in list(message): print('ch : ', ch) if ch in cnt: cnt[ch] += 1 else: cnt[ch] = 1 return cnt
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): words = dict() for i in message: words[i] = words.get(i,0)+1 return words pass
## Description Welcome, Warrior! In this kata, you will get a message and you will need to get the frequency of each and every character! ## Explanation Your function will be called `char_freq`/`charFreq`/`CharFreq` and you will get passed a string, you will then return a dictionary (object in JavaScript) with as keys the characters, and as values how many times that character is in the string. You can assume you will be given valid input. ## Example ```python char_freq("I like cats") // Returns {'a': 1, ' ': 2, 'c': 1, 'e': 1, 'I': 1, 'k': 1, 'l': 1, 'i': 1, 's': 1, 't': 1} ```
def char_freq(message): dct = {} for char in message: dct[char] = dct.get(char,0) + 1 return dct
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
import re def my_very_own_split(string, delimiter = None): if delimiter == '': raise ValueError('empty delimiter') if delimiter == None: delimiter = '\s+' else: delimiter = re.escape(delimiter) pos = 0 for m in re.finditer(delimiter, string): yield string[pos:m.start()] pos = m.end() yield string[pos:]
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
def my_very_own_split(string, delimiter=None): if delimiter == '': raise ValueError if delimiter is None: string = string.replace('\t', ' ') while ' ' in string: string = string.replace(' ', ' ') delimiter = ' ' last, l = 0, len(delimiter) for i in range(len(string)): if string[i:i+l] == delimiter: yield string[last:i] last = i+l yield string[last:]
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
def my_very_own_split(string, delimiter = None): for s in __import__('string').split(string,delimiter): yield s
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
# I think the anti-cheat failed somewhere my_very_own_split = str.split
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
def my_very_own_split(string, delimiter=None): for w in eval('string.split(delimiter)'): yield w
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
import re def my_very_own_split(string, delimiter=None): if delimiter == '': raise ValueError('empty separator') delim_re = re.escape(delimiter) if delimiter is not None else r'\s+' for s in getattr(re, 'split')(delim_re, string): yield s
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
import re def my_very_own_split(string, delimiter=None): if delimiter == '': raise ValueError('empty separator') if delimiter == None: delimiter = re.compile(r'\s+') else: delimiter = re.compile(re.escape(delimiter)) print(delimiter) start = 0 for m in re.finditer(delimiter, string): yield string[start:m.start()] start = m.end() yield string[start:]
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
from string import whitespace, maketrans convert_whitespace = lambda s: s.translate(maketrans(whitespace, ' ' * len(whitespace))) def my_very_own_split(strng, sep=None): start, fil = 0, False if sep == '': raise ValueError("empty separator") if sep is None: sep, fil, strng = ' ', True, convert_whitespace(strng) while start <= len(strng): end = strng.find(sep, start) if end < 0: end = len(strng) if not fil or strng[start: end]: yield strng[start: end] start = end + len(sep)
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
from re import escape, split as my_split def my_very_own_split(string, delimiter = None): if delimiter == '': raise None for s in my_split(r'{0}'.format(escape(delimiter) if delimiter else '[\s\t$]+'), string): yield s
Quite recently it happened to me to join some recruitment interview, where my first task was to write own implementation of built-in split function. It's quite simple, is it not? However, there were the following conditions: * the function **cannot** use, in any way, the original `split` or `rsplit` functions, * the new function **must** be a generator, * it should behave as the built-in `split`, so it will be tested that way -- think of `split()` and `split('')` *This Kata will control if the new function is a generator and if it's not using the built-in split method, so you may try to hack it, but let me know if with success, or if something would go wrong!* Enjoy!
def my_very_own_split(string, delimiter = None): return string.split(delimiter)
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def solution(M1, M2, m1, m2, V, T) : return (m1/M1+m2/M2)*0.082*(T+273.15)/V
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def solution(M1, M2, m1, m2, V, T): return (m1 / M1 + m2 / M2) * (T + 273.15) * .082 / V
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def solution(molar_mass1, molar_mass2, given_mass1, given_mass2, volume, temp) : # 1 - Calculate the amount of substance in moles n1 = given_mass1 / molar_mass1 n2 = given_mass2 / molar_mass2 # 2 - Convert the temperature from Celcius to kelvin Temp_Kelvin = temp + 273.15 # 3 - Enter the gas constant R = 0.082 # 4 - Calculate the ideal gas law P1 = (n1 * R * Temp_Kelvin) / volume P2 = (n2 * R * Temp_Kelvin) / volume # 5 - Apply Dalton's law P = P1 + P2 return P
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def solution(molar_mass1, molar_mass2, given_mass1, given_mass2, volume, temp) : t = temp + 273.15 R = 0.082 n_mol1 = given_mass1 / molar_mass1 n_mol2 = given_mass2 / molar_mass2 return (n_mol1 * R * t/volume) + (n_mol2 * R * t/volume)
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def pressure(molar_mass, given_mass, v, t) : return given_mass*0.082*(t+273.15)/molar_mass/v def solution(molar_mass1, molar_mass2, given_mass1, given_mass2, volume, temp) : return pressure(molar_mass1, given_mass1, volume, temp) + \ pressure(molar_mass2, given_mass2, volume, temp)
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def solution(molar_mass1, molar_mass2, given_mass1, given_mass2, volume, temp) : temp += 273.15 R = 0.082 n = given_mass1/molar_mass1 + given_mass2/molar_mass2 return n*R*temp/volume
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
def solution(M1, M2, m1, m2, V, T): t = T + 273.15 return 0.082 * (m1/M1 + m2/M2) * t / V
Given the moleculer mass of two molecules ( __M1__ and __M2__ ), their masses present ( __m1__ and __m2__ ) in a vessel of volume ( __V__ ) at a specific temperature ( __T__ ). Find the total pressure exerted by the molecules ( __Ptotal__ ) . input ==== Six values : - __m1__ - __m2__ - __M1__ - __M2__ - __V__ - __T__ output ==== One value : - __Ptotal__ notes ==== Units for each of the following are given as under : - _m1_ = gram - _m2_ = gram - _M1_ = _gram.mole^(-1)_ - _M2_ = _gram.mole^(-1)_ - _V_ = _dm^(3)_ - _T_ = Celsius - __Ptotal__ = atmpspheric pressure (_atm_) Remember : Temperature is given in Celsius while SI unit is Kelvin (_K_) 0 Celsius = 273.15Kelvin The gas constant (_R_) has value of _0.082dm^(3).atm.K^(-1).mol^(-1)_
solution=lambda m,n,M,N,V,T:(M/m+N/n)*0.082*(T+273.15)/V