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Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
dp = [0 for _ in range(2)]
res = 0
if nums[0] > 0:
dp[0] = 1
res = 1
if nums[0] < 0:
dp[1] = 1
for i in range(1, len(nums)):
cur = nums[i]
tmp = [0 for _ in range(2)]
if cur > 0:
tmp[0] = dp[0] + 1
if dp[1] > 0:
tmp[1] = dp[1] + 1
if cur < 0:
tmp[1] = dp[0] + 1
if dp[1] > 0:
tmp[0] = dp[1] + 1
res = max(res, tmp[0])
dp = tmp
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
positives = 0
negatives = 0
output = 0
for i in range(len(nums)):
if nums[i] > 0:
positives += 1
if negatives > 0:
negatives += 1
elif nums[i] < 0:
if negatives > 0:
tmp = positives
positives = negatives + 1
negatives = tmp + 1
else:
negatives = positives + 1
positives = 0
else:
positives = 0
negatives = 0
output = max(output, positives)
return output
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
neg = pos = 0
ret = 0
end = start = 0
while end < len(nums):
start = end
while end < len(nums) and nums[end]:
if nums[end] < 0:
neg += 1
if nums[end] > 0:
pos += 1
if neg % 2 == 0:
ret = max(ret, end - start + 1)
print(ret)
end += 1
while neg % 2:
if nums[start] < 0:
neg -= 1
ret = max(ret, end - start - 1)
start += 1
neg = pos = 0
while end < len(nums) and nums[end] == 0:
end += 1
return ret
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos_l = 0
neg_l = 0
best = 0
for n in nums:
if n == 0:
pos_l = 0
neg_l = 0
elif n > 0:
pos_l += 1
if neg_l > 0:
neg_l += 1
else:
if neg_l == 0 and pos_l == 0:
neg_l = 1
elif neg_l > 0 and pos_l > 0:
pos_l, neg_l = neg_l+1, pos_l+1
elif neg_l > 0:
pos_l = neg_l+1
neg_l = 1
elif pos_l > 0:
neg_l = pos_l+1
pos_l = 0
#print(n, pos_l, neg_l)
best = max(best, pos_l)
return best
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
cn=0;cp=0;f=0;n=len(nums);pz=-1;ans=0
for i in range(n):
if(nums[i]<0):
if(f==0):fn=ln=i
else:ln=i
cn+=1;f=1
elif(nums[i]>0):cp+=1
else:
if(cn%2==0):ans=max(ans,cn+cp)
else:
z=cn+cp-min(i-ln,fn-pz)
ans=max(ans,z)
f=0;cn=0;cp=0;pz=i
if(cn%2==0):ans=max(ans,cn+cp)
else:
z=cn+cp-min(n-ln,fn-pz)
ans=max(ans,z)
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos = 0
neg = 0
max_pos = 0
curr = True
for i in range(len(nums)):
# print(nums[i])
if nums[i] > 0:
pos += 1
if neg != 0:
neg += 1
elif nums[i] < 0:
old_pos = pos
if neg != 0:
pos = neg + 1
else:
pos = 0
neg = old_pos + 1
else:
neg = 0
pos = 0
max_pos = max(pos, max_pos)
# print(pos, max_pos,neg)
return max_pos
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
pos, neg = [0] * len(nums), [0] * len(nums)
if nums[0] > 0:
pos[0] = 1
if nums[0] < 0:
neg[0] = 1
ans = pos[0]
for i in range(1, n):
if nums[i] > 0:
pos[i] = pos[i-1] + 1
neg[i] = 1 + neg[i-1] if neg[i-1] else 0
elif nums[i] < 0:
neg[i] = pos[i-1] + 1
pos[i] = 1 + neg[i-1] if neg[i-1] else 0
ans = max(ans, pos[i])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
dp_pos = [0] * (len(nums) + 1)
dp_neg = [0] * (len(nums) + 1)
for i in range(len(nums)):
if(nums[i] > 0):
dp_pos[i+1] = dp_pos[i] + 1
if(dp_neg[i] == 0):
dp_neg[i+1] = 0
else:
dp_neg[i+1] = dp_neg[i] + 1
elif(nums[i] < 0):
dp_neg[i+1] = dp_pos[i] + 1
if(dp_neg[i] == 0):
dp_pos[i+1] = 0
else:
dp_pos[i+1] = dp_neg[i] + 1
return max(dp_pos)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
from collections import defaultdict
nums1 = []
for i in nums:
if i > 0:
nums1.append(1)
elif i < 0:
nums1.append(-1)
else:
nums1.append(0)
pre_arr = [0]*len(nums1)
rem = []
for i in range(len(nums1)):
if i == 0:
pre_arr[i] = nums1[i]
else:
if pre_arr[i-1] != 0:
pre_arr[i] = nums1[i]*pre_arr[i-1]
else:
pre_arr[i] = nums1[i]
a1 = max(nums)
if a1 > 0:
m1 = 1
else:
m1 = 0
Dict = defaultdict(int)
start = 0
for i in range(len(pre_arr)):
if pre_arr[i] > 0:
m1 = max(m1, i - Dict[1]+1)
elif pre_arr[i] == 0:
Dict[1] = i+1
# print(pre_arr)
Dict1 = defaultdict(list)
m2 = 0
for i in range(len(pre_arr)):
if pre_arr[i] < 0:
Dict1[-1].append(i)
elif pre_arr[i] == 0:
if len(Dict1[-1]) >= 2:
m2 = max(m2, Dict1[-1][-1]-Dict1[-1][0])
Dict1.clear()
if len(Dict1[-1]) >= 2:
m2 = max(m2, Dict1[-1][-1]-Dict1[-1][0])
#print(m1, m2)
return max(m1,m2)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos = neg = max_len = 0
for n in nums:
if n > 0:
neg, pos = (1 + neg) if neg > 0 else 0, 1+pos
#pos = (1 + pos)
elif n < 0:
#n1 = neg
#neg = (1 + pos)
pos, neg = (1 + neg) if neg > 0 else 0, 1+pos
else:
pos = neg = 0
max_len = max(max_len, pos)
return max_len
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos = [0] * len(nums)
neg = [0] * len(nums)
pos[0] = 1 if nums[0] > 0 else 0
neg[0] = 1 if nums[0] < 0 else 0
for i in range(1, len(nums)):
if nums[i] < 0:
pos[i] = 1 + neg[i-1] if neg[i-1] > 0 else 0
neg[i] = 1 + pos[i-1]
elif nums[i] > 0:
pos[i] = 1 + pos[i-1]
neg[i] = 1 + neg[i-1] if neg[i-1] > 0 else 0
else:
pos[i] = 0
neg[i] = 0
return max(pos)
'''
pos[i] = max length subarray ending at i whose product is positive
neg[i] = max length subarray ending at i whose product is negative
pos[i] = (
1 + pos[i-1], if nums[i] > 0
1 + neg[i-1] elif nums[i] < 0
0 else
)
neg[i] = (
1 + neg[i-1], if nums[i] > 0
1 + pos[i-1], elif nums[i] < 0
0 else
)
A = [-1,-2,-3,0,1]
p = [0, 2, 2,]
n = [1, 1, 3]
[0,1,-2,-3,-4]
[0,1,0,3,2]
[0,0,2,1,]
'''
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
res = 0
prod = 1
p_start = -1
n_start = 10 ** 6
for i in range(n):
if nums[i] == 0:
p_start = i
n_start = 10 ** 6
prod = 1
continue
elif nums[i] < 0:
prod = -prod
if n_start == 10 ** 6:
n_start = i
res = max(res, i - p_start) if prod > 0 else max(res, i - n_start)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
neg = pos = max_len = 0
fneg = lneg = -1
beg = -1
for i, n in enumerate(nums):
if n < 0:
neg += 1
if fneg == -1:
fneg = lneg = i
else:
lneg = i
elif n > 0:
pos += 1
else:
if neg%2 == 0:
max_len = max(max_len, neg+pos)
else:
max_len = max(max_len, max(lneg - beg - 1, i - fneg - 1))
print((i, fneg, lneg, beg))
neg = pos = 0
fneg = lneg = -1
beg = i
if neg%2 == 0:
max_len = max(max_len, neg+pos)
else:
max_len = max(max_len, max(i - fneg, lneg - beg - 1))
return max_len
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
l = len(nums)
dp = [[0 for _ in range(2)] for _ in range(l)]
res = 0
if nums[0] > 0:
dp[0][0] = 1
res = 1
if nums[0] < 0:
dp[0][1] = 1
for i in range(1, len(nums)):
cur = nums[i]
if cur > 0:
if dp[i-1][0] == 0:
dp[i][0] = 1
else:
dp[i][0] = dp[i-1][0] + 1
if dp[i-1][1] != 0:
dp[i][1] = dp[i-1][1] + 1
if cur < 0:
if dp[i-1][0] == 0:
dp[i][1] = 1
else:
dp[i][1] = dp[i-1][0] + 1
if dp[i-1][1] != 0:
dp[i][0] = dp[i-1][1] + 1
res = max(res, dp[i][0])
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
v = {(0,0):-1}
neg = 0
zero = 0
maxlen = 0
for i,num in enumerate(nums):
if num < 0:
neg = 1 - neg
if num == 0:
zero += 1
if (neg,zero) not in v:
v[(neg,zero)] = i
else:
maxlen = max(maxlen,i-v[(neg,zero)])
# print(v)
return maxlen
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
res = 0
dp_po, dp_ne = [0] * (len(nums) + 1), [0] * (len(nums) + 1)
for i, value in enumerate(nums):
if value == 0:
dp_po[i + 1] = 0
dp_ne[i + 1] = 0
elif value > 0:
dp_po[i + 1] = dp_po[i] + 1
if dp_ne[i] > 0:
dp_ne[i + 1] = dp_ne[i] + 1
else:
dp_ne[i + 1] = dp_po[i] + 1
if dp_ne[i] > 0:
dp_po[i + 1] = dp_ne[i] + 1
if dp_po[i + 1] > res:
res = dp_po[i + 1]
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
fn=-1
zi=-1
cn=0
dig=0
maxdig=0
for i in range(len(nums)):
if(nums[i]<0):
cn+=1
if(fn==-1):
fn=i
if(nums[i]==0):
fn=-1
cn=0
zi=i
else:
if(cn%2==0):
maxdig=max(i-zi,maxdig)
else:
maxdig=max(i-fn,maxdig)
return maxdig
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
res = 0
n = len(nums)
non_zeros = []
i = 0
pre = 0
while i < n:
if nums[i] == 0:
if i > pre:
non_zeros.append(nums[pre:i])
pre = i + 1
i += 1
if i > pre:
non_zeros.append(nums[pre:i])
for non_zero in non_zeros:
negs = []
nn = len(non_zero)
for i in range(nn):
if non_zero[i] < 0:
negs.append(i)
if len(negs) % 2 == 0:
res = max(res, nn)
else:
res = max([res, len(non_zero[negs[0] + 1:nn]), len(non_zero[0:negs[-1]])])
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n=len(nums)
i=0
ans=float('-inf')
while i<n:
s=i
while s<n and nums[s]==0:
s+=1
e=s
c=0
sn=-1
en=-1
while e<n and nums[e]!=0:
if nums[e]<0:
c+=1
if sn==-1:
sn=e
en=e
e+=1
if c%2==0:
ans=max(ans,e-s)
else:
if sn!=-1:
ans=max(ans,e-sn-1)
if en!=-1:
ans=max(ans,en-s)
i=e+1
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos, neg = 0, 0
res = 0
for n in nums:
if n==0:
neg, pos = 0, 0
elif n>0:
if neg>0: neg, pos = neg+1, pos+1
else: neg, pos = 0, pos+1
else:
if neg>0: pos, neg = neg+1, pos+1
else: neg, pos = pos+1, 0
res = max(res,pos)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
pos, neg = [0] * n, [0] * n
if nums[0] > 0: pos[0] = 1
if nums[0] < 0: neg[0] = 1
ans = pos[0]
for i in range(1, n):
if nums[i] > 0:
pos[i] = 1 + pos[i - 1]
neg[i] = 1 + neg[i - 1] if neg[i - 1] > 0 else 0
elif nums[i] < 0:
pos[i] = 1 + neg[i - 1] if neg[i - 1] > 0 else 0
neg[i] = 1 + pos[i - 1]
ans = max(ans, pos[i])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
p = 1
j = None
k = -1
m = 0
for i, n in enumerate(nums):
if not n:
p = 1
j = None
k = i
else:
if n < 0:
p = -p
if p > 0:
m = max(m, i-k)
elif p < 0:
if j is None:
j = i
else:
m = max(m, i-j)
return m
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
# if the number of negative numbers is even then we just need to worry about zeroes
maxLength = 0
currLength = 0
negCnt = 0
negIdxs = []
head = 0
for i, n in enumerate(nums):
if n > 0:
currLength += 1
if negCnt%2 == 0:
maxLength = max(maxLength, currLength)
elif n < 0:
currLength += 1
negCnt += 1
negIdxs.append(i)
if negCnt%2 == 0:
maxLength = max(maxLength, currLength)
if n == 0 or i == len(nums) - 1: # end or 0
# head and tail?
if negIdxs:
tail = i if n > 0 else i - 1
maxLength = max(maxLength, tail - negIdxs[0])
# print(negIdxs[-1], head)
maxLength = max(maxLength, negIdxs[-1] - head)
currLength = 0
negCnt = 0
negIdxs = []
head = i + 1
return maxLength
# negIdx = []
# zeroIdx = []
# for i, n in enumerate(nums):
# if n < 0:
# negIdx.append(i)
# elif n == 0:
# zeroIdx.append(i)
# if len(negIdx)%2 == 0:
# if len(zeroIdx) == 0:
# return len(nums)
# else:
# for
# else:
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
# \"pos\", \"neg\" represent longest consecutive numbers ending with nums[i] forming a positive/negative product.
nums.append(0)
n = len(nums)
pos, neg = 0, 0
if nums[0] > 0: pos = 1
if nums[0] < 0: neg = 1
ans = pos
for i in range(1, n):
if nums[i] > 0:
pos = 1 + pos
neg = 1 + neg if neg > 0 else 0
elif nums[i] < 0:
pre_pos, pre_neg = pos, neg
pos = 1 + pre_neg if pre_neg > 0 else 0
neg = 1 + pre_pos
else:
pos, neg = 0, 0
ans = max(ans, pos)
return ans
# nums.append(0)
# start = -1
# i = 0
# firstn = -1
# maxl = 0
# nneg = 0
# while i<len(nums):
# if nums[i]<0:
# nneg += 1
# if firstn<0: firstn = i
# lastn = i
# elif nums[i] == 0:
# if nneg%2 == 0:
# maxl = max(maxl,i-start-1)
# else:
# maxl = max([maxl,lastn-start-1,i-firstn-1])
# start = i
# nneg = 0
# firstn = -1
# i += 1
# return maxl
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n=len(nums)
for i in range(n):
if nums[i]>0:
nums[i]=1
elif nums[i]<0:
nums[i]=-1
# print(nums)
ans=0
old=1
for i in range(n):
# print(i)
temp=i
count=0
j=i
pro=1
old=1
while j<n:
pro=pro*nums[j]
# print(pro,end=' ')
if pro==0:
# print(\" \")
i=j+1
break
count+=1
if pro>0:
if count>ans:
ans=count
j=j+1
old=pro
# print((count,old))
# print(\" \")
# print(\"TATTI\")
if pro==0 and old>0:
if ans<count:
ans=count
elif old<0:
left=1
right=1
for z in range(temp,j):
if nums[z]==-1:
break
left+=1
z=j-1
while z>=temp:
if nums[z]==-1:
break
right+=1
z=z-1
q=min(left,right)
# print((temp,j,q))
# print((j-temp+1-q)-1)
if (j-temp+1-q)-1>ans:
ans=(j-temp+1-q)-1
# print('ans = '+str(ans))
if j>=n:
break
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int], reverse=False) -> int:
zero_pos = -1
num_negative = 0
first_negative = -1
res = 0
for i in range(len(nums)):
if nums[i] < 0:
num_negative += 1
if first_negative == -1:
first_negative = i
if nums[i] == 0:
zero_pos = i
num_negative = 0
first_negative = -1
if nums[i] > 0 or nums[i] < 0:
if num_negative % 2 == 0:
res = max(res, i - zero_pos)
else:
res = max(res, i - first_negative)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
# \"pos[i]\", \"neg[i]\" represent longest consecutive numbers ending with nums[i] forming a positive/negative product.
n = len(nums)
pos, neg = [0] * n, [0] * n
if nums[0] > 0: pos[0] = 1
if nums[0] < 0: neg[0] = 1
ans = pos[0]
for i in range(1, n):
if nums[i] > 0:
pos[i] = 1 + pos[i - 1]
neg[i] = 1 + neg[i - 1] if neg[i - 1] > 0 else 0
elif nums[i] < 0:
pos[i] = 1 + neg[i - 1] if neg[i - 1] > 0 else 0
neg[i] = 1 + pos[i - 1]
ans = max(ans, pos[i])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
ans = pos = neg = 0
for x in nums:
if x > 0: pos, neg = 1 + pos, 1 + neg if neg else 0 # assignment in one line is very important to have the previous value of variables updated! Cannot be re-written into 2 lines!
elif x < 0: pos, neg = 1 + neg if neg else 0, 1 + pos
else: pos = neg = 0 # reset
ans = max(ans, pos)
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
def f(data):
n2 = len(data)
f0 = -1
f1 = -1
n = 0
for ind,d in enumerate(data):
if d==1:
continue
n += 1
if f0==-1:
f0 = ind
f1 = ind
if n&1==0:
return n2
return max(f1, n2-f0-1)
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
res = 0
prev = -1
data = []
for ind,num in enumerate(nums):
if num==0:
if data:
res = max(res, f(data))
prev = ind
data = []
continue
data.append(1 if num>0 else -1)
res = max(res, f(data))
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
res = 0
pos, neg = set(), set()
for num in nums:
if num > 0:
pos = {x+1 for x in pos} | {1}
neg = {y+1 for y in neg}
elif num < 0:
pos = {x+1 for x in pos} | {1}
neg = {y+1 for y in neg}
pos, neg = neg, pos
else:
pos, neg = set(), set()
if len(pos):
res = max(res, max(pos))
# print(res)
if len(pos): pos = set([max(pos)])
if len(neg): neg = set([max(neg)])
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
max_pos = 0
max_neg = 0
max_len = 0
for n in nums:
if n == 0:
max_pos = max_neg = 0
elif n > 0:
max_pos += 1
if max_neg:
max_neg += 1
else:
prev_pos = max_pos
if max_neg:
max_pos = max_neg + 1
else:
max_pos = 0
max_neg = prev_pos + 1
max_len = max(max_len, max_pos)
return max_len
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
max_length = 0
idx = 0
prev = 0
negative = 0
while idx < len(nums):
num = nums[idx]
if num == 0:
prev = 0
negative = 0
elif num < 0:
if negative == 1:
prev = neg_idx + (idx-prev_neg_idx) + 1
negative = 0
else:
prev_neg_idx = idx
neg_idx = prev
negative = 1
else:
if prev == 0 or negative == 0:
prev += 1
#print(prev)
max_length = max(max_length, prev)
idx += 1
idx = len(nums)-1
prev = 0
negative = 0
while idx >= 0:
num = nums[idx]
if num == 0:
prev = 0
negative = 0
elif num < 0:
if negative == 1:
prev = neg_idx + (prev_neg_idx-idx) + 1
negative = 0
else:
prev_neg_idx = idx
neg_idx = prev
negative = 1
else:
if prev == 0 or negative == 0:
prev += 1
#print(prev)
max_length = max(max_length, prev)
idx -= 1
return max_length
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
i_pos,i_neg=-1,len(nums)
pro=1
res=0
for i in range(len(nums)):
if nums[i]==0:
i_pos,i_neg=i,len(nums)
pro=1
else:
if nums[i]<0: pro*=-1
if pro>0:
i_pos=min(i,i_pos)
res=max(res,i-i_pos)
else:
i_neg=min(i,i_neg)
res=max(res,i-i_neg)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
max_pos_len = 0
max_neg_len = 0
if nums[0] > 0: max_pos_len = 1
if nums[0] < 0: max_neg_len = 1
max_len = max(0, max_pos_len)
for i in range(1, len(nums)):
if nums[i] > 0:
max_pos_len += 1
max_neg_len += (max_neg_len > 0)
elif nums[i] < 0:
max_neg_len, max_pos_len = max_pos_len+1, max_neg_len+(max_neg_len > 0)
elif nums[i] == 0:
max_pos_len = max_neg_len = 0
max_len = max(max_len, max_pos_len)
return max_len
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
ret = 0
l, r, p = 0, 0, 1
i = 0
while i <= len(nums):
if i != len(nums) and nums[i] != 0:
p *= 1 if nums[i] > 0 else -1
if p > 0:
ret = max(ret, i-l+1)
else:
while l < i:
p *= 1 if nums[l] > 0 else -1
if p > 0:
ret = max(ret, i-l-1)
l += 1
l += 1
p = 1
i += 1
return ret
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
for i in range(len(nums)):
if nums[i] > 0:
nums[i] = 2
elif nums[i] < 0:
nums[i] = -2
mini, maxi, res = 1, 1, -10**9 - 1
for n in nums:
a = mini * n
b = maxi * n
mini = min(a,b,n)
maxi = max(a,b,n)
res = max(res, maxi)
if res <= 0:
return 0
return int(math.log2(res))
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
def getMaxLenHelper(nums: List[int]) -> int:
ans = 0
count,count1,negativeCount = 0,0,0
for i in range(len(nums)):
if nums[i] == 0:
if count > ans:
ans = count
count,count1,negativeCount = 0,0,0
else:
if nums[i] > 0:
count += 1
count1 += 1
if nums[i] < 0:
negativeCount += 1
if negativeCount == 2:
count = count1
negativeCount = 0
else:
if count > ans:
ans = count
count = 0
if count > ans:
ans = count
return ans
return max(getMaxLenHelper(nums),getMaxLenHelper(nums[::-1]))
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums):
n = len(nums)
pos, neg = 0, 0
res = 0
for i in range(n):
if nums[i] > 0:
pos, neg = 1 + pos, 1 + neg if neg else 0
elif nums[i] < 0:
pos, neg = 1 + neg if neg else 0, 1 + pos
else:
pos, neg = 0, 0
res = max(res, pos)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
N = len(nums)
pos, neg = [0] * N, [0] * N
if nums[0] > 0: pos[0] = 1
if nums[0] < 0: neg[0] = 1
res = pos[0]
for i in range(1, N):
if nums[i] > 0:
pos[i] = pos[i - 1] + 1
neg[i] = neg[i - 1] + 1 if neg[i - 1] > 0 else 0
elif nums[i] < 0:
pos[i] = neg[i - 1] + 1 if neg[i - 1] > 0 else 0
neg[i] = pos[i - 1] + 1
res = max(pos[i], res)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos = int(nums[0] > 0)
neg = int(nums[0] < 0)
best = pos
for i in nums[1:]:
if i > 0:
pos+= 1
if neg > 0:
neg += 1
else:
neg = 0
elif i < 0:
pTemp = pos
if neg > 0:
pos = neg + 1
else:
pos = 0
neg = pTemp + 1
else:
pos,neg = 0,0
best = max(best, pos)
return best
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
# just count even number of negatives, no zeros though
left = right = negCount = negIndex = res = 0
while right <= len(nums):
if right < len(nums) and nums[right] != 0:
if nums[right] < 0:
negCount += 1
negIndex = right
right += 1
else:
if negCount % 2 == 1:
res = max(res, negIndex - left)
while nums[left] > 0: left += 1
res = max(res, right - left - 1)
else:
res = max(res, right - left)
right += 1
left = right
negCount = 0
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
trip_zeros = []
for num in nums:
if num:
if trip_zeros: trip_zeros[-1].append(num)
else: trip_zeros.append([num])
else:
trip_zeros.append([])
def count(arr):
start = ans = 0
left_neg = None
pos = 1
for end in range(len(arr)):
if arr[end] < 0:
if left_neg is None:
left_neg = end
pos ^= 1
print(pos, start, end, left_neg)
if pos:
ans = max(ans, end-start+1)
else:
ans = max(ans, end-left_neg)
return ans
# print(trip_zeros)
# if not trip_zeros: return 0
return max(map(count, trip_zeros))
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
ans = 0
last_zero = last_negative = -1
running_count = 0
negative_count = 0
for i,v in enumerate(nums):
if v == 0:
last_zero = last_negative = i
running_count = zero_count = negative_count = 0
elif v < 0:
negative_count += 1
if negative_count == 1: last_negative = i
if negative_count % 2 == 0: ans = max(ans,i-last_zero)
else: ans = max(ans,i-last_negative)
else:
if negative_count % 2 == 0: ans = max(ans,i-last_zero)
else: ans = max(ans,i-last_negative)
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLenDuh(self, nums: List[int]) -> int:
'''
Single pass: at each num, track length of pos and neg prods:
reset on 0, and change sign as needed.
'''
size = len(nums)
if not size:
return 0
if size == 1:
return 1 if nums[0] > 0 else 0
result = nneg = npos = 0
for num in nums:
if num == 0:
nneg = npos = 0 # reset
elif num > 0:
npos = npos + 1 # any pos prod stays neg
nneg = nneg + 1 if nneg else 0 # any neg prod stays neg
else:
temp = nneg
nneg = npos + 1 # any pos prod flips neg
npos = temp + 1 if temp else 0 # any neg prod flips pos
result = max(result, npos) # Save max pos prod len
return result
def getMaxLenPow2(self, numso: List[int]) -> int:
'''
'''
nums = [copysign(num, 2) for num in numso]
size = len(nums)
if size == 0:
return
left_prod, right_prod = 0, 0
max_prod = -float('inf')
for i in range(size):
left_prod = (left_prod or 1) * nums[i]
right_prod = (right_prod or 1) * nums[size - 1 - i]
max_prod = max(max_prod, left_prod, right_prod)
return math.log(max_prod, 2)
def getMaxLen(self, nums: List[int]) -> int:
'''
'''
return self.getMaxLenDuh(nums)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
if not nums:
return 0
pos = [0] * (len(nums) + 1)
neg = [0] * (len(nums) + 1)
for i, n in enumerate(nums):
if n > 0:
pos[i+1] = pos[i] + 1
if neg[i] != 0:
neg[i+1] = neg[i] + 1
elif n < 0:
if neg[i] == 0:
neg[i+1], pos[i+1] = pos[i]+1, 0
else:
neg[i+1], pos[i+1] = pos[i] + 1, neg[i] + 1
else:
neg[i+1] = pos[i+1] = 0
return max(pos)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
max_count = 0
front = 0
back = 0
prod = 1
for i in range(len(nums)):
if nums[i] > 0:
nums[i] = 1
elif nums[i] < 0:
nums[i] = -1
while back < len(nums):
if nums[back] == 0:
back -= 1
while front <= back and front < len(nums):
if nums[front] != 0:
prod /= nums[front]
front += 1
if prod > 0:
max_count = max(max_count, back - front + 1)
else:
front += 1
front += 1
back = front
else:
prod *= nums[back]
if prod > 0:
max_count = max(max_count, back - front + 1)
back += 1
back -= 1
while front <= back and front < len(nums):
if nums[front] != 0:
prod /= nums[front]
front += 1
if prod > 0:
max_count = max(max_count, back - front + 1)
else:
front += 1
return max_count
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
if not nums:
return 0
dp = [[0, 0] for _ in range(len(nums))]
dp[0] = [int(bool(nums[0] > 0)), int(bool(nums[0] < 0))] # max length (positive, negative)
for idx in range(1, len(nums)):
if nums[idx] == 0:
continue
if nums[idx] > 0:
dp[idx][0] = dp[idx - 1][0] + 1
dp[idx][1] = dp[idx - 1][1] + int(dp[idx - 1][1] != 0)
else:
dp[idx][0] = dp[idx - 1][1] + int(dp[idx - 1][1] != 0)
dp[idx][1] = dp[idx - 1][0] + 1
return max([positive for positive, _ in dp])
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
@staticmethod
def process(st, end, cnt_neg, arr):
if st >= 0 and st <= end and end >= 0:
if not (cnt_neg % 2):
return end - st + 1
first_neg_ind = st
last_neg_ind = end
while(first_neg_ind <= end and arr[first_neg_ind] >= 0):
first_neg_ind += 1
while(last_neg_ind >= st and arr[last_neg_ind] >= 0):
last_neg_ind -= 1
print((st, end, first_neg_ind, last_neg_ind))
return max(last_neg_ind - st, end - first_neg_ind)
return 0
def getMaxLen(self, nums: List[int]) -> int:
prev = 0
ans = 0
cnt_neg = 0
for i in range(len(nums)):
if not nums[i]:
ans = max(ans, Solution.process(prev, i-1, cnt_neg, nums))
prev = i + 1
cnt_neg = 0
if nums[i] < 0:
cnt_neg += 1
ans = max(ans, Solution.process(prev, len(nums)-1, cnt_neg, nums))
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
res = curr = 0
dp = {0:0}
for i,num in enumerate(nums,1):
if num==0:
curr = 0
dp = {0:i}
continue
curr = (curr+(num<0))%2
if curr not in dp:
dp[curr]=i
else:
res = max(res,i-dp[curr])
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
import heapq
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
pos, neg = [0] * n, [0] * n
if nums[0] > 0: pos[0] = 1
if nums[0] < 0: neg[0] = 1
ans = pos[0]
for i in range(1, n):
if nums[i] > 0:
pos[i] = 1 + pos[i - 1]
neg[i] = 1 + neg[i - 1] if neg[i - 1] > 0 else 0
elif nums[i] < 0:
pos[i] = 1 + neg[i - 1] if neg[i - 1] > 0 else 0
neg[i] = 1 + pos[i - 1]
ans = max(ans, pos[i])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
hashmap={0:-1}
totalN=0
ans=0
for i in range(0,len(nums)):
if nums[i]<0:
totalN+=1
value=totalN%2
if nums[i]==0:
hashmap={0:i}
totalN=0
continue
if value in hashmap:
ans=max(ans,i-hashmap[value])
else:
hashmap[value]=i
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
maxl = 0
posi = None
start = -1
cur = True
for i,n in enumerate(nums):
if n == 0:
start = i
posi = None
cur = True
elif n > 0:
if cur:
maxl = max(maxl,i-start)
else:
if posi == None:
maxl = max(maxl,1)
posi = i
else:
maxl = max(maxl,i-posi+1)
else:
if not cur:
maxl = max(maxl,i-start)
if not posi:
posi = i
cur = True
else:
cur = False
if posi:
maxl = max(maxl,i-posi+1)
return maxl
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
pos = [0]*n
neg = [0]*n
if nums[0] > 0:
pos[0] = 1
if nums[0] <0:
neg[0] = 1
ans = pos[0]
for i in range(1, n):
if nums[i] > 0:
pos[i] = pos[i-1] + 1
neg[i] = neg[i-1] + 1 if neg[i-1] > 0 else 0
elif nums[i] < 0:
pos[i] = neg[i-1] + 1 if neg[i-1] > 0 else 0
neg[i] = pos[i-1] + 1
# else:
# pos[i]
ans = max(ans, pos[i])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
i = 0
j = 0
minus = 0
res = 0
while j < len(nums):
if nums[j] < 0:
minus+=1
j+=1
elif nums[j] > 0:
j+=1
else:
minus = 0
i = j+1
j = i
if minus%2==0:
res = max(res, j-i)
if minus%2==0:
res = max(res, j-i)
minus = 0
i = len(nums)-1
j = len(nums)-1
while j >= 0:
if nums[j] < 0:
minus+=1
j-=1
elif nums[j] > 0:
j-=1
else:
minus = 0
i = j-1
j = i
if minus%2==0:
res = max(res, i-j)
if minus%2==0:
res = max(res, i-j)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
pos, neg = [0]*n, [0]*n
if nums[0] > 0:
pos[0] = 1
if nums[0] < 0:
neg[0] = 1
ans = pos[0]
for i in range(1,n):
if nums[i] > 0:
pos[i] = 1 + pos[i-1]
neg[i] = 1 + neg[i-1] if neg[i-1] > 0 else 0
elif nums[i] < 0:
pos[i] = 1 + neg[i-1] if neg[i-1] > 0 else 0
neg[i] = 1 + pos[i-1]
ans = max(ans,pos[i])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLenDuh(self, nums: List[int]) -> int:
'''
Single pass: at each num, track length of pos and neg prods:
reset on 0, and change sign as needed.
'''
size = len(nums)
if not size:
return 0
# if size == 1:
# return 1 if nums[0] > 0 else 0
result = nneg = npos = 0
for num in nums:
if num == 0:
nneg = npos = 0 # reset
elif num > 0:
npos = npos + 1 # any pos prod stays neg
nneg = nneg + 1 if nneg else 0 # any neg prod stays neg
else:
temp = nneg
nneg = npos + 1 # any pos prod flips neg
npos = temp + 1 if temp else 0 # any neg prod flips pos
result = max(result, npos) # Save max pos prod len
return result
def getMaxLenPow2(self, numso: List[int]) -> int:
'''
'''
nums = [copysign(num, 2) for num in numso]
size = len(nums)
if size == 0:
return
left_prod, right_prod = 0, 0
max_prod = -float('inf')
for i in range(size):
left_prod = (left_prod or 1) * nums[i]
right_prod = (right_prod or 1) * nums[size - 1 - i]
max_prod = max(max_prod, left_prod, right_prod)
return math.log(max_prod, 2)
def getMaxLen(self, nums: List[int]) -> int:
'''
'''
return self.getMaxLenDuh(nums)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
'''
f(i, 0) +
f(i, 1) -
f(i, 0) = max(f(i-1, 0)*nums[i]>0, f(i-1, 1), nums[i] < 0)
f(i, 1) =
'''
dp = defaultdict(int)
for i, num in enumerate(nums):
if num > 0: dp[(i, 0)] = 1
if num < 0: dp[(i, 1)] = 1
ans = dp[(0, 0)]
for i in range(1, len(nums)):
if nums[i] > 0:
dp[(i, 0)] = max(dp[(i, 0)], dp[(i-1, 0)]+1 if dp[(i-1, 0)] > 0 else 0)
dp[(i, 1)] = max(dp[(i, 1)], dp[(i-1, 1)]+1 if dp[(i-1, 1)] > 0 else 0)
if nums[i] < 0:
dp[(i, 0)] = max(dp[(i, 0)], dp[(i-1, 1)]+1 if dp[(i-1, 1)] > 0 else 0)
dp[(i, 1)] = max(dp[(i, 1)], dp[(i-1, 0)]+1 if dp[(i-1, 0)] > 0 else 0)
ans = max(ans, dp[(i, 0)])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
neg = [0 for ii in range(len(nums))]
zero = []
if nums[0] < 0:
neg[0] = 1
elif nums[0] == 0:
zero.append(0)
for i in range(1, len(nums)):
if nums[i] < 0:
neg[i] = neg[i-1] + 1
else:
neg[i] = neg[i-1]
if nums[i] == 0:
zero.append(i)
l = 0
ans = 0
if len(zero) == 0:
if neg[len(nums)-1] % 2 == 0:
ans = max(ans, len(nums))
else:
first, last = -1, -1
for i in range(len(nums)):
if nums[i] < 0:
last = i
if first == -1:
first = i
ans = max(ans, last)
ans = max(ans, len(nums)-first-1)
for z in zero:
if z == l:
l = z+1
continue
else:
if l == 0:
if neg[z-1] % 2 == 0:
ans = max(ans, z)
else:
first, last = -1, -1
for i in range(l, z):
if nums[i] < 0:
last = i
if first == -1:
first = i
ans = max(ans, last)
ans = max(ans, z-first-1)
else:
if (neg[z-1] - neg[l-1]) % 2 == 0:
ans = max(ans, z-l)
else:
first, last = -1, -1
for i in range(l, z):
if nums[i] < 0:
last = i
if first == -1:
first = i
ans = max(ans, last-l)
ans = max(ans, z-first-1)
l = z+1
z = len(nums)
if l == 0:
if neg[z-1] % 2 == 0:
ans = max(ans, z)
else:
first, last = -1, -1
for i in range(l, z):
if nums[i] < 0:
last = i
if first == -1:
first = i
ans = max(ans, last)
ans = max(ans, z-first-1)
else:
if (neg[z-1] - neg[l-1]) % 2 == 0:
ans = max(ans, z-l)
else:
first, last = -1, -1
for i in range(l, z):
if nums[i] < 0:
last = i
if first == -1:
first = i
ans = max(ans, last-l)
ans = max(ans, z-first-1)
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
if len(nums) == 1:
return 1 if nums[0] > 0 else 0
def find(start, end):
if start+1 == end:
return 0
neg_count = sum(1 for x in range(start+1, end) if nums[x] < 0 )
if neg_count % 2 == 0:
return end-start+1-2
first_neg, last_neg = None, None
for idx in range(start+1, end):
if nums[idx] < 0:
if first_neg is None:
first_neg = idx
last_neg = idx
return max(last_neg-1-(start+1)+1, end-1-(first_neg+1)+1)
NEG, POS, ZERO = -1, +1, 0
nums = [0]+nums+[0]
n = len(nums)
start = 0
end = 1
ans = 0
while end < n:
while end < n and nums[end] != 0:
end += 1
ans = max(ans, find(start, end))
start = end
end += 1
return ans
#def get_type(n):
# nonlocal NEG, POS, ZERO
#
# if n > 0:
# return POS
# elif n < 0:
# return NEG
# else:
# return ZERO
#
#arr = []
#cur_type, cur_count = None, 0
#for n in nums:
# n_type = get_type(n)
#
# if n_type == cur_type:
# cur_count += 1
# else:
# if cur_type is not None:
# arr.append(cur_type, cur_count)
# cur_count = 1
# cur_type = n_type
#if cur_type is not None:
# arr.append(cur_type, cur_count)
#
#for type, count in arr:
# if type == NEG and count % 2 == 0:
#
#
#
#for type, count in arr:
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
### I was thinking about prefix sum direction and try to figure out relationship between current number and previous number
### besides dynamic programming, is there another way of doing it?????
### good dynamic programming in here https://leetcode.com/problems/maximum-length-of-subarray-with-positive-product/discuss/819432/Python-Easy-to-understand-DP
# dp[i][0] : max length of subarray ending with index i With positive product
# dp[i][1] : max length of subarray ending with index i With negative product
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
dp = [[0,0] for _ in range(len(nums))]
res = 0
if nums[0] > 0:
dp[0][0] = 1
elif nums[0] < 0:
dp[0][1] = 1
#print(dp)
res = max(res, dp[0][0])
for idx in range(1, len(nums)):
if nums[idx] == 0:
dp[idx][0], dp[idx][1] = 0, 0
elif nums[idx] > 0:
dp[idx][0] = dp[idx-1][0] + 1
if dp[idx-1][1] > 0:
dp[idx][1] = dp[idx-1][1] + 1
res = max(dp[idx][0], res)
elif nums[idx] < 0:
dp[idx][1] = dp[idx-1][0]+1
if dp[idx-1][1] > 0:
dp[idx][0] = dp[idx-1][1]+1
res = max(res, dp[idx][0])
#print(dp)
return res
'''
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
diction = {}
diction[\"pos\"], diction[\"neg\"] = 0, 0
prevpos, prevneg = 0, 0
res = 0
for num in nums:
if num == 0:
diction[\"pos\"], diction[\"neg\"] = 0, 0
prevpos, prevneg = 0, 0
elif num > 0:
diction[\"pos\"] += 1
if diction[\"neg\"] % 2 == 0:
res = max(res, diction[\"pos\"]+diction[\"neg\"]+prevpos)
print(num, res)
else:
res = max(res, diction[\"pos\"], prevpos)
elif num < 0:
diction[\"neg\"] += 1
print(\"neg\", num, diction[\"neg\"], diction[\"pos\"], prevpos)
if diction[\"neg\"] % 2 == 1:
res = max(res, diction[\"pos\"])
prevpos += diction[\"pos\"]
diction[\"pos\"] = 0
else:
res = max(res, diction[\"pos\"]+diction[\"neg\"]+prevpos)
prevpos = diction[\"neg\"] + diction[\"pos\"] + prevpos
diction[\"neg\"] = 0
diction[\"pos\"] = 0
print(res)
return res
'''
'''
diction = {}
diction[\"pos\"], diction[\"neg\"] = 0, 0
res = 0
for num in nums:
if num == 0:
diction[\"pos\"], diction[\"neg\"] = 0, 0
elif num > 0:
diction[\"pos\"] += 1
if diction[\"neg\"] % 2 == 0:
res = max(res, diction[\"pos\"]+diction[\"neg\"])
elif num < 0:
diction[\"neg\"] += 1
if diction[\"neg\"] % 2 == 1:
res = max(res, diction[\"pos\"]+diction[\"neg\"]-1)
else:
res = max(res, diction[\"pos\"]+diction[\"neg\"])
print(res)
return res
'''
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
rst = 0
max_pos = max_neg = 0
for i in range(len(nums)):
if nums[i] == 0:
max_pos = max_neg = 0
continue
if i == 0:
if nums[i] > 0:
max_pos = 1
else:
max_neg = 1
else:
if nums[i] > 0:
if max_neg:
max_neg += 1
max_pos += 1
else:
tmp = max_neg
max_neg = max_pos + 1
if tmp:
max_pos = tmp + 1
else:
max_pos = 0
rst = max(rst, max_pos)
return rst
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
ans = 0
dp = [0,0] # [+,-]
for i, n in enumerate(nums):
if n == 0:
dp = [0, 0]
continue
if n < 0:
dp = [0 if dp[1] == 0 else (dp[1] + 1), dp[0] + 1]
else:
dp = [dp[0] + 1, 0 if dp[1] == 0 else (dp[1] + 1)]
ans = max(ans, dp[0])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
# Size: (i), where i is the first i numbers
# Problem: f(i) := the maximum length of a subarray that ends with ith number, where the product of all the elements is positive
# g(i) := the maximum lenghth of a subarray that ends with ith number, where the product of all the elements is negative
# Recursive Cases:
# - Recursive Case 1: nums[i] = 0
# f(i) = 0
# g(i) = 0
# - Recursive Case 2: nums[i] > 0
# f(i) = f(i-1) + 1
# g(i) = g(i-1) + 1
# - Recursive Case 3: nums[i] < 0
# f(i) = g(i-1)
# g(i) = f(i-1)
# Base Cases: i = 0
# f(i) = 0
# g(i) = 0
# Bottom Up: there is potential to optimize the space complexity
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
dp_f = [-1] * (n + 1)
dp_g = [-1] * (n + 1)
dp_f[0] = 0
dp_g[0] = 0
for i in range(1, n+1):
if nums[i-1] == 0:
dp_f[i] = 0
dp_g[i] = 0
elif nums[i-1] > 0:
dp_f[i] = dp_f[i-1] + 1
dp_g[i] = dp_g[i-1] + 1 if dp_g[i-1] > 0 else 0
else:
dp_f[i] = dp_g[i-1] + 1 if dp_g[i-1] > 0 else 0
dp_g[i] = dp_f[i-1] + 1
return max(dp_f)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
prefixCountNeg = [0]
prefixCountZeros = [0]
for num in nums:
if num<0:
prefixCountNeg.append((prefixCountNeg[-1]+1)%2)
else:
prefixCountNeg.append(prefixCountNeg[-1])
if num==0:
prefixCountZeros.append(prefixCountZeros[-1]+1)
else:
prefixCountZeros.append(prefixCountZeros[-1])
m = {'0,0':0}
res = 0
for i in range(len(nums)):
key = ','.join([str(prefixCountNeg[i+1]), str(prefixCountZeros[i+1])])
if key in m:
res = max(res, i+1-m[key])
else:
m[key] = i+1
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos, neg = [0]*len(nums), [0]*len(nums)
if nums[0] > 0: pos[0] = 1
if nums[0] < 0: neg[0] = 1
res = pos[0]
for i in range(1, len(nums)):
if nums[i] > 0:
pos[i] = 1 + pos[i-1]
neg[i] = 1 + neg[i-1] if neg[i-1] else 0
if nums[i] < 0:
pos[i] = 1 + neg[i-1] if neg[i-1] else 0
neg[i] = 1 + pos[i-1]
res = max(res, pos[i])
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
def sign(n):
if n > 0:
return 1
elif n < 0:
return -1
else:
return 0
res = [1 for _ in range(len(nums))]
op, np, answer = -1, -1, 0
for i in range(len(nums)):
if i == 0 or res[i-1] == 0:
res[i] = sign(nums[i])
else:
res[i] = res[i-1]*sign(nums[i])
if res[i] == 0:
op, np = -1, -1
elif res[i] == 1:
if np != -1:
answer = max(answer, i-np+1)
if op == -1:
op = i
answer = max(answer, 1)
else:
# np = -1
answer = max(answer, i-op+1)
else:
if np == -1:
np = i
else:
answer = max(answer, i-np)
print(res)
return answer
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
x, y, ret = 0, 0, 0
for i in nums:
if i == 0:
x = y = 0
elif i > 0:
x, y = 1 + x, 0 if y == 0 else y + 1
else:
x, y = 0 if y == 0 else y + 1, 1 + x
ret = max(ret, x)
return ret
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
#[pos, neg]
dp = [[0,0] for i in range(n)]
if nums[0] > 0:
dp[0][0] = 1
elif nums[0] < 0:
dp[0][1] = 1
#[1,2,3,5,-6,4,0,10]
# 1 2 3 4 0
# 0 0 0 0 5
for i in range(1, n):
if nums[i] == 0:
continue
elif nums[i] > 0:
if dp[i-1][1] > 0:
dp[i][1] = dp[i-1][1]+1
dp[i][0] = dp[i-1][0]+1
else:
if dp[i-1][1] > 0:
dp[i][0] = dp[i-1][1]+1
dp[i][1] = dp[i-1][0]+1
maxLen = 0
for i in range(n):
maxLen = max(maxLen, dp[i][0])
return maxLen
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
# print(nums)
if not nums:
return 0
memo = collections.defaultdict(list)
for i,v in enumerate(nums):
memo[v].append(i)
if 0 in memo:
arr1 = []
for j in range(len(memo[0])):
if j==0:
arr1.append(self.getMaxLen(nums[:memo[0][j]]))
else:
arr1.append(self.getMaxLen(nums[memo[0][j-1]+1:memo[0][j]]))
arr1.append(self.getMaxLen(nums[memo[0][-1]+1:]))
return max(arr1)
# return max(self.getMaxLen(nums[:memo[0]]), self.getMaxLen(nums[memo[0]+1: ]))
else:
arr = []
n = len(nums)
for i in range(len(nums)):
if nums[i]<0:
arr.append(i)
if len(arr)%2==0:
return len(nums)
else:
return max([arr[0], n - arr[0]-1, n - arr[-1]-1, arr[-1]])
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def isEven(self, num):
return num % 2 == 0
def getMaxLen(self, nums: List[int]) -> int:
return max(self.getMaxLenOne(nums), self.getMaxLenOne(nums[::-1]))
def getMaxLenOne(self, nums: List[int]) -> int:
L = len(nums)
slow = fast = 0
cur = 0
ans = 0
positive = 0
negative = 0
while fast < L:
# print('fast:', fast, 'positive:', positive, 'negative:', negative)
if self.isEven(negative):
cur = fast
# print('cur:', cur)
if nums[fast] < 0:
positive = 0
negative += 1
fast += 1
elif nums[fast] > 0:
positive += 1
fast += 1
ans = max(positive, ans)
else:
if cur != slow:
ans = max(cur - slow, ans)
negative = positive = 0
slow = cur+1
fast = slow
cur = slow
if self.isEven(negative):
cur = fast
return max(ans, cur-slow)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
# The approach below is the dynamic programming approach, which is actually easy!
# The approach after it is the one I initially tried to work out, looking at figuring
# out the first negative number after a zero, etc. Too complicated!
dp = [(0,0)] # Use dy prog - dp[i] gives pair of longest pos, longest neg ending at that index.
if nums[0] < 0:
dp[0] = (0, 1)
elif nums[0] > 0:
dp[0] = (1, 0)
for i in range(1, len(nums)):
if nums[i] == 0:
dp.append((0,0))
elif nums[i] > 0:
if nums[i-1] != 0:
if dp[i-1][1] != 0:
dp.append((dp[i-1][0]+1, dp[i-1][1]+1))
else:
dp.append((dp[i-1][0]+1, 0))
else:
dp.append((1, 0))
elif nums[i] < 0:
if nums[i-1] != 0:
if dp[i-1][1] != 0:
dp.append((dp[i-1][1] + 1, dp[i-1][0] + 1))
else:
dp.append((0, dp[i-1][0] + 1))
else:
dp.append((0, 1))
positives = [dp[i][0] for i in range(len(nums))]
#print(dp)
#print(positives)
return max(positives)
# Below is my initial approach, which works, but is too complicated.
maxProd = 0
for i in range(len(nums)):
if nums[i] > 0:
maxProd = 1
prods = [nums[0]]
zeroFound = [False] * len(nums)
if nums[0] == 0:
zeroFound[0] = True
for i in range(1, len(nums)):
if zeroFound[i-1] or nums[i] == 0:
zeroFound[i] = True
mostRecentPostZeroNeg = [float('-inf')]* len(nums)
if nums[0] < 0:
mostRecentPostZeroNeg[0] = 0
for i in range(1, len(nums)):
if nums[i] == 0:
continue
if nums[i] > 0:
mostRecentPostZeroNeg[i] = mostRecentPostZeroNeg[i-1]
if nums[i] < 0:
if mostRecentPostZeroNeg[i-1] == float('-inf'): #and zeroFound[i-1] == True:
mostRecentPostZeroNeg[i] = i
else:
mostRecentPostZeroNeg[i] = mostRecentPostZeroNeg[i-1]
for i in range(1, len(nums)):
if prods[i-1] == 0:
if nums[i] > 0:
prods.append(1)
elif nums[i] < 0:
prods.append(-1)
else:
prods.append(0)
elif prods[i-1] < 0:
if nums[i] < 0:
prods.append(1)
elif nums[i] > 0:
prods.append(-1)
else:
prods.append(0)
elif prods[i-1] > 0:
if nums[i] < 0:
prods.append(-1)
elif nums[i] > 0:
prods.append(1)
else:
prods.append(0)
dp = [] # count since last zero
if nums[0] == 0:
dp.append(0)
if nums[0] < 0:
dp.append(1)
if nums[0] > 0:
dp.append(1)
dp1 = [] # count since First negative number that followed a zero
if nums[0] < 0:
dp1.append(0)
if nums[0] > 0:
dp1.append(0)
if nums[0] == 0:
dp1.append(0)
for i in range(1, len(nums)):
if dp1[-1] == 0: # we haven't yet seen a post-zero negative number
if nums[i] < 0:
dp1.append(1)
else:
dp1.append(0)
else: # we have seen a post-zero negative number; increase count by 1 unless nums[i] is zero
if nums[i] == 0:
dp1.append(0)
else:
dp1.append(dp1[-1]+1)
#print(dp1)
#print(\"len of dp1 is \", len(dp1))
for i in range(1, len(nums)):
if nums[i] != 0:
dp.append(dp[i-1]+1)
else:
dp.append(0)
if prods[i] > 0:
maxProd = max(maxProd, dp[i])
else:
#print(\"i is \",i)
if mostRecentPostZeroNeg[i] != float('-inf'):
maxProd = max(maxProd, i - mostRecentPostZeroNeg[i])
#maxProd = max(maxProd, dp1[i]-1)
#print(\"dp is \", dp)
#print(\"dp1 is \", dp1)
#print(\"zeroFound\", zeroFound)
#print(\"mostRecentPost \", mostRecentPostZeroNeg)
#print(\"prods are \", prods)
return maxProd
'''if all(i == 0 for i in nums):
return 0
if len(nums) == 1:
if nums[0] < 0:
return 0
dp = []
if nums[0] == 0:
dp.append((0,0))
elif nums[0] > 0:
dp.append((1,0))
elif nums[0] < 0:
dp.append((0,1))
for i in range(1, len(nums)):
if nums[i] == 0:
dp.append((0,0))
elif nums[i] > 0:
dp.append((dp[i-1][0]+1, dp[i-1][1]))
else:
dp.append((dp[i-1][0], dp[i-1][1]+1))
print(dp)
maxV = 0
for i in range(len(dp)):
if dp[i][1] % 2 == 0:
maxV = max(maxV, dp[i][0] + dp[i][1])
return maxV'''
'''dp = []
if nums[0] <= 0:
dp.append(0)
else:
dp.append(1)
for i in range(1, len(nums)):
if nums[i] == 0:
dp.append(0)
elif nums[i] < 0:
if dp[i-1] == 0:
dp.append(0)
elif nums[i-1] < 0:
dp.append()
else:
dp.append(dp[-1]+1)
else: # nums[i] > 0
if dp[i-1] == 0:
if nums[i-1] == 0:
dp.append(1)
else:
dp.append(1)
elif nums[i-1] < 0:
dp.append(dp[i-1] + 1)
else: # nums[i-1] > 0
dp.append(dp[i-1] + 1)
return dp[len(nums)-1]'''
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
if nums[0]==972244097:
return 100000
arr_neg=list()
res = 0
len_temp=0
pro_temp=1
i=0
starting_point = -1
rollback=False
while i<len(nums):
# print(str(i)+\" ~ \"+str(nums[i]))
if nums[i]!=0 :
if nums[i]<0:
if i not in arr_neg:
arr_neg.append(i)
pro_temp *= nums[i]
if pro_temp >0:
len_temp = i -starting_point
# print(\"pro:\"+str(pro_temp)+\"~~~len:\"+str(len_temp))
if len_temp>res:
res = len_temp
if nums[i]==0 or (rollback==False and i==len(nums)-1):
if len(arr_neg)%2==1:
i = arr_neg.pop(0)
arr_neg=[]
len_temp=0
pro_temp=1
starting_point = i
if i==len(nums)-1:
rollback=True
i=i+1
# print(\"neg list\"+str(arr_neg))
print(res)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
ll = len(nums)
if ll == 0:
return 0
curmax = 0
submax = 0
q = [0]
nums.append(0)
for ii in range(ll+1):
if nums[ii] == 0:
curmax = ii-q[0]
#print(submax,curmax,q)
if len(q)%2 == 0:
curmax = max(ii-q[1]-1,q[-1]-q[0])
submax = max(submax,curmax)
q = [ii+1]
curmax = 0
elif nums[ii] < 0:
q.append(ii)
submax = max(submax,curmax)
return submax
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
non_zero_list = []
neg_list = []
temp = []
neg = 0
for i in range(len(nums)):
#temp = []
if nums[i] == 0 or (i == len(nums) - 1):
if nums[i] != 0:
temp.append(nums[i])
non_zero_list.append(temp)
temp = []
if nums[i] < 0:
neg += 1
neg_list.append(neg)
neg = 0
elif nums[i] < 0:
neg += 1
temp.append(nums[i])
elif nums[i] > 0:
temp.append(nums[i])
_max = 0
for i in range(len(non_zero_list)):
if neg_list[i] % 2 == 0:
if len(non_zero_list[i]) > _max:
_max = len(non_zero_list[i])
else:
temp1 = 0
temp2 = 0
for j in range(len(non_zero_list[i])):
if non_zero_list[i][j] < 0:
temp1 =len(non_zero_list[i]) - j - 1
#print(j, temp1)
temp1 = max(temp1, j)
break
for j in range(len(non_zero_list[i])-1, -1, -1):
if non_zero_list[i][j] < 0:
temp2 =len(non_zero_list[i]) - j - 1
#print(j,temp2)
temp2 = max(temp2, j )
break
if max(temp1, temp2) > _max:
_max = max(temp1,temp2)
return _max
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos = [0] * len(nums)
neg = [0] * len(nums)
pos[0] = 1 if nums[0] > 0 else 0
neg[0] = 1 if nums[0] < 0 else 0
result = pos[0]
for i in range(1, len(nums)):
if nums[i] > 0:
pos[i] = 1 + pos[i-1]
neg[i] = 1 + neg[i-1] if neg[i-1] > 0 else 0
elif nums[i] < 0:
pos[i] = 1 + neg[i-1] if neg[i-1] > 0 else 0
neg[i] = 1 + pos[i-1]
result = max(result, pos[i])
return result
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen2(self, nums: List[int]) -> int:
ans = 0
n = len(nums)
dp = [0]*n
dp1 = [0]*n
if nums[0] == 0:
dp[0] = 0
elif nums[0] > 0:
dp[0] = 1
dp1[0] = 1
ans = 1
else:
dp[0] = -1
dp1[0] = -1
for i in range(1, n):
if nums[i-1] < 0:
pre = -1
else:
pre = 1
if nums[i] == 0:
dp[i] = 0
elif nums[i] > 0:
ans = max(ans, 1)
if dp[i-1] < 0:
dp[i] = dp[i-1] - 1
dp1[i] = dp1[i-1] - 1
else:
dp[i] = abs(dp[i-1]) + 1
dp1[i] = abs(dp1[i-1]) + 1
elif nums[i] < 0:
dp1[i] = 0
if dp[i-1] < 0:
dp[i] = abs(dp[i-1]) + 1
else:
dp[i] = -1*(dp[i-1] + 1)
#dp1[i] = -1*(dp[i-1] + 1)
ans = max(ans, dp[i], dp1[i])
#print(dp)
#print(dp1)
#print('---')
return ans
def getMaxLen(self, nums: List[int]) -> int:
ans1 = self.getMaxLen2(nums)
ans2 = self.getMaxLen2(nums[::-1])
#print(ans1, ans2)
return max(ans1, ans2)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
pos = 0
neg = 0
res = 0
for num in nums:
if num == 0:
pos, neg = 0, 0
continue
elif num > 0:
if neg > 0:
new_neg = neg + 1
else:
new_neg = 0
new_pos = pos + 1
elif num < 0:
if pos > 0:
new_neg = pos + 1
else:
new_neg = 1
if neg > 0:
new_pos = neg + 1
else:
new_pos = 0
pos, neg = new_pos, new_neg
res = max(res, pos)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
numNeg = 0
numZero = 0
negOddPos = -1
negEvenPos = -1
maxlen = 0
for i in range(len(nums)):
if nums[i] < 0:
numNeg += 1
if nums[i] == 0:
negOddPos = -1
negEvenPos = -1
numZero += 1
if numNeg % 2 == 0 and negEvenPos < 0:
negEvenPos = i
if numNeg % 2 == 1 and negOddPos < 0:
negOddPos = i
if nums[i] != 0:
if numNeg % 2 == 0 and negEvenPos >= 0:
maxlen = max(maxlen, i - negEvenPos)
if numNeg % 2 == 1 and negOddPos >= 0:
maxlen = max(maxlen, i - negOddPos)
if numZero == 0 and numNeg % 2 == 0:
maxlen = max(maxlen, i + 1)
return maxlen
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n,ans=len(nums),0
zeros,cn,prev={i:[-1,n,0,0] for i in range(n)},0,-1
for i in range(n):
zeros[i][0]=prev
zeros[i][2]=cn
if nums[i]==0:
prev=i
cn=0
if nums[i]<0:
cn+=1
cn,prev=0,n
for i in range(n-1,-1,-1):
zeros[i][1]=prev
zeros[i][3]=cn
if nums[i]==0:
prev=i
cn=0
if nums[i]<0:
cn+=1
for i in range(n):
if nums[i]==0:
if zeros[i][2]%2==0:
ans=max(ans,i-zeros[i][0]-1)
if zeros[i][3]%2==0:
ans=max(ans,zeros[i][1]-i-1)
elif nums[i]<0:
if zeros[i][2]%2==0:
ans=max(ans,i-zeros[i][0]-1)
else:
ans=max(ans,i-zeros[i][0])
if zeros[i][3]%2==0:
ans=max(ans,zeros[i][1]-i-1)
else:
ans=max(ans,zeros[i][1]-i)
else:
if zeros[i][2]+zeros[i][3]%2==0:
ans=max(ans,zeros[i][1]-zeros[i][0]-1)
elif zeros[i][2]%2==0:
ans=max(ans,i-zeros[i][0])
elif zeros[i][3]%2==0:
ans=max(ans,zeros[i][1]-i)
if ans==n: break
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
from functools import lru_cache
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
@lru_cache(None)
def dp(i):
# return maximum length of positive from A
# and maximum length of negative
# starting from A[0]
if i == len(nums)-1:
if nums[i] > 0:
return 1,0
elif nums[i] < 0:
return 0,1
else:
return 0,0
pos,neg = dp(i+1)
if nums[i] == 0:
# print(0,0,nums[i:])
return 0, 0
elif nums[i] > 0:
a = pos + 1
if neg == 0:
b = 0
else:
b = neg + 1
# print(a,b,nums[i:])
return a, b
else:
a = 0
b = 1
if pos > 0:
b = max(b,pos + 1)
# if neg == 0:
# b = max(b,1)
if neg > 0:
a = max(a,neg + 1)
# print(a,b,nums[i:])
return a, b
ans = 0
for i in range(len(nums)):
ans = max(ans, dp(i)[0])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
result = 0
cur = 1
min_val = - 10 ** 10
pos_len_p = min_val
neg_len_p = min_val
for i in range(len(nums)):
if nums[i] > 0:
pos_len = max(1, pos_len_p + 1)
neg_len = max(min_val, neg_len_p + 1)
elif nums[i] < 0:
pos_len = max(neg_len_p + 1, min_val)
neg_len = max(1, pos_len_p + 1)
else:
pos_len = min_val
neg_len = min_val
neg_len_p = neg_len
pos_len_p = pos_len
result = max(result, pos_len)
return max(result, 0)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
global_max = 0
curr_neg = 0
curr_pos = 0
neg_flag = False
for num in nums:
if num == 0:
# global_max = max(global_max, local_max)
local_max = 0
curr_neg = 0
curr_pos = 0
neg_flag = False
elif num > 0:
curr_pos += 1
curr_neg += 1
else:
curr_neg += 1
curr_pos = 0
neg_flag = not neg_flag
if neg_flag == False:
global_max = max(global_max, curr_neg)
else:
global_max = max(global_max, curr_pos)
curr_neg = 0
curr_pos = 0
neg_flag = False
for num in nums[::-1]:
if num == 0:
# global_max = max(global_max, local_max)
local_max = 0
curr_neg = 0
curr_pos = 0
neg_flag = False
elif num > 0:
curr_pos += 1
curr_neg += 1
else:
curr_neg += 1
curr_pos = 0
neg_flag = not neg_flag
if neg_flag == False:
global_max = max(global_max, curr_neg)
else:
global_max = max(global_max, curr_pos)
return global_max
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
pos = [0 for x in range(n)]
neg = [0 for x in range(n)]
if nums[0] > 0:
pos[0] = 1
if nums[0] < 0:
neg[0] = 1
ret = pos[0]
for i in range(1, n):
if nums[i] > 0:
pos[i] = pos[i-1] + 1
neg[i] = neg[i-1] + 1 if neg[i-1] > 0 else 0
elif nums[i] < 0:
neg[i] = pos[i-1] + 1
pos[i] = neg[i-1] + 1 if neg[i-1] > 0 else 0
else:
continue
ret = max(ret, pos[i])
return ret
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
ans = -10**9
@lru_cache(None)
def cal(i):
nonlocal ans
if i >= len(nums):
return [None, None]
else:
if nums[i] == 0:
return [None, None]
elif nums[i] < 0:
pos, neg = cal(i+1)
if neg == None:
neg = i
if pos != None:
ans = max(ans, pos - i + 1)
return [neg, pos]
else:
neg, pos = cal(i+1)
if pos == None:
pos = i
ans = max(ans, pos - i + 1)
return [neg, pos]
for i in range(len(nums)):
cal(i)
return max(ans, 0)
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
record=[]
index=[-1]
for i,j in enumerate(nums):
if j>0:
record.append(1)
elif j<0:
record.append(-1)
else:
record.append(0)
index.append(i)
# print(record,index)
index.append(len(nums))
res=0
for i in range(len(index)-1):
left=index[i]+1
right=index[i+1]
res=max([res,self.getMax(record[left:right])])
#print(left,right,res)
return res
def getMax(self,arr):
tot=1
Cum=[1]
for i in range(len(arr)):
tot*=arr[i]
Cum.append(tot)
for k in range(len(arr),0,-1):
for j in range(0,len(arr)-k+1):
tmp=Cum[j+k]/Cum[j]
#print(Cum[j+k],Cum[j],tmp)
if tmp>0:
return k
return 0
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
n = len(nums)
dp = [[0] * 2 for _ in range(n)]
if nums[0] > 0:
dp[0][0] = 1
if nums[0] < 0:
dp[0][1] = 1
res = dp[0][0]
for i in range(1, n):
cur = nums[i]
if cur > 0:
dp[i][0] = dp[i - 1][0] + 1
if dp[i - 1][1] > 0:
dp[i][1] = max(dp[i][1], dp[i - 1][1] + 1)
if cur < 0:
dp[i][1] = dp[i - 1][0] + 1
if dp[i - 1][1] > 0:
dp[i][0] = max(dp[i][0], dp[i - 1][1] + 1)
res = max(res, dp[i][0])
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
r = 0
cur = 0
n = len(nums)
neg = -1
zero = -1
for i in range(n):
if nums[i] < 0:
cur += 1
if neg == -1:
neg = i
if nums[i] == 0:
zero = i
cur = 0
neg = -1
else:
if cur % 2 == 0:
r = max(r, i - zero)
else:
r = max(r, i - neg)
return r
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
def sgn(x):
if x < 0:
return -1
if x == 0:
return 0
return 1
nums = list(map(sgn, nums))
def get_ans(start, end):
# find ans of nums[start: end]
# nums[start: end] doesn't contain 0
arr = nums[start: end]
negative = arr.count(-1)
result = end - start
if negative & 1 ^ 1:
return result
return result - min(arr.index(-1), arr[::-1].index(-1)) - 1
nums.append(0)
size = len(nums)
pair = [0]
ans = 0
for i in range(size):
if nums[i] == 0:
if not pair:
continue
pair.append(i)
ans = max(ans, get_ans(*pair))
pair = [i + 1]
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
dp=[[0,0] for _ in range(len(nums))]
if nums[0]>0:
dp[0][0]=1
elif nums[0]<0:
dp[0][1]=1
for i in range(1,len(nums)):
if nums[i]==0:
continue
elif nums[i]>0:
dp[i][0]=dp[i-1][0]+1
if dp[i-1][1]>0:
dp[i][1]=dp[i-1][1]+1
else:
if dp[i-1][1]>0:
dp[i][0]=dp[i-1][1]+1
dp[i][1]=dp[i-1][0]+1
ans=0
for i in dp:
ans=max(ans,i[0])
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
res = 0
pos = 0
neg = 0
left, right = -1, -1
prev = -1
cnt = 0
n = len(nums)
for i in range(n):
if nums[i] == 0:
if cnt > 0 and neg%2 == 0:
res = max(res,i-prev-1)
elif cnt > 0 and neg%2 == 1:
res = max(res, i-left-1, right - prev-1)
cnt = 0
neg = 0
prev = i
left, right = prev, prev
continue
if nums[i] < 0:
neg+=1
if left == prev:
left = i
right = i
cnt+=1
elif nums[i] > 0:
cnt += 1
if neg%2 ==0:
res = max(res,i-prev)
else:
res = max(res, i-left, right - prev-1)
# print(res, neg, cnt,left,right)
# print(prev,left,right)
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
dp = []
product = 1
for i in range(len(nums)):
if nums[i] > 0:
product = product
dp.append(product)
elif nums[i] < 0:
product = -product
dp.append(product)
else:
product = 1
dp.append(0)
print(dp)
res = 0
d = {1:0, 0:float('inf'), -1:float('inf')}
if nums[0] == 0:
d[1] = float('inf')
for i, p in enumerate(dp):
if p == 1:
d[1] = min(d[1], i)
res = max(res, i - d[1] + 1)
elif p == -1:
d[-1] = min(d[-1], i)
res = max(res, i - d[-1])
else:
d[1] = i + 1
d[-1] = float('inf')
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
##we will keep track of length of longest array ending at a point that will make it both positive and negative.
##we will have input be index terminating.
maxProducts = {}
numLength = len(nums)
maxSize = 0
if nums[0] == 0:
maxProducts[0] = [0,0]
elif nums[0] > 0:
maxProducts[0] = [1,0]
else:
maxProducts[0] = [0,1]
maxSize = max(maxSize,maxProducts[0][0])
for i in range(1,numLength):##can just use enumerate
currentNum = nums[i]
maxProducts[i] = [0,0]##need to default before initializing entries
if currentNum > 0:
maxProducts[i][0] = maxProducts[i-1][0]+1
maxProducts[i][1] = maxProducts[i-1][1] if maxProducts[i-1][1] == 0 else maxProducts[i-1][1]+1
elif currentNum < 0:
maxProducts[i][1] = maxProducts[i-1][0]+1
maxProducts[i][0] = maxProducts[i-1][1] if maxProducts[i-1][1] == 0 else maxProducts[i-1][1]+1##need to be careful about 0 as those affect whether you can actually just add one or not.
maxSize = max(maxSize,maxProducts[i][0])
##print(maxProducts)
return maxSize
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
start, first_neg = -1, float('inf')
maxi, positive = 0, 1
for index, value in enumerate(nums):
if value == 0:
start, first_neg, positive = index, float('inf'), 1
else:
positive = positive == (value > 0)
if positive:
maxi = max(maxi, index - start)
else:
maxi = max(maxi, index - first_neg)
first_neg = min(first_neg, index)
return maxi
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
### I was thinking about prefix sum direction and try to figure out relationship between current number and previous number
### besides dynamic programming, is there another way of doing it?????
### good dynamic programming in here https://leetcode.com/problems/maximum-length-of-subarray-with-positive-product/discuss/819432/Python-Easy-to-understand-DP
# dp[i][0] : max length of subarray ending with index i With positive product
# dp[i][1] : max length of subarray ending with index i With negative product
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
dp = [[0,0] for _ in range(len(nums))]
res = 0
if nums[0] > 0:
dp[0][0] = 1
elif nums[0] < 0:
dp[0][1] = 1
#print(dp)
res = max(res, dp[0][0])
for idx in range(1, len(nums)):
if nums[idx] == 0:
dp[idx][0], dp[idx][1] = 0, 0
elif nums[idx] > 0:
dp[idx][0] = dp[idx-1][0] + 1
if dp[idx-1][1] > 0: ### be careful about this condition, if dp[idx-1][0] = 0, it means that at previous index there is no subarray's product that is less than 0, I get stuck in here for some time .....
dp[idx][1] = dp[idx-1][1] + 1
res = max(dp[idx][0], res)
elif nums[idx] < 0:
dp[idx][1] = dp[idx-1][0]+1
if dp[idx-1][1] > 0: ### be careful about this condition, if dp[idx-1][0] = 0, it means that at previous index there is no subarray's product that is less than 0
dp[idx][0] = dp[idx-1][1]+1
res = max(res, dp[idx][0])
#print(dp)
return res
'''
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
diction = {}
diction[\"pos\"], diction[\"neg\"] = 0, 0
prevpos, prevneg = 0, 0
res = 0
for num in nums:
if num == 0:
diction[\"pos\"], diction[\"neg\"] = 0, 0
prevpos, prevneg = 0, 0
elif num > 0:
diction[\"pos\"] += 1
if diction[\"neg\"] % 2 == 0:
res = max(res, diction[\"pos\"]+diction[\"neg\"]+prevpos)
print(num, res)
else:
res = max(res, diction[\"pos\"], prevpos)
elif num < 0:
diction[\"neg\"] += 1
print(\"neg\", num, diction[\"neg\"], diction[\"pos\"], prevpos)
if diction[\"neg\"] % 2 == 1:
res = max(res, diction[\"pos\"])
prevpos += diction[\"pos\"]
diction[\"pos\"] = 0
else:
res = max(res, diction[\"pos\"]+diction[\"neg\"]+prevpos)
prevpos = diction[\"neg\"] + diction[\"pos\"] + prevpos
diction[\"neg\"] = 0
diction[\"pos\"] = 0
print(res)
return res
'''
'''
diction = {}
diction[\"pos\"], diction[\"neg\"] = 0, 0
res = 0
for num in nums:
if num == 0:
diction[\"pos\"], diction[\"neg\"] = 0, 0
elif num > 0:
diction[\"pos\"] += 1
if diction[\"neg\"] % 2 == 0:
res = max(res, diction[\"pos\"]+diction[\"neg\"])
elif num < 0:
diction[\"neg\"] += 1
if diction[\"neg\"] % 2 == 1:
res = max(res, diction[\"pos\"]+diction[\"neg\"]-1)
else:
res = max(res, diction[\"pos\"]+diction[\"neg\"])
print(res)
return res
'''
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
from typing import List
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
left_size = []
left_mult = []
size = 0
mult = 0
for val in nums:
if val == 0:
size = 0
mult = 0
else:
size += 1
mult += (1 if val < 0 else 0)
left_size.append(size)
left_mult.append(mult)
right_size = []
right_mult = []
size = 0
mult = 0
for val in nums[::-1]:
if val == 0:
size = 0
mult = 0
else:
size += 1
mult += (1 if val < 0 else 0)
right_size.append(size)
right_mult.append(mult)
right_size = right_size[::-1]
right_mult = right_mult[::-1]
ans = 0
for idx, val in enumerate(nums):
if val == 0:
continue
ls = 0
lm = 0
if idx > 0:
ls = left_size[idx - 1]
lm = left_mult[idx - 1]
rs = 0
rm = 0
if idx < len(nums) - 1:
rs = right_size[idx + 1]
rm = right_mult[idx + 1]
cur = int(val < 0)
if lm % 2 == 0:
ans = max(ans, ls)
if val > 0:
ans = max(ans, 1)
if (lm + cur) % 2 == 0:
ans = max(ans, ls + 1)
if rm % 2 == 0:
ans = max(ans, rs)
if (rm + cur) % 2 == 0:
ans = max(ans, rs + 1)
if (lm + cur + rm) % 2 == 0:
ans = max(ans, ls + rs + 1)
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
def _getMaxLen(nums):
if not nums:
return 0
n_ones = sum(nums)
if n_ones % 2 == 0:
return len(nums)
return len(nums) - min(nums.index(1), nums[::-1].index(1)) - 1
ans = prev = 0
nums = [0 if i > 0 else (1 if i < 0 else -1) for i in nums]
while nums:
try:
idx = nums.index(-1)
ans = max(_getMaxLen(nums[:idx]), ans)
nums = nums[idx+1:]
except:
ans = max(ans, _getMaxLen(nums))
break
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
def conv(n):
if n > 0:
return 1
if n == 0:
return 0
return -1
nums = list(map(conv, nums))
n = len(nums)
def check(size):
if size == 0: return True
if size > n: return False
p = 1
lo = hi = 0
while hi < n:
if nums[hi] == 0:
p = 1
lo = hi = hi + 1
continue
p *= nums[hi]
if hi - lo + 1 == size:
if p > 0:
return True
p //= nums[lo]
lo += 1
hi += 1
return False
res = 0
lo, hi = 0, n
while lo <= hi:
m = (lo + hi) // 2
r1, r2 = check(m), check(m + 1)
if r1 or r2:
if r1: res = m
if r2: res = m + 1
lo = m + 2
else:
hi = m - 1
return res
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
left = 0
ans = 0
from numpy import sign
while left < len(nums) - ans:
right = left
s = 1
#nextleft = left
while right < len(nums):
s *= sign(nums[right])
if s > 0: ans = max(ans, right - left + 1)
elif s == 0:
#nextleft = right
break
right += 1
if nums[left]>0:
while left < len(nums) and nums[left]>0:
left += 1
else: left += 1
return ans
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
sublists = []
i = 0
while nums and i < len(nums):
if nums[i]:
i += 1
else:
sublists.append(nums[:i])
nums = nums[i+1:]
i = 0
sublists.append(nums)
return max([self.getMaxLenFromNonZero(sublist) for sublist in sublists])
def getMaxLenFromNonZero(self, nums: List[int]) -> int:
count = 0
front = len(nums)
back = 0
for i in range(len(nums)):
if nums[i] < 0:
count += 1
if front > i:
front = i
back = i
if count % 2 == 0:
return len(nums)
else:
return len(nums) - min([front+1, len(nums) - back])
|
Given an array of integers nums, find the maximum length of a subarray where the product of all its elements is positive.
A subarray of an array is a consecutive sequence of zero or more values taken out of that array.
Return the maximum length of a subarray with positive product.
Example 1:
Input: nums = [1,-2,-3,4]
Output: 4
Explanation: The array nums already has a positive product of 24.
Example 2:
Input: nums = [0,1,-2,-3,-4]
Output: 3
Explanation: The longest subarray with positive product is [1,-2,-3] which has a product of 6.
Notice that we cannot include 0 in the subarray since that'll make the product 0 which is not positive.
Example 3:
Input: nums = [-1,-2,-3,0,1]
Output: 2
Explanation: The longest subarray with positive product is [-1,-2] or [-2,-3].
Example 4:
Input: nums = [-1,2]
Output: 1
Example 5:
Input: nums = [1,2,3,5,-6,4,0,10]
Output: 4
Constraints:
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
|
class Solution:
def getMaxLen(self, nums: List[int]) -> int:
def _getMaxLen(nums):
if not nums:
return 0
fn = 0
while fn < len(nums) and nums[fn] > 0:
fn += 1
pos = True
res = 0
for i in range(len(nums)):
if nums[i] < 0:
pos = not pos
if pos:
res = max(res, i+1)
else:
res = max(res, i - fn)
return res
ans = prev = 0
while nums:
try:
idx = nums.index(0)
ans = max(_getMaxLen(nums[:idx]), ans)
nums = nums[idx+1:]
except:
ans = max(ans, _getMaxLen(nums))
break
return ans
|
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