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1ktedymra | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | 1 mol of an octahedral metal complex with formula MCl<sub>3</sub> . 2L on reaction with excess of AgNO<sub>3</sub> gives 1 mol of AgCl. The denticity of Ligand L is ____________. (Integer answer) | [] | null | 2 | MCl<sub>3</sub> . 2L octahedral<br><br>$$\mathop {MC{l_3}.2L}\limits_{1\,mole} \buildrel {Ex.\,AgN{O_3}} \over
\longrightarrow $$ 1 mole of AgCl<br><br>Its means that one Cl<sup>$$-$$</sup> ion present in ionization sphere.<br><br>$$\therefore$$ formula = [MCl<sub>2</sub>L<sub>2</sub>]Cl<br><br>For octahedral complex ... | integer | jee-main-2021-online-27th-august-morning-shift | 1,719 |
1l55o4wja | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>$${[Fe{(CN)_6}]^{4 - }}$$</p>
<p>$${[Fe{(CN)_6}]^{3 - }}$$</p>
<p>$${[Ti{(CN)_6}]^{3 - }}$$</p>
<p>$${[Ni{(CN)_4}]^{2 - }}$$</p>
<p>$${[Co{(CN)_6}]^{3 - }}$$</p>
<p>Among the given complexes, number of paramagnetic complexes is ____________.</p> | [] | null | 2 | $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} \quad$ Diamagnetic<br/><br/>
$\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-} \quad$ Paramagnetic (1 unpaired electron)<br/><br/>
$\left[\mathrm{Ti}(\mathrm{CN})_6\right]^{3-} \quad$ Paramagnetic (1 unpaired electron)<br/><br/>
$\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} \qu... | integer | jee-main-2022-online-28th-june-evening-shift | 1,721 |
1l56aywg1 | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Given below are two statements :</p>
<p>Statement I : [Ni(CN)<sub>4</sub>]<sup>2$$-$$</sup> is square planar and diamagnetic complex, with dsp<sup>2</sup> hybridization for Ni but [Ni(CO)<sub>4</sub>] is tetrahedral, paramagnetic and with sp<sup>3</sup>-hybridication for Ni.</p>
<p>Statement II : [NiCl<sub>4</sub>]... | [{"identifier": "A", "content": "Both Statement I and Statement II are true."}, {"identifier": "B", "content": "Both Statement I and Statement II are false."}, {"identifier": "C", "content": "Statement I is correct but Statement II is false."}, {"identifier": "D", "content": "Statement I is false but Statement II is co... | ["B"] | null | [Ni(CN)<sub>4</sub>]<sup>2–</sup> : d<sup>8</sup> configuration, SFL, sq. planar splitting (dsp<sup>2</sup>), diamagnetic.<br/><br/>
[Ni(CO)<sub>4</sub>] : d<sup>10</sup> config (after excitation), SFL, tetrahedral splitting (sp<sup>3</sup>), diamagnetic. <br/><br/>
[NiCl<sub>4</sub>]<sup>2–</sup> : d<sup>8</sup> confi... | mcq | jee-main-2022-online-28th-june-morning-shift | 1,722 |
1l56xoaew | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers : Mn = 25; Fe = 26)</p>
<p>A. [FeF<sub>6</sub>]<sup>3$$-$$</sup></p>
<p>B. [Fe(CN)<sub>6</sub>]<sup>3$$-$$</sup></p>
<p>C. [MnCl<sub>6</sub>]<sup>3$$-$$</sup> (high spin)</p>
<p>D. [Mn(CN)<sub>6</sub>]<sup>3$$-$... | [{"identifier": "A", "content": "A < B < D < C"}, {"identifier": "B", "content": "B < D < C < A"}, {"identifier": "C", "content": "A < C < D < B"}, {"identifier": "D", "content": "B < D < A < C"}] | ["B"] | null | <style type="text/css">
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overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sa... | mcq | jee-main-2022-online-27th-june-evening-shift | 1,723 |
1l57t60wh | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the manganese product formed from the above reaction is ____________ B.M. (Nearest integer)</p> | [] | null | 6 | $\mathrm{KMnO}_{4}$ (acidic medium) $+\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \rightarrow \mathrm{CO}_{2}+\mathrm{Mn}^{+2}$<br/><br/> $\mathrm{Mn}^{+2}$ has 5 unpaired electrons
<br/><br/>
$\therefore $ Spin only magnetic moment $=\sqrt{5(5+2)}$
<br/><br/>
$$
\begin{aligned}
&=\sqrt{5 \times 7} \\\\
&=\sqrt{35} \\... | integer | jee-main-2022-online-27th-june-morning-shift | 1,724 |
1l59romut | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Amongst FeCl<sub>3</sub>.3H<sub>2</sub>O, K<sub>3</sub>[Fe(CN)<sub>6</sub>] and [Co(NH<sub>3</sub>)<sub>6</sub>]Cl<sub>3</sub>, the spin-only magnetic moment value of the inner-orbital complex that absorbs light at shortest wavelength is ____________ B.M. [nearest integer]</p> | [] | null | 2 | $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3} \mathrm{Cl}_{3}\right] \rightarrow$ Outer-orbital complex
<br/><br/>
$$
\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \text { Inner-orbital complex }
$$
<br/><br/>
$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}... | integer | jee-main-2022-online-25th-june-evening-shift | 1,725 |
1l5c644lu | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Match List - I with List - II :</p>
<p><style type="text/css">
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overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:so... | [{"identifier": "A", "content": "(A)-(II), (B)-(IV), (C)-(I), (D)-(III)"}, {"identifier": "B", "content": "(A)-(III), (B)-(IV), (C)-(I), (D)-(II)"}, {"identifier": "C", "content": "(A)-(III), (B)-(I), (C)-(IV), (D)-(II)"}, {"identifier": "D", "content": "(A)-(II), (B)-(I), (C)-(IV), (D)-(III)"}] | ["B"] | null | <style type="text/css">
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overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sa... | mcq | jee-main-2022-online-24th-june-morning-shift | 1,726 |
1l5w6wen9 | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>In the following brown complex, the oxidation state of iron is +_____________.</p>
<p>$${[Fe{({H_2}O)_6}]^{2 + }} + NO \to \mathop {{{[Fe{{({H_2}O)}_5}(NO)]}^{2 + }}}\limits_{\text{Brown complex}} + {H_2}O$$</p> | [] | null | 1 | <p>To determine the oxidation state of iron in the brown complex ${[Fe({H_2}O)_5(NO)]^{2+}}$, we need to analyze the ligands and their charges, as well as the overall charge of the complex.</p>
<h3><strong>Step 1: Understanding the Complex</strong></h3>
<p>The complex is:</p>
<p>$ {[Fe({H_2}O)_5(NO)]^{2+}} $</p>
<p><p... | integer | jee-main-2022-online-30th-june-morning-shift | 1,727 |
1l5w6xmox | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Spin only magnetic moment ($$\mu$$<sub>s</sub>) of $${K_3}[Fe{(CN)_6}]$$ is ____________ B.M.</p>
<p>(Nearest integer)</p> | [] | null | 2 | $\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$
<br><br>
$\mathrm{CN}^{-}$ have $-1$ oxidation State.
<br><br>
Let oxidation state of $\mathrm{Fe}$ in the complex is $x$.
<br><br>
So, $x-6=-3 \Rightarrow x=+3$
<br><br>
Now, $\mathrm{CN}^{-}$ion is a strong field ligand.
<br><br>
For $Fe^{3+}: -3d^54s^0$ <img ... | integer | jee-main-2022-online-30th-june-morning-shift | 1,728 |
1l6gsorj6 | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The difference between spin only magnetic moment values of $$\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\mathrm{Cl}_{2}$$ and $$\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3}$$ is ___________.</p> | [] | null | 0 | $\mathrm{Co} \rightarrow 4 s^{2} 3 d^{7}$
<br/><br/>
$\mathrm{H}_{2} \mathrm{O}$ is weak field ligand.
<br/><br/>
$\mathrm{Co}^{+2} \rightarrow 3 d^{7}$
<br/><br/>
$$
\begin{aligned}
\mathrm{n}=3 \quad \mu_{1} &=\sqrt{n(\mathrm{n}+2)} \\
&=\sqrt{15} \text { B.M. }
\end{aligned}
$$
<br/><br/>
$\mathrm{Cr} \rightarrow 4 ... | integer | jee-main-2022-online-26th-july-morning-shift | 1,729 |
1l6i597wj | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The metal complex that is diamagnetic is (Atomic number: $$\mathrm{Fe}, 26 ; \mathrm{Cu}, 29)$$</p> | [{"identifier": "A", "content": "$$\\mathrm{K}_{3}\\left[\\mathrm{Cu}(\\mathrm{CN})_{4}\\right]$$"}, {"identifier": "B", "content": "$$\\mathrm{K}_{2}\\left[\\mathrm{Cu}(\\mathrm{CN})_{4}\\right]$$"}, {"identifier": "C", "content": "$$\\mathrm{K}_{3}\\left[\\mathrm{Fe}(\\mathrm{CN})_{4}\\right]$$"}, {"identifier": "D",... | ["A"] | null | $$\Rightarrow \mathrm{K}_{3}\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]$$ is diamagnetic
<br/><br/>
$$\mathrm{Cu}(\mathrm{I}) \Rightarrow \mathrm{d}^{10}$$ configuration $$\Rightarrow$$ No unpaired electrons.
<br/><br/>
$$\Rightarrow \mathrm{K}_{2}\left[\mathrm{Cu}(\mathrm{CN})_{4}\right], \mathrm{K}_{3}\left[\mathrm{Fe}... | mcq | jee-main-2022-online-26th-july-evening-shift | 1,730 |
1l6nwo1vw | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Match List I with List II</p>
<p><style type="text/css">
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overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-IV, B-I, C-III, D-II"}, {"identifier": "B", "content": "A-I, B-IV, C-III, D-II"}, {"identifier": "C", "content": "A-I, B-IV, C-II, D-III"}, {"identifier": "D", "content": "A-IV, B-I, C-II, D-III"}] | ["B"] | null | Ni(CO)<sub>4</sub> Hybridisation sp<sup>3</sup>
<br/><br/>
[Ni(CN)<sub>4</sub>]<sup>2–</sup> Hybridisation dsp<sup>2</sup><p></p>
[Co(CN)<sub>6</sub>]<sup>3–</sup> Hybridisation d<sup>2</sup>sp<sup>3</sup><br/><br/>
[Co(F)<sub>6</sub>]<sup>3–</sup> Hybridisation sp<sup>3</sup>d<sup>2</sup> | mcq | jee-main-2022-online-28th-july-evening-shift | 1,731 |
1ldo47x16 | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The spin only magnetic moment of $$\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$$ complexes is _________ B.M. (Nearest integer)</p>
<p>(Given : Atomic no. of Mn is 25)</p> | [] | null | 6 | <p>The spin only magnetic moment of the $$\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$$ complex can be calculated using the formula:</p>
<p>μ = $$\sqrt {n\left( {n + 2} \right)} $$ Bohr magnetons</p>
<p>Where n is the number of unpaired electrons in the complex. To find the number of unpai... | integer | jee-main-2023-online-1st-february-evening-shift | 1,732 |
1ldpp939b | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Cobalt chloride when dissolved in water forms pink colored complex $$\underline{\mathrm{X}}$$ which has
octahedral geometry. This solution on treating with conc $$\mathrm{HCl}$$ forms deep blue complex, $$\underline{\mathrm{Y}}$$ which has a $$\underline{\mathrm{Z}}$$ geometry. $$\mathrm{X}, \mathrm{Y}$$ and $$\math... | [{"identifier": "A", "content": "$$\\mathrm{X}=\\left[\\mathrm{Co}\\left(\\mathrm{H}_{2} \\mathrm{O}\\right)_{6}\\right]^{2+}, \\mathrm{Y}=\\left[\\mathrm{CoCl}_{4}\\right]^{2-}, \\mathrm{Z}=$$ Tetrahedral"}, {"identifier": "B", "content": "$$\\mathrm{X}=\\left[\\mathrm{Co}\\left(\\mathrm{H}_{2} \\mathrm{O}\\right)_{6}... | ["A"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lek28jdu/ded028fd-494e-4d51-a00b-ef00f0590bf3/11f4a910-b519-11ed-9a0f-aff9709555bd/file-1lek28jdv.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lek28jdu/ded028fd-494e-4d51-a00b-ef00f0590bf3/11f4a910-b519-11ed-9a0f-aff9709555bd/fi... | mcq | jee-main-2023-online-31st-january-morning-shift | 1,733 |
ldqwtmcv | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Match List <b>I</b> with List <b>II</b>:</p>
<style type="text/css">
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.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-st... | [{"identifier": "A", "content": "A-I, B-II, C-III, D-IV"}, {"identifier": "B", "content": "A-II, B-I, C-III, D-IV"}, {"identifier": "C", "content": "A-I, B-II, C-IV, D-III"}, {"identifier": "D", "content": "A-II, B-I, C-IV, D-III"}] | ["C"] | null | <p>$$\mathrm{Ni{(CO)_4}\buildrel {} \over
\longrightarrow s{p^3}}$$</p>
<p>$$\mathrm{{\left[ {Cu{{(N{H_3})}_4}} \right]^{2 + }}\buildrel {} \over
\longrightarrow ds{p^2}}$$</p>
<p>$$\mathrm{{\left[ {Fe{{(N{H_3})}_6}} \right]^{2 + }}\buildrel {} \over
\longrightarrow {d^2}s{p^3}}$$</p>
<p>$$\mathrm{{\left[ {Fe{{({H_2... | mcq | jee-main-2023-online-30th-january-evening-shift | 1,734 |
1ldu3xkmx | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Total number of moles of AgCl precipitated on addition of excess of AgNO$$_3$$ to one mole each of the following complexes $$\mathrm{[Co(NH_3)_4Cl_2]Cl,[Ni(H_2O)_6]Cl_2,[Pt(NH_3)_2Cl_2]}$$ and $$\mathrm{[Pd(NH_3)_4]Cl_2}$$ is ___________.</p> | [] | null | 5 | $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} \stackrel{\mathrm{AgNO}_{3}}{\longrightarrow} \mathrm{AgCl}$
<br/><br/>
$$
\begin{aligned}
& {\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{2} \stackrel{\mathrm{AgNO}_{3}}{\longrightarrow} 2 \mathrm{A... | integer | jee-main-2023-online-25th-january-evening-shift | 1,735 |
1ldv0y5cp | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The number of paramagnetic species from the following is _____________.</p>
<p>$$\mathrm{{[Ni{(CN)_4}]^{2 - }},[Ni{(CO)_4}],{[NiC{l_4}]^{2 - }}}$$</p>
<p>$$\mathrm{{[Fe{(CN)_6}]^{4 - }},{[Cu{(N{H_3})_4}]^{2 + }}}$$</p>
<p>$$\mathrm{{[Fe{(CN)_6}]^{3 - }}\,and\,{[Fe{({H_2}O)_6}]^{2 + }}}$$</p> | [] | null | 4 | $$
\begin{array}{ll}
\text { Species } & \text { Magnetic property } \\\\
{\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}} & \text { Diamagnetic } \\\\
{\left[\mathrm{Ni}(\mathrm{CO})_4\right]} & \text { Diamagnetic } \\\\
\left.[\mathrm{NiCl}]_4\right]^{2-} & \text { Paramagnetic } \\\\
\left.[\mathrm{FeCN})_6\right]^{4... | integer | jee-main-2023-online-25th-january-morning-shift | 1,736 |
1ldwuyjew | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The hybridization and magnetic behaviour of cobalt ion in $$\mathrm{[Co(NH_3)_6]^{3+}}$$ complex, respectively is :</p> | [{"identifier": "A", "content": "$$\\mathrm{sp^3d^2}$$ and paramagnetic"}, {"identifier": "B", "content": "$$\\mathrm{sp^3d^2}$$ and diamagnetic"}, {"identifier": "C", "content": "$$\\mathrm{d^2sp^3}$$ and diamagnetic"}, {"identifier": "D", "content": "$$\\mathrm{d^2sp^3}$$ and paramagnetic"}] | ["C"] | null | $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ is diamagnetic with $\mathrm{d}^{2} \mathrm{sp}^{3}$ hybridisation of $\mathrm{Co}^{+3}$.
<br/><br/>
This is because $\mathrm{NH}_{3}$ is a strong field ligand and forces electrons to pair up in a $\mathrm{d}^{6}$ configuration.
| mcq | jee-main-2023-online-24th-january-evening-shift | 1,737 |
1lgp2ph10 | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Which of the following complexes will exhibit maximum attraction to an applied magnetic field?</p> | [{"identifier": "A", "content": "$$\\left[\\mathrm{Ni}\\left(\\mathrm{H}_{2} \\mathrm{O}\\right)_{6}\\right]^{2+}$$"}, {"identifier": "B", "content": "$$\\left[\\mathrm{Co}\\left(\\mathrm{H}_{2} \\mathrm{O}\\right)_{6}\\right]^{2+}$$"}, {"identifier": "C", "content": "$$\\left[\\mathrm{Co}(\\mathrm{en})_{3}\\right]^{3+... | ["B"] | null | To determine which complex exhibits maximum attraction to an applied magnetic field, we need to look at the number of unpaired electrons in each complex. The more unpaired electrons a complex has, the greater the attraction to the magnetic field.
<br/><br/>
1. Option A: [Ni(H₂O)₆]²⁺
Ni²⁺ has a 3d⁸ electron configuratio... | mcq | jee-main-2023-online-13th-april-evening-shift | 1,738 |
1lgsyk75j | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The magnetic moment is measured in Bohr Magneton (BM).</p>
<p>Spin only magnetic moment of $$\mathrm{Fe}$$ in $$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$$ and $$\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$$ complexes respectively is :</p> | [{"identifier": "A", "content": "3.87 B.M. and 1.732 B.M."}, {"identifier": "B", "content": "5.92 B.M. and 1.732 B.M."}, {"identifier": "C", "content": "6.92 B.M. in both"}, {"identifier": "D", "content": "4.89 B.M. and 6.92 B.M."}] | ["B"] | null | <p>For spin-only magnetic moment, we use the formula:<br/><br/>
$$\mathrm{Magnetic ~moment} = \sqrt{n(n+2)} \cdot \mathrm{BM}$$<br/><br/>
where $n$ is the total number of unpaired electrons.</p>
<p>For $$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$$, the electronic configuration of $\mathrm{... | mcq | jee-main-2023-online-11th-april-evening-shift | 1,739 |
jaoe38c1lscrbrsx | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Identify from the following species in which $$\mathrm{d}^2 \mathrm{sp}^3$$ hybridization is shown by central atom :</p> | [{"identifier": "A", "content": "$$\\left[\\mathrm{Co}\\left(\\mathrm{NH}_3\\right)_6\\right]^{3+}$$\n"}, {"identifier": "B", "content": "$$\\mathrm{SF}_6$$\n"}, {"identifier": "C", "content": "$$\\left[\\mathrm{Pt}\\left(\\mathrm{Cl}_4\\right)\\right]^{2-}$$\n"}, {"identifier": "D", "content": "$$\\mathrm{BrF}_5$$"}] | ["A"] | null | <p>$$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{+3}-\mathrm{d}^2 \mathrm{sp}^3$$ hybridization</p>
<p>$$\mathrm{BrF}_5-\mathrm{sp}^3 \mathrm{d}^2$$ hybridization</p>
<p>$$\left[\mathrm{PtCl}_4\right]^{-2}-\mathrm{dsp}^2$$ hybridization</p>
<p>$$\mathrm{SF}_6-\mathrm{sp}^3 \mathrm{d}^2$$ hybridization</p> | mcq | jee-main-2024-online-27th-january-evening-shift | 1,740 |
jaoe38c1lse78fvs | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The correct statements from following are:</p>
<p>A. The strength of anionic ligands can be explained by crystal field theory.</p>
<p>B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.</p>
<p>C. The hybridization involved in formation of $$\left[\mathrm... | [{"identifier": "A", "content": "B, C only"}, {"identifier": "B", "content": "B, D only"}, {"identifier": "C", "content": "A, C only"}, {"identifier": "D", "content": "A, D only"}] | ["A"] | null | <p>(A) Strength of anionic ligands cannot be explained by CFT instead LFT i.e., ligand field theory explains the strength of ligands.</p>
<p>(B) VBT does not give a quantitative interpretation of kinetic stability of coordination compounds.</p>
<p>(C) $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} \rightarrow \mathrm{... | mcq | jee-main-2024-online-31st-january-morning-shift | 1,741 |
luxzq6jp | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Match List I with List II</p>
<p><style type="text/css">
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.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-III, B-II, C-IV, D-I\n"}, {"identifier": "B", "content": "A-III, B-I, C-II, D-IV\n"}, {"identifier": "C", "content": "A-I, B-III, C-II, D-IV\n"}, {"identifier": "D", "content": "A-III, B-I, C-IV, D-II"}] | ["D"] | null | <p>$$\begin{aligned}
& \stackrel{+2}{\text { (A) } \mathrm{K}_2\left[\mathrm{Ni}(\mathrm{CN})_4\right]} \\
& \mathrm{Ni}^{2+}:[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^{\circ},\left(\mathrm{CN}^{-} \text {is } \mathrm{S} . \mathrm{F} . \mathrm{L}\right) \\
& \text { Pre hybridization state of } \mathrm{Ni... | mcq | jee-main-2024-online-9th-april-evening-shift | 1,742 |
luxzq6ml | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>The coordination environment of $$\mathrm{Ca}^{2+}$$ ion in its complex with $$\mathrm{EDTA}^{4-}$$ is :</p> | [{"identifier": "A", "content": "trigonal prismatic\n"}, {"identifier": "B", "content": "octahedral\n"}, {"identifier": "C", "content": "square planar\n"}, {"identifier": "D", "content": "tetrahedral"}] | ["B"] | null | <p>The coordination environment of the $$\mathrm{Ca}^{2+}$$ ion when it forms a complex with $$\mathrm{EDTA}^{4-}$$ (ethylenediaminetetraacetic acid) is octahedral. Ethylenediaminetetraacetic acid (EDTA) is a hexadentate ligand, which means it has six donor atoms that can bind to a central metal ion. In the case of EDT... | mcq | jee-main-2024-online-9th-april-evening-shift | 1,743 |
luy1mwog | chemistry | coordination-compounds | warner's-theory-and-valence-bond-theory | <p>Consider the following test for a group-IV cation.</p>
<p>$$\mathrm{M}^{2+}+\mathrm{H}_2 \mathrm{S} \rightarrow \mathrm{A} \text { (Black precipitate)+ byproduct }$$</p>
<p>$$\mathrm{A}+\text { aqua regia } \rightarrow \mathrm{B}+\mathrm{NOCl}+\mathrm{S}+\mathrm{H}_2 \mathrm{O}$$</p>
<p>$$\mathrm{B}+\mathrm{KNO}_2+\... | [] | null | 0 | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1lw34bqtd/c7afdc1d-639f-4a60-adbb-ff97779dfc82/cf29af10-1023-11ef-a674-953487056389/file-jaoe38c1lw34bqte.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/jaoe38c1lw34bqtd/c7afdc1d-639f-4a60-adbb-ff97779dfc82/cf29af10-1023-1... | integer | jee-main-2024-online-9th-april-evening-shift | 1,744 |
aQaC4dPa13FZvLPn | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | When KMnO<sub>4</sub> acts as an oxidising agent and ultimately forms [MnO<sub>4</sub>]<sup>-2</sup>, MnO<sub>2</sub>, Mn<sub>2</sub>O<sub>3</sub>, Mn<sup>+2</sup>
then the number of electrons transferred in each case respectively is : | [{"identifier": "A", "content": "4, 3, 1, 5"}, {"identifier": "B", "content": "1, 5, 3, 7"}, {"identifier": "C", "content": "1, 3, 4, 5"}, {"identifier": "D", "content": "3, 5, 7, 1"}] | ["C"] | null | <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266666/exam_images/lilflgpamj1p25vsl4mh.webp" loading="lazy" alt="AIEEE 2002 Chemistry - d and f Block Elements Question 199 English Explanation"> | mcq | aieee-2002 | 1,747 |
TlqI0SzeQZIcJIl3 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | How do we differentiate between Fe<sup>3+</sup> and Cr<sup>3+</sup> in group III? | [{"identifier": "A", "content": "by taking excess of NH<sub>4</sub>OH solution"}, {"identifier": "B", "content": "by increasing $$NH_4^+$$ ion concentration"}, {"identifier": "C", "content": "by decreasing OH<sup>-</sup> ion concentration"}, {"identifier": "D", "content": "both (b) and (c)"}] | ["B"] | null | FeCl<sub>3</sub> + 3NH<sub>4</sub>OH $$ \to $$ Fe(OH)<sub>3</sub> ↓(reddish brown) + 3NH<sub>4</sub>Cl
<br><br>CrCl<sub>3</sub> + 3NH<sub>4</sub>OH $$ \to $$ Cr(OH)<sub>3</sub> (Bluish green) + 3NH<sub>4</sub>Cl | mcq | aieee-2002 | 1,748 |
KugVJyu3U5Sj62wc | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid? | [{"identifier": "A", "content": "$$Cr_2O^{2-}_7$$ and H<sub>2</sub>O are formed"}, {"identifier": "B", "content": "$$CrO^{2-}_4$$ is reduced to +3 state of Cr"}, {"identifier": "C", "content": "$$CrO^{2-}_4$$ is oxidized to +7 state of Cr"}, {"identifier": "D", "content": "Cr<sup>3+</sup> and $$Cr_2O^{2-}_7$$ are forme... | ["A"] | null | When a solution of potassium chromate is treated with an excess of dilute nitric acid. Potassium dichromate and $${H_2}O$$ are formed.
<br><br>$$2{K_2}Cr{O_4} + 2HN{O_3} \to {K_2}C{r_2}{O_7} + 2KN{O_3} + {H_2}O$$
<br><br>Hence $$C{r_2}{O_7}^ - $$ and $${H_2}O$$ are formed. | mcq | aieee-2003 | 1,749 |
qRZOZiuvp3UDoAVQ | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Which one of the following nitrates will leave behind a metal on strong heating? | [{"identifier": "A", "content": "Copper nitrate"}, {"identifier": "B", "content": "Manganese nitrate"}, {"identifier": "C", "content": "Silver nitrate"}, {"identifier": "D", "content": "Ferric nitrate"}] | ["C"] | null | $$AgN{O_3}$$ on heating till red <b>hot</b> decomposes as follows:
<br><br>$$AgN{O_3} \to Ag + N{O_2} + {1 \over 2}{O_2}$$ | mcq | aieee-2003 | 1,750 |
3EsBxv3qNbGk3x9Q | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Excess of KI reacts with CuSO<sub>4</sub> solution and then Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub> solution is added to it. Which of the statements is incorrect for this reaction? | [{"identifier": "A", "content": "Cu<sub>2</sub>I<sub>2</sub> is reduced"}, {"identifier": "B", "content": "Evolved I<sub>2</sub> is reduced "}, {"identifier": "C", "content": "Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub> is oxidized "}, {"identifier": "D", "content": "CuI<sub>2</sub> is formed"}] | ["D"] | null | $$4\mathop {KI}\limits^{ - 1} + 2CuS{O_4} \to \mathop {{I_2}}\limits^0 + C{u_2}{I_2} + 2{K_2}S{O_4}$$
<br><br>$$\mathop {{I_2}}\limits^0 + 2N{a_2}\mathop {{S_2}}\limits^{2 + } {O_3} \to N{a_2}\mathop {{S_4}}\limits^{ + 2.5} {O_6} + \mathop {2NaI}\limits^{ - 1} $$
<br><br>In this $$Cu{I_2}$$ is <b>not</b> formed | mcq | aieee-2004 | 1,751 |
giu36jkEKD5k2Tao | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The oxidation state of chromium in the final product formed the reaction between $$K{\rm I}$$ and acidified potassium dichromate solution is : | [{"identifier": "A", "content": "$$+3$$ "}, {"identifier": "B", "content": "$$+2$$ "}, {"identifier": "C", "content": "$$+6$$ "}, {"identifier": "D", "content": "$$+4$$ "}] | ["A"] | null | $$C{r_2}O_7^{2 - } + 6{{\rm I}^ - } + 14{H^ + }\buildrel \, \over
\longrightarrow 3{{\rm I}_2} + 7{H_2}O + 2C{r^{3 + }}$$
<br><br>oxidation state of $$Cr$$ is $$3+.$$ | mcq | aieee-2005 | 1,752 |
eMllOmkYpMeILw7S | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The colour of KMnO<sub>4</sub> is due to : | [{"identifier": "A", "content": "d \u2013 d transition"}, {"identifier": "B", "content": "L $$\\to$$ M charge transfer transition"}, {"identifier": "C", "content": "$$\\sigma$$ \u2013 $$\\sigma$$* transition"}, {"identifier": "D", "content": "M $$\\to$$ L charge transfer transition"}] | ["B"] | null | $$L \to M$$ charge transfer spectra. $$KMn{O_4}$$ is colored because it absorbs light in the visible range of electromagnetic radiation. The permanganate ion is the source of color, as a ligand to metal, $$\left( {L \to M} \right)$$ charge transfer takes place between oxygen's $$p$$ orbitals and the empty $$d$$-orbital... | mcq | jee-main-2015-offline | 1,754 |
OFwhY75bqYtioWQosutex | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Wilkinson catalyst is : (Et = C<sub>2</sub>H<sub>5</sub>) | [{"identifier": "A", "content": "[(Ph<sub>3</sub>P)<sub>3</sub> RhCl]"}, {"identifier": "B", "content": "[(Et<sub>3</sub>P)<sub>3</sub>RhCl] \n"}, {"identifier": "C", "content": "[(Et<sub>3</sub>P)<sub>3</sub>IrCl] "}, {"identifier": "D", "content": "[(Ph<sub>3</sub>P)<sub>3</sub>IrCl]"}] | ["A"] | null | Wilkinsion catalyst is [(Ph<sub>3</sub>P)<sub>3</sub>RhCl] | mcq | jee-main-2019-online-10th-january-morning-slot | 1,755 |
X0NwS1pgV5RmJHa2yt7k9k2k5eqtor1 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Consider the following reactions :<br/><br/>
$$NaCl{\rm{ }} + {\rm{ }}{K_2}C{r_2}{O_7} + \mathop {{H_2}S{O_4}}\limits_{(conc.)} $$$$ \to $$ (A) + side products
<br/><br/>
(A) + NaOH $$ \to $$ (B) + Side products<br/><br/>
$$\left( B \right){\rm{ }} + \mathop {{H_2}S{O_4}}\limits_{(dilute)} + {\rm{ }}{H_2}{O_2}$$ $$ \t... | [] | null | 18 | $$NaCl{\rm{ }} + {\rm{ }}{K_2}C{r_2}{O_7} + \mathop {{H_2}S{O_4}}\limits_{(conc.)} $$$$ \to $$ <br>2CrO<sub>2</sub>Cl<sub>2</sub>(A) + 4NaHSO<sub>4</sub> + 2KHSO<sub>4</sub> + 3H<sub>2</sub>O
<br><br>CrO<sub>2</sub>Cl<sub>2</sub>(A) + 4NaOH $$ \to $$ Na<sub>2</sub>CrO<sub>4</sub>(B) + 2NaCl + 2H<sub>2</sub>O
<br><br>Na... | integer | jee-main-2020-online-7th-january-evening-slot | 1,757 |
SxP5UynwIehkRfgJOp7k9k2k5llbck3 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | 5 g of zinc is treated separately with an excess
of<br/><br/>
(a) dilute hydrochloric acid and<br/>
(b) aqueous sodium hydroxide.<br/><br/>
The ratio of the volumes of H<sub>2</sub> evolved in these
two reactions is : | [{"identifier": "A", "content": "1 : 2"}, {"identifier": "B", "content": "1 : 1"}, {"identifier": "C", "content": "1 : 4"}, {"identifier": "D", "content": "2 : 1"}] | ["B"] | null | Zn + 2dil. HCl $$ \to $$ ZnCl<sub>2</sub> + H<sub>2</sub>
<br><br>Zn + 2NaOH $$ \to $$ Na<sub>2</sub>ZnO<sub>2</sub> + H<sub>2</sub>
<br><br>From one mole of Zn, 1 mol of H<sub>2</sub> is produced
by both NaOH and HCl.
<br><br>The ratio of the volume of H<sub>2</sub> is 1 : 1 | mcq | jee-main-2020-online-9th-january-evening-slot | 1,758 |
8elVg3l68FRHZgcZpe7k9k2k5llwccv | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The sum of the total number of bonds between
chromium and oxygen atoms in chromate and
dichromate ions is ____________. | [] | null | 18 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264322/exam_images/fklzaa8q1dbhwuoktths.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 9th January Evening Slot Chemistry - d and f Block Elements Question 140 English Explanation">
<br... | integer | jee-main-2020-online-9th-january-evening-slot | 1,759 |
gafN2KKWlOo1S7JqAljgy2xukf3lsk6i | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The incorrect statement is : | [{"identifier": "A", "content": "In manganate and permanganate ions, the p-bonding takes place by overlap of p-orbitals\nof oxygen and d-orbitals of manganese"}, {"identifier": "B", "content": "Manganate ion is green in colour and\npermanganate ion in purple in colour"}, {"identifier": "C", "content": "Manganate and pe... | ["C"] | null | <p>To identify the incorrect statement, let's analyze each option :</p>
<p>Option A : "In manganate and permanganate ions, the π-bonding takes place by overlap of p-orbitals of oxygen and d-orbitals of manganese."
This statement is true. In both manganate ${MnO}_4^{2-} $ and permanganate ${MnO}_4^- $ ion... | mcq | jee-main-2020-online-3rd-september-evening-slot | 1,760 |
gUir0qIwpPZX21KJaN1klrtkun7 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The <b>incorrect</b> statement among the following is : | [{"identifier": "A", "content": "RuO<sub>4</sub> is an oxidizing agent"}, {"identifier": "B", "content": "Cr<sub>2</sub>O<sub>3</sub> is an amphoteric oxide."}, {"identifier": "C", "content": "VOSO<sub>4</sub> is a reducing agent"}, {"identifier": "D", "content": "Red colour of ruby is due to the presence of Co<sup>3+<... | ["D"] | null | Red colour of ruby is due to presence of ${Cr}^{3+} $ (chromium ions), not ${Co}^{3+} $ (cobalt ions). in Al<sub>2</sub>O<sub>3</sub>.
Chromium is the trace element that causes ruby’s red colour, which
ranges from an orange red to a publish red. The strength of ruby’s
red depends on how much chromium is present. | mcq | jee-main-2021-online-24th-february-evening-slot | 1,761 |
4Yrcg4938nta7EUAAY1klusuvh8 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | In mildly alkaline medium, thiosulphate ion is oxidized by $$MnO_4^ - $$ to "A". The oxidation state of sulphur in "A" is __________. | [] | null | 6 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l3gzc6fl/cf7ea024-730c-46bc-8c9e-62a3882986b8/00af4010-d9a1-11ec-ac3c-3195763ffb62/file-1l3gzc6fm.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l3gzc6fl/cf7ea024-730c-46bc-8c9e-62a3882986b8/00af4010-d9a1-11ec-ac3c-3195763ffb62/fi... | integer | jee-main-2021-online-26th-february-evening-slot | 1,762 |
1E1QnAxA5sobgtH1AF1kmittq0r | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Fex<sub>2</sub> and Fey<sub>3</sub> are known when x and y are : | [{"identifier": "A", "content": "x = F, Cl, Br, I and y = F, Cl, Br, I"}, {"identifier": "B", "content": "x = F, Cl, Br and y = F, Cl, Br, I"}, {"identifier": "C", "content": "x = F, Cl, Br, I and y = F, Cl, Br"}, {"identifier": "D", "content": "x = Cl, Br, I and y = F, Cl, Br, I"}] | ["C"] | null | FeI<sub>3</sub> does not exist as I<sup>–</sup> reduces Fe<sup>3+</sup> to Fe<sup>2+</sup>.<br><br>
2Fe<sup>3+</sup> + 2I
<sup>– </sup> $$ \to $$ 2Fe<sup>2+</sup> + I<sub>2</sub>. | mcq | jee-main-2021-online-16th-march-evening-shift | 1,763 |
CivhjvqqskbrvQSBAK1kmj7jzgu | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Given below are two statements :<br/><br/>Statement I : Potassium permanganate on heating at 573K forms potassium manganate.<br/><br/>Statement II : Both potassium permanganate and potassium manganate are tetrahedral and paramagnetic in nature.<br/><br/>In the light of the above statements, choose the most appropriate ... | [{"identifier": "A", "content": "Statement I is true but statement II is false"}, {"identifier": "B", "content": "Statement I is false but statement II is true"}, {"identifier": "C", "content": "Both statement I and statement II are false"}, {"identifier": "D", "content": "Both statement I and statement II are true"}] | ["A"] | null | <b>Statement-1</b> : KMnO<sub>4</sub> $$\buildrel {573K} \over
\longrightarrow $$ K<sub>2</sub>MnO<sub>4</sub> + MnO<sub>2</sub> + O<sub>2</sub><br><br>
<b>Statement-2</b> :<br> KMnO4 $$ \Rightarrow $$ Mn<sup>7+</sup> $$ \Rightarrow $$ Diamagnetic.<br>
KMnO<sub>4</sub> $$ \Rightarrow $$ Mn<sup>6+</sup> $$ \Rightarrow... | mcq | jee-main-2021-online-17th-march-morning-shift | 1,764 |
nsNSJSMsWHkLexcvYi1kmlmoebj | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Match List - I with List - II<br/><br/><table>
<thead>
<tr>
<th></th>
<th>List - I<br/></th>
<th></th>
<th>List - II<br/></th>
</tr>
</thead>
<tbody>
<tr>
<td>(a)</td>
<td>Chlorophyll</td>
<td>(i)</td>
<td>Ruthenium</td>
</tr>
<tr>
<td>(b)</td>
<td>Vitamin-$${B_{12}}$$</td>
<td>(ii)</td>
<td>Platinum</td>
</tr>
<tr>
<t... | [{"identifier": "A", "content": "(a) - (iii), (b) - (ii), (c) - (iv), (d) - (i)"}, {"identifier": "B", "content": "(a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)"}, {"identifier": "C", "content": "(a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)"}, {"identifier": "D", "content": "(a) - (iv), (b) - (ii), (c) - (iii), (d) ... | ["B"] | null | Chlorophyll is a coordination compound of
magnesium.<br><br>
Vitamin B-12, cyanocobalamine is a
coordination compound of cobalt.<br><br>
Cisplatin is used as an anti-cancer drug and
is a coordination compound of platinum.
Grubbs catalyst is a compound of Ruthenium. | mcq | jee-main-2021-online-18th-march-morning-shift | 1,765 |
1krut0zde | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The correct order of following 3d metal oxides, according to their oxidation numbers is :<br/><br/>(a) CrO<sub>3</sub>, (b) Fe<sub>2</sub>O<sub>3</sub>, (c) MnO<sub>2</sub>, (d) V<sub>2</sub>O<sub>5</sub>, (e) Cu<sub>2</sub>O | [{"identifier": "A", "content": "(d) > (a) > (b) > (c) > (e)"}, {"identifier": "B", "content": "(a) > (c) > (d) > (b) > (e)"}, {"identifier": "C", "content": "(a) > (d) > (c) > (b) > (e)"}, {"identifier": "D", "content": "(c) > (a) > (d) > (e) > (b)"}] | ["C"] | null | (a) $$\mathop C\limits^{ + 6} r{O_3}$$ : Since there are three oxygen atoms each with an oxidation number of -2, the total oxidation number from the oxygen atoms is -6. To make the compound neutral, Chromium (Cr) must therefore have an oxidation number of +6.
<br><br>(b) $$\mathop {F{e_2}}\limits^{ + 3} {O_3}$$ : Here... | mcq | jee-main-2021-online-25th-july-morning-shift | 1,767 |
1krx8i6bf | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Which one of the following metals forms interstitial hydride easily? | [{"identifier": "A", "content": "Cr"}, {"identifier": "B", "content": "Fe"}, {"identifier": "C", "content": "Mn"}, {"identifier": "D", "content": "Co"}] | ["A"] | null | Elements of group 7, 8, 9 do not form hydrides thus Cr will only form hydride among the given elements (Fe, Mn, Co). | mcq | jee-main-2021-online-25th-july-evening-shift | 1,768 |
1ktfrjv92 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | The addition of dilute NaOH to Cr<sup>3+</sup> salt solution will give : | [{"identifier": "A", "content": "a solution of [Cr(OH)<sub>4</sub>]<sup>$$-$$</sup>"}, {"identifier": "B", "content": "precipitate of Cr<sub>2</sub>O<sub>3</sub>(H<sub>2</sub>O)<sub>n</sub>"}, {"identifier": "C", "content": "precipitate of [Cr(OH)<sub>6</sub>]<sup>3$$-$$</sup>"}, {"identifier": "D", "content": "precipi... | ["B"] | null | $$C{r^{3 + }} + \mathop {NaOH}\limits_{dil.} \buildrel {} \over
\longrightarrow \mathop {C{r_2}{O_3}.{{({H_2}O)}_n}}\limits_{precipitate} $$ | mcq | jee-main-2021-online-27th-august-evening-shift | 1,769 |
1ktia93a7 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | In the structure of the dichromate ion, there is a : | [{"identifier": "A", "content": "linear symmetrical Cr-O-Cr bond."}, {"identifier": "B", "content": "non-linear symmetrical Cr-O-Cr bond."}, {"identifier": "C", "content": "linear unsymmetrical Cr-O-Cr bond."}, {"identifier": "D", "content": "non-linear unsymmetrical Cr-O-Cr bond."}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265364/exam_images/vtruigkiqvmgy9fgbjmn.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 31st August Morning Shift Chemistry - d and f Block Elements Question 102 English Explanation"><br... | mcq | jee-main-2021-online-31st-august-morning-shift | 1,771 |
1ktjv4lb6 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | In which one of the following sets all species show disproportionation reaction? | [{"identifier": "A", "content": "ClO$$_2^ - $$, F<sub>2</sub>, MnO$$_4^ - $$ and Cr<sub>2</sub>O$$_7^{2 - }$$"}, {"identifier": "B", "content": "Cr<sub>2</sub>O$$_7^{2 - }$$, MnO$$_4^{ - }$$, ClO$$_2^{- }$$ and Cl<sub>2</sub>"}, {"identifier": "C", "content": "MnO$$_4^{ - }$$, ClO$$_2^{- }$$, Cl<sub>2</sub> and Mn<sup>... | [] | null | No option contains all species that show disproportionation reaction. So question is bonus.<br><br>MnO$$_4^{ - }$$, ClO$$_4^{ - }$$, Cr<sub>2</sub>O$$_7^{2 - }$$ - Cl, Mn, Cr in these anions are present in highest oxidation state. These will not undergo disproportionation. | mcq | jee-main-2021-online-31st-august-evening-shift | 1,772 |
1ktn0xa2k | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | In the given chemical reaction, colors of the Fe<sup>2+</sup> and Fe<sup>3+</sup> ions, are respectively :<br/><br/>5Fe<sup>2+</sup> + MnO$$_4^ - $$ + 8H<sup>+</sup> $$\to$$ Mn<sup>2+</sup> + 4H<sub>2</sub>O + 5Fe<sup>3+</sup> | [{"identifier": "A", "content": "Yellow, Orange"}, {"identifier": "B", "content": "Yellow, Green"}, {"identifier": "C", "content": "Green, Orange"}, {"identifier": "D", "content": "Green, Yellow"}] | ["D"] | null | Colour of Fe<sup>2+</sup> is observed green and Fe<sup>3+</sup> is yellow. | mcq | jee-main-2021-online-1st-september-evening-shift | 1,773 |
1l54a60dt | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The number of terminal oxygen atoms present in the product B obtained from the following reaction is _____________.</p>
<p>FeCr<sub>2</sub>O<sub>4</sub> + Na<sub>2</sub>CO<sub>3</sub> + O<sub>2</sub> $$\to$$ A + Fe<sub>2</sub>O<sub>3</sub> + CO<sub>2</sub></p>
<p>A + H<sup>+</sup> $$\to$$ B + H<sub>2</sub>O + Na<sup... | [] | null | 6 | $\mathrm{FeCr}_{2} \mathrm{O}_{4}+\mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{O}_{2} \longrightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}+\mathrm{CO}_{2}$ $+\mathrm{Na}_{2} \mathrm{CrO}_{4}$
(A)
<br><br>
$$
\mathrm{Na}_{2} \mathrm{CrO}_{4}+\mathrm{H}^{+} \longrightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{-2}+\mathrm{H}_{2} \mathrm... | integer | jee-main-2022-online-29th-june-morning-shift | 1,774 |
1l54a770k | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>An acidified manganate solution undergoes disproportionation reaction. The spin-only magnetic moment value of the product having manganese in higher oxidation state is _____________ B.M. (Nearest integer)</p> | [] | null | 0 | $$
\begin{aligned}
& 3 \mathrm{MnO}_4^{2-}+4 \mathrm{H}^{+} \longrightarrow 2 \overset{+7}{\mathrm{MnO}_4^{-}}+\overset{+4}{\mathrm{MnO}_2}+2 \mathrm{H}_2 \mathrm{O} \\\\
& \overset{+7}{\mathrm{Mn}}=\text { no. of unpaired electrons is '0' } \\\\
& \mu=0 \text { B.M. }
\end{aligned}
$$ | integer | jee-main-2022-online-29th-june-morning-shift | 1,775 |
1l58emcfu | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The spin-only magnetic moment value of the most basic oxide of vanadium among V<sub>2</sub>O<sub>3</sub>, V<sub>2</sub>O<sub>4</sub> and V<sub>2</sub>O<sub>5</sub> is _____________ B.M. (Nearest integer)</p> | [] | null | 3 | The most basic oxide among $\mathrm{V}_{2} \mathrm{O}_{3}, \mathrm{~V}_{2} \mathrm{O}_{4}$ and $\mathrm{V}_{2} \mathrm{O}_{5}$ is $\mathrm{V}_{2} \mathrm{O}_{3}$
<br/><br/>
$$
\mathrm{V}_{2} \mathrm{O}_{3}=\mathrm{V}^{+3}\left(\mathrm{~d}^{2}\right)
$$
<br/><br/>
Magnetic moment $=\sqrt{2(2+2)}=\sqrt{8}$
<br/><br/>
$$
... | integer | jee-main-2022-online-26th-june-morning-shift | 1,777 |
1l5be2i25 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is ____________.</p> | [] | null | 3 | Manganese $(\mathrm{VI})$ disproportionates in acidic medium as
<br/><br/>
$3 \mathrm{MnO}_{4}^{2-}+4 \mathrm{H}^{+} \longrightarrow 2 \mathrm{MnO}_{4}^{-}+\mathrm{MnO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$
<br/><br/>
The difference in oxidation states of $\mathrm{Mn}$ in the products formed $=7-4=3$ | integer | jee-main-2022-online-24th-june-evening-shift | 1,778 |
1l6gqc32g | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The dark purple colour of $$\mathrm{KMnO}_{4}$$ disappears in the titration with oxalic acid in acidic medium. The overall change in the oxidation number of manganese in the reaction is :</p> | [{"identifier": "A", "content": "5"}, {"identifier": "B", "content": "1"}, {"identifier": "C", "content": "7"}, {"identifier": "D", "content": "2"}] | ["A"] | null | $2 \overset{+7}{\mathrm{KMnO}_{4}}+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow$
$$
\mathrm{K}_{2} \mathrm{SO}_{4}+2 \overset{+2}{\mathrm{MnSO}_{4}}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O}
$$
<br/><br/>
Change is oxidation state $M n$ is 5. | mcq | jee-main-2022-online-26th-july-morning-shift | 1,780 |
1l6jlflsr | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The total number of $$\mathrm{Mn}=\mathrm{O}$$ bonds in $$\mathrm{Mn}_{2} \mathrm{O}_{7}$$ is __________.</p> | [{"identifier": "A", "content": "4"}, {"identifier": "B", "content": "5"}, {"identifier": "C", "content": "6"}, {"identifier": "D", "content": "3"}] | ["C"] | null | Structure of $\mathrm{Mn}_{2} \mathrm{O}_{7}$ is as :<br><br>
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7nreei3/4229ec84-e0ad-46f8-b21b-c5ac84c2001a/4f908bb0-2c8c-11ed-a521-1f85f535c206/file-1l7nreei4.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7nreei3/4229ec84-e0ad-... | mcq | jee-main-2022-online-27th-july-morning-shift | 1,782 |
1l6kppnlu | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>In neutral or alkaline solution, $$\mathrm{MnO}_{4}^{-}$$ oxidises thiosulphate to :</p> | [{"identifier": "A", "content": "$$\\mathrm{S}_{2} \\mathrm{O}_{7}^{2-}$$"}, {"identifier": "B", "content": "$$\\mathrm{S}_{2} \\mathrm{O}_{8}^{2-}$$"}, {"identifier": "C", "content": "$$\\mathrm{SO}_{3}^{2-}$$"}, {"identifier": "D", "content": "$$\\mathrm{SO}_{4}^{2-}$$"}] | ["D"] | null | $8 \mathrm{MnO}_{4}^{-}+3 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-}+ \mathrm{H}_{2} \mathrm{O}\rightarrow 8 \mathrm{MnO}_{2}+6 \mathrm{SO}_{4}^{2-}+$ $2 \mathrm{OH}^{-}$ | mcq | jee-main-2022-online-27th-july-evening-shift | 1,783 |
1l6mcwkxm | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Match List - I with List - II, match the gas evolved during each reaction.</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;... | [{"identifier": "A", "content": "$$(\\mathrm{A})-(\\mathrm{II}),(\\mathrm{B})-(\\mathrm{III}),(\\mathrm{C})-(\\mathrm{I}),(\\mathrm{D})-(\\mathrm{IV})$$"}, {"identifier": "B", "content": "$$(\\mathrm{A})-(\\mathrm{III}),(\\mathrm{B})-(\\mathrm{I}),(\\mathrm{C})-(\\mathrm{IV}),(\\mathrm{D})-(\\mathrm{II})$$"}, {"identif... | ["C"] | null | $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow} \mathrm{N}_{2}+4 \mathrm{H}_{2} \mathrm{O}+\mathrm{Cr}_{2} \mathrm{O}_{3}$
<br/><br/>
$\mathrm{KMnO}_{4}+\mathrm{HCl} \longrightarrow \mathrm{KCl}+\mathrm{MnCl}_{2}+\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}$
<br/><br/>
$... | mcq | jee-main-2022-online-28th-july-morning-shift | 1,784 |
1l6mee2n8 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The disproportionation of $$\mathrm{MnO}_{4}^{2-}$$ in acidic medium resulted in the formation of two manganese compounds $$\mathrm{A}$$ and $$\mathrm{B}$$. If the oxidation state of $$\mathrm{Mn}$$ in $$\mathrm{B}$$ is smaller than that of A, then the spin-only magnetic moment $$(\mu)$$ value of B in BM is ________... | [] | null | 4 | $3 \overset{+6}{\mathrm{MnO}_{4}^{-2}}+4 \mathrm{H}^{+} \rightarrow \overset{+4}{\mathrm{MnO}_{2}}+\overset{+7}{\mathrm{MnO}_{4}^{-}}$
<br/><br/>
$\mathrm{Mn} \rightarrow 4 s^{2} 3 d^{5}$
<br/><br/>
$\mathrm{Mn}^{+4} \rightarrow 3 d^{3}$
<br/><br/>
$$
\mathrm{n}=3
$$
<br/><br/>
$$
\begin{aligned}
\mu &=\sqrt{n(n+2)} \\... | integer | jee-main-2022-online-28th-july-morning-shift | 1,785 |
1l6p79nx0 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>In neutral or faintly alkaline medium, $$\mathrm{KMnO}_{4}$$ being a powerful oxidant can oxidize, thiosulphate almost quantitatively, to sulphate. In this reaction overall change in oxidation state of manganese will be :</p> | [{"identifier": "A", "content": "5"}, {"identifier": "B", "content": "1"}, {"identifier": "C", "content": "0"}, {"identifier": "D", "content": "3"}] | ["D"] | null | In neutral or Faintly alkaline medium, thiosulphate is oxidised almost quantitatively to sulphate ion according to reaction given below, <br/><br/>$8 \mathrm{MnO}_{4}^{-}+3 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-}+\mathrm{H}_{2} \mathrm{O} \rightarrow 8 \mathrm{MnO}_{2}+6 \mathrm{SO}_{4}^{2-}+2 \mathrm{OH}^{-}$<br/><br/> He... | mcq | jee-main-2022-online-29th-july-morning-shift | 1,786 |
1ldo21hi2 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Which element is not present in Nessler's reagent?</p> | [{"identifier": "A", "content": "Mercury"}, {"identifier": "B", "content": "Iodine"}, {"identifier": "C", "content": "Potassium"}, {"identifier": "D", "content": "Oxygen"}] | ["D"] | null | <p>Nessler’s reagent is K<sub>2</sub>[HgI<sub>4</sub>]
</p>
<p>Therefore, among the options given, oxygen is the only element that is not present in Nessler's reagent.</p> | mcq | jee-main-2023-online-1st-february-evening-shift | 1,787 |
1ldpnrqsa | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>When $$\mathrm{Cu}^{2+}$$ ion is treated with $$\mathrm{KI}$$, a white precipitate, $$\mathrm{X}$$ appears in solution. The solution is titrated with sodium thiosulphate, the compound $$\mathrm{Y}$$ is formed. $$\mathrm{X}$$ and $$\mathrm{Y}$$ respectively are :</p> | [{"identifier": "A", "content": "<style type=\"text/css\">\n.tg {border-collapse:collapse;border-spacing:0;}\n.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;\n overflow:hidden;padding:10px 5px;word-break:normal;}\n.tg th{border-color:black;border-style:solid... | ["B"] | null | $2 \mathrm{Cu}^{2+}+4 \mathrm{KI} \longrightarrow \underset{\text { White ppt. }}{\mathrm{Cu}_{2} \mathrm{I}_{2}}+\mathrm{I}_{2}$
<br/><br/>$\mathrm{I}_{2}+\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} \longrightarrow 2 \mathrm{Nal}+\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}$
<br/><br/>$\mathrm{X}=\mathrm{Cu}_{2... | mcq | jee-main-2023-online-31st-january-morning-shift | 1,789 |
ldqwh7u7 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | Formulae for Nessler's reagent is : | [{"identifier": "A", "content": "$\\mathrm{KHgI}_3$"}, {"identifier": "B", "content": "$\\mathrm{HgI}_2$"}, {"identifier": "C", "content": "$\\mathrm{KHg}_2 \\mathrm{I}_2$"}, {"identifier": "D", "content": "$\\mathrm{K}_2 \\mathrm{HgI}_4$"}] | ["D"] | null | <p>Nessler's reagent is $$\mathrm{K_2H_g I_4}$$</p> | mcq | jee-main-2023-online-30th-january-evening-shift | 1,790 |
ldqx15cc | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | $\mathrm{KMnO}_4$ oxidises $\mathrm{I}^{-}$ in acidic and neutral/faintly alkaline solutions, respectively, to : | [{"identifier": "A", "content": "$\\mathrm{IO}_3^{-} ~\\&~ \\mathrm{IO}_3^{-}$"}, {"identifier": "B", "content": "$\\mathrm{I}_2 ~\\&~ \\mathrm{I}_2$"}, {"identifier": "C", "content": "$\\mathrm{I}_2 ~\\&~ \\mathrm{IO}_3^{-}$"}, {"identifier": "D", "content": "$\\mathrm{IO}_3^{-} ~\\&~ \\mathrm{I}_2$"}] | ["C"] | null | <p>Potassium permanganate ($\mathrm{KMnO}_4$) is a strong oxidizing agent that can oxidize iodide ions ($\mathrm{I}^{-}$) to different products depending on the pH of the solution.</p>
<p>In acidic solutions, $\mathrm{KMnO}_4$ oxidizes $\mathrm{I}^{-}$ to molecular iodine ($\mathrm{I}_2$) according to the following eq... | mcq | jee-main-2023-online-30th-january-evening-shift | 1,791 |
1ldr3yvmy | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>During the qualitative analysis of $$\mathrm{SO}_{3}^{2-}$$ using dilute $$\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{2}$$ gas is evolved which turns $$\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$$ solution (acidified with dilute $$\mathrm{H}_{2} \mathrm{SO}_{4}$$) :</p> | [{"identifier": "A", "content": "blue"}, {"identifier": "B", "content": "black"}, {"identifier": "C", "content": "red"}, {"identifier": "D", "content": "green"}] | ["D"] | null | <p>$$\mathrm{S{O_2} + C{r_2}O_7^{2 - }\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}} \mathop {C{r^{3 + }}}\limits_{(green)} + SO_4^{2 - }}$$</p> | mcq | jee-main-2023-online-30th-january-morning-shift | 1,792 |
1ldsdaytw | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>An indicator 'X' is used for studying the effect of variation in concentration of iodide on the rate of reaction of iodide ion with $$\mathrm{H_2O_2}$$ at room temp. The indicator 'X' forms blue coloured complex with compound 'A' present in the solution. The indicator 'X' and compound 'A' respectively are :</p> | [{"identifier": "A", "content": "Methyl orange and $$\\mathrm{H_2O_2}$$"}, {"identifier": "B", "content": "Methyl orange and iodine"}, {"identifier": "C", "content": "Starch and $$\\mathrm{H_2O_2}$$"}, {"identifier": "D", "content": "Starch and iodine"}] | ["D"] | null | <p>Starch forms blue coloured complex with iodine.</p> | mcq | jee-main-2023-online-29th-january-evening-shift | 1,794 |
1ldu17vhf | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>A chloride salt solution acidified with dil.HNO$$_3$$ gives a curdy white precipitate, [A], on addition of AgNO$$_3$$. [A] on treatment with NH$$_4$$OH gives a clear solution B. A and B are respectively :</p> | [{"identifier": "A", "content": "$$\\mathrm{H[AgCl_3]~\\&~(NH_4)[Ag(OH)_2]}$$"}, {"identifier": "B", "content": "$$\\mathrm{AgCl~\\&~[Ag(NH_3)_2]Cl}$$"}, {"identifier": "C", "content": "$$\\mathrm{H[AgCl_3]~\\&~[Ag(NH_3)_2]Cl}$$"}, {"identifier": "D", "content": "$$\\mathrm{AgCl~\\&~(NH_4)[Ag(OH)_2]}$$"}] | ["B"] | null | $\mathrm{Cl}^{-}(\mathrm{aq})+\mathrm{AgNO}_{3}(\mathrm{aq}) \stackrel{\text { dil } \mathrm{HNO}_{3}}{\longrightarrow} \underset{(\mathrm{A})}{\mathrm{AgCl}} \downarrow$
<br/><br/>
$$
\mathrm{AgCl} \downarrow+2 \mathrm{NH}_4 \mathrm{OH}(\mathrm{aq}) \rightarrow\underset{(B)}{\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)... | mcq | jee-main-2023-online-25th-january-evening-shift | 1,795 |
1ldyftq2e | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>An ammoniacal metal salt solution gives a brilliant red precipitate on addition of dimethylglyoxime. The metal ion is :</p> | [{"identifier": "A", "content": "Co$$^{2+}$$"}, {"identifier": "B", "content": "Fe$$^{2+}$$"}, {"identifier": "C", "content": "Ni$$^{2+}$$"}, {"identifier": "D", "content": "Cu$$^{2+}$$"}] | ["C"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1le1x32p8/5609e813-3302-4d6a-abff-05c8f8ccca78/d0b00ac0-ab1e-11ed-b00f-ddbbe8b1b51b/file-1le1x32p9.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1le1x32p8/5609e813-3302-4d6a-abff-05c8f8ccca78/d0b00ac0-ab1e-11ed-b00f-ddbbe8b1b51b/fi... | mcq | jee-main-2023-online-24th-january-morning-shift | 1,796 |
1lgyg9nee | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Prolonged heating is avoided during the preparation of ferrous ammonium sulphate to :</p> | [{"identifier": "A", "content": "prevent hydrolysis"}, {"identifier": "B", "content": "prevent breaking"}, {"identifier": "C", "content": "prevent oxidation"}, {"identifier": "D", "content": "prevent reduction"}] | ["C"] | null | <p>Prolonged heating is avoided during the preparation of ferrous ammonium sulfate to <strong>prevent oxidation</strong>. Ferrous ammonium sulfate is a green crystalline solid that is used as a reducing agent in various chemical reactions. When heated, it can undergo oxidation to form ferric ammonium sulfate, which is ... | mcq | jee-main-2023-online-10th-april-morning-shift | 1,797 |
1lh0385nl | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Which halogen is known to cause the reaction given below :</p>
<p>$$2 \mathrm{Cu}^{2+}+4 \mathrm{X}^{-} \rightarrow \mathrm{Cu}_{2} \mathrm{X}_{2}(\mathrm{s})+\mathrm{X}_{2}$$</p> | [{"identifier": "A", "content": "All halogens"}, {"identifier": "B", "content": "Only Iodine"}, {"identifier": "C", "content": "Only Bromine"}, {"identifier": "D", "content": "Only Chlorine"}] | ["B"] | null | <p>The given reaction describes the formation of a copper(II) halide and the corresponding diatomic halogen molecule. Not all halogens will cause this reaction to occur.</p>
<p>This reaction is known to occur with iodine (I) because the formation of $\mathrm{I}_{2}$ (a diatomic iodine molecule) is easier due to the rel... | mcq | jee-main-2023-online-8th-april-morning-shift | 1,798 |
1lh31tr0z | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Element not present in Nessler's reagent is :</p> | [{"identifier": "A", "content": "I"}, {"identifier": "B", "content": "$$\\mathrm{N}$$"}, {"identifier": "C", "content": "$$\\mathrm{K}$$"}, {"identifier": "D", "content": "$$\\mathrm{Hg}$$"}] | ["B"] | null | Nessler's reagent is a 2% solution of potassium tetraiodomercurate(II) in aqueous potassium hydroxide. Its chemical formula is $$\mathrm{K}_2[\mathrm{HgI}_4]$$. The elements present in it are Potassium (K), Mercury (Hg), and Iodine (I). Nitrogen (N) is not present in Nessler's reagent. | mcq | jee-main-2023-online-6th-april-evening-shift | 1,799 |
jaoe38c1lsc62dmq | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>$$\mathrm{NaCl}$$ reacts with conc. $$\mathrm{H}_2 \mathrm{SO}_4$$ and $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ to give reddish fumes (B), which react with $$\mathrm{NaOH}$$ to give yellow solution (C). (B) and (C) respectively are ;</p> | [{"identifier": "A", "content": "$$\\mathrm{CrO}_2 \\mathrm{Cl}_2, \\mathrm{Na}_2 \\mathrm{CrO}_4$$\n"}, {"identifier": "B", "content": "$$\\mathrm{Na}_2 \\mathrm{CrO}_4, \\mathrm{CrO}_2 \\mathrm{Cl}_2$$\n"}, {"identifier": "C", "content": "$$\\mathrm{CrO}_2 \\mathrm{Cl}_2, \\mathrm{KHSO}_4$$\n"}, {"identifier": "D", "... | ["A"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lscvor9c/e53bb6fb-78f6-4b7f-9de1-bfb3b99afd16/ffd73000-c650-11ee-9d8b-f1be86a1b2f3/file-6y3zli1lscvor9d.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lscvor9c/e53bb6fb-78f6-4b7f-9de1-bfb3b99afd16/ffd73000-c650-11ee-9d... | mcq | jee-main-2024-online-27th-january-morning-shift | 1,800 |
jaoe38c1lsd96guq | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Choose the correct statements from the following</p>
<p>A. $$\mathrm{Mn}_2 \mathrm{O}_7$$ is an oil at room temperature</p>
<p>B. $$\mathrm{V}_2 \mathrm{O}_4$$ reacts with acid to give $$\mathrm{VO}_2{ }^{2+}$$</p>
<p>C. $$\mathrm{CrO}$$ is a basic oxide</p>
<p>D. $$\mathrm{V}_2 \mathrm{O}_5$$ does not react with ac... | [{"identifier": "A", "content": "A, B and D only"}, {"identifier": "B", "content": "A, B and C only"}, {"identifier": "C", "content": "A and C only"}, {"identifier": "D", "content": "B and C only"}] | ["C"] | null | <p>(A) $$\mathrm{Mn}_2 \mathrm{O}_7$$ is green oil at room temperature.</p>
<p>(B) $$\mathrm{V}_2 \mathrm{O}_4$$ dissolve in acids to give $$\mathrm{VO}^{2+}$$ salts.</p>
<p>(C) $$\mathrm{CrO}$$ is basic oxide</p>
<p>(D) $$\mathrm{V}_2 \mathrm{O}_5$$ is amphoteric it reacts with acid as well as base.</p> | mcq | jee-main-2024-online-31st-january-evening-shift | 1,801 |
jaoe38c1lse7jz29 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Identify correct statements from below:</p>
<p>A. The chromate ion is square planar.</p>
<p>B. Dichromates are generally prepared from chromates.</p>
<p>C. The green manganate ion is diamagnetic.</p>
<p>D. Dark green coloured $$\mathrm{K}_2 \mathrm{MnO}_4$$ disproportionates in a neutral or acidic medium to give per... | [{"identifier": "A", "content": "B, D, E only"}, {"identifier": "B", "content": "A, B, C only"}, {"identifier": "C", "content": "A, D, E only"}, {"identifier": "D", "content": "B, C, D only"}] | ["A"] | null | <p>A. $$\mathrm{CrO}_4{ }^{2-}$$ is tetrahedral</p>
<p>B. $$2 \mathrm{Na}_2 \mathrm{CrO}_4+2 \mathrm{H}^{+} \rightarrow \mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7+2 \mathrm{Na}^{+}+\mathrm{H}_2 \mathrm{O}$$</p>
<p>C. As per NCERT, green manganate is paramagnetic with 1 unpaired electron.</p>
<p>D. Statement is correct</p... | mcq | jee-main-2024-online-31st-january-morning-shift | 1,802 |
jaoe38c1lse7lhct | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The metals that are employed in the battery industries are</p>
<p>A. $$\mathrm{Fe}$$</p>
<p>B. $$\mathrm{Mn}$$</p>
<p>C. $$\mathrm{Ni}$$</p>
<p>D. $$\mathrm{Cr}$$</p>
<p>E. $$\mathrm{Cd}$$</p>
<p>Choose the correct answer from the options given below:</p> | [{"identifier": "A", "content": "A, B, C, D and E"}, {"identifier": "B", "content": "A, B, C and D only"}, {"identifier": "C", "content": "B, D and E only"}, {"identifier": "D", "content": "B, C and E only"}] | ["D"] | null | <p>Mn, Ni and Cd metals used in battery industries.</p> | mcq | jee-main-2024-online-31st-january-morning-shift | 1,803 |
jaoe38c1lsfjw2ps | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>$$\mathrm{KMnO}_4$$ decomposes on heating at $$513 \mathrm{~K}$$ to form $$\mathrm{O}_2$$ along with</p> | [{"identifier": "A", "content": "$$\\mathrm{K}_2 \\mathrm{MnO}_4 ~\\& \\mathrm{~Mn}$$"}, {"identifier": "B", "content": "$$\\mathrm{MnO}_2 ~\\& \\mathrm{~K}_2 \\mathrm{O}_2$$\n"}, {"identifier": "C", "content": "\n$$\\mathrm{K}_2 \\mathrm{MnO}_4 ~\\& \\mathrm{~MnO}_2$$\n"}, {"identifier": "D", "content": "$$\\mathrm{Mn... | ["C"] | null | <p>$$\mathrm{KMnO}_4 \xrightarrow{\Delta} \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{MnO}_2+\mathrm{O}_2$$</p> | mcq | jee-main-2024-online-29th-january-morning-shift | 1,804 |
jaoe38c1lsfmsj1m | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The correct IUPAC name of $$\mathrm{K}_2 \mathrm{MnO}_4$$ is</p> | [{"identifier": "A", "content": "Potassium tetraoxidomanganate (VI)\n"}, {"identifier": "B", "content": "Dipotassium tetraoxidomanganate (VII)\n"}, {"identifier": "C", "content": "Potassium tetraoxopermanganate (VI)\n"}, {"identifier": "D", "content": "Potassium tetraoxidomanganese (VI)"}] | ["A"] | null | <p>$$\begin{aligned}
& \mathrm{K}_2 \mathrm{MnO}_4 \\
& 2+\mathrm{x}-8=0 \\
& \Rightarrow \mathrm{x}=+6
\end{aligned}$$</p>
<p>$$\mathrm{O.S.}$$ of $$\mathrm{Mn}=+6$$
<p>IUPAC Name $$=$$</p>
<p>Potassium tetraoxidomanganate(VI)</p> | mcq | jee-main-2024-online-29th-january-evening-shift | 1,805 |
lv0vytoz | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>Consider the following reaction</p>
<p>$$\mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{A}+\mathrm{H}_2 \mathrm{O} \text {. }$$</p>
<p>Product '$$\mathrm{A}$$' in neutral or acidic medium disproportionate to give products '$$\mathrm{B}$$' and '$$\mathrm{C}$$' along with water. The sum of spin-only magn... | [] | null | 4 | <p>$$\mathrm{A}$$ is $$\mathrm{K}_2 \mathrm{MnO}_4$$</p>
<p>$$\mathrm{B}$$ and $$\mathrm{C}$$ are $$\mathrm{KMnO}_4$$ and $$\mathrm{MnO}_2$$</p>
<p>$$\mathrm{KMnO}_4(\mu=0)$$</p>
<p>$$\mathrm{MnO}_2(\mathrm{Mn}^{4+})(\mu=3.87)$$</p>
<p>Sum $$=3.87=4$$ (Nearest integer)</p> | integer | jee-main-2024-online-4th-april-morning-shift | 1,807 |
lv9s2836 | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>While preparing crystals of Mohr's salt, dil $$\mathrm{H}_2 \mathrm{SO}_4$$ is added to a mixture of ferrous sulphate and ammonium sulphate, before dissolving this mixture in water, dil $$\mathrm{H_2SO_4}$$ is added here to :</p> | [{"identifier": "A", "content": "prevent the hydrolysis of ferrous sulphate\n"}, {"identifier": "B", "content": "prevent the hydrolysis of ammonium sulphate\n"}, {"identifier": "C", "content": "increase the rate of formation of crystals\n"}, {"identifier": "D", "content": "make the medium strongly acidic"}] | ["A"] | null | <p>While preparing crystal of Mohr's salt, dil. $$\mathrm{H}_2 \mathrm{SO}_4$$ is added to prevent hydrolysis of ferrous sulphate.</p> | mcq | jee-main-2024-online-5th-april-evening-shift | 1,808 |
lv9s2shw | chemistry | d-and-f-block-elements | important-compounds-of-transition-elements | <p>The fusion of chromite ore with sodium carbonate in the presence of air leads to the formation of products $$\mathrm{A}$$ and $$\mathrm{B}$$ along with the evolution of $$\mathrm{CO}_2$$. The sum of spin-only magnetic moment values of A and B is _________ B.M. (Nearest integer)</p>
<p>[Given atomic number : $$\mathr... | [] | null | 6 | <p>To determine the spin-only magnetic moments of products A and B formed from the fusion of chromite ore with sodium carbonate in the presence of air, we first need to examine the given reaction and the properties of the products.</p>
<p>The reaction provided is:</p>
<p>$4 \mathrm{FeCr}_2 \mathrm{O}_4 + 8 \mathrm{Na... | integer | jee-main-2024-online-5th-april-evening-shift | 1,809 |
rMWuSvmK8txGwumX | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Most common oxidation states of Ce (cerium) are : | [{"identifier": "A", "content": "+3, +4"}, {"identifier": "B", "content": "+2, +3"}, {"identifier": "C", "content": "+2, +4"}, {"identifier": "D", "content": "+3, +5"}] | ["A"] | null | Common oxidation states of $$Ce$$(Cerium) are $$+3$$ and $$+4$$ | mcq | aieee-2002 | 1,810 |
BzdJkiaPuWzEeo3R | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The radius of La<sup>3+</sup> (Atomic number of La = 57) is 1.06 Å. Which one of the following given values will be
closest to the radius of Lu<sup>3+</sup> (Atomic number of Lu = 71) ? | [{"identifier": "A", "content": "1.60 \u00c5"}, {"identifier": "B", "content": "1.40 \u00c5"}, {"identifier": "C", "content": "0.85 \u00c5"}, {"identifier": "D", "content": "1.60 \u00c5"}] | ["C"] | null | Ionic radili $$ \propto {1 \over z}$$
<br><br>Thus, $${{{z_2}} \over {{z_1}}} \Rightarrow {{1.06} \over {\left( {Ionic\,\,\,radii\,\,\,of\,\,L{u^{3 + }}} \right)}} = {{71} \over {57}}$$
<br><br>$$ \Rightarrow \,\,\,$$ Ionic radii of $$L{u^{3 + }} = 0.85\,\mathop A\limits^ \circ $$ | mcq | aieee-2003 | 1,811 |
SOC7p4CYPq8SZE4f | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Cerium (Z = 58) is an important member of the lanthanoids. Which of the following
statements about cerium is incorrect? | [{"identifier": "A", "content": "The common oxidation states of cerium are +3 and +4 "}, {"identifier": "B", "content": "Cerium (IV) acts as an oxidizing agent"}, {"identifier": "C", "content": "The +4 oxidation state of cerium is not known in solutions"}, {"identifier": "D", "content": "The +3 oxidation state of ceriu... | ["C"] | null | The $$+4$$ oxidation state of cerium is also known in solution. | mcq | aieee-2004 | 1,812 |
UNfFO5A13eyZ3FwU | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The lanthanide contraction is responsible for the fact that : | [{"identifier": "A", "content": "Zr and Y have about the same radius"}, {"identifier": "B", "content": "Zr and Nb have similar oxidation\nstate"}, {"identifier": "C", "content": "Zr and Hf have about the same radius"}, {"identifier": "D", "content": "Zr and Zn have the same oxidation"}] | ["C"] | null | <img class="question-image" src="https://gateclass.cdn.examgoal.net/3udCM69k2avFw0ION/hbLEzQaWGSNu3bA7Cp91aPYvY4Gxu/BuMBJ39E5g1boXS0ZyR2pG/uploadfile.jpg" loading="lazy" alt="AIEEE 2005 Chemistry - d and f Block Elements Question 191 English Explanation">
<br>In the entire d-block,
<br><br>Only in group 3, the size inc... | mcq | aieee-2005 | 1,813 |
xHdlQU9vRCF2N2Dt | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Lanthanoid contraction is caused due to : | [{"identifier": "A", "content": "the appreciable shielding on outer electrons by 4f electrons from the nuclear charge "}, {"identifier": "B", "content": "the appreciable shielding on outer electrons by 5d electrons from the nuclear charge "}, {"identifier": "C", "content": "the same effective nuclear charge from Ce to ... | ["D"] | null | The main reason of lanthanide contraction is, poor shielding of 4f electrons on the outer most shell electrons. As f orbital is defused nature so shielding of 4f electron is imperfect that is why nucleus can attract outer most shell electron easily and the size of atom decreases.
<br><br>In lanthanides, there is poorer... | mcq | aieee-2006 | 1,815 |
vkQWbGmfXb3czMGv | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Identify the incorrect statement among the following : | [{"identifier": "A", "content": "d-Block elements show irregular and erratic chemical properties among themselves "}, {"identifier": "B", "content": "La and Lu have partially filled d orbitals and no other partially filled orbitals "}, {"identifier": "C", "content": "The chemistry of various lanthanoids is very similar... | ["D"] | null | $$4f$$ orbital is nearer to nucleus as compared to $$5f$$ orbital therefore, shielding of $$4f$$ is more than $$5f.$$ | mcq | aieee-2007 | 1,816 |
f17ZKRxpl8yhjmJE | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The actinoids exhibits more number of oxidation states in general than the lanthanoids. This is
because : | [{"identifier": "A", "content": "the 5f orbitals are more buried than the 4f orbitals "}, {"identifier": "B", "content": "there is a similarity between 4f and 5f orbitals in their angular part of the wave function "}, {"identifier": "C", "content": "the actinoids are more reactive than the lanthanoids"}, {"identifier":... | ["D"] | null | <b>NOTE :</b> More the distance between nucleus and outer orbitals, lesser will be force of attraction on them. Distance between nucleus and $$5f$$ orbitals is more as compared to distance between $$4f$$ orbital and nucleus. So actinoids exhibit more number of oxidation states in general than the lanthanoids. | mcq | aieee-2007 | 1,817 |
hNmVvGkN1yQnU3ow | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Knowing that the Chemistry of lanthanoids (Ln) is dominated by its +3 oxidation state, which of the
following statements is incorrect? | [{"identifier": "A", "content": "Because of the large size of the Ln (III) ions the bonding in its compounds is predominantly ionic in\n character."}, {"identifier": "B", "content": "The ionic sizes of Ln (III) decrease in general with increasing atomic number. "}, {"identifier": "C", "content": "Ln (III) compounds are... | ["C"] | null | Most of the $$L{n^{3 + }}\,\,$$ compounds except $$L{a^{3 + }}$$ and $$L{u^{3 + }}$$ are coloured due to the presence of $$f$$-electrons. | mcq | aieee-2009 | 1,819 |
WgbWXKM8BPGc0MzE | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The outer electron configuration of $$Gd$$ (Atomic No. $$64$$) is : | [{"identifier": "A", "content": "$$4{f^3}\\,5{d^5}\\,6{s^2}$$ "}, {"identifier": "B", "content": "$$4{f^8}\\,5{d^0}\\,6{s^2}$$ "}, {"identifier": "C", "content": "$$4{f^4}\\,5{d^4}\\,6{s^2}$$ "}, {"identifier": "D", "content": "$$4{f^7}\\,5{d^1}\\,6{s^2}$$ "}] | ["D"] | null | The configuration of $$Gd$$ is $$4{f^7}\,5{d^1}\,6{s^2}.$$ | mcq | aieee-2011 | 1,821 |
k0uJtq12n57MHda8pZnYI | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The 71<sup>st</sup> electron of an element X with an atomic number of 71 enters into the orbital : | [{"identifier": "A", "content": "4f"}, {"identifier": "B", "content": "6s"}, {"identifier": "C", "content": "6p"}, {"identifier": "D", "content": "5d"}] | ["D"] | null | In lutetium (<sup>71</sup>Lu) the 71<sup>st</sup> electron enters in 5d-orbital.
<br><br>Electron configuration is [Xe]4f<sup>14</sup>5d<sup>1</sup>6s<sup>2</sup> | mcq | jee-main-2019-online-10th-january-evening-slot | 1,822 |
aWVsQPjYWGgDCNuRY93rsa0w2w9jx0usadf | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The highest possible oxidation states of uranium and plutonium, respectively are : | [{"identifier": "A", "content": "4 and 6"}, {"identifier": "B", "content": "6 and 4"}, {"identifier": "C", "content": "7 and 6"}, {"identifier": "D", "content": "6 and 7"}] | ["D"] | null | <p>The highest possible oxidation states of uranium and plutonium can be identified by considering the electronic configurations of these elements and noting the number of valence electrons available for bonding.</p>
<p>Uranium (U, atomic number 92) has the electronic configuration:
$ [Rn] 5f^3 6d^1 7s^2 $</p>
<p>Plut... | mcq | jee-main-2019-online-10th-april-evening-slot | 1,823 |
YZw5LxVmGvfP0XcP7o2Nb | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The maximum number of possible oxidation
states of actinoides are shown by : | [{"identifier": "A", "content": "nobelium (No) and lawrencium (Lr)"}, {"identifier": "B", "content": "actinium (Ac) and thorium (Th)"}, {"identifier": "C", "content": "neptunium (Np) and plutonium (Pu)"}, {"identifier": "D", "content": "berkelium (Bk) and californium (Cf)"}] | ["C"] | null | Actinoid 'Th' shows oxidation state = +4
<br><br>Actinoid 'Ac' shows oxidation state = +3
<br><br>Actinoid 'Pu' shows oxidation states = +3, +4, +5, +6, +7
<br><br>Actinoid 'Np' shows oxidation states = +3, +4, +5, +6, +7
<br><br>Actinoid 'Bk' shows oxidation states = +3, +4
<br><br>Actinoid 'Cm' shows oxidation ... | mcq | jee-main-2019-online-9th-april-evening-slot | 1,824 |
lIWVGnyLpdmSmh30Pa7k9k2k5dyq67i | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The atomic radius of Ag is closed to : | [{"identifier": "A", "content": "Au"}, {"identifier": "B", "content": "Cu"}, {"identifier": "C", "content": "Hg"}, {"identifier": "D", "content": "Ni"}] | ["A"] | null | Atomic radius of Ag and Au is nearly same due
to lanthanide contraction.
<br><br>In periodic table in group 1, 2, 3 from top to bottom radius increases but from group 4 to 12 size increases for 3d to 4d series elements but size of 4d and 5d series elements are approximately same. | mcq | jee-main-2020-online-7th-january-morning-slot | 1,827 |
tjhpo7wTWUUy8ri0CGjgy2xukf7tp6os | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The elements with atomic numbers 101 and 104
belong to, respectively : | [{"identifier": "A", "content": "Group 6 and Actinoids"}, {"identifier": "B", "content": "Actinoids and Group 4"}, {"identifier": "C", "content": "Group 11 and Group 4"}, {"identifier": "D", "content": "Actinoids and Group 6"}] | ["B"] | null | Actinoids contains 14 elements with atomic
number 90 to 103. Hence element with atomic
number 101 is Actinoids.
<br><br>Element with atomic number 104 is a d-block
element of group 4. | mcq | jee-main-2020-online-4th-september-morning-slot | 1,828 |
EE7yHwfZ44ANu6MLUWjgy2xukfjernn9 | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The correct electronic configuration and spin-only<br/> magnetic moment (BM) of Gd<sup>3+</sup> (Z = 64),
respectively, are : | [{"identifier": "A", "content": "[Xe]5f<sup>7</sup> and 8.9"}, {"identifier": "B", "content": "[Xe]4f<sup>7</sup> and 7.9"}, {"identifier": "C", "content": "[Xe]5f<sup>7</sup> and 7.9"}, {"identifier": "D", "content": "[Xe]4f<sup>7</sup> and 8.9"}] | ["B"] | null | Gd<sup>3+</sup> (Z = 64) = [Xe] 4f<sup>7</sup>
<br><br>Magnetic moment ($$\mu $$) = $$\sqrt {n\left( {n + 2} \right)} $$ B.M
<br><br>= $$\sqrt {7\left( {7 + 2} \right)} $$
<br><br>= 7.9 B.M
| mcq | jee-main-2020-online-5th-september-morning-slot | 1,829 |
MrqfcjQFcUHNHBRLD5jgy2xukfjew7v5 | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | In the sixth period, the orbitals that are filled are : | [{"identifier": "A", "content": "6s, 5d, 5f, 6p"}, {"identifier": "B", "content": "6s, 4f, 5d, 6p"}, {"identifier": "C", "content": "6s, 6p, 6d, 6f"}, {"identifier": "D", "content": "6s, 5f, 6d, 6p"}] | ["B"] | null | As per (n + l) rule in 6th period, order of orbitals filling is 6s, 4f, 5d, 6p. | mcq | jee-main-2020-online-5th-september-morning-slot | 1,830 |
hxibXXrIJqOcv64lxcjgy2xukftcqe4v | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | The lanthanoid that does NOT show +4 oxidation
state is : | [{"identifier": "A", "content": "Tb"}, {"identifier": "B", "content": "Dy"}, {"identifier": "C", "content": "Ce"}, {"identifier": "D", "content": "Eu"}] | ["D"] | null | Europium (Eu)
<br>Atomic No = 63
<br>Electronic configuration = [Xe]4f<sup>7</sup>6s<sup>2</sup>
<br>Can show only + 2 and + 3 oxidation state. | mcq | jee-main-2020-online-6th-september-morning-slot | 1,831 |
ccqOfVQo69dnf1hXLSjgy2xukg395sas | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Mischmetal is an alloy consisting mainly of : | [{"identifier": "A", "content": "lanthanoid and actinoid metals"}, {"identifier": "B", "content": "actinoid and transition metals"}, {"identifier": "C", "content": "lanthanoid metals"}, {"identifier": "D", "content": "actinoid metals"}] | ["C"] | null | Misch metal is an alloy consisting mainly of
lanthanoid metals. | mcq | jee-main-2020-online-6th-september-evening-slot | 1,832 |
kn7Boe9n5zzM1GWloO1kls8ub6s | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Given below are two statements :<br/><br/>Statement I : CeO<sub>2</sub> can be used for oxidation of aldehydes and ketones.<br/><br/>Statement II : Aqueous solution of EuSO<sub>4</sub> is a strong reducing agent.<br/><br/>In the light of the above statements, choose the correct answer from the options given below : | [{"identifier": "A", "content": "Statement I is true but Statement II is false."}, {"identifier": "B", "content": "Statement I is false but Statement II is true"}, {"identifier": "C", "content": "Both Statement I and Statement II are false"}, {"identifier": "D", "content": "Both Statement I and Statement II are true"}] | ["D"] | null | The +3 oxidation state of lanthanide is most
stable and therefore lanthanide in +4 oxidation
state has strong tendence to gain e<sup>–</sup>
and
converted into +3 and therefore act as strong
oxidizing agent.
eg Ce<sup>+4</sup>
<br>And therefore CeO<sub>2</sub>
is used to oxidized alcohol
aldehyde and ketones.
<br><br... | mcq | jee-main-2021-online-25th-february-morning-slot | 1,833 |
j7TTVpuLtdcxOEc0UU1klud3myx | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Which one of the following lanthanoids does not form MO<sub>2</sub>? [M is lanthanoid metal] | [{"identifier": "A", "content": "Nd"}, {"identifier": "B", "content": "Dy"}, {"identifier": "C", "content": "Yb"}, {"identifier": "D", "content": "Pr"}] | ["C"] | null | Nd (60) = 4f<sup>4</sup> 6s<sup>2</sup><br><br>
Pr (59) = 4f<sup>3</sup> 6s<sup>2</sup><br><br>
Dy (66) = 4f<sup>10</sup> 6s<sup>2</sup><br><br>
Yb (70) = 4f<sup>14</sup> 6s<sup>2</sup><br><br>
Yb<sup>+2</sup> has fully-filled 4f orbital, it will require very
large amount of energy to reach +4 oxidation
state. | mcq | jee-main-2021-online-26th-february-morning-slot | 1,834 |
InQgxujNCfLRXCd2q91kmht4ltc | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Given below are two statements :<br/><br/>Statement I : The E<sup>o</sup> value for Ce<sup>4+</sup> / Ce<sup>3+</sup> is + 1.74 V.<br/><br/>Statement II : Ce is more stable in Ce<sup>4+</sup> state than Ce<sup>3+</sup> state.<br/><br/>In the light of the above statements, choose the most appropriate answer from the opt... | [{"identifier": "A", "content": "Statement I is incorrect but statement II is correct"}, {"identifier": "B", "content": "Both statement I and statement II are correct"}, {"identifier": "C", "content": "Both statement I and statement II are incorrect"}, {"identifier": "D", "content": "Statement I is correct but statemen... | ["D"] | null | Ce<sup>4+</sup> $$\buildrel {{e^ - }} \over
\longrightarrow $$ Ce<sup>3+</sup> E° = +1.74 V<br><br>
Positive SRP and higher SRP means greater
oxidising power. So, Ce<sup>4+</sup> wants to reduce to Ce<sup>3+</sup>.
Indicates Ce<sup>4+</sup> is less stable than Ce<sup>3+</sup>. | mcq | jee-main-2021-online-16th-march-morning-shift | 1,835 |
VydGFYjRQaFrqKxMRP1kmhul9yp | chemistry | d-and-f-block-elements | inner-transition-elements-(lanthanoids-and-actinoids) | Given below are two statement : one is labelled as Assertion A and the other is labelled as Reason R :<br/><br/>Assertion A : Size of Bk<sup>3+</sup> ion is less than Np<sup>3+</sup> ion.<br/><br/>Reason R : The above is a consequence of the lanthanoid contraction.<br/><br/>In the light of the above statements, choose ... | [{"identifier": "A", "content": "Both A and B are true and R is the correct explanation of A"}, {"identifier": "B", "content": "A is false but R is true"}, {"identifier": "C", "content": "A is true but R is false"}, {"identifier": "D", "content": "Both A and B are true but R is not the correct explanation of A"}] | ["C"] | null | Size of Bk<sup>3+</sup> is 98 pm<br><br>
Size of Np<sup>3+</sup> is 101 pm<br><br>
So size of Np<sup>3+</sup> is more than Bk3+ ion.<br><br>
there is a gradual decrease in the size of M<sup>3+</sup> ions
across the series. This may be referred to as the
actinoid contraction. | mcq | jee-main-2021-online-16th-march-morning-shift | 1,836 |
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