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1ktb4nsec | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | Given below are two statements.<br/><br/>Statement I : In the titration between strong acid and weak base methyl orange is suitable as an indicator.<br/><br/>Statement II : For titration of acetic acid with NaOH phenolphthalein is not a suitable indicator.<br/><br/>In the light of the above statements, choose the most ... | [{"identifier": "A", "content": "Statement I is false but Statement II is true"}, {"identifier": "B", "content": "Statement I is true but Statement II is false"}, {"identifier": "C", "content": "Both Statement I and Statement II are true"}, {"identifier": "D", "content": "Both Statement I and Statement II are false"}] | ["B"] | null | Titration curve for strong acid and weak base initially a buffer of weak base and conjugate acid is :<br><br><picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264699/exam_images/xveccnwefoetzqwygw2p.webp"><source media="(max-width: 500px)" srcset="https://res.clo... | mcq | jee-main-2021-online-26th-august-morning-shift | 2,716 |
1l55mylff | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4. The ratio of $${{[C{H_3}C{H_2}CO{O^ - }]} \over {[C{H_3}C{H_2}COOH]}}$$ required to make buffer is ___________.</p>
<p>Given : $${K_a}(C{H_3}C{H_2}COOH) = 1.3 \times {10^{ - 5}}$$</p> | [{"identifier": "A", "content": "0.03"}, {"identifier": "B", "content": "0.13"}, {"identifier": "C", "content": "0.23"}, {"identifier": "D", "content": "0.33"}] | ["B"] | null | $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH} \rightleftharpoons \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO}^{-}+\mathrm{H}^{+}$
<br/><br/>
From Henderson equation
<br/><br/>
$\mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{\left[\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO}^{-}\right]}{\left[\mathrm{CH}_{3} \mathrm{C... | mcq | jee-main-2022-online-28th-june-evening-shift | 2,718 |
1l56yv4v5 | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>pH value of 0.001 M NaOH solution is ____________.</p> | [] | null | 11 | $$
\begin{aligned}
&{\left[\mathrm{OH}^{-}\right]=0.001=10^{-3} \mathrm{M}} \\\\
&{\left[\mathrm{H}^{+}\right]\left[\mathrm{OH}^{-}\right]=10^{-14}} \\\\
&\quad\left[\mathrm{H}^{+}\right]=10^{-11} \\\\
&\begin{aligned}
\mathrm{pH} &=-\log \left[\mathrm{H}^{+}\right] \\\\
=&-\log \left(10^{-11}\right) \\\\
\mathrm{pH} &... | integer | jee-main-2022-online-27th-june-evening-shift | 2,719 |
1l58eiij8 | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>50 mL of 0.1 M CH<sub>3</sub>COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be _____________ $$\times$$ 10<sup>$$-$$2</sup>. (Nearest integer)</p>
<p>(Given : pK<sub>a</sub> (CH<sub>3</sub>COOH) = 4.76)</p>
<p>log 2 = 0.30</p>
<p>log 3 = 0.48</p>
<p>log 5 = ... | [] | null | 476 | <p>CH<sub>3</sub>COOH + NaOH $$\to$$ CH<sub>3</sub>COONa + H<sub>2</sub>O</p>
<p>After adding 25 ml of NaOH volume of mixture = 50 + 25 = 75 ml</p>
<p>Initially,</p>
<p>Number of millimole of NaOH = 25 $$\times$$ 0.1 = 2.5 mm</p>
<p>Number of millimole of CH<sub>3</sub>COOH = 50 $$\times$$ 0.1 = 5 mm</p>
<p>After nutri... | integer | jee-main-2022-online-26th-june-morning-shift | 2,720 |
1l6i4j1yd | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>Class XII students were asked to prepare one litre of buffer solution of $$\mathrm{pH} \,8.26$$ by their Chemistry teacher: The amount of ammonium chloride to be dissolved by the student in $$0.2\, \mathrm{M}$$ ammonia solution to make one litre of the buffer is :</p>
<p>(Given: $$\mathrm{pK}_{\mathrm{b}}\left(\math... | [{"identifier": "A", "content": "53.5 g"}, {"identifier": "B", "content": "72.3 g"}, {"identifier": "C", "content": "107.0 g"}, {"identifier": "D", "content": "126.0 g"}] | ["C"] | null | For basic Buffer, $$\mathrm{pOH}=\mathrm{pK}_{\mathrm{b}}+\log \frac{[\text { salt }]}{[\text { Base }]}$$
<br/><br/>
$$\mathrm{pOH}=14-8.26=5.74$$
<br/><br/>
$$5.74=4.74+\log \frac{\left[\mathrm{NH}_{4} \mathrm{Cl}\right]}{0.2}$$
<br/><br/>
$$\left[\mathrm{NH}_{4} \mathrm{Cl}\right]=2 \mathrm{M}$$
<br/><br/>
Moles of ... | mcq | jee-main-2022-online-26th-july-evening-shift | 2,721 |
1l6me6wut | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>$$\mathrm{K}_{\mathrm{a}}$$ for butyric acid $$\left(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{COOH}\right)$$ is $$2 \times 10^{-5}$$. The $$\mathrm{pH}$$ of $$0.2 \,\mathrm{M}$$ solution of butyric acid is __________ $$\times 10^{-1}$$. (Nearest integer)</p>
<p>[Given $$\log 2=0.30$$]</p> | [] | null | 27 | $\mathrm{K}_{\mathrm{a}}$ of Butyric acid $\Rightarrow 2 \times 10^{-5} \,\mathrm{PKa}=4.7$ <br/><br/>$\mathrm{pH}$ of $0.2 \mathrm{M}$ solution,<br/><br/>
$$
\mathrm{pH}=\frac{1}{2} \mathrm{pK}_{\mathrm{a}}-\frac{1}{2} \log \mathrm{C}
$$<br/><br/>
$$
\begin{aligned}
&=\frac{1}{2}(4 \cdot 7) - \frac{1}{2} \log (0.2) \\... | integer | jee-main-2022-online-28th-july-morning-shift | 2,723 |
1l6rjgnmc | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>$$200 \mathrm{~mL}$$ of $$0.01 \,\mathrm{M} \,\mathrm{HCl}$$ is mixed with $$400 \mathrm{~mL}$$ of $$0.01 \,\mathrm{M} \,\mathrm{H}_{2} \mathrm{SO}_{4}$$. The $$\mathrm{pH}$$ of the mixture is _________.</p>
<p>Given: $$\log {2}=0.30, \log 3=0.48, \log 5=0.70, \log 7=0.84, \log 11=1.04$$</p> | [{"identifier": "A", "content": "1.14"}, {"identifier": "B", "content": "1.78"}, {"identifier": "C", "content": "2.34"}, {"identifier": "D", "content": "3.02"}] | ["B"] | null | $$\begin{aligned} {\left[\mathrm{H}^{+}\right] } &=\frac{0.01 \times 200+2 \times 0.01 \times 400}{600} \\ &=\frac{0.01+2 \times 0.01 \times 2}{3} \\ &=\frac{0.01+0.04}{3} \\ &=\frac{5}{3} \times 10^{-2} \\ \mathrm{pH} &=-\log \left[\mathrm{H}^{+}\right] \\ &=-\log \left(\frac{5}{3} \times 10^{-2}\right) \\ &=-\left[\l... | mcq | jee-main-2022-online-29th-july-evening-shift | 2,724 |
ldo9pvcf | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | The incorrect statement for the use of indicators in acid-base titration is : | [{"identifier": "A", "content": "Phenolphthalein is a suitable indicator for a weak acid vs strong base titration."}, {"identifier": "B", "content": "Methyl orange may be used for a weak acid vs weak base titration."}, {"identifier": "C", "content": "Methyl orange is a suitable indicator for a strong acid vs weak base ... | ["B"] | null | <style type="text/css">
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.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sa... | mcq | jee-main-2023-online-31st-january-evening-shift | 2,725 |
1ldsslkqu | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is $$x\times10^{-1}$$. The value of $$x$$ is ___________ (Nearest integer).</p>
<p>Assume complete dissociation.</p> | [] | null | 5 | $$
\begin{aligned}
& \mathrm{pH}=12, \\\\
& \mathrm{pH}+\mathrm{pOH}=14 \\\\
& \mathrm{pOH}=14-12=2 \\\\
& {\left[\mathrm{OH}^{-}\right]=10^{-2} \mathrm{~mol} \mathrm{~L}} \\\\
& \underset{5 \times 10^{-3}}{\mathrm{Ca}(\mathrm{OH})_2} \longrightarrow \underset{5 \times 10^{-3}}{\mathrm{Ca}^{2+}}+\underset{10^{-2}}{2 \m... | integer | jee-main-2023-online-29th-january-morning-shift | 2,727 |
1ldu0alpt | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>When the hydrogen ion concentration [H$$^+$$] changes by a factor of 1000, the value of pH of the solution __________</p> | [{"identifier": "A", "content": "decreases by 2 units"}, {"identifier": "B", "content": "increases by 2 units"}, {"identifier": "C", "content": "decreases by 3 units"}, {"identifier": "D", "content": "increases by 1000 units"}] | ["C"] | null | Let the initial concentration of $\mathrm{H}^{+}$ be 1
<br/><br/>
$\therefore \left[\mathrm{H}^{+}\right]_{\mathrm{i}}=1 \Rightarrow \mathrm{pH}=0$
<br/><br/>
It changes by 1000 units
<br/><br/>
$\therefore \left[\mathrm{H}^{+}\right]_{\mathrm{f}}=10^{3} \Rightarrow \mathrm{pH}=-3$
<br/><br/>
$\therefore \mathrm{pH}$ d... | mcq | jee-main-2023-online-25th-january-evening-shift | 2,728 |
1ldwvwi86 | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>If the pKa of lactic acid is 5, then the pH of 0.005 M calcium lactate solution at 25$$^\circ$$C is ___________ $$\times$$ 10$$^{-1}$$ (Nearest integer)</p>
<p><img src="data:image/png;base64,UklGRsAIAABXRUJQVlA4ILQIAAAwgQCdASoAAygBP4HA3GS2MS2nIxKpCsAwCWlu4WhBG/Pt89+jfqbz3dncxgGN3TvZ/iI1m2opVGbailUZtqKU6q5CKPLyr7bsK... | [] | null | 85 | <p>Concentration of calcium lactate $=0.005 \mathrm{M}$, concentration of lactate ion $=(2 \times 0.005) \mathrm{M}$. <br/><br/>Calcium lactate is a salt of weak acid $+$ strong base<br/><br/> $\therefore$ Salt hydrolysis will take place.</p>
$$
\begin{aligned}
& \mathrm{pH}=7+\frac{1}{2}(\mathrm{pKa}+\log \mathrm{C}) ... | integer | jee-main-2023-online-24th-january-evening-shift | 2,730 |
1ldyhq88p | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>The dissociation constant of acetic acid is $$x\times10^{-5}$$. When 25 mL of 0.2 $$\mathrm{M~CH_3COONa}$$ solution is mixed with 25 mL of 0.02 $$\mathrm{M~CH_3COOH}$$ solution, the pH of the resultant solution is found to be equal to 5. The value of $$x$$ is ____________</p> | [] | null | 10 | $\mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \left(\frac{25 \times 0.2}{25 \times 0.02}\right)$
<br/><br/>
$5=\mathrm{pK}_{\mathrm{a}}+\log 10$
<br/><br/>
$\mathrm{pK}_{\mathrm{a}}=4 \Rightarrow \mathrm{K}_{\mathrm{a}}=10^{-4}=10 \times 10^{-5}$
<br/><br/>
$x=10$ | integer | jee-main-2023-online-24th-january-morning-shift | 2,731 |
1lgp3t9aa | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>20 mL of $$0.1 ~\mathrm{M} ~\mathrm{NaOH}$$ is added to $$50 \mathrm{~mL}$$ of $$0.1 ~\mathrm{M}$$ acetic acid solution. The $$\mathrm{pH}$$ of the resulting solution is ___________ $$\times 10^{-2}$$ (Nearest integer)</p>
<p>Given : $$\mathrm{pKa}\left(\mathrm{CH}_{3} \mathrm{COOH}\right)=4.76$$</p>
<p>$$\log 2=0.3... | [] | null | 458 | First, we need to find the moles of NaOH and acetic acid (CH₃COOH) in the solution:
<br/><br/>
Moles of NaOH = Volume × Molarity = 20 mL × 0.1 M = 2 mmol<br/><br/>
Moles of acetic acid = Volume × Molarity = 50 mL × 0.1 M = 5 mmol
<br/><br/>
Since NaOH is a strong base, it will react with acetic acid to form acetate ion... | integer | jee-main-2023-online-13th-april-evening-shift | 2,733 |
1lgrlpojp | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>An analyst wants to convert $$1 \mathrm{~L} \mathrm{~HCl}$$ of $$\mathrm{pH}=1$$ to a solution of $$\mathrm{HCl}$$ of $$\mathrm{pH} ~2$$. The volume of water needed to do this dilution is __________ $$\mathrm{mL}$$. (Nearest integer)</p> | [] | null | 9000 | <p>We can use the formula for pH to calculate the concentration of hydrogen ions in each solution:</p>
<p>$$\mathrm{pH} = -\log_{10}[\mathrm{H}^+]$$</p>
<p>For the first solution, we have:</p>
<p>$$1 = -\log_{10}[\mathrm{H}^+]$$</p>
<p>Solving for $[\mathrm{H}^+]$, we get:</p>
<p>$$[\mathrm{H}^+] = 0.1 \mathrm{~M}$$</p... | integer | jee-main-2023-online-12th-april-morning-shift | 2,734 |
1lh04uidt | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>The titration curve of weak acid vs. strong base with phenolphthalein as indictor) is shown below. The $$\mathrm{K}_{\text {phenolphthalein }}=4 \times 10^{-10}$$.</p>
<p>Given: $$\log 2=0.3$$</p>
<p><img src="data:image/png;base64,UklGRiAPAABXRUJQVlA4IBQPAABw3gCdASoAA30CP4G41ma2LT+noNDJQ/AwCWlu/BV5Uc4eVbRkp4eg8Xxwh... | [] | null | 2 | <p>A. This statement is incorrect. Phenolphthalein cannot be used as an indicator for the titration of a weak acid with a weak base because the pH at the equivalence point is not within the color change range of phenolphthalein (8.2-10.0).</p>
<p>B. This statement is correct. Phenolphthalein begins to change color at a... | integer | jee-main-2023-online-8th-april-morning-shift | 2,735 |
1lsg889tg | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>The $$\mathrm{pH}$$ of an aqueous solution containing $$1 \mathrm{M}$$ benzoic acid $$\left(\mathrm{pK}_{\mathrm{a}}=4.20\right)$$ and $$1 \mathrm{M}$$ sodium benzoate is 4.5. The volume of benzoic acid solution in $$300 \mathrm{~mL}$$ of this buffer solution is _________ $$\mathrm{mL}$$. (given : $$\log 2=0.3$$)</p... | [] | null | 100 | <p>$$\begin{array}{ccc}
& \text { 1M Benzoic acid } & +1 \mathrm{M} \text { Sodium Benzoate } \\
& \left(\mathrm{V}_{\mathrm{a}} \mathrm{ml}\right) & \left(\mathrm{V}_{\mathrm{s}} \mathrm{ml}\right) \\
\text { Millimole } & \mathrm{V}_{\mathrm{a}} \times 1 & \mathrm{~V}_{\mathrm{s}} \times 1
\end{array}$$</p>
<p>$$\be... | integer | jee-main-2024-online-30th-january-evening-shift | 2,737 |
lv3xmb5f | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>Given below are two statements :</p>
<p>Statement (I) : A Buffer solution is the mixture of a salt and an acid or a base mixed in any particular quantities</p>
<p>Statement (II) : Blood is naturally occurring buffer solution whose $$\mathrm{pH}$$ is maintained by $$\mathrm{H}_2 \mathrm{CO}_3 / \mathrm{HCO}_3{ }^{\om... | [{"identifier": "A", "content": "Both Statement I and Statement II are false\n"}, {"identifier": "B", "content": "Both Statement I and Statement II are true\n"}, {"identifier": "C", "content": "Statement I is false but Statement II is true\n"}, {"identifier": "D", "content": "Statement I is true but Statement II is fal... | ["C"] | null | <p>Let's analyze both statements given to determine the correct answer.</p>
<p>Statement (I) describes a buffer solution as a mixture of a salt and an acid or a base mixed in any particular quantities. However, this definition is partially incorrect. A buffer solution is more accurately defined as a mixture of a weak ... | mcq | jee-main-2024-online-8th-april-evening-shift | 2,738 |
lv3xmaun | chemistry | ionic-equilibrium | ph,-buffer-and-indicators | <p>The equilibrium $$\mathrm{Cr}_2 \mathrm{O}_7^{2-} \rightleftharpoons 2 \mathrm{CrO}_4^{2-}$$ is shifted to the right in :</p> | [{"identifier": "A", "content": "a weakly acidic medium\n"}, {"identifier": "B", "content": "a basic medium\n"}, {"identifier": "C", "content": "a neutral medium\n"}, {"identifier": "D", "content": "an acidic medium"}] | ["B"] | null | <p>The equilibrium $$\mathrm{Cr}_2 \mathrm{O}_7^{2-} \rightleftharpoons 2 \mathrm{CrO}_4^{2-}$$ can be influenced by changes in the pH of the medium, according to Le Chatelier's principle. This principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to c... | mcq | jee-main-2024-online-8th-april-evening-shift | 2,739 |
Foi0Nvb4HaCq16QX | chemistry | ionic-equilibrium | salt-hydrolysis | An aqueous solution contains 0.10 M H<sub>2</sub>S and 0.20 M HCl. If the equilibrium constants for the formation of HS<sup>–</sup> from H<sub>2</sub>S is 1.0 $$\times$$ 10<sup>–7</sup> and that of S<sup>2-</sup> from HS<sup>–</sup> ions is 1.2 $$\times$$ 10<sup>–13</sup> then the concentration of S<sup>2-</sup> ions i... | [{"identifier": "A", "content": "5 $$\\times$$ 10<sup>\u201319</sup>"}, {"identifier": "B", "content": "5 $$\\times$$ 10<sup>\u20138</sup>"}, {"identifier": "C", "content": "3 $$\\times$$ 10<sup>\u201320</sup>"}, {"identifier": "D", "content": "6 $$\\times$$ 10<sup>\u201321</sup>"}] | ["C"] | null | HCl $$ \to $$ H<sup>+</sup> + Cl<sup>$$-$$</sup>
<br><br>H<sup>+</sup> concentration is = 0.2 M.
<br><br>H<sub>2</sub>S $$\rightleftharpoons$$ H<sup>+</sup> + HS<sup>$$-$$</sup>; K<sub>1</sub> = 1.0 $$ \times $$ 10<sup>$$-$$7</sup>
<br><br>HS<sup>$$-$$</sup> $$\rightleftharpoons$$ H<sup>+</sup> + S<sup>2$$-$$</sup>... | mcq | jee-main-2018-offline | 2,740 |
cmYmpm6gdsmzUDxsCn3rsa0w2w9jx0xo7lv | chemistry | ionic-equilibrium | salt-hydrolysis | The pH of a 0.02 M NH<sub>4</sub>Cl solution will be :
<br/> [given K<sub>b</sub> (NH<sub>4</sub>OH) = 10<sup>–5</sup>
and log 2 = 0.301] | [{"identifier": "A", "content": "2.56"}, {"identifier": "B", "content": "5.35"}, {"identifier": "C", "content": "4.35"}, {"identifier": "D", "content": "4.65"}] | ["B"] | null | NH<sub>4</sub><sup>+</sup> + H<sub>2</sub>O ⇋ NH<sub>4</sub>OH + H<sup>+</sup>
<br><br>[H<sup>+</sup>] = c$$\alpha $$
<br><br>= $$\sqrt {{k_a}\left( {NH_4^ + } \right) \times c} $$
<br><br>= $$\sqrt {{{{k_w}} \over {{k_b}\left( {N{H_4}OH} \right)}} \times c} $$
<br><br>= $$\sqrt {{{{{10}^{ - 14}}} \over {{{10}^{ - 5}}... | mcq | jee-main-2019-online-10th-april-evening-slot | 2,742 |
1l6e0t4v9 | chemistry | ionic-equilibrium | salt-hydrolysis | <p>$$20 \mathrm{~mL}$$ of $$0.1\, \mathrm{M} \,\mathrm{NH}_{4} \mathrm{OH}$$ is mixed with $$40 \mathrm{~mL}$$ of $$0.05 \mathrm{M} \mathrm{HCl}$$. The $$\mathrm{pH}$$ of the mixture is nearest to :</p>
<p>(Given : $$\mathrm{K}_{\mathrm{b}}\left(\mathrm{NH}_{4} \mathrm{OH}\right)=1 \times 10^{-5}, \log 2=0.30, \log 3=0... | [{"identifier": "A", "content": "3.2"}, {"identifier": "B", "content": "4.2"}, {"identifier": "C", "content": "5.2"}, {"identifier": "D", "content": "6.2"}] | ["C"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lc5n3y8t/576dd6a8-b446-4165-bbae-8a689475d4ae/819a5cd0-8592-11ed-a4e1-239777dab634/file-1lc5n3y8u.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lc5n3y8t/576dd6a8-b446-4165-bbae-8a689475d4ae/819a5cd0-8592-11ed-a4e1-239777dab634... | mcq | jee-main-2022-online-25th-july-morning-shift | 2,744 |
jaoe38c1lsc5ys78 | chemistry | ionic-equilibrium | salt-hydrolysis | <p>Given below are two statements :</p>
<p>Statement (I) : Aqueous solution of ammonium carbonate is basic.</p>
<p>Statement (II) : Acidic/basic nature of salt solution of a salt of weak acid and weak base depends on $$K_a$$ and $$K_b$$ value of acid and the base forming it.</p>
<p>In the light of the above statements,... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct\n"}, {"identifier": "B", "content": "Statement I is correct but Statement II is incorrect\n"}, {"identifier": "C", "content": "Both Statement I and Statement II are incorrect\n"}, {"identifier": "D", "content": "Statement I is incorrect but ... | ["A"] | null | <p>The correct answer is Option A: Both Statement I and Statement II are correct.</p>
<p>Explanation:</p>
<p>Statement I explains that an aqueous solution of ammonium carbonate is basic. This is because ammonium carbonate ($$\text{(NH}_4)_2\text{CO}_3$$) dissociates in water to form ammonium ions ($$\text{NH}_4^+$$) ... | mcq | jee-main-2024-online-27th-january-morning-shift | 2,745 |
P0hxinWVAB203vL9 | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | Let the solubility of an aqueous solution of Mg(OH)<sub>2</sub> be x then its K<sub>sp</sub> is : | [{"identifier": "A", "content": "4x<sup>3</sup>"}, {"identifier": "B", "content": "108x<sup>5</sup>"}, {"identifier": "C", "content": "27x<sup>4</sup>"}, {"identifier": "D", "content": "9x"}] | ["A"] | null | $$Mg{\left( {OH} \right)_2} \to \mathop {\left[ {M{g^{2 + }}} \right]}\limits_x + 2\mathop {\left[ {O{H^ - }} \right]}\limits_{2x} $$
<br><br>$${K_{sp}} = \left[ {Mg} \right]{\left[ {OH} \right]^2}$$
<br><br>$$ = \left[ x \right]{\left[ {2x} \right]^2}$$
<br><br>$$ = x.4{x^2} = 4{x^3}.$$ | mcq | aieee-2002 | 2,746 |
h4URh3UyijpeHvTH | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility in water of a sparingly soluble salt AB<sub>2</sub> is 1.0 $$\times$$ 10<sup>-5</sup> mol L<sup>-1</sup>. Its solubility product number will be : | [{"identifier": "A", "content": "4 $$\\times$$ 10<sup>-10</sup>"}, {"identifier": "B", "content": "1 $$\\times$$ 10<sup>-15</sup>"}, {"identifier": "C", "content": "1 $$\\times$$ 10<sup>-10</sup>"}, {"identifier": "D", "content": "4 $$\\times$$ 10<sup>-15</sup>"}] | ["D"] | null | $$A{B_2}\rightleftharpoons\,{A^{ + 2}} + 2{B^ - }$$
<br><br>$$\left[ A \right] = 1.0 \times {10^{ - 5}},\,\,$$
<br><br>$$\left[ B \right] = \left[ {2.0 \times {{10}^{ - 5}}} \right],$$
<br><br>$${K_{sp}} = {\left[ B \right]^2}\left[ A \right]$$
<br><br>$$ = {\left[ {2 \times {{10}^{ - 5}}} \right]^2}\left[ {1.0 \times... | mcq | aieee-2003 | 2,747 |
xxqL8L3VO9oz19IW | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The molar solubility (in ol L<sup>-1</sup>) of a sparingly soluble salt MX<sub>4</sub> is "s". The corresponding solubility product is K<sub>sp</sub>. 's' is given in term of K<sub>sp</sub> by the relation : | [{"identifier": "A", "content": "s = (256 K<sub>sp</sub>)<sup>1/5</sup>"}, {"identifier": "B", "content": "s = (128 K<sub>sp</sub>)<sup>1/4</sup>"}, {"identifier": "C", "content": "s = ( K<sub>sp</sub> / 128)<sup>1/4</sup>"}, {"identifier": "D", "content": "s = (K<sub>sp</sub> / 256)<sup>1/5</sup>"}] | ["D"] | null | $$M{X_4}\rightleftharpoons\,\mathop {{M^{4 + }}}\limits_{S\,\,\,\,\,\,\,} + \mathop {4{X^ - }}\limits_{4S} $$
<br><br>$${K_{sp}} = \left[ s \right]{\left[ {4s} \right]^4} = 256\,{s^5}$$
<br><br>$$\therefore$$ $$\,\,\,\,\,s = {\left( {{{{K_{sp}}} \over {256}}} \right)^{1/5}}$$ | mcq | aieee-2004 | 2,748 |
rnHtJcU7gKFAqmjU | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility product of a salt having general formula MX<sub>2</sub>, in water is: 4 $$\times$$ 10<sup>-12</sup> . The
concentration of M<sup>2+</sup> ions in the aqueous solution of the salt is : | [{"identifier": "A", "content": "2.0 $$\\times$$ 10<sup>-6</sup> M"}, {"identifier": "B", "content": "4.0 $$\\times$$ 10<sup>-10</sup> M"}, {"identifier": "C", "content": "1.0 $$\\times$$ 10<sup>-4</sup> M"}, {"identifier": "D", "content": "1.6 $$\\times$$ 10<sup>-4</sup> M"}] | ["C"] | null | $$M{X_2}\,\rightleftharpoons\,\,\mathop {{M^{ 2 + }}}\limits_{s\,\,\,\,\,\,\,\,} \,\, + \,\,\mathop {2{X^ - }}\limits_{2s} $$
<br><br>Where $$s$$ is the solubility of $$M{X_2}$$
<br><br>then $${K_{sp}} = $$ $$s \times {\left( {2s} \right)^2}$$ = $$4{s^3}$$;
<br><br>$$ \Rightarrow $$$$ 4 \times {10^{ - 12}} = 4{s^3};$... | mcq | aieee-2005 | 2,749 |
MyppAjJ3G6Ufgaoa | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | In a sautrated solution of the sparingly soluble strong electrolyte AgIO<sub>3</sub> (Molecular mass = 283) the
equilibrium which sets in is <br/>
AgIO<sub>3(s)</sub> $$\leftrightharpoons$$ Ag<sup>+</sup>(aq) + $$IO_3^-$$<br/>
If the solubility product constant K<sub>sp</sub> of AgIO<sub>3</sub> at a given temperature ... | [{"identifier": "A", "content": "28.3 \u00d7 10<sup>\u22122</sup> g"}, {"identifier": "B", "content": "2.83 \u00d7 10<sup>\u22123</sup> g"}, {"identifier": "C", "content": "1.0 \u00d7 10<sup>\u22127</sup> g"}, {"identifier": "D", "content": "1.0 \u00d7 10<sup>\u22124</sup> g"}] | ["B"] | null | Let $$\,\,\,s = \,\,\,$$ solubility
<br><br>$$Ag{\rm I}{O_3}\,\rightleftharpoons\,\mathop {A{g^ + }}\limits_s \,\,\mathop {{\rm I}{O_3}^ - }\limits_s $$
<br><br>$${K_{sp}} = \left[ {A{g^ + }} \right]\left[ {{\rm I}{O_3}^ - } \right]$$
<br><br>$$ = s \times s = {s^2}$$
<br><br>Given $$\,\,\,{K_{sp}} = 1 \times {10^{ - 8... | mcq | aieee-2007 | 2,750 |
4dFsBO6B8XgokkaY | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | Solid Ba(NO<sub>3</sub>)<sub>2</sub> is gradually dissolved in a 1.0 $$\times$$ 10<sup>-4</sup> M Na<sub>2</sub>CO<sub>3</sub> solution. At what concentration of Ba<sup>2+</sup> will a precipitate begin to form ?<br/>
(K<sub>sp</sub> for BaCO<sub>3</sub> = 5.1 $$\times$$ 10<sup>−9</sup> ) | [{"identifier": "A", "content": "5.1 $$\\times$$ 10<sup>-5</sup> M"}, {"identifier": "B", "content": "8.1 $$\\times$$ 10<sup>-8</sup> M"}, {"identifier": "C", "content": "8.1 $$\\times$$ 10<sup>-7</sup> M"}, {"identifier": "D", "content": "4.1 $$\\times$$ 10<sup>-5</sup> M"}] | ["A"] | null | $$\mathop {N{a_2}C{O_3}}\limits_{1 \times {{10}^{ - 4}}M} \to \mathop {2N{a^ + }}\limits_{1 \times {{10}^{ - 4}}M} \,\, + \,\,\mathop {C{O_3}^{2 - }}\limits_{1 \times {{10}^{ - 4}}M} $$
<br><br>$${K_{SP\left( {BaC{O_3}} \right)}} = \left[ {B{a^{2 + }}} \right]\left[ {CO_3^{2 - }} \right]$$
<br><br>$$\left[ {B{a^{2 +... | mcq | aieee-2009 | 2,751 |
ZYnlp6BhJXpGc1fB | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | Solubility product of silver bromide is 5.0 $$\times$$ 10<sup>–13</sup>. The quantity of potassium bromide (molar mass taken as 120g of mol<sup>–1</sup>) to be added to 1 litre of 0.05 M solution of silver nitrate to start the
precipitation of AgBr is : | [{"identifier": "A", "content": "1.2 $$\\times$$ 10<sup>\u201310</sup> g"}, {"identifier": "B", "content": "1.2 $$\\times$$ 10<sup>\u20139</sup> g"}, {"identifier": "C", "content": "6.2 $$\\times$$ 10<sup>\u20135</sup> g"}, {"identifier": "D", "content": "5.0 $$\\times$$ 10<sup>\u20138</sup> g"}] | ["B"] | null | $$AgBr\,\rightleftharpoons\,A{g^ + } + B{r^ - }$$
<br><br>$${K_{sp}} = \left[ {A{g^ + }} \right]\left[ {B{r^ - }} \right]$$
<br><br>For precipitation to occur
<br><br>Ionic product $$>$$ Solubility product
<br><br>$$\left[ {B{r^ - }} \right] = {{{K_{sp}}} \over {\left[ {A{g^ + }} \right]}} = {{5 \times {{10}^{ - 13}... | mcq | aieee-2010 | 2,752 |
4REoJPtiRGdnZEXE | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | An aqueous solution contains an unknown concentration of Ba<sup>2+</sup>. When 50 mL of a 1 M solution of Na<sub>2</sub>SO<sub>4</sub> is added, BaSO<sub>4</sub> just begins to precipitate. The final volume is 500 mL. The solubility product of BaSO<sub>4</sub> is 1 $$\times$$ 10<sup>–10</sup>. What is the original conc... | [{"identifier": "A", "content": "1.0 $$\\times$$ 10<sup>\u201310</sup> M "}, {"identifier": "B", "content": "5 $$\\times$$ 10<sup>\u20139</sup> M "}, {"identifier": "C", "content": "2 $$\\times$$ 10<sup>\u20139</sup> M "}, {"identifier": "D", "content": "1.1 $$\\times$$ 10<sup>\u20139</sup> M "}] | ["D"] | null | Let initially concentration of Ba<sup>+2</sup> = x m.
<br><br>After adding 50 ml Na<sub>2</sub>SO<sub>4</sub> in Ba<sup>+2</sup> solution final volume becomes 500 ml.
<br><br>$$\therefore\,\,\,$$ Initial volume of Ba<sup>+2</sup> solution
<br><br>= (500 $$-$$ 50) ml = 450 ml
<br><br>As at the begining of precipitat... | mcq | jee-main-2018-offline | 2,753 |
9L2veFGDZcPzQu5zUJcko | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The minimum volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution (K<sub>sp</sub> of PbCl<sub>2</sub> = 3.2 $$ \times $$ 10<sup>-8</sup> atomic mass of Pb = 207 u ) is : | [{"identifier": "A", "content": "0.36 L"}, {"identifier": "B", "content": "17.98 L"}, {"identifier": "C", "content": "0.18 L"}, {"identifier": "D", "content": "1.798 L"}] | ["C"] | null | Given,
<br><br>K<sub>sp</sub> of PbCl<sub>2</sub> = 3.2 $$ \times $$10<sup>$$-$$8</sup>
<br><br><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;border:none;}
.tg td{font-family:Arial, sans-serif;font-size:14px;padding:10px 5px;border-style:solid;border-width:0px;overflow:hidden;word-break:nor... | mcq | jee-main-2018-online-15th-april-morning-slot | 2,754 |
ruSuuwhZ7iwJLKmaGKODQ | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | If K<sub>sp</sub> of Ag<sub>2</sub>CO<sub>3</sub> is 8 $$ \times $$ 10<sup>–12</sup>, the molar solubility of Ag<sub>2</sub>CO<sub>3</sub> in 0.1 M AgNO<sub>3</sub> is - | [{"identifier": "A", "content": "8 $$ \\times $$ 10<sup>\u201312</sup> M "}, {"identifier": "B", "content": "8 $$ \\times $$ 10<sup>\u201310</sup> M "}, {"identifier": "C", "content": "8 $$ \\times $$ 10<sup>\u201313</sup> M "}, {"identifier": "D", "content": "8 $$ \\times $$ 10<sup>\u201311</sup> M "}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265174/exam_images/qsaudv1ekpp1e0rjorfh.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Ionic Equilibrium Question 77 English Explanation">
<br>$$... | mcq | jee-main-2019-online-12th-january-evening-slot | 2,758 |
utgcehQJcUzIbmHTinyGy | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | A mixture of 100 m mol of Ca(OH)<sub>2</sub> and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of OH<sup>–</sup> in resulting solution, respectively, are : (Molar mass of Ca (OH)<sub>2</sub>, Na<sub>2</sub>SO<sub>4</sub> and... | [{"identifier": "A", "content": "13.6g, 0.28 mol L<sup>$$-$$1</sup>"}, {"identifier": "B", "content": "13.6g, 0.14 mol L<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "1.9g, 0.28 mol L<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "1.9g, 0.14 mol L<sup>$$-$$1</sup>"}] | ["C"] | null | Ca(OH)<sub>2</sub> + Na<sub>2</sub>SO<sub>4</sub> $$ \to $$ CaSO<sub>4</sub> + 2NaOH
<br><br>100 m mol 14 m mol $$-$$ $$-$$ $$-$$
<br><br>$$-$$ $$-$$ $$-$$ &... | mcq | jee-main-2019-online-10th-january-morning-slot | 2,759 |
GHQulOrsKHJzMcocrh7k9k2k5h5o46m | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively :
<img src="data:image/png;base64,UklGRkAKAABXRUJQVlA4IDQKAACwRACdASokAeMAPm0yl0kkIqIhIjDaAIANiWlu8n+d62vIiq8D/yL8VfAv+tfkH1znfv2b3Ub4d7uX23+X/uV/UP2H98/8R/Vf168/fUh6hHqL+3/yT9e/Pv/d+4zqT+gHsEdpv7L/G/2v/wfnSfr35Fe5... | [{"identifier": "A", "content": "XY, 2 \u00d7 10<sup>\u20136</sup> M<sup>3</sup>"}, {"identifier": "B", "content": "XY<sub>2</sub>, 1 \u00d7 10<sup>\u20139</sup> M<sup>3</sup>"}, {"identifier": "C", "content": "XY<sub>2</sub>, 4 \u00d7 10<sup>\u20139</sup> M<sup>3</sup>"}, {"identifier": "D", "content": "X<sub>2</sub>Y... | ["C"] | null | From the given curve,
<br><br>if [X] = 1 mM then [Y] = 2 mM
<br><br>$$ \therefore $$ Salt is XY<sub>2</sub>
<br><br>XY<sub>2</sub>(s) ⇌ X<sup>2+</sup>(aq.) + 2Y<sup>-</sup>(aq.)
<br><br>k<sub>sp</sub> = [X<sup>2+</sup>][Y<sup>–</sup>]<sup>2</sup>
<br><br>= (10<sup>–3</sup>) (2 × 10<sup>–3</sup>)<sup>2</sup>
<br><br>= ... | mcq | jee-main-2020-online-8th-january-morning-slot | 2,760 |
iJn3IKg7Pnd9s0V1vS7k9k2k5lla8rp | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility product of Cr(OH)<sub>3</sub> at 298 K is
6.0 × 10<sup>–31</sup>. The concentration of hydroxide ions
in a saturated solution of Cr(OH)<sub>3</sub> will be : | [{"identifier": "A", "content": "(2.22 \u00d7 10<sup>\u201331</sup>)<sup>1/4</sup>"}, {"identifier": "B", "content": "(4.86 \u00d7 10<sup>\u201329</sup>)<sup>1/4</sup>"}, {"identifier": "C", "content": "(18 \u00d7 10<sup>\u201331</sup>)<sup>1/4</sup>"}, {"identifier": "D", "content": "(18 \u00d7 10<sup>\u201331</sup>)<... | ["C"] | null | <table class="tg">
<tbody><tr>
<th class="tg-nrix">Cr(OH)<sub>3</sub></th>
<th class="tg-nrix">⇌</th>
<th class="tg-nrix">Cr<sup>+3</sup></th>
<th class="tg-nrix">+</th>
<th class="tg-nrix">3OH<sup>-</sup></th>
</tr>
<tr>
<td class="tg-nrix"></td>
<td class="tg-nrix"></td>
<td clas... | mcq | jee-main-2020-online-9th-january-evening-slot | 2,762 |
H2zZyPaYCYEshked6Gjgy2xukevfq7al | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | For the following <b>Assertion</b> and <b>Reason</b>, the
correct option is
<br/><br/><b>Assertion (A):</b> When Cu (II) and sulphide ions
are mixed, they react together
extremely quickly to give a
solid.
<br/><br/><b>Reason (R):</b> The equilibrium constant of
<br/>Cu<sup>2+</sup>(aq) + S<sup>2–</sup>(aq) ⇌ CuS(s) is
... | [{"identifier": "A", "content": "(A) is false and (R) is true."}, {"identifier": "B", "content": "Both (A) and (R) are true but (R) is not the\nexplanation for (A)."}, {"identifier": "C", "content": "Both (A) and (R) are true and (R) is the\nexplanation for (A)."}, {"identifier": "D", "content": "Both (A) and (R) are f... | ["C"] | null | K<sub>sp</sub> value of CuS is very low 10<sup>–36</sup> (3.6 × 10<sup>–36</sup>)
due to low K<sub>sp</sub> value Cu<sup>+2</sup> ion gets precipitated
very quickly even with very low concentration
of S<sup>–2</sup> ion. | mcq | jee-main-2020-online-2nd-september-morning-slot | 2,763 |
LZvQFJXke06eYwWeEajgy2xukg4nse7j | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | If the solubility product of AB<sub>2</sub> is 3.20 $$ \times $$ 10<sup>–11</sup> M<sup>3</sup>,
then the solubility of AB<sub>2</sub> in pure water is
_____ $$ \times $$ 10<sup>–4</sup> mol L<sup>–1</sup>.
<br/>[Assuming that neither kind
of ion reacts with water] | [] | null | 2 | <table class="tg">
<thead>
<tr>
<th class="tg-baqh">AB<sub>2</sub></th>
<th class="tg-baqh">⇌</th>
<th class="tg-baqh">A<sup>2+</sup>(aq)</th>
<th class="tg-baqh">+</th>
<th class="tg-baqh">2B<sup>-</sup>(aq)</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-baqh"></td>
<td class="tg-baqh... | integer | jee-main-2020-online-6th-september-evening-slot | 2,764 |
eoJGRg1yAf9eucbt8O1klrv7cqq | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility product of PbI<sub>2</sub> is 8.0 $$\times$$ 10<sup>$$-$$9</sup>. The solubility of lead iodide in 0.1 molar solution of lead nitrate is x $$\times$$ 10<sup>$$-$$6</sup>. mol/L. The value of x is __________. (Rounded off to the nearest integer) [Given $$\sqrt 2 $$ = 1.41] | [] | null | 141 | Given, $${[{K_{sp}}]_{Pb{l_2}}} = 8 \times {10^{ - 9}}$$<br/><br/>To calculate solubility of Pbl<sub>2</sub> in 0.1 M solution of Pb(NO<sub>3</sub>)<sub>2</sub>,<br/><br/>(I) $$\mathop {Pb{{(N{O_3})}_2}}\limits_{0. 1 M} \to \mathop {P{b^{2 + }}(aq)}\limits_{0.1 M} + \mathop {2NO_3^ - (aq)}\limits_{0. 2 M} $$<br/><br/... | integer | jee-main-2021-online-24th-february-evening-slot | 2,765 |
9tluPF7LC9EBRnfOeF1kls7vr2v | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility of AgCN in a buffer solution of pH = 3 is x. The value of x is : [Assume : No cyano complex is formed; K<sub>sp</sub>(AgCN) = 2.2 $$\times$$ 10<sup>$$-$$16</sup> and K<sub>a</sub>(HCN) = 6.2 $$\times$$ 10<sup>$$-$$10</sup>] | [{"identifier": "A", "content": "1.9 $$\\times$$ 10<sup>$$-$$5</sup>"}, {"identifier": "B", "content": "1.6 $$\\times$$ 10<sup>$$-$$6</sup>"}, {"identifier": "C", "content": "2.2 $$\\times$$ 10<sup>$$-$$16</sup>"}, {"identifier": "D", "content": "0.625 $$\\times$$ 10<sup>$$-$$6</sup>"}] | ["A"] | null | Let solubility is x<br><br><picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266551/exam_images/wmzy67d962sr3u5oybne.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263624/exam_images/gumayomfjhdesu8ekiyd.we... | mcq | jee-main-2021-online-25th-february-morning-slot | 2,766 |
d5nZSxCsVC9CoGEX1N1kltas7ex | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility of Ca(OH)<sub>2</sub> in water is :<br/><br/>[Given : The solubility product of Ca(OH)<sub>2</sub> in water = 5.5 $$\times$$ 10<sup>$$-$$6</sup>] | [{"identifier": "A", "content": "1.11 $$\\times$$ 10<sup>$$-$$6</sup>"}, {"identifier": "B", "content": "1.11 $$\\times$$ 10<sup>$$-$$2</sup>"}, {"identifier": "C", "content": "1.77 $$\\times$$ 10<sup>$$-$$6</sup>"}, {"identifier": "D", "content": "1.77 $$\\times$$ 10<sup>$$-$$2</sup>"}] | ["B"] | null | <p>Let, solubility of Ca(OH)<sub>2</sub> in pure water = S mol/L</p>
<p>$$Ca{(OH)_2}$$ $$\rightleftharpoons$$ $$\mathop {C{a^{2 + }}}\limits_{S\,mol/L} + \mathop {2O{H^ - }}\limits_{2 \times S\,(mol/L)} $$</p>
<p>K<sub>sp</sub> = [Ca<sup>2+</sup>] [OH<sup>$$-$$</sup>]<sup>2</sup> = S $$\times$$ (2S)<sup>2</sup> = 4 S<... | mcq | jee-main-2021-online-25th-february-evening-slot | 2,767 |
ywjhuLjM6QKZMBELtB1kmm27yc2 | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The solubility of CdSO<sub>4</sub> in water is 8.0 $$\times$$ 10<sup>$$-$$4</sup> mol L<sup>$$-$$1</sup>. Its solubility in 0.01 M H<sub>2</sub>SO<sub>4</sub> solution is __________ $$\times$$ 10<sup>$$-$$6</sup> mol L<sup>$$-$$1</sup>. (Round off to the Nearest Integer). (Assume that solubility is much less than 0.01 ... | [] | null | 64 | In pure water<br><br> <picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266524/exam_images/cl79fjsa4ty6xbsrveqw.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265420/exam_images/m2caaaud6r4fa48n4jvc.webp"><... | integer | jee-main-2021-online-18th-march-evening-shift | 2,769 |
1ktihjurh | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | A<sub>3</sub>B<sub>2</sub> is a sparingly soluble salt of molar mass M (g mol<sup>$$-$$1</sup>) and solubility x g L<sup>$$-$$1</sup>. The solubility product satisfies $${K_{sp}} = a{\left( {{x \over M}} \right)^5}$$. The value of a is _____________. (Integer answer) | [] | null | 108 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263453/exam_images/sduvrntvzc6vz9f5sz10.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 31st August Morning Shift Chemistry - Ionic Equilibrium Question 44 English Explanation"><br><br>K... | integer | jee-main-2021-online-31st-august-morning-shift | 2,771 |
1ktn2aoyo | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | The molar solubility of Zn(OH)<sub>2</sub> in 0.1 M NaOH solution is x $$\times$$ 10<sup>$$-$$18</sup> M. The value of x is _________ (Nearest integer)<br/><br/>(Given : The solubility product of Zn(OH)<sub>2</sub> is 2 $$\times$$ 10<sup>$$-$$20</sup>) | [] | null | 2 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1kwopll5y/1b87b674-5e27-4886-8831-8b9dd4ae62a1/ac994060-534b-11ec-9cbb-695a838b20fb/file-1kwopll5z.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1kwopll5y/1b87b674-5e27-4886-8831-8b9dd4ae62a1/ac994060-534b-11ec-9cbb-695a838b20fb/fi... | integer | jee-main-2021-online-1st-september-evening-shift | 2,772 |
1l548kqa9 | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>The solubility of AgCl will be maximum in which of the following?</p> | [{"identifier": "A", "content": "0.01 M KCl"}, {"identifier": "B", "content": "0.01 M HCl"}, {"identifier": "C", "content": "0.01 M AgNO<sub>3</sub>"}, {"identifier": "D", "content": "Deionised water"}] | ["D"] | null | <p>In deionized water no common ion effect will take
place so maximum solubility.</p> | mcq | jee-main-2022-online-29th-june-morning-shift | 2,773 |
1l56bjhok | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>The solubility product of a sparingly soluble salt A<sub>2</sub>X<sub>3</sub> is 1.1 $$\times$$ 10<sup>$$-$$23</sup>. If specific conductance of the solution is 3 $$\times$$ 10<sup>$$-$$5</sup> S m<sup>$$-$$1</sup>, the limiting molar conductivity of the solution is $$x \,\times$$ 10<sup>$$-$$3</sup> S m<sup>2</sup>... | [] | null | 3 | $A_{2} X_{3} \rightleftharpoons \underset{2S}{2 \mathrm{~A}}+\underset{3S}{3 \mathrm{X}}$
<br/><br/>
$$
\begin{aligned}
&\mathrm{K}_{\mathrm{sp}}=(2 \mathrm{~s})^{2}(3 s)^{3}=1.1 \times 10^{-23} \\\\
&\mathrm{~S} \approx 10^{-5}
\end{aligned}
$$
<br/><br/>
For sparingly soluble salts
<br/><br/>
$$
\begin{aligned}
\wedg... | integer | jee-main-2022-online-28th-june-morning-shift | 2,774 |
1l59qmg9d | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>The K<sub>sp</sub> for bismuth sulphide (Bi<sub>2</sub>S<sub>3</sub>) is 1.08 $$\times$$ 10<sup>$$-$$73</sup>. The solubility of Bi<sub>2</sub>S<sub>3</sub> in mol L<sup>$$-$$1</sup> at 298 K is :</p> | [{"identifier": "A", "content": "1.0 $$\\times$$ 10<sup>$$-$$15</sup>"}, {"identifier": "B", "content": "2.7 $$\\times$$ 10<sup>$$-$$12</sup>"}, {"identifier": "C", "content": "3.2 $$\\times$$ 10<sup>$$-$$10</sup>"}, {"identifier": "D", "content": "4.2 $$\\times$$ 10<sup>$$-$$8</sup>"}] | ["A"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5k0djkt/0df5bd8d-fc81-45e3-8459-254386070eb4/d87bb0d0-02e3-11ed-baaf-13f0aedc901d/file-1l5k0djku.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5k0djkt/0df5bd8d-fc81-45e3-8459-254386070eb4/d87bb0d0-02e3-11ed-baaf-13f0aedc901d/fi... | mcq | jee-main-2022-online-25th-june-evening-shift | 2,775 |
1l6p8vlrf | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>If the solubility product of PbS is 8 $$\times$$ 10<sup>$$-$$28</sup>, then the solubility of PbS in pure water at 298 K is x $$\times$$ 10<sup>$$-$$16</sup> mol L<sup>$$-$$1</sup>. The value of x is __________. (Nearest Integer)</p>
<p>[Given : $$\sqrt2$$ = 1.41]</p> | [] | null | 282 | $$\mathrm{K}_{\mathrm{sp}}=\mathrm{S}^{2}$$
<br/><br/>
$$\mathrm{S}=\sqrt{K_{s p}}=\sqrt{8 \times 10^{-28}}=2 \sqrt{2} \times 10^{-14}$$
<br/><br/>
$$=2.82 \times 10^{-14}$$
<br/><br/>
$$=282 \times 10^{-16}$$
<br/><br/>$$ \therefore $$ Ans. 282 | integer | jee-main-2022-online-29th-july-morning-shift | 2,777 |
1lgq5g5il | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>$$25.0 \mathrm{~mL}$$ of $$0.050 ~\mathrm{M} ~\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}$$ is mixed with $$25.0 \mathrm{~mL}$$ of $$0.020 ~\mathrm{M} ~\mathrm{NaF} . \mathrm{K}_{\mathrm{Sp}}$$ of $$\mathrm{BaF}_{2}$$ is $$0.5 \times 10^{-6}$$ at $$298 \mathrm{~K}$$. The ratio of $$\left[\mathrm{Ba}^{2+}\right]\left... | [] | null | 5 | Initial concentrations before mixing:<br/><br/>
$$[\mathrm{Ba(NO_3)_2}] = 0.050\, \mathrm{M}$$<br/><br/>
$$[\mathrm{NaF}] = 0.020\, \mathrm{M}$$
<br/><br/>
Volumes of the solutions:<br/><br/>
$$V_{\mathrm{Ba(NO_3)_2}} = V_{\mathrm{NaF}} = 25.0\, \mathrm{mL}$$
<br/><br/>
After mixing, the total volume becomes:<br/><br/>... | integer | jee-main-2023-online-13th-april-morning-shift | 2,779 |
1lguzjr9b | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>$$25 \mathrm{~mL}$$ of silver nitrate solution (1M) is added dropwise to $$25 \mathrm{~mL}$$ of potassium iodide $$(1.05 \mathrm{M})$$ solution. The ion(s) present in very small quantity in the solution is/are :</p> | [{"identifier": "A", "content": "$$\\mathrm{I^-}$$ only"}, {"identifier": "B", "content": "$$\\mathrm{K^+}$$ only"}, {"identifier": "C", "content": "$$\\mathrm{Ag^+}$$ and $$\\mathrm{I^-}$$ both"}, {"identifier": "D", "content": "$$\\mathrm{NO_3^-}$$ only"}] | ["C"] | null | The reaction between silver nitrate (AgNO<sub>3</sub>) and potassium iodide (KI) forms silver iodide (AgI), which is practically insoluble in water. The reaction is as follows :
<br/><br/>AgNO<sub>3</sub>(aq) + KI(aq) → AgI(s) + KNO<sub>3</sub>(aq)
<br/><br/>Although the reaction stoichiometry indicates that iodide i... | mcq | jee-main-2023-online-11th-april-morning-shift | 2,780 |
lsanzb5m | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | Solubility of calcium phosphate (molecular mass, M) in water is $\mathrm{W_{g}}$ per $100 \mathrm{~mL}$ at $25^{\circ} \mathrm{C}$. Its solubility product at $25^{\circ} \mathrm{C}$ will be approximately. | [{"identifier": "A", "content": "$10^7\\left(\\frac{W}{M}\\right)^3$"}, {"identifier": "B", "content": "$10^3\\left(\\frac{\\mathrm{W}}{\\mathrm{M}}\\right)^5$"}, {"identifier": "C", "content": "$10^7\\left(\\frac{W}{M}\\right)^5$"}, {"identifier": "D", "content": "$10^5\\left(\\frac{\\mathrm{W}}{\\mathrm{M}}\\right)^5... | ["C"] | null | <p>To determine the solubility product (K<sub>sp</sub>) of calcium phosphate, we need to consider its chemical formula and how it dissociates in water. The formula for calcium phosphate is $\text{Ca}_3(\text{PO}_4)_2$. When dissolved in water, it dissociates according to the following equation:</p>
<p>$$
\text{Ca}_3(\t... | mcq | jee-main-2024-online-1st-february-evening-shift | 2,782 |
1lsgz2sxr | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>The $$\mathrm{pH}$$ at which $$\mathrm{Mg}(\mathrm{OH})_2\left[\mathrm{~K}_{\mathrm{sp}}=1 \times 10^{-11}\right]$$ begins to precipitate from a solution containing $$0.10 \mathrm{~M} \mathrm{~Mg}^{2+}$$ ions is __________.</p> | [] | null | 9 | <p>$$\begin{aligned}
& \text { Precipitation when } Q_{s p}=K_{s p} \\
& {\left[\mathrm{Mg}^{2+}\right]\left[\mathrm{OH}^{-}\right]^2=10^{-11}} \\
& 0.1 \times\left[\mathrm{OH}^{-}\right]^2=10^{-11} \Rightarrow\left[\mathrm{OH}^{-}\right]=10^{-5} \\
& \Rightarrow \mathrm{pOH}=5 \quad \Rightarrow \mathrm{pH}=9
\end{alig... | integer | jee-main-2024-online-30th-january-morning-shift | 2,783 |
luxzq6c0 | chemistry | ionic-equilibrium | solubility-product-and-common-ion-effect | <p>For a sparingly soluble salt $$\mathrm{AB}_2$$, the equilibrium concentrations of $$\mathrm{A}^{2+}$$ ions and $$B^{-}$$ ions are $$1.2 \times 10^{-4} \mathrm{M}$$ and $$0.24 \times 10^{-3} \mathrm{M}$$, respectively. The solubility product of $$\mathrm{AB}_2$$ is :</p> | [{"identifier": "A", "content": "$$0.069 \\times 10^{-12}$$\n"}, {"identifier": "B", "content": "$$0.276 \\times 10^{-12}$$\n"}, {"identifier": "C", "content": "$$6.91 \\times 10^{-12}$$\n"}, {"identifier": "D", "content": "$$27.65 \\times 10^{-12}$$"}] | ["C"] | null | <p>For a sparingly soluble salt $\mathrm{AB}_2$, the dissolution in water can be represented by the following equilibrium equation:</p>
<p>$ \mathrm{AB}_2 \rightleftharpoons \mathrm{A}^{2+} + 2\mathrm{B}^{-} $</p>
<p>When $\mathrm{AB}_2$ dissolves in water, it generates one $\mathrm{A}^{2+}$ ion and two $\mathrm{B}^{... | mcq | jee-main-2024-online-9th-april-evening-shift | 2,784 |
i4GqcPX1rTNDDfuk | chemistry | isolation-of-elements | concentration-of-ore | Which one of the following ores is best concentrated by froth – floatation method? | [{"identifier": "A", "content": "Magnetite"}, {"identifier": "B", "content": "Malachite "}, {"identifier": "C", "content": "Galena"}, {"identifier": "D", "content": "Cassiterite"}] | ["C"] | null | <b>NOTE :</b> Galena is PbS and thus purified by froth floatation method.
<br><br>Froath floatation method is used to concentrate sulphide ores. This method is based on the preferential wetting properties with the froathing agent and water. | mcq | aieee-2004 | 2,785 |
QHtu3F3jR3nmee7n | chemistry | isolation-of-elements | concentration-of-ore | Which of the following factors is of <b>no significance</b> for roasting sulphide ores to the oxides and not
subjecting the sulphide ores to carbon reduction directly? | [{"identifier": "A", "content": "Metal sulphides are thermodynamically more stable than CS<sub>2</sub>"}, {"identifier": "B", "content": "CO<sub>2</sub> is thermodynamically more stable than CS<sub>2</sub>"}, {"identifier": "C", "content": "Metal sulphides are less stable than the corresponding oxides"}, {"identifier":... | ["C"] | null | <b>NOTE :</b> The reduction of metal sulphides by carbon reduction process is not spontaneous because $$\Delta G$$ for such a process is positive. The reduction of metal oxide by carbon reduction process is spontaneous as $$\Delta G$$ for such a process is negative.
<br><br>From this we find that on thermodynamic consi... | mcq | aieee-2008 | 2,786 |
QPpBDaEXy72VYavK | chemistry | isolation-of-elements | concentration-of-ore | Which one of the following ores is best concentrated by froth floatation method? | [{"identifier": "A", "content": "Siderite"}, {"identifier": "B", "content": "Galena"}, {"identifier": "C", "content": "Malachite"}, {"identifier": "D", "content": "Magnetite"}] | ["B"] | null | Froth floatation method is mainly applicable for sulphide ores.
<br><br>$$(1)$$ Malachite ore : $$Cu{\left( {OH} \right)_2},\,\,CuC{O_3}$$
<br><br>$$(2)$$ Magnetite ore : $$F{e_3}{O_4}$$
<br><br>$$(3)$$ Siderite ore : $$FeC{O_3}$$
<br><br>$$(4)$$ Galena ore : $$PbS$$ (Sulphide Ore) | mcq | jee-main-2016-offline | 2,787 |
1fM0uOKXgH77sdhdAcrUU | chemistry | isolation-of-elements | concentration-of-ore | In the leaching method, bauxite ore is digested with a concentrated solution of NaOH that produces 'X'. When CO<sub>2</sub> gas is passed through the aqueous solution of 'X', a hydrated compound 'Y' is precipitated. 'X' and 'Y' respectively are : | [{"identifier": "A", "content": "NaAlO<sub>2</sub> and Al<sub>2</sub>(CO<sub>3</sub>)<sub>3</sub>.x H<sub>2</sub>O"}, {"identifier": "B", "content": "A(OH)<sub>3</sub> and Al<sub>2</sub>O<sub>3</sub>.x H<sub>2</sub>O"}, {"identifier": "C", "content": "Na[Al(OH)<sub>4</sub>] and ... | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265657/exam_images/nbgod9tzqmbe3kfvlxaj.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Evening Slot Chemistry - Isolation of Elements Question 103 English Explanation"> | mcq | jee-main-2018-online-15th-april-evening-slot | 2,788 |
8kOTKOq3hXvrPlSSSm3rsa0w2w9jx4z8tme | chemistry | isolation-of-elements | concentration-of-ore | The idea of froth floatation method came from a person X and this method is related to the process Y of ores. X and Y, respectively, are : | [{"identifier": "A", "content": "washer woman and concentration"}, {"identifier": "B", "content": "fisher woman and concentration"}, {"identifier": "C", "content": "wisher man and reduction"}, {"identifier": "D", "content": "fisher man and reduction"}] | ["A"] | null | Froth floatation is a method of concentration
and it was discovered by a washer women. | mcq | jee-main-2019-online-12th-april-morning-slot | 2,789 |
1krutaldk | chemistry | isolation-of-elements | concentration-of-ore | In the leaching of alumina from bauxite, the ore expected to leach out in the process by reacting with NaOH is : | [{"identifier": "A", "content": "TiO<sub>2</sub>"}, {"identifier": "B", "content": "Fe<sub>2</sub>O<sub>3</sub>"}, {"identifier": "C", "content": "ZnO"}, {"identifier": "D", "content": "SiO<sub>2</sub>"}] | ["D"] | null | In bauxite impurities of Fe<sub>2</sub>O<sub>3</sub>, TiO<sub>2</sub> and SiO<sub>2</sub> are present, Fe<sub>2</sub>O<sub>3</sub> and TiO<sub>2</sub> are basic oxides therefore does not reacts with or dissolve in NaOH whereas SiO<sub>2</sub> is acidic oxide it gets dissolve in NaOH, hence leach out<br><br>$$Si{O_2} + ... | mcq | jee-main-2021-online-25th-july-morning-shift | 2,791 |
1l56wthv6 | chemistry | isolation-of-elements | concentration-of-ore | <p>Statement I : Leaching of gold with cyanide ion in absence of air / O<sub>2</sub> leads to cyano complex of Au(III).</p>
<p>Statement II : Zinc is oxidized during the displacement reaction carried out for gold extraction.</p>
<p>In the light of the above statements, choose the correct answer from the options given b... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct."}, {"identifier": "B", "content": "Both Statement I and Statement II are incorrect."}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect."}, {"identifier": "D", "content": "Statement I is incorrect but Sta... | ["D"] | null | Leaching of gold with cyanide ion is done in
presence of air/O<sub>2</sub> leading to cyano complex [Au(CN)<sub>2</sub>]<sup>–</sup> where Au is in +1 oxidation state.<br/><br/>
4Au(s) + 8CN<sup>–</sup>(aq) + 2H<sub>2</sub>O(aq) + O<sub>2</sub>(g) $$\longrightarrow 4\left[\mathrm{Au}(\mathrm{CN})_{2}\right]_{\mathrm{a... | mcq | jee-main-2022-online-27th-june-evening-shift | 2,793 |
1l58iyg9y | chemistry | isolation-of-elements | concentration-of-ore | <p>The role of depressants in 'Froth Flotation method' is to</p> | [{"identifier": "A", "content": "selectively prevent one component of the ore from coming to the froth."}, {"identifier": "B", "content": "reduce the consumption of oil for froth formation."}, {"identifier": "C", "content": "stabilize the froth."}, {"identifier": "D", "content": "enhance non-wettability of the mineral ... | ["A"] | null | Depressant prevent one component from coming to
the froth.<br/><br/>
For eg., in Galena ore, the depressant (NaCN)
prevents impurity (ZnS) from coming to the froth. | mcq | jee-main-2022-online-26th-june-evening-shift | 2,795 |
1l5altec2 | chemistry | isolation-of-elements | concentration-of-ore | <p>Leaching of gold with dilute aqueous solution of NaCN in presence of oxygen gives complex [A], which on reaction with zinc forms the elemental gold and another complex [B]. [A] and [B], respectively are :</p> | [{"identifier": "A", "content": "$${[Au{(CN)_4}]^ - }$$ and $${[Zn{(CN)_2}{(OH)_2}]^{2 - }}$$"}, {"identifier": "B", "content": "$${[Au{(CN)_2}]^ - }$$ and $${[Zn{(OH)_4}]^{2 - }}$$"}, {"identifier": "C", "content": "$${[Au{(CN)_2}]^{ - }}$$ and $${[Zn{(CN)_4}]^{2 - }}$$"}, {"identifier": "D", "content": "$${[Au{(CN)_4... | ["C"] | null | In the metallurgy of gold <br/><br/>
$$4 \mathrm{Au}+8 \mathrm{CN}^{-}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2} \rightarrow 4\left[\mathrm{Au}(\mathrm{CN})_{2}\right]^{-}+4 \mathrm{OH}^{-}$$<br/><br/>
$$2\left[\mathrm{Au}(\mathrm{CN})_{2}\right]^{-}+\mathrm{Zn} \rightarrow\left[\mathrm{Zn}(\mathrm{CN})_{4}\right]^{2-... | mcq | jee-main-2022-online-25th-june-morning-shift | 2,796 |
1l6mckl7d | chemistry | isolation-of-elements | concentration-of-ore | <p>Which of the reaction is suitable for concentrating ore by leaching process ?</p> | [{"identifier": "A", "content": "$$\n2 \\mathrm{Cu}_{2} \\mathrm{~S}+3 \\mathrm{O}_{2} \\rightarrow 2 \\mathrm{Cu}_{2} \\mathrm{O}+2 \\mathrm{SO}_{2}\n$$"}, {"identifier": "B", "content": "$$\\mathrm{Fe}_{3} \\mathrm{O}_{4}+\\mathrm{CO} \\rightarrow 3 \\mathrm{FeO}+\\mathrm{CO}_{2}$$"}, {"identifier": "C", "content": "... | ["C"] | null | Leaching involves the treatment of ore with a suitable reagent so as it make it soluble while impurities remain insoluble.
<br/><br/>
$\mathrm{Al}_{2} \mathrm{O}_{3}+2 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \underset{\text{Soluble complex}}{2 \mathrm{Na}\left[\mathrm{Al}(\mathrm{OH})_{4}\right]}$ | mcq | jee-main-2022-online-28th-july-morning-shift | 2,797 |
lgnzhs7y | chemistry | isolation-of-elements | concentration-of-ore | Which one of the following is not an example of calcination?
| [{"identifier": "A", "content": "$\\mathrm{CaCO}_{3} \\cdot \\mathrm{MgCO}_{3} \\stackrel{\\Delta}{\\longrightarrow} \\mathrm{CaO}+\\mathrm{MgO}+2 \\mathrm{CO}_{2}$"}, {"identifier": "B", "content": "$2 \\mathrm{PbS}+3 \\mathrm{O}_{2} \\stackrel{\\Delta}{\\longrightarrow} 2 \\mathrm{PbO}+2 \\mathrm{SO}_{2}$"}, {"identi... | ["B"] | null | Calcination is the process of heating a solid material in the absence of air or with limited air to remove volatile components or to cause thermal decomposition. Among the given reactions:
<br/><br/>
(A) $\mathrm{CaCO}_3 \cdot \mathrm{MgCO}_3 \stackrel{\Delta}{\longrightarrow} \mathrm{CaO}+\mathrm{MgO}+2 \mathrm{CO}_2... | mcq | jee-main-2023-online-15th-april-morning-shift | 2,800 |
1lgsxytzu | chemistry | isolation-of-elements | concentration-of-ore | <p>Given below are two statements :</p>
<p>Statement I : In the metallurgy process, sulphide ore is converted to oxide before reduction.</p>
<p>Statement II : Oxide ores in general are easier to reduce.</p>
<p>In the light of the above statements, choose the most appropriate answer from the options given below:</p> | [{"identifier": "A", "content": "Both Statement I and Statement II are correct"}, {"identifier": "B", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect"}, {"identifier": "D", "content": "Statement I is incorrect but Statem... | ["A"] | null | Option A is the correct answer.
<br/><br/><b>Statement I :</b> In the metallurgy process, sulphide ore is converted to oxide before reduction.
<br/><br/>This is correct. In metallurgy, it is common to first convert sulphide ores to oxides because it's typically easier to reduce oxides to extract the metal. This proc... | mcq | jee-main-2023-online-11th-april-evening-shift | 2,801 |
1lgyg7v84 | chemistry | isolation-of-elements | concentration-of-ore | <p>Which of the following is used as a stabilizer during the concentration of sulphide ores?</p> | [{"identifier": "A", "content": "Cresols"}, {"identifier": "B", "content": "Xanthates"}, {"identifier": "C", "content": "Fatty acids"}, {"identifier": "D", "content": "Pine oils"}] | ["A"] | null | In the froth floatation process pine oils, fatty acids, and xanthates are collectors, and froth stabilizers cresols, and aniline are used. | mcq | jee-main-2023-online-10th-april-morning-shift | 2,802 |
n1na8OMg6dfS7k3d0cPd8 | chemistry | isolation-of-elements | ellingham-diagram | The correct statement regarding the given Ellingham diagram is :
<br/><br/><img src="data:image/png;base64,UklGRp4jAABXRUJQVlA4IJIjAABQhgGdASoAA6ECP4G+12Q2MCwmolKKOsAwCWlu/BV39HCv6B4T6vmH9hPX/8+/pP2H82dXvgT+M6P/77e8v+8/Pjzb/ZPn/9wv+R/4/p7QSHB3Pl61n/HjTf9unHWif/71E/n//49gj+Qf/8ZEREREREREQ+pF7goiIcRzBR/3d3d3d3WB+bevfi86... | [{"identifier": "A", "content": "At 1400<sup>o</sup>C, Al can be used for the extraction of Zn from ZnO"}, {"identifier": "B", "content": "At 500<sup>o</sup>C, coke can be used for the extraction of Zn from ZnO"}, {"identifier": "C", "content": "Coke cannot be used for the extraction of Cu from Cu<sub>2</sub>O. "}, {"... | ["A"] | null | According to the given diagram A1 can reduce ZnO.
<br><br>3ZnO + 2Al $$ \to $$ 3Zn + Al<sub>2</sub>O<sub>3</sub> | mcq | jee-main-2019-online-9th-january-evening-slot | 2,803 |
3aMFytgPWP5T3vn5B7Hhm | chemistry | isolation-of-elements | ellingham-diagram | With respect to an ore, Ellingham diagram helps to predict the feasibility of its. | [{"identifier": "A", "content": "Electrolysis"}, {"identifier": "B", "content": "Thermal reducation"}, {"identifier": "C", "content": "Vapour phase refining"}, {"identifier": "D", "content": "Zone refining"}] | ["B"] | null | Ellingham diagram gives idea that which sustance or metal is suitable for thermal reduction of oxide. | mcq | jee-main-2019-online-8th-april-morning-slot | 2,804 |
WJhy8wq0ceMlXGDnZK7k9k2k5ic7l7f | chemistry | isolation-of-elements | ellingham-diagram | According to the following diagram, A reduces
BO<sub>2</sub> when the temperature is :
<img src="data:image/png;base64,UklGRuoUAABXRUJQVlA4IN4UAABQaQCdASqkAesAPm0ylkikIqIhIvN68IANiWlu/CX4putQzP0j/nn5JeBX9c/sfj/+EfKP2n8jvSt+GupG+Ke6p+A/i/9f/1f5s+9H+S/lf9d/2fmj7p/4r1BfTf9v/iP9Z/6H9m9PX+l/hv9e7/EAX5X/Jf8B/I/67/z/7N5xn75/I... | [{"identifier": "A", "content": "> 1400 \u00b0C"}, {"identifier": "B", "content": "> 1200 \u00b0C but < 1400 \u00b0C"}, {"identifier": "C", "content": "< 1400 \u00b0C"}, {"identifier": "D", "content": "< 1200 \u00b0C"}] | ["A"] | null | Reduction of BO<sub>2</sub> using A
<br><br>A + BO<sub>2</sub> $$ \to $$ B + AO<sub>2</sub>
<br><br>$$\Delta $$G = –ve
<br><br>Only above 1400 <sup>o</sup>C. | mcq | jee-main-2020-online-9th-january-morning-slot | 2,805 |
5ZWNUw5xBZyL610W1Tjgy2xukfja5umg | chemistry | isolation-of-elements | ellingham-diagram | An Ellingham diagram provides information
about : | [{"identifier": "A", "content": "the temperature dependence of the\nstandard Gibbs energies of formation of\nsome metal oxides"}, {"identifier": "B", "content": "the pressure dependence of the standard\nelectrode potentials of reduction reactions\ninvolved in the extraction of metals"}, {"identifier": "C", "content": "... | ["A"] | null | An Ellingham diagram provides information
about, the temperature dependence of the
standard gibbs energies of formation of some
metal oxides. | mcq | jee-main-2020-online-5th-september-morning-slot | 2,806 |
en8KxGfA8e01Wp6oft1klsbki4q | chemistry | isolation-of-elements | ellingham-diagram | Ellingham diagram is a graphical representation of : | [{"identifier": "A", "content": "$$\\Delta$$G vs P"}, {"identifier": "B", "content": "$$\\Delta$$G vs T"}, {"identifier": "C", "content": "($$\\Delta$$G $$-$$ T$$\\Delta$$S) vs T"}, {"identifier": "D", "content": "$$\\Delta$$H vs T"}] | ["B"] | null | Ellingham diagram is a graphical
representation of $$\Delta $$G vs T when metal heated
with oxygen to form metal oxide. | mcq | jee-main-2021-online-25th-february-morning-slot | 2,807 |
tU16jaFQXDsLtm5blc1kmj7x0my | chemistry | isolation-of-elements | ellingham-diagram | The point of intersection and sudden increase in the slope, in the diagram given below, respectively, indicates :<br/><br/><img src="data:image/png;base64,UklGRqgoAABXRUJQVlA4IJwoAADQ1ACdASoRAtABP4G21GO2Laumo7ELQsAwCWlu/C50HjATWmNwtX8F/pH/A/tndd/yv8V5S+fr6vtj/kmSO132Deg/7VeI/zx///UF8/+lt9f2MWx/8b0BfcvND+e8yf5P/bewBwG/5... | [{"identifier": "A", "content": "$$\\Delta$$G > 0 and decomposition of the metal oxide"}, {"identifier": "B", "content": "$$\\Delta$$G < 0 and decomposition of the metal oxide"}, {"identifier": "C", "content": "$$\\Delta$$G = 0 and reduction of the metal oxide"}, {"identifier": "D", "content": "$$\\Delta$$G = 0 a... | ["D"] | null | From the Ellingham diagram given, the point of
intersection represents ΔG = 0 and the temperature
at which sudden increase in the slope occurs is
indicated by melting or boiling. | mcq | jee-main-2021-online-17th-march-morning-shift | 2,808 |
1krz18yvs | chemistry | isolation-of-elements | ellingham-diagram | The statement is incorrect about Ellingham diagram is | [{"identifier": "A", "content": "provides idea about the reaction rate."}, {"identifier": "B", "content": "provides idea about free energy change."}, {"identifier": "C", "content": "provides idea about changes in the phases during the reaction."}, {"identifier": "D", "content": "provides idea about reduction of metal o... | ["A"] | null | Ellingham diagram is a plot between $$\Delta$$G$$^\circ$$ and T and does not give any information regarding rate of reaction. | mcq | jee-main-2021-online-27th-july-morning-shift | 2,809 |
1ktb50g0y | chemistry | isolation-of-elements | ellingham-diagram | Given below are two statements :<br/><br/>Statement I : The choice of reducing agents for metals extraction can be made by using Ellingham diagram, a plot of $$\Delta$$G vs temperature.<br/><br/>Statement II : The value of $$\Delta$$S increases from left to right in Ellingham diagram.<br/><br/>In the light of the above... | [{"identifier": "A", "content": "Both Statement I and Statement II are true"}, {"identifier": "B", "content": "Statement I is false but Statement II is true"}, {"identifier": "C", "content": "Both Statement I and Statement II are false"}, {"identifier": "D", "content": "Statement I is true but Statement II is false"}] | ["D"] | null | Given Statement I is true as in a number of processes, one element is used to reduce the oxide of another metal. Any element will reduce the oxide of other metal which lie above it in the Ellingham diagram because the free energy change will become more negative.<br><br>Given Statement II is false as the value of $$\De... | mcq | jee-main-2021-online-26th-august-morning-shift | 2,810 |
1l58dpl6l | chemistry | isolation-of-elements | ellingham-diagram | <p>Given below are two statements :</p>
<p>Statement I : According to Ellingham diagram, any metal oxide with higher $$\Delta$$G$$^\circ$$ is more stable than the one with lower $$\Delta$$G$$^\circ$$.</p>
<p>Statement II : The metal involved in the formation of oxide placed lower in the Ellingham diagram can reduce the... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct."}, {"identifier": "B", "content": "Both Statement I and Statement II are incorrect."}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect."}, {"identifier": "D", "content": "Statement I is incorrect but Sta... | ["D"] | null | Ellingham diagram is plot of $$\Delta $$G vs T.
The criterion for the feasibility of a thermal
reduction is that at a given temperature Gibbs
energy change of a reaction must be negative. The
change in Gibbs energy, $$\Delta $$G for any process at any
specified temperature is given by the equation<br/><br/>
$$\Delta $$... | mcq | jee-main-2022-online-26th-june-morning-shift | 2,811 |
1ldoia26j | chemistry | isolation-of-elements | ellingham-diagram | <p>Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R</p>
<p>Assertion A: In an Ellingham diagram, the oxidation of carbon to carbon monoxide shows a negative slope with respect to temperature.</p>
<p>Reason R: CO tends to get decomposed at higher temperature.</p>
<p>In... | [{"identifier": "A", "content": "A is correct but R is not correct"}, {"identifier": "B", "content": "Both A and R are correct but R is NOT the correct explanation of A"}, {"identifier": "C", "content": "A is not correct but R is correct"}, {"identifier": "D", "content": "Both A and R are correct and R is the correct e... | ["A"] | null | $$
2 \mathrm{C}(\mathrm{s})+\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{CO}(\mathrm{g})
$$
<br/><br/>$\Delta_{\mathrm{r}} \mathrm{S}^0$ is $+v e, \Delta_{\mathrm{r}} \mathrm{G}^0=\Delta_{\mathrm{r}} \mathrm{H}^0-\mathrm{T} \Delta_{\mathrm{r}} \mathrm{S}^0$;
<br/><br/>Thus slope is negative.
<br/><br/>As temperatur... | mcq | jee-main-2023-online-1st-february-morning-shift | 2,812 |
1lgp2vpwg | chemistry | isolation-of-elements | ellingham-diagram | <p>Given below are two statements related to Ellingham diagram:</p>
<p>Statement I : Ellingham diagrams can be constructed for formation of oxides, sulfides and halides of metals.</p>
<p>Statement II : It consists of plots of $$\Delta_{\mathrm{f}} \mathrm{H}^{0}$$ vs $$\mathrm{T}$$ for formation of oxides of elements.<... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct"}, {"identifier": "B", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect"}, {"identifier": "D", "content": "Statement I is incorrect but Statem... | ["C"] | null | <p><b>Statement I is correct</b>, Ellingham diagram can be constructed for formation of oxides, sulphides and halides of metals. (As per NCERT)</p>
<p><b>Statement II is incorrect</b> because Ellingham diagram consists of $\Delta_t G^0$ vs $T$ for formation of oxides of elements.</p> | mcq | jee-main-2023-online-13th-april-evening-shift | 2,813 |
1lgrkermy | chemistry | isolation-of-elements | ellingham-diagram | <p>Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R</p>
<p>Assertion A : In the Ellingham diagram, a sharp change in slope of the line is observed for $$\mathrm{Mg} \rightarrow \mathrm{MgO}$$ at $$\sim 1120^{\circ} \mathrm{C}$$</p>
<p>Reason R: There is a large change... | [{"identifier": "A", "content": "Both $$\\mathbf{A}$$ and $$\\mathbf{R}$$ are true and $$\\mathbf{R}$$ is the correct explanation of $$\\mathbf{A}$$"}, {"identifier": "B", "content": "$$\\mathbf{A}$$ is false but $$\\mathbf{R}$$ is true"}, {"identifier": "C", "content": "Both $$\\mathbf{A}$$ and $$\\mathbf{R}$$ are tru... | ["A"] | null | In the Ellingham diagram, a sharp change in slope of the line is observed for $\mathrm{Mg}-\mathrm{MgO}$ at $\sim 1120^{\circ} \mathrm{C}$ because that is the boiling point of magnesium.<br/><br/>
There is a large increase in entropy associated with the change of state of magnesium. So, both Assertion (A) and Reason (R... | mcq | jee-main-2023-online-12th-april-morning-shift | 2,814 |
1lgvtn5wo | chemistry | isolation-of-elements | ellingham-diagram | <p>Gibbs energy vs T plot for the formation of oxides is given below.</p>
<p><img src="data:image/png;base64,UklGRpIbAABXRUJQVlA4IIYbAADwOAGdASoAA2gCP4G+12Q2MKwmovLKEsAwCWlu/AkYS02nZ18frZ+yXe/kM6bD///ye3ztd3unmAQQVc/Pjkd8v/lmze2PUMNVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVU37TqC3YUi8nMFss80+afNPmnzT5p80+afNPmnzT5p803OyVZW8zMZWFIv... | [{"identifier": "A", "content": "At $$600^{\\circ} \\mathrm{C}, \\mathrm{C}$$ can reduce $$\\mathrm{FeO}$$"}, {"identifier": "B", "content": "At $$600{ }^{\\circ} \\mathrm{C}, \\mathrm{C}$$ can reduce $$\\mathrm{ZnO}$$"}, {"identifier": "C", "content": "At $$600^{\\circ} \\mathrm{C}, \\mathrm{CO}$$ can reduce $$\\mathr... | ["A"] | null | <p>The Ellingham diagram is a graphical representation of the Gibbs Free Energy change of various reactions, mainly reduction reactions of metal oxides to the metal. The temperature is plotted on the x-axis, and the Gibbs Free Energy per mole of O<sub>2</sub> is plotted on the y-axis.</p>
<p>In the Ellingham diagram, e... | mcq | jee-main-2023-online-10th-april-evening-shift | 2,815 |
TnyU78xKvWYnv0Hv | chemistry | isolation-of-elements | extractions-of-metals | Aluminium is extracted by the electrolysis of | [{"identifier": "A", "content": "bauxite"}, {"identifier": "B", "content": "alumina"}, {"identifier": "C", "content": "alumina mixed with molten cryolite"}, {"identifier": "D", "content": "molten cryolite"}] | ["C"] | null | Pure aluminium can be obtained by electrolysis of a mixture containing alumina, crayolite and fluorspar in the ratio $$20:24:20.$$ The fusion temperature of this mixture is $${900^ \circ }C$$ and it is a good conductor of electricity. | mcq | aieee-2002 | 2,816 |
wHgo9N84n61Kzqkz | chemistry | isolation-of-elements | extractions-of-metals | The metal extracted by leaching with a cyanide is | [{"identifier": "A", "content": "Mg"}, {"identifier": "B", "content": "Ag"}, {"identifier": "C", "content": "Cu"}, {"identifier": "D", "content": "Na"}] | ["B"] | null | Silver ore forms a soluble complex with $$NaCN$$ from which silver is precipitated using scrap zinc.
<br><br>$$A{g_2}S + 2NaCN \to $$
<br><br>$$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Na\left[ {Ag{{\left( {CN} \right)}_2}} \right]\buildrel {Zn} \over
\longrightarrow $$
<br><br>$$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\... | mcq | aieee-2002 | 2,817 |
iVORBt4a2dAC3T1vsAi9N | chemistry | isolation-of-elements | extractions-of-metals | Extraction of copper by smelting uses silica as an additive to remove : | [{"identifier": "A", "content": "Cu<sub>2</sub>S"}, {"identifier": "B", "content": "FeO"}, {"identifier": "C", "content": "FeS"}, {"identifier": "D", "content": "Cu<sub>2</sub>O"}] | ["B"] | null | <p>The gangue material in the ore is removed by adding
another chemical substance called flux. If ore has basic
impurities, such as FeO, CaO, MgO, etc. suitable acid
flux such as SiO<sub>2</sub>
, P<sub>2</sub>O<sub>5</sub>
, etc. are used. For example, in the
extraction of copper, ferrous oxide (FeO), a basic impurity... | mcq | jee-main-2016-online-10th-april-morning-slot | 2,818 |
ObIp8z72OiwR9tsWjXi30 | chemistry | isolation-of-elements | extractions-of-metals | Hall- Heroult's process is given by : | [{"identifier": "A", "content": "Cu<sup>2+</sup> (aq) + H<sub>2</sub>(g) $$ \\to $$ Cu(s) + 2H<sup>+</sup> (aq)"}, {"identifier": "B", "content": "Cr<sub>2</sub>O<sub>3</sub> + 2AI $$ \\to $$ Al<sub>2</sub>O<sub>3</sub> + 2Cr"}, {"identifier": "C", "content": "2Al<sub>2</sub>O<sub>3</sub> + 3C &nbs... | ["C"] | null | In Hall-Heroult's process is given by
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264504/exam_images/gzkqzkappwphsku6fbfe.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Isolation of Ele... | mcq | jee-main-2019-online-10th-january-morning-slot | 2,820 |
Ndqg2KPW3H8RC9m7UEqfj | chemistry | isolation-of-elements | extractions-of-metals | In the Hall-Heroult process, aluminium is formed at the cathode. The cathode is made out of - | [{"identifier": "A", "content": "Copper "}, {"identifier": "B", "content": "Platinum "}, {"identifier": "C", "content": "Carbon"}, {"identifier": "D", "content": "Pure aluminium "}] | ["C"] | null | In the Hall-Heroult process the cathode is made of carbon. | mcq | jee-main-2019-online-12th-january-morning-slot | 2,821 |
DeCVT3bOXyRFMsxPWSsH2 | chemistry | isolation-of-elements | extractions-of-metals | The pair that does NOT require calcination is - | [{"identifier": "A", "content": "Fe<sub>2</sub>O<sub>3</sub> and CaCO<sub>3</sub>\u22c5MgCO<sub>3</sub>"}, {"identifier": "B", "content": "ZnCO<sub>3</sub> and CaO "}, {"identifier": "C", "content": "ZnO and Fe<sub>2</sub>O<sub>3</sub>\u22c5xH<sub>2</sub>O"}, {"identifier": "D", "content": "ZnO and MgO "}] | ["D"] | null | In calcination, we convert a compound or ore into oxide.
<br><br>In option (D) you can see there is ZnO and MgO, as they are already in oxide form so no calcination required for then. | mcq | jee-main-2019-online-12th-january-evening-slot | 2,822 |
OyCo4tb0bZEABK8UBzOr8 | chemistry | isolation-of-elements | extractions-of-metals | <b>Assertion: </b>For the extraction of iron, haematite
ore is used.<br/><br/>
<b>Reason:</b> Haematite is a carbonate ore of iron. | [{"identifier": "A", "content": "Both the assertion and reason are correct\nand the reason is the correct explanation for\nthe assertion."}, {"identifier": "B", "content": "Only the reason is correct."}, {"identifier": "C", "content": "Both the assertion and reason are correct,\nbut the reason is not the correct explan... | ["D"] | null | For the extraction of iron, haematite ore in
used.
<br><br>Haematite = Fe<sub>2</sub>O<sub>3</sub> which is a oxide ore not carbonate ore. | mcq | jee-main-2019-online-9th-april-evening-slot | 2,823 |
JREybSne4o6KDMU9XW3rsa0w2w9jx85286e | chemistry | isolation-of-elements | extractions-of-metals | The correct statement is : | [{"identifier": "A", "content": "leaching of bauxite using concentrated NaOH solution gives sodium aluminate and sodium silicate"}, {"identifier": "B", "content": "the Hall-Heroult process is used for the production of aluminium and iron"}, {"identifier": "C", "content": "pig iron is obtained from cast iron"}, {"identi... | ["A"] | null | (A) Leaching of bauxite :
<br>Al<sub>2</sub>O<sub>3</sub>.H<sub>2</sub>O + NaOH $$ \to $$ Na[Al(OH)<sub>4</sub>] + Na<sub>2</sub>SiO<sub>3</sub>
<br>So, option (A) is correct.
<br><br>(B) Hall Heroult’s process is used for aluminium only not for iron.
<br>So, option (B) is wrong.
<br><br>(C) From Blast Furnace, at the... | mcq | jee-main-2019-online-12th-april-evening-slot | 2,824 |
yGuymlnZ8QqbaYboGe7k9k2k5hkj969 | chemistry | isolation-of-elements | extractions-of-metals | Among the reactions (a) - (d), the reaction(s)
that does/do not occur in the blast furnace
during the extraction of iron is/are :<br/>
(a) CaO + SiO<sub>2</sub> $$ \to $$ CaSiO<sub>3</sub><br/>
(b) 3Fe<sub>2</sub>O<sub>3</sub> + CO $$ \to $$ 2Fe<sub>3</sub>O<sub>4</sub> + CO<sub>2</sub><br/>
(c) FeO + SiO<sub>2</sub> $... | [{"identifier": "A", "content": "(a) and (d)"}, {"identifier": "B", "content": "(c) and (d)"}, {"identifier": "C", "content": "(a)"}, {"identifier": "D", "content": "(d)"}] | ["B"] | null | In blast furnace (metallugy of iron) involved
reactions are
<br><br>(a) CaO + SiO<sub>2</sub> $$ \to $$ CaSiO<sub>3</sub>
<br><br>(b) 3Fe<sub>2</sub>O<sub>3</sub> + CO $$ \to $$ 2Fe<sub>3</sub>O<sub>4</sub> + CO<sub>2</sub> | mcq | jee-main-2020-online-8th-january-evening-slot | 2,826 |
7imRerkDmrKVkYWsFbjgy2xukexzdnpf | chemistry | isolation-of-elements | extractions-of-metals | Cast iron is used for the manufacture of : | [{"identifier": "A", "content": "wrought iron, pig iron and steel"}, {"identifier": "B", "content": "wrought iron and pig iron"}, {"identifier": "C", "content": "wrought iron and steel"}, {"identifier": "D", "content": "pig iron, scrap iron and steel"}] | ["C"] | null | Cast iron is used for manufacturing of wrought
iron and steel. | mcq | jee-main-2020-online-2nd-september-evening-slot | 2,827 |
WN4UCaO02aiJMbBB2S1klurlmb0 | chemistry | isolation-of-elements | extractions-of-metals | Match List - I with List - II.<br/><br/><table>
<thead>
<tr>
<th></th>
<th>List - I </th>
<th></th>
<th>List - II</th>
</tr>
</thead>
<tbody>
<tr>
<td>(a)</td>
<td>Sodium Carbonate</td>
<td>(i)</td>
<td>Deacon</td>
</tr>
<tr>
<td>(b)</td>
<td>Titanium</td>
<td>(ii)</td>
<td>Castner-Kellner</td>
</tr>
<tr>
<td>(c)</td>
... | [{"identifier": "A", "content": "(a) $$ \\to $$ (iv), (b) $$ \\to $$ (iii), (c) $$ \\to $$ (i), (d) $$ \\to $$ (ii)"}, {"identifier": "B", "content": "(a) $$ \\to $$ (iv), (b) $$ \\to $$ (i), (c) $$ \\to $$ (ii), (d) $$ \\to $$ (iii)"}, {"identifier": "C", "content": "(a) $$ \\to $$ (iii), (b) $$ \\to $$ (ii), (c) $$ \... | ["A"] | null | (a) Sodium carbonate is prepared by Solvay
process<br><br>
(b) Titanium is refined by Van-Arkel process<br><br>
(c) Chlorine is prepared by Deacon process<br><br>
(d) Sodium hydroxide is prepared by Castner-Kellner process
| mcq | jee-main-2021-online-26th-february-evening-slot | 2,828 |
igxsI4p6NuXqY3PNOp1klusni8h | chemistry | isolation-of-elements | extractions-of-metals | Calgon is used for water treatment. Which of the following statement is NOT true about Calgon? | [{"identifier": "A", "content": "It is also known as Graham's salt. "}, {"identifier": "B", "content": "It is polymeric compound and is water soluble."}, {"identifier": "C", "content": "It does not remove Ca<sup>2+</sup> ion by precipitation."}, {"identifier": "D", "content": "Calgon contains the 2<sup>nd</sup> most ab... | ["D"] | null | Calgon is sodium hexametaphosphate, a
polymeric compound also called as Graham’s
salt.<br><br>
Order of abundance of element in earth crust is<br><br>
O > Si > Al > Fe > Ca > Na > Mg > K<br><br>
So second most abundant element in earth crust is Si not Ca. | mcq | jee-main-2021-online-26th-february-evening-slot | 2,829 |
piPmrb97jTRvovoAqn1kmhtoobd | chemistry | isolation-of-elements | extractions-of-metals | The process that involves the removal of sulphur from the ores is : | [{"identifier": "A", "content": "Roasting"}, {"identifier": "B", "content": "Smelting"}, {"identifier": "C", "content": "Leaching"}, {"identifier": "D", "content": "Refining"}] | ["A"] | null | Removal of sulphur from the ore is done by
Roasting. | mcq | jee-main-2021-online-16th-march-morning-shift | 2,830 |
NDKD4oPlCMkymvn4261kmiup4ww | chemistry | isolation-of-elements | extractions-of-metals | Which of the following reduction reaction CANNOT be carried out with coke? | [{"identifier": "A", "content": "ZnO $$ \\to $$ Zn"}, {"identifier": "B", "content": "Fe<sub>2</sub>O<sub>3</sub> $$ \\to $$ Fe"}, {"identifier": "C", "content": "Cu<sub>2</sub>O $$ \\to $$ Cu"}, {"identifier": "D", "content": "Al<sub>2</sub>O<sub>3</sub> $$ \\to $$ Al"}] | ["D"] | null | Al<sub>2</sub>O<sub>3</sub> is reduced by the electrolytic reduction method. | mcq | jee-main-2021-online-16th-march-evening-shift | 2,831 |
4xv3ylxzIWHghwSi411kmlnjabg | chemistry | isolation-of-elements | extractions-of-metals | The chemical that is added to reduce the melting point of the reaction mixture during the extraction of aluminium is : | [{"identifier": "A", "content": "Cryolite"}, {"identifier": "B", "content": "Bauxite"}, {"identifier": "C", "content": "Calamine"}, {"identifier": "D", "content": "Kaolite"}] | ["A"] | null | Alumina is mixed with Na<sub>3</sub>AlF<sub>6</sub> (Cryolite) and CaF<sub>2</sub> to lower the melting point of mixture. | mcq | jee-main-2021-online-18th-march-morning-shift | 2,832 |
1ks1gnx25 | chemistry | isolation-of-elements | extractions-of-metals | Which one of the following set of elements can be detected using sodium fusion extract? | [{"identifier": "A", "content": "Sulfur, Nitrogen, Phosphorous, Halogens"}, {"identifier": "B", "content": "Phosphorous, Oxygen, Nitrogen, Halogens"}, {"identifier": "C", "content": "Nitrogen, Phosphorous, Carbon, Sulfur"}, {"identifier": "D", "content": "Halogens, Nitrogen, Oxygen, Sulfur"}] | ["A"] | null | By sodium fusion extract we can detect Sulphur, Nitrogen, Phosphorous and Halogens, because they are converted in to their ionic form with sodium metal. | mcq | jee-main-2021-online-27th-july-evening-shift | 2,833 |
1ks1ir1k8 | chemistry | isolation-of-elements | extractions-of-metals | The addition of silica during the extraction of copper from its sulphide ore :- | [{"identifier": "A", "content": "converts copper sulphide into copper silicate"}, {"identifier": "B", "content": "converts iron oxide into iron silicate"}, {"identifier": "C", "content": "reduces copper sulphide into metallic copper"}, {"identifier": "D", "content": "reduces the melting point of the reaction mixture"}] | ["B"] | null | Silica is used to remove FeO impurity from the ore of copper<br><br>$$FeO + Si{O_2} \to \mathop {FeSi{O_3}}\limits_{iron\,silicate\,(Slag)} $$ | mcq | jee-main-2021-online-27th-july-evening-shift | 2,834 |
1l55n81ek | chemistry | isolation-of-elements | extractions-of-metals | <p>In the metallurgical extraction of copper, following reaction is used :</p>
<p>FeO + SiO<sub>2</sub> $$\to$$ FeSiO<sub>3</sub></p>
<p>FeO and FeSiO<sub>3</sub> respectively are.</p> | [{"identifier": "A", "content": "gangue and flux."}, {"identifier": "B", "content": "flux and slag."}, {"identifier": "C", "content": "slag and flux."}, {"identifier": "D", "content": "gangue and slag."}] | ["D"] | null | FeO + SiO<sub>2</sub> → FeSiO<sub>3</sub><br/><br/>
FeO = Gangue and FeSiO<sub>3</sub> = Slag | mcq | jee-main-2022-online-28th-june-evening-shift | 2,837 |
1l56aonz6 | chemistry | isolation-of-elements | extractions-of-metals | <p>Given are two statements one is labelled as Assertion A and other is labelled as Reason R.</p>
<p>Assertion A : Magnesium can reduce Al<sub>2</sub>O<sub>3</sub> at a temperature below 1350$$^\circ$$C, while above 1350$$^\circ$$C, while above 1350$$^\circ$$C aluminium can reduce MgO.</p>
<p>Reason R : The melting and... | [{"identifier": "A", "content": "Both A and R are correct, and R is correct explanation of A."}, {"identifier": "B", "content": "Both A and R are correct, but R is NOT the correct explanation of A."}, {"identifier": "C", "content": "A is correct R is not correct."}, {"identifier": "D", "content": "A is not correct, R i... | ["B"] | null | Magnesium can reduce Al<sub>2</sub>O<sub>3</sub> at a temperature
below 1350°C while above 1350°C aluminium can
reduce MgO because below 1350°C $$\Delta $$G of MgO
(formation) is more negative and above 1350°C $$\Delta $$G
of Al<sub>2</sub>O<sub>3</sub> (formation) is more negative.<br/><br/>
The melting and boiling po... | mcq | jee-main-2022-online-28th-june-morning-shift | 2,838 |
1l5bd6zfn | chemistry | isolation-of-elements | extractions-of-metals | <p>Which of the following chemical reactions represents Hall-Heroult Process?</p> | [{"identifier": "A", "content": "Cr<sub>2</sub>O<sub>3</sub> + 2Al $$\\to$$ Al<sub>2</sub>O<sub>3</sub> + 2Cr"}, {"identifier": "B", "content": "2Al<sub>2</sub>O<sub>3</sub> + 3C $$\\to$$ 4Al + 3CO<sub>2</sub>"}, {"identifier": "C", "content": "FeO + CO $$\\to$$ Fe + CO<sub>2</sub>"}, {"identifier": "D", "content": "2[... | ["B"] | null | Hall-Herault process is used for the extraction of aluminium by electrolysis molten $$\mathrm{Al}_{2} \mathrm{O}_{3}$$
<br/><br/>
$$
2 \mathrm{Al}_{2} \mathrm{O}_{3}+3 \mathrm{C} \rightarrow 4 \mathrm{Al}+3 \mathrm{CO}_{2}
$$ | mcq | jee-main-2022-online-24th-june-evening-shift | 2,839 |
1l6e15u5y | chemistry | isolation-of-elements | extractions-of-metals | <p>The compound(s) that is (are) removed as slag during the extraction of copper is :</p>
<p>(A) CaO</p>
<p>(B) FeO</p>
<p>(C) Al<sub>2</sub>O<sub>3</sub></p>
<p>(D) ZnO</p>
<p>(E) NiO</p>
<p>Choose the correct answer from the options given below:</p> | [{"identifier": "A", "content": "(C), (D) only"}, {"identifier": "B", "content": "(A), (B), (E) only"}, {"identifier": "C", "content": "(A), (B) only"}, {"identifier": "D", "content": "(B) only"}] | ["D"] | null | The compound(s) that are removed as a slag during the extraction of copper is :
<br/><br/>
$$
\mathrm{FeS} \stackrel{\mathrm{O}_2 / \mathrm{SiO}_2}{\longrightarrow} \underset{\text { slag }}{\mathrm{FeSiO}_3}+\mathrm{SO}_2
$$
<br/><br/>
$\therefore$ Only iron oxide (FeO) formed slag during extraction of copper. | mcq | jee-main-2022-online-25th-july-morning-shift | 2,840 |
1l6f6s3ba | chemistry | isolation-of-elements | extractions-of-metals | <p>Given below are two statements.</p>
<p>Statement I : Pig iron is obtained by heating cast iron with scrap iron.</p>
<p>Statement II : Pig iron has a relatively lower carbon content than that of cast iron.</p>
<p>In the light of the above statements, choose the correct answer from the options given below.</p> | [{"identifier": "A", "content": "Both Statement I and Statement II are correct."}, {"identifier": "B", "content": "Both Statement I and Statement II are not correct."}, {"identifier": "C", "content": "Statement I is correct but Statement II is not correct."}, {"identifier": "D", "content": "Statement I is not correct b... | ["B"] | null | Cast iron is made by melting pig iron with scrap iron
and coke using hot air blast.<br/><br/>
Hence Statement-I is incorrect<br/><br/>
But Pig iron has relatively more carbon content<br/><br/>
Hence statement-II is incorrect | mcq | jee-main-2022-online-25th-july-evening-shift | 2,841 |
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