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|---|---|---|---|---|---|---|---|---|---|---|---|
nHiB0rxXmLUhyOHZVe7k9k2k5h626lr | chemistry | structure-of-atom | hydrogen-spectrum | For the Balmer series in the spectrum of H atom,
<br/>$$\overline \nu = {R_H}\left\{ {{1 \over {n_1^2}} - {1 \over {n_2^2}}} \right\}$$, the correct statements among (I) to (IV)
are :
<br/>(I) As wavelength decreases, the lines in the series converge
<br/>(II) The integer n<sub>1</sub> is equal to 2
<br/>(III) The li... | [{"identifier": "A", "content": "(II), (III), (IV)"}, {"identifier": "B", "content": "(I), (II), (III)"}, {"identifier": "C", "content": "(I), (III), (IV)"}, {"identifier": "D", "content": "(I), (II), (IV)"}] | ["B"] | null | For balmer series : n<sub>1</sub> = 2, n<sub>2</sub> = 3, 4, 5, .....$$\infty $$
<br><br>For longest wavelength n<sub>2</sub> = 3
<br><br>$${1 \over \lambda } = R\left( {{1 \over {{2^2}}} - {1 \over {{3^2}}}} \right)$$
<br><br>As wavelength decreases the lines in the
Balmer series converge. The correct
statements are (... | mcq | jee-main-2020-online-8th-january-morning-slot | 3,959 |
fTRDvW7BzAYr0TJ9DNjgy2xukfcegnyw | chemistry | structure-of-atom | hydrogen-spectrum | The shortest wavelength of H atom in the
Lyman series is $$\lambda $$<sub>1</sub>. The longest wavelength in
the Balmar series of He<sup>+</sup> is : | [{"identifier": "A", "content": "$${{5{\\lambda _1}} \\over 9}$$"}, {"identifier": "B", "content": "$${{36{\\lambda _1}} \\over 5}$$"}, {"identifier": "C", "content": "$${{27{\\lambda _1}} \\over 5}$$"}, {"identifier": "D", "content": "$${{9{\\lambda _1}} \\over 5}$$"}] | ["D"] | null | For Shortest wavelength energy should be maximum.
<br><br>For maximum energy transition must be form n = $$\infty $$ to n = 1.
<br><br>$${1 \over {{\lambda _1}}} = {R_H}{\left( 1 \right)^2}\left[ {{1 \over 1} - 0} \right]$$
<br><br>$$ \Rightarrow $$ $${1 \over {{\lambda _1}}} = {R_H}$$
<br><br>For longest wavelength, $... | mcq | jee-main-2020-online-4th-september-evening-slot | 3,960 |
kJgtQcrQQjJh5krB8Djgy2xukf93lzve | chemistry | structure-of-atom | hydrogen-spectrum | The region in the electromagnetic spectrum
where the Balmar series lines appear is : | [{"identifier": "A", "content": "Microwave"}, {"identifier": "B", "content": "Ultraviolet"}, {"identifier": "C", "content": "Visible"}, {"identifier": "D", "content": "Infrared"}] | ["C"] | null | In the hydrogen spectrum,
<br>Balmer series lies in visible region. | mcq | jee-main-2020-online-4th-september-morning-slot | 3,961 |
1l6f7mmva | chemistry | structure-of-atom | hydrogen-spectrum | <p>When the excited electron of a H atom from n = 5 drops to the ground state, the maximum number of emission lines observed are _____________.</p> | [] | null | 10 | Maximum number of emission lines
<br/><br/>
$$
=\frac{\left(n_{2}-n_{1}\right)\left(n_{2}-n_{1}+1\right)}{2}
$$
<br/><br/>
$$
\begin{aligned}
&\mathrm{n}_{2}=5 \\
&\mathrm{n}_{1}=1 \\
&\Rightarrow \frac{(5-1)(5-1+1)}{2}=10
\end{aligned}
$$
<br/><br/>
Hence maximum number of emission lines observed are $10 .$ | integer | jee-main-2022-online-25th-july-evening-shift | 3,962 |
1ldpoziwp | chemistry | structure-of-atom | hydrogen-spectrum | <p>Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from $$\mathrm{n=4}$$ to $$\mathrm{n}=2$$ of $$\mathrm{He}^{+}$$ spectrum</p> | [{"identifier": "A", "content": "$$\\mathrm{n}=3$$ to $$\\mathrm{n}=4$$"}, {"identifier": "B", "content": "$$\\mathrm{n}=2$$ to $$\\mathrm{n}=1$$"}, {"identifier": "C", "content": "$$\\mathrm{n}=1$$ to $$\\mathrm{n}=2$$"}, {"identifier": "D", "content": "$$\\mathrm{n}=1$$ to $$\\mathrm{n}=3$$"}] | ["B"] | null | $\mathrm{He}^{+}$ion :
<br/><br/>$$
\begin{aligned}
& \frac{1}{\lambda(\mathrm{H})}=\mathrm{R}(1)^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right] \\\\
& \frac{1}{\lambda\left(\mathrm{He}^{+}\right)}=\mathrm{R}(2)^2\left[\frac{1}{2^2}-\frac{1}{4^2}\right] \\\\
& \text { Given } \lambda(\mathrm{H})=\lambd... | mcq | jee-main-2023-online-31st-january-morning-shift | 3,963 |
1ldsrgqai | chemistry | structure-of-atom | hydrogen-spectrum | <p>The shortest wavelength of hydrogen atom in Lyman series is $$\lambda$$. The longest wavelength is Balmer series of He$$^+$$ is </p> | [{"identifier": "A", "content": "$$\\frac{36\\lambda}{5}$$"}, {"identifier": "B", "content": "$$\\frac{5}{9\\lambda}$$"}, {"identifier": "C", "content": "$$\\frac{9\\lambda}{5}$$"}, {"identifier": "D", "content": "$$\\frac{5\\lambda}{9}$$"}] | ["C"] | null | For H: $\frac{1}{\lambda}=\mathrm{R}_{\mathrm{H}} \times 1^{2}\left(\frac{1}{1^{2}}-\frac{1}{\infty^{2}}\right) \quad...(1)$
<br/><br/>
$$
\frac{1}{\lambda_{\mathrm{He}^{+}}}=\mathrm{R}_{\mathrm{H}} \times 2^{2} \times\left(\frac{1}{4}-\frac{1}{9}\right)\quad...(2)
$$
<br/><br/>
From (1) & (2) $\frac{\lambda_{\math... | mcq | jee-main-2023-online-29th-january-morning-shift | 3,964 |
1ldyhxf9x | chemistry | structure-of-atom | hydrogen-spectrum | <p>If wavelength of the first line of the Paschen series of hydrogen atom is 720 nm, then the wavelength of the second line of this series is _________ nm. (Nearest integer)</p> | [] | null | 492 | $\frac{1}{720}=R \times\left(\frac{1}{9}-\frac{1}{16}\right)$
<br/><br/>
$$
\begin{aligned}
& \Rightarrow R=\frac{9 \times 16}{720 \times 7} \\\\
& \frac{1}{\lambda^{\prime}}=\frac{9 \times 16}{720 \times 7} \times\left(\frac{1}{9}-\frac{1}{25}\right) \\\\
& \lambda^{\prime}=492.18 \mathrm{~nm} \\\\
& \lambda^{\prime}=... | integer | jee-main-2023-online-24th-january-morning-shift | 3,965 |
jaoe38c1lsfmnzhl | chemistry | structure-of-atom | hydrogen-spectrum | <p>Match List I with List II</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-II, B-IV, C-III, D-I\n"}, {"identifier": "B", "content": "A-I, B-III, C-II, D-IV\n"}, {"identifier": "C", "content": "A-II, B-III, C-I, D-IV\n"}, {"identifier": "D", "content": "A-I, B-II, C-III, D-IV"}] | ["A"] | null | <p>A - II, B - IV, C - III, D - I</p>
<p>Fact based.</p> | mcq | jee-main-2024-online-29th-january-evening-shift | 3,966 |
1lsg85c7e | chemistry | structure-of-atom | hydrogen-spectrum | <p>Number of spectral lines obtained in $$\mathrm{He}^{+}$$ spectra, when an electron makes transition from fifth excited state to first excited state will be</p> | [] | null | 10 | <p>$$\begin{aligned}
& 5^{\text {th }} \text { excited state } \Rightarrow n_1=6 \\
& 1^{\text {st }} \text { excited state } \Rightarrow n_2=2 \\
& \Delta n=n_1-n_2=6-2=4
\end{aligned}$$</p>
<p>Maximum number of spectral lines</p>
<p>$$=\frac{\Delta \mathrm{n}(\Delta \mathrm{n}+1)}{2}=\frac{4(4+1)}{2}=10$$</p> | integer | jee-main-2024-online-30th-january-evening-shift | 3,967 |
lv40v90v | chemistry | structure-of-atom | hydrogen-spectrum | <p>Wavenumber for a radiation having 5800 $$\mathop A\limits^o $$ wavelength is $$x \times 10 \mathrm{~cm}^{-1}$$ The value of $$x$$ is ________. (Integer answer)</p> | [] | null | 1724 | <p>The wavenumber of a radiation is defined as the number of wavelengths per unit distance and is the reciprocal of the wavelength. Wavenumber is commonly represented in units of $$\mathrm{cm}^{-1}$$.</p>
<p>First, convert the given wavelength from angstroms ($$\mathop A\limits^o $$) to centimeters (cm). We know that:... | integer | jee-main-2024-online-8th-april-evening-shift | 3,968 |
lvb2a7vy | chemistry | structure-of-atom | hydrogen-spectrum | <p>Match List I with List II.</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;b... | [{"identifier": "A", "content": "(A)-(II), (B)-(IV), (C)-(III), (D)-(I)\n"}, {"identifier": "B", "content": "(A)-(III), (B)-(I), (C)-(IV), (D)-(II)\n"}, {"identifier": "C", "content": "(A)-(I), (B)-(IV), (C)-(III), (D)-(II)\n"}, {"identifier": "D", "content": "(A)-(IV), (B)-(II), (C)-(I), (D)-(III)"}] | ["B"] | null | <p>To match List I (Alkali Metals) with List II (Emission Wavelength in nm), we need to know the characteristic emission lines of these elements. Here is the information for the typical emission wavelengths:</p>
<ul>
<li><b>Lithium (Li):</b> 670.8 nm</li>
<li><b>Sodium (Na):</b> 589.2 nm</li>
<li><b>Rubidium (Rb):<... | mcq | jee-main-2024-online-6th-april-evening-shift | 3,969 |
xOzKpr8XmbTNXmji | chemistry | structure-of-atom | photoelectric-effect | A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at
680 nm, the other is at : | [{"identifier": "A", "content": "325 nm "}, {"identifier": "B", "content": "743 nm "}, {"identifier": "C", "content": "518 nm"}, {"identifier": "D", "content": "1035 nm"}] | ["B"] | null | Here a photon is divided into two photons of different wavelength.
<br><br>According to the law of conservation of energy,
<br><br>Energy of photon before dividing into two parts = Energy of first photon + Energy of second photon
<br><br>$${{hc} \over \lambda } = {{hc} \over {{\lambda _1}}} + {{hc} \over {{\lambda _2}}... | mcq | aieee-2011 | 3,970 |
HqyOr7yIZjbwsK73rBKuD | chemistry | structure-of-atom | photoelectric-effect | Ejection of the photoelectron from metal in the photoelectric experiment can be stopped by applying 0.5 V when the radiation of 250 nm is used. The work function of the metal is : | [{"identifier": "A", "content": "4 eV"}, {"identifier": "B", "content": "4.5 eV"}, {"identifier": "C", "content": "5 eV"}, {"identifier": "D", "content": "5.5 eV"}] | ["B"] | null | $$\lambda $$ = 250 nm = 2500 $$\mathop A\limits^ \circ $$
<br><br>E = $${{hc} \over \lambda }$$ = $${{12400} \over {2500}}$$ = 4.96 eV
<br><br>K. E = 0.5 eV
<br><br>As, $$\,\,\,\,\,\,$$ K. E = E $$-$$ $$\omega $$<sub>0</sub>
<br><br>$$ \Rightarrow $$ $$\,\,\,$$ 0.5 = 4.96 $$-$$ $${\omega _0}$$
<br><br>$$ \Rightarrow... | mcq | jee-main-2018-online-15th-april-morning-slot | 3,971 |
ONDHnJZUt92VJhPkRo97i | chemistry | structure-of-atom | photoelectric-effect | Which of the graphs shown below does not represent the relationship between incident light and the electron ejected from metal surface ?
| [{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734263355/exam_images/dnct7czrok6djsflrqku.webp\" style=\"max-width: 100%; height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Structure of Atom ... | ["B"] | null | E = W + $${1 \over 2}$$mv<sup>2</sup>
<br><br>K.E. = hv $$-$$ 4v<sub>0</sub>
<br><br>K.E. = hv + ($$-$$ hv<sub>0</sub>)
<br><br>y = mx + $$\underline C $$ | mcq | jee-main-2019-online-10th-january-morning-slot | 3,972 |
HJ6RKzhE1DmEBo3FpEwJo | chemistry | structure-of-atom | photoelectric-effect | The de Broglie wavelength ($$\lambda $$) associated with a photoelectron varies with the frequency (v) of the incident radiation as, [v<sub>0</sub> is threshold frequency] : | [{"identifier": "A", "content": "$$\\lambda \\,\\infty \\,{1 \\over {{{\\left( {v - {v_0}} \\right)}^{{3 \\over 2}}}}}$$"}, {"identifier": "B", "content": "$$\\lambda \\,\\infty \\,{1 \\over {{{\\left( {v - {v_0}} \\right)}^{{1 \\over 4}}}}}$$"}, {"identifier": "C", "content": "$$\\lambda \\,\\infty \\,{1 \\over {\\lef... | ["D"] | null | By photoelectric effect
<br><br>KE = h$$\gamma $$ - h$$\gamma $$<sub>o</sub> ....(1)
<br><br>de broglie wavelength,
<br><br>$$\lambda $$ = $${h \over {mv}}$$ = $${h \over {\sqrt {2m \times K.E} }}$$ ...(2)
<br><br>Using equation (1) and (2), we get
<br><br>$$\lambda $$ = $${h \over {\sqrt {2m \times \left( {h\nu - h{\... | mcq | jee-main-2019-online-11th-january-evening-slot | 3,973 |
6SUkkVQp6A51tmJMhTdmX | chemistry | structure-of-atom | photoelectric-effect | What is the work function of the metal if the light of wavelength 4000$$\mathop A\limits^ \circ $$ generates photoelectrons of velocity 6 $$ \times $$ 10<sup>5</sup> ms<sup>–1</sup> from it ?
<br/>(Mass of electron = 9 $$ \times $$ 10<sup>–31</sup> kg;
<br/>Velocity of light = 3 $$ \times $$ 10<sup>8</sup> ms<sup>$$... | [{"identifier": "A", "content": "4.0 eV"}, {"identifier": "B", "content": "0.9 eV "}, {"identifier": "C", "content": "2.1 eV "}, {"identifier": "D", "content": "3.1 eV "}] | ["C"] | null | E = $$\phi $$ + K.E
<br><br>$$ \Rightarrow $$ h$$\nu $$ = $$\phi $$ + $${1 \over 2}m{v^2}$$
<br><br>$$ \Rightarrow $$ $$\phi $$ = $$h\nu - {1 \over 2}m{v^2}$$
<br><br>= $${{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {4000 \times {{10}^{ - 10}}}} - {1 \over 2} \times 9 \times {10^{ - 31}} \times {\left... | mcq | jee-main-2019-online-12th-january-morning-slot | 3,974 |
sI7DoE0aS5ag5IKFOvjgy2xukevc89sh | chemistry | structure-of-atom | photoelectric-effect | The figure that is not a direct manifestation of
the quantum nature of atoms is : | [{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734266369/exam_images/uhcjsum4ryxecogdw3tv.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2020 (Online) 2nd September Morning Slot Chemistry - Structure of Atom Q... | ["A"] | null | Internal energy of ‘Ar’ or any gas, has nothing to do with Quantum nature of atom.
<br><br>Photoelectric effect, atomic spectrum and Black body radiations may be
explained by quantum theory. | mcq | jee-main-2020-online-2nd-september-morning-slot | 3,977 |
V9Ddm3ABnoBSo1fweXjgy2xukeyhee0e | chemistry | structure-of-atom | photoelectric-effect | The work function of sodium metal is
4.41 $$ \times $$ 10<sup>–19</sup> J. If photons of wavelength 300 nm
are incident on the metal, the kinetic energy of
the ejected electrons will be (h = 6.63 $$ \times $$ 10<sup>–34</sup> J s;
c = 3 $$ \times $$ 10<sup>8</sup> m/s) ________ × 10<sup>–21</sup> J. | [] | null | 222 | E = W + KE<sub>max</sub>
<br><br>$$ \Rightarrow $$ KE<sub>max</sub> = E - W
<br><br>= $${{hc} \over \lambda }$$ - 4.41 $$ \times $$ 10<sup>–19</sup>
<br><br>= $${{6.63 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {300 \times {{10}^{ - 9}}}}$$ - 4.41 $$ \times $$ 10<sup>–19</sup>
<br><br>= 2.22 × 10<sup>–19</s... | integer | jee-main-2020-online-2nd-september-evening-slot | 3,978 |
zDcPY0JPQIw2VjhHIX1kltc9o9t | chemistry | structure-of-atom | photoelectric-effect | Electromagnetic radiation of wavelength 663 nm is just sufficient to ionise the atom of metal A. The ionization enegy of metal A in kJ mol<sup>$$-$$1</sup> is __________. (Rounded off to the nearest integer)<br/><br/>[h = 6.63 $$\times$$ 10<sup>$$-$$34</sup> Js, c = 3.00 $$\times$$ 10<sup>8</sup> ms<sup>$$-$$1</sup>, N... | [] | null | 181 | <p>Energy of EMR = IE of the metal (A)</p>
<p>$$ = hv = {{hc} \over \lambda }$$ atom<sup>$$-$$1</sup> $$ = {{hc} \over \lambda } \times {N_A}$$ mol<sup>$$-$$1</sup></p>
<p>$$ = {{(6.63 \times {{10}^{ - 34}}) \times (3 \times {{10}^8}) \times (6.02 \times {{10}^{23}})} \over {(663 \times {{10}^{ - 9}})}}$$ J mol<sup>$$-... | integer | jee-main-2021-online-25th-february-evening-slot | 3,979 |
1krutmuy0 | chemistry | structure-of-atom | photoelectric-effect | A source of monochromatic radiation of wavelength 400 nm provides 1000 J of energy in 10 seconds. When this radiation falls on the surface of sodium, x $$\times$$ 10<sup>20</sup> electrons are ejected per second. Assume that wavelength 400 nm is sufficient for ejection of electron from the surface of sodium metal. The ... | [] | null | 2 | Total energy provided by<br><br>Source per second = $${{1000} \over {10}} = 100$$ J<br><br>Energy required to eject electron = $${{hc} \over \lambda }$$<br><br>= $${{6.626 \times {{10}^{ - 34}}} \over {400 \times {{10}^{ - 9}}}} \times 3 \times {10^8}$$<br><br>Number of electrons ejected<br><br>= $${{100} \over {{{6.62... | integer | jee-main-2021-online-25th-july-morning-shift | 3,982 |
1ktcsbdrt | chemistry | structure-of-atom | photoelectric-effect | A metal surface is exposed to 500 nm radiation. The threshold frequency of the metal for photoelectric current is 4.3 $$\times$$ 10<sup>14</sup> Hz. The velocity of ejected electron is ____________ $$\times$$ 10<sup>5</sup> ms<sup>$$-$$1</sup> (Nearest integer)<br/><br/>[Use : h = 6.63 $$\times$$ 10<sup>$$-$$34</sup> J... | [] | null | 5 | $$\upsilon $$ : speed of electron having max. K.E.<br><br> $$\Rightarrow$$ from Einstein equation : E = $$\phi$$ + K.E.<sub>max</sub><br><br>$$ \Rightarrow {{hc} \over \lambda } = h{\upsilon _0} + {1 \over 2}m{v^2}$$<br><br>$$ \Rightarrow {{6.63 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {500 \times {{10}^{ ... | integer | jee-main-2021-online-26th-august-evening-shift | 3,983 |
1ktfufsq2 | chemistry | structure-of-atom | photoelectric-effect | The number of photons emitted by a monochromatic (single frequency) infrared range finder of power 1 mW and wavelength of 1000 nm, in 0.1 second is x $$\times$$ 10<sup>13</sup>. The value of x is _____________. (Nearest integer)<br/><br/>(h = 6.63 $$\times$$ 10<sup>$$-$$34</sup> Js, c = 3.00 $$\times$$ 10<sup>8</sup> m... | [] | null | 50 | Energy emitted in 0.1 sec.<br><br>= 0.1 sec. $$\times$$ $${10^{ - 3}}{J \over s}$$<br><br>= 10<sup>$$-$$4</sup> J<br><br>If 'n' photons of $$\lambda$$ = 1000 nm are emitted, then 10<sup>$$-$$4</sup> = n $$\times$$ $${{hc} \over \lambda }$$<br><br>$$ \Rightarrow {10^{ - 4}} = {{n \times 6.63 \times {{10}^{ - 34}} \times... | integer | jee-main-2021-online-27th-august-evening-shift | 3,984 |
1ktn2s6sg | chemistry | structure-of-atom | photoelectric-effect | A 50 watt bulb emits monochromatic red light of wavelength of 795 nm. The number of photons emitted per second by the bulb is x $$\times$$ 10<sup>20</sup>. The value of x is __________. [Given : h = 6.63 $$\times$$ 10<sup>$$-$$34</sup> Js and c = 3.0 $$\times$$ 10<sup>8</sup> ms<sup>$$-$$1</sup>] | [] | null | 2 | Energy of photon is given as $$E = {{nhc} \over \lambda }$$ .... (i)<br/><br/>where, E = energy of photon (50 W),<br/><br/>n = number of photon<br/><br/>h = Planck's constant (6.63 $$\times$$ 10<sup>$$-$$34</sup> Js)<br/><br/>c = speed of light (3 $$\times$$ 10<sup>8</sup> m/s)<br/><br/>$$\lambda$$ = wavelength of ligh... | integer | jee-main-2021-online-1st-september-evening-shift | 3,985 |
1l56bev0h | chemistry | structure-of-atom | photoelectric-effect | <p>If the work function of a metal is 6.63 $$\times$$ 10<sup>$$-$$19</sup>J, the maximum wavelength of the photon required to remove a photoelectron from the metal is ____________ nm. (Nearest integer)</p>
<p>[Given : h = 6.63 $$\times$$ 10<sup>$$-$$34</sup> J s, and c = 3 $$\times$$ 10<sup>8</sup> m s<sup>$$-$$1</sup>... | [] | null | 300 | <p>Given,</p>
<p>Work function = 6.63 $$\times$$ 10<sup>$$-$$19</sup> J</p>
<p>$$ = {{6.63 \times {{10}^{ - 19}}} \over {1.6 \times {{10}^{ - 19}}}}$$</p>
<p>= 4.14 eV</p>
<p>We know,</p>
<p>$$E = {{1240} \over {\lambda \,(nm)}}$$</p>
<p>$$ \Rightarrow 4.14 = {{1240} \over \lambda }$$</p>
<p>$$\lambda$$ = 300 nm</p> | integer | jee-main-2022-online-28th-june-morning-shift | 3,986 |
1l59qewbw | chemistry | structure-of-atom | photoelectric-effect | <p>The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is :</p>
<p>[Given : The threshold frequency of platinum is 1.3 $$\times$$ 10<sup>15</sup> s<sup>$$-$$1</sup> and h = 6.6 $$\times$$ 10<sup>$$-$$34</sup> J s.]</p> | [{"identifier": "A", "content": "3.21 $$\\times$$ 10<sup>$$-$$14</sup> J"}, {"identifier": "B", "content": "6.24 $$\\times$$ 10<sup>$$-$$16</sup> J"}, {"identifier": "C", "content": "8.58 $$\\times$$ 10<sup>$$-$$19</sup> J"}, {"identifier": "D", "content": "9.76 $$\\times$$ 10<sup>$$-$$20</sup> J"}] | ["C"] | null | <p>The minimum energy possessed by photons will be
equal to the work function of the metal.</p>
<p>$$ \therefore $$ E<sub>min</sub> = h$$\nu $$<sub>0</sub> J</p>
<p>= 6.6 $$\times$$ 10<sup>$$-$$34</sup> $$ \times $$ 1.3 $$\times$$ 10<sup>15</sup></p>
<p>= 8.58 $$\times$$ 10<sup>$$-$$19</sup> J</p> | mcq | jee-main-2022-online-25th-june-evening-shift | 3,987 |
1l6nxk0mz | chemistry | structure-of-atom | photoelectric-effect | <p>If the wavelength for an electron emitted from $$\mathrm{H}$$-atom is $$3.3 \times 10^{-10} \mathrm{~m}$$, then energy absorbed by the electron in its ground state compared to minimum energy required for its escape from the atom, is _________ times. (Nearest integer)</p>
<p>$$\left[\right.$$ Given $$: \mathrm{h}=6.6... | [] | null | 2 | $\lambda=\frac{\mathrm{h}}{\mathrm{mv}}$
<br/><br/>
$$
\begin{aligned}
&\Rightarrow \mathrm{mv}=\frac{\mathrm{h}}{\lambda}=\frac{6.626 \times 10^{-34} \mathrm{~kg} \frac{\mathrm{m}^{2}}{\mathrm{sec}^{2}} \times \mathrm{sec}}{3.3 \times 10^{-10} \mathrm{~m}} \\\\
&\mathrm{mv}=\frac{6.626 \times 10^{-24}}{3.3}=2 \times 1... | integer | jee-main-2022-online-28th-july-evening-shift | 3,988 |
1lgyhok29 | chemistry | structure-of-atom | photoelectric-effect | <p>The number of incorrect statement/s about the black body from the following is __________</p>
<p>(A) Emit or absorb energy in the form of electromagnetic radiation.</p>
<p>(B) Frequency distribution of the emitted radiation depends on temperature.</p>
<p>(C) At a given temperature, intensity vs frequency curve passe... | [] | null | 0 | <p>All the statements (A, B, C, D) provided about black bodies are correct. </p>
<p>(A) A black body is an idealized physical body that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence. It also emits energy in the form of electromagnetic radiation.</p>
<p>(B) The frequency d... | integer | jee-main-2023-online-10th-april-morning-shift | 3,991 |
jaoe38c1lse8d793 | chemistry | structure-of-atom | photoelectric-effect | <p>The ionization energy of sodium in $$\mathrm{~kJ} \mathrm{~mol}^{-1}$$, if electromagnetic radiation of wavelength $$242 \mathrm{~nm}$$ is just sufficient to ionize sodium atom is _______.</p> | [] | null | 494 | <p>$$\begin{aligned}
& \mathrm{E}=\frac{1240}{\lambda(\mathrm{nm})} \mathrm{eV} \\
& =\frac{1240}{242} \mathrm{eV} \\
& =5.12 \mathrm{eV} \\
& =5.12 \times 1.6 \times 10^{-19} \\
& =8.198 \times 10^{-19} \mathrm{~J} / \text { atom } \\
& =494 \mathrm{~kJ} / \mathrm{mol}
\end{aligned}$$</p> | integer | jee-main-2024-online-31st-january-morning-shift | 3,992 |
lv5gt4sj | chemistry | structure-of-atom | photoelectric-effect | <p>A hypothetical electromagnetic wave is show below.</p>
<p><img src="data:image/png;base64,UklGRoQIAABXRUJQVlA4IHgIAAAwhwCdASoAA3gBP4HA3WU2MS4nIlI44sAwCWlu8mSdukHCN+fn6C/2NqfZy3KhC1L/Nn9AVTSU/bXLsXKItqA+mCPId2Me8h0wR5Duxj1IsJLnoIdQwDZx2CJdYVH5x4sJLrCo/OPFhJdYWvJcnyvL8HKvVwLytKWEkNoJa34oc0c1+E8dwIw48WEl1hUfahqSL6Chvr3... | [] | null | 5 | <p>$$\begin{aligned}
\lambda & =1.5 \times 4=6 \mathrm{~pm} \\
\nu & =\frac{C}{\lambda} \\
\nu & =\frac{3 \times 10^8}{6 \times 10^{-12}} \\
& =0.5 \times 10^{20} \\
\nu & =5 \times 10^{19} \\
x & =5
\end{aligned}$$</p> | integer | jee-main-2024-online-8th-april-morning-shift | 3,994 |
WuxX0SVyhNlwREz1yOcAy | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | If the de Broglie wavelength of the electron in n<sup>th</sup> Bohr orbit in a hydrogenic atom is equal to 1.5 $$\pi $$a<sub>0</sub> (a<sub>0</sub> is Bohr radius), then the value of n/z is - | [{"identifier": "A", "content": "0.75"}, {"identifier": "B", "content": "0.40"}, {"identifier": "C", "content": "1.50"}, {"identifier": "D", "content": "1.0"}] | ["A"] | null | According to debroglie hypothesis,
<br><br>2$$\pi $$r<sub><i>n</i></sub> = <i>n</i>$$\lambda $$
<br><br>$$ \therefore $$ $$\lambda $$ = $${{2\pi {r_n}} \over n}$$
<br><br>According to the question,
<br><br>$${{2\pi {r_n}} \over n}$$ = 1.5 $$\pi $$<i>a</i><sub>0</sub>
<br><br>We know,
<br><br><i>r<sub>n</sub... | mcq | jee-main-2019-online-12th-january-evening-slot | 3,996 |
XaEFXP0Tja2lYqx59Lvx2 | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | Which one of the following about an electron
occupying the 1s orbital in a hydrogen atom is
incorrect ?<br/><br/> (The Bohr radius is represented
by a<sub>0</sub>) | [{"identifier": "A", "content": "The probability density of finding the\nelectron is maximum at the nucleus."}, {"identifier": "B", "content": "The electron can be found at a distance 2a<sub>0</sub>\nfrom the nucleus"}, {"identifier": "C", "content": "The total energy of the electron is maximum\nwhen it is at a distanc... | ["C"] | null | Probablity density = $${\psi ^2}$$
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263846/exam_images/xuzlpvd0itv9joyksdst.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264420/exam_images/xu1itgvarsoihun9kzl1.webp" style="max-width: 10... | mcq | jee-main-2019-online-9th-april-evening-slot | 3,997 |
RrwU4MXk1RukKRgSe33rsa0w2w9jwwehu6n | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | The graph between $${\left| \psi \right|^2}$$ and r (radial distance) is shown below. This represents :
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264481/exam_images/fdb04jcez7momsu4zm21.webp"/><img src="data:image/png;base64,UklGRgIFAABXRUJQVlA4IPYEAAAwS... | [{"identifier": "A", "content": "3s orbital"}, {"identifier": "B", "content": "2s orbital"}, {"identifier": "C", "content": "2p orbital"}, {"identifier": "D", "content": "1s orbital"}] | ["B"] | null | In this $${\left| \psi \right|^2}$$ vs r graph, value of r is zero at only one point. So this orbital must have one radial node.
<br><br>Here $${\left| \psi \right|^2} \ne 0$$ at r = 0, so orbital should be s orbital. Then $$l$$ = 0.
<br><br>We know,
<br><br>No of radial node = n - $$l$$ - 1
<br><br>$$ \therefore $$ ... | mcq | jee-main-2019-online-10th-april-morning-slot | 3,998 |
GI3CiWL2J90ORSC1LB3rsa0w2w9jx4zbx3y | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | The electrons are more likely to be found :
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265137/exam_images/b5q8xnyrckc34ckvf0w4.webp"/><img src="data:image/png;base64,UklGRiYKAABXRUJQVlA4IBoKAACQgQCdASqoAqoBP4HA3GW2MK2nIVWY+sAwCWlu/Gf4putQ3v1Y7Scgmz17J5XwQT... | [{"identifier": "A", "content": "only in the region a"}, {"identifier": "B", "content": "in the region a arid c"}, {"identifier": "C", "content": "only in the region c"}, {"identifier": "D", "content": "in the region a and b"}] | ["B"] | null | Probability of finding an electron is given by
4$$\pi $$r<sup>2</sup>dr $${\psi ^2}$$ and at
both 'a' and 'c' it will have maximum value.
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267408/exam_images/rocjduzzetva7iwljfp1.webp"><source media="(max-width: 50... | mcq | jee-main-2019-online-12th-april-morning-slot | 3,999 |
qsZP0WPT9wfLCKwnyxjgy2xukfouqx0h | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | The correct statement about probability density (except at infinite distance from nucleus) is : | [{"identifier": "A", "content": "It can be zero for 1s orbital"}, {"identifier": "B", "content": "It can be zero for 3p orbital"}, {"identifier": "C", "content": "It can never be zero for 2s orbital"}, {"identifier": "D", "content": "It can negative for 2p orbital"}] | ["B"] | null | $$\phi $$<sup>2</sup> (probability density) can be zero for 3p
orbital other than infinite distance. It has one
radial node. | mcq | jee-main-2020-online-5th-september-evening-slot | 4,000 |
zSuZ14oVpGv7ZpDZSM1klrgte33 | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | A proton and a Li<sup>3+</sup> nucleus are accelerated by the same potential. If $$\lambda _{Li}$$ and $$\lambda _p$$ denote the
de Broglie wavelengths of Li<sup>3+</sup> and proton respectively, then the value of
$${{{\lambda _{Li}}} \over {{\lambda _p}}}$$ is x $$ \times $$ 10<sup>-1</sup>.<br/>
The value of x is ___... | [] | null | 2 | Given, mass of Li<sup>3+</sup> = 8.3 times of mass of proton formula,<br/><br/>De-Broglie wavelength, $$\lambda = {h \over {\sqrt {2mqV} }}$$<br/><br/>Here, h = Planck's constant = 6.624 $$\times$$ 10<sup>$$-$$34</sup> J-s<br/><br/>m = Mass of atom<br/><br/>q = Charge (or number of electrons)<br/><br/>$${\lambda _{Li}... | integer | jee-main-2021-online-24th-february-morning-slot | 4,001 |
o4aC9l2tePKlz69NpY1kls81s7u | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | The plots of radial distribution functions for various orbitals of hydrogen atom against 'r' are given below :<br/><br/><img src="data:image/png;base64,UklGRnYaAABXRUJQVlA4IGoaAAAwzgCdASrwAd0CP4G+2mS2MDqnItHZc1AwCWlu40J0ffcO/Hzw8o/6f0//Nv43Hfy//XX/Zd4vAI/cttF4DzAvcvLP+a8xeQPvKfw3/g9gL+U/4X0rvvbz7/tf/n9W3/rdaQW18Y/qamTM... | [{"identifier": "A", "content": "(B)"}, {"identifier": "B", "content": "(A)"}, {"identifier": "C", "content": "(C)"}, {"identifier": "D", "content": "(D)"}] | ["D"] | null | Number of radial nodes = n – (l + 1)
<br><br>For 3s orbital n = 3, l = 0
<br><br>Number of radial nodes = 3 – 0 – 1 = 2
<br><br>It is correctly represented in graph of option D. | mcq | jee-main-2021-online-25th-february-morning-slot | 4,002 |
1krrkw22e | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | The wavelength of electrons accelerated from rest through a potential difference of 40 kV is x $$\times$$ 10<sup>$$-$$12</sup> m. The value of x is ___________. (Nearest integer)<br/><br/>Give : Mass of electron = 9.1 $$\times$$ 10<sup>$$-$$31</sup> kg<br/><br/>Charge on an electron = 1.6 $$\times$$ 10<sup>$$-$$19</sup... | [] | null | 6 | Wavelength of electron is given by<br><br>$$\lambda = {h \over {\sqrt {2mqV} }}$$<br><br>Here q = charge on electron, V = potential difference<br><br>$$\lambda = {{6.63 \times {{10}^{ - 34}}} \over {\sqrt {2 \times 9.1 \times {{10}^{ - 31}} \times 1.6 \times {{10}^{ - 19}} \times 40 \times {{10}^3}} }}$$<br><br>$$ = ... | integer | jee-main-2021-online-20th-july-evening-shift | 4,003 |
1l54xzcbj | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | <p>Which of the following is the correct plot for the probability density $${\psi ^2}$$ (r) as a function of distance 'r' of the electron from the nucleus for 2s orbital?</p> | [{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1l55fuejp/295df638-251f-4d62-bcc2-264ad195f27e/948c6550-fae0-11ec-b8f8-f787cc45caa2/file-1l55fuejq.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1l55fuejp/295df638-251f-4d62-bcc2-264ad195f27e/948... | ["B"] | null | <p>Formula for number of radial nodes in n<sup>th</sup> orbital = n - $$l$$ - 1</p>
<p>For 2s, number of radial nodes = 2 – 0 – 1 = 1 and value of $${\psi ^2}$$ is always positive. </p> | mcq | jee-main-2022-online-29th-june-evening-shift | 4,004 |
1l5bcu17r | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | <p>The energy of one mole of photons of radiation of wavelength 300 nm is<br/><br/> (Given : h = 6.63 $$\times$$ 10<sup>$$-$$34</sup> J s, N<sub>A</sub> = 6.02 $$\times$$ 10<sup>23</sup> mol<sup>$$-$$1</sup>, c = 3 $$\times$$ 10<sup>8</sup> m s<sup>$$-$$1</sup>)</p> | [{"identifier": "A", "content": "235 kJ mol<sup>$$-$$1</sup>"}, {"identifier": "B", "content": "325 kJ mol<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "399 kJ mol<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "435 kJ mol<sup>$$-$$1</sup>"}] | ["C"] | null | <p>Energy of one photon</p>
<p>$$E = {{1240} \over {\lambda (nm)}}eV$$</p>
<p>$$ = {{1240} \over {300}}$$</p>
<p>$$ = 4.1333\,eV$$</p>
<p>$$\therefore$$ Energy of one mole of photon</p>
<p>$$ = 4.1333 \times 6.02 \times {10^{23}}\,eV$$</p>
<p>$$ = 4.1333 \times 6.02 \times {10^{23}} \times 1.6 \times {10^{ - 19}}\,J$$<... | mcq | jee-main-2022-online-24th-june-evening-shift | 4,005 |
ldqxknea | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | The wave function $(\Psi)$ of $2 \mathrm{~s}$ is given by<br/><br/>
$$
\Psi_{2 \mathrm{~s}}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-r / 2 a_0}
$$<br/><br/>
At $r=r_0$, radial node is formed. Thus, $r_0$ in terms of $a_0$ | [{"identifier": "A", "content": "$r_0=a_0$"}, {"identifier": "B", "content": "$r_0=4 a_0$"}, {"identifier": "C", "content": "$r_0=2 a_0$"}, {"identifier": "D", "content": "$r_0=\\frac{a_0}{2}$"}] | ["C"] | null | <p>For radial node $${\psi _{2s}} = 0$$</p>
<p>$$\therefore$$ $$r = 2{a_0}$$</p> | mcq | jee-main-2023-online-30th-january-evening-shift | 4,007 |
1ldr5fvfd | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | <p>The energy of one mole of photons of radiation of frequency $$2 \times 10^{12} \mathrm{~Hz}$$ in $$\mathrm{J} ~\mathrm{mol}^{-1}$$ is ___________. (Nearest integer)</p>
<p>[Given : $$\mathrm{h}=6.626 \times 10^{-34} ~\mathrm{Js}$$</p>
<p>$$\mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23} \mathrm{~mol}^{-1}$$]</p> | [] | null | 798 | <p>$$\mathrm{E=nhv}$$</p>
<p>$$=(6.022\times10^{23})(6.626\times10^{-34})\times(2\times10^{12})$$</p>
<p>$$=798.03$$ J</p>
<p>$$\approx$$ $$798$$ J</p> | integer | jee-main-2023-online-30th-january-morning-shift | 4,008 |
1ldygzd8w | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | <p>It is observed that characteristic X-ray spectra of elements show regularity. When frequency to the power "n" i.e. $${v^n}$$ of X-rays emitted is plotted against atomic number "Z", following graph is obtained.</p>
<p><img src="data:image/png;base64,UklGRkoIAABXRUJQVlA4ID4IAAAwuQCdASoAA8wCP4HA22a2MS2noLZomsAwCWlu4XPV... | [{"identifier": "A", "content": "1"}, {"identifier": "B", "content": "$$\\frac{1}{2}$$"}, {"identifier": "C", "content": "2"}, {"identifier": "D", "content": "3"}] | ["B"] | null | $\mathrm{h} v=\Delta \mathrm{E}=13.6 \times \mathrm{Z}^{2}\left(\frac{1}{\mathrm{n}_{1}^{2}}-\frac{1}{\mathrm{n}_{2}^{2}}\right)$
<br/><br/>
$\Rightarrow v \propto Z^{2}$<br/><br/>
$\Rightarrow (v)^{1 / 2} \propto Z \quad\left(\mathrm{n}=\frac{1}{2}\right)$ | mcq | jee-main-2023-online-24th-january-morning-shift | 4,009 |
1lgys6ajd | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | <p>Henry Moseley studied characteristic X-ray spectra of elements. The graph which represents his observation correctly is</p>
<p>Given $$v=$$ frequency of $$\mathrm{X}$$-ray emitted</p>
<p>Z = atomic number</p> | [{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lgzoipfl/e04dc876-8cd2-417e-8c9f-f04c871732ea/660f7b10-e548-11ed-8e50-a5d5ce4e2da5/file-1lgzoipfm.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lgzoipfl/e04dc876-8cd2-417e-8c9f-f04c871732ea/660... | ["B"] | null | Moseley's observation on characteristic X-ray spectra of elements relates frequency $(v)$ of X-rays emitted to the atomic number by the following relation:<br><br>
$$
\sqrt{v}=a(Z-b)
$$<br><br>
The plot of $\sqrt{v}$ vs $\mathrm{Z}$ is linear with -ve intercept on Y-axis.<br><br>
<img src="https://app-content.cdn.examg... | mcq | jee-main-2023-online-8th-april-evening-shift | 4,010 |
1lh29koof | chemistry | structure-of-atom | quantum-mechanical-model-of-atom | <p>The wavelength of an electron of kinetic energy $$4.50\times10^{-29}$$ J is _________ $$\times 10^{-5}$$ m. (Nearest integer)</p>
<p>Given : mass of electron is $$9\times10^{-31}$$ kg, h $$=6.6\times10^{-34}$$ J s</p> | [] | null | 7 | $$
\begin{aligned}
& \lambda_{\mathrm{d}}=\frac{\mathrm{h}}{\mathrm{mv}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mKE}}}=\frac{6.6 \times 10^{-34}}{\sqrt{2 \times 9 \times 10^{-31} \times 4.5 \times 10^{-29}}} \\\\
& =\frac{6.6 \times 10^{-34}}{\sqrt{9^2 \times 10^{-60}}} \\\\
& =\frac{6.6 \times 10^{-34}}{9 \times 10^{-30}}=... | integer | jee-main-2023-online-6th-april-morning-shift | 4,011 |
kn7jsYYGSQqucQDd | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The orbital angular momentum for an electron revolving in an orbit is given by $$\sqrt {l(l + 1)} {h \over {2\pi }}$$. This momentum for an s-electron will be given by | [{"identifier": "A", "content": "zero"}, {"identifier": "B", "content": "$${h \\over {2\\pi }}$$"}, {"identifier": "C", "content": "$$\\sqrt 2 {h \\over {2\\pi }}$$"}, {"identifier": "D", "content": "$$ + {1 \\over 2}{h \\over {2\\pi }}$$"}] | ["A"] | null | For s-electron l = 0<br><br>
$$\therefore $$ $$\sqrt {l(l + 1)} {h \over {2\pi }}$$<br><br>
= $$\sqrt {0(0 + 1)} {h \over {2\pi }}$$<br><br>
= $$\sqrt 0 {h \over {2\pi }}$$ = 0 (zero)<br> | mcq | aieee-2003 | 4,014 |
OfWe1r8mlv35VE0s | chemistry | structure-of-atom | quantum-numbers-and-orbitals | Consider the ground state of Cr atom (Z = 24). The number of electrons with the azimuthal quantum numbers, l = 1 and 2 are respectively | [{"identifier": "A", "content": "16 and 4"}, {"identifier": "B", "content": "12 and 5"}, {"identifier": "C", "content": "12 and 4"}, {"identifier": "D", "content": "16 and 5"}] | ["B"] | null | Electronic configuration of Cr (Z = 24) =
<br><br>1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup> 3s<sup>2</sup> 3p<sup>6</sup> 4s<sup>1</sup> 3d<sup>5</sup>
<br><br>For 2p<sup>6</sup> and 3p<sup>6</sup> , l = 1. Here in 2p and 3p orbital total 6 + 6 = 12 electrons present.
<br><br>For 3d<sup>5</sup> , l = 2. Here in 3d o... | mcq | aieee-2004 | 4,016 |
AU3WplgNeEgPJaPK | chemistry | structure-of-atom | quantum-numbers-and-orbitals | In a multi-electron atom, which of the following orbitals described by the three quantum members will have the same energy in the absence of magnetic and electric fields?<br/>
<b>(A)</b> n = 1, l = 0, m = 0<br/>
<b>(B)</b> n = 2, l = 0, m = 0<br/>
<b>(C)</b> n = 2, l = 1, m = 1<br/>
<b>(D)</b> n = 3, l = 2, m = 1<br/>
... | [{"identifier": "A", "content": "(D) and (E)"}, {"identifier": "B", "content": "(C) and (D)"}, {"identifier": "C", "content": "(B) and (C)"}, {"identifier": "D", "content": "(A) and (B)"}] | ["A"] | null | As here is no electric and magnetic field so ignore m to calculate the energy of orbital.
<br><br>As here atom is multi-electron so ( n + l ) rule is applicable here. This rule says those orbitals which have more value of ( n + l ) will have more energy.
<br><br>In (A), n + l = 1 + 0 = 1
<br><br>In (B), n + l = 2 + 0 =... | mcq | aieee-2005 | 4,017 |
ELLdcc63i6nzceU7 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | Which of the following sets of quantum numbers represents the highest energy of an atom? | [{"identifier": "A", "content": "n = 3, l = 0, m = 0, s = +1/ 2"}, {"identifier": "B", "content": "n = 3, l = 1, m = 1, s = +1/ 2"}, {"identifier": "C", "content": "n = 3, l = 2, m = 1, s = +1/ 2"}, {"identifier": "D", "content": "n = 4, l = 0, m = 0, s = +1/ 2"}] | ["C"] | null | In which quantum number have highest ( n + l ) value, will represent highest energy of an atom.
<br><br>In option (C), n + l = 3 + 2 = 5 = maximum. | mcq | aieee-2007 | 4,018 |
kuUs7Pzl8TLEZHtZ | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The electrons identified by quantum numbers n and l :<br/>
(a) n = 4, $$l$$ = 1<br/>
(b) n = 4, $$ l$$ = 0<br/>
(c) n = 3, $$l$$ = 2<br/>
(d) n = 3, $$l$$ = 1<br/>
Can be placed in order of increasing energy as : | [{"identifier": "A", "content": "(c) < (d) < (b) < (a)"}, {"identifier": "B", "content": "(d) < (b) < (c) < (a)"}, {"identifier": "C", "content": "(b) < (d) < (a) < (c)"}, {"identifier": "D", "content": "(a) < (c) < (b) < (d)"}] | ["B"] | null | (a) n = 4, $$l$$ = 1 (p-subshell), so 4p<br>
(b) n = 4, $$l$$ = 0 (s-subshell), so 4s<br>
(c) n = 3, $$l$$ = 2 (d-subshell), so 3d<br>
(d) n = 3, $$l$$ = 1 (p-subshell), so 3p<br>
<br>Accroding to the Bohr ( n + $$l$$ ) rule,
<br>Enery order of the subshell : 3p < 4s < 3d < 4p
<br><br><b>Note:</b> When two orb... | mcq | aieee-2012 | 4,019 |
2Dl5N3E8p9oof6za | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The correct set of four quantum numbers for the valence elections of rubidium atom (Z= 37) is: | [{"identifier": "A", "content": "5, 1, 1, + 1/2"}, {"identifier": "B", "content": "5, 1, 0, + 1/2"}, {"identifier": "C", "content": "5, 0, 0, + 1/2"}, {"identifier": "D", "content": "5, 0, 1, + 1/2"}] | ["C"] | null | The electronic configuration of Rubidium (Rb = 37):
<br>1s<sup>2</sup>2s<sup>2</sup>2p<sup>6</sup>3s<sup>2</sup>3p<sup>6</sup>3d<sup>10</sup>4s<sup>2</sup>4p<sup>6</sup>5s<sup>1</sup>
<br><br>As you can see last electron or valence electron enterin 5s subshell
<br><br>So, the quantum numbers are n = 5, $$l$$ = 0, m = 0... | mcq | jee-main-2014-offline | 4,020 |
uZKcj9ZVstfKbQckfQORm | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The total number of orbitals associated with the principal quantum number 5 is : | [{"identifier": "A", "content": "5"}, {"identifier": "B", "content": "10"}, {"identifier": "C", "content": "20"}, {"identifier": "D", "content": "25"}] | ["D"] | null | <p>Total number of orbitals associated with principal quantum number n is = n<sup>2</sup>.</p>
<p>Here, n = 5.
<br/><br/>$$ \therefore $$ The total number of orbitals associated with the principal quantum number 5 is = 5<sup>2</sup> = 25</p>
| mcq | jee-main-2016-online-9th-april-morning-slot | 4,021 |
ZJwfAyrNkLLSdcdVLlB31 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The highest value of the calculated spin only magnetic moment (in BM) among all the transition metal complexes is : | [{"identifier": "A", "content": "5.92"}, {"identifier": "B", "content": "6.93"}, {"identifier": "C", "content": "3.87"}, {"identifier": "D", "content": "4.90"}] | ["A"] | null | In transition metal contains d orbital, and in d orbital maximum no of unpaired electron possible = 5.
<br><br>Spin only magnetic moment,
<br><br>$${\mu _{spin}} = \sqrt {n\left( {n + 2} \right)} $$ B. M
<br><br>here n $$=$$ Number of unpaired electrons.
<br><br>$$ \therefore $$ &nbs... | mcq | jee-main-2019-online-9th-january-morning-slot | 4,022 |
YI1qnu75AyGwhM6uNfioM | chemistry | structure-of-atom | quantum-numbers-and-orbitals | Which of the following combination of statements is true regarding the interpretation of the atomic orbitals ? <br/><br/>
(a) An electron in an orbital of high angular momentum stays away from the nucleus than an electron in the orbital of lower angular momentum. <br/><br/>
(b) For a given value of the principal quantu... | [{"identifier": "A", "content": "(a), (b)"}, {"identifier": "B", "content": "(a), (d)"}, {"identifier": "C", "content": "(b), (c)"}, {"identifier": "D", "content": "(a), (c)"}] | ["B"] | null | <p>(a) Angular momentum, $$mvr = {{nh} \over {2\pi }}$$</p>
<p>$$ \Rightarrow mvr \propto n$$ $$\propto$$ distance from the nucleus</p>
<p>(b) This statement is incorrect as size of an orbit $$\propto$$ Azimuthal quantum number (l) ($$\because$$ n = constant)</p>
<p>(c) This statement is incorrect as at ground state,</... | mcq | jee-main-2019-online-9th-january-evening-slot | 4,023 |
FD5WMRAgscXSkzRrqWAsl | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The quantum number of four electrons are given below :<br/>
n = 4, l = 2, m<sub>l</sub> =–2, m<sub>s</sub> = –1/2<br/>
n = 3, l = 2, m<sub>l</sub> = 1, m<sub>s</sub> = +1/2<br/>
n = 4, l = 1, m<sub>l</sub> = 0, m<sub>s</sub> = +1/2<br/>
n = 3, l = 1, m<sub>l</sub> = 1, m<sub>s</sub> = –1/2<br/>
The correct order of the... | [{"identifier": "A", "content": "IV < II < III < I"}, {"identifier": "B", "content": "I < III < II < IV"}, {"identifier": "C", "content": "IV < III < II < I"}, {"identifier": "D", "content": "I < II < III < IV"}] | ["A"] | null | n = 4, l = 2, 4d orbital, n + l = 6 <br><br>
n = 3, l = 2, 3d orbital, n + l = 5<br><br>
n = 4, l = 1, 4p orbital, n + l = 5<br><br>
n = 3, l = 1, 3p orbital, n + l = 4<br>
<br>more is n + l value, more is energy
<br><br>$$ \therefore $$ 3p < 3d < 4p < 4d | mcq | jee-main-2019-online-8th-april-morning-slot | 4,024 |
fNVB1JjmQVWjETZenV7k9k2k5dzy7mo | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The number of orbitals associated with quantum number n = 5, m<sub>s</sub> = +$${1 \over 2}$$ is : | [{"identifier": "A", "content": "11"}, {"identifier": "B", "content": "25"}, {"identifier": "C", "content": "15"}, {"identifier": "D", "content": "50"}] | ["B"] | null | Total number of orbitals<br>
= n<sup>2</sup> = (5)<sup>2</sup> = 25
| mcq | jee-main-2020-online-7th-january-morning-slot | 4,025 |
l90OnnrzB5z7lw0oLOjgy2xukey6zsg9 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The number of subshells associated with n = 4
and m = –2 quantum numbers is | [{"identifier": "A", "content": "8"}, {"identifier": "B", "content": "2"}, {"identifier": "C", "content": "16"}, {"identifier": "D", "content": "4"}] | ["B"] | null | For n = 4 possible value of
l = 0, 1, 2, 3.
<br><br>Only l = 2 and l = 3 can have m = -2
<br><br>$$ \therefore $$ 4d & 4f subshell associated with n = 4, m = –2. | mcq | jee-main-2020-online-2nd-september-evening-slot | 4,027 |
Bxf1KYS5pjfd8V46BA1kmiuw96b | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The number of orbitals with n = 5, m<sub>1</sub> = +2 is ___________. (Round off to the Nearest Integer). | [] | null | 3 | <p>Given, n = 5, m<sub>l</sub> = + 2</p>
<p>For n = 5, possible value of l = 0, 1, 2, 3, 4</p>
<p>For l = 0, m<sub>l</sub> = 0</p>
<p>l = 1, m<sub>l</sub> = $$-$$1, 0, 1</p>
<p>l = 2, m<sub>l</sub> = $$-$$2, $$-$$1, 0, 1, 2</p>
<p>l = 3, m<sub>l</sub> = $$-$$3, $$-$$2, $$-$$1, 0, 1, 2, 3</p>
<p>l = 4, m<sub>l</sub> = $... | integer | jee-main-2021-online-16th-march-evening-shift | 4,028 |
dGDIgRV9rLc6ZxwdIk1kmj8fz0m | chemistry | structure-of-atom | quantum-numbers-and-orbitals | A certain orbital has n = 4 and m<sub>L</sub> = $$-$$3. The number of radial nodes in this orbital is ____________. (Round off to the Nearest Integer). | [] | null | 0 | Number of radial nodes = n – $$\ell $$ – 1<br><br>
n = 4, m<sub>L</sub> =–3 so $$\ell $$ = 3<br><br>
radial nodes = 4 – 3 – 1 = 0
| integer | jee-main-2021-online-17th-march-morning-shift | 4,029 |
1krq6gf1t | chemistry | structure-of-atom | quantum-numbers-and-orbitals | The Azimuthal quantum number for the valence electrons of Ga<sup>+</sup> ion is ___________.<br/><br/>(Atomic number of Ga = 31) | [] | null | 0 | Ga = 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup> 3s<sup>2</sup> 3p<sup>6</sup> 3d<sup>10</sup> 4s<sup>2</sup> 4p<sup>1</sup>
<br><br>Ga<sup>+</sup>
= 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup> 3s<sup>2</sup> 3p<sup>6</sup> 3d<sup>10</sup> 4s<sup>2</sup>
<br><br>Azimuthal Quantum number (l) for valence shell electro... | integer | jee-main-2021-online-20th-july-morning-shift | 4,030 |
1ktiheu9z | chemistry | structure-of-atom | quantum-numbers-and-orbitals | Ge(Z = 32) in its ground state electronic configuration has x completely filled orbitals with m<sub>l</sub> = 0. The value of x is ___________. | [] | null | 7 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264714/exam_images/dsv1lbbkb9ywfbctiqeb.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 31st August Morning Shift Chemistry - Structure of Atom Question 81 English Explanation"><br><br>C... | integer | jee-main-2021-online-31st-august-morning-shift | 4,031 |
1l548hspn | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Which of the following statements are correct?</p>
<p>(A) The electronic configuration of Cr is [Ar] 3d<sup>5</sup> 4s<sup>1</sup>.</p>
<p>(B) The magnetic quantum number may have a negative value.</p>
<p>(C) In the ground state of an atom, the orbitals are filled in order of their increasing energies.</p>
<p>(D) Th... | [{"identifier": "A", "content": "(A), (C) and (D) only"}, {"identifier": "B", "content": "(A) and (B) only"}, {"identifier": "C", "content": "(A) and (C) only"}, {"identifier": "D", "content": "(A), (B) and (C) only"}] | ["D"] | null | <p>(A) Cr (24) = 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup> 3s<sup>2</sup> 3p<sup>6</sup> 3d<sup>5</sup> 4s<sup>1</sup></p>
<p>= [Ar] 3d<sup>5</sup> 4s<sup>1</sup></p>
<p>(B) Magnetic quantum number (m) values ranging from $$-$$ l to + l including zero.</p>
<p>$$\therefore$$ It can have negative value.</p>
<p>(C) Acc... | mcq | jee-main-2022-online-29th-june-morning-shift | 4,032 |
1l55mu84s | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Consider the following statements :</p>
<p>(A) The principal quantum number 'n' is a positive integer with values of 'n' = 1, 2, 3, ...</p>
<p>(B) The azimuthal quantum number 'l' for a given 'n' (principal quantum number) can have values as 'l' = 0, 1, 2, ...... n</p>
<p>(C) Magnetic orbital quantum number 'm<sub>l... | [{"identifier": "A", "content": "(A), (B) and (C)"}, {"identifier": "B", "content": "(A), (C), (D) and (E)"}, {"identifier": "C", "content": "(A), (C) and (D)"}, {"identifier": "D", "content": "(A), (B), (C) and (D)"}] | ["C"] | null | <p>(A) Principle quantum number n is a positive integer and it's possible values are n = 1, 2, 3 ........</p>
<p>$$\therefore$$ A is correct.</p>
<p>(B) Azimuthal quantum number 'l' for a given 'n' can have values as l = 0, 1, 2 ....... (n $$-$$ 1)</p>
<p>$$\therefore$$ Statement B is wrong.</p>
<p>(C) Magnetic orbital... | mcq | jee-main-2022-online-28th-june-evening-shift | 4,033 |
1l56yq4l8 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Consider the following set of quantum numbers.</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;... | [] | null | 2 | <p><b>For A</b>,</p>
<p>Given n = 3 and l = 3</p>
<p>but we know maximum value of l = n $$-$$ 1.</p>
<p>$$\therefore$$ l can't be equal to n.</p>
<p>So, Set A of quantum numbers is not possible.</p>
<p><b>For B</b>,</p>
<p>Given n = 3, l = 2, m = $$-$$ 2</p>
<p>Here, l = 2 which follow the rule l = n $$-$$ 1.</p>
<p>An... | integer | jee-main-2022-online-27th-june-evening-shift | 4,034 |
1l5c5zysg | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Consider the following pairs of electrons</p>
<p>(A) (a) n = 3, $$l$$ = 1, m<sub>1</sub> = 1, m<sub>s</sub> = + $${1 \over 2}$$</p>
<p> (b) n = 3, 1 = 2, m<sub>1</sub> = 1, m<sub>s</sub> = + $${1 \over 2}$$</p>
<p>(B) (a) n = 3, $$l$$ = 2, m<sub>1</sub> = $$-$$2, m<sub>s</sub> = $$-$$$${1 \over 2}$$</p>
<p> ... | [{"identifier": "A", "content": "Only (A)"}, {"identifier": "B", "content": "Only (B)"}, {"identifier": "C", "content": "Only (C)"}, {"identifier": "D", "content": "(B) and (C)"}] | ["B"] | null | <p>For degenerate orbitals, only the value of m must
be different. The value of (n + l) must be the
same.</p>
<p>Hence, the pair of electrons with quantum numbers
given in (B) are degenerate.
</p> | mcq | jee-main-2022-online-24th-june-morning-shift | 4,035 |
1l5w5fan6 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The number of radial nodes and total number of nodes in 4p orbital respectively are :</p> | [{"identifier": "A", "content": "2 and 3"}, {"identifier": "B", "content": "2 and 2"}, {"identifier": "C", "content": "3 and 4"}, {"identifier": "D", "content": "4 and 4"}] | ["A"] | null | For $4 p$
<br/><br/>
$$
n=4, l=1
$$
<br/><br/>
Total number of nodes $=n-1=4-1=3$
<br/><br/>
Total radial nodes $=n-l-1=4-1-1=2$ | mcq | jee-main-2022-online-30th-june-morning-shift | 4,036 |
1l6e0k8m9 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Which of the following sets of quantum numbers is not allowed?</p> | [{"identifier": "A", "content": "$$\n\\mathrm{n}=3,1=2, \\mathrm{~m}_{\\mathrm{l}}=0, \\mathrm{~s}=+\\frac{1}{2}\n$$"}, {"identifier": "B", "content": "$$\n\\mathrm{n}=3, \\mathrm{l}=2, \\mathrm{~m}_{\\mathrm{l}}=-2, \\mathrm{~s}=+\\frac{1}{2}\n$$"}, {"identifier": "C", "content": "$$\n\\mathrm{n}=3, \\mathrm{l}=3, \\m... | ["C"] | null | If $$n=3$$, then possible values of $$l=0,1,2$$
<br/><br/>
But in option (C), the value of $$\mathrm{l}$$ is given ' 3 ', this is not possible. | mcq | jee-main-2022-online-25th-july-morning-shift | 4,037 |
1l6kov76x | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The correct decreasing order of energy for the orbitals having, following set of quantum numbers :</p>
<p>(A) n = 3, l = 0, m = 0</p>
<p>(B) n = 4, l = 0, m = 0</p>
<p>(C) n = 3, l = 1, m = 0</p>
<p>(D) n = 3, l = 2, m = 1</p>
<p>is :</p> | [{"identifier": "A", "content": "(D) > (B) > (C) > (A)"}, {"identifier": "B", "content": "(B) > (D) > (C) > (A)"}, {"identifier": "C", "content": "(C) > (B) > (D) > (A)"}, {"identifier": "D", "content": "(B) > (C) > (D) > (A)"}] | ["A"] | null | (A) $\mathrm{n}+\ell=3+0=3$<br/><br/>
(B) $\mathrm{n}+\ell=4+0=4$<br/><br/>
(C) $\mathrm{n}+\ell=3+1=4$<br/><br/>
(D) $\mathrm{n}+\ell=3+2=5$<br/><br/>
Higher $\mathrm{n}+\ell$ valuc, higher the encrgy & if same $\mathrm{n}+\ell$ value, then higher $\mathrm{n}$ value, higher the energy.<br/><br/>
Thus : $\mathrm{D}>\ma... | mcq | jee-main-2022-online-27th-july-evening-shift | 4,038 |
1l6nughc7 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Given below are two statements: One is labelled as Assertion $$\mathbf{A}$$ and the other is labelled as Reason $$\mathbf{R}$$</p>
<p>Assertion $$\mathbf{A}$$ : Zero orbital overlap is an out of phase overlap.</p>
<p>Reason $$\mathbf{R}$$ : It results due to different orientation / direction of approach of orbitals.... | [{"identifier": "A", "content": "Both A and R are true and R is the correct explanation of A"}, {"identifier": "B", "content": "Both A and R are true but R is NOT the correct explanation of A"}, {"identifier": "C", "content": "A is true but R is false"}, {"identifier": "D", "content": "A is false but R is true"}] | ["A"] | null | Zero overlapping is something in which there is no overlapping between two orbitals. The first condition is that the two orbitals should not be symmetrical and the second condition is that both orbitals should be in different planes. | mcq | jee-main-2022-online-28th-july-evening-shift | 4,039 |
1l6rj8621 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Given below are the quantum numbers for 4 electrons.</p>
<p>A. $$\mathrm{n}=3,l=2, \mathrm{~m}_{1}=1, \mathrm{~m}_{\mathrm{s}}=+1 / 2$$</p>
<p>B. $$\mathrm{n}=4,l=1, \mathrm{~m}_{1}=0, \mathrm{~m}_{\mathrm{s}}=+1 / 2$$</p>
<p>C. $$\mathrm{n}=4,l=2, \mathrm{~m}_{1}=-2, \mathrm{~m}_{\mathrm{s}}=-1 / 2$$</p>
<p>D. $$\m... | [{"identifier": "A", "content": "D < B < A < C"}, {"identifier": "B", "content": "D < A < B < C"}, {"identifier": "C", "content": "B < D < A < C"}, {"identifier": "D", "content": "B < D < C < A"}] | ["B"] | null | Energy of the sub-shell is given by, $(n+l)$ rule.
<br/><br/>$\mathrm{A} \Rightarrow 3 \mathrm{~d} \Rightarrow \mathrm{n}+1=5$
<br/><br/>$\mathrm{~B} \Rightarrow 4 \mathrm{p} \Rightarrow \mathrm{n}+\lambda=5$
<br/><br/>$\mathrm{C} \Rightarrow 4 \mathrm{~d} \Rightarrow \mathrm{n}+\ell \Rightarrow 6$
<br/><br/>$\mathrm{D... | mcq | jee-main-2022-online-29th-july-evening-shift | 4,040 |
ldo9gadb | chemistry | structure-of-atom | quantum-numbers-and-orbitals | Arrange the following orbitals in decreasing order of energy.<br/><br/>
A. $\mathrm{n}=3, \mathrm{l}=0, \mathrm{~m}=0$<br/><br/>
B. $\mathrm{n}=4, \mathrm{l}=0, \mathrm{~m}=0$<br/><br/>
C. $\mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}=0$<br/><br/>
D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}=1$
<br/><br/>
The correct option ... | [{"identifier": "A", "content": "$\\mathrm{B}>\\mathrm{D}>\\mathrm{C}>\\mathrm{A}$"}, {"identifier": "B", "content": "$\\mathrm{A}>\\mathrm{C}>\\mathrm{B}>\\mathrm{D}$"}, {"identifier": "C", "content": "$\\mathrm{D}>\\mathrm{B}>\\mathrm{A}>\\mathrm{C}$"}, {"identifier": "D", "content": "$\\mathrm{D}>\\mathrm{B}>\\mathr... | ["D"] | null | (A) n = 3; l = 0; m = 0 ; 3s orbital
<br/><br/>(B) n = 4; l = 0; m = 0 ; 4s orbital
<br/><br/>(C) n = 3; l = 1; m = 0 ; 3p orbital
<br/><br/>(D) n = 3; l = 2; m = 0 ; 3d orbital
<br/><br/>As per Hund’s ruleo of energy is given by (n + l) value.
If value of (n + l) remains same then energy is given
by n only. | mcq | jee-main-2023-online-31st-january-evening-shift | 4,041 |
ldqxaaeh | chemistry | structure-of-atom | quantum-numbers-and-orbitals | Maximum number of electrons that can be accommodated in shell with $n=4$ are: | [{"identifier": "A", "content": "50"}, {"identifier": "B", "content": "32"}, {"identifier": "C", "content": "72"}, {"identifier": "D", "content": "16"}] | ["B"] | null | <p>Maximum electrons accommodated in $$\mathrm{(n = 4)}$$ is $$\mathrm{2n^2=32}$$ electrons</p> | mcq | jee-main-2023-online-30th-january-evening-shift | 4,042 |
1ldu3um1f | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The number of given orbitals which have electron density along the axis is _________</p>
<p>$$\mathrm{p_x,p_y,p_z,d_{xy},d_{yz},d_{xz},d_{z^2},d_{x^2-y^2}}$$</p> | [] | null | 5 | The orbitals which have electron density along the axis are all the $p$-orbitals $\left(p_x, p_y\right.$ and $\left.p_z\right)$ while, out of five $d$-orbitals only two $\left(d_{x^2-y^2}\right.$ and $\left.d_{z^2}\right)$ have electron density along the axis.
<br/><br/>Therefore, the total number of given orbitals whi... | integer | jee-main-2023-online-25th-january-evening-shift | 4,043 |
1lgp3kr4t | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The orbital angular momentum of an electron in $$3 \mathrm{~s}$$ orbital is $$\frac{x h}{2 \pi}$$. The value of $$x$$ is ____________ (nearest integer)</p> | [] | null | 0 | The orbital angular momentum (L) of an electron can be determined using the formula:
<br/><br/>
$$L = \sqrt{l(l+1)} \frac{h}{2\pi}$$
<br/><br/>
Where $$l$$ is the azimuthal quantum number (orbital angular momentum quantum number) and $$h$$ is the Planck's constant.
<br/><br/>
For a 3s orbital, the principal quantum num... | integer | jee-main-2023-online-13th-april-evening-shift | 4,045 |
jaoe38c1lsc6t483 | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The number of electrons present in all the completely filled subshells having $$\mathrm{n}=4$$ and $$\mathrm{s}=+\frac{1}{2}$$ is _______.</p>
<p>(Where $$\mathrm{n}=$$ principal quantum number and $$\mathrm{s}=$$ spin quantum number)</p> | [] | null | 16 | <p>To determine the number of electrons with a spin quantum number of $$s=+\frac{1}{2}$$ in all completely filled subshells with principal quantum number $$n=4$$, we must first identify the subshells in the n=4 shell and then calculate the electrons with the specified spin.</p>
<p>The n=4 shell has the following subshe... | integer | jee-main-2024-online-27th-january-morning-shift | 4,047 |
jaoe38c1lsd9bc2m | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are</p> | [{"identifier": "A", "content": "$$\\mathrm{n}=3, l=0, \\mathrm{~m}=1, \\mathrm{~s}=+\\frac{1}{2}$$\n"}, {"identifier": "B", "content": "$$\\mathrm{n}=4, l=0, \\mathrm{~m}=0, s=+\\frac{1}{2}$$\n"}, {"identifier": "C", "content": "$$\\mathrm{n}=2, l=0, \\mathrm{~m}=0, s=+\\frac{1}{2}$$\n"}, {"identifier": "D", "content"... | ["B"] | null | <p>$${ }_{19} \mathrm{~K} \quad 1 \mathrm{~s}^2, 2 \mathrm{~s}^2, 2 \mathrm{p}^6, 3 \mathrm{~s}^2, 3 \mathrm{p}^6, 4 \mathrm{~s}^1 \text {. }$$</p>
<p>Outermost orbital of potassium is $$4 \mathrm{~s}$$ orbital</p>
<p>$$\mathrm{n}=4,1=0, \mathrm{~m}_{\mathrm{l}}=0, \mathrm{~s}= \pm \frac{1}{2}$$</p> | mcq | jee-main-2024-online-31st-january-evening-shift | 4,048 |
jaoe38c1lsfjl0qx | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The correct set of four quantum numbers for the valence electron of rubidium atom $$(\mathrm{Z}=37)$$ is :</p> | [{"identifier": "A", "content": "$$5,1,1,+\\frac{1}{2}$$\n"}, {"identifier": "B", "content": "$$5,0,0,+\\frac{1}{2}$$\n"}, {"identifier": "C", "content": "$$5,0,1,+\\frac{1}{2}$$\n"}, {"identifier": "D", "content": "$$5,1,0,+\\frac{1}{2}$$"}] | ["B"] | null | <p>$$\begin{aligned}
& \mathrm{Rb}=[\mathrm{Kr}] 5 \mathrm{~s}^1 \\
& \mathrm{n}=5 \\
& l=0 \\
& \mathrm{~m}=0 \\
& \mathrm{~s}=+1 / 2 \text { or }-1 / 2
\end{aligned}$$</p> | mcq | jee-main-2024-online-29th-january-morning-shift | 4,049 |
1lsgy7zzo | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Given below are two statements :</p>
<p>Statement (I) : The orbitals having same energy are called as degenerate orbitals.</p>
<p>Statement (II) : In hydrogen atom, 3p and 3d orbitals are not degenerate orbitals.</p>
<p>In the light of the above statements, choose the most appropriate answer from the options given b... | [{"identifier": "A", "content": "Statement I is true but Statement II is false\n"}, {"identifier": "B", "content": "Statement I is false but Statement II is true\n"}, {"identifier": "C", "content": "Both Statement I and Statement II are false\n"}, {"identifier": "D", "content": "Both Statement I and Statement II are tr... | ["A"] | null | <p>For single electron species the energy depends upon principal quantum number '$$n$$' only. So, statement II is false.</p>
<p>Statement I is correct definition of degenerate orbitals.</p> | mcq | jee-main-2024-online-30th-january-morning-shift | 4,050 |
luz2un1m | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>Compare the energies of following sets of quantum numbers for multielectron system.</p>
<p>(A) $$\mathrm{n}=4,1=1$$</p>
<p>(B) $$\mathrm{n}=4,1=2$$</p>
<p>(C) $$\mathrm{n}=3, \mathrm{l}=1$$</p>
<p>(D) $$\mathrm{n}=3,1=2$$</p>
<p>(E) $$\mathrm{n}=4,1=0$$</p>
<p>Choose the correct answer from the options given below :... | [{"identifier": "A", "content": "$$\n(\\mathrm{E})>(\\mathrm{C})>(\\mathrm{A})>(\\mathrm{D})>(\\mathrm{B})\n$$"}, {"identifier": "B", "content": "$$\n(\\mathrm{B})>(\\mathrm{A})>(\\mathrm{C})>(\\mathrm{E})>(\\mathrm{D})\n$$"}, {"identifier": "C", "content": "$$\n(\\mathrm{C})<(\\mathrm{E})<(\\mathrm{D})<(\\mathrm{A})<(... | ["C"] | null | <p>To compare the energies of electrons in a multielectron system, we must consider both the principal quantum number ($$\mathrm{n}$$) and the azimuthal quantum number ($$\mathrm{l}$$). In multielectron atoms, the energy levels are influenced by electron-electron repulsions, which modify the energy ordering compared to... | mcq | jee-main-2024-online-9th-april-morning-shift | 4,051 |
lv2erl3p | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>The maximum number of orbitals which can be identified with $$\mathrm{n}=4$$ and $$m_l=0$$ is _________.</p> | [] | null | 4 | <p>Possible combination of first three quantum numbers are</p>
<p>$$\begin{aligned}
& n=4, l=3, m=0 \\
& n=4, l=2, m=0 \\
& n=4, l=1, m=0 \\
& n=4, l=0, m=0
\end{aligned}$$</p> | integer | jee-main-2024-online-4th-april-evening-shift | 4,052 |
lv9s2q0t | chemistry | structure-of-atom | quantum-numbers-and-orbitals | <p>In an atom, total number of electrons having quantum numbers $$\mathrm{n}=4,\left|\mathrm{~m}_l\right|=1$$ and $$\mathrm{m}_{\mathrm{s}}=-\frac{1}{2}$$ is _________.</p> | [] | null | 6 | <p>To find the total number of electrons with the given quantum numbers, let's first understand what each quantum number represents:</p>
<ul>
<li><strong>n (Principal Quantum Number):</strong> This specifies the energy level or shell of the electron in the atom. Here, $$n = 4$$ means we are dealing with the fourth en... | integer | jee-main-2024-online-5th-april-evening-shift | 4,053 |
1krz0qljv | chemistry | structure-of-atom | thomson's-model-and-rutherford's-model | Given below are two statements :<br/><br/>Statement I : Rutherford's gold foil experiment cannot explain the line spectrum of hydrogen atom.<br/><br/>Statement II : Bohr's model of hydrogen atom contradicts Heisenberg' uncertainty principle.<br/><br/>In the light of the above statements, choose the most appropriate ans... | [{"identifier": "A", "content": "Statement I is false but statement II is true."}, {"identifier": "B", "content": "Statement I is true but statement II is false."}, {"identifier": "C", "content": "Both statement I and statement II are false."}, {"identifier": "D", "content": "Both statement I and statement II are true.... | ["D"] | null | Rutherford's gold foil experiment only proved that electrons are held towards nucleus by electrostatic forces of attraction and move in circular orbits with very high speeds.<br><br>Bohr's model gave exact formula for simultaneous calculation of speed & distance of electron from the nucleus, something which was dee... | mcq | jee-main-2021-online-27th-july-morning-shift | 4,054 |
1ks1id595 | chemistry | structure-of-atom | thomson's-model-and-rutherford's-model | If the Thompson model of the atom was correct, then the result of Rutherford's gold foil experiment would have been : | [{"identifier": "A", "content": "All of the $$\\alpha$$-particles pass through the gold foil without decrease in speed."}, {"identifier": "B", "content": "$$\\alpha$$-particles are deflected over a wide range of angles."}, {"identifier": "C", "content": "All $$\\alpha$$-particles get bounced back by 180$$^\\circ$$"}, {... | ["D"] | null | As in Thompson model, protons are diffused (charge is not centred) $$\alpha$$-particles deviate by small angles and due to repulsion from protons, their speed decreases. | mcq | jee-main-2021-online-27th-july-evening-shift | 4,055 |
1lh04ort5 | chemistry | structure-of-atom | thomson's-model-and-rutherford's-model | <p>The number of following statement/s which is/are incorrect is ___________</p>
<p>(A) Line emission spectra are used to study the electronic structure</p>
<p>(B) The emission spectra of atoms in the gas phase show a continuous spread of wavelength from red to violet</p>
<p>(C) An absorption spectrum is like the photo... | [] | null | 1 | <p>(A) This statement is <b>correct</b>. Line emission spectra (or atomic emission spectra) are indeed used to study the electronic structure of atoms. These spectra are produced when photons are emitted from atoms as excited electrons return to a lower energy level. Each line corresponds to a particular quantum leap b... | integer | jee-main-2023-online-8th-april-morning-shift | 4,056 |
lv2erjgk | chemistry | structure-of-atom | thomson's-model-and-rutherford's-model | <p>Choose the Incorrect Statement about Dalton's Atomic Theory</p> | [{"identifier": "A", "content": "Compounds are formed when atoms of different elements combine in any ratio.\n"}, {"identifier": "B", "content": "Matter consists of indivisible atoms.\n"}, {"identifier": "C", "content": "chemical reactions involve reorganization of atoms\n"}, {"identifier": "D", "content": "All the ato... | ["A"] | null | <p>According to Dalton’s theory, compounds are
formed when atoms of different elements combine
in fixed ratio.</p> | mcq | jee-main-2024-online-4th-april-evening-shift | 4,057 |
lv7v3tzr | chemistry | structure-of-atom | thomson's-model-and-rutherford's-model | <p>The incorrect postulates of the Dalton's atomic theory are :</p>
<p>(A) Atoms of different elements differ in mass.</p>
<p>(B) Matter consists of divisible atoms.</p>
<p>(C) Compounds are formed when atoms of different element combine in a fixed ratio.</p>
<p>(D) All the atoms of given element have different propert... | [{"identifier": "A", "content": "(B), (D) only\n"}, {"identifier": "B", "content": "(A), (B), (D) only\n"}, {"identifier": "C", "content": "(B), (D), (E) only\n"}, {"identifier": "D", "content": "(C), (D), (E) only"}] | ["A"] | null | <p>Matter consists of non-divisible atoms.</p>
<p>All the atoms of given element have same properties including mass.</p>
<p>Hence, statements (B) and (D) are incorrect.</p> | mcq | jee-main-2024-online-5th-april-morning-shift | 4,058 |
jaoe38c1lse7p62x | chemistry | surface-chemistry | adsorption | <p>'Adsorption' principle is used for which of the following purification method?</p> | [{"identifier": "A", "content": "Chromatography\n"}, {"identifier": "B", "content": "Sublimation\n"}, {"identifier": "C", "content": "Distillation\n"}, {"identifier": "D", "content": "Extraction"}] | ["A"] | null | <p>Principle used in chromotography is adsorption.</p> | mcq | jee-main-2024-online-31st-january-morning-shift | 4,059 |
lv2es2sk | chemistry | surface-chemistry | adsorption | <p>The adsorbent used in adsorption chromatography is/are -</p>
<p>A. silica gel</p>
<p>B. alumina</p>
<p>C. quick lime</p>
<p>D. magnesia</p>
<p>Choose the most appropriate answer from the options given below :</p> | [{"identifier": "A", "content": "C and D only\n"}, {"identifier": "B", "content": "A only\n"}, {"identifier": "C", "content": "B only\n"}, {"identifier": "D", "content": "A and B only"}] | ["D"] | null | <p>Commonly used adsorbents in adsorption
chromatography are silica gel and alumina.</p> | mcq | jee-main-2024-online-4th-april-evening-shift | 4,060 |
qmJpQFnpbWjVANadlI886 | chemistry | surface-chemistry | catalysis | Match the catalysts <b>(Column I)</b> with products
<b>(Column II)</b>.<br/><br/>
<style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;width:100%}
.tg td{font-family:Arial, sans-serif;font-size:14px;padding:10px 5px;border-style:solid;border-width:1px;overflow:hidden;word-break:normal;border-color:bl... | [{"identifier": "A", "content": "(A)-(iii); (B)-(i); (C)-(ii); (D)-(iv)"}, {"identifier": "B", "content": "(A)-(ii); (B)-(iii); (C)-(i); (D)-(iv)"}, {"identifier": "C", "content": "(A)-(iii); (B)-(iv); (C)-(i); (D)-(ii)"}, {"identifier": "D", "content": "(A)-(iv); (B)-(iii); (C)-(ii); (D)-(i)"}] | ["A"] | null | (A) V<sub>2</sub>O<sub>5</sub> is used for preparation of H<sub>2</sub>SO<sub>4</sub> in
contacts process.
<br><br>(B) TiCl<sub>4</sub> + Al(Me)<sub>3</sub> this mixture is called Ziegler-Natta catalyst which is used in the synthesis of high density polyethene from ethene.
<br><br>(C) PdCl<sub>2</sub> is used in ethano... | mcq | jee-main-2019-online-9th-april-morning-slot | 4,062 |
1l6mcfm48 | chemistry | surface-chemistry | catalysis | <p>Match List - I with List - II.</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:sol... | [{"identifier": "A", "content": "$$(\\mathrm{A})-(\\mathrm{II}),(\\mathrm{B})-(\\mathrm{III}),(\\mathrm{C})-(\\mathrm{I}),(\\mathrm{D})-(\\mathrm{IV})$$"}, {"identifier": "B", "content": "$$(\\mathrm{A})-(\\mathrm{III}),(\\mathrm{B})-(\\mathrm{II}),(\\mathrm{C})-(\\mathrm{I}),(\\mathrm{D})-(\\mathrm{IV})$$"}, {"identif... | ["C"] | null | (A) $4 \mathrm{NH}_{3}(\mathrm{~g})+5 \mathrm{O}_{2}(\mathrm{~g}) \stackrel{\mathrm{Pt}(\mathrm{s})}{\longrightarrow} 4 \mathrm{NO}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$
<br/><br/>
(B) $\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Fe}(\mathrm{s})}{\longrightarrow} 2 \mathrm... | mcq | jee-main-2022-online-28th-july-morning-shift | 4,064 |
1ldukpgcb | chemistry | surface-chemistry | catalysis | <p>The variation of the rate of an enzyme catalyzed reaction with substrate concentration is correctly represented by graph :</p>
<p><img src="data:image/png;base64,UklGRlYWAABXRUJQVlA4IEoWAADQ4ACdASoAA94BP4G81mU2LywnIlHKMsAwCWlu/DZ4hW9nZ19/rx+u3e54K1v/P/9//eV2b75r/zbwGAPusZ9n3dpU5H835q/+6/3/FsFyFgGifqqqqqqqqqqqqqqqfSL... | [{"identifier": "A", "content": "(a)"}, {"identifier": "B", "content": "(b)"}, {"identifier": "C", "content": "(d)"}, {"identifier": "D", "content": "(c)"}] | ["D"] | null | <p>The correct plot for enzyme catalysed reaction is</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lebw7t8n/af32c844-861b-46cb-ae81-c170f2328fd8/41ca2660-b09b-11ed-aed4-45743bda0b59/file-1lebw7t8o.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lebw7t8n/af32c844-861b-46... | mcq | jee-main-2023-online-25th-january-morning-shift | 4,065 |
pEeegZrKsKEzGaE8 | chemistry | surface-chemistry | colloids | Gold numbers of protective colloids A, B, C and D are 0.50, 0.01, 0.10 and 0.005, respectively. The
correct order of their protective powers is | [{"identifier": "A", "content": "D < A < C < B"}, {"identifier": "B", "content": "C < B < D < A "}, {"identifier": "C", "content": "A < C < B < D"}, {"identifier": "D", "content": "B < D < A < C "}] | ["C"] | null | For a protective colloid $$\mu $$ lesser the value of gold number better is the protective power.
<br><br>Thus the correct order of protective power of $$A,B,C$$ and $$D$$ is
<br><br>$$ \Rightarrow $$ $$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$$ $$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$$ $$\left( A \right)\,\, < \,\,\left( C \... | mcq | aieee-2008 | 4,069 |
Ql4OXRsAXcqFDiN5 | chemistry | surface-chemistry | colloids | The coagulating power of electrolytes having ions Na<sup>+</sup>, Al<sup>3+</sup> and Ba<sup>2+</sup> for arsenic sulphide sol increases in the order: | [{"identifier": "A", "content": "Na<sup>+</sup> < Ba<sup>2+</sup> < Al<sup>3+</sup>"}, {"identifier": "B", "content": "Al<sup>3+</sup> < Ba<sup>2+</sup> < Na<sup>+</sup> "}, {"identifier": "C", "content": "Ba<sup>2+</sup> < Na<sup>+</sup> < Al<sup>3+</sup> "}, {"identifier": "D", "content": "Al<sup... | ["A"] | null | According to Hardly Schulze rule, greater the charge or cation, greater is its coagulating power for negatively charged solution. Hence the correct order of coagulating power : $$N{a^ + } < B{a^{2 + }} < A{l^{3 + }}$$ | mcq | jee-main-2013-offline | 4,070 |
fRCyhch2Z1CLXq2A | chemistry | surface-chemistry | colloids | The Tyndall effect is observed only when following conditions are satisfied:<br/>
(a) The diameter of the dispersed particles is much smaller than the wavelength of the light used.<br/>
(b) The diameter of the dispersed particle is not much smaller than the wavelength of the light used.<br/>
(c) The refractive indices ... | [{"identifier": "A", "content": "(b) and (d)"}, {"identifier": "B", "content": "(a) and (c)"}, {"identifier": "C", "content": "(b) and (c)"}, {"identifier": "D", "content": "(a) and (d)"}] | ["A"] | null | Tyndall effect is observed only when
<br><br>(i) The diameter of the dispersed particle is not much smaller than the wavelength of the light used.
<br><br>(ii) The refractive indices of the dispersed phase and dispersion medium differ greatly in magnitude.
<br><br>So, (b) and (d) are correct. | mcq | jee-main-2017-offline | 4,073 |
VVuTz7zOVa1BI6sbMl6AV | chemistry | surface-chemistry | colloids | Among the following, correct statement is : | [{"identifier": "A", "content": "Brownian movement is more pronounced for smaller particles than for bigger\u2013particles"}, {"identifier": "B", "content": "Sols of metal sulphides are lyophilic."}, {"identifier": "C", "content": "Hardy Schulze law states that bigger the size of the ions, the greater is its\ncoagulati... | ["D"] | null | (a) Brownian motion caused by the bombardment of the particles by molecules of the median. In smaller particle the bombardment is not effective enough so that it can change it's direction and perform zig zag motion. But for bigger particle zig zag motion happens as bombardment is effective.
<br><br>(b)... | mcq | jee-main-2017-online-8th-april-morning-slot | 4,074 |
7QMYW58iC205VnmxBxLr7 | chemistry | surface-chemistry | colloids | Which of the following statements about colloids is <b>False </b>? | [{"identifier": "A", "content": "Freezing point of colloidal solution is lower than true solution at same concentration of a solute. "}, {"identifier": "B", "content": "Colloidal particles can pass through ordinary filter paper."}, {"identifier": "C", "content": "When silver nitrate solution is added to potassium iodid... | ["A"] | null | Freezing point of colloidal solution is same as true solution at same concentration of a solute. | mcq | jee-main-2018-online-15th-april-morning-slot | 4,075 |
YCDBZD9RuHNJOecoH7dUZ | chemistry | surface-chemistry | colloids | Among the colloids cheese (C), milk (M), and smoke (S), the correct combination of the dispersed phase and dispersion medium, respectively is : | [{"identifier": "A", "content": "C : liquid in solid ; M : liquid in liquid ; S : solid in gas "}, {"identifier": "B", "content": "C : liquid in solid ; M : liquid in solid ; S : solid in gas"}, {"identifier": "C", "content": "C : solid in liquid ; M : liquid in liquid ; S : gas in solid "}, {"identifier": "D", "conten... | ["A"] | null | Cheese (C) is liquid dispersed in solid.
<br><br>Milk (M) is liquid dispersed in liquid.
<br><br>Smoke (S) is solid dispersed in gas.
| mcq | jee-main-2019-online-11th-january-evening-slot | 4,076 |
qzWni6Pu21YFK21OQb3rsa0w2w9jx7vzvnw | chemistry | surface-chemistry | colloids | Among the following, the INCORRECT statement about colloids is :
| [{"identifier": "A", "content": "The range of diameters of colloidal particles is between 1 and to 1000 nm"}, {"identifier": "B", "content": "they are larger than small molecules and have high molar mass"}, {"identifier": "C", "content": "They can scatter light"}, {"identifier": "D", "content": "The osmotic pressure of... | ["D"] | null | Osmotic pressure of colloidal solution is lower than true solution of same concentration. | mcq | jee-main-2019-online-12th-april-evening-slot | 4,077 |
c5ed5JYlxACfvwUrVV3rsa0w2w9jx4z1vgb | chemistry | surface-chemistry | colloids | Peptization is a : | [{"identifier": "A", "content": "process of converting soluble particles to form colloidal solution"}, {"identifier": "B", "content": "process of converting precipitate into colloidal solution"}, {"identifier": "C", "content": "process of bringing colloidal molecule into solution"}, {"identifier": "D", "content": "proc... | ["B"] | null | Peptisation is the process of converting a
precipitate into a colloidal solution by shaking it with
dispersion medium in the presence of small
amount of electrolyte. | mcq | jee-main-2019-online-12th-april-morning-slot | 4,078 |
Ay5VmT5sAvYMA4FHDM3rsa0w2w9jx0ufiqs | chemistry | surface-chemistry | colloids | The correct option among the following is : | [{"identifier": "A", "content": "Addition of alum to water makes it unfit for drinking."}, {"identifier": "B", "content": "Colloidal medicines are more effective because they have small surface area."}, {"identifier": "C", "content": "Colloidal paraticles in lyophobic sols can be precipitated by electrophoresis."}, {"i... | ["C"] | null | Electrophoresis is used to coagulate lyophobic
colloids. | mcq | jee-main-2019-online-10th-april-evening-slot | 4,079 |
fh7FvpbAwAgAAkX8hEf91 | chemistry | surface-chemistry | colloids | Among the following the false statement is - | [{"identifier": "A", "content": "Lyophilic sol can be coagulated by adding an electrote "}, {"identifier": "B", "content": "Tyndall effect can be used to distinguish between a colloidal solution and a true solution "}, {"identifier": "C", "content": "It is possible to cause artificial rain by throwing electrified sand ... | ["D"] | null | Latex is a colloidal solution of rubber particles which are negatively charged. | mcq | jee-main-2019-online-12th-january-evening-slot | 4,081 |
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