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24.5k
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13.4k
|
|---|---|---|---|---|---|---|---|---|---|---|---|
1krt57bdl
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
Thiamine and pyridoxine are also known respectively as :
|
[{"identifier": "A", "content": "Vitamin B<sub>2</sub> and Vitamin E"}, {"identifier": "B", "content": "Vitamin E and Vitamin B<sub>2</sub>"}, {"identifier": "C", "content": "Vitamin B<sub>6</sub> and Vitamin B<sub>2</sub>"}, {"identifier": "D", "content": "Vitamin B<sub>1</sub> and Vitamin B<sub>6</sub>"}]
|
["D"]
| null |
Vitamine-B<sub>1</sub> is also known as Thiamine while Vitamin B-6 is known as Pyridoxine.
|
mcq
|
jee-main-2021-online-22th-july-evening-shift
| 753
|
1krx884rr
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
Which one of the following is correct structure for cytosine?
|
[{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734266690/exam_images/hftskwampmbdjudeowfv.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 25th July Evening Shift Chemistry - Biomolecules Question 81 English Option 1\">"}, {"identifier": "B", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734266820/exam_images/mzm3t0ux1zn6gq0q6thy.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 25th July Evening Shift Chemistry - Biomolecules Question 81 English Option 2\">"}, {"identifier": "C", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734263904/exam_images/jyittmyvlzwj557wmytf.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 25th July Evening Shift Chemistry - Biomolecules Question 81 English Option 3\">"}, {"identifier": "D", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734266992/exam_images/cax0z59l8zlqmudsi3ae.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 25th July Evening Shift Chemistry - Biomolecules Question 81 English Option 4\">"}]
|
["C"]
| null |
The correct structure of cytosine<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263904/exam_images/jyittmyvlzwj557wmytf.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 25th July Evening Shift Chemistry - Biomolecules Question 81 English Explanation">
|
mcq
|
jee-main-2021-online-25th-july-evening-shift
| 754
|
1krz1bm1o
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<img src="data:image/png;base64,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"/><br/>The compound 'A' is a complementary base of _______________ in DNA stands.
|
[{"identifier": "A", "content": "Uracil"}, {"identifier": "B", "content": "Guanine"}, {"identifier": "C", "content": "Adenine"}, {"identifier": "D", "content": "Cytosine"}]
|
["C"]
| null |
<p>Given structure of compound A is thymine, so its complementary
base will be adenine.</p>
<p>Adenine form hydrogen bonds with thymine and cytosine will form
hydrogen bond with guanine.
</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lfuy1m0u/326ae13e-0b69-405b-bc70-d745a2b17b79/83562de0-cee1-11ed-b57d-252f40f16b4e/file-1lfuy1m0v.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lfuy1m0u/326ae13e-0b69-405b-bc70-d745a2b17b79/83562de0-cee1-11ed-b57d-252f40f16b4e/file-1lfuy1m0v.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2021 (Online) 27th July Morning Shift Chemistry - Biomolecules Question 79 English Explanation"></p>
|
mcq
|
jee-main-2021-online-27th-july-morning-shift
| 755
|
1ktece1cn
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
Out of following isomeric forms of uracil, which one is present in RNA?
|
[{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734263393/exam_images/asfadgjup4z7bvww9end.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Biomolecules Question 75 English Option 1\">"}, {"identifier": "B", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734265352/exam_images/ogzwtphwjexlsszkzn4w.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Biomolecules Question 75 English Option 2\">"}, {"identifier": "C", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734264098/exam_images/wtijzph5gjtqygwiuezs.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Biomolecules Question 75 English Option 3\">"}, {"identifier": "D", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734266456/exam_images/jjzdtc3bv9vv6wo9inqz.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Biomolecules Question 75 English Option 4\">"}]
|
["D"]
| null |
Isomeric form of uracil present in RNA<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266456/exam_images/jjzdtc3bv9vv6wo9inqz.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Biomolecules Question 75 English Explanation">
|
mcq
|
jee-main-2021-online-27th-august-morning-shift
| 756
|
1l549r7g9
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Sugar moiety in DNA and RNA molecules respectively are</p>
|
[{"identifier": "A", "content": "$$\\beta$$-D-2-deoxyribose, $$\\beta$$-D-deoxyribose."}, {"identifier": "B", "content": "$$\\beta$$-D-2-deoxyribose, $$\\beta$$-D-ribose"}, {"identifier": "C", "content": "$$\\beta$$-D-ribose, $$\\beta$$-D-2-deoxyribose."}, {"identifier": "D", "content": "$$\\beta$$-D-deoxyribose, $$\\beta$$-D-2-deoxyribose."}]
|
["B"]
| null |
DNA contains $$ \Rightarrow $$ $$\beta $$– D – 2 – deoxyribose
<br/><br/>RNA contains $$ \Rightarrow $$ $$\beta $$– D – ribose
|
mcq
|
jee-main-2022-online-29th-june-morning-shift
| 757
|
1l58jz7v2
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Which one of the following is a water soluble vitamin, that is not excreted easily?</p>
|
[{"identifier": "A", "content": "Vitamin B<sub>2</sub>"}, {"identifier": "B", "content": "Vitamin B<sub>1</sub>"}, {"identifier": "C", "content": "Vitamin B<sub>6</sub>"}, {"identifier": "D", "content": "Vitamin B<sub>12</sub>"}]
|
["D"]
| null |
Vitamin B<sub>12</sub> is water soluble and not excreted easily.
|
mcq
|
jee-main-2022-online-26th-june-evening-shift
| 759
|
1l5w6evbk
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>The sugar produced after complete hydrolysis of DNA is</p>
|
[{"identifier": "A", "content": "a pentose sugar."}, {"identifier": "B", "content": "a hexose sugar."}, {"identifier": "C", "content": "a polysaccharide."}, {"identifier": "D", "content": "a disaccharide."}]
|
["A"]
| null |
DNA mainly consist of a nitrogeneous base, phosphate group and a pentose sugar.
<br/><br/>
So, hydrolysis of DNA produces a pentose sugar.
|
mcq
|
jee-main-2022-online-30th-june-morning-shift
| 760
|
1ldo12mbi
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>All structures given below are of vitamin C. Most stable of them is :</p>
|
[{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1ldob78i5/a55e3ea3-80d8-4b80-9c79-a8f96a03110f/0b1f97d0-a3a3-11ed-ba58-bbbbd3e496d9/file-1ldob78i6.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1ldob78i5/a55e3ea3-80d8-4b80-9c79-a8f96a03110f/0b1f97d0-a3a3-11ed-ba58-bbbbd3e496d9/file-1ldob78i6.png\" loading=\"lazy\" style=\"max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;\" alt=\"JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Biomolecules Question 45 English Option 1\">"}, {"identifier": "B", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1ldob6n5a/0d434d16-477c-4ec5-886f-2d43eac517d4/faa01ce0-a3a2-11ed-ba58-bbbbd3e496d9/file-1ldob6n5b.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1ldob6n5a/0d434d16-477c-4ec5-886f-2d43eac517d4/faa01ce0-a3a2-11ed-ba58-bbbbd3e496d9/file-1ldob6n5b.png\" loading=\"lazy\" style=\"max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;\" alt=\"JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Biomolecules Question 45 English Option 2\">"}, {"identifier": "C", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1ldob6a25/70f35c95-1556-4a31-9fba-430f3df893c0/f08411d0-a3a2-11ed-810c-6704daa1bcc1/file-1ldob6a26.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1ldob6a25/70f35c95-1556-4a31-9fba-430f3df893c0/f08411d0-a3a2-11ed-810c-6704daa1bcc1/file-1ldob6a26.png\" loading=\"lazy\" style=\"max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;\" alt=\"JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Biomolecules Question 45 English Option 3\">"}, {"identifier": "D", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1ldob5tqb/494d0747-621f-4894-b2eb-05939b9e53aa/e3e70130-a3a2-11ed-810c-6704daa1bcc1/file-1ldob5tqc.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1ldob5tqb/494d0747-621f-4894-b2eb-05939b9e53aa/e3e70130-a3a2-11ed-810c-6704daa1bcc1/file-1ldob5tqc.png\" loading=\"lazy\" style=\"max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;\" alt=\"JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Biomolecules Question 45 English Option 4\">"}]
|
["B"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1leu5kppv/fde4ac0d-4491-4256-8569-2153e28fdae3/f670c830-baa5-11ed-905b-c3b697a31028/file-1leu5kppw.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1leu5kppv/fde4ac0d-4491-4256-8569-2153e28fdae3/f670c830-baa5-11ed-905b-c3b697a31028/file-1leu5kppw.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 60vh" alt="JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Biomolecules Question 45 English Explanation">
|
mcq
|
jee-main-2023-online-1st-february-evening-shift
| 761
|
1ldo39rmq
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Testosterone, which is a steroidal hormone, has the following structure.</p>
<p><img src="data:image/png;base64,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"/></p>
<p>The total number of asymmetric carbon atom/s in testosterone is ____________.</p>
|
[]
| null |
6
|
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1ldr81obw/d10a33f0-7120-407f-b91c-7d244157ba0a/0f0e0ac0-a53d-11ed-9c6f-c949bf5cccc2/file-1ldr81obx.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1ldr81obw/d10a33f0-7120-407f-b91c-7d244157ba0a/0f0e0ac0-a53d-11ed-9c6f-c949bf5cccc2/file-1ldr81obx.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Biomolecules Question 46 English Explanation">
|
integer
|
jee-main-2023-online-1st-february-evening-shift
| 762
|
1ldyhk5rm
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Uracil is a base present in RNA with the following structure. % of N in uracil is ___________</p>
<p><img src="data:image/png;base64,UklGRu4KAABXRUJQVlA4IOIKAADQwwCdASoJAgADP4HA3WU2MS4nIjSY4sAwCWlu8p9XgS/KyettUfP2l9NHTbz5gT+ejtD+Siomr/6MtbP1/4/4bOxDqTk7oh1Jyd0Q6k5O55Q0fXFafgmMGj64rT8Exg0fZ/g0fXFafgmMGj64rT8Exg0fZ/g0fXFaerEmGgoefQ/fjYvs/DqZeCYwaPritPwTGLnwTGDR9ZDZGabfgrIbBJAmG/erK4rT8Exg0fXF10fXFafgbQnEaI0zrTONsl6YU5O6IdScndDpH+CYwaM0Z8A3FxN+FO6PnO4VG54gaAgfNe8AQPmvbmn4JjBozFzGqRrh9pcJPvWTGDR9cVp+CYxc+CYwaPrVQprBcax6A2qsg70xg0fXFafgn+afgmMGje79aySZK+XGDR9cVp+CZGZ+CYwaPpVQr/mYwaPritPwTGDrwTGDR9cNMqRgwHnnvNuZH5Mm7u4ho+uK0/BMYNMxMYNH1w4JIWrwdQJt6XlbJ1B42eRwUTi89l3jmfR3a/A0fXFafgmMGmYmMGj5IMf41jk4lM8KpYXWNkph9YNBvezAZs92QUoBXnuv7r+6/uvz+DR9YrLtdSnmcSwSow1NgbWrFswx7IPOiqV5q+uVLzvVSSGSQySGSQySGSQzEemK9mJS8eJsiB/VBL/jblHrzXjxVtzmleWVjAtHHAMzftDzPByZMybFYjSOMYFT+f8AFXEoSpAn2f4FA5vfOGAtmWvmX7KBkIGNFFQ62DnFBLsJ9GLzPcl43UWhIXzQbnL9tkcU8hUftYvA7mtZaOqaYex4S5VlgiHFrdKdceCYxv3JkZ8XV4EUizyAoHu5fEa3UtckybTRI5XsCVvIxc9+yReVlVJsxBMY37kyZQ0wTSQ7Jo6tHDTEKX7Q/aQLERJAVpigLaZZEs7EDmHbpmJcUU3f6EgvjRXFcKnaX1hzvGjGZhj7K3kBDaGZuSCO6qAWjh7zMHXgjaALQplafwQtKSaw8XYNrvf21waZiYOKmKpmMGnFCweX7g4qnYAtQFxWo31t72PfiUNIJMQ04oV2LBIqT8Exi579kksmN0rUk1iuFTsve0xWn4JjFz37JJZMbpWpJrFcKnZe9pitPwTGLnv2JzHOvvih4mSj66GLPtZ1oALWp+CYwaZiYOKgwodrbTFafwQtKSaxLbBWkWVhkNH1xWo31mnD7DvbS+tWtElGT0U7itSTWK4VNRlACG/FxhaLnm/t/+S0wRb4oWk/BMjM+8qqfD5XZ+S3Ct5q1Kd0MKNtZ1o+SAD/SAYfrqC7uZP/P2DmSYoLvBqd3WjbsNaSXV4PdaVp+za8Am0k1hbj6pujiQ0poS1Z/wQu0hHPEJSLBKQpOYF5tRFgcZECX7rsPq8+dJkVGmwt8zvVBKf4j7CWn7NrkuelP2Qdisstl2r2/+LHalRgiAIG3t6dnFyb/1afQS06/TjIHJeX70IaqGe3cYOPN9yTteAzAryGp752rmfPSBPGDMreJQqrGmL8R+3cNAqtIXz1eCyBbKxmZGWnRk3Thu1yreaUUBsD9cgUfRFHUbuM0TthQcmk021xW8lSSC+tk1rt5ix3ikRDXFVJvJ9cLJc6UAlzmBO79gEg7NM6WJCqvkuMHXhLlafgl4S4lBZTF9ihzZvEJ+Y+8zR9cYHEHbw0TeD/kZipRvs/waPrhYVEijGrsWlFwZKXkIbnwhJO0bXFaevHxg0gTyMz8Exg0AGkjnFafgmMGj64uumYmMGj6zhfX9ZXNritPwTGDR9cXXTMTGDR9be9pitPwTGDR9cVp+za5DR9cVoxFWLoQF5P2DR9cVp+CYwaQJ5GZ+CYwdt9cVp+CYwaPritRvs/waPrhThm7nSgBFFJxJ/HdkjEF5DR9cVp+CYwaQJ5GZ+CYwVJZI7avuxZ9cVp+CYwaPs/xc+CYwZ/+aVYVCPAdcqZjBo+uK0/BMYOvCXK0/BLjs4Qb6o7tuefTck/u4VVSTGDR9cVp+CYxc+zaVp+CEB/OhgbdKQyKJC52HPBMYNH1xWn4S5ddH1xW88LtxUn4JjBo+uK3m4njBo+uK0/BMYNH1xWn4JjFz7NpWn4JjBo+uK0/BMYNH1xUAAA/vtaAAAAAAABxsn4RT6AG4gg0YbSUCBwQ5f8x+ddgV6fzsvAAB34i3vEj72c/ZhiKD0Yr1aVdju7ukD3zZgAVQ19SwDTvWvxPmYoNANhSP4AtsDmD8BWylWNlA3yZ5U390D5F9EUhXNwB4L12FLcucL5pcpCNDao/+PYqKmw8HMtkgAA3YeGMALdeOsj4gCrIsAAP/f1MqU2jkZgAHTvXX+ng2P9ABKRCbDLwqxilKfBSRb73ECERS05UJd3tYG4sJVQJs32k+gQ95MWFuSniLwPzgDn370Qr2Bi8zJiu8HjOhnRP59pBGe1N+JHC7I9LKQl4fJdT9jA4vFM2kVfIgFP2WiuSGc+0gx8cWXLpBZnn4xZ8S91x662RNovuIEeU7A5+0qPzjuTWmBQgaY8YrLboaU/VUJWASGlHW5IRl/+5H+cOPCYm7Epg9BepmsWEWx9Iu9QRw3t7f2Ama6nDk2OJO7fk2PeSwVSczbyUJcVYw4utwnt7FfJBai468NLXKQnjJqQ7hDgoMrMxfAeYipJN9iOpQGPlHd0s0iKdvdosnI4suYUhZW8w+tmson/8Jib6bl/vQXrjaxUcBCHwbThD333Ui81Lb4vHp0DtOPPMNTXowd1hzlckPtObJ0qdafUSiPAEBILEhBOwWjmjAAnK3aoJ3uWzd55/UAWexW8NuFAT74KDDZ9GGHeIv6BR9mzRrbPbUll7Gf61Y1INVVIVetm/V27x24KbhbQmtHJ01kGADF3nKIrJTOBCo+DIbGhWGQGVJQQ6Bmmb8AQkgmC12Ehx6+2CkJQOscq+IlGBnWzBA4ineEMwAU5hDjKABw0WACAHBAA+RWUAPDhMHboQgFb8iqU6cVEihsauc930xxPZCNgvVuOF5Q7tHbhXiobE+3uhHRC8BD0MJND6N7M7vA30ic00YFI/fHKMwtkDoDAN4Pi28MYUjSjsy5B/KzjUm+jYfCYmvxxI4PhesWEWyNg8gQdCBTdSsF64vb8soIDBHEqFZJOnDY28Jid3wrxwaWt0o7MuNPV54lPDz0R8C8+XrTWUzFCECB2tyYGzOqN3rMQmoxUmWvndlzIiiDa0yh+r8TDzdrDDoTWmCTUo5Ck8X0x4WamtDR230OA2LorpxhKSc60T4CzLv2RR67n63ouzPPhuIS9lusCARqM74d73ECQaPV8SEUaQ2aCCLbJpo6h03NjKj7HY3c1LmClOUe5CPKaIYpIjeoUwp3J5t/i8f5O41Xzj3jxqh6iJ2EpYJkIvPyZUesABx1cI1eZ+sV7nFE8bGSh1P303nqg1fd+7TPixn0s708AfbjRe+VGGFYoZiyXNOUD1Z8R6FiQF+YZ9ZtXCG0MlLSQUUC14AxclW8YALs4e/FYknukJXaZ1kODBLQ6ovvsOokIA50VyNFTWJpIAEf1xjliflAMjwADPjAAt2l8IoLADJVDlPO146xyAAAAjXTjBoM+hdZcBWVdEwBwV5vH95zDzscFYlAdwVfh+Y4ZuzO64JDgAavo1DrBy2+S9Kf8Eg0L6lYAyIink1Wf0s2mSTO9Dcn+YAPPgVlqQvmQKjx0o5nZUEBNJiaHAQDwBl1eHMicokAAAAAAAAAAAA=="/></p>
<p>Given:</p>
<p>Molar mass N = 14 g mol$$^{-1}$$</p>
<p>O = 16 g mol$$^{-1}$$</p>
<p>C = 12 g mol$$^{-1}$$</p>
<p>H = 1 g mol$$^{-1}$$</p>
|
[]
| null |
25
|
Uracil is $\mathrm{C}_{4} \mathrm{H}_{4} \mathrm{~N}_{2} \mathrm{O}_{2}$
<br/><br/>
Mol. Wt of $\mathrm{C}_{4} \mathrm{H}_{4} \mathrm{~N}_{2} \mathrm{O}_{2}$ = 112 <br/><br/>
$\%$ by mass of $N=\frac{14 \times 2}{112} \times 100$
<br/><br/>
$$
=25 \%
$$
|
integer
|
jee-main-2023-online-24th-january-morning-shift
| 763
|
lgnzgm5p
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
Which is not true for arginine?
|
[{"identifier": "A", "content": "It has a fairly high melting point."}, {"identifier": "B", "content": "It is associated with more than one $\\mathrm{pK}_{\\mathrm{a}}$ values."}, {"identifier": "C", "content": "It has high solubility in benzene."}, {"identifier": "D", "content": "It is a crystalline solid. "}]
|
["C"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lgrkncln/e55d2b89-9ff2-4a0a-82e1-ca339d60d119/fd7b65b0-e0d2-11ed-8b13-b3bb227d6f90/file-1lgrknclo.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lgrkncln/e55d2b89-9ff2-4a0a-82e1-ca339d60d119/fd7b65b0-e0d2-11ed-8b13-b3bb227d6f90/file-1lgrknclo.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 15th April Morning Shift Chemistry - Biomolecules Question 33 English Explanation"><br>Arginine is an amino acid that has a basic side chain containing a guanidino group. The other three options are true for arginine:
<br><br>
(A) It has a fairly high melting point due to the presence of strong ionic interactions between the positively charged guanidino group and the negatively charged carboxylate group in the solid state.<br><br>
(B) It is associated with more than one pKa values because it contains multiple ionizable groups, including the amino group, the carboxylate group, and the guanidino group. These groups can dissociate in a stepwise manner, leading to multiple pKa values.<br><br>
(D) It is a crystalline solid due to the presence of strong ionic interactions between the positively charged guanidino group and the negatively charged carboxylate group, which leads to the formation of a well-ordered crystal lattice.
<br><br>
However, option (C) is not true because arginine is not soluble in benzene. This is because benzene is a nonpolar solvent, and arginine is a polar and charged molecule. Therefore, arginine is more soluble in polar solvents such as water and less soluble in nonpolar solvents such as benzene.
|
mcq
|
jee-main-2023-online-15th-april-morning-shift
| 764
|
1lgp2jfq1
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>The naturally occurring amino acid that contains only one basic functional group in its chemical structure is</p>
|
[{"identifier": "A", "content": "asparagine"}, {"identifier": "B", "content": "arginine"}, {"identifier": "C", "content": "histidine"}, {"identifier": "D", "content": "lysine"}]
|
["A"]
| null |
Among the given options, arginine, histidine, and lysine are all basic amino acids because they contain amino (-NH<sub>2</sub>) and imino (-NH=) functional groups that can accept a proton (H<sup>+</sup>) to become positively charged.
<br/><br/>
Asparagine, on the other hand, contains an amide (-CONH<sub>2</sub>) functional group instead of an imino group. This functional group is not basic because it does not have a proton that can be easily removed. Therefore, the answer is: asparagine.
|
mcq
|
jee-main-2023-online-13th-april-evening-shift
| 765
|
1lgysfdkf
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Match List I with List II</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
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.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-baqh{text-align:center;vertical-align:top}
.tg .tg-amwm{font-weight:bold;text-align:center;vertical-align:top}
.tg .tg-0lax{text-align:left;vertical-align:top}
</style>
<table class="tg" style="undefined;table-layout: fixed; width: 658px">
<colgroup>
<col style="width: 46px"/>
<col style="width: 300px"/>
<col style="width: 48px"/>
<col style="width: 264px"/>
</colgroup>
<thead>
<tr>
<th class="tg-amwm"></th>
<th class="tg-amwm">LIST I<br/>Natural amino acid</th>
<th class="tg-amwm"></th>
<th class="tg-amwm">LIST II<br/>One letter code</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-baqh">A.</td>
<td class="tg-0lax">Glutamic acid</td>
<td class="tg-baqh">I.</td>
<td class="tg-0lax">Q</td>
</tr>
<tr>
<td class="tg-baqh">B.</td>
<td class="tg-0lax">Glutamine</td>
<td class="tg-baqh">II.</td>
<td class="tg-0lax">W</td>
</tr>
<tr>
<td class="tg-baqh">C.</td>
<td class="tg-0lax">Tyrosine</td>
<td class="tg-baqh">III.</td>
<td class="tg-0lax">E</td>
</tr>
<tr>
<td class="tg-baqh">D.</td>
<td class="tg-0lax">Tryptophan</td>
<td class="tg-baqh">IV.</td>
<td class="tg-0lax">Y</td>
</tr>
</tbody>
</table></p>
<p>Choose the correct answer from the options given below:</p>
|
[{"identifier": "A", "content": "A-III, B-IV, C-I, D-II"}, {"identifier": "B", "content": "A-IV, B-III, C-I, D-II"}, {"identifier": "C", "content": "A-II, B-I, C-IV, D-III"}, {"identifier": "D", "content": "A-III, B-I, C-IV, D-II"}]
|
["D"]
| null |
<p>The one-letter code for each amino acid is as follows:</p>
<p>Glutamic Acid (A) is represented by the letter E (III).<br/><br/>
Glutamine (B) is represented by the letter Q (I).<br/><br/>
Tyrosine (C) is represented by the letter Y (IV).<br/><br/>
Tryptophan (D) is represented by the letter W (II).</p>
<p>These one-letter codes are part of the standard notation used in biology and biochemistry to represent the 20 standard amino acids, plus a few others. The codes are designed to be short and easy to remember, while still being distinct from each other.</p>
|
mcq
|
jee-main-2023-online-8th-april-evening-shift
| 766
|
1lh32d6j3
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Match List I with List II</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top}
.tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top}
.tg .tg-0pky{border-color:inherit;text-align:left;vertical-align:top}
</style>
<table class="tg" style="undefined;table-layout: fixed; width: 616px">
<colgroup>
<col style="width: 46px"/>
<col style="width: 258px"/>
<col style="width: 48px"/>
<col style="width: 264px"/>
</colgroup>
<thead>
<tr>
<th class="tg-7btt"></th>
<th class="tg-7btt">LIST I <br/>Natural Amino Acid</th>
<th class="tg-7btt"></th>
<th class="tg-7btt">LIST II <br/>One Letter Code</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-c3ow">A.</td>
<td class="tg-0pky">Arginine</td>
<td class="tg-c3ow">I.</td>
<td class="tg-0pky">D</td>
</tr>
<tr>
<td class="tg-c3ow">B.</td>
<td class="tg-0pky">Aspartic acid</td>
<td class="tg-c3ow">II.</td>
<td class="tg-0pky">N</td>
</tr>
<tr>
<td class="tg-c3ow">C.</td>
<td class="tg-0pky">Asparagine</td>
<td class="tg-c3ow">III.</td>
<td class="tg-0pky">A</td>
</tr>
<tr>
<td class="tg-c3ow">D.</td>
<td class="tg-0pky">Alanine</td>
<td class="tg-c3ow">IV.</td>
<td class="tg-0pky">R</td>
</tr>
</tbody>
</table></p>
<p>Choose the correct answer from the options given below:</p>
|
[{"identifier": "A", "content": "(A) - IV, (B) - I, (C) - III, (D) - II"}, {"identifier": "B", "content": "(A) - III, (B) - I, (C) - II, (D) - IV"}, {"identifier": "C", "content": "(A) - IV, (B) - I, (C) - II, (D) - III"}, {"identifier": "D", "content": "(A) - I, (B) - III, (C) - IV, (D) - II"}]
|
["C"]
| null |
<p>In protein chemistry, each amino acid is assigned a one-letter code to simplify notation. The matching for the given amino acids to their one-letter codes is as follows:</p>
<ul>
<li>Arginine (A) - R (IV)</li>
<li>Aspartic Acid (B) - D (I)</li>
<li>Asparagine (C) - N (II)</li>
<li>Alanine (D) - A (III)</li>
</ul>
<p>So, the correct answer is Option C: (A) - IV, (B) - I, (C) - II, (D) - III.</p>
|
mcq
|
jee-main-2023-online-6th-april-evening-shift
| 767
|
lsbmnxvx
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
If one strand of a DNA has the sequence ATGCTTCA, sequence of the bases in complementary strand is :
|
[{"identifier": "A", "content": "CATTAGCT"}, {"identifier": "B", "content": "TACGAAGT"}, {"identifier": "C", "content": "ATGCGACT"}, {"identifier": "D", "content": "GTACTTAC"}]
|
["B"]
| null |
DNA is made up of two strands that are complementary to each other. The base pairing rules state that adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G). Using these rules, we can determine the sequence of the complementary strand of the given DNA sequence ATGCTTCA.
Here's the pairing for the given sequence:
<p>A (adenine) pairs with T (thymine)</p>
<p>T (thymine) pairs with A (adenine)</p>
<p>G (guanine) pairs with C (cytosine)</p>
<p>C (cytosine) pairs with G (guanine)</p>
<p>T (thymine) pairs with A (adenine)</p>
<p>T (thymine) pairs with A (adenine)</p>
<p>C (cytosine) pairs with G (guanine)</p>
<p>A (adenine) pairs with T (thymine)</p>
So, the complementary base sequence to the given DNA strand ATGCTTCA would be:
<p>1. A pairs with T</p>
<p>2. T pairs with A</p>
<p>3. G pairs with C</p>
<p>4. C pairs with G</p>
<p>5. T pairs with A</p>
<p>6. T pairs with A</p>
<p>7. C pairs with G</p>
<p>8. A pairs with T</p>
Putting it all together, the complementary sequence is: TACGAAGT. Therefore, the correct answer is:
Option B - TACGAAGT
|
mcq
|
jee-main-2024-online-1st-february-morning-shift
| 768
|
jaoe38c1lsc4rx0p
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>Two nucleotides are joined together by a linkage known as :</p>
|
[{"identifier": "A", "content": "Phosphodiester linkage\n"}, {"identifier": "B", "content": "Glycosidic linkage\n"}, {"identifier": "C", "content": "Disulphide linkage\n"}, {"identifier": "D", "content": "Peptide linkage"}]
|
["A"]
| null |
<p>Phosphodiester linkage</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lscv4crp/cd09282d-d50f-43ce-9dd7-b22841787518/c876ed50-c64e-11ee-9d8b-f1be86a1b2f3/file-6y3zli1lscv4crq.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lscv4crp/cd09282d-d50f-43ce-9dd7-b22841787518/c876ed50-c64e-11ee-9d8b-f1be86a1b2f3/file-6y3zli1lscv4crq.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 27th January Morning Shift Chemistry - Biomolecules Question 20 English Explanation"></p>
|
mcq
|
jee-main-2024-online-27th-january-morning-shift
| 769
|
jaoe38c1lsd9yf4l
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>From the vitamins $$\mathrm{A}, \mathrm{B}_1, \mathrm{~B}_6, \mathrm{~B}_{12}, \mathrm{C}, \mathrm{D}, \mathrm{E}$$ and $$\mathrm{K}$$, the number of vitamins that can be stored in our body is _________.</p>
|
[]
| null |
5
|
<p>Vitamins A, D, E, K and B$$_{12}$$ are stored in liver and adipose tissue.</p>
|
integer
|
jee-main-2024-online-31st-january-evening-shift
| 770
|
1lsg843uz
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>The total number of correct statements, regarding the nucleic acids is _________.</p>
<p>A. RNA is regarded as the reserve of genetic information</p>
<p>B. DNA molecule self-duplicates during cell division</p>
<p>C. DNA synthesizes proteins in the cell</p>
<p>D. The message for the synthesis of particular proteins is present in DNA</p>
<p>E. Identical DNA strands are transferred to daughter cells.</p>
|
[]
| null |
3
|
<p>A. RNA is regarded as the reserve of genetic information. (False)</p>
<p>B. DNA molecule self-duplicates during cell division. (True)</p>
<p>C. DNA synthesizes proteins in the cell. (False)</p>
<p>D. The message for the synthesis of particular proteins is present in DNA. (True)</p>
<p>E. Identical DNA strands are transferred to daughter cells. (True)</p>
|
integer
|
jee-main-2024-online-30th-january-evening-shift
| 771
|
luz2uu5m
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>The $$\mathrm{F}^{-}$$ ions make the enamel on teeth much harder by converting hydroxyapatite (the enamel on the surface of teeth) into much harder fluoroapatite having the formula.</p>
|
[{"identifier": "A", "content": "$$\\left[3\\left(\\mathrm{Ca}_3\\left(\\mathrm{PO}_4\\right)_2\\right) \\cdot \\mathrm{CaF}_2\\right]$$\n"}, {"identifier": "B", "content": "$$\\left[3\\left(\\mathrm{Ca}_3\\left(\\mathrm{PO}_4\\right)_2\\right) \\cdot \\mathrm{Ca}(\\mathrm{OH})_2\\right]$$\n"}, {"identifier": "C", "content": "$$\\left[3\\left(\\mathrm{Ca}_3\\left(\\mathrm{PO}_4\\right)_3\\right) \\cdot \\mathrm{CaF}_2\\right]$$\n"}, {"identifier": "D", "content": "$$\\left[3\\left(\\mathrm{Ca}_2\\left(\\mathrm{PO}_4\\right)_2\\right) \\cdot \\mathrm{Ca}(\\mathrm{OH})_2\\right]$$"}]
|
["A"]
| null |
<p>Hydroxyapatite : $$\left[3\left(\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2\right) \cdot \mathrm{Ca}(\mathrm{OH})_2\right]$$</p>
<p>Fluoroapatite : $$\left[3\left(\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2\right) \cdot \mathrm{CaF}_2\right]$$</p>
|
mcq
|
jee-main-2024-online-9th-april-morning-shift
| 772
|
lvc58ep5
|
chemistry
|
biomolecules
|
vitamins-and-nucleic-acids
|
<p>DNA molecule contains 4 bases whose structure are shown below. One of the structures is not correct, identify the incorrect base structure.</p>
|
[{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lvc3gscv/94244162-3886-468c-92c7-5664f7b042dd/48bc71f0-0147-11ef-9994-d5a6f8729fd1/file-1lvc3gscw.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lvc3gscv/94244162-3886-468c-92c7-5664f7b042dd/48bc71f0-0147-11ef-9994-d5a6f8729fd1/file-1lvc3gscw.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Option 1\">"}, {"identifier": "B", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lvc3h56z/aa89e153-5ac1-4c75-b779-0b2911e2ade9/52a6e5b0-0147-11ef-9994-d5a6f8729fd1/file-1lvc3h570.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lvc3h56z/aa89e153-5ac1-4c75-b779-0b2911e2ade9/52a6e5b0-0147-11ef-9994-d5a6f8729fd1/file-1lvc3h570.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Option 2\">"}, {"identifier": "C", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lvc3hnb4/dbfd5a29-6257-4920-961b-d783d2807aa3/60a53400-0147-11ef-9994-d5a6f8729fd1/file-1lvc3hnb5.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lvc3hnb4/dbfd5a29-6257-4920-961b-d783d2807aa3/60a53400-0147-11ef-9994-d5a6f8729fd1/file-1lvc3hnb5.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Option 3\">"}, {"identifier": "D", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lvc3i1a1/6a817b3c-c697-40bd-8be6-c3eb32d2e51f/6b6fce90-0147-11ef-9994-d5a6f8729fd1/file-1lvc3i1a2.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lvc3i1a1/6a817b3c-c697-40bd-8be6-c3eb32d2e51f/6b6fce90-0147-11ef-9994-d5a6f8729fd1/file-1lvc3i1a2.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Option 4\">"}]
|
["D"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lx1j9vov/3706743b-a317-4e8d-a4d5-c49e69b3eb33/ea540b00-2310-11ef-9133-d75aec91fe89/file-6y3zli1lx1j9vow.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lx1j9vov/3706743b-a317-4e8d-a4d5-c49e69b3eb33/ea540b00-2310-11ef-9133-d75aec91fe89/file-6y3zli1lx1j9vow.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Explanation 1">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lx1j79rs/c10c115b-b267-4c1a-8d03-7575160ba81c/a1c70b80-2310-11ef-9133-d75aec91fe89/file-6y3zli1lx1j79rt.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lx1j79rs/c10c115b-b267-4c1a-8d03-7575160ba81c/a1c70b80-2310-11ef-9133-d75aec91fe89/file-6y3zli1lx1j79rt.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Explanation 2">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lx1j768t/bae4212b-2f89-467a-802e-e7e95cd300ef/9f0d90d0-2310-11ef-9133-d75aec91fe89/file-6y3zli1lx1j768u.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lx1j768t/bae4212b-2f89-467a-802e-e7e95cd300ef/9f0d90d0-2310-11ef-9133-d75aec91fe89/file-6y3zli1lx1j768u.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 6th April Morning Shift Chemistry - Biomolecules Question 1 English Explanation 3">
<p>Are bases of DNA molecule. As DNA contain four bases, which are adenine, guanine, cytosine and thymine.</p>
|
mcq
|
jee-main-2024-online-6th-april-morning-shift
| 773
|
4cdlCNiVegCDNUzm
|
chemistry
|
chemical-bonding-and-molecular-structure
|
back-bonding
|
The bond dissociation energy of B - F in BF<sub>3</sub> is 646 kJ mol<sup>-1</sup> whereas that of C - F in CF<sub>4</sub> is 515 kj mol<sup>-1</sup>. The correct reason for higher B - F bond dissociation energy as compared to that of C - F is
|
[{"identifier": "A", "content": "stronger $$\\sigma$$ bond between B and F in BF<sub>3</sub> as compared to that between C and F in CF<sub>4</sub>"}, {"identifier": "B", "content": "significant $$p\\pi - p\\pi$$ interaction between B and F in BF<sub>3</sub> whereas there is no possibility of such interaction between C and F in CF<sub>4</sub>"}, {"identifier": "C", "content": "lower degree of $$p\\pi - p\\pi$$ interaction between B and F in BF<sub>3</sub> than that between C and F in CF<sub>4</sub>"}, {"identifier": "D", "content": "smaller size of B - atom as compared to that of C- atom."}]
|
["B"]
| null |
In BF<sub>3</sub>, B is sp<sup>2</sup>
hybridised and by Back Bonding method strong p$$\pi $$-p$$\pi $$ bond is created between filled p-orbital of F and vacant p-orbital of
B which leads to shortening of B–F bond length which results in higher bond dissociation energy of
the B–F bond. However in CF<sub>4</sub>, C does not have any vacant
p-orbitals to undergo $$\pi $$-bonding.
|
mcq
|
aieee-2008
| 774
|
hIKAVgpODAw47kWU
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
The correct order of bond angles (smallest first) in H<sub>2</sub>S, NH<sub>3</sub>, BF<sub>3 </sub> and SiH<sub>4</sub> is
|
[{"identifier": "A", "content": "H<sub>2</sub>S < SiH<sub>4</sub> < NH<sub>3</sub> < BF<sub>3</sub> "}, {"identifier": "B", "content": "H<sub>2</sub>S < NH<sub>3</sub> < BF<sub>3</sub> < SiH<sub>4</sub>"}, {"identifier": "C", "content": "H<sub>2</sub>S < NH<sub>3</sub> < SiH<sub>4</sub> < BF<sub>3</sub> "}, {"identifier": "D", "content": "NH<sub>3 </sub> < H<sub>2</sub>S < SiH<sub>4</sub> < BF<sub>3</sub>"}]
|
["C"]
| null |
<b>1.</b> In H<sub>2</sub>S molecule, central atom S is a 3rd period element and according to Dragos rule, when a 3rd period or higher period element overlap with a small element whose electronegetivity is low then that over lapping cannot be a effective overlapping, because of higher size of 3rd or higher periods element and smaller size of low electronegative element.
<br><br>Here in H<sub>2</sub>S, H atom has very low electronegativity and smaller in size so it create more negative charge around sulphur(S) atom and size of S<sup>$$-$$2</sup> ion increases, because of this higher size difference efficiency overlapping is not possible. So, any hybridization do not happen in between S and H atom. Lone pair electrons of S atom is present in the pure orbital like s, p<sub>x</sub>, p<sub>y</sub>, p<sub>z</sub> and it look like this :
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263399/exam_images/i79hzr33uomve2k7wepw.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 217 English Explanation 1">
<br><br>As we know the angle between and p<sub>y</sub> is 90<sup>o</sup>, so bond angle is 90<sup>o</sup>.
<br><br><b>2.</b> In NH<sub>3</sub>, 3 Bond pair(BP) + 1 lone pair (LP) present so angle between bond 107<sup>o</sup>.
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264658/exam_images/s0gxmglputhr9raob41j.webp" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 217 English Explanation 2">
<br><br>3. $$\,\,\,\,$$ BF<sub>3</sub> has sp<sup>2</sup> hybridization. So bond angle is 120<sup>o</sup>.
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264555/exam_images/xwkxjygw4ae2v5yybp3k.webp" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 217 English Explanation 3">
<br><br><b>4.</b><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264421/exam_images/boqghclvxlqbi3ifhjlv.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 217 English Explanation 4">
<br>Here Si is sp<sup>3</sup> hybridised and shape is regular tetrahedral and bond angle 109<sup>o</sup> 28'
|
mcq
|
aieee-2004
| 775
|
JwF7qXS0mwqWGfITfQaAz
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
The bond angle H - X - H is the greatest in the compound :
|
[{"identifier": "A", "content": "CH<sub>4</sub>"}, {"identifier": "B", "content": "NH<sub>3</sub>"}, {"identifier": "C", "content": "H<sub>2</sub>O"}, {"identifier": "D", "content": "PH<sub>3</sub>"}]
|
["A"]
| null |
CH<sub>4</sub> - sp<sup>3</sup> hybridisation - Bond angle (109<sup>o</sup>28')
<br><br>NH<sub>3</sub> - sp<sup>3</sup> hybridisation - Bond angle ( 107.8<sup>o</sup>)
<br><br>H<sub>2</sub>O - sp<sup>3</sup> hybridisation - Bond angle ( 104.5<sup>o</sup>)
<br><br>PH<sub>3</sub> - No hybridisation - Bond angle ( 90<sup>o</sup>)
<br><br><b>Note :</b> According to DRAGO RULE, lone pair of electrons are in pure s- orbital of the atom P. That is why PH<sub>3</sub> has no hybridisation.
|
mcq
|
jee-main-2016-online-10th-april-morning-slot
| 776
|
InOV4zYIksaJMKRwThbM1
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
<img src="data:image/png;base64,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"/>
<br/>In hydrogen azide (above) the bond orders of bond (I) and (II) are :
|
[{"identifier": "A", "content": "$$\\eqalign{\n & (\\mathrm{I})\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(\\mathrm{II}) \\cr \n & < 2\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, > 2 \\cr} $$"}, {"identifier": "B", "content": "$$\\eqalign{\n & (\\mathrm{I})\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(\\mathrm{II}) \\cr \n & > 2\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, < 2 \\cr} $$"}, {"identifier": "C", "content": "$$\\eqalign{\n & (\\mathrm{I})\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(\\mathrm{II}) \\cr \n & > 2\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, > 2 \\cr} $$"}, {"identifier": "D", "content": "$$\\eqalign{\n & (\\mathrm{I})\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(\\mathrm{II}) \\cr \n & < 2\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\, < 2 \\cr} $$"}]
|
["A"]
| null |
Structure of hydrogen azide is
<br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7u7y9cg/59d5fd4e-90bd-40d6-a67e-44e4d4638c4d/bdba1d00-3019-11ed-ab58-4f43f7f8c851/file-1l7u7y9ch.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7u7y9cg/59d5fd4e-90bd-40d6-a67e-44e4d4638c4d/bdba1d00-3019-11ed-ab58-4f43f7f8c851/file-1l7u7y9ch.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 182 English Explanation"><br>Bond order of bond I is less than 2 and Bond order of bond II is greater than 2.
|
mcq
|
jee-main-2018-online-15th-april-morning-slot
| 777
|
Q5p4VRyvV5jm4HGfqo7k9k2k5e068e6
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
Chlorine reacts with hot and concentrated NaOH and produces compounds (X) and (Y). Compound
(X) gives white precipitate with silver nitrate solution. The average bond order between CI and O
atoms in (Y) is.
|
[]
| null |
1.66to1.67
|
3Cl<sub>2</sub> + 6NaOH $$ \to $$ 5NaCl + NaClO<sub>3</sub> + 3H<sub>2</sub>O
<br><br>NaCl + AgNO<sub>3</sub> $$ \to $$ AgCl<sup>-</sup> $$ \downarrow $$ + NaNO<sub>3</sub>
<br><br>$$ \therefore $$ X = NaCl then Y = NaClO<sub>3</sub>
<br><br>Here in anion ClO<sub>3</sub><sup>-</sup> has bond between Cl and O atom.
<br><br>Bond order of Cl–O Bond = <span style="display: inline-block;vertical-align: middle;">
<div style="text-align: center;border-bottom: 1px solid black;">Total bond</div>
<div style="text-align: center;">Total resonating structure</div>
</span>.
<br><br>= $${5 \over 3}$$ = 1.67
|
integer
|
jee-main-2020-online-7th-january-morning-slot
| 778
|
upxFmVOuay2cBhvViHjgy2xukf9k2fko
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
The intermolecular potential energy for the
molecules A, B, C and D given below suggests
that :
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267082/exam_images/vhxznouask9fgfmemehc.webp"/><img 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"/></picture>
|
[{"identifier": "A", "content": "A-B has the stiffest bond"}, {"identifier": "B", "content": "A-D has the shortest bond length"}, {"identifier": "C", "content": "A-A has the largest bond enthalpy"}, {"identifier": "D", "content": "D is more electronegative than other atoms"}]
|
["A"]
| null |
From the given graph, potential energy of A-B molecule is minimum.
<br><br>Thus A-B bond is most stable as it
requires more energy to dissociate and have strongest bond amongst these.
<br><br>B = Most electronegative
<br><br>D = Least electronegative
<br><br>A - B = Shortest bond length
<br><br>A - B = Largest bond enthalpy
|
mcq
|
jee-main-2020-online-4th-september-morning-slot
| 780
|
VSvDRTNVr5I8GcIzWg1kmhskjjf
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
Given below are two statements : one is labeled as Assertion A and the other is labelled as Reason R :<br/><br/>Assertion A : The H$$-$$O$$-$$H bond angle in water molecule is 104.5$$^\circ$$.<br/><br/>Reason R : The lone pair - lone pair repulsion of electrons is higher than the bond pair - bond pair repulsion.<br/><br/>In the light of the above statements, choose the correct answer from the options given below :
|
[{"identifier": "A", "content": "Both A and R are true, and R is the correct explanation of A"}, {"identifier": "B", "content": "A is true but R is false"}, {"identifier": "C", "content": "A is false but R is true"}, {"identifier": "D", "content": "Both A and R are true, but R is not the correct explanation of A"}]
|
["A"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263756/exam_images/e4xxeb5kncycpevgt6jc.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 16th March Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 132 English Explanation"><br><br>
due to lp - lp repulsion bond angle decrease.
|
mcq
|
jee-main-2021-online-16th-march-morning-shift
| 781
|
1ldo0umhx
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
<p>$$\mathrm{O}-\mathrm{O}$$ bond length in $$\mathrm{H}_{2} \mathrm{O}_{2}$$ is $$\underline{\mathrm{X}}$$ than the $$\mathrm{O}-\mathrm{O}$$ bond length in $$\mathrm{F}_{2} \mathrm{O}_{2}$$. The $$\mathrm{O}-\mathrm{H}$$ bond length in $$\mathrm{H}_{2} \mathrm{O}_{2}$$ is $$\underline{Y}$$ than that of the $$\mathrm{O}-\mathrm{F}$$ bond in $$\mathrm{F}_{2} \mathrm{O}_{2}$$.</p>
<p>Choose the correct option for $$\underline{X}$$ and $$\underline{Y}$$ from those given below :</p>
|
[{"identifier": "A", "content": "$$\\mathrm{X}$$ - shorter, $$\\mathrm{Y}$$ - longer"}, {"identifier": "B", "content": "$$\\mathrm{X}$$ - longer, $$\\mathrm{Y}$$ - shorter"}, {"identifier": "C", "content": "$$\\mathrm{X}$$ - shorter, $$\\mathrm{Y}$$ - shorter"}, {"identifier": "D", "content": "$$\\mathrm{X}$$ - longer, $$\\mathrm{Y}$$ - longer"}]
|
["B"]
| null |
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.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-baqh{text-align:center;vertical-align:top}
.tg .tg-amwm{font-weight:bold;text-align:center;vertical-align:top}
</style>
<table class="tg">
<thead>
<tr>
<th class="tg-amwm">Bond</th>
<th class="tg-amwm">Bond Length</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-baqh">O - O</td>
<td class="tg-baqh">$1.48 \,\mathop A\limits^o\left(\text { In }{\mathrm{H}_2 \mathrm{O}_2}\right)$</td>
</tr>
<tr>
<td class="tg-baqh">O - O</td>
<td class="tg-baqh">$1.22 \,\mathop A\limits^o\left(\text { In }{\mathrm{O}_2 \mathrm{F}_2}\right)$</td>
</tr>
</tbody>
</table>
<br/>Thus, $\mathrm{O}-\mathrm{O}$ bond length in $\mathrm{H}_2 \mathrm{O}_2$ is longer than $\mathrm{O}-\mathrm{O}$ bond length in $\mathrm{O}_2 \mathrm{~F}_2$.
<br/><br/><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-baqh{text-align:center;vertical-align:top}
.tg .tg-amwm{font-weight:bold;text-align:center;vertical-align:top}
</style>
<table class="tg">
<thead>
<tr>
<th class="tg-amwm">Bond</th>
<th class="tg-amwm">Bond Length</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-baqh">O - F</td>
<td class="tg-baqh">$158 \,\mathrm{pm}\left(\text { In }{\mathrm{O}_2 \mathrm{F}_2}\right)$</td>
</tr>
<tr>
<td class="tg-baqh">O - H</td>
<td class="tg-baqh">$95 \,\mathrm{pm}\left(\text { In }{\mathrm{H}_2 \mathrm{O}_2}\right)$</td>
</tr>
</tbody>
</table>
<br/>Thus, the $\mathrm{O}-\mathrm{H}$ bond length in $\mathrm{H}_2 \mathrm{O}_2$ is shorter than $\mathrm{O}-\mathrm{F}$ bond length in $\mathrm{O}_2 \mathrm{~F}_2$.
|
mcq
|
jee-main-2023-online-1st-february-evening-shift
| 782
|
1ldr41fo8
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
<p>For $$\mathrm{OF}_{2}$$ molecule consider the following :</p>
<p>A. Number of lone pairs on oxygen is 2 .</p>
<p>B. FOF angle is less than $$104.5^{\circ}$$.</p>
<p>C. Oxidation state of $$\mathrm{O}$$ is $$-2$$.</p>
<p>D. Molecule is bent '$$\mathrm{V}$$' shaped.</p>
<p>E. Molecular geometry is linear.</p>
<p>correct options are:</p>
|
[{"identifier": "A", "content": "A, C, D only"}, {"identifier": "B", "content": "A, B, D only"}, {"identifier": "C", "content": "C, D, E only"}, {"identifier": "D", "content": "B, E, A only"}]
|
["B"]
| null |
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lepyowjc/b75f9e2e-81b7-4b8b-ac25-d0f4582815f4/e87a5430-b857-11ed-8195-4f3c56fa1eb5/file-1lepyowkz.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lepyowjc/b75f9e2e-81b7-4b8b-ac25-d0f4582815f4/e87a5430-b857-11ed-8195-4f3c56fa1eb5/file-1lepyowkz.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 77 English Explanation 1"></p>
<p>A : No. of lone pairs on oxygen = 2</p>
<p>B : <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lepyqlmw/80db52cf-4290-4aba-b6f0-e3591df33d7e/17a3d880-b858-11ed-8195-4f3c56fa1eb5/file-1lepyqlmx.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lepyqlmw/80db52cf-4290-4aba-b6f0-e3591df33d7e/17a3d880-b858-11ed-8195-4f3c56fa1eb5/file-1lepyqlmx.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 77 English Explanation 2"></p>
<p>($$\theta$$ < Bond angle in H$$_2$$O (104.5$$^\circ$$)</p>
<p>D : molecule is bent "v" shaped</p>
|
mcq
|
jee-main-2023-online-30th-january-morning-shift
| 783
|
1ldsrb3lq
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
<p>The bond dissociation energy is highest for</p>
|
[{"identifier": "A", "content": "Cl$$_2$$"}, {"identifier": "B", "content": "I$$_2$$"}, {"identifier": "C", "content": "Br$$_2$$"}, {"identifier": "D", "content": "F$$_2$$"}]
|
["A"]
| null |
Bond energy of $\mathrm{F}_{2}$ less than $\mathrm{Cl}_{2}$ due to lone pair lone pair repulsions.
<br/><br/>
Bond energy order $\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}_{2}$
|
mcq
|
jee-main-2023-online-29th-january-morning-shift
| 784
|
1lgp2tgig
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
<p>Given below are two statements :</p>
<p>Statement I : $$\mathrm{SO}_{2}$$ and $$\mathrm{H}_{2} \mathrm{O}$$ both possess V-shaped structure.</p>
<p>Statement II : The bond angle of $$\mathrm{SO}_{2}$$ is less than that of $$\mathrm{H}_{2} \mathrm{O}$$.</p>
<p>In the light of the above statements, choose the most appropriate answer from the options given below:</p>
|
[{"identifier": "A", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "B", "content": "Both Statement I and Statement II are correct"}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect"}, {"identifier": "D", "content": "Statement I is incorrect but Statement II is correct"}]
|
["C"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lgsm006a/ddbebe6c-5a07-4b21-b13c-30c1e7d3bc39/0f2e1c20-e165-11ed-95df-fb857d00bffe/file-1lgsm006b.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lgsm006a/ddbebe6c-5a07-4b21-b13c-30c1e7d3bc39/0f2e1c20-e165-11ed-95df-fb857d00bffe/file-1lgsm006b.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 13th April Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 65 English Explanation"><br><b>Statement I:</b> Both SO₂ and H₂O have a V-shaped (or bent) molecular structure. SO₂ has a central sulfur atom with two oxygen atoms and one lone pair, while H₂O has a central oxygen atom with two hydrogen atoms and two lone pairs. In both cases, the repulsion between the lone pairs and the bonded electron pairs leads to a V-shaped structure.
<br><br>
<b>Statement II:</b> The bond angle in H₂O is approximately 104.5° due to the tetrahedral arrangement of electron pairs (including the lone pairs) around the central oxygen atom. In SO₂, the bond angle is approximately 119°. The presence of a lone pair and the double bonds in SO₂ results in a different electron distribution, leading to a larger bond angle compared to H₂O.
|
mcq
|
jee-main-2023-online-13th-april-evening-shift
| 785
|
1lsgyis0f
|
chemistry
|
chemical-bonding-and-molecular-structure
|
bond-parameters
|
<p>Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).</p>
<p>Assertion (A) : There is a considerable increase in covalent radius from $$\mathrm{N}$$ to $$\mathrm{P}$$. However from As to Bi only a small increase in covalent radius is observed.</p>
<p>Reason (R) : Covalent and ionic radii in a particular oxidation state increases down the group. In the light of the above statements, choose the most appropriate answer from the options given below:</p>
|
[{"identifier": "A", "content": "(A) is false but (R) is true"}, {"identifier": "B", "content": "Both (A) and (R) are true and (R) is the correct explanation of (A)"}, {"identifier": "C", "content": "Both (A) and (R) are true but (R) is not the correct explanation of (A)"}, {"identifier": "D", "content": "(A) is true but (R) is false"}]
|
["C"]
| null |
<p>According to NCERT,</p>
<p>Statement-I : Factual data,</p>
<p>Statement-II is true.</p>
<p>But correct explanation is presence of completely filled $$d$$ and $$f$$-orbitals of heavier members</p>
|
mcq
|
jee-main-2024-online-30th-january-morning-shift
| 786
|
aUOtRsLU7g18b1R8
|
chemistry
|
chemical-bonding-and-molecular-structure
|
covalent-and-co-ordinate-bond
|
Which of the following compounds contain(s) no covalent bond(s)?
KCl, PH<sub>3</sub>, O<sub>2</sub>, B<sub>2</sub>H<sub>6</sub>, H<sub>2</sub>SO<sub>4</sub>
|
[{"identifier": "A", "content": "KCl, B<sub>2</sub>H<sub>6</sub>"}, {"identifier": "B", "content": "KCl, B<sub>2</sub>H<sub>6</sub>, PH<sub>3</sub>"}, {"identifier": "C", "content": "KCl, H<sub>2</sub>SO<sub>4</sub>"}, {"identifier": "D", "content": "KCl"}]
|
["D"]
| null |
Here only KCl is ionic compound all other compound has covalent bond.
|
mcq
|
jee-main-2018-offline
| 788
|
XWE0iO8fDLO3VWW534T2w
|
chemistry
|
chemical-bonding-and-molecular-structure
|
covalent-and-co-ordinate-bond
|
The covalent alkaline earth metal halide
(X = Cl, Br, I) is :
|
[{"identifier": "A", "content": "CaX<sub>2</sub>"}, {"identifier": "B", "content": "SrX<sub>2</sub>"}, {"identifier": "C", "content": "MgX<sub>2</sub>"}, {"identifier": "D", "content": "BeX<sub>2</sub>"}]
|
["D"]
| null |
According to Fajan’s rule, when the size of cation is less then the
covalent character would be more for the cation.
<br><br>Since Be<sup>2+</sup> has minimum size
among given cation, therefore, BeX<sub>2</sub> would be
most covalent among given alkaline with metal
halides
|
mcq
|
jee-main-2019-online-8th-april-evening-slot
| 789
|
1l6i4ejlq
|
chemistry
|
chemical-bonding-and-molecular-structure
|
covalent-and-co-ordinate-bond
|
<p>Arrange the following in increasing order of their covalent character.</p>
<p>A. $$\mathrm{CaF}_{2}$$</p>
<p>B. $$\mathrm{CaCl}_{2}$$</p>
<p>C. $$\mathrm{CaBr}_{2}$$</p>
<p>D. $$\mathrm{CaI}_{2}$$</p>
<p>Choose the correct answer from the options given below.</p>
|
[{"identifier": "A", "content": "B < A < C < D"}, {"identifier": "B", "content": "A < B < C < D"}, {"identifier": "C", "content": "A < B < D < C"}, {"identifier": "D", "content": "A < C < B < D"}]
|
["B"]
| null |
From Fajan's rule, for a given metal ion, as the size of anion increases, polarizability of anion increases and hence covalent character of the given ionic compound increases.
<br/><br/>
Hence, the increasing order of covalent character is $\mathrm{CaF}_{2}<\mathrm{CaCl}_{2}<\mathrm{CaBr}_{2}<\mathrm{Cal}_{2}$
|
mcq
|
jee-main-2022-online-26th-july-evening-shift
| 790
|
1l6jkbg8k
|
chemistry
|
chemical-bonding-and-molecular-structure
|
covalent-and-co-ordinate-bond
|
<p>Given below are two statements.</p>
<p>Statement I: $$\mathrm{O}_{2}, \mathrm{Cu}^{2+}$$, and $$\mathrm{Fe}^{3+}$$ are weakly attracted by magnetic field and are magnetized in the same direction as magnetic field.</p>
<p>Statement II: $$\mathrm{NaCl}$$ and $$\mathrm{H}_{2} \mathrm{O}$$ are weakly magnetized in opposite direction to magnetic field.</p>
<p>In the light of the above statements, choose the most appropriate answer from the options given below.</p>
|
[{"identifier": "A", "content": "Both Statement I and Statement II are correct."}, {"identifier": "B", "content": "Both Statement I and Statement II are incorrect."}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect."}, {"identifier": "D", "content": "Statement I is incorrect but Statement II is correct."}]
|
["A"]
| null |
$\mathrm{O}_{2}, \mathrm{Cu}^{2+}$ and $\mathrm{Fe}^{3+}$ have 2,1 and 5 unpaired electrons respectively, so these are the paramagnetic species. Hence, they are attracted by magnetic field.
<br/><br/>
$\mathrm{NaCl}$ and $\mathrm{H}_{2} \mathrm{O}$ are the diamagnetic species so they are repelled by the magnetic field.
|
mcq
|
jee-main-2022-online-27th-july-morning-shift
| 791
|
1ldygderb
|
chemistry
|
chemical-bonding-and-molecular-structure
|
covalent-and-co-ordinate-bond
|
<p>Order of Covalent bond;</p>
<p>$$\mathrm{A.~KF > KI ; LiF > KF}$$</p>
<p>$$\mathrm{B.~KF < KI ; LiF > KF}$$</p>
<p>$$\mathrm{C.~SnCl_4 > SnCl_2 ; CuCl > NaCl}$$</p>
<p>$$\mathrm{D.~LiF > KF ; CuCl < NaCl}$$</p>
<p>$$\mathrm{E.~KF < KI ; CuCl > NaCl}$$</p>
<p>Choose the correct answer from the options given below :</p>
|
[{"identifier": "A", "content": "B, C only"}, {"identifier": "B", "content": "A, B only"}, {"identifier": "C", "content": "C, E only"}, {"identifier": "D", "content": "B, C, E only"}]
|
["D"]
| null |
B is correct $\mathrm{KF}<\mathrm{KI}$; $\mathrm{LiF}>\mathrm{KF}$
<br/><br/>
$\mathrm{C}$ is correct $\underset{+4}{\mathrm{SnCl}_{4}}>\underset{+2}{\mathrm{SnCl}_{2}} ; \mathrm{CuCl}>\mathrm{NaCl}$
<br/><br/>
$\mathrm{E}$ is correct $\mathrm{KF}<\mathrm{KI}$; $\mathrm{CuCl}>\mathrm{NaCl}$
|
mcq
|
jee-main-2023-online-24th-january-morning-shift
| 792
|
lv7v49r8
|
chemistry
|
chemical-bonding-and-molecular-structure
|
covalent-and-co-ordinate-bond
|
<p>Number of $$\sigma$$ and $$\pi$$ bonds present in ethylene molecule is respectively :</p>
|
[{"identifier": "A", "content": "3 and 1\n"}, {"identifier": "B", "content": "5 and 1\n"}, {"identifier": "C", "content": "4 and 1\n"}, {"identifier": "D", "content": "5 and 2"}]
|
["B"]
| null |
<p>Let's analyze the bond structure in an ethylene molecule (C<sub>2</sub>H<sub>4</sub>) to determine the count of $$\sigma$$ and $$\pi$$ bonds.
</p>
<p>Ethylene consists of two carbon atoms double-bonded to each other, with each carbon atom also bonded to two hydrogen atoms. Each single bond is a $$\sigma$$ bond. The double bond between the carbon atoms is made up of one $$\sigma$$ bond and one $$\pi$$ bond. Here's how the bonds break down:</p>
<ol>
<li>Each carbon-hydrogen bond is a $$\sigma$$ bond. Since there are four C-H bonds, we have 4 $$\sigma$$ bonds from C-H bonding.</li>
<li>The carbon-carbon double bond consists of one $$\sigma$$ bond and one $$\pi$$ bond. Thus, we have 1 additional $$\sigma$$ bond from the C=C double bond.</li>
<li>Total $$\sigma$$ bonds = 4 (from C-H) + 1 (from C=C) = 5.</li>
<li>There is 1 $$\pi$$ bond present in the carbon-carbon double bond.</li>
</ol>
<p>Therefore, the correct option is:<br>
<p>Option B: 5 and 1</p></p>
|
mcq
|
jee-main-2024-online-5th-april-morning-shift
| 793
|
JJFWyBvJ5UgeAmFi
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
Which one of the following pairs of molecules will have permanent dipole moments for both members
|
[{"identifier": "A", "content": "NO<sub>2</sub> and CO<sub>2</sub>"}, {"identifier": "B", "content": "NO<sub>2</sub> and O<sub>3</sub>"}, {"identifier": "C", "content": "SiF<sub>4</sub> abd CO<sub>2</sub>"}, {"identifier": "D", "content": "SiF<sub>4</sub> abd NO<sub>2</sub>"}]
|
["B"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266045/exam_images/z11v85ub097vvh76c2gn.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 220 English Explanation 1">
<br>Here $$\mu $$<sub>total</sub> = $$\mu $$<sub>1</sub> + $$\mu $$<sub>2</sub> $$ \ne $$ 0
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266923/exam_images/aifsdddelolnxulo7req.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 220 English Explanation 2">
<br>$$\mu $$<sub>total</sub> = $$\mu $$<sub>1</sub> $$-$$ $$\mu $$<sub>2</sub> = 0
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264841/exam_images/bntxcqhlg8wpcqxsuhnx.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 220 English Explanation 3">
<br>$$\mu $$<sub>total</sub> = $$\mu $$<sub>1</sub> + $$\mu $$<sub>2</sub> $$ \ne $$ 0
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265759/exam_images/oepndi21uz0xgaduv1ul.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 220 English Explanation 4">
<br>$$\mu $$<sub>1</sub> + $$\mu $$<sub>2</sub> + $$\mu $$<sub>3</sub> = $$\mu $$<sub>4</sub>
<br><br> $$\mu $$<sub>total</sub> = 0
<br><br>In NO<sub>2</sub> and O<sub>3</sub> have permanent dipole moment as both of them are not symmetric molecule.
<br><br>In CO<sub>2</sub> and SiF<sub>4</sub> each individual bond c = O and S- $$-$$ F have dipole moment but because of symmetric structure individual dipole moment get's cancelled.
|
mcq
|
aieee-2003
| 794
|
J4tsIqf7yGQjgt3luQ7k9k2k5dzd7pc
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
The dipole of CCl<sub>4</sub>, CHCl<sub>3</sub> and CH<sub>4</sub> are in the order :
|
[{"identifier": "A", "content": "CCl<sub>4</sub> < CH<sub>4</sub> < CHCl<sub>3</sub>"}, {"identifier": "B", "content": "CH<sub>4</sub> = CCl<sub>4</sub> < CHCl<sub>3</sub>\n"}, {"identifier": "C", "content": "CH<sub>4</sub> < CCl<sub>4</sub> < CHCl<sub>3</sub>"}, {"identifier": "D", "content": "CHCl<sub>3</sub> < CH<sub>4</sub>= CCl<sub>4</sub>"}]
|
["B"]
| null |
CHCl<sub>3</sub> is polar while CH<sub>4</sub> and CCl<sub>4</sub> are nonpolar.
<br><br>So, dipole moment order is :
<br><br> CH<sub>4</sub> = CCl<sub>4</sub> < CHCl<sub>3</sub>
|
mcq
|
jee-main-2020-online-7th-january-morning-slot
| 795
|
1l59ri3lw
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Amongst BeF<sub>2</sub>, BF<sub>3</sub>, H<sub>2</sub>O, NH<sub>3</sub>, CCl<sub>4</sub> and HCl, the number of molecules with non-zero net dipole moment is ____________.</p>
|
[]
| null |
3
|
$\mathrm{BeF}_2, \mathrm{BF}_3$ and $\mathrm{CCl}_4 \Rightarrow \mu_{\mathrm{net}}=0$ <br/><br/>$\mathrm{H}_2 \mathrm{O}, \mathrm{NH}_3$ and $\mathrm{HCl} \Rightarrow \mu_{\mathrm{net}} \neq 0$
|
integer
|
jee-main-2022-online-25th-june-evening-shift
| 796
|
1ldu0xek7
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Statement I : Dipole moment is a vector quantity and by convention it is depicted by a small arrow with tail on the negative centre and head pointing towards the positive centre.</p>
<p>Statement II : The crossed arrow of the dipole moment symbolizes the direction of the shift of charges in the molecules.</p>
<p>In the light of the above statements, choose the most appropriate answer from the options given below :</p>
|
[{"identifier": "A", "content": "Statement I is correct but Statement II is incorrect"}, {"identifier": "B", "content": "Statement I is incorrect but Statement II is correct"}, {"identifier": "C", "content": "Both Statement I and Statement II are correct"}, {"identifier": "D", "content": "Both Statement I and Statement II are incorrect"}]
|
["B"]
| null |
The dipole moment is a vector quantity and is
depicted by an arrow with tail on the positive centre
and head pointing towards the negative centre. So,
Statement-I is incorrect.<br><br> The crossed arrow of the
dipole moment symbolizes the direction of the shift
of charges in the molecules. So, Statement-II is
correct.
<br><br>For example,
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lfhir5ak/bef2a348-5bc6-4420-b1b9-83b80f289fc8/86f105b0-c77f-11ed-ad62-0de788836124/file-1lfhir5al.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lfhir5ak/bef2a348-5bc6-4420-b1b9-83b80f289fc8/86f105b0-c77f-11ed-ad62-0de788836124/file-1lfhir5al.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 25th January Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 72 English Explanation">
|
mcq
|
jee-main-2023-online-25th-january-evening-shift
| 799
|
lgnzt580
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
Consider the following statements:
<br/><br/>
(A) NF<sub>3</sub> molecule has a trigonal planar structure.
<br/><br/>
(B) Bond length of $\mathrm{N}_{2}$ is shorter than $\mathrm{O}_{2}$.
<br/><br/>
(C) Isoelectronic molecules or ions have identical bond order.
<br/><br/>
(D) Dipole moment of $\mathrm{H}_{2}\mathrm{S}$ is higher than that of water molecule.
<br/><br/>
Choose the correct answer from the options given below:
|
[{"identifier": "A", "content": "(C) and (D) are correct"}, {"identifier": "B", "content": "(A) and (B) are correct"}, {"identifier": "C", "content": "(B) and (C) are correct"}, {"identifier": "D", "content": "(A) and (D) are correct\n"}]
|
["C"]
| null |
The correct answer is (B) and (C).
<br/><br/>
(A) NF<sub>3</sub> molecule has a trigonal pyramidal structure, not a trigonal planar structure. Therefore, statement (A) is false.
<br/><br/>
(B) The bond length of $\mathrm{N}_{2}$ is shorter than that of $\mathrm{O}_{2}$ due to the smaller atomic radius of nitrogen compared to oxygen. Therefore, statement (B) is true.
<br/><br/>
(C) Isoelectronic molecules or ions have the same number of electrons and hence the same bond order. Therefore, statement (C) is true.
<br/><br/>
(D) The dipole moment of water ($\mathrm{H}_{2}\mathrm{O}$) is higher than that of $\mathrm{H}_{2}\mathrm{S}$ due to the greater electronegativity of oxygen compared to sulfur. Therefore, statement (D) is false.
|
mcq
|
jee-main-2023-online-15th-april-morning-shift
| 800
|
jaoe38c1lsc5b7uk
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Choose the polar molecule from the following:</p>
|
[{"identifier": "A", "content": "$$\\mathrm{CCl}_4$$\n"}, {"identifier": "B", "content": "$$\\mathrm{CO}_2$$\n"}, {"identifier": "C", "content": "$$\\mathrm{CH}_2=\\mathrm{CH}_2$$\n"}, {"identifier": "D", "content": "$$\\mathrm{CHCl}_3$$"}]
|
["D"]
| null |
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lscvbo4p/8a37a3ab-5c10-46d0-80cc-caf15a53ab27/93e7c4a0-c64f-11ee-9d8b-f1be86a1b2f3/file-6y3zli1lscvbo4q.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lscvbo4p/8a37a3ab-5c10-46d0-80cc-caf15a53ab27/93e7c4a0-c64f-11ee-9d8b-f1be86a1b2f3/file-6y3zli1lscvbo4q.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 27th January Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 42 English Explanation"></p>
<p>$$\mu \neq 0$$</p>
<p>$$\mathrm{CHCl}_3$$ is polar molecule and rest all molecules are non-polar.</p>
|
mcq
|
jee-main-2024-online-27th-january-morning-shift
| 801
|
jaoe38c1lsda0qxg
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>A diatomic molecule has a dipole moment of $$1.2 \mathrm{~D}$$. If the bond distance is $$1 \mathrm{~A}^{\circ}$$, then fractional charge on each atom is _________ $$\times 10^{-1}$$ esu.</p>
<p>(Given $$1 \mathrm{~D}=10^{-18}$$ esucm)</p>
|
[]
| null |
0
|
<p>To find the fractional charge on each atom in a diatomic molecule, we can use the relationship between dipole moment (μ), charge (q), and distance (d):</p>
<p>$$ \mu = q \times d $$</p>
<p>Where:</p>
<ul>
<li>μ is the dipole moment.</li>
<br/><li>q is the magnitude of the charge on each atom.</li>
<br/><li>d is the distance between the charges.</li>
</ul>
<p>First, convert units to be consistent with esu:</p>
<ul>
<li>Bond distance in cm: $$ 1 \mathrm{~A}^{\circ} = 1 \times 10^{-8} \mathrm{~cm} $$</li>
<br/><li>Dipole moment in esu·cm: $$ 1.2 \mathrm{~D} = 1.2 \times 10^{-18} \mathrm{~esucm} $$</li>
</ul>
<p>We are given that the bond distance ($ d $) is $ 1 \mathrm{~A}^{\circ} $ and that the dipole moment $( \mu $) is $ 1.2 \mathrm{~D} $. Using these values, we can calculate the charge ($ q $) as follows:</p>
<p>$$ q = \frac{\mu}{d} $$</p>
<p>Now plug in the given values:</p>
<p>$$ q = \frac{1.2 \times 10^{-18} \mathrm{~esucm}}{1 \times 10^{-8} \mathrm{~cm}} $$</p>
<p>$$ q = 1.2 \times 10^{-10} \mathrm{~esu} $$</p>
<p>$$ q = 1.2 \times 10^{-9} \times 10^{-1} \mathrm{~esu} $$</p>
<p>$$ q = 0.000000012 \times 10^{-1} \mathrm{~esu} $$</p>
|
integer
|
jee-main-2024-online-31st-january-evening-shift
| 802
|
jaoe38c1lsfpfuqi
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>The total number of molecules with zero dipole moment among $$\mathrm{CH}_4, \mathrm{BF}_3, \mathrm{H}_2 \mathrm{O}, \mathrm{HF}, \mathrm{NH}_3, \mathrm{CO}_2$$ and $$\mathrm{SO}_2$$ is ________.</p>
|
[]
| null |
3
|
<p>Molecules with zero dipole moment $$=\mathrm{CO}_2, \mathrm{CH}_4, \mathrm{BF}_3$$</p>
|
integer
|
jee-main-2024-online-29th-january-evening-shift
| 803
|
1lsg7fij3
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Given below are two statements:</p>
<p>Statement - I: Since Fluorine is more electronegative than nitrogen, the net dipole moment of $$\mathrm{NF}_3$$ is greater than $$\mathrm{NH}_3$$.</p>
<p>Statement - II: In $$\mathrm{NH}_3$$, the orbital dipole due to lone pair and the dipole moment of $$\mathrm{NH}$$ bonds are in opposite direction, but in $$\mathrm{NF}_3$$ the orbital dipole due to lone pair and dipole moments of N-F bonds are in same direction.</p>
<p>In the light of the above statements, choose the most appropriate from the options given below:</p>
|
[{"identifier": "A", "content": "Statement I is true but Statement II is false.\n"}, {"identifier": "B", "content": "Both Statement I and Statement II are true.\n"}, {"identifier": "C", "content": "Both Statement I and Statement II are false.\n"}, {"identifier": "D", "content": "Statement I is false but Statement II is true."}]
|
["C"]
| null |
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lspvjcem/17b02273-0610-4df1-827c-98d0774820d2/99c36ae0-cd76-11ee-9be1-85ca54b9efcb/file-6y3zli1lspvjcen.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lspvjcem/17b02273-0610-4df1-827c-98d0774820d2/99c36ae0-cd76-11ee-9be1-85ca54b9efcb/file-6y3zli1lspvjcen.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 33 English Explanation"></p>
|
mcq
|
jee-main-2024-online-30th-january-evening-shift
| 804
|
lv0vyr14
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Which one of the following molecules has maximum dipole moment?</p>
|
[{"identifier": "A", "content": "$$\\mathrm{CH}_4$$\n"}, {"identifier": "B", "content": "$$\\mathrm{NF}_3$$\n"}, {"identifier": "C", "content": "$$\\mathrm{NH}_3$$\n"}, {"identifier": "D", "content": "$$\\mathrm{PF}_5$$"}]
|
["C"]
| null |
<p>$$\mathrm{NH}_3 \text { have more dipole moment than } \mathrm{NF}_3 \text {. }$$</p>
|
mcq
|
jee-main-2024-online-4th-april-morning-shift
| 805
|
lv2ertou
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Number of compounds / species from the following with non-zero dipole moment is _________.</p>
<p>$$\mathrm{BeCl}_2, \mathrm{BCl}_3, \mathrm{NF}_3, \mathrm{XeF}_4, \mathrm{CCl}_4, \mathrm{H}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{~S}, \mathrm{HBr}, \mathrm{CO}_2, \mathrm{H}_2, \mathrm{HCl}$$</p>
|
[]
| null |
5
|
<p>$$\mathrm{NF}_3, \mathrm{H}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{S}, \mathrm{HBr}, \mathrm{HCl}$$ have non zero dipole moments.</p>
|
integer
|
jee-main-2024-online-4th-april-evening-shift
| 806
|
lv9s2jkm
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).</p>
<p>Assertion (A) : $$\mathrm{NH}_3$$ and $$\mathrm{NF}_3$$ molecule have pyramidal shape with a lone pair of electrons on nitrogen atom. The resultant dipole moment of $$\mathrm{NH}_3$$ is greater than that of $$\mathrm{NF}_3$$.</p>
<p>Reason (R) : In $$\mathrm{NH}_3$$, the orbital dipole due to lone pair is in the same direction as the resultant dipole moment of the $$\mathrm{N}-\mathrm{H}$$ bonds. $$\mathrm{F}$$ is the most electronegative element.</p>
<p>In the light of the above statements, choose the correct answer from the options given below :</p>
|
[{"identifier": "A", "content": "(A) is false but (R) is true"}, {"identifier": "B", "content": "(A) is true but (R) is false"}, {"identifier": "C", "content": "Both (A) and (R) are true but (R) is NOT the correct explanation of (A)"}, {"identifier": "D", "content": "Both (A) and (R) are true and (R) is the correct explanation of (A)"}]
|
["D"]
| null |
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1lwf4zbgo/6dc6afa5-feb2-4a85-b646-70d4bbe32b1c/c683dd70-16bf-11ef-b04b-e5aed4adba7d/file-jaoe38c1lwf4zbgp.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/jaoe38c1lwf4zbgo/6dc6afa5-feb2-4a85-b646-70d4bbe32b1c/c683dd70-16bf-11ef-b04b-e5aed4adba7d/file-jaoe38c1lwf4zbgp.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 5th April Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 7 English Explanation"></p>
<p>Dipole moment of $$\mathrm{NH}_3$$ is higher than $$\mathrm{NF}_3$$ as $$\mu$$ of lone-pair is in same direction as the resultant dipole moment of $$\mathrm{N}-\mathrm{H}$$ bonds.
</p><p>So, both (A) & (R) are true, & (R) is the correct explanation of (A)</p>
|
mcq
|
jee-main-2024-online-5th-april-evening-shift
| 807
|
lv9s2skh
|
chemistry
|
chemical-bonding-and-molecular-structure
|
dipole-moment
|
<p>Number of compounds from the following with zero dipole moment is _________.</p>
<p>$$\mathrm{HF}, \mathrm{H}_2, \mathrm{H}_2 \mathrm{~S}, \mathrm{CO}_2, \mathrm{NH}_3, \mathrm{BF}_3, \mathrm{CH}_4, \mathrm{CHCl}_3, \mathrm{SiF}_4, \mathrm{H}_2 \mathrm{O}, \mathrm{BeF}_2$$</p>
|
[]
| null |
6
|
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lwf77qu6/70b40b08-a3ad-446b-8d2d-507f3fcc063a/831fbbe0-16c8-11ef-8b7b-e581310b9cf7/file-1lwf77qu7.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lwf77qu6/70b40b08-a3ad-446b-8d2d-507f3fcc063a/831fbbe0-16c8-11ef-8b7b-e581310b9cf7/file-1lwf77qu7.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline" alt="JEE Main 2024 (Online) 5th April Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 6 English Explanation"></p>
|
integer
|
jee-main-2024-online-5th-april-evening-shift
| 808
|
mpj6Sr9z39a6FjpW
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Hybridisation of underline atom changes in
|
[{"identifier": "A", "content": "$$\\underline {Al} {H_3}$$ changes to $$AlH_4^-$$"}, {"identifier": "B", "content": "$${H_2}\\underline O $$ changes to $$H_3O^+$$"}, {"identifier": "C", "content": "$$\\underline N {H_3}$$ changes to $$NH_4^+$$"}, {"identifier": "D", "content": "in all cases"}]
|
["A"]
| null |
(a) $$\,\,\,$$ AlH<sub>3</sub> + H<sup>$$-$$</sup> $$ \to $$ AlH$$_4^ - $$
<br><br>Steric number of AlH<sub>3</sub> is = $${1 \over 2}$$ [3 + 3] = 3
<br><br>$$\therefore\,\,\,$$ AlH<sub>3</sub> is sp<sup>2</sup> hybridized.
<br><br>Steric number of AlH$$_4^ - $$ = $${1 \over 2}$$ [3 + 4 +1] = 4
<br><br>$$\therefore\,\,\,$$ AlH$$_4^ - $$ is sp<sup>3</sup> hybridized.
<br><br>(b) $$\,\,\,$$ H<sub>2</sub>O + H<sup>+</sup> $$ \to $$ H<sub>3</sub>O<sup>+</sup>
<br><br>Steric no of H<sub>2</sub>O = $${1 \over 2}$$ (6+ 2) = 4
<br><br>$$\therefore\,\,\,\,$$ H<sub>2</sub>O s sp<sup>3</sup> hybridized.
<br><br>Steric no of H<sub>3</sub>O<sup>+</sup> = $${1 \over 2}$$ [ 8 + 3 $$-$$1] = 4
<br><br>$$\therefore\,\,\,$$ H<sub>3</sub>O<sup>+</sup> s also sp<sup>3</sup> hybridized.
<br><br>(c) $$\,\,\,$$ NH<sub>3</sub> + H<sup>+</sup> $$ \to $$ NH<sub>4</sub><sup>+</sup>
<br><br>Steric no of NH<sub>3</sub> = $${1 \over 2}$$ [5 + 3] = 4
<br><br>$$\therefore\,\,\,$$ hybridization of NH<sub>3</sub> is sp<sup>3</sup>
<br><br>Steric number of NH<sub>4</sub><sup>+</sup> = $${1 \over 2}$$ [5 + 4 $$-$$ ] = 4
<br><br>$$\therefore\,\,\,$$ Hybridization of NH<sub>4</sub><sup>+</sup> is sp<sup>3</sup>
|
mcq
|
aieee-2002
| 809
|
0Suq8v7ysInTEviK
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
In which of the following species is the underlined carbon having sp<sup>3</sup> hybridisation?
|
[{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs1idf/1791c77b-6d13-4c1c-afa8-b9d19d3f04a1/2cb52930-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1idg.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs1idf/1791c77b-6d13-4c1c-afa8-b9d19d3f04a1/2cb52930-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1idg.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Option 1\">"}, {"identifier": "B", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs1fo1/597e1cf5-6e2b-4f1f-b555-44e8ba6d831f/2a9e3010-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1fo2.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs1fo1/597e1cf5-6e2b-4f1f-b555-44e8ba6d831f/2a9e3010-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1fo2.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Option 2\">"}, {"identifier": "C", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs1d69/dba0d8c7-b9c9-4f0f-8959-b1f32a144e42/28b10610-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1d6a.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs1d69/dba0d8c7-b9c9-4f0f-8959-b1f32a144e42/28b10610-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1d6a.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Option 3\">"}, {"identifier": "D", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs1amk/5033664e-6db0-4219-aaa3-63df9e127d78/26b954c0-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1aml.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs1amk/5033664e-6db0-4219-aaa3-63df9e127d78/26b954c0-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs1aml.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Option 4\">"}]
|
["B"]
| null |
<br><br>(a) $$\,\,\,\,$$ <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264975/exam_images/xcldci9y1mcguxtcjkdk.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Explanation 1">
<br><br>(b) $$\,\,\,\,$$ <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265508/exam_images/dyp9hqxjsxauvuklsbb3.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Explanation 2">
<br><br>(c) $$\,\,\,\,$$ <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266811/exam_images/gojo2hjbo3ysxxzssi8x.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Explanation 3">
<br><br>(d) $$\,\,\,\,$$ <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265011/exam_images/ndmn7oksxuxuljxbabp6.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 192 English Explanation 4">
<br><br>So, option (B) is correct
<br><br><b><u>Note</u> : </b>
<br>If in carbon(C) all 4 bonds are sigma bond then it is sp<sup>3</sup> hybridization and if there is 3 sigma bond then sp<sup>2</sup> and if there is only 2 sigma bond there sp hybridization.
|
mcq
|
aieee-2002
| 810
|
gm5x4qpYa6KEna62
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
A square planar complex is formed by hybridisation of which atomic orbitals ?
|
[{"identifier": "A", "content": "s, p<sub>x</sub>, p<sub>y</sub>, d<sub>xy</sub>"}, {"identifier": "B", "content": "s, p<sub>x</sub>, p<sub>y</sub>, d<sub>x<sup>2</sup> - y<sup>2</sup></sub>"}, {"identifier": "C", "content": "s, p<sub>x</sub>, p<sub>y</sub>, d<sub>z<sup>2</sup></sub>"}, {"identifier": "D", "content": "s, p<sub>x</sub>, p<sub>y</sub>, d<sub>yz</sub>"}]
|
["B"]
| null |
Hybridization of square planar complex is dsp<sup>2</sup> .
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265664/exam_images/cvgzlwaqivdtqrw22dgz.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 190 English Explanation 1">
<br><br>In square planar complex all 4 surrounding atoms and central atom are in the same plane and let this plane is x $$-$$ y plane. As it is dsp<sup>2</sup> hybridized, so it has 1 d orbital, 1 s orbital and 2 p orbital.
<br><br>s orbital is non-directional, so we just write it as s.
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264584/exam_images/ccwkblveutwldmmbivlf.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 190 English Explanation 2">
<br><br>In p<sub>x</sub> the two lobes are along x-axis and in p<sub>y</sub> two lobes are along y-axis
<br><br>One d orbital is d<sub>x<sup>2</sup> $$-$$ y<sup>2</sup></sub>, it means out of four lobes of d orbital two along x-axis and two along y-axis.
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266231/exam_images/pu8w7vscrj4gnimolmi5.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Chemical Bonding & Molecular Structure Question 190 English Explanation 3">
|
mcq
|
aieee-2002
| 811
|
xcsm0nql60z3oXg7
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The pair of species having identical shapes for molecules of both species is
|
[{"identifier": "A", "content": "XeF<sub>2</sub>, CO<sub>2</sub>"}, {"identifier": "B", "content": "BF<sub>3</sub>, PCl<sub>3</sub>"}, {"identifier": "C", "content": "PF<sub>5</sub>, IF<sub>5</sub>"}, {"identifier": "D", "content": "CF<sub>4</sub>, SF<sub>4</sub>"}]
|
["A"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264535/exam_images/h9htvtwrpabm0iitdah6.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 218 English Explanation 1">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263283/exam_images/e2onju4tfynm5shcxeuq.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 218 English Explanation 2">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265944/exam_images/f9lfgjos4feds6tfz501.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 218 English Explanation 3">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266198/exam_images/qdumnmmqedko8j2ugv31.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 218 English Explanation 4">
|
mcq
|
aieee-2003
| 813
|
f9uqujHVgoME8wvM
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Which one of the following compounds has the smallest bond angle in its molecule?
|
[{"identifier": "A", "content": "OH<sub>2</sub>"}, {"identifier": "B", "content": "SH<sub>2</sub>"}, {"identifier": "C", "content": "NH<sub>3</sub>"}, {"identifier": "D", "content": "SO<sub>2</sub>"}]
|
["B"]
| null |
(a) H<sub>2</sub>O is sp<sup>3</sup> hybridized, and oxygen atom has 2 bond pair and 2 lone pair. So the angle between two O $$-$$ H bond is 104.5<sup>o</sup>
<br><br>(b) In H<sub>2</sub>S molecule, central atom S is a 3rd period element and according to Dragos rule, when a 3rd period or higher period element overlap with a small element whose electronegetivity is low then that over lapping cannot be a effective overlapping, because of higher size of 3rd or higher periods element and smaller size of low electronegative element.
<br><br>Here in H<sub>2</sub>S, H atom has very low electronegativity and smaller in size so it create more negative charge around sulphur(s) atom and size of S<sup>$$-$$2</sup> ion increases, because of this higher size difference efficiency overlapping is not possible. So, any hybridization do not happen in between S and H atom. Lone pair electrons of S atom is present in the pure orbital like s, p<sub>x</sub>, p<sub>y</sub>, p<sub>z</sub> and it look like this :
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263399/exam_images/i79hzr33uomve2k7wepw.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 219 English Explanation 1">
<br><br>As we know the angle between and p<sub>y</sub> is 90<sup>o</sup>, so bond angle is 90<sup>o</sup>.
<br><br>(c) NH<sub>3</sub> has sp<sup>3</sup> hybridization and N atom has 3 bond pair and one lone pair so bond angle is 107<sup>o</sup>
<br><br>(d) SO<sub>2</sub> is sp<sup>2</sup> hybridized and bond angle is 117<sup>o</sup>.
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266120/exam_images/lbdanv3any5pupghsvuw.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2003 Chemistry - Chemical Bonding & Molecular Structure Question 219 English Explanation 2">
|
mcq
|
aieee-2003
| 814
|
KxDI6IEJbr7AahXR
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The states of hybridization of boron and oxygen atoms in boric acid (H<sub>3</sub>BO<sub>3</sub>) are respectively
|
[{"identifier": "A", "content": "sp<sup>2</sup> and sp<sup>2</sup>\n "}, {"identifier": "B", "content": "sp<sup>3</sup> and sp<sup>3</sup>"}, {"identifier": "C", "content": "sp<sup>3</sup> and sp<sup>2</sup>"}, {"identifier": "D", "content": "sp<sup>2</sup> and sp<sup>3</sup>\n "}]
|
["D"]
| null |
Structure of H<sub>3</sub>BO<sub>3</sub> is
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263708/exam_images/bvr2mjvci5q3lgksjutl.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 215 English Explanation">
<br><br>Here Boron has 3 sigma bond. So it is sp<sup>2</sup> hybridised.
<br><br>And oxygen has two sigma bond and two lone pair. So it sp<sup>3</sup> hybridised.
|
mcq
|
aieee-2004
| 815
|
5urq95W4yMPfUd4T
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Which one of the following has the regular tetrahedral structure? <br/>
(Atomic nos : B = 5, S = 16, Ni = 28, Xe = 54)
|
[{"identifier": "A", "content": "XeF<sub>4</sub>"}, {"identifier": "B", "content": "[Ni(CN)<sub>4</sub>]<sup>2- </sup>"}, {"identifier": "C", "content": "$$BF_4^-$$"}, {"identifier": "D", "content": "SF<sub>4</sub>"}]
|
["C"]
| null |
Regular Tetrahedral structure is possible in sp<sup>3</sup> hybridization where central atom has 4 bond pair and no lone pair.
<br><br>(a) XeF<sub>4</sub> is sp<sup>3</sup>d<sup>2</sup> hybridised and structure is square planar.
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264255/exam_images/pyrwkkkosv1muxq7bcmw.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 214 English Explanation 1">
<br><br>(b) [Ni(CN)<sub>4</sub><sub></sub>]<sup>$$-$$2</sup> is coordinate compound and oxidation number of Ni is +2.
<br><br>Electronic configuration of Ni<sup>+2</sup> is $$=$$ [Ar]3d<sup>8</sup>
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264394/exam_images/vrsgrn90wnv2pzcp8c6l.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 214 English Explanation 2">
<br><br>But because of CN<sup>$$-$$</sup> ion which is a strong field ligand , it can perform pairing of electron.
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267347/exam_images/nfb8a2e2kczpv35bodtj.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 214 English Explanation 3">
<br><br>And the structure of dsp<sup>2</sup> hybridization is square planar.
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264703/exam_images/peselxahv5tllop7vpc3.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 214 English Explanation 4">
<br><br>(C) $$\,\,\,\,$$ BF$$_4^ - $$, 4 bond pair present so angle is 109<sup>o</sup> 28<sup>'</sup> and sp<sup>3</sup> hybridised. So structure is regular tetrahedral.
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267054/exam_images/jzkitnrboscu5illespj.webp" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 214 English Explanation 5">
<br><br>(d) <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266207/exam_images/alxbz0wrpowuvob980ot.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2004 Chemistry - Chemical Bonding & Molecular Structure Question 214 English Explanation 6">
<br><br>SF<sub>4</sub> is sp<sup>3</sup>d hybridised and structure is see-saw.
|
mcq
|
aieee-2004
| 816
|
UwJG6rOuj439QRBl
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The decreasing values of bond angles from NH<sub>3</sub> (106<sup>o</sup>) to SbH<sub>3</sub> (91<sup>o</sup>
) down group-15 of the periodic table is due to
|
[{"identifier": "A", "content": "increasing bp-bp repulsion"}, {"identifier": "B", "content": "increasing p-orbital character in sp<sup>3</sup>"}, {"identifier": "C", "content": "decreasing lp-bp repulsion"}, {"identifier": "D", "content": "decreasing electronegativity "}]
|
["C"]
| null |
Nitrogen(N) atom is smaller in size so it's lone pair is relatively unstable. That is why repulsion between lone pairs present on nitrogen atom and bonded pairs of electrons is relatively high.
<br><br>But size of Sb is more so its lone pair is relatively stable. That is why it does not want to perticipate in bond pair lone pair repulsion and decreases lp-bp repulsion.
|
mcq
|
aieee-2006
| 819
|
9GahDMGK1F3fXjfs
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The hybridization of orbitals of N atom in $$NO_3^-$$, $$NO_2^+$$ and $$NH_4^+$$ are respectively :
|
[{"identifier": "A", "content": "sp , sp<sup>2</sup>, sp<sup>3</sup>"}, {"identifier": "B", "content": "sp<sup>2</sup>, sp , sp<sup>3</sup>"}, {"identifier": "C", "content": "sp , sp<sup>3</sup>, sp<sup>2</sup>"}, {"identifier": "D", "content": "sp<sup>2</sup>, sp<sup>3</sup>, sp "}]
|
["B"]
| null |
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266431/exam_images/ag1cw5twoviafdn5jb7p.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264986/exam_images/hpcqpggqujqxzx4kirek.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264343/exam_images/fwioi08oj6fdn6irigkc.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2011 Chemistry - Chemical Bonding & Molecular Structure Question 200 English Explanation 1"></picture>
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264673/exam_images/psly1ryvxeemtxjlyfpk.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264059/exam_images/xunlowd1ftmnusdy1crt.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267527/exam_images/tdc7raq1likttnsr48qu.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2011 Chemistry - Chemical Bonding & Molecular Structure Question 200 English Explanation 2"></picture>
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265441/exam_images/vtlg0tjhbxtzvo0mhlcp.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266276/exam_images/mnb4tyrnc838ug9b4b7b.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264722/exam_images/gt1mlsl29kdbjo97k2t6.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2011 Chemistry - Chemical Bonding & Molecular Structure Question 200 English Explanation 3"></picture>
|
mcq
|
aieee-2011
| 820
|
KElf6QK1sAhJKW8C
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The structure of IF<sub>7</sub> is :
|
[{"identifier": "A", "content": "trigonal bipyramid"}, {"identifier": "B", "content": "octahedral"}, {"identifier": "C", "content": "pentagonal bipyramid"}, {"identifier": "D", "content": "square pyramid"}]
|
["C"]
| null |
The structure of IF<sub>7</sub> pentagonal bipyramidal having
sp<sup>3</sup>d<sup>3</sup>
hybridisation.
<br><picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264868/exam_images/pdoqynnk42zurygod6y3.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264930/exam_images/kr8cla2qktdupwy9nuro.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267533/exam_images/yfx8hvpj0djlpe2jyyqb.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="AIEEE 2011 Chemistry - Chemical Bonding & Molecular Structure Question 199 English Explanation"></picture>
|
mcq
|
aieee-2011
| 821
|
ubhEmYxLSYmZXGqc
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
In which of the following pairs the two species are not isostructural ?
|
[{"identifier": "A", "content": "$$CO_3^{2-}$$ and $$NO_3^-$$"}, {"identifier": "B", "content": "$$PCl_4^{+}$$ and $$SiCl_4$$"}, {"identifier": "C", "content": "PF<sub>5</sub> and BrF<sub>5</sub>"}, {"identifier": "D", "content": "$$AlF_6^-$$ and $$SF_6$$"}]
|
["C"]
| null |
PF<sub>5</sub>
$$ \Rightarrow $$ sp<sup>3</sup>d hybridized and shape is trigonal bipyramidal.
<br><br>BrF<sub>5</sub> $$ \Rightarrow $$ 5 bond pair and 1 lone pair present so sp<sup>3</sup>d<sup>2</sup> hybridized and shape is square pyramidal.
|
mcq
|
aieee-2012
| 822
|
vqAPe6uexarsrvlAJ7vIJ
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The group of molecules having identical shape is :
|
[{"identifier": "A", "content": "SF<sub>4</sub> , XeF<sub>4</sub> , CCl<sub>4</sub>"}, {"identifier": "B", "content": "ClF<sub>3</sub> , XeOF<sub>2</sub> , XeF$$_3^ + $$"}, {"identifier": "C", "content": "BF<sub>3</sub> , PCl<sub>3</sub> , XeO<sub>3</sub>"}, {"identifier": "D", "content": "PCl<sub>5</sub> , IF<sub>5</sub> , XeO<sub>2</sub>F<sub>2</sub>"}]
|
["B"]
| null |
H = $${1 \over 2}$$[VE + MA – c + a]
<br><br>ClF<sub>3</sub>
, H =
$${1 \over 2}$$
(7 + 3 – 0 + 0) = 5 (sp<sup>3</sup>d)
<br><br>XeOF<sub>2</sub>
, H = $${1 \over 2}$$(8 + 2 – 0 + 0) = 5 (sp<sup>3</sup>d)
<br><br>XeF<sub>3</sub><sup>+</sup>
, H =
$${1 \over 2}$$
(8 + 3 – 1 + 0 ) = 5 (sp<sup>3</sup>d)
<br><br>All molecules have sp<sup>3</sup>d hybridization and 3 bond pair + 2 lone pairs. Hence all have identical stucture (T-shape).
|
mcq
|
jee-main-2016-online-9th-april-morning-slot
| 823
|
l86jb8sy
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The species in which the $\mathrm{N}$ atom is in a state of $s p$ hybridization is :
|
[{"identifier": "A", "content": "$\\mathrm{NO}_2^{+}$"}, {"identifier": "B", "content": "$\\mathrm{NO}_2^{-}$\n"}, {"identifier": "C", "content": "$\\mathrm{NO}_3^{-}$\n"}, {"identifier": "D", "content": "$\\mathrm{NO}_3^{-}$"}]
|
["A"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l86jawng/e743a55b-f683-49b3-a376-bbafdf022476/89a767d0-36df-11ed-a9f0-f56124f74cf4/file-1l86jawnh.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l86jawng/e743a55b-f683-49b3-a376-bbafdf022476/89a767d0-36df-11ed-a9f0-f56124f74cf4/file-1l86jawnh.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 70vh" alt="JEE Main 2016 (Offline) Chemistry - Chemical Bonding & Molecular Structure Question 82 English Explanation">
|
mcq
|
jee-main-2016-offline
| 824
|
wJuktyJ7ppW8x7QwGSrdn
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
sp<sup>3</sup>d<sup>2</sup> hybridization is <b>not</b> displayed by :
|
[{"identifier": "A", "content": "BrF<sub>5</sub>"}, {"identifier": "B", "content": "SF<sub>6</sub>"}, {"identifier": "C", "content": "[CrF<sub>6</sub>]<sup>3$$-$$</sup>"}, {"identifier": "D", "content": "PF<sub>5</sub>"}]
|
["D"]
| null |
Hybridization (X) = $${1 \over 2}$$ [ VE + MA – c + a ]
<br><br>where, VE = No. of valence electrons of central atom
<br>MA = No. of monovalent atoms/groups surrounding the central
atom,
<br>c = Charge on the cation,
<br>a = Charge on the anion
<br><br>(A) [BrF<sub>5</sub>] : X = $${1 \over 2}$$[ 7 + 5 - 0 + 0] = 6 = sp<sup>3</sup>d<sup>2</sup> hybridized
<br><br>(B) [SF<sub>6</sub>] : X = $${1 \over 2}$$[ 6 + 6 - 0 + 0] = 6 = sp<sup>3</sup>d<sup>2</sup> hybridized
<br><br>(C) [CrF<sub>6</sub>]<sup>3$$-$$</sup> : Cr<sup>+3</sup> = [Ar]3d<sup>3</sup>
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264623/exam_images/ed4ci4lnzwdqy0mmubkw.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266889/exam_images/tgkqnzowpqo3j66lclsu.webp"><source media="(max-width: 680px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265049/exam_images/koliovjt5msi50pe6g7r.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263343/exam_images/uwgnwaiqfanwybbqj1hr.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2017 (Online) 8th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 177 English Explanation"></picture>
<br><br>(D) [PF<sub>5</sub>] : X = $${1 \over 2}$$[ 5 + 5 - 0 + 0] = 5 = sp<sup>3</sup>d hybridized
<br><br><b>Note :</b> [CrF<sub>6</sub>]<sup>3$$-$$</sup> shows d<sup>2</sup>sp<sup>3</sup> hybridization not sp<sup>3</sup>d<sup>2</sup>. So option (C) should also be the correct answer.
|
mcq
|
jee-main-2017-online-8th-april-morning-slot
| 825
|
RNVhXFNTgCG2USg2qReSo
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The group having triangular planar structures is :
|
[{"identifier": "A", "content": "BF<sub>3</sub>, NF<sub>3</sub>, $$CO_3^{2 - }$$"}, {"identifier": "B", "content": "$$CO_3^{2 - }$$, $$NO_3^ - $$, SO<sub>3</sub>"}, {"identifier": "C", "content": "NH<sub>3</sub>, SO<sub>3</sub>, $$CO_3^{2 - }$$"}, {"identifier": "D", "content": "NCl<sub>3</sub>, BCl<sub>3</sub>, SO<sub>3</sub>"}]
|
["B"]
| null |
(A) BF<sub>3</sub> : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>NF<sub>3</sub> : sp<sup>3</sup> Hybridization : Tetrahedral
<br><br>$$CO_3^{2 - }$$ : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>(B) $$CO_3^{2 - }$$ : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>$$NO_3^ - $$ : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>SO<sub>3</sub> : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>(C) NH<sub>3</sub> : sp<sup>3</sup> Hybridization : Tetrahedral
<br><br>SO<sub>3</sub> : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>$$CO_3^{2 - }$$ : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>(D) NCl<sub>3</sub> : sp<sup>3</sup> Hybridization : Tetrahedral
<br><br>BCl<sub>3</sub> : sp<sup>2</sup> Hybridization : Triangular Planar
<br><br>SO<sub>3</sub> : sp<sup>2</sup> Hybridization : Triangular Planar
|
mcq
|
jee-main-2017-online-9th-april-morning-slot
| 826
|
Q1FlgwO0fiKugPkd7zZYg
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The <b>incorrect</b> geometry is represented by :
|
[{"identifier": "A", "content": "BF<sub>3</sub> - trigonal planar"}, {"identifier": "B", "content": "H<sub>2</sub>O - bent"}, {"identifier": "C", "content": "NF<sub>3</sub> - trigonal planar "}, {"identifier": "D", "content": "AsF<sub>5</sub> - trigonal bipyramidal "}]
|
["C"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267404/exam_images/rffnwwheova2wzrcp1ed.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 16th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 180 English Explanation">
<br><br>NF3 has trigonal pyramidal geometry. Here central atom nitrogen has sp<sup>3</sup> hybridization and one lone pair of electron. Because of lone pair there exist repulsion force between lone pair and bond pair of electrons, that is why bond angles are lower than tetrahedral bond angle.
|
mcq
|
jee-main-2018-online-16th-april-morning-slot
| 827
|
mH7bhHWLOeDctdqbPfpd6
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Identify the pair in which the geometry of the species is $$T$$-shape and square - pyraidal, respectively :
|
[{"identifier": "A", "content": "ClF<sub>3</sub> and $$I{O_4}^ - $$ "}, {"identifier": "B", "content": "ICl<sub>2</sub><sup>-</sup> and ICl<sub>5</sub>"}, {"identifier": "C", "content": "XeOF<sub>2</sub> and XeOF<sub>4</sub>"}, {"identifier": "D", "content": "IO<sub>3</sub><sup>-</sup> and IO<sub>2</sub>F<sub>2</sub><sup>-</sup>"}]
|
["C"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263817/exam_images/yz2vnobmd4gdky6l6cp8.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 184 English Explanation 1">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264356/exam_images/ildet5xusjp1rebry8ix.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 184 English Explanation 2">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265227/exam_images/bv1dbrqaljsr3pky2nxy.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 184 English Explanation 3">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266078/exam_images/wcx7tioayfp0y808ziow.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 184 English Explanation 4">
|
mcq
|
jee-main-2018-online-15th-april-morning-slot
| 829
|
RrllQEe4krGwgmj9
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Total number of lone pair of electrons in $${\rm I}_3^ - $$ ion is
|
[{"identifier": "A", "content": "3"}, {"identifier": "B", "content": "9"}, {"identifier": "C", "content": "6"}, {"identifier": "D", "content": "12"}]
|
["B"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264784/exam_images/ox9u4d9vskfpz0ze0tkp.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Offline) Chemistry - Chemical Bonding & Molecular Structure Question 187 English Explanation">
<br><br>$$\therefore\,\,\,$$ Total number of lone pair = 9
|
mcq
|
jee-main-2018-offline
| 830
|
JQtM1Iubq2JHnySXbobVJ
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The decreasing order of bond angles in BF<sub>3</sub>, NH<sub>3</sub>, PF<sub>3</sub> and I<sub>3</sub><sup>-</sup> is :
|
[{"identifier": "A", "content": "I<sub>3</sub><sup>-</sup> > NH<sub>3</sub> > PF<sub>3</sub> > BF<sub>3</sub>"}, {"identifier": "B", "content": "I<sub>3</sub><sup>-</sup> > BF<sub>3</sub> > NH<sub>3</sub> > PF<sub>3</sub>"}, {"identifier": "C", "content": "BF<sub>3</sub> > I<sub>3</sub><sup>-</sup> > PF<sub>3</sub> > NH<sub>3</sub>"}, {"identifier": "D", "content": "BF<sub>3</sub> > NH<sub>3</sub> > PF<sub>3</sub> > I<sub>3</sub><sup>-</sup>"}]
|
["B"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267161/exam_images/u5mnojkykht9vo9kznqu.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 183 English Explanation 1">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266260/exam_images/zzsct06yvgtznbapbwdy.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 183 English Explanation 2">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267551/exam_images/zisebgzmtsegnuaqgtxb.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 183 English Explanation 3">
<br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263365/exam_images/h71uy5re0z4wx0olnhwz.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 15th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 183 English Explanation 4">
|
mcq
|
jee-main-2018-online-15th-april-morning-slot
| 831
|
xrxSs5Zo7exG8RTfiTO76
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The ion that has sp<sup>3</sup>d<sup>2</sup> hybridization for the
central atom, is :
|
[{"identifier": "A", "content": "[ICl<sub>2</sub>]<sup>-</sup>"}, {"identifier": "B", "content": "[ICl<sub>4</sub>]<sup>-</sup>"}, {"identifier": "C", "content": "[IF<sub>6</sub>]<sup>-</sup>"}, {"identifier": "D", "content": "[BrF<sub>2</sub>]<sup>-</sup>"}]
|
["B"]
| null |
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266883/exam_images/rdp8joexq2x1okn4mokl.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263950/exam_images/siqh94apkvnbynd6mu74.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267065/exam_images/fahvisurqjiirr7xphp6.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 168 English Explanation"></picture>
|
mcq
|
jee-main-2019-online-8th-april-evening-slot
| 833
|
oAa6YvGMfJQ4vKQf77p3L
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The correct statement about ICl<sub>5</sub> and $$ICl_4^-$$ is
|
[{"identifier": "A", "content": "ICl<sub>5</sub> is square pyramidal and $$ICl_4^-$$ is square\nplanar."}, {"identifier": "B", "content": "ICl<sub>5</sub> is trigonal bipyramidal and is\ntetrahedral."}, {"identifier": "C", "content": "ICl<sub>5</sub> is square pyramidal and $$ICl_4^-$$ is\ntetrahedral"}, {"identifier": "D", "content": "Both are isostructural."}]
|
["A"]
| null |
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263377/exam_images/bbz8sl4mqz6lwrqbmndf.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264597/exam_images/ugtmhdptrsxg6qlk5vo1.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266324/exam_images/cfwpm8gzkp4gjtocgi7e.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 165 English Explanation"></picture>
|
mcq
|
jee-main-2019-online-8th-april-evening-slot
| 834
|
vLMXNDzSRUPPkXYgDM3rsa0w2w9jwwe7xj7
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The oxoacid of sulphur that does not contain bond between sulphur atoms is
|
[{"identifier": "A", "content": "H<sub>2</sub>S<sub>2</sub>O<sub>7</sub>"}, {"identifier": "B", "content": "H<sub>2</sub>S<sub>2</sub>O<sub>3</sub>"}, {"identifier": "C", "content": "H<sub>2</sub>S<sub>4</sub>O<sub>6</sub>"}, {"identifier": "D", "content": "H<sub>2</sub>S<sub>2</sub>O<sub>4</sub>"}]
|
["A"]
| null |
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263301/exam_images/rs4lzjuqxatk4vmfb6o9.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264283/exam_images/gyoazye20bmyt1qyabck.webp"><source media="(max-width: 680px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267292/exam_images/cagn8kez9nmtn9wdnjtm.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265387/exam_images/icobxapkfloaugx3byyk.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 10th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 160 English Explanation"></picture>
<br><br>Here you can see, H<sub>2</sub>S<sub>2</sub>O<sub>7</sub> does not have S – S linkage.
|
mcq
|
jee-main-2019-online-10th-april-morning-slot
| 835
|
CZw8iRqaJAkptjk3dB3rsa0w2w9jx56xgdk
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The correct statement among the following is :
|
[{"identifier": "A", "content": "(SiH<sub>3</sub>)<sub>3</sub>N is planar and more basic than (CH<sub>3</sub>)<sub>3</sub>N"}, {"identifier": "B", "content": "(SiH<sub>3</sub>)<sub>3</sub>N is pyramidal and more basic than (CH<sub>3</sub>)<sub>3</sub>N"}, {"identifier": "C", "content": "(SiH<sub>3</sub>)<sub>3</sub>N is pyramidal and less basic than (CH<sub>3</sub>)<sub>3</sub>N"}, {"identifier": "D", "content": "(SiH<sub>3</sub>)<sub>3</sub>N is planar and less basic than (CH<sub>3</sub>)<sub>3</sub>N"}]
|
["D"]
| null |
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264376/exam_images/obdcfybfvcetetsqaz23.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266171/exam_images/sqvqhnwdqovtcwtrkaok.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 159 English Explanation 1"></picture>
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266666/exam_images/wjjcd14e47o3u2cowyd9.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265114/exam_images/k7o8xh6ervtl39tizpvf.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 159 English Explanation 2"></picture>
<br>In (CH<sub>3</sub>)<sub>3</sub>N, one lone pair and 3 sigma bond present. So it's shape is pyramidal.
<br><br>But in (SiH<sub>3</sub>)<sub>3</sub>N, due to backbonding lone pair of N shift to vacant 3d orbital of Si. So now N have only 3 sigma bond and hybridization is sp<sup>2</sup>, that is why it has triangular planar geometry.
<br><br>As in (SiH<sub>3</sub>)<sub>3</sub>N. nitrogen(N) don't have any lone pair to donate but in (CH<sub>3</sub>)<sub>3</sub>N, lone pair of nitrogen(N) can easily be donated. That is why (CH<sub>3</sub>)<sub>3</sub>N is more basic.
|
mcq
|
jee-main-2019-online-12th-april-morning-slot
| 836
|
qq20iRhwJH3Mt3t8PXjgy2xukfoup9d3
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The compound that has the largest H–M–H bond angle (M = N, O, S, C) is :
|
[{"identifier": "A", "content": "CH<sub>4</sub>"}, {"identifier": "B", "content": "H<sub>2</sub>S"}, {"identifier": "C", "content": "NH<sub>3</sub>"}, {"identifier": "D", "content": "H<sub>2</sub>O"}]
|
["A"]
| null |
CH<sub>4</sub> - Bond angle = 109<sup>o</sup>28'
<br><br>H<sub>2</sub>S - Bond angle = 92<sup>o</sup>
<br><br>NH<sub>3</sub> - Bond angle = 107<sup>o</sup>
<br><br>H<sub>2</sub>O - Bond angle = 104<sup>o</sup>5'
|
mcq
|
jee-main-2020-online-5th-september-evening-slot
| 837
|
9fIRZYzuHw4D3nSNnBjgy2xukfjadluh
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The structure of PCl<sub>5</sub>
in the solid state is :
|
[{"identifier": "A", "content": "square pyramidal"}, {"identifier": "B", "content": "tetrahedral [PCl<sub>4</sub>]<sup>+</sup> and octahedral [PCl<sub>6</sub>]<sup>\u2013</sup>"}, {"identifier": "C", "content": "square planar [PCl<sub>4</sub>]<sup>+</sup> and octahedral [PCl<sub>6</sub>]<sup>\u2013</sup>"}, {"identifier": "D", "content": "trigonal bipyramidal"}]
|
["B"]
| null |
In solid state PCl<sub>5</sub>
exist in Ionpair i.e. [PCl<sub>4</sub>]
<sup>+</sup> and [PCl<sub>6</sub>]
<sup>–</sup>
<br><br>[PCl<sub>4</sub>]<sup>+</sup> is tetrahedral.
<br>[PCl<sub>6</sub>]<sup>–</sup> is octahedral.
|
mcq
|
jee-main-2020-online-5th-september-morning-slot
| 838
|
A0YqhXuA1n1m3q3G9Ejgy2xukfcd054c
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The reaction in which the hybridisation of the
underlined atom is affected is :
|
[{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs83fh/8f320a03-c0e9-4d80-81c2-0ae6f37fdb4a/e3d420d0-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs83fi.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs83fh/8f320a03-c0e9-4d80-81c2-0ae6f37fdb4a/e3d420d0-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs83fi.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 1\">"}, {"identifier": "B", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs80z8/1d4f1eaf-ca9b-4c08-9264-c7862b7bcc69/e1ef5b40-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs80z9.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs80z8/1d4f1eaf-ca9b-4c08-9264-c7862b7bcc69/e1ef5b40-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs80z9.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 2\">"}, {"identifier": "C", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs7yj2/82fa8c0d-4dd5-4e97-9bdd-cab5d5b9ab6c/e00b0ae0-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs7yj3.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs7yj2/82fa8c0d-4dd5-4e97-9bdd-cab5d5b9ab6c/e00b0ae0-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs7yj3.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 3\">"}, {"identifier": "D", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ltbs7vax/0c2aabcc-9676-42ed-b541-1b113fc977e3/dd8d1290-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs7vay.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/6y3zli1ltbs7vax/0c2aabcc-9676-42ed-b541-1b113fc977e3/dd8d1290-d982-11ee-bce9-1f4a70aeb3d5/file-6y3zli1ltbs7vay.png\" loading=\"lazy\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 40vh;vertical-align: baseline\" alt=\"JEE Main 2020 (Online) 4th September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 145 English Option 4\">"}]
|
["A"]
| null |
To determine the option in which the hybridisation of the underlined atom is affected, we need to look at each reaction and predict the changes in hybridisation that might be occuring with the reactants and products.
<p>Option A:</p>
<p>In the reaction $$ \underline {Xe}F_4 + SbF_5 \to $$, xenon tetrafluoride (XeF<sub>4</sub>) reacts with antimony pentafluoride (SbF<sub>5</sub>). XeF<sub>4</sub> is a square planar molecule, and the central Xe atom is $sp^3d^2$ hybridised. The reaction with SbF<sub>5</sub> can lead to the formation of a complex where the hybridisation of Xe changes if it coordinates with SbF<sub>5</sub>. Thus, the hybridisation of Xe may indeed be affected in this case.</p>
<table class="tg">
<thead>
<tr>
<th class="tg-baqh">$$\underline {Xe} $$F<sub>4</sub></th>
<th class="tg-baqh">+</th>
<th class="tg-baqh">SbF<sub>5</sub></th>
<th class="tg-baqh">$$ \to $$</th>
<th class="tg-baqh">[XeF<sub>3</sub>]<sup>+</sup>[SbF<sub>6</sub>]<sup>-</sup></th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-baqh">sp<sup>3</sup>d<sup>2</sup></td>
<td class="tg-baqh"></td>
<td class="tg-baqh"></td>
<td class="tg-baqh"></td>
<td class="tg-baqh">sp<sup>3</sup>d sp<sup>3</sup>d<sup>2</sup></td>
</tr>
</tbody>
</table>
<p>Option B:</p>
<p>In the reaction $$ H_2\underline{S}O_4 + NaCl \buildrel {420K} \over \longrightarrow $$, sulfuric acid (H<sub>2</sub>SO<sub>4</sub>) reacts with sodium chloride (NaCl). The underlined atom here is sulfur (S). In sulfuric acid, sulfur is hybridised as $sp^3$. Upon heating, there is typically no change in the hybridisation of the sulfur atom within sulfuric acid as part of this reaction. Therefore, the hybridisation of S is likely not affected.</p>
<p>Option C:</p>
<p>In the reaction $$ H_3\underline{P}O_2 \buildrel {Disproportionation} \over \longrightarrow $$, phosphorous acid (H<sub>3</sub>PO<sub>2</sub>) is undergoing a disproportionation reaction. The underlined atom is phosphorus (P). In H<sub>3</sub>PO<sub>2</sub>, the hybridisation of the phosphorus atom is $sp^3$. A typical disproportionation reaction of phosphorous acid would result in phosphine (PH<sub>3</sub>) and orthophosphoric acid (H<sub>3</sub>PO<sub>4</sub>). The phosphorus atom in PH<sub>3</sub> will have $sp^3$ hybridisation while in H<sub>3</sub>PO<sub>4</sub> the phosphorus atom is $sp^3$ hybridised. Given this information, the hybridisation of phosphorus may or may not change, depending on the resulting state of the phosphorus atom in the products. It's not a clear-cut case without knowing the specific products.</p>
<p>Option D:</p>
<p>In the reaction $$ \underline{N}H_3 \buildrel {{H^+}} \over \longrightarrow $$, ammonia (NH<sub>3</sub>) is reacting with a proton (H<sup>+</sup>). The underlined atom is nitrogen (N). In NH<sub>3</sub>, the nitrogen is $sp^3$ hybridised. When ammonia accepts a proton, it forms ammonium ion (NH<sub>4</sub><sup>+</sup>), which is also $sp^3$ hybridised. Therefore, there is no change in the hybridisation of nitrogen in this case.</p>
<p>Given this information, the option in which the hybridisation of the underlined atom is most clearly affected is <strong>Option A</strong>, where the reaction can lead to coordination changes to the Xe atom, potentially affecting its hybridisation.</p>
|
mcq
|
jee-main-2020-online-4th-september-evening-slot
| 839
|
WFXn6ZDj7Ne3LISNMWjgy2xukeyfkp6d
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The molecular geometry of SF<sub>6</sub> is octahedral.
What is the geometry of SF<sub>4</sub> (including lone
pair(s) of electrons, if any)?
|
[{"identifier": "A", "content": "Tetrahedral"}, {"identifier": "B", "content": "Trigonal bipyramidal"}, {"identifier": "C", "content": "Square planar"}, {"identifier": "D", "content": "Pyramidal"}]
|
["B"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263360/exam_images/hzqviod1jrllko8vzhxn.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 2nd September Evening Slot Chemistry - Chemical Bonding & Molecular Structure Question 149 English Explanation">
<br><br>Here 4$$\sigma $$ bonds +1 lone pair
<br><br>Electronic geometry is Trigonal bipyramidal. Moleculer Geometry
or
Moleculer Shape is see-saw.
<br><br><b>Note :</b> The difference between Electronic Geometry and Moleculer Geometry(Moleculer Shape) is that in Electronic Geometry we include lone pair but in Moleculer Geometry(Moleculer Shape) we do not include lone pair.
|
mcq
|
jee-main-2020-online-2nd-september-evening-slot
| 840
|
m9nI60z407ispZxrApjgy2xukeyg5mny
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The shape / structure of [XeF<sub>5</sub>]<sup>–</sup> and XeO<sub>3</sub>F<sub>2</sub>,
respectively, are
|
[{"identifier": "A", "content": "Pentagonal planar and trigonal bipyramidal"}, {"identifier": "B", "content": "Trigonal bipyramidal and pentagonal\nplanar"}, {"identifier": "C", "content": "Octahedral and square pyramidal"}, {"identifier": "D", "content": "Trigonal bipyramidal and trigonal\nbipyramidal"}]
|
["A"]
| null |
[XeF<sub>5</sub>]<sup>–</sup> $$ \to $$ 5BP + 2LP $$ \to $$ sp<sup>3</sup>d<sup>3</sup> hybridisation $$ \to $$ Pentagonal planar
<br><br>XeO<sub>3</sub>F<sub>2</sub>
$$ \to $$ 5BP + 0LP $$ \to $$ sp<sup>3</sup>d hybridisation $$ \to $$ Trigonal bipyramidal
|
mcq
|
jee-main-2020-online-2nd-september-evening-slot
| 842
|
EH7XWeAT0VLMyVxT5e7k9k2k5llkutr
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The number of sp<sup>2</sup> hybrid orbitals in a molecule
of benzene is :
|
[{"identifier": "A", "content": "24"}, {"identifier": "B", "content": "12"}, {"identifier": "C", "content": "6"}, {"identifier": "D", "content": "18"}]
|
["D"]
| null |
Each carbon atom is sp<sup>2</sup> hybrid
<br><br>$$ \therefore $$ 3 sp<sup>2</sup> hybrid orbitals are formed by each
carbon atom
<br><br>Total sp<sup>2</sup> orbitals = 6 × 3 = 18
|
mcq
|
jee-main-2020-online-9th-january-evening-slot
| 843
|
eAwLd70abt7Dh4fFYm1kmj7ywbn
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
A central atom in a molecule has two lone pairs of electrons and forms three single bonds. The shape of this molecule is :
|
[{"identifier": "A", "content": "trigonal pyramidal"}, {"identifier": "B", "content": "T-shaped"}, {"identifier": "C", "content": "see-saw"}, {"identifier": "D", "content": "planar triangular"}]
|
["B"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267475/exam_images/ikyy2xvsehf2rnp50132.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 17th March Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 131 English Explanation"><br>
sp<sup>3</sup>d hybridised<br>
T-shaped
|
mcq
|
jee-main-2021-online-17th-march-morning-shift
| 847
|
bStxnIbOS1q0TO4EeC1kmki78mh
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Amongst the following, the linear species is :
|
[{"identifier": "A", "content": "O<sub>3</sub>"}, {"identifier": "B", "content": "Cl<sub>2</sub>O"}, {"identifier": "C", "content": "N$$_3^ - $$"}, {"identifier": "D", "content": "NO<sub>2</sub>"}]
|
["C"]
| null |
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264965/exam_images/ox4owl5r7abrp6o3rhe7.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 17th March Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 130 English Explanation">
|
mcq
|
jee-main-2021-online-17th-march-evening-shift
| 848
|
xzNUatmHPwWdaKZYvy1kmm1w3ue
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The number of species below that have two lone pairs of electrons in their central atom is _________. (Round off to the Nearest Integer).<br/><br/>SF<sub>4</sub>, BF$$_4^ - $$, ClF<sub>3</sub>, AsF<sub>3</sub>, PCl<sub>5</sub>, BrF<sub>5</sub>, XeF<sub>4</sub>, SF<sub>6</sub>
|
[]
| null |
2
|
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1kxpyy0y2/1d70fcec-a606-45a3-9dc8-dd4b5b57635c/38b07aa0-67c9-11ec-876a-c595023c9bc7/file-1kxpyy0y3.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1kxpyy0y2/1d70fcec-a606-45a3-9dc8-dd4b5b57635c/38b07aa0-67c9-11ec-876a-c595023c9bc7/file-1kxpyy0y3.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 60vh" alt="JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 128 English Explanation 1">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1kxpyypmn/c55c80cd-260f-48dc-8868-1b491c0a06b1/4bc19cf0-67c9-11ec-876a-c595023c9bc7/file-1kxpyypmo.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1kxpyypmn/c55c80cd-260f-48dc-8868-1b491c0a06b1/4bc19cf0-67c9-11ec-876a-c595023c9bc7/file-1kxpyypmo.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 60vh" alt="JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 128 English Explanation 2">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1kxpyzes0/b3ec239c-756c-4e83-bf2c-c5b9bfe2fda6/5f2f1010-67c9-11ec-876a-c595023c9bc7/file-1kxpyzes1.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1kxpyzes0/b3ec239c-756c-4e83-bf2c-c5b9bfe2fda6/5f2f1010-67c9-11ec-876a-c595023c9bc7/file-1kxpyzes1.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 60vh" alt="JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 128 English Explanation 3">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1kxpyzykx/8bba3d3c-057d-4daf-bd60-1b5ba25afa1b/6e7b3b20-67c9-11ec-876a-c595023c9bc7/file-1kxpyzyky.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1kxpyzykx/8bba3d3c-057d-4daf-bd60-1b5ba25afa1b/6e7b3b20-67c9-11ec-876a-c595023c9bc7/file-1kxpyzyky.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2021 (Online) 18th March Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 128 English Explanation 4">
|
integer
|
jee-main-2021-online-18th-march-evening-shift
| 849
|
1krq6e1ck
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The number of lone pairs of electrons on the central I atom in I$$_3^ - $$ is ____________.
|
[]
| null |
3
|
<p>Shape of I<sub>3</sub><sup>-</sup> is :</p>
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l2piubu4/f87a8e33-73a3-474a-95be-c3971c8e1552/54b18ac0-ca87-11ec-ab2b-7960e659c3b6/file-1l2piubu5.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l2piubu4/f87a8e33-73a3-474a-95be-c3971c8e1552/54b18ac0-ca87-11ec-ab2b-7960e659c3b6/file-1l2piubu5.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2021 (Online) 20th July Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 127 English Explanation">
<p>The number of lone pairs of electron on the central atom is 3.</p>
|
integer
|
jee-main-2021-online-20th-july-morning-shift
| 850
|
1krriq8sk
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
The hybridisations of the atomic orbitals of nitrogen in NO$$_2^ - $$, NO$$_2^ + $$ and NH$$_4^ + $$ respectively are.
|
[{"identifier": "A", "content": "sp<sup>3</sup>, sp<sup>2</sup> and sp"}, {"identifier": "B", "content": "sp, sp<sup>2</sup> and sp<sup>3</sup>"}, {"identifier": "C", "content": "sp<sup>3</sup>, sp and sp<sup>2</sup>"}, {"identifier": "D", "content": "sp<sup>2</sup>, sp and sp<sup>3</sup>"}]
|
["D"]
| null |
Hybridisation = Number of sigma bonds + number of lone pair of electrons + number of coordinate bond.<br><br>For $$NO_2^ - $$ hybridisation = 2 sigma NO bonds + 1 lone pair on N = 3; so $$NO_2^ - $$ is sp<sup>2</sup>-hybridised.<br><br> <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l2pl7aq0/65e1e218-9a3b-4a96-93bc-5b24c1373cd6/8f9c2880-ca90-11ec-ace3-f5b4d86f7970/file-1l2pl7aq1.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l2pl7aq0/65e1e218-9a3b-4a96-93bc-5b24c1373cd6/8f9c2880-ca90-11ec-ace3-f5b4d86f7970/file-1l2pl7aq1.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 126 English Explanation 1"><br>For $$NO_2^ + $$ hybridisation = 2 sigma NO bonds = 2; so $$NO_2^ + $$ sp-hybridised.<br><br> <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l2pl7wzv/dce2e0bf-11ef-4f3e-81cb-8d56fb756cae/a0d0e9b0-ca90-11ec-ace3-f5b4d86f7970/file-1l2pl7wzw.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l2pl7wzv/dce2e0bf-11ef-4f3e-81cb-8d56fb756cae/a0d0e9b0-ca90-11ec-ace3-f5b4d86f7970/file-1l2pl7wzw.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 126 English Explanation 2"><br>For $$NO_4^ + $$ Hybridisation = 4 sigma NH bonds = 4; so $$NO_4^ + $$ is sp<sup>3</sup>-hybridised.<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l2pl8o53/71642e94-0c63-47b2-9296-d8d639dac1c0/b5c8f470-ca90-11ec-ace3-f5b4d86f7970/file-1l2pl8o54.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l2pl8o53/71642e94-0c63-47b2-9296-d8d639dac1c0/b5c8f470-ca90-11ec-ace3-f5b4d86f7970/file-1l2pl8o54.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 126 English Explanation 3"><br>Therefore, hybridisation of N in $$NO_2^ - $$, $$NO_2^ + $$, $$NO_4^ + $$ are sp<sup>2</sup>, sp, sp<sup>3</sup> respectively.
|
mcq
|
jee-main-2021-online-20th-july-evening-shift
| 851
|
1krt46woa
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Match List-I with List-II :<br/><br/><table>
<thead>
<tr>
<th></th>
<th>List-I<br/>(Species)</th>
<th></th>
<th>List-II<br/>(Hybrid Orbitals)</th>
</tr>
</thead>
<tbody>
<tr>
<td>(a)</td>
<td>$$S{F_4}$$</td>
<td>(i)</td>
<td>$$s{p^3}{d^2}$$</td>
</tr>
<tr>
<td>(b)</td>
<td>$$I{F_5}$$</td>
<td>(ii)</td>
<td>$${d^2}s{p^3}$$</td>
</tr>
<tr>
<td>(c)</td>
<td>$$NO_2^ + $$</td>
<td>(iii)</td>
<td>$$s{p^3}d$$</td>
</tr>
<tr>
<td>(d)</td>
<td>$$NH_4^ + $$</td>
<td>(iv)</td>
<td>$$s{p^3}$$</td>
</tr>
<tr>
<td></td>
<td></td>
<td>(v)</td>
<td>$$sp$$</td>
</tr>
</tbody>
</table><br/><br/>Choose the correct answer from the options given below :
|
[{"identifier": "A", "content": "(a)-(i), (b)-(ii), (c)-(v) and (d)-(iii)"}, {"identifier": "B", "content": "(a)-(ii), (b)-(i), (c)-(iv) and (d)-(v)"}, {"identifier": "C", "content": "(a)-(iii), (b)-(i), (c)-(v) and (d)-(iv)"}, {"identifier": "D", "content": "(a)-(iv), (b)-(iii), (c)-(ii) and (d)-(v)"}]
|
["C"]
| null |
(a) SF<sub>4</sub> - sp<sup>3</sup>d hybridization<br><br>(b) IF<sub>5</sub> - sp<sup>3</sup>d<sup>2</sup> hybridization<br><br>(c) NO$$_2^ + $$ - sp hybridization<br><br>(d) NH$$_4^ + $$ - sp<sup>3</sup> hybridization
|
mcq
|
jee-main-2021-online-22th-july-evening-shift
| 852
|
1ktb5pthc
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
AB<sub>3</sub> is an interhalogen T-shaped molecule. The number of lone pairs of electrons on A is __________. (Integer answer)
|
[]
| null |
2
|
T-shaped molecule means 3 sigma bond and 2 lone pairs of electron on central atom.<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265831/exam_images/osuebnrkekbw52or2jrs.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 26th August Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 120 English Explanation">
|
integer
|
jee-main-2021-online-26th-august-morning-shift
| 853
|
1kte9zt2x
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Match List - I with List - II :<br/><br/><img src="data:image/png;base64,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"/><br/>Choose the most appropriate answer from the options given below :
|
[{"identifier": "A", "content": "(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)"}, {"identifier": "B", "content": "(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)"}, {"identifier": "C", "content": "(a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)"}, {"identifier": "D", "content": "(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)"}]
|
["D"]
| null |
<table style="width:100%">
<thead>
<tr>
<th>Species<br></th>
<th>(Number of lone pairs of <br><br>electrons on the central atom)</th>
</tr>
</thead>
<tbody>
<tr>
<td>$$Xe{F_2}$$</td>
<td><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265079/exam_images/rcq352tggid48hvq03yf.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 118 English Explanation 1"></td>
</tr>
<tr>
<td>$$Xe{O_2}{F_2}$$</td>
<td><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267354/exam_images/yu3jyyalyf18ui7izofp.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 118 English Explanation 2"></td>
</tr>
<tr>
<td>$$Xe{O_3}{F_2}$$</td>
<td><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265262/exam_images/qmthfz4fsuge6vh1dxgr.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 118 English Explanation 3"></td>
</tr>
<tr>
<td>$$Xe{F_4}$$</td>
<td><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266451/exam_images/aas0iz1e9k24p5owlsvu.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 118 English Explanation 4"></td>
</tr>
</tbody>
</table>
|
mcq
|
jee-main-2021-online-27th-august-morning-shift
| 854
|
1l54y1m1n
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Consider the species CH<sub>4</sub>, NH$$_4^ + $$ and BH$$_4^ - $$. Choose the correct option with respect to the these species.</p>
|
[{"identifier": "A", "content": "They are isoelectronic and only two have tetrahedral structures."}, {"identifier": "B", "content": "They are isoelectronic and all have tetrahedral structures."}, {"identifier": "C", "content": "Only two are isoelectronic and all have tetrahedral structures."}, {"identifier": "D", "content": "Only two are isoelectronic and only two have tetrahedral structures."}]
|
["B"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l97wmvs0/61a9048e-4f47-448d-a6f9-c21ca939ed1e/ad654600-4b6c-11ed-9399-cda4ba1d6994/file-1l97wmvs1.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l97wmvs0/61a9048e-4f47-448d-a6f9-c21ca939ed1e/ad654600-4b6c-11ed-9399-cda4ba1d6994/file-1l97wmvs1.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 29th June Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 110 English Explanation"><br>All are tetrahedral and each have 10 electrons.
|
mcq
|
jee-main-2022-online-29th-june-evening-shift
| 856
|
1l55mwdtf
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>In the structure of SF<sub>4</sub>, the lone pair of electrons on S is in.</p>
|
[{"identifier": "A", "content": "equatorial position and there are two lone pair - bond pair repulsions at 90$$^\\circ$$."}, {"identifier": "B", "content": "equatorial position and there are three lone pair - bond pair repulsions at 90$$^\\circ$$."}, {"identifier": "C", "content": "axial position and there are three lone pair - bond pair repulsion at 90$$^\\circ$$."}, {"identifier": "D", "content": "axial position and there are two lone pair - bond pair repulsion at 90$$^\\circ$$."}]
|
["A"]
| null |
SF<sub>4</sub> → sp<sup>3</sup>d hybridisation.<br><br>
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5iu8g2m/f6e3a0e9-18f5-4382-97a8-c36fd2d57935/0b4e00d0-023f-11ed-9915-b142ef5d751a/file-1l5iu8g2n.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5iu8g2m/f6e3a0e9-18f5-4382-97a8-c36fd2d57935/0b4e00d0-023f-11ed-9915-b142ef5d751a/file-1l5iu8g2n.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 28th June Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 109 English Explanation"><br>
The lone pair of electrons on S is in an equatorial position and there are two lone pair-bond pair repulsions at 90°.
|
mcq
|
jee-main-2022-online-28th-june-evening-shift
| 858
|
1l56bfg52
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>The hybridization of P exhibited in PF<sub>5</sub> is sp<sup>x</sup>d<sup>y</sup>. The value of y is __________.</p>
|
[]
| null |
1
|
$\mathrm{PF}_5 \Rightarrow \mathrm{sp}^3 \mathrm{~d}$ hybridisation
<br/><br/>(5 sigma bonds, zero lone pair on central atom)
<br/><br/>Value of $y=1$
|
integer
|
jee-main-2022-online-28th-june-morning-shift
| 859
|
1l56wr85r
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Identify the incorrect statement for PCl<sub>5</sub> from the following.</p>
|
[{"identifier": "A", "content": "In this molecule, orbitals of phosphorous are assumed to undergo sp<sup>3</sup>d hybridization."}, {"identifier": "B", "content": "The geometry of PCl<sub>5</sub> is trigonal bipyramidal."}, {"identifier": "C", "content": "PCl<sub>5</sub> has two axial bonds stronger than three equatorial bonds."}, {"identifier": "D", "content": "The three equatorial bonds of PCl<sub>5</sub> lie in a plane."}]
|
["C"]
| null |
<b>PCl<sub>5</sub></b><br><br>
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5jkmy8x/8796e7cd-77d0-4f27-bcbb-1f9449bc2e5a/4c07f510-02a6-11ed-b0f0-b1d5b36f6c01/file-1l5jkmy8y.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5jkmy8x/8796e7cd-77d0-4f27-bcbb-1f9449bc2e5a/4c07f510-02a6-11ed-b0f0-b1d5b36f6c01/file-1l5jkmy8y.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 27th June Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 106 English Explanation"><br>
All three equatorial bonds in a plane<br><br>
sp<sup>3</sup>d hybridization<br><br>
Trigonal bipyramidal<br><br>
Axial bonds are weaker than equatorial bonds.
|
mcq
|
jee-main-2022-online-27th-june-evening-shift
| 860
|
1l57r9zwv
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Based upon VSEPR theory, match the shape (geometry) of the molecules in List-I with the molecules in List-II and select the most appropriate option.</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-1wig{font-weight:bold;text-align:left;vertical-align:top}
.tg .tg-0lax{text-align:left;vertical-align:top}
</style>
<table class="tg" style="undefined;table-layout: fixed; width: 472px">
<colgroup>
<col style="width: 44px"/>
<col style="width: 143px"/>
<col style="width: 42px"/>
<col style="width: 243px"/>
</colgroup>
<thead>
<tr>
<th class="tg-1wig"></th>
<th class="tg-1wig">List - I<br/>(Shape)</th>
<th class="tg-1wig"></th>
<th class="tg-1wig">List - II<br/>(Molecules)</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-0lax">(A)</td>
<td class="tg-0lax">T-shaped</td>
<td class="tg-0lax">(I)</td>
<td class="tg-0lax">XeF$$_4$$</td>
</tr>
<tr>
<td class="tg-0lax">(B)</td>
<td class="tg-0lax">Trigonal planar</td>
<td class="tg-0lax">(II)</td>
<td class="tg-0lax">SF$$_4$$</td>
</tr>
<tr>
<td class="tg-0lax">(C)</td>
<td class="tg-0lax">Square planar</td>
<td class="tg-0lax">(III)</td>
<td class="tg-0lax">ClF$$_3$$</td>
</tr>
<tr>
<td class="tg-0lax">(D)</td>
<td class="tg-0lax">See-saw</td>
<td class="tg-0lax">(IV)</td>
<td class="tg-0lax">BF$$_3$$</td>
</tr>
</tbody>
</table></p>
|
[{"identifier": "A", "content": "(A) - (I), (B) - (II), (C) - (III), (D) - (IV)"}, {"identifier": "B", "content": "(A) - (III), (B) - (IV), (C) - (I), (D) - (II)"}, {"identifier": "C", "content": "(A) - (III), (B) - (IV), (C) - (I), (D) - (I)"}, {"identifier": "D", "content": "(A) - (IV), (B) - (III), (C) - (I), (D) - (II)"}]
|
["B"]
| null |
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5jlr69n/5cc75343-17c1-431f-bb06-5f551c4c042b/aa9794b0-02aa-11ed-9031-556e2cf7e851/file-1l5jlr69o.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5jlr69n/5cc75343-17c1-431f-bb06-5f551c4c042b/aa9794b0-02aa-11ed-9031-556e2cf7e851/file-1l5jlr69o.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 60vh" alt="JEE Main 2022 (Online) 27th June Morning Shift Chemistry - Chemical Bonding & Molecular Structure Question 105 English Explanation">
|
mcq
|
jee-main-2022-online-27th-june-morning-shift
| 861
|
1l58k33jj
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Amongst SF<sub>4</sub>, XeF<sub>4</sub>, CF<sub>4</sub> and H<sub>2</sub>O, the number of species with two lone pairs of electrons is _____________.</p>
|
[]
| null |
1
|
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lc3z50ks/35bf580e-a9f8-46ae-bd1a-4ecbcea03479/fb76dfb0-84a7-11ed-9e2c-bf48676ab5eb/file-1lc3z50kt.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lc3z50ks/35bf580e-a9f8-46ae-bd1a-4ecbcea03479/fb76dfb0-84a7-11ed-9e2c-bf48676ab5eb/file-1lc3z50kt.png" loading="lazy" style="max-width: 100%;height: auto;display: block;margin: 0 auto;max-height: 60vh" alt="JEE Main 2022 (Online) 26th June Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 103 English Explanation">
|
integer
|
jee-main-2022-online-26th-june-evening-shift
| 862
|
1l6f63903
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Match List I with List II:</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top}
.tg .tg-0pky{border-color:inherit;text-align:left;vertical-align:top}
</style>
<table class="tg">
<thead>
<tr>
<th class="tg-7btt"></th>
<th class="tg-7btt">List I<br/>(molecule)</th>
<th class="tg-7btt"></th>
<th class="tg-7btt">List II<br/>(hybridization ; shape)</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-0pky">(A)</td>
<td class="tg-0pky">XeO$$_3$$</td>
<td class="tg-0pky">(I)</td>
<td class="tg-0pky">sp$$^3$$d ; linear</td>
</tr>
<tr>
<td class="tg-0pky">(B)</td>
<td class="tg-0pky">XeF$$_2$$</td>
<td class="tg-0pky">(II)</td>
<td class="tg-0pky">sp$$^3$$ ; pyramidal</td>
</tr>
<tr>
<td class="tg-0pky">(C)</td>
<td class="tg-0pky">XeOF$$_4$$</td>
<td class="tg-0pky">(III)</td>
<td class="tg-0pky">sp$$^3$$d$$^3$$ ; distorted octahedral</td>
</tr>
<tr>
<td class="tg-0pky">(D)</td>
<td class="tg-0pky">XeF$$_6$$</td>
<td class="tg-0pky">(IV)</td>
<td class="tg-0pky">sp$$^3$$d$$^2$$ ; square pyramidal</td>
</tr>
</tbody>
</table></p>
<p>Choose the correct answer from the options given below:</p>
|
[{"identifier": "A", "content": "A-II, B-I, C-IV, D-III"}, {"identifier": "B", "content": "A-II, B-IV, C-III, D-I"}, {"identifier": "C", "content": "A-IV, B-II, C-III, D-I"}, {"identifier": "D", "content": "A-IV, B-II, C-I, D-III"}]
|
["A"]
| null |
$$\mathrm{XeO}_{3}-s p^{3}$$, Pyramidal
<br/><br/>
$$\mathrm{XeF}_{2}-s p^{3} d$$, linear
<br/><br/>
$$\mathrm{XeOF}_{4}-s p^{3} d^{2}$$, Square Pyramidal
<br/><br/>
$$\mathrm{XeF}_{6}-s p^{3} d^{3}$$, distorted octahedral
|
mcq
|
jee-main-2022-online-25th-july-evening-shift
| 864
|
1l6f7udhr
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>The sum of number of lone pairs of electrons present on the central atoms of XeO<sub>3</sub>, XeOF<sub>4</sub> and XeF<sub>6</sub>, is ______________</p>
|
[]
| null |
3
|
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7p0kshw/3dd46c9b-e1c2-4526-8f29-bf0b442bddd1/fc0ad750-2d3c-11ed-b59b-c52a043bb9dc/file-1l7p0kshx.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7p0kshw/3dd46c9b-e1c2-4526-8f29-bf0b442bddd1/fc0ad750-2d3c-11ed-b59b-c52a043bb9dc/file-1l7p0kshx.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 25th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 95 English Explanation 1">
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263562/exam_images/wqes6qrlw73fpigbtuiv.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2022 (Online) 25th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 95 English Explanation 2">
<br><br>From structure, it is clear that it has five bond pairs and one
lone pair.
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7p0rtjm/934357fc-5a88-40a8-9777-fc9352a2e2b6/bf83e320-2d3d-11ed-b59b-c52a043bb9dc/file-1l7p0rtjn.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7p0rtjm/934357fc-5a88-40a8-9777-fc9352a2e2b6/bf83e320-2d3d-11ed-b59b-c52a043bb9dc/file-1l7p0rtjn.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 25th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 95 English Explanation 3">
|
integer
|
jee-main-2022-online-25th-july-evening-shift
| 865
|
1l6gp10zq
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Match List-I with List-II :</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;}
.tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top}
.tg .tg-0pky{border-color:inherit;text-align:left;vertical-align:top}
</style>
<table class="tg">
<thead>
<tr>
<th class="tg-7btt"></th>
<th class="tg-7btt">List I<br/>(Compound)</th>
<th class="tg-7btt"></th>
<th class="tg-7btt">List II<br/>(Shape)</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-0pky">(A)</td>
<td class="tg-0pky">BrF$$_5$$</td>
<td class="tg-0pky">(I)</td>
<td class="tg-0pky">bent</td>
</tr>
<tr>
<td class="tg-0pky">(B)</td>
<td class="tg-0pky">[CrF$$_6$$]$$^{3 - }$$</td>
<td class="tg-0pky">(II)</td>
<td class="tg-0pky">square pyramidal</td>
</tr>
<tr>
<td class="tg-0pky">(C)</td>
<td class="tg-0pky">O$$_3$$</td>
<td class="tg-0pky">(III)</td>
<td class="tg-0pky">trigonal bipyramidal</td>
</tr>
<tr>
<td class="tg-0pky">(D)</td>
<td class="tg-0pky">PCl$$_5$$</td>
<td class="tg-0pky">(IV)</td>
<td class="tg-0pky">octahedral</td>
</tr>
</tbody>
</table></p>
<p>Choose the correct answer from the options given below :</p>
|
[{"identifier": "A", "content": "$$(\\mathrm{A})-(\\mathrm{I}),(\\mathrm{B})-(\\mathrm{II}),(\\mathrm{C})-(\\mathrm{III}),(\\mathrm{D})-(\\mathrm{IV})$$"}, {"identifier": "B", "content": "$$(\\mathrm{A})-(\\mathrm{IV}),(\\mathrm{B})-(\\mathrm{III}),(\\mathrm{C})-(\\mathrm{II}),(\\mathrm{D})-(\\mathrm{I})$$"}, {"identifier": "C", "content": "$$(\\mathrm{A})-(\\mathrm{II}),(\\mathrm{B})-(\\mathrm{IV}),(\\mathrm{C})-(\\mathrm{I}),(\\mathrm{D})-(\\mathrm{III})$$"}, {"identifier": "D", "content": "$$(\\mathrm{A})-(\\mathrm{III}),(\\mathrm{B})-(\\mathrm{IV}),(\\mathrm{C})-(\\mathrm{II}),(\\mathrm{D})-(\\mathrm{I})$$"}]
|
["C"]
| null |
(A) $$\mathrm{BrF}_{5}-$$ square pyramidal<br/><br/>
(B) $$\left[\mathrm{CrF}_{6}\right]^{3-}-$$ octahedral<br/><br/>
(C) $$\mathrm{O}_{3}-$$ bent<br/><br/>
(D) $$\mathrm{PCl}_{5}$$ - trigonal bipyramidal
|
mcq
|
jee-main-2022-online-26th-july-morning-shift
| 866
|
1l6p6q3wz
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?</p>
|
[{"identifier": "A", "content": "$$\\mathrm{BCl}_{3}$$ and $$\\mathrm{SF}_{6}$$"}, {"identifier": "B", "content": "$$\\mathrm{NO}$$ and $$\\mathrm{H}_{2} \\mathrm{SO}_{4}$$"}, {"identifier": "C", "content": "$$\\mathrm{SF}_{6}$$ and $$\\mathrm{H}_{2} \\mathrm{SO}_{4}$$"}, {"identifier": "D", "content": "$$\\mathrm{BCl}_{3}$$ and $$\\mathrm{NO}$$"}]
|
["B"]
| null |
(A) $\mathrm{BCl}_{3}$ - Even electron molecules
<br/> $\mathrm{SF}_{6}$ - Expended octet molecules
<br/><br/>
(B) $\mathrm{NO}$ - Odd electron molecules<br/>
$\mathrm{H}_{2} \mathrm{SO}_{4}$ - Expanded octet<br/><br/>
(C) $\mathrm{SF}_{6}-$ Even electron molecules<br/>
$\mathrm{H}_{2} \mathrm{SO}_{4}$ - Expanded octet
<br/><br/>
(D) $\mathrm{BCl}_{3}-$ Even electron molecules
<br/> $\mathrm{NO}$ - odd electron molecules
|
mcq
|
jee-main-2022-online-29th-july-morning-shift
| 869
|
1l6rlc43e
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
<p>Consider, $$\mathrm{PF}_{5}, \mathrm{BrF}_{5}, \mathrm{PCl}_{3}, \mathrm{SF}_{6},\left[\mathrm{ICl}_{4}\right]^{-}, \mathrm{ClF}_{3}$$ and $$\mathrm{IF}_{5}$$.</p>
<p>Amongst the above molecule(s)/ion(s), the number of molecule(s)/ion(s) having $$\mathrm{sp}^{3}\mathrm{~d}^{2}$$ hybridisation is __________.</p>
|
[]
| null |
4
|
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7nqvd68/cab139cf-e263-4f83-8376-948ba4f86329/3e29f700-2c8a-11ed-a521-1f85f535c206/file-1l7nqvd69.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7nqvd68/cab139cf-e263-4f83-8376-948ba4f86329/3e29f700-2c8a-11ed-a521-1f85f535c206/file-1l7nqvd69.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 29th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 83 English Explanation 1">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7nqxk4x/9aab81ed-5142-4461-8a86-598af522d660/7b295a10-2c8a-11ed-a521-1f85f535c206/file-1l7nqxk4y.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7nqxk4x/9aab81ed-5142-4461-8a86-598af522d660/7b295a10-2c8a-11ed-a521-1f85f535c206/file-1l7nqxk4y.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 29th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 83 English Explanation 2">
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7nqy9o6/23634821-5352-4435-bae7-df0b5346b1cf/8ee2f160-2c8a-11ed-a521-1f85f535c206/file-1l7nqy9o7.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7nqy9o6/23634821-5352-4435-bae7-df0b5346b1cf/8ee2f160-2c8a-11ed-a521-1f85f535c206/file-1l7nqy9o7.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2022 (Online) 29th July Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 83 English Explanation 3">
|
integer
|
jee-main-2022-online-29th-july-evening-shift
| 871
|
ldo9trsz
|
chemistry
|
chemical-bonding-and-molecular-structure
|
hybridization-and-vsepr-theory
|
Amongst the following, the number of species having the linear shape is _________.
<br/><br/>
$\mathrm{XeF}_{2}, \mathrm{I}_{3}^{+}, \mathrm{C}_{3} \mathrm{O}_{2}, \mathrm{I}_{3}^{-}, \mathrm{CO}_{2}, \mathrm{SO}_{2}, \mathrm{BeCl}_{2}$ and $\mathrm{BCl}_{2}^{\ominus}$
|
[]
| null |
5
|
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lect9lyz/7e414fab-0229-4be9-958f-650518fba5c3/810e44b0-b11c-11ed-8d19-c1418e0c6b67/file-1lect9lz0.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lect9lyz/7e414fab-0229-4be9-958f-650518fba5c3/810e44b0-b11c-11ed-8d19-c1418e0c6b67/file-1lect9lz0.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 80 English Explanation 1">
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lecta5wo/b5c903a6-ce4b-4d99-baeb-22c842c84403/90748770-b11c-11ed-b393-e7fb130a46e6/file-1lecta5wp.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lecta5wo/b5c903a6-ce4b-4d99-baeb-22c842c84403/90748770-b11c-11ed-b393-e7fb130a46e6/file-1lecta5wp.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 80 English Explanation 2">
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lectao44/77127ea5-4cfb-4dd7-b519-b2bf5b1441b6/9e852540-b11c-11ed-b393-e7fb130a46e6/file-1lectao45.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lectao44/77127ea5-4cfb-4dd7-b519-b2bf5b1441b6/9e852540-b11c-11ed-b393-e7fb130a46e6/file-1lectao45.png" loading="lazy" style="max-width: 100%; height: auto; display: block; margin: 0px auto; max-height: 40vh;" alt="JEE Main 2023 (Online) 31st January Evening Shift Chemistry - Chemical Bonding & Molecular Structure Question 80 English Explanation 3">
|
integer
|
jee-main-2023-online-31st-january-evening-shift
| 872
|
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