input stringlengths 358 16.1k | output stringlengths 24 805 |
|---|---|
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM enrolled WHERE school = 'smc' AND month = 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM enlist WHERE organ = 'air_force'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT organ FROM enlist WHERE name = 'student168'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM disabled AS T1 LEFT JOIN male AS T2 ON T2.name = T1.name INNER JOIN enlist AS T3 ON T3.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM enrolled AS T1 INNER JOIN disabled AS T2 ON T2.name = T1.name GROUP BY T1.school; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT IIF(T2.name IS NULL, 'female', 'male') AS gender FROM enlist AS T1 LEFT JOIN male AS T2 ON T2.name = T1.name GROUP BY T1.organ; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T.name FROM ( SELECT T1.name, COUNT(T1.organ) AS num FROM enlist AS T1 INNER JOIN enrolled AS T2 ON T1.name = T2.name GROUP BY T1.name ) T WHERE T.num = 2; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT CAST(((SUM(IIF(month = 0, 1, 0)) - SUM(IIF(month = 9, 1, 0)))) AS REAL) * 100 / SUM(IIF(month = 0, 1, 0)) FROM longest_absense_from_school; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T.school, num FROM ( SELECT T1.school, COUNT(T2.name) AS num FROM enrolled AS T1 LEFT JOIN filed_for_bankrupcy AS T2 ON T2.name = T1.name GROUP BY T1.school ) T ORDER BY T.num DESC LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM disabled AS T1 INNER JOIN unemployed AS T2 ON T2.name = T1.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM enlist AS T1 INNER JOIN enrolled AS T2 ON T2.name = T1.name WHERE T2.school = 'occ' AND T1.organ = 'fire_department'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM unemployed AS T1 INNER JOIN disabled AS T2 ON T2.name = T1.name INNER JOIN longest_absense_from_school AS T3 ON T3.name = T2.name WHERE T3.month = 5; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT name FROM enrolled WHERE school IN ('occ', 'ulca') AND name NOT IN ( SELECT name FROM male ); |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T2.school, T1.organ FROM enlist AS T1 INNER JOIN enrolled AS T2 ON T2.name = T1.name WHERE T1.name = 'student211'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T2.name) - SUM(IIF(T2.name IS NULL, 1, 0)) AS num FROM filed_for_bankrupcy AS T1 LEFT JOIN male AS T2 ON T2.name = T1.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT AVG(T2.month) AS avg FROM unemployed AS T1 INNER JOIN longest_absense_from_school AS T2 ON T2.name = T1.name INNER JOIN male AS T3 ON T3.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT CAST((SUM(IIF(T2.name IS NOT NULL AND T1.month = 0, 1, 0)) - SUM(IIF(T2.name IS NULL AND T1.month = 0, 1, 0))) AS REAL) * 100 / COUNT(T1.name), IIF(SUM(IIF(T2.name IS NOT NULL AND T1.month = 0, 1, 0)) - SUM(IIF(T2.name IS NULL AND T1.month = 0, 1, 0)) > 0, 'YES', 'NO') AS isHigh FROM longest_absense_from_school ... |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT AVG(T1.month) FROM longest_absense_from_school AS T1 INNER JOIN disabled AS T2 ON T2.name = T1.name INNER JOIN male AS T3 ON T3.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT CAST(SUM(IIF(T2.month = 0, 1, 0)) AS REAL) * 100 / COUNT(T1.name) FROM unemployed AS T1 INNER JOIN longest_absense_from_school AS T2 ON T2.name = T1.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM no_payment_due AS T1 INNER JOIN male AS T2 ON T2.name = T1.name WHERE T1.bool = 'pos'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM filed_for_bankrupcy AS T1 INNER JOIN no_payment_due AS T2 ON T2.name = T1.name WHERE T2.bool = 'pos'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT `bool` FROM no_payment_due WHERE name = 'student124'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM no_payment_due AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name WHERE T1.bool = 'neg'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM longest_absense_from_school AS T1 INNER JOIN no_payment_due AS T2 ON T1.name = T2.name WHERE T2.bool = 'neg' ORDER BY T1.month DESC LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM longest_absense_from_school AS T1 INNER JOIN no_payment_due AS T2 ON T1.name = T2.name WHERE T1.month = 5 AND T2.bool = 'neg'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM disabled AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T2.organ = 'marines'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.NAME) FROM longest_absense_from_school AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T2.organ = 'peace_corps' ORDER BY T1.month DESC LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM enlist AS T1 INNER JOIN filed_for_bankrupcy AS T2 ON T1.name = T2.name WHERE T1.organ = 'navy'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM no_payment_due AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T1.bool = 'pos' AND T2.organ = 'marines'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT 100 * SUM(IIF(T2.month = 0, 1, 0)) AS num FROM disabled AS T1 INNER JOIN longest_absense_from_school AS T2 ON T1.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM enlist WHERE organ = 'air_force'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM longest_absense_from_school WHERE month < 4; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(*) FROM person AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T1.name = T3.name WHERE T2.organ = 'marines' AND T3.name IS NULL; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT AVG(T2.month) FROM person AS T1 INNER JOIN longest_absense_from_school AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T1.name = T3.name WHERE T3.name IS NULL; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM person AS T1 INNER JOIN filed_for_bankrupcy AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T1.name = T3.name WHERE T3.name IS NULL; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT bool FROM no_payment_due WHERE name = 'student299'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM enlist WHERE organ = 'air_force'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM longest_absense_from_school WHERE month > 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT name FROM enlist WHERE organ = 'fire_department'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM no_payment_due AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name WHERE T1.bool = 'pos'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM filed_for_bankrupcy AS T1 INNER JOIN enrolled AS T2 ON T1.name = T2.name WHERE T2.school = 'occ'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM male AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM enlist AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name WHERE T1.organ = 'navy'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM male AS T1 INNER JOIN no_payment_due AS T2 ON T1.name = T2.name WHERE T2.bool = 'pos'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.bool FROM no_payment_due AS T1 INNER JOIN unemployed AS T2 ON T1.name = T2.name WHERE T1.name = 'student110'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT CAST(COUNT(T2.name) AS REAL) * 100 / COUNT(T1.name) FROM person AS T1 LEFT JOIN male AS T2 ON T1.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.school , IIF(T3.name IS NULL, 'female', 'male') AS gender FROM enrolled AS T1 INNER JOIN person AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T2.name = T3.name WHERE T2.name = 'student34'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.month FROM longest_absense_from_school AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T2.organ = 'fire_department' ORDER BY T1.month DESC LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM longest_absense_from_school AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T1.month = 1 AND T2.organ = 'air_force'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T2.NAME FROM unemployed AS T1 INNER JOIN male AS T2 ON T1.name = T2.name INNER JOIN disabled AS T3 ON T3.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM enrolled AS T1 INNER JOIN male AS T2 ON T1.name = T2.name WHERE T1.school = 'occ'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT CAST(COUNT(T4.name) AS REAL) * 100 / COUNT(T2.name) FROM enlist AS T1 INNER JOIN person AS T2 ON T1.name = T2.name INNER JOIN enrolled AS T3 ON T3.name = T2.name LEFT JOIN male AS T4 ON T2.name = T4.name WHERE T3.school = 'ucla' AND T1.organ = 'air_force'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT CAST(SUM(IIF(T1.school = 'uci' AND T4.name IS NULL, 1, 0)) AS REAL) / COUNT(T1.name) FROM enrolled AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name INNER JOIN person AS T3 ON T1.name = T3.name LEFT JOIN male AS T4 ON T3.name = T4.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM longest_absense_from_school WHERE month = 0; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT name FROM enlist WHERE organ = 'marines'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM enlist WHERE organ = 'navy'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT name FROM longest_absense_from_school WHERE month = ( SELECT MAX(month) FROM longest_absense_from_school ); |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT organ FROM ( SELECT organ, COUNT(organ) AS num FROM enlist GROUP BY organ ) T ORDER BY T.num DESC LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(name) FROM longest_absense_from_school WHERE month < 3; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM no_payment_due AS T1 INNER JOIN unemployed AS T2 ON T1.name = T2.name WHERE T1.bool = 'pos'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT SUM(IIF(T3.name IS NULL, 1, 0)) AS "result" FROM enlist AS T1 INNER JOIN person AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T2.name = T3.name WHERE T1.organ = 'army'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T.organ FROM ( SELECT T2.organ, COUNT(T1.name) AS num FROM male AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name GROUP BY T2.organ ) T ORDER BY T.num LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM disabled AS T1 INNER JOIN longest_absense_from_school AS T2 ON T1.name = T2.name WHERE T2.month = 0; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM unemployed AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.name FROM longest_absense_from_school AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name WHERE T1.month > 5; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM filed_for_bankrupcy AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name WHERE T2.organ = 'marines'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM disabled AS T1 INNER JOIN filed_for_bankrupcy AS T2 ON T1.name = T2.name; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T1.month FROM longest_absense_from_school AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name ORDER BY T1.month DESC LIMIT 1; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM longest_absense_from_school AS T1 INNER JOIN filed_for_bankrupcy AS T2 ON T1.name = T2.name INNER JOIN enlist AS T3 ON T3.name = T2.name WHERE T3.organ = 'fire_department'; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT COUNT(T1.name) FROM longest_absense_from_school AS T1 INNER JOIN disabled AS T2 ON T1.name = T2.name INNER JOIN unemployed AS T3 ON T3.name = T2.name WHERE T1.month = 0; |
[INST] Here is a database schema:
bool :
name [ TEXT ] primary_key
person :
name [ TEXT ] primary_key
disabled :
name [ TEXT ] primary_key disabled.name = person.name
enlist :
name [ TEXT ] enlist.name = person.name
organ [ TEXT ]
filed_for_bankrupcy :
name [ TEXT ] primary_key filed_for_bankrupcy.name = person.nam... | SELECT T.organ, T.per FROM ( SELECT T1.organ, CAST(COUNT(T3.name) AS REAL) / COUNT(T2.name) AS per , COUNT(T3.name) AS num FROM enlist AS T1 INNER JOIN person AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T2.name = T3.name GROUP BY T1.organ ) T ORDER BY T.num DESC LIMIT 1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(QuestionID) FROM Answer WHERE QuestionID = 19 AND AnswerText LIKE 'No'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT SurveyID, COUNT(UserID) FROM Answer WHERE QuestionID = 13 AND SurveyID BETWEEN 2016 AND 2019 GROUP BY SurveyID; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T1.UserID FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T1.SurveyID = 2018 AND T2.questionid = 1 AND T1.AnswerText BETWEEN '27' AND '35'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T1.UserID) FROM Answer AS T1 INNER JOIN ( SELECT T2.questionid FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T1.SurveyID = 2019 AND T2.questionid = 6 AND T1.AnswerText LIKE 'Yes' ) AS T2 ON T1.QuestionID = T2.questionid WHERE T1.SurveyID = 2019 AND T2.questionid = 3 AND... |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T1.SurveyID FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T1.SurveyID BETWEEN 2016 AND 2019 AND T2.questionid = 34 AND T1.AnswerText LIKE 'Yes' GROUP BY T1.SurveyID ORDER BY COUNT(T1.UserID) DESC LIMIT 1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(*) FROM ( SELECT T2.UserID FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID INNER JOIN Survey AS T3 ON T2.SurveyID = T3.SurveyID WHERE T3.Description = 'mental health survey for 2017' AND T1.questionid = 2 AND T2.AnswerText = 'Female' UNION SELECT T2.UserID FROM Question AS T1 I... |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T1.UserID) FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T2.questionid = 54 AND T1.AnswerText LIKE 'Yes'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT MAX(T1.AnswerText), MIN(T1.AnswerText) , ( SELECT T1.UserID FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T2.questionid = 1 ORDER BY T1.AnswerText LIMIT 1 ) AS "youngest id" FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T2.questionid = 1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T1.AnswerText FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T2.questionid = 3 GROUP BY T1.AnswerText ORDER BY COUNT(T1.UserID) DESC LIMIT 1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT CAST(SUM(T1.AnswerText) AS REAL) / COUNT(T1.UserID) FROM Answer AS T1 INNER JOIN ( SELECT T1.UserID FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T2.questionid = 3 AND T1.AnswerText = 'United States' ) AS T2 ON T1.UserID = T2.UserID INNER JOIN Question AS T3 ON T1.QuestionID ... |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT CAST(SUM(CASE WHEN T1.AnswerText LIKE 'Yes' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.UserID) FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid WHERE T2.questionid = 12; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(QuestionID) FROM Answer WHERE SurveyID LIKE 2014 GROUP BY QuestionID ORDER BY COUNT(QuestionID) > 200 LIMIT 1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T2.AnswerText FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T1.questiontext = 'What is your age?' AND T2.SurveyID = 2014 ORDER BY T2.AnswerText DESC LIMIT 1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T2.UserID) FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T1.questiontext = 'Would you bring up a mental health issue with a potential employer in an interview?' AND T2.SurveyID = 2014 AND T2.AnswerText LIKE 'NO'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T2.UserID FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T1.questiontext = 'Do you think that discussing a physical health issue with your employer would have negative consequences?' AND T2.AnswerText LIKE 'Yes' AND T2.SurveyID = 2014; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(DISTINCT T1.UserID) FROM Answer AS T1 INNER JOIN Survey AS T2 ON T1.SurveyID = T2.SurveyID WHERE T2.Description = 'mental health survey for 2014'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T2.AnswerText FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T1.questiontext = 'Any additional notes or comments' AND T2.SurveyID = 2014 AND T2.AnswerText <> -1; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T1.questiontext FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T2.SurveyID IN (2014, 2016) GROUP BY T1.questiontext; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T2.UserID) FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T2.SurveyID = 2018 AND T1.questiontext = 'What country do you live in?' AND T2.AnswerText = 'Canada'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT T2.questiontext FROM Answer AS T1 INNER JOIN Question AS T2 ON T1.QuestionID = T2.questionid INNER JOIN Survey AS T3 ON T1.SurveyID = T3.SurveyID WHERE T3.Description LIKE 'mental health survey for 2014' GROUP BY T2.questiontext; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T2.UserID) FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T2.SurveyID = 2016 AND T1.questiontext LIKE 'Have you had a mental health disorder in the past?' AND T2.AnswerText = 'Yes'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T2.UserID) FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T2.SurveyID IN (2016, 2017, 2018) AND T1.questiontext LIKE 'Have you had a mental health disorder in the past?' AND T2.AnswerText = 'Yes'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT CAST(SUM(T2.AnswerText) AS REAL) / COUNT(T2.UserID) AS "avg" FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T2.SurveyID = 2014 AND T1.questiontext LIKE 'What is your age?'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT CAST(( SELECT COUNT(T2.UserID) FROM Question AS T1 INNER JOIN Answer AS T2 ON T1.questionid = T2.QuestionID WHERE T2.SurveyID = 2019 AND T1.questiontext LIKE 'Do you currently have a mental health disorder?' AND T2.AnswerText = 'Yes' ) - ( SELECT COUNT(T2.UserID) FROM Question AS T1 INNER JOIN Answer AS T2 ON T1... |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT questionid FROM Question WHERE questiontext LIKE 'Would you bring up a physical health issue with a potential employer in an interview?'; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT MAX(UserID) - MIN(UserID) + 1 FROM Answer WHERE QuestionID = 20; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(QuestionID) FROM Answer WHERE UserID = 5; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(DISTINCT UserID) FROM Answer WHERE SurveyID LIKE 2016; |
[INST] Here is a database schema:
Question :
questiontext [ TEXT ]
questionid [ INTEGER ] primary_key
Survey :
SurveyID [ INTEGER ] primary_key
Description [ TEXT ]
Answer :
AnswerText [ TEXT ]
SurveyID [ INTEGER ]
UserID [ INTEGER ]
QuestionID [ INTEGER ]
Please write me a SQL statement that answers the following q... | SELECT COUNT(T1.QuestionID) FROM Answer AS T1 INNER JOIN Survey AS T2 ON T1.SurveyID = T2.SurveyID WHERE T2.Description = 'mental health survey for 2018'; |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.