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problem_description
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s220952302
p00022
Wrong Answer
n=int(input()) while(n!=0): index=0 list=[] sum=0 max=0 for i in range(n): list.append(int(input())) while (index < len(list) and list[index] < 0): index += 1 while (index < len(list) and list[index] >= 0): sum += list[index] index += 1 max=sum while(index<len(list)): plus_sum = 0 minus_sum = 0 while (index < len(list) and list[index] < 0): minus_sum += list[index] index += 1 while (index < len(list) and list[index] >= 0): plus_sum += list[index] index += 1 if abs(minus_sum)<plus_sum: sum+=(minus_sum+plus_sum) if max<sum: max=sum else: sum=plus_sum if max<sum: max=sum print(max) n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s484982120
p00022
Wrong Answer
n=int(input()) while(n!=0): index=0 list=[] sum=0 max=0 for i in range(n): list.append(int(input())) while (index < len(list) and list[index] < 0): sum += list[index] index += 1 max=sum sum=0 while (index < len(list) and list[index] >= 0): sum += list[index] index += 1 if sum>0: max=sum while(index<len(list)): plus_sum = 0 minus_sum = 0 while (index < len(list) and list[index] < 0): minus_sum += list[index] index += 1 while (index < len(list) and list[index] >= 0): plus_sum += list[index] index += 1 if abs(minus_sum)<plus_sum: sum+=(minus_sum+plus_sum) if max<sum: max=sum else: sum=plus_sum if max<sum: max=sum print(max) n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s758552678
p00022
Wrong Answer
n=int(input()) while(n!=0): index=0 list=[] sum=0 max=0 for i in range(n): list.append(int(input())) max=list[0] while (index < len(list) and list[index] < 0): if max<list[index]: max = list[index] index += 1 while (index < len(list) and list[index] >= 0): sum += list[index] index += 1 if sum>0: max=sum while(index<len(list)): plus_sum = 0 minus_sum = 0 while (index < len(list) and list[index] < 0): minus_sum += list[index] index += 1 while (index < len(list) and list[index] >= 0): plus_sum += list[index] index += 1 if abs(minus_sum)<plus_sum: sum+=(minus_sum+plus_sum) if max<sum: max=sum else: sum=plus_sum if max<sum: max=sum print(max) n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s677349725
p00022
Wrong Answer
n=int(input()) while(n!=0): index=0 list=[] sum=-1 max=0 for i in range(n): list.append(int(input())) max=list[0] while (index < len(list) and list[index] < 0): if max<list[index]: max = list[index] index += 1 while (index < len(list) and list[index] >= 0): sum += list[index] index += 1 if sum>=0: max=sum while(index<len(list)): plus_sum = 0 minus_sum = 0 while (index < len(list) and list[index] < 0): minus_sum += list[index] index += 1 while (index < len(list) and list[index] >= 0): plus_sum += list[index] index += 1 if abs(minus_sum)<plus_sum: sum+=(minus_sum+plus_sum) if max<sum: max=sum else: sum=plus_sum if max<sum: max=sum print(max) n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s769414390
p00022
Wrong Answer
n=int(input()) while(n!=0): index=0 list=[] sum=0 max=0 for i in range(n): list.append(int(input())) max=list[0] while (index < len(list) and list[index] < 0): if max<list[index]: max = list[index] index += 1 while (index < len(list) and list[index] >= 0): sum += list[index] index += 1 if sum>=0: max=sum while(index<len(list)): plus_sum = 0 minus_sum = 0 while (index < len(list) and list[index] < 0): minus_sum += list[index] index += 1 while (index < len(list) and list[index] >= 0): plus_sum += list[index] index += 1 if abs(minus_sum)<plus_sum: sum+=(minus_sum+plus_sum) if max<sum: max=sum else: sum=plus_sum if max<sum: max=sum print(max) n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s720024912
p00022
Wrong Answer
n=int(input()) while(n!=0): index=0 list=[] sum=0 max=0 break_flag=False for i in range(n): list.append(int(input())) max=list[0] while (index < len(list) and list[index] < 0): if max<list[index]: max = list[index] index += 1 if index==len(list): print(max) break_flag=True if not break_flag: while (index < len(list) and list[index] >= 0): sum += list[index] index += 1 if sum>=0: max=sum while(index<len(list)): plus_sum = 0 minus_sum = 0 while (index < len(list) and list[index] < 0): minus_sum += list[index] index += 1 while (index < len(list) and list[index] >= 0): plus_sum += list[index] index += 1 if abs(minus_sum)<plus_sum: sum+=(minus_sum+plus_sum) if max<sum: max=sum else: sum=plus_sum if max<sum: max=sum print(max) n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s999132310
p00022
Wrong Answer
if __name__ == '__main__': while True: # ??????????????\??? loop = int(input()) if loop == 0: break data = [int(input()) for _ in range(loop)] # ??????????????? max_total = 0 # ??£?¶?????????°???????????§????¨???? total = 0 for d in data: if d > 0: # ??°??????+??§????????°?????±????°???? total += d # ????¨?????¶???????????¨?????????´??°????????????????¢???????????????? if total > max_total: max_total = total else: # ??°??????-?????´?????????????????§????????£???????????????????????§?????????????????? if total > abs(d): # ???????????§??????????????????????????§????????°???total???????????????????¶??¶??????? total += d # ???????????????????????????????????§???max_total?????´??°??????????????§????????? else: total = 0 # ???????????????????????§??????????????????????????§??????????????§????¨??????????????????????????¬?????????????????????????????????? # ???????????¨??? print(max_total)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s844140537
p00022
Wrong Answer
n = int(input()) while n > 0: q = 0 m = 0 for j in range(n): i = int(input()) if q == 0: if i <= 0: continue else: q = i else: q += i if q < 0: q = 0 else: m = max(m,q) print(m) n = int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s436314548
p00022
Wrong Answer
n = int(input()) while n > 0: q = 0 m = 0 a = -100000 for j in range(n): i = int(input()) if i <= 0: a = max(a,i) if q == 0: if i <= 0: continue else: q = i else: q += i if q <= 0: q = 0 else: m = max(m,q) print(m if m > 0 else a) n = int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s706513649
p00022
Wrong Answer
n = int(input()) while n > 0: s = [] m = 0 for i in range(n): m += int(input()) s.append(m) print(max(s)) n = int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s320629973
p00022
Wrong Answer
n = int(input()) while n > 0: s = [0] m = 0 for i in range(n): m += int(input()) s.append(m) m = s[0] for i in range(1,n+1): for j in s[0:i]: m = max(m,s[i]-j) print(m) n = int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s465339022
p00022
Wrong Answer
while 1: n = int(raw_input()) if n==0: break max = 0 for i in range(n): tmax = max + int(raw_input()) if tmax > max: max = tmax print tmax
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s763485803
p00022
Wrong Answer
while 1: n = int(raw_input()) if n==0: break m = 0 pm = 0 for i in range(n): m += int(raw_input()) pm = max(m, pm) print pm
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s707611696
p00022
Wrong Answer
while True: n=int(input()) if n==0: break a=[int(input()) for i in range(n)] MAX=0 SUM=0 for i in a: SUM+=i MAX=max(MAX,SUM) if SUM<0: SUM=0 print(MAX)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s501522021
p00022
Wrong Answer
def solve0(v): w = [] for i in range(len(v)): for j in range(len(v[i:])): w.append(sum(v[i:(j+1)])) return(max(w)) def sign(x): if x >= 0: s=+1 else: s=-1 return(s) def solve(v): w = [] sig=sign(v[0]) x = v[0] for i in range(1,len(v)): if v[i] * sig >= 0: x += v[i] else: w.append(x) sig=sign(v[i]) x=v[i] w.append(x) # print(w) return(solve0(w)) if __name__ == "__main__": while True: n = int(input()) if n == 0: break v = [] for i in range(n): v.append(int(input())) print(solve(v))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s784328337
p00022
Wrong Answer
def solve0(v): w = [] for i in range(len(v)): for j in range(len(v[i:])): w.append(sum(v[i:(j+1)])) return(max(w)) def sign(x): if x >= 0: s=+1 else: s=-1 return(s) def solve(v): w = [] sig=sign(v[0]) x = v[0] for i in range(1,len(v)): if v[i]==0: continue elif v[i] * sig > 0: x += v[i] else: w.append(x) sig=sign(v[i]) x=v[i] w.append(x) # print(w) return(solve0(w)) if __name__ == "__main__": while True: n = int(input()) if n == 0: break v = [] for i in range(n): v.append(int(input())) print(solve(v))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s174980146
p00022
Wrong Answer
while True: n = int(input()) if n==0 : break a = [] for i in range(n): a.append(int(input())) maxp = 0 maxcont = 0 for i in range(n): maxcont = max(0, maxcont + a[i]) maxp = max(maxp, maxcont) print(maxp)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s988796563
p00022
Wrong Answer
while True: n = int(input()) if n==0 : break a = [] for i in range(n): a.append(int(input())) maxp = 0 maxcont = 0 for i in range(n): maxcont = max(a[i], maxcont + a[i]) maxp = max(maxp, maxcont) print(maxp)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s833863479
p00022
Wrong Answer
# -*- coding: utf-8 -*- import sys import os def max_seq(A): acc = max(0, A[0]) ans = max(0, A[0]) for i in range(1, len(A)): v = acc + A[i] if v < 0: # ???????????§???????????????acc??????????¶??????????????????? ans = max(ans, acc) # ???????????? acc = max(0, A[i]) else: acc = v ans = max(ans, acc) return ans while True: s = input().strip() if s == '0': break N = int(s) A = [] for i in range(N): v = int(input()) A.append(v) print(max_seq(A))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s093703212
p00022
Wrong Answer
# -*- coding: utf-8 -*- import sys import os def max_seq(A): acc = max(0, A[0]) ans = max(0, A[0]) for i in range(1, len(A)): v = acc + A[i] if v < 0: # ???????????§???????????????acc??????????¶??????????????????? ans = max(ans, acc) # ???????????? acc = max(0, A[i]) else: acc = v ans = max(ans, acc) return ans while True: s = input().strip() if s == '0': break N = int(s) A = [] for i in range(N): v = int(input()) A.append(v) print(max_seq(A))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s273150585
p00022
Wrong Answer
# -*- coding: utf-8 -*- import sys import os def max_seq(A): acc = max(0, A[0]) ans = max(0, A[0]) for i in range(1, len(A)): v = acc + A[i] if v < 0: # ???????????§???????????????acc??????????¶??????????????????? ans = max(ans, acc) # ???????????? acc = 0 else: # ??????????????£?????????????????§????????? acc = v ans = max(ans, acc) return ans while True: s = input().strip() if s == '0': break N = int(s) A = [] for i in range(N): v = int(input()) A.append(v) print(max_seq(A))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s953691088
p00022
Wrong Answer
while True: num = int(input()) if num == 0: break list = [] for i in range(num): list.append(int(input())) for i in range(1, num): list[i] = max(list[i - 1] + list[i], list[i]) print((list))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s049176488
p00022
Wrong Answer
import sys while True: n=int(input()) if n==0: sys.exit() sum_list=[0] for i in range(n): sum_list.append(sum_list[-1]+int(input())) maximum=0 for i in range(n): for j in range(i,n+1): maximum=max(maximum,sum_list[j]-sum_list[i]) if maximum==0: sum_list.pop(0) maximum=max(sum_list) print(maximum)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s776692209
p00022
Wrong Answer
import sys while True: n=int(input()) if n==0: sys.exit() a=[0] for i in range(n): a.append(int(input())+a[-1]) maximum=0 for i in range(n+1): for j in range(i): maximum=max(maximum,a[i]-a[j]) if maximum==0: b=a.copy() b.pop(0) maximum=max(b) print(maximum)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s337830965
p00022
Wrong Answer
from sys import stdin def getMax(array): mx = mx2 = array[0] for i in array[1:]: mx2 = max(i, mx2 + i) print(mx2,mx) mx = max(mx, mx2) return mx for line in stdin: n = int(line) if n == 0: break array = [] for line in stdin: line = int(line) array.append(line) if len(array) == n: break print(getMax(array))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s239873580
p00022
Wrong Answer
# Aizu Problem 0022: Maximum Sum Sequence # import sys, math, os # read input: PYDEV = os.environ.get('PYDEV') if PYDEV=="True": sys.stdin = open("sample-input.txt", "rt") def max_sum_subsequence(seq): maxsofar = 0 maxendinghere = 0 for s in seq: # invariant: maxendinghere and maxsofar are accurate # are accurate up to s maxendinghere = max(maxendinghere + s, 0) maxsofar = max(maxsofar, maxendinghere) return maxsofar while True: try: N = int(input()) except EOFError: break if N == 0: break seq = [int(input()) for _ in range(N)] print(max_sum_subsequence(seq))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s429424638
p00022
Wrong Answer
# Aizu Problem 0022: Maximum Sum Sequence # import sys, math, os # read input: PYDEV = os.environ.get('PYDEV') if PYDEV=="True": sys.stdin = open("sample-input.txt", "rt") def max_sum_subsequence(seq): maxsofar = 0 maxendinghere = 0 for s in seq: # invariant: maxendinghere and maxsofar are accurate # are accurate up to s maxendinghere = max(maxendinghere + s, 0) maxsofar = max(maxsofar, maxendinghere) return maxsofar while True: N = int(input()) if N == 0: break seq = [int(input()) for _ in range(N)] print(max_sum_subsequence(seq))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s835317942
p00022
Wrong Answer
# Aizu Problem 0022: Maximum Sum Sequence # import sys, math, os # read input: PYDEV = os.environ.get('PYDEV') if PYDEV=="True": sys.stdin = open("sample-input.txt", "rt") def max_sum_subsequence(seq): maxsofar = 0 maxendinghere = 0 for s in seq: # invariant: maxendinghere and maxsofar are accurate # are accurate up to s maxendinghere = max(maxendinghere + s, 0) maxsofar = max(maxsofar, maxendinghere) return max(maxsofar, max(seq)) while True: N = int(input()) if N == 0: break seq = [int(input()) for _ in range(N)] print(max_sum_subsequence(seq))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s392818319
p00022
Wrong Answer
while 1: n = input() if n == 0: break a = [] for i in range(n): k = input() a.append(k) print max([sum(a[i:(j+1)]) for i in range(7) for j in range(i,7)])
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s838378669
p00022
Wrong Answer
while 1: n = input() if n == 0: break a = [] sum = 0 for i in range(n): k = input() a.append(k) sum += k i = 0 j = n - 1 sums = [sum] while i != j: if a[i] < a[j]: sums.append(sums[-1] - a[i]) i += 1 else: sums.append(sums[-1] - a[j]) j -= 1 print max(sums)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s506768054
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] minv = maxv = tmp = 0 for i in range(n): tmp += a[i] maxv = max(maxv, tmp - minv) minv = min(minv, tmp) print(maxv)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s714573154
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] minv = tmp = 0 maxv = -50000 for i in range(n): tmp += a[i] maxv = max(maxv, tmp - minv) minv = min(minv, tmp) print(maxv)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s538674244
p00022
Wrong Answer
while True: n = int(input()) sumlist=[] sum=0 max=-10000 if n==0: break for i in range(n): sumlist.append(int(input())) for i in range(n): sum=0 for j in range(0,n-i): sum=sumlist[i+j]+sum if max<sum: max=sum print(max)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s348500559
p00022
Wrong Answer
while True: n = int(input()) sumlist=[] max=-100000 if n==0: break for i in range(n): sumlist.append(int(input())) sum=0 buf=0 for i in range(n): buf = sumlist[i]+buf if sumlist[i] > max: sum = sumlist[i] max = sumlist[i] buf = 0 if buf + sum > max: sum = sum+buf max=sum buf = 0 print(max)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s691580406
p00022
Wrong Answer
while True: n = int(input()) sumlist=[] max=-100000 if n==0: break for i in range(n): sumlist.append(int(input())) sum=0 buf=0 for i in range(n): buf = sumlist[i]+buf if buf + sum > max: sum = sum+buf max=sum buf = 0 if sumlist[i] > max: sum = sumlist[i] max = sumlist[i] buf = 0 print(max)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s363943138
p00022
Wrong Answer
while True: n = int(input()) sumlist=[] max=-100000 if n==0: break for i in range(n): sumlist.append(int(input())) sum=0 buf=0 for i in range(n): buf = sumlist[i]+buf if buf + sum > max: sum = sum+buf max=sum buf = 0 if sumlist[i] > max and (buf <= 0): sum = sumlist[i] max = sumlist[i] buf = 0 print(max)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s946431892
p00022
Wrong Answer
while True: n = int(input()) sumlist=[] max=-100000 if n==0: break for i in range(n): sumlist.append(int(input())) sum=0 buf=0 for i in range(n): buf = sumlist[i]+buf if sumlist[i] > max and (buf <= 0): sum = 0 max = sumlist[i] buf = 0 elif buf + sum > max: sum = sum+buf max=sum buf = 0 print(max)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s392714427
p00022
Wrong Answer
while True: n = int(input()) sumlist=[] max=-100000 if n==0: break for i in range(n): sumlist.append(int(input())) sum=0 buf=0 for i in range(n): buf = sumlist[i]+buf if buf + sum > max: sum = sum+buf if sum + buf > sumlist[i] else sumlist[i] max=sum buf = 0 elif sumlist[i] > max and (buf <= 0): sum = 0 max = sumlist[i] buf = 0 print(max)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s320548928
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break sum = 0 for _ in range(n): sum += max(int(input()), 0) print(sum)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s337215576
p00022
Wrong Answer
# coding: utf-8 # Your code here! n=int(input()) while n!=0: list=[0]*n for i in range(n): list.append(int(input())) a=0 b=0 for i in range(n): for j in range(n-i): a+=list[i+j] if b<a: b=a print a n=int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s925305747
p00022
Wrong Answer
while(1): a=[] n = int(input()) if n==0: break a=[int(input()) for i in range(n)] print(sum(a))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s806882858
p00022
Wrong Answer
while(1): a=[] result=0 n = int(input()) if n==0: break a=[int(input()) for i in range(n)] for i in range(n): if a[i]>=0: result=result+a[i] print(result)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s675535878
p00022
Wrong Answer
while(1): a=[] n = int(input()) if n==0: break a=[int(input()) for i in range(n)] result=0 for i in range(n): result1=a[i] if result<=a[i]: result=a[i] for j in range(i+1,n): result1=result1+a[j] if result<=result1: result=result1 print(result)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s965072142
p00022
Wrong Answer
# -*- coding:utf-8 -*- n = input() while n != 0: slist = [] for i in range(n): slist.append(input()) a = 0 b = 0 for i in range(n): for j in range(n - i): a += slist[i + j] if b < a: b = a a = 0 print b n = input()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s889801032
p00022
Wrong Answer
import math def sign(x): if x >= 0: return True else: return False n = int(input()) while n != 0: a = [] for i in range(n): a.append(int(input())) b = [] b.append(a[0]) for i in range(1,len(a)): if sign(b[len(b)-1]) == sign(a[i]): b[len(b)-1] = b[len(b)-1] + a[i] else: b.append(a[i]) ans = b[0] for i in range(len(b)): S = 0 for j in range(i,len(b)): S = S + b[j] ans = max(S, ans) print(ans) n = int(input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s490601978
p00022
Wrong Answer
while 1: n=int(input()) if n==0:break a=[int(input())for _ in[0]*n] for i in range(n-1):a[i]=max(a[i],a[i]+a[i-1]) print(max(a))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s834878451
p00022
Wrong Answer
while(1): N = int(input()) if N==0: break sums = [] s = 0 for i in range(N): s += int(input()) if s<0: s=0 sums.append(s) print(max(sums))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s618424577
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] d = [a[0]] for i in range(n): if d[0] == 0: d[0] += a[i] elif a[i] / d[-1] >= 0: d[-1] += a[i] else: d.append(a[i]) for i in range(2, len(d)): if d[i - 1] < 0 and d[i -2] > d[i - 1] and d[i] > d[i - 1]: d[i] += d[i -2] + d[i -1] print(max(d))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s326397709
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] d = [a[0]] for i in range(n): if d[0] == 0: d[0] += a[i] elif a[i] / d[-1] >= 0: d[-1] += a[i] else: d.append(a[i]) if d[0] < 0: d.pop(0) if d == []: print(max(a)) elif len(d) <= 2: print(max(d)) else: maxd = max(d) for i in range(0, len(d), 2): for j in range(i + 1, len(d) + 1, 2): maxd = max(maxd, sum(d[i:j])) print(maxd)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s964666548
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] d = [a[0]] for i in range(n): if d[0] == 0: d[0] += a[i] elif a[i] / d[-1] >= 0: d[-1] += a[i] else: d.append(a[i]) if len(d) <= 2: print(max(max(d), max(a))) else: if d[0] < 0: d.pop(0) maxd = max(d) for i in range(0, len(d), 2): for j in range(i + 1, len(d) + 1, 2): maxd = max(maxd, sum(d[i:j])) print(maxd)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s862102218
p00022
Wrong Answer
while True: INF = 10 ** 20 n = int(input()) if not n: break cum_sum = [0] acc = 0 for i in range(n): acc += int(input()) cum_sum.append(acc) ans = -INF for i in range(n): ans = max(ans, max(cum_sum[i:]) - cum_sum[i]) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s007008753
p00022
Wrong Answer
def max_sub(array): x = max(array[0], 0) ans = 0 for a in array[1:]: x = max(0, x+a) ans = max(ans, x) return ans while True: n = int(input()) if n == 0: break array = [int(input()) for _ in range(n)] print(max_sub(array))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s623030257
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break acc = int(input()) min_n = min(0, acc) max_n = acc ans = acc for _ in range(n - 1): acc += int(input()) min_n = min(min_n, acc) max_n = max(max_n, acc) ans = max(ans, max_n - min_n) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s400477637
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break acc = int(input()) min_n = min(0, acc) max_n = max(0, acc) ans = acc for _ in range(n - 1): acc += int(input()) min_n = min(min_n, acc) max_n = max(max_n, acc) ans = max(ans, max_n - min_n) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s581659428
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break acc = int(input()) min_n = acc max_n = acc ans = acc for _ in range(n - 1): acc += int(input()) min_n = min(min_n, acc) max_n = max(max_n, acc) ans = max(ans, max_n - min_n, max_n) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s436432050
p00022
Wrong Answer
while True: n = int(input()) if n == 0: break acc = int(input()) min_n = min(0, acc) max_n = acc ans = acc for _ in range(n - 1): acc += int(input()) max_n = max(max_n, acc) ans = max(ans, max_n - min_n) min_n = min(min_n, acc) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s254169443
p00022
Wrong Answer
#!/usr/bin/env python # -*- coding: utf-8 -*- import sys def solve(): while True: n = input() if n > 0: tmp_lst = [] for i in xrange(n): tmp_lst.append(input()) lst = compress(tmp_lst) accumurate_lst = calc_accumurate_lst(lst) max_value = 0 size = len(lst) for to in xrange(size): for frm in xrange(to + 1): value = accumurate_lst[to] if frm == 0 else accumurate_lst[to] - accumurate_lst[frm - 1] if max_value < value: max_value = value print max_value else: sys.exit() def calc_accumurate_lst(lst): accum = [0 for i in lst] accum[0] = lst[0] for i in xrange(1, len(lst)): accum[i] = accum[i - 1] + lst[i] return accum #同じ符号の数列は圧縮できる def compress(tmp_lst): lim = len(tmp_lst) #リスト圧縮 lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst if __name__ == "__main__": solve()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s904425058
p00022
Wrong Answer
#!/usr/bin/python from sys import stdin def datasets(): raw_input() for l in stdin: yield int(l) def main(): ds = datasets() first = next(ds) lastnum = count = maximum = first for n in ds: if n == lastnum: count += n else: if count > maximum: maximum = count count = n lastnum = n if __name__ == '__main__': main()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s156497475
p00022
Wrong Answer
while True: n = int(raw_input()) if n == 0: break numbers = [int(raw_input()) for i in range(n)] for i in range(n): ans = 0 tmp = 0 for j in range(i,n): tmp += j ans = max(ans,tmp) print ans
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s355707261
p00022
Wrong Answer
while True: n = int(raw_input()) if n == 0: break numbers = [int(raw_input()) for i in range(n)] ans = 0 for i in range(n): tmp = 0 for j in range(i,n): tmp += j ans = max(ans,tmp) print ans
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s565274918
p00022
Wrong Answer
while True: n = int(raw_input()) if n == 0: break numbers = [int(raw_input()) for i in range(n)] ans = 0 for i in range(n): tmp = 0 for j in range(i,n): tmp += numbers[j] ans = max(ans,tmp) print ans
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s416882001
p00022
Wrong Answer
while True: n = int(raw_input()) if n == 0: break numbers = [int(raw_input()) for i in range(n)] if max(numbers) <= 0: print max(numbers) ans = 0 for i in range(n): tmp = 0 for j in range(i,n): tmp += numbers[j] ans = max(ans,tmp) print ans
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s009942738
p00022
Wrong Answer
from __future__ import (absolute_import, division, print_function, unicode_literals) from sys import stdin while True: n = int(stdin.readline()) if not n: break tup = tuple(int(stdin.readline()) for _ in xrange(n)) L = [tup[0]] for i in tup[1:]: if 0 > i and 0 > L[-1]: L[-1] += i elif 0 <= i and 0 <= L[-1]: L[-1] += i else: L.append(i) while True: length = len(L) if length > 1 and L[0] <= 0: L.pop(0) continue if length > 1 and L[-1] <= 0: L.pop() continue if length > 1 and L[0] + L[1] <= 0: L.pop(0) L.pop(0) continue if length > 1 and L[-1] + L[-2] <= 0: L.pop() L.pop() continue if length > 2 and sum(L[:3]) >= L[2]: L[2] = sum(L[:3]) L.pop(0) L.pop(0) continue if length > 2 and sum(L[-3:]) >= L[-3]: L[-3] = sum(L[-3:]) L.pop(0) L.pop(0) continue break m = 0 for i in xrange(len(L)): for j in xrange(1 + i, len(L) + 1): t = sum(L[i:j]) if t > m: m = t print(m)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s057609169
p00022
Wrong Answer
from __future__ import (division, absolute_import, print_function, unicode_literals) from sys import stdin def grouping(nums): it = iter(nums) L = [next(nums)] minus = L[0] < 0 for n in it: if (n < 0 and minus) or (n >= 0 and not minus): L[-1] += n else: L.append(n) minus = not minus return L def collect(nl): result = 0 while len(nl) > 1: nl = grouping(nl[i] + nl[i+1] for i in xrange(0, len(nl), 2)) if len(nl) > 0 and nl[-1] <= 0: nl.pop() if len(nl) > 0 and nl[0] >= 0: result += nl[0] nl.pop(0) return result while True: n = int(stdin.readline()) if not n: break L = grouping(int(stdin.readline()) for _ in xrange(n)) if len(L) > 1 and L[0] <= 0: L.pop(0) if len(L) > 1 and L[-1] <= 0: L.pop() val = max(L) idx = L.index(val) val += collect(list(reversed(L[:idx]))) val += collect(L[idx+1:]) print(val)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s924602459
p00022
Wrong Answer
from __future__ import (division, absolute_import, print_function, unicode_literals) from sys import stdin def grouping(nums): it = iter(nums) try: L = [next(it)] except StopIteration: return [] minus = L[0] < 0 for n in it: if (n < 0 and minus) or (n >= 0 and not minus): L[-1] += n else: L.append(n) minus = not minus return L def collect(nl): result = 0 if len(nl) % 2 != 0: nl = grouping(nl) while len(nl) > 0: if len(nl) > 1: nl = grouping(nl[i] + nl[i+1] for i in xrange(0, len(nl), 2)) if len(nl) > 0 and nl[-1] <= 0: nl.pop() if len(nl) > 0 and nl[0] >= 0: result += nl[0] nl.pop(0) return result while True: n = int(stdin.readline()) if not n: break L = [int(stdin.readline()) for _ in xrange(n)] val = max(L) idx = L.index(val) if len(L[:idx]) > 1: val += collect(list(reversed(L[:idx]))) if len(L[idx+1:]) > 1: val += collect(L[idx+1:]) print(val)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s329216223
p00022
Wrong Answer
from __future__ import (division, absolute_import, print_function, unicode_literals) from sys import stdin from array import array def grouping(nums): sign = None L = array(b'i') for s, n in ((i < 0, i) for i in nums): if sign is s: L[-1] += n else: sign = s L.append(n) if len(L) and L[-1] <= 0: del L[-1] return L def collect(nl): result = 0 while True: nl = grouping(nl) if len(nl) and nl[0] >= 0: result += nl.pop(0) if not len(nl): return result nl = array(b'i', (nl[i] + nl[i+1] for i in xrange(0, len(nl), 2))) while True: n = int(stdin.readline()) if not n: break L = array(b'i', (int(stdin.readline()) for _ in xrange(n))) val = max(L) idx = L.index(val) Lprev = L[:idx] Lprev.reverse() Lnext = L[idx+1:] val += collect(Lprev) + collect(Lnext) print(val)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s275013456
p00022
Wrong Answer
from __future__ import (division, absolute_import, print_function, unicode_literals) from sys import stdin from array import array def grouping(nums): sign = None L = array(b'i') for s, n in ((i < 0, i) for i in nums): if sign is s: L[-1] += n else: sign = s L.append(n) if len(L) and L[-1] <= 0: del L[-1] return L def collect(nl): result = 0 while True: nl = grouping(nl) if len(nl) and nl[0] >= 0: result += nl.pop(0) if not len(nl): return result nl = array(b'i', (nl[i] + nl[i+1] for i in xrange(0, len(nl), 2))) while True: n = int(stdin.readline()) if not n: break L = array(b'i', (int(stdin.readline()) for _ in xrange(n))) val = max(L) if val <= 0: print(val) continue L = grouping(L) val = max(L) idx = L.index(val) Lprev = L[:idx] Lprev.reverse() Lnext = L[idx+1:] val += collect(Lprev) + collect(Lnext) print(val)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s379908934
p00022
Wrong Answer
while True: n = input() if n == 0: break else: nums = [] for val in range(1,n+1): num = int(raw_input()) nums.append(num) sums = [] for val in range(0,n): sums.append(nums[val-1]+nums[val]) sums.sort() sums.reverse() print sums[0] continue
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s985328093
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 lis = compress(lis) l = len(lis) max_val = 0 tmp_val = 0 for i in lis: tmp_val = max(0, tmp_val + i) max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] def compress(tmp_lst): lim = len(tmp_lst) lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s101653248
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 lis = compress(lis) l = len(lis) max_val = 0 tmp_val = 0 for i in xrange(0, l): tmp_val = 0 for j in xrange(i, l): tmp_val = tmp_val + lis[j] max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] def compress(tmp_lst): lim = len(tmp_lst) lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s321849401
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 # lis = compress(lis) l = len(lis) max_val = 0 tmp_val = 0 for i in xrange(0, l): tmp_val = 0 for j in xrange(i, l): tmp_val = tmp_val + lis[j] max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] #def compress(tmp_lst): # lim = len(tmp_lst) # lst = [] # index = 0 # while index < lim: # tmp = tmp_lst[index] # index += 1 # while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: # tmp += tmp_lst[index] # index += 1 # lst.append(tmp) # return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s662322279
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 lis = compress(lis) l = len(lis) max_val = 0 tmp_val = 0 for i in xrange(0, l): tmp_val = 0 for j in xrange(i, l): tmp_val = max(0, tmp_val + lis[j]) max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] def compress(tmp_lst): lim = len(tmp_lst) lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s581530294
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 lis = compress(lis) l = len(lis) max_val = 0 for i in xrange(0, l): # tmp_val = 0 for j in xrange(i, l): if j == i: tmp_val = lis[j] else: tmp_val = max(0, tmp_val + lis[j]) max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] def compress(tmp_lst): lim = len(tmp_lst) lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s438768441
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 lis = compress(lis) l = len(lis) max_val = 0 for i in xrange(0, l): # tmp_val = 0 for j in xrange(i, l): if j == i: tmp_val = lis[j] else: tmp_val = max(tmp_val, tmp_val + lis[j]) max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] def compress(tmp_lst): lim = len(tmp_lst) lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s973360559
p00022
Wrong Answer
import sys def max_sum_seq(lis): m = 0 lis = compress(lis) l = len(lis) max_val = 0 for i in xrange(0, l): # tmp_val = 0 for j in xrange(i, l): if j == i: tmp_val = lis[j] else: # tmp_val = max(tmp_val, tmp_val + lis[j]) tmp_val = tmp_val + lis[j] max_val = max(max_val, tmp_val) return max_val #def every_slice(lis, n): # l = len(lis) # for i in range(l-n+1): # yield lis[i:i+n] def compress(tmp_lst): lim = len(tmp_lst) lst = [] index = 0 while index < lim: tmp = tmp_lst[index] index += 1 while tmp > 0 and index < lim and tmp * tmp_lst[index] > 0: tmp += tmp_lst[index] index += 1 lst.append(tmp) return lst while True: n = int(sys.stdin.readline()) if n == 0: break lis = [] for i in range(n): lis.append(int(sys.stdin.readline())) print max_sum_seq(lis)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s798137281
p00022
Wrong Answer
while True: n = int(raw_input()) if n == 0: break sumn = 0 for i in range(n): sumn += int(raw_input()) print sumn
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s919529454
p00022
Wrong Answer
#!/usr/bin/python # -*- coding: utf-8 -*- def main(): while True: terms = int(raw_input()) if terms == 0: break data = [] for i in xrange(terms): data.append(int(raw_input())) print(max_sum_sequence(data)) def max_sum_sequence(data): max = 0 num_data = len(data) for l in xrange(num_data + 1): sum = max_at_length(data, l) if sum > max: max = sum return max def max_at_length(data, length): max = 0 num_data = len(data) first = 0 before = None for begin in xrange(num_data): sum = 0 if begin > 0: first = data[begin - 1] if before is None: for i in xrange(begin, begin + length): if i >= num_data: continue sum += data[i] else: if begin + length + 1 < num_data: sum = before - first + data[begin + length + 1] else: sum = before - first; before = sum if sum > max: max = sum return max main()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s122320434
p00022
Wrong Answer
#!/usr/bin/python # -*- coding: utf-8 -*- import sys def main(): while True: try: num_data = int(raw_input()) if num_data == 0: break data = [] for i in xrange(num_data): data.append(int(raw_input())) max = max_sum_sequence(data) print(max) except: break def max_sum_sequence(data): max = 0 num_data = len(data) for l in xrange(1, num_data + 1): #print ("testing at l = " + str(l) + "..") sum = max_at_length(data, l) if sum > max: max = sum return max def max_at_length(data, length): max = 0 num_data = len(data) sum = None old_head = 0 #print "length = " + str(length) while True: if sum is None: sum = 0 for i in xrange(0, length): sum += data[i] #print "initial = " + str(sum) max = sum else: if old_head + length < num_data: #print "sum = %d - %d + %d" % (sum, data[old_head], data[old_head + length]) sum = sum - data[old_head] + data[old_head + length] #print " = " + str(sum) if sum > max: max = sum old_head += 1 else: break return max main()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s217049956
p00022
Wrong Answer
#!/usr/bin/python def main(): while True: try: num_data = int(raw_input()) if num_data == 0: break data = [] for i in xrange(num_data): data.append(int(raw_input())) max = max_sum_sequence(data) print(max) except: break def max_sum_sequence(data): max = 0 num_data = len(data) for l in xrange(1, num_data + 1): # print ("testing at l = " + str(l) + "..") sum = max_at_length(data, l) if sum > max: max = sum return max def max_at_length(data, length): max = 0 num_data = len(data) sum = None old_head = 0 #print "length = " + str(length) while True: if sum is None: sum = 0 for i in xrange(0, length): sum += data[i] #print "initial = " + str(sum) max = sum else: if old_head + length < num_data: #print "sum = %d - %d + %d" % (sum, data[old_head], data[old_head + length]) sum = sum - data[old_head] + data[old_head + length] #print " = " + str(sum) if sum > max: max = sum old_head += 1 else: break return max main()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s347975589
p00022
Wrong Answer
while True: n = int(raw_input()) if n == 0: break a=[] for i in range(n): a.append(int(raw_input())) max = -1e10 for i in range(len(a)): sum = 0 for j in range(i+1,len(a)): sum += a[j] if sum > max: max = sum print max
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s014436863
p00022
Wrong Answer
n=input() while n: x=0 m=0 s=0 while n: a=input() x=max(x,0)+a m=max(m,x) n-=1 print m n=input()
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s812635844
p00022
Wrong Answer
n = int(raw_input()) while n > 0: a = [] for i in range(n): a.append(int(raw_input())) print max(a) n = int(raw_input())
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s242800549
p00022
Wrong Answer
n = int(raw_input()) ans = [] while n > 0: a = [] for i in range(n): a.append(int(raw_input())) ans.append(sum(a)) n = int(raw_input()) for i in ans: print i
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s651738606
p00022
Time Limit Exceeded
while 1: n=int(input()) if n==0:break nlist=[] nans=[] for i in range(n): nlist.append(int(input())) for j in range(i+1): nn=0 for k in range(j,i+1): nn+=nlist[k] nans.append(nn) print(max(nans))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s472481064
p00022
Time Limit Exceeded
while 1: n=int(input()) if n==0:break nlist=[] nans=-100001 for i in range(n): nlist.append(int(input())) for j in range(i+1): nn=0 for k in range(j,i+1): nn+=nlist[k] if nans<nn:nans=nn print(nans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s300784333
p00022
Time Limit Exceeded
#!/usr/bin/env python # -*- coding: utf-8 -*- import sys lis = [] lis2 = [] def sum(lis): s = 0 for e in lis: s += e return s while True: num = input() if num == 0: break else: lis = [] lis2 = [] for i in range(num): lis.append(input()) for i in range(len(lis)): for j in range(i+1,len(lis)+1): lis2.append(sum(lis[i:j])) print max(lis2)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s712637475
p00022
Time Limit Exceeded
#!/usr/bin/env python # -*- coding: utf-8 -*- import sys lis = [] lis2 = [] def sum(lis): s = 0 for e in lis: s += e return s while True: num = input() if num == 0: break else: lis = [] lis2 = [] maxnum = -99999 for i in range(num): lis.append(input()) for i in range(len(lis)): for j in range(i+1,len(lis)+1): su = sum(lis[i:j]) if su > maxnum: maxnum = su print maxnum
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s026663111
p00022
Time Limit Exceeded
#!/usr/bin/env python # -*- coding: utf-8 -*- n = [] a = [] i = 0 while True: n.append(int(input())) if n[i] == 0: break for j in range(0,n[i]): a.append(int(input())) i += 1 for i in range(0,len(n)): sumMax = 0 for j in range(sum(n[0:i-1 if i != 0 else 0]),sum(n[0:i])): for k in range(j,sum(n[0:i])+1): if j==k: continue sumMax = max(sumMax,sum(a[j:k])) print(sumMax)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s268918548
p00022
Time Limit Exceeded
while True: n = int(input()) if n == 0: break a = [] for i in range(n): a.append(int(input())) m = 0 for i in range(0, len(a)): for j in range(i + 1, len(a) + 1): m = max(m, sum(a[i:j])) print(m)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s887898462
p00022
Time Limit Exceeded
import sys while 1: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] sums = [] for i in range(len(a)+1): for j in range(i, len(a)+1): sums.append(sum(a[i:j])) print(max(sums))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s157727009
p00022
Time Limit Exceeded
import sys while 1: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] sumMax = 0 for i in range(len(a)+1): for j in range(i, len(a)+1): if sum(a[i:j]) > 0: sumMax = sum(a[i:j]) print(sumMax)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s005178424
p00022
Time Limit Exceeded
import sys while 1: n = int(input()) if n == 0: break a = [int(input()) for _ in range(n)] sumMax = 0 for i in range(len(a)+1): for j in range(i, len(a)+1): if sum(a[i:j]) > sumMax: sumMax = sum(a[i:j]) print(sumMax)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s579445892
p00022
Time Limit Exceeded
def take(n, iterable): start, end = 0, n while True: chunk = iterable[start:end] if len(chunk) < n: raise StopIteration() yield chunk start += 1 end += 1 while True: num = int(input()) if not num: break data = [int(input()) for _ in range(num)] print(max((sum(chunk) for i in range(1,num+1) for chunk in take(i, data))))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s522884803
p00022
Time Limit Exceeded
while True: n = int(input()) if n == 0: break else: a = [int(input()) for i in range(n)] ans = a[0] for j in range(n): for k in range(n): ans = max(ans, sum(a[j:k + 1])) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s559160399
p00022
Time Limit Exceeded
while True: n=int(input()) if n==0: break A=[] for i in range(n): A.append(int(input())) MAX=[0]*(len(A)) for i in range(len(A)): for j in range(i,len(A)+1): if MAX[i]<sum(A[i:j]): MAX[i]=sum(A[i:j]) MAX.sort(reverse=True) print(MAX[0])
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s509029296
p00022
Time Limit Exceeded
while True: n=int(input()) if n==0: break A=[] for i in range(n): A.append(int(input())) MAX=[0]*(len(A)) end=len(A) for i in range(end): for j in range(i+1,end+1): if MAX[i]<sum(A[i:j]): MAX[i]=sum(A[i:j]) MAX.sort() print(MAX[-1])
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s631840143
p00022
Time Limit Exceeded
while True: n=int(input()) if n==0: break A=[] for i in range(n): A.append(int(input())) MAX=[0]*(len(A)) end=len(A) for i in range(end): for j in range(i+1,end+1): s=sum(A[i:j]) if MAX[i]<s: MAX[i]=s print(max(MAX))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s092400143
p00022
Time Limit Exceeded
while True: n=int(input()) if n==0: break A=[] for i in range(n): A.append(int(input())) end=len(A) MAX=[0]*end for i in range(end): for j in range(i+1,end+1): s=sum(A[i:j]) if MAX[i]<s: MAX[i]=s print(max(MAX))
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s721426937
p00022
Time Limit Exceeded
while 1: n=input() if n==0: break else: a=[input() for _ in xrange(n)] ans=-float('inf') for i in xrange(n): for j in xrange(i,n): if ans<sum(a[i:j+1]): ans=sum(a[i:j+1]) print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>
s588126748
p00022
Time Limit Exceeded
while 1: n=input() if n==0: break else: a=[input() for _ in xrange(n)] ans=-float('inf') for i in xrange(n): for j in xrange(i,n): suma=sum(a[i:j+1]) if ans<suma: ans=suma print(ans)
7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0
19 14 1001
<H1>Maximum Sum Sequence</H1> <p> Given a sequence of numbers <var>a<sub>1</sub></var>, <var>a<sub>2</sub></var>, <var>a<sub>3</sub></var>, ..., <var>a<sub>n</sub></var>, find the maximum sum of a contiguous subsequence of those numbers. Note that, a subsequence of one element is also a <i>contiquous</i> subsequence. </p> <H2>Input</H2> <p> The input consists of multiple datasets. Each data set consists of: <pre> <var>n</var> <var>a<sub>1</sub></var> <var>a<sub>2</sub></var> . . <var>a<sub>n</sub></var> </pre> <p> You can assume that 1 &le; <var>n</var> &le; 5000 and -100000 &le; <var>a<sub>i</sub></var> &le; 100000. </p> <p> The input end with a line consisting of a single 0. </p> <H2>Output</H2> <p> For each dataset, print the maximum sum in a line. </p> <H2>Sample Input</H2> <pre> 7 -5 -1 6 4 9 -6 -7 13 1 2 3 2 -2 -1 1 2 3 2 1 -2 1 3 1000 -200 201 0 </pre> <H2>Output for the Sample Input</H2> <pre> 19 14 1001 </pre>