submission_id string | problem_id string | status string | code string | input string | output string | problem_description string |
|---|---|---|---|---|---|---|
s189868088 | p00004 | Wrong Answer | while 1:
try:
a,b,c,d,e,f=map(int,raw_input().split())
x=float(c*e-b*f)/(a*e-b*d)
y=(c-a*x)/float(b)
print "%.3f %.3f"%(x,y)
except:break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s687751811 | p00004 | Wrong Answer | import sys
for l in sys.stdin:
a,b,c,d,e,f=map(float,l.split())
x=(f-e*c/b)/(d-e*a/b)
y=(a*x-c)/b
print "%.3f %.3f" % (x,-y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s247457770 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = map(float, line.split())
print(a, b, c, d, e, f)
print('{0:.3f} {1:.3f}'.format(
(e * c - f * b) / (e * a - d * b), (d * c - f * a) / (d * b - e * a))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s767779811 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = map(float, line.split())
print('{0:.3f} {1:.3f}'.format(
(e * c - f * b) / (e * a - d * b), (d * c - f * a) / (d * b - e * a))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s281959449 | p00004 | Wrong Answer | # -*- coding: utf-8 -*-
import sys
import os
for s in sys.stdin:
a, b, c, d, e, f = list(map(int, s.split()))
delta = a * e - b * d
x = 1 / delta * (e * c - b * f)
y = 1 / delta * (-d * c + a * f)
print(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s319446670 | p00004 | Wrong Answer | # -*- coding: utf-8 -*-
import sys
import os
for s in sys.stdin:
a, b, c, d, e, f = list(map(int, s.split()))
delta = a * e - b * d
x = 1 / delta * (e * c - b * f)
y = 1 / delta * (-d * c + a * f)
print(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s883594250 | p00004 | Wrong Answer | # -*- coding: utf-8 -*-
import sys
import os
for s in sys.stdin:
a, b, c, d, e, f = list(map(int, s.split()))
delta = a * e - b * d
x = 1 / delta * (e * c - b * f)
y = 1 / delta * (-d * c + a * f)
print('{:.3f} {:.3f}'.format(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s774766870 | p00004 | Wrong Answer | # -*- coding: utf-8 -*-
import sys
import os
for s in sys.stdin:
a, b, c, d, e, f = list(map(int, s.split()))
delta = a * e - b * d
if delta == 0:
break
else:
x = 1 / delta * (e * c - b * f)
y = 1 / delta * (-d * c + a * f)
print('{:.3f} {:.3f}'.format(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s036724378 | p00004 | Wrong Answer | def my_func(a):
ans1=(a[2]*a[4]-a[1]*a[5])/(a[0]*a[4]-a[1]*a[3])
ans2=(-a[3]*a[2]+a[0]*a[5])/(a[0]*a[4]-a[1]*a[3])
print ans1,ans2
while True:
try:
splited = map(float, raw_input().split())
my_func(splited)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s032670490 | p00004 | Wrong Answer | def mul4(v1, v2, v3, v4):
return (v1 * v2) - (v3 * v4)
for d in [input().split() for _ in range(2)]:
a, b, e, c, d, f = tuple(map(float, d))
det = mul4(a, d, c, b)
print("{:.3f} {:.3f}".format(
mul4(d, e, b, f) / det or 0.0,
-mul4(c, e, a, f) / det or 0.0)
) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s969688705 | p00004 | Wrong Answer | while True:
try:
a,b,c,d,e,f = map(float,raw_input().split())
x = ( e*c - b*f ) / ( e*a - b*d )
y = ( c*d - a*f ) / ( b*d - e*a )
print '%.3f %.3f' % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s403827433 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
nums = line.split(" ")
a, b, e, c, d, f = int(nums[0]),int(nums[1]),int(nums[2]),int(nums[3]),int(nums[4]),int(nums[5])
print('{0:.3f} {1:.3f}'.format((e*d-b*f)/(a*d-b*c), (a*f-e*c)/(a*d-b*c))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s729901417 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
nums = line.split(" ")
a, b, e, c, d, f = int(nums[0]),int(nums[1]),int(nums[2]),int(nums[3]),int(nums[4]),int(nums[5])
print('{0:.3f} {1:.3f}'.format(round((e*d-b*f)/(a*d-b*c),3), round((a*f-e*c)/(a*d-b*c),3))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s323247258 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
nums = line.split(" ")
a, b, e, c, d, f = int(nums[0]),int(nums[1]),int(nums[2]),int(nums[3]),int(nums[4]),int(nums[5])
print('{0:.3f} {1:.3f}'.format(round((e*d-b*f)/(a*d-b*c),4), round((a*f-e*c)/(a*d-b*c),4))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s238892799 | p00004 | Wrong Answer | # coding: utf-8
# Here your code !
import sys
for line in sys.stdin:
nums = line.split(" ")
a, b, e, c, d, f = int(nums[0]),int(nums[1]),int(nums[2]),int(nums[3]),int(nums[4]),int(nums[5])
print('{0:.3f} {1:.3f}'.format(round((e*d-b*f)/(a*d-b*c),4), round((a*f-e*c)/(a*d-b*c),4))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s596574302 | p00004 | Wrong Answer | def main():
def get_inputs():
li = []
try:
while True:
li.append(input())
except EOFError:
return li
li = get_inputs()
for str_num in li:
tmp = str_num.split(" ")
for i in range(len(tmp)):
tmp[i] = int(tmp[i])
a,b,c,d,e,f = tmp[0],tmp[1],tmp[2],tmp[3],tmp[4],tmp[5]
x = (c*e - b*f) / (a*e - b*d)
x = round(x, 3)
y = (c*d - a*f) / (b*d - a*e)
y = round(y, 3)
print("{} {}".format(x,y))
return None
if __name__ == '__main__':
main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s355761907 | p00004 | Wrong Answer | import sys
while True:
line = sys.stdin.readline()
if not line:
break
a,b,c,d,e,f = map(int, line.rstrip().split(' '))
x = (f - c*e/b)/(d - a*e/b)
y = (f - d*c/a)/(e - b*d/a)
print("{:.3f} {:.3f}".format(round(x,3),round(y,3))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s609134289 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a,b,c,d,e,f = map(float, line.rstrip().split(' '))
x = round((b*f-c*e)/(b*d-a*e), 3)
y = round((a*f-d*c)/(a*e-b*d), 3)
print("{:.3f} {:.3f}".format(x,y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s286631543 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
try:
a,b,c,d,e,f = map(float, line.rstrip().split(' '))
x = round((b*f-c*e)/(b*d-a*e), 3)
y = round((a*f-d*c)/(a*e-b*d), 3)
print("{:.3f} {:.3f}".format(x,y))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s526418112 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
try:
a,b,c,d,e,f = map(float, line.rstrip().split(' '))
x = (b*f-c*e)/(b*d-a*e)
y = (a*f-d*c)/(a*e-b*d)
print("{:.3f} {:.3f}".format(x,y))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s449917297 | p00004 | Wrong Answer | import fileinput
for line in fileinput.input():
v = [int(i) for i in line.split(" ")]
x = (v[2] * v[4] - v[1] * v[5]) / (v[0] * v[4] - v[1] * v[3])
y = (v[2] * v[3] - v[0] * v[5]) / (v[1] * v[3] - v[0] * v[4])
print("%.3f" % x, "%.3f" % y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s434708739 | p00004 | Wrong Answer | import fileinput
if __name__ == "__main__":
for line in fileinput.input():
v = [int(i) for i in line.split(" ")]
x = (v[2] * v[4] - v[1] * v[5]) / (v[0] * v[4] - v[1] * v[3])
y = (v[2] * v[3] - v[0] * v[5]) / (v[1] * v[3] - v[0] * v[4])
print("%.3f" % x, "%.3f" % y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s557776072 | p00004 | Wrong Answer | import fileinput
if __name__ == "__main__":
for line in fileinput.input():
v = [int(i) for i in line.split(" ")]
x = (v[2] * v[4] - v[1] * v[5]) / (v[0] * v[4] - v[1] * v[3])
y = (v[2] * v[3] - v[0] * v[5]) / (v[1] * v[3] - v[0] * v[4])
print(format(x, ".3f"), format(y, ".3f")) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s872671002 | p00004 | Wrong Answer | import fileinput
if __name__ == "__main__":
for line in fileinput.input():
v = [int(i) for i in line.split(" ")]
x = (v[2] * v[4] - v[1] * v[5]) / (v[0] * v[4] - v[1] * v[3])
y = (v[2] * v[3] - v[0] * v[5]) / (v[1] * v[3] - v[0] * v[4])
print(format(x, ".3f"), format(y, ".3f")) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s751891343 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a,b,c,d,e,f = map(int,line.strip().split(' '))
x = (c*e - b*f) / (a*e - b*d)
y = (c*d - a*f) / (b*d - a*e)
print("{:.3f} {:.3f}".format(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s158364839 | p00004 | Wrong Answer | import sys
strs = sys.stdin.readlines()
for s in strs:
a, b, c, d, e, f = map(int, s.split())
print('{:.3f} {:.3f}'.format((c*e - b*f) / (a*e - b*d), (a*f - c*d) / (a*e - b*d))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s987902221 | p00004 | Wrong Answer | import sys
strs = sys.stdin.readlines()
for s in strs:
a, b, c, d, e, f = map(float, s.split())
print('{:.3f} {:.3f}'.format((c*e - b*f) / (a*e - b*d), (a*f - c*d) / (a*e - b*d))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s648947711 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = map(float, line.split())
print('{:.3f} {:.3f}'.format((c*e - b*f) / (a*e - b*d), (a*f - c*d) / (a*e - b*d))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s246620449 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = list(map(int, line.split()))
delta = (a*e - b*d)
x = 1/delta * (e*c - b*f)
y = 1/delta * (-d*c + a*f)
print("%.3f %.3f"%(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s178681613 | p00004 | Wrong Answer | def get_input():
while True:
try:
yield ''.join(input())
except EOFError:
break
input_list = list(get_input()) # [a1, a2, a3, ...]
for line in input_list:
a, b, c, d, e, f = list(map(int, line.split()))
delta = (a*e - b*d)
x = 1/delta * (e*c - b*f)
y = 1/delta * (-d*c + a*f)
print("%.3f %.3f"%(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s412936042 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = map(float, line.split())
x = (c * e - f * b) / (a * e - d * b)
y = (c * d - f * a) / (b * d - e * a)
print('{0:.3f} {1:.3f}'.format(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s793072559 | p00004 | Wrong Answer | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
import sys
import math
def my_round(x):
xx = 1000*x
f, _ = math.modf(xx)
if f >= 0.5:
xx += 1
return xx / 1000
def main():
for line in sys.stdin:
a, b, c, d, e, f = map(float, line.split())
det = a*e - b*d
x = ( e*c - b*f) / det
y = (-d*c + a*f) / det
xr = my_round(x)
yr = my_round(y)
print("{:.3f} {:.3f}".format(x, y))
if __name__ == "__main__": main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s713928263 | p00004 | Wrong Answer | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
import sys
import math
def my_round(x):
xx = 1000*x
f, i = math.modf(xx)
print(f,i)
if f < 0.0 and f <= -0.5:
i -= 1
if f >= 0.0 and f >= 0.5:
i += 1
return i/1000
def main():
for line in sys.stdin:
a, b, c, d, e, f = map(float, line.split())
det = a*e - b*d
x = ( e*c - b*f) / det
y = (-d*c + a*f) / det
xr = my_round(x)
yr = my_round(y)
print("{:.3f} {:.3f}".format(x, y))
if __name__ == "__main__": main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s959631678 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a,b,c,d,e,f=list(map(int,line.split()))
x=(c*e-b*f)/(a*e-b*d)
y=(a*f-c*d)/(a*e-b*d)
print("{0:.3f} {1:.3f}".format(x,y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s653285906 | p00004 | Wrong Answer | while True:
try:
a, b, c, d, e, f = map(float, input().split())
except:
break
y = (c*d-f*a) / (b*d-e*a)
x = (c - b*y) / a
print(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s533824645 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = list(map(float, line.split()))
x = (c * e - b * f) / (a * e - b * d)
y = (a * f - c * d) / (a * e - b * d)
print("{0:.3f} {1:.3f}") | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s123288616 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
a, b, c, d, e, f = list(map(float, line.split()))
x = (c * e - b * f) / (a * e - b * d)
y = (a * f - c * d) / (a * e - b * d)
print("{0:.3f} {1:.3f}".format(x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s389602459 | p00004 | Wrong Answer | try:
s = []
while True:
l = list(map(float, input().split()))
x = (l[2] * l[4] - l[5] * l[1]) / (l[0] * l[4] - l[3] * l[1])
y = (l[2] - l[0] * x) / l[1]
x_2 = "{0:.3f}".format(x)
y_2 = "{0:.3f}".format(y)
print(str(x_2) + " " + str(y_2))
except EOFError:
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s768407074 | p00004 | Wrong Answer | while 1:
try:
a,b,c,d,e,f=[int(i) for i in input().split()]
y=float((c*d-f*a)/(b*d-e*a))
x=float((c-b*y)/a)
print("{0:.4f}".format(x)," ","{0:.4f}".format(y))
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s178450355 | p00004 | Wrong Answer | while 1:
try:
a,b,c,d,e,f=[int(i) for i in input().split()]
y=float((c*d-f*a)/(b*d-e*a))
x=float((c-b*y)/a)
print("{0:.4f}".format(x),"{0:.4f}".format(y))
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s038248711 | p00004 | Wrong Answer | import sys
for s in list(sys.stdin):
a,b,e,c,d,f = list(map(float,s.split()))
base = a*d-b*c
x = e*d-b*f
y = a*f-e*c
print('%.3f %.3f' % (x/base,y/base)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s149497881 | p00004 | Wrong Answer | import sys
def main():
""" ????????? """
istr = sys.stdin.read()
wi = istr.splitlines()
for i in wi:
a, b, c, d, e, f = list(map(int,i.split()))
z = (a * e - b * d)
x = round((c * e - b * f) / z, 3)
y = round((a * f - c * d) / z, 3)
print("{0:.3f} {1:.3f}".format(x,y))
if __name__ == '__main__':
main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s659832701 | p00004 | Wrong Answer | import sys
for line in sys.stdin.readlines():
#for line in data.split('\n'):
a,b,c,d,e,f = [int(s) for s in line.split()]
x = (c*e-b*f) / (a*e-b*d)
y = (c*d-a*f) / (b*d-a*e)
print('{0:.3f} {1:.3f}'.format(x,y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s012178904 | p00004 | Wrong Answer | # Aizu Problem 0004: Simultaneous Equation
#
import sys, math, os
# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
sys.stdin = open("sample-input.txt", "rt")
for line in sys.stdin:
a, b, c, d, e, f = [int(_) for _ in line.split()]
det = a * e - b * d
det1 = c * e - b * f
det2 = a * f - c * d
x = round(det1 / det, 3)
y = round(det2 / det, 3)
#if -.001 < x < 0:
# x = 0
print("%.3f %.3f" % (x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s672444894 | p00004 | Wrong Answer | import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[int(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])
x = (l[2]-l[1]*y)/l[0]
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s801025888 | p00004 | Wrong Answer | import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])
x = (l[2]-l[1]*y)/l[0]
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s211800652 | p00004 | Wrong Answer | import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])
x = (l[2]*l[4]-l[5]*l[1])/(l[0]*l[4]-l[3]*l[1])
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s365017739 | p00004 | Wrong Answer | # coding: utf-8
# Here your code !
import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
print(l)
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])+0
x = (l[2]*l[4]-l[5]*l[1])/(l[0]*l[4]-l[3]*l[1])+0
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s053609116 | p00004 | Wrong Answer | # coding: utf-8
# Here your code !
import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])+0
x = (l[2]*l[4]-l[5]*l[1])/(l[0]*l[4]-l[3]*l[1])+0
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s989145382 | p00004 | Wrong Answer |
import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])+0
x = (l[2]*l[4]-l[5]*l[1])/(l[0]*l[4]-l[3]*l[1])+0
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s233786287 | p00004 | Wrong Answer |
import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])+0
x = (l[2]*l[4]-l[5]*l[1])/(l[0]*l[4]-l[3]*l[1])+0
print("%.3f %.3f" %(x, y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s362373964 | p00004 | Wrong Answer |
import sys
import math
r = sys.stdin.readlines()
r.pop(0)
n = [[float(i) for i in (j.split())] for j in r]
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])+0
x = (l[2]*l[4]-l[5]*l[1])/(l[0]*l[4]-l[3]*l[1])+0
print("%.3f %.3f" %(x, y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s104375899 | p00004 | Wrong Answer | try:
while True:
a,b,c,d,e,f=map(int, input().split())
print( (c*e-b*f)/(a*e-b*d), (a*f-c*d)/(a*e-b*d) )
except EOFError:
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s783096777 | p00004 | Wrong Answer | try:
while True:
a,b,c,d,e,f=map(int, input().split())
print( "{0:.3f}".format(round((c*e-b*f)/(a*e-b*d),3)), "{0:.3f}".format(round((a*f-c*d)/(a*e-b*d),3)) )
except EOFError:
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s031263256 | p00004 | Wrong Answer | try:
while True:
a,b,c,d,e,f=map(int, input().split())
print( "{0:.3f}".format(round((c*e-b*f)/(a*e-b*d),4)), "{0:.3f}".format(round((a*f-c*d)/(a*e-b*d),4)) )
except EOFError:
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s414391058 | p00004 | Wrong Answer | try:
while True:
a,b,c,d,e,f=map(float, input().split())
x=(c*e-b*f)/(a*e-b*d)
y=(a*f-c*d)/(a*e-b*d)
x=round(x,3)
y=round(y,3)
print("{0:.3f}".format(x),"{0:.3f}".format(y))
except EOFError:
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s634413806 | p00004 | Wrong Answer | import math
import sys
while True:
try:
a,b,c,d,e,f = map(float, input().split())
if a*e == b*d:
continue
x = (c*e - b*f)/(a*e - b*d)
y = (c*d - a*f)/(b*d - a*e)
print('{0:.3f} {1:.3f}'.format(x,y))
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s575663779 | p00004 | Wrong Answer | from __future__ import division
import sys
# ad*x + bd*y = cd
# -)ad*x + ae*y = af
# (bd-ae)*y = cd-af
# and so on...
while True:
try:
a, b, c, d, e, f = map(float, raw_input().split())
except:
break
x = (c*e - b*f) / (a*e - b*d)
y = (c*d - a*f) / (b*d - a*e)
print "{:.3f} {:.3f}".format(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s723503443 | p00004 | Wrong Answer | from __future__ import division
# ad*x + bd*y = cd
# -)ad*x + ae*y = af
# (bd-ae)*y = cd-af
# and so on...
while True:
try:
a, b, c, d, e, f = map(float, raw_input().split())
except:
break
x = (c*e - b*f) / (a*e - b*d)
y = (c*d - a*f) / (b*d - a*e)
print "{:.3f} {:.3f}".format(round(x,3), round(y,3)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s063892321 | p00004 | Wrong Answer | import sys
d = sys.stdin.readline()
while d:
a,b,c,d,e,f = map(int,d.split())
inv = 1/(a*e - b*d)
iA = [[e,-b],[-d,a]]
B = [c,f]
sol = list()
for i in range(2):
tmp = 0
for j in range(2):
tmp += iA[i][j] * B[j]
sol.append(tmp*inv)
print("%.3f %.3f"%(sol[0],sol[1]))
d = sys.stdin.readline() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s903719485 | p00004 | Wrong Answer | a,b,c,d,e,f = [int(i) for i in input().split()]
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s128860033 | p00004 | Wrong Answer | t = 0
while t == 0:
try:
a,b,c,d,e,f = [int(i) for i in input().split()]
except:
break
else:
print(1) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s721819744 | p00004 | Wrong Answer | t = 0
while t == 0:
try:
a,b,c,d,e,f = [int(i) for i in input().split()]
except:
break
else:
x = (e*c - b*f) / (a*e - b*d)
y = (a*f - c*d) / (a*e - b*d)
print("{0:.3f}".format(x) + " " + "{0:.3f}".format(y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s884957896 | p00004 | Wrong Answer | t = 0
while t == 0:
try:
a,b,e,c,d,f = [int(i) for i in input().split()]
except:
break
else:
x = (d*e - b*f) / (a*d - b*c)
y = (a*f - c*e) / (a*d - b*c)
print("{0:.3f}".format(x) + " " + "{0:.3f}".format(y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s376476072 | p00004 | Wrong Answer | x = []
y = []
while True:
try:
a, b, p, c, d, q = map(int, input().split())
x.append((d*p-b*q)/(a*d-b*c))
y.append((a*q-c*p)/(a*d-b*c))
except EOFError:
break
for i in range(len(x)):
print("{:.3f} {:.3f}".format(x[i], y[i])) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s742431180 | p00004 | Wrong Answer |
while True:
try:
data = raw_input()
except EOFError:
break
a,b,c,d,e,f = map(int, data.split())
x = ( e*c - b*f ) / ( b*d - a*c )
y = ( c - a*x ) / b
print "%.3f %.3f" % ( round(x,3), round(y,3) ) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s028983429 | p00004 | Wrong Answer | while True:
try:
data = raw_input()
except EOFError:
break
a,b,c,d,e,f = map(int, data.split())
x = ( c*e - b*f ) / ( b*d - a*e )
y = ( c - a*x ) / b
print "%.3f %.3f" % ( round(x,3), round(y,3) ) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s855026306 | p00004 | Wrong Answer | while True:
try:
data = raw_input()
except EOFError:
break
a,b,c,d,e,f = map(int, data.split())
x = ( b*f - c*e ) / ( b*d - a*e )
y = ( c - a*x ) / b
print "%.3f %.3f" % ( round(x,3), round(y,3) ) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s893210894 | p00004 | Wrong Answer | while True:
try:
data = raw_input()
except EOFError:
break
a,b,c,d,e,f = map(int, data.split())
if b == 0:
x = c / a
y = ( f - d*x ) / e
else:
x = ( b*f - e*c ) / ( b*d - a*e )
y = ( c - a*x ) / b
print "%.3f %.3f" % ( round(x,3), round(y,3) ) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s431951490 | p00004 | Wrong Answer |
while True:
try:
data = raw_input()
except EOFError:
break
a,b,c,d,e,f = map(float, data.split())
if b == 0:
x = c / a
y = ( f - d*x ) / e
else:
x = ( b*f - e*c ) / ( b*d - a*e )
y = ( c - a*x ) / b
print "%.3f %.3f" % ( round(x,3), round(y,3) ) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s446057127 | p00004 | Wrong Answer | import sys
from fractions import Fraction
def main():
input_strings = sys.stdin.readlines()
for matrix_string in input_strings:
matrix = list(map(Fraction, list(matrix_string.split())))
if matrix[0] == 0:
matrix = matrix[3:] + matrix[:3]
matrix = list(map(lambda x: x / matrix[0], matrix[:3])) + matrix[3:]
matrix = matrix[:3] + list(map(lambda x: x[1] - matrix[3] * x[0], zip(matrix[:3], matrix[3:])))
matrix = matrix[:3] + list(map(lambda x: x / matrix[4], matrix[3:]))
matrix = list(map(lambda x: x[0] - matrix[1] * x[1], zip(matrix[:3], matrix[3:]))) + matrix[3:]
matrix = list(map(int, matrix))
print('%.3f %.3f' % (matrix[2], matrix[5]))
main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s130148580 | p00004 | Wrong Answer | import sys
from fractions import Fraction
def main():
input_strings = sys.stdin.readlines()
for matrix_string in input_strings:
matrix = list(map(Fraction, list(matrix_string.split())))
if matrix[0] == 0:
matrix = matrix[3:] + matrix[:3]
matrix = list(map(lambda x: x / matrix[0], matrix[:3])) + matrix[3:]
matrix = matrix[:3] + list(map(lambda x: x[1] - matrix[3] * x[0], zip(matrix[:3], matrix[3:])))
matrix = matrix[:3] + list(map(lambda x: x / matrix[4], matrix[3:]))
matrix = list(map(lambda x: x[0] - matrix[1] * x[1], zip(matrix[:3], matrix[3:]))) + matrix[3:]
matrix = list(map(int, matrix))
matrix = list(map(lambda x: x + 0, matrix))
print('%.3f %.3f' % (matrix[2], matrix[5]))
main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s037893538 | p00004 | Wrong Answer | import sys
def simeq(a,b,c,d,e,f):
return ((c*e-b*f)/(a*e-b*d),((a*f-c*d)/(a*e-b*d)))
if __name__ == '__main__':
for line in sys.stdin:
(a,b,c,d,e,f) = map(int,line.split())
(x,y) = simeq(a,b,c,d,e,f)
print("{:.3f} {:.3f}".format(x,y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s099915518 | p00004 | Wrong Answer | import sys
import math
def simeq(a,b,c,d,e,f):
return ((c*e-b*f)/(a*e-b*d),((a*f-c*d)/(a*e-b*d)))
if __name__ == '__main__':
for line in sys.stdin:
(a,b,c,d,e,f) = map(int,line.split())
(x,y) = simeq(a,b,c,d,e,f)
print("{:.3f} {:.3f}".format(round(x,3),round(y,3))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s935070296 | p00004 | Wrong Answer | import sys
#from me.io import dup_file_stdin
#@dup_file_stdin
def solve():
for line in sys.stdin:
a,b,c,d,e,f=map(float,line.split(' '))
print("{:.3f} {:.3f}".format((c*e-b*f)/(a*e-b*d),(c*d-a*f)/(b*d-a*e)))
solve() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s551713358 | p00004 | Wrong Answer | while 1:
try:
a, b, c, d, e, f = map(float, raw_input().split())
d = a
e = e * a/d
f = f * a/d
y = (c - f)/(b - e)
x = (c - b * y)/a
print "%.3f %.3f" % (x, y)
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s957283508 | p00004 | Wrong Answer | while 1:
try:
a, b, c, d, e, f = map(float, raw_input().split())
d = a
e = e * a / d
f = f * a / d
y = (c - f) / (b - e)
x = (c - b * y) / a
print "%.3f %.3f" % (x, y)
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s503790506 | p00004 | Wrong Answer | while 1:
try:
a, b, c, d, e, f = map(float, raw_input().split())
d = a
e = e * a / d
f = f * a / d
y = (c - f) / (b - e)
x = (c - b * y) / a
if a == -0:
a = 0
if b == -0:
b = 0
print "%.3f %.3f" % (x, y)
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s966299414 | p00004 | Wrong Answer | while 1:
def solver(a, b, c, d, e, f):
answer = []
m = a / d
d = d * m
e = e * m
f = f * m
y = (c - f)/(b - e)
x = (c - b * y)/a
answer.append(x)
answer.append(y)
return answer
try:
p_1, p_2, p_3, p_4, p_5, p_6 = map(float, raw_input().split())
ans = []
ans = solver(p_1, p_2, p_3, p_4, p_5, p_6)
print "%.3f %.3f" % (ans[0], ans[1])
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s447314706 | p00004 | Wrong Answer | r = [0 for i in range(4)]
for i in range(0, 4, 2):
a, b, c, d, e, f = map(int, input().split(" "))
detA = a * e - b * d
r[i] = (c * e - b * f) / detA
r[i + 1] = (a * f - c * d) / detA
for i in range(0, 4, 2):
print("{:.3f} {:.3f}".format(r[i], r[i + 1])) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s499807104 | p00004 | Wrong Answer | r = [0 for i in range(4)]
for i in range(0, 4, 2):
a, b, c, d, e, f = map(int, input().split(" "))
detA = a * e - b * d
x = (c * e - b * f)
y = (a * f - c * d)
r[i] = x / detA
r[i + 1] = y / detA
for i in range(0, 4, 2):
print("{:.3f} {:.3f}".format(round(r[i]), round(r[i + 1]))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s194212030 | p00004 | Wrong Answer | inputs = list(input())
print(inputs) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s417893048 | p00004 | Wrong Answer | # usr/bin/python
# coding: utf-8
################################################################################
# Simultaneous Equation
# Write a program which solve a simultaneous equation:
#
# ax+by=c
# dx+ey=f
#
# The program should print x and y for given a, b, c, d, e and f (-1,000 ??? a,b,c,d,e,f ??? 1,000). You can suppose that given equation has a unique solution.
#
# Input
# The input consists of several data sets, 1 line for each data set. In a data set, there will be a,b,c,d,e,f separated by a single space. The input terminates with EOF.
#
# Output
# For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
#
# Sample Input 1
# 1 2 3 4 5 6
# 2 -1 -2 -1 -1 -5
# Output for the Sample Input 1
# -1.000 2.000
# 1.000 4.000
# Sample Input 2
# 2 -1 -3 1 -1 -3
# 2 -1 -3 -9 9 27
# Output for the Sample Input 2
# 0.000 3.000
# 0.000 3.000
#
################################################################################
import fileinput
if __name__ == "__main__":
for line in fileinput.input():
a = float(line.split(" ")[0])
b = float(line.split(" ")[1])
c = float(line.split(" ")[2])
d = float(line.split(" ")[3])
e = float(line.split(" ")[4])
f = float(line.split(" ")[5])
x = (e*c-b*f)/(a*e-b*d)
y = (-d*c+a*f)/(a*e-b*d)
print("{: .4f} {: .4f}".format(round(x,4),round(y,4))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s585302350 | p00004 | Wrong Answer | # usr/bin/python
# coding: utf-8
################################################################################
# Simultaneous Equation
# Write a program which solve a simultaneous equation:
#
# ax+by=c
# dx+ey=f
#
# The program should print x and y for given a, b, c, d, e and f (-1,000 ??? a,b,c,d,e,f ??? 1,000). You can suppose that given equation has a unique solution.
#
# Input
# The input consists of several data sets, 1 line for each data set. In a data set, there will be a,b,c,d,e,f separated by a single space. The input terminates with EOF.
#
# Output
# For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
#
# Sample Input 1
# 1 2 3 4 5 6
# 2 -1 -2 -1 -1 -5
# Output for the Sample Input 1
# -1.000 2.000
# 1.000 4.000
# Sample Input 2
# 2 -1 -3 1 -1 -3
# 2 -1 -3 -9 9 27
# Output for the Sample Input 2
# 0.000 3.000
# 0.000 3.000
#
################################################################################
import fileinput
if __name__ == "__main__":
for line in fileinput.input():
a = float(line.split(" ")[0])
b = float(line.split(" ")[1])
c = float(line.split(" ")[2])
d = float(line.split(" ")[3])
e = float(line.split(" ")[4])
f = float(line.split(" ")[5])
x = (e*c-b*f)/(a*e-b*d)
y = (-d*c+a*f)/(a*e-b*d)
print("{: .4f} {: .4f}".format(round(x,4),round(y,4)))
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s978681701 | p00004 | Wrong Answer | # usr/bin/python
# coding: utf-8
################################################################################
# Simultaneous Equation
# Write a program which solve a simultaneous equation:
#
# ax+by=c
# dx+ey=f
#
# The program should print x and y for given a, b, c, d, e and f (-1,000 ??? a,b,c,d,e,f ??? 1,000). You can suppose that given equation has a unique solution.
#
# Input
# The input consists of several data sets, 1 line for each data set. In a data set, there will be a,b,c,d,e,f separated by a single space. The input terminates with EOF.
#
# Output
# For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
#
# Sample Input 1
# 1 2 3 4 5 6
# 2 -1 -2 -1 -1 -5
# Output for the Sample Input 1
# -1.000 2.000
# 1.000 4.000
# Sample Input 2
# 2 -1 -3 1 -1 -3
# 2 -1 -3 -9 9 27
# Output for the Sample Input 2
# 0.000 3.000
# 0.000 3.000
#
################################################################################
import sys
if __name__ == "__main__":
for line in sys.stdin:
a = float(line.split(" ")[0])
b = float(line.split(" ")[1])
c = float(line.split(" ")[2])
d = float(line.split(" ")[3])
e = float(line.split(" ")[4])
f = float(line.split(" ")[5])
x = (e*c-b*f)/(a*e-b*d)
y = (-d*c+a*f)/(a*e-b*d)
print("{:-.4f} {:-.4f}".format(round(x,4),round(y,4)))
pass | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s821382822 | p00004 | Wrong Answer | # usr/bin/python
# coding: utf-8
################################################################################
# Simultaneous Equation
# Write a program which solve a simultaneous equation:
#
# ax+by=c
# dx+ey=f
#
# The program should print x and y for given a, b, c, d, e and f (-1,000 ??? a,b,c,d,e,f ??? 1,000). You can suppose that given equation has a unique solution.
#
# Input
# The input consists of several data sets, 1 line for each data set. In a data set, there will be a,b,c,d,e,f separated by a single space. The input terminates with EOF.
#
# Output
# For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
#
# Sample Input 1
# 1 2 3 4 5 6
# 2 -1 -2 -1 -1 -5
# Output for the Sample Input 1
# -1.000 2.000
# 1.000 4.000
# Sample Input 2
# 2 -1 -3 1 -1 -3
# 2 -1 -3 -9 9 27
# Output for the Sample Input 2
# 0.000 3.000
# 0.000 3.000
#
################################################################################
import sys
if __name__ == "__main__":
for line in sys.stdin:
a = float(line.split(" ")[0])
b = float(line.split(" ")[1])
c = float(line.split(" ")[2])
d = float(line.split(" ")[3])
e = float(line.split(" ")[4])
f = float(line.split(" ")[5])
x = (e*c-b*f)/(a*e-b*d)
y = (-d*c+a*f)/(a*e-b*d)
print("{:-.4f} {:-.4f}".format(round(x,4),round(y,4))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s741555892 | p00004 | Wrong Answer | # usr/bin/python
# coding: utf-8
################################################################################
# Simultaneous Equation
# Write a program which solve a simultaneous equation:
#
# ax+by=c
# dx+ey=f
#
# The program should print x and y for given a, b, c, d, e and f (-1,000 ??? a,b,c,d,e,f ??? 1,000). You can suppose that given equation has a unique solution.
#
# Input
# The input consists of several data sets, 1 line for each data set. In a data set, there will be a,b,c,d,e,f separated by a single space. The input terminates with EOF.
#
# Output
# For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
#
# Sample Input 1
# 1 2 3 4 5 6
# 2 -1 -2 -1 -1 -5
# Output for the Sample Input 1
# -1.000 2.000
# 1.000 4.000
# Sample Input 2
# 2 -1 -3 1 -1 -3
# 2 -1 -3 -9 9 27
# Output for the Sample Input 2
# 0.000 3.000
# 0.000 3.000
#
################################################################################
import sys
def get_input():
while True:
try:
yield ''.join(input())
except EOFError:
break
if __name__ == "__main__":
inputlist = list(get_input())
for line in inputlist:
a = float(line.split(" ")[0])
b = float(line.split(" ")[1])
c = float(line.split(" ")[2])
d = float(line.split(" ")[3])
e = float(line.split(" ")[4])
f = float(line.split(" ")[5])
x = (e*c-b*f)/(a*e-b*d)
y = (-d*c+a*f)/(a*e-b*d)
print("{:-.4f} {:-.4f}".format(round(x,4),round(y,4))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s192911811 | p00004 | Wrong Answer | # usr/bin/python
# coding: utf-8
################################################################################
# Simultaneous Equation
# Write a program which solve a simultaneous equation:
#
# ax+by=c
# dx+ey=f
#
# The program should print x and y for given a, b, c, d, e and f (-1,000 ??? a,b,c,d,e,f ??? 1,000). You can suppose that given equation has a unique solution.
#
# Input
# The input consists of several data sets, 1 line for each data set. In a data set, there will be a,b,c,d,e,f separated by a single space. The input terminates with EOF.
#
# Output
# For each data set, print x and y separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
#
# Sample Input 1
# 1 2 3 4 5 6
# 2 -1 -2 -1 -1 -5
# Output for the Sample Input 1
# -1.000 2.000
# 1.000 4.000
# Sample Input 2
# 2 -1 -3 1 -1 -3
# 2 -1 -3 -9 9 27
# Output for the Sample Input 2
# 0.000 3.000
# 0.000 3.000
#
################################################################################
import sys
import fileinput
if __name__ == "__main__":
for line in fileinput.input():
a = float(line.split(" ")[0])
b = float(line.split(" ")[1])
c = float(line.split(" ")[2])
d = float(line.split(" ")[3])
e = float(line.split(" ")[4])
f = float(line.split(" ")[5])
x = (e*c-b*f)/(a*e-b*d)
y = (-d*c+a*f)/(a*e-b*d)
print("{:-.4f} {:-.4f}".format(round(x,4),round(y,4))) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s784750557 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
ll = [int(x) for x in line.split()]
#print(ll)
a = ll[0]
b = ll[1]
c = ll[2]
d = ll[3]
e = ll[4]
f = ll[5]
x = (c*e-b*f)/(a*e-b*d)
y = (a*f-d*c)/(a*e-d*b)
print(round(x,3), round(y,3)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s665164077 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
ll = [int(x) for x in line.split()]
#print(ll)
a = ll[0]
b = ll[1]
c = ll[2]
d = ll[3]
e = ll[4]
f = ll[5]
x = format((c*e-b*f)/(a*e-b*d), '.3f')
y = format((a*f-d*c)/(a*e-d*b), '.3f')
print(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s132536325 | p00004 | Wrong Answer | import sys
for line in sys.stdin:
ll = [int(x) for x in line.split()]
#print(ll)
a = ll[0]
b = ll[1]
c = ll[2]
d = ll[3]
e = ll[4]
f = ll[5]
x = format(round((c*e-b*f)/(a*e-b*d),3), '.3f')
y = format(round((a*f-d*c)/(a*e-d*b),3), '.3f')
print(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s899020224 | p00004 | Wrong Answer | while True:
try:
a, b, c, d, e, f = map(float, input().split())
x = (c*e - b*f)/(a*e - b*d)
y = (f*a - c*d)/(a*e - d*b)
print( "{0:.3f} {1:.3f}".format(x,y))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s689680730 | p00004 | Wrong Answer | while True:
try:
a, b, c, d, e, f = map(int, input().split())
except:
break
y = (c * d - f * a) / (b * d - e * a)
x = (c - (b * y)) / a
print(x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s041779569 | p00004 | Wrong Answer | while True:
try:
a,b,c,d,e,f=map(int,raw_input().split())
if a*d-b*c==0:
print "not exist answer"
else:
x = (c*e-b*f) / (a*e-b*d)
y = (a*f-c*d) / (a*e-b*d)
print ('%.3f' % x), ('%.3f' % y)
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s586251179 | p00004 | Wrong Answer | while True:
try:
a,b,c,d,e,f=map(int,raw_input().split())
if a*d-b*c==0:
print "not exist answer"
else:
x = (c*e-b*f) / (a*e-b*d)
y = (a*f-c*d) / (a*e-b*d)
if x==-0:
x=0
if y==-0:
y=0
print ('%.3f' % x), ('%.3f' % y)
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s705573265 | p00004 | Wrong Answer | while True:
try:
a,b,c,d,e,f=map(int,raw_input().split())
if a*d-b*c==0:
print "not exist answer"
else:
x = (c*e-b*f) / (a*e-b*d)
y = (a*f-c*d) / (a*e-b*d)
print ('%.3f' % round(x,3)), ('%.3f' % round(y,3))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s286696503 | p00004 | Wrong Answer | while True:
try:
a,b,c,d,e,f=map(int,raw_input().split())
if a*d-b*c==0:
print "not exist answer"
else:
x = float((c*e-b*f)) / (a*e-b*d)
y = float((a*f-c*d)) / (a*e-b*d)
print ('%.3f' % round(x,3)), ('%.3f' % round(y,3))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s682745361 | p00004 | Wrong Answer | while True:
try:
a,b,c,d,e,f=map(float,raw_input().split())
if a*d-b*c==0:
print "not exist answer"
else:
x = float((c*e-b*f)) / (a*e-b*d)
y = float((a*f-c*d)) / (a*e-b*d)
print ('%.3f' % round(x,3)), ('%.3f' % round(y,3))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s295671597 | p00004 | Wrong Answer | import sys
def det(mat):
t = 1 / (mat[0][0] * mat[1][1] - mat[0][1] * mat[1][0])
a = t * mat[1][1]
b = t * -1 * mat[0][1]
c = t * -1 * mat[1][0]
d = t * mat[0][0]
return [[a, b], [c, d]]
for line in sys.stdin:
try:
a, b, c, d, e, f = [int(i) for i in line.split()]
A = [[a, b], [d, e]]
P = [c, f]
detA = det(A)
print("%lf %lf" % (detA[0][0] * P[0] + detA[0][1] * P[1], detA[1][0] * P[0] + detA[1][1] * P[1]))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s316551436 | p00004 | Wrong Answer | class Equation():
def __init__(self, a, b, c, d, e, f):
self.a = a
self.b = b
self.c = c
self.d = d
self.e = e
self.f = f
def calc(self):
temp = (self.a * self.e - self.b * self.d)
temp_a = (self.c * self.e - self.b * self.f)
temp_b = (self.f * self.a - self.c * self.d)
x = round(temp_a/temp,4)
y = round(temp_b/temp,4)
return x, y
def print(self):
self.ans = self.calc()
print("{0:.3f} {1:.3f}".format(self.ans[0],self.ans[1]))
def main():
data = []
while 1:
try:
n = input().split()
a = float(n[0])
b = float(n[1])
c = float(n[2])
d = float(n[3])
e = float(n[4])
f = float(n[5])
data.append(Equation(a, b, c, d, e, f))
except EOFError:
break
for datas in data:
datas.print()
if __name__ == "__main__":
main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
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