submission_id string | problem_id string | status string | code string | input string | output string | problem_description string |
|---|---|---|---|---|---|---|
s980910776 | p00004 | Runtime Error | import sys
import numpy as np
for i in sys.stdin:
a,b,c,d,e,f=list(map(float, i.split()))
A=np.matrix([[a,b],[d,e]])
inv_A = np.linalg.inv(A)
P=np.matrix([[c],[f]])
X=inv_A.dot(P)
print("{0:.3f} {1:.3f}".format(X[0,0], X[1,0])) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s925082788 | p00004 | Runtime Error | while True:
try:
a,b,c,d,e,f=map(int,raw_input().split())
if a*d-b*c==0:
print "not exist answer"
else:
x = (c*e-b*f) / (a*e-b*d)
y = (a*f-c*d) / (a*e-b*d)
print ('%.3f' % round(x,3), ('%.3f' % round(y,3))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s309809646 | p00004 | Runtime Error | def main():
while True:
try:
Array = list(map(int,input().split()))
x = (Array[2]-(Array[1]/Array[4])*Array[5])/(Array[0]-(Array[1]/Array[4])*Array[3])
y = (Array[5]-Array[3]*x)/Array[4]
except EOFError:
break
print("{0:.3f} {1:.3f} ".format(x,y))
if __name__ == '__main__':
main() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s005377108 | p00004 | Runtime Error | import itertools, sys
d = {i: 0 for i in range(51)}
for i in itertools.combinations_with_replacement(range(0,10), 4):
if i[0] == i[1] == i[2] == i[3]:
continue
d[sum(i)] += 1
for i in map(int, sys.stdin):
if i / 4 == 0:
print(d[i]*4+1)
else:
print(d[i]*4) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s816478435 | p00004 | Runtime Error | import sys
for e in sys.stdin:
a, b, c, d, e, f = map(int, e.split())
a * (e*y-f) / d + b * y = c
x = (e*y-f) / d
print round(x, 3)+' '+round(y, 3)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s419085566 | p00004 | Runtime Error | import sys
for e in sys.stdin:
a, b, c, d, e, f = map(int, e.split())
a * (e*y-f) / d + b * y = c
x = (e*y-f) / d
print (round(x, 3)+' '+round(y, 3))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s383001316 | p00004 | Runtime Error | import sys
for e in sys.stdin:
a, b, c, d, e, f = map(int, e.split())
a * (-e*y+f) / d + b * y = c
-x = (e*y-f) / d
print (round(x, 3)+' '+round(y, 3))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s117395668 | p00004 | Runtime Error | import sys
for e in sys.stdin:
a, b, c, d, e, f = map(int, e.split())
y=(c*d-a*f)/(b*d-a*e)
x = (e*y-f) / -d
print (round(x, 3)+' '+round(y, 3))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s667607793 | p00004 | Runtime Error | import sys
for e in sys.stdin:
a, b, c, d, e, f = map(int, e.split())
y=(c*d-a*f)/(b*d-a*e)
x = (c-b*y)/a
print (round(x, 3)+' '+round(y, 3))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s146889010 | p00004 | Runtime Error | import sys
import numpy as np
#np.set_printoptions(formatter={'float': '{: 0.3f}'.format}) #桁を揃える
line = sys.stdin.readlines()
#print(line)
for i in line:
cnt = 0
idx = 0
a = np.array([0.0, 0.0, 0.0, 0.0])
b = np.array([0.0, 0.0])
for k in list(map(float, i.split(" "))):
if cnt == 2:
b[0] = k
idx -= 1
elif cnt == 5:
b[1] = k
else:
a[idx] = k
cnt += 1
idx += 1
#print(a, b)
a = a.reshape(2, 2)
x = np.linalg.solve(a, b)
print('{0: 0.3f} {1: 0.3f}'.format(x[0], x[1]))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s573855141 | p00004 | Runtime Error | import sys
import numpy as np
#np.set_printoptions(formatter={'float': '{: 0.3f}'.format}) #桁を揃える
line = sys.stdin.readlines()
#print(line)
for i in line:
cnt = 0
idx = 0
a = np.array([0.0, 0.0, 0.0, 0.0])
b = np.array([0.0, 0.0])
for k in list(map(float, i.split(" "))):
if cnt == 2:
b[0] = k
idx -= 1
elif cnt == 5:
b[1] = k
else:
a[idx] = k
cnt += 1
idx += 1
#print(a, b)
a = a.reshape(2, 2)
x = np.linalg.solve(a, b)
print('{0: .3f} {1: .3f}'.format(x[0], x[1]))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s875431776 | p00004 | Runtime Error | import sys
import numpy as np
#np.set_printoptions(formatter={'float': '{: 0.3f}'.format}) #桁を揃える
while True:
line = sys.stdin.readline()
if line is '':
break
#print(line)
cnt = 0
idx = 0
a = np.array([0.0, 0.0, 0.0, 0.0])
b = np.array([0.0, 0.0])
for k in list(map(float, line.split(" "))):
if cnt == 2:
b[0] = k
idx -= 1
elif cnt == 5:
b[1] = k
else:
a[idx] = k
cnt += 1
idx += 1
#print(a, b)
a = a.reshape(2, 2)
x = np.linalg.solve(a, b)
print('{0: .3f} {1: .3f}'.format(x[0], x[1]))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s915968211 | p00004 | Runtime Error | import sys
#import numpy as np
# AOJではnumpy使えません
#np.set_printoptions(formatter={'float': '{: 0.3f}'.format}) #桁を揃える
while True:
line = sys.stdin.readline()
if line is '':
break
#print(line)
a = list(map(float, line.split(" ")))
#print(a)
tmp = a[0]
for i in range(0, 3):
a[i] = a[i] * a[3]
for i in range(3, 6):
a[i] = a[i] * tmp
#print(a)
y = (a[2] - a[5]) / (a[1] - a[4])
x = (a[2] - a[1] * y) / a[0]
print("{0:0.3f}".format(x), "{0:0.3f}".format(y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s567439283 | p00004 | Runtime Error | import sys
#import numpy as np
# AOJではnumpy使えません
#np.set_printoptions(formatter={'float': '{: 0.3f}'.format}) #桁を揃える
lines = sys.stdin.readlines()
for line in lines:
a = list(map(float, line.split(" ")))
tmp = a[0]
for i in range(0, 3):
a[i] = a[i] * a[3]
for i in range(3, 6):
a[i] = a[i] * tmp
y = (a[2] - a[5]) / (a[1] - a[4])
x = (a[2] - a[1] * y) / a[0]
print("{0:0.3f}".format(x), "{0:0.3f}".format(y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s079075057 | p00004 | Runtime Error | import sys
#import numpy as np
# AOJではnumpy使えません
#np.set_printoptions(formatter={'float': '{: 0.3f}'.format}) #桁を揃える
lines = sys.stdin.readlines()
for line in lines:
a = list(map(float, line.split(" ")))
tmp = a[0]
for i in range(0, 3):
a[i] = a[i] * a[3]
for i in range(3, 6):
a[i] = a[i] * tmp
y = (a[2] - a[5]) / (a[1] - a[4])
x = (a[2] - a[1] * y) / a[0]
print("{0:0.3f} {1:0.3f}".format(x, y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s794959803 | p00004 | Runtime Error | import sys
lines = sys.stdin.readlines()
for line in lines:
a = list(map(float, line.split(" ")))
tmp = a[0]
for i in range(0, 3):
a[i] = a[i] * a[3]
for i in range(3, 6):
a[i] = a[i] * tmp
y = (a[2] - a[5]) / (a[1] - a[4])
x = (a[2] - a[1] * y) / a[0]
print("{0:0.3f} {1:0.3f}".format(x, y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s262645081 | p00004 | Runtime Error | l = [[]]
i = 0
y,x = []
while(True):
try:
l[i] = list(map(float, input().split()))
i += 1
except:
break
for i in range(len(i)):
a = l[i][0]/l[i][4]
l[i] *= l[i] * a
y[i] = (l[i][2]-l[i][5])/(l[i][1]-l[i][4])
x[i] = (l[i][2]-l[i][1]*y[i])/l[i][0]
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s469869019 | p00004 | Runtime Error | import numpy as np
lst=[]
while 1:
try:
lst.append(list(map(int, input().split())))
except EOFError:
break
for a in lst:
A = np.array([[a[0],a[1]],
[a[3],a[4]]])
b = np.array([a[2],a[5]])
x = np.linalg.solve(A, b)
print(x)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s760769135 | p00004 | Runtime Error | import numpy as np
while 1:
try:
a = list(map(float, input().split()))
A = np.array([[a[0],a[1]],
[a[3],a[4]]])
b = np.array([a[2],a[5]])
x = np.linalg.solve(A, b)
print(x)
except EOFError:
break
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s337897652 | p00004 | Runtime Error | import sys
import numpy as np
while 1:
line = sys.stdin.readline()
if line is '':
break
a = list(map(float, input().split()))
A = np.array([[a[0],a[1]],
[a[3],a[4]]])
b = np.array([a[2],a[5]])
x = np.linalg.solve(A, b)
print(x)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s015979155 | p00004 | Runtime Error | import sys
import numpy as np
while 1:
line = sys.stdin.readline()
if line is ' ':
break
a = list(map(float, input().split()))
A = np.array([[a[0],a[1]],
[a[3],a[4]]])
b = np.array([a[2],a[5]])
x = np.linalg.solve(A, b)
print(x)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s958674838 | p00004 | Runtime Error | import numpy as np
while 1:
try:
a = list(map(float, input().split()))
A = np.array([[a[0],a[1]],
[a[3],a[4]]])
b = np.array([a[2],a[5]])
x = np.linalg.solve(A, b)
print(x)
except:
break
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s480166199 | p00004 | Runtime Error | import sys
while 1:
line = sys.stdin.readline()
if line is ' ':
break
a,b,c,d,e,f = map(float, input().split())
y=(c*d-a*f)/(b*d-a*e)
x=(c-b*y)/a
print("{0:.3f} {1:.3f}".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s443954602 | p00004 | Runtime Error | import sys
for e in sys.stdin:
a,b,c,d,e,f=map(int,e.split())
y=(c*d-a*f)/(b*d-a*e)
print(f'{(c-b*y)/a:.3f} {y:.3f}")
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s148324567 | p00004 | Runtime Error | import sys
import numpy
for i in sys.stdin:
a, b, c, d, e, f = map(int, i.split())
print("{0:.3f} {1:.3f}".format(numpy.round((c * e - b * f) / (a * e - b * d), 3), numpy.round((c * d - a * f) / (b * d - a * e), 3)))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s276088111 | p00004 | Runtime Error | import sys
import numpy
for i in sys.stdin:
a, b, c, d, e, f = map(int, i.split())
x = (c * e - b * f) / (a * e - b * d)
x = abs(x) if x < 10e-4 else x
print("{:.3f} {:.3f}".format(x, (c - x) / b))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s249126437 | p00004 | Runtime Error | import sys
for i in sys.stdin:
a, b, c, d, e, f = map(int, i.split())
x = (c * e - b * f) / (a * e - b * d)
y = (c * d - a * f) / (b * d - a * e)
x = abs(x) if x < 10e-4 else x
y = abs(y) if y < 10e-4 else y
print("{:.3f} {:.3f}".format(round(x,3), rount(y,3)))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s427758387 | p00004 | Runtime Error | import sys
for i in sys.stdin:
a, b, c, d, e, f = map(int, i.split())
x = (c * e - b * f) / (a * e - b * d)
y = (c * d - a * f) / (b * d - a * e)
x = abs(x) if abs(x) < 10e-4 else x
y = abs(y) if abs(y) < 10e-4 else y
print("{:.3f} {:.3f}".format(x, y)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s031472624 | p00004 | Runtime Error | # Vol0004.
import sys
def main():
data = []
lines = sys.stdin.readlines()
for line in lines:
data.append(line.split()) # スペース区切りで放り込む
# ax + by = c, dx + ey = fの解は、
# x = (ce - bf) / (ae - bd), y = (af - cd) / (ae - bd).
# これをround(float, 3)すれば答えが出る。
N = len(data)
for i in range(N):
det = data[i][0] * data[i][4] - data[i][1] * data[i][3]
gx = data[i][2] * data[i][4] - data[i][1] * data[i][5]
gy = data[i][0] * data[i][5] - data[i][2] * data[i][3]
print(str(round(gx / det, 3)) + " " + str(round(gy / det, 3)))
if __name__ == "__main__":
main()
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s938695192 | p00004 | Runtime Error | # Vol0004.
import sys
def main():
data = []
lines = sys.stdin.readlines()
fp.close()
for line in lines:
data.append(line.split()) # スペース区切りで放り込む
# ax + by = c, dx + ey = fの解は、
# x = (ce - bf) / (ae - bd), y = (af - cd) / (ae - bd).
# これをround(float, 3)すれば答えが出る。
N = len(data)
for i in range(N):
for k in range(6):
data[i][k] = int(data[i][k])
det = data[i][0] * data[i][4] - data[i][1] * data[i][3]
gx = data[i][2] * data[i][4] - data[i][1] * data[i][5]
gy = data[i][0] * data[i][5] - data[i][2] * data[i][3]
if det < 0:
det = -det;
if gx != 0: gx = -gx
if gy != 0: gy = -gy
print("{0:.3f}".format(gx / det) + " " + "{0:.3f}".format(gy / det))
if __name__ == "__main__":
main()
# 補足、0.1とか0.22でも3桁目まで表示しないとWrongになる。
# 表示するにはprint("{0:.nf}".format(数))ってやる(nのところは桁数)。
# さらに、0を負の数で割ると表示が-0.000になってしまうのでそこの処理も重要。
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s696215705 | p00004 | Runtime Error |
def ans(a, b, c, d, e, f):
x = ((e*c - b*f)/(a*e-b*d))
y = ((-d*x + f)/e)
x = "%.3f" % x
y = "%.3f" % y
return x, y
sets = []
while True:
try:
line = list(map(int, input().split()))
if(line[0] == " "):
break;
else:
sets.append(line)
except IndexError:
break
for i in sets:
x, y = ans(i[0],i[1],i[2],i[3],i[4],i[5])
print(x, y)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s115125560 | p00004 | Runtime Error | def ans(a, b, c, d, e, f):
x = ((e*c - b*f)/(a*e-b*d))
y = ((-d*x + f)/e)
x = "%.3f" % x
y = "%.3f" % y
return x, y
sets = []
while True:
try:
line = list(map(int, input().split()))
if(line[0] == " "):
break;
else:
sets.append(line)
except IndexError:
break
for i in sets:
x, y = ans(i[0],i[1],i[2],i[3],i[4],i[5])
print(x, y)
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s844581128 | p00004 | Runtime Error | while True:
try:
q = map(int,raw_input().split(" "))
y = (-1*q[0]*q[5] + q[2] * q[3]) / (-1*q[0] * q[4] + q[1] * q[3])
x = (q[5]-q[4]* y)/ q[3]
if x == -0 or y == -0 :
x == 0
y == 0
print "%.3f %.3f" % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s659966677 | p00004 | Runtime Error | import sys
for x in sys.stdin.readlines():
n = [int(y) for y in x.split()]
print "%.3f %.3f" % ((n[2]*n[4]-n[1]*n[5])/(n[0]*n[3]-n[1]*n[3]),(n[5]*n[0]-n[2]*n[3])/(n[0]*n[4]-n[3]*n[1])) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s598512375 | p00004 | Runtime Error | while True:
a = map(float, raw_input().split(' '))
if a[1]*a[3]-a[0]*a[4] == 0:
print 'No answer'
else:
x = (a[1]*a[5]-a[2]*a[4])/(a[1]*a[3]-a[0]*a[4])
y = (a[2]*a[3]-a[0]*a[5])/(a[1]*a[3]-a[0]*a[4])
print '%.3f %.3f ' % (x,y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s715293989 | p00004 | Runtime Error | while True:
a = map(float, raw_input().split(' '))
if a[1]*a[3]-a[0]*a[4] == 0:
print 'No answer'
else:
x = (a[1]*a[5]-a[2]*a[4])/(a[1]*a[3]-a[0]*a[4])
y = (a[2]*a[3]-a[0]*a[5])/(a[1]*a[3]-a[0]*a[4])
if x == 0:
x = abs(x)
if y == 0:
y = abs(y)
print '%.3f %.3f ' % (x,y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s786587056 | p00004 | Runtime Error | while True:
a = map(float, raw_input().split(' '))
x = (a[1]*a[5]-a[2]*a[4])/(a[1]*a[3]-a[0]*a[4])
y = (a[2]*a[3]-a[0]*a[5])/(a[1]*a[3]-a[0]*a[4])
if x == 0:
x = abs(x)
if y == 0:
y = abs(y)
print '%.3f %.3f ' % (x,y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s710674563 | p00004 | Runtime Error | x = map(int,input().split(' '))
a = x[0]
b = x[1]
c = x[2]
d = x[3]
e = x[4]
f = x[5]
print round((c*e-b*f)/(a*e-d*b),4),round((c*d-a*f)/(b*d-a*e),4) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s470511508 | p00004 | Runtime Error | x = map(float,input().split(' '))
a = x[0]
b = x[1]
c = x[2]
d = x[3]
e = x[4]
f = x[5]
print round((c*e-b*f)/(a*e-d*b),4),round((c*d-a*f)/(b*d-a*e),4) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s090205221 | p00004 | Runtime Error | x = map(float,input().split(' '))
a = x[0]
b = x[1]
c = x[2]
d = x[3]
e = x[4]
f = x[5]
g = (c*e-b*f)/(a*e-d*b)
h = (c*d-a*f)/(b*d-a*e)
print round(g,4),round(h,4) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s309625368 | p00004 | Runtime Error | x = map(float,input().split(' '))
a = x[0]
b = x[1]
c = x[2]
d = x[3]
e = x[4]
f = x[5]
g = (c*e-b*f)/(a*e-d*b)
h = (c*d-a*f)/(b*d-a*e)
print round(g,3),round(h,3) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s775557315 | p00004 | Runtime Error | data = []
try:
while True:
data.append(raw_input())
except EOFError:
pass
for i in data:
a, b, c, d, e, f = i.split()
a, b, c, d, e, f = int(a), int(b), int(c), int(d), int(e), int(f)
if abs(a) or abs(b) or abs(c) or abs(d) or abs(e) or abs(f) <= 1000:
for j in range(-1000, 1001):
if j != 0:
y1 = (c - (a*j)) / float(b)
y2 = (f - (d*j)) / float(e)
if y1 == y2:
print "{:.4f} {:.4f}".format(j, y1)
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s353071858 | p00004 | Runtime Error | data = []
try:
while True:
data.append(raw_input())
except EOFError:
pass
for i in data:
a, b, c, d, e, f = i.split()
a, b, c, d, e, f = int(a), int(b), int(c), int(d), int(e), int(f)
if abs(a) or abs(b) or abs(c) or abs(d) or abs(e) or abs(f) <= 1000:
for j in range(-1000, 1001):
if j != 0:
y1 = (c - (a*j)) / float(b)
y2 = (f - (d*j)) / float(e)
if y1 == y2:
print "{:.3f} {:.3f}".format(j, y1)
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s725660881 | p00004 | Runtime Error | data = []
try:
while True:
data.append(raw_input())
except EOFError:
pass
for i in data:
a, b, c, d, e, f = i.split()
a, b, c, d, e, f = int(a), int(b), int(c), int(d), int(e), int(f)
if abs(a) or abs(b) or abs(c) or abs(d) or abs(e) or abs(f) <= 1000:
for j in range(-1000, 1001):
if j != 0:
y1 = (c - (a * j)) / float(b)
y2 = (f - (d * j)) / float(e)
if y1 == y2:
print "{:.3f} {:.3f}".format(j, y1)
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s278644503 | p00004 | Runtime Error | data = []
try:
while True:
data.append(raw_input())
except EOFError:
pass
for i in data:
a, b, c, d, e, f = i.split()
a, b, c, d, e, f = int(a), int(b), int(c), int(d), int(e), int(f)
if abs(a) or abs(b) or abs(c) or abs(d) or abs(e) or abs(f) <= 1000:
for j in range(-1000, 1001):
if j != 0:
if (c - (a * j)) / float(b) == (f - (d * j)) / float(e):
print "{:.3f} {:.3f}".format(j, (c - (a * j)) / float(b))
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s378807113 | p00004 | Runtime Error | data = []
try:
while True:
data.append(raw_input())
except EOFError:
pass
for i in data:
a, b, c, d, e, f = i.split()
a, b, c, d, e, f = int(a), int(b), int(c), int(d), int(e), int(f)
if abs(a) or abs(b) or abs(c) or abs(d) or abs(e) or abs(f) <= 1000:
for j in range(-1000, 1001):
y1 = (c - (a * j)) / float(b)
y2 = (f - (d * j)) / float(e)
if y1 == y2:
print "{:.3f} {:.3f}".format(j, y1)
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s382379409 | p00004 | Runtime Error | data = []
try:
while True:
data.append(raw_input())
except EOFError:
pass
for i in data:
a, b, c, d, e, f = i.split()
a, b, c, d, e, f = int(a), int(b), int(c), int(d), int(e), int(f)
if (abs(a) <= 1000
and abs(b) <= 1000
and abs(c) <= 1000
and abs(d) <= 1000
and abs(e) <= 1000
and abs(f) <= 1000):
for j in range(-1000, 1001):
y1 = (c - (a * j)) / float(b)
y2 = (f - (d * j)) / float(e)
if y1 == y2:
print "{:.3f} {:.3f}".format(j, y1)
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s136531953 | p00004 | Runtime Error | e True:
try:
a = map(long,raw_input().split())
m = a[0]*a[4]-a[1]*a[3]
x = (a[4]*a[2] - a[1]*a[5])/m
y = (a[0]*a[5] - a[2]*a[3])/m
if x == -0:
x = 0
if y == -0:
y = 0
print "%.3f %.3f" % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s214080166 | p00004 | Runtime Error |
import sys
def solv(a,b,c,d,e,f):
x = (c * e - b * f) / (a * e - b * d)
y = (f - d * x) / e
return (x, y)
lis = sys.stdin.readlines()
for line in lis:
a, b, c, d, e, f = tuple(map((lambda x: float(x)), line.split(' ')))
(x, y) = solv(a, b, c, d, e, f)
print "%5.3f %5.3f" % (x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s755943373 | p00004 | Runtime Error |
import sys
def solv(a,b,c,d,e,f):
x = (c * e - b * f) / (a * e - b * d)
y = (f - d * x) / e
return (x, y)
lis = sys.stdin.readlines()
for line in lis:
a, b, c, d, e, f = tuple(map(float, line.split(' ')))
(x, y) = solv(a, b, c, d, e, f)
print "%5.3f %5.3f" % (x, y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s863639694 | p00004 | Runtime Error | import sys
def gcd(a, b):
return gcd(b, a % b) if a % b else b
def lcm(a, b):
return a * b / gcd(a, b)
for line in sys.stdin:
data = map(int, line.split())
a, b, c, d, e, f = data
ix = lcm(a, d) / a
jx = lcm(a, d) / d
iy = lcm(b, e) / b
jy = lcm(b, e) / e
x = (c*1.0*iy - f*jy) / (a*iy - d*jy)
y = (c*1.0*ix - f*jx) / (b*ix - e*jx)
print "%.3f %.3f" % (round(x, 4), round(y, 4)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s764105194 | p00004 | Runtime Error | import sys
def gcd(a, b):
return gcd(b, a % b) if a % b else b
def lcm(a, b):
return a * b / gcd(a, b)
for line in sys.stdin:
data = line.split()
a, b, c, d, e, f = data
ix = lcm(a, d) / a
jx = lcm(a, d) / d
iy = lcm(b, e) / b
jy = lcm(b, e) / e
x = (c*1.0*iy - f*jy) / (a*iy - d*jy)
y = (c*1.0*ix - f*jx) / (b*ix - e*jx)
print "%.3f %.3f" % (round(x, 4), round(y, 4)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s320826900 | p00004 | Runtime Error | import sys
def gcd(aa, bb):
return gcd(bb, aa % bb) if aa % bb else bb
def lcm(aa, bb):
return aa * bb / gcd(aa, bb)
for line in sys.stdin:
data = line.split()
a, b, c, d, e, f = data
ix = lcm(a, d) / a
jx = lcm(a, d) / d
iy = lcm(b, e) / b
jy = lcm(b, e) / e
x = (c*1.0*iy - f*jy) / (a*iy - d*jy)
y = (c*1.0*ix - f*jx) / (b*ix - e*jx)
print "%.3f %.3f" % (round(x, 4), round(y, 4)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s493866624 | p00004 | Runtime Error | import sys
def gcd(a, b):
return gcd(b, a % b) if a % b else b
def lcm(a, b):
return a * b / gcd(a, b)
for line in sys.stdin:
data = map(int, line.split())
a, b, c, d, e, f = data
ix = lcm(a, d) / a
jx = lcm(a, d) / d
iy = lcm(b, e) / b
jy = lcm(b, e) / e
x = (c*1.0*iy - f*jy) / (a*iy - d*jy)
y = (c*1.0*ix - f*jx) / (b*ix - e*jx)
print "%.3f %.3f" % (round(x, 4), round(y, 4)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s125266767 | p00004 | Runtime Error | while 1:
a, b, c, d, e, f = map(int,input().split())
x = (c/b-f/e) / (a/b-d/e)
y = (c/a-f/d) / (b/a-e/d)
print("{:+.3f} {:+.3f}".format(x,y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s144980213 | p00004 | Runtime Error | while 1:
P = map(float,raw_input().split())
x = (P[2]*P[4]-P[1]*P[5])/(P[0]*P[4]-P[1]*P[3])
y = (P[2]*P[3]-P[0]*P[5])/(P[1]*P[3]-P[0]*P[4])
x = x if x else 0
y = y if y else 0
print "{:.3f} {:.3f}".format(x,y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s004681144 | p00004 | Runtime Error | data = raw_input()
while data:
a, b, c, d, e, f = map(int, data.split())
det = a*e-b*d
x, y = float(e*c+(-b)*f)/det, float((-d)*c+a*f)/det
print '%.3f %.3f' % (x, y)
data = raw_input() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s303487883 | p00004 | Runtime Error | while True:
a, b, c, d, e, f = map(float, raw_input().split())
x = (c * e - b * f) / (a * e - d * b)
y = (c * d - f * a) / (b * d - e * a)
print ("{0:.3f} {1:.3f}".format(x + 0, y + 0)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s776170609 | p00004 | Runtime Error | while True:
try:
a, b, c, d, e, f = map(int, raw_input().split())
x = float(c*e - b*f)/(a*e - b*d)
y = float(c*d - a*f)/(b*d - a*e)
print ("%f %f" % (round(x,-3), round(y,-3))
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s901379636 | p00004 | Runtime Error | import sys
for i in stdin.sys:
a, b, c, d, e, f = map(float, raw_input().split())
x = float(c*e - b*f)/(a*e - b*d)
y = float(c*d - a*f)/(b*d - a*e)
if x == -0:
x = 0
if y == -0:
y = 0
print ("%.3f %.3f" % (x, y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s253842544 | p00004 | Runtime Error | while 1:
a, b, c, d, e, f = map(int, raw_input().split())
g = b / e
x = (c - g * f) / (a - g)
y = (c - a * x) / b
print str(x) + " " + str(y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s097642153 | p00004 | Runtime Error | while 1:
a, b, c, d, e, f = map(int, raw_input().split())
g = b / e
x = (c - g * f) / (float(a) - g)
y = (c - a * x) / float(b)
print str(x) + " " + str(y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s990231557 | p00004 | Runtime Error | import sys
while 1:
try:
a, b, c, d, e, f = map(int, raw_input().split())
g = b / e
x = (c - g * f) / (float(a) - g)
y = (c - a * x) / float(b)
print str(x) + " " + str(y)
except: EOFError
sys.exit() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s655322490 | p00004 | Runtime Error | import sys
while 1:
try:
a, b, c, d, e, f = map(int, raw_input().split())
g = b / e
x = (c - g * f) / (float(a) - g)
y = (c - a * x) / float(b)
print str(x) + " " + str(y)
exception: EOFError
sys.exit() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s747276575 | p00004 | Runtime Error | import sys
while 1:
try:
a, b, c, d, e, f = map(int, raw_input().split())
g = b / e
x = (c - g * f) / (float(a) - g)
y = (c - a * x) / float(b)
print str(x) + " " + str(y)
except EOFError:
sys.exit() | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s787322030 | p00004 | Runtime Error | while 1:
try:
a, b, c, d, e, f = map(int, raw_input().split())
g = b / e
x = (c - g * f) / (float(a) - g)
y = (c - a * x) / float(b)
print str(x) + " " + str(y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s532186463 | p00004 | Runtime Error | while 1:
try:
a, b, c, d, e, f = map(float, raw_input().split())
g = b / e
x = (c - g * f) / a - g)
y = (c - a * x) / b
print str(x) + " " + str(y) + "\n"
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s696119348 | p00004 | Runtime Error | while 1:
try:
a, b, c, d, e, f = map(int, raw_input().split())
g = float(b) / float(e)
float(x) = (c - g * f) / (a - g)
float(y) = (c - a * x) / b
print str(x) + " " + str(y) + "\n"
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s456604543 | p00004 | Runtime Error | while 1:
try:
a, b, c, d, e, f = map(float, raw_input().split())
x = (c * e - b * f) * / (a * e - b * d)
y = (f * a - c * d) * / (a * e - d * b)
print str('%.3f' % x) + " " + str('%.3f' % y) + "\n"
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s106350730 | p00004 | Runtime Error | while True:
line = raw_input()
if not line: break;
lines = [int(x) for x in line.split(" ")]
if lines.length == 6:
x = 0
y = 0
(A1, B1, E1, A2, B2, E2) = lines
if A1*B2==B1*A2 or A1*B2-A2*B1:
break;
x=1000*(E1*B2-B1*E2)/(A1*B2-B1*A2)
y=1000*(E2*A1-E1*A2)/(A1*B2-A2*B1)
print "%.3f %.3f" % (round(x)/1000, round(y)/1000) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s125155628 | p00004 | Runtime Error | while True:
a,b,e,d,e,f = map(float,raw_input().split())
x = (e*c-b*f) / (e*a-b*d)
y = (c*d-a*f) / (b*d-e*a)
print '%d %d' % (x,y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s586332088 | p00004 | Runtime Error | while True:
a,b,c,d,e,f = map(float,raw_input().split())
x = (e*c-b*f) / (e*a-b*d)
y = (c*d-a*f) / (b*d-e*a)
print '%.3f %.3f' % (x,y) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s836918580 | p00004 | Runtime Error | while True:
try:
a,b,c,d,e,f = map(float,raw_input().split())
x = (e*c-b*f) / (e*a-b*d)
y = (c*d-a*f) / (b*d-e*a)
if x == -0.0:
x = 0
if y == -0.0
y = 0
print '%.3f %.3f' % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s124632260 | p00004 | Runtime Error | x=(e*d-b*f)/(a*d-b*c)
y=(-e*c+a*f)/(a*d-b*c)
print x
print y | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s784309889 | p00004 | WA: Presentation Error | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy
sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
class Matrix():
def __init__(self, A):
self.A = A
self.row = len(A)
self.col = len(A[0])
def __iter__(self):
return self.A.__iter__()
def __getitem__(self, i):
return self.A.__getitem__(i)
def __add__(self, B):
aa = self.A
bb = B.A
return Matrix([[aa[i][j] + bb[i][j] for j in range(self.col)] for i in range(self.row)])
def __sub__(self, B):
aa = self.A
bb = B.A
return Matrix([[aa[i][j] - bb[i][j] for j in range(self.col)] for i in range(self.row)])
def __mul__(self, B):
aa = self.A
bb = B.A
a = []
for i in range(self.row):
ai = aa[i]
r = []
for j in range(B.col):
r.append(sum([ai[k] * bb[k][j] for k in range(self.col)]))
a.append(r)
return Matrix(a)
def __truediv__(self, x):
pass
def lu(self):
# squaren??????
size = self.row
T = copy.deepcopy(self.A)
L = [[0]*size for _ in range(size)]
U = [[0]*size for _ in range(size)]
for i in range(size):
for j in range(i,size):
L[j][i] = T[j][i]
for j in range(i,size):
U[i][j] = T[i][j] / T[i][i]
for j in range(i+1,size):
for k in range(i+1,size):
T[j][k] -= L[j][i] * U[i][k]
return Matrix(L),Matrix(U)
def __str__(self):
return self.A.__str__()
# ??£???????¨????????§£???
def solve_se(A, b):
n = A.row
L,U = A.lu()
y = []
for i in range(n):
t = b[i]
for k in range(i):
t -= L[i][k] * y[k]
y.append(t / L[i][i])
x = [0] * n
for i in range(n-1,-1,-1):
t = y[i]
for k in range(i+1,n):
t -= U[i][k] * x[k]
x[i] = t
return x
def main():
sa = [s for s in sys.stdin.read().split('\n') if s]
r = []
for s in sa:
a,b,c,d,e,f = [int(c) for c in s.split()]
A = Matrix([[a,b],[d,e]])
B = [c,f]
x = solve_se(A,B)
r.append(' '.join(map(lambda t: '{:01.3f}'.format(t), x)))
return '\n'.join(r) + '\n'
print(main()) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s031575188 | p00004 | WA: Presentation Error | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy
sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
class Matrix():
def __init__(self, A):
self.A = A
self.row = len(A)
self.col = len(A[0])
def __iter__(self):
return self.A.__iter__()
def __getitem__(self, i):
return self.A.__getitem__(i)
def __add__(self, B):
aa = self.A
bb = B.A
return Matrix([[aa[i][j] + bb[i][j] for j in range(self.col)] for i in range(self.row)])
def __sub__(self, B):
aa = self.A
bb = B.A
return Matrix([[aa[i][j] - bb[i][j] for j in range(self.col)] for i in range(self.row)])
def __mul__(self, B):
aa = self.A
bb = B.A
a = []
for i in range(self.row):
ai = aa[i]
r = []
for j in range(B.col):
r.append(sum([ai[k] * bb[k][j] for k in range(self.col)]))
a.append(r)
return Matrix(a)
def __truediv__(self, x):
pass
def lu(self):
size = self.row
T = copy.deepcopy(self.A)
L = [[0]*size for _ in range(size)]
U = [[0]*size for _ in range(size)]
for i in range(size):
for j in range(i,size):
L[j][i] = T[j][i]
for j in range(i,size):
U[i][j] = T[i][j] / T[i][i]
for j in range(i+1,size):
for k in range(i+1,size):
T[j][k] -= L[j][i] * U[i][k]
return Matrix(L),Matrix(U)
def __str__(self):
return self.A.__str__()
def solve_se(A, b):
n = A.row
L,U = A.lu()
y = []
for i in range(n):
t = b[i]
for k in range(i):
t -= L[i][k] * y[k]
y.append(t / L[i][i])
x = [0] * n
for i in range(n-1,-1,-1):
t = y[i]
for k in range(i+1,n):
t -= U[i][k] * x[k]
x[i] = t
return x
def main():
sa = [s for s in sys.stdin.read().split('\n') if s]
r = []
for s in sa:
a,b,c,d,e,f = [int(c) for c in s.split()]
A = Matrix([[a,b],[d,e]])
B = [c,f]
x = solve_se(A,B)
r.append(' '.join(map(lambda t: '{:01.3f}'.format(t), x)))
return '\n'.join(r) + '\n'
print(main()) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s286432034 | p00004 | WA: Presentation Error | import sys
import math
r = sys.stdin.readlines()
#r.pop(0)
n = [[int(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])
x = (l[2]-l[1]*y)/l[0]
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s415945611 | p00004 | WA: Presentation Error | import sys
import math
r = sys.stdin.readlines()
n = [[int(i) for i in (j.split())] for j in r] #n is list of each lines
for l in n:
y = (l[2]*l[3]-l[0]*l[5])/(l[1]*l[3]-l[0]*l[4])
x = (l[2]-l[1]*y)/l[0]
print("{:.3f} {:.3f} ".format(x,y))
| 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s379884261 | p00004 | WA: Presentation Error | t = 0
while t == 0:
try:
a,b,e,c,d,f = [int(i) for i in input().split()]
except:
break
else:
x = (d*e - b*f) / (a*d - b*c) + 0
y = (a*f - c*e) / (a*d - b*c) + 0
print("{0:.3f}".format(x) + " " + "{0:.3f}".format(y)) | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s081661194 | p00004 | WA: Presentation Error | while True:
try:
a = map(float, raw_input().split(' '))
if a[1]*a[3]-a[0]*a[4] == 0:
print 'No answer'
else:
x = (a[1]*a[5]-a[2]*a[4])/(a[1]*a[3]-a[0]*a[4])
y = (a[2]*a[3]-a[0]*a[5])/(a[1]*a[3]-a[0]*a[4])
if x == 0:
x = abs(x)
if y == 0:
y = abs(y)
print '%.3f %.3f ' % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s138697210 | p00004 | WA: Presentation Error | while True:
try:
a = map(float, raw_input().split(' '))
x = (a[1]*a[5]-a[2]*a[4])/(a[1]*a[3]-a[0]*a[4])
y = (a[2]*a[3]-a[0]*a[5])/(a[1]*a[3]-a[0]*a[4])
if x == 0:
x = abs(x)
if y == 0:
y = abs(y)
print '%.3f %.3f ' % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s015185707 | p00004 | WA: Presentation Error | while True:
try:
a = map(float, raw_input().split(' '))
x = (a[1]*a[5]-a[2]*a[4])/(a[1]*a[3]-a[0]*a[4])
y = (a[2]*a[3]-a[0]*a[5])/(a[1]*a[3]-a[0]*a[4])
if x == 0:
x = 0
if y == 0:
y = 0
print '%.3f %.3f ' % (x,y)
except EOFError:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s995251037 | p00004 | WA: Presentation Error | while 1:
try:
a, b, c, d, e, f = map(float, raw_input().split())
x = (c * e - b * f) / (a * e - b * d)
y = (f * a - c * d) / (a * e - d * b)
if x == -0.000:
x = 0.000
if y == -0.000:
y = 0.000
print str('%.3f' % x) + " " + str('%.3f' % y) + "\n"
except:
break | 1 2 3 4 5 6
2 -1 -2 -1 -1 -5
| -1.000 2.000
1.000 4.000
|
<H1>Simultaneous Equation</H1>
<p>
Write a program which solve a simultaneous equation:<br>
<br>
<var> ax + by = c</var><br>
<var> dx + ey = f</var><br>
<br>
The program should print <var>x</var> and <var>y</var> for given <var>a</var>, <var>b</var>, <var>c</var>, <var>d</var>, <var>e</var> and <var>f</var> (-1,000 ≤ <var>a, b, c, d, e, f</var> ≤ 1,000). You can suppose that given equation has a unique solution.
</p>
<H2>Input</H2>
<p>
The input consists of several data sets, 1 line for each data set. In a data set, there will be <var>a, b, c, d, e, f</var> separated by a single space. The input terminates with EOF.
</p>
<H2>Output</H2>
<p>
For each data set, print <var>x</var> and <var>y</var> separated by a single space. Print the solution to three places of decimals. Round off the solution to three decimal places.
</p>
<H2>Sample Input 1</H2>
<pre>
1 2 3 4 5 6
2 -1 -2 -1 -1 -5
</pre>
<H2>Output for the Sample Input 1</H2>
<pre>
-1.000 2.000
1.000 4.000
</pre>
<H2>Sample Input 2</H2>
<pre>
2 -1 -3 1 -1 -3
2 -1 -3 -9 9 27
</pre>
<H2>Output for the Sample Input 2</H2>
<pre>
0.000 3.000
0.000 3.000
</pre>
|
s937099911 | p00005 | Wrong Answer | import sys
for i in sys.stdin :
m,n = map(int , i.split())
t1,t2=m,n
while 1 :
if m % n == 0 :
break
m , n = n , m % n
a = n
b = (t1 / a ) * t2
print "%d %d" % (a,b) | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s374927746 | p00005 | Wrong Answer | import sys
for line in sys.stdin:
a, b = map(int, line.split())
A, B = min(a, b), max(a, b)
while True:
mod = B % A
if mod == 0:
gcd = B / A
break
else:
A, B = mod, A
lcm = gcd * (a / gcd) * (b / gcd)
print '%d %d' % (gcd, lcm) | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s723808020 | p00005 | Wrong Answer | while True:
try:
i=list(map(int,input().split()))
i.sort()
x=i[:]
while True:
if i[1]%i[0]!=0:
i[0],i[1] = i[1]%i[0],i[1]
else:
print(i[0],int(x[0]*x[1]/i[0]))
break;
except:
break; | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s664711126 | p00005 | Wrong Answer | import sys
def main():
a = sys.stdin.readline()
print ("Hello World")
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s435656420 | p00005 | Wrong Answer | import sys
def main():
tmp = sys.stdin.readline().split(" ")
print ("Hello World")
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s147281364 | p00005 | Wrong Answer | import sys
def main():
tmp = sys.stdin.readline().split(" ")
print (tmp[0])
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s015390918 | p00005 | Wrong Answer | import sys
def main():
tmp = sys.stdin.readline().split(" ")
print (tmp[0])
print (tmp[1])
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s799982375 | p00005 | Wrong Answer | import sys
def main():
tmp = sys.stdin.readline().split(" ")
print (str(int(tmp[0])))
print (str(int(tmp[1])))
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s045083332 | p00005 | Wrong Answer | import sys
def main():
for line in iter(sys.stdin.readline, ""):
print (line)
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s277195747 | p00005 | Wrong Answer | import sys
#最大公約数
def gcd(x, y):
s = x / y
r = x % y
if r == 0:
return y
else:
return gcd(y, r)
#最小公倍数
def lcm(x, y):
return x*y/gcd(x, y)
def main():
#print ("a")
for line in iter(sys.stdin.readline, ""):
print (line)
#tmp = sys.stdin.readline().split(" ")
#print ("b")
tmp = line.split(" ")
a = int(tmp[0])
b = int(tmp[1])
#print ("a="+str(a))
#print ("b="+str(b))
#b = sys.stdin.readline()
#print ("d")
if a > b:
c = a
d = b
else:
c = b
d = a
print (str(gcd(c, d)) + " " + str(int(lcm(c,d))))
#tmp = sys.stdin.readline()
#if len(tmp) == 1:
# break
#else:
# tmp = tmp.split(" ")
#print ("exit")
if __name__ == "__main__":
main() | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s008641712 | p00005 | Wrong Answer | while True:
try:
spam=map(int, input().split(' '))
spam = [i for i in spam]
spam.sort()
cola = spam[0] * spam[1]
while True:
if spam[0] == 0:
print(spam[1])
print(int(cola/spam[1]))
break
pre = spam[0]
spam[0] = spam[1] % spam[0]
spam[1] = pre
except:
break | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s976630252 | p00005 | Wrong Answer | import sys
def dividend(num, Q):
a = Q
b = (num / Q) * Q
Q = num - (num / Q) * Q
if num == b:
aaa(a)
dividend(num, Q)
def aaa(greatest_common_divisor):
least_common_multiple = num1 * num2 / greatest_common_divisor
print('%s %s' % (greatest_common_divisor, least_common_multiple))
sys.exit()
for input_line in sys.stdin:
num1 = int(input_line.split(' ')[0])
num2 = int(input_line.split(' ')[1])
if num1 <= num2:
dividend(num2, num1)
elif num1 > num2:
dividend(num1, num2) | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s654593618 | p00005 | Wrong Answer | import sys
def dividend(num, Q):
a = Q
b = (num / Q) * Q
Q = num - (num / Q) * Q
if num == b:
return aaa(a)
dividend(num, Q)
def aaa(greatest_common_divisor):
least_common_multiple = num1 * num2 / greatest_common_divisor
print('%s %s' % (greatest_common_divisor, least_common_multiple))
return
for input_line in sys.stdin:
num1 = int(input_line.split(' ')[0])
num2 = int(input_line.split(' ')[1])
if num1 <= num2:
dividend(num2, num1)
elif num1 > num2:
dividend(num1, num2) | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s348863279 | p00005 | Wrong Answer | import sys
def dividend(num, Q):
a = Q
b = (num / Q) * Q
Q = num - (num / Q) * Q
if num == b:
aaa(a)
return
dividend(num, Q)
def aaa(greatest_common_divisor):
least_common_multiple = num1 * num2 / greatest_common_divisor
print('%s %s' % (greatest_common_divisor, least_common_multiple))
return
for input_line in sys.stdin:
num1 = int(input_line.split(' ')[0])
num2 = int(input_line.split(' ')[1])
if num1 <= num2:
dividend(num2, num1)
elif num1 > num2:
dividend(num1, num2) | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s384148001 | p00005 | Wrong Answer | def gcd(a, b):
while b:
a, b = b, a % b
return a
while True:
try:
a, b = map(int, (input.split()))
except:
break
g = gcd(a, b)
print(g, a * b // g) | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s752438284 | p00005 | Wrong Answer | def gcd(a, b):
while b:
a, b = b, a % b
return a
while True:
try:
a, b = map(int, input().split())
print(gcd(a, b), a * b // gcd(a, b))
except:
break | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
s955372955 | p00005 | Wrong Answer | def gcd(a,b): return a if b==0 else gcd(b,a%b)
def lcm(a,b): return a*b/gcd(a,b)
while 1:
try:
a,b=map(int,raw_input().split())
except:
break | 8 6
50000000 30000000
| 2 24
10000000 150000000
|
<H1>GCD and LCM</H1>
<p>
Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given <var>a</var> and <var>b</var>.
</p>
<H2>Input</H2>
<p>
Input consists of several data sets. Each data set contains <var>a</var> and <var>b</var> separated by a single space in a line. The input terminates with EOF.
</p>
<h2>Constraints</h2>
<ul>
<li> 0 < <var>a, b</var> ≤ 2,000,000,000</li>
<li> LCM(<var>a, b</var>) ≤ 2,000,000,000</li>
<li> The number of data sets ≤ 50</li>
</ul>
<H2>Output</H2>
<p>
For each data set, print GCD and LCM separated by a single space in a line.
</p>
<H2>Sample Input</H2>
<pre>
8 6
50000000 30000000
</pre>
<H2>Output for the Sample Input</H2>
<pre>
2 24
10000000 150000000
</pre>
|
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