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SELECT AVG(transaction_amount), MIN(transaction_amount), MAX(transaction_amount), SUM(transaction_amount) FROM Financial_transactions
What is the average, minimum, maximum, and total transaction amount?
CREATE TABLE Financial_transactions (transaction_amount INTEGER)
Qual é o valor médio, mínimo, máximo e total da transação?
901
SELECT transaction_id FROM Financial_transactions WHERE transaction_amount > (SELECT AVG(transaction_amount) FROM Financial_transactions)
Show ids for all transactions whose amounts are greater than the average.
CREATE TABLE Financial_transactions (transaction_id VARCHAR, transaction_amount INTEGER)
Mostrar IDs para todas as transações cujos valores são maiores que a média.
902
SELECT transaction_type, SUM(transaction_amount) FROM Financial_transactions GROUP BY transaction_type
Show the transaction types and the total amount of transactions.
CREATE TABLE Financial_transactions (transaction_type VARCHAR, transaction_amount INTEGER)
Mostrar os tipos de transação e a quantidade total de transações.
903
SELECT T2.account_name, T1.account_id, COUNT(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id
Show the account name, id and the number of transactions for each account.
CREATE TABLE Financial_transactions (account_id VARCHAR); CREATE TABLE Accounts (account_name VARCHAR, account_id VARCHAR)
Mostre o nome da conta, o ID e o número de transações para cada conta.
904
SELECT account_id FROM Financial_transactions GROUP BY account_id ORDER BY COUNT(*) DESC LIMIT 1
Show the account id with most number of transactions.
CREATE TABLE Financial_transactions (account_id VARCHAR)
Mostre o ID da conta com o maior número de transações.
905
SELECT T1.account_id, T2.account_name FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id HAVING COUNT(*) >= 4
Show the account id and name with at least 4 transactions.
CREATE TABLE Financial_transactions (account_id VARCHAR); CREATE TABLE Accounts (account_name VARCHAR, account_id VARCHAR)
Mostre o ID da conta e o nome com pelo menos 4 transações.
906
SELECT DISTINCT product_size FROM Products
Show all product sizes.
CREATE TABLE Products (product_size VARCHAR)
Mostrar todos os tamanhos do produto.
907
SELECT DISTINCT product_color FROM Products
Show all product colors.
CREATE TABLE Products (product_color VARCHAR)
Mostrar todas as cores do produto.
908
SELECT invoice_number, COUNT(*) FROM Financial_transactions GROUP BY invoice_number
Show the invoice number and the number of transactions for each invoice.
CREATE TABLE Financial_transactions (invoice_number VARCHAR)
Mostre o número da fatura e o número de transações para cada fatura.
909
SELECT T2.invoice_number, T2.invoice_date FROM Financial_transactions AS T1 JOIN Invoices AS T2 ON T1.invoice_number = T2.invoice_number GROUP BY T1.invoice_number ORDER BY COUNT(*) DESC LIMIT 1
What is the invoice number and invoice date for the invoice with most number of transactions?
CREATE TABLE Invoices (invoice_number VARCHAR, invoice_date VARCHAR); CREATE TABLE Financial_transactions (invoice_number VARCHAR)
Qual é o número da fatura e a data da fatura para a fatura com o maior número de transações?
910
SELECT COUNT(*) FROM Invoices
How many invoices do we have?
CREATE TABLE Invoices (Id VARCHAR)
Quantas faturas temos?
911
SELECT T1.invoice_date, T1.order_id, T2.order_details FROM Invoices AS T1 JOIN Orders AS T2 ON T1.order_id = T2.order_id
Show invoice dates and order id and details for all invoices.
CREATE TABLE Invoices (invoice_date VARCHAR, order_id VARCHAR); CREATE TABLE Orders (order_details VARCHAR, order_id VARCHAR)
Mostrar as datas da fatura e o ID do pedido e os detalhes de todas as faturas.
912
SELECT order_id, COUNT(*) FROM Invoices GROUP BY order_id
Show the order ids and the number of invoices for each order.
CREATE TABLE Invoices (order_id VARCHAR)
Mostre os IDs do pedido e o número de faturas para cada pedido.
913
SELECT T2.order_id, T2.order_details FROM Invoices AS T1 JOIN Orders AS T2 ON T1.order_id = T2.order_id GROUP BY T2.order_id HAVING COUNT(*) > 2
What is the order id and order details for the order more than two invoices.
CREATE TABLE Orders (order_id VARCHAR, order_details VARCHAR); CREATE TABLE Invoices (order_id VARCHAR)
Qual é o ID do pedido e os detalhes do pedido mais de duas faturas.
914
SELECT T2.customer_last_name, T1.customer_id, T2.phone_number FROM Orders AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) DESC LIMIT 1
What is the customer last name, id and phone number with most number of orders?
CREATE TABLE Orders (customer_id VARCHAR); CREATE TABLE Customers (customer_last_name VARCHAR, phone_number VARCHAR, customer_id VARCHAR)
Qual é o sobrenome do cliente, ID e número de telefone com o maior número de pedidos?
915
SELECT product_name FROM Products EXCEPT SELECT T1.product_name FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id
Show all product names without an order.
CREATE TABLE Products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE Order_items (product_id VARCHAR); CREATE TABLE Products (product_name VARCHAR)
Mostre todos os nomes de produtos sem uma ordem.
916
SELECT T2.product_name, SUM(T1.product_quantity) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name
Show all product names and the total quantity ordered for each product name.
CREATE TABLE Products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE Order_items (product_quantity INTEGER, product_id VARCHAR)
Mostrar todos os nomes dos produtos e a quantidade total encomendada para cada nome de produto.
917
SELECT order_id, COUNT(*) FROM Order_items GROUP BY order_id
Show the order ids and the number of items in each order.
CREATE TABLE Order_items (order_id VARCHAR)
Mostre os IDs da ordem e o número de itens em cada ordem.
918
SELECT product_id, COUNT(DISTINCT order_id) FROM Order_items GROUP BY product_id
Show the product ids and the number of unique orders containing each product.
CREATE TABLE Order_items (product_id VARCHAR, order_id VARCHAR)
Mostre os IDs do produto e o número de pedidos exclusivos que contêm cada produto.
919
SELECT T2.product_name, COUNT(*) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T3.order_id = T1.order_id GROUP BY T2.product_name
Show all product names and the number of customers having an order on each product.
CREATE TABLE Order_items (product_id VARCHAR, order_id VARCHAR); CREATE TABLE Orders (order_id VARCHAR); CREATE TABLE Products (product_name VARCHAR, product_id VARCHAR)
Mostre todos os nomes de produtos e o número de clientes que têm um pedido em cada produto.
920
SELECT order_id, COUNT(DISTINCT product_id) FROM Order_items GROUP BY order_id
Show order ids and the number of products in each order.
CREATE TABLE Order_items (order_id VARCHAR, product_id VARCHAR)
Mostrar IDs de pedidos e o número de produtos em cada pedido.
921
SELECT order_id, SUM(product_quantity) FROM Order_items GROUP BY order_id
Show order ids and the total quantity in each order.
CREATE TABLE Order_items (order_id VARCHAR, product_quantity INTEGER)
Mostrar IDs de ordem e a quantidade total em cada ordem.
922
SELECT COUNT(*) FROM products WHERE NOT product_id IN (SELECT product_id FROM Order_items)
How many products were not included in any order?
CREATE TABLE products (product_id VARCHAR); CREATE TABLE Order_items (product_id VARCHAR)
Quantos produtos não foram incluídos em nenhuma ordem?
923
SELECT COUNT(*) FROM Church WHERE Open_Date < 1850
How many churches opened before 1850 are there?
CREATE TABLE Church (Open_Date INTEGER)
Quantas igrejas foram abertas antes de 1850?
924
SELECT name, open_date, organized_by FROM Church
Show the name, open date, and organizer for all churches.
CREATE TABLE Church (name VARCHAR, open_date VARCHAR, organized_by VARCHAR)
Mostre o nome, a data de abertura e o organizador de todas as igrejas.
925
SELECT name FROM church ORDER BY open_date DESC
List all church names in descending order of opening date.
CREATE TABLE church (name VARCHAR, open_date VARCHAR)
Listar todos os nomes da igreja em ordem decrescente de data de abertura.
926
SELECT open_date FROM church GROUP BY open_date HAVING COUNT(*) >= 2
Show the opening year in whcih at least two churches opened.
CREATE TABLE church (open_date VARCHAR)
Mostre o ano de abertura em whcih pelo menos duas igrejas abertas.
927
SELECT organized_by, name FROM church WHERE open_date BETWEEN 1830 AND 1840
Show the organizer and name for churches that opened between 1830 and 1840.
CREATE TABLE church (organized_by VARCHAR, name VARCHAR, open_date INTEGER)
Mostre o organizador e o nome das igrejas que abriram entre 1830 e 1840.
928
SELECT open_date, COUNT(*) FROM church GROUP BY open_date
Show all opening years and the number of churches that opened in that year.
CREATE TABLE church (open_date VARCHAR)
Mostre todos os anos de abertura e o número de igrejas que abriram naquele ano.
929
SELECT name, open_date FROM church ORDER BY open_date DESC LIMIT 3
Show the name and opening year for three churches that opened most recently.
CREATE TABLE church (name VARCHAR, open_date VARCHAR)
Mostre o nome e o ano de abertura para três igrejas que foram inauguradas mais recentemente.
930
SELECT COUNT(*) FROM people WHERE is_male = 'F' AND age > 30
How many female people are older than 30 in our record?
CREATE TABLE people (is_male VARCHAR, age VARCHAR)
Quantas mulheres têm mais de 30 anos em nosso registro?
931
SELECT country FROM people WHERE age < 25 INTERSECT SELECT country FROM people WHERE age > 30
Show the country where people older than 30 and younger than 25 are from.
CREATE TABLE people (country VARCHAR, age INTEGER)
Mostre ao país de onde vêm pessoas com mais de 30 anos ou menos de 25 anos.
932
SELECT MIN(age), MAX(age), AVG(age) FROM people
Show the minimum, maximum, and average age for all people.
CREATE TABLE people (age INTEGER)
Mostre a idade mínima, máxima e média para todas as pessoas.
933
SELECT name, country FROM people WHERE age < (SELECT AVG(age) FROM people)
Show the name and country for all people whose age is smaller than the average.
CREATE TABLE people (name VARCHAR, country VARCHAR, age INTEGER)
Mostre o nome e o país para todas as pessoas cuja idade seja menor que a média.
934
SELECT T2.name, T3.name FROM wedding AS T1 JOIN people AS T2 ON T1.male_id = T2.people_id JOIN people AS T3 ON T1.female_id = T3.people_id WHERE T1.year > 2014
Show the pair of male and female names in all weddings after year 2014
CREATE TABLE wedding (male_id VARCHAR, female_id VARCHAR, year INTEGER); CREATE TABLE people (name VARCHAR, people_id VARCHAR)
Mostre o par de nomes masculinos e femininos em todos os casamentos após o ano de 2014
935
SELECT name, age FROM people WHERE is_male = 'T' AND NOT people_id IN (SELECT male_id FROM wedding)
Show the name and age for all male people who don't have a wedding.
CREATE TABLE wedding (name VARCHAR, age VARCHAR, is_male VARCHAR, people_id VARCHAR, male_id VARCHAR); CREATE TABLE people (name VARCHAR, age VARCHAR, is_male VARCHAR, people_id VARCHAR, male_id VARCHAR)
Mostre o nome e a idade para todos os homens que não têm um casamento.
936
SELECT name FROM church EXCEPT SELECT T1.name FROM church AS T1 JOIN wedding AS T2 ON T1.church_id = T2.church_id WHERE T2.year = 2015
Show all church names except for those that had a wedding in year 2015.
CREATE TABLE church (name VARCHAR); CREATE TABLE wedding (church_id VARCHAR, year VARCHAR); CREATE TABLE church (name VARCHAR, church_id VARCHAR)
Mostre todos os nomes da igreja, exceto aqueles que tiveram um casamento no ano de 2015.
937
SELECT T1.name FROM church AS T1 JOIN wedding AS T2 ON T1.church_id = T2.church_id GROUP BY T1.church_id HAVING COUNT(*) >= 2
Show all church names that have hosted least two weddings.
CREATE TABLE wedding (church_id VARCHAR); CREATE TABLE church (name VARCHAR, church_id VARCHAR)
Mostre todos os nomes de igrejas que já receberam pelo menos dois casamentos.
938
SELECT T2.name FROM wedding AS T1 JOIN people AS T2 ON T1.female_id = T2.people_id WHERE T1.year = 2016 AND T2.is_male = 'F' AND T2.country = 'Canada'
Show the names for all females from Canada having a wedding in year 2016.
CREATE TABLE people (name VARCHAR, people_id VARCHAR, country VARCHAR, is_male VARCHAR); CREATE TABLE wedding (female_id VARCHAR, year VARCHAR)
Mostre os nomes de todas as mulheres do Canadá que têm um casamento no ano de 2016.
939
SELECT COUNT(*) FROM wedding WHERE YEAR = 2016
How many weddings are there in year 2016?
CREATE TABLE wedding (YEAR VARCHAR)
Quantos casamentos existem no ano de 2016?
940
SELECT T4.name FROM wedding AS T1 JOIN people AS T2 ON T1.male_id = T2.people_id JOIN people AS T3 ON T1.female_id = T3.people_id JOIN church AS T4 ON T4.church_id = T1.church_id WHERE T2.age > 30 OR T3.age > 30
Show the church names for the weddings of all people older than 30.
CREATE TABLE church (name VARCHAR, church_id VARCHAR); CREATE TABLE people (people_id VARCHAR, age VARCHAR); CREATE TABLE wedding (male_id VARCHAR, female_id VARCHAR, church_id VARCHAR)
Mostre os nomes da igreja para os casamentos de todas as pessoas com mais de 30 anos.
941
SELECT country, COUNT(*) FROM people GROUP BY country
Show all countries and the number of people from each country.
CREATE TABLE people (country VARCHAR)
Mostrar todos os países e o número de pessoas de cada país.
942
SELECT COUNT(DISTINCT church_id) FROM wedding WHERE YEAR = 2016
How many churches have a wedding in year 2016?
CREATE TABLE wedding (church_id VARCHAR, YEAR VARCHAR)
Quantas igrejas têm um casamento no ano de 2016?
943
SELECT COUNT(*) FROM artist
How many artists do we have?
CREATE TABLE artist (Id VARCHAR)
Quantos artistas temos?
944
SELECT name, age, country FROM artist ORDER BY Year_Join
Show all artist name, age, and country ordered by the yeared they joined.
CREATE TABLE artist (name VARCHAR, age VARCHAR, country VARCHAR, Year_Join VARCHAR)
Mostre todo o nome do artista, idade e país ordenados pelo ano em que se juntaram.
945
SELECT DISTINCT country FROM artist
What are all distinct country for artists?
CREATE TABLE artist (country VARCHAR)
O que é um país distinto para os artistas?
946
SELECT name, year_join FROM artist WHERE country <> 'United States'
Show all artist names and the year joined who are not from United States.
CREATE TABLE artist (name VARCHAR, year_join VARCHAR, country VARCHAR)
Mostre todos os nomes de artistas e o ano que se juntou que não são dos Estados Unidos.
947
SELECT COUNT(*) FROM artist WHERE age > 46 AND year_join > 1990
How many artists are above age 46 and joined after 1990?
CREATE TABLE artist (age VARCHAR, year_join VARCHAR)
Quantos artistas estão acima dos 46 anos e se juntaram depois de 1990?
948
SELECT AVG(age), MIN(age) FROM artist WHERE country = 'United States'
What is the average and minimum age of all artists from United States.
CREATE TABLE artist (age INTEGER, country VARCHAR)
Qual é a idade média e mínima de todos os artistas dos Estados Unidos?
949
SELECT name FROM artist ORDER BY year_join DESC LIMIT 1
What is the name of the artist who joined latest?
CREATE TABLE artist (name VARCHAR, year_join VARCHAR)
Qual é o nome do artista que se juntou mais tarde?
950
SELECT COUNT(*) FROM exhibition WHERE YEAR >= 2005
How many exhibition are there in year 2005 or after?
CREATE TABLE exhibition (YEAR VARCHAR)
Quantas exposições existem no ano de 2005 ou depois?
951
SELECT theme, YEAR FROM exhibition WHERE ticket_price < 15
Show theme and year for all exhibitions with ticket prices lower than 15.
CREATE TABLE exhibition (theme VARCHAR, YEAR VARCHAR, ticket_price INTEGER)
Mostre o tema e o ano para todas as exposições com preços de ingressos inferiores a 15.
952
SELECT T2.name, COUNT(*) FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id GROUP BY T1.artist_id
Show all artist names and the number of exhibitions for each artist.
CREATE TABLE artist (name VARCHAR, artist_id VARCHAR); CREATE TABLE exhibition (artist_id VARCHAR)
Mostre todos os nomes dos artistas e o número de exposições para cada artista.
953
SELECT T2.name, T2.country FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id GROUP BY T1.artist_id ORDER BY COUNT(*) DESC LIMIT 1
What is the name and country for the artist with most number of exhibitions?
CREATE TABLE exhibition (artist_id VARCHAR); CREATE TABLE artist (name VARCHAR, country VARCHAR, artist_id VARCHAR)
Qual é o nome e o país do artista com maior número de exposições?
954
SELECT name FROM artist WHERE NOT artist_id IN (SELECT artist_id FROM exhibition)
Show names for artists without any exhibition.
CREATE TABLE artist (name VARCHAR, artist_id VARCHAR); CREATE TABLE exhibition (name VARCHAR, artist_id VARCHAR)
Mostre nomes para artistas sem nenhuma exposição.
955
SELECT T1.theme, T2.name FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id WHERE T1.ticket_price > (SELECT AVG(ticket_price) FROM exhibition)
What is the theme and artist name for the exhibition with a ticket price higher than the average?
CREATE TABLE exhibition (ticket_price INTEGER); CREATE TABLE exhibition (theme VARCHAR, artist_id VARCHAR, ticket_price INTEGER); CREATE TABLE artist (name VARCHAR, artist_id VARCHAR)
Qual é o tema e nome do artista para a exposição com um preço de bilhete superior à média?
956
SELECT AVG(ticket_price), MIN(ticket_price), MAX(ticket_price) FROM exhibition WHERE YEAR < 2009
Show the average, minimum, and maximum ticket prices for exhibitions for all years before 2009.
CREATE TABLE exhibition (ticket_price INTEGER, YEAR INTEGER)
Mostre os preços médios, mínimos e máximos dos ingressos para as exposições de todos os anos anteriores a 2009.
957
SELECT theme, YEAR FROM exhibition ORDER BY ticket_price DESC
Show theme and year for all exhibitions in an descending order of ticket price.
CREATE TABLE exhibition (theme VARCHAR, YEAR VARCHAR, ticket_price VARCHAR)
Mostre o tema e o ano para todas as exposições em uma ordem decrescente de preço do bilhete.
958
SELECT T2.theme, T1.date, T1.attendance FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id WHERE T2.year = 2004
What is the theme, date, and attendance for the exhibition in year 2004?
CREATE TABLE exhibition_record (date VARCHAR, attendance VARCHAR, exhibition_id VARCHAR); CREATE TABLE exhibition (theme VARCHAR, exhibition_id VARCHAR, year VARCHAR)
Qual é o tema, data e presença para a exposição no ano de 2004?
959
SELECT name FROM artist EXCEPT SELECT T2.name FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id WHERE T1.year = 2004
Show all artist names who didn't have an exhibition in 2004.
CREATE TABLE exhibition (artist_id VARCHAR, year VARCHAR); CREATE TABLE artist (name VARCHAR); CREATE TABLE artist (name VARCHAR, artist_id VARCHAR)
Mostre todos os nomes de artistas que não tiveram uma exposição em 2004.
960
SELECT T2.theme FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id WHERE T1.attendance < 100 INTERSECT SELECT T2.theme FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id WHERE T1.attendance > 500
Show the theme for exhibitions with both records of an attendance below 100 and above 500.
CREATE TABLE exhibition (theme VARCHAR, exhibition_id VARCHAR); CREATE TABLE exhibition_record (exhibition_id VARCHAR, attendance INTEGER)
Mostre o tema para exposições com ambos os registros de um atendimento abaixo de 100 e acima de 500.
961
SELECT COUNT(*) FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id WHERE T1.attendance > 100 OR T2.ticket_price < 10
How many exhibitions have a attendance more than 100 or have a ticket price below 10?
CREATE TABLE exhibition_record (exhibition_id VARCHAR, attendance VARCHAR); CREATE TABLE exhibition (exhibition_id VARCHAR, ticket_price VARCHAR)
Quantas exposições têm uma participação superior a 100 ou têm um preço de bilhete abaixo de 10?
962
SELECT T3.name FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id JOIN artist AS T3 ON T3.artist_id = T2.artist_id GROUP BY T3.artist_id HAVING AVG(T1.attendance) > 200
Show all artist names with an average exhibition attendance over 200.
CREATE TABLE artist (name VARCHAR, artist_id VARCHAR); CREATE TABLE exhibition (exhibition_id VARCHAR, artist_id VARCHAR); CREATE TABLE exhibition_record (exhibition_id VARCHAR, attendance INTEGER)
Mostre todos os nomes de artistas com um público médio de exposição superior a 200.
963
SELECT i_id FROM item WHERE title = "orange"
Find the id of the item whose title is "orange".
CREATE TABLE item (i_id VARCHAR, title VARCHAR)
Encontre o id do item cujo título é "laranja".
964
SELECT * FROM item
List all information in the item table.
CREATE TABLE item (Id VARCHAR)
Liste todas as informações na tabela de itens.
965
SELECT COUNT(*) FROM review
Find the number of reviews.
CREATE TABLE review (Id VARCHAR)
Encontre o número de reviews.
966
SELECT COUNT(*) FROM useracct
How many users are there?
CREATE TABLE useracct (Id VARCHAR)
Quantos usuários existem?
967
SELECT AVG(rating), MAX(rating) FROM review
Find the average and maximum rating of all reviews.
CREATE TABLE review (rating INTEGER)
Encontre a classificação média e máxima de todas as avaliações.
968
SELECT MIN(rank) FROM review
Find the highest rank of all reviews.
CREATE TABLE review (rank INTEGER)
Encontre a classificação mais alta de todas as avaliações.
969
SELECT COUNT(DISTINCT u_id) FROM review
How many different users wrote some reviews?
CREATE TABLE review (u_id VARCHAR)
Quantos usuários diferentes escreveram alguns comentários?
970
SELECT COUNT(DISTINCT i_id) FROM review
How many different items were reviewed by some users?
CREATE TABLE review (i_id VARCHAR)
Quantos itens diferentes foram revisados por alguns usuários?
971
SELECT COUNT(*) FROM item WHERE NOT i_id IN (SELECT i_id FROM review)
Find the number of items that did not receive any review.
CREATE TABLE review (i_id VARCHAR); CREATE TABLE item (i_id VARCHAR)
Encontre o número de itens que não receberam nenhuma revisão.
972
SELECT name FROM useracct WHERE NOT u_id IN (SELECT u_id FROM review)
Find the names of users who did not leave any review.
CREATE TABLE review (name VARCHAR, u_id VARCHAR); CREATE TABLE useracct (name VARCHAR, u_id VARCHAR)
Encontre os nomes dos usuários que não deixaram nenhum comentário.
973
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating = 10
Find the names of goods that receive a rating of 10.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rating VARCHAR)
Encontre os nomes das mercadorias que recebem uma classificação de 10.
974
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > (SELECT AVG(rating) FROM review)
Find the titles of items whose rating is higher than the average review rating of all items.
CREATE TABLE review (rating INTEGER); CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rating INTEGER)
Encontre os títulos dos itens cuja classificação é maior do que a média de avaliação de todos os itens.
975
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
Find the titles of items that received any rating below 5.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rating INTEGER)
Encontre os títulos dos itens que receberam qualquer classificação abaixo de 5.
976
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > 8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
Find the titles of items that received both a rating higher than 8 and a rating below 5.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rating INTEGER)
Encontre os títulos dos itens que receberam uma classificação superior a 8 e uma classificação abaixo de 5.
977
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rank > 3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id HAVING AVG(T2.rating) > 5
Find the names of items whose rank is higher than 3 and whose average rating is above 5.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rank INTEGER, rating INTEGER)
Encontre os nomes dos itens cuja classificação é superior a 3 e cuja classificação média é superior a 5.
978
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY AVG(T2.rating) LIMIT 1
Find the name of the item with the lowest average rating.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rating INTEGER)
Encontre o nome do item com a classificação média mais baixa.
979
SELECT title FROM item ORDER BY title
List the titles of all items in alphabetic order .
CREATE TABLE item (title VARCHAR)
Liste os títulos de todos os itens em ordem alfabética .
980
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY COUNT(*) DESC LIMIT 1
Find the name of the user who gives the most reviews.
CREATE TABLE useracct (name VARCHAR, u_id VARCHAR); CREATE TABLE review (u_id VARCHAR)
Encontre o nome do usuário que dá mais avaliações.
981
SELECT T1.title, T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY AVG(T2.rating) DESC LIMIT 1
Find the name and id of the item with the highest average rating.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (i_id VARCHAR, rating INTEGER)
Encontre o nome e o ID do item com a classificação média mais alta.
982
SELECT T1.title, T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY AVG(T2.rank) DESC LIMIT 1
Find the name and id of the good with the highest average rank.
CREATE TABLE review (i_id VARCHAR, rank INTEGER); CREATE TABLE item (title VARCHAR, i_id VARCHAR)
Encontre o nome e o ID do bem com a classificação média mais alta.
983
SELECT T1.name, AVG(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
For each user, return the name and the average rating of reviews given by them.
CREATE TABLE review (rating INTEGER, u_id VARCHAR); CREATE TABLE useracct (name VARCHAR, u_id VARCHAR)
Para cada usuário, devolva o nome e a classificação média das avaliações dadas por eles.
984
SELECT T1.name, COUNT(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
For each user, find their name and the number of reviews written by them.
CREATE TABLE useracct (name VARCHAR, u_id VARCHAR); CREATE TABLE review (u_id VARCHAR)
Para cada usuário, encontre seu nome e o número de comentários escritos por eles.
985
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id ORDER BY T2.rating DESC LIMIT 1
Find the name of the user who gave the highest rating.
CREATE TABLE review (u_id VARCHAR, rating VARCHAR); CREATE TABLE useracct (name VARCHAR, u_id VARCHAR)
Encontre o nome do usuário que deu a classificação mais alta.
986
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.source_u_id GROUP BY T2.source_u_id ORDER BY AVG(trust) DESC LIMIT 1
Find the name of the source user with the highest average trust score.
CREATE TABLE useracct (name VARCHAR, u_id VARCHAR); CREATE TABLE trust (source_u_id VARCHAR)
Encontre o nome do usuário de origem com a maior pontuação média de confiança.
987
SELECT T1.name, AVG(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id GROUP BY T2.target_u_id
Find each target user's name and average trust score.
CREATE TABLE trust (target_u_id VARCHAR); CREATE TABLE useracct (name VARCHAR, u_id VARCHAR)
Encontre o nome de cada usuário-alvo e a pontuação média de confiança.
988
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id ORDER BY trust LIMIT 1
Find the name of the target user with the lowest trust score.
CREATE TABLE trust (target_u_id VARCHAR); CREATE TABLE useracct (name VARCHAR, u_id VARCHAR)
Encontre o nome do usuário-alvo com a menor pontuação de confiança.
989
SELECT title FROM item WHERE NOT i_id IN (SELECT i_id FROM review)
Find the names of the items that did not receive any review.
CREATE TABLE item (title VARCHAR, i_id VARCHAR); CREATE TABLE review (title VARCHAR, i_id VARCHAR)
Encontre os nomes dos itens que não receberam nenhuma revisão.
990
SELECT COUNT(*) FROM useracct WHERE NOT u_id IN (SELECT u_id FROM review)
Find the number of users who did not write any review.
CREATE TABLE review (u_id VARCHAR); CREATE TABLE useracct (u_id VARCHAR)
Encontre o número de usuários que não escreveram nenhuma revisão.
991
SELECT COUNT(*) FROM player
How many players are there?
CREATE TABLE player (Id VARCHAR)
Quantos jogadores existem?
992
SELECT Player_name FROM player ORDER BY Votes
List the names of players in ascending order of votes.
CREATE TABLE player (Player_name VARCHAR, Votes VARCHAR)
Listar os nomes dos jogadores em ordem crescente de votos.
993
SELECT Gender, Occupation FROM player
What are the gender and occupation of players?
CREATE TABLE player (Gender VARCHAR, Occupation VARCHAR)
Qual é o gênero e a ocupação dos jogadores?
994
SELECT Player_name, residence FROM player WHERE Occupation <> "Researcher"
List the name and residence for players whose occupation is not "Researcher".
CREATE TABLE player (Player_name VARCHAR, residence VARCHAR, Occupation VARCHAR)
Liste o nome e a residência de jogadores cuja ocupação não seja "Pesquisador".
995
SELECT Sponsor_name FROM player WHERE Residence = "Brandon" OR Residence = "Birtle"
Show the names of sponsors of players whose residence is either "Brandon" or "Birtle".
CREATE TABLE player (Sponsor_name VARCHAR, Residence VARCHAR)
Mostre os nomes dos patrocinadores dos jogadores cuja residência seja "Brandon" ou "Birtle".
996
SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1
What is the name of the player with the largest number of votes?
CREATE TABLE player (Player_name VARCHAR, Votes VARCHAR)
Qual é o nome do jogador com o maior número de votos?
997
SELECT Occupation, COUNT(*) FROM player GROUP BY Occupation
Show different occupations along with the number of players in each occupation.
CREATE TABLE player (Occupation VARCHAR)
Mostrar diferentes ocupações, juntamente com o número de jogadores em cada ocupação.
998
SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1
Please show the most common occupation of players.
CREATE TABLE player (Occupation VARCHAR)
Por favor, mostre a ocupação mais comum de jogadores.
999
SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*) >= 2
Show the residences that have at least two players.
CREATE TABLE player (Residence VARCHAR)
Mostre as residências que têm pelo menos dois jogadores.