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help-10
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Brightness
02/07/2022 02:30:51
https://cdn.discordapp.c…556/IMG_0509.jpg
IMG_0509.jpg
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Ansh_
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Brightness
02/07/2022 02:30:53
https://cdn.discordapp.c…376/IMG_0511.png
IMG_0511.png
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help-10
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Brightness
02/07/2022 02:31:00
This is my working, wondering if it is correct or wrong?
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help-10
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Brightness
02/07/2022 02:31:09
Especially for part (I)
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help-10
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Brightness
02/07/2022 02:31:13
I mean ii
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help-10
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475,966,350,322,303,000
Brightness
02/07/2022 02:31:26
Part ii i think there exist two solutions
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help-10
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Ansh_
02/07/2022 02:32:27
honestly, there's 3
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help-10
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475,966,350,322,303,000
Brightness
02/07/2022 02:33:24
What where is the third?
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Ansh_
02/07/2022 02:33:29
oiii =_+ rotation is multiplication by a complex number? idkkk what you did for (i)
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help-10
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Brightness
02/07/2022 02:34:46
What i did from (ii) is using the property of the lines joining from the origin to the circumference is double the angle from the angle created from the line from the circumference joined to a single point
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help-10
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Ansh_
02/07/2022 02:38:27
I thinkkk I get what you did with i. Although I don't get how you arrived at your conclusion 🤦‍♂️
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help-10
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Ansh_
02/07/2022 02:39:48
As for (ii), there's RS parallel to PQ, PS parallel to QR and SQ parallel to PR
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help-10
3fc8100e8dc34bc5af32342fe2688908
475,966,350,322,303,000
Brightness
02/07/2022 02:42:10
Is my solution for part(ii) okay?
1
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help-10
3fc8100e8dc34bc5af32342fe2688908
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Brightness
02/07/2022 02:42:21
This is only 2 marks, and that’s too much work
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help-10
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Ansh_
02/07/2022 02:45:10
I think z2 + z3 - z1 only gives you one of the possible choices for S, so.. if your question's good with only one S, then okie
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help-10
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Brightness
02/07/2022 02:47:09
So my answer does give one possible solution, or am I just stupid? And it doesn’t
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help-10
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Ansh_
02/07/2022 03:20:33
yeah only one possible soln
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help-10
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Ansh_
02/07/2022 03:21:08
consider z2 + z3 - z1, z2 + z1 - z3, z1 + z3 - z2
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1
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541
help-10
3fc8100e8dc34bc5af32342fe2688908
475,966,350,322,303,000
Brightness
02/07/2022 03:47:55
I asked someone from my house, and he said that it is PQRS and that it should be in the fourth quadrant
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help-10
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Ansh_
02/07/2022 04:49:03
Yep, with that reasoning, it's restricted to only one solution
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Ansh_
02/07/2022 04:49:32
which is still not the one you found
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help-10
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Ansh_
02/07/2022 04:49:39
your point lies still in the third quadrant
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Issackepler
02/07/2022 04:50:40
Rotation theorem will work here?
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help-10
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Issackepler
02/07/2022 04:52:36
Final vec/ initial vec= length of final vec/ length of initial vec×e^itheta
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help-10
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Issackepler
02/07/2022 04:52:56
Isn't that a mains question?
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help-10
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Ansh_
02/07/2022 04:53:14
they got the first part :o
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help-10
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Ansh_
02/07/2022 04:53:29
the second part tho, they're confusing the quadrants
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help-10
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Issackepler
02/07/2022 04:53:41
Quadrants? Wait a sec
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help-10
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Ansh_
02/07/2022 04:54:35
the choice of S for PQRS parallelogram. Boruto figured that S must be in 4th quad but not clear about why their computation spits out S in 3rd quad
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help-10
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Issackepler
02/07/2022 04:56:17
Dude i think is u nedd to find out Z2 and z3
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help-10
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Issackepler
02/07/2022 04:56:23
For 2nd part
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Ansh_
02/07/2022 04:58:07
._. Isn't z_2 and z_3 already figured in (i) lol
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Issackepler
02/07/2022 04:58:27
Ok ig
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help-10
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Issackepler
02/07/2022 04:58:47
Yeah it's given lol
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help-10
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Issackepler
02/07/2022 04:59:03
It's there in question only 🤣
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help-10
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Issackepler
02/07/2022 05:00:11
So covert it into Cartesian equation and solve the slopes of a parallelogram
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help-10
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Ansh_
02/07/2022 05:03:38
watttt? You can directly write the third point lmao
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help-10
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Ansh_
02/07/2022 05:04:27
@Brightness the 4th point will be $z_3 + (z_1 - z_2)$ and not $z_3 + (z_2 - z_1)$
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help-10
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TeXit
02/07/2022 05:04:30
**Ansh**
https://cdn.discordapp.c…233012371577.png
706934233012371577.png
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help-10
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Phoenix775
02/07/2022 05:57:50
What are the total number of 12 letter words that contain 3 'A's and 2'E's?
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 05:59:50
define 'word'
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:00:07
Dude we can make words from all the alphabet?
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:00:12
sufosumosdumfosdmf <- is this a word?
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:00:38
@s_chanch no need of meaning ig
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:00:58
i need to make sure by word he means 'any combination of letters'
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help-10
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Issackepler
02/07/2022 06:01:03
My answer is 26c12/3!×2!
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Not Trout
02/07/2022 06:01:21
26c12 assumes that its all unique letters right?
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help-10
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Not Trout
02/07/2022 06:02:21
i think its 26^7/3!2!
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Issackepler
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Issackepler
02/07/2022 06:02:30
Why?
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Phoenix775
02/07/2022 06:02:36
all the words possible
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1005ffb5aca94a4897d9b6a5bc052eb8
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Phoenix775
02/07/2022 06:02:40
with or without meaning
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:02:41
???
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:02:44
oh
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
632,802,569,764,339,700
Phoenix775
02/07/2022 06:02:58
yeah exactly any combination of letters
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:02:58
you know combinations right?
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help-10
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s_chanch
02/07/2022 06:03:05
computing n choose k
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help-10
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632,802,569,764,339,700
Phoenix775
02/07/2022 06:03:06
yeah i do
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Issackepler
02/07/2022 06:03:11
@Not Trout in this case u r saying repitition is allowed for all alphabets
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help-10
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701,895,792,763,600,900
s_chanch
02/07/2022 06:03:18
but you don't know how to approach this?
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
939,423,550,912,208,900
calvin_keiker
02/07/2022 06:03:18
What you all talking bout
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help-10
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Phoenix775
02/07/2022 06:03:20
but im confused with how to calculate the question
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Not Trout
02/07/2022 06:03:21
wait is
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
841,679,117,350,994,000
Not Trout
02/07/2022 06:03:25
zzzzzzzzzzzz
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Phoenix775
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help-10
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Not Trout
02/07/2022 06:03:27
a possible word
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Not Trout
02/07/2022 06:03:31
assuming thats 12 Zs
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Issackepler
02/07/2022 06:03:44
But there's no 3a or 2 e?
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
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s_chanch
02/07/2022 06:03:45
so you're asking for the number of strings such that: - contains 3 'A's - contains 2 'E's - is 12 in length
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help-10
1005ffb5aca94a4897d9b6a5bc052eb8
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Phoenix775
02/07/2022 06:03:52
like... i dont know if i should do permutation for those 5 letters or do permutation for all or do multiplhying with all
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Phoenix775
02/07/2022 06:03:56
yeah
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Not Trout
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Not Trout
02/07/2022 06:03:59
that's the _total_
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Not Trout
02/07/2022 06:04:05
now you would want to then change that to yk
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Issackepler
02/07/2022 06:04:27
It' should contain 3a and 2e
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help-10
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s_chanch
02/07/2022 06:04:35
try considering (conditions 1 and 3) and (conditions 2 and 3)
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Not Trout
02/07/2022 06:04:35
yes BUT im not doing the conditions yet
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Not Trout
02/07/2022 06:04:36
i wanna know
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Issackepler
02/07/2022 06:04:44
?so how can it be z 12 times?
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s_chanch
02/07/2022 06:04:48
and then combine them
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1005ffb5aca94a4897d9b6a5bc052eb8
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Not Trout
02/07/2022 06:04:48
how many possible words you can form then do complimentary counting
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Phoenix775
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844,563,108,554,866,700
Issackepler
02/07/2022 06:04:58
Nope
0
1
701,895,792,763,600,900
s_chanch
2633
s_chanch
false
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:05:35
We have 12 places i think the answer is 3c1 2c1 24c10/2!×3!
0
1
701,895,792,763,600,900
s_chanch
2633
s_chanch
false
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
841,679,117,350,994,000
Not Trout
02/07/2022 06:06:22
actually
0
1
844,563,108,554,866,700
Issackepler
2955
Issackepler
false
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
841,679,117,350,994,000
Not Trout
02/07/2022 06:06:47
24^7 x [ways you can mess up 3As and 2Es]
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
841,679,117,350,994,000
Not Trout
02/07/2022 06:07:02
so now second term is 5!/3!2!
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:07:45
lol
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:07:47
U r taking power 7 cuz a and e aren't same?
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:07:50
just consider the possible placements
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:07:53
of a and e
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:07:59
the rest of the spaces can be anything but a or e
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:08:19
Yeah but ita very long
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:08:43
wdym
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:09:11
Yeah I didn't think of it
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:09:30
Then it'll be 12c2×24c10?
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:10:15
@s_chanch uhm makes sense
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:12:08
Yeah I got it ig 12c3×9c2×24^7
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
701,895,792,763,600,900
s_chanch
02/07/2022 06:12:21
dont spoil
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
632,802,569,764,339,700
Phoenix775
02/07/2022 06:19:55
is it (12C2) * (10C3) * (26)^7?
1
0
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
844,563,108,554,866,700
Issackepler
02/07/2022 06:21:00
@Phoenix775 I'm getting that it can be wrong
0
1
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
632,802,569,764,339,700
Phoenix775
02/07/2022 06:23:47
yeah i got that too and a friend of mine got that answer as well
1
0
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
632,802,569,764,339,700
Phoenix775
02/07/2022 06:23:54
for some reason i have a bad feeeling about this answer
1
0
null
null
null
null
null
542
help-10
1005ffb5aca94a4897d9b6a5bc052eb8
632,802,569,764,339,700
Phoenix775
02/07/2022 06:24:17
cuz the last time i used this method of "eliminating" the requirements it didnt end up correct
1
0
null
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null
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null