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799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 09:50:28 | Then I did, $0< \frac{2c}{c-5}<3$ | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 510,789,298,321,096,700 | TeXit | 02/21/2022 09:50:30 | **Sakata Yaksha** | 748029603087384657.png | 0 | 1 | null | null | null | null | null | ||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 09:50:34 | And took intersection, my answer however does not match to the correct one, did I miss something perhaps? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 09:54:13 | My final answer is $5<c<15$ | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 510,789,298,321,096,700 | TeXit | 02/21/2022 09:54:16 | **Sakata Yaksha** | 748029603087384657.png | 0 | 1 | null | null | null | null | null | ||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:08:15 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:19:46 | 🥲 | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:35:48 | What is an integral value | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:35:51 | A root? | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:35:56 | #❓how-to-get-help | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:35:56 | X=0? | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:36:19 | Okay I’ll go get help then 🙄 | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:36:20 | Oh lol. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:36:24 | You're helping me | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:36:26 | I forgot | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:36:35 | I thought you were asking something of your own. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:36:49 | So integral value means a value which is integer. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:37:31 | So integer values of c | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:37:39 | Okay | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:37:42 | Yeah | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:38:21 | Have you tried solving quadratic equation and restraining there | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:38:39 | Solving the quadratic equation, you mean using quadratic formula? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:38:45 | Yeah that’s what I mean | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:38:49 | That makes no sense does it? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:39:04 | Your constraint is on the two roots, no? | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:39:14 | Definitely. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:39:21 | But wouldn't that be crazy calculation? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:39:47 | I mean like there’s only one way to find out | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:40:55 | I personally would then break it into two restraints for the /pm | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:41:01 | Try to bound them | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 193,942,262,336,454,660 | KurtDee | 02/21/2022 10:41:08 | Get a range for c for each one | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:41:15 | No it's not that hard | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:41:22 | Well if the roots are between 0,2 and 2,3 the roots are basically in interval (0,3) therefore p(2) is negative.
Then sum of the roots also lies in the interval (0,3) | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:41:28 | I used stuff like This | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:41:28 | the roots in terms of c will be an increasing function for the smaller root and a decreasing function for the bigger root | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:44:09 | How would that be? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:44:30 | If you use the quadratic formula it simplifies quite nicely at the end, imo | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:44:44 | I see, I'll try that then. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:45:11 | But then I'll have two roots. Which one do I put in first interval lol. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:45:20 | If that's how we're doing it. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:45:42 | the terms for the roots just differ by a minus sign | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:46:03 | so the bigger root corresponds to the term with the positive sign | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:46:37 | No. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:46:48 | That's not really correct imo. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:47:05 | write it out | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:47:05 | p+q>p-q are you implying? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:47:14 | Okay yeah my bad XD. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:48:29 | No, if you apply the quadratic formula you'll get x_1 and x_2, the two roots in terms of c, only. x_1 = u(c) + v(c) and x_2 = u(c) - v(c). Something like that should come out | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:48:52 | v(c) is a square root so that can only be positive | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:49:00 | unless you deal with complex numbers | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:49:04 | $\frac{2c±\sqrt{4c^2-4(c-5)(c-4)}}{2(c-5)}$ | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 510,789,298,321,096,700 | TeXit | 02/21/2022 10:49:07 | **Sakata Yaksha** | 748029603087384657.png | 0 | 1 | null | null | null | null | null | ||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:51:44 | I got $x_{1,2} = \frac{c}{c-5} \pm \sqrt{\qty(\frac{c}{c-5})^2 - \frac{c-4}{c-5}}$ | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 510,789,298,321,096,700 | TeXit | 02/21/2022 10:51:47 | **Navix** | 392341051794391040.png | 0 | 1 | null | null | null | null | null | ||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:54:12 | It is. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:54:37 | Yes, now? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:55:07 | common denominator and simplify | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 10:58:23 | should become $\frac{c \pm \sqrt{9c - 20}}{c-5}$ | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 510,789,298,321,096,700 | TeXit | 02/21/2022 10:58:26 | **Navix** | 392341051794391040.png | 0 | 1 | 392,341,051,794,391,040 | Navix | 0001 | nvx | false | ||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:59:46 | Alright, I'm back. | 1 | 0 | 748,029,603,087,384,700 | Yours truly | 3785 | What the hell am I doing here? | false | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 10:59:50 | So, this is correct. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:00:32 | Even then | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:00:41 | There's no way to say the one with plus sign is larger root. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:00:43 | Obviously. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:00:45 | why not? | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:00:57 | Bruh. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:01:21 | well split into two cases: c > 5 and c < 5 | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:02:09 | Lol at c=3 check for yourself first of all. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:02:18 | Now you're talking. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:03:31 | But truly mate, this is too much work I'd say.
I'll try it this way too definitely, could you find an error in my calculation and stuff too for reference? I'd appreciate it. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:03:56 | Yea, I'll work it out this way and show you if you want, as well | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:04:14 | Yes, so first we'll finish it this way. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:04:43 | For c>5 the denominator is always positive, and so is numerator. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:05:16 | C≥20/9 | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:05:29 | This we have to always keep in mind as well. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:06:09 | So case the two cases would be c>5
second 29/5≤c<5 | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:06:17 | But cases for what? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:06:43 | It's not like we have any RHS. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:07:00 | What I did was notice that the term is an increasing function on c > 5. | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:07:25 | So we should be able to simply set it equal to the endpoints? | 0 | 1 | 392,341,051,794,391,040 | Navix | 0001 | nvx | false | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:07:39 | of the root boundaries | 0 | 1 | 392,341,051,794,391,040 | Navix | 0001 | nvx | false | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:07:56 | Basically the minimum value for the function should lie in interval (2,3)? | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:09:11 | That's what I thought | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:11:08 | basically for c > 5 the smaller root in (0,2) will be the term with the minus sign. so to find the bounds for c we can simply set this term equal to 2 and 0 and solve for c. | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:12:36 | because it's increasing, that should also correspond to the interval for our feasible values for c | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 551,807,466,631,987,200 | Mat | 02/21/2022 11:14:01 | A quick solution comes from just setting $$p(0)p(3)>0 \land p(0)p(2)<0,$$ which gives $13 \leq c \leq 23$ | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 510,789,298,321,096,700 | TeXit | 02/21/2022 11:14:18 | **Mat** | 551807466631987211.png | 0 | 1 | null | null | null | null | null | ||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:17:47 | That's what I was talking about. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:18:03 | I did p(2) part, but not p(0)p(3) thingy. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 392,341,051,794,391,040 | Navix | 02/21/2022 11:18:11 | Agree, that's pretty neat | 0 | 1 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:18:36 | Yes, this is the only way I do these, unfortunately my sol was lacking as you can see. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:18:41 | That was nice, thanks mate. | 1 | 0 | null | null | null | null | null | |||||
799 | help-10 | 6268617cabf8450aa15187f8b1e4eb88 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:20:52 | .close | 1 | 0 | null | null | null | null | null | |||||
800 | help-10 | 8389a9cf55bd4018b4523970c9f858a3 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:21:01 | .reopen | 1 | 0 | null | null | null | null | null | |||||
800 | help-10 | 8389a9cf55bd4018b4523970c9f858a3 | 551,807,466,631,987,200 | Mat | 02/21/2022 11:21:15 | Np! Yeah we were basically on the same idea | 0 | 1 | null | null | null | null | null | |||||
800 | help-10 | 8389a9cf55bd4018b4523970c9f858a3 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:21:27 | Hm, yeah. | 1 | 0 | null | null | null | null | null | |||||
800 | help-10 | 8389a9cf55bd4018b4523970c9f858a3 | 748,029,603,087,384,700 | Yours truly | 02/21/2022 11:21:28 | .close | 1 | 0 | null | null | null | null | null | |||||
801 | help-10 | aeb6e91318fb4adfa044352ee7763f86 | 456,226,577,798,135,800 | Deleted User | 02/21/2022 11:37:03 | IMG_20220221_220551.jpg | 1 | 0 | null | null | null | null | null | |||||
801 | help-10 | aeb6e91318fb4adfa044352ee7763f86 | 456,226,577,798,135,800 | Deleted User | 02/21/2022 11:37:03 | Find if convergent or divergent | 1 | 0 | null | null | null | null | null | |||||
801 | help-10 | aeb6e91318fb4adfa044352ee7763f86 | 332,849,454,753,251,300 | sucka mah | 02/21/2022 11:37:47 | use the integral test. Take the integral of that series and see if the value of the integral is fixed or if it goes towards infinity. | 0 | 1 | 551,807,466,631,987,200 | Mat | 9616 | Mat | false |
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