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961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:36:34 | you got something wrong | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:37:11 | n⁵+3 ≤ n⁵ is most certainly not correct | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:38:00 | As for the methodology, recall that Θ is not about *always* being bounded by constant multiples of n², just that being true *for large enough n* | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:38:52 | I took the whole fraction as a whole, maybe that was my mistake | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:39:03 | what if I add any constant to make it larger? | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:39:15 | Have you studied limits yet? | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:39:19 | n^5 + 3 <= 4n^5 for ex | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:39:31 | that does work | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:39:39 | Yes but im prompted to use ad hoc calculations not limit theorem | 1 | 0 | 845,597,669,614,157,800 | tcpip | 4691 | tcpip | false | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:40:43 | like manually test each Big-O and Big-Omega instead of lim f(x)/g(x) | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:41:10 | I see | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:41:20 | Anyway, n^5+3 ≤ 4n^5 works | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:42:02 | and i can make n^3 + 9 <= 4n^3 so I get n^2 | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:42:17 | Although, for the second inequality i don't get what you did | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:42:25 | 4n^5/4n^3 = n^2 | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:42:42 | which one | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:42:49 | You (up to a few inaccuracies) proved f(n) ≤ n² and n²/2 ≤ n² | 0 | 1 | 193,692,307,453,771,780 | Syst3ms | 9959 | Syst3ms | false | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:43:09 | But that does absolutely not imply f(n) ≥ n²/2 | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:44:00 | I must use a different approach to find Big-Omega then | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:45:42 | My idea was, since I previously proved n^2 from 4n^5/4n^3 is >= n^5+3/n^3+9 I can just replace it | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:45:51 | so n^2 >= Cn^2 | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:46:20 | Both proofs must have the same constant C and starting n? | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:46:29 | Again, a>b and a>c does not mean b>c | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:46:35 | nor b<c for that matter | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:46:50 | Honestly you can just do the same thing you did for the first direction | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:47:00 | i trust you to find a reasonable lower bound for n^5+3 | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 06:47:22 | As for 1/(n^3+9), that means finding an upper bound for n^3+9, which you can do similarly | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:49:12 | May I ask why n^5+3 needs a lower bound and n^3+9 needs an upper bound? | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:49:39 | Why not find lower bound of both for ex | 1 | 0 | 193,692,307,453,771,780 | Syst3ms | 9959 | Syst3ms | false | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:51:10 | and this^ | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 804,151,776,412,041,200 | penguin | 02/28/2022 06:57:33 | For big omega:
h(n) = a/b = 4n^2
since h(x) >= n^5 +3/n^3 +9 I can just use h(n) instead
n^5 +3 <= 8n^5 (a)
n^3 +9 <= 2n^3 (b)
so at the end im gonna get
4n^2 >= 2n^2 >= n^2 with C = 2, n > 1
f(n) belongs to big theta(n^2) | 1 | 0 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 07:22:08 | Because 1/a > 1/b if and only if a < b | 0 | 1 | null | null | null | null | null | |||||
961 | help-10 | 37ecb410bb6d4a298633ed58f4d80e17 | 193,692,307,453,771,780 | Syst3ms | 02/28/2022 07:22:22 | 1/2 > 1/3 because 2 < 3 | 0 | 1 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 411,122,254,286,422,000 | Yuki_ | 02/28/2022 09:24:29 | anyone help with set in discrete math | 1 | 0 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/28/2022 09:34:36 | Pleased don’t ask to ask… | 0 | 1 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 456,226,577,798,135,800 | Deleted User | 02/28/2022 09:42:15 | that's not even a definite question. If you want to discuss this go to #math-discussion | 0 | 1 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 411,122,254,286,422,000 | Yuki_ | 02/28/2022 09:43:09 | @Deleted User if its not a question what is it ? | 1 | 0 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/28/2022 09:45:41 | #❓how-to-get-help | 0 | 1 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/28/2022 09:46:07 | It says , don’t ask permission to ask, just ask. | 0 | 1 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/28/2022 09:47:14 | If you still don’t want to give you question, better close this channel for others. | 0 | 1 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 411,122,254,286,422,000 | Yuki_ | 02/28/2022 10:13:54 | let me do a favor . i betta quit the server. | 1 | 0 | null | null | null | null | null | |||||
962 | help-10 | b64c36966a0a4e188a406a45df779118 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/28/2022 10:15:31 | Yeah you better | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 215,090,636,192,350,200 | نعمان | 02/28/2022 11:15:27 | "The integration here is over y, along the wire, with x treated as a constant. We must now write theta as a function of y, or y as a function of theta"
why is that? | 20220228_170308.png | 1 | 0 | null | null | null | null | null | ||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 215,090,636,192,350,200 | نعمان | 02/28/2022 11:16:05 | (I posted this here since its more a question about integration then electric fields, tell me if it doesnt belong here and i'll repost it to the physics help channel) | 1 | 0 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:21:12 | Well, the distance from the wire, x is constant | 0 | 1 | 804,151,776,412,041,200 | penguin | 2507 | penguin | false | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:21:33 | The variable here is y | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:21:52 | To integrate, you need to make a substitution, writing y in terms of θ | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:23:04 | You see, instead of dealing with square roots and stuff, you can directly write the hypotenuse as y cscθ | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:23:49 | Well yea you need to convert it into a function in θ | 0 | 1 | 411,122,254,286,422,000 | Yuki_ | 7688 | Yuki_ | false | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 215,090,636,192,350,200 | نعمان | 02/28/2022 11:24:35 | I dont get why you would have to write y in terms of theta honestly | 1 | 0 | 456,226,577,798,135,800 | Deleted User | 0000 | Deleted User | false | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:28:48 | Wait @نعمان | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:28:56 | The components | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:29:05 | The electric field is a vector | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:29:16 | Thats why we need to convert it into terms of θ | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 844,913,236,989,837,300 | 5lttrz | 02/28/2022 11:29:28 | We cannot integrate directly, as its not a scalar | 0 | 1 | null | null | null | null | null | |||||
963 | help-10 | 1dbb2f5d00b4487da15bbe8e8c5ac2bb | 215,090,636,192,350,200 | نعمان | 02/28/2022 11:30:07 | Hmm okey, ig i'll start working on my calculus bcs idk how to integrate a vector | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:02:30 | hello | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:02:36 | the question is | 1 | 0 | 215,090,636,192,350,200 | نعمان | 0934 | نعمان | false | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:02:46 | the sum of three consecutive multiples of 9 is 162 | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:02:49 | find the multiples | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:02:52 | how will u do dis | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 693,116,087,390,175,400 | _06Cupcake | 02/28/2022 12:05:49 | u know the concept of AP? | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:05:50 | Hey Tornado | 0 | 1 | 844,913,236,989,837,300 | 5lttrz | 9727 | 5lttrz | false | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 693,116,087,390,175,400 | _06Cupcake | 02/28/2022 12:05:57 | Arithmetic progression | 0 | 1 | 215,090,636,192,350,200 | نعمان | 0934 | نعمان | false | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 693,116,087,390,175,400 | _06Cupcake | 02/28/2022 12:06:03 | @krakenlord | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:06:10 | how do you write a multiple of 9? | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:06:50 | i thought of doing | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:07:06 | x + (x+9) + (x+18) | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:07:12 | as 9 and 18 and multiple of 9 | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:08:26 | wow, that would help though | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:08:35 | 3x + 27 = 162 | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:08:41 | ,calc (162 - 27)/3 | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 510,789,298,321,096,700 | TeXit | 02/28/2022 12:08:42 | Result:
```
45
``` | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:08:49 | You'll get x = 45 | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 706,934,233,012,371,600 | Ansh_ | 02/28/2022 12:09:11 | And consequently, the values of x, x + 9, x + 18 | 0 | 1 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:09:40 | so if x is 45 | 1 | 0 | 900,070,996,852,240,400 | krakenlord | 1754 | krakenlord | false | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:09:53 | i do 45+ 9 and 45 + 18 for values right? | 1 | 0 | null | null | null | null | null | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:12:07 | close | 1 | 0 | 900,070,996,852,240,400 | krakenlord | 1754 | krakenlord | false | |||||
964 | help-10 | 90e09312d6c747a8bdabec2809aed566 | 900,070,996,852,240,400 | krakenlord | 02/28/2022 12:12:11 | .close | 1 | 0 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 634,217,988,064,673,800 | brandon barber | 02/28/2022 14:44:08 | Hi | 1 | 0 | 706,934,233,012,371,600 | Ansh_ | 3502 | Arya | false | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 634,217,988,064,673,800 | brandon barber | 02/28/2022 14:44:14 | Screenshot_20220228-114233_Chrome.jpg | 1 | 0 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 634,217,988,064,673,800 | brandon barber | 02/28/2022 14:44:36 | D correct? | 1 | 0 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 310,413,396,434,485,250 | mei ♡ | 02/28/2022 14:56:09 | yes | 0 | 1 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 634,217,988,064,673,800 | brandon barber | 02/28/2022 14:56:51 | Screenshot_20220228-113906_Chrome.jpg | 1 | 0 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 800,622,149,903,056,900 | Shen | 02/28/2022 15:02:37 | ^^ | 0 | 1 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 606,859,042,849,030,100 | Valoche | 02/28/2022 15:14:02 | You devide the speed by 2 couse you have half an hour | 0 | 1 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 606,859,042,849,030,100 | Valoche | 02/28/2022 15:14:49 | Then you do a cross product with the conversion ft -> miles | 0 | 1 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 606,859,042,849,030,100 | Valoche | 02/28/2022 15:15:20 | Do you understand why? | 0 | 1 | null | null | null | null | null | |||||
965 | help-10 | 4c361494b06b4c48825b660da4fee710 | 606,859,042,849,030,100 | Valoche | 02/28/2022 15:19:29 | @brandon barber | 0 | 1 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 16:59:55 | can someone explain this | unknown.png | 1 | 0 | null | null | null | null | null | ||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 17:00:01 | i didnt get the last part | 1 | 0 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 200,013,547,491,688,450 | a disappointing son | 02/28/2022 17:00:14 | splitting the fraction? | 0 | 1 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 17:00:22 | yea | 1 | 0 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 17:00:50 | i get the first and second operations | 1 | 0 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 17:01:01 | but the last got me confused | 1 | 0 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 17:01:09 | 1+1/x-1 | 1 | 0 | 634,217,988,064,673,800 | brandon barber | 4492 | brandon barber | false | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 200,013,547,491,688,450 | a disappointing son | 02/28/2022 17:01:40 | you're confused on why $\frac{x-1}{x-1}+\frac{1}{x-1}=1+\frac{1}{x-1}$? | 0 | 1 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 510,789,298,321,096,700 | TeXit | 02/28/2022 17:01:43 | **a disappointing son** | 200013547491688448.png | 0 | 1 | 805,217,272,087,838,700 | Mathematics Bot | 0196 | Bot | true | ||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 777,469,972,343,423,000 | Nix | 02/28/2022 17:02:45 | yes | 1 | 0 | null | null | null | null | null | |||||
966 | help-10 | 0236be58eb55427e9bfb3b067ba31dbc | 200,013,547,491,688,450 | a disappointing son | 02/28/2022 17:03:07 | well... $\frac{x}{x}=1$... | 0 | 1 | null | null | null | null | null |
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