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987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:49:27
were gonna factor them alright?
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:49:45
f(x)=(x-4)(x+1)Q(x)+4x-1
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:08
f(x)=(2x-1)(x-1)Q'(x)+2x+7
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:13
so we can get
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:21
f(4)=15
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:31
f(-1)=-5
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:41
f(1/2)=8
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:46
f(1)=9
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:50:55
now we look at the question
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:51:17
f(x)=2x²-9x+4Q''(x)+ax+b
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:51:22
so
0
1
806,712,357,123,784,700
Serenity
4586
Serenity
false
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:51:50
f(x)=(2x-1)(x-4)Q''(x)+ax+b
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:52:07
f(1/2)=1/2a+b=8
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:52:20
f(4)=4a+b=15
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:52:26
a+2b=16
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:52:34
8a+2b=30
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:52:41
-7a=-14
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:52:51
a=2 and b=7
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:53:00
so the final answer: 2x+7
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:53:04
@Serenity
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
896,979,437,692,813,300
lil droptop$$
03/01/2022 21:59:45
howd u get that
0
1
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
806,712,357,123,784,700
Serenity
03/01/2022 22:09:22
Thanks so much!
1
0
null
null
null
null
null
987
help-10
ec5a3143e1eb4e679c13066755d2722d
806,712,357,123,784,700
Serenity
03/01/2022 22:09:29
.close
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:19:21
arccos(\sqrt((((1+cosx))/(2))))
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:19:34
How to simplify this equation?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
198,191,547,970,355,200
sills
03/01/2022 22:20:28
$\arccos(\sqrt{\frac{1+\cos{x}}{2}})$
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
118,536,946,527,109,120
Migillope
03/01/2022 22:20:33
That is so many parenthesis
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
198,191,547,970,355,200
sills
03/01/2022 22:20:41
dw i TeX'd
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:20:51
yes
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
510,789,298,321,096,700
TeXit
03/01/2022 22:21:12
**sills**
https://cdn.discordapp.c…547970355200.png
198191547970355200.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:21:26
I just don't know where to start
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:21:45
And how to simplify it can anyone help?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:22:41
hint: the thing inside the square root is what a certain double-angle formula looks like if you move things around
0
1
806,712,357,123,784,700
Serenity
4586
Serenity
false
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:25:31
arccos(sqrt((1+cos²(x)+2cos(x))/2(1+cosx))?
1
0
270,606,727,907,508,220
mvoiddd
6227
mvoiddd
false
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:26:26
I am dumb so not so sure about that...
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:26:54
do you know the double angle formulas?
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:27:20
bad at english but
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:27:22
cos 2A = cos2A - sin2A (or) 2cos2A - 1
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:27:24
???
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
186,109,587,366,215,680
Omegabet_
03/01/2022 22:28:23
cos^2A
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
186,109,587,366,215,680
Omegabet_
03/01/2022 22:28:27
not cos2A
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:28:29
yes
1
0
510,789,298,321,096,700
TeXit
0796
TeXit
true
988
help-10
66de33714f5a429e8f4594902777fc80
299,271,213,967,081,500
Chtholly Nota Seniorious
03/01/2022 22:28:30
double angles
https://cdn.discordapp.c…71b48abcfcaa.png
SPOILER_2e689d_2e114fa0c01d4dfd8ee871b48abcfcaa.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:29:28
right, so one of these formulas, if you move things around, will look something like the thing underneath the square root
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:29:46
bear in mind that a is not necessarily the same as x
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:33:20
is it (sqrt(sin²(x)+cos²(x)+sqrt(1-sin²(x))/2)?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:35:52
or should I put like x=2b?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:38:20
so by replacing x by 2b
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:39:11
I obtained sqrt(1+cos(2b)/2)= sqrt(cos²(b))
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:39:46
then arccos|cosb|
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:39:58
which means
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:40:03
it's x/2???
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:40:11
is this it?
1
0
747,990,866,798,313,600
SAB
3071
SAB
false
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:40:21
assuming cos (x/2) >= 0, yes
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:40:38
i don't know what range you're carrying it out in
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:40:54
x VR
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:41:04
x is real
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 22:44:12
if you're doing it for $x\in\bR$, then you need to consider two cases: $\arccos\qty|\cos\frac x2| = \arccos\qty(\cos\frac x2)$ and $\arccos\qty|\cos\frac x2| = \arccos\qty(-\cos\frac x2)$
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
510,789,298,321,096,700
TeXit
03/01/2022 22:44:16
**Camilleone**
https://cdn.discordapp.c…697925898261.png
569167697925898261.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:46:57
then does that mean it's emm gonna be -b and b?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:47:02
for the answer?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:51:06
ahh c bon
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:51:40
it's gonna be arccos(-cosb)=arccos(cos(b+pi))??
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:51:50
so either the answer is x/2 or
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:51:59
x+2pi/2
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:52:00
??
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 22:58:49
?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:01:29
@Helpers
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
456,226,577,798,135,800
Deleted User
03/01/2022 23:02:11
https://cdn.discordapp.c…7550/unknown.png
unknown.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
456,226,577,798,135,800
Deleted User
03/01/2022 23:02:15
@Helpers
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:02:36
NO
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
456,226,577,798,135,800
Deleted User
03/01/2022 23:02:41
pls
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:02:55
go to help 35
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
456,226,577,798,135,800
Deleted User
03/01/2022 23:03:01
ok
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:03:02
it's available
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:03:05
#❓how-to-get-help
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:03:16
sorry, i just got back from sending some emails
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:03:40
no need to apologize. I am sorry for the bother
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:03:51
yes, this is what happens, but you need to be careful about arccos
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:04:39
because arccos usually outputs a value in [0, pi]
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:05:10
ahhh
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:05:27
so i should determine the value of x
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:05:37
(hope that was correct)
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:06:05
which means
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:06:17
-pi/2<x<0
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:06:18
?
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:06:35
hmm
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:06:38
rather than saying that
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:06:51
you want to solve it for all $x\in\bR$?
0
1
456,226,577,798,135,800
Deleted User
0000
Deleted User
false
988
help-10
66de33714f5a429e8f4594902777fc80
510,789,298,321,096,700
TeXit
03/01/2022 23:06:54
**Camilleone**
https://cdn.discordapp.c…697925898261.png
569167697925898261.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:07:00
or just for some specific values of $x$?
0
1
569,167,697,925,898,240
Camilleone
1596
Camilleone
false
988
help-10
66de33714f5a429e8f4594902777fc80
510,789,298,321,096,700
TeXit
03/01/2022 23:07:03
**Camilleone**
https://cdn.discordapp.c…697925898261.png
569167697925898261.png
0
1
747,990,866,798,313,600
SAB
3071
SAB
false
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:07:13
for all x in R
1
0
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:07:57
okay, then this is what you do
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:08:12
for the first case, say $\arccos\qty|\cos\frac x2| = \arccos\qty(\cos\frac x2)$
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
510,789,298,321,096,700
TeXit
03/01/2022 23:08:15
**Camilleone**
https://cdn.discordapp.c…697925898261.png
569167697925898261.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:09:34
of course, $\arccos$ is the inverse cosine function, so you need to find the particular value of $y\in[0,\pi]$ such that $\cos y = \cos \frac x2$
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
510,789,298,321,096,700
TeXit
03/01/2022 23:09:36
**Camilleone**
https://cdn.discordapp.c…697925898261.png
569167697925898261.png
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
569,167,697,925,898,240
Camilleone
03/01/2022 23:10:03
and that y will be the result
0
1
null
null
null
null
null
988
help-10
66de33714f5a429e8f4594902777fc80
747,990,866,798,313,600
SAB
03/01/2022 23:10:18
I c will try it
1
0
null
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