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1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 665,511,201,928,773,600 | b0a | 03/14/2022 16:40:06 | How would you draw the point of, on a graph, something like..
Y is bigger than or equal to -2
× > 3
Y > 3x + 1 | 1 | 0 | null | null | null | null | null | |||||
1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 193,942,262,336,454,660 | KurtDee | 03/14/2022 16:44:15 | It’s not a point l | 0 | 1 | null | null | null | null | null | |||||
1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 193,942,262,336,454,660 | KurtDee | 03/14/2022 16:44:17 | It’s an area | 0 | 1 | null | null | null | null | null | |||||
1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 193,942,262,336,454,660 | KurtDee | 03/14/2022 16:44:25 | Draw a line and shade the inequality | 0 | 1 | null | null | null | null | null | |||||
1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 392,341,051,794,391,040 | Navix | 03/14/2022 16:46:34 | Also, because x > 3 and y > 3x + 1, you automatically get y > 10, which makes the y >= -2 condition redundant | 0 | 1 | null | null | null | null | null | |||||
1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 665,511,201,928,773,600 | b0a | 03/14/2022 16:56:38 | I'm confused lol | 1 | 0 | null | null | null | null | null | |||||
1,249 | help-10 | 187bdbb3c0e1456da83e633c17c322e3 | 665,511,201,928,773,600 | b0a | 03/14/2022 16:56:49 | I think I get it nvm | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:15:37 | Find solutions for 11x+7y=200 in set of natural numbers, i got:
(x,y)=(400+7k,-600-11k);keZ
but how do i make it be in set of natural numbers | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:23:48 | 11 and 7 are coprime | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:24:00 | There is a result about solutions of ax+by=c where a and b are relatively prime | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:24:07 | if you find one solution (x_0,y_0) then all solutions are (x_0+bt,y_0-at) for all integers t. Use this | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:24:11 | yes | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:24:13 | i did that | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:24:25 | but for just natural numbers/ whole numbers >0 | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:24:28 | i tried this | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:24:31 | Just solve range of t then | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:24:36 | k | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:24:39 | You used k | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:25:08 | 400+7k>0 => k>-57
-600-11k>0 => k<-54
k e {-56,-55} | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:25:12 | is that correct | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:25:15 | 400+k>=0,-600-11k>=0 | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:25:27 | no just >0 | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:25:32 | 0 isnt a natural number | 1 | 0 | 392,341,051,794,391,040 | Navix | 0001 | nvx | false | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:25:59 | I see, so 0 isn’t in your version | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:26:13 | wdym my version? | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:26:42 | Wrong, k>=-57 | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:27:13 | k>-57,1428… right? So k>=-57 | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:27:41 | oh yes correct, i tought that it was -7k my bad | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:27:51 | So -57,-56,-55 | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:27:51 | so that it would be negative | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:27:58 | Yeah negative | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:28:18 | thanks | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:30:37 | Np | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:33:17 | could you also help me with this (4x+10y)(8x+7y)=86, i have no idea how to do it | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:33:40 | i can only think of writing 86 as a product of whole numbers | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:34:12 | but thats too much work, there has to be a "smarter" way to do it | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:38:07 | Thought the same | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:39:00 | But don’t worry for each linear system there will be only one solution (x,y) | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:39:25 | Because
(4 10
8 7)
is invertible | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:39:46 | But yeah.,, still so much work😂 | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 17:42:19 | So 4 solutions | 0 | 1 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:47:27 | i solved it, you get 8 systems of equations but since its a diophantine equation only 2 valid solutions, rest arent integers | 1 | 0 | null | null | null | null | null | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:48:03 | unknown.png | 1 | 0 | 403,868,346,455,556,100 | ChuFta | 9335 | ChuFta | false | |||||
1,250 | help-10 | 638ebe68a32a4d3e9eb8221005250368 | 403,868,346,455,556,100 | ChuFta | 03/14/2022 17:48:05 | i wrote it in paint | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:26:50 | You know sum of C(n,k) k from 0 to n is 2^n right? | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:27:11 | The first equation, the left hand side, is half of the total sum | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:27:21 | 2) is trivially just solve it | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:30:49 | No | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:30:53 | 2^26 | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:31:20 | (1+x)^n=ΣC(n,k)x^k we just let x=1 | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:33:21 | Yeah | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:46:27 | Just by definition I think, it holds for any c actually | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:51:46 | d>=x^2+42-c right | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:52:12 | You can always find such d, no matter what x and c are | 1 | 0 | 403,868,346,455,556,100 | ChuFta | 9335 | ChuFta | false | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:56:01 | Make d larger than the right hand side | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 18:56:03 | Yeah | 1 | 0 | null | null | null | null | null | |||||
1,251 | help-10 | 28f1be460e6440f89794a268c828eb48 | 826,318,983,413,366,800 | Cogwheels of the mind | 03/14/2022 19:01:23 | 👍 | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:43:30 | Just wanted to check my method and answer | unknown.png | 1 | 0 | null | null | null | null | null | ||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:43:45 | I've calculated the perpendicular distance to be 4sin(3) x 80N | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:44:04 | and the other force should just be x100N | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:44:20 | and equating the two together | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:44:24 | I have x = 1.6 | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:44:53 | am I missing something?, and also which distance have I just calculated?, the distance from wall to x or from x to the point at the end of the rod | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 19:47:28 | seems to simple to be true 🚟 | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 19:52:10 | Perpendicular distance? Perpendicular to what? | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 19:52:19 | There's an N in your distance | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 19:56:11 | You are confused about whether your equation represents a force, or a distance. 4sin(30) is the height of the wall section, why are we multiplying that by 80N? | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 19:57:17 | Wait, no it isn't even that. What is 4sin(30) here? | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 19:58:16 | Make sure to draw an FBD and split it into components | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:04:01 | Sorry should have clarified | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:04:37 | The moment of the tension force is perpendicular distance x force | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:04:53 | Distance is 4sin(30) and force is 80N | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:05:53 | The 4sin(30) is also the perpendicular distance if you make another triangle | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:06:02 | Sorry im on phone but I'll try to draw it | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:06:46 | Screenshot_20220315-000618.jpg | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 20:08:35 | That blue line is 4sin(30) indeed | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:08:41 | Mhm | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:08:55 | Aka, the perpendicular distance to the tension | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 20:18:32 | Why is that important? | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 20:19:49 | Seeing as gravity acts directly downward, I don't see what you gain from picking a weird frame of reference | 0 | 1 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:21:39 | Its about the tension... When I'm resolving forces tension acts anti clockwise while gravity acts clockwise | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:21:51 | And it says they are in equilibrium | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 268,789,506,663,120,900 | verιғιed 𝓒𝓸м𝓫Ø | 03/14/2022 20:22:24 | How would you solve it? | 1 | 0 | null | null | null | null | null | |||||
1,252 | help-10 | c5be3166bd4246d2a5b9469e1ff60802 | 356,908,116,429,897,700 | Kaynex | 03/14/2022 20:30:43 | There's forces holding up the left and right side of the rod. Having the tension of the cable is enough to get the force on the right using an FBD. Then check the moment at the left side. | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 196,803,594,576,592,900 | nix | 03/14/2022 21:28:53 | suppose you have n dice. every time you roll all of them, you remove every die that shows a 6. for example, if 2 show up as 6s, you remove them and then roll n-2 dice, etc. (the original problem was with 25 dice)
what is the probability that it will take N rolls to eliminate all the dice? | 1 | 0 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 196,803,594,576,592,900 | nix | 03/14/2022 21:43:47 | i started by just looking at n=2 but i wasnt able to figure out a pattern | 1 | 0 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 21:45:51 | well maybe the first step to solving this problem could be observing each individual probability in the first trial/roll.
let's say you roll all N dice, with an even 1/6 chance of rolling a six for each individual die. Then the probability of rolling x sixes is equal to the binomial pdf of x, given that p=1/6 and n=N | 0 | 1 | 356,908,116,429,897,700 | Kaynex | 7520 | Kaynex | false | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 21:48:08 | in the second trial, the probability of rolling x sixes is equal to the binomial pdf of x, given that p=1/6 and n= the amount of dice remaining from the first trial | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 21:50:25 | i can't think of where to go from here though; my method might lead to nowhere. i'm thinking about it | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 141,791,176,540,946,430 | frownyfrog | 03/14/2022 22:03:20 | it's that thing where you go in circles | 0 | 1 | 356,908,116,429,897,700 | Kaynex | 7520 | Kaynex | false | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 22:03:26 | ? | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 141,791,176,540,946,430 | frownyfrog | 03/14/2022 22:03:39 | what if n = 1 | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 22:04:05 | then P=1-(5/6)^N), where N is the amount of trials/rolls | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 141,791,176,540,946,430 | frownyfrog | 03/14/2022 22:04:46 | but what is the probability | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 141,791,176,540,946,430 | frownyfrog | 03/14/2022 22:04:49 | N = 10, n = 1 | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 22:04:58 | yea sorry for the confusing variables im tired | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 141,791,176,540,946,430 | frownyfrog | 03/14/2022 22:05:26 | it's 5/6 × [same problem with N = 9] | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 22:05:27 | probability is equal to 1-(5/6)^N, N rolls for n=1 die | 0 | 1 | 356,908,116,429,897,700 | Kaynex | 7520 | Kaynex | false | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 141,791,176,540,946,430 | frownyfrog | 03/14/2022 22:06:30 | we're probably not seeing the same problem | 0 | 1 | null | null | null | null | null | |||||
1,253 | help-10 | ee448639576c4143891f4790ad67b2df | 766,866,943,566,938,100 | demaw | 03/14/2022 22:06:35 | how so | 0 | 1 | 356,908,116,429,897,700 | Kaynex | 7520 | Kaynex | false |
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