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1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:38:14 | so that it could be 11 in base 11 | 0 | 1 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:38:24 | like A in base 11 would be 11 in base 10 | 0 | 1 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:38:38 | does that make sense? | 0 | 1 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 621,954,973,013,377,000 | Kabel | 03/17/2022 10:39:14 | I think this makes sense to me | 1 | 0 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:39:35 | 👍 | 0 | 1 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:39:42 | so for base 12 for example | 0 | 1 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:39:51 | we might create another symbol B that is 12 in base 10 | 0 | 1 | null | null | null | null | null | |||||
1,299 | help-10 | 22f125e8508f47f99fdaa5b8c0d35515 | 546,082,107,944,861,700 | pistashios | 03/17/2022 10:40:12 | for higher bases we run out of symbols to write the numbers with, so we just make more | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:46:23 | What is the formula to solve for intersection of events? | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:47:24 | IMG_9590.jpg | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:48:01 | So i have P(A), P(B), P(AUB) as given | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:48:49 | I tried to do P(A)•P(B) and got 0.195 | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:49:01 | Im just not sure if its correct | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:50:19 | Well, no | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:50:47 | The events are dependent, since P(A) + P(B) doesn't equal P(A or B) | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:52:27 | Note that: | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:52:39 | P(A or B) = P(A) + P(B) - P(A and B) | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:52:48 | Try plugging in the values | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:55:00 | Wait so if P(A)+P(A) doesnt equal P(A or B) its dependet? | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:55:12 | If its equal then its independent? | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:55:54 | I meant P(A) + P(B) | 0 | 1 | 546,082,107,944,861,700 | pistashios | 4611 | pistashios | false | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 13:55:54 | My bad | 0 | 1 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 13:55:59 | Oh | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 14:02:29 | So 0.55+0.35-0.15
=0.75 | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 14:02:44 | P(AUB)= 0.75 | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 14:02:47 | Correct? | 1 | 0 | null | null | null | null | null | |||||
1,300 | help-10 | 175b0d96410247b48e62c532d7d481e1 | 620,181,036,936,069,100 | phantom | 03/17/2022 14:02:54 | Thats for number 2 | 1 | 0 | null | null | null | null | null | |||||
1,302 | help-10 | d345dc3a9b534816b596330e56063938 | 691,474,609,161,371,600 | LaFlare | 11/09/2021 18:04:43 | will a graph will contain an Euler path only if all edges have even degree. | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 755,813,014,250,455,000 | am123450 | 03/17/2022 15:08:14 | 20220318_030736.jpg | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 755,813,014,250,455,000 | am123450 | 03/17/2022 15:08:37 | Can anyone show me the step on how to find the answer? Thanks | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 755,813,014,250,455,000 | am123450 | 03/17/2022 15:09:06 | Question 5 and 6 | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 536,177,306,578,845,700 | Shallow. | 03/17/2022 15:13:35 | hint: $x^{-a} = \frac {1} {x^{a}}$ | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 755,813,014,250,455,000 | am123450 | 03/17/2022 15:14:54 | Question num 5? | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 536,177,306,578,845,700 | Shallow. | 03/17/2022 15:15:03 | Ya | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 15:15:13 | @Shallow. Maybe write down what x^(-a) equals | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 15:15:29 | $hint: x^{-a} = \frac{1}{x^{a}}$ | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 536,177,306,578,845,700 | Shallow. | 03/17/2022 15:15:35 | Hmm well that will be good idea | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 15:15:36 | like this | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 510,789,298,321,096,700 | TeXit | 03/17/2022 15:15:58 | **RedstonePlayz09** | 282398643519225857.png | 0 | 1 | null | null | null | null | null | ||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 510,789,298,321,096,700 | TeXit | 03/17/2022 15:16:00 | **Deep** | 536177306578845708.png | 0 | 1 | null | null | null | null | null | ||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 536,177,306,578,845,700 | Shallow. | 03/17/2022 15:16:05 | Ya | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 15:16:06 | Yeah | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 282,398,643,519,225,860 | RedstonePlayz09 | 03/17/2022 15:16:08 | ok gl | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 755,813,014,250,455,000 | am123450 | 03/17/2022 15:16:34 | But how does that apply on question number 5? | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 755,813,014,250,455,000 | am123450 | 03/17/2022 15:16:56 | I know that number 6 uses that | 1 | 0 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 284,065,859,515,973,630 | Erzis | 03/17/2022 15:26:57 | the denominator is incorrect | 0 | 1 | null | null | null | null | null | |||||
1,303 | help-10 | 136193c9c109430298dc2cf220d3a88d | 284,065,859,515,973,630 | Erzis | 03/17/2022 15:27:22 | after you correct it cancel out and you should get a simplified form | 0 | 1 | null | null | null | null | null | |||||
1,304 | help-10 | 7e2356d1c0494701a67fc2365131dd24 | 926,918,502,441,427,000 | M1111111 | 03/17/2022 17:50:51 | inverse fourier transform of 1 | 1 | 0 | null | null | null | null | null | |||||
1,304 | help-10 | 7e2356d1c0494701a67fc2365131dd24 | 926,918,502,441,427,000 | M1111111 | 03/17/2022 17:51:02 | Can someone help me on how to solve the inverse fourier transform of 1? | 1 | 0 | null | null | null | null | null | |||||
1,305 | help-10 | 5d7a0980fffa475e9ac3302617e5411d | 594,363,497,698,295,800 | uqq | 03/17/2022 18:28:55 | @Helpers | 1 | 0 | 536,177,306,578,845,700 | Shallow. | 8817 | Shallow. | false | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:42:25 | I ended up applying logs to get
log(y) = log(A) +xlog(k)
which the the equation of the line of the form y=mx+c
and from the graph I plotted
I found the y intercept to be 20
But how do I find the values of A and K ?
every value of A and K I find, seem to be incorrect so far | 4e5bdfe8-f66d-4ee0-98a9-e3c0648a9514.png | 1 | 0 | null | null | null | null | null | ||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 18:47:45 | @melon lord One strategy would be to: | 0 | 1 | 536,177,306,578,845,700 | Shallow. | 8817 | Shallow. | false | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 18:48:05 | Calculate K first, then calculate A. | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 18:48:24 | Do you have any suggestion on how to do that? | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:49:47 | I know that log(A) is the y intercept
and the estimated y intercept is 20
so is it that A would be e^20?
or would A itself be 20? | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:50:15 | like I said
I have attempted it multiple times
and every value of A and K i get seem to be off | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 18:52:10 | You are analysing this:
log(y) = log(A) +xlog(k)
Or this:
y=Ak^x | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 18:53:17 | It depends on what you are doing... could you show your calculations (or explain how you calculated A)? | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:57:02 | part one of the question stated to to express y=Ak^x in a form suitable for drawing a straight line graph
so I applied logs and got log(y) = log(A) +xlog(k)
which is of the form y=mx+c (the equation of a straight line)
and I plotted the graph | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:57:13 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:57:33 | but I honestly don't know how to estimate the values of A and k | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 18:58:02 | How did you calculate the intercept? The 20 you mentioned before | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:58:47 | the question said to estimate the intercept from the graph | 1 | 0 | 755,813,014,250,455,000 | am123450 | 7423 | am123450 | false | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 18:59:07 | I estimated that the y intercept would be around 20 | unknown.png | 1 | 0 | null | null | null | null | null | ||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 19:02:09 | Try ploting the log(y) chart? How does that looks? | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 19:04:29 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 19:05:03 | That looks better, right? | 0 | 1 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 19:05:16 | yes, yes it does | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 653,715,253,925,773,300 | keepitalphanumeric | 03/17/2022 19:06:20 | Based on this, you can estimate the intercept and m. Those will produce something like log(y) = A + x * m ... That m is the log(k). You can go back to the original equation from that. | 0 | 1 | 814,486,194,775,523,300 | melon lord | 4793 | melon lord | false | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 19:07:04 | thank you so much | 1 | 0 | null | null | null | null | null | |||||
1,306 | help-10 | ebc08a23d0c14e339ea3058edab6a0f8 | 814,486,194,775,523,300 | melon lord | 03/17/2022 19:07:08 | .close | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:09:48 | Hi, does this calcul is possible ? ((-4 - (-4)) / 4) - (-4) = 4 | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 321,445,119,171,756,000 | Shuri2060 | 03/17/2022 19:10:47 | ,calc ((-4 - (-4)) / 4) - (-4) | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 510,789,298,321,096,700 | TeXit | 03/17/2022 19:10:48 | Result:
```
4
``` | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 321,445,119,171,756,000 | Shuri2060 | 03/17/2022 19:11:03 | https://www.mathsisfun.com/operation-order-bodmas.html | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:11:13 | yes but are we allowed to divibe 0 by 4 ? | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 327,794,296,877,219,840 | Bello友 | 03/17/2022 19:11:15 | ((-4 - (-4)) / 4) - (-4) = 4
((-4 + 4)) / 4) - (-4) = 4
(0 / 4) - (-4) = 4
0 - (-4) = 4
0 + 4 = 4
4=4 | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 249,995,298,632,368,130 | Cat Bread | 03/17/2022 19:11:31 | you can divide 0 by 4 | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 249,995,298,632,368,130 | Cat Bread | 03/17/2022 19:11:35 | you just can't divde by 0 | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 249,995,298,632,368,130 | Cat Bread | 03/17/2022 19:11:47 | so 0/4 is perfectly fine but 4/0 is not | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:12:04 | So this calcul is ok ? | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 327,794,296,877,219,840 | Bello友 | 03/17/2022 19:12:15 | Yes its fine | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 249,995,298,632,368,130 | Cat Bread | 03/17/2022 19:12:19 | just think of it like "i can distribute nothing to 4 people, but i can't distribute 4 things to nothing" | 0 | 1 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:12:59 | tysm guys | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:13:05 | Have a good night | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:13:18 | with cold pillow | 1 | 0 | null | null | null | null | null | |||||
1,307 | help-10 | 586ee8f1cc054db0962f27d67dbefdb5 | 320,262,787,177,644,000 | SandroLeCroco | 03/17/2022 19:13:50 | .close | 1 | 0 | null | null | null | null | null | |||||
1,308 | help-10 | 49e6e077a2a543318c9a2b6a5723c820 | 800,643,616,828,555,300 | vi | 03/17/2022 19:50:00 | Can I ask for help on probability? | 1 | 0 | null | null | null | null | null | |||||
1,308 | help-10 | 49e6e077a2a543318c9a2b6a5723c820 | 800,643,616,828,555,300 | vi | 03/17/2022 19:50:07 | IMG_20220316_181318.jpg | 1 | 0 | null | null | null | null | null | |||||
1,308 | help-10 | 49e6e077a2a543318c9a2b6a5723c820 | 761,155,030,513,352,700 | Bungo | 03/17/2022 19:56:07 | do you have any thoughts on these questions? which ones are you having trouble with? | 0 | 1 | null | null | null | null | null | |||||
1,308 | help-10 | 49e6e077a2a543318c9a2b6a5723c820 | 742,674,439,623,409,700 | wwywinym | 03/17/2022 19:57:16 | IMG_0568.jpg | 0 | 1 | null | null | null | null | null | |||||
1,308 | help-10 | 49e6e077a2a543318c9a2b6a5723c820 | 742,674,439,623,409,700 | wwywinym | 03/17/2022 19:57:22 | This illustration might help you | 0 | 1 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 122,121,221,876,875,260 | ChrisJ | 03/17/2022 20:31:13 | For a certain company, the cost for producing x items is 50x+300 and the revenue for selling x items is 90x−0.5x2. | 1 | 0 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 122,121,221,876,875,260 | ChrisJ | 03/17/2022 20:31:23 | My problem is with equation setup | 1 | 0 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 426,443,702,932,733,950 | Pluton | 03/17/2022 20:35:26 | Well whats the question? | 0 | 1 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 426,443,702,932,733,950 | Pluton | 03/17/2022 20:35:37 | Thats only the information of the problem | 0 | 1 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 122,121,221,876,875,260 | ChrisJ | 03/17/2022 20:35:51 | Part a: Set up an expression for the profit from producing and selling x items. We assume that the company sells all of the items that it produces. | 1 | 0 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 122,121,221,876,875,260 | ChrisJ | 03/17/2022 20:35:58 | Part b: Find two values of x that will create a profit of $50. | 1 | 0 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 426,443,702,932,733,950 | Pluton | 03/17/2022 20:37:10 | Profit is how much you earned - how much you lost | 0 | 1 | null | null | null | null | null | |||||
1,309 | help-10 | 5f60d5634cb3409f8415af502f0991e6 | 122,121,221,876,875,260 | ChrisJ | 03/17/2022 20:38:05 | so The problem would be (50x + 300) - (90x-0.5x2) then | 1 | 0 | null | null | null | null | null |
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