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1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:09:18 | because y=0 is the equilibrium solution | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:09:25 | The book I'm using says "Be sure to state the common interval for which the solution and diffeq make sense" | 1 | 0 | 529,668,257,339,408,400 | Mr.Darkside | 0064 | Mr.Darkside | false | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:09:39 | what does that mean | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:10:00 | sorry if thats a dumb question the book hasnt used that term | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:10:03 | if y=0, y'=0 so 0=0 means it's a solution for initial condition y(0)=0 | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:10:16 | equilibrium solutions are constant solutions. | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:11:32 | if its a constant solution why is it excluded from the interval | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:11:41 | im not following | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:11:46 | cause you start on an equilibrium, so you stay on the equilbrium | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:11:52 | instead of following a curved path | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:14:33 | sorry you need to dumb this down more. Is it similar to how in a piecewise function there can be a solution to both "parts" of the function but a discontinuity still exists? | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:14:57 | alternatively when you actually solve the DE you have to divide by x, so you remove the fact x=0 from the y=x^2 solution | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:15:32 | no, DE has solutions depending on the initial condition
ie depending on where you start dictates what curve is the solution | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:16:10 | do you have a visual example? | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:16:15 | sure | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:16:19 | $xy'=2y$ | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 510,789,298,321,096,700 | TeXit | 10/29/2021 16:16:21 | **Mosh** | 186109587366215691.png | 0 | 1 | null | null | null | null | null | ||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:17:37 | if y=0, then you can easily check it's a solution. and this solution has y(0)=0, so if the IVP had y(0)=0 as the condition, then you know the solution is just y=0 | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:19:52 | okay what is the IVP | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:19:58 | initial value problem | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:20:07 | so the y = x^2 | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:20:09 | no | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:20:12 | that's a solution. | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:20:20 | y = 0 then? | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:20:25 | y=0 is also a solution. | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:20:30 | oh man | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:20:33 | IVP is the DE and initial condition... | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:20:56 | $f(x,y,y')=g(x,y,y') \\ y(0)=y_0$ | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 510,789,298,321,096,700 | TeXit | 10/29/2021 16:20:58 | **Mosh** | 186109587366215691.png | 0 | 1 | null | null | null | null | null | ||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:21:09 | or whatever initial condition you have | 0 | 1 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:22:49 | hmm I havent seen any of this yet in the book. I might need to plug away and return when I have more of the vocabulary down. | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 186,109,587,366,215,680 | Omegabet_ | 10/29/2021 16:22:59 | Ok | 0 | 1 | 624,799,147,148,443,600 | Shmoich | 9172 | Shmoich | false | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:23:41 | I have a note on the some of the term you used so when they come up all have something to refer back to | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:23:44 | thank though | 1 | 0 | null | null | null | null | null | |||||
1,446 | help-10 | fd6b3da6ffa845778122f81caea5bca3 | 624,799,147,148,443,600 | Shmoich | 10/29/2021 16:23:49 | .close | 1 | 0 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 793,106,135,678,058,500 | the | 11/10/2021 10:05:50 | just wanna check my answer | unknown.png | 1 | 0 | null | null | null | null | null | ||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 793,106,135,678,058,500 | the | 11/10/2021 10:21:57 | i just drew some constructions at OB, OC, OA, OD and bisected AD and called it OE
i then said since OBC and OAD are isosceles that AE=ED and BE=EC
then i just went AE-BE=AB and ED-CE=CD
then i said therefore AB is congruent to CD | 1 | 0 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 793,106,135,678,058,500 | the | 11/10/2021 10:22:03 | is that correct? | 1 | 0 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 793,106,135,678,058,500 | the | 11/10/2021 10:22:38 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 346,652,719,173,599,200 | Leοn | 11/10/2021 10:25:40 | you have to prove that OE is perpendicular to BC | 0 | 1 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 346,652,719,173,599,200 | Leοn | 11/10/2021 10:25:49 | or maybe you are allowed to accept it as true? | 0 | 1 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 793,106,135,678,058,500 | the | 11/10/2021 10:26:16 | how 2 do? | 1 | 0 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 346,652,719,173,599,200 | Leοn | 11/10/2021 10:30:56 | So E is the midpoint of AD and OAD is an isosceles | 0 | 1 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 346,652,719,173,599,200 | Leοn | 11/10/2021 10:31:54 | That means OE is a perpendicular bisector of AD | 0 | 1 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 346,652,719,173,599,200 | Leοn | 11/10/2021 10:32:08 | Thus it is perpendicular to BC | 0 | 1 | null | null | null | null | null | |||||
1,447 | help-10 | 61b3e48d28a246c59385c08c7b014f39 | 793,106,135,678,058,500 | the | 11/10/2021 10:32:10 | how tf is OAB isosceles | 1 | 0 | null | null | null | null | null | |||||
1,448 | help-10 | 9da06716aa8e42309b138a804d3e124e | 319,444,879,656,878,100 | Palpoutine | 03/24/2022 04:20:48 | how does a function y = 3x + 21 mod26 gets its inverse being x = 9y + 19 | 1 | 0 | null | null | null | null | null | |||||
1,448 | help-10 | 9da06716aa8e42309b138a804d3e124e | 319,444,879,656,878,100 | Palpoutine | 03/24/2022 04:32:27 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 07:41:43 | New_Screen_Shot_NameScreenshot_6.png | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 07:41:53 | is the answer c | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 07:55:48 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 07:59:15 | no, the answer is not c | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 844,913,236,989,837,300 | 5lttrz | 03/24/2022 07:59:21 | It is | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:00:15 | eh no, the side of the smallest triangle is 4/5, QR shouldnt sum up to be C | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:00:24 | unless im misreading the diagram | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 844,913,236,989,837,300 | 5lttrz | 03/24/2022 08:00:48 | x
2x
4x
8x
16x | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:01:05 | how do I solve it? | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:01:31 | start by labelling a side | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 844,913,236,989,837,300 | 5lttrz | 03/24/2022 08:01:40 | Screenshot_20220324-173134.png | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:01:40 | sorry, brainfart there | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:02:29 | lemme guess, you forgot to exclude the side with length of x | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:02:41 | PQ=15x in your case and not 16x | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:03:10 | oh | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:03:10 | Q is notated to be the right angle here by how its drawn | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:03:15 | oh my god ohhh | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:03:28 | i didnt know it halves | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:03:32 | every 90 degrees | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:04:12 | do i do 16x = 12 | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:04:35 | oh wait | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:04:38 | ...apparently i havent said anything above | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:04:41 | oh sry | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:04:48 | didnt read carefully | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:04:57 | so 15x = 12? | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:05:02 | yes | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:05:11 | even if PQ=16x, the answer wouldnt have been B | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:05:18 | ic | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:05:37 | thanks :) | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:06:25 | could u help me with another one | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:08:00 | just send it, and i will if i know how | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:08:11 | New_Screen_Shot_NameScreenshot.png | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:08:25 | ive tried to make (p-q)^2 = (p-q)(p+q) | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:08:33 | then its n(p-q) | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:08:40 | but i dont know how to get a p - q | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:09:01 | can you expand (p-q)^2 for me | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:09:15 | ok | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:09:47 | so p^2 - 2pq + q^2 | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:09:53 | great | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:10:00 | so now can you find what n^2 equals from the given information? | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:10:13 | p^2 + 2pq + q^2 | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:10:16 | ok good | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:10:27 | notice that it just differs from the middle term | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:10:33 | mhm | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:10:58 | so we in order to have a -2pq in n^2, we can add and subtract a 4pq correct? | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:11:04 | since 2pq - 4pq = -2pq | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:11:07 | mhm | 1 | 0 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:11:23 | so n^2 = p^2 -2pq + q^2 + 4pq | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:11:38 | which gives n^2 = (p-q)^2 + 4pq | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:11:48 | now the only thing is we need to find what pq equals | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 271,133,126,728,613,900 | waler | 03/24/2022 08:12:02 | we also know that 1/p + 1/q = m, can you find what pq equals? | 0 | 1 | null | null | null | null | null | |||||
1,449 | help-10 | e3a12c5096444be1a37579e0b03febbb | 568,416,924,564,848,640 | Macro | 03/24/2022 08:12:06 | hm | 1 | 0 | null | null | null | null | null |
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