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help-10
02ca9a39b43b4e22a2ef740735ef60ec
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Eureka
11/10/2021 16:35:15
.close
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Jun♾
03/28/2022 07:31:50
I need help with finding the volume of this shape.
https://cdn.discordapp.c…800/IMG_3656.png
IMG_3656.png
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Jun♾
03/28/2022 07:32:32
I’m having trouble with finding the area of the front shape
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Mr.Darkside
03/28/2022 07:33:02
Can you find the area of the front if there was no hole?
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help-10
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Jun♾
03/28/2022 07:33:22
Yes
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Mr.Darkside
03/28/2022 07:33:45
And can you find the area of the hole? Its a semi circle
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Jun♾
03/28/2022 07:34:00
Yh ok let me try again
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help-10
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Jun♾
03/28/2022 07:35:06
Ok got it
1
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Jun♾
03/28/2022 07:35:17
Thanks
1
0
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Jun♾
03/28/2022 07:35:23
.close
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Deleted_User
03/28/2022 07:51:11
https://cdn.discordapp.c…7304/unknown.png
unknown.png
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Deleted_User
03/28/2022 07:51:21
why does this limit equal infinity, ignore first equal sign
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help-10
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axis
03/28/2022 08:17:32
numerator becomes 3^+, and denom becomes 0^+
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help-10
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axis
03/28/2022 08:17:44
which simplifies to infinity
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AuHasard
03/28/2022 08:32:39
if\ $$tan(x)=2$$\ what\ is\ $$sin(2x)$$? $$\frac{sin(x)}{cos(x)} =2;\ 2cos(x)\ =\ sin(x)$$
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TeXit
03/28/2022 08:34:08
**AuHasard**
https://cdn.discordapp.c…827648045137.png
933153827648045137.png
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AuHasard
03/28/2022 08:34:42
how do i proceed from here
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AuHasard
03/28/2022 08:36:42
$$\left( 2cos(x)-sin(x)\right)^{2} =(2cos(x)-sin(x))(2cos(x)-sin(x))\ =\ 0$$
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Omegabet_
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TeXit
03/28/2022 08:37:55
**AuHasard**
https://cdn.discordapp.c…827648045137.png
933153827648045137.png
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AuHasard
03/28/2022 08:38:35
i dont know haha
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AuHasard
03/28/2022 08:39:02
hmm
1
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AuHasard
03/28/2022 08:39:09
2cos(x) = sin(x)
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AuHasard
03/28/2022 08:39:39
if i multiply by 2 on both sides
1
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AuHasard
03/28/2022 08:39:46
nah
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AuHasard
03/28/2022 08:40:08
i know what it is
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AuHasard
03/28/2022 08:40:11
2sinxcosx
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help-10
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AuHasard
03/28/2022 08:40:15
but we have sin x on the right
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AuHasard
03/28/2022 08:40:22
so what are you trying to tell me
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AuHasard
03/28/2022 08:40:35
i didnt know that
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Omegabet_
03/28/2022 08:40:39
??
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AuHasard
03/28/2022 08:40:43
??
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AuHasard
03/28/2022 08:40:47
yes, i didnt know that
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Omegabet_
03/28/2022 08:40:50
what was literally anything you were saying then?
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Deleted_User
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AuHasard
03/28/2022 08:42:23
$$sin(2x)=2sin(x)cos(x)$$ $$\frac{sin(2x)}{sin(x)} =\frac{1}{sin(x)} \times 2sin(x)cos(x)$$ $$
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AuHasard
03/28/2022 08:43:08
can you chill
1
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AuHasard
03/28/2022 08:43:14
mate
1
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help-10
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AuHasard
03/28/2022 08:43:24
sin(2x)/sin(x) = 2cos(x)
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AuHasard
03/28/2022 08:43:27
right?
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Omegabet_
03/28/2022 08:43:31
yes.
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AuHasard
03/28/2022 08:43:32
that's what i'm trying to prove up there
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AuHasard
03/28/2022 08:43:35
ok
1
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Omegabet_
03/28/2022 08:43:47
provided x != n*pi blahblahblah
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AuHasard
03/28/2022 08:44:37
ok so we have 2cos(x) = sin(x) and we know that sin(2x) = 2sin(x)cos(x) so 2cos(x) is basically just 2sin(x)cos(x)/sin(x)
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AuHasard
03/28/2022 08:45:06
what then?
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AuHasard
03/28/2022 08:45:16
let me check what you wrote
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AuHasard
03/28/2022 08:45:26
yes
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help-10
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AuHasard
03/28/2022 08:46:02
$2sinxcosx=(sin(x))(2cos(x))=sin(2x)$
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help-10
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TeXit
03/28/2022 08:46:05
**AuHasard**
https://cdn.discordapp.c…827648045137.png
933153827648045137.png
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AuHasard
03/28/2022 08:46:06
yes?
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Omegabet_
03/28/2022 08:46:16
pointless symbol pushing
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Omegabet_
03/28/2022 08:46:19
but yes
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Omegabet_
03/28/2022 08:46:31
It is.
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AuHasard
03/28/2022 08:47:22
i would've if it was that easy
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help-10
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AuHasard
03/28/2022 08:47:52
here let me show you the alternatives
1
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help-10
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AuHasard
03/28/2022 08:48:22
”what's sin (2x)”
https://cdn.discordapp.c…kl._14.47.59.png
Skarmavbild_2022-03-28_kl._14.47.59.png
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Omegabet_
03/28/2022 08:48:34
@AuHasard if you had y=3x and I asked you what y was when x=2, would you be able to do that?
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AuHasard
03/28/2022 08:48:50
yes
1
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Omegabet_
03/28/2022 08:48:58
Ok, what would it be, and why?
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AuHasard
03/28/2022 08:49:24
y would be 6 because the value of the function is 6 at x = 2
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Omegabet_
03/28/2022 08:49:29
yes
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Omegabet_
03/28/2022 08:49:55
so If I had $\sin(2x)=2\sin(x)\cos(x)$ and I asked you what it became when $\sin(x)=2\cos(x)$
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TeXit
03/28/2022 08:49:58
**Mosh**
https://cdn.discordapp.c…587366215691.png
186109587366215691.png
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Omegabet_
03/28/2022 08:50:05
you should be able to do this on the back of what you just said.
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Omegabet_
03/28/2022 08:51:14
I disagree that it'd be easier
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AuHasard
03/28/2022 08:51:26
I don't know tbh
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AuHasard
03/28/2022 08:51:28
and I feel bad
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all lines are flat
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AuHasard
03/28/2022 08:51:34
I've studied trig identities for a while
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Omegabet_
03/28/2022 08:51:36
why is 3x 6 when x=2?
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Omegabet_
03/28/2022 08:51:46
ELI5
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AuHasard
03/28/2022 08:51:57
because of the value
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AuHasard
03/28/2022 08:52:03
of the function
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Omegabet_
03/28/2022 08:52:05
so 3x=2?
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AuHasard
03/28/2022 08:52:13
no, x is 2
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Omegabet_
03/28/2022 08:52:20
yeah but you just said cause of the value
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AuHasard
03/28/2022 08:52:34
you probably know what i meant
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AuHasard
03/28/2022 08:52:38
what's your point
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AuHasard
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Omegabet_
03/28/2022 08:53:00
Cause you're failing to recognize that this problem too is *just a substitution*
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help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:53:07
$2sinxcosx=(sin(x))(2cos(x))=sin(2x)$
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
510,789,298,321,096,700
TeXit
03/28/2022 08:53:10
**AuHasard**
https://cdn.discordapp.c…827648045137.png
933153827648045137.png
0
1
null
null
null
null
null
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help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:53:10
No
0
1
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null
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help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:53:13
nobody said if this was wrong
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:53:18
Yeah, cause it's not
0
1
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null
null
null
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help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:53:22
it's just pointless
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:53:30
$\sin(2x)=2\sin(x)\cos(x)=2(2\cos(x))\cos(x)$
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
510,789,298,321,096,700
TeXit
03/28/2022 08:53:32
**Mosh**
https://cdn.discordapp.c…587366215691.png
186109587366215691.png
0
1
186,109,587,366,215,680
Omegabet_
9771
Omegabet_
false
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:53:44
cause sin(x)=2cos(x)
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:54:17
can we treat them as variables?
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:54:20
yeah?
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:54:36
no i mean the trig functions
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:54:41
Yeah
0
1
null
null
null
null
null
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help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:54:49
algebra doesn't magically break as soon as trig appears
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:55:01
ok so a = sin(x), b = cos(x) a = 2b
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:55:09
so i need to prove that a is equal 2b
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:55:14
NO
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
186,109,587,366,215,680
Omegabet_
03/28/2022 08:55:27
**That is the assumption tan(x)=2**
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:55:49
okay type it out
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:59:10
$a=sin(2x)=2\sin \left( x\right) \cos \left( x\right) =\sin \left( x\right) (2\cos \left( x\right) )=bc$
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
510,789,298,321,096,700
TeXit
03/28/2022 08:59:13
**AuHasard**
https://cdn.discordapp.c…827648045137.png
933153827648045137.png
0
1
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:59:22
hmm
1
0
null
null
null
null
null
1,538
help-10
7955627e484a42c59b538f4e13a5d848
933,153,827,648,045,200
AuHasard
03/28/2022 08:59:48
okay so sin(x) = 2cos(x)
1
0
null
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null