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1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:11:25 | so after each loop, u lose 2 in total? | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:12:13 | y not? | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:12:22 | s | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:12:41 | so 26 decreases by 2 each time after the loop? | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:13:26 | so answer is 0 since 26 is even? | 1 | 0 | 220,517,274,845,577,200 | ramonov | 0921 | ℝamonov | false | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:13:45 | maybe not lol | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:13:48 | 0 is wrong | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:14:10 | just think | 1 | 0 | null | null | null | null | null | |||||
1,614 | help-10 | 1f616d6bde1e4d9ebf27521d7a1c98db | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:14:16 | what happens when u reach 6 | 1 | 0 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:15:02 | bruh it's nothing | 1 | 0 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:15:11 | u get to 4 | 1 | 0 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:15:23 | then u can't give 5 out of 4 n it stops there | 1 | 0 | 873,934,641,910,931,600 | ColtyDay | 3818 | ColtyDay | false | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 874,215,957,113,995,300 | 1234567 | 04/01/2022 03:15:31 | nvm then | 1 | 0 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:23:09 | IMG_20220401_152240.jpg | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:23:18 | I'm not sure how to do this I need some help | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:24:21 | So you have something with unit cm, and you want cm/t where t is time | 0 | 1 | 178,975,316,893,630,460 | Ceecks | 3667 | Ceecks | false | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:24:24 | what do you do? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:24:40 | dr/dt | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:24:50 | yes, you take the derivative | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:25:43 | and so y'(t) tells you how the radius change given t, so what do you let t be when you evaluate this formula? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:26:15 | Will t be 0? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:26:48 | t needs to be such that y(t) = 5 right? ' | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:26:55 | Yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:27:19 | here $y(t)=\sqrt{1+t}$ | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 510,789,298,321,096,700 | TeXit | 04/01/2022 03:27:21 | **bim** | 140814505226534912.png | 0 | 1 | null | null | null | null | null | ||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:27:32 | so you solve for t, take the derivative, and plug in your t | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:27:40 | do you see why? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:29:06 | So y'(t) will be 1/2 sqrt (1+t)? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:29:28 | where is the sqrt(1+t)? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:29:31 | (be careful, sqrt(1+t) is not the radius after t seconds)) | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:29:42 | ah thats true | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:29:50 | I'm getting confused now | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:29:59 | okey let us start from the beginning | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:30:07 | Okay | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:30:10 | What do you want to find? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:30:28 | Rate at which radius is increasing | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:30:39 | dr/dt | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:30:43 | yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:30:53 | can you find the radius in the exercise ? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:31:09 | 5cm | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:31:29 | that is when you want the rate of change | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:31:39 | so you wrote dr/dt | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:31:54 | which means that r is a function that you take the derivative with respect to t right? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:32:04 | Yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:32:10 | so what is this function r ? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:32:33 | tell me in words, no need to give it | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:32:48 | I'm not sure | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:33:17 | so dr/dt = change of radius with respect to time, right ? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:33:27 | Yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:33:40 | so r should be the function for the radius | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:33:48 | Yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:33:54 | do the exercise give such a function ? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:34:05 | No | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:34:25 | but it does give a function for the volume, can you connect the volume with the radius of the balloon? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:34:54 | Volume of balloon is 4/3 pi r 3 | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:35:23 | So I make r the subject of the formula? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:35:49 | well yes, so you have a formula that gives the volume for a given t, and you have another formula that gives r for a certain volume | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:35:54 | do you see what i mean ? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:36:12 | Yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:36:30 | so you should be able to express the radius of the balloon as a function of t | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:36:46 | Okay thank you Ill try it out now | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:36:59 | good luck and let me know if you need more help! | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:37:05 | Yep thanks! | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:37:36 | a general tip, if you dont understand an execise, break it down into smaller questions like i tried to do for you above | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 140,814,505,226,534,910 | bim | 04/01/2022 03:37:42 | you see what i mean by that? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:44:03 | Im not rlly sure now | 20220401_154348.jpg | 0 | 1 | null | null | null | null | null | ||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:45:26 | try to establish the functions slowly | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:45:40 | like bim said, you can express v(t) in terms of r(t) | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:45:48 | can you try to write that out? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:46:37 | 20220401_154632.jpg | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:47:10 | i asked for v(t) in terms of r(t), you are trying to express v'(t) as a result of chain rule | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:48:27 | 20220401_154821.jpg | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:48:30 | This? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:48:36 | almost | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:48:50 | but yes, v(t)=4/3pi *r^3(t) | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:48:58 | however v(t) is not sqrt(1+t)/t | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 510,789,298,321,096,700 | TeXit | 04/01/2022 03:49:42 | **waler** | 271133126728613896.png | 0 | 1 | null | null | null | null | null | ||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:50:01 | now instead of actually solving for r, a quicker way is to just find r'(t) in terms of r(t) and t | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:50:17 | have you learnt implicit differentiation? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:50:29 | Not sure | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:50:36 | I don't think so | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:51:00 | right, that means we would have to solve for r(t) then | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:51:10 | well, it's not too bad either | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:52:13 | are you sure you havent learnt implicit differentiation? It's basically differentiation but with functions relative to t instead of differentiating functions in terms of t | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:53:01 | i think you should know this from the fact that you wrote out the chain rule for v'(t) | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:53:02 | I'm pretty sure I have yet to learn that | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:53:05 | ok then | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:53:41 | so basically just solve for r(t), differentiate r(t) wrt t, then substitute t into the derivative | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:54:27 | How do I solve for r(t)? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:54:42 | just like how you would solve for x in an equation | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:54:56 | try to look at t as a constant, then solve for r in terms of t | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:56:05 | So do I sub t as a number? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:56:16 | Like t=3 | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:56:21 | Then I solve for r | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:56:34 | no, just treat it as if it was a constant | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:57:28 | for example y^3=x would be equivalent to y=cbrt(x), what i did was solve for y in terms of x as I took the cube root on both sides | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:57:50 | Yes | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 03:58:10 | So I just move all the things except for r to the right side with t? | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 271,133,126,728,613,900 | waler | 04/01/2022 03:58:22 | sure | 0 | 1 | null | null | null | null | null | |||||
1,615 | help-10 | 170a007e36804f0d92b8ab429c23ee8e | 686,556,225,827,242,000 | Kokonut | 04/01/2022 04:00:07 | 20220401_160001.jpg | 0 | 1 | null | null | null | null | null |
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