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1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:29:25 | Uh | 0 | 1 | 793,888,357,397,954,600 | Kev Martin | 6735 | Kev Martin | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:29:30 | dw, I finished my Gcse in y 10 | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:29:35 | Likes perpendicular lines on graphs | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:29:53 | my school didn’t let me do my maths a level in y11 | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:29:59 | I would have if they let me | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:30:33 | My teacher basically let me self-learn it her maths classes | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:30:55 | demarche.PNG | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:30:57 | Rather than the gcse stuff because they ended up just doing the same things again and again | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:31:10 | IMG_1351.png | 0 | 1 | 793,888,357,397,954,600 | Kev Martin | 6735 | Kev Martin | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:31:32 | basically that | 0 | 1 | 793,888,357,397,954,600 | Kev Martin | 6735 | Kev Martin | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:31:34 | you invert the vector and negate one component of it | 0 | 1 | 373,884,980,977,336,300 | Remavas | 3737 | Remavas | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:31:44 | Nice shortcut to get perpendicular vectors in 2d | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:31:46 | ye | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:31:49 | in 2d | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:31:53 | very specifically | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:31:58 | indeed | 0 | 1 | 884,904,554,037,141,600 | dk.dkn | 6601 | dk.dkn | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:32:15 | It’s not too bad in 3d even before you learn the cross product* | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:32:16 | 3d and your dot product = 0 | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:32:54 | You have a whole plane of vectors perpendicular to a single 3d vector | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:33:34 | it’s scalar product unless we’re tryna find the perpendicular vector of 2 distinct non parallel lines | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:33:56 | I just dont understand the 1/ square root 10 | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:34:11 | ok, i’ll try explain this | 0 | 1 | 884,904,554,037,141,600 | dk.dkn | 6601 | dk.dkn | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:34:20 | so that initial vector there | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:34:31 | it travels 1 and 3 | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:34:32 | This is called "normalizing" a vector. Basically, you divide a vector by its length to get a unit vector in the same direction. | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:34:39 | Yes | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:34:39 | right | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:34:58 | so, the total displacement is sqrt(10) | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:35:02 | yes? | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:35:12 | Yes because its the result of my product | 1 | 0 | 793,888,357,397,954,600 | Kev Martin | 6735 | Kev Martin | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:35:15 | yep | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:35:30 | but we want our vector to only travel 1 | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:35:39 | Yep which is 1 unit | 1 | 0 | 373,884,980,977,336,300 | Remavas | 3737 | Remavas | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:35:44 | yep | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:36:05 | so we divide the whole vector by sqrt(10) | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:36:26 | Yea that’s what I was talking about, I see this problem as more ‘like’ that than just finding the plane | 0 | 1 | 373,884,980,977,336,300 | Remavas | 3737 | Remavas | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:37:19 | how were you planning to do vector product with two, let me try it | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:37:48 | Wdym? | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:37:55 | |i j
1 -3| | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:38:13 | yeah it works i think | 0 | 1 | 884,904,554,037,141,600 | dk.dkn | 6601 | dk.dkn | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:38:16 | Oh 2d not 2 vectors | 0 | 1 | 880,503,100,711,010,300 | Rylo | 1068 | Rylo | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:38:23 | Was gonna say | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:38:28 | it still works | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:38:32 | so it’s gucci | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:38:55 | -3i - j | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:39:09 | Yep | 0 | 1 | 880,503,100,711,010,300 | Rylo | 1068 | Rylo | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:39:19 | And just adjust for unit vector obv | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 880,503,100,711,010,300 | Rylo | 04/01/2022 11:39:43 | oh ye | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:40:21 | I flip my sign now i have a new vector which would be (-1 3)
Then i do the product thing of my initial vector which will be Square root 10
And to find my unit i divide my ''x'' and ''y'' by the square root
x : -1 / sqr 10 = -.31
y : 3 / sqr 10 = .94 | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:40:34 | That would be one unit right ? | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:40:43 | $\approx$ | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 510,789,298,321,096,700 | TeXit | 04/01/2022 11:40:45 | **Remavas** | 373884980977336321.png | 0 | 1 | null | null | null | null | null | ||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:40:53 | Ah, yes | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:41:31 | Yeah but it’s better to leave in exact form | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:41:40 | Unless the exact form looks outrageous | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:41:53 | ,w continued fraction of sqrt(10) | 0 | 1 | 880,503,100,711,010,300 | Rylo | 1068 | Rylo | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:42:03 | final.PNG | 1 | 0 | 884,904,554,037,141,600 | dk.dkn | 6601 | dk.dkn | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 510,789,298,321,096,700 | TeXit | 04/01/2022 11:42:04 | Results provided by WolframAlpha | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:42:06 | like that | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 373,884,980,977,336,300 | Remavas | 04/01/2022 11:42:09 | yes | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:42:22 | Its not that complicated | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:42:30 | Yeah | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:42:56 | If you think about the gradient of each vector from the origin it makes sense | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:43:33 | Like how the normal gradient is the negative reciprocal | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:44:11 | It works off that logic, it’s also obvious looking at a circle with the desired length as the radius (unit circle here) | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:44:20 | Not sure what would be gradient in French but i guess i figured the big picture of this problem | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:44:49 | Um | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:45:00 | At first i just didnt knew how to find perpendicular vectors, but if i just have to flip the signs and stuff im fine with that | 1 | 0 | 884,904,554,037,141,600 | dk.dkn | 6601 | dk.dkn | false | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:45:07 | pente? | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:45:09 | YES | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:45:20 | y2-y1/x2-x1 | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:45:24 | eeh | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:45:24 | Yeah | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:45:32 | well something like that | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:46:04 | okay alright thanks for helping me with that i really appreciate ! | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 884,904,554,037,141,600 | dk.dkn | 04/01/2022 11:46:15 | Np man | 0 | 1 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 793,888,357,397,954,600 | Kev Martin | 04/01/2022 11:50:06 | .close | 1 | 0 | null | null | null | null | null | |||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 313,241,736,816,361,500 | P5 | 04/01/2022 12:05:14 | **Using the PEMDAS rules, and one parathethes, how can you make the following equation**
So far, I haven't found the answer, and all I am doing so far is literally guessing by placing the parantheses somewhere.
Is there a better way of doing this without having to guess? | unknown.png | 0 | 1 | null | null | null | null | null | ||||
1,621 | help-10 | c3a78417a1e4471ab73e0a49fcb13e8f | 935,206,623,507,525,600 | ax3__39 | 04/01/2022 12:18:30 | Is the : a division sign? | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:31:49 | hello, just need quick help with this one question :D | unknown.png | 1 | 0 | 793,888,357,397,954,600 | Kev Martin | 6735 | Kev Martin | false | ||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 391,270,706,186,420,200 | illuminator3 | 04/01/2022 12:33:13 | what have you done so far | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:34:48 | well i started plugging in -1 for the n but then what do i do with the -2 for a1 | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 391,270,706,186,420,200 | illuminator3 | 04/01/2022 12:37:33 | why -1 for n? | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:40:08 | bc its a -1 for a0 | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:40:12 | idk what to do with it | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:41:32 | look at what you're being asked to find | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:41:43 | what is the first box asking for? | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:42:38 | a2 ! | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:42:46 | a_2 yes | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:43:24 | and you're given that
$$a_n = na_{n-2} - a_{n-1} - 1$$
without overthinking this, which value of $n$ will most likely get you what you want? | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 510,789,298,321,096,700 | TeXit | 04/01/2022 12:43:27 | **ℝamonov** | 220517274845577216.png | 0 | 1 | null | null | null | null | null | ||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:44:26 | wouldnt you just plug in 2 for the n values | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:45:00 | yes, exactly | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:45:36 | oh see i thought so! but the values it was giving me for a0 and a1 were throwing me off i thought i had to use those | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:45:39 | thanks a lot! | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:45:46 | well you will | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:46:08 | oh? okay but when | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 220,517,274,845,577,200 | ramonov | 04/01/2022 12:51:21 | what do you have after plugging in n=2 | 0 | 1 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:53:03 | ooo okay wait i think. i got it thx | 1 | 0 | null | null | null | null | null | |||||
1,622 | help-10 | ba5619c5a04746ee8579c897fdf2acc8 | 632,455,793,576,247,300 | malus | 04/01/2022 12:53:04 | .close | 1 | 0 | null | null | null | null | null |
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