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1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:19:54 | n=1
11111
01111
One switch | 0 | 1 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:20:34 | n=2
11111
00111
Two switches | 0 | 1 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:22:03 | n=3
11111
01111
01011
11011
10011
00011
Six switches | 0 | 1 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:27:33 | n=4
11111
10111
00111
00101
10101
11101
01101
01001
11001
10001
00001
Eleven switches | 0 | 1 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:28:42 | It kinda looks like it adds on 2 more to the rate each time | 0 | 1 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:33:47 | So because the rate of change was 5 switches when n=4 when n=5 the rate of change will be 7 switches and so
n=5
Eighteen switches? | 1 | 0 | 373,884,980,977,336,300 | Remavas | 3737 | Remavas | false | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:34:16 | Thats my thinking | 0 | 1 | 299,974,051,127,099,400 | Zanarcane | 6798 | what is a manifold? | false | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:36:02 | So could the recurrence relation be described as something like:
a(n) = [a(n-1) - a(n-2)] + 2 ? | 1 | 0 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:37:06 | Wait | 1 | 0 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:37:49 | I think it would be a(n) = a(n-1) + [a(n-1) - a(n-2)] + 2 | 1 | 0 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:38:47 | YEAH THATS IT | 1 | 0 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:38:49 | THANK YOU | 1 | 0 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 251,854,584,597,708,800 | PapaBread | 10/29/2021 17:39:21 | Epic | 0 | 1 | null | null | null | null | null | |||||
1,668 | help-10 | 502468ffd7d745e68abd3f4958fdeca6 | 185,214,393,749,995,520 | gg | 10/29/2021 17:39:38 | .close | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:26:29 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:26:43 | How did we get from the top line to the bottom line | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:27:20 | through the middle line? 😄 | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:28:16 | hi | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:35:55 | Are you still there? | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:36:46 | yes | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:37:09 | oh ok | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:37:36 | i just dont know what the question is, there is a line between top and bottom that you asked about? where exactly are you unclear | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:38:17 | I meant | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 477,823,425,893,629,950 | kattunge | 11/11/2021 14:38:19 | .... | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:38:37 | im getting confused | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:39:06 | im asking how did the top line equal the second line | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:43:55 | well for example, the first part becomes
$$\frac{81}{n^4}\left( \frac{n(n+1)}{2} \right)^2 = \frac{81}{4n^4} n^2(n+1)^2$$
$$ = \frac{81}{4n^2} (n+1)^2 = \frac{81}{4} \left( \frac{n+1}{n} \right)^2 $$
$$ = \frac{81}{4} \left( 1 + \frac{1}{n} \right)^2 $$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 652,336,711,325,712,400 | quantum | 11/11/2021 14:43:58 | for the first term, they changed 1/n^4 into 1/(n^2)^2 | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 14:43:58 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:46:03 | because of an LCD between the 2 expressions | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:46:05 | for step 2? | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:46:52 | you mean the n^4 and the n^2 is cancelling out? | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:47:32 | I meant that a 4 appears in the denominator of 81 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 652,336,711,325,712,400 | quantum | 11/11/2021 14:48:17 | they just switched the denominators | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:48:31 | it comes from the 2 in the denominator at the beginning | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:48:40 | it is squared, so i can take it outside and it becomes 4 | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:49:19 | $\left( \frac{1}{2} \right)^2 = \frac{1}{4}$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 14:49:23 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:51:20 | lol | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:52:07 | im lost | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:52:31 | I understand the denominator in the expression is squared. That its denominator will equal 4 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:53:51 | ok | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:53:52 | so | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:54:28 | the denominators are multiplied giving 81/4n^4 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:54:38 | n^2 is cancelled out | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:54:46 | leaving 81/4n^2 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:55:28 | (n+1)^2 = (n+1)(n+1) = n^2 +2n +1 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:56:37 | 81/4n^2 = 81/4 because n^2 is now canceled | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:56:43 | there is no need to multiply that out | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:56:59 | you can just move the n^2 inside | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:57:35 | $\frac{1}{n^2} \left( n+1 \right)^2 = \left( \frac{n+1}{n} \right) ^2$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 14:57:37 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:58:39 | because.. well
$\left(\frac{A}{B} \right)^2 = \frac{A^2}{B^2}$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 14:58:54 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 14:59:11 | you see?? | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:59:31 | yes | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 14:59:56 | (n+1)^2 / n^2 = (n+1 / n )^2 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:00:27 | I'm sorry, I forgot a lot of basic math skills | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:00:58 | going from step 2 to step 3 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:04:05 | yes? or ? | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:04:15 | how? | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:04:31 | what happened to n? | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:04:36 | $\frac{n^2}{n^4} = \frac{1}{n^2}$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 15:04:39 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:05:27 | $\frac{n \cdot n}{n \cdot n \cdot n \cdot n}$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 15:05:30 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:05:31 | they cancel out, right? | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:05:45 | yes I understand that | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:06:03 | but the final answer is -6.75 | 1 | 0 | 456,226,577,798,135,800 | Deleted User | 0000 | Deleted User | false | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:06:14 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:06:23 | oops wrong one | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:06:39 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:06:51 | i guess i dont know what you mean by step 2 and step 3 | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:06:54 | I understand now how we go from step 1 to step 2 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:07:04 | thanks for that | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:07:06 | but now I am asking | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:07:19 | how do we go from step 2, the middle line, to step 3 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:07:33 | where n is no longer present and the solution is given as -6.75 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:07:51 | because when n goes to infinity, you can simply remove all 1/n | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:07:57 | it goes to zero | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:08:26 | so you have
$\frac{81}{4}(1+0)^2 - 27(1+0)^2$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 15:08:28 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:08:35 | is that true for all variables when their limit is infinity? | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:08:54 | yeah, well, theres nothing special about the l etter 'n' | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:09:03 | if x goes to infinity, 1/x goes to zero | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:09:11 | what about just x | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:09:16 | that goes to infinity | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:09:20 | so its troublesome | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:09:36 | so if n where not 1/n in the above problem | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:09:42 | it would remain as n | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:09:51 | thats why they did the stuff from top line to middle line. to get rid of n in the numerator | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:10:20 | I see | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:10:24 | well thanks for the help | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:10:27 | that has helped a lot | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:13:32 | is there a place where I can find the limit laws? | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 456,226,577,798,135,800 | Deleted User | 11/11/2021 15:13:43 | so I know that as n approaches infinity that 1/n = 0 | 1 | 0 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:19:46 | it can be shown like this. for any small $\epsilon > 0$, we can find a large $N$ such that the distance between 1/n and 0
$$|1/n - 0| = |1/n| $$
is less than $\epsilon$, whenever $n \geq N$ | 0 | 1 | null | null | null | null | null | |||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 510,789,298,321,096,700 | TeXit | 11/11/2021 15:19:49 | **reking** | 123486388548141059.png | 0 | 1 | null | null | null | null | null | ||||
1,669 | help-10 | e267d99acbad4917963cf258e3459345 | 123,486,388,548,141,060 | reking | 11/11/2021 15:21:49 | but if that doesn't make sense to you yet, i don't know how else to show it :v | 0 | 1 | null | null | null | null | null | |||||
1,670 | help-10 | f1c771f25f974120b5ef14e281ef6ba7 | 399,727,937,634,566,140 | Redacted | 04/03/2022 18:54:44 | I know that the given angle and the opposite one have to equal 90 degrees but I dont know how to do that in this form. I also dont really know what to do after that 😅 (plz ping) | unknown.png | 1 | 0 | null | null | null | null | null |
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