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1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:05:56 | what do I do now | 1 | 0 | 220,517,274,845,577,200 | ramonov | 0921 | ℝamonov | false | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:06:09 | ok I’m so dumb | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:06:12 | I swear | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:06:13 | nvm | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:06:13 | wait | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:08:06 | idk what to do now | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:08:07 | 91ADCE5A-92FB-4072-8078-F52397B3DCCA.jpg | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:10:42 | do I just delete the h | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:10:44 | ? | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:25:05 | ye | 1 | 0 | null | null | null | null | null | |||||
1,832 | help-10 | bbd87e55f254429cad2810beb1c7a5f2 | 426,918,851,813,441,540 | Squishey | 04/12/2022 00:25:06 | .close | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:27:42 | 1 | 0 | null | null | null | null | null | ||||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:27:49 | evening gentlemen | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:27:59 | coukd i get some help on this pls | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:29:43 | q4 | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:31:07 | what is confusing? find the mcclaurin series and then find the coefficient of x^(2022) and multiply it by 2022! | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:31:23 | because coeff of $x^n = \frac{f^{(n)}(0)}{n!}$ | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 510,789,298,321,096,700 | TeXit | 04/12/2022 00:31:30 | **! Brontochad (RYC4blushysully)** | 328662734008745984.png | 0 | 1 | null | null | null | null | null | ||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:31:38 | (in a mcclaurin series) | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:32:38 | i can’t take derivative 2022 times | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 711,226,895,483,535,400 | INACTIVE | 04/12/2022 00:33:42 | Doesn’t it just mean (f(0))^2022? | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:34:05 | wut | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:37:53 | no | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:38:18 | and you aren't supposed to, find the mcclaurin series (pretty simple, its just a geometric series, but you have to multiply it by x^2), and then solve for the n such that the power = 2022 | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:38:23 | and then find the coefficient after doing that | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:38:58 | could u write this out for me? im afraid i dno what you’re talking about | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:40:29 | $\sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!}x^n$ | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 510,789,298,321,096,700 | TeXit | 04/12/2022 00:40:32 | **! Brontochad (RYC4blushysully)** | 328662734008745984.png | 0 | 1 | null | null | null | null | null | ||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:40:34 | it will look something like this | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:40:41 | right | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:40:41 | and what you are trying todo | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:40:46 | i understand that part | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:40:51 | is solve for the n such that the power of x = 2022 | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:40:58 | then you can just take the coefficeint and multiply it by 2022! | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:40:58 | but how do i actually find the value of the numerator | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:41:06 | no n is 2022 | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:41:08 | you find the mcclaurin series | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:41:17 | well first find the mcclaurin series | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:41:18 | then come back | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:41:43 | this is the mac series no? | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:42:13 | not for your function | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:42:16 | that's just the general form | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:42:16 | the stuff in front of x^n | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:42:30 | do you know how to find a mac series | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:43:07 | no because i dno how to differentiate f(x) 2000 times | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:43:23 | if n was 2 or 3 yeah | 1 | 0 | 711,226,895,483,535,400 | INACTIVE | 9772 | INACTIVE | false | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:43:36 | okay well then you should read up / review notes on how to find a general mcclaurin series | 0 | 1 | 852,592,874,754,932,700 | CoffeePls | 8979 | CoffeePls | false | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:43:43 | (or how to use a geometric series in this case) | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:43:49 | here ill write it like this | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:43:55 | $x^2 \cdot \frac{1}{1-x^2}$ | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 510,789,298,321,096,700 | TeXit | 04/12/2022 00:43:57 | **! Brontochad (RYC4blushysully)** | 328662734008745984.png | 0 | 1 | null | null | null | null | null | ||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:11 | do you recognize that the second term has a very simple series expansion? | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:19 | (hint: geometric series) | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:44:25 | oh yeah | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:29 | so we get this | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:44:36 | i forgot the exact form tho | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:38 | $x^2 \cdot \sum_{n=0}^{\infty} x^{2n}$ | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 510,789,298,321,096,700 | TeXit | 04/12/2022 00:44:41 | **! Brontochad (RYC4blushysully)** | 328662734008745984.png | 0 | 1 | null | null | null | null | null | ||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:46 | geometric series is something you should know cold | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:51 | so keep that in mind | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:57 | anyways we can simplify this b/c x^2 is a constant in the n world | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:44:59 | so we get : | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:45:06 | $\sum_{n=1}^{\infty} x^{2n+2}$ | 0 | 1 | 510,789,298,321,096,700 | TeXit | 0796 | TeXit | true | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 510,789,298,321,096,700 | TeXit | 04/12/2022 00:45:09 | **! Brontochad (RYC4blushysully)** | 328662734008745984.png | 0 | 1 | null | null | null | null | null | ||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:45:16 | so now here is where i was saying solve for when the power of x = 2022 | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:45:26 | so we get: 2n+2 = 2022 => n+1 = 1011 => n = 1010 | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:45:32 | right does this make sense? | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:47:35 | yes | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:48:02 | okay so now we need to compare this to our form from before | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:48:07 | this | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:48:22 | but in this case it turns out that the massive coefficient is just 1! | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:48:27 | well im still lost on why u didn’t just substitute 2022 into n | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:48:45 | $\sum_{n=1}^{\infty} 1\cdot x^{2n+2} = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!}x^n$ | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 510,789,298,321,096,700 | TeXit | 04/12/2022 00:48:47 | **! Brontochad (RYC4blushysully)** | 328662734008745984.png | 0 | 1 | null | null | null | null | null | ||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:49:00 | cuz then the power of x (the thing we care about) wouldn't equal 0 | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:49:09 | anyways in this case it doesn't matter what n is because the coefficients are always 1 | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:49:23 | so now you just have to note that the coefficient of x^(2022) = f^(2022)(0)/2022! | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:49:29 | and then from there you can solve what f^(2022)(0) is | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:49:55 | ok I’m gonna go pray they donkt ask this tmrw | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:50:09 | well where are you confused | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:50:18 | because this is something that is ALWAYS on a midterm | 0 | 1 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:51:07 | well i have my final tmrw morning | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:51:44 | ok yeah no | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:55:05 | @Geopchad alright well i donkt understand this but thank you | 1 | 0 | null | null | null | null | null | |||||
1,833 | help-10 | 9a2a75d390c74965ae803af61bf34d85 | 852,592,874,754,932,700 | CoffeePls | 04/12/2022 00:55:08 | .close | 1 | 0 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 488,442,431,352,733,700 | almand | 04/12/2022 00:56:43 | (a-2)^2 = 12 | 1 | 0 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 488,442,431,352,733,700 | almand | 04/12/2022 00:57:10 | hi im having issues on solving perfect square equations | 1 | 0 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:57:24 | what is confusing ? | 0 | 1 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 488,442,431,352,733,700 | almand | 04/12/2022 00:57:36 | just solving the problem, im not sure where to start or what to do | 1 | 0 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 328,662,734,008,746,000 | Geopchad | 04/12/2022 00:57:44 | take square root of both sides | 0 | 1 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 488,442,431,352,733,700 | almand | 04/12/2022 00:58:41 | square root of both sides? | 1 | 0 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 488,442,431,352,733,700 | almand | 04/12/2022 00:59:20 | like square root of (a-2)^2/12 ? | 1 | 0 | null | null | null | null | null | |||||
1,834 | help-10 | 73534d40d792494f8be6b4a36d2b7787 | 488,442,431,352,733,700 | almand | 04/12/2022 01:03:34 | .close | 1 | 0 | 510,789,298,321,096,700 | TeXit | 0796 | TeXit | true | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 456,226,577,798,135,800 | Deleted User | 11/12/2021 16:08:15 | can i please understand how to find a counter example to a^3 = b^3 => a = b in complex numbers? | 1 | 0 | null | null | null | null | null | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 456,226,577,798,135,800 | Deleted User | 11/12/2021 16:08:49 | if you can provide an example and explain how did you come to it (through experience, deduction, ...?) | 1 | 0 | null | null | null | null | null | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 351,449,458,136,842,240 | Kiretori | 11/12/2021 16:16:53 | Well | 0 | 1 | null | null | null | null | null | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 351,449,458,136,842,240 | Kiretori | 11/12/2021 16:17:00 | 1 has 3 cubic roots | 0 | 1 | null | null | null | null | null | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 351,449,458,136,842,240 | Kiretori | 11/12/2021 16:17:09 | They're all different from each other | 0 | 1 | 852,592,874,754,932,700 | CoffeePls | 8979 | CoffeePls | false | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 351,449,458,136,842,240 | Kiretori | 11/12/2021 16:17:43 | But when you add the third power to them they become equal to 1 | 0 | 1 | null | null | null | null | null | |||||
1,835 | help-10 | 1bab00acaf8c4f69821f6cc76dc6d5c3 | 351,449,458,136,842,240 | Kiretori | 11/12/2021 16:17:48 | So that's a counter example | 0 | 1 | null | null | null | null | null |
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