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1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:27:11 | 0a = 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:29:15 | But in the example I posted, there are two solutions, x = -6 and x = 0 . In the branch that determines x=-6, it looks like they just drop that first x? Or is "or" part of the statement itself? | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:29:58 | If you say x=0, then you shouldn't be able to do further evaluation of the x+6 inside the x(x+6)? | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 220,517,274,845,577,200 | ramonov | 04/15/2022 23:30:01 | x=0
or
x=-6 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 220,517,274,845,577,200 | ramonov | 04/15/2022 23:30:26 | if x is 0,
x(x+6) will be 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 220,517,274,845,577,200 | ramonov | 04/15/2022 23:30:35 | if x=-6
x(x+6) will also be 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:31:00 | f(x) = x(x+6)
f(0) = 0(6) = 0
f(-6) = -6(0) = 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:32:26 | Only one of the factors is 0 at a time. When we use the zero product property we are implicitly making the assumption that one of the factors is not zero and then solving for x | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:33:05 | Because obviously we can't divide by 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:35:45 | Hmm I'm not sure if I'm fully satisfied with these answers. Thanks though. I'll work more of these examples | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:35:58 | Ok look at it this way. | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:36:19 | We have that:
x(x+6) = 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:36:29 | Now assume that (x+6) is not 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:36:39 | So divide both sides by (x+6) | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:36:45 | Then we get that x=0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:37:08 | Okay, that I understand | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:37:16 | And same thing for the other solution | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:37:48 | x(x+6) = 0
Assume that x is not 0
So divide both sides by x
x+6 = 0
x = -6 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:38:57 | Okay, that understand | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:39:08 | Thanks! | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 220,517,274,845,577,200 | ramonov | 04/15/2022 23:39:21 | 0 * stuff = 0
0 * x = 0
0 * (x+6) = 0 | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:40:28 | From a logical standpoint it does rely on casework and making these assumptions | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:41:43 | When I gave this problem to symolab it just whipped out the quadratic formula | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 551,269,104,800,104,450 | EndTimes | 04/15/2022 23:42:13 | Try WolframAlpha instead, it's a bit smarter | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:46:25 | What other webapps do you guys recommend besides Symbolab and WolframAlpha for checking answers? | 1 | 0 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 220,517,274,845,577,200 | ramonov | 04/15/2022 23:47:47 | none | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 220,517,274,845,577,200 | ramonov | 04/15/2022 23:48:15 | well i suppose desmos and geogebra for graphs | 0 | 1 | null | null | null | null | null | |||||
1,911 | help-10 | b13d7e50b4a644e9929fea2ce1d6d505 | 952,268,248,248,897,700 | Noneuclidian | 04/15/2022 23:58:36 | Thanks | 1 | 0 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 703,317,182,683,021,400 | duckecheese | 04/16/2022 01:28:45 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 703,317,182,683,021,400 | duckecheese | 04/16/2022 01:29:06 | can someone tell me the first step in solving this | 1 | 0 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 118,536,946,527,109,120 | Migillope | 04/16/2022 01:29:22 | close your other channel | 0 | 1 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 118,536,946,527,109,120 | Migillope | 04/16/2022 01:29:34 | #help-7 | 0 | 1 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 703,317,182,683,021,400 | duckecheese | 04/16/2022 01:29:44 | how do i close | 1 | 0 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 703,317,182,683,021,400 | duckecheese | 04/16/2022 01:37:23 | i fgiured it out | 1 | 0 | null | null | null | null | null | |||||
1,912 | help-10 | f731114cad4a4fe4a0601742a83ad6d4 | 703,317,182,683,021,400 | duckecheese | 04/16/2022 01:37:24 | .close | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:15:41 | Hello I am stuck on this question, I do not know how to proceed. | Screenshot_697.png | 1 | 0 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:15:49 | This is all I could do. | IMG_2665.JPG | 1 | 0 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:16:01 | Oh no it's tilted. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:17:23 | There we go. | IMG_2665.jpg | 1 | 0 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:23:25 | **kiid** | 292286971970191360.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:23:36 | none of solutions to choose from are in good form | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:23:43 | ln(e) = 1 but they didn't factor that | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:23:55 | Wait what. | 1 | 0 | 551,269,104,800,104,450 | EndTimes | 8053 | EndTimes | false | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:23:56 | Oh. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 292,286,971,970,191,360 | kiid | 11/13/2021 01:24:03 | ? one of them is correct | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:24:20 | oh yeah i see im blind | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:24:20 | lne just becomes 1 right? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:24:38 | Because log(e)e = 1. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 292,286,971,970,191,360 | kiid | 11/13/2021 01:25:08 | use $\log_a b^c = c \log_a b$ and $a^{\log_a k}=k$ to simplify $e^{x\ln a}$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:25:11 | **kiid** | 292286971970191360.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:25:38 | 20211113_002520.jpg | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 292,286,971,970,191,360 | kiid | 11/13/2021 01:26:14 | why did you do it for them 😦 | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:26:23 | e^ln(ax) = a^x? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:26:24 | to explain it in concrete numbers | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:26:35 | no | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:27:19 | $$e^{a \cdot ln{x}} = e^{ln{(x^a)}}$$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:27:36 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:27:49 | If there is a log anywhere in the equation I can bring the exponent to the front? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:30:39 | it goes both ways with this formula, idk what you mean by "anywhere" | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:30:45 | the entire quantity is to said power | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:31:11 | Oh uhh. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:31:32 | $$e^{3 \cdot ln{(3x^2+7x)}} = e^{ln{((3x^2+7x)^3)}} = (3x^2+7x)^3$$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:31:58 | Those are equivalent? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:32:00 | yes | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:32:09 | I thought the 3 wouldn't affect the numbers inside like the cube does. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:32:45 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:32:49 | all 3 of those are equal | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:33:07 | Wait so the e or the ln is irrelevant here? | 1 | 0 | 205,143,587,749,494,800 | MattDog_222 | 1131 | MattDog_222 | false | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 567,490,557,572,546,600 | boneslayer_suvy | 11/13/2021 01:33:20 | Basically | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:33:26 | Because the second and third one are basically the same except the third doesn't have ln or e. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:33:40 | because they cancel each other out since they share the natural base | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:34:10 | OH because ln = loge, and it's basically the same as log base e (e)? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:38:22 | $$ ln \neq log(e) $$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:38:24 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:38:43 | $$ln(x) = log_e(x)$$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:38:46 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:40:01 | This is 1 right? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:40:16 | Wait nvm. | 1 | 0 | 769,113,579,403,608,000 | カナン | 7512 | カナン | false | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:40:45 | Due to this the majority of the first bit is taken away, leaving us with a^x? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:41:13 | wdym | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:41:31 | In here. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:41:51 | $$e^{x \cdot ln(a)} = e^{ln(a^x)}$$ | 0 | 1 | 510,789,298,321,096,700 | TeXit | 0796 | TeXit | true | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:41:54 | You went from e^xlna to e^ln(a^x) so I assumed that you brought ln to the front. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:42:05 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:42:28 | this is a logarithm law | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:42:36 | Oh. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:42:41 | well | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:42:42 | So it can never be x^a? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:42:51 | $$x \cdot ln(a) = ln(a^x)$$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:42:53 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | null | null | null | null | null | ||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:42:56 | is the law | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:43:00 | it just occures inside the exponent | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:43:15 | Oh. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:43:30 | and we need to do that so we can cancel the e and the ln | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:43:32 | So we take the last number and raise it to the power of first number? | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:43:44 | huh? | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 769,113,579,403,608,000 | カナン | 11/13/2021 01:43:56 | Like we take a, and raise it to x. | 1 | 0 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:44:18 | yes because its being multiplied on the outside, so its the same as raising to the power on the inside | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 205,143,587,749,494,800 | MattDog_222 | 11/13/2021 01:44:41 | $$z \cdot ln(x+y) = ln((x+y)^z)$$ | 0 | 1 | null | null | null | null | null | |||||
1,913 | help-10 | 0196cb93ba3241ae932338f6b936ef66 | 510,789,298,321,096,700 | TeXit | 11/13/2021 01:44:44 | **MattDog\_222** | 205143587749494784.png | 0 | 1 | 510,789,298,321,096,700 | TeXit | 0796 | TeXit | true |
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