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1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:26:24 | oh great | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:26:25 | you could have given other answers | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:26:27 | but ok | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:26:31 | {t-2, t^2-4} | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:26:37 | this set is linearly independent, as should be clear. | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:27:04 | can you now explain why every polynomial in H can be expressed as a linear combination of these two? | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:29:10 | since they are linearly independent, so everything else would be a linear combination of the two, and hence in the span of the two | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:29:47 | no | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:29:58 | 'linear independence' and 'spanning' are different notions that should not be conflated. | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:30:46 | oh why? | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:33:13 | wym why | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:33:35 | just because a set is linearly independent does not automatically mean it spans the space it's in | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:34:05 | okay but when it is linearly independent and has the same no. of vectors as the dimension of the space | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:34:14 | then it spans it, right? | 1 | 0 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:34:14 | {x} is a linearly independent subset of P_5 yet you would not claim every polynomial in P_5 is a linear combination of {x} would you? | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:34:44 | yes | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:34:52 | but it appears you're expected not to use that | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:35:11 | and instead show directly that every polynomial in H is a linear combination of your basis (in our case {t-2, t^2-4}) | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:37:09 | oh okay okay so like this? | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:38:25 | $$ a + bt + ct^2 = d (t-2) + k (t^2 - 4) $$ | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:39:02 | :badtex: | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 510,789,298,321,096,700 | TeXit | 04/17/2022 03:39:29 | **ibzi** | 380989650615140362.png | 0 | 1 | null | null | null | null | null | ||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:39:42 | ~~and now bad notation + apparent eagerness to plunge headfirst into equation-bashing~~ | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:39:57 | i mean ok like. sure i guess | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:40:13 | you could show that if a + 2b + 4c = 0 then there exist d and k such that what you wrote is true | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:40:20 | if you want to do it like that, who am i to stop you | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:40:57 | okay then what's the other way | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:41:00 | the one you were asking | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:42:01 | i would say that any polynomial in H can be written as (at+b)(t-2) | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:42:22 | and that in turn can be written as [a(t+2) + (b-2a)](t-2) = a(t+2)(t-2) + (b-2a)(t-2) | 0 | 1 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:42:29 | which is a linear combination of your basis | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:43:12 | oh okay okay | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:43:26 | and also how is it bad notation | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:43:44 | i personally don't like it, that's how :kekw: | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:43:53 | in this particular case i was not being very objective about it | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:44:06 | oh lmao okay | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:44:31 | altho out of curiosity, what did u not prefer? | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:45:07 | the d and k do not strike me as good name choices for two constants that should appear related | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:45:45 | oh i just used them because i couldn't figure out how to add subscripts | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:46:00 | because it italicised my text instead | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:46:10 | underscores work just fine | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 03:46:15 | @ibzi For the record, my earlier question about factoring was leading to this.
Every polynomial such that P(2)=0 is divisible by X-2, so every polynomial in H is of the form (X-2)Q with Q some polynomial. Since we are restricted to degree 2 or less, Q must be of degree at most 1.
Since a basis for such polynomials is {... | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:46:23 | despite discord treating them as italics, the tex bot does them just fine | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 183,668,144,404,037,630 | Ann | 04/17/2022 03:46:39 | $c_0 + c_1t + c_2t^2$ | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 510,789,298,321,096,700 | TeXit | 04/17/2022 03:46:41 | **Ann** | 183668144404037632.png | 0 | 1 | null | null | null | null | null | ||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 03:46:42 | But it was good to yake your time with it | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:47:17 | $c_(0) + c_(1)t + c_(2)t^2$ | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 03:47:17 | As my teacher says, "the correct method will be whichever one you wind up using" | 0 | 1 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:47:25 | oh it works without brackets | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:47:41 | oh okay okay | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:48:14 | alright, thanks a lot! | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:48:21 | and sorry for taking up so much of ur time | 1 | 0 | null | null | null | null | null | |||||
1,923 | help-10 | 64bb8913e7b14d06aa9900fca1da50dc | 380,989,650,615,140,350 | ibzi | 04/17/2022 03:48:41 | .close | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 02:26:02 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 02:26:15 | can't figure out how to get to 5 as the answer here | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 02:49:47 | @Helpers | 1 | 0 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 02:59:32 | Yeah I just don't get this | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 02:59:41 | I can think of more than 5 specific strings that match those requirements | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 03:01:23 | 1000000111111111
1100000011111111
1110000001111111
1111000000111111
1111100000011111
1111110000001111
1111111000000111
1111111100000011
1111111110000001 | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 714,483,444,394,229,900 | Frosty_ | 11/13/2021 03:03:45 | 9 sounds like the right answer i think | 0 | 1 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 03:03:57 | god I hate my prof lol | 1 | 0 | null | null | null | null | null | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 03:04:08 | thanks for validating | 1 | 0 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false | |||||
1,924 | help-10 | 970b0c072188488c8d52e658c9488421 | 290,723,508,563,214,340 | Poop | 11/13/2021 03:04:10 | .close | 1 | 0 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:08:23 | How? | IMG_0733.jpg | 1 | 0 | null | null | null | null | null | ||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:09:00 | How it forces it to be one-one? | 1 | 0 | 380,989,650,615,140,350 | ibzi | 9426 | ibzi | false | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 183,668,144,404,037,630 | Ann | 04/17/2022 04:09:35 | isn't that exactly what is explained in the next lines | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:09:55 | The fact that it is injective is explained right after | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:10:26 | Surjectivity isn't too hard to see, because for instance f(f(n)+f(0))=n so every natural number is reached | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:11:03 | Yo lol my math’s weak i dont get it | 1 | 0 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:11:39 | How do you see it? | 1 | 0 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 183,668,144,404,037,630 | Ann | 04/17/2022 04:20:27 | have you read the lines immediately after the "In fact, we see that"? | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:20:41 | Yes | 1 | 0 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:20:47 | I got it | 1 | 0 | 193,692,307,453,771,780 | Syst3ms | 9959 | Syst3ms | false | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:20:50 | Thanks | 1 | 0 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:21:58 | The definition of surjectivity is that for any number n, you can find an input k such that f(k)=n | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:22:04 | i.e every output is reached | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:22:12 | In this case, we have f(f(n)+f(0)) = n | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:22:27 | So for any output, we can find a corresponding input, namely f(n)+f(0) | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 193,692,307,453,771,780 | Syst3ms | 04/17/2022 04:22:35 | By definition, it is surjective | 0 | 1 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:23:22 | But in here k is independent of n right? | 1 | 0 | null | null | null | null | null | |||||
1,925 | help-10 | 720b617d6d7b48c2af76d73947bb18d3 | 943,069,425,274,339,300 | PuddinAru | 04/17/2022 04:35:17 | .close | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 04:39:48 | Hi, can anyone help me? I don't know how to start 😄 | unknown.png | 1 | 0 | null | null | null | null | null | ||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 396,015,145,131,835,400 | Limitless222 | 04/17/2022 04:59:03 | Without working it out myself, I would start with working out the probability of getting two 6's in a row in 2 rolls. Then getting two 6's in a row on the third roll without getting it on the 2nd roll. I'd then either expect to see some telescoping sum or to realise that I have to work out the probability of not gettin... | 0 | 1 | 290,723,508,563,214,340 | Poop | 8573 | Poop | false | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:05:11 | Let's say I have 3 throws, then there are two possible solutions, 6X6 and XX6. What are the chances of me throwing one of them?
(1/6)*(5/6)*(1/6) + (5/6)*(5/6)*(1/6) = 5/36 | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:08:09 | that's good? | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:13:23 | Or I have to do all the possible combinations | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 396,015,145,131,835,400 | Limitless222 | 04/17/2022 05:14:02 | If X is a result that is not 6, your calculations are correct. Don't you want to find when there are two 6s in a row?
So for two rolls, you're looking for exactly (6,6), which is (1/6)(1/6).
For 3 rolls, we have (X,6,6) which is (5/6)(1/6)(1/6).
For 4 rolls, (6/6)(5/6)(1/6)(1/6). | 0 | 1 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:18:54 | I have to calculate the probability of "ai" first.
(does not fall twice 6 in a row and six fall in the last roll)
Then the probability of "bi."
(does not fall twice 6 in a row and six not fall in last roll)
So then I can calculate it now as described. | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:21:52 | Then I have to find the generating function for a (x) and b (x) with a system of recurrent relationships | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 396,015,145,131,835,400 | Limitless222 | 04/17/2022 05:29:33 | Your calculations look correct for ai for 3 rolls. | 0 | 1 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:45:17 | Thanks for the help 🙂 | 1 | 0 | null | null | null | null | null | |||||
1,926 | help-10 | 87550ce8850841c3a686685d33d14546 | 406,811,109,522,407,400 | Dávid | 04/17/2022 05:46:17 | .close | 1 | 0 | null | null | null | null | null | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 451,866,498,357,526,500 | HimboKisser | 04/17/2022 07:00:42 | What do you do when two directional vectors aren't parallel and they intersect, how do you calculate that? | 1 | 0 | 193,692,307,453,771,780 | Syst3ms | 9959 | Syst3ms | false | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 396,015,145,131,835,400 | Limitless222 | 04/17/2022 07:02:29 | Break them up into components. | 0 | 1 | 943,069,425,274,339,300 | PuddinAru | 5894 | PuddinAru | false | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 451,866,498,357,526,500 | HimboKisser | 04/17/2022 07:03:11 | What do you mean? | 1 | 0 | null | null | null | null | null | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 825,402,355,168,051,200 | theguy | 04/17/2022 07:03:40 | Do u want to calculate the point where they interesect? | 0 | 1 | null | null | null | null | null | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 451,866,498,357,526,500 | HimboKisser | 04/17/2022 07:04:47 | I'm unsure, to be honest.
My teacher gave us this sort of map, what they are if they're parallel and if they're not. But we aren't at that point of just *what* to do if they intersect. | 1 | 0 | null | null | null | null | null | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 667,385,854,687,182,800 | Kulsgam | 04/17/2022 07:04:57 | are you aware of vector equations? | 0 | 1 | 943,069,425,274,339,300 | PuddinAru | 5894 | PuddinAru | false | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 667,385,854,687,182,800 | Kulsgam | 04/17/2022 07:05:10 | if 2 vectors intersect you can equate the vector equations | 0 | 1 | null | null | null | null | null | |||||
1,927 | help-10 | ae4acc759aee453a8eab791110b6569d | 667,385,854,687,182,800 | Kulsgam | 04/17/2022 07:05:22 | and then find a common scalar product value | 0 | 1 | null | null | null | null | null |
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