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help-10
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gav
04/18/2022 00:23:02
I think f(2) is an inflection point
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gav
04/18/2022 00:23:28
I might be 100% wrong though, just laying out my thought process
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Herels
04/18/2022 00:32:05
f(2) = 0, look at the graph but im not sure about f'(2) f is decreasing so f'(2) should be negative
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help-10
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Herels
04/18/2022 00:33:30
But i dont know how to compare f'(2) and f''(2)
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elon mask
04/18/2022 01:40:04
The slope is going from a more negative number to a less negative number So f’’(2) is actually positive
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Gwaine
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kryptek
04/18/2022 03:06:09
hello
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Syst3ms
04/18/2022 03:07:32
:JustAsk:
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kryptek
04/18/2022 03:07:37
oh sorry
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kryptek
04/18/2022 03:07:41
im having trouble with this
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kryptek
04/18/2022 03:07:48
https://cdn.discordapp.c…5497/unknown.png
unknown.png
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0
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kryptek
04/18/2022 03:08:30
I solved the first 2 but this one is different and I have no clue how to do it
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help-10
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Syst3ms
04/18/2022 03:08:32
What are the quantities denoting? Lengths? If so, of what?
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help-10
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kryptek
04/18/2022 03:10:01
imma be honest its for a test and idk how to so it just trying not to fail you dont have to help tho if u dont want to waste time
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help-10
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Syst3ms
04/18/2022 03:10:30
Wait, homework or...?
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help-10
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kryptek
04/18/2022 03:10:40
no its a test
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help-10
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Syst3ms
04/18/2022 03:14:12
> • Cheating on tests and exams, as well as other forms of academic dishonesty, will result in an immediate ban. from #❓how-to-get-help
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help-10
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kryptek
04/18/2022 03:14:20
oh
1
0
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help-10
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Syst3ms
04/18/2022 03:14:23
I'd advise you to close this
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help-10
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kryptek
04/18/2022 03:14:31
i didnt see
1
0
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help-10
1faedf9c12164bc7b1c1b7791572a041
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kryptek
04/18/2022 03:14:36
i was joking its homework
1
0
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help-10
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Syst3ms
04/18/2022 03:17:43
i have a hard time trusting you on this
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help-10
1faedf9c12164bc7b1c1b7791572a041
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kryptek
04/18/2022 03:17:54
i was joking
1
0
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help-10
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kryptek
04/18/2022 03:18:12
its calm its calm trust
1
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help-10
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Syst3ms
04/18/2022 03:18:20
Hmmm, sure
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help-10
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Syst3ms
04/18/2022 03:18:32
i'll leave it up to someone else though
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help-10
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kryptek
04/18/2022 03:19:00
what if i cashapp you
1
0
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help-10
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Syst3ms
04/18/2022 03:23:19
don't make me call mods
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help-10
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kryptek
04/18/2022 03:23:23
: (
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help-10
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riemann
04/18/2022 03:33:20
Don't cheat. Kthxbai
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riemann
04/18/2022 03:33:22
.close
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kenZo
04/18/2022 05:50:50
https://cdn.discordapp.c…2616/unknown.png
unknown.png
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help-10
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kenZo
04/18/2022 05:50:58
What does the unlined statement mean?
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help-10
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kenZo
04/18/2022 05:51:26
I've always thought dividing in trig equations was a no go because you lose solutions
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help-10
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Syst3ms
04/18/2022 05:52:17
Well, perhaps cosθ+sinθ ≠ 0 does get rid of solutions, but you can check those later
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help-10
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Syst3ms
04/18/2022 05:52:28
Right now, you can exclude that and find the other solutions
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help-10
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kenZo
04/18/2022 05:52:52
well does it get rid of solutions?
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help-10
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kenZo
04/18/2022 05:52:55
or do you not know
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Syst3ms
04/18/2022 05:52:59
Who knows
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help-10
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Syst3ms
04/18/2022 05:53:14
Dividing and making hypotheses can and often does lose solutions, but it's not a big deal as long as you go back and check if you missed anything by making these hypotheses
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help-10
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kenZo
04/18/2022 05:53:29
how would you check?
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help-10
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kenZo
04/18/2022 05:53:46
besides graphing
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help-10
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Syst3ms
04/18/2022 05:55:20
$\cos\theta+\sin\theta = 0$ means $\cos\theta = -\sin\theta = cos(\frac\pi{2}+\theta)$, which is a nice formula to have in mind
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help-10
11c3026612db45fb9dd8b3a49255099c
510,789,298,321,096,700
TeXit
04/18/2022 05:55:22
**Syst3ms**
https://cdn.discordapp.c…307453771776.png
193692307453771776.png
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help-10
11c3026612db45fb9dd8b3a49255099c
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Syst3ms
04/18/2022 05:56:44
The equality of cosines means either $\theta = \theta+\frac\pi{2} [2\pi]$ or $\theta = -\theta-\frac{\pi}2 [2\pi]$
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TeXit
04/18/2022 05:56:47
**Syst3ms**
https://cdn.discordapp.c…307453771776.png
193692307453771776.png
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help-10
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Syst3ms
04/18/2022 05:56:55
The first equation has no solutions
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help-10
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Syst3ms
04/18/2022 05:57:36
The second one means 2t = -π/2 [2π] ie t = -π/4 [π] (notice the modulus change)
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help-10
11c3026612db45fb9dd8b3a49255099c
193,692,307,453,771,780
Syst3ms
04/18/2022 05:57:50
Hence t = 3π/4 or t = -π/4
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help-10
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Syst3ms
04/18/2022 05:58:15
You just have to check if those are solutions that you didn't account for yet
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help-10
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kenZo
04/18/2022 06:01:20
ok
1
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help-10
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kenZo
04/18/2022 06:01:57
I think i see what you are talking about now
1
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help-10
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kenZo
04/18/2022 06:02:48
thanks
1
0
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help-10
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kenZo
04/18/2022 06:02:51
.close
1
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kryptek
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help-10
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Asmit
04/18/2022 06:04:40
hey
1
0
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Asmit
04/18/2022 06:05:25
https://cdn.discordapp.c…20418_153500.jpg
20220418_153500.jpg
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0
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
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Asmit
04/18/2022 06:05:25
am i going right
1
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help-10
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Asmit
04/18/2022 06:08:18
i think i messed up in dividing
1
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
310,130,706,518,900,740
Murat
04/18/2022 06:08:20
Where did 4+sqrt12+sqrt 8 come from
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
901,453,463,437,840,500
Asmit
04/18/2022 06:08:32
thats where i got stuck
1
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
310,130,706,518,900,740
Murat
04/18/2022 06:09:03
That is not the same as first x
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
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Murat
04/18/2022 06:09:08
X+4
0
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help-10
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Asmit
04/18/2022 06:09:25
whats the next step after 2√3 -2√2 / 4
1
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
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Murat
04/18/2022 06:11:48
you can write it as 2√3/4 - 2√2 / 4
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
310,130,706,518,900,740
Murat
04/18/2022 06:13:14
cancel 2s so you get √3/2 - √2/2
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
901,453,463,437,840,500
Asmit
04/18/2022 06:15:06
oh yes
1
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
901,453,463,437,840,500
Asmit
04/18/2022 06:17:57
so is it perhaps the value of 1/x
1
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help-10
0a9ba39d3ed94947aa2962a2f8ca4119
310,130,706,518,900,740
Murat
04/18/2022 06:18:34
yea
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0a9ba39d3ed94947aa2962a2f8ca4119
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Asmit
04/18/2022 06:19:52
(Thank you)²
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0a9ba39d3ed94947aa2962a2f8ca4119
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Asmit
04/18/2022 06:19:57
.close
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e17d8dcfa723446f8beffb09950818e8
456,226,577,798,135,800
Deleted User
04/18/2022 08:12:15
Okay, so i have a task to do with basic maths and im paying 10€ if someone can solve it. If you know Coding (Javascript) it will be perfect. https://i.xpyth.dev/paclOR9l.png Default rate: a: 10 b: 60 c: 40 (ME) If i put custom rate (Line 89) a: ? (something like 8% ??) b: ?? (something like 50% ??) c: **60** (ME) If...
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help-10
e17d8dcfa723446f8beffb09950818e8
456,226,577,798,135,800
Deleted User
04/18/2022 08:12:57
**10€ On the line rn, willing to pay a lil bit more if someone can even bring the code with it**
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help-10
e17d8dcfa723446f8beffb09950818e8
456,226,577,798,135,800
Deleted User
04/18/2022 08:14:20
(This is not homework assignment btw)
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help-10
e17d8dcfa723446f8beffb09950818e8
485,903,210,272,391,200
dldh06
04/18/2022 08:14:33
Please read #❓how-to-get-help and #rules
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help-10
e17d8dcfa723446f8beffb09950818e8
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Deleted User
04/18/2022 08:14:54
I don't think im violating the rules considering thoses are not homework assignment, am i wrong ? @dldh06 :/
1
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help-10
e17d8dcfa723446f8beffb09950818e8
485,903,210,272,391,200
dldh06
04/18/2022 08:15:16
Bullet 5 in rules
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help-10
e17d8dcfa723446f8beffb09950818e8
456,226,577,798,135,800
Deleted User
04/18/2022 08:15:44
Oh, do you know where this type of request could be placed ?
1
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help-10
e17d8dcfa723446f8beffb09950818e8
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dldh06
04/18/2022 08:16:12
I'm not sure sorry but definitely not this server
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help-10
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Deleted User
04/18/2022 08:16:30
I see, thanks anyway i guess :/
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Deleted User
04/18/2022 08:16:37
.close
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J64n
04/18/2022 09:22:45
Need help with b
https://cdn.discordapp.c…8864/unknown.png
unknown.png
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04b6054815d44c479bb525413ef49503
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Element118
04/18/2022 09:25:15
hmm what are the two equations you found?
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J64n
04/18/2022 09:25:25
https://cdn.discordapp.c…A5B78CC9DD1E.jpg
49279D59-59F5-4644-8B4A-A5B78CC9DD1E.jpg
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J64n
04/18/2022 09:25:34
a) `x = r - 4`
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Element118
04/18/2022 09:25:52
and?
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J64n
04/18/2022 09:25:59
its to do with the triangle in the circle
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J64n
04/18/2022 09:26:06
what were you asking for sorry?
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Element118
04/18/2022 09:26:12
you have two equations right?
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J64n
04/18/2022 09:26:58
one was the answer for a, which was what one side of the triangle was and the other one i was tryna use pythagorus to find the hypotenuse (radius)
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Element118
04/18/2022 09:29:30
Yeah, did you manage to use the Pythagorean theorem?
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help-10
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J64n
04/18/2022 09:29:56
yeah but i got stuck at ``c^2 = 7^2 + (r-4)^2`` `c^2 = 47 + (r-4)^2`
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help-10
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J64n
04/18/2022 09:33:21
so is this correct `c^2 = 7^2 + (r-4)^2` `c^2 = 49 + (r-4)^2` `c^2 = 49 + x^2 - 8x + 16` `c^2 = 65 + x^2 - 8x` `c = sqrt(65 + x^2 - 8x)` `therefor r = sqrt(65 + x^2 - 8x)`
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Element118
04/18/2022 09:33:54
can you express c in terms of x and r?
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Element118
04/18/2022 09:34:34
ouch 7^2 is 49
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J64n
04/18/2022 09:44:09
https://cdn.discordapp.c…B6E4EBE771A7.jpg
B9D29976-C9D8-40C0-9C5B-B6E4EBE771A7.jpg
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J64n
04/18/2022 09:44:20
c^2 = a^2 + b^2 c is the hypotenuse but also equivilent to the radius so c, r and (if sub x for c in the eq), c are all equal so ill just use r for the term to describe em all
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J64n
04/18/2022 09:44:40
so in the end r = sqrt(67 + r^2 - 8r)
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help-10
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Element118
04/18/2022 09:45:25
it's not very useful to have r stuck inside and outside
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Deleted User
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Element118
04/18/2022 09:45:36
we want all the variables r to be put on one side
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Element118
04/18/2022 09:46:04
$c^2 = 7^2 + (r-4)^2$ is okay, which can substitute to get $r^2 = 7^2 + (r-4)^2$
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TeXit
04/18/2022 09:46:07
**Element118**
https://cdn.discordapp.c…409991626752.png
104219409991626752.png
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