conversation_id int64 1 206k | help_channel stringlengths 6 7 | __rowid__ stringlengths 32 32 | author_id int64 62,061,868B 1,071,443,446B | author_name stringlengths 2 32 | timestamp stringlengths 19 19 | content stringlengths 0 3.97k | reference.messageId stringclasses 3
values | reference.channelId stringclasses 3
values | reference.guildId stringclasses 1
value | url stringlengths 0 591 | fileName stringlengths 0 513 | student int64 0 1 | helper int64 0 1 | references.id float64 62,061,868B 1,071,056,124B ⌀ | references.name stringlengths 2 32 ⌀ | references.discriminator stringlengths 4 4 ⌀ | references.nickname stringlengths 1 32 ⌀ | references.isBot bool 2
classes |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 872,024,354,572,103,700 | <><><> | 01/19/2022 03:05:05 | Try to find inverse function for f(x) | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 872,024,354,572,103,700 | <><><> | 01/19/2022 03:06:02 | look | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 872,024,354,572,103,700 | <><><> | 01/19/2022 03:07:59 | let $y = -\sqrt{1+\sqrt{1+x}}$ we want to solve for $x$. $y^2 = 1+\sqrt{1+x} \iff y^2-1=\sqrt{1+x} \iff 1+x = (y^2-1)^2 \iff x = y^4-2y^2 \iff f^{-1}(x) = x^4-2x^2$ | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 510,789,298,321,096,700 | TeXit | 01/19/2022 03:08:13 | **azeem321** | 872024354572103731.png | 0 | 1 | null | null | null | null | null | ||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 872,024,354,572,103,700 | <><><> | 01/19/2022 03:10:03 | sorry, i need to start reading questions | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 872,024,354,572,103,700 | <><><> | 01/19/2022 03:10:17 | I thought the graph in sketch was f(x) | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 872,024,354,572,103,700 | <><><> | 01/19/2022 03:12:13 | if a root doesn't exist, it's most likely because it's undefined when you put it under the radical | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:20:20 | This one is rather simple :o | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:20:36 | ^ right? | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:22:09 | Note that the graph for y = -root(1 + root(1+x)) is decreasing starts at x = -1, corresponding to y = -1 and continues decreasing forever
while y = x^4 - 2x^2 is always above y = -1 | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:22:19 | So only one intersection point, (-1, -1) | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:26:17 | As for this one, you just need to know that _Inverse of a function only exists if the function is 1-1 on-to in that interval_ :o | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:28:45 | So ask yourself... since it's a cubic equation, what is it's peculiar behaviour? where does the graph go as x tends to + ∞ and - ∞, look out for the turning points on the graph, and note that after turning, the graph doesn't remain 1-1, is why you need to separate the graph into 3 intervals according to the turning poi... | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 03:28:54 | one of them... might satisfy your options | 0 | 1 | null | null | null | null | null | |||||
205,506 | help-1 | fdbb99176760413ca3cd08e085ec6579 | 869,532,694,688,706,600 | EpsilonNought | 01/19/2022 04:02:07 | @Brightness u still there | 1 | 0 | null | null | null | null | null | |||||
205,507 | help-1 | 73a467e950a14624bbee23883baca47e | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:14:59 | IMG_20220119_101435.jpg | 1 | 0 | 321,445,119,171,756,000 | Shuri2060 | 9525 | a μ-er | false | |||||
205,507 | help-1 | 73a467e950a14624bbee23883baca47e | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:15:11 | Is exercise 1 solvable using the sum of integers formula | 1 | 0 | null | null | null | null | null | |||||
205,507 | help-1 | 73a467e950a14624bbee23883baca47e | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:15:27 | 1/2 * n (n+1) | 1 | 0 | null | null | null | null | null | |||||
205,507 | help-1 | 73a467e950a14624bbee23883baca47e | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:15:34 | Or do we have to do it manually | 1 | 0 | null | null | null | null | null | |||||
205,507 | help-1 | 73a467e950a14624bbee23883baca47e | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:18:02 | Yes you can use that here | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:46:33 | How sir | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:46:51 | I'm not sure how | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:47:06 | Just break up the sum | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:47:16 | Can you show me | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:47:33 | sum of 9 - 2i is the same as sum of 9 plus sum of -2i | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:49:06 | $\sum_{i = 1}^4(9 - 2i) = \sum_{i = 1}^4{9} - 2\sum_{i = 1}^4{i}$ | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 510,789,298,321,096,700 | TeXit | 01/19/2022 04:49:08 | **Beans** | 348696743388381195.png | 0 | 1 | 782,087,086,416,461,800 | LittleMouse | 2603 | LittleMouse | false | ||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:51:00 | Ok ty | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:51:07 | But that's additivity | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:51:25 | Not the sum of integers formula | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:51:27 | 1/2 * n (n+1) | 1 | 0 | 782,087,086,416,461,800 | LittleMouse | 2603 | LittleMouse | false | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:51:33 | We don't use that one so we | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:52:22 | Look at the $\sum_{i = 1}^4{i}$ | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 510,789,298,321,096,700 | TeXit | 01/19/2022 04:52:24 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:52:30 | Yeah ok | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:52:33 | If n was big | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:52:37 | You could use it | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:52:43 | Right? | 1 | 0 | 569,167,697,925,898,240 | Camilleone | 1596 | Camilleone | false | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:52:47 | That's all. | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:53:00 | You can use it for any number replaced with 4 there | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:53:13 | Of course | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:53:19 | Ty | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:53:47 | IMG_20220119_105330.jpg | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:53:47 | What about this | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:53:48 | Im stuck here | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:54:54 | @A Lonely Bean | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:55:44 | Is that $\sum_{i = 1}^n\sum_{j = 1}^m(2i + 3j)$ ? | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:55:58 | I think you can use additivity here too | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 510,789,298,321,096,700 | TeXit | 01/19/2022 04:56:06 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:56:15 | Yes | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:56:25 | But how to solve | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:56:31 | From the step im at | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 04:57:48 | Can't really see what's in the end there | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:59:38 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 04:59:39 | like this | 1 | 0 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 05:01:52 | Ye it's correct, the sum is 90, which is the same as 6(1 + 2 + 3) + 3*18 | 0 | 1 | null | null | null | null | null | |||||
205,508 | help-1 | a1e51649b5544272a7c43eaf23145680 | 456,226,577,798,135,800 | Deleted User | 01/19/2022 05:11:06 | Super ty | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:14:43 | 1 | 0 | null | null | null | null | null | ||||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:15:27 | Am I missing something here, when x = 1/n, xn^2=n which goes to infinity when the limit is taken | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:15:31 | so how does it converge pointwise? | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 484,702,191,156,985,860 | themateo713 | 12/21/2021 08:25:57 | wrong perspective. You look at f(x), so x stays fixed. As n goes to infinity, in what category does x fall ? | 0 | 1 | 569,167,697,925,898,240 | Camilleone | 1596 | Camilleone | false | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 684,674,576,998,858,800 | kloser | 12/21/2021 08:26:40 | (not helping) wait are you the same guy who posted a question about 3 cats + 4 cats? | 0 | 1 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:26:55 | :happy: | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:27:14 | so isn't just x 0 if n->infty | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:27:34 | 0<=x<=1/infty | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 484,702,191,156,985,860 | themateo713 | 12/21/2021 08:28:38 | if x = 0, f(x) = 0. Otherwise there is always a n big enough (like 2*floor(1/x + 1)) such that 2/n < x, and then f(x) = 0 | 0 | 1 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 484,702,191,156,985,860 | themateo713 | 12/21/2021 08:30:01 | see how to do the integral ? | 0 | 1 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:30:38 | is it related to rearranging the limits? | 1 | 0 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 484,702,191,156,985,860 | themateo713 | 12/21/2021 08:31:16 | it is about breaking up the integral into integrals where the bounds correspond to f's definition | 0 | 1 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:32:11 | something like this? | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 484,702,191,156,985,860 | themateo713 | 12/21/2021 08:33:14 | for the integral, n appears to be held constant, so there are no limits | 0 | 1 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 714,074,341,809,061,900 | Mushfiqur | 12/21/2021 08:35:57 | Can anyone help me with this problem:-
What's the average distance between two random dots in a square that has a length of 1 unit | 0 | 1 | null | null | null | null | null | |||||
205,509 | help-1 | 3267e02ba532491fbac6371cf5e011fd | 225,110,750,161,666,050 | Neko | 12/21/2021 08:36:39 | .close | 1 | 0 | null | null | null | null | null | |||||
205,510 | help-1 | 369a3087601a4dc0b2a5675805b78a94 | 175,328,346,291,306,500 | Swivel | 01/19/2022 07:41:36 | Can someone help me get started with this? 🙂 | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,510 | help-1 | 369a3087601a4dc0b2a5675805b78a94 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 07:43:25 | c_1 and c_2 are scalars... just put u and v in terms of i and j and equate with a = j + i | 0 | 1 | null | null | null | null | null | |||||
205,510 | help-1 | 369a3087601a4dc0b2a5675805b78a94 | 175,328,346,291,306,500 | Swivel | 01/19/2022 07:45:46 | in terms of? | 1 | 0 | null | null | null | null | null | |||||
205,510 | help-1 | 369a3087601a4dc0b2a5675805b78a94 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 07:48:48 | u = 3i + 6j and v = 8i + 19j | 0 | 1 | 321,445,119,171,756,000 | Shuri2060 | 9525 | a μ-er | false | |||||
205,510 | help-1 | 369a3087601a4dc0b2a5675805b78a94 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 07:48:49 | ... | 0 | 1 | null | null | null | null | null | |||||
205,510 | help-1 | 369a3087601a4dc0b2a5675805b78a94 | 175,328,346,291,306,500 | Swivel | 01/19/2022 07:57:02 | hmm could you elaborate? | 1 | 0 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 175,328,346,291,306,500 | Swivel | 01/19/2022 08:12:20 | .reopen | 1 | 0 | 782,087,086,416,461,800 | LittleMouse | 2603 | LittleMouse | false | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:17:17 | a = i + j = c1\*u + c2*v | 0 | 1 | 912,292,630,036,099,100 | Peppermint Demon | 3120 | Peppermint Demon | false | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 175,328,346,291,306,500 | Swivel | 01/19/2022 08:17:36 | yes | 1 | 0 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:17:37 | you have u and v | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:17:57 | just write c1\*u + c2*v in terms of i and j | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:18:12 | and solve for c1 and c2 | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:24:03 | ,w inverse {{3,8},{6,19}} | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 510,789,298,321,096,700 | TeXit | 01/19/2022 08:24:06 | Results provided by WolframAlpha | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:25:07 | ,w {{19/9, -8/9},{-6/9, 3/9}} \times {{1},{1}} | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 08:26:28 | ~~so lazy~~ XD | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:26:47 | ~~i have better things to do lol~~ | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 706,934,233,012,371,600 | Ansh_ | 01/19/2022 08:27:20 | then just add 'em and get it done with >_< you just have to add the row entries anyways | 0 | 1 | null | null | null | null | null | |||||
205,511 | help-1 | f56fb1f924da4248b464d3ec646eabc9 | 411,882,877,933,060,100 | Ｈｅｒｅｌｓ | 01/19/2022 08:28:03 | yea lol | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 175,328,346,291,306,500 | Swivel | 01/19/2022 08:33:36 | Thanks 🙂 | 1 | 0 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 136,358,786,054,094,850 | Gaping Hole | 01/19/2022 08:36:59 | Hey fellow discorders.
I am in Precalculus on the start of my semester and I have been trying to grasp my type of learning into my class. I was given polynomials and 6 different ways on how to do it such as square root, difference of squares, and Etc… I get the types done. But I can’t understand this in the applicatio... | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 136,358,786,054,094,850 | Gaping Hole | 01/19/2022 08:38:11 | It’s more of a conceptual question. | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 08:39:52 | So you're curious about applications of zeros of polynomials? | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 136,358,786,054,094,850 | Gaping Hole | 01/19/2022 08:40:37 | I’m curious on how all my learning of factoring polynomials and square roots incorporates to real life | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 08:42:20 | Well for example you can represent height of an object in free fall as a polynomial function | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 348,696,743,388,381,200 | A Lonely Bean | 01/19/2022 08:42:47 | Or taylor polynomials are used to approximate values of sin and cos for not-so-nice angles | 0 | 1 | null | null | null | null | null | |||||
205,512 | help-1 | 9c51a3d4165f492d94483eca2a52e413 | 381,524,178,165,039,100 | Door 'GG' VB | 01/19/2022 08:43:34 | Also solving linear differential equations often involves solving polynomials | 0 | 1 | null | null | null | null | null |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.