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205,606 | help-1 | 8592a2e58c01476ca5721e30f91b1ede | 414,557,649,045,159,940 | Somalian Space Pirate | 01/23/2022 10:27:15 | I think my teacher just gave us a matrix with random numbers as an example of a question we might get tomorrow | 1 | 0 | null | null | null | null | null | |||||
205,606 | help-1 | 8592a2e58c01476ca5721e30f91b1ede | 414,557,649,045,159,940 | Somalian Space Pirate | 01/23/2022 10:27:27 | That's the most logical reason it's a bad solution | 1 | 0 | null | null | null | null | null | |||||
205,606 | help-1 | 8592a2e58c01476ca5721e30f91b1ede | 321,445,119,171,756,000 | Shuri2060 | 01/23/2022 10:27:30 | #linear-algebra you can try here | 0 | 1 | null | null | null | null | null | |||||
205,606 | help-1 | 8592a2e58c01476ca5721e30f91b1ede | 414,557,649,045,159,940 | Somalian Space Pirate | 01/23/2022 10:29:09 | Anyways, thanks for the attempt lol | 1 | 0 | null | null | null | null | null | |||||
205,606 | help-1 | 8592a2e58c01476ca5721e30f91b1ede | 414,557,649,045,159,940 | Somalian Space Pirate | 01/23/2022 10:29:15 | Mystery uncovered | 1 | 0 | null | null | null | null | null | |||||
205,606 | help-1 | 8592a2e58c01476ca5721e30f91b1ede | 414,557,649,045,159,940 | Somalian Space Pirate | 01/23/2022 10:29:18 | .close | 1 | 0 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 638,437,422,807,384,000 | du | 01/23/2022 10:32:41 | In a geometric sequence, the second term is equal to the square of the fifth term. The third term is 32. How many terms should be taken starting from rhe first term for the sum to be 255 1/2 | 1 | 0 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 909,773,741,196,730,400 | bayka | 01/23/2022 10:32:54 | thanks! | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:40:08 | So let's say $b_n$ is the sequence and since it's geometric one we can express every term as $b_1q^{n - 1}$, since second term is square of the fifth term we say that $b_2 = b_5^2$, which is equivalent to $b_1q = (b_1q^4)^2$, so $b_1q = b_1^2q^8$. $b_1$ can't be zero (because then every term would basically be 0, contr... | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:40:42 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:41:32 | We can now also use the fact that the third term ($b_1q^2$) is equal to $32$, so $1 = b_1q^7 = b_1q^2q^5 = 32q^5$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:41:35 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:41:48 | $1 = (2q)^5$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:41:51 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:42:01 | $2q = 1$, $q = \frac{1}{2}$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:42:04 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:42:42 | Now that we know q, we can easily solve for $b_1$ by plugging the value into $b_1q^2 = 32$ equation, so we get $\frac{b_1}{4} = 32$. And $b_1 = 128$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:43:06 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:45:01 | Now, are you familiar with the formula of geometric sum? | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 638,437,422,807,384,000 | du | 01/23/2022 10:46:21 | No | 1 | 0 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:49:24 | I don't think you'd be given this problem without that formula but here it is | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:49:54 | $S_n = b_1\frac{1 - q^n}{1 - q}$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:49:57 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:50:23 | So we now have to set this equal to 255.5 | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:50:33 | And also plug in the value of q and b_1 | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:50:55 | So we have $128\frac{1 - \frac{1}{2^n}}{1 - \frac{1}{2}} = 255.5$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:51:11 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:51:50 | 1 - 1/2 is just 1/2 | 0 | 1 | 869,532,694,688,706,600 | EpsilonNought | 8684 | EpsilonNought | false | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:52:41 | $128\frac{1 - \frac{1}{2^n}}{\frac{1}{2}} = 256(1 - \frac{1}{2^n}) = 255.5$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:52:44 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:53:14 | $1 - \frac{1}{2^n} = \frac{256 - 0.5}{256}$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:53:16 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:53:21 | (here I rewrote 255.5) | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:53:58 | $1 - \frac{1}{2^n} = 1 - \frac{0.5}{256}$, $\frac{1}{2^n} = \frac{0.5}{256}$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:54:00 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:54:11 | $2^n = 2\cdot{256}$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:54:14 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:54:33 | $2^n = 512 = 2^9$ | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:54:35 | So n = 9 | 0 | 1 | null | null | null | null | null | |||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 510,789,298,321,096,700 | TeXit | 01/23/2022 10:54:36 | **Beans** | 348696743388381195.png | 0 | 1 | null | null | null | null | null | ||||
205,607 | help-1 | 8c995228b1694d88803af25a351f0a9d | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 10:54:53 | So 9 terms should be taken for the sum to be 255.5 | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:21:16 | hello | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:25:35 | how to calculate this? | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:25:37 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:26:05 | Trying to solve A and B | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:27:01 | What have you tried so far? | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:27:33 | $y(1)=A*1^2+B*1?3=3$ | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 510,789,298,321,096,700 | TeXit | 01/23/2022 11:27:36 | **cakeee** | 504278422521118721.png | 0 | 1 | null | null | null | null | null | ||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 485,903,210,272,391,200 | dldh06 | 01/23/2022 11:27:39 | If you plug in each point, you'll end up with two equations, two unknowns | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:27:57 | I hope you meant A + B + 3 = 3 there | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:28:14 | Which implies that A + B = 0 | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:28:23 | y(-1)=A*(.1)^2+B*(-1)+3=9 | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:28:25 | Now do the same with the other equation, as dldh06 said | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:28:43 | Yeah so you get A - B = 6 | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:28:50 | A+B=0 and A-B=6 | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:28:52 | Yep | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:28:56 | This is just a set of 2 linear equations in A and B | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:28:58 | And now what? | 1 | 0 | 706,934,233,012,371,600 | Ansh_ | 3502 | Arya | false | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:29:01 | Should be easy to solve | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:29:11 | By summing the equations | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:29:15 | That's what you could do | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:29:31 | Can you show? | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:30:02 | A + B = 0
A - B = 6
(A + B) + (A - B) = 0 + 6 | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 485,903,210,272,391,200 | dldh06 | 01/23/2022 11:30:06 | You can do either elimination or substitution | 0 | 1 | 755,831,671,588,126,700 | RepliedPencil | 9129 | - A Pencil in Progress | false | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:30:32 | I don't think you'd be given this problem if you can't solve a set of linear equations :thonk: | 0 | 1 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:34:12 | A=3, B=-3 | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:34:16 | Yeah 😄 | 1 | 0 | null | null | null | null | null | |||||
205,608 | help-1 | 98a25d598bcd44e69934b93a11f3dded | 504,278,422,521,118,700 | kasperky | 01/23/2022 11:34:18 | Thanks | 1 | 0 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 753,933,776,018,604,000 | dumpling | 12/22/2021 02:28:58 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 753,933,776,018,604,000 | dumpling | 12/22/2021 02:29:06 | hi could someone explain this part | 1 | 0 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 799,900,545,384,316,900 | Harshit Chitkara | 12/22/2021 02:55:42 | unknown.png | 0 | 1 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 799,900,545,384,316,900 | Harshit Chitkara | 12/22/2021 02:55:45 | unknown.png | 0 | 1 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 799,900,545,384,316,900 | Harshit Chitkara | 12/22/2021 02:55:53 | can somebody help me with these | 0 | 1 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 799,900,545,384,316,900 | Harshit Chitkara | 12/22/2021 02:56:00 | it would be a gr8 help | 0 | 1 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 799,900,545,384,316,900 | Harshit Chitkara | 12/22/2021 02:56:12 | and this | unknown.png | 0 | 1 | null | null | null | null | null | ||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 753,933,776,018,604,000 | dumpling | 12/22/2021 02:56:56 | this channel is still occupied. | 1 | 0 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 753,933,776,018,604,000 | dumpling | 12/22/2021 02:57:00 | ^ | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 197,677,205,382,365,200 | .nai | 12/22/2021 03:07:18 | You are told that m is a constant. For that to be true you need make it independant of n. In your case, the terms that are dependant on n is the 3^{3n}/3^{nk}. So you find value for k such that that term (refering to the 3^blabla) never changes which implies that m would never change. You solve 3n-nk=0 and find a value... | 0 | 1 | null | null | null | null | null | |||||
205,609 | help-1 | 49034a9025834c70bdb827ff2bf2cb18 | 197,677,205,382,365,200 | .nai | 12/22/2021 03:09:34 | I should mention that you find values when 3^{3n}/3^{nk}=1 because 1m is equal to that expression above (the one after if in first row) | 0 | 1 | null | null | null | null | null | |||||
205,610 | help-1 | f31eba03b81d4711bacaf57e894ddc41 | 705,960,295,809,417,300 | not a robot | 01/23/2022 11:57:13 | Here is a right triangle with 3 sectors at each vertex. How is it that the angle of sector 2 is pi/2 - theta ? I can't figure that out | 20220123_085445.jpg | 1 | 0 | 396,018,393,452,642,300 | Wumpie | 8322 | Wumpie | false | ||||
205,610 | help-1 | f31eba03b81d4711bacaf57e894ddc41 | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:58:23 | What's theta? Is it angle of sector 1? | 0 | 1 | 328,019,240,898,789,400 | dino dik | 9674 | dino | false | |||||
205,610 | help-1 | f31eba03b81d4711bacaf57e894ddc41 | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 11:59:07 | If so, then yes, the angle of sector 2 must be pi/2 - theta because sum of acute angles in a right triangle is always pi/2 | 0 | 1 | null | null | null | null | null | |||||
205,610 | help-1 | f31eba03b81d4711bacaf57e894ddc41 | 705,960,295,809,417,300 | not a robot | 01/23/2022 11:59:39 | ohhh i see | 1 | 0 | null | null | null | null | null | |||||
205,610 | help-1 | f31eba03b81d4711bacaf57e894ddc41 | 705,960,295,809,417,300 | not a robot | 01/23/2022 11:59:46 | thanks | 1 | 0 | null | null | null | null | null | |||||
205,610 | help-1 | f31eba03b81d4711bacaf57e894ddc41 | 705,960,295,809,417,300 | not a robot | 01/23/2022 11:59:59 | .close | 1 | 0 | null | null | null | null | null | |||||
205,611 | help-1 | 232c5ac5ac29477c9cd00cb045a01900 | 806,268,973,100,433,500 | lebedevhh | 01/23/2022 12:08:34 | $$\frac{3}{2}$$ | 1 | 0 | null | null | null | null | null | |||||
205,611 | help-1 | 232c5ac5ac29477c9cd00cb045a01900 | 510,789,298,321,096,700 | TeXit | 01/23/2022 12:08:37 | **𝓁𝑒𝒷𝑒𝒹𝑒𝓋𝒽𝒽⸕** | 806268973100433499.png | 0 | 1 | null | null | null | null | null | ||||
205,611 | help-1 | 232c5ac5ac29477c9cd00cb045a01900 | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 12:10:56 | Post the question if you have one | 0 | 1 | null | null | null | null | null | |||||
205,611 | help-1 | 232c5ac5ac29477c9cd00cb045a01900 | 348,696,743,388,381,200 | A Lonely Bean | 01/23/2022 12:11:18 | If you want to practice LaTeX, consider visiting #latex-testing | 0 | 1 | null | null | null | null | null | |||||
205,612 | help-1 | 671abcf34d9c4b71a202ebbc6ac72792 | 456,226,577,798,135,800 | Deleted User | 01/23/2022 12:31:31 | image.png | 1 | 0 | null | null | null | null | null | |||||
205,612 | help-1 | 671abcf34d9c4b71a202ebbc6ac72792 | 456,226,577,798,135,800 | Deleted User | 01/23/2022 12:32:23 | Anyone? | 1 | 0 | null | null | null | null | null | |||||
205,612 | help-1 | 671abcf34d9c4b71a202ebbc6ac72792 | 456,226,577,798,135,800 | Deleted User | 01/23/2022 12:44:24 | image.png | 1 | 0 | null | null | null | null | null | |||||
205,612 | help-1 | 671abcf34d9c4b71a202ebbc6ac72792 | 456,226,577,798,135,800 | Deleted User | 01/23/2022 12:46:03 | How is v1=v2 | 1 | 0 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 535,142,622,113,562,600 | Singularity2024 | 01/23/2022 14:15:11 | In mechanics do i take gravity as -9.81 or 9.81 and if so if the calculation also includes s do i take a downwards displacement as negative for example using s=ut +1/2at<squared> i got a quadratic with no real roots as ended up with the equation 4.905t<squared>+6.4(height in the question) | 1 | 0 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 321,445,119,171,756,000 | Shuri2060 | 01/23/2022 14:17:00 | all depends on context I think | 0 | 1 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 321,445,119,171,756,000 | Shuri2060 | 01/23/2022 14:17:12 | if ur measuring height from the ground upwards | 0 | 1 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 321,445,119,171,756,000 | Shuri2060 | 01/23/2022 14:17:22 | then clearly gravitational acceleration is negative | 0 | 1 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 328,662,734,008,746,000 | Geopchad | 01/23/2022 14:17:38 | yeah gravitational acceleration pulls the object down | 0 | 1 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 328,662,734,008,746,000 | Geopchad | 01/23/2022 14:17:43 | so it would be negative like shuri said | 0 | 1 | null | null | null | null | null | |||||
205,613 | help-1 | f935180b041e4129a89572ad1e820584 | 328,662,734,008,746,000 | Geopchad | 01/23/2022 14:18:06 | but if you are dealing with like circular motion then it would be accelerating towards the center of the circle | 0 | 1 | null | null | null | null | null |
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