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205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:16:41 | i just get -4.67 basically | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:17:01 | dont use your calculator | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:17:09 | what you get is the negative of -14/3 | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:17:18 | and how do you write that | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:18:09 | ok in my head it goes up to -4.5 roughly | 1 | 0 | 321,074,029,291,372,540 | Jason_Bjorn | 0254 | Jason_Bjorn | false | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:18:15 | i donht think im understanding siomething your tellign me | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:18:16 | im sorry | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:18:22 | i am really bad at math 😦 | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:18:54 | how do you write the negative of a number | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:19:34 | with a -???? | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 02:19:49 | So if you're given a number, say 4, what is the negative of it? | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:20:09 | yes | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:20:10 | precisely | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:20:11 | with a - | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:20:21 | so how do you write the negative of -14/3 | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 02:20:59 | the negative of a number has - sign, so the negative of -14/3 is -14/3 :devastation: \s | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:21:53 | let them answer first | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:23:07 | i am so confused. | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:23:19 | so the answer to -x is basically right there? | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:23:20 | answer this | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:23:31 | you said the negative of a number is putting - before it | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:23:34 | -14/3 i guess | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:23:46 | i thought you were asking me to solve 14/3 and then find the negative of it that way because im tired and didnt understand what you were asking | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:23:49 | but x already has a - before it | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:23:53 | what ansh said i was like "oh." | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:23:54 | so you need to put another - before -14/3 | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:24:02 | so it becomes - -14/3? | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:24:05 | or --14/3 | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:24:42 | i would write that as -(-14/3) | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:25:06 | remember what i said about the negative of a negative being positive | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:25:33 | yea i keep forgettign that rule | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:25:36 | hghhh | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:27:12 | me :d | Boruto_Ending_7__Polaris_HD.gif | 1 | 0 | null | null | null | null | null | ||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:29:34 | hhh | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:29:37 | i think that helps | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:31:29 | you ok now | 0 | 1 | 312,559,012,346,331,140 | xdk1235 | 7777 | xdk1235 | false | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:31:46 | yea | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:31:49 | i guess you know what -x is now | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:31:49 | Thank you | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:32:32 | Yea, and altohugh i dont feel like i understand anything at all i will make sure to ask my teacher in class next time wtf this means and maybe i can understand it better than i do rn, altho u guys did help. so thank you. | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:34:25 | -x is putting a - before x even if x itself has a - | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 710,074,310,462,668,800 | sat | 01/27/2022 02:34:59 | if this helps @Fullmetal Akabaneist | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:35:10 | oh | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:35:13 | So lets say theres a problem | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:35:30 | Find the -x if x is listed, and thje problem is 5 divided by 3, so x = 5/3 | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 207,711,768,795,938,800 | Fullmetal Akabaneist | 01/27/2022 02:35:42 | the answer would be - -5/3 | 1 | 0 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 02:35:56 | Fun fact: negative of any value is actually $-1$ times the value | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 510,789,298,321,096,700 | TeXit | 01/27/2022 02:35:58 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 02:36:43 | so -ve of 5/3 would be $\frac{5}{3} \times (-1) = -\frac{5}{3}$ | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 510,789,298,321,096,700 | TeXit | 01/27/2022 02:36:45 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 02:37:06 | And -ve of (-5/3) would be $-\frac{5}{3} \times (-1) = +\frac{5}{3}$ | 0 | 1 | null | null | null | null | null | |||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 510,789,298,321,096,700 | TeXit | 01/27/2022 02:37:09 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,678 | help-1 | 2823d27894f642f19ebec9843bc80315 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 02:37:45 | that's the basic understanding of how negative integers work | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:14:04 | Is there any formula from which I can get the sum of the positive factors of a number | 1 | 0 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:14:40 | whaaaaaaa | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:15:02 | > • Ask your math question in a clear, concise manner. | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:15:06 | Give the context please | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:15:39 | If there's a question you're stuck at, it helps to know which formula or what exactly are you looking for | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:15:59 | like for 12 factors are 1,2,3,4,6,12 then I need 1+2+3+4+6+12 | 1 | 0 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:16:28 | just out of curiosity | 1 | 0 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:17:13 | Maybe you're looking for divisor function | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 478,703,800,463,523,840 | sadkid | 01/27/2022 03:17:46 | https://planetmath.org/formulaforsumofdivisors | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:18:01 | https://en.wikipedia.org/wiki/Divisor_function#:~:text=The%20notations%20d(n)%2C,)%20(OEIS%3A%20A000203).
Look this up as well | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:18:35 | $\sigma_x(n) = \sum_{d|n} d^x$ | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 510,789,298,321,096,700 | TeXit | 01/27/2022 03:18:38 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:19:03 | no I want a formula for n where the answer is in terms of n | 1 | 0 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 706,934,233,012,371,600 | Ansh_ | 01/27/2022 03:19:46 | can't really be, because we can't generalize the prime factorization of any number "n" | 0 | 1 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:19:57 | ok | 1 | 0 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:20:00 | thnx | 1 | 0 | null | null | null | null | null | |||||
205,679 | help-1 | 426a5fdff9b142f98a3af1220ea26117 | 644,866,111,505,956,900 | BLACK1 | 01/27/2022 03:20:16 | .close | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 03:57:23 | how do u do this without taylor expansion | Screen_Shot_2022-01-27_at_12.53.28_AM.png | 1 | 0 | null | null | null | null | null | ||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 03:57:47 | i know it converges to f(x) = 1 for 0 < x < 1 and f(x) = x for x > 1 by graph | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 03:57:57 | but I can't simplify |f_n(x) - f(x)| | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 03:59:48 | Simplify it pointwise, like the problem says | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 03:59:59 | yea i did that | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:00:12 | but like how do u simplify (1+x^n)^(1/n) - x | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:00:32 | Take the limit | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:01:27 | Oh you're doing the unform part? | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:03:02 | nah im trying to think how to take the limit lol | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:03:03 | rusty af | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:04:03 | If you're doing the pointwise part, you shouldn't be subtracting your guess | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:04:34 | Are you trying to prove this? | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:04:42 | ye | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:09:39 | (1+ x^n)^(1/n) = e^(1/n *log(1+x^n)) then lhopital | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:10:21 | ok i think i figured out pointwise sort of, I can do $(1+x^n)^\frac{1}{n} \leq (2x^n)^\frac{1}{n}$ for $x > 1$ | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:10:33 | no l'hopital can be used | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:10:39 | Or maybe not | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:10:45 | Just take the limit | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:11:05 | and for $x < 1$ then $(1+x^n)^\frac{1}{n} \leq (2)^\frac{1}{n}$ | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 510,789,298,321,096,700 | TeXit | 01/27/2022 04:11:14 | **Anticipation** | 734628928420839496.png | 0 | 1 | null | null | null | null | null | ||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:11:38 | This gives you 1 for x in (0,1) | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 510,789,298,321,096,700 | TeXit | 01/27/2022 04:11:39 | **Anticipation** | 734628928420839496.png | 0 | 1 | null | null | null | null | null | ||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:11:50 | yea problem is uniform now | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:13:16 | for when $x > 1$ this strategy doesnt work because $\sup_{x > 1} (2^\frac{1}{n}-1) x$ is always infinity | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 510,789,298,321,096,700 | TeXit | 01/27/2022 04:13:39 | **Anticipation** | 734628928420839496.png | 0 | 1 | null | null | null | null | null | ||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:14:22 | What's your starting statement for uniform convergence | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:15:24 | for given epsilon theres a point when all the f_n is at most epsilon apart from f everywhere | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:15:35 | just the standard def | 1 | 0 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 261,933,205,387,477,000 | riemann | 01/27/2022 04:17:26 | Maybe bound 1+x^n something tighter than 2x^n | 0 | 1 | null | null | null | null | null | |||||
205,680 | help-1 | a1e48cbce73f4aa2bc17c56e14d88c2a | 734,628,928,420,839,600 | Anticipation | 01/27/2022 04:17:44 | or could it be possible its not uniform | 1 | 0 | null | null | null | null | null |
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