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205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 10:30:57 | is this provable graphically (that this is always the case?) | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 872,024,354,572,103,700 | <><><> | 12/22/2021 10:38:25 | Ohh. I get your question. Hmm, it appears to be so. As for a proof, maybe big brain ann can help @Ann | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 183,668,144,404,037,630 | Ann | 12/22/2021 10:38:36 | nyeh? | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 183,668,144,404,037,630 | Ann | 12/22/2021 10:38:46 | oh | 0 | 1 | 420,244,167,726,333,950 | kirby your mom | 8749 | kirby your mom | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 183,668,144,404,037,630 | Ann | 12/22/2021 10:38:46 | this | 0 | 1 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 183,668,144,404,037,630 | Ann | 12/22/2021 10:38:52 | i don't have the energy for this sorry | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 13:54:59 | Solutions to your quartic in y are +-3 and +-√(-20). Since "y" was taken to be a real number, solutions +-√(-20) are discarded. | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 13:57:31 | From 2xy=12√5,
y=3 gives us x=2√5 and y=-3 gives x=-2√5 | 0 | 1 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 14:30:33 | My question isn't about solutions | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 14:30:51 | It's about why the second solution is the value of the corresponding variable | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 14:31:46 | Wdym "second solution"? And you do know that finding the solution here means finding the values of x,y, such that the equations are satisfied right? | 0 | 1 | 420,244,167,726,333,950 | kirby your mom | 8749 | kirby your mom | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 14:42:26 | You could solve for x first and then find the values of y from there it doesn't matter | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 700,047,727,366,635,500 | Tøøthpick | 12/22/2021 14:42:57 | 7B2EF9CD-4837-4953-B088-FDAFFDB59EEE.jpg | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 700,047,727,366,635,500 | Tøøthpick | 12/22/2021 14:43:03 | Can anyone help me with that | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 700,047,727,366,635,500 | Tøøthpick | 12/22/2021 14:43:33 | ? | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 14:43:35 | Post in an unoccupied channel. Read #❓how-to-get-help | 0 | 1 | 261,933,205,387,477,000 | riemann | 2529 | riemann | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 15:01:58 | When finding values of y, you also get complex roots for y | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 15:02:08 | Those complex roots correspond to the values of x | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 15:02:23 | My question was if this is always true and if there is a graphical proof | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 18:31:23 | No they don't. The values of x we get are +-√20 which is not related to the imaginary values +-i√20 we get while solving for y. | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:32:52 | the root(-20) is the x value | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:33:00 | it corresponds to the other value | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:33:05 | it done it in every question i did | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:33:22 | im tryna find a proof for it to see if it **always** does it | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 18:33:25 | root(-20) is not a real number. x was given as a real number | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:33:32 | alright then | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:33:36 | its the negative of x | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:33:58 | its the variable x multiplied by -i | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:34:13 | whatever u wanna call it, its possible to take the other value from it none the less | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 18:34:20 | and im wondering why this is, graphically what is going on. | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 18:42:11 | If you allow the complex values of y from the quartic you got, then the extra solutions you get are y=+-i√(20) and x=-+3i which also does provide us with the square roots of 11+12√5i when we write them in the form x+iy. The fact that we are multiplying i to "y" again transforms +-i√(20) to -+√20 which we need as the re... | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 18:51:23 | Because we know that finally, there are exactly two square roots of 11+12√5i namely, √(20)+3i and -√(20)-3i | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 19:02:51 | From the solution standpoint, if we have some x=a, y=b satisfying x²-y²=11 and 2xy=12√5 then x=bi, y=-ai also qualifies as a solution | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 19:18:53 | All of this stems from the fact that allowing x,y to be either purely real or purely imaginary implies the equation a+bi=x+iy (a,b real) has two pairs of solutions namely x=a, y=b and x=bi, y=-ai | 0 | 1 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 19:30:23 | Graphically, it's not that nice since you can't plot (bi,-ai) | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:55:23 | Uhhhh | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:56:33 | I kinda understand but half don't | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:56:52 | Multiplying I to y. What does that mean? | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:57:26 | Also is the conjugate as well as the +- solutions? | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:57:53 | The real value can be +- too? Doesn't that mean there is indeed 4 solutions? | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:58:41 | Your solution standpoint works fine tho thanks | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/22/2021 19:58:48 | So that proves it's always the case. | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 20:02:32 | No. Conjugates have nothing to do with this. | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 691,679,326,164,222,100 | Euclid31415 | 12/22/2021 20:05:39 | There are only two squareroots of 11+12√5i in the end. Allowing x,y to be either purely real or purely imaginary gives us 4 pairs of solutions (x,y) for 11+12√5i=(x+iy)^2 | 0 | 1 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/23/2021 03:45:24 | Gonna thjnj about it iab | 1 | 0 | null | null | null | null | null | |||||
205,698 | help-1 | 8b04c92fe27c4ec48854d270088b60ff | 456,226,577,798,135,800 | Deleted User | 12/23/2021 07:48:16 | .close | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:24:56 | Hello, I tried two approaches but ended up with two different answers. Now I can’t continue cause I don’t know which one is correct | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:25:01 | IMG_2652.jpg | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:26:22 | What was the integral btw? because your expression and your first steps don't match | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:26:41 | Maybe a mistake in copying the question right | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:27:36 | $\int \frac {2sec^{2}\theta d\theta } {(2sec\theta)^{4}}$ | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 510,789,298,321,096,700 | TeXit | 01/28/2022 05:28:56 | **aIex** | 677350243293069312.png | 0 | 1 | null | null | null | null | null | ||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:29:04 | Ah that makes much more sense | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:29:09 | yep | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:29:59 | $\frac{2}{16}\int \frac {sec^{2}\theta} {(sec\theta)^{4}} \dd{\theta}$ | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 510,789,298,321,096,700 | TeXit | 01/28/2022 05:30:01 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:30:14 | yep | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:30:37 | Are you allowed to do substitution? Or are you doing it without substitution? | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:32:05 | allowed | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:33:02 | btw $\frac{1}{8}\int \frac {1} {\sec^{2}\theta} \dd{\theta} = \frac{1}{8}\int \frac {1} {\underbrace{\tan^{2}\theta +1}} \dd{\theta}$ is not actually what you'd want to do. I'd suggest using sec cos relation | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:34:09 | ohh okay | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 510,789,298,321,096,700 | TeXit | 01/28/2022 05:34:22 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:34:24 | @aab:this: ~~sorry ale, wrong ping~~ | 0 | 1 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:35:09 | imma make it cos^2(theta) instead? | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:35:15 | Yeah | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:35:24 | and integrate cos^2(theta) | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:36:25 | okay cool imma work on it and come back if i got some troubles | 1 | 0 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:43:49 | ok i think i got it now. thanks @Ansh_ !! | 1 | 0 | 716,505,727,367,249,900 | your brother | 2441 | your brother | false | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:43:57 | :D | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 706,934,233,012,371,600 | Ansh_ | 01/28/2022 05:44:04 | > .close
before you leave | 0 | 1 | null | null | null | null | null | |||||
205,699 | help-1 | a890ca2139e041be98772204f4d231f4 | 677,350,243,293,069,300 | aab | 01/28/2022 05:59:04 | .close | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:33:25 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:33:56 | I don't understand this almost at all | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:34:32 | Solving for m simultaneously yields me `m = 1` or `m = -3` but I don't know how that plays into "infinitely many solutions" and "no solutions" | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:36:49 | Context: New school, some unfamiliar content, I don't understand the single example provided in the textbook (too vague) | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:03 | okay | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:06 | let’s think about it | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:17 | these two equations | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:20 | what are they? | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:37:27 | Straight lines | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:31 | yep | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:37:33 | Can be rearranged into y=mx+c | 1 | 0 | 259,180,275,345,391,600 | barrelbarrelbarrel | 1229 | barrelbarrelbarrel | false | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:45 | true | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:50 | they can also be in the form of | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:55 | ax+by+c=0 | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:37:59 | but anyway | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:38:14 | if two lines have infinitely many solutions | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:38:23 | what does that say about the relation between these lines? | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:38:37 | That's where I'm stuck | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:38:44 | I'm not entirely sure what a "solution" here is | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:39:15 | for example we have the lines x+2y+3=0 and 2x+3y+5=0 | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:39:40 | is there at least a pair of (x,y) that’ll satisfy both linear equations? | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:39:54 | in what case will there be no (x,y) pairs? | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:40:03 | Right gotcha | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:40:40 | So it's asking what value of *m* allows infinite x and y solutions? | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:40:52 | yep | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 456,226,577,798,135,800 | Deleted User | 01/28/2022 06:41:00 | Alright | 1 | 0 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:41:10 | but now think about two lines | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:41:20 | when you input any x value | 0 | 1 | null | null | null | null | null | |||||
205,700 | help-1 | 5c401f58b5854f3c8036a2204e3dcecf | 277,133,612,812,468,220 | HeadShotCem | 01/28/2022 06:41:29 | they’ll output the same y value | 0 | 1 | null | null | null | null | null |
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