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205,724 | help-1 | 0c610917b4b4442b87682f0700204715 | 321,445,119,171,756,000 | Shuri2060 | 01/29/2022 00:52:51 | Not saying the answer will look nicer. | 0 | 1 | null | null | null | null | null | |||||
205,724 | help-1 | 0c610917b4b4442b87682f0700204715 | 321,445,119,171,756,000 | Shuri2060 | 01/29/2022 00:53:01 | But I would see maybe | 0 | 1 | null | null | null | null | null | |||||
205,724 | help-1 | 0c610917b4b4442b87682f0700204715 | 677,350,243,293,069,300 | aab | 01/29/2022 00:53:39 | okay okay gotcha. thanks! .close | 1 | 0 | null | null | null | null | null | |||||
205,724 | help-1 | 0c610917b4b4442b87682f0700204715 | 677,350,243,293,069,300 | aab | 01/29/2022 00:53:41 | .close | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:15:54 | no clue on how to do this | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:17:22 | That means it's a right angled triangle | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:17:35 | Draw the triangle and apply pythagoras theorem | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:19:32 | to which sides? | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:20:43 | No wait | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:21:00 | Ooh yeah I've gotten it | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:21:09 | Draw triangle ABC | 0 | 1 | 935,204,719,972,974,700 | HA2814 | 1529 | HA2814 | false | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:21:33 | Then drop a perpendicular line from A to BC | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:21:49 | Then the meeting point is D | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:21:52 | Solve... | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:22:26 | so d should be between c and b | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:23:00 | hmmmm but how do i extract an answer from this | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:23:24 | nowhere does it state that cd is half of cb | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:23:56 | It's at 90° | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:24:08 | so is the answer 4.5? | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:24:57 | Wait a sec | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:25:46 | alright | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:28:31 | Apply cosine rule | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:28:33 | so do i literally just cut bc in half | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:28:41 | haven't covered cosine before | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:28:51 | No that's not right | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:29:01 | not really sure where to go with this | 1 | 0 | 825,545,259,194,515,500 | Incipience | 0159 | Incipience | false | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:36:32 | Okay | 0 | 1 | 825,545,259,194,515,500 | Incipience | 0159 | Incipience | false | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:36:47 | Let me give you another method | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:38:01 | Once you've drawn the triangle, Let AD be y and CD be x and use pythagorean theorem to find the eqns and solve them | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:40:14 | Do you have the solution to this problem? | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:41:18 | I'm pretty sure it's 4.5, but ive been wrong before | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:42:05 | CD is undefined though | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:42:24 | can't find the answer with only one variable | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:42:37 | 4.5 comes out as wrong | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:42:47 | BD will be 9+x mind you | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:43:10 | So you'll have to eqns for y | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:43:17 | eqns? | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:43:27 | Equations | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:44:29 | i will try | 1 | 0 | 353,581,489,201,348,600 | RaceDaleJr88Fan | 1107 | RaceDaleJr88Fan | false | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:44:38 | gonna ask the teacher tomorrow if it doesn't make enough sense | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:44:46 | The ans should be 25/6 | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:45:36 | Does D lie outside of the triangle? | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:46:37 | Yes | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:47:12 | If the angles were acute, would it just be 4.5? | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:47:49 | My ACD was obtuse | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:48:30 | Not really sure | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:50:20 | wait how did you get this? | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:50:25 | i put it in and it worked | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:51:25 | Basically drew triangle ABC with angle ACD obtuse | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:51:56 | So AD will be outside the triangle... to an extension of BC | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:52:52 | Represented CD as x and AD as y
So basically BD will be 9+x | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:53:27 | kinda makes sense | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:53:31 | thank you for the help :) | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:53:53 | Used pythagorean theorem to find the 2 eqns and solved them simultaneously | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:54:02 | Welcome | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 01:55:06 | this isn't perpendicular though | 1 | 0 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:55:18 | my drawing is horrible | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:55:49 | This is correct | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:56:12 | how would it look? | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:56:19 | can you sketch for me? | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 914,473,169,648,255,000 | skymoon | 01/29/2022 01:58:09 | 20220129_095746.jpg | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:58:37 | ohh | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 872,024,354,572,103,700 | <><><> | 01/29/2022 01:58:38 | i see | 0 | 1 | null | null | null | null | null | |||||
205,725 | help-1 | 86d78b7f860d40b38025beed8c0b81e8 | 541,081,246,252,531,700 | nals | 01/29/2022 02:10:21 | it has been, thanks bros | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:17:06 | IMG_0341.png | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:17:15 | i don’t get why n has no effect on F(b) - F(a) | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:18:03 | F(b), F(a) are integrals whose accuracies are affected by how big n is | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:18:11 | by riemann sums, they have n partitions | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:19:13 | see the first two lines and substitute that into the middle sum on the fourth line | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:19:42 | taking limits | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:19:44 | the way c_k is defined makes it not matter | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:20:49 | wdym | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:23:08 | c_k is defined such that <middle of the second line> | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:24:03 | i’m concerned about n not affecting LHS | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:25:27 | now i'm confused | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:25:34 | which line are you having a problem with? | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:26:18 | final | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:27:47 | ah okay | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:28:38 | the thing is, for each n, the c_k's change because your partitions change | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:28:44 | yea | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:29:24 | but the $c_k$'s are always defined so that the $\sum_{k=1}^n \dots$ is equal to $F(b) - F(a)$ | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 510,789,298,321,096,700 | TeXit | 01/29/2022 02:29:27 | **Camilleone** | 569167697925898261.png | 0 | 1 | null | null | null | null | null | ||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:30:03 | we’re taking lim of n on both sides | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:30:06 | and the limit of a constant sequence is just that constant | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:30:14 | so won’t ie affect LHS in some way | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:31:03 | no, because you're going $\lim \sum \dots = \lim (F(b) - F(a)) = F(b) - F(a)$ | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 510,789,298,321,096,700 | TeXit | 01/29/2022 02:31:05 | **Camilleone** | 569167697925898261.png | 0 | 1 | null | null | null | null | null | ||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:31:32 | from the third last line | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:32:31 | why lim (F(b) - F(a)) = F(b) - F(a) | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:33:06 | limit of a constant sequence is that same constant | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:34:07 | constant sequence? | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:35:20 | a sequence $(a_k)$ is said to be constant if $\exists c$ such that $a_k = c$ for all $k$
for such a sequence, $\lim_k a_k = c$. | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 510,789,298,321,096,700 | TeXit | 01/29/2022 02:36:35 | **Camilleone** | 569167697925898261.png | 0 | 1 | null | null | null | null | null | ||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 569,167,697,925,898,240 | Camilleone | 01/29/2022 02:36:43 | sorry, i'm a bit out of it today, sick | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 261,933,205,387,477,000 | riemann | 01/29/2022 02:42:36 | I think that was a good explanation, camil | 0 | 1 | 748,636,086,816,866,400 | !Flip.gg harshithimself | 3587 | !Flip.gg harshithimself | false | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 261,933,205,387,477,000 | riemann | 01/29/2022 02:43:50 | Just to add. It's like dividing up the interval [0, 1] into n parts. | 0 | 1 | 456,226,577,798,135,800 | Deleted User | 0000 | Deleted User | false | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 261,933,205,387,477,000 | riemann | 01/29/2022 02:44:11 | No matter how you divide up the interval, the lengths will always sum to 1 | 0 | 1 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:44:43 | F(x) = int f(t) dt [a, x] here | 1 | 0 | null | null | null | null | null | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 261,933,205,387,477,000 | riemann | 01/29/2022 02:45:21 | Yea and the endpoints are [F(a), F(b)] | 0 | 1 | 701,895,792,763,600,900 | s_chanch | 2633 | s_chanch | false | |||||
205,726 | help-1 | 41e26f76a25345bb9b35f8790cfe531a | 701,895,792,763,600,900 | s_chanch | 01/29/2022 02:46:10 | i still don’t get why taking the limit doesn’t affect LHS | 1 | 0 | 456,226,577,798,135,800 | Deleted User | 0000 | Deleted User | false |
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