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205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 22:51:27 | is the plus (x^2 + i) correct? | 1 | 0 | 220,517,274,845,577,200 | ramonov | 0921 | ℝamonov | false | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 22:51:35 | that says x^2+1 | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 22:51:53 | i^2+1=0 | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 22:53:29 | it might help to remember the conjugate root theorem to understand where i got x^2+1 from. i being a zero implies -i being a zero, implies (x-i)(x+i)=x^2+1 being a factor. | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 22:55:00 | I'm not accustomed with complex numbers yet, but about the exercise I'm sure it's like that | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 22:56:10 | I couldn't interpret the graph in regards to division by 6 | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 22:56:37 | ah, it states = 27 | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 22:57:37 | It does work if g is meant to be an integer polynomial with those conditions | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 22:58:01 | but in the realm of real polynomials, there are certainly many g st g(0) isn't divisible by 6 | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 22:58:30 | when we take out the 0.5 we'd have 54 which is divisible | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 22:58:40 | yes you would. | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 23:00:17 | that doesn't discount the fact that 0.5(x-2)(x-3)^2(x^2+1) is a counterexample | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:02:31 | it wouldn't save the question if I said if we scale the polynomial, we expect to scale the value 6 aswell, no? | 1 | 0 | 220,517,274,845,577,200 | ramonov | 0921 | ℝamonov | false | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:02:55 | because instead of 0.5 we can use any arbitrary scaling | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:03:14 | so division by whole number would get lost definitely | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:03:25 | or not? | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 23:04:07 | This could be me but I can't really figure out what you're trying to say | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 329,749,386,315,956,200 | Sneaky | 12/23/2021 23:04:55 | The simplest way to save the problem would be to say g has to be an integer polynomial, but I don't really like doing the "guess what the question is meant to say" thing | 0 | 1 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:06:21 | I had a fallacy | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:08:25 | well then | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:08:49 | seems like a dead end to me with having your counterexample, so I'll have to ask my tutor | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:09:06 | I thank you for your help @Sneaky | 1 | 0 | null | null | null | null | null | |||||
205,809 | help-1 | 8e56f39d9d704e209d984c55ffabc3ac | 332,164,791,143,759,900 | tarık b. | 12/23/2021 23:09:36 | .close | 1 | 0 | 320,090,412,012,404,740 | Kubra | 2061 | Kubra | false | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 760,358,915,925,475,300 | Intrexa | 01/31/2022 21:14:22 | Hey, I'm stumped on lim(x->pi/2) for (cos^2 x)/(1-sin x). I've tried messing around with substituting identities, either I'm off base, or not seeing it, or w/e | 1 | 0 | null | null | null | null | null | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 760,358,915,925,475,300 | Intrexa | 01/31/2022 21:14:49 | Any help for the answer is good, any insight into the intuition as to why it's the answer is what I'm looking for | 1 | 0 | null | null | null | null | null | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 186,109,587,366,215,680 | Omegabet_ | 01/31/2022 21:15:18 | Hint: Pythagorean identity | 0 | 1 | null | null | null | null | null | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 760,358,915,925,475,300 | Intrexa | 01/31/2022 21:16:05 | I tried throwing that in, (cos^2 x)/(cos^2 x + sin^2 x - sin x), but I'm stumped on that front | 1 | 0 | null | null | null | null | null | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 186,109,587,366,215,680 | Omegabet_ | 01/31/2022 21:16:18 | $\cos^2(x)=1-\sin^2(x)$ | 0 | 1 | null | null | null | null | null | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 510,789,298,321,096,700 | TeXit | 01/31/2022 21:16:20 | **Mosh** | 186109587366215691.png | 0 | 1 | null | null | null | null | null | ||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 760,358,915,925,475,300 | Intrexa | 01/31/2022 21:16:48 | ahhh yeah | 1 | 0 | 320,090,412,012,404,740 | Kubra | 2061 | Kubra | false | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 308,723,121,744,248,800 | noot noot | 01/31/2022 21:17:54 | thanks pythagoras | 0 | 1 | null | null | null | null | null | |||||
205,810 | help-1 | 5e1c9660972744508d4374eef73167e6 | 760,358,915,925,475,300 | Intrexa | 01/31/2022 21:17:57 | .close | 1 | 0 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 760,358,915,925,475,300 | Intrexa | 01/31/2022 21:18:02 | thx all | 1 | 0 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:11:26 | how do i understand what {u, v} is because i set up the equations but don't know how they are equal to {u, v} | unknown.png | 0 | 1 | null | null | null | null | null | ||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:12:24 | wdym? | 0 | 1 | 320,090,412,012,404,740 | Kubra | 2061 | Kubra | false | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:12:53 | i don't know how to set up the system of equations | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:14:35 | ok so lets do the first one together | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:15:11 | we want to see if there are numbers (scalars) a,b such that a*[1,-2] + b * [-2,5] = [-2,5] correct? | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:15:30 | yeah | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:15:58 | ok, so then we simplify the LHS | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:16:14 | we have [a-2a] + [-2b+5b] = [-2,5] | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:16:26 | which implies that a-2b = -2, -2a+5b = 5 | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:16:28 | with me so far? | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:16:51 | we then solve this system of linear equations | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:16:58 | (which im assuming you know how to do) | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:18:16 | ohh i think i understand how you made the system | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:18:20 | yup | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:18:35 | because [a,b] + [c,d] = [a+c, b+d] | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:19:41 | ok then you can prove its a linear combination by finding a and b? | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:33:01 | is the vector a linear combination of {u,v}? i solved the system of equations and got a=0 and b=1 | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:33:15 | great | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:33:20 | yup | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:34:22 | since the A vector is similar to C is it also a correct linear combination? | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:34:47 | what do you mean "similar" | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:34:58 | but to answer your question, you did prove that it is a linear combination | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:35:34 | they are both equal to the given vectors u and v | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:35:56 | i dont see what you mean | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:36:01 | plz give an example | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:36:36 | unknown.png | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:36:36 | unknown.png | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:36:36 | unknown.png | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:37:12 | correct | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:38:33 | are those the only linear combinations in the list? | unknown.png | 0 | 1 | null | null | null | null | null | ||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:38:44 | that is for you to figure out | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:38:47 | repeat the process | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:38:48 | 😉 | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:39:21 | is it only a linear comb if there's a solution to the system | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:39:41 | well yes | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:39:47 | like if u = v = [0,0] | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:40:07 | then if answer H is "The vector [1,1] is a lin. comb. of {u,v} | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:40:09 | it is false | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 714,316,705,303,625,900 | Invictus | 01/31/2022 22:40:11 | get it? | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:40:52 | ohh ok then this probably means all real vectors are linear combinations | 0 | 1 | null | null | null | null | null | |||||
205,811 | help-1 | 5a7aec2de37a4a9588e6f74e2ca31bd1 | 315,292,317,315,629,060 | Ptolemy | 01/31/2022 22:48:17 | @Invictus is choosing every vector that's not a multiple of u1 and u2 a good strategy to tell what's not in the span? | unknown.png | 0 | 1 | null | null | null | null | null | ||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:16:13 | the one sheeted hyperboloid has cartesian eqn: | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:16:40 | x^2/a^2 + y^2/b^2 - z^2/c^2 = 1 | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:16:51 | what do a b c represent here | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:17:05 | geometrically speaking! | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:17:09 | lol | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:19:12 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 551,269,104,800,104,450 | EndTimes | 01/31/2022 23:44:22 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 569,167,697,925,898,240 | Camilleone | 02/01/2022 00:24:04 | geometrically they're the principal semi-axes | 0 | 1 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 183,668,144,404,037,630 | Ann | 02/01/2022 00:51:08 | @EndTimes the 'unit' hyperboloid of one sheet has equation x^2 + y^2 - z^2 = 1 | 0 | 1 | null | null | null | null | null | |||||
205,812 | help-1 | 23adb9c9ea384313bf6c80dbb3393f7a | 183,668,144,404,037,630 | Ann | 02/01/2022 00:51:22 | dilating it by a, b and c along the x, y and z axes gives yours | 0 | 1 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:27:44 | Hey Guys, I have a problem with the calculation
I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not: | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:27:44 | Hey Guys, I have a problem with the calculation
I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not: | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:28:17 | Also, I got out for x1 = 1.5, for x2 =0 and for x3 = -1 | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:29:34 | Or was I wrong to use the Gauss Algorithm here? | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 510,789,298,321,096,700 | TeXit | 02/01/2022 02:32:50 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 706,934,233,012,371,600 | Ansh_ | 02/01/2022 02:33:17 | hmm the Z7 | 0 | 1 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:33:45 | Well, I was a bit confused because I'm limited to the body ZZ7 right? This one | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:34:16 | Or maybe its called a "field" in english | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:34:35 | So the number only goes from 0 up to 6 | 1 | 0 | 320,090,412,012,404,740 | Kubra | 2061 | Kubra | false | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:34:42 | (I think) | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 02:41:53 | yup | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 03:42:42 | Well, if no one knows the answer to those, I would need help with something else as well | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 03:43:18 | Give the generator polynomials and the corresponding generator matrices and control polynomials of all 6-digit cyclic codes with 3 control digits over Z5. | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 236,549,522,178,834,430 | Revogue | 02/01/2022 03:43:43 | And I'm absolutely confused on how I can do that | 1 | 0 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 915,938,343,857,037,300 | Quincy | 02/01/2022 04:05:27 | If u know inverse matrix, then just multiply inverse of the 3*3 matrix to both the sides. The LHS become only x1,x2,x3 and RHS will be inv(3*3) matrix * (1,3,1) matrix | 0 | 1 | null | null | null | null | null | |||||
205,813 | help-1 | 3cb2f7639f2549b1a75e0907763ac032 | 595,185,421,743,554,600 | Sepdron | 02/01/2022 04:27:27 | i think i know how to do it, i think it's like gauss algorithm but instead of dividing, you multiply it by its multiplicative inverse in the finite field
i think it helps if you make the multiplication table for the finite field first | 0 | 1 | null | null | null | null | null |
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