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help-10
ceae3f82efb743a59d56be209e856fa6
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physilei
01/24/2022 19:55:05
Sry guys
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physilei
01/24/2022 19:55:08
.close
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blue™
01/24/2022 21:33:33
Hi
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blue™
01/24/2022 21:35:22
The line L goes through O(0,0,0) and is perpendicular to the line k: λ(1,0,1). The line L makes an φ angle with the y-axis so that cos φ = 1/3
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help-10
f33d950fb8ef485b8f291bb41c6a1a8f
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blue™
01/24/2022 21:35:30
Give a vector equation of line L
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help-10
f33d950fb8ef485b8f291bb41c6a1a8f
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blue™
01/24/2022 21:35:48
So if it’s perpendicular to K i have this: a + c = 0
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help-10
f33d950fb8ef485b8f291bb41c6a1a8f
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blue™
01/24/2022 21:36:00
I have tried with inproduct but there are too many variables for me to have an answer
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help-10
f33d950fb8ef485b8f291bb41c6a1a8f
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blue™
01/24/2022 21:36:05
So i don’t know what to do now
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blue™
01/24/2022 21:51:16
@Helpers
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coldfloor
01/24/2022 21:52:03
Idk it either lol
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blue™
01/24/2022 21:56:02
Lol my classmates also don’t and teacher is not responding to messages 🥲
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blue™
01/24/2022 22:35:50
.close
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eswag
01/24/2022 22:45:08
hello
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eswag
01/24/2022 22:45:34
I am sort of confused as to what the word calculate in this sense means
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 22:48:01
get rid of the infinite sum
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help-10
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eswag
01/24/2022 22:48:09
so convert it into a function?
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 22:48:26
it's a function even if it has an infinite sum
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help-10
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rept1d
01/24/2022 22:49:06
but the task is most likely about expressing it using elementary functions
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help-10
a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 22:49:07
so how does one get rid of the infinite sum
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help-10
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eswag
01/24/2022 22:49:19
yea i guess that sounds about right
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eswag
01/24/2022 22:49:56
okay that makes a little more sense - i thought i had to find a numerical value or something like that and i was confused
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 22:51:09
do you know what is the value of a series?
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help-10
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eswag
01/24/2022 22:51:31
honestly i forgot all about series i studied this stuff 6 months ago
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help-10
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rept1d
01/24/2022 22:53:52
by definition \[ \sum_{n=1}^\infty f_n(x) = \lim_{k \to \infty}\sum_{n=k}^\infty f_n(x) \]
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help-10
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TeXit
01/24/2022 22:53:54
**rept1d**
https://cdn.discordapp.c…478529998860.png
586955478529998860.png
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 22:54:09
and there are also some helpful formulas
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help-10
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eswag
01/24/2022 22:54:51
but is this problem specifically looking for the value of that series?
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rept1d
01/24/2022 22:57:01
yes, they just probably want you to use the given fact
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help-10
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rept1d
01/24/2022 22:58:04
the first one is obvious for example
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eswag
01/24/2022 22:58:31
yeah i gotta see how to apply this then
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help-10
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rept1d
01/24/2022 23:01:04
\[ \sum_{n=1}^\infty p (1-p)^{n-1} = p \sum_{n=0}^\infty (1-p)^n = \frac{p}{1-(1-p)} = 1 \]
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help-10
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TeXit
01/24/2022 23:01:07
**rept1d**
https://cdn.discordapp.c…478529998860.png
586955478529998860.png
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help-10
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eswag
01/24/2022 23:02:18
ohhh
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eswag
01/24/2022 23:02:57
yea i gotta refresh on these
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help-10
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eswag
01/24/2022 23:03:01
thank you for your help @rept1d
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help-10
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rept1d
01/24/2022 23:03:09
np
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eswag
01/24/2022 23:07:11
@rept1d sorry one more quesiton
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help-10
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eswag
01/24/2022 23:07:19
would part b just be constant of integration + 1 then?
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help-10
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eswag
01/24/2022 23:07:28
not sure if thats how you should represent your answer
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help-10
a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:09:25
im probably trolling nvm
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rept1d
01/24/2022 23:10:23
it'd be (1-x)^n, not n-1
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help-10
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rept1d
01/24/2022 23:10:27
so the sum is starting from n=1
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rept1d
01/24/2022 23:10:40
you've probably missed that
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help-10
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eswag
01/24/2022 23:10:50
yeah i noticed that
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help-10
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rept1d
01/24/2022 23:15:49
did you get an answer?
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help-10
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eswag
01/24/2022 23:16:13
Nah im stuck i’m trying to find resources to study from but i’m not in luck
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help-10
a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:16:38
Assuming this is a geometric series
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help-10
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rept1d
01/24/2022 23:16:46
where exactly are you stuck?
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help-10
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eswag
01/24/2022 23:16:57
I did the integral which was easy
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help-10
a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:17:04
So just the constant + the integrated series
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eswag
01/24/2022 23:17:13
And the bound is still at n = 1
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help-10
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eswag
01/24/2022 23:17:33
But i’m stuck at what to do next
1
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help-10
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eswag
01/24/2022 23:19:31
Do i just take the limit?
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help-10
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rept1d
01/24/2022 23:20:20
that's another possibility (and is much easier in my opinion), but let's still discuss the method the book wants
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rept1d
01/24/2022 23:21:22
I assume you know how the formula of the derivative of power series
0
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help-10
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rept1d
01/24/2022 23:21:26
https://cdn.discordapp.c…6278/unknown.png
unknown.png
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help-10
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eswag
01/24/2022 23:21:31
Yeah
1
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rept1d
01/24/2022 23:21:43
in our case k=1, so it's very simple
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help-10
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rept1d
01/24/2022 23:22:57
do you agree that \[ \sum_{n=1}^\infty np(1-p)^{n-1} = -p \qty(\sum_{n=1}^\infty (1-p)^n)' \]
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eswag
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help-10
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rept1d
01/24/2022 23:23:11
a mistake
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rept1d
01/24/2022 23:23:12
wait
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help-10
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eswag
01/24/2022 23:23:15
Positive p
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help-10
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rept1d
01/24/2022 23:23:31
no
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eswag
01/24/2022 23:23:38
Oh
1
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TeXit
01/24/2022 23:23:42
**rept1d**
https://cdn.discordapp.c…478529998860.png
586955478529998860.png
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a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 23:23:47
now it should be right
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eswag
01/24/2022 23:23:52
Oh its because 1-p
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rept1d
01/24/2022 23:23:56
yes
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eswag
01/24/2022 23:24:14
Yes
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eswag
01/24/2022 23:24:16
I see that
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a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 23:24:17
can you go from here?
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a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:24:47
Oh I accidentally took the integral lol
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help-10
a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:24:52
I guess there was no point in doing that
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rept1d
01/24/2022 23:25:38
kinda true
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eswag
01/24/2022 23:25:44
I got it yeah just use the derivative formula
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help-10
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rept1d
01/24/2022 23:25:53
the answer should be 1/p
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help-10
a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:25:56
And then the bound will be n = 0
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 23:27:01
i might have misunderstood you, but the derivative formula has been used already
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eswag
01/24/2022 23:27:24
Yeah im lost then
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 23:27:28
i mean \[ \sum_{n=1}^\infty np(1-p)^{n-1} = -p \sum_{n=1}^\infty \qty((1-p)^n)' = -p \qty(\sum_{n=1}^\infty (1-p)^n)' \]
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help-10
a0ba10ff794242659235550ebe7d8311
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rept1d
01/24/2022 23:27:37
that's how we got there
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a0ba10ff794242659235550ebe7d8311
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eswag
01/24/2022 23:27:41
I’m unable to understand how to evaluate with the n=1
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null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:28:03
We cant make the exponent n-1 right?
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
586,955,478,529,998,800
rept1d
01/24/2022 23:28:06
evaluate with n = 0 and then subtract f_0(p)
0
1
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
510,789,298,321,096,700
TeXit
01/24/2022 23:29:39
**rept1d**
https://cdn.discordapp.c…478529998860.png
586955478529998860.png
0
1
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:29:55
Okay
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:30:21
But if you evaluate with n = 0
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:30:26
You must change the exponent to n-1
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
586,955,478,529,998,800
rept1d
01/24/2022 23:30:46
do you?
0
1
587,696,976,951,377,900
eswag
3269
eswag
false
272
help-10
a0ba10ff794242659235550ebe7d8311
586,955,478,529,998,800
rept1d
01/24/2022 23:30:50
look at the formula at the top
0
1
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
586,955,478,529,998,800
rept1d
01/24/2022 23:30:55
it's just x^n
0
1
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:31:11
It is but how do we start at n = 0 if its n = 1
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:31:47
We can just start at n = 0 and remove the first term?
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
586,955,478,529,998,800
rept1d
01/24/2022 23:31:55
Yes, that's what I said
0
1
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:32:00
Ah right
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:43:31
Well i think i got the steps
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:43:50
I just used the general formula of the sum of the series though
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:43:55
I didnt understand the subtraction part
1
0
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
586,955,478,529,998,800
rept1d
01/24/2022 23:44:20
:(
0
1
null
null
null
null
null
272
help-10
a0ba10ff794242659235550ebe7d8311
587,696,976,951,377,900
eswag
01/24/2022 23:44:39
https://cdn.discordapp.c…BEC2360FD4BD.jpg
EAF99FAE-B4AC-4B48-B260-BEC2360FD4BD.jpg
1
0
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null
null