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[ { "content": "Return your final response within \\boxed{} and only include the letter choice (A, B, C, or D) as your final response.\nProblem: Identify the compound C9H11NO2 using the given data.\nIR: medium to strong intensity bands at 3420 cm-1, 3325 cm-1\nstrong band at 1720 cm-1\n1H NMR: 1.20 ppm (t, 3H); 4...
{ "do_sample": true, "max_new_tokens": 32768, "seed": 2, "temperature": 0.7 }
2
46
GPQADiamond
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
Let's break down the problem step by step. First, the molecular formula is C9H11NO2. That means the compound has 9 carbon atoms, 11 hydrogen atoms, 1 nitrogen atom, and 2 oxygen atoms. Let's look at each option and see which one fits. Starting with option A: N-(4-ethoxyphenyl)formamide. Let's parse this. The parent s...
[ { "content": "Problem: What is the product of all solutions to the equation\n\\[\\log_{7x}2023\\cdot \\log_{289x}2023=\\log_{2023x}2023\\]\nMark your solution with \\boxed\nAnswer:", "role": "user" } ]
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3
8
AMC23
{ "expected_answer": "1", "problem_id": "10", "reference_solution": "", "subject": null, "type": null }
To solve the equation \(\log_{7x}2023 \cdot \log_{289x}2023 = \log_{2023x}2023\), we start by letting \(y = \log_{2023} x\). This substitution can help simplify the logarithmic expressions. First, recall the change of base formula for logarithms: \(\log_a b = \frac{\log_c b}{\log_c a}\). Using this, we can rewrite ea...
[ { "content": "Generate an executable Python function generated from the given prompt. Return the function body without invoking it at the final solution.You are given a 0-indexed 2D integer array nums. Initially, your score is 0. Perform the following operations until the matrix becomes empty:\n\nFrom each row ...
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0
10
LiveCodeBench
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
<think> Okay, I need to create a Python function that calculates the final score based on the given matrix operations. Let me think through how to approach this. First, the problem says that in each iteration, we select the largest number from each row, remove it, and then add the highest of those removed numbers to o...
[ { "content": "In this problem, multiple options can be correct. Give a detailed solution and end the solution with the final answer. Mark your solution, which should be one or more multiple-choice letter(s), with \\boxed\nAnswer:\n\nProblem: Addition of excess aqueous ammonia to a pink coloured aqueous solution...
{ "do_sample": false, "max_new_tokens": 32768, "seed": 0, "temperature": 0.7 }
0
78
JEEBench
{ "expected_answer": "BCD", "problem_id": "23", "reference_solution": null, "subject": "chem", "type": "MCQ(multiple)" }
To solve this problem, we need to analyze the given chemical transformations and properties of the complexes involved. Let's break down the problem step by step. ### Step 1: Understanding the Complexes and Reactions 1. **Complex X**: It is given as \(\mathrm{MCl}_2 \cdot 6\mathrm{H}_2\mathrm{O}\) with a pink color. Wh...
[ { "content": "Problem: The asymptotes of a hyperbola are $y = 2x - 3$ and $y = 17 - 2x.$ Also, the hyperbola passes through the point $(4,7).$ Find the distance between the foci of the hyperbola.\nMark your solution with \\boxed\nAnswer:", "role": "user" } ]
{ "do_sample": false, "max_new_tokens": 32768, "seed": 0, "temperature": 0.7 }
0
409
MATH500
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
To find the distance between the foci of the hyperbola, we start by determining the equation of the hyperbola given its asymptotes and a point it passes through. The asymptotes are given by the equations \(y = 2x - 3\) and \(y = 17 - 2x\). First, we find the center of the hyperbola. The center is the intersection poi...
[ { "content": "Problem: For how many integers $n$ does the expression\\[\\sqrt{\\frac{\\log (n^2) - (\\log n)^2}{\\log n - 3}}\\]represent a real number, where log denotes the base $10$ logarithm?\nMark your solution with \\boxed\nAnswer:", "role": "user" } ]
{ "do_sample": false, "max_new_tokens": 32768, "seed": 0, "temperature": 0.7 }
0
37
AMC23
{ "expected_answer": "901", "problem_id": "47", "reference_solution": "", "subject": null, "type": null }
To determine for how many integers \( n \) the expression \[ \sqrt{\frac{\log (n^2) - (\log n)^2}{\log n - 3}} \] represents a real number, we need to analyze the conditions under which the expression inside the square root is non-negative. Let's denote \( \log n \) by \( x \). Then the expression becomes: \[ \sqrt...
[ { "content": "Generate an executable Python function generated from the given prompt. Return the function body without invoking it at the final solution.You are given a 0-indexed string s, a string a, a string b, and an integer k.\nAn index i is beautiful if:\n\n0 <= i <= s.length - a.length\ns[i..(i + a.length...
{ "do_sample": false, "max_new_tokens": 32768, "seed": 1, "temperature": 0.7 }
1
163
LiveCodeBench
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
<think> Okay, I need to solve this problem where I have to find all the beautiful indices in the string 's' based on the given strings 'a' and 'b' and an integer 'k'. Let me try to understand the problem carefully. First, a beautiful index 'i' must satisfy certain conditions. The index 'i' should be within the length ...
[ { "content": "Generate an executable Python function generated from the given prompt. The function should take stdin as input and print the output. Simply call the function after the definition.You are given N integers A_1, A_2, \\dots, A_N.\r\nAlso, define B_i = A_i \\times A_{i+1}\\ (1 \\leq i \\leq N-1).\nPr...
{ "do_sample": false, "max_new_tokens": 32768, "seed": 2, "temperature": 0.7 }
2
410
LiveCodeBench
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
<nobr><font face="Helvetica, Arial, sans-serif">Alright, I need to write a Python function that takes N integers as input and prints the product of consecutive pairs. Let me think through this step by step. First, the input is read from stdin. The first line gives N, the number of integers. The second line is the list...
[ { "content": "Generate an executable Python function generated from the given prompt. The function should take stdin as input and print the output. Simply call the function after the definition.Takahashi has placed N gifts on a number line. The i-th gift is placed at coordinate A_i.\nYou will choose a half-open...
{ "do_sample": false, "max_new_tokens": 32768, "seed": 1, "temperature": 0.7 }
1
313
LiveCodeBench
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
def solve(): import sys input = sys.stdin.readline n, m = map(int, input().split()) a = sorted(map(int, input().split())) left = 0 right = m ans = 0 while left <= right: mid = (left + right) // 2 cnt = 0 pos = 0 for i in range(n): if ...
[ { "content": "Problem: Simplify $\\tan 100^\\circ + 4 \\sin 100^\\circ.$\nMark your solution with \\boxed\nAnswer:", "role": "user" } ]
{ "do_sample": false, "max_new_tokens": 32768, "seed": 0, "temperature": 0.7 }
0
164
MATH500
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
To simplify \(\tan 100^\circ + 4 \sin 100^\circ\), we start by expressing the tangent function in terms of sine and cosine. Recall that \(\tan \theta = \frac{\sin \theta}{\cos \theta}\). Therefore, we can rewrite the given expression as: \[ \frac{\sin 100^\circ}{\cos 100^\circ} + 4 \sin 100^\circ \] Next, we factor o...
[ { "content": "Return your final response within \\boxed{{}} and only include the letter choice (A, B, C, D, E, F, G, H, I, or J) as your final response.\nProblem: A \"strictly binary tree\" is a binary tree in which every node that is not a leaf has two children. Suppose that for a class of strictly binary tree...
{ "do_sample": true, "max_new_tokens": 32768, "seed": 0, "temperature": 0.7 }
0
26
MMLUPro
{ "expected_answer": "", "problem_id": "", "reference_solution": "", "subject": null, "type": null }
To solve this problem, we need to understand the properties of a strictly binary tree and the given condition about the ratio of the lengths of any two root-to-leaf paths being bounded by a constant \( c \). First, let's recall that in a strictly binary tree, every non-leaf node has exactly two children. This means t...
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mlfoundations-dev/a1_code_stackexchange_1744693112_eval_1331

Precomputed model outputs for evaluation.

Evaluation Results

Summary

Metric AIME24 AMC23 MATH500 GPQADiamond JEEBench MMLUPro LiveCodeBench CodeElo
Accuracy 15.7 54.8 71.2 37.4 37.5 29.0 11.0 5.2

AIME24

  • Average Accuracy: 15.67% ± 0.95%
  • Number of Runs: 10
Run Accuracy Questions Solved Total Questions
1 20.00% 6 30
2 16.67% 5 30
3 16.67% 5 30
4 20.00% 6 30
5 16.67% 5 30
6 16.67% 5 30
7 13.33% 4 30
8 13.33% 4 30
9 13.33% 4 30
10 10.00% 3 30

AMC23

  • Average Accuracy: 54.75% ± 1.30%
  • Number of Runs: 10
Run Accuracy Questions Solved Total Questions
1 65.00% 26 40
2 57.50% 23 40
3 50.00% 20 40
4 52.50% 21 40
5 55.00% 22 40
6 52.50% 21 40
7 52.50% 21 40
8 52.50% 21 40
9 52.50% 21 40
10 57.50% 23 40

MATH500

  • Accuracy: 71.20%
    Accuracy Questions Solved Total Questions
    71.20% 356 500

GPQADiamond

  • Average Accuracy: 37.37% ± 2.49%
  • Number of Runs: 3
Run Accuracy Questions Solved Total Questions
1 31.31% 62 198
2 40.91% 81 198
3 39.90% 79 198

JEEBench

  • Average Accuracy: 37.48% ± 0.70%
  • Number of Runs: 3
Run Accuracy Questions Solved Total Questions
1 38.79% 199.75 515
2 35.87% 184.75 515
3 37.77% 194.5 515

MMLUPro

  • Average Accuracy: 29.00% ± 0.00%
  • Number of Runs: 1
Run Accuracy Questions Solved Total Questions
1 29.00% 145 500

LiveCodeBench

  • Average Accuracy: 10.96% ± 0.88%
  • Number of Runs: 3
Run Accuracy Questions Solved Total Questions
1 12.72% 65 511
2 10.18% 52 511
3 9.98% 51 511

CodeElo

  • Average Accuracy: 5.20% ± 0.70%
  • Number of Runs: 3
Run Accuracy Questions Solved Total Questions
1 5.63% 22 391
2 3.84% 15 391
3 6.14% 24 391
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