db_id
stringlengths
4
31
SQL
stringlengths
18
1.45k
input_sequence
stringlengths
148
11k
question
stringlengths
16
325
store_1
select first_name , last_name from employees order by birth_date desc limit 1;
Question: what si the youngest employee's first and last name? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, fi...
what si the youngest employee's first and last name?
store_1
select first_name , last_name from employees order by hire_date asc limit 10;
Question: list top 10 employee work longest in the company. list employee's first and last name. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phon...
list top 10 employee work longest in the company. list employee's first and last name.
store_1
select first_name , last_name from employees order by hire_date asc limit 10;
Question: what are the first and last names of the top 10 longest-serving employees? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, emai...
what are the first and last names of the top 10 longest-serving employees?
store_1
select count(*) , city from employees where title = 'it staff' group by city
Question: find the number of employees whose title is it staff from each city? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. cus...
find the number of employees whose title is it staff from each city?
store_1
select count(*) , city from employees where title = 'it staff' group by city
Question: how many employees who are it staff are from each city? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id,...
how many employees who are it staff are from each city?
store_1
select t2.first_name , t2.last_name , count(t1.reports_to) from employees as t1 join employees as t2 on t1.reports_to = t2.id group by t1.reports_to order by count(t1.reports_to) desc limit 1;
Question: which employee manage most number of peoples? list employee's first and last name, and number of people report to that employee. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, addres...
which employee manage most number of peoples? list employee's first and last name, and number of people report to that employee.
store_1
select t2.first_name , t2.last_name , count(t1.reports_to) from employees as t1 join employees as t2 on t1.reports_to = t2.id group by t1.reports_to order by count(t1.reports_to) desc limit 1;
Question: what are the first and last names of all the employees and how many people report to them? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, ...
what are the first and last names of all the employees and how many people report to them?
store_1
select count(*) from customers as t1 join invoices as t2 on t1.id = t2.customer_id where t1.first_name = 'lucas' and t1.last_name = 'mancini';
Question: how many orders does lucas mancini has? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, las...
how many orders does lucas mancini has?
store_1
select count(*) from customers as t1 join invoices as t2 on t1.id = t2.customer_id where t1.first_name = 'lucas' and t1.last_name = 'mancini';
Question: how many orders does luca mancini have in his invoices? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id,...
how many orders does luca mancini have in his invoices?
store_1
select sum(t2.total) from customers as t1 join invoices as t2 on t1.id = t2.customer_id where t1.first_name = 'lucas' and t1.last_name = 'mancini';
Question: what is the total amount of money spent by lucas mancini? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> i...
what is the total amount of money spent by lucas mancini?
store_1
select sum(t2.total) from customers as t1 join invoices as t2 on t1.id = t2.customer_id where t1.first_name = 'lucas' and t1.last_name = 'mancini';
Question: how much money did lucas mancini spend? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, las...
how much money did lucas mancini spend?
store_1
select name from media_types;
Question: list all media types. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, last_name, company, a...
list all media types.
store_1
select name from media_types;
Question: what are the names of all the media types? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, ...
what are the names of all the media types?
store_1
select distinct name from genres;
Question: list all different genre types. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, last_name, ...
list all different genre types.
store_1
select distinct name from genres;
Question: what are the different names of the genres? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name,...
what are the different names of the genres?
store_1
select name from playlists;
Question: list the name of all playlist. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, last_name, c...
list the name of all playlist.
store_1
select name from playlists;
Question: what are the names of all the playlists? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, la...
what are the names of all the playlists?
store_1
select composer from tracks where name = 'fast as a shark';
Question: who is the composer of track fast as a shark? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_nam...
who is the composer of track fast as a shark?
store_1
select composer from tracks where name = 'fast as a shark';
Question: what is the composer who created the track 'fast as a shark'? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers ...
what is the composer who created the track 'fast as a shark'?
store_1
select milliseconds from tracks where name = 'fast as a shark';
Question: how long does track fast as a shark has? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, la...
how long does track fast as a shark has?
store_1
select milliseconds from tracks where name = 'fast as a shark';
Question: how many milliseconds long is fast as a shark? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_na...
how many milliseconds long is fast as a shark?
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id where t1.name = 'rock';
Question: what is the name of tracks whose genre is rock? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_n...
what is the name of tracks whose genre is rock?
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id where t1.name = 'rock';
Question: what is the name of all tracks in the rock genre? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first...
what is the name of all tracks in the rock genre?
store_1
select t1.title from albums as t1 join tracks as t2 on t1.id = t2.genre_id where t2.name = 'balls to the wall';
Question: what is title of album which track balls to the wall belongs to? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. custome...
what is title of album which track balls to the wall belongs to?
store_1
select t1.title from albums as t1 join tracks as t2 on t1.id = t2.genre_id where t2.name = 'balls to the wall';
Question: what is the name of the album that has the track ball to the wall? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. custo...
what is the name of the album that has the track ball to the wall?
store_1
select t2.name from albums as t1 join tracks as t2 on t1.id = t2.genre_id where t1.title = 'balls to the wall';
Question: list name of all tracks in balls to the wall. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_nam...
list name of all tracks in balls to the wall.
store_1
select t2.name from albums as t1 join tracks as t2 on t1.id = t2.genre_id where t1.title = 'balls to the wall';
Question: what is the name of all tracks in the album named balls to the wall? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. cus...
what is the name of all tracks in the album named balls to the wall?
store_1
select t1.title from albums as t1 join tracks as t2 on t1.id = t2.album_id group by t1.id having count(t1.id) > 10;
Question: list title of albums have the number of tracks greater than 10. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customer...
list title of albums have the number of tracks greater than 10.
store_1
select t1.title from albums as t1 join tracks as t2 on t1.id = t2.album_id group by t1.id having count(t1.id) > 10;
Question: what are the names of the albums that have more than 10 tracks? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customer...
what are the names of the albums that have more than 10 tracks?
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id join media_types as t3 on t3.id = t2.media_type_id where t1.name = 'rock' and t3.name = 'mpeg audio file';
Question: list the name of tracks belongs to genre rock and whose media type is mpeg audio file. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phon...
list the name of tracks belongs to genre rock and whose media type is mpeg audio file.
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id join media_types as t3 on t3.id = t2.media_type_id where t1.name = 'rock' and t3.name = 'mpeg audio file';
Question: what are the names of all rock tracks that are stored on mpeg audio files? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, emai...
what are the names of all rock tracks that are stored on mpeg audio files?
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id join media_types as t3 on t3.id = t2.media_type_id where t1.name = 'rock' or t3.name = 'mpeg audio file';
Question: list the name of tracks belongs to genre rock or media type is mpeg audio file. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax,...
list the name of tracks belongs to genre rock or media type is mpeg audio file.
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id join media_types as t3 on t3.id = t2.media_type_id where t1.name = 'rock' or t3.name = 'mpeg audio file';
Question: what are the names of all tracks that belong to the rock genre and whose media type is mpeg? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code...
what are the names of all tracks that belong to the rock genre and whose media type is mpeg?
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id where t1.name = 'rock' or t1.name = 'jazz'
Question: list the name of tracks belongs to genre rock or genre jazz. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -...
list the name of tracks belongs to genre rock or genre jazz.
store_1
select t2.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id where t1.name = 'rock' or t1.name = 'jazz'
Question: what are the names of the tracks that are rock or jazz songs? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers ...
what are the names of the tracks that are rock or jazz songs?
store_1
select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t3.id = t2.playlist_id where t3.name = 'movies';
Question: list the name of all tracks in the playlists of movies. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id,...
list the name of all tracks in the playlists of movies.
store_1
select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t3.id = t2.playlist_id where t3.name = 'movies';
Question: what are the names of all tracks that are on playlists titled movies? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. cu...
what are the names of all tracks that are on playlists titled movies?
store_1
select t2.name from playlist_tracks as t1 join playlists as t2 on t2.id = t1.playlist_id group by t1.playlist_id having count(t1.track_id) > 100;
Question: list the name of playlist which has number of tracks greater than 100. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. c...
list the name of playlist which has number of tracks greater than 100.
store_1
select t2.name from playlist_tracks as t1 join playlists as t2 on t2.id = t1.playlist_id group by t1.playlist_id having count(t1.track_id) > 100;
Question: what are the names of all playlists that have more than 100 tracks? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. cust...
what are the names of all playlists that have more than 100 tracks?
store_1
select t1.name from tracks as t1 join invoice_lines as t2 on t1.id = t2.track_id join invoices as t3 on t3.id = t2.invoice_id join customers as t4 on t4.id = t3.customer_id where t4.first_name = 'daan' and t4.last_name = 'peeters';
Question: list all tracks bought by customer daan peeters. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_...
list all tracks bought by customer daan peeters.
store_1
select t1.name from tracks as t1 join invoice_lines as t2 on t1.id = t2.track_id join invoices as t3 on t3.id = t2.invoice_id join customers as t4 on t4.id = t3.customer_id where t4.first_name = 'daan' and t4.last_name = 'peeters';
Question: what are the tracks that dean peeters bought? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_nam...
what are the tracks that dean peeters bought?
store_1
select unit_price from tracks where name = 'fast as a shark';
Question: how much is the track fast as a shark? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, last...
how much is the track fast as a shark?
store_1
select unit_price from tracks where name = 'fast as a shark';
Question: what is the unit price of the tune 'fast as a shark'? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, f...
what is the unit price of the tune 'fast as a shark'?
store_1
select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name = 'movies' except select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name = ...
Question: find the name of tracks which are in movies playlist but not in music playlist. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax,...
find the name of tracks which are in movies playlist but not in music playlist.
store_1
select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name = 'movies' except select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name = ...
Question: what are the names of all tracks that are on the movies playlist but not in the music playlist? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_c...
what are the names of all tracks that are on the movies playlist but not in the music playlist?
store_1
select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name = 'movies' intersect select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name ...
Question: find the name of tracks which are in both movies and music playlists. | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. cu...
find the name of tracks which are in both movies and music playlists.
store_1
select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name = 'movies' intersect select t1.name from tracks as t1 join playlist_tracks as t2 on t1.id = t2.track_id join playlists as t3 on t2.playlist_id = t3.id where t3.name ...
Question: what are the names of all the tracks that are in both the movies and music playlists? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone...
what are the names of all the tracks that are in both the movies and music playlists?
store_1
select count(*) , t1.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id group by t1.name;
Question: find number of tracks in each genre? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, last_n...
find number of tracks in each genre?
store_1
select count(*) , t1.name from genres as t1 join tracks as t2 on t1.id = t2.genre_id group by t1.name;
Question: how many tracks are in each genre? | Tables: artists -> id, name. sqlite_sequence -> name, seq. albums -> id, title, artist_id. employees -> id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email. customers -> id, first_name, last_nam...
how many tracks are in each genre?
journal_committee
select count(*) from editor
Question: how many editors are there? | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
how many editors are there?
journal_committee
select name from editor order by age asc
Question: list the names of editors in ascending order of age. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
list the names of editors in ascending order of age.
journal_committee
select name , age from editor
Question: what are the names and ages of editors? | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
what are the names and ages of editors?
journal_committee
select name from editor where age > 25
Question: list the names of editors who are older than 25. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
list the names of editors who are older than 25.
journal_committee
select name from editor where age = 24 or age = 25
Question: show the names of editors of age either 24 or 25. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
show the names of editors of age either 24 or 25.
journal_committee
select name from editor order by age asc limit 1
Question: what is the name of the youngest editor? | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
what is the name of the youngest editor?
journal_committee
select age , count(*) from editor group by age
Question: what are the different ages of editors? show each age along with the number of editors of that age. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_co...
what are the different ages of editors? show each age along with the number of editors of that age.
journal_committee
select age from editor group by age order by count(*) desc limit 1
Question: please show the most common age of editors. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
please show the most common age of editors.
journal_committee
select distinct theme from journal
Question: show the distinct themes of journals. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_ID,
show the distinct themes of journals.
journal_committee
select t2.name , t3.theme from journal_committee as t1 join editor as t2 on t1.editor_id = t2.editor_id join journal as t3 on t1.journal_id = t3.journal_id
Question: show the names of editors and the theme of journals for which they serve on committees. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Edit...
show the names of editors and the theme of journals for which they serve on committees.
journal_committee
select t2.name , t3.theme from journal_committee as t1 join editor as t2 on t1.editor_id = t2.editor_id join journal as t3 on t1.journal_id = t3.journal_id
Question: for each journal_committee, find the editor name and the journal theme. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.E...
for each journal_committee, find the editor name and the journal theme.
journal_committee
select t2.name , t2.age , t3.theme from journal_committee as t1 join editor as t2 on t1.editor_id = t2.editor_id join journal as t3 on t1.journal_id = t3.journal_id order by t3.theme asc
Question: show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Jour...
show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme.
journal_committee
select t2.name from journal_committee as t1 join editor as t2 on t1.editor_id = t2.editor_id join journal as t3 on t1.journal_id = t3.journal_id where t3.sales > 3000
Question: show the names of editors that are on the committee of journals with sales bigger than 3000. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee...
show the names of editors that are on the committee of journals with sales bigger than 3000.
journal_committee
select t1.editor_id , t1.name , count(*) from editor as t1 join journal_committee as t2 on t1.editor_id = t2.editor_id group by t1.editor_id
Question: show the id, name of each editor and the number of journal committees they are on. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID...
show the id, name of each editor and the number of journal committees they are on.
journal_committee
select t1.name from editor as t1 join journal_committee as t2 on t1.editor_id = t2.editor_id group by t1.name having count(*) >= 2
Question: show the names of editors that are on at least two journal committees. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Ed...
show the names of editors that are on at least two journal committees.
journal_committee
select name from editor where editor_id not in (select editor_id from journal_committee)
Question: list the names of editors that are not on any journal committee. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Editor_ID = editor.Editor_I...
list the names of editors that are not on any journal committee.
journal_committee
select date , theme , sales from journal except select t1.date , t1.theme , t1.sales from journal as t1 join journal_committee as t2 on t1.journal_id = t2.journal_id
Question: list the date, theme and sales of the journal which did not have any of the listed editors serving on committee. | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_I...
list the date, theme and sales of the journal which did not have any of the listed editors serving on committee.
journal_committee
select avg(t1.sales) from journal as t1 join journal_committee as t2 on t1.journal_id = t2.journal_id where t2.work_type = 'photo'
Question: what is the average sales of the journals that have an editor whose work type is 'photo'? | Tables: journal -> Journal_ID, Date, Theme, Sales. editor -> Editor_ID, Name, Age. journal_committee -> Editor_ID, Journal_ID, Work_Type. | Joins: journal_committee.Journal_ID = journal.Journal_ID, journal_committee.Ed...
what is the average sales of the journals that have an editor whose work type is 'photo'?
customers_card_transactions
select count(*) from accounts
Question: how many accounts do we have? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_type_code...
how many accounts do we have?
customers_card_transactions
select count(*) from accounts
Question: count the number of accounts. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_type_code...
count the number of accounts.
customers_card_transactions
select account_id , customer_id , account_name from accounts
Question: show ids, customer ids, names for all accounts. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_...
show ids, customer ids, names for all accounts.
customers_card_transactions
select account_id , customer_id , account_name from accounts
Question: what are the account ids, customer ids, and account names for all the accounts? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Custo...
what are the account ids, customer ids, and account names for all the accounts?
customers_card_transactions
select other_account_details from accounts where account_name = '338'
Question: show other account details for account with name 338. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, cus...
show other account details for account with name 338.
customers_card_transactions
select other_account_details from accounts where account_name = '338'
Question: what are the other account details for the account with the name 338? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards...
what are the other account details for the account with the name 338?
customers_card_transactions
select t2.customer_first_name , t2.customer_last_name , t2.customer_phone from accounts as t1 join customers as t2 on t1.customer_id = t2.customer_id where t1.account_name = '162'
Question: what is the first name, last name, and phone of the customer with account name 162? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. C...
what is the first name, last name, and phone of the customer with account name 162?
customers_card_transactions
select t2.customer_first_name , t2.customer_last_name , t2.customer_phone from accounts as t1 join customers as t2 on t1.customer_id = t2.customer_id where t1.account_name = '162'
Question: give the full name and phone of the customer who has the account name 162. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_...
give the full name and phone of the customer who has the account name 162.
customers_card_transactions
select count(*) from accounts as t1 join customers as t2 on t1.customer_id = t2.customer_id where t2.customer_first_name = 'art' and t2.customer_last_name = 'turcotte'
Question: how many accounts does the customer with first name art and last name turcotte have? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. ...
how many accounts does the customer with first name art and last name turcotte have?
customers_card_transactions
select count(*) from accounts as t1 join customers as t2 on t1.customer_id = t2.customer_id where t2.customer_first_name = 'art' and t2.customer_last_name = 'turcotte'
Question: return the number of accounts that the customer with the first name art and last name turcotte has. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_cus...
return the number of accounts that the customer with the first name art and last name turcotte has.
customers_card_transactions
select customer_id , count(*) from accounts group by customer_id
Question: show all customer ids and the number of accounts for each customer. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -...
show all customer ids and the number of accounts for each customer.
customers_card_transactions
select customer_id , count(*) from accounts group by customer_id
Question: how many accounts are there for each customer id? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, custome...
how many accounts are there for each customer id?
customers_card_transactions
select customer_id , count(*) from accounts group by customer_id order by count(*) desc limit 1
Question: show the customer id and number of accounts with most accounts. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> ca...
show the customer id and number of accounts with most accounts.
customers_card_transactions
select customer_id , count(*) from accounts group by customer_id order by count(*) desc limit 1
Question: what is the customer id of the customer with the most accounts, and how many accounts does this person have? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, ...
what is the customer id of the customer with the most accounts, and how many accounts does this person have?
customers_card_transactions
select t2.customer_first_name , t2.customer_last_name , t1.customer_id from accounts as t1 join customers as t2 on t1.customer_id = t2.customer_id group by t1.customer_id order by count(*) asc limit 1
Question: what is the customer first, last name and id with least number of accounts. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers...
what is the customer first, last name and id with least number of accounts.
customers_card_transactions
select t2.customer_first_name , t2.customer_last_name , t1.customer_id from accounts as t1 join customers as t2 on t1.customer_id = t2.customer_id group by t1.customer_id order by count(*) asc limit 1
Question: give the full name and customer id of the customer with the fewest accounts. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customer...
give the full name and customer id of the customer with the fewest accounts.
customers_card_transactions
select count(*) from customers where customer_id not in (select customer_id from accounts)
Question: show the number of all customers without an account. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, cust...
show the number of all customers without an account.
customers_card_transactions
select count(*) from customers where customer_id not in (select customer_id from accounts)
Question: how many customers do not have an account? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, c...
how many customers do not have an account?
customers_card_transactions
select customer_first_name , customer_last_name from customers except select t1.customer_first_name , t1.customer_last_name from customers as t1 join accounts as t2 on t1.customer_id = t2.customer_id
Question: show the first names and last names of customers without any account. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards...
show the first names and last names of customers without any account.
customers_card_transactions
select customer_first_name , customer_last_name from customers except select t1.customer_first_name , t1.customer_last_name from customers as t1 join accounts as t2 on t1.customer_id = t2.customer_id
Question: what are the full names of customers who do not have any accounts? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards ->...
what are the full names of customers who do not have any accounts?
customers_card_transactions
select distinct t1.customer_first_name , t1.customer_last_name from customers as t1 join accounts as t2 on t1.customer_id = t2.customer_id
Question: show distinct first and last names for all customers with an account. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards...
show distinct first and last names for all customers with an account.
customers_card_transactions
select distinct t1.customer_first_name , t1.customer_last_name from customers as t1 join accounts as t2 on t1.customer_id = t2.customer_id
Question: what are the full names of customers who have accounts? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, c...
what are the full names of customers who have accounts?
customers_card_transactions
select count(distinct customer_id) from accounts
Question: how many customers have an account? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_typ...
how many customers have an account?
customers_card_transactions
select count(distinct customer_id) from accounts
Question: count the number of customers who hold an account. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, custom...
count the number of customers who hold an account.
customers_card_transactions
select count(*) from customers
Question: how many customers do we have? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_type_cod...
how many customers do we have?
customers_card_transactions
select count(*) from customers
Question: count the number of customers. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_type_cod...
count the number of customers.
customers_card_transactions
select customer_id , customer_first_name , customer_last_name , customer_phone from customers
Question: show ids, first names, last names, and phones for all customers. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> c...
show ids, first names, last names, and phones for all customers.
customers_card_transactions
select customer_id , customer_first_name , customer_last_name , customer_phone from customers
Question: what are the ids, full names, and phones of each customer? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id...
what are the ids, full names, and phones of each customer?
customers_card_transactions
select customer_phone , customer_email from customers where customer_first_name = 'aniyah' and customer_last_name = 'feest'
Question: what is the phone and email for customer with first name aniyah and last name feest? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. ...
what is the phone and email for customer with first name aniyah and last name feest?
customers_card_transactions
select customer_phone , customer_email from customers where customer_first_name = 'aniyah' and customer_last_name = 'feest'
Question: return the phone and email of the customer with the first name aniyah and last name feest. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_det...
return the phone and email of the customer with the first name aniyah and last name feest.
customers_card_transactions
select count(*) from customers_cards
Question: show the number of customer cards. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_type...
show the number of customer cards.
customers_card_transactions
select count(*) from customers_cards
Question: how many customer cards are there? | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards -> card_id, customer_id, card_type...
how many customer cards are there?
customers_card_transactions
select card_id , customer_id , card_type_code , card_number from customers_cards
Question: show ids, customer ids, card type codes, card numbers for all cards. | Tables: Accounts -> account_id, customer_id, account_name, other_account_details. Customers -> customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details. Customers_Cards ...
show ids, customer ids, card type codes, card numbers for all cards.