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)n≥1. 117 18.01 Calculus Jason Starr Fall 2005 A sequence (an)n≥1 converges to a limit L if the sequence becomes arbitrarily close to L, and stays arbitrarily close to L. More precisely, the sequence converges to L if for every positive number �, there exists an integer N (depending on the sequence and �) such ...
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There are 2 remaining cases. If r = −1, then an = (−1)n diverges. If r = 1, then an = 1 converges to 1. 2. Tests for convergence/divergence. One useful test for convergence is the Squeezing Lemma. The squeezing lemma. Let (an)n≥1, (bn)n≥1 and (cn)n≥1 be sequences such that for every index n, an ≤ bn ≤ cn. In othe...
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2005 Monotone Convergence Test. A non­decreasing sequence converges if and only if it is bounded above. In this case, the limit of the sequence is the least upper bound for the sequence. Similarly, a non­increasing sequence converges if and only if it is bounded below and the limit is the greatest lower bound for t...
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conditionally. k ak Examples. The harmonic sequence is the sequence an = 1/n. As will be shown soon, the harmonic series 1/n diverges to ∞. The alternating harmonic sequence is, � n an = (−1)n . n The alternating harmonic series, ∞ � (−1)n , n n=1 does converge. This will also be shown soon. Since the se...
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the partial sums. But because we add positive terms with a much higher frequency than negative terms, the sequence of partial sums is diverging to +∞. Similarly, we could negative terms with a very high frequency and make the partial sums diverge to −∞. Now it is not so surprising that by adding the terms in a caref...
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For to 0, then the series example, it immediately follows that the series ∞ n=1(−1)n diverges (arguing the opposite is a favorite pasttime of “mathematical cranks”). � � The most basic test for absolute convergence of a sequence follows from the monotone convergence test. The sequence of partial absolute sums, ...
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essentially the geometric sequence. Assuming r = 1, the geometric sequence rn+1 converges if and only if |r| < 1. In this case, the sequence of partial absolute sums, 1 1 − r 1 1 − r r n+1 . − = Bn = 1 + |r| + r 2 | | + · · · + |r|n = 1 1 − |r| + 1 1 − |r| n+1 |r| , also converges. Thus, the geometric seri...
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an+1/an| converges to a real number r > 1 (in which case, the sequence (an)n≥1 does not converge to 0). There is no information if the sequence converges to 1 or diverges. ∞ n=1 � � � , � � Similarly, if the following limit, exists, call it r. Then the sequence (an)n≥1 to the root test : The series number r ...
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g(x)dx, 1 121 � � 18.01 Calculus diverges, then the series sequence (cn) by, Jason Starr Fall 2005 � ∞ n=1 an does not converge absolutely. For both directions, define the The absolute partial sum of the series n � cn = n+1 f (x)dx, or cn = � n k=1 ck � n is simply, � ck = f (x)dx, or n � � n+1 ...
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1 by, The series ∞ n=1 1/ns equals 1 + ∞ n=2 � � an = 1 . ns 1/ns, which is the same as, ∞ � 1 + n=1 1 . (n + 1)s Let f (x) be the function f (x) = 1/xs . Then for each integer n, f (x) ≥ 1/(n + 1)s for every x in [n, n + 1]. The partial sum of (cn) is, � cn = n 1 xs 1 dx = � 1 � 1 n � � � 1 ...
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million prize for an accepted, refereed solution. Lecture 31. December 8, 2005 Practice Problems. Course Reader: 7B­4, 7B­6, 7C­1, 7C­5, 7D­1, 7D­2. 1. Power series. Given a real number a and a sequence of real numbers (cn)n≥0, there is an associated expression, called a power series about x = a, ∞ � cn(x − a)n =...
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es if x ≥ 1. | | n=1 3. Consider the power series, 1 + x + x 2/2 + x /3! + · · · = 3 123 � 1∞ n! n=0 n x . 18.01 Calculus Jason Starr Fall 2005 The ratio of the nth and (n + 1)st terms in the series is, (x n+1/(n + 1)!)/(x /n!) = n x . n + 1 For fixed x, as n grows, this sequence of ratios converges to 0...
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ratio or root test gives an answer. � cn(x − a)n is positive, 2. Analytic functions. If the radius of convergence R of a power series then the power series defines a function on the interval (a − R, a + R), f (x) = ∞ � cn(x − a)n . n=0 A function defined in this manner is called an analytic function. This is th...
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only 1 of many useful properties of analytic functions. Which functions f (x) are analytic functions? By the last paragraph, if f (x) is analytic, then it is infinitely differentiable. Are there other restrictions? Can more than 1 power series about x = a give rise to the same analytic function? To answer both of the...
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(i.e., the corresponding coefficients of the 2 series are equal). Moreover, this gives us alot of information about the first question. For an infinitely differentiable function f (x) defined at a point x = a, there is a very important power series, the Taylor series expansion of f (x) about x = a, �∞ n=0 f (n) (a) n!...
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same. For definiteness, consider the Taylor series expansion of f (x) = (1 − x)−1 about the point x = 0. Step 1. Compute all derivatives of f (x). If this sounds like alot of work, it is! In most examples, this really comes down to finding an inductive formula for the derivatives of f (x). In the example, the “zeroth...
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+1 = (n + 1)cn. 126 � 18.01 Calculus Jason Starr Fall 2005 Thus the result is proved by induction on k. In fact, more has been accomplished, since now there is an inductive formula for the numbers cn, cn = ncn−1 = n(n−1)cn−2 = n(n−1)(n−2)cn−3 = · · · = n(n−1)(n−2)·· · ··3c2 = n(n−1)(n−2)·· · ·· 3·2· 1. This num...
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series is simply the geometric series. By the previous lecture, the geometric series converges absolutely with radius R = 1. Moreover, it converges absolutely to (1 −x)−1 . Notice, this gives another explanation for the radius R = 1. Since (1 − x)−1 has a vertical asymptote at x = 1, the Taylor series cannot conver...
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+1 ]/[(1 − a)−n−1(x − a)n] = (1 − a)−1(x − a). This is independent of n. Thus, this constant sequence converges to its constant value (1 − a)−1(x − a). By the ratio test, the sequence is absolutely convergent if and only if this limit has absolute value less than 1, (1 − a)−1(x − a) ≤ 1. | | Rearranging, the serie...
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of convergence is R = ∞. Therefore, for every x, the power series converges absolutely to e , x e x = �∞ n=0 xn/n!. This equation is sometimes taken as the definition of e . It has certain advantages to our original definition of ex . Importantly, it is easy for a computer to determine ex to very high precision usin...
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Starr Fall 2005 Example 3. Consider the function f (x) = sin(x). The derivatives of f (x) are, f (x) = f �(x) = f ��(x) = f (3)(x) = f (n+4)(x) = sin(x), cos(x), − sin(x), − cos(x), f (n)(x) Together, these give all the derivatives of f (x). Write n = 4l, 4l + 1, 4l + 2 or 4l + 3 for some nonnegative i...
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0, ∞ (−1)m � (2m + 1)! m=0 x 2m+1 . The ratio of consecutive terms in the series is, [(−1)m+1 x 2m+3 /(2m + 3)!]/[(−1)m x 2m+1/(2m + 1)!] = −x /(4m 2 + 8m + 3). 2 This sequence converges to 0. Therefore, by the ratio test, the power series converges absolutely to sin(x) for every choice of x, sin(x) = �∞ m=0...
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series expansions of sin(x) and cos(x) about a point x = a, we can follow the procedure above. However, it is much faster to use the angle addition formulas, sin(x) = sin(a + (x − a)) = cos(a) sin(x − a) + sin(a) cos(x − a), cos(x) = cos(a + (x − a)) = cos(a) cos(x − a) − sin(a) sin(x − a). This gives the Taylor se...
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beyond the scope of this class). However, it is quite easy to write down a power series expansion for f (x). First of all, the Taylor series for e−t2 about t = 0 is obtained by substituting x = −t2 in the Taylor series for ex about x = 0, e−t2 = ∞ � (−1)nt2n/n!. n=0 Because this series converges absolutely, the i...
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� f (n)(a) n! n=0 (x − a)n + RN,a(x). The precise version of the questions above is, what bounds exist for RN,a(x)? To understand the answer, consider the simplest case where N = 0. Then the remainder term is simply, R0,a(x) = f (x) − f (a). By the Mean Value Theorem, for every x there exists a real number c (de...
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−1, 1), then M equals e. To make the remainder term less than 10−10, it suffices to take N = 12. 3. Review problems. Each of the following problems was discussed in lecture. Here are the problems and answers, without the discussion. Problem 1. Let a and b be positive real numbers. There are 2 tangent lines to the ell...
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solid is, Volume = 3π/10. Problem 4. Using a trigonometric substitution and a trigonometric identity, compute the an­ tiderivative, √ � 2 1 − x 2x dx. The antiderivative equals, � √ 1 − x2 x2 √ dx = − 1 − x2/x − sin−1(x ) + C. Problem 5. Using integration by parts, compute the following antiderivative, � x ...
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Lecture 16 8.324 Relativistic Quantum Field Theory II Fall 2010 8.324 Relativistic Quantum Field Theory II MIT OpenCourseWare Lecture Notes Hong Liu, Fall 2010 Lecture 16 Firstly, we summarize the results of the vertex correction from the previous lecture: Γµ 1 (k1, k2) ≡ q k2 + l µ k1 + l l k2 k1 = γµA(...
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in the λ −→ 0 limit cancel among virtual and real soft photon emissions, and we can safely take the λ −→ 0 limit in the end. 3.4: VACUUM POLARIZATION We will now evaluate the one-loop correction to the photon propagator, and consider the physical interpretation, recalling the general structure we considered in lec...
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)γν (i/q + m) [ γµ(i/p + i(1 − x)k/ + m)γν (i = tr [ = −tr ] ] p/ − ixk/ + m) γµpγ/ ν p/ + m 2tr [γµγν ] + x(1 − x)tr [γµ / +terms linear in p+terms with an odd number of γmatrices. kγν / k] We note that the trace of a term with an odd number of γ-matrices gives zero, and that tr [γµγν ] = 4ηµν , tr [γµγν γργσ] =...
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pE 2 and p → E ipd , dd p → → 2 pE . We recall that ˆ ddpE (2π)d (pE (p2 )a E 2 + D)b = Γ(b − a − d )Γ(a + d ) 2 2 (4π) Γ(b)Γ( d 2 ) d 2 D−(b−a− , d ) 2 and so (1 − ˆ 2 ) d p2 E ddpE (2π)d (p2 + D)2 E ˆ = −D Hence, the numerator of (8) can be replaced by 1 ddpE (2π)d (p2 + D) E 2 . (A...
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� iΠµν (k) = dx x(1 − x) − γ + log −8ie2k2P µν 16π2 T (k) ˆ 1 0 [ 2 ϵ )] µν − i(Z3 − 1)k2P , T 4πµ2 D and so with Πµν (k) = k2PT µν Π(k2), e2 Π(k2) = − 2 π ˆ 1 dx x(1 − x) ( 1 ϵ − log 1 2 D 2e−γ 4πµ ) − (Z3 − 1). 0 The physical field condition constrains that Π(k2 = 0) = 0, and so Z3 is fi...
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We see that for q2 ≫ m2 , a large spacelike momentum, from (17) we have Π(q 2) ≈ = 2 e 2 π α 3π log 2 log q2 2 m q2 , m2 ˆ 1 0 dx x(1 − x) e π . Then, the internal propagator goes as where α = 4 2 e2 q2 − iϵ −→ e2 1 1 − Π(q2) q2 − iϵ ≡ e2(q) q2 − iϵ , (18) the running coupling constant. with e2(...
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p′ 1 µν = ηµν − qµ q2 and P T p2)u2(p2) = 0. We now want to consider corrections to the Coulomb potential. We consider the low energy, non-relativistic limit, where we derive most of our intuition about electromagnetism from, and where the notion of a potential makes most sense. The lowest two diagrams drawn ab...
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− x) log 1 + ⃗2q m2 x(1 − x) ) , and the term provides a correction to the Coulomb potential δV (⃗r) = e1e2 ˆ 2) ⃗q d3⃗r e−i⃗q.⃗r Π( . 2 ⃗q From now on, we will for convenience write q ≡ |⃗q|, r ≡ ∥⃗r∥. The angular integral is given by (24) (25) ˆ π dθ sin θeiqr cos θ 0 ( eiqr − e−iqr ) , 2π 3 (2π) 1 1 ...
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π4 ir 0 ) ( dx x(1 − x) ˆ ∞ −∞ ( log 1 + dz iz e z ) 2 z a2 . (26) log 2 z 1 + a 2 , can be computed using the complex contour shown in figure 1, I = 2 ˆ ∞ dλ a ˆ ∞ e−λ λ iπ = 2iπ dλ 1 e−aλ λ after setting λ → aλ. So, our result for the correction to the Coulomb potential is given by ˆ 1 ˆ ...
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4πr e˜i(r) = ei (1 + Z(mr)) . 1 2 5 (28) (29) Re(s)Im(s)ia Lecture 16 8.324 Relativistic Quantum Field Theory II Fall 2010 Figure 2: Virtual electron-positron pairs form a screening effect. We observe that ˜ei(r) −→ ∞ as r −→ 0, and ˜ei(r) −→ ei as r −→ 0, with small experimental corrections. Physically, we c...
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Turbulent Flow and Transport 6 6.1 Introduction to Turbulent Boundary Layers The nature of flow in turbulent boundary layers. Inner and outer regions, eddy diffusivity distributions, intermittency, etc. 6.2 Integral form of the mean flow boundary layer equations. 6.3 6.4 6.5 Reasons for why the turbulent bou...
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Welcome to ... 2.717J/MAS.857J Optical Engineering MIT 2.717J wk1-b p-1 This class is about • Statistical Optics – models of random optical fields, their propagation and statistical – properties (i.e. coherence) imaging methods based on statistical properties of light: coherence imaging, coherence tomography ...
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-6 Syllabus (summary) • Review of Fourier Optics, probability & statistics 4 weeks • Light statistics and theory of coherence 2 weeks • The van Cittert-Zernicke theorem and applications of statistical optics to imaging 3 weeks • Basic concepts of inverse problems (ill-posedness, regularization) and examples (Rado...
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plane MIT 2.717J wk1-b p-10   ′′ ′′ x y   G 1 , λf 1 λf 1   Fourier plane   g 1  − f 1 y ′ f x ′ − , f 1 f 2 Image plane 2    The 4F system 1f 2f 2f 1f θx )vuG ( , 1 u = x θ sin λ θ sin λ y v = ( , ) yx g 1 object plane MIT 2.717J wk1-b p-11   ′′ ′′ x y   G 1 , ...
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r  circ  R    ( g 1  )  ∗ h −  f 1 f 2 ′ − , x f ′ 1 y f 2    Fourier plane: aperture-limited Image plane: blurred (i.e. low-pass filtered) The 4F system with FP aperture Transfer function: circular aperture ′′ r   circ  R    Impulse response: Airy function  r  ′R  jinc  λf ...
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Transfer Function (MTF) Transfer Function (OTF) MIT 2.717J wk1-b p-15 Coherent vs incoherent imaging 1f 1f 2f 2f 2a ( )u H 1 ~( ) u H 1 −u c u −2u c a u = c λf 1 u 2u c Coherent illumination Incoherent illumination MIT 2.717J wk1-b p-16 Aberrations: geometrical Paraxial (Gaussian) image poi...
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9 Fourier Transform Properties The Fourier transform is a major cornerstone in the analysis and representa- tion of signals and linear, time-invariant systems, and its elegance and impor- tance cannot be overemphasized. Much of its usefulness stems directly from the properties of the Fourier transform, which we discuss...
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is reflected in an inverse scaling in frequency. As we discuss and demonstrate in the lecture, we are all likely to be somewhat familiar with this property from the shift in frequencies that oc- curs when we slow down or speed up a tape recording. More generally, this is one aspect of a broader set of issues relating t...
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transform. This is in fact very heavily exploited in discrete-time signal analy- sis and processing, where explicit computation of the Fourier transform and its inverse play an important role. There are many other important properties of the Fourier transform, such as Parseval's relation, the time-shifting property, an...
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product of their corresponding Fourier transforms. For the analy- sis of linear, time-invariant systems, this is particularly useful because through the use of the Fourier transform we can map the sometimes difficult problem of evaluating a convolution to a simpler algebraic operation, namely multiplication. Furthermor...
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ideas of Fourier series and the Fourier transform for the discrete-time case so that when we discuss filtering, modulation, and sam- pling we can blend ideas and issues for both classes of signals and systems. Suggested Reading Section 4.6, Properties of the Continuous-Time Fourier Transform, pages 202-212 Section 4.7,...
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Fourier Transform Properties 9-5 Example 4.7: eat u(t) a+jcw a > o IxMe) 1/a/2 1/a - -- 1/a -a a TRANSPARENCY 9.3 The Fourier transform for an exponential time function illustrating the property that the Fourier transform magnitude is even and the phase is odd. 7r/4 -7/4 IT/2 Time and frequency scaling: x(at) ...
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Fourier transform. Differentiation: x(t-t ) .- e-jwto X(o) dx(t) dt jw X(W) Integration: Linearity: f tf00 x(T)dr 4-+ - Jco X(W) + 7r X(O) b(w) ax (t) + bx 2 (t) -. aX1 (w) + bX 2 (w) TRANSPARENCY 9.9 Transparencies 9.9 and 9.10 illustrate the convolution property and its interpretation for LTI systems. This transp...
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-- [S(w) * P(co)] 27r Convolution: s(t) * p(t) S(co) P(W) MARKERBOARD 9.1 -t %~, %~' I Y~wj~ jQ4I I _+)+ Gt (t) =At (7): (V j. J)j &o ,e - I =,ji342. I Jh~+I t ~ MIT OpenCourseWare http://ocw.mit.edu Resource: Signals and Systems Professor Alan V. Oppenheim The following may not correspond to a particular cou...
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6.851: Advanced Data Structures Spring 2012 Lecture 3 — February 23, 2012 Prof. Erik Demaine 1 Overview In the last lecture we saw the concepts of persistence and retroactivity as well as several data structures implementing these ideas. In this lecture we are looking at data structures to solve the geometric pr...
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first line segment lying above it. Equivalently, if we imagine shooting a vertical ray from the query point, we want to return the first map segment that it intersects (see Figure 2). We can use vertical ray shooting to solve the planar point location problem in the static case by precomputing, for each edge, what th...
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a balanced binary search tree. More specifically, we are doing successor queries. In the last lecture we saw how to make a partially persistent balanced binary search tree with O(log n) time queries, and we know that a fully retroactive successor query structure can be made with O(log n) queries as well. Note, howev...
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ray shooting when the rays do not have to be vertical? Note that the three dimensional version of this problem is motivated by ray tracing. 2.3 Finding Intersections The line sweep method can also be used to find intersections in a set of line segments, and this problem gives a good illustration of the line sweep me...
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data in O(log n) time per update, and when performing a swap can be done in constant time. 3 Orthogonal range searching In this problem we’re given n points in d dimensions, and the query is determining which points fall into a given box (a box is defined as the cross product of d intervals; in two dimensions, this...
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Let’s start with the 1-dimensional case, d = 1. To solve it, we can just sort the points and use binary search. The query is an interval [a, b]; we can find the predecessor of a and the successor of b in the sorted list and use the results to figure out whether there are any points in the box; subtract the indices to ...
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know that all the leaves of the right subtree of that node are in the given interval. The same thing is true for left subtrees of the right branch. If the left tree branches right or the right tree branches left, we don’t care about the subtree of the other child; those leaves are outside the interval. The answer is...
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sorted by their y-coordinate. We’ll also store a pointer in each node of the x range tree to the corresponding y tree (see Figure 7 for an example). For example, αx, βx, and γx point to Figure 7: Each of the nodes at the x level have a pointer to all of the children of that node sorted in the y dimension, which is d...
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takes O(n log n) time for d = 1. Building the range trees in this time bound is nontrivial, but it can be done. 3.2 Layered Range Trees We can improve on this data structure by a factor of log n using an idea called layered range trees (See [9], [17], [15]). This is also known as fractional cascading, or cross link...
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subset is arbitrary, as it depends on the x-coordinate of the points. 7 Figure 9: Here is an example of cascading arrays in the final dimension. The large array contains all the points, sorted on the last dimensions. The smaller arrays only contain points in a relevant subtree (the small subtree has a pointer to ...
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turns out that if we have O(n logd−1 n) space and preprocessing time, we can make the structure dynamic for free using weight balanced trees. 3.4 Weight Balanced Trees There are different kinds of weight balanced trees; we’ll look at the oldest and simplest version, BB[α] trees [14]. We’ve seen examples of height-ba...
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as a perfectly balanced tree. Our data structure only has pointers in one direction - each parent points to its children nodes, but children don’t point to their parents, or up the tree in general. As a result, we’re free to rebuild an entire subtree whenever it’s unbalanced. And once we rebuild a subtree, we can ma...
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or more intervals start or end at infinity. 4 Fractional Cascading Fractional cascading is a technique from Chazelle and Guibas in [6] and [7], and the dynamic version is discussed by Mehlhorn and N¨aher in [13]. It is essentially the idea from layered range trees put into a general setting that allows one to elimin...
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≤ 2n = O(n). i+1 k k 1 |Li 2 For each i < k, keep two pointers from each element. If the element came from Li, keep a pointer to the two neighboring elements from Li i+1, and vice versa. These pointers allow us to take information of our placement in Li and in O(1) turn it into information about our placement in Li...
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using smaller α, we can do fractional cascading on any graph, rather than just the single path that 1 10 we had here. To do this, we just (modulo some details) cascade α of the set from each vertex along each of its outgoing edges. When we do this, cycles may cause a vertex to cascade into itself, but if we choos...
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��cient dynamic orthogonal point location, segment intersection, and range reporting, SODA 2008:894-903. [5] B. Chazelle, Reportin and counting segment intersections, Journal of Computer and System Sciences 32(2):156-182, 1986. [6] B. Chazelle, L. Guibas, Fractional Cascading: I. A Data Structuring Technique, Algor...
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[14] J. Nievergelt, E. M. Reingold, Binary search trees of bounded balance, Symposium on Theory of Computing, 1972. Proceedings, 4th annual symposium. [15] D.E. Willard, New Data Structures for Orthogonal Range Queries, SIAM Journal on Comput­ ing, 14(1):232-253. 1985. [16] D.E. Willard, New Data Structures for Orth...
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MIT 3.071 Amorphous Materials 10: Electrical and Transport Properties Juejun (JJ) Hu 1 After-class reading list  Fundamentals of Inorganic Glasses  Ch. 14, Ch. 16  Introduction to Glass Science and Technology  Ch. 8  3.024 band gap, band diagram, engineering conductivity 2 Basics of electrical c...
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moves after M hops in 1-D is: r   d M  Average diffusion distance: + r  2 D (1-D) r  6 D (3-D)    d D 1 2    d D 1 6 2 2 (1-D) (3-D) Average spacing between adjacent sites: d  For correlated hops: D 1   6 2 f d 0  f 1 Ion hopping frequency:  6 A tale of two valleys Electric field E = 0  ...
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 Ze d E k T B     Net ion drift velocity: DEa + ZeEd v       v d v   2 0ZeEd v 2k T B  exp     D  E a  Bk T  8 A tale of two valleys Electric field E > 0  Ion mobility   2 v Zed 0 2 k T B  exp    D E a k T B     Electrical conductivity (1-D, random hop)   2  nv Zed 0 2 k T B ...
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ionic conductivity Dispersion of activation energy in amorphous solids leads to slight non-Arrhenius behavior 1/T (× 1,000) (K-1) Phys. Rev. Lett. 109, 075901 (2012) 10 0lnlnaBETkTDSlope: aBEkD Theoretical ionic conductivity limit in glass    0 T  exp     D E a k T B     0  2  fnv Zed 0 6...
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V0 / J > 3 P. W. Anderson Image is in the public domain. Source: Wikimedia Commons. Disorder leads to (electron, photon, etc.) wave function localization 15 Anderson localization in disordered systems Extended states (Bloch states) Localized states 16 Density of states (DOS) in crystalline and amorphous s...
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�334ERgD1344min2249BBERkTgkTD14expVRH T1489BRgkT DC conductivity in amorphous semiconductors ln Extended state conduction VRH is most pronounced at low temperature Measured DC conductivity Variable range hopping 1/T 21 1expexT14expVRHT VRH in As-Se-Te...
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� Summary  Electronic structure of amorphous semiconductors  Anderson localization: extended vs. localized states  Density of states  Mobility edge E Conduction band  Band tail and mid-gap states  Extended state conduction  Free vs. drift mobility  Thermally activated process  Localized stat...
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r 1:  P 1 8.3 1 1 re   u Lect inciples  of  Applied  Mathematics   Rodolfo  Rosales Spring  2014 .   t e ,   s flow c  characteristics,   f  o d o th Me s,    covered:   nel ved.  chan d invol ra n e e G syllabus,  grading,  books,  notes,  etc.   s s u c is  D . s s a...
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Finite N •  and s i ty  analys li tabi  s y: r o e ic  th Bas • sis  to  the anal ity l b sta From   iscr D y i • . s d o al  meth r t c e p  s d n  a FFT • .   ms r o f s n a r T ce a l p a L d n  a r ie r Fou • S b y Other  topics,  ma .   bus a ee  syll .   e tivate  the...
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• .   s e Traffic  flow  wav r :   s e Oth • • y  waves  [say,  in  lakes]. Solitar Diffusion nc e ffer ge r nve .    etc].   ab  nebula].  Di  co ete  Fourier  Transforms  to  Fourier  Series.   es.   .   nce                       ...
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Impact Assessment 2 Massachusetts Institute of Technology Department of Materials Science & Engineering ESD.123/3.560: Industrial Ecology – Systems Perspectives Randolph Kirchain LCA: Slide 84 What is Impact Assessment? Massachusetts Institute of Technology Department of Materials Science & Engineering ESD.123/3...
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Technology Department of Materials Science & Engineering ESD.123/3.560: Industrial Ecology – Systems Perspectives Randolph Kirchain LCA: Slide 91 Issue 1: Relevance •Translating from inventory to impact is – Introduces numerous assumptions • What are examples of assumptions? – Controversial – Necessity depend...
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priorities system – Human health – Biological diversity – Ecosystem production capacity (crops…) – Abiotic resources (metals…) – Cultural & recreational value (e.g., aesthetics…) – Resource depletion • Energy & material • Water • Land use – Human health • Toxicological • Non-toxicological • Work/living en...
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7 Characterization: Eco-Indicator Damage Model • Fate – Where does the emission end up • Water soluble Æ likely in water supply • Insoluble Æ soil – How durable is the emission • Some substances degrade quickly, reducing the opportunity for impact. • Exposure – How many / much are effected? • How much of a ...
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Europe • At target level the occurrence of smog periods is extremely unlikely Massachusetts Institute of Technology Department of Materials Science & Engineering ESD.123/3.560: Industrial Ecology – Systems Perspectives Randolph Kirchain LCA: Slide 105 Eco-Indicator 95 Weighting factors Greenhouse Ozone layer A...
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) 10 Comparing Impact Assessment Change in … Impact on … Damage to … y r o t n e v n I Atmospheric concentration Land availability Ore availability Human health Ecosystem Resources Species number Global Warming Ozone Depletion … Massachusetts Institute of Technology Department of Materials Scien...
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•Substances are included if there is an indication of impact – Classes 1 -3 carcinogens are included to the extent that information is available •Damages are included if possible •Fossil fuel cannot be subsituted – Cost of replacement is high •DALYs are not age weighted Massachusetts Institute of Technology De...
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& Engineering Respiratory (inorg) Radiation Acidification Fossil Use Respiratory (org) Ozone Depletion Land-use – ESD.123/3.560: Industrial Ecology Systems Perspectives Randolph Kirchain LCA: Slide 117 Issues with Eco-Indicator • Weaknesses • Strengths – Comparatively comprehensive – Provides consistent ...
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Filter design FIR filters Chebychev design linear phase filter design equalizer design filter magnitude specifications • • • • • 1 FIR filters finite impulse response (FIR) filter: n−1 y(t) = hτ u(t � τ =0 τ ), t Z ∈ − (sequence) u : Z (sequence) y : Z → → R is input signal R is output signal hi are call...
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frequency response magnitude (i.e., H(ω) ): | | 1 10 0 10 −1 10 −2 10 | ) ω ( H | −3 10 0 0.5 frequency response phase (i.e., 2 2.5 3 1 1.5 ω H(ω)): ) ω ( H 3 2 1 0 −1 −2 −3 0 0.5 1 1.5 ω 2 2.5 3 Filter design 5 � � Chebychev design minimize max H(ω) ω∈[0,π] | Hdes(ω) | − C is (given) ...
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) = h = � �   cos ωk sin ωk − Hdes(ωk) Hdes(ωk) 1 0 ℜ ℑ h0 .. . hn−1   Filter design 7 Linear phase filters suppose n = 2N + 1 is odd impulse response is symmetric about midpoint: • • ht = hn−1−t, t = 0, . . . , n 1 − then H(ω) = h0 + h1e −iω + + hn−1e −i(n−1)ω · · · = e −iN ω (2h0 cos N ...
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ω 0 ≤ ≤ ωp minimum stopband attenuation ( 20 log10 δ2 in dB): − • • H(ω) | | ≤ δ2, ωs ≤ ω ≤ π Filter design 11 Linear phase lowpass filter design sample frequency can assume wlog H (0) > 0, so ripple spec is • • � 1/δ1 ≤ H (ωk) δ1 ≤ � design for maximum stopband attenuation: δ2 minimize subject to 1...
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band attenuation • • • • impulse response h: 0.2 0.1 0 −0.1 −0.2 ) t ( h 0 2 4 6 8 10 t 12 14 16 18 20 Filter design 14 frequency response magnitude (i.e., H(ω) ): | | 1 10 0 10 | ) ω ( H | −1 10 −2 10 −3 10 0 0.5 frequency response phase (i.e., 2 2.5 3 1 1.5 ω H(ω)): 3 2 1 0 −1 −2 ...
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Gdes(ω) = e−iDω , gdes(t) = 1 t = D 0 t = D � sample design: minimize maxt� subject to =D | g˜(D) = 1 g˜(t) | an LP can use • • g˜(t)2 or =D t� =D t� | g˜(t) | � � Filter design 18 � extensions: can impose (convex) constraints can mix time- and frequency-domain specifications can equalize multiple sy...
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Chebychev equalizer design: ˜ minimize max G(ω) � � � ω − equalized system impulse response g˜ e −i10ω � � � ) t ( g˜ 1 0.8 0.6 0.4 0.2 0 −0.2 0 5 10 15 20 25 30 35 t Filter design 22 equalized frequency response magnitude 1 10 0 10 | ) ω ( Ge | G | | � −1 10 0 0.5 1 2 2.5 3 1.5 ω equalized fr...
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specifications transfer function magnitude spec has form L(ω) H(ω) | ≤ ≤ | U (ω), ω [0, π] ∈ where L, U : R R+ are given → lower bound is not convex in filter coefficients h arises in many applications, e.g., audio, spectrum shaping can change variables to solve via convex optimization • • • Filter design 26 A...
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question: when is r answer: (spectral factorization theorem) if and only if R(ω) Rn the autocorrelation coefficients of some h Rn? ∈ 0 for all ω ∈ ≥ spectral factorization condition is convex in r • many algorithms for spectral factorization, i.e., finding an h s.t. • R(ω) = H(ω) | 2 | magnitude design via autoc...
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� ≤ 1 10 0 10 2 | ) ω ( H | −1 10 −2 10 −1 10 0 10 ω optimal fit: 0.5dB ± Filter design 31 MIT OpenCourseWare http://ocw.mit.edu 6.079 / 6.975 Introduction to Convex Optimization Fall 2009 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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Today’s topics: • UC ZK from UC commitments (this is information theoretic and unconditional; no crypto needed) • MPC, under any number of faults (using the paradigm of [GMW87]) • MPC in the plain model with an honest majority (using elements of [BOGW88] and [RBO89]) 1 UC Zero Knowledge from UC Commitments To imp...
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set v ← 1. Else set v ← 0. Finally, output (sid, P, V, G, v) to (sid, V ) and to S, and halt. [the Blum protocol?] Claim 1 The Blum protocol security realizes F H wzk in the Fcom­hybrid model. Proof Sketch: Let A be an adversary that interacts with the protocol. We construct an ideal­process adversary S that fo...
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0 to A. If b = 0 (no cheating allowed), then send c = 1 to A. (c) Obtain A’s openings of the commitments (either a permutation of the graph, or a Hamiltonian cycle). If c = 0 (permutation) and all openings are consistent with G, then send b� = 1 to Fwzk; if some openings are bad then send b� = 0. If c = 1 (cycle) a...
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the F R F R and fools all environments. There are four cases: zk wzk­hybrid model; we’ll construct an adversary that interacts with 1. If A controls the verifier: this case is simple. All A expects to see is k copies of (x, b) being delivered zk, sends k copies to A, and outputs whatever by the copies of Fwzk. S r...
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