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unless there is a large difference in the cross-sections Example: Si transistor, τphonon dominates even though τimpur gets worse with scaling 6 ©1999 E.A. Fitzgerald Example: Electron Mobility in Ge μ~T-3/2 if phonon dominated (T-1/2 from vth, T-1 from x-section σ 106 3 105 3 104 3 s - t l o v / 2 m c , e m T-3/...
https://ocw.mit.edu/courses/3-225-electronic-and-mechanical-properties-of-materials-fall-2007/43fea384070aa4c2f247637091f10d55_lecture_8.pdf
– Go is the equilibrium generation rate • Recombination – intrinsic: across band gap, R=# carriers/vol.-sec – extrinsic: deep levels due to traps – Ro is the equilibrium recombination rate, which is balanced by Go Non-equilibrium intrinsic recombination Non-equilibrium extrinsic recombination n-type material R ...
https://ocw.mit.edu/courses/3-225-electronic-and-mechanical-properties-of-materials-fall-2007/43fea384070aa4c2f247637091f10d55_lecture_8.pdf
6.S096 Lecture 1 – Introduction to C Welcome to the Memory Jungle Andre Kessler Andre Kessler 6.S096 Lecture 1 – Introduction to C 1 / 30 Outline 1 Motivation 1 2 Class Logistics 2 3 Memory Model 3 4 Compiling 4 5 Wrap-up 5 Andre Kessler 6.S096 Lecture 1 – Introduction to C 2 / 30 First Example (Pyth...
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C++? Speed Graph of prog Source: http://benchmarksgame.alioth.debian.org/u64q/which-programs-are-fastest.php. ram s peed acro ss language im plementations remove d due to copy right r estrictions. Andre Kessler 6.S096 Lecture 1 – Introduction to C 5 / 30 Why C or C++? Motivation Power C: direct access to memory and m...
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9 10 Topic Introduction to C: memory and the compiler Subtleties of C: memory, floating point Guest lectures: Assembly and Secure C Transition from C to C++ Object-oriented programming in C++ Design patterns and anti-patterns Generic programming: templates and more Projects: putting it all together Pro...
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To compile: make nothing Previous step produced an executable named nothing To run: ./nothing Surprise! Does nothing. But you probably have higher aspirations for your programs... Andre Kessler 6.S096 Lecture 1 – Introduction to C 13 / 30 Class Logistics Hello, world! hello.c: takes no a...
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– Introduction to C 17 / 30 Memory Model Pointers How do you get at this information about memory? Through pointers; that is, the & and * operators int a = 5; The address of a is &a. int *a ptr = &a; Read declarations from right to left. See it this way: “*a ptr is declared to be of type i...
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Memory Model It’s all about the memory int a = 5; int *a ptr = &a; &a &a ptr Memory Address 0x7fff6f641914 0x000000000005 a 0x7fff6f641918 0x7fff6f641914 a ptr Value Identifier Note: definitely a 64-bit machine, since the addresses are larger than 232 . Andre Kessler 6.S096 Lecture 1 – Introduction to C 21...
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.h> int do_thing( float a, float b ) { /* do things */ } void call(void) { /* do stuff */ do_thing( a, b ); /* do more */ } int main(void) { call(); return 0; } Andre Kessler 6.S096 Lecture 1 – Introduction to C 25 / 30 What happens when we compile? Compiling Three functions main, c...
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/ 30 Wrap-up & Friday Wrap-up Open lab Bring your laptops, get a C programming environment working Test out the automatic grader Cl ass on Friday Will cover floating point arithmetic, memory management, and headers in more depth. Q estions? u Andre Kessler 6.S096 Lecture 1 – Introduction to C 30 / ...
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Imperative Programming in Haskell? Armando Solar-Lezama Computer Science and Artificial Intelligence Laboratory MIT With content from Nirav Dave (used with permission) and examples from Dan Piponi’s great blog Post “You could have invented Monads! And Maybe You Already Have” http://blog.sigfpe.com/2006/08/you-c...
https://ocw.mit.edu/courses/6-820-fundamentals-of-program-analysis-fall-2015/444a3c5a42232c471d9386191f58fc9f_MIT6_820F15_L09.pdf
unit * f = f * unit = f – lift f * lift g = lift (f . g) October 7, 2015 L09-4 Random Numbers • Consider the “function” rand() – Not really a function, but you can make it a function • rand: StdGen->(int, StdGen) – think of StdGen as the seed that gets updated (or as some infinitely long list of pre-gener...
https://ocw.mit.edu/courses/6-820-fundamentals-of-program-analysis-fall-2015/444a3c5a42232c471d9386191f58fc9f_MIT6_820F15_L09.pdf
– unit * f = f * unit = f – lift f * lift g = lift (f . g) October 7, 2015 L09-8 Monads as a type class • Monad is a typeclass that requires – x >>= f • (>>=) :: something->(a->something)->something • (equivalent to bind f x) – return x • return :: a -> something • (equivalent to unit x) – etc. • So ...
https://ocw.mit.edu/courses/6-820-fundamentals-of-program-analysis-fall-2015/444a3c5a42232c471d9386191f58fc9f_MIT6_820F15_L09.pdf
\y do plusrand y) return 5 >>= \x (timesrand x >>= \y plusrand y) MyRand Int Int->MyRand Int MyRand Int Int -> MyRand Int October 7, 2015 L09-16 IO with Monads October 7, 2015 L09-17 Word Count Program Flag to indicate we are inside a word wc :: String -> (Int,Int,Int) wcs :: String -> Bool -> (Int...
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wcs cs True ((nc+1),nw,nl) September 29, 2010 L09-19 File Handling Primitives type Filepath = String data IOMode = ReadMode | WriteMode | ... data Handle = ... implemented as built-in type openFile :: FilePath -> IOMode -> Handle hClose :: Handle -> () -- void hIsEOF :: Handle -> Bool hGetChar :...
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By embedding the concept of I/O in a monad we guarantee that there is a single sequence of the monadic I/O operations (no nondeterminism issues) IO a: computation which does some I/O, producing a value of type a. • Unlike other monads, there is no way to make an IO a into an a No operation to take a value out o...
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filename putStr “\n” no return ! print :: String -> (Int,Int,Int) -> IO () September 29, 2010 L09-27 Word Count using monads - version 1 main = do (filename:_) <- getArgs contents <- getFileContents filename let (nc,nw,nl) = wc contents print filename (nc,nw,nl) pure functional ...
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ch h True ((nc+1),(nw+1),nl) else wch h True ((nc+1),nw,nl) September 29, 2010 L09-30 Beyond I/O • Monadic I/O is a clever way to force meaningful interactions with the outside world. This is what most people think of when they think of monads • But monads can do more – A mechanism to structure...
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18.417 Introduction to Computational Molecular Biology Lecture 7: September 30, 2004 Lecturer: Ross Lippert Scribe: Mark Halsey Editor: Rob Beverly Divide and Conquer: More Efficient Dynamic Programming Introduction We have seen both global and local alignment problems in previous lectures. Briefly: • Global Align...
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n ) time. 7-1 7-2 Lecture 7: September 30, 2004 Space-Efficient Sequence Alignment The space complexity of the algorithms we have seen previously is proportional to the number of vertices in the edit graph, i.e. O(nm). Observe however that the only values needed to compute the alignment scores in column j in the ...
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optimal alignment is simply pref ix(i) + suf f ix(i). pref ix(i) can be Lecture 7: September 30, 2004 7-3 computed by finding the score si, , i.e. we compute the score in linear space as shown earlier for just the first half of the graph. To compute the suf f ix, we rely on the fact that in a DAG we can flip the dir...
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from Figure 7.2: Iteratively Computing the Optimal Alignment Midpoints 7-4 Lecture 7: September 30, 2004 Block Alignment and the Four-Russians Speedup The time complexity of the dynamic programming global alignment algorithm we’ve studied previously was O(n 2). In this section we examine a trick to speedup the al...
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4 7-5 • Output: The block alignment of v and w with the maximum score Let �i,j be the alignment score for the (i, j) block. The recurrence for the block alignment algorithm is: si−1,j − �block � si,j = max si,j−1 − �block ⎧ � si−1,j−1 + �i,j ⎧ � where �block is the indel block penalty. Since the indices of the...
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time is: O( logn ). 2 n t t 2 LCS and the Four-Russians Speedup Finally, the path corresponding to the LCS does not necessarily enter and exit through the corners of blocks. In this section we turn to the more involved problem of allowing unrestricted entry and exit between blocks in the partitioned edit graph. W...
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4t possible strings, the lookup table requires 2t2t4t4t = 26t space. Setting t = 4 logn as before makes the table of size O(n1.5). This allows computation of the n1.5 entries in the table to be constructed in O(n1.5log2n) time. As in the block alignment problem, this time is dominated by the DP and allows for an O...
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16 RICHARD B. MELROSE 3. Measureability of functions Suppose that M is a �-algebra on a set X 4 and N is a �-algebra on another set Y. A map f : X � Y is said to be measurable with respect to these given �-algebras on X and Y if (3.1) f −1(E) ≤ M � E ≤ N . Notice how similar this is to one of the characterizati...
https://ocw.mit.edu/courses/18-155-differential-analysis-fall-2004/447c5870100c43f0ded7978fc946e4f4_section3.pdf
X then (3.4) f�(M) = E ∀ Y ; f −1(E) ≤ M is always a �-algebra on Y. � In particular if f −1(A) ≤ M for all A ≤ G ∀ N then f�(M) is a �- algebra containing G, hence containing N by the generating condition. Thus f −1(E) ≤ M for all E ≤ N so f is measurable. � Proposition 3.2. Any continuous map f : X � Y between...
https://ocw.mit.edu/courses/18-155-differential-analysis-fall-2004/447c5870100c43f0ded7978fc946e4f4_section3.pdf
�-algebra in [−⊂, ⊂] the smallest �-algebra containing all open subsets of R and all sets (a, ⊂] and [−⊂, b); in fact it is generated by the sets (a, ⊂]. (See Problem 6.) Our main task is to define the integral of a measurable function: we start with simple functions. Observe that the characteristic function of a ...
https://ocw.mit.edu/courses/18-155-differential-analysis-fall-2004/447c5870100c43f0ded7978fc946e4f4_section3.pdf
22n − 1, set En,k = {x ≤ X; 2−nk ⊃ f (x) < 2−n(k + 1)}, ∗E = {x ≤ X; f (x) → 2n}. n 18 RICHARD B. MELROSE These are measurable sets. On increasing n by one, the interval in the definition of En,k is divided into two. It follows that the sequence of simple functions (3.6) fn = 2−nk�Ek,n + 2n�E� n is incr...
https://ocw.mit.edu/courses/18-155-differential-analysis-fall-2004/447c5870100c43f0ded7978fc946e4f4_section3.pdf
BUILD IT Teaching Notes Charcoal Press This project is a very low-cost device for forming charcoal briquettes. It is composed of three welded metal parts and a wooden block. To make it, you will learn to use a band saw, a sander, a drill press, the OMAX water jet cutter and several hand tools. You will also learn to ...
https://ocw.mit.edu/courses/ec-720j-d-lab-ii-design-spring-2010/449159c23d3552f73d7d59c5808c7f55_MITEC_720JS10_bldit_chrc.pdf
Build-It modules were designed to give students experience with a variety of tools and manufacturing techniques while at the same time exposing them to some simple, appropriate technologies. These modules show them both the rapid prototyping equipment that is available at MIT as well as techniques that are used in ...
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to give the students time to finish the necessary work before the next session. It is intended that the projects are done as part of a hands-on tutorial, with plenty of guidance from the teacher. Some instructions are given in the text of the exercise, but it is assumed that the teacher will go over basic safety an...
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sure that the guard is set to the right height before beginning to cut. Once the initial cut is made, turning the pipe slowly as you cut into it makes a cleaner, squarer cut. If you are using a hack saw to cut the pieces, be sure that the pipe is held firmly in a vise, near the place where you are making the cut. ...
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the $2 charcoal press Additional Teaching Notes You may also want to talk with the students about pipe nomenclature—in the case of steel pipe, ½” refers to the inner diameter. You can also explain the difference between welded pipe, which will have a small ridge running through it (which can be a problem if som...
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too great, then the parts will not be able to be fit together. We will be welding the two parts together, so the fit need only hold the part in place while we are welding it, and the interference can be relatively small. Also note that more compliant materials, such as wood and plastic, can have larger interference...
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fit an endplate configuration Fig 2b Overhang endplate configuration 4 Session 3 Welding the parts: Now that the pieces are cut to size you will put them together to make the final parts. Welding is the process of joining two pieces by melting the adjacent material and having it re-solidify to form a joint. In some c...
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MIT OpenCourseWare http://ocw.mit.edu 8.512 Theory of Solids II Spring 2009 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. Lecture 3: Properties of t h e Response Function In this lecture we will discuss some general properties of the response functions X, and som...
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the curved portion of the Kramers­Kronig 2 contour. Since we have ensured that χ(ω) is analytic in the upper half plane, Cauchy’s residue theorem guarantees that the integral over the entire contour is 0. As a result, the piece we need, i.e. the integral from −∞ to ∞ along the real axis, must also be 0. Thus χ(t)...
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dω�χ(q, ω� �) Pr � � 1 ω − ω� + iπχ(�q, ω) (3.9) where the additional term iπχ(� we picked up by making a hump over the pole. Thus for fixed �q, q, ω) is one half of the contribution from the pole at ω� = ω that χ�(� q, ω) = − χ��(� q, ω) = − 1 π 1 π �� Pr ∞ −∞ ∞ �� Pr −∞ � � dω� χ��(� q, ω) ω...
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Application Specific Integrated Circuit Design Lecture 5 Vladimir Stojanoviü 6.973 Communication System Design – Spring 2006 Massachusetts Institute of Technology Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts ...
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increases design cost „ Can make faster designs but harder to verify and more expensive Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.973 Communicat...
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encourseware (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.973 Communication System Design Gate Arrays Can cut mark costs by prefabricating arrays of transistors on wafers Only customize metal layer for each design Image removed due to copyright restrictions. Fi...
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Opencourseware (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.973 Communication System Design Field-Programmable Gate Arrays (FPGA) Each cell in array contains a programmable logic function Array has programmable interconnect between logic functions Arrays mass-pro...
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mask costs in advanced technologies „ Currently a mask set is a couple $M „ FPGAs are getting increased attention ‰ We will use this approach Courtesy of Arvind and Krste Asanovic. Used with permission. Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. MIT OpenCou...
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permission. Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. M I T OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.973 Communication System Design Standard cell characterization Power Supply Line (V,,)...
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2006. M I T OpenCourseWare (http://ocw,mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.973Communication System Design The front-end: Verilog to ASIC layout flow ‰ The “push-button” approach Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spr...
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I Fast w t h timincl constraint I - bad fast path camot be fixed without redesign1 - might have t o add delay into paths t o satisfy hold time Courtesy of Arvind and Krste Asanovic. Used with permission. Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. MIT Opencour...
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‰ Recursive pattern to match delay „ Much less power than grid „ More skew and jitter „ Skew „ Non-uniform loading „ Buffer mismatch „ Jitter „ Supply noise on buffers Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. MIT OpenCourseWare (http://ocw.mit.edu/), Massach...
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2006. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.973 Communication System Design Wire capacitance Capacitance depends on geometry o f surrounding wires and relative permittivity, &,,of insulating dielectric 3-9 - silicon dioxide, SiOp E, ...
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atically with length Simple lumped n model gives reasonable approximation - Rw is lumped resistance o f wire - Cw is lumped capacitance (put half at each end) cw Delay = Rdriver x -+ (Rdriver + Rw) x 2 Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. M I T OpenCou...
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. Cite as: Vladimir Stojanovic, course materials for 6.973 Communication System Design, Spring 2006. MIT Opencourseware (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYW]. 6.973 Communication System Design Wire delay scaling, global wires For wire crossing whole chip - Re...
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Topic 11 Notes Jeremy Orloff 11 Argument Principle 11.1 Introduction The argument principle (or principle of the argument) is a consequence of the residue theorem. It connects the winding number of a curve with the number of zeros and poles inside the curve. This is useful for applications (mathematical and otherwi...
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2 Likewise, if 0 is a pole of order then the Laurent series for () near 0 is () = ( − 0)−() where () is analytic and never 0 on a small neighborhood of 0. Thus, 0)− ′() ′() () ( − = − 0)−−1() + ( − 0)−() ( − ′() () = − − 0 + Again we have that 0 is a simple pole of ′()∕ () and ( Res ′() ...
https://ocw.mit.edu/courses/18-04-complex-variables-with-applications-spring-2018/44f1db513a6a17d655abe0b6ff7748fc_MIT18_04S18_topic11.pdf
give a few examples. This is a key concept in the argument principle and you should make sure you are very comfortable with it. Example 11.2. Let () = e with 0 ≤ ≤ 2 (the unit circle). Let () = 2. Describe the curve (cid:253). Solution: Clearly (cid:253)() = e2 traverses the unit circle twice as goes from 0 to 2. ...
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= ′() so ′() () ∫ = ∫ (cid:253) = 2 Ind( (cid:253), 0) The last equality in the above equation comes from the definition of winding number. Note that by assumption does not go through any zeros of , so = (()) is never zero and 1∕ in the integral is not a problem. Here is an easy corollary to the argument pri...
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of = poles of 1 + ) 1 = circle of radius 2. 2 = circle of radius 1/2. 3 = circle of radius 1. Example 11.5. Let () = 2 + Find the winding number of (cid:253) around 0 for each of the following curves. 1. 2. 3. answers. () has zeros at 0, −1. It has no poles. So, has no poles and two zeros inside , = 2 Like...
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a leash of length ℎ(cid:253). Here is the analytic proof. The argument principle requires the function to have no zeros or poles on . So we first show that this is true of , + ℎ, ( + ℎ)∕ . The argument is goes as follows. Zeros: The fact that 0 ≤ (cid:240)ℎ(cid:240) < (cid:240) (cid:240) on implies has no zeros on ....
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� ′ = 0. (We showed above that has Now, it’s easy to compute that ′ = ( + ℎ)′ + ℎ − ′ . So, using ′ ( + ℎ)′ + ℎ = ∫ Ind((cid:253), 0) = ∫ Now equations 5 and 6 tell us , − , = +ℎ, − +ℎ, , i.e. we have proved Rouchés theorem. Corollary. Under the same hypotheses, If ℎ and are analytic (no poles) th...
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(cid:240)(cid:240) = 2. 1 + shown below. To apply the corollary to Rouchés theorem we need to check that (for large) (cid:240)ℎ(cid:240) < (cid:240) (cid:240) on On 1, = , so (cid:240) ()(cid:240) = (cid:240)3 + (cid:240) ≥ 3, (cid:240)ℎ()(cid:240) = 2(cid:240)e(cid:240) = 2. 1 + . So (cid:240)ℎ(cid:240) < (cid...
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, (cid:240) 0 (cid:240)ℎ(cid:240) ≤ (cid:240)−1 (cid:240)−1 + (cid:240)−2 (cid:240)−2 + … + (cid:240) 0 (cid:240) ≤ −1 + −2 + … + < . Re(z)Im(z)iR−iRCRC1 11 ARGUMENT PRINCIPLE 7 On (cid:240)(cid:240) = we have (cid:240) ()(cid:240) = , so we have shown (cid:240)ℎ(cid:240) < (cid:240) (cid:240) on the cur...
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function which is a function of a complex variable. Typically, the complex variable is denoted by and a capital letter is used for the system function. Let () be such a system function. We will make a standard assumption that () is meromorphic with a finite number of (finite) poles. This assumption holds in many intere...
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casual and say ‘the system ()’. It is perfectly 11 ARGUMENT PRINCIPLE 8 clear and rolls off the tongue a little easier! 11.3.2 Pole-zero diagrams We can visualize () using a pole-zero diagram. This is a diagram in the -plane where we put a small cross at each pole and a small circle at each zero. Example 1...
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That is, if the unforced system always settled down to equilibrium. 11.3.4 Closed loop systems If the system with system function () is unstable it can sometimes be stabilized by what is called a negative feedback loop. The new system is called a closed loop system. Its system function is given Re(s)Im(s)xxxG1(s)1i...
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( − 0( − 0) + … 0 it equals ∕() = 1∕.) which is clearly analytic at Example 11.13. Set the feedback factor = 1. Assume is real, for what values of is the open loop system () = stable? For what values of is the corresponding closed loop system () stable? (There is no particular reason that needs to be real in t...
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is a case where feedback stabilized an unstable system. − 1 + 1 Example 11.15. () = when = 2. Solution: The only pole of () is in the left half-plane, so the open loop system is stable. The closed loop system function is . Is the open loop system stable? Is the closed loop system stable () = = ( − 1)∕( + 1)...
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() = 1∕( + 1), with = 1. Example 11.17. Take () from the previous example. Describe the Nyquist plot with gain factor = 2. Solution: The Nyquist plot is the graph of (). The factor = 2 will scale the circle in the previous example by 2. That is, the Nyquist plot is the circle through the origin with center = 1. I...
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curve.) Thus, for all large the system is stable ⇔ 1+, = 0 ⇔ Ind((cid:253), −1) = , . Finally, we can let go to infinity. The assumption that () decays 0 to as goes to ∞ implies Re(w)Im(w)iR−iRCRC1xz1xz2 11 ARGUMENT PRINCIPLE 12 that in the limit, the entire curve (cid:253) becomes a single point at the origin. ...
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Nyquist plot around -1? Is the closed loop system stable? Solution: The curve winds twice around -1 in the counterclockwise direction, so the winding number Ind((cid:253), −1) = 2. Since the number of poles of in the right half-plane is the same as this winding number, the closed loop system is stable. Example 11.2...
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ø 3.17. Example 11.23. What happens when goes to 0. Solution: As goes to 0, the Nyquist plot shrinks to a single point at the origin. In this case the winding number around -1 is 0 and the Nyquist criterion says the closed loop system is stable if and only if the open loop system is stable. This should make sense, ...
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feel yourself falling you compensate by shifting your weight or tensing your muscles to counteract the unwanted acceleration. MIT OpenCourseWare https://ocw.mit.edu 18.04 Complex Variables with Applications Spring 2018 For information about citing these materials or our Terms of Use, visit: https://ocw.mit.edu/te...
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18.404/6.840 Lecture 23 Last time: - !"#$%↑ is EXPSPACE-complete - Thus !"#$%↑ ∉ PSPACE - Oracles and P versus NP Today: (Sipser §10.2) - Probabilistic computation - The class BPP - Branching programs 1 Probabilistic TMs Defn: A probabilistic Turing machine (PTM) is a var...
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error probability. Significance: Can make the error probability so small it is negligible. 3 NP and BPP NP Computation trees for ! on " BPP ≥ 1 accepting Many accepting Few rejecting " ∈ $ " ∉ $ all rejecting Few accepting Many rejecting Check-in 23.1 Which of these are known to be true? Check all that apply. (a) B...
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equivalent read-once BPs} Theorem: !"ROBP ∈ BPP Check-in 23.2 Assuming (as we will show) that !"ROBP ∈ BPP, can we use that to show !"BP ∈ BPP by converting branching programs to read-once branching programs? (a) Yes, there is no need to re-read inputs. (b) No, we cannot do that conversion in general. (c) No, the co...
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1 1 0 !# 0 0 !$ 0 0 0 0 Show by example: Input is !" = 0, !# = 1, !$ = 1 The BP follows its execution path. Label all nodes and edges on the execution path with 1 and off the execution path with 0. Output the label of the output node 1. Obtain the labeling inductively by using these rules: ' !) 0 1 ' ∧ !) ' ∧ !) '# '" ...
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= −7 1 Check-in 23.3 Revised 4 for 56ROBP: “On input ;", ;# What is the output for this branching program using 1. Pick a random non-Boolean input assignment. the arithmetized interpretation if !" = 1, !# = < ? 2. Evaluate ;" and ;# on that assignment. 3. If ;" and ;# disagree then reject. (1 − <) (a) (< + 1) If they...
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Massachusetts Institute of Technology Department of Materials Science and Engineering 77 Massachusetts Avenue, Cambridge MA 02139-4307 3.21 Kinetics of Materials—Spring 2006 February 22, 2006 Lecture 5: Effects of Capillarity and Stress on Diffusion. References 1. Balluffi, Allen, and Carter, Kinetics of Material...
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in solids can affect diffusion in a variety of ways, including via the mobility, its effect on diffusion potential, and via influencing the boundary conditions for diffusion. • Even a uniform state of stress may break symmetry and cause jumps in certain directions in the material to be favored and modify the mobility...
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3.012 Fund of Mat Sci: Bonding – Lecture 1 bis WAVE MECHANICS Photo courtesy of Malene Thyssen, www.mtfoto.dk/malene/ 3.012 Fundamentals of Materials Science: Bonding - Nicola Marzari (MIT, Fall 2005) Last Time 1. Players: particles (protons and neutrons in the nuclei, electrons) and electromagnetic fields (photons)...
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• Potential energy V 3.012 Fundamentals of Materials Science: Bonding - Nicola Marzari (MIT, Fall 2005) Polar Representation Diagram of the Argand plane removed for copyright reasons. See Mortimer, R. G. Physical Chemistry. 2nd ed. San Diego, CA: Elsevier, 2000, p. 1011, figure B.6. 3.012 Fundamentals of Materials Sci...
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6.626 x 10-34 J s = 2π a.u.) See animation at http://www.kfunigraz.ac.at/imawww/vqm/movies.html Select “Samples from Visual Quantum Mechanics” > “Double-slit experiment” 3.012 Fundamentals of Materials Science: Bonding - Nicola Marzari (MIT, Fall 2005) Time-dependent Schrödinger’s equation (Newton’s 2nd law for quantu...
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Equation (II) − ⎡ ⎢ ⎣ 2 h 2 m 2 +∇ r )( rV ⎤ r )( r ϕ = ⎥ ⎦ r rE )( ϕ 3.012 Fundamentals of Materials Science: Bonding - Nicola Marzari (MIT, Fall 2005)
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Lecture 8 Understanding Transcription RNA-seq analysis Foundations of Computational Systems Biology David K. Gifford 1 Lecture 8 – RNA-seq Analysis •  RNA-seq principles –  How can we characterize mRNA isoform expression using high-throughput sequencing? •  Differential expression and PCA –  What genes are di...
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to RNA-seq analysis Short sequencing reads, randomly sampled from a transcript exon 1 exon 2 exon 3 1.  Assemble reads into transcripts. Typical issues with coverage and correctness. 2.  Map reads to reference genome and identify isoforms using constraints •  Goal is to quantify isoforms and determine s...
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starting at a specific position Si in a transcript of length lj is:"" P(S = Si | T = Tj ) = 1 l j starting position in transcript, Si Ri Tj Transcript length lj Courtesy of Cole Trapnell. Used with permission. Slide courtesy Cole Trapnell 13 P(Ri | T=Tj) – Paired end reads Assume our library fragments have a len...
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●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ● ● ● ● ● ● ● ●● ●● ●● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ●● ●● ●● ●● ●● ●● ●● ●● ●● ● ● ●● ●● ● ● ●● ● ● ●● ● ● ● ● ● ●● ● ● ● ● ●● ●● ●● ●● ● ● ● ● ● ● ●● ●● ● ●● ●● ● ● ●● ● ●● ●● ● ● ● ● ● ● ● ● ● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ● ●● ● ●● ●● ● ● ●● ●● 0.01 0.1 1 10 100 1000 10...
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a r T s t p i r c s n a r T Transcript categories, by coverage ●● ●● match contained intra−intron ● novel isoform repeat other ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ●● ● ● ● ● ● ● ● ●● ●● ●● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ●● ●● ●● ●● ●● ●● ●● ●● ●● ● ● ●● ●● ● ● ●● ● ● ●● ● ● ● ● ● ●● ● ● ● ● ●● ●● ...
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•  Differential expression and PCA –  What genes are differentially expressed, and how can we characterize expressed genes? •  Single cell RNA-seq –  What are the benefits and challenges of working with single cells for RNA-seq? 18 19 20 21 22 23 Scaling RNA-seq data (DESeq) i gene or isoform •  j sample (e...
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parameters in H1 minus the number of free parameters in H0; in this case degrees of freedom is 4 – 2 = 2 (H1 has an extra mean and variance). •  Likelihood ratio test defines a test statistic that follows the Chi Squared distribution iT = 2 log P( iAK | H1)P( P iAK , P(H 0) ≈ 1− ChiSquaredCDF (T i | dof ) iBK | H...
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K., Rahul Satija, et al. "Single-cell Transcriptomics Reveals Bimodality in Expression and Splicing in Immune Cells." Nature (2013). AK Shalek et al. Nature 000, 1-5 (2012) doi:10.1038/nature12172 38 Analysis of co-variation in single-cell mRNA expression levels reveals distinct maturity states and an antiviral cell...
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2014 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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Course Organization Spirit of the Undertaking 6.871: Knowledge-Based Systems Spring 2005 Randall Davis Logistics • Info sheet, syllabus • Personnel: – Lecturers: Davis (and friends) • Course notes: – 1st installment ready now • You are responsible for what happens in lecture. • No open laptops. 2 Course Charac...
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and Barings Bank The week before Nick Leeson disappeared he had kept throwing up at work. Colleagues did not know why but were soon to find out. The ego of a 28-year-old trader on the Singapore Monetary Exchange and the greed and stupidity of a 233-years-old bank had combined to distroy an investment empire and in ...
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procedure 13 Character of the problems attacked • Balancing your checkbook vs. Getting out of the supermarket • Telling it what to do vs. Telling it what to know – Write down some relevant knowledge – Advice, not a procedure „ Knowledge leads to action, But knowledge is more fundamental –The barge story 14 Wh...
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To see this image please visit: http://images.google.com/images?q=charles_babbage.full.jpg 21 Image removed due to copyright considerations. 22 Image removed due to copyright considerations. 23 Intellectual Origins • 2000 years ago – Aristotle and the art of rhetoric – The syllogisms • 17th century: Leibniz an...
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ationality. • Knowledge is closely linked to rationality. • Knowledge is competence-like notion. 30 Character of Knowledge • Most of what we know knowledge is non numeric. • Most of what we know is heuristic. – What’s certain? – What’s the alternative? 31 Character of Knowledge • Empirical, experiential knowl...
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Chapter 7 Scattering c(cid:13) B. Zwiebach In high energy physics experiments a beam of particles hits a target composed of par- ticles. By detecting the by-products one aims to study the interactions that occur during the collision. Collisions can be rather intricate. For example, the particles involved may be not ele...
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(cid:126)2 2M (7.1.1) (7.1.2) (7.1.3) Figure 7.1: Potential is finite range, or vanishes faster than 1 r as r → ∞ Will be consider solutions with positive energy. The energy is the energy of the particle far away from the potential, E = (cid:126)2k2 2M . The Schr¨odinger equation then takes the form (cid:20) − (cid:126)...
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ϕ(r) satisfies (7.1.4) for any r > a. For r < a, however, it does not satisfy the equation; ϕ(r) is a solution everywhere only if the potential vanishes. Given an incident wave we will also have a scattered wave. Could it be an ψ(r) = eikr that propagates radially out? (cid:0)∇2 + k2(cid:1) eikr (cid:54)= 0 fails badl...
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