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the car separations do not vary very rapid ly, except for a few isolated places where \jumps" occur. This process is il lustrated by the MatLab script randCFSM in the Athena 18311-Toolkit, which solves the equations in this model with random initial separations between the cars. We wil l come back to these issues in re...
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since (cid:15) = = . In fact, note that (cid:15) = O(N ) | since = O(1). L L L(cid:26) (cid:26) N J J L (cid:26) J 1 (cid:26) (cid:3) ! (cid:0) 1 (cid:3) (cid:26) Because of the way the equations were nondimensionalized, we see that: The separation between cars satis(cid:12)es (cid:15) (cid:15) h = x x = O((cid:15)) : ...
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0) n +1 n ! (cid:0) where the densities, velocities and positions are related, in the usual way, by u = U ((cid:26) ) and n n (cid:26) = (cid:15)=(x x ). Again, in addition to initial conditions a boundary condition is needed. For n n n +1 (cid:0) example, if there are N cars, then velocity (or the density) u of the le...
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:26)u = (cid:26)U ((cid:26)) = Q((cid:26)) and c = c((cid:26)) = . Thus we obtain the same dq ! d(cid:26) continuous tra(cid:14)c (cid:13)ow model that was developed in the lectures (see the lecture notes or the book by Haberman) using a phenomenological approach and conservation of cars. An interesting point arises no...
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in the equations. However, as long as 0 < (cid:26) 1, neither of these two things can happen. n (cid:20) Note 2.1 Notice that the argument in (ii) above shows that a density of one can be maintained only if the density is identical ly one from some car on forward. Else a decrease in density wil l propagate backward thr...
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also shows progressive steepening of the density pro(cid:12)le. However, rather than \topple over" and develop multiple values 9 > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > (as happens with the solution by characteristics of (2.5)), the solution of (2.6) (1.4) develops a very sharp tra...
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of the characteristic curves for equation (2.5), this means that the curves converge into the shock | and terminate there. Thus the shock path acts as a \cut" in space{ time, where the characteristic curves end. This prevents their crossing and the formation of multiply valued regions in the solution. Simple Tra(cid:1...
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h + u h + : : :, n +1 n n n n +1 n n n (1) (2) 2 1 where h = x x and we use the notation u = (x ; t). Thus n n n n +1 n j (cid:0) @x j ( ) j @ u 2 u u @u 1 1 @u 1 1 n n +1 (2) (3) 2 (2) 2 (3) (cid:0) n n n = (x ; t) + u h + u h + : : : = (x ; t) + (cid:15)u + (cid:15) u + : : : ; n n n n n x x @x 2 6 @x 2(cid:26) 6(cid...
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:26), this yields the equation @(cid:26) @(cid:26) 1 @ @ + c = (cid:15) (cid:23) ((cid:26)) (cid:26) ; (2.9) @ t @x 2 @x @x ! where (cid:23) = (notice that (cid:23) is a POSITIVE function of (cid:26)). Thus a (small) amount of dU (cid:0) d(cid:26) di(cid:11)usion is added to equation (2.5). As long as the derivatives a...
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of a few cars, which agrees well with the numerical results in (2.6). 3 Numerical Issues. Sti(cid:11)ness of the equations. We now go back to the discrete equations and perform an analysis to see what sort of time scales are involved in their behavior. This is important for many reasons, some of which we will explain l...
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7) t) (cid:0) (cid:0) 1 2 1 2 ik (cid:14) = e ; with (cid:27) = (cid:15) (cid:23) (cid:26) e 1 = (cid:15) (cid:23) (cid:26) (cos(k) 1) + i sin(k) ; (3.3) (cid:3) (cid:3) n (cid:3) (cid:3) 6 Notice that this is the same type of solution used in the von Neumann stability analysis of numerical schemes. (cid:0) f (cid:0) g...
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3.1 We note that (cid:28) is a very short time. As pointed out in remark 1.2, O(1) times m in the nondimensional equations typical ly correspond to a few minutes in dimensional units. Since (cid:15) = O(10 ), we see that (cid:28) corresponds to a dimensional time scale that must be measured m (cid:0) 2 in seconds! Now ...
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a new car added (or one gone) to the line. Note that it is important that a mathematical model be \stable" to such perturbations, else it is worthless (as the neglected e(cid:11)ects would be able to completely change the nature of the solution). On this last account (at least), the model (1.4) behaves the right way. ...
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equations given by (1.4) this would mean a time step as short as (cid:28) , which is disastrous! That is, we would be forced to resolve time scales m in the order of seconds (or fractions), while in fact the phenomena we are real ly interested in fol lowing take place over minutes or even hours. In fact, nothing happen...
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on being re-introduced by external perturbations). But the large scales have decay times much longer than (cid:28) | since the real part of (cid:27) behaves like k for k smal l. Thus, m 2 while short scale variations wil l be quickly dampened (and wil l become irrelevant), longer scales wil l remain for \reasonable" ti...
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other e(cid:11)ects destabilize. The interesting fact is that the time scales associated with them are about the same as those given by (cid:28) . But perhaps this is not too surprising, if one postulates a tendency m to \push the envelope" in terms of safety. That is: drivers wil l drive as fast and as close to the ne...
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15) (cid:0) Since u = U ((cid:26) + (cid:14) ) = u (cid:23) (cid:14) , we then have (using (3.4) n n n (cid:3) (cid:3) (cid:3) (cid:0) dy 1 n = (y y ) ; (3.5) n n +1 dt 2 (cid:28) m (cid:0) which (of course) is the same equation the (cid:14) ’s satisfy! n 4 Examples. In this section we consider examples of choices for ...
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40 mph was reasonable). In general these numbers are meant only as bal lpark (cid:12)gures. After nondimensionalization, we have the forms Q = 4(cid:26)(1 (cid:26)) ; U = 4(1 (cid:26)) and c = 4(1 2(cid:26)) : (4.1) (cid:0) (cid:0) (cid:0) In this case the shock speed in (2.7) is the average of the characteristic speed...
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26) u = : m max m m m m v (cid:26) r J v (cid:26) u r J max v + u v + u r max r max With u = 50 mph, v = 10 mph and (cid:26) = 160 cpm this yields (cid:26) 27 cpm and q 1330 cph max r J m m (cid:25) (cid:25) | not altogether unreasonable numbers. One point though is that (cid:26) = 160 cpm corresponds to J ‘ = 33 f t, ...
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:11) (1 (cid:11)) ! (cid:18) (cid:19) (cid:0) (cid:0) (cid:0) where 0 < (cid:11) = < 1. Note the strange feature of a piece-wise constant wave speed (cid:26) m (cid:26) J c. Thus, in the continuum limit, the parts of the density pro(cid:12)le with (cid:26) > (cid:11) move (backwards) at constant speed ((cid:11) 1) . Si...
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26, 1999 | Rosales. 5 Notes on the MatLab script quadCFSM. The MatLab script quadCFSM in the Athena 18311-Toolkit solves the equations in (1.4) us- ing the quadratic (cid:13)ow function (4.1) in example 4.1. A (cid:12)nite number of cars N is used, with x < x < : : : < x and the density 0 < (cid:26) < 1 at the leading ...
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have h (cid:0) N 1 (cid:15) (cid:25) = x (0) x (0) = : N p (cid:0) (cid:26) n n p = X 9 The leading car velocity is then also constant = 4(1 ). u (cid:26) N N (cid:0) Simple Tra(cid:14)c Flow Model. 16 MIT, Friday March 26, 1999 | Rosales. This equation determines the value of (cid:15) in terms of the number of cars i...
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(2.5) to deal with the well behaved parts of the solution | where we can use the characteristic method | and equations (2.7) and (2.8) to deal with the discontinuities (shocks). Notice that in this case the wave speed satis(cid:12)es c = 4 8(cid:26) and is a linear function of the density (cid:0) (cid:26). It then foll...
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the value of x on the (cid:0) Simple Tra(cid:14)c Flow Model. 17 MIT, Friday March 26, 1999 | Rosales. characteristic at time t = 0 and S (x; 0) = (x). This follows from the general solution of the dC equation above for S along characteristics: (cid:0) dx S ((cid:16) ; 0) S = : 1 + S ((cid:16) ; 0)t An analysis of thi...
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hump "die" at the shock. More precisely, the density disturbance will be made up only from characteristics that start near the leading edge (x = 0) of the initial hump, i.e. x = ct + (cid:16) ; with c = c C ((cid:16) ) and (cid:16) small and negative. (5.4) N (cid:0) Simple Tra(cid:14)c Flow Model. 18 MIT, Friday Marc...
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0) x 2. For x < x c t : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : c = . S N (cid:20) t 3. Elsewhere : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : c = c . N 4. The car density follows from : : : : : : : : : : ...
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That is, so that S the equation 2A = (c c )(c t x ) holds. Note that here we have used the fact that c N S N S itself is conserved, as stated earlier in (5.3). (cid:0) (cid:0) A more detailed justi(cid:12)cation of the arguments above can be found in the book by G. B. Whitham: Linear and Nonlinear Waves. Hopefully, it ...
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initial data close to the origin, with the rest meaningful only as far as determining the area parameter A. Thus, instead of reducing the information about this 10 Given any solution = ( ), = ( ) is also a solution (for any constants and ). The problem c c x; t c c x x ; t t x t (cid:0) (cid:0) (cid:3) (cid:3) (cid:3) ...
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(cid:3) > > > 2. For x < x c t : : : : : : : : : : : : : : : : : : : c = c + (x c t) = , > S N N N (cid:0) (cid:20) (cid:0) 1 + B t t t (cid:3) (cid:0) where x = c t and t = 1=B . N (cid:3) (cid:3) (cid:3) (cid:0) 3. Elsewhere : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : :...
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(cid:20) (cid:20) until after the target time. It is then over this range x x 0 that we need the approximation ‘ (cid:20) (cid:20) (5.6) to hold. Of course, the target time cannot be too small, for the range x x 0 has to be ‘ (cid:20) (cid:20) small enough that an approximation of the form (5.6) makes sense. Once x is ...
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26, 1999 | Rosales. Thus, we obtain (cid:15)(N ‘) + x (cid:26) ‘ N B = 16 : (5.8) (cid:0) 2 x ‘ Exact and approximate solutions. Shock r r N Dashed line = approximation. x Figure 5.4: This (cid:12)gure shows an example comparing an exact so- lution of the continuum limit and the approximation given by (5.7). Rema...
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Strategic Architectural Approaches at NASA Gary Martin November 14, 2004 MIT Overview • Decadal Planning Team (DPT) /NASA Exploration Team (NEXT) • Space Architect Team/New Vision for Space Exploration • Advanced Planning and Integration Office • A Few Points to Remember 2 Decadal Planning Team (DPT) /NASA Explorat...
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order to support future missions the NEXT team has identified the criteria that must be satisfied (the list runs in a logical order from top to bottom). • Transition to next chart: The technology needed to overcome these hurdles and enable new missions is determined in a systematic way. The NEXT is structured to co...
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food •• Materials, factor of 20 Materials, factor of 20 avionics /Nano-- avionics •• MicroMicro--/Nano •• •• ETO $/kg (under review) •• ETO $/kg (under review) Payload: 100+mt mt Payload: 100+ space propulsion, InIn--space propulsion, Isp>3000 sec, high thrust Isp>3000 sec, high thrust Sustainable power •• Sustai...
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and Research and Technology Technology 3.03.0 Technology Flight Technology Flight Demonstrations Demonstrations 2.12.1 Space Space Resources Resources Development Development 2.22.2 Space Utilities Space Utilities and Power and Power 2.32.3 Habitation and Habitation and BioBio-- astronautics astronautics 2....
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) • Intelligent Systems • ISTP • SLI • SBIR supporting (THREADS) • New Millennium Program • Data from Robotic Mars Missions/Experiments • In-Space Transportation Technology Program (ISTP) • Space Launch Initiative (SLI--coordination) • Instrument Incubator Program • Advanced Technology Initiative • Advanced Informat...
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w o L n I s s a M l a i t i n I 4000 ~~ 2000 ) t m ( 1500 1000 500 ISS Mass (~470 mt) All Solar Electric Propulsion 7 3 Opp-class Tether / Chemical 3 - Tether / Chemical 4 - High powered electric propulsion/nuclear electric propulsion (HPEP / NEP) 5 - Variable Specific Impulse Rocket (VaSImR) 6 - Solar Electric (S...
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90 2000 1990 2000 25 35 45 55 1.0 1.8 2.5 3.0 0.4 0.6 0.9 1.7 1.5 2.5 3.2 4.0 0.7 1.0 1.5 3.0 Age at First Mission No. of 180-day LEO missions** 25 35 45 55 Female 0 1 1 2 Male 1 1 2 3 Considerations • Costs of training • Costs of crew replacement • Career corps vs one- mission astronauts * 1 SV = 100 REM. 1 REM = mea...
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• Experience and Lessons Learned • Mission Performance Assessments 16 Example Science Activities Creating science instruments and observing platforms to search for life sustaining planets Search for evidence of life on planetary surfaces Large Space Telescope Construction and Maintenance Complexity/ Capabilit...
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and development plans – Define and prioritize requirements – Define and prioritize flight experiments • Comparing architectures specific measures of merit; – Safety – Cost – Performance – Mission return – Schedule 20 Space Architecture Planning Process Strategic Plan Enterprise Strategies Architectural Studies Goals ...
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3 Architecture Study #2 Focus • Multi-Enterprise Lunar Surface Exploration – Lunar surface biological research – Ops preparation for human Mars exploration – South Pole-Aitken Basin sample return – ISRU identification and assessment – South Pole observation station – Opportunistic lunar science Structure & Evol...
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solar system and beyond Extend human presence across the solar system, starting with a human return to the Moon by the year 2020, in preparation for human exploration of Mars and other destinations; Develop the innovative technologies, knowledge, and infrastructures both to explore and to support decisions about ...
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Orbital Tech Demos Lunar Exploration Systems Life Finder Planet Imager Extrasolar Planets Deep Space Telescope Deployment/Upgrades Mars and Beyond Exploration Systems Building Blocks CEV Test Flights CEV Operational Station Assembly Complete Human Research Complete Station Transition Space Shuttle Retirement Soyuz and...
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purposes and to support human exploration. (1.7) NASA shall conduct advanced telescope searches for Earth-like planets and habitable environments around other stars. 28 Level 0 Exploration Requirements (cont) (2) NASA shall acquire an exploration transportation system to support delivery of crew and cargo from the s...
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30 Notional Architecture Level 0 Architecture Trade Tree Science Investigation Surface Duration SFL ancient Life (See Chart ? for science content) SFL Modern Life (See Chart ? for science content) SFL extant life (Hydrothermal deposits) SFL Global Evolution 1 - 29 Days 30-90 days (Short) 91-500 Days (Long) (See C...
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deploy assets conjunction (See chart ? for details) deploy together opposition Aeroassisted Orbit Insertion Direct Entry from Earth Propulsive Orbit Insertion Mars Arrival, Descent/Ascent & Departure Separate Lander & Habitat Lander as Habitat Mars Orbit Rendezvous Direct Return to Earth Return in same vehicle Orbit th...
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ELV Different LV New LV HEO HEO Existing LV GEO GEO Update existing infrastructure Build new NASA Infrastructure Use new Industry infrastructure Nuclear Nuclear predeploy assets crew & cargo together as required for specific mission in campaign Advanced Chemical Advanced Chemical deploy together Crew Separate/ Split ...
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Current Structure and Management Methods Keep current NASA Infrastructure Keep current NASA workforce levels and competences Yes, in critical path (i.e. ISS) Government as System Integrator Design to cost Capability/Technology Development Develop Capabilities through infusion of new technologies as they become av...
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g e e t t a a r r t t S S Crew to Orbit approach Orbit Location for Assembly** Orbit Location for final Crew Rendezvous Launch Infrastructure Crew propulsive transit Cargo Propulsive Transit Cargo Predeployment Earth to Moon Transit Lunar Arrival Lunar Ascent/Descent Lunar Departure Earth Arrival Earth Surface Landing...
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30 2032 > 2032 Operations Infrastructure for Mars Combined DRAs IDs Overlaps Mars Surface Systems & Operations Science Investigation Surface Duration SFL ancient Life (See Chart ? for science content) 1 - 29 Days SFL Modern Life (See Chart ? for science content 30-90 days (Short) (See Chart ? for infered capabilit...
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/Communication Space Weather Use existing US assets, no additional investment Use existing US assets, no additional investment Emplace additional evolved infrastructure Emplace additional evolved infrastructure Cargo to Earth Orbit & Assembly Approach System Level Assy. & Docking - Infers AR&D an HLLV (See Chart ? ...
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Mission Duration on Moon All Systems Short (1-90days) Must Systems Long (>90da) Location Global Access Equatorial Must/Ought (See charts ? For test approach) Polar (See Chart ? for location/orbit metrics) Lunar Surface Systems and Operations Use an appropriate mix o military, NASA and indust assets Surface Approach C...
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Infrastructure Use new Industry infrastructure Nuclear Nuclear Advanced Chemical Advanced Chemical predeploy assets deploy together Transfer to Moon Chem/electric Chem/electric crew & cargo together as required for specific mission campaign Crew Separate/ Split Mission Lunar Arrival, Descent/Ascent, and Return Orbit...
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Current Structure & new managem methods New Structure & management methods Keep current NASA Infrastructure Keep current NASA workforc levels and competences Smaller NASA Infrastructure optimized with industry, universities, other agencies Smaller NASA workforce optimiz for critical NASA functions New NASA Infrastru...
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Mars Surface Landing Separate Lander & Habitat Lander as Habitat Mars Departure Mars Orbit Rendezvous Direct Return Heliocentric Transfer to Earth Return in same vehicle Return in different vehicle Earth Return Earth Arrival Earth Surface Landing Orbit then go get crew from Earth water Orbit, then Enter Direct Entry r...
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Orbit Operations System Level assy. & docking AR&D and Evolved ELV Different LV New LV HEO HEO Existing LV GEO GEO Update existing infrastructure Build new NASA Infrastructure Use new Industry infrastructure Nuclear Nuclear Advanced Chemical Advanced Chemical predeploy assets deploy together Transfer to Moon Chem/elect...
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e with flight hardware schedule Develop Capabilities through infusion o breakthrough technologies when they become available Agency Programmatic Approach Management Structure Current Structure and Management Methods Current Structure & new managem methods New Structure & management methods Agency Infrastructure Same ...
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argo* separately predeploy assets deploy together conjunction opposition (See chart 8 for details) conjunction (See chart 10 for details) opposition Aeroassisted Orbit Insertion Direct Entry Propulsive Orbit Insertion Mars Arrival, Descent/Ascent & Departure Separate Lander & Habitat Lander as Habitat Mars Orbit Rendez...
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evolved infrastructure Earth Orbit Approach Crew to Orbit approach Orbit Location for Assembly** Orbit Location for final Crew Rendezvous Launch Infrastructure Crew propulsive transit Cargo Propulsive Transit Cargo Predeployment Earth to Moon Transit Earth-to-Orbit and Orbit Operations System Level assy. & docking Au...
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onl (See Chart ? for lunar robotic optio Precursors Start in 2011 - multiple missions (S Chart ? for Mars robotic options) Start in 2016 or later Multiple orbiters, landers & sample returnsMultiple orbiters and landers Bioastronautics Use ground research only to certify crews for deep space Use ISS and ground research ...
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ARTH EARTH 33 Notional Architecture Example Short-Stay Missions • Typically referred to as opposition class missions • Characterized by – Only 1 Hohman transfer (short leg) – High-propulsive requirements for other leg (long leg) • Venus swing-by or deep-space Maneuvers • Close perihelion passage – Large variation i...
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requirements across mission opportunities Total Mission DV vs Earth Departure Date Depart Earth 2/18/31 Depart Mars 2/12/33 ) s / m k ( V D n o i s s i M 24 20 16 12 8 4 0 Sun Arrive Earth 9/18/33 γ Arrive Mars 9/16/31 01-Jan-15 31-Dec-18 30-Dec-22 29-Dec-26 28-Dec-30 Earth Departure Date 36 Notional Architect...
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vous and Docking – On-orbit assembly In-Space Transportation – Aeroassist – Electric propulsion – Nuclear Propulsion – High-efficiency chemical propulsion – Long-Term Propellant storage and handling • Planetary Operations – Entry / Descent / Landing • Aero Entry • Precision landing • Planetary Operations continued – Su...
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A Nuclear Transfer Propulsion DDT&E Subscale Test Off-Ramp Non-Nuclear Transfer Propulsion DDT&E Mars President's Vision President's Vision Milestone Milestone ATP ATP Key Decision Key Decision Pre-Phase A Transfer Vehicle DDT&E Pre-Phase A Lander Pre-Phase A Habitat Demo Pre-Phase A Nuclear Surface Power Pr...
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Portfolio Integration/ Portfolio Management Input to Strategic Process Academic & Industrial Community/ Directorates/ Centers Planning and Execution Directorates Advanced Planning and Integration Office Directorates 43 • Roadmapping Strategic Roadmap – A coordinated and comprehensive longitudinal strategy, with k...
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Lab 3 Revisited • Zener diodes R C 6.091 IAP 2008 Lecture 4 1 Lab 3 Revisited ready • Voltage regulators • 555 timers Vs = 5 V Vin Vc V c = V s − t RC 1 − e ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ +15 270 1N758 0.1uf 5K pot VCC 8 Threshold Control Voltage Trigger 6 5 2 5k 5k 5k V+ V- . + Comp A _ + Comp B _ 2N2222 Vo 0.1uf R S Flip Flop Q I...
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AP 2008 Lecture 4 4 Digital Circuits HCMOS 1 (high) – Output high: >3.98v – Input voltage high: >2.0V HCMOS 0 (low) – Output low: <0.4v – Input voltage low: 0.0 – 0.7v +5V +3.98V input high range +2.0V 0.7V Forbidden Zone 0.4V input low rage output high range noise margin noise margin output low range 6.091 IAP 2008...
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.091 IAP 2008 Lecture 4 10 74LS00 NAND Gate Dual-In-Line Package VCC B4 A4 Y4 B3 A3 Y3 14 13 12 11 10 9 8 1 2 3 4 5 6 7 A1 B1 Y1 A2 B2 Y2 GND This device contains four independent gates each of which performs the logic NAND function. Figure by MIT OpenCourseWare, adapted from the National Semiconductor 54LS00 datashee...
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51 8-1 Multiplexer Dual-in-line Package Data Inputs Data Select Inputs ready VCC D4 D5 D6 D7 A B C 16 15 14 13 12 11 10 9 1 2 3 4 5 6 7 8 D3 D2 D1 D0 Y W Strobe GND Data Inputs Outputs Select B X L L H H L L H H C X L L L L H H H H A X L H L H L H L H Strobe S H L L L L L L L L Outputs Y L D0 D1 D2 D3 D4 D5 D6 D7 W H ...
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H L H Z L H H L 6.091 IAP 2008 Lecture 4 Figure by MIT OpenCourseWare, based on Motorola datasheet. 16 74LS74 D Flip Flop Note both Q and Qbar SET-PRESET CLK SET D Q Q CLR CLR circle indicates inversion (active low) CLK D Q Reprinted with permission of National Semiconductor Corporation. 6.091 IAP 2008 Lecture 4 17 ...
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parallel data to serial data. 6.091 IAP 2008 Lecture 4 20 74LS175 4 Bit Shift Register 74LS175 13 15 12 10 5 7 4 2 SET D Q SET D Q SET D Q SET D Q CLR Q CLR Q CLR Q CLR Q 9 1 14 clock clear 11 6 3 Clock and Clear are common for all FF. The D FF will store the state of their individual D inputs on the LOW to HIGH ...
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Cin A 0 0 0 0 1 0 1 0 0 1 0 1 1 1 1 1 B 0 1 0 1 0 1 0 1 Sum Cout 0 0 0 1 0 1 1 0 0 1 1 0 1 0 1 1 A B Cin ADDER Cout Sum Sum = Cout = 6.091 IAP 2008 Lecture 4 23 Signed Numbers – Twos Complement • Positive Number: MSB=0 • Negative Number: MSB=1 • 4 Bit example • Simple addition & subtraction • Most common notation ...
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008 Lecture 4 26 Lab Exercise 4 Bit Counter – Logic Analyzer +5 Power connections not shown for 74LS163 7 10 9 1 P T LD CLR 14 13 12 11 QA QB QC QD 74LS163 counter +5 1.8432 Mhz crystal osc. Attach LA probe A2 to QA-QD 6.091 IAP 2008 Lecture 4 triangle is symbol for clock input 27 Lab Exercise Ramp Generator R R ...
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30 DA Summary • Output from digital to analog conversion are discrete levels. • More bits means better resolution. • An example of DA conversion – Current audio CD’s have 16 bit resolution or 65,536 possible output levels – New DVD audio samples at 192 khz with 24 bit resolution or 224 = 16,777,216 6.091 IAP 2008 ...
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at the end of the lab 6.091 IAP 2008 Lecture 4 37 Lab 5 • Design, build and keep the electronics for a digital lock. • Unlock key based on sequence of 0, 1. 6.091 IAP 2008 Lecture 4 38
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6.867 Machine learning, lecture 6 (Jaakkola) 1 Lecture topics: • Active learning • Non-linear predictions, kernels Active learning We can use the expressions for the mean squared error to actively select input points x1, . . . , xn, when possible, so as to reduce the resulting estimation error. This is an active...
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and therefore won’t affect how we should choose the inputs. When the choice of inputs is indeed up to us (e.g., which experiments to carry out) we can select them so as to minimize T r (XT X)−1 . One caveat of this approach is that it relies on the underlying relationship between the inputs and the responses to be li...
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v = [xT , 1]T . We would like to find a valid v that minimizes � T r (A−1 + vv T )−1 � The matrix inverse can actually be carried out in closed form (easy enough to check) (A−1 + vv T )−1 = A − 1 (1 + vT Av) AvvT A so that the trace becomes � T r (A−1 + vv T )−1 = T r [A] − � = T r [A] − = T r [A] − � T r...
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of A are positive as it is an inverse of a positive definite matrix XT X). It is indeed advantageous in linear regression to have the input points as far from each other as possible (see Figure 1). If we constrain �v� ≤ c, then the maximizing v is the normalized eigenvector of A with the largest eigenvalue, Cite as:...
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constrained to lie within [−1, 1]. Assume we have already observed responses for x1 = 1 and x2 = −1. Thus � X = 1 1 −1 1 � , XT X = � 2 0 0 2 � , A = (XT X)−1 = � � 1 1 0 0 1 2 (9) v = [x, 1]T and therefore vT Av = (x2 + 1)/2 and vT AAv = (x2 + 1)/4. The criterion to be maximized becomes vT AAv (1 +...
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on [DD Month YYYY].(cid:13)(cid:10) 6.867 Machine learning, lecture 6 (Jaakkola) 4 we are the most uncertain about. We again write v = [xT , 1]T so that V ar{y|x, X} = E ˆθT x + ˆθ0 − θ∗T x − θ∗ �� �� = E x 1 �T �� � � − ˆθ ˆθ0 � �T = x 1 = σ∗2 · v T Av � σ∗2(XT X)−1 x 1 θ∗ θ∗ 0 � � �2 ...
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∼ N (0, σ2). We can obtain a quadratic model by simply mapping the input x to a longer feature vector that includes a term quadratic in x. A third order model can be constructed by including all terms up to degree three, and so on. Explicitly, we would make linear predictions using feature vectors √ √ φ x → [1, φ ...
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were generated from a linear model). Note that all these models are linear in the parameters but non-linear in x, save the standard linear regression model in Figure 2a. The polynomial expansion of input vectors works the same in higher dimensions, e.g., x = [x1, x2]T → [1, x1, x2, φ √ 2x1x2, x 1, x 2]T = φ(x) 2...
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of the power of this approach, let’s evaluate the inner product between two feature vectors corresponding to the specific cubic expansions of 1-dimensional inputs shown before: φ(x) = φ(x�) = √ √ [1, [1, √ √ 3x, 3x�, , 3]T 2 3x , x 3x�2 , x�3]T , φ(x)T φ(x�) = 1 + 3xx� + 3(xx�)2 + (xx�)3 = (1 + xx�)3 (20) ...
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in conjunction with mapping examples to higher dimensional feature vectors. The regularized least squares objective to be minimized, with parameter λ, is given by J(θ) = n � � yt − θT φ(xt) �2 + λ�θ�2 (23) t=1 Cite as: Tommi Jaakkola, course materials for 6.867 Machine Learning, Fall 2006. MIT OpenCourseWare (h...
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6.720J/3.43J - Integrated Microelectronic Devices - Spring 2007 Lecture 8-1 Lecture 8 - Carrier Drift and Diffusion (cont.), Carrier Flow February 21, 2007 Contents: 1. Quasi-Fermi levels 2. Continuity equations 3. Surface continuity equations Reading assignment: del Alamo, Ch. 4, §4.6; Ch. 5, §§5.1, 5.2 Cite as...
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EF relates no with Nc and po with Nv: no = NcF1/2( EF − Ec ) kT po = NvF1/2( Ev − EF kT ) Outside TE, EF cannot be used. Define two ”quasi-Fermi levels” such that: n = NcF1/2( Efe − Ec ) kT p = NvF1/2( Ev − Efh ) kT Under Maxwell-Boltzmann statistics (n (cid:3) Nc, p (cid:3) Nv): n = Nc exp Efe − Ec kT ...
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Integrated Microelectronic Devices, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.720J/3.43J - Integrated Microelectronic Devices - Spring 2007 Lecture 8-5 � Physical meaning of ∇Ef For electrons, Then: Je = μen dEfe dx = −qnve dE...
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(http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.720J/3.43J - Integrated Microelectronic Devices - Spring 2007 Lecture 8-7 2. Visualize currents dEfe Je = μen dx = 0 • ∇Efe = 0 ⇒ Je = 0 ⇒ Je = 0 • ∇Efe (cid:5) • if n high, ∇Efe small to maintain a certain current lev...
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materials for 6.720J Integrated Microelectronic Devices, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.720J/3.43J - Integrated Microelectronic Devices - Spring 2007 Lecture 8-9 2. Continuity Equations Semiconductor physics so far: Gau...
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electrons in ΔV = rate of electron generation in ΔV - rate of electron recombination in ΔV - net flow of electrons leaving ΔV per unit time ∂(nΔV ) ∂t = GΔV − RΔV − Fe.dS � (cid:2) (cid:2) Dividing by ΔV and taking the limit of small ΔV : ∂n ∂t = G − R − (cid:2) F(cid:2) e∇. Cite as: Jesús del Alamo, course m...
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Gs-Rs=Fs Fs>0 Fs<0 Fs<0 Fs>0 x x x x Rewrite in terms of current densities normal to surface: |Us| = 1 q |Jes| = 1 |Jhs| q Always, no net current into surface: Js = Jes + Jhs = 0 =⇒ Jes = −Jhs Cite as: Jesús del Alamo, course materials for 6.720J Integrated Microelectronic Devices, Spring 2007. MIT Open...
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- Spring 2007 Lecture 8-14 � If there is net generation or recombination at surface right below ohmic contact ⇒ minority carrier current in addition to majority carrier current Three possible cases (examples for n-type): I Fes I Fes I Fhs n Fhs Fes n ohmic contact with net recombination ohmic contact w...
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Continuity equations: ”book-keeping” relations for carriers. • Surfaces cannot store carriers: at all times must have current balance at surface. • At ”free” surface: electron and hole currents result from carrier generation or recombination at surface (but net current is zero). • At ohmic contact: – additional m...
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3.37 (Class8) Review C4 (Area Array) 1000-2000 I/O Cold welding • Aluminum is the second easiest metal to cold weld • Make near perfect welds in aluminum wire Adhesive Bonding • Unique in that it does not remove surface contamination • Type I Adhesive Bonding results from attractive force of wetted liquid at th...
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Joints, Acad Press, 1961 o None of the modern books on adhesives go through this • Force*time product = see equation on board o Viscosity o Initial and final separations o Radius for a circular disc • Looking at different forces, viscosities, radii, and separations o Water at given parameters 7.5ms o As the joi...
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MIT OpenCourseWare http://ocw.mit.edu 18.727 Topics in Algebraic Geometry: Algebraic Surfaces Spring 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. ALGEBRAIC SURFACES, LECTURE 4 LECTURES: ABHINAV KUMAR We recall the theorem we stated and lemma we proved f...
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1) S1 q � � S q� �������� � � � S� φ The projections q, q� are birational morphisms and the diagonal morphism com­ mutes. Since φ−1(q) is not defined, (q�)−1(p) is not defined either, so ∃C1 ⊂ S an irreducible curve s.t. q�(C1) = {p}. Moreover, q(C1) = C is a curve in S: if not, since S1 ⊂ S × S�, q(C1) a point ...
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p. Let Ox,q be the local ring of X at q, and let mq be its maximal ideal. We claim that there is a local coordinate y on S at p s.t. f ∗y ∈ m2 q . To see this, let (x, t) be a local system of coordinates at p. If f ∗t ∈ m2 q , then f ∗t vanishes on f −1(p) with multiplicity 1, so it defines a local equation for f ...
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morphism of surfaces. Then ∃ a (k = 1, . . . , n) and an isomorphism S ∼ Sn Proposition 1. Every morphism from S˜ to a variety X that contracts E to a point must factor through S. Proof. We can reduce to X affine, then to X = An, then to X = A1 . Then f defines a function on ˜ � Theorem 2. Let f : S → sequence of blowu...
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