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Recursion Theorem (Sipser Theorem 6.3): Let T be a TM that computes a (possibly partial) 2-argument function t: Σ* × Σ* → Σ*. <M> w T t(<M>, w) Then there is another TM R that computes the function r: Σ* → Σ*, where for any w, r(w) = t(<R>, w). w R t(<R>, w) Applications of the Recursion Theorem Applications of...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
w> then accept. Application 1: AccTM is undecidable • Suppose for contradiction that D decides AccTM. • R: On input w: – Obtain < R > – Run D on input <R, w> – Do the opposite of what D does: • If D accepts <R, w> then reject. • If D rejects <R, w> then accept. • Now get a contradiction: – If R accepts w, then • D ...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
else), by definition of R. – If R does not accept 01, then • D rejects <R> since D is a decider for Acc01TM, so • R accepts 01 (and everything else), by definition of R. • Contradiction. So D can’t exist, so Acc01TM is undecidable. Applications of Recursion Theorem • Application 3: Using Recursion Theorem to prove R...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
• Rice’s Theorem: Let P be a nontrivial property of Turing- recognizable languages. Let MP = { < M > | L(M) ∈ P }. Then MP is undecidable. • L(M1) ∈ P, L(M2) ∉ P. • D decides MP. • R: On input w: – Obtain < R > – Run D on input <R> – If D accepts <R> then run M2 on input w and do the same thing. – If D rejects <R> t...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
the same language }. – Theorem: MINTM is not Turing-recognizable. – Note: This doesn’t follow from Rice: • Requires non-T-recognizability, not just undecidability. • Besides, it’s not a language property. – Proof: • Assume for contradiction that MINTM is Turing-recognizable. • Then it’s enumerable, say by enumerator ...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
. w Q q(w) = < Pw > Proof of RT: Special Case • Lemma: (Sipser Lemma 6.1): There is a computable function q: Σ* → Σ* such that, for any string w, q(w) is the description of a TM Pw that just prints out w and halts. w Q q(w) = < Pw > • Now, back to the machine that outputs its own description… • Consists of 2 sub-...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
• Claim A ° B outputs its own description, which is < A ° B >. • Check this… • A is P<B>, so the output from A to B is <B>: <B> A = P<B> • Substituting B for M in B’s output: <B> A = P<B> B B < P<B> ° B > Combining the Pieces • A ° B: A B • Claim A ° B outputs its own description, which is < A ° B >. <B> A = P<B> B < ...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
�* → Σ*, where for any w, r(w) = t(<R>, w). • Construct R from: – The given T, and – Variants of A and B from the special- case proof. <M> w T R t(<M>, w) w t(<R>, w) Proof of RT: General Case • R looks like: A B T • Write this as (A ° B) °1 T – The °1 means that the output from (A ° B) connects to the first (top) ...
https://ocw.mit.edu/courses/6-045j-automata-computability-and-complexity-spring-2011/2fe1aea3ab4dd67aff81f2a04fc010ef_MIT6_045JS11_lec10.pdf
B • Now combine with T, plugging in R for M in T’s input: <B °1 T > < R> A B t(<R>,w) T w Combining the Pieces <B °1 T > < R> A B t(<R>,w) T w • Thus, R = (A ° B) °1 T, on input w, produces t(<R>,w), as needed for the Recursion Theorem. w R t(<R>, w) Next time… • More on computabilty theory • Reading: – "Computin...
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Examples of Transient RC and RL Circuits. The Series RLC Circuit Impulse response of RC Circuit. Let’s examine the response of the circuit shown on Figure 1. The form of the source voltage Vs is shown on Figure 2. R Vs C + vc - Figure 1. RC circuit Vs Vp 0 tp Figure 2. t We will investigate the response vc t ( ...
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⎦ ⎞ ⎟ ⎟ ⎠ 0 t ≤ ≤ tp (1.3) When RC t(cid:21) the higher order terms may be neglected resulting in vc t ( ) (cid:17) Vp t RC 0 t ≤ ≤ tp At the end of the pulse (at t tp= ) the voltage becomes vc t ( = tp ) (cid:17) Vptp RC 6.071/22.071 Spring 2006, Chaniotakis and Cory (1.4) (1.5) 2 ...
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2 Volt car battery. The spark plug is connected actors the inductor and current may flow though it only if the voltage across the gap of the plug exceeds a very large value (about 20 kV). + Vb - R L + vL - Figure 5 spark plug When the switch is closed, the current through the inductor reaches a maximum value of /V...
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The voltage across the coil when the switch is opened is v L = i ∆ t ∆ = 0.01 2.4 1 10 × − 6 = 24 kV 6.071/22.071 Spring 2006, Chaniotakis and Cory 5 Response of RC circuit driven by a square wave. Let’s now consider the RC circuit shown on Figure 6(a) driven by a square wave signal of the for...
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⎤ ⎥ ⎦ + t − RC ⎤ Vp e ⎥ ⎥ ⎦ (1.13) (1.14) Similarly the response during the first part of the second cycle starts with the value of vc at t=T and evolves towards the value Vp. If the time constant is small compared to the period of the square wave, the response will reach the maximum and minimum values of the sq...
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9 Second Order Circuits Series RLC circuit The circuit shown on Figure 10 is called the series RLC circuit. We will analyze this circuit in order to determine its transient characteristics once the switch S is closed. Vs S + vR - + vL - R L C + vc - Figure 10 The equation that describes the response of...
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And 2 s + R L s + 1 LC = 0 α= R L 2 οω = 1 LC The characteristic equation becomes 2 s + = οα ω 0 2 + s 2 The roots of the characteristic equation are 1s 2s = − + 2 α α ω ο − 2 = − − 2 α α ω ο − 2 And the homogeneous solution becomes hvc = A e 1 1 s t 2 s t + A e 2 The total solution now becomes vc Vs A e 1 = + s...
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− α ω ο = j 2 ω ο 2 −α In this case the roots s1 and s2 are complex 2 α ω α − 2 ο j s 1 = − + numbers: oscillatory behavior Under Damped System s , 2 = − − 2 α ω α − j 2 ο . System exhibits Important observations for the series RLC circuit. • As the resistance increases the value of α increases and the system is ...
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solution of the form stAe the characteristic equation is Where οω = 1 LC The two roots are 2 s 2 οω+ = 0 1s j οω= + 2s j οω= − And the solution is a linear combination of 11 s t A e and A e 22 s t ( ) vc t = 1 A e oj ω t + 2 A e t j ω− ο By using Euler’s relation Equation (1.34) may also be written as vc t ( )...
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( t ω ω ο ο ) (1.36) (1.37) (1.38) (1.39) (1.40) And the voltage across the inductor is easily determined from KVL or from the element relation of the inductor vL L = di dt vL = − = − vc Vo cos( tω )o (1.41) Figure 13 shows the plots of vL t and i t ( ) between vc(t) and vL(t) and the 90 degree phase differenc...
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Image Quality Metrics • Image quality metrics • Mutual information (cross-entropy) metric • Intuitive definition • Rigorous definition using entropy • Example: two-point resolution problem • Example: confocal microscopy • Square error metric • Receiver Operator Characteristic (ROC) • Heterodyne detection MIT 2.71...
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  2σ Precision of measurement = C + ... n1 ∑ 2 k 1=   ln + 1  2   ln + 1  µ 2 − 2 t 2σ  µ k  = 2σ      ln +  + 1   ≈precision of (t-2)th measurement E.g. 0.5470839348 these digits worthless if σ ≈10-5 MIT 2.717 Image quality metrics p-5 2 < < −µ σ µ 2 2 t t 1 no...
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6 Formal definition of cross-entropy (2) • Fair coin: p(H)=1/2; p(T)=1/2 1 Entropy = − 2 log 2 1 2 − 1 2 log2 = bit1 1 2 • Unfair coin: p(H)=1/4; p(T)=3/4 1 Entropy = − 4 log2 log 2 1 4 3 4 − 3 = 4 81.0 bits Maximum entropy ⇔⇔⇔⇔⇔⇔⇔⇔ Maximum uncertainty Maximum uncertainty Maximum entropy MIT 2.717 ...
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hardware channel “physical attributes” (measurement) H detection g Formal definition of cross-entropy (5) object hardware channel “physical attributes” (measurement) f field propagation H detection g Noise adds uncertainty ⇔ eliminates information adds uncertainty to the measurement wrt the object elim...
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2.717 Image quality metrics p-13 Entropy & Differential Entropy • Discrete objects (can take values among a discrete set of states) – definition of entropy ( Entropy = −∑ x p k )log 2 ( x p k ) k – unit: 1 bit (=entropy value of a YES/NO question with 50% uncertainty) • Continuous objects (can take values fro...
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metrics p-16 n  + 1 ∑  ln 1 2  = 1 k 2 k 2 µ σ    As noise increases is lost whenever • one rank of σ2 overcomes a new eigenvalue • the remaining ranks lose precision H 2σ Example: two-point resolution Finite-NA imaging system, unit magnification Two point-sources (object) f A A x ...
https://ocw.mit.edu/courses/2-717j-optical-engineering-spring-2002/302f8fb4454a52e44502785c2e046203_imgq.pdf
��  + 1 2 ) ( 1 − s 2σ MIT 2.717 Image quality metrics p-19  1  +  2   ln + 1   ( 1 + s 2σ ) 2     IMI vs source separation MIT 2.717 Image quality metrics p-20 s→ 1 ) ( = SNR 1 σ 2 s→ 0 IMI for rectangular matrices (1) H = = H underdetermined underdetermined (more unknowns than ...
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Image quality metrics p-23 Confocal microscope Small pinhole: Depth resolution Light efficiency Large pinhole: Depth resolution Light efficiency virtual slice pi nhole object beam splitter Intensity detector MIT 2.717 Image quality metrics p-24 Depth “resolution” vs. noise NA=0.2 Object structure: p...
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 result of inversion    – e.g. pseudoinverse minimizes MSQ in an overdetermined problem – obvious problem: most of the time, we don’t know what f is! – more when we deal with Wiener filters and regularization • • Receiver Operator Cha Receiver Operator Charracteacterriisstictic – measures the performance of a c...
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6.231: DYNAMIC PROGRAMMING LECTURE 1 LECTURE OUTLINE Problem Formulation Examples The Basic Problem Significance of Feedback • • • • 1 DP AS AN OPTIMIZATION METHODOLOGY Generic optimization problem: • min g(u) u∈U where u is the optimization/decision variable, g(u) is the cost function, and U is the constraint set • Cat...
https://ocw.mit.edu/courses/6-231-dynamic-programming-and-stochastic-control-fall-2015/304cf17d604e774625dae63810777264_MIT6_231F15_Lec1.pdf
Stock at Period k xk Inventory System Stock at Period k + 1 xk + 1 = xk + uk - wk Cost of Period k r(xk) + cuk Stock ordered at Period k uk Discrete-time system xk+1 = fk(xk, uk, wk) = xk + uk wk − Cost function that is additive over time • • N −1 E gN (xN ) + ( k=0 X N −1 gk(xk, uk, wk) ) = E cuk + r(xk + uk ( k=0 X (...
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CCA CCD CD ABC CCD ACB CBD ACD CDB CAB CBD CAD CDB CBC CCB CCD CAB CAD CDA CDA CAB 6 STOCHASTIC FINITE-STATE PROBLEMS • Example: Find two-game chess match strategy Timid play draws with prob. pd > 0 and loses pd. Bold play wins with prob. pw < • with prob. 1 − 1/2 and loses with prob. 1 pw − 0.5-0.5 pd 0 - 0 1 - pd pw ...
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uk) of wk ∈ Expected cost of π starting at x0 is • • • Jπ(x0) = E gN (xN ) + ( N −1 k=0 X gk(xk, µk(xk), wk) ) Optimal cost function J ∗(x0) = min Jπ(x0) π Optimal policy π∗ satisfies • • Jπ∗ (x0) = J ∗(x0) When produced by DP, π∗ is independent of x0. 8 SIGNIFICANCE OF FEEDBACK • Open-loop versus closed-loop policies w...
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Horizon Problems - Simple (Vol. 1, Ch. − − • 7, 3 lectures) ******************************************** • − Infinite Horizon Problems - Advanced (Vol. 2) Chs. 1, 2: Discounted problems - Computa- tional methods (3 lectures) Ch. 3: Stochastic shortest path problems (2 lectures) Chs. 6, 7: Approximate DP (6 lectures) − −...
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6.776 High Speed Communication Circuits Lecture 2 Transceiver Architectures Massachusetts Institute of Technology February 3, 2005 Copyright © 2005 by H.-S. Lee and M. H. Perrott Transceivers for Amplitude Modulation H.-S. Lee & M.H. Perrott MIT OCW Amplitude Modulation Review Transmitter Output 0 x(t) y(t) 2cos(2πfo...
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AM Transmitter Balanced modulator -90o phase shifter Balanced modulator Power Amp + RF Filter QAM H.-S. Lee & M.H. Perrott MIT OCW SSB Transmitter I (cid:131) Phase-shift SSB Modulator Balanced modulator -90o phase shifter -90o phase shifter Balanced modulator Power Amp + RF Filter SSB (cid:131) Sideband removal depen...
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Crystal (piezo) Earpiece (cid:131) Applicable only to standard AM signals (DC shifted baseband) (cid:131) No active component: very simple and cheap (cid:131) Low sensitivity: only strong stations can be tuned in (cid:131) Poor selectivity (single RF filter) (cid:131) Low baseband output power: can only drive high effi...
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& M.H. Perrott MIT OCW Super-regeneration Receiver R1 -R2 Envelope Detector Audio out Quench (cid:131) Quench circuit is either an oscillator (quenching at regular intervals) or amplitude detector (quenches when predetermined amplitude is reached) (cid:131) Large effective RF gain can be achieved by a single stage ...
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Perrott MIT OCW Superheterodyne Receiver Spectra H.-S. Lee & M.H. Perrott MIT OCW Image Rejection in Superheterodyne Receivers (cid:131) Key Point: image signal at equidistance from flo converts to the same IF band (cid:131) The RF filter must remove image! (image reject filter) (cid:131) Want high IF frequency for e...
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Extractor or LO LPF Audio Freq. (AF) Amplifier (cid:131) Mixes RF signal with the carrier frequency down directly to baseband: no image to reject H.-S. Lee & M.H. Perrott MIT OCW Homodyne Receiver Cont’d (cid:131) No local oscillator if pilot carrier is present – carrier extracted from the transmitted signal (carri...
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and high selectivity in the baseband processing circuit (cid:131) Channel filtering is typically performed by DSP (cid:131) No image to reject (cid:131) Time-varying DC offset due to local oscillator leakage is an important issue (cid:131) DC offset can be larger than signal and saturate baseband circuits H.-S. Lee ...
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- 4&1 I-Phase (cid:131) Similar to Weaver SSB generator (P.S. #1) (cid:131) Image rejection by phase relationship – no passive Figure by MIT OCW. components (cid:131) Image rejection limited by amplitude and phase matching of 6 mixers! H.-S. Lee & M.H. Perrott MIT OCW Low-IF Receiver RF Filter RF Amplifier (LNA) Qua...
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’s (Albert Jerng’s VCO’s) 1.8V 1.8V L L Vtune L Vtune L NMOS VCO PMOS VCO H.-S. Lee & M.H. Perrott Figure by MIT OCW. MIT OCW PLL-Based Frequency Modulation Phase detector Loop filter VCO (cid:131) The loop bandwidth must be lower than the lowest signal frequency (cid:131) The center frequency is precisely maintaine...
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H.-S. Lee & M.H. Perrott MIT OCW FM Demodulator Using Phase-Locked Loop Limiter Phase detector Loop filter VCO (cid:131) VCO input voltage is used as output (cid:131) VCO is in feedback loop: input output characteristic is the inverse of VCO function (thus f-to-v conversion). H.-S. Lee & M.H. Perrott MIT OCW
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Lecture 7 PN Junction and MOS Electrostatics(IV) Metal­Oxide­Semiconductor Structure (contd.) Outline 1. Overview of MOS electrostatics under bias 2. Depletion regime 3. Flatband 4. Accumulation regime 5. Threshold 6. Inversion regime Reading Assignment: Howe and Sodini, Chapter 3, Sections 3.8-3.9 6.012 Sprin...
https://ocw.mit.edu/courses/6-012-microelectronic-devices-and-circuits-spring-2009/30d115908b75764ef7ebe79517ac5e8a_MIT6_012S09_lec07.pdf
example: Depletion region thickness: xd (VGB ) =  εεεεs   1+ Cox  2C 2 (φφφφB + VGB) εεεεsqNa ox   − 1   Potential drop across semiconductor SCR: VB (VGB ) = qN x 2 d a 2ε s Surface potential φφφφ(0) = φφφφp + VB(VGB) Potential drop across oxide: Vox (VGB ) = qN a x d t ox ε ox 6.012 Spri...
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) kT Solve for φ(0) at VGB = VT: φφφφ( 0 ) VGB =VT = kT q • ln n ( 0 ) n i VGB = VT = kT q • ln N a = − φφφφp ni Hence: VB (VT ) = −2φφφφp 6.012 Spring 2009 Lecture 7 9 Computation of threshold voltage (contd.) Second, compute potential drop in oxide at threshold. Obtain xd(VT) using relationship betwe...
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↑↑. The higher the doping, the more voltage required to produce n(0) = Na • If C ox ↑↑↑↑ (tox ↓↓↓↓) ⇒⇒⇒⇒ VT ↓↓↓↓. The thinner the oxide, the less voltage dropped across the oxide. 6.012 Spring 2009 Lecture 7 11 6. Inversion What happens for VGB > VT? More electrons at Si/SiO2 interface than acceptors ⇒⇒⇒⇒ inv...
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inv.) ≈ VB(VT ) = −2φφφφP 6.012 Spring 2009 Lecture 7 14 Charge­Control Relation (contd..) • All extra voltage beyond VT used to increase inversion charge Qn. Think of it as capacitor: – Top plate: metal gate – Bottom plate: inversion layer Q = CV ⇒ QN = −Cox (VGB − VT ) Coul/cm2 for VGB > VT Existence of...
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s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 10 1 5 3 2 4 3 2 3 6 5 -15 4 1 5 6 -5 2 4 6 7 10 The s...
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3 10 11 9 7 6 13 1 4 8 12 2 5 3 10 11 9 7 6 13 1 4 8 12 2 5 3 10 11 9 7 6 13 1 4 8 12 2 5 3 10 11 9 7 6 13 1 4 8 12 2 5 3 10 11 9 7 6 13 MIT OpenCourseWare http://ocw.mit.edu 15.093J / 6.255J Optimization Methods Fall 2009 For information about citing these materials or our Terms of Use, visit: http://ocw.mit...
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Advanced System Architecture ESD.342/EECS 6.883 2006 • Goals of this course: • Gain an understanding of system architecture • Learn existing theoretical and analytical methods • Compare systems in different domains and understand what influences their architectures • Apply/extend existing theory in case studies Adv Sy...
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assignments and exercises to learn to use the software • Case study project with periodic reports in class • Class overheads, assigned reading, and optional reading posted on class website. Adv Sys Arch intro 8/24/2006 © Daniel E Whitney 5 Grading Formula • 15% in-class participation (especially reading connections...
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through these different lenses. Adv Sys Arch intro 8/24/2006 © Daniel E Whitney 9 A “Perfect” Theory of Architecture Would Permit Us To: • Measure • Characterize • Understand at a fundamental level • Design, operate, evaluate, improve • Predict future behavior Adv Sys Arch intro 8/24/2006 © Daniel E Whitney 10 A Def...
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4 (see assignment 1) Adv Sys Arch intro 8/24/2006 © Daniel E Whitney 14 Some Things Do Not Have Architectures with Internal Structure • Random Networks • Perfect gases • Crowds of people • Their behavior can still be analyzed and often forms a baseline for comparison to things that do have architectures with signif...
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Overtly designed – Can be an architect – A design strategy is practical – Products, product families – Cars, airplanes – Bell System – Organizations – Centrally-planned economies • Infrastructures – Architect not common – Protocols and standards are crucial – Design strategy may or may not be practical – May be d...
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9 Comments on Typologies: Attributes of Effective Classification Standards for Taxonomy • – Collectively Exhaustive and Mutually Exclusive – Internally Homogeneous – Stability – Understandable Representation and Naming • None of the approaches really fulfill these criteria. Interestingly (more later in course), no c...
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they be used? • Assuming we know what functions, performance, and ilities we want, what methods can be used to create a suitable architecture? • Assuming we know what architecture we want, what are the most effective ways of influencing the architecture of complex, evolving engineering systems? Adv Sys Arch intro 8...
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2.997 Decision-Making in Large-Scale Systems MIT, Spring 2004 March 8 Handout #13 Lecture Note 10 1 Value Function Approximation DP problems are centered around the cost-to-go function J ⁄ or the Q-factor Q⁄. In certain problems, such as linear-quadratic-Gaussian systems, J ⁄ exhibits some structure which allows for it...
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current falling piece. More speciflcally, we have b(i; j) = 1, if position (i; j) of the board is fllled, and b(i; j) = 0 otherwise. If there are p difierent types of pieces, and the board has dimension n £ m, the number of states is on the order of p £ 2n£m, which grows exponentially with n and m. Since exact solution of...
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‚(u); (1) where U is the set of all possible policies. In principle, we could solve (1) by enumerating all policies and choosing the one with the smallest value of ‚(u); however, note that the number of policies is exponential in the number of states | we have jYj = jAjjSj; if there is no special structure to U, this p...
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efiective approximation. First, we need to choose a parameterization ~J that can closely approximate the desired cost-to-go function. In this respect, a suitable choice requires some practical experience or theoretical analysis that provides rough information on the shape of the function to be approximated. \Regularitie...
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easy to see that a neural network represents a function ~J(x; r), where x is the input and r is the set of weights in each of the perceptrons. Recall that we are interested in representing a function J ⁄(x) as ~J(x; r), for some set of weights r. Part of the appeal of neural networks is that they can be e–ciently train...
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partitioning of the state space as a tree or using adaptive methods for choosing the partitions, for instance. 4 (cid:15) (cid:15) (cid:16) (cid:16) (cid:17) (cid:17) (cid:18) (cid:18) (cid:19) (cid:19) (cid:20) (cid:20) 2.3 Features A special case of state space partitioning consists of mapping states to features, an...
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130 RICHARD B. MELROSE 18. Solutions to (some of) the problems Solution 18.1 (To Problem 10). (by Matjaˇz Konvalinka). Since the topology on N, inherited from R, is discrete, a set is com­ C)→ pact if and only if it is finite. If a sequence {xn} (i.e. a function N is in C0(N) if and only if for any � > 0 there exist...
https://ocw.mit.edu/courses/18-155-differential-analysis-fall-2004/316b53904ce106dc33393334695469c8_solution_prob.pdf
� y �→ xnyn is linear and bounded ( �x�0, the mapping � | ∞ =1n n=1 xnyn| ≤ ∞ =1n � |xn||yn| ≤ �x�0 �y�1) by Φ : l1 �−→ c∗ 0 defined by � �→ y x �→ � ∞ � xnyn n=1 is a (linear) well­defined mapping with norm at most 1. In fact, Φ is an isometry because if |xj| = �x�0 then Φ(x)(ej)| = 1 where ej is the j­...
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H(x)ϕ � ∞ i � ϕ (x) dx = i(0 − ϕ(0)) = −iδ(ϕ), we get DxH = Cδ for C = −i. 0 LECTURE NOTES FOR 18.155, FALL 2004 131 Solution 18.3 (To Problem 40). (Matjaˇz Konvalinka) Let us prove this in the case where n = 1. Define (for b = 0) U (x) = u(b) − u(x) − (b − x)u�(x) − . . . − (b − x)k−1 (k − 1)! u (k−1)(x); t...
https://ocw.mit.edu/courses/18-155-differential-analysis-fall-2004/316b53904ce106dc33393334695469c8_solution_prob.pdf
decomposition is u(x) = p(x) + v(x) for p(x) = u(0) + u�(0)x + u��(0) 2 2 x + . . . + u(k−1)(0) (k − 1)! x k−1 + u(k)(0) k! k x , v(x) = u(x) − p(x) = u(k)(ζ) − u(k)(0) k! k x for ζ between 0 and x, and since u(k) is continuous, (u(x) − p(x))/xk tends to 0 as x tends to 0. The proof for general n is n...
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p (od degree k), and we have vx(1) |k | x so it is bounded by a positive combination of terms of the form wx (ζx) − wx (0) k!|x|k u(x) − p(x) |k | x = = , (k) (k) � � � � ∂x l1 ∂lu 1 ∂x l2 2 · · · li ∂x i (ζxx) − ∂lu 1 ∂x l2 2 · · · ∂x l1 li ∂x i (0) � � � � with l1 + . . . + li = k and 0 < ζx < 1...
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well­defined, coincides with f on Sn−1, and is continuous: if M is the maximum of |g| on Sn−1, and � > 0 is given, then f (x) < � for | | x < �/M. | | Solution 18.5. (partly Matjaˇz Konvalinka) For any ϕ ∈ S(R) ∞ � | −∞ ϕ(x)dx| ≤ | ϕ(x) dx ≤ sup((1+x | we have � ∞ −∞ � � ∞ 2 | | ) ϕ(x) ) | (1+ x| | 2)−1dx ...
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) � LECTURE NOTES FOR 18.155, FALL 2004 133 so it suffices to show that xkAψ is bounded for any k as |x| → ±∞. Since ψ(t) − cφ(t) ≤ Ckt−k−1 in t ≥ 1 it follows from (18.2) that x kAψ(x) ≤ Cx k | | ∞ t−k−1dt ≤ C �, k > 1, in x > 1. � x A similar estimate as x → −∞ follows from (18.1). Now, A is clearly linear, a...
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� Rn �ξ�2(m+m� ) 2 dξ < ∞. | | u � �ξ�2(m+m�)|�|2 dξ = u �ξ�2m� (1 + ξ1 2 + . . . + ξ2 n)m|u| � 2 dξ = But that is true since � Rn � = Rn �ξ�2m� ⎛ ⎝ � |α|≤m Cαξ2α � Rn ⎞ ⎠ |�|2 dξ = u � |α|≤m Cα �� Rn � �ξ�2m� ξ2α u |�|2 dξ u = ξ�m� Dαu is in L2(Rn) (note that u ∈ H m(Rn) � � (Rn), α ≤ m). The...
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j Then obviously we have 1 = χEj v. Then �x� is bounded by Ej, 1 ≤ j ≤ n, we have � x� xj| | ≤ (1 + n|xj|2)1/2 |xj| = � n + 1/|xj �1/2 ≤ (2n)1/2 , 2 | 134 RICHARD B. MELROSE n xjwj for wj ∈ L2(Rn). j=1 = xjwj for wj ∈ L2(Rn). But that means that �x�v = w0 + � x�vj so � If u is in L2(Rn) then �u ∈ L2(Rn), a...
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= Solution 18.9. It is equivalent to ask when �ξ�mδ�0 is in L2(Rn). Since −∞ i.− δ�0(ψ) = δ0(ψ�) = ψ�(0) = ψ(x) dx = 1(ψ), � Rn ξ� 2m has a finite integral over this is equivalent to finding m such that � Rn . One option is to write �ξ� = (1 + r2)1/2 in spherical coordinates, and to recall that the Jacobian of sph...
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1, . . . , n, vi ∈ S; (Rn) have Fourier transforms ξ−n−1χAi. = and for i |ξi| > c�ξ� on the support of v�i for each i = 1, . . . , n, each term Since { ξ; ξi = supj |ξj , ξ | | ≥ 1} { | | | | i LECTURE NOTES FOR 18.155, FALL 2004 135 is in H m for any m < 1 + n/2 so, by the Sobolev embedding theorem, each vi ∈ C...
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MIT OpenCourseWare http://ocw.mit.edu 18.014 Calculus with Theory Fall 2010 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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The Challenges of Delivering The Challenges of Delivering Content on the Internet Content on the Internet Tom Leighton Tom Leighton Chief Scientist Chief Scientist Akamai Technologies Akamai Technologies Outline Outline How the Web Works How the Web Works Services Akamai’s Services Akamai’s Technology Overview Techn...
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Bottleneck Implications Slow downloads •• Slow downloads Content must traverse multiple backbones and long distances -- Content must traverse multiple backbones and long distances Unreliable performance •• Unreliable performance Content may be blocked by congestion or backbone -- Content may be blocked by congestion o...
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 Results Results Keynote Web Site Performance Typical Improvement with Akamai 5 1 y a M n o o N 6 1 y a M n o o N 7 1 y a M n o o N 8 1 y a M n o o N 9 1 y a M n o o N 0 2 y a M n o o N 1 2 y a M n o o N 2 2 y a M n o o N 3 2 y a M n o o N 4 2 y a M n o o N 5 2 y a M n o o N 6 2 y a M n o o N 7 2 y a M n o o N Web ob...
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functionality of ordinary conference calls Akamai Forum:: enables businesses to enables businesses to Webcasts produce live, interactive Webcasts produce live, interactive •• Akamai Conference •• Akamai Forum Akamai Forum Akamai Forum No special No special client software client software Demand Live or On--Deman...
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amai’s storage management service •• ACSACS:: storage management service that persistently stores content delivered to that persistently stores content delivered to network Akamai’s network end users via Akamai’s end users via a comprehensive Digital Parcel Service:: a comprehensive •• Digital Parcel Service dig...
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0 Minutes 10 1 Browser’s Cache 2 9 3 8 OS Downloading www.xyz.com Downloading www.xyz.com Akamai’s EdgeSuite with with Akamai’s EdgeSuite WWW.XYZ.COM WWW.XYZ.COM 11 22 DNS 66 55 77 33 User enters www.xyz.com •• User enters www.xyz.com Browser requests IP •• Browser requests IP address for www.xyz.com address for ...
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.net 20.20.123.55 11 12 a212.g.akamai.net .net Root (InterNIC) Akamai High-Level DNS Servers 30.30.123.5 13 Akamai Low-Level DNS Servers End User 16 1 Local Name Server 3 14 Browser’s Cache 2 15 OS DNS Maps & Time--ToTo--LiveLive DNS Maps & Time Maps created using •• Maps created using info on: info on: Internet c...
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also breaks also breaks performance performance bottlenecks when bottlenecks when distributed across distributed across 12,000 servers 12,000 servers Used as an API to •• Used as an API to party third--party third applications on applications on Akamai’s network Akamai’s network <html> <asi version = “1.0...
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Satellite Uplink Encoding Entry Point 1 2 33 44 1 2 X X X X 1 2 3 4 1 2 3 4 x 11 22 3 43 4 1 2 3 4 1 2 3 4 Top-level reflectors Regions Outline Outline How the Web Works How the Web Works Services Akamai’s Services Akamai’s Technology Overview Technology Overview Technological Challenges Technological Challenges T...
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data mining time monitoring of system for NOCC with •• RealReal--time monitoring of system for NOCC with meaningful alerts and performance metrics meaningful alerts and performance metrics time SQL queries to the system Support for real--time SQL queries to the system •• Support for real Technological Challenges Tec...
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we called Akamai. Tuesday night we were Akamaized and instantly 6-10 times faster.” Craig Maccubbin CTO of BET.com BET.com Akamaized 90% of Each Web Page with FreeFlow: • Improved site performance (6-10 times) • Quadrupled page view capacity • Postponed 2nd data center build out • Preserved graphic-rich page design...
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L1: 6.111 Course Overview L1: 6.111 Course Overview Acknowledgements: Materials in this lecture are courtesy of the following sources and are used with permission. Rex Min J. Rabaey, A. Chandrakasan, B. Nikolic. Digital Integrated Circuits: A Design Perspective. Prentice Hall/Pearson, 2003. L1: 6.111 Spring 2006 Intro...
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(cid:134) Prior digital design experience is NOT Required (cid:134) 6.004 is not a prerequisite! (cid:129) Take 6.004 before 6.111 or (cid:129) Take 6.004 after 6.111 or (cid:129) Take both in the same term (cid:134) Must have basic background in circuit theory (cid:134) Some basic material might be a review for those ...
https://ocw.mit.edu/courses/6-111-introductory-digital-systems-laboratory-spring-2006/317da3eef4612e543559758c871d25d8_l1_overview.pdf
) Must emphasize digital concepts, but inclusion of analog interfaces (e.g., data converters, sensors or motors) common and often desirable (cid:134) Proposal Conference (cid:134) Design Review(s) (cid:132) Design presentation in class (% of the final grade for the in- class presentation) (cid:132) Top projects will ...
https://ocw.mit.edu/courses/6-111-introductory-digital-systems-laboratory-spring-2006/317da3eef4612e543559758c871d25d8_l1_overview.pdf
should be joint with individual authors specified for each section (cid:122) Copy anything you want (with attribution) for your project report L1: 6.111 Spring 2006 Introductory Digital Systems Laboratory 6 The First Computer The First Computer Photograph of the Babbage Difference Engine. Image removed due to copyri...
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132) Shannon’s 1937 MIT Master’s Thesis introduces the world to binary digital electronics L1: 6.111 Spring 2006 Introductory Digital Systems Laboratory 9 Evolution of Digital Electronics Evolution of Digital Electronics Vacuum Tubes Transistors VLSI Circuits ENIAC, 1946 First Transistor Bell Labs, 1948 4004, 1971 U...
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(cid:132) Labs & Design project (cid:132) Product specs algorithm selection, flowcharts, etc. Behavioral Description software-like programming (cid:132) Algorithms, RTL, etc. (cid:132) Flowcharts (cid:132) State transition diagrams HDL Description (cid:132) Verilog code (cid:132) VHDL code automated synthesis Hardware ...
https://ocw.mit.edu/courses/6-111-introductory-digital-systems-laboratory-spring-2006/317da3eef4612e543559758c871d25d8_l1_overview.pdf
:132) Dataflow Level (cid:134) The flow of data through components is specified based on the idea of how data is processed (cid:132) Gate Level (cid:134) Specified as wiring between logic gates (cid:134) Not practical for large examples (cid:132) Switch Level (cid:134) Description in terms of switching (modeling a tr...
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Embedded Digital System Embedded Digital System Analog Inputs (sensors, audio, video, tablet) A/D digitize synchronize Digital Inputs (peripherals, buses, switches) Sync. Memory D/A Control Data Processing Analog Outputs (actuators, motors, multimedia) Digital Outputs (peripherals, buses, lights) (cid:132) Digit...
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are important components of digital design L1: 6.111 Spring 2006 Introductory Digital Systems Laboratory 19 The Inverter: Voltage Transfer Characteristic The Inverter: Voltage Transfer Characteristic IN OUT Digital circuits perform operations on logical (or Boolean) variables A logical variable is a mathematical abst...
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of inverters v0 v1 v2 v3 v4 v5 v6 out v3 v1 f (v) Simulated response 5 3 1 ) t l o V ( V fin v(v) v0 v1 v 2 v2 v0 2 1 0 in 2 4 6 8 10 t (nsec) | Voltage gain | should be > 1 between logic states L1: 6.111 Spring 2006 Introductory Digital Systems Laboratory 23 Lab Hours, Equipment, Computers Lab Hours, Equipment, Com...
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use ‘setup 6.111’- ‘setup 6.111’ sources /mit/6.111/.attachrc which attaches 6.111-nfs and sources /mit/6.111-nfs/.attachrc which sets up your path and environment variables, etc. L1: 6.111 Spring 2006 Introductory Digital Systems Laboratory 24 The 6.111 Lab The 6.111 Lab Courtesy of Tony Rinaldo. Used with permis...
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Determinants 2. Area and Volume Area and volume interpretation of the determinant: (1) ± � � a 1 a 2 � b2 b1 � � � � � = area of parallelogram with edges A = (a1, a2), B = (b1, b2). B θ A (2) � � � a1 a2 a3 � � � b3 � = volume of parallelepiped with edges row-vectors A, B, C. ± � b1 b2 � � c3 �...
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= = A · B ′ , = a1b2 − a2b1 ′ , by the above observations b 1 B b 2 by the geometric definition of dot product by the formula for B ′ This proves the area interpretation (1) if A and B have the position shown. If their positions are reversed, then the area is the same, but the sign of the determinant is chan...
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D-Lab Spring 2010 1 Today in class: • Review of the Design Process • Design for Manufacture – No Spare Parts • Books Assignment • Readings 2 D-Lab Design for Manufacture 3 DfM Definition: Adapting a design to make it more easily manufactured and to reduce its manufacturing costs. 4 DfM Definition: To g...
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