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�� o q · 0 0 0 o q 0 0 + q2 y − q2 x − q2 q2 z 2(qyqx + q0qz) 2(qzqx − q0qy) 0 2(qxqy − q0qz) y − q2 x + q2 0 − q2 q2 z 2(qzqy + q0qz) 0 2(qxqz + q0qy) 2(qyqz − q0qx) y + q2 x − q2 0 − q2 q2 z      The matrix ¯QT Q has skew-symmetric components and symmetric components. This is useful for conversions. Given a quat...
https://ocw.mit.edu/courses/6-801-machine-vision-fall-2020/3684c9529d76a9a87fe3db7ae5e91f71_MIT6_801F20_lec19.pdf
the angle (we can solve for θ through arccos of the expression above), it is not the best way to do instead. so: we will encounter problems near θ ≈ 0, π. Instead, we can use the off-diagonal elements, which depend on sin (cid:17) (cid:16) θ 2 Note that this works because at angles θ where cos and vice versa. (cid:17) (...
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= 4q0qx r21 + r12 = 4qxqy r32 + r23 = 4qyqz r13 + r31 = 4qzqz Adding/subtracting off-diagonals give us 6 relations, of which we only need 3 (since we have 1 relation from the diagonals). For instance, if we have qi = qy, then we pick off-diagonal relations involving qy, and we solve the four equations given by: 1 − r11 +...
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. sl ∆= (cid:80)n i=1 ||r(cid:48) l,i||2 2 Then we can write this objective for the optimal scaling factor s∗ as: s∗ = arg min s {J(s) ∆= sr − 2sD + s2sl} Since this is an unconstrained optimization problem, we can solve this by taking the derivative w.r.t. s and setting it equal to 0: dJ(s) ds = (cid:16) d ds sr − 2sD...
https://ocw.mit.edu/courses/6-801-machine-vision-fall-2020/3684c9529d76a9a87fe3db7ae5e91f71_MIT6_801F20_lec19.pdf
we can write our objective and optimization problem over scale as: || 1 √ s r(cid:48) r,i − √ sR(r(cid:48) l,i)||2 2 (cid:19) − 2 n (cid:88) (cid:16) ||r(cid:48) r,i||2 2 r,iR(r(cid:48) r(cid:48) l,i) n (cid:88) (cid:17) + s ||R(r(cid:48) l,i)||2 2 n (cid:88) i=1 n (cid:88) i=1 (cid:18) 1 s s∗ = arg min s = arg min s =...
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scaling factor s∗ as: s∗ = arg min s {J(s) ∆= 1 s sr − 2D + ssl} 4 Since this is an unconstrained optimization problem, we can solve this by taking the derivative w.r.t. s and setting it equal to 0: dJ(s) ds = (cid:19) (cid:18) 1 s sr − 2D + ssl d ds 1 s2 sr + sl = 0 =⇒ s2 = = 0 = − sl sr Therefore, we can see that go...
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the derivative of this objective w.r.t. our quaternion o q and setting it equal to zero. Note the following helpful identities with matrix and vector calculus: 1. 2. d da (a · b) = b d da (aT M b) = 2M b However, since we are working with quaternions, we must take this constraint into account. We saw in lecture 18 that...
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= 0 N ( o q 2 T o q)2 o q 2N T o o q q − o q ( 5 = 0 From here, we can write this first order condition result as: o q o q = N o q o q T o q N T o q Note that T o q o N q T o q o q ∈ R (this is our objective). Therefore, we are searching for a vector of quaternion coefficients such applying the rotation matrix to this ve...
https://ocw.mit.edu/courses/6-801-machine-vision-fall-2020/3684c9529d76a9a87fe3db7ae5e91f71_MIT6_801F20_lec19.pdf
.1 How Many Correspondences Do We Need? Recall that we are looking for 6 parameters (for translation and rotation) or 7 parameters (for translation, rotation, and scaling). Since each correspondence provides three constraints (since we equate the 3-dimensional coordinates of two 3D points in space), assuming non-redund...
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note, this is often not needed, especially for finding the absolute orientation between two cameras, because oftentimes the only transformations that need to be considered due to the design constraints of the system (e.g. an autonomous car with two lidar systems, one on each side) are translation and rotation. 1.4.2 Whe...
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ar. 1.4.3 What Happens When Points are Coplanar? When points are coplanar, we have that the matrix N , composed of the sum of dyadic products between the correspondences in the two point clouds, will be singular. To describe this plane in space, we need only find a normal vector ˆn that is orthogonal to all points in th...
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at least Span({ˆn}), and therefore M is singular. Recall that a matrix M ∈ Rn×d is singular if ∃ x ∈ Rd, x (cid:54)= 0 such that M x = 0, i.e. the matrix has a non-trivial null space. 1.4.4 What Happens When Both Coordinate Systems Are Coplanar Visually, when two point clouds are coplanar, we have: Figure 3: Two coplan...
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can orient two planes on top of each other, and then just solve a 2D least-squares problem to solve for our in-place rotation. With these steps, we have a rotation between the two point clouds! 1.5 Robustness In many methods in this course, we have looked at the use of Least Squares methods to solve for estimates in th...
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just immediately terminating once you have a good fit, you can run this many times, and then take the best fit from that. Furthermore, for step 3, we threshold the band from the fitted line/hyperplane to determine which points of the dataset are inliers, and which are outliers (see figure below). This band is usually given...
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this space? Many orientation problems we have studied so far do not have a closed-form solution and may require sampling. How do we sample from the space of rotations? 1.6.1 Initial Procedure: Sampling from a Sphere Let us start by sampling from a unit sphere (we will start in 3D, aiming eventually for 4D, but our fram...
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the sphere. Generalization to 4D: As we mentioned above, our goal is to generalize this from 3D to 4D. Cubes and spheres simply become 4-dimensional - enabling us to sample quaternions. 1.6.3 Sampling From Spheres Using Regular and Semi-Regular Polyhedra We saw the approach above requires discarding samples, which is c...
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:0)− π 4 o q = (cos (cid:0)− π 4 (cid:1) , sin (cid:0)− π 4 (cid:1) ˆx) = 1√ 2 (1, −ˆx) (cid:1) , sin (cid:0)− π 4 (cid:1) ˆy) = 1√ 2 (1, −ˆy) (cid:1) , sin (cid:0)− π 4 (cid:1) ˆz) = 1√ 2 (1, −ˆz) These 10 rotations by themselves give us 10 ways to sample the rotation space. How can we construct more samples? We can d...
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1) (cid:17) (cid:16) θ 2 = 1 2 =⇒ θ 2 = π 3 =⇒ θ = 2π 3 Therefore, we have produced a new rotation that we can sample from! These are just a few of the pairwise quaternion products we can compute. It turns out that these pairwise quaternion products produce a total of 24 new rotations from the original 10 rotations. Th...
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-tXt 4 AX ret Ie C.lb\Ai .- L-D%= LSnattt liS V\ I (.A%>3 =~2 c \2t 1 MIA\ A r&\ - Ickt J . * - b -o - i S~~~~ ,,,,, ! %LLI I =4/ & . 4~p/kb ' A'- @ C5 le-J11 V, 0 F,, LCC, ) I- _ :. -. fact f*> At _ e,, 2_ V(+) _~ rl si, ,° ( F . . 0 I r_· ^_ ' ' (* e-lt fGe i. ­ t ~aI I...
https://ocw.mit.edu/courses/8-322-quantum-theory-ii-spring-2003/36b3cccc5336969c0304126613a3121e_83223Lecture2.pdf
. (\ N e ivit 0 e w4 QLbeA p se X , I - 6, %9 &A-e o q&)7Xe Anfta. '-are- S*K S4OAMAle C' 6 L4HV I\ e A IaO., we at-pt cla r.- SQ-C,~C~4054d cry;Pwddf) I- CT" QA; SSi&N,- " ukloiri L9q. ke [A. dl F--Yocv CP­ 2- tk-e. <.~em AY\%fKX:9 C'e.AO(WeQ COAtiw -fwtC.ke ( t-o , I-) in meunrcc...
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Lecture 2 8.321 Quantum Theory I, Fall 2017 5 Lecture 2 (Sep. 11, 2017) 2.1 More Relevant Math 2.1.1 Inner Products Last time, we discussed the concept of a maximally linearly independent set, which is a set {|αj(cid:105)} of vectors that are linearly independent, and such that there exists no |β(cid:105) such that {|α...
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α(cid:105), |β(cid:105))∗ = (|β(cid:105), |α(cid:105)) . (|α(cid:105), |β(cid:105) + |β(cid:48)(cid:105)) = (|α(cid:105), |β(cid:105)) + (|α(cid:105), |β(cid:48)(cid:105)) . 4. For all |α(cid:105) ∈ V , and if (|α(cid:105), |α(cid:105)) = 0, then |α(cid:105) is the zero ket, |α(cid:105) = 0. (|α(cid:105), |α(cid:105)) ...
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8) Lecture 2 8.321 Quantum Theory I, Fall 2017 as we discussed in the last lecture, which can be endowed with the inner product ˆ (f, g) = 0 1 dx f ∗(x)g(x) . 6 (2.9) Now we introduce a bit of terminology. The vectors we have been discussing are referred to as kets. Two kets are orthogonal if (|α(cid:105), |β(cid:105)...
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104)γ|, such that for any basis {|αj(cid:105)}, the statement γ : |αj(cid:105) (cid:55)→ cj (2.14) implies that (cid:104)γ|αj(cid:105) = cj . We see that the dual space is just the space of linear functionals on V . The {γ} form an n- dimensional vector space V ∗, where n = dim V . We then have a duality V ↔ V ∗, given...
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017 7 2.1.4 Operators Recall the second postulate of quantum mechanics: observables are represented in quantum me- chanics as Hermitian operators acting on the Hilbert space H (from here on out, we will consider states in the Hilbert space H rather than an arbitrary vector space V ). In order to understand this stateme...
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105) + c∗ βX|β(cid:105) (2.22) for all cα, cβ ∈ F and |α(cid:105), |β(cid:105) ∈ H. We can also define an action of these same operators on the dual space, which will be a right action of the form (cid:104)β|X for (cid:104)β| ∈ H∗. We define this object via its inner product with kets, by requiring that it satisfy the pr...
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2.27) for all |α(cid:105) ∈ H. Given an orthonormal basis |{a(cid:48)}(cid:105) (notation from Sakurai), the identity operator can be expressed in the form 1 = (cid:88)(cid:12) (cid:12) . (cid:12)a(cid:48)(cid:11)(cid:10)a(cid:48)(cid:12) We can use Eq. (2.28) to write any operator X in the form a(cid:48) X = 1X1 (cid:...
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(cid:48)|X|a(cid:48)(cid:48)(cid:105), given any orthonormal basis |{a(cid:48)}(cid:105). This defines an n × n matrix with complex entries corresponding to each operator X. For this reason, we will often use the words “operator” and “matrix” interchangeably if the chosen basis is clear, even though the concept of an op...
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|(XY )† = (cid:104)γ| , (2.31) (2.32) (2.33) (2.34) which we can compare with the second equation in (2.33) to yield (XY )† = Y †X †. This same concept has a well-defined meaning for matrices. As we have seen, any operator has the same information content as an n × n matrix, where n = dim H. If M is a matrix correspondi...
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(2.37) (2.38) As a second example, consider the Hilbert space H of square-integrable functions on (−∞, ∞), with inner product (cid:104)f1|f2(cid:105) = ˆ ∞ −∞ dx f1 ∗(x)f2(x) (2.39) for |f1(cid:105), |f d 2(cid:105) ∈ H. Now consider the operator A = . Using integration by parts, we see that dx ˆ ∞ ˆ dx f1 ∗(x) d dx f2...
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which we have already seen. For some operators, we can define an inverse operator: for an operator A, its inverse operator A−1 (if it exists) satisfies A−1A = AA−1 = 1 . (2.44) Inverse operators are not guaranteed to exist. Of special interest to us are unitary operators: a unitary operator U is one that satisfies U −1 = ...
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of A with distinct eigenvalues are orthogonal. Proof. Suppose that for some Hermitian operator A and kets |a(cid:48)(cid:105), |a(cid:48)(cid:48)(cid:105) ∈ H we have (cid:12)a(cid:48)(cid:11) = a(cid:48)(cid:12) A(cid:12) a (cid:12) (cid:12) (cid:12) (cid:10) (cid:10) (cid:12)A = a(cid:48)(cid:48) a(cid:48)(cid:48) (c...
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Eqs. (2.48a) and (2.48b), we see that (cid:2)(cid:0)a(cid:48)(cid:48)(cid:1)∗ − a(cid:48)(cid:3)(cid:10)a(cid:48)(cid:48)(cid:12) (cid:11) (cid:12)a(cid:48) = 0 . (2.48a) (2.48b) (2.49) |a(cid:48)(cid:48)(cid:105) and we have (cid:54)= a(cid:48)(cid:48), then this proves that (cid:104)a(cid:48)(cid:48)|a(cid:48)(cid:10...
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5)(cid:104)a| . We can check that for some eigenket |b(cid:105), we have A|b(cid:105) = (cid:88) a a|a a (cid:105)(cid:104) |b(cid:105) = (cid:88) a a |a(cid:105)δab = b|b(cid:105) . Note that the equation is simply a special case of Eq. (2.51). (cid:88) 1 = |a(cid:105)(cid:104)a| a (2.50) (2.51) (2.52) (2.53) MIT Ope...
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Queueing Systems: Lecture 5 Amedeo R. Odoni October 30, 2006 Lecture Outline • A fundamental result for queueing networks • State transition diagrams for Markovian queueing systems and networks: examples • Examples • Dynamic queueing systems and viable approaches • Qualitative discussion of behavior Reference:...
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Poisson arrivals; λ One server; neg. exp’l; μ 1 One server; neg. exp’l; μ 2 No queuing space No queuing space Note: The queuing system on the right may “block” the one on the left. Example 2: M/Ek/1 System, with system capacity for total of N users See distributed notes. Example 3: Two Types of Users a...
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imate Methods Problems with Approach 1: • 1. For cases in which demand varies significantly (e.g., >10% from overall average value) the delay estimates can be VERY poor 2. Will underestimate overall average delay, possibly by a lot Problems with Approach 2: • 1. May not have ρ < 1, for some intervals; then wha...
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15 1:00 3:00 5:00 7:00 9:00 11:00 13:00 15:00 17:00 19:00 21:00 23:00 Dem R1 R2 R3 R4 (R1= capacity is 80 movements per hour; R2 = 90; R3 = 100; R4 = 110) Two Recent References on Numerical Methods for Dynamic Queueing Systems • Escobar, M., A. R. Odoni and E. Roth, “Approximate Solutions for Mult...
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“Medicine and the Computer: The Promise and Problems of Change” (cid:216) Perceived problems —W.B. Schwartz, NEJM 1970 (cid:216) Physician shortage and maldistribution (cid:216) Ever-expanding body of knowledge, so that the physician cannot keep up (cid:216) Exploit the computer as an “intellectual”, “deductive” i...
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) use some representation of disease and a diagnostic algorithm (cid:216)disease/symptom associations (since 1960’s) (cid:216)probabilistic version (since 1960’s) (cid:216)causal models (since 1980’s) 5 Flowcharts contain all of… Diagnostic Approach Domain Knowledge Inference Engine 9 Flowcharts (cid:216) ...
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organism is organism is streptococcus. streptococcus. streptococcus. streptococcus. 11 Mycin consult Mycin consult Davis, et al., Artificial Intelligence 8: 15-45 (1977) 12 12 How Mycin Works (cid:216) To find out a fact (cid:216) If there are rules that can conclude it, try them (cid:216) Ask the user (ci...
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Representation s1 s2 s3 s4 s5 s6 s7 s8 s9 s10 s... Disease s1 s2 s3 s4 s5 s6 s7 s8 s9 s10 s... Disease 16 Diagnosis by Card Selection s1 s2 s3 s4 s5 s6 s7 s8 s9 s10 s... Disease 17 Diagnosis by Edge-Punched Cards (cid:216) Dx is intersection of sets of diseases that may cause al...
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NEPHROTIC SYNDROME, a clinical state FINDINGS: 1* Low serum albumin concentration 2. Heavy proteinuria 3* >5 gm/day proteinuria 4* Massive symmetrical edema 5* Facial or peri-orbital symmetric edema 6. High serum cholesterol 7. Urine lipids present IS-SUFFICIENT: Massive pedal edema & >5 gm/day proteinuria MUST-NOT-HAV...
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SYMMETRICAL. … DIAGNOSES THAT HAVE BEEN ACCEPTED ARE: NEPHROTIC SYNDROME AND SODIUM RETENTION. THE LEADING HYPOTHESIS IS IDIOPATHIC NEPHROTIC SYNDROME. IDIOPATHIC NEPHROTIC SYNDROME ACUTE GLOMERULONEPHRITIS HENOCH SCHOENLEIN PURPURA fit 0.80 0.22 0.07 explained score 0.58 0.37 0.24 0.27 0.09 0.10 24 Other “Frame-bas...
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4 M5 M6 H2 29 Competitors H1 M1 M2 M3 M4 M5 M6 H2 30 Still Competitors H1 M1 M2 M3 M4 M5 M6 H2 31 Probably Complementary H1 M1 M2 M3 M4 M5 M6 H2 32 Multi-Hypothesis Diagnosis (cid:216) Set aside complementary hypotheses (cid:216) … and manifestations predicted by them (cid:216) Solve diagnostic problem among comp...
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loss (cid:216) Vomiting causes acid loss (cid:216) Therefore, normal pH is a manifestation of {diarrhea + vomiting}! 39 Temporal Reasoning (cid:216)Keeping track of multiple forms of temporal relations (Kahn '75) (cid:216)The time line (cid:216)“On Dec. 12 last year . . .” (cid:216)Special reference events (cid:216...
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to anticipate them all (cid:216) Strawman: Fit parameters to a physiological model, then predict consequences to suggest (cid:216) other expected findings (cid:216) reasonable interventions (cid:216) Qualitative models (cid:216) Combining associational and model-based reasoning 44 Guyton's Model of Cardiovascular D...
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216) A few sophisticated, modern, probability-based systems are now being built (cid:216) HIS's really are being developed (slowly, but surely) and will provide a critical opportunity for experimentation (cid:216) No large, broad-domain, deep systems are being tackled today (cid:216) Research advances are laying the...
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Lecture #1 Instructor Notes First off, welcome. I hope that these notes are interesting and helpful to you. Also, please note that there is a set of “Comments” on each lecture, that go along with the readings and the Instructor’s Notes here. Let us start with the first question you should always ask in a course….. ...
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the water comes from an equation of state relating the soundspeed to temperature T, salinity S, and depth z. In a very simplified form, the soundspeed as a function of depth z (its main dependence) is This is the first equation in the Computational Ocean Acoustics book, and shows that the soundspeed is very sensit...
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8 Continuous-Time Fourier Transform In this lecture, we extend the Fourier series representation for continuous- time periodic signals to a representation of aperiodic signals. The basic ap- proach is to construct a periodic signal from the aperiodic one by periodically replicating it, that is, by adding it to itself s...
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represents the sig- nal. This envelope is defined as the Fourier transform of the aperiodic signal remaining when the period goes to infinity. Although the Fourier transform is developed in this lecture beginning with the Fourier series, the Fourier transform in fact becomes a framework that can be used to encompass bo...
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Aperiodic Signals: The Continuous-Time Four- ier Transform, pages 186-195 Section 4.5, Periodic Signals and the Continuous-Time Fourier Transform, pages 196-202 Continuous-Time Fourier Transform MARKERBOARD 8.1(a) Cw%-nwnsA -TWAe Ferio. SAsDg Nce pevb~e.t. r. T . 4,) .4 FOURIER REPRESENTATION OF APERIODIC SIGNALS (""N...
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dt Then: Toak X(W) I=kcoo X(w) is the envelope of To ak e jkoot = +00 k=-co k=-00 +00 x(t) = 27 X(kco) k k=-Oo X(kwO) ejkwot Continuous-Time Fourier Transform +00 X(o) = x(t) ei jWt dt 00 Fourier transform - analysis x(t) = E X(kwo) ejkwo tWO k=-0O As To-- oo, coo -* 0 1x t) - x (t), we doE - +a( x(t) = 2 X(o) e j...
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4T1 x(t)1 -T1 0 T, JT F7-1 *.. To TRANSPARENCY 8.7 ±(t) and its Fourier series coefficients with To = 8T1. [As the figure is drawn, To and T, are not to scale.] T,1X(W) t. e I - S T t V T 1 / 'it/I Continuous-Time Fourier Transform MARKERBOARD 8.1(b) ExCapkt (Td' 4.'1) 4S e.e -i - e. I ~ c*w-+ a4-30& I~ V~V ~-~-...
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-20 -40 -601 -r/4 -~ /2 -37r/4 - _ ~ 0.1a _ ~ I 10a I 100a frequency (CO ) Fourier Series coefficients equal times samples of Fourier 1 To transform of one period 7(t) r __ . . 27> T /2 x(t) = one period of x(t) x(t) + k x(t) -) X((I) Continuous-Time Fourier Transform TRANSPARENCY 8.11 The Fourier transform ...
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PERIODIC SIGNAL R(t) TRANSPARENCY 8.14 Representation of the Fourier series in terms of the Fourier transform. (t) + N(t) ak X Fourier series coefficients Fourier transform +00 i(t) - 21r _ ., X(o) eict dw +00 2r k=- 00 27r ak +00 f (w-kco0 ) e- jet dw Continuous-Time Fourier Transform 8-11 TRANSPARENCY 8.15 Illu...
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series for a periodic signal. TRANSPARENCY 8.18 Summary example illustrating some of the relationships between the Fourier series and Fourier transform. MIT OpenCourseWare http://ocw.mit.edu Resource: Signals and Systems Professor Alan V. Oppenheim The following may not correspond to a particular course on MIT Ope...
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Observers, state feedback 6.011, Spring 2018 Lec 10 1 Observers 2 System (“plant”) x[n] w[n] q[n] A, b, cT, d y[n] + 1[n] 3 A good model x[n] w[n] [n q[n] A, b, cT, d b y[n] + y[n] b 1[n] 4 Observer configuration x[n] w[n] q[n] A, b, cT Plant y[n] + Z[n] y[n] q[n] [n...
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1 2 3 4 5 6 7 8 MIT OpenCourseWare http://ocw.mit.edu 6.890 Algorithmic Lower Bounds: Fun with Hardness Proofs Fall 2014 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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18.336 spring 2009 lecture 13 03/19/09 Initial Value Problems (IVP) ⎧ ⎨ ⎩ in Ω×]0, T [ on Ω × {0} on ∂Ω×]0, T [ ut = Lu u = u0 u = g where L differential operator. ← ← ← PDE initial condition boundary condition ⎫ ⎬ ⎭ Ex.: • L = � 2 → Poisson equation •Lu = b · �u advection equation •Lu = −�2(�2 biharm...
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Δt) − u(x, t) Δt Approximate time derivative by step: d dt → unew(x) = u(x) + ΔtLu(x) = (I + ΔtL)u(x) Need to know about ODE solvers. Stationary problem: [explicit Euler] 1 Numerical Methods for ODE � � y(t) ∈ Rd y˙(t) = f (y(t)) y(0) = ˚y yn ≈ y(t), yn+1 ≈ y(t + Δt) y Linear approximation: y˙ ≈ Explicit ...
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stable: Δt < IE unconditionally stable 2 ρ(A) Message: One step implicit is more costly than one step explicit. , then implicit pays! But: If ρ(A) large � � �� stiffness Ex.: Different time scales −50 49 49 −50 A = � Solution: y(t) = e−t � , ˚y = � · �� 1 1 behavior � � � 2 0 � � + e−99t −1 · 1 �� ...
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6.241 Dynamic Systems and Control Lecture 1: Introduction, linear algebra review Readings: DDV, Chapter 1 Emilio Frazzoli Aeronautics and Astronautics Massachusetts Institute of Technology February 2, 2011 E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 1 / 22 Outline 1 Syllabus review 2 Linear Algeb...
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algebra, and of least squares problems. Representation, structure, and behavior of multi-input, multi-output (MIMO) linear time-invariant (LTI) systems. Robust Stability and Performance. Approaches to optimal and robust control design. Hopefully, the material learned in this course will form a valuable foundation ...
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Vaccaro, Digital Control: A State-Space Approach, McGraw-Hill, 1995. E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 7 / 22 Tentative schedule # 1 2 3 4 5 6 7 Date Topic Feb 2, 2011 Introduction to dynamic systems and control. Matrix algebra. Feb 7, 2011 Least Squares error solut...
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6 18 19 E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 8 / 22 Tentative schedule Date Topic # 14 15 16 17 18 Mar 28, 2011 Mar 30, 2011 Apr 4, 2011 Apr 6, 2011 Apr 11, 2011 19 Apr 13, 2011 20 Apr 20, 2011 21 22 23 24 25 26 Apr 25, 2011 Apr 27, 2011 May 2, 2011 May 4, 2011 May 9, ...
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(MIT) Lecture 1: Introduction Feb 2, 2011 10 / 22 Vector Spaces A vector space is defined as a set V over a (scalar) field F , together with two binary operations, i.e., vector addition (+) and scalar multiplication ( ), satisfying the following axioms: · Commutativity of +: u + v = v + u, ∀u, v , ∈ V ; Associat...
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y (t) of the LTI ODE dy (t)/dt + 3y (t) = 0; The set of points (x1, x2, x3) ∈ R3 satisfying x1 2 + x2 2 + x 2 = 1. 3 The set of solutions y (t) of the LTI ODE dy (t)/dt + 3y (t) = 0. E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 12 / 22 Subspaces A subspace of a vector space is a subset of vectors that i...
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vectors that are independent. Any set of n independent vectors is also called a basis for the space. if a space contains a set of n independent vectors for any n ∈ N, then the space is infinite-dimensional. E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 15 / 22 Norms Norms measure the ‘length” of a vecto...
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E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 17 / 22 � Inner product An inner product on a vector space V (with scalar field F ) is a binary operation �·, ·� : V × V F , with the following properties: → 1 2 3 Symmetry: �x, y � = �y , x��, ∀x, y ∈ V ; Linearity: �x, ay + bz� = a�x, y � + b�x, z�; Positivit...
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norm is that induced by the inner product) Proof 0 ≤ �x + αy , x + αy � = x �x + α�y �x + αx �y + |α|2 y �y Choose α = −x �y /�y , y � : 0 ≤ �x, x��y , y � − �x, y �2 . E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 19 / 22 The Projection Theorem Let M be a subspace of an inner product space V . Given s...
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. E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 21 / 22 � Linear Systems of equations Consider the following system of (real or complex) linear equations: Ax = y , A ∈ Rm×n , x ∈ Rn , y ∈ Rm . Given A and y , is there a solution x? ∃ a solution x ⇔ y ∈ A ⇔ R([A|y ]) = R(A). There are three cases: ...
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this case it is desired to find the solution than minimizes some cost criterion. E. Frazzoli (MIT) Lecture 1: Introduction Feb 2, 2011 22 / 22 � MIT OpenCourseWare http://ocw.mit.edu 6.241J / 16.338J Dynamic Systems and Control Spring 2011 For information about citing these materials or our Terms of Use, visi...
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Lectures 11 and 12 Air Pollution and SI Engine Emissions Atmospheric Pollution • SMOG O || O3 NO2 – Ozone Nitrogen dioxide R-C-OONO2 PAN(Peroxyacyl Nitrate) • TOXICS – CO, Benzene, 1-3 butadiene, POM (Polycyclic organic Matters), Aldehydes Primary Pollutants: Direct emissions from vehicles  CO, HC, NOx...
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1994 TLEV Euro 4 Euro 5 1997 TLEV 1997-2003 ULEV ) e l i / m g ( x O N 0.1 1975 1977 1 1981 1994 TLEV Euro 3 1997-2003 ULEV Euro 4 Euro 5 PZEV PZEV 1975 1980 1985 1990 1995 2000 2005 2010 1975 1980 1985 1990 1995 2000 2005 2010 0.01 Starting year of implementation Starting year of implementation H...
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rication oil contribution • Hydrocarbon emissions – Fuel hydrocarbons escape oxidation (or only partially oxidized) via various pathways 3 Typical steady state SI engine-out emissions • NOx is a few thousand parts per million • CO is around 0.5-1% for stoichiometric operation • HC is 500-2000 ppm for fully...
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�� Engine-out [NO2]/[NOx]  2% 5 dxNO dt (s-1) x 0 NO SI Engine NO formation Fig. 11-4 Adiabatic flame temperature, Kerosene combustion with 700K, 15 bar air Dash line is adiabatic flame temperature for kerosene combustion with 700K 15 bar air d[NO] dt (Zeldovich)   2k1  O   1...
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Very temperature sensitive 2000 2200 2400 2600 T (oK) © McGraw-Hill Education. All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use. ) a p M ( P ) K ( u T , b T ) m p p ( O N Thermodynamic state of charge x b Fig. 9-5...
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© McGraw-Hill Education. All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use. 7 NO control by EGR • EGR is a dilution effect – Reduce burned gas temperature via increase in thermal inertia 1600 rpm; v=0.5; MBT tim...
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800 using O3 as indicator. Maximum O3 formation occurs at about 1500-1700 hr. Carter Index for Ozone Forming Potential (CARB July, 1992) Table from SAE Paper 932718 (Tauchida et.al) Methodology explained in SAE Paper 900710 (Lowi and Carter) © Society of Automotive Engineers. All rights reserved. This content...
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l i O Compression stroke Desorption of fuel vapor Burned gas m l i f l i O Expansion stroke Ishizawa and Takagi (Nissan) JSME Int. Jnl. 1987 Vol. 30 No. 260 pp. 310-317 © JSME. All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/fa...
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(1.6%) Fully Burned Exhaust Tailpipe- out HC (0.1-0.4%) Catalyst HC Sources: Magnitudes and Percent of Total Engine-out Emissions* (SAE Paper 932708) Source Crevices Quench Oil Layers Deposits Liquid Fuel Valve Leakage Total % Fuel Escaping Normal Combustion 5.2 Fraction Emitted % Fuel as HC % of Tota...
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ustion Engines Spring 2017 For information about citing these materials or our Terms of Use, visit: https://ocw.mit.edu/terms.
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6.825 Techniques in Artificial Intelligence What is Artificial Intelligence (AI)? Lecture 1 • 1 If you're going to teach or take an AI course, it's useful to ask: "What's AI?" It's a lot of different things to a lot of different people. Let's go through a few things that AI is thought to be and situate them within...
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area called cognitive neuroscience. The research strategy is to affiliate with someone who does experiments that reveal something about what goes on inside people's heads and then build computational models that mirror those kind of processes. A crucial question is to decide at what level to mirror what goes on in...
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systems drawn from this larger class. But then you get into terrible trouble because you have to say what it means to behave intelligently. We might feel that although we can't define what it is to be intelligent, we can recognize it when we see it. We'll give up on trying to decide what intelligence is and spend o...
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. Some of these applications you might not want to call "intelligent" or "rational" but it is work that has traditionally been done in the field of AI. Usually, they are problems in computer science that don't feel well specified enough for the rest of the computer science community to want to work on. For instance,...
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could get that very badly wrong and so you want a system that's good and reliable. There are long lists of examples; AI applications are very viable. We're going to spend most of our time thinking, or at least feeling motivated, by computational systems that behave rationally. But a lot of the techniques that we wil...
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an account of how an agent works by separating it from the world it works in, because the interface is so big and so complicated. And that may be right. That I can't get exactly right a description of how the agent needs to operate in the world by separating it from the world. But, it gives me a kind of leverage i...
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environment actions Lecture 1 • 10 And, so, here's another view of the world. We're going to be thinking about the agent as the software that runs some big hardware system. That is not to make light of or say that it's easy to design the hardware part, and depending on how the hardware part has been designed your...
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World Model • A – the action space • P – the percept space Lecture 1 • 13 Next, we need a percept space: what are all the things that the agent can perceive in the world? These spaces can be continuous; you can imagine that the agent can perceive how high its arm is raised or the temperature in some reaction ves...
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Model • A – the action space • P – the percept space • E – the environment: A* • Alternatively, define P → • • • S – internal state [may not be visible to agent] Perception function: S A World dynamics: S P S → → × s p Perception Function World Dynamics a Lecture 1 • 15 Usually we'll think...
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We need a utility function. It’s typically thought of as a mapping from states in the world to real values, or maybe sequences of states into real values. It is meant to say, "Agent, these are the states of the world and this is how valuable they are from your perspective." So that indirectly tells the agent what y...
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its goals. This is all in high-level pseudo-psychological talk that makes some people nervous. We can cache it out into something more concrete in a minute but the idea is that you're rational if you take actions that are consistent with what you are trying to achieve in the grand scheme of things. Let's say that ...
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to have watched the weather forecast the night before. But, given what I knew it was ok to ride my bike, even though it turned out be dumb at some level, because I didn't know what was happening. 19 Rationality • A rationa l agent takes actions it believes will achieve its goals . • Assume I don’t like to get ...
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big problem with our definition of rationality… Lecture 1 • 21 This is still not a good enough notion to decide what should go in the head of our agent or our robot. Do you see any potential problem with this as a criterion for behavior in real systems? 21 Limited Rationality • • There is a big problem with o...
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, we might be able to make a robot that's the best possible chess player, but it might not be able to cross the street. If our robot needs to be able to cross the street, its aggregate behavior is not rational. So, when we think about rationality we may we want to think about it in a much broader context: given all...
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that someone was given the job of writing a specification of the environment that we want our agent to work in. You could say: "Oh, but you can't do that. This whole approach seems pretty silly because how is it that anyone could specify the domain that the agent is going to work in?" It does seem hard to write dow...
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those constraints. The problem is that, although information theoretically this is a specification for the correct program, it is not an effective specification. It's not a specification that the computer can use. There is a huge gap between the specification for what you want the agent to do and what you can write...
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